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A = [2, 1; -3, 1; -1, 1]; B = [-1; -2; 1]; X = A \ B; disp(X); err = abs (A * X - B); disp (err);
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//example8.4 clc disp("Given: I_CO=1.1 uA, I_E=21 uA") disp("I_CEO=(1+(beta_dc))*(I_CO)") disp("1+(beta_dc)=(I_CEO).(I_CO)=(21 uA)/(1.1 uA)=19") b=19-1 disp(b,"Therefore, (beta_dc)=") a=18/19 format(6) disp(a,"(alpha_dc)=(beta_dc)/(1+(beta_dc))=18/(1+18)=")
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// Examle 16.5 V=440; // Supply Voltage Rsh=110; // Resistance of Shunt field Ish=V/Rsh; // Current through Shunt field Ra=0.02; // Resistance of Armature winding Il=496; // Generator current Ia=Il+Ish; // Armeture Current (Ia) di...
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// Exa 2.26 clc; clear; close; // Given data T1 = 400;// in K T2 = 300;// in K N_V = 1.04*10^19;// in cm^-3 N1 = N_V*((T1/T2)^(3/2));// in cm^-3 KT = 0.0259*(T1/T2);// in eV FermiLevel= 0.27;// in eV P_O = N1*exp( (-FermiLevel)/KT );// in cm^-3 disp(P_O,"The thermal equillibrium hole concentration in cm^-3 ...
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//chapter 2 //Gd=antilog(12db/10) printf("\n"); Gd=15.85; Prad=5*10^3; r=3*10^3; E=sqrt(60*Gd*Prad)/r; printf("the electric field is %gV/m",E);
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// This GUI file is generated by guibuilder version 3.0 ////////// clear all clear f=figure('figure_position',[400,50],'figure_size',[700,593],'auto_resize','on','background',[33],'figure_name','Graphic window number %d'); ////////// delmenu(f.figure_id,gettext('File')) delmenu(f.figure_id,gettext('?')) delm...
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x=[0.107533427909220; 0.663644537348001; 0.970587221665023; 0.608390883863076; -0.293540506673764; -1.42787086899790; -2.19233932281606; -1.88376277475872; 0.351621088370924; 4.20456888982602; 7.02440717036035; 6.65058196622351; 2.57013250348360; -3.50487012663216; -8.16852139220758; -8.56013313698647; -4.2042820915121...
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errcatch(-1,"stop");mode(2);//caption:Find output voltage if input is 101101111 //Ex6.3 V=10.3*10^-3//input voltage of DAC convertor(in V) Vo=(V)*(1*2^8+0*2^7+1*2^6+1*2^5+0*2^4+1*2^3+1*2^2+1*2^1+1*2^0) disp(Vo,'output voltage(in V)=') exit();
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Ex2_13.txt
//Caption:Find the percentage reduction in speed //Exa:2.13 clc; clear; close; P1=200*10^3;//initial load in watts P2=125*10^3;//final load in watts V_t=250;//in volts V_b=2;//total brush drop in volts P=6;//no. of poles R_a=0.015;//armature winding resistance in ohms I_g1=P1/V_t;//in amperes I_a1=I_g1;//in...
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timeoffset.tst
## Test the timeoffset command read <min.fi :2 timeoffset +5 write -
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2_11.sce
// Value of s_x based on allowable stresses on glued joint s_t = -750; //psi t = -50; //degree T_t = -500; //psi sg_x_1 = s_t/(cosd(t)^2) sg_x_2 = -T_t/(cosd(t)*sind(t)) // Value of s_x based on allowable stresses on plastic sp_x_1 = -1100; //psi T_t_p =600; //psi t_p = 45; //degree sp_x_2 = -T_t_p/(co...
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12_7.sce
clear clc V=300e3 R=400 k=1.5e-27 E=10 x=1 e=1e-5 while (E>e) f=(k*R*x^6) +x -(2*V) df=(6* k*R*x^5) +1 x1=x-(f/df) E=abs(x1-x) x=x1 end eA=round(x) IA=k*eA^6 mprintf("eA=%d, Ia=%d ",eA, IA)
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Ch015Ex7.sce
// Scilab code Ex15.7 : Pg:773(2011) clc;clear; function [bini]= decimal_binary(ni) // Function to convert decimal to binary bini = 0; i = 1; while (ni <> 0) rem = ni-fix(ni./2).*2; ni = int(ni/2); bini = bini + rem*i; i = i * 10; end endfunction function [deci]...
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//Chapter 11 Example 2// clc clear // capacitance value of pin to earth=c,capacitance of top unit=c1// c=1; c1=5;// let us assume to be// // since voltage across c2 same as c1// c2=c+c1; printf("\n So capacitance across the second unit c2 = %.fC \n",c2); c3=2*c+c2;// since capacitance across c3=c2+2 times cap...
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load MyDMux4Way.hdl, output-file MyDMux4Way.out, output-list in%B3.1.3 sel%B2.2.2 a%B3.1.3 b%B3.1.3 c%B3.1.3 d%B3.1.3; set in 0, set sel %B00, eval, output; set in 0, set sel %B01, eval, output; set in 0, set sel %B10, eval, output; set in 0, set sel %B11, eval, output; set in 1, set sel %B00, eval, output; set in 1, s...
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1_12.sce
clc clear r=15;//Compression ratio of a diesel engine Q=5;//Heat supplied upto 5 percent of the stroke r1=1.4;//Isentropic ratio //Calculations p=1+(Q/100)*(r-1);//Cut off ratio n=(1-((1/r^(r1-1)*(p^r1-1)/(r1*(p-1)))))*100;//Efficiency of diesel cycle in percent //Output printf('Air standard efficiency of ...
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Example2_2.sce
//Chapter-2,Example2_2,pg 2_11 n=8 Res1=2^n Vofs=2.55//full scale output voltage Res2=Vofs/(Res1-1) printf("resolution through method-1\n") printf("Res1=%.2f \n",Res1) printf("resolution through method-2\n") printf("Res2=%.2f \n",Res2)
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Resultat.sce
/* Créateur: Jinshan GUO et Anais Debureaux */ exec(fullpath(pwd() + '\Routine.sci'),-1); //===========Exo1-solsup=========== U = [1 2 3;0 4 8;0 0 5]; b = [6 16 15]; [x]=solsup(U,b); disp("Exo1-x=",x); //Vérification par Scilab //disp("Exo1-x_resultat_scilab",U\b); //===========Exo2-trisup=========== A ...
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7_3.sce
clc //Initialization of variables T1=540 //R T2=960 //R disp("From gas tables,") h2=231.06 //B/lbm h1=129.06 //B/lbm cp=0.24 //calculations W=h2-h1 dh=cp*(T2-T1) //results printf("Change in enthalpy = %.1f B/lbm",dh)
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// Ex 20 Page 361 clc;clear;close; // Given //Ia=0.0004*(Va+40*Vg)**(3/2);// mA --eqn(1) Va=250;//V Vg=-3;//V //mu=delVa/delVg //differentiation wrt Vg eqn(1) //(4*10**-6*3/2*(Va+40*Vg))**(1/2)*(mu+40)=0 mu=-40;//constant printf("Amplification factor, mu = %.f",mu) //differentiation wrt Va eqn(1) //delIa/delVa=(4*10**...
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function [x,L,U] = lu_gauss(A,b) // Método da Eliminação de Gauss Sem Pivotamento [m,n] = size(A); if m~=n, error('Matriz A deve ser quadrada'); end // Inicializa Matriz Triangular Inferior com 1 // na diagonal () L=eye(A); // Construindo a Matriz Aumentada [A b] nb = n+1; Aug = [A]; // Fase 1: Eliminação (na...
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clc; clear; disp("BY following the procedure discussed in Section 8.6"); disp("we find that {a}={0 or 2 or 3,9,15}"); disp("and {b}={7,8.11.13.14}"); disp("Thus the minimal sets of tests for the above network are "); disp("{T}={0 or 2 or 3,7,8,9,11,13,14,15}"); disp("In this case the s-tests and b-tests correspo...
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//Introductory Topics :example 1-2 : (pg no. 9 & 10) P=0.001; R=75; R1=50; x=(8/20); y=(10^x); V2=(y*0.775); V=sqrt(P*R); V1=sqrt(P*R1); //It is a 600 ohm system so 0.775 V reference is used printf("\ndBm(600)= 20log(V2/0.775)"); printf("\nV2 = %.3f V",V2); //voltage reference for 75-ohm system printf("\nV...
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//ANALOG AND DIGITAL COMMUNICATION //BY Dr.SANJAY SHARMA //CHAPTER 11 //Information Theory clear all; clc; printf("EXAMPLE 11.46(PAGENO 532)"); //given P_x1 = .4//probability of first signal P_x2 = .19//probability of second signal P_x3 = .16//probability of third signal P_x4 = .15//probability of fourth s...
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; @Harness: disassembler ; @Result: PASS section .text size=0x00000054 vma=0x00000000 lma=0x00000000 offset=0x00000034 ;2**0 section .data size=0x00000000 vma=0x00000000 lma=0x00000000 offset=0x00000088 ;2**0 start .text: label 0x00000000 ".text": 0x0: 0x0f 0xe7 ldi r16, 0x7F ; 127 0x2: 0x1f...
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//Chapter-3, Example 3.25, Page 95 //============================================================================= clc clear //INPUT DATA Q=300;//Heat produced by the oranges in W/m^2 s=0.08;//Size of the orange in m k=0.15;//Thermal conductivity of the sphere in W/m.K //CALCULATIONS q=(3*Q)/(s/2);//Heat f...
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//find... clc //solution //given D=300//mm R=0.150//mm Cs=0.003 N=1800//rpm w=188.5//rad/s rho=7250//kg/m^3 //let m eb the mass of fly wheel //ref fig 22.6 //total energy at E =total energy at A //Eb=E+295 //Ec=E+295-685=E-390 //Ed=E-350 //Ee=E-690 //Ef=E+270 //Eg=E //Ea=E //max energy is at B and m...
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clc // initialization of variables clear SF=1.75 p1=300 //MPa S_rr=-SF*p1 S_th=SF*325 Y=1/sqrt(2)*sqrt((S_th-S_rr)^2+S_rr^2+S_th^2) printf(' Y = %.1f MPa',Y)
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function [listOutput, iLevelIndicies] = LvlMultiOffsetToBoundary(listInput, listMultiPassOffsetRegimes, listMultiPassOffsetComponents, plBoundary, iStartLevel, bIsSliceFirst) listInputBuffer = listInput; listOutput = list(); iLevelIndicies = []; bPointsRemaining = %T; iLevel = iStartLevel; ...
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//exapple 8.6 clc; funcprot(0); // Initialization of Variable mu=0.224; rho=1328; K=5; b=3*.5;//radius h=2.5; pi=3.1428; x=2.1*.5; rhos=1581;//density of sucrose e=0.435;//void ratio J=0.097;//mass fraction m=3500;//mass flowing a=85/10^6;//side length L=48/1000;//thickness omega=2*pi*325/60; //ca...
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** File Info Version Id = 65536 Num Writers = 0 Total Entries = 14 Transaction Id = 24 Index Free List = 13 Total Size of Data = 612 Data Transformation Id = 24 Index Transformation Id = 65 ** Entry Info for: all num: 0000000000000000 ver: 00000000 txi: 0000000000000017 txo: 00000000 ...
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//Chapter 18 //Example 18_11 //Page 437 clear;clc; a=1*(cosd(120)+%i*sind(120)); Ir=20*(cosd(0)+%i*sind(0)); Iy=20*(cosd(180)+%i*sind(180)); Ib=0; Ir0=1/3*(Ir+Iy+Ib); Ir1=1/3*(Ir+a*Iy+a^2*Ib); Ir2=1/3*(Ir+a^2*Iy+a*Ib); Iy0=Ir0; Iy1=a^2*Ir1; Iy2=a*Ir2; Ib0=Ir0; Ib1=a*Ir1; Ib2=a^2*Ir2; printf("Ir = %.2f /_%.2f A \...
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errcatch(-1,"stop");mode(2);//Caption: Probability //Example 2.3 //page no 43 //find the probability ; ; total_cards=52; ways_of_drawingtwocards=52*51/(2*1);//ways of drawing 2cards from a deck of 52cards diamonds=13; Hearts=13; waysof_diamonds_Hearts=diamonds*Hearts;//ways of drawing a Diamond and a Heart ...
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function[a1]=bubble(a,n) i=1; j=1; temp=0; for i=1:n-1 for j=1:n-i if(a(j)>a(j+1)) temp=a(j); a(j)=a(j+1); a(j+1)=temp; end j=j+1; end i=i+1; end a1=a; disp(a1,"Sorted array is:"); endfunction //Calling Routine: a=[23 21 232 121 2324 ...
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// 08.09.16 // 08.10.11 // 08.10.15 // 10.02.16 Eps // 13.10.22 ( __ added to varibles ) function OutL__=Crvonsfparadata(varargin) global PARTITIONPT HIDDENDATA CRVONSFHIDDENDATA Nargs__=length(varargin); Eps__0=10^(-4); Figuv__=varargin(1); Fbdy__=Projpara(varargin(2)); Fd__=varargin(3); N__=4; Fd__L=F...
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load CS16B032RAM16K.hdl, output-file CS16B032RAM16K.out, compare-to CS16B032RAM16K.cmp, output-list time%S1.4.1 in%D1.6.1 load%B2.1.2 address%D2.5.2 out%D1.6.1; set in 11877, set load 0, set address 13353, tick, output; tock, output; set in 18498, set load 1, set address 6843, tick, output; tock, output; set in 1126...
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//pagenumber 405 example 7 clear rg=40*10^3;//ohm voltag=(1-6*50)*3.3*10^3/(5.3*10^3); disp("output voltage = "+string((voltag))+"volt");//correction in the book
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clc; pathname=get_absolute_file_path('5_6_soln.sce') filename=pathname+filesep()+'5_6_data.sci' exec(filename) // Solutions: // Theoretical flow rate, Qt=Qa/(eta_v/100); //gpm // Area of piston, A=(%pi/4)*(d^2); //in^2 // tan of offset angle, T_theta=(231*Qt)/(D*A*N*Y); // offset angle, theta=atand(T_theta); //deg /...
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s=%s; G=1/(1+2*s); sys=syslin("c",G); clf();bode(sys,1e-2,1e1,0.01)
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clc; clear; printf("\t\t\tChapter2_example8\n\n\n"); // determination of temperature profile, heat transferred, efficiency, effectiveness. printf("\n\t\t\tSolution to part (a)"); k=24.8; // thermal conductivity of 1C steel in BTU/(hr.ft.degree Rankine)from appendix table B2 D=(5/16)/12; // diameter of the rod in ft P=(...
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//Function migration (image list to matrix) for: getgaussiankernel //Generated by migrate.cpp //Author: Anirudh Katoch function res = getgaussiankernel(varargin) select length(varargin) case 03 then res = raw_getgaussiankernel(varargin(01), varargin(02), varargin(03)) else error(39) end endfunction
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clear all; clc; disp("Assume uniform axial flow at the inlet") disp("(a) At the hub") disp("V_a=15.5m/s") omega=157 D_h=0.37 U_h=0.5*omega*D_h printf(" Uh= %0.2f m/s",U_h) disp("Vu2=(Vmu2*Dm)/Dh") V_mu2=15 D_m=0.585 V_u2=(V_mu2*D_m)/D_h printf(" Hence Vu2= %0.1f m/s",V_u2) V_a=15.5 disp("tan(ß1)=(...
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//// //Variable Declaration beta = 2.04e-4 //Thermal exapansion coefficient, /K kapa = 45.9e-6 //Isothermal compressibility, /bar T = 298.15 //Std. Temperature, K R = 8.206e-2 //Ideal gas constant, atm.L/(mol.K) T1 = 320.0 //Temperature, K Pi = 1.0 ...
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//Ex.3.1 clc; clear; close; x1=[1 2 3 4]; //assume x2=[1 2 1 2]; //assume a=1; b=1; y=[2 2 2 2]; //y(n)=2 for all x //Test for homogeneity k=2; hom=0; for n=1: length (x1) if (k*y(n)==k*x1(n)) hom=hom+1; end end //Test for additivity for n =1: length (x1) ...
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// ***************************************** // * Universidad Católica del Uruguay // * Cálculo Numérico 2016 // * Laboratorio 4 // * Eduardo Senturión - Federico González // ***************************************** // Esta función se utiliza para saber quienes son los participantes del grupo function Grupo=AlumnosDe...
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// Example 32_34 clc;funcprot(0); //Given data L_cap=1500;// kW // n=0.43*(L)^0.48;(given) T=[0 4 8 12 16 20 24];// Time in hours L_a=[200 600 1000 400 200 100];// Load in kW L_b=[800 400 200 200 600 400];// Load in kW L_t=[1000 1000 1200 600 800 500];// Load in kW CV=45*10^3;// MJ/kg Dc=30;// The cost of die...
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//Example 4.15. clc format(6) disp("For a Wien bridge oscillator,") disp(" f = 1 / 2*pi*R*C") fm=(1/(2*%pi*(100*10^3)*(50*10^-12)))*10^-3 // in kHz disp(fm,"Therefore, f_max(in kHz) =") fmi=(1/(2*%pi*(100*10^3)*(500*10^-12)))*10^-3 disp(fmi,"and f_min(in kHz) =") fn=31.83+50 disp(fn,"Now f_new(in kHz) = ...
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clear; clc; V_s=230; n=6;//on cycles m=4;//off cycles k=n/(n+m); V_or=V_s*sqrt(k); printf("rms value of o/ voltage=%.3f V",V_or); pf=sqrt(k); printf("\ni/p pf=%.4f",pf); R=15; I_m=V_s*sqrt(2)/R; I_TA=k*I_m/%pi; printf("\navg thyristor current=%.4f A",I_TA); I_TR=I_m*sqrt(k)/2; printf("\nrms value...
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load ParityGenCheck.hdl; output-file ParityGenCheck.out; output-list x7 x6 x5 x4 x3 x2 x1 x0 pIn pOut z; set x7 0,set x6 0,set x5 0,set x4 1,set x3 0,set x2 0,set x1 0,set x0 0,set pIn 0,eval,output; set x7 0,set x6 0,set x5 0,set x4 0,set x3 0,set x2 0,set x1 0,set x0 0,set pIn 1,eval,output; set x7 0,set x6 0,set x5 ...
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//Example5.14:"Output noise voltage"" //Page 167 //figure 5.29 clear; clc; Rf=99000; // in Ohm Ri=1000; //in ohm Rs=100; //in ohm Av=1+Rf/Ri; disp(Av,"Av ordinary value"); disp(20*log10(Av),"Av dB value"); Anoise=Av; //for non inverting amplifier Rnoise=Rs+Rf*Ri/(Rf+Ri); disp("...
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//Solved Example 5: //Convering an infix expression to a Postfix Expression: function[sta]=push(stac,ele) sta=0; if(stac.top==0) stac.a=ele; stac.top=stac.top+1; else stac.a=[stac.a(:,:) ele] stac.top=stac.top+1; end disp(stac); sta=stac; endfunction function[ele,sta]=pop(sta...
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//Chapter 17, Example 17.3 clc //Initialisation VDD=15 //voltage Vq=10 //quiescent output voltage VGS=3 //voltage RD=2.5*10**3 //resistance in Ohm //Calculation VR=VDD-Vq //voltage ID=VR/RD ...
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// ==================================================================== // Allan CORNET // Simon LIPP // INRIA 2008 // This file is released into the public domain // ==================================================================== sci_gateway_dir = get_absolute_file_path('builder_gateway.sce'); tbx_builder_gatewa...
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__gamma__ = 0.1; __m__ = 1.0; __a__ = 0.25; __b__ = 0.50; __omega__ =2.4; __F0__ = 2.0; t0 = 0.0; t = linspace(t0,100.0,1000); x0 = [0.5;0.0]; function z=DuffingOscillator(t,x) z(1) = x(2); z(2) = (-__gamma__*x(2) + 2*__a__*x(1) - 4*__b__*x(1)*x(1)*x(1) + __F0__*cos(__omega__*t))/__m__; endfunction y = ode("s...
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clear;lines(0); sl=syslin('c',[1 0;0 2],[1;0],[2 1]); ssprint(sl); ssprint(minss(sl))
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//Exa 3.3 clc; clear; close; format('v',6); //Given Data : Q2=100;//KJ/sec or KW T2=-20+273;//K T1=35+273;//K COP=T2/(T1-T2); disp(COP,"COP is : "); W=Q2/COP;//KW disp(W,"Power input in KJ/s or KW : "); COPheatpump=T1/(T1-T2);// disp(COPheatpump,"COP as heat pump : "); Eta_engine=(1-T2/T1)*100; disp(...
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//ques9 //determining exit plane properties in control volume clear clc //x-inlet //y-exit Mx=1.5;//mach number for inlet My=0.7011;//mach number for exit Px=272.4;//inlet pressure in kPa Tx=248.3;//inlet temperature in K Pox=1000;//stagnation pressure for inlet Py=2.4583*Px;//Exit Pressure in kPa Ty=1.320*...
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clc disp("Example 8.10") printf("\n") printf("Given") disp("vs= 5V t<0") disp("vs=5*sin(w*t) t>0") vs=5; R=5;L=10*10^-3; //At t<0 //Inductor behaves as a short circuit //Let i(0-)=i i=vs/R; printf("i(0-)=%dA\n",i) //During the transition from t=0- to t=0+ //Let i(0+)=i1 i1=i printf("i(0+)=%dA...
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res_log=read('../data/gps_kf_pv_log.m',-1,24); [r_n,c_n]=size(res_log); idx=[1:r_n]; // First plot KF state //xset('color',3); //xset('background', 1); xbasc(); xset('window',0); // plot pos_x result subplot(811); plot2d(res_log(:,1)); xtitle("ECEF_x",'100ms','m'); xset('background', 4); // plot pos_y result subplot...
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//Example 7.10 clc disp("the given values are I_0 = 3 uA, T = 27 C = 27+273 = 300 K, eta =1") disp("Now I_rated = 1 A for diode") disp("and I = 1% of I_rated at 27 C") disp("Therefore, I = 0.01 A") vt=300*8.62*10^-5 format(6) disp(vt,"V_T(in V) = k*T =") disp("According to diode equation, I = I_0 * (e^(V/e...
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//**************************** Hysteretic Differentiator ****************************** if (blk_name.entries(bl) =='hystdiff') then mputl("# histdiff",fd_w); for ss = 1:scs_m.objs(bl).model.ipar(1) mputl(".subckt hyst_diff in[0]=net"+string(blk(blk_objs(bl),2))+ "_" + string(ss)+" out[0]=net"+ string(...
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l=2.7+1//span, in m R=0.15//rise, in m t=0.27//tread, in m fck=15//in MPa fy=415//in MPa D=200//assume, in mm W1=D/10^3*25*sqrt(R^2+t^2)/t//slab load on plan, in kN/m W2=1/2*R*t*25/t//load of step per metre, in kN/m W3=3//live load, in kN/m W=W1+W2+W3//in kN/m Wu=1.5*W//in kN/m Mu=Wu*l^2/8//in kN-m d=sqrt(M...
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clc; //page no 8-65 //Example 8.26 fmax=1600;//in kHz fmin=550;//in kHz IF=455;//in kHz Csmax=350;//in pF //Let Csmax/Csmin=C C=(fmax/fmin)^2; disp(C,'Csmax/Csmin='); fomin=fmin+IF; fomax=fmax+IF; disp(+'kHz',fomin,'fomin='); disp(+'kHz',fomax,'fomax='); //Let Comax/Comin be denoted by C1 C1=(fomax/fomin...
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clear // // // //Variable declaration d=2.82*10^-10; //lattice spacing(m) sintheta=1; n=1; //Calculation lamda_max=2*d*sintheta/n; //longest wavelength(m) //Result printf("\n longest wavelength is %0.3f angstrom",lamda_max*10^10)
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ก ร อ ด โ น g r o d n o ก ร า เ ซ ี ย ส g r a c i a s ก ร ิ ด g r i d ก ร ิ ม ม ิ ต g r i m m e t t ก ร ี ด g r e d e ก ร ี น ส แ ป น , แ อ ล ั น g r e e n s p a n , a l a n ก ร ี น ฮ ิ ล g r e e n h i l l ก ร ี น ิ ช เ ม ร ิ เ ด ี ย น g r e e n w i c h m e r i d i a n ก ร ู เ ว อ ร ์ g r o o v e r ก ร ู เ อ อ ร ...
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x = -10:10; ReLU = max(0,x) figure(1) plot(x,ReLU)
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exec('Prix_en_zero.sci'); function [Y] = Prix_en_zero_Amer(N,K,r,a,b,x) p_etoile = (b - r) / (b - a) // proba d'aller en 1+a p1 = p_etoile / (1 + r);// proba "actualisee" de choisir 1+a p2 = (1 - p_etoile) / (1 + r);// proba "actualisee" de choisir 1+b Y = Prix_Amer(0,N,K,p1,p2,a,b,x); endfunction ...
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clc //Chapter 8:Linear model of phase locked loop //example 8.1 page no 314 //given fo=1*10^6//output frequency fr=25*10^3//reference frequency N=fo/fr Kd=2//phase detector gain factor Ko=100//VCO gain factor thetao=(2*100*2*%pi)//output phase s=poly(0,"s") thetar=s+(2*100*2*%pi)/N//input phase Tf=thetao/th...
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// Example 13_11 clc;funcprot(0); // Given data T_1=800;// R T_4=530;// R T_3=T_4;// R p_4=14.7;// psia p_3=p_4;// psia p_2s=p_3;// psia m=1.00*10^-3;// lbm of air R=53.34;// ft.lbf/lbm.R k=1.4;// The specific heat ratio // Calculation // (a) V_4=(m*R*T_4)/(p_4*144);// ft^3 V_1=V_4;// ft^3 p_1=(m*R*T_...
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clc clear //Initialization of variables g=32.2 //ft/s^2 Pb=29.5 //in of Hg Pv=10 //in of Hg //calculations AP=(Pb-Pv)*0.491 //results printf("Absoulte pressure = %.2f psia",AP)
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// Calculate ac voltage,rectification efficiency // Basic Electronics // By Debashis De // First Edition, 2010 // Dorling Kindersley Pvt. Ltd. India // Example 3-14 in page 160 clear; clc; close; // Given data Vdc=100; // DC voltage in V Rl=500; // Load resistance in ohms Rf=20; // Internal resistance in ...
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clc; printf("Example 3.3\n"); Dia_tank=5; //Diameter of the tank len_pipe=100; //Length of pipe dia_pipe=225e-3; //Diameter of pipe printf("\n Given:\n Diameter of the tank = %d m\n Length of pipe = %d m\n Diameter of pipe = %.2f m",Dia_tank,len_pipe,dia_pipe); //If at time t the liquid level is D m above the...
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clc; //Example 24.2 //Page No 988 disp("Given: d1=18.6Km, d=14.4Km, Hn=H1=200meters, n=1"); //solution d1=18.6; d=14.4; H1=0.2; n=1; c=3*10^8; disp("From equation 24-10, the height of the nth fresnel zone Hn is, "); l=(((H1^2)*d)/(n*d1*(d1-d))); l=l*10^3; disp('m',l,"l = ") f=(c/l); f...
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//CHAPTER 7- SINGLE PHASE TRANSFORMER //Example 31 clc; disp("CHAPTER 7"); disp("EXAMPLE 31"); //single phase transformer having 400 primary and 1000 secondary turns //VARIABLE INITIALIZATION N1=400; N2=1000; coreA=60; //net core area in cm^2 v1=500; //...
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//clc() A = 13.8587; B = 2911.32; C = 56.56; T1 = 325;//K //Pressure at normal condition = 101.3kPa P2 = 101.3;//kPa //Antoine equation - lnP = A - B / (T - C) lnP = A - (B / (T1 - C)); P1 = exp(lnP); disp("kPa",P1,"(a)Vapour pressure of n-heptane at 325K = ") T2 = B/(A - log(P2)) + C; disp("K",T2,"(b)Normal boiling po...
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//Initilization of variables m_A=40 //kg m_B=15 //kg F=500 //N g=9.8 //m/s^2 theta=30 //degrees //Calculations m=m_A+m_B //kg a=(F-m*g*sind(theta))/(m) //m/s^2 //Summing forces parallel and perpendicular to the plane //Simplfying equation (1) and (2) Nb=m_B*g+(m_B*a*sind(theta)) //N //Substituting this in e...
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function []=manedit(manitem,editor) // manitem : character string giving a manitem // // Copyright INRIA [lhs,rhs]=argn(0) if rhs<=1, editor ="emacs -geometry 81x50+427+143 -fn 9x15 ";end fname='fname=`ls $SCI/man/*/'+manitem+'.man 2>/dev/null `;'; unixstr=fname+"if [ $fname ] ; then "+editor+" $fname;else echo No m...
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clc; clear; close; x = [1 2 3 4 5 6 7 8 9 10 11] y = [1.7 2.5 3.8 4.4 4.9 5.2 5.5 5.6 5.8 5.9 6] n = size(cos(x),'c') sumX = sum(cos(x),'c') sumX2 = sum(cos(x)^2,'c') sumY = sum(y,'c') sumYX = sum(y.*cos(x),'c') A = [n sumX; sumX sumX2] B = [sumY; sumYX] C = A\B printf("\n| n sumX | | a0 | | sunY |") prin...
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errcatch(-1,"stop");mode(2);//page 156 ; ; a=[1;1;1]; disp(a,'a='); P=(a*a')/(a'*a); disp(P,'Matrix that projects onto a line through a=(1,1,1) is'); //end exit();
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clc clear Ma=5400; //in kg/hr Tfw=42; //in C P=7.6; //in bar Mf=670; //in kg/hr x=0.98; //Dryness Fraction CV=31000; //kJ/kg Ms=Ma/Mf; Hf=175.81; //in kJ/kg Hfw=Hf; //Now at 7.6 bar pressure Hf=711...
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//chapter 15 //example 15.5 //page 652 printf("\n") printf("given") Acl=100;Av=10; disp(" for Cf=30pF") GBW=800*10^3; F2=GBW/Acl disp(" for Cf=3pF") GBW=(800*10^3)*Av; f2=GBW/Acl
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//Problem 15.18: A coil having a resistance of 10 ohms and an inductanc of 125 mH is connected in series with a 60 μF capacitor across a 120 V supply. At what frequency does resonance occur? Find the current flowing at the resonant frequency. //initializing the variables: R = 10; // in ohms C = 60E-6; // in Farad...
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// Exa 2.29 clc; clear; close; format('v',7) // Given data R1 = 10;// in ohm R2 = 20;// in ohm R3 = 60;// in ohm R4 = 30;// in ohm E1 = 120;// in V E2 = 60;// in V R_T = ((R2*R3)/(R2+R3)) + R4+R1;// in ohm I_T = E1/R_T;// in A I1 = (R3/(R2+R3))*I_T;// in A R_T = ( ((R1+R4)*R2)/((R1+R4)+R2) ) + R3;// in o...
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//clear// //Example10.12:Inverse z tranform:For Finite duration discrete sequence syms z; X = [4*z^2 0 2 3*z^-1]; n = -2:1; for i = 1:length(X) x(i) = X(i)*(z^n(i)); end disp(x,'x[n]=')
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#************************************************************ # Scenario of humanTestEnv # # date : Wed Mar 13 13:43:36 2013 #************************************************************ p3d_sel_desc_name P3D_ENV humanTestEnv p3d_sel_desc_name P3D_ROBOT PR2_ROBOT p3d_set_robot_steering_method Linear p3d_set_robot...
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//Example 4.1.1 Page 94 //Non-Linear Dynamics and Chaos, First Indian Edition Print 2007 //Steven H. Strogatz clear; clc; close; set(gca(),"auto_clear","off") //hold on //Representing theta by O --> not zero it is alphabet "O" //Given :- O(dot) = f(O) = sinO. O1 = 0; //first Fix Point. O2 = %p...
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clc; eta=0.8; F1_2=5.67*10^-8; T1=533;//K T2=293;//K alpha=eta*F1_2*(T1^2+T2^2)*(T1+T2); A=%pi*0.6*0.9; Q1=alpha*A*(T1-T2); alpha=8.8; A=5; Q2=alpha*A*(T1-T2); Q=Q1+Q2; disp("total heat loss is:"); disp("kW",Q/1000)
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clc; clear; A=1*(10^(-4));//m^2 p1=80;//kPa(abs) p2=40;//kPa(abs) p0=101;//kPa(abs) pcritical=0.528*p0;//kPa(abs) k=1.4; //for (a) pth=p1>pcritical Math1=((((p0/p1)^((k-1)/k))-1)/((k-1)/2))^0.5;//Math=Mach number at throat //dth/d0=p1/p0; dth=density at throat dth1=(1.23)*(1/(1+(((k-1)/2)*(Math1^2))))^(1/(k-...
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//Determine the current in parallel branches and supply current clc; clear; Xl=%i*100; // Inductance R=10; // Resistance V=10; Xco=-%i*100; Q=abs(Xl)/R; Z0=Q*abs(Xco); I0=V/Z0; Ic=V/Xco; Il=V/Xl; Pi=V*I0; // Power Input Pc=(I0^2)*10; // Copper Loss // Frequency reduced to fo/2 Xl1=Xl/2;...
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clear; clc; L=60*(10^-3);C=0.2*(10^-6); fc=1/(%pi*(sqrt(L*C))); printf("(i)Cut off frequency fc for the low pass filter = %f kHz\n\n",round(fc*(10^-1))/100); fa=1000; Za=(sqrt(L/C))*(sqrt(1-((fa/fc)^2))); printf(" (ii)Iterative impedance at f=1 KHz = %f ohms\n",fix(Za)); fb=5000; Zb=(sqrt(L/C))*(sqrt(1-((fb/fc...
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//Example 7.3 //Find the laplace transform and Roc of the following signal clc; close; syms t; a=3;b1=-8; x1=exp(-a*t); b=6;c=7; s=b+c*%i; X1=integrate((exp(-(a+s)*t)),'t',0,%inf); x2=exp(-2*t); X2=integrate((exp(-(b1+s)*t)),'t',-%inf,0); disp(X1); disp(X2); X=X1+X2;disp(X); disp(real(s)); disp('Since...
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//To find dimensions of contact surfaces clc //Given: alpha=30/2 //degrees pn=0.35 //N/mm^2 P=22.5*1000 //W N=2000 //rpm mu=0.15 //Solution: //Calculating the angular speed of the clutch omega=2*%pi*N/60 //rad/s //Calculating the torque transmitted by the clutch T=P/omega*1000 //N-mm //Calculating the mean...
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clc; clear all; close; x1=[1,3,7,-2,5]; h=[2,-1,0,3]; y=convol(x1,h); disp(y,"is the required convolution"); l=length(y); t=0:l-1; plot2d3(t,y); xlabel("n"); ylabel("Amplitude"); title("y(n)=x(n)*h(n)"); figure;
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//Example 3.11(b) clear; clc; m=1;//Q is maximised at m=1 n=2;//Order of filter f0=10*10^(3); Qnum=(m*n)^(1/2); Qden=m+1; Q=Qnum/Qden; C=1*10^(-9);//Assuming C=1 nF C2=C; C1=n*C; R=1/(Qnum*C*2*%pi*f0); R2=R; R1=m*R; w=4*%pi*10^4; f=2*10^4; Hw=1/(1-(w^(2)*R1*R2*C1*C2)+%...
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//Ch25_Ex16 clc; clear; close; vol=2.2/1000; //converting into cubic meter d=0.5/100; //diameter in meter r=d/2; //radius h=vol/(%pi*r^2); mprintf("The length of wire is %.0f meter",h);
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clc // Fundamental of Electric Circuit // Charles K. Alexander and Matthew N.O Sadiku // Mc Graw Hill of New York // 5th Edition // Part 1 : AC Circuits // Chapter 3: Magnetically Couple Circuits // Example 13 - 2 clear; clc; close; // // Given data Z11 = complex(4.0000,3.0000); Z12 = comple...
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Ex2_1.sce
//Chapter 2,Example 2.1 Page 78 clc clear //(i) Determine volatge regulation C = 0.06 // micro farad I = 1 //mA f = 150 //Hz n = 10 V = (1/(f*C))*((2*n^3/3)+(n^2/2)) perc = (V*100)/(2*10*100) printf (" (ia) Volatge regulation = %f kV \n ",V) printf (" (ib) percentage volatge regulation = %f \n ",perc) //(ii) Ripple ...