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//i/p arg b has complex elements x=[1 2 3 4 5 6 6]; b=[0.1 2 3 4 5+0.12*%i]; y=fftfilt(b,x); disp(y); // column 1 to 2 // // 0.1 + 1.443D-15i 2.2 - 4.163D-17i // // column 3 to 4 // // 7.3 - 3.331D-16i 16.4 + 9.992D-16i // // column 5 to 7 // // 30.5 - 0.12i 44.6 - 0.24i 5...
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//Chapter 13: Fuel and Combustions //Problem: 7 clc; // Solution wt_O = 2 * 32 / 12.0 wt_a = wt_O * 100 / 23.2 vol_a = wt_a / 28.94 * 22.4 mprintf("Volume of air needed for the complete combustion of 2kg coke is %.3f litres at NTP",vol_a)
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clc(); clear; //Given : lambda = 5890; //Wavelength in A //(a)Calcite crystal mu1_o = 1.658;//refractive index for ordinary ray mu1_e = 1.486;//refractive index for extraordinary ray t1 = 0.0052 ; //thickness in mm // 1 A = 1.0*10^-7 mm alpha1 = ((2*%pi*(mu1_o-mu1_e)*t1)/(lambda*10^-7)); // phase difference in...
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// Scilab Code Ex9.2 Page:278 (2006) clc; clear; H0 = 1970; // Critical field at absolute zero, Oe T_c = 9.25; // Transition temperature of specimen Nb, Kelvin T = 4; // Temperature at which destruction of superconductivity is to be found, Kelvin H_c = H0*[1-(T/T_c)^2]; // Limiting magnetic field, Oe ...
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// page no 414 // example no 14.1 // INITIALIZE HYPOTHETICAL CHIP AS OUTPUT BUFFER clc; printf('MVI A,01H \n'); // Set D0=1, D1 through D7 are don't care lines. a=hex2dec(['1']); b=dec2bin(a,8); printf('A--> ') disp(b); printf('\n \n OUT FFH \n \n'); // write in the control register. printf('MVI A,BYTE1 \...
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//exapple 5.8 clc; funcprot(0); // Initialization of Variable pi=3.14; theta=pi/3; h=1/tan(theta); B=0.845; E=0.375; g=9.81; //calculation //part1 //deducing a polynomial(quadratic) in Dc a=5*h; b=3*B-4*h*E; c=-2*E*B; y=poly([c b a],'x','coeff'); x=roots(y); disp(x(2),"critical depth in (m):"); ...
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clc; //ex3.12 d=0.001; q=1.6*10**-19; ND=10**20; R=1000; mun=0.1; n=ND;//number of free electrons sigma=q*n*mun;//conductivity disp('S/m',sigma*1,"sigma="); a=(1/sigma)*(1/(%pi*(0.001^2)/4)); l=R/a; disp('mm',l*10**3,"l=");
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//Chapter-10, Example 10.21, Page 434 //============================================================================= clc clear //INPUT DATA T1=127+273;//Temperature of the outer side of the brick setting in K T2=50+273;//Temperature of the inside of the steel plate in K e1=0.6;//Emissivity of steel e2=0.8;//...
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clc //Initialization of variables Ws = 1.3 //lb Fv = 22 //lb yW = 64.0 // lb/ft^3 yF = 2.0 // lb/ft^3 // Calculations Vr = (Ws + Fv)/(yW-yF) //results printf(" the minimum volume of foam is %.3f ft^3",Vr)
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run2"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monitor...
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scenario = "EEGetMouvementSimple"; response_matching = simple_matching; default_background_color = 255,255,255; active_buttons =14; button_codes = 1,2,3,4,5,6,7,8,9,10,11,12,13,14; #pulse_out = false; pulse_value = 5; pulse_width = 20; # if using parallel port #-----------------Définition des variables---...
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//Arithmetic Mean Filter // Dikshita Kambri 118A2044 clc; clear all; im = imread("C:\Users\hp\Documents\Image Processing-Scilab\Images\coins.png"); imng=imnoise(im,'gaussian',0,0.01); imng-double(imng); [r c]=size(imng); //zero pad the image imgpad=zeros (r+2,c+2); out=zeros(r,c); outp=zeros(r+2,c+2); rp=r+2; cp=c+2; ...
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//Section-14,Example-1,Page no.-PC.61 //To find absolute viscosity of liquid. clc; d_s=8*10^3 //kg/m^3 d_l=2*10^3 //kg/m^3 r=10^-3 //m l=0.1 //m t=20 //s g=9.8 //m/s^2 n_l=(2*g*r^2*...
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//CHAPTER 12 ILLUSRTATION 1 PAGE NO 310 //TITLE:Balancing of reciprocating of masses clc clear pi=3.141 N=250// speed of the reciprocating engine in rpm s=18// length of stroke in mm mR=120// mass of reciprocating parts in kg m=70// mass of revolving parts in...
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// Exa 4.26 clc; clear; close; // Given data V_CC = 10;// in V V_BE = 0.7;// in V R_B = 250;// in kohm R_B= R_B*10^3;// in ohm bita = 90; R_C = 4.7;// in kohm R_C= R_C*10^3;// in ohm R_E = 1.2;// in kohm R_E= R_E*10^3;// in ohm I_BQ = (V_CC - V_BE)/(R_B + bita*(R_C+R_E));// in A disp(I_BQ*10^6,"The base ...
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// Chapter 10 example 3 //------------------------------------------------------------------------------ clc; clear; Vr = 150 c = 3*10^8 df1= 10^6; // Given data // fd = (2*Vr)/lamda = (2*Vr*f)/c // for 'Vr' and 'c' as constant(for a given radial velocity,Vr is constant) // fd = K.f where 'f' is the ope...
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//Exa 10.1 clc; clear; close; //Given data : L=200;//m w=0.7;//kg T=1400;//kg S=w*L^2/(8*T);//,m disp(S,"maximum sag(m) :");
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clc;clear;close; function [A]=SubSpaces(A,b) A = [A b] disp(A,'A='); [m,n] = size(A); [v,pivot]=rref(A); disp(v); r = length(pivot); disp(r,'rank=') cs = A(:,pivot); disp(cs,'Column Space='); ns = kernel(A); disp(ns,'Null Space='); rs=v(1:r,:)'; ...
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// Additional solved examples , Example 18 , pg 339 r=1.575 *10^-10 //radius of atom (in m) a=2*r//lattice constant (for HCP structure) (in m) c=a*sqrt(8/3) //(in m) V=(3*sqrt(3)*a^2*c)/2 //volume of unit cell printf("volume of unit cell(in m^3)\n") disp(V)
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function [h2]=cheb2mag(n,omegar,A,sample) //<h2>=cheb2mag(n,omegar,A,sample) //Square magnitude response of a type 1 Chebyshev filter //omegar = stopband edge //sample = vector of frequencies where the square magnitude //h2 is desired. // n :Filter order // omegar :Cut-off frequency // A :Attenuation in...
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errcatch(-1,"stop");mode(2);//Chapter 7, Problem 8 ; A=10*10^-4; //cross-sectional area l=0.2; //mean circumference in meter phi=0.3*10^-3; //flux B=phi/A; //flux density H=1000; mmf=H*l; //magnetomotive force ...
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Chapter12_example3.sce
clc clear //Input data R=[4,12,2,12]//Resistances from circuit diagram 12.12 on page no. 177 in ohms V=12//Voltage in V from circuit diagram 12.12 on page no. 177 //Calculations Rth=((R(1)+R(3))*R(2))/(R(1)+R(3)+R(2))//Equivalent resistance in ohms Vth=(V*R(2))/(R(1)+R(3)+R(2))//Equivalent voltage in V I=(Vth...
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[fd,err] = mopen("fer2d","r") fer2d = read("fer2d",10100,101) mclose(fd) x=[1:1:101] y=[1:1:101] for t=0:99 drawlater(); clf() surf(fer2d(x+(t*101),y)) drawnow(); end
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clc; //Example 18.8 //page no 233 printf("\n Example 18.8 page no 233\n\n"); //refer to example no 18.7 rho=1000//density g=9.807//gravitational acc. h_f=38.39//head loss P_rise=rho*g*h_f//pressure rise across the pump P_rise=475000//in book by mistake this value instead original value q=0.0126//flow rate fr...
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clc // initialization of variables clear D=5 //cm d=2 //cm t_y=3000 //kg/cm^2 // calculations R=D/2 r=d/2 Tep=2*%pi*R^3*t_y/3-%pi*r^3*t_y/6 t_er=2*Tep/(%pi*R^3) t_er1=t_er*r/R prs=t_y-t_er1 nrs=t_er-t_y // results printf('Maximum +ve residual stress occurs at %d cm radius and is equal to \n %d kg/cm^2'...
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//Example 15.2 clc k_e=8.99*10^9 //N.m^2/c^2 q2=2*10^-9// in c q3=5*10^-9// in c r1=4//in m F_23=(q2*q3*k_e)/(r1*r1) disp(F_23,"The force in N= ") q1=6*10^-9 r2=5//in m F_13=(q1*q3*k_e)/(r2*r2) disp(F_13,"The force in N= ")
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n = int(input("Enter n : ")); p = int(input("Enter p : ")); m = int(input("Enter m :")); A = zeros(n,p); B = zeros(p,m); disp("Enter elements of A :\n") for i=1:n for j=1:p A(i,j) = int(input("enter element "+string(i)+","+string(j)+" : ")); end end disp("Enter elements of B :\n") for i=1:p ...
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9_2.sci
//Chapter 9 Example 2// clc clear //let all the cpnductors are equally placed,so ds1=ds2=....=ds// // self GMD of strand1=ds1 and assuming r=1,d=1// k1=0.7788;//d11=d22=d33=d44=d55=d66=d77=k1// ds1=(k1*1*sqrt(2)*1)^(1/4); printf("\n Equivalent radius or self-GMD of conductors = %.3f r^1/4 d^3/4\n",ds1);
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MUX.tst
load MUX.hdl, output-file MUX.out, output-list a b s out; set a 0, set b 0, set s 0, eval, output; set a 0, set b 1, set s 0, eval, output; set a 1, set b 0, set s 0, eval, output; set a 1, set b 1, set s 0, eval, output; set a 0, set b 0, set s 1, eval, output; set a 0, set b 1, set s 1, eval, output; set a 1, set b ...
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xicara_ciclo.sce
// JOSÉ CLEITON function xicara_ciclo() k = -0.4 // k que depende de quanto café há na xícara ta = 24 // temperatura ambiente 24º dt = 0.1 // 10 medidas por segundo T(1) = 90 // Café inicia em 90º t(1) = 0 // tempo inicia em 0 clf() // limpa tela for i=1:303 T(i+1) = (k*(T(i)-...
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simplifications de A, N.sce
// ----------------------------------------------------------------------------- // VALEURS NUMERIQUES DES CONSTANTES DU PROBLEME // ----------------------------------------------------------------------------- //Température Temperature = 37.5; T_opt_L = 37.5; // température optimale de croissance des légionnelles ...
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Ghost_Flick_Practice_1.sce
Name=Ghost_Flick_Practice_1 PlayerCharacters=Ghost_Flick BotCharacters=TileFrenzy Sphere.bot IsChallenge=false Timelimit=30.0 PlayerProfile=TileFrenzy Challenger AddedBots=TileFrenzy Cube.bot;TileFrenzy Cube.bot;TileFrenzy Cube.bot PlayerMaxLives=0 BotMaxLives=0;0;0 PlayerTeam=1 BotTeams=2;2;2 MapName=TileFrenzy_05x.ma...
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clear; path_rna = get_absolute_file_path('rna.sce'); exec( path_rna+"\_input_data_file.sce" ); exec( path_rna+"\..\RNA_ANALISE_TECNICA.sce" ); printf( 'Iniciando rna...\n' ); input_data = getInputDataFile(); output_data = rna_indicador(input_data(1),input_data(2),input_data(3),input_data(4),input_data(5),input_data(6...
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//OptoElectronics and Fibre Optics Communication, by C.K Sarkar and B.C Sarkar //Example 9.7 //OS=Windows 10 ////Scilab version Scilab 6.0.0-beta-2(64 bit) clc; clear; //given P1=100;//power at the input in microwatts P2=83.2;//power at the output in microwatts P3=35.5;//power at the ouput after connector i...
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//ques-35.4 //Calculating reduced mass of CN molecule clc C=12.011;//atomic weight of C (in amu) N=14.0067;//atomic weight of N (in amu) r_m=(C*N)/((C+N)*6.023*10^23); printf("The reduced mass of CN molecule is %.4f*10^-26 kg.",r_m*10^23);
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// Exa 1.12 clc; clear; close; format('v',7) // Given data n_i = 2.5*10^13;// in /cm^3 miu_e = 3800;//in cm^2/V-s miu_h = 1800;// in m^2/V-s e = 1.6*10^-19;// in C sigma_i = n_i*e*(miu_e+miu_h);// in (ohm-cm)^-1 disp(sigma_i,"The intrinsic conductivity in (ohm-cm)^-1 is"); n = 4.4*10^22; impurity = 10^-7; ...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monitor...
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clear; clc; dia=2*(10^-2);f=50;d=3.5; r=dia/2; Cab=0.01207/(log10(d/r))*(10^-6); Xc=1/(2*%pi*f*Cab); Bc=(1/Xc)*10^6; printf("Capacitive susceptance per km = %f * 10^-6 mho/km",round(Bc*100)/100);
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//Example 2.11 // determine the possible phase angles clc; clear; close; //given data : y1=1.25; // division y2=2.5; // division pi=asind(y1/y2); disp("the possible angles,pi(degree) "+string(pi)+" or "+string(360-pi)+" = ")
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//find.. clc //solution //given d=250//mm r=125//mm q=%pi/4 P=700//N u=0.35 ub=(4*u*sin(q))/(2*q+sin(2*q))//eqivalent coffint of friction //Ft=ub*Rn //taking moment abt O //700*(250+200)+Ft*50=Rn*200=Ft/ub*200=520*Ft Ft=700*(250+200)/470//N Tb=Ft*r printf("torque applied is,%f N-mm\n",Tb)
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clear // // //Initilization of Variables D=400 //mm //Overall Depth //Flanges b=300 //mm //Width t=50 //mm //Thickness t2=30 //mm //Web Thickness dell=10 //mm //Deflection w=40 //N/mm //Load FOS=1.75 //Factor of safety E=2*10**5 //N/mm**2 //Calculations //M.I at x-x axis I_x=1*12**-1*(b*D**3-(b-t2)*b**3) //mm**4...
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//control systems by Nagoor Kani A //Edition 3 //Year of publication 2015 //Scilab version 6.0.0 //operating systems windows 10 // Example 5.28 clc; clear; s=poly(0,'s')//defines s as poly nomial variable h=syslin('c',(s+2)/(s+1)*(s-1))//the given transfer function assigned to variable h scf() nyquist(h) ...
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/* Generated at yyyy-mm-dd hh:mm by java -cp dist/ramath.jar org.teherba.ramath.ProgramGenerator -l 2 -f test/PG20.data.tmp pident Do N O T edit this file, but ProgramGenerator.java instead! */ #include <stdio.h> #include <stdlib.h> int main(int argc, char *argv[]) { int reslines = 0; printf("#---> start ...
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clc clear //Input data bsfc=0.3;//The brake specific fuel consumption in kg/kWh bp=250;//The brake power in kW N=1500;//Number of cycles per min in rpm CA=15;//Crank angle in degrees pi1=30;//The pressure of air in the cylinder at the beginning of the injection in bar pi2=60;//The pressure of air in the cylinde...
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//Chapter-6, Illustration 17, Page 324 //Title: Refrigeration cycles //============================================================================= clc clear //INPUT DATA T1=271;//Temperature at point 1 in K T=265;//Temperature at point 1' in K Ta=303;//Temperature at point 2' in K Cpv=0.733;//Specific heat...
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function [a]=select_greedy(R) K=length(R); if sum(R)==0 then a = choix_uniforme(K), else Amax=ActionMax(R); // choix équitable a=Amax(choix_uniforme(length(Amax))); end; endfunction function [a]=select_egreedy(R,epsilon) K=length(R); greedy = rand()>...
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//Example 4.6.1 page 4.34 clc; clear; lamda = 1300*10^-9; Id= 4*10^-9; n=0.9; Rl= 1000; Pincident= 300*10^-9; BW= 20*10^6; q= 1.602*10^-19; h= 6.625*10^-34; v= 3*10^8; Iq= sqrt((q*Pincident*n*lamda)/(h*v)); Iq= sqrt(Iq); Iq=Iq*100; //converting in proper format for displaying... printf("Mean square qua...
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//ques7 //determining exit properties in a control volume clear clc Po=1000;//stagnation pressure in kPa To=360;//stagnation temperature in K //when diverging section acting as nozzle Pe1=0.0939*Po;//exit pressure of air in kPa Te1=0.5089*To;//exit temperature in K k=1.4;//constant R=0.287;//gas constant fo...
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//(13.2) Methane, CH4, is burned with dry air. The molar analysis of the products on a dry basis is CO2, 9.7%; CO, 0.5%; O2, 2.95%; and N2, 86.85%. Determine (a) the air–fuel ratio on both a molar and a mass basis, (b) the percent theoretical air, (c) the dew point temperature of the products, in C, if the mixture we...
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// Exa 4.29 clc; clear; close; k= 1.38*10^-23; T= 300;// in K (assume) V_D= 0.7;// The depletion voltage for silicon e=1.6*10^-19;// in C // n_n/n_p= p_p/p_n = %e^(e*V_D/(k*T)) ratio= %e^(e*V_D/(k*T));// ratio of majority to minority charge carriers in n and p of a silicon semiconductor disp(ratio,"Ratio of m...
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errcatch(-1,"stop");mode(2); syms a; syms b; syms c; A=[a a^2 a^3-1;b b^2 b^3-1;c c^2 c^3-1] det(A) exit();
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Ps = 0.033363; P = 1.0132; W2 = (0.622*Ps)/(P-Ps); hfg2 = 2439.9; hf2 = 109.1; cpa = 1.005; hg = 2559.9; hw1 = hg; T2 = 25+273; T1 = 32+273; W1 = (cpa*(T2-T1)+(W2*hfg2))/(hw1-hf2); Pw = ((W1/0.622)*P)/(1+(W1/0.622)); disp("kg vap./kg dry air",W1,"Specific humidity is") disp("bar",Pw,"Partial pressure of water v...
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//Section-6,Example-3,Page no.-P.32 //To find the Mole fraction of glycine in given aqueous solution. clc; m_g=0.1*1 //moles of glycine m_w=10^3/18 //moles of water in 1 kg of water m_f=m_g/(m_g+m_w) disp(m_f,'Mole fraction of glycine')
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//Chapter 18, Example 18.7 clc //Initialisation vcc=15 //voltage RC=5.6*10**3 //resistance in ohm RE=1.3*10**3 //resistance in ohm R2=13*10**3 //resistance in ohm, R1=82*10**3 //resistance in ohm pi=3.14 ...
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//Parametros del Pendulo //masa del carro 0.696 kg, masa de la parte superior 0.017 kg, longitud de la barra 0.3 m, //inercia del péndulo 0.0011 kg/m2. Este modelo presenta dos sensores, un ultrasónico //HC-SR04 que mide la posición del carro y un sensor tipo MEMS MPU-6050 que mide el ángulo del péndulo. //Parameters...
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// Premier oracle (fonction + gradient) function [F,G,ind] = OraclePG(qc, ind) q = q0+B*qc; if ind == 2 then F = (1/3)*q'*(r.*q.*abs(q)) + pr'*(Ar*q); G = zeros(n-md,1); elseif ind == 3 then F = 0; G = B'*((r.*q.*abs(q)) + Ar'*pr); else F = (1/3...
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//To calculate the electron concentration Na = 5*10^23; //atoms of boron Nd = 3*10^23; //arsenic atoms p = 2*(Na-Nd)/2; //hole concentration per m^3 ni = 2*10^16; //intrinsic charge carriers per m^3 n = ni^2/p; //electron concentration per m^3 printf("electron concentration per m^3 is"); ...
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clc; c=12.01; //mass of carbon h=1.008; //mass of hydrogen mass=((2*c)+(2*h)); //calculating mass o=16.00; //mass of oxygen moles=200/mass; //moles mo=2*o*19.20; //mass of O2 disp(mo,"Mass of O2 in g= "); //displaying result mc=((2*o)+c)*15.36; //mass of CO2; disp(mc,"Mass of CO2 in g= "); ...
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//Ex:4.44 clc; clear; close; f=3*10^3;// frequency in MHz y=300/f;// wavelength in m Ap=26;// power gain in dB Ap1=10^(Ap/10);// power gain D=sqrt((Ap1*y^2)/6);// diameter of antenna in m hpbw=(58*y)/D;// the half power point beam width in degree printf("The diameter of antenna = %f cm", D*100); printf("\n T...
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//Ex 1.11.6 clc;clear;close; format('v',9); //Given : A=2.5*10^-4;//m^2 n=1.5*10^16;//per m^3 q=1.6*10^-19;//Coulomb mu_n=0.14;//m^2/V-s mu_p=0.05;//m^2/V-s I=1.2*10^-3;//A V=9;//Volts ni=n;// per m^3 sigma_i=ni*q*(mu_n+mu_p);//(ohm-m)^-1 rho_i=1/sigma_i;//ohm-m R=V/I;//ohm l=R*A/rho_i;//m disp(l*100...
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//EXAMPLE 8-41 PG NO-557 N=7.943; Z=300; //IMPEDANCE R1=[(N-1)/N]*Z; R2=Z/(N-1); disp('i) RESISTANCE (R1) is = '+string (R1) +' ohm '); disp('ii) RESISTANCE (R2) is = '+string (R2) +' ohm ');
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clear; clf; //============================================================================== // This function creates the penta-diagonal matrix M used in the FD method // For a problem with nx * ny internal nodes, matrix M has a size of n * n, // where n = nx * ny. M is a tri-diagonal block matrix: // A I O // I A I /...
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// C-Exercise 7 // Jurain Kahl // Nattawut Phanrattinon function test_binomial(v,p0,beta) [p,q]=cdfbin('PQ',sum(v),length(v),p0,1-p0); if p<=beta return 1; else return 0; end // From C-Exercise 5 function v = VaR_log_normal (s, alpha) x = diff(log(s)) mu = mean(x); sigma = sqrt(variance(x...
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//EXAMPLE 2-12 PG NO-66-67 W1=80*%pi; //womega W2=100*%pi; PV=14.14; //peak value t1=0.025; //time t2=0.05; t3=0.075; I1=PV*(cos(80*%pi*t1)+cos(100*%pi*t1)); //current I2=PV*(cos(80*%pi*t2)+cos(100*%pi*t2)); //curren...
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clc; //pg n0 120 IZ=10*10**-3; vz=0.05; rz=vz/IZ; disp('ohm',rz*1,"rz=");
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/* Bat Algorithm Functions Aviliable: ReportBat Bat PreEvaluateBat EvaluateBat */ function [Report,Table,RProm] = ReportBat(TotalOfElements) Table=[]; tprom=0; Report=[]; TC = TotalOfElements; TotalExper = 10; Dimensions = 10; Ixprom=zeros(1,TC); ...
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double Gauss_densite(double x) function [res] = Gauss_densite(nb_quant,init,nb_iter) { // printf("g\n"); double res; res = PI; // printf("pi = %f\n",res); res = exp(-x*x/2)/sqrt(2*res); //printf("gauss(x) = %f\n",res); return res; }
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load Xor.hdl, output-file Xor.out, compare-to Xor.cmp, output-list ip1%B3.1.3 ip2%B3.1.3 out%B3.1.3; set ip1 0, set ip2 0, eval, output; set ip1 0, set ip2 1, eval, output; set ip1 1, set ip2 0, eval, output; set ip1 1, set ip2 1, eval, output;
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clc; clear all; disp("Heat loss calculation") r=0.6/2;//m L=1;//m H=1.8;//m k=0.51;// W/(m*C) tp=95;// degree C te=25;// degree C Sfc=2*3.1416*L/(log(2*H/r)); Q=k*Sfc*(tp-te); disp("W",Q,"Heat loss from the pipe meter length, Q =")
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(unwatch all) (clear) (set-strategy depth) (open "Results//jstfctns.rsl" jstfctns "w") (dribble-on "Actual//jstfctns.out") (batch "jstfctns.bat") (dribble-off) (load "compline.clp") (printout basicfnx "jstfctns.bat differences are as follows:" crlf) (compare-files "Expected//jstfctns.out" "Actual//jstfctns.out" jstfctn...
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//calculate the total amprers turns u=1//for air gap F=1.2e-3//flux A=10e-4 //area B=F/A H=B/(4*3.14*10^-7*u) l=0.2e-3//air gap S=H*l//amps turns in air gap l1=15e-2//air gap A1=8e-4 H1=450 S1=H1*l1 F1=0.6e-3 B1=F1/A1 H2=140 S2=H2*30e-2 TN=500 TAN=S+S1+S2 EI=TAN/TN disp('exciting current =' +strin...
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clear clc //Example 6.1 THRUST OF ROCKET g=9.81; //[m/s^2] m=0.04; //mass[kg] D=0.01; //[m] A=%pi*D^2/4 //area[m^2] rho=0.5; //density[kg/m^3] v=450; //[m/s] //Sum of forces, Fz=-Fb-m.g Mo=-rho*A*v^2 //momentum outflow[N] Fz=Mo //[N] Fb=-Fz-m*g //Force on beam[N] printf("\n The force acting on the beam tha...
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exec("swigtest.start", -1); i = new_iFoo(); checkequal(iFoo_blah_test(i, 4), 4, "iFoo_blah_test(i, 4) test fails"); checkequal(iFoo_spam_test(i, 5), 5, "iFoo_spam_test(i, 5) test fails"); checkequal(iFoo_groki_test(i, 6), 6, "iFoo_groki_test(i, 6) test fails"); delete_iFoo(i); d = new_dFoo(); checkequal(dFoo_blah_tes...
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//example-8.2 //page no-235 //given //density of alpha and beta phases rhoalpha=10300 //kg/m^3 rhobeta=7300 //kg/m^3 //refer to fig-8.5 in book //at point B, the composition of lead in alpha-phase is 82% and that of tin in alpha-phase is 18% leadalpha=82 tinalpha=18 //so we get //82/rholead+18/rhotin=100/r...
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//exapple 13.6 clc; funcprot(0); // Initialization of Variable rho=1.210;//density of air mu=1.78/10^5; g=9.81; rhos=2655;//density of ore pi=3.1428; d=0.095; dp=2*10^-6//particle diameter dt=0.333;//dia of cyclone separator h=1.28; //calculation U=dp^2*g*(rhos-rho)/18/mu; Q=0.2*(pi*d^2/4)^2*d*g/U/pi...
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//Exa 2.38 clc; clear; close; //Given data : format('v',6); f=50;//in Hz P=6;//no. of poles phase=3;//no. of phase R2=0.02;//in ohm X2=0.1;//in ohm S=R2/X2;//slip(unitless) Ns=120*f/P;//in rpm Nr=Ns-Ns*S;//in rpm //At starting S=1 S=1;//slip //Formula : T=K*S*R2/(R2^2+X2^2) //Starting torque, Tst=K*R2/...
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//mesh equations: //60*I1 - 20*I2 = 20 //-20*I1 + 80*I2 = -65 R = [60 -20;-20 80]; E = [120;-65]; I = inv(R)*E; I1 = I(1,:); //current flowing in first mesh I2 = I(2,:); //current flowing in second mesh Ibd = I1 - I2; //current flowing through branch bd Iab = I1; //current flowing through branch ab Icb =...
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clc //Chapter8 //Example8.24, page no 354 //Given f=20e6//tuned freq ZR=100//Equivalent aerial Resistance Zin=500//input impedance c=3e8 lambda=c/f l=lambda/4//lambda/4 Transformer Zo=sqrt(Zin*ZR)//Characteristic impedance mprintf('the Length of the transformer(stub) is %f metres\n The characteristic imped...
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//Example 20.1 delta_Q1=720;//Charge moved by truck battery (C) delta_t1=4;//Time (s) I1=delta_Q1/delta_t1;//Current (A) printf('a.Current flowing through the truck battery = %0.1f A',I1) I2=0.3*10^-3;//Current flowing through calculator (A) delta_Q2=1;//Charge moving through calculator (C) delta_t2=delta_Q2/I2;...
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//Motorist travelling //refer fig. 15.5 u=(70*1000)/(60*60) //m/sec v=0 s=50 //m //Using equation of linear motion a=-(19.44^2)/(2*50) //m/sec^2 //again t=19.44/3.78 //sec //Applying equilibrium equationswe get mu=(3.78)/(9.81) printf("\nt=%.2f sec\nmu=%.3f ",t,mu)
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// Scilab Code Ex4.3:: Page-4.6 (2009) clc; clear; mu = 1.53; // Refractive index of the material from Brewster's law // As mu = tand(ip), solving for ip ip = atand(mu); // Polarizing angle, degrees // But mu = sind(ip)/sind(r), solving for r r = asind(sind(ip)/mu); // Angle of refraction, degrees pr...
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clear; clc; printf("\t\t\tchapter1_example4\n\n\n"); // determining average film conductance D=2.43/100; // diameter in meter L=20/100; // length in meter A=3.14*D*L; // cross-sectional area in sq.m cp=4200; // specific heat of water in J/kg.K T_b2=21.4; // temperature of bulk fluid in degree celsius T_in=20; ...
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clc; clear all; disp("Mass transfer coefficient") U=6.2;// m/s d=35/1000;// m v=15.5*10^(-6);//m^2/s D=0.82*10^(-5);//m^2/s Sc=v/D;// Schmidt No. Re=U*d/v;// Reynolds No. Sh=0.023*((Re)^0.83)*(Sc)^0.44; hm=Sh*D/d;// m/s disp("m/s",hm,"mass transfer coefficient = ")
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clear all; clc; printf("\n Example 13.4"); diameter = [2 3 4 5 6]; number = [30 120 200 80 20]; function[x] = Sum_d1cube() sum = 0; i = 1; while (i <= 5) sum = sum + number(i)*(diameter(i))^3; i = i+1; end x = sum; funcprot(0); endfunction function[y]=sum_d1squ...
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function mayor = MAYOR(y0) [m,n] = size(y0) mayor = 0 for j=1:m if abs(y0(j,1)) > abs(mayor) mayor = y0(j,1) end end endfunction clc A = [2 -12;1 -5] x = [1 1]' y = A*x disp(y0, "y0") for i=1:10 y = A*x valor = MAYOR(y) x = y/valor end disp(y,"y - 10 iteracio...
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// s:2008,05.12 // e:2014.09.08 [A,B] supported // e:2014.10.24 N,R => N__, ... function P=Circledata(varargin) Nargs=length(varargin); C=varargin(1); if length(C)==4 then ra=norm(C(1:2)-C(3:4)); C=C(1:2); Nop=2; else ra=varargin(2); Nop=3; end; R__=[0,2*%pi]; N__=50; // Numpoints ...
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clc //Initialization of variables t1=80 //F t2=60 //F p=14.696 //psia ps=0.5069 //psia pss=0.2563 //psia cp=0.24 //calculations pw= pss- (p-pss)*(t1-t2)/(2830- 1.44*t2) phi=pw/ps w=0.622*pw/(p-pw) ws=0.0111 hfg=1059.9 hw=1096.5 hf=28 w2= (cp*(t2-t1)+ ws*hfg)/(hw-hf) //results printf("relative humidity...
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//Exa 5.13 clc; clear; close; //Given data : f=50;//Hz l=30;//km Z=40+%i*125;//ohm Y=10^-3;//mho P=50*10^6;//W VRL=220*10^3;//Volt VR=VRL/sqrt(3);//Volt pf=0.8;//power factor cos_fi_r=pf; sin_fi_r=sqrt(1-cos_fi_r^2); IR=P/(sqrt(3)*VRL*pf);//A IR=IR*(cos_fi_r-%i*sin_fi_r);//A ICR=1/2*%i*Y*VR;//A IL=IR+...
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errcatch(-1,"stop");mode(2);//Initilization of variables m=900 //kg mu=0.2 //coefficient of friction g=9.8 //m/s^2 //Calculations T2=m*g/(exp(2*2*%pi*mu)) //N //Result printf('The force needed to hold the mass is %fN',T2) exit();
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//================================================================================== //chapter 1 example 8 clc; clear all; //intercepts given are a,2b,-3c/2 //from the law of rational indices //a:2b:-3c/2=a/h:b/k:c/l //variable declaration h12 = 1; //miller indices k12 = 1/2; ...
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function [x,y,z] = rect3D(orig,n,xd,yd,l,w) //Author : Maxens ACHIEPI //Space Robotics Laboratory - Tohoku University //Description: //Outputs the coordinates of the four corners of a lxw rectangle with //surface normal n //INPUT //orig : one of the rectangle's corner. Line vector...
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//ANALOG AND DIGITAL COMMUNICATION //BY Dr.SANJAY SHARMA //CHAPTER 11 //Information Theory clear all; clc; printf("EXAMPLE 11.49(PAGENO 534)"); //given P_x1 = .4//probability of first signal P_x2 = .2//probability of second signal P_x3 = .8//probability of third signal P_x4 = .08//probability of fourth sig...
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//332 clear; close; clc; A=[1 -2;3 -1]; disp(A,'A='); [U S V]=svd(A); Q=U*V'; S=V*S*V'; disp(Q,'Q='); disp(S,'S='); disp(Q*S,'A=SQ=') //end
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function x=%slsp(a,x) // a^-1*x a full,x sparse x=a\full(x)
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SCSI Tape Streamers supported by TapeBIOS - Tested ================================================== The tape drives that have been tested with TapeBIOS, with the caveats stated, are listed below:- Tandberg TDC 36xx series. Works faultlessy. No timeout value needed whatsoever. Archive Viper 150S. Timeo...