text
stringlengths
0
205
align:start position:0%
the random variable of interest takes
the value of 1 over 12 and with
align:start position:0%
the value of 1 over 12 and with
align:start position:0%
the value of 1 over 12 and with
probability 1/2
align:start position:0%
probability 1/2
align:start position:0%
probability 1/2
this random variable takes a value of 4
align:start position:0%
this random variable takes a value of 4
align:start position:0%
this random variable takes a value of 4
over 12 and this number happens to be 5
align:start position:0%
over 12 and this number happens to be 5
align:start position:0%
over 12 and this number happens to be 5
over 24 finally let us calculate the
align:start position:0%
over 24 finally let us calculate the
align:start position:0%
over 24 finally let us calculate the
variance of the conditional expectation
align:start position:0%
variance of the conditional expectation
align:start position:0%
variance of the conditional expectation
since we have complete information about
align:start position:0%
since we have complete information about
align:start position:0%
since we have complete information about
the distribution of the conditional
align:start position:0%
the distribution of the conditional
align:start position:0%
the distribution of the conditional
expectation calculating its variance is
align:start position:0%
expectation calculating its variance is
align:start position:0%
expectation calculating its variance is
not going to be difficult so what is it
align:start position:0%
not going to be difficult so what is it
align:start position:0%
not going to be difficult so what is it
with probability 1/2 the conditional
align:start position:0%
with probability 1/2 the conditional
align:start position:0%
with probability 1/2 the conditional
expectation takes a value of 1/2 we
align:start position:0%
expectation takes a value of 1/2 we
align:start position:0%
expectation takes a value of 1/2 we
subtract from this the mean of the