text stringlengths 0 205 |
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algebra the answer turns out to be 9 |
over 16 and now we can go back to the |
align:start position:0% |
over 16 and now we can go back to the |
align:start position:0% |
over 16 and now we can go back to the |
law of the total variance and calculate |
align:start position:0% |
law of the total variance and calculate |
align:start position:0% |
law of the total variance and calculate |
that the total variance is equal to the |
align:start position:0% |
that the total variance is equal to the |
align:start position:0% |
that the total variance is equal to the |
expected value of the variance which is |
align:start position:0% |
expected value of the variance which is |
align:start position:0% |
expected value of the variance which is |
5 over 24 and then we have the variance |
align:start position:0% |
5 over 24 and then we have the variance |
align:start position:0% |
5 over 24 and then we have the variance |
of the expected value which is 9 over 16 |
align:start position:0% |
of the expected value which is 9 over 16 |
align:start position:0% |
of the expected value which is 9 over 16 |
and this number evaluates to 37 over 48 |
align:start position:0% |
align:start position:0% |
so we have managed to find the variance |
align:start position:0% |
so we have managed to find the variance |
align:start position:0% |
so we have managed to find the variance |
of this random variable using the divide |
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of this random variable using the divide |
align:start position:0% |
of this random variable using the divide |
and conquer method and the law of the |
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and conquer method and the law of the |
align:start position:0% |
and conquer method and the law of the |
total variance |
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the following content is provided under |
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the following content is provided under |
align:start position:0% |
the following content is provided under |
a Creative Commons license your support |
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a Creative Commons license your support |
align:start position:0% |
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