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clc;funcprot(0);//Example 5.5 //Initilisation of Variables x1=0.3;....//distance 1 in m x2=0.5;....//distance 2 in m L=1;...//Length of the flat plate in m T=300;...//Temperature of air in K p=1;.....//Air pressure in bar v=5;...//Velocity of air in m/s mu=1.85*10^-5;...//Viscosity of air in kg/m s R=0.287;...//Universal gas contant in kJ/kg K //calculation rho=p/(R*T);...//Density of air at 300 K Re1=rho*v*x1/mu;....//Reynolds number at x=0.3 m Re2=rho*v*x2/mu;....//Reynolds number at x=0.5 m del1=4.64*x1/sqrt(Re1);....//Displacement thickness at x=0.3m del2=4.64*x2/sqrt(Re2);....//Displacement thickness at x=0.5m m=(5/8)*rho*v*(del2-del1);.....//mass flow rate in kg/s disp(m,"mass flow rate in kg/s:")
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// 6.2 clc; Vcc=4.76; t=50*10^-6; R=0.2*10^3; C=0.2*10^-6; tc=R*C; Vo=Vcc*[exp(-t/tc)]; printf("\nvoltage across the capacitor after 50 microsecond=%.2f V",Vo)
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clc clear //1iii function [f,df]= newtonraphsonFunc(x) f = (x^3)-(x)-3; df =(3*x^2)-1; endfunction //main x=[0.0]; maxIteration = 100; Iteration=[0]; tolerance = 0.000001; large = 10^200; difference = 1; while(1) if ((Iteration($)== maxIteration)||(difference<tolerance)||(abs(x($))>large)) then break; end [fx, dfx] = newtonraphsonFunc(x($)); x($+1) = x($) - fx/dfx; difference = abs(x($)-x($-1)); Iteration($+1) = Iteration($) + 1; end disp(x); plot(Iteration, x);
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s=%s; L=0.5; G0=1/((s+1)*(s+4)); DelayN=1-(L/2)*s+(1/10)*(L*s)^2-(1/120)*(L*s)^3; DelayD=1+(L/2)*s+(1/10)*(L*s)^2+(1/120)*(L*s)^3; Delay=DelayN/DelayD
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//ques-25.27 //Calculating coefficient of viscosity of benzene clc t1=46;//time taken by benzene (in s) t2=68;//time taken by water (in s) den1=0.8;//density of benzene (in g/mL) den2=0.998;//density of water (in g/mL) visc2=1.008;//coefficient of viscosity of water (in centipoise) visc1=(den1*t1*visc2)/(den2*t2); printf("The coefficient of viscosity of benzene is %.4f centipoise.",visc1);
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clear; clc; close; f = 1000; T = 1/f; C = 0.1*10^(-6); R = 100*10^(3); Vk = 0.7; //between t1-->t2 vo_1 = 4.3; Vc = 25-0.7; //between t2-->t3 Rth = 0; Eth = 4.3; vo_2 =34.3; tau = R*C; discharge_time = 5*tau; //between t3-->t4 vo_3 = 5; disp(vo_1,'output voltage during t1-->t2 : '); disp(vo_2,'output voltage during t2-->t3 : '); disp(vo_3,'output voltage during t3-->t4 : '); t = 0:10^(-6):2.5*10^(-3); for i= 1:length(t) if(t(i)>=0 & t(i)<=0.5*10^(-3)) y(i) = 0; elseif(t(i)>=0.5*10^(-3) & t(i)<=10^(-3)) y(i) = 4.3; elseif(t(i)>=10^(-3) & t(i)<=1.5*10^(-3)) y(i)=34.3; elseif(t(i)>=1.5*10^(-3) & t(i)<=2.0*10^(-3)) y(i)=4.3; elseif(t(i)>=2.0*10^(-3) & t(i)<=2.5*10^(-3)) y(i)=34.3; end end a = gca(); a.thickness = 2; plot2d(t,y); a.x_label.text = 't'; a.y_label.text = 'Vo'; xset('thickness',2); xstring(0.5*10^(-3),0,'t1'); xstring(10^(-3),0,'t2'); xstring(1.5*10^(-3),0,'t3'); xstring(2*10^(-3),0,'t4'); xstring(0,4.3,'4.3'); xstring(0,34.3,'34.3');
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clear; clc; x=0:.1:11 f=0.2; plot(x,sin(2*%pi*x*f)); xtitle('Continuous Sine Signal') xlabel('x') ylabel('sin(x)')
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//Chapter-2,Example2_4_4,pg 2-25 wavelength=6328*10^-10 //wavelength of light m1=1 //for first order m2=2 //for second order N= 6000*10^2 //Number of lines per unit length angle_1=asind(N*m1*wavelength) angle_2=asind(N*m2*wavelength) printf('\nangle of diaffraction for 1st order minima is ang1 = %.2f degrees',angle_1) printf('\nangle of diaffraction for 2nd order minima is ang2 = %.2f degrees',angle_2)
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//Example 8.2 clear; clc; R=159*10^3; C=10*10^(-9); f0=1/(2*%pi*R*C); ft=10^6; fx=sqrt(f0*ft); Q=sqrt(ft/f0); d=-90-((180/%pi)*atan(fx/f0)); pm=180+d; printf("fx=%.2f kHz",fx*10^(-3)); printf("\nQ=%.f",Q); printf("\nPhase Margin (PM)=%.1f degrees",pm);
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function [w]=l2r(x) w=r2l(x')'
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clc clear //INPUT DATA x=6.40*10^7//electrical conductivity in mho m^-1 t=300//temperature of copper in k L=2.44*10^-8//Lorentz number in W ohm K^-2 //CALCULATION K=x*t*L//thermal conductivity of copper in W m^-1 K^-1 //OUTPUT printf('The thermal conductivity of copper is %3.2f W.m^-1.K^-1',K)
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A = imread("C:\Users\ADMIN\Documents\PHYSICS\6thYear\186\AP186\186A6\correlation\A.png"); A = rgb2gray(double(A)); B = imread("C:\Users\ADMIN\Documents\PHYSICS\6thYear\186\AP186\186A6\correlation\phrase.png"); B = rgb2gray(double(B)); //get FT of A & B ftA = fft2(A); f=scf(); imshow(fftshift(uint8(imnorm(abs(ftA))*255))); isoview(); ftB = fft2(B); f=scf(); imshow(fftshift(uint8(imnorm(abs(ftB))*255))); isoview(); //correlation; denoted by P in frequency space ftP = conj(ftB).*ftA f=scf(); imshow(fftshift(uint8(imnorm(abs(ftP))*255))); isoview(); P = fftshift(fft2(ftP)); //takes the lowest value and makes it 0 P = abs(P) - min(abs(P(:))); //imshow wont work since there are values greater than 255; //thus the need for line P = abs(P)... P = P.^2 //dots become more noticable (edit the power) f=scf(); imshow(uint8(imnorm(P)*255)); //white dots indicate the letters that are the same isoview();
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//example6.4 clc disp("a) The drop across the shunt is same as drop across the coil.") disp("Therefore, [(I_sh)*(R_sh)]=400 mV") i=(400*10^-3)/0.01 disp(i,"Therefore, I_sh(in A)=(400*10^-3)/0.01= ") disp("b) The voltage across shunt for shunted current of 50 A is,") v=50*0.01 disp(v,"V_sh(in V)=[(I_sh)*(R_sh)]=50*0.01=") disp("For this voltage the meter should give full scale deflection. In first case, the current through meter for full deflection was,") i=(400*10^-3)/750 disp(i,"I_m(in A)=(400mV)/(R_m)=(400*10^-3)/750=") disp("The same I_m must flow for new voltage across the meter of 0.5 V") disp("Therefore, [(I_m)*(R_m)'']=0.5") disp("Therefore, [(5.33*10^-4)*(R_m)'']=0.5") r=0.5/(5.33*10^-4) disp(r,"Therefore, (R_m'')[in ohm]=") disp("This is the resistance of the meter required for 50 A shunted current to give full scale defection.")
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//Example 4.16 A random sample of 10 students of class II was selected from schools in a certain region clc; clear; x=[38 46 45 40 35 39 44 45 33 37]; n=10; m=sum(x)/n; s=sqrt(18.96); disp((m+2.26*(s/3)),"to",(m-2.26*(s/3)),"The 95% confidence limits for mean weight are "),
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function precisao = verifica(A,p) [l,c] = size(A) precisao = 0 //supoe verdadeira para dps verificar se é realmente ;) for i = 1 : l for j = 1 : c if (i > j) then //para elementos abaixo da diag if (abs(A(i,j)) > p) then precisao = 1 //nao atingiu o valor dado em p end end end end endfunction
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function set_linewidth(h,lw) // Does nothing endfunction
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clear;lines(0); bool2s([%t %t %f %t]) bool2s([2.3 0 10 -1])
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errcatch(-1,"stop");mode(2); disp('Data is not provided,only graph is provided') exit();
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// Example 4.1, page no-209 clear clc //(a) k=50 m=0.005 wn=sqrt(k/m) printf("(a)\nNatural frequency(wn)= %d rad/s",wn) //(b) Cc=2*sqrt(m*k) printf("\n(b)\nCc=%d",Cc)
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clear clc //Example 14.9 CENTRIFUGAL COMPRESSOR p1=100; //pressure [kPa] p2=200; //[kPa] k=1.4; Q1=1;//discharge [m^3/s] eta=0.65; //efficiency //Theoretical power Ptheo=(k/(k-1))*Q1*p1*[(p2/p1)^((k-1)/k)-1] //[kW] //Shaft power Pshaft=Ptheo/eta //[kW] printf("\nThe shaft power required to operate the compressor = %.f kW.\n",Pshaft)
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//Ex19_12 Pg-962 clc oct='257'; //binary input dec=oct2dec(oct) //decimal output disp("The decimal equivalent of 257 is") disp(dec)
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//Example6_34 // To design a phase shifter clc; clear; close; f = 2*10^3 ; PS = -135 ; // the phase shift // PS = -2*atand(2*%pi*R*C); //RC = 192.1*10^-6 ; C = 0.1*10^-6 ; R = (192.1*10^-6)/C disp('The value of resistance is = '+string(R)+ ' ohm');
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errcatch(-1,"stop");mode(2);//Part B Chapter 4 Example 9 ; ; d=120;//mm D1=120;//mm D2=60;//mm ThBYTs=(D1^4-D2^4)/d^4; WhBYWs=%pi/4*((D1^2-D2^2)/(%pi/4)/d^2); disp("Strength ratio, Th/Ts is "+string(ThBYTs)); disp("Weight ratio, Wh/Ws is "+string(WhBYWs)); exit();
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argc:7 Dataset: ../datasets/converted/football.net Nodes Edges Com Mod NMI Time seq async 115 1226 9 0.602529 -1 0.000248959 par async 115 1226 13 0.50171 -1 0.071628
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//find.. clc //soltuion //given d1=400//mm r1=200//mm d2=1600//mm r2=800//mm q1=2.5//rad q2=3.78//rad u1=0.3 u2=0.25 N1=700//rpm P=22.5*10^3//W t=0.005//mm f=2.3*10^6//N/m^2 //ref fig 18.19 v=%pi*N1*d1/60//m/s //let T1 and T2 be tneion on tight and slag side printf("the vel of belt is,%f m/s\n",v) //P=(T1-T2)*v//W //T1-T2=P/v=1530//N //log(T1/T2)=u*q=0.25*3.477=0.75 //T2=T1/2.21//N T1=2896//N T2=1366//N //let b is width //m=A*rho=b*t*rho=5*b//kg/m //Tc=m*v^2=1080*b //T=T1+Tc=f*b*t //11500*b=2896+1080*b b=2896/(11500-1080)//m printf("the widht of belt is,%f m\n",b)
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clear clc //Example 11.6 disp('Example 11.6') //Drawing on example 11.4 s=%s; theta=1;tau=100;K=100; delay=(1-theta/2*s+theta^2/10*s^2-theta^3/120*s^3)/(1+theta/2*s+theta^2/10*s^2+theta^3/120*s^3);//Third order pade approx G=K*delay/(tau*s+1); Kc=0.556;taui=5; Gc=Kc.*(1+(1)./([taui]*s)) G_CL=syslin('c',Gc*G./(1+Gc*G)); t=0:0.1:20; y1=csim('step',t,G_CL); y1(:,1:theta/0.1)=0;//accounting for time delay--this is required otherwise //an unrealistic inverse response is seen due to the pade/taylor approx beta=0.5; G_CL2=syslin('c',(Gc+beta-1)*G./(1+Gc*G));//This can be obtained on taking //laplace transform of eqn 11-39 and making a block diagram //In Eqn 11-39 p refers to input to the process t=0:0.1:20; y2=csim('step',t,G_CL2); y2(:,1:theta/0.1)=0;//accounting for time delay--this is required otherwise //an unrealistic inverse response is seen due to the pade/taylor approx plot(t,[y1; y2]); xgrid() xtitle('Ex-11.3 Tracking problem','Time(min)','y(t)'); a=legend("$\beta=1$","$\beta=0.5$",position=4); a.font_size=2; a=get("current_axes");b=a.title;b.font_size=5;c=a.x_label;c.font_size=5; c=a.y_label;c.font_size=5; //Note that there is a slight mis-match between the plots obtained from scilab code //and that of the book because of third order pade approximation //The plots in the book have been produced using advanced proprietary software //which supports using exact delays while scilab does not have that functionality
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function [f]=%ras(f,m) // f=%ras(f,m) <=> f = f+m //! [p,q]=size(m); if p+q=-2 then m=m*eye(f(3)); end; if p*q=1 then f(2)=f(2)+m*f(3);return;end f(2)=f(2)+m.*f(3)
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//COMO USAR: //A=[x0 x1 x2 ... xN] //D=[f[x0] f[x0 x1] ... f[x0...xN]] //N=grado del polinomio //horner(A,D,N,x) //Grafico f(x) //x=-10:0.1:10; //plot2d(x, f(x)); //xgrid(3,1,7); //muestra grilla function horner(X,d,N,x) // X=vector de raices, d=diferencias divididas, N=grado(P(x)) p=d(N+1); // es N+1 porque los indices van de 1 a N+1 en lugar de 0 a N for i=N:-1:1 p=d(i)+p*(x-X(i)); end printf("\np=%12.9f",p); endfunction
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//Given that lambda = 550*10^-9 //in m T = 300 //in K room temprature h = 6.62*10^-34 //in J-s c = 3*10^8 //in m/s e = 1.6*10^-19 K = 8.62*10^-5*e //Sample Problem 41-6a printf("**Sample Problem 41-6a**\n") deltaE = h*c/lambda ratio = %e^(-(deltaE)/(K*T)) printf("The ratio is equal to %e\n", ratio) //Sample Problem 41-6b printf("\n**Sample Problem 41-6b**\n") ratio = 0.5 T = -deltaE/K/log(ratio) printf("The temprature required for the given ratio is equal to %fK", T)
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// function [B,degB] = ext(A,degA,k,l) // EXTRACTS THE (k,l) ELEMENT OF A polynomial matrix A into B function [B,degB] = ext(A,degA,k,l) [rA,cA] = polsize(A,degA); degB = degA; B = zeros(1,degB+1); for m = 0:degB B(1,m+1) = A(k,(m*cA)+l); end [B,degB] = clcoef(B,degB); endfunction;
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errcatch(-1,"stop");mode(2);//Chapter 19,Example 2,page 667 //Determine the pumping pressure p0 = 30*10^-3 // C/m^3 V = 30*10^3 // V P = p0*V printf("\n The pumping pressure P = %f N/m^2",P) // Answers may vary due to round off error exit();
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//**************************** Min_detect ********************************** if (blk_name.entries(bl) == "Min_detect") then mputl("#Min_detect",fd_w); for ss=1:scs_m.objs(bl).model.ipar(1) Min_detect_str= '.subckt Min_detect'+' in[0]=net'+string(blk(blk_objs(bl),2))+'_'+string(ss)+' out[0]=net'+string(blk(blk_objs(bl),2+numofip))+'_'+string(ss)+' #Min_detect_ls =0'+'&Min_detect_fgswc_ibias ='+string(sprintf('%e',scs_m.objs(bl).model.rpar(scs_m.objs(bl).model.ipar(1)*(1-1)+ss)))+'&Min_detect_ota0_ibias ='+string(sprintf('%e',scs_m.objs(bl).model.rpar(scs_m.objs(bl).model.ipar(1)*(2-1)+ss))) mputl(Min_detect_str,fd_w); mputl("",fd_w); //select board_num //case 2 then plcloc=[plcloc;'net'+string(blk(blk_objs(bl),2+numofip))+'_'+ string(ss),'6 '+string(ss)+' 0']; //case 3 then plcloc=[plcloc;'net'+string(blk(blk_objs(bl),2+numofip))+'_'+ string(ss),'1 '+string(ss)+' 0']; // end if scs_m.objs(bl).model.rpar(scs_m.objs(bl).model.ipar(1)*(3-1)+1) == 1 then plcvpr = %t; plcloc=[plcloc;'net'+string(blk(blk_objs(bl),2+numofip))+'_'+string(ss),string(scs_m.objs(bl).model.rpar(scs_m.objs(bl).model.ipar(1)*(3-1)+1+2*ss-1))+' '+string(scs_m.objs(bl).model.rpar(scs_m.objs(bl).model.ipar(1)*(3-1)+1+2*ss))+' 0']; end end end
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//Initilization of variables L=1000 //lb P=10 //lb //Calculations mu=log(L/P)/(4*2*%pi) //Result clc printf('The coefficient of friction is %f',mu)
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::::::::::::::::::::::::::: ::deep SHA256 round testing bitseal 64-bit Debian 7 vps passwd: 'Satoshi Nakamoto' sharnd: '0x93a4bfec9','39632764617' calctm: '17674 secs' prvkey: '26f8f2f71b246d21bf292d724648ff00452e32060c0ed8b7811f3817886d04c2' prvb58: '5J7T5dUirMX2LLJVoVy3gxxVBUFNrifK7hRaUbwvK89QxeAvNj5' pubb58: '1Dx6nfHg6YrvMUsK6o8gdaQEoPk1poAAKT' passwd: 'rabbit*&^%' sharnd: '39632764617','0x93a4bfec9' calctm: '16823 secs' prvkey: '1076379daaafae6933a3070570c3b0c9895401c4556f8c078e89cd1f8846d7b1' prvb58: '5HwY5M3p3hrmA53jJcJEBsURnR7PZqJs55bVABj4aHS74ejmU3N' pubb58: '12aQkUbrmvmxVHokZYVMuE7jCYACxpoKnz' bitseal 32-bit Debian 7 vps passwd_: 'Satoshi Nakamoto' sha_rnd: '0x93a4bfec9','39632764617' calctm_: '27511 secs' privkey: '26f8f2f71b246d21bf292d724648ff00452e32060c0ed8b7811f3817886d04c2' privb58: '5J7T5dUirMX2LLJVoVy3gxxVBUFNrifK7hRaUbwvK89QxeAvNj5' pub_b58: '1Dx6nfHg6YrvMUsK6o8gdaQEoPk1poAAKT' passwd_: 'rabbit*&^%' sha_rnd: '0x93a4bfec9','39632764617' calctm_: '27590 secs' privkey: '1076379daaafae6933a3070570c3b0c9895401c4556f8c078e89cd1f8846d7b1' privb58: '5HwY5M3p3hrmA53jJcJEBsURnR7PZqJs55bVABj4aHS74ejmU3N' pub_b58: '12aQkUbrmvmxVHokZYVMuE7jCYACxpoKnz' :::::::::::::::::::::::::::::::::::::::::::::::::::::::::::: ::short repetitive testing to check for out of bounds errors ::the public b58 is most complex so test it ::any breakage before it will be reflected here while true; do ./bitseal | grep pubb58 | cut -d "'" -f 2 >> output; done grep -v 1Z2A5K7WxYpYLCSMXKKeiNSvamS7C34UQ output ::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::: ::simple checking across multiple platforms with short rounds bitseal 64-bit Debian 7 phys passwd: 'Satoshi Nakamoto' sharnd: '10067967','0x999fff' calctm: '7 secs' prvkey: '4640eeb02392e618749f5abe6de9bf199a6c82f894c1919e26ce5ad87c65c38f' prvb58: '5JME7iBPhFJ7SatrqoXrh86yD5Xtf54T8rEfFmEQLtz5t8L5UJD' pubb58: '14S5b16e4hmYbytxNe7y53v8zjEQRDx8Ru' bitseal 64-bit Debian 7 vps passwd: 'Satoshi Nakamoto' sharnd: '10067967','0x999fff' calctm: '4 secs' prvkey: '4640eeb02392e618749f5abe6de9bf199a6c82f894c1919e26ce5ad87c65c38f' prvb58: '5JME7iBPhFJ7SatrqoXrh86yD5Xtf54T8rEfFmEQLtz5t8L5UJD' pubb58: '14S5b16e4hmYbytxNe7y53v8zjEQRDx8Ru' bitseal 32-bit Debian 7 vps passwd: 'Satoshi Nakamoto' sharnd: '10067967','0x999fff' calctm: '15 secs' prvkey: '4640eeb02392e618749f5abe6de9bf199a6c82f894c1919e26ce5ad87c65c38f' prvb58: '5JME7iBPhFJ7SatrqoXrh86yD5Xtf54T8rEfFmEQLtz5t8L5UJD' pubb58: '14S5b16e4hmYbytxNe7y53v8zjEQRDx8Ru' ::::::::::::::::::::::::::::::: ::check with alternate programs c=$(echo -n "Satoshi Nakamoto" | sha256sum | awk '{print $1}'); echo -n 0x$c | xxd -r -c 64 | sha256sum 21ee5734569831d26b398831435f01a137102322ea4fceff2cd5f0ae99080727 passwd: 'Satoshi Nakamoto' sharnd: '2','0x2' calctm: '0 secs' prvkey: '21ee5734569831d26b398831435f01a137102322ea4fceff2cd5f0ae99080727' prvb58: '5J5EJaKzoB7TjjRzyJDGpPhiDo9jQevCKpXYjHZq4wekMYG7Pjt' pubb58: '1CNRGf4Xcvjozp7hdJ3ucWUAndWtsCV4de #bash will start tripping up after lots of rounds since it doesn't #handle binary that well.
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clc // Given that theta = 13 // rotation of plane of polarization in degree s = 65 // specific rotation of sugar solution in degree per decimeter per unit concentration l = 2 // length of Polari meter in decimeter // Sample Problem 20 on page no. 221 printf("\n # PROBLEM 20 # \n") c = theta / (s * l) // calculation for concentration of sugar solution printf("\n Standard formula used \n c = theta / (s * l). \n") printf("\n Concentration of sugar solution = %f gm/cc or %d percent.",c,c*100)
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errcatch(-1,"stop");mode(2);//Example 1.18.1: voltage of the capacitor ; ; format('v',7) r=10;//in ohms l=10;///inductance in mH c=10;//capacitance in micro farads v=100;//in volts t=((%pi)/(sqrt((1/(l*10^-3*c*10^-6))-(r^2/(4*(l*10^-3)^2)))));// time in seconds vc= v*(1-cosd(t/(sqrt(l*10^-3*c*10^-6))));//in volts disp(vc,"the capacitor voltage in volts is") //answer is wrong in the textbook exit();
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//x+2*y=5, 3*x-2*y=7 clear; clc; close; x=poly(0,'x'); //graph of x+2*y=5 x=[0 -1 2 5]; y=(5-x)/2; x_vs_y=[x;y]; plot(x,y,'b--.x') //graph of 3*x-2*y=7 x=[0 -1 7/8 4]; y=(3*x-7)/2; plot(x,y,'b--.o') for x=1:100 if((5-x)/2==(3*x-7)/2) break end end mprintf("the solution of the equation is") y=(5-x)/2; mprintf("x=%i\ny=%i ",x,y) plot(x,y,'r.->') xtitle("graph of simultaneous equations","x axis","y axis"); xgrid; legend("x+2*y=5","3*x-2*y=7",4);
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clc; // Air conditioning unit TL=278; // Operating temperature in kelvin TH=318; // Operating temperature in kelvin COP1=TL/(TH-TL); // COP of Air conditioning unit QL=1; // For some calculation purpose W1=QL/COP1; // Work input of Air conditioning unit // Food refrigeration unit TL=258; // Operating temperature in kelvin TH=318; // Operating temperature in kelvin COP2=TL/(TH-TL); // COP of Food refrigeration unit W2=QL/COP2; // Work input of Food refrigeration unit Wper=(W2-W1)/W1; // Increase in work input disp ("%",Wper*100,"Increase in work input = ");
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//simplify 3a(a^2-4ab+4b^2)/6a(a^2+3ab-10b^2) clear; clc; close; //the factors 3a(a-2b) are common to numerator & denominator. mprintf("\n the fraction is :\n") string('(a-2b)/(2a(a+5b))')
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clc; E=400; // supply voltage l1=200; // load connected across 75% tapping l2=400; // load connected between 25% and 100% tapping t1=25; // 25% tapping point t2=50; // 50% tapping point t3=75; // 75% tapping point V2=(t3/100)*E; // voltage across 200 ohm load I2=V2/l1; // current through 200 ohm load I1=(V2*I2)/E; // from fig.(1.46 b), KCL at point d gives idb=I2-I1; // same secondary voltage is applied against load of 400 ohm I2=V2/l2; // current through 400 ohm load I1=(V2*I2')/E; // from fig (1.46 c), KCL at point c gives ica=I2-I1; // superimposing the currents of above results current in three portion of winding can be known icd=ica; disp('current in section cd of winding is') printf('%f A\n',icd); ibc=I1; disp('current in section bc of winding is') printf('%f A\n',ibc); iab=idb+I1; disp('current in section ab of winding is') printf('%f A\n',iab);
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function [x,y,typ] = mdaq_dac(job,arg1,arg2) dac_desc = ["This block sets MicroDAQ analog outputs (AO)."; "DAC block allows to set terminate voltage which will be set at"; "the end of simulation in Ext mode."; ""; "User can use option Terminate all DACs with voltage to set"; "same voltage at all DAC channels. Without selecting this option"; "user can define different terminate voltages for DAC channel."; ""; "input(1) - input value in volts" ""; "Converter:"; " DAC01 - 8 channel, 12-bit, 0-5V range"; " DAC02 - 8 channel, 12-bit, ±10V range"; " DAC03 - 8 channel, 16-bit, ±10V range"; ""; "Mode:"; " 1 - Sequential"; " 2 - Simultaneous"; ""; "Set block parameters:"]; x=[];y=[];typ=[]; select job case 'set' then x=arg1 model=arg1.model; graphics=arg1.graphics; exprs=graphics.exprs; while %t do try getversion('scilab'); [ok,converter_str,channel,dac_mode,term_value,exprs]=.. scicos_getvalue(dac_desc,.. ['Converter:'; 'Channels:'; 'Mode:'; 'Termination value:'],.. list('str',1,'vec',-1,'vec',1,'vec',-1),exprs) catch [ok,converter_str,channel,dac_mode,term_value,exprs]=.. scicos_getvalue(dac_desc,.. ['Converter:'; 'Channels:'; 'Mode:'; 'Termination value:'],.. list('str',1,'vec',-1,'vec',1,'vec',-1),exprs) end; if ~ok then break end converter_str = convstr(converter_str, 'l'); converter = strtod(part(converter_str, 4:5)); if isnan(converter) == %t | part(converter_str, 1:3) <> "dac" then ok = %f; message("Wrong DAC converter selected!"); end if converter > 3 | converter < 1 then ok = %f; message("Wrong DAC converter selected!"); end n_channels = size(channel); if n_channels(2) > 8 then ok = %f; error_msg = 'Too many channels selected for DAC0' + string(converter) + '!'; message(error_msg); end if max(channel) > 8 | min(channel) < 1 then ok = %f; error_msg = 'Wrong channel number selected for DAC0' + string(converter) + '!'; message(error_msg); end if dac_mode > 2 | dac_mode < 1 then ok = %f; message("Wrong mode selected, use 1 or 2!"); end if ok then n_channels = size(channel); n_term_value = size(term_value); if n_term_value(2) > 1 then if n_term_value(2) <> n_channels(2) then message('Set termination value for selected channels or set one value which will be used for all channels!') ok = %f; end term_value = term_value'; else term_value(1:8) = term_value; end end if ok then [model,graphics,ok] = check_io(model,graphics, n_channels(2), [], 1, []); graphics.exprs = exprs; model.rpar = [8; term_value]; model.ipar = [converter;dac_mode;n_channels(2);channel']; model.dstate = []; x.graphics = graphics; x.model = model; break end end case 'define' then converter=1 converter_str = []; channel=1 term_value=0 dac_mode=1 model=scicos_model() model.sim=list('mdaq_dac_sim',5) model.in =1 model.in2=1 model.intyp=1 model.out=[] model.evtin=1 model.rpar = [1; term_value]; model.ipar = [converter;dac_mode;1;channel']; model.dstate=[]; model.blocktype='d' model.dep_ut=[%t %f] exprs=["DAC01";sci2exp(channel);sci2exp(dac_mode);sci2exp(term_value)] gr_i=['xstringb(orig(1),orig(2),[''CH:'' ; string(channel)],sz(1),sz(2),''fill'');'] x=standard_define([4 3],model,exprs,gr_i) x.graphics.in_implicit=[]; x.graphics.exprs=exprs; x.graphics.style=["blockWithLabel;verticalLabelPosition=center;displayedLabel=CH:%2$s;fontColor=#5f5f5f"] end endfunction
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//Variable declaration: D = 5 //Diameter of pipe (ft) V = 10 //Fluid velocity (ft/s) p = 50 //Fluid density (lb/ft^3) u = 0.65 //Fluid viscosity (lb/ft.s) F = 1.0/12.0 //Feet in an inch VCp = 6.72*10**-4 //Viscosity of centipoise (lb/ft.s) //Calculation: A = D*V*p*F/u/VCp //Reynolds Number //Result: if(A>2100) then printf("The Reynolds number is :%.0f therefore, the flow is turbulent.",A) else if(A<2100) then printf("The Reynolds number is : %f therefore, the flow is not turbulent.",A) end end;
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clear; clc; // Illustration 3.2 // Page: 56 printf('Illustration 3.2 - Page: 56\n\n'); // solution //***Data****// d = 0.025;// [m] avg_velocity = 3;// [m/s] viscosity = 8.937*10^(-4);// [kg/m.s] density = 997;// [kg/m^3] //*********// kinematic_viscosity = viscosity/density;// [square m/s] Re = d*avg_velocity*density/viscosity; // Reynold's number comes out to be 83670 // At this Reynold's number fanning factor = 0.0047 f = 0.0047; L = 1;// [m] press_drop = 2*density*f*L*(avg_velocity^2)/(d);// [N/square m] P = 3.141*(d^2)*avg_velocity*press_drop/4;// [N.m/s] for 1m pipe m = 3.141*(d^2)*L*density/4; // From Eqn. 3.24 Ld = ((kinematic_viscosity^3)*m/P)^(1/4);// [m] // From Eqn. 3.25 Ud = (kinematic_viscosity*P/m)^(1/4);// [m/s] printf('Velocity of small eddies is %f m/s\n',Ud); printf('Length scale of small eddies is %e m',Ld);
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G = zeros(3,3) d = [1 0 0]' x0 = [1 0 0]' for i=1:3 for j=1:3 if i==j then G(i,j) = 1/2 end if abs(i-j) == 1 then G(i,j) = 1/4 end end end cu = 0 x1 = 0 cont = 0 while cu~=69 x1 = G*x0+d if norm((x0-x1),1) < 10^(-2) then cu = 69 end x0 = x1 cont = cont + 1 end disp(cont)
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Scilab
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ex12_6.sce
// Network Synthesis : example 12.6 : (pg 12.4) s=poly(0,'s'); p1=((2*(s^4))+(6*(s)^2)+1); p2=((5*(s^3))+(3*s)); [r,q]=pdiv(p1,p2); [r1,q1]=pdiv(p2,r); [r2,q2]=pdiv(r,r1); [r3,q3]=pdiv(r1,r2); printf("\nEven part of P(s) = ((2*s^4)+(6*(s)^2)+1)"); printf("\nOdd part of P(s) = ((5*s^3)+(3*s))"); printf("\nQ(s)= m(s)/n(s)"); // values of quotients in continued fraction expansion disp(q); disp(q1); disp(q2); disp(q3); printf("\nSince all the quotient terms are positive, P(s) is hurwitz");
cc6e79ffed072ea5647788e2beab26de05f4586a
931df7de6dffa2b03ac9771d79e06d88c24ab4ff
/Juggling Aimer.sce
616a085dc88950ca31d4df4e4b59f52b3fd97398
[]
no_license
MBHuman/Scenarios
be1a722825b3b960014b07cda2f12fa4f75c7fc8
1db6bfdec8cc42164ca9ff57dd9d3c82cfaf2137
refs/heads/master
2023-01-14T02:10:25.103083
2020-11-21T16:47:14
2020-11-21T16:47:14
null
0
0
null
null
null
null
UTF-8
Scilab
false
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161,354
sce
Juggling Aimer.sce
Name=Juggling Aimer PlayerCharacters=Juggler BotCharacters=Juggling Ball.bot IsChallenge=true Timelimit=60.0 PlayerProfile=Juggler AddedBots=Juggling Ball.bot;Juggling Ball.bot;Juggling Ball.bot PlayerMaxLives=1 BotMaxLives=0;0;0 PlayerTeam=1 BotTeams=2;2;2 MapName=juggling_arena.map MapScale=1.0 BlockProjectilePredictors=true BlockCheats=true InvinciblePlayer=false InvincibleBots=false Timescale=1.0 BlockHealthbars=true TimeRefilledByKill=0.0 ScoreToWin=1.0 ScorePerDamage=1.0 ScorePerKill=0.0 ScorePerMidairDirect=0.0 ScorePerAnyDirect=0.0 ScorePerTime=0.0 ScoreLossPerDamageTaken=0.1 ScoreLossPerDeath=0.0 ScoreLossPerMidairDirected=0.0 ScoreLossPerAnyDirected=0.0 ScoreMultAccuracy=false ScoreMultDamageEfficiency=false ScoreMultKillEfficiency=false GameTag=Fun WeaponHeroTag= DifficultyTag=4 AuthorsTag=pleasewait BlockHitMarkers=false BlockHitSounds=false BlockMissSounds=true BlockFCT=true Description=Entertain audience with your aim. GameVersion=1.0.7.2 ScorePerDistance=0.0 [Aim Profile] Name=Default MinReactionTime=0.3 MaxReactionTime=0.4 MinSelfMovementCorrectionTime=0.001 MaxSelfMovementCorrectionTime=0.05 FlickFOV=30.0 FlickSpeed=1.5 FlickError=15.0 TrackSpeed=3.5 TrackError=3.5 MaxTurnAngleFromPadCenter=75.0 MinRecenterTime=0.3 MaxRecenterTime=0.5 OptimalAimFOV=30.0 OuterAimPenalty=1.0 MaxError=40.0 ShootFOV=15.0 VerticalAimOffset=0.0 MaxTolerableSpread=5.0 MinTolerableSpread=1.0 TolerableSpreadDist=2000.0 MaxSpreadDistFactor=2.0 [Bot Profile] Name=Juggling Ball DodgeProfileNames= DodgeProfileWeights= DodgeProfileMaxChangeTime=5.0 DodgeProfileMinChangeTime=1.0 WeaponProfileWeights=1.0;1.0;1.0;1.0;1.0;1.0;1.0;1.0 AimingProfileNames=Default;Default;Default;Default;Default;Default;Default;Default WeaponSwitchTime=60.0 UseWeapons=false CharacterProfile=Juggling Ball SeeThroughWalls=false NoDodging=true NoAiming=false [Character Profile] Name=Juggler MaxHealth=1.0 WeaponProfileNames=Juggler;;;;;;; MinRespawnDelay=0.000001 MaxRespawnDelay=0.000001 StepUpHeight=160.0 CrouchHeightModifier=0.5 CrouchAnimationSpeed=1.0 CameraOffset=X=0.000 Y=0.000 Z=72.000 HeadshotOnly=false DamageKnockbackFactor=0.0 MovementType=Base MaxSpeed=0.0 MaxCrouchSpeed=1600.0 Acceleration=9000.0 AirAcceleration=16000.0 Friction=6.0 BrakingFrictionFactor=6.0 JumpVelocity=2700.0 Gravity=10.0 AirControl=0.1 CanCrouch=true CanPogoJump=true CanCrouchInAir=true CanJumpFromCrouch=true EnemyBodyColor=X=1.000 Y=0.000 Z=0.000 EnemyHeadColor=X=1.000 Y=1.000 Z=1.000 TeamBodyColor=X=0.000 Y=0.000 Z=1.000 TeamHeadColor=X=1.000 Y=1.000 Z=1.000 BlockSelfDamage=false InvinciblePlayer=false InvincibleBots=false BlockTeamDamage=false AirJumpCount=0 AirJumpVelocity=0.0 MainBBType=Cylindrical MainBBHeight=72.0 MainBBRadius=36.0 MainBBHasHead=false MainBBHeadRadius=16.0 MainBBHeadOffset=0.0 MainBBHide=false ProjBBType=Cylindrical ProjBBHeight=72.0 ProjBBRadius=36.0 ProjBBHasHead=false ProjBBHeadRadius=16.0 ProjBBHeadOffset=0.0 ProjBBHide=true HasJetpack=false JetpackActivationDelay=0.2 JetpackFullFuelTime=4.0 JetpackFuelIncPerSec=1.0 JetpackFuelRegensInAir=false JetpackThrust=6000.0 JetpackMaxZVelocity=400.0 JetpackAirControlWithThrust=0.25 AbilityProfileNames=;;; HideWeapon=false AerialFriction=0.0 StrafeSpeedMult=1.0 BackSpeedMult=1.0 RespawnInvulnTime=0.0 BlockedSpawnRadius=0.0 BlockSpawnFOV=0.0 BlockSpawnDistance=0.0 RespawnAnimationDuration=0.0 AllowBufferedJumps=true BounceOffWalls=false LeanAngle=0.0 LeanDisplacement=0.0 AirJumpExtraControl=0.0 ForwardSpeedBias=1.0 HealthRegainedonkill=0.0 HealthRegenPerSec=0.0 HealthRegenDelay=0.0 JumpSpeedPenaltyDuration=0.0 JumpSpeedPenaltyPercent=0.0 ThirdPersonCamera=false TPSArmLength=300.0 TPSOffset=X=0.000 Y=150.000 Z=150.000 BrakingDeceleration=2048.0 VerticalSpawnOffset=0.0 [Character Profile] Name=Juggling Ball MaxHealth=10000.0 WeaponProfileNames=;;;;;;; MinRespawnDelay=0.000001 MaxRespawnDelay=0.000001 StepUpHeight=0.0 CrouchHeightModifier=0.5 CrouchAnimationSpeed=2.0 CameraOffset=X=0.000 Y=0.000 Z=0.000 HeadshotOnly=false DamageKnockbackFactor=0.0 MovementType=Base MaxSpeed=200.0 MaxCrouchSpeed=500.0 Acceleration=9000.0 AirAcceleration=16000.0 Friction=4.0 BrakingFrictionFactor=2.0 JumpVelocity=0.0 Gravity=0.375 AirControl=0.0 CanCrouch=true CanPogoJump=false CanCrouchInAir=true CanJumpFromCrouch=false EnemyBodyColor=X=1.000 Y=0.000 Z=0.000 EnemyHeadColor=X=1.000 Y=1.000 Z=1.000 TeamBodyColor=X=0.000 Y=0.000 Z=1.000 TeamHeadColor=X=1.000 Y=1.000 Z=1.000 BlockSelfDamage=false InvinciblePlayer=false InvincibleBots=false BlockTeamDamage=false AirJumpCount=0 AirJumpVelocity=0.0 MainBBType=Spheroid MainBBHeight=32.0 MainBBRadius=16.0 MainBBHasHead=false MainBBHeadRadius=0.1 MainBBHeadOffset=0.0 MainBBHide=false ProjBBType=Spheroid ProjBBHeight=32.0 ProjBBRadius=16.0 ProjBBHasHead=false ProjBBHeadRadius=0.1 ProjBBHeadOffset=0.0 ProjBBHide=true HasJetpack=false JetpackActivationDelay=0.000001 JetpackFullFuelTime=100000.0 JetpackFuelIncPerSec=1000.0 JetpackFuelRegensInAir=true JetpackThrust=200.0 JetpackMaxZVelocity=400.0 JetpackAirControlWithThrust=0.0 AbilityProfileNames=Juggling Initial Popup.abilmov;Juggling Popup.abilmov;Kill Player.abilmelee; HideWeapon=true AerialFriction=0.0 StrafeSpeedMult=1.0 BackSpeedMult=1.0 RespawnInvulnTime=0.0 BlockedSpawnRadius=0.0 BlockSpawnFOV=0.0 BlockSpawnDistance=0.0 RespawnAnimationDuration=0.0 AllowBufferedJumps=true BounceOffWalls=false LeanAngle=0.0 LeanDisplacement=0.0 AirJumpExtraControl=0.0 ForwardSpeedBias=1.0 HealthRegainedonkill=0.0 HealthRegenPerSec=0.0 HealthRegenDelay=0.0 JumpSpeedPenaltyDuration=0.0 JumpSpeedPenaltyPercent=0.0 ThirdPersonCamera=false TPSArmLength=300.0 TPSOffset=X=0.000 Y=150.000 Z=150.000 BrakingDeceleration=2048.0 VerticalSpawnOffset=0.0 [Weapon Profile] Name=Juggler Type=Hitscan ShotsPerClick=1 DamagePerShot=1.0 KnockbackFactor=0.0 TimeBetweenShots=0.1 Pierces=false Category=SemiAuto BurstShotCount=1 TimeBetweenBursts=0.5 ChargeStartDamage=10.0 ChargeStartVelocity=X=500.000 Y=0.000 Z=0.000 ChargeTimeToAutoRelease=2.0 ChargeTimeToCap=1.0 ChargeMoveSpeedModifier=1.0 MuzzleVelocityMin=X=6787.000 Y=0.000 Z=0.000 MuzzleVelocityMax=X=6787.000 Y=0.000 Z=0.000 InheritOwnerVelocity=0.0 OriginOffset=X=0.000 Y=0.000 Z=0.000 MaxTravelTime=5.0 MaxHitscanRange=1000000.0 GravityScale=0.0 HeadshotCapable=false HeadshotMultiplier=2.0 MagazineMax=1 AmmoPerShot=1 ReloadTimeFromEmpty=0.5 ReloadTimeFromPartial=0.5 DamageFalloffStartDistance=1000000.0 DamageFalloffStopDistance=1000000.0 DamageAtMaxRange=1.0 DelayBeforeShot=0.0 HitscanVisualEffect=None ProjectileGraphic=Rocket VisualLifetime=0.1 WallParticleEffect=None HitParticleEffect=None BounceOffWorld=false BounceFactor=0.0 BounceCount=0 HomingProjectileAcceleration=0.0 ProjectileEnemyHitRadius=2.0 CanAimDownSight=false ADSZoomDelay=0.0 ADSZoomSensFactor=0.7 ADSMoveFactor=1.0 ADSStartDelay=0.0 ShootSoundCooldown=0.01 HitSoundCooldown=0.01 HitscanVisualOffset=X=0.000 Y=0.000 Z=0.000 ADSBlocksShooting=false ShootingBlocksADS=false KnockbackFactorAir=0.0 RecoilNegatable=false DecalType=0 DecalSize=30.0 DelayAfterShooting=0.0 BeamTracksCrosshair=false AlsoShoot= ADSShoot= StunDuration=0.0 CircularSpread=true SpreadStationaryVelocity=0.0 PassiveCharging=false BurstFullyAuto=true FlatKnockbackHorizontal=0.0 FlatKnockbackVertical=0.0 HitscanRadius=0.0 HitscanVisualRadius=6.0 TaggingDuration=0.0 TaggingMaxFactor=0.0 TaggingHitFactor=1.0 ProjectileTrail=Smoke RecoilCrouchScale=1.0 RecoilADSScale=1.0 PSRCrouchScale=1.0 PSRADSScale=1.0 ProjectileAcceleration=0.0 AccelIncludeVertical=true AimPunchAmount=0.0 AimPunchResetTime=0.1 AimPunchCooldown=0.5 AimPunchHeadshotOnly=false AimPunchCosmeticOnly=true MinimumDecelVelocity=0.0 PSRManualNegation=false PSRAutoReset=true AimPunchUpTime=0.05 AmmoReloadedOnKill=0 CancelReloadOnKill=false FlatKnockbackHorizontalMin=0.0 FlatKnockbackVerticalMin=0.0 ADSScope=No Scope ADSFOVOverride=90.0 ADSFOVScale=Horizontal (4:3) ADSAllowUserOverrideFOV=true IsBurstWeapon=false ForceFirstPersonInADS=true ZoomBlockedInAir=false ADSCameraOffsetX=0.0 ADSCameraOffsetY=0.0 ADSCameraOffsetZ=0.0 QuickSwitchTime=0.1 Explosive=false Radius=0.1 DamageAtCenter=0.0 DamageAtEdge=0.0 SelfDamageMultiplier=0.0 ExplodesOnContactWithEnemy=true DelayAfterEnemyContact=0.0 ExplodesOnContactWithWorld=false DelayAfterWorldContact=0.0 ExplodesOnNextAttack=false DelayAfterSpawn=0.0 BlockedByWorld=true SpreadSSA=1.0,1.0,-1.0,0.0 SpreadSCA=1.0,1.0,-1.0,0.0 SpreadMSA=1.0,1.0,-1.0,0.0 SpreadMCA=1.0,1.0,-1.0,0.0 SpreadSSH=1.0,1.0,-1.0,0.0 SpreadSCH=1.0,1.0,-1.0,0.0 SpreadMSH=1.0,1.0,-1.0,0.0 SpreadMCH=1.0,1.0,-1.0,0.0 MaxRecoilUp=0.0 MinRecoilUp=0.0 MinRecoilHoriz=0.0 MaxRecoilHoriz=0.0 FirstShotRecoilMult=1.0 RecoilAutoReset=false TimeToRecoilPeak=0.05 TimeToRecoilReset=0.35 AAMode=2 AAPreferClosestPlayer=false AAAlpha=0.5 AAMaxSpeed=0.5 AADeadZone=0.0 AAFOV=180.0 AANeedsLOS=true TrackHorizontal=true TrackVertical=true AABlocksMouse=false AAOffTimer=0.0 AABackOnTimer=0.0 TriggerBotEnabled=true TriggerBotDelay=0.001 TriggerBotFOV=1.0 StickyLock=false HeadLock=false VerticalOffset=0.0 DisableLockOnKill=false UsePerShotRecoil=false PSRLoopStartIndex=0 PSRViewRecoilTracking=0.45 PSRCapUp=9.0 PSRCapRight=4.0 PSRCapLeft=4.0 PSRTimeToPeak=0.095 PSRResetDegreesPerSec=40.0 UsePerBulletSpread=false PBS0=0.0,0.0 [Movement Ability Profile] Name=Juggling Initial Popup MaxCharges=1.0 ChargeTimer=0.1 ChargesRefundedOnKill=0.0 DelayAfterUse=0.0 FullyAuto=false AbilityDuration=0.0 LockDirectionForDuration=true NegateGravityForDuration=true MainVelocity=0.0 MainVelocityCanGoVertical=false MainVelocitySetToMovementKeys=false UpVelocity=320.0 EndVelocityFactor=1.0 Hurtbox=false HurtboxRadius=50.0 HurtboxDamage=50.0 HurtboxGroundKnockbackFactor=1.0 HurtboxAirKnockbackFactor=1.0 AbilityBlocksTurning=false AbilityBlocksMovement=true AbilityBlocksAttack=false AttackCancelsAbility=false AbilityReloadsWeapon=false HealthRestore=0.0 AIUseInCombat=true AIUseOutOfCombat=true AIUseOnGround=true AIUseInAir=true AIReuseTimer=60.0 AIMinSelfHealth=100.0 AIMaxSelfHealth=100.0 AIMinTargHealth=0.0 AIMaxTargHealth=100.0 AIMinTargDist=0.0 AIMaxTargDist=1000000.0 AIMaxTargFOV=360.0 AIDamageReaction=false AIDamageReactionIgnoreChance=0.0 AIDamageReactionMinDelay=0.0001 AIDamageReactionMaxDelay=0.001 AIDamageReactionCooldown=0.1 AIDamageReactionThreshold=1.0 AIDamageReactionResetTimer=0.001 [Movement Ability Profile] Name=Juggling Popup MaxCharges=1.0 ChargeTimer=0.1 ChargesRefundedOnKill=0.0 DelayAfterUse=0.0 FullyAuto=false AbilityDuration=0.0 LockDirectionForDuration=true NegateGravityForDuration=true MainVelocity=300.0 MainVelocityCanGoVertical=false MainVelocitySetToMovementKeys=false UpVelocity=280.0 EndVelocityFactor=1.0 Hurtbox=false HurtboxRadius=50.0 HurtboxDamage=50.0 HurtboxGroundKnockbackFactor=1.0 HurtboxAirKnockbackFactor=1.0 AbilityBlocksTurning=false AbilityBlocksMovement=true AbilityBlocksAttack=false AttackCancelsAbility=false AbilityReloadsWeapon=false HealthRestore=0.0 AIUseInCombat=true AIUseOutOfCombat=false AIUseOnGround=false AIUseInAir=true AIReuseTimer=0.1 AIMinSelfHealth=0.0 AIMaxSelfHealth=100.0 AIMinTargHealth=0.0 AIMaxTargHealth=100.0 AIMinTargDist=0.0 AIMaxTargDist=0.0 AIMaxTargFOV=360.0 AIDamageReaction=true AIDamageReactionIgnoreChance=0.0 AIDamageReactionMinDelay=0.1 AIDamageReactionMaxDelay=0.1 AIDamageReactionCooldown=0.1 AIDamageReactionThreshold=1.0 AIDamageReactionResetTimer=0.1 [Melee Ability Profile] Name=Kill Player MaxCharges=1.0 ChargeTimer=0.1 ChargesRefundedOnKill=0.0 DelayAfterUse=0.0 FullyAuto=false AbilityDuration=1.0 HurtboxRadius=4000.0 HurtboxDamage=1.0 HurtboxGroundKnockbackFactor=0.0 HurtboxAirKnockbackFactor=0.0 BlockAttackTimer=0.0 AbilityBlockedWhenAttacking=false AmmoPerShot=0 FlatKnockbackHorizontal=0.0 FlatKnockbackVertical=0.0 FlatKnockbackHorizontalMin=0.0 FlatKnockbackVerticalMin=0.0 AIUseInCombat=true AIUseOutOfCombat=true AIUseOnGround=true AIUseInAir=false AIReuseTimer=0.1 AIMinSelfHealth=0.0 AIMaxSelfHealth=100.0 AIMinTargHealth=0.0 AIMaxTargHealth=100.0 AIMinTargDist=0.0 AIMaxTargDist=8000.0 AIMaxTargFOV=360.0 AIDamageReaction=false AIDamageReactionIgnoreChance=0.0 AIDamageReactionMinDelay=0.125 AIDamageReactionMaxDelay=0.25 AIDamageReactionCooldown=1.0 AIDamageReactionThreshold=0.0 AIDamageReactionResetTimer=0.1 [Map Data] reflex map version 8 global entity type WorldSpawn String32 targetGameOverCamera end Float sky.timeOfDay 13.000000 ColourXRGB32 sky.sunColor ffffde8c Float sky.sunIntensitySize 64.000000 Float sky.sunSharpness 128.000000 Bool8 sky.sunEnabled 0 ColourXRGB32 sky.horizonColor fffff4b5 Float sky.horizonIntensity 0.250000 Float sky.horizonHaloExponentSunIntensity 0.300000 ColourXRGB32 sky.cloudsColor ffffffff Float sky.cloudsCoverage 0.500000 Float sky.cloudsCoverageMultiplier 24.000000 Float sky.cloudsRoughness 0.400000 UInt8 playersMin 1 UInt8 playersMax 16 Bool8 modeFFA 0 brush 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clc //initialization of new variables clear u=12 //m/s w=10 //m L=4 //m rho=1.22 //kg/m^3 mu=1.8*10^-5 //calculations ReL=rho*u*L/mu Cd=0.0032 //from figure D=2*Cd*1/2*rho*u^2*(w*L) //results printf('Total drag on plates is %.2f N',D)
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//calculation of nuclear binding energy clear; clc; printf("\t Example 23.2\n"); NA=6.022*10^23;//avogadro number c=3*10^8;//speed of light, m/s p=1.007825;//mass of proton, amu n=1.008665;//mass of neutron, amu mI=126.9004;//atomic mass of I, amu pI=53*p+74*n;//estimated mass of I, amu deltam=mI-pI;//mass defect, amu deltaE=-deltam*c^2;//energy released, amu m^2/s^2 deltaE=deltaE/(NA*1000);//energy released in J deltaE=deltaE/127;//binding energy per nucleon, J printf("\t the nuclear binding energy per nucleon is : %4.2f *10^-12 J/nucleon\n",deltaE*10^12); //End
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//Eg-8.3 //pg-369 clear clc A = [2 3 1 4 5]; n = length(A); for(i = 2:n) t = A(i); j = i; while((j > 1) & (A(j-1) > t)) A(j) = A(j-1); j = j-1; end A(j) = t; end printf('Using the insertion sort method the arranged form of the given array\n') disp(A)
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//Initilization of variables P=[4.82, -2.33, 5.47] //N Q=[-2.81,-6.09,1.12 ] //m //Calculations M=P*Q' //Nm //Results clc printf('Result is:%f N.m',M) //N-m
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syms G1 G2 G3 G4 G5 H5 //with X(s)=0 a= G2/(G2+1) b= a*G3*(G5/(1+G5*H5)) //G5 and H5 are in a loop c= b/(1+b) //unity feedback Y= G1*c disp(Y,"R/S=") //with R(s)=0 x=G2/(1+G2) y=G5/(1+G5*H5) z=x*(-G3) Y2=y/(1-(z)) disp(Y2,"X/C = ")
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3
12
null
null
null
null
UTF-8
Scilab
false
false
483
sce
11_8.sce
clear; clc; //Example - 11.8 //Page number - 394 printf("Example - 11.8 and Page number - 394\n\n"); //This problem involves proving a relation in which no mathematics and no calculations are involved. //For prove refer to this example 11.8 on page number 394 of the book. printf(" This problem involves proving a relation in which no mathematics and no calculations are involved.\n\n"); printf(" For prove refer to this example 11.8 on page number 394 of the book.")
c377ec3c338faf89f1a8ef395c4143e6eb99c631
089894a36ef33cb3d0f697541716c9b6cd8dcc43
/NLP_Project/test/tweet/bow/bow.14_16.tst
f2f9578027e2d3b79a31396a44e3088dfd4060e0
[]
no_license
mandar15/NLP_Project
3142cda82d49ba0ea30b580c46bdd0e0348fe3ec
1dcb70a199a0f7ab8c72825bfd5b8146e75b7ec2
refs/heads/master
2020-05-20T13:36:05.842840
2013-07-31T06:53:59
2013-07-31T06:53:59
6,534,406
0
1
null
null
null
null
UTF-8
Scilab
false
false
43,648
tst
bow.14_16.tst
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/2258/CH1/EX1.14/1_14.sce
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clc(); clear; // To calculate the wavelength of an electron V=10; //potential in kV V=V*10^3; //potential in V lamda=12.26/sqrt(V); //wavelength printf("The wavelength is %f Armstrong",lamda);
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//caption:stability_using_Routh-hurwitz_criterion //example 7.5.3 //page 203 s=%s; A=s^5+4*1.5*s^4+4*s^3+4*s^2+5*s+10; C=2*s+5; CL=A/C; disp(CL,"C(s)/R(s)="); disp('=0',A,"characteristics eq is:") b=coeff(A) n=length(b) B=routh_t(A) disp(B,"routh table:"); c=0; r=1; for(i=1:n) if(B(i,1)<0) c=c+1; if(i==n & B(n,1)<0) r=r; else r=r+1; end end end if(c>=1) printf("system is unstable\n"); else("system is stable " ); end mprintf('no. of roots with positive real parts=%d',r);
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clc //Initialization of variables Q=0.6 //m^3/s l1=1200 //m l2=800 //m d1=0.3 //m //calculations V1=1.02 //m/s d5= d1*l2*4^2 *Q^2 /(l1*%pi^2 *V1^2) d=d5^(1/5) //results printf("diameter of the single pipe = %.2f m",d)
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// Exercise A19 // ------------ // Find the relative and absolute error of // n! ~ sqrt(2·Pi·n)·(n/e)^n // for n = 1, ..., 10 MIN = 1 MAX = 10 STEP = 1 for n = MIN : STEP : MAX orig_val = factorial(n) appr_val = sqrt(2 * %pi * n) * (n / %e)^n abs_err = abs(orig_val - appr_val) rel_err = abs(abs_err / orig_val) per_err = rel_err * 100 printf('input %d\n' , n) printf('value %d\n' , orig_val) printf('approximation %f\n' , appr_val) printf('absolute error %f\n' , abs_err) printf('relative error %f\n' , rel_err) printf('percent error %.2f%%\n', per_err) printf('------------------------------------------\n') end // Results and Commentary // ---------------------- // As 'n' increases the absolute error ('abs_err') increases. // As 'n' increases the relative error ('rel_err') decreases. // // This means that as 'n' increases the magnitude between the exact // value and the approximation increases, but, the affect of the // difference lowers, as that magnitude becomes lesser important in // comparison to the value. // In other words, as 'n' increases, the magnitude between the exact // and approximation value increases, but the pace with which that // happens is much slower to the pace that the actual value increases, // and slows down as the input increases, which in turn means that the // magnitude becomes irrelevant for some big enough input. // // Output: // > input 1 // > value 1 // > approximation 0.922137 // > absolute error 0.077863 // > relative error 0.077863 // > percent error 7.79% // > ------------------------------------------ // > input 2 // > value 2 // > approximation 1.919004 // > absolute error 0.080996 // > relative error 0.040498 // > percent error 4.05% // > ------------------------------------------ // > input 3 // > value 6 // > approximation 5.836210 // > absolute error 0.163790 // > relative error 0.027298 // > percent error 2.73% // > ------------------------------------------ // > input 4 // > value 24 // > approximation 23.506175 // > absolute error 0.493825 // > relative error 0.020576 // > percent error 2.06% // > ------------------------------------------ // > input 5 // > value 120 // > approximation 118.019168 // > absolute error 1.980832 // > relative error 0.016507 // > percent error 1.65% // > ------------------------------------------ // > input 6 // > value 720 // > approximation 710.078185 // > absolute error 9.921815 // > relative error 0.013780 // > percent error 1.38% // > ------------------------------------------ // > input 7 // > value 5040 // > approximation 4980.395832 // > absolute error 59.604168 // > relative error 0.011826 // > percent error 1.18% // > ------------------------------------------ // > input 8 // > value 40320 // > approximation 39902.395453 // > absolute error 417.604547 // > relative error 0.010357 // > percent error 1.04% // > ------------------------------------------ // > input 9 // > value 362880 // > approximation 359536.872842 // > absolute error 3343.127158 // > relative error 0.009213 // > percent error 0.92% // > ------------------------------------------ // > input 10 // > value 3628800 // > approximation 3598695.618741 // > absolute error 30104.381259 // > relative error 0.008296 // > percent error 0.83% // > ------------------------------------------
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.341965D+00 2 -0.443009D-02 0.277191D-02 3 0.195323D-01 -0.413884D-03 0.263918D+00 4 -0.523284D-03 0.112841D-03 -0.216062D-02 0.212927D-02 5 -0.106700D-03 -0.800021D-04 -0.786954D-03 -0.895598D-04 0.245779D-02 6 0.101048D-02 -0.193810D-03 0.889938D-03 -0.114456D-04 0.174791D-03 7 0.594548D-03 -0.798593D-04 0.889605D-03 0.329524D-04 -0.419300D-04 8 0.137761D-02 -0.425104D-05 0.284417D-03 -0.371258D-04 -0.972349D-04 9 -0.560185D+00 0.234000D-01 -0.111705D+00 0.630314D-02 0.167589D+00 10 -0.111955D+00 -0.109439D-01 0.101776D+00 -0.345664D-02 0.139210D+00 11 -0.514904D-01 0.538791D-02 -0.809156D-01 0.125061D-01 0.103087D-01 12 0.207775D+00 -0.690080D-02 0.178449D+00 -0.326363D-02 -0.166014D-01 13 -0.277616D-01 -0.325932D-02 0.764072D-01 -0.262558D-02 -0.510919D-02 14 -0.504811D-02 0.799072D-02 0.232349D+00 0.537665D-02 -0.187395D-01 15 -0.167605D+01 -0.605703D-01 -0.307438D+00 0.999638D-02 -0.126313D+00 16 -0.408355D-01 -0.259442D-02 0.100201D-01 -0.302067D-02 0.236412D-02 17 0.805429D-02 0.323875D-03 -0.145376D-03 0.296243D-03 -0.643983D-03 18 0.182326D-02 -0.742874D-02 -0.650047D+00 -0.590867D-01 0.399277D-01 19 -0.792052D-01 0.109096D-01 0.949837D-01 -0.257646D-02 -0.164047D-01 20 -0.411652D+00 -0.523959D-02 0.325117D+00 0.161170D-01 0.246015D-01 21 0.129332D+00 -0.167938D-01 -0.126746D+00 0.119389D-02 0.145511D-01 22 -0.387131D-02 0.341727D-03 0.341178D-02 0.394174D-03 -0.817745D-04 23 -0.554412D-02 -0.160529D-02 0.229192D-01 0.264397D-02 0.343711D-03 24 0.213061D-03 0.116882D-03 0.181437D-03 0.207793D-03 -0.227759D-03 ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 6 7 8 9 10 ________ ________ ________ ________ ________ 6 0.146067D-02 7 0.661299D-03 0.129462D-02 8 -0.256452D-03 0.393416D-04 0.252066D-02 9 -0.980804D-03 0.200785D-01 0.654142D-02 0.108848D+03 10 0.233569D-01 -0.391744D-02 -0.262622D-02 0.111003D+02 0.227003D+02 11 0.152396D-01 0.196053D-01 0.121693D-01 -0.919743D+00 0.965078D+00 12 -0.117740D-01 -0.585040D-02 0.800413D-01 0.271523D+01 -0.101118D+01 13 0.440453D-01 0.389471D-01 -0.675424D-02 0.981774D+00 0.176171D+00 14 -0.226474D-01 -0.141247D-01 0.126258D+00 0.144929D+00 0.649000D-01 15 -0.348858D-01 -0.206449D-01 0.599938D-01 -0.162222D+02 -0.141025D+02 16 0.109510D-02 0.869370D-03 -0.150540D-03 0.168110D+01 0.428573D-01 17 -0.537765D-04 0.489850D-04 -0.251465D-03 -0.319644D+00 -0.415517D-01 18 -0.338493D-01 -0.488762D-01 0.392181D-01 0.215076D+00 0.394035D+01 19 -0.595311D-02 0.109469D-01 0.351272D-02 -0.577040D+00 -0.144008D+01 20 0.263073D-01 0.529334D-01 -0.106077D+00 0.150077D+01 0.420987D+01 21 0.489169D-02 -0.103789D-01 -0.284721D-02 0.388689D+00 0.145035D+01 22 -0.261786D-03 -0.190765D-03 -0.237485D-03 -0.942320D-02 -0.394458D-01 23 0.114619D-03 -0.495045D-03 0.102481D-03 0.277930D+00 -0.739828D-02 24 0.229455D-04 -0.168218D-03 -0.338861D-03 -0.557811D-01 -0.987848D-02 ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 11 12 13 14 15 ________ ________ ________ ________ ________ 11 0.241308D+02 12 0.580751D+00 0.424476D+02 13 -0.434868D+00 0.646139D+00 0.652965D+01 14 0.146153D+01 0.149333D+01 -0.190088D+01 0.207091D+02 15 0.342173D+01 0.347039D+01 0.134828D+01 0.622056D+01 0.298249D+03 16 -0.101165D+00 -0.215186D+00 0.268017D-01 -0.723159D-01 0.244288D+01 17 0.400439D-02 -0.115201D-02 -0.337759D-02 -0.236215D-01 -0.140419D+01 18 -0.370111D+01 0.276808D+01 -0.221474D+01 0.258674D+01 0.351084D+02 19 0.156907D+01 0.466580D+00 0.104907D+00 0.176407D+00 0.426549D+01 20 -0.182103D+01 -0.163847D+02 0.230367D+01 -0.889262D+01 0.132159D+02 21 -0.102509D+01 -0.411280D+00 -0.105412D+00 0.447234D-01 -0.381952D+01 22 -0.347966D-01 -0.338707D-01 -0.193747D-01 -0.155427D-01 -0.262836D+00 23 -0.113474D-01 0.185912D+00 0.366838D-01 -0.392929D-01 0.257144D-01 24 -0.574328D-02 -0.171855D-01 0.409852D-02 -0.310187D-01 -0.106287D+00 ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 16 17 18 19 20 ________ ________ ________ ________ ________ 16 0.566912D+00 17 -0.515617D-01 0.180769D-01 18 0.284875D+00 -0.286699D+00 0.154951D+03 19 0.130827D+00 -0.311237D-01 -0.868581D+00 0.418241D+01 20 0.392344D+00 -0.100539D+00 0.113279D+02 0.255246D+01 0.170058D+03 21 0.937123D-02 0.980066D-02 0.327134D+01 -0.379323D+01 -0.334955D+01 22 -0.112304D-01 0.375423D-02 -0.748032D+00 -0.509693D-02 -0.100563D+00 23 0.901251D-02 -0.211792D-02 -0.612072D+00 -0.838946D-02 0.116632D+01 24 -0.440907D-02 0.946428D-03 -0.134671D+00 -0.356834D-02 -0.789962D+00 ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 21 22 23 24 ________ ________ ________ ________ 21 0.434565D+01 22 -0.362520D-01 0.804120D-02 23 -0.811804D-02 0.269085D-02 0.214620D+00 24 0.442963D-02 0.144318D-02 -0.157395D-01 0.809521D-02 ESTIMATED CORRELATION MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 1.000 2 -0.144 1.000 3 0.065 -0.015 1.000 4 -0.019 0.046 -0.091 1.000 5 -0.004 -0.031 -0.031 -0.039 1.000 6 0.045 -0.096 0.045 -0.006 0.092 7 0.028 -0.042 0.048 0.020 -0.024 8 0.047 -0.002 0.011 -0.016 -0.039 9 -0.092 0.043 -0.021 0.013 0.324 10 -0.040 -0.044 0.042 -0.016 0.589 11 -0.018 0.021 -0.032 0.055 0.042 12 0.055 -0.020 0.053 -0.011 -0.051 13 -0.019 -0.024 0.058 -0.022 -0.040 14 -0.002 0.033 0.099 0.026 -0.083 15 -0.166 -0.067 -0.035 0.013 -0.148 16 -0.093 -0.065 0.026 -0.087 0.063 17 0.102 0.046 -0.002 0.048 -0.097 18 0.000 -0.011 -0.102 -0.103 0.065 19 -0.066 0.101 0.090 -0.027 -0.162 20 -0.054 -0.008 0.049 0.027 0.038 21 0.106 -0.153 -0.118 0.012 0.141 22 -0.074 0.072 0.074 0.095 -0.018 23 -0.020 -0.066 0.096 0.124 0.015 24 0.004 0.025 0.004 0.050 -0.051 ESTIMATED CORRELATION MATRIX FOR PARAMETER ESTIMATES 6 7 8 9 10 ________ ________ ________ ________ ________ 6 1.000 7 0.481 1.000 8 -0.134 0.022 1.000 9 -0.002 0.053 0.012 1.000 10 0.128 -0.023 -0.011 0.223 1.000 11 0.081 0.111 0.049 -0.018 0.041 12 -0.047 -0.025 0.245 0.040 -0.033 13 0.451 0.424 -0.053 0.037 0.014 14 -0.130 -0.086 0.553 0.003 0.003 15 -0.053 -0.033 0.069 -0.090 -0.171 16 0.038 0.032 -0.004 0.214 0.012 17 -0.010 0.010 -0.037 -0.228 -0.065 18 -0.071 -0.109 0.063 0.002 0.066 19 -0.076 0.149 0.034 -0.027 -0.148 20 0.053 0.113 -0.162 0.011 0.068 21 0.061 -0.138 -0.027 0.018 0.146 22 -0.076 -0.059 -0.053 -0.010 -0.092 23 0.006 -0.030 0.004 0.058 -0.003 24 0.007 -0.052 -0.075 -0.059 -0.023 ESTIMATED CORRELATION MATRIX FOR PARAMETER ESTIMATES 11 12 13 14 15 ________ ________ ________ ________ ________ 11 1.000 12 0.018 1.000 13 -0.035 0.039 1.000 14 0.065 0.050 -0.163 1.000 15 0.040 0.031 0.031 0.079 1.000 16 -0.027 -0.044 0.014 -0.021 0.188 17 0.006 -0.001 -0.010 -0.039 -0.605 18 -0.061 0.034 -0.070 0.046 0.163 19 0.156 0.035 0.020 0.019 0.121 20 -0.028 -0.193 0.069 -0.150 0.059 21 -0.100 -0.030 -0.020 0.005 -0.106 22 -0.079 -0.058 -0.085 -0.038 -0.170 23 -0.005 0.062 0.031 -0.019 0.003 24 -0.013 -0.029 0.018 -0.076 -0.068 ESTIMATED CORRELATION MATRIX FOR PARAMETER ESTIMATES 16 17 18 19 20 ________ ________ ________ ________ ________ 16 1.000 17 -0.509 1.000 18 0.030 -0.171 1.000 19 0.085 -0.113 -0.034 1.000 20 0.040 -0.057 0.070 0.096 1.000 21 0.006 0.035 0.126 -0.890 -0.123 22 -0.166 0.311 -0.670 -0.028 -0.086 23 0.026 -0.034 -0.106 -0.009 0.193 24 -0.065 0.078 -0.120 -0.019 -0.673 ESTIMATED CORRELATION MATRIX FOR PARAMETER ESTIMATES 21 22 23 24 ________ ________ ________ ________ 21 1.000 22 -0.194 1.000 23 -0.008 0.065 1.000 24 0.024 0.179 -0.378 1.000
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clear// //Variables VS1 = 5 //Voltage source 1 (in volts) VS2 = 3 //Voltage source 2 (in volts) V6 = 0 //Voltage drop across 6 ohm resistor when AB is open (in volts) R1 = 6 //Resistor (in ohm) R2 = 4 //Resistor (in ohm) //Calculation I = 5.0/4 //Current through 4 ohm resistor (in Ampere) V = I * R2 //Voltage drop across 4 ohm Resistor (in volts) VOC = VS2 + V6 + V //Open circuit voltage (in volts) Rth = R1 //Result printf("\n Thevenins equivalent Voltage is %0.3f V.\nThevenins equivalent resistance is %0.3f ohm.",VOC,Rth)
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//Ex11_7 clc; //Given: density1=11.35;// density of copper l=6.022*10^23;// avogadro constant ue=0.211;// electron absorption coefficent in barn per electron // 1 b=10^(-24) cm^2 //solution: uPb=ue*82;//atomic absorbtion coefficient in b/atom umPb=(6.022*10^23*uPb*10^-24)/207.2; // mass absorbtion coefficient in cm^2/g ulPb=umPb*density1;// linear absorption coefficient in cm^-1 // we know that, i2=i1*exp(ulCu*x) // Case (i) from 0.1 Gy/min to 3.1 mGy/h i1=6;// in Gy/h i2=3.1*10^-3;//in Gy/h x=log(i1/i2)/(ulPb);// thickness of the lead plate printf("\n The thickness of lead nedded to reduce the intensity of the radiation in cm is =%f",x) // Case (ii) from 100 Gy/min to 0.1 mGy/h j1=6000;// in Gy/h j2=0.1*10^-3;// in Gy/h y=log(j1/j2)/(ulPb);// thickness of the lead plate printf("\n \n The thickness of lead nedded to reduce the intensity of the radiation in cm is =%f",y) // Case (iii) half thickness z=(0.693)/ulPb;// thickness of the lead plate printf("\n \n The thickness of lead nedded to reduce the intensity of the radiation in cm is =%f",z)
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function LU(a,n) n = input('nº de equações' ) //matriz for k = 1,n - 1 for i = k + 1,n fator = a(i,k),k/a(k,k) a(i,k) = fator for j = k + 1,n a(i,j) = a(i,j) - fator * a(k,j) end endfunction
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// Exa 9.21 clc; clear; close; format('v',8) // Given data VA = 400*10^3;// in Mean Eta_fl = 98.77/100;// in % phi1= acosd(0.8);// in ° phi2= acosd(1);// in ° Eta_hl = 99.13/100;// in % n = 1/2; //For full load, Eta_f1 = ((VA*cosd(phi1))/( VA*cosd(phi1) + Pi + Pcu_f1 )) or Pi+Pcu_f1 = VA*cosd(phi1)*(1-Eta_fl)/(Eta_f1) (i) //For half load, Eta_hl = n*VA*cosd(phi2)/(n*VA*cosd(phi2)+Pi+n^2*Pcu_f1) or Pi+n^2*Pcu_f1 = n*VA*cosd(phi2)*( 1-Eta_hl)/Eta_hl (ii) // From eq(i) and (ii) Pcu_fl=(n*VA*cosd(phi2)*( 1-Eta_hl)/Eta_hl-VA*cosd(phi1)*(1-Eta_fl)/(Eta_fl))/(n^2-1);// in W Pi=VA*cosd(phi1)*(1-Eta_fl)/(Eta_fl)-Pcu_fl;// in W disp(Pi,"The iron loss on full load and half load remain same in W which are : ") disp(Pcu_fl,"The copper loss on full load in W is : ") // The copper loss on half load C_loss_half_load=n^2*Pcu_fl;// in W disp(C_loss_half_load,"The copper loss on half load in W is : ")
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//Chapter 07: Discrete Probability clc; clear; max_integers=100 E1=100/2 //event that random integer is divisible by 2 E2=100/5 //event that random integer is divisible by 5 E1IE2=100/(5*2) //event that random integer is divisible by 5 and 2 pE1=E1/max_integers //probability of event E1 pE2=E2/max_integers //probability of event E2 pE1IE2=E1IE2/max_integers //probability of event E1IE2 pE1UE2=pE1+pE2-pE1IE2 disp(pE1UE2,'Probability that random integer is divisible by either 2 or 5 is')
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// Scilab code Ex11.1: Pg 380 (2005) clc; clear; // Part (a) f = 1.15e+11; // Frequency of transitions, Hz omega = 2*(%pi)*f; // Angular frequency of absorbed radiations, Hz h_cross = 1.055e-34; // Reduced planks constant, J-s // Since E = (h_cross)^2/I_CM = h_cross*omega, solving for I_CM I_CM = h_cross/omega; // Moment of inertia of molecule about its center of mass, kg-m^2 printf("\nThe moment of inertia of molecule about its center of mass = %4.2e kg-m^2", I_CM); // Part (b) m_O = 16; // Mass of oxygen atom, a.m.u m_C = 12; // Mass of carbon atom, a.m.u mu = ( m_O * m_C *0.166e-26)/(m_O + m_C); // Reduced mass, kg // Since I_CM = mew*R_o^2, solving for R_o R_0 = sqrt(I_CM/mu); // Bond length of carbon monoxide molecule, m printf("\nThe bond length of carbon monoxide molecule = %5.3f nm", R_0/1e-09); // Result // The moment of inertia of molecule about its center of mass = 1.46e-046 kg-m^2 // The bond length of carbon monoxide molecule = 0.113 nm
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//Chapter-5, Example 5.42, Page 209 //============================================================================= clc clear //INPUT DATA V1=400;//voltage in volts Z1=(3+((%i)*4));//impedance in ohms //CALCULATIONS //in star connected system,phase voltage=(line voltage) Ep=V1/(sqrt(3));//voltage in volts Ip=Ep/Z1;//current in A ip1=abs(Ip);//line current in A theta=atan((imag(Ip)/real(Ip))); Pt=sqrt(3)*V1*ip1*cos(theta);//total power consumed in load in W mprintf("Thus total power consumed in load is %f W",Pt); //note:for line current the answer given is 46.02A instead of 46.2 A and hence total power consumed changes //=================================END OF PROGRAM======================================================================================================
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//example 2.14 //aitken's process //page 36 clc,clear,close deff('x=f(x)','x=(3+cos(x))/2'); x0=1.5; y=0; e=0.0001; c=0; printf('successive iterations \tx0\t x1\t x2\t x3\t y\n') for i=1:10 x1=f(x0),x2=f(x1),x3=f(x2); y=x3-((x3-x2)^2)/(x3-2*x2+x1); d=y-x0; x0=y; if abs(f(x0))<e then break; end c=c+1; printf(' \t%f %f %f %f %f\n',x0,x1,x2,x3,y) end printf('the root of the equation after %i iteration is %f',c,y);
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//Rodríguez Montiel Moises Ulises //2MN51 function X = jacobi(A, B, fx) [m,n] = size(A) iter = 0 if (m <> n) then error("La matriz no es cuadrada.") end e = 5*10^-fx X = zeros(n, 1); y=[]; fin=%F; while fin==%F fin=%T; for i=1:1:n y(i)=B(i); for j=1:1:n if (i~=j) y(i)=y(i)-A(i,j)*X(j); end end y(i)=y(i)/A(i,i); delta=abs(X(i)-y(i)); if (delta>e) fin=%F; end end for i=1:1:n X(i)=y(i); end iter = iter + 1; if(iter>100) break; end end endfunction
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function [x,y,typ]=EVTGEN_f(job,arg1,arg2) x=[];y=[];typ=[]; select job case 'plot' then standard_draw(arg1) graphics=arg1(2); [orig,sz,label]=graphics([1:2 4]) model=arg1(3);tt=model(11) xstringb(orig(1),orig(2),['Event at';'time '+string(tt)],sz(1),sz(2),'fill') case 'getinputs' then [x,y,typ]=standard_inputs(arg1) case 'getoutputs' then [x,y,typ]=standard_outputs(arg1) case 'getorigin' then [x,y]=standard_origin(arg1) case 'set' then x=arg1; graphics=arg1(2);label=graphics(4) model=arg1(3);tt=model(11); while %t do [ok,label,tt]=getvalue('Set Event time',.. ['Block label';'Event Time'],.. list('str',1,'vec',1),.. [label;string(tt)]) if ~ok then break,end if ok then graphics(4)=label if model(11)<>tt then model(11)=tt x_message(['Because of this modification,';.. 'diagram should be manually compiled';.. '(Compile) before simulation (Run).']) end x(2)=graphics;x(3)=model break end end case 'define' then tt=0 model=list('trash',0,0,0,1,[],[],[],[],'d',tt,[%f %f]) x=standard_define([2 2],model) end
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//find clc //solution //given b=6//mm t1=0.25//mm l=2500//mm t=800//N/mm^2 E=200*1000//N/mm^2 M=t*b*t1^2/(12)//N-mm printf("bending moment is,%f N-mm\n",M) q=12*M*l/(E*b*t1^2)//rad printf("angular def is,%f rad\n",q) U=0.5*M*q printf("energy stored is,%f N-mm",U)
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clear; clc; V_p=18; n=.72; V_BB=V_p/n; I_p=.6*10^-3; I_v=2.5*10^-3; V_v=1; R_max=V_BB*(1-n)/I_p; printf("R_max=%.2f kilo-ohm",R_max/1000); R_min=(V_BB-V_v)/I_v; printf("\nR_min=%.2f kilo-ohm",R_min/1000); C=.04*10^-6; f_min=1/(R_max*C*log(1/(1-n))); printf("\nf_min=%.3f kHz",f_min/1000); f_max=1/(R_min*C*log(1/(1-n))); printf("\nf_max=%.2f kHz",f_max/1000);
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//fonction : 'triGauss' //paremetre : A une matrcie ,b,un vecteur de reel //retour ; A un vecteur TS, b un vecteur de reel function [At,bt]=trigGauss(A,b) n = length(b); for k = 1:n-1 if A(k,k)=0 printf("erreur"); return 1; else for i = k+1:n c=A(i,k)/A(k,k); b(i)=b(i)-c*b(k); A(i,k)=0; for j=k+1:n A(i,j)=A(i,j)-c*A(k,j) end end end end At=A; bt=b; endfunction
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clc clear //input vp=440;//primary voltage in volts vs=240;//secondary voltage in volts f=50;//supply voltage in hertz i0=0.5;//no load current in amperes pf=0.3;//lagging power factor //calculations ii=i0*pf;//in phase component in amperes r0=vp/(ii*1000);//resistance in ohms iq=((i0^2)-(ii^2))^0.5;//quadrature component in amperes x0=vp/iq;//reactance in ohms l0=x0/(2*%pi*f);//inductance in henry //output mprintf('the transformer on load may be represented by %3.2fkOhms resistance in parallel with a pure inductance of %3.2fH',r0,l0)
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clc // Given that B = 20 // Width of the cut in mm Z = 10 // No of teeth in milling cutter D = 75 // Diameter of the milling cutter in mm alpha = 10 // Radial rake angle in Degree f = 25 // Feed velocity of the table in mm/min N =60 // Rpm of the cutter t = 5 // Depth of cut in mm mu = 0.5 // Cofficient of friction T_s = 400 // Shear yield stress in N/mm^2 t_a = 0.043 // Avg uncut thickness in mm // Sample Problem 17 on page no. 240 printf("\n # PROBLEM 4.17 # \n") t1_max = 0.01 lambda = 0.28 // From the table 4.13 Given in the book nu = 1400 // From the table 4.13 Given in the book t1_av = t1_max/2 P = nu*B*t*f*(10^-4)/(6*((t1_av)^(lambda))) printf(" \n Power required = %f W.",P)
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//Chapter 13, Problem 1, Figure 13.3, clc; //branch currents in figure 13.3 (a) I1=50-20; I2=20+15; I3=I1-120; I4=15-I3; I5=120-40; disp("(a) from Fig. 13.3(a)."); disp("For junction B:"); printf("I1 = %d A",I1); disp("For junction C:"); printf("I2 = %d A",I2); disp("For junction D:"); printf("I3 = %d A",I3); disp("For junction E:"); printf("I4 = %d A",I4); disp("For junction F:"); printf("I5 = %d A\n\n\n",I5); disp("(b) from Fig. 13.3(b)."); printf("Applying Kirchhoff’s voltage law and moving clockwise around the loop,\n"); printf("starting at point A, we get,\n"); //from figure 13.3(b) I=2; E=I*(2+2.5+1.5+1)-(3+6-4); printf("emf E = %d V",E);
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Ex9_16.sce
// Example 9_16 clc;funcprot(0); // Given data T_3=-10+273;// K T_2=-40+273;// K r=10;// The compression ratio c_p=1.00// kJ/kg.K k=1.4;// The specific heat ratio // Calculation T_4=T_3*(r)^((k-1)/k);// K T_5=T_3;// K T_6=T_2;// K T_1=T_6*(1/r)^((k-1)/k);// K T_1C=T_1-273;// The minimum cycle temperature in °C q_in=c_p*(T_2-T_1);// kJ/kg w_comp=c_p*(T_4-T_3);// kJ/kg w_turb=c_p*(T_6-T_1);// kJ/kg COP=q_in/(w_comp-w_turb);// The coefficient of performance printf("\nThe minimum cycle temperature,T_1=%3.0f°C \nThe coefficient of performance,COP=%0.3f",T_1C,COP);
57d48797c83365ed34aafee433bbf6c73573bf17
61da6be21995bc4b23f268b03fc13d0a33d818f3
/test/authorswrite.tst
57d4215b89f000d04f2ddb729f305264e63da788
[ "BSD-3-Clause", "BSD-2-Clause" ]
permissive
warmchang/reposurgeon
657fe5f63fdd0db560b46ccff11478c73c69b150
43e553d9ff0ad4a9c39f4c94b58856f2e5c99297
refs/heads/master
2020-12-08T19:41:16.920673
2020-01-10T14:58:55
2020-01-10T14:58:55
233,076,382
0
0
null
null
null
null
UTF-8
Scilab
false
false
121
tst
authorswrite.tst
## Regression test authors write format # Expected format: USER = Name <USER@DOMAIN> read <authorswrite.fi authors write
65778df0df3239e92ee3010fd5d279b47b02860a
65a7d82662b27e0f753f5125002922a6fe14d001
/BIND_scripts/import/Training/scenarios/natio2.sce
c3ca5b2008cf5a54df991bf34c30b8ea8f138205
[]
no_license
Anais-Hoarau/BING_GUI_Plugins
12f6308cad028e338022ce658e2d12d61115d412
59f50d7e990dc8a19173652f52831785a0848b91
refs/heads/master
2023-05-13T05:22:44.647105
2021-06-02T16:00:31
2021-06-02T16:00:31
360,511,786
0
0
null
null
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ISO-8859-1
Scilab
false
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34,913
sce
natio2.sce
V4.6 français commentaireManip= Manip training1 2010 rédigé par Joceline !! TACHE DE DETECTION NATIO2 nbreCoups= 251 numeroVhSujet= 0 autoriserHyperDepSgi= oui lancerMdv= non sautAleatoire= Oui INSTRUCTION_VARIABLES() DECLARE(dist,ENTIER) AFFECTE(dist,0) FIN INSTRUCTION(0,0,FAUX,FAUX,VRAI,VRAI) SI Immediate() FAIRE NeRienFaire() JSQA OU(Exterieure("B31"),Exterieure("F1")) ALLER ESSAI(1) FINSI FIN INSTRUCTION(10,1,FAUX,FAUX,VRAI,VRAI) SI NumeroEssai() FAIRE ChangerEnvMessage(5,"Contact_SVP",50,50,255,0,0) JSQA Attente(2) ALLER ESSAI(2) FINSI FIN INSTRUCTION(20,2,FAUX,FAUX,VRAI,VRAI) SI NumeroEssai() FAIRE ChangerEnvMessage(5,"NATIO2",50,50,255,0,0) JSQA Immediate() ALLER ESSAI(3) FINSI FIN ;--------------------------------------------------------------------------------------------------------------------------------------------------------- ;--2RM12 détection frontale sur N2, 2RM21 dépasse fourgon sur la voie opposée au sujet sur N2, 2RM14 dépassement droite sur N3 --------------------------- ;-- 2RM15 dépassement sujet sur N5, 2RM2 détection latérale droite sur B1, 2RM2 stationaire sur B1, 2RM16 détection latérale droite sur rond-point d6 ---- ;------------------------------Redémarrage sur N10 dans le sens indirect à 5m après l'intersection N10XN2------------------------------------------------- ; Pk N10XN2=2619.9m+20=2639.9(2639m),le sujet (-1) est à 20m avant N10XN2 dans 2besafe.vp INSTRUCTION(30,3,FAUX,FAUX,VRAI,VRAI) SI Immediate() FAIRE ChangerEnvMessage(5,"12*21*14*15*2*2*16",50,50,255,0,0) JSQA Position(-1,"mobile","N10",26599,VRAI,FAUX,">") ; Pk N10XN2=2619.9m+40=2659.9(26599),le sujet (-1) est à 40m avant N10XN2 ALLER ESSAI(79) FINSI FIN ;-------------------------------------------------- Flot4: Trafic sur la N2----------------------------------------------------- ;------------------------CitroenC4(-10),Smart (-222),RAV4Tex (-3),C4Noire(-4),Chrysler(-5)------------------------------- ;--sens de circulation: 1er véhicule----- 2ème véhi--3eme véhi------4eme véhi------5eme véhi --------------------------------- ;---------------------Détection frontale de la 2RM12 (-106) alors que le sujet est derrière le flot4---------- INSTRUCTION(790,79,FAUX,FAUX,VRAI,VRAI) SI NumeroEssai() FAIRE CreerMobile ("V2","M1",-10,"Asservi",02,VRAI,194,"N2",FAUX,-18,FAUX,52821,180) ; Création CitroenC4 (-10) sur la N2 roulant en sens indirect à 70 km/h (194) ; trajectoire 2besafe.v02,CitroenC4 à 60m de N2XN10=5182.1+100m=5282.1m (52821) CreerMobile ("V1","M2",-222,"Asservi",02,VRAI,194,"N2",FAUX,-18,VRAI,600,-10,180) ; Création Smart (-222) roulant en sens indirect sur la N2 à 70 km/h (194).Smart (-222) est à 60 m derrière la CitroenC4(-10). ; Smart (-222) suit la trajectoire 2besafe.v02 sur la N2 CreerMobile ("V1","M1",-3,"Asservi",02,VRAI,194,"N2",FAUX,-18,VRAI,800,-222,180) ; Création RAV4Tex (-3) roulant en sens indirect sur la N2 à 70 km/h (194).RAV4Tex (-3) est à 80 m derrière la Smart (-222). ; RAV4Tex (-3) suit la trajectoire 2besafe.v02 sur la N2 CreerMobile ("V2","M4",-4,"Asservi",02,VRAI,194,"N2",FAUX,-18,VRAI,1500,-3,180) ; Création C4Noire(-4) roulant en sens indirect sur la N2 à 70 km/h (194). C4Noire (-4) est à 150 m derrière la RAV4Tex(-4). ; C4Noire (-4) suit la trajectoire 2besafe.v02 sur la N2. CreerMobile ("V3","M1",-5,"Asservi",02,VRAI,194,"N2",FAUX,-18,VRAI,1500,-4,180) ; Création AudiTT (-5) roulant en sens indirect sur la N2 à 70 km/h (194). AudiTT(-5) est à 150 m derrière la C4Noire(-4). ; AudiTT (-5) suit la trajectoire 2besafe.v02 sur la N2. JSQA Immediate() ALLER ESSAI(80) FINSI FIN ;------Création de la 2RM21(-25) sur N2 derrière le fourgon (-102) qui déboitera en frontal au moment où le sujet arrivera sur la voie d'en face------------- ;--------------------------------------------Creation du ballon (-1000) ---------------------------------- INSTRUCTION(800,80,FAUX,FAUX,VRAI,VRAI) SI NumeroEssai() FAIRE CreerMobile ("PL3","M3",-104,"Asservi",-1,VRAI,0.0,"N2",FAUX,-30,FAUX,30990,180) ; Création du BusTex (-104) stationnaire sur le bord de la N2 en sens indirect ; Bustext (-104) est à 500m après N2XN6: 3489.5m-390.5=3099.0 (30990) CreerMobile ("PL3","M3",-103,"Asservi",-1,VRAI,0.0,"N2",FAUX,-30,FAUX,14791,180) ; Création du BusTex (-103) stationnaire sur le bord de la N2 en sens indirect ; Bustext (-103) est à 500m avant N2XN3: 964.1m+515=1479.1 (14791) CreerMobile("C","M4",-102,"Asservi",17,VRAI,194,"N2",FAUX,18,FAUX,9841,0) ; Création d'un Fourgon (-102) roulant à 70 km/h (194) en sens direct sur N2 (34) ; Trajectoire 2BeSafe.v17,à 20m après N2XN3:964.1m+20=984.1(9841) CreerMobile("M1","M1",-25,"Asservi",17,VRAI,194,"N2",FAUX,18,FAUX,9741,0) ; Création de la 2RM21(-25), 10 m derrrière le fourgon (-102) roulant à 70 km/h (194) dans la voie de gauche en sens direct sur N2(34) ; Trajectoire 2BeSafe.v17, 974.1m-5=969.1(9691) CreerMobile("PL3","M4",-101,"Asservi",17,VRAI,194 ,"N2",FAUX,18,VRAI,1500,-102,0) ; Création d'un camion de pompier (-101) roulant à 70 km/h (194) en sens direct sur N2 (34) ; Trajectoire lepsis.v17,à 150m (1500) devant le Fourgon (-102) CreerMobile("V2","M3",-100,"Asservi",17,VRAI,194 ,"N2",FAUX,18,VRAI,800,-101,0) ; Création de la ModusNoire(-100) roulant à 70 km/h (194) en sens direct sur N2 (34) ; Trajectoire lepsis.v17,à 80m (800) devant le Pompier (-101) JSQA Position(-1,"mobile", "N2",51771, VRAI,FAUX,">") ; le sujet (-1) a démarré et se trouve sur N2 (34) à 5m après N2XN10: 5182.1m -5=5177.1 (51771) ALLER ESSAI(81) FINSI FIN INSTRUCTION(810,81,FAUX,FAUX,VRAI,VRAI) SI OU(NumeroEssai(),Position(-1,"mobile","N2",44491,VRAI,FAUX,">")) ; Sujet se trouve à 35 m avant N2XN7:4114.1+35=4449.1(44491) FAIRE NeRienFaire() JSQA Position(-1,"mobile","N2",44441,VRAI,FAUX,">") ; Sujet se trouve à 30 m avant N2XN7:4114.1+30=4444.1(44441) ALLER ESSAI(82) FINSI FIN INSTRUCTION(820,82,FAUX,FAUX,VRAI,VRAI) SI NumeroEssai() FAIRE ; Création de la 2RM12 (-106) CreerMobile ("M1","M1",-106,"Asservi",12,VRAI,138,"N7",FAUX,18,FAUX,39601,0) ChangerIndicateur(-106,VRAI,"phares",1) ChangerEnvMessage(5,"2RM12_N7",50,50,255,0,0) ; Création de la 2RM12 (-106) en sens direct sur N7,10m avant N7XN2. Elle est dissimulée par une maison. ; 2RM12 se lance dans l'intersection à 50km/h(138) ; Pk N7XN2=3970.1m, 3970.1-10=3960.1 (39601). ; 2RM12 (-106) suit la trajectoire 2besafe.v12 sur la N7 puis tourne à droite sur la N2 et roule en sens direct. JSQA Interdistance(-25,"mobile",-1,"mobile",5500,"<=") ; le 2RM21(-25) se trouve à 550m (5500) devant le sujet (-1) ALLER ESSAI(83) FINSI FIN INSTRUCTION(830,83,FAUX,FAUX,VRAI,VRAI) SI NumeroEssai() FAIRE ChangerEnvMessage(5,"Enfants_N2",50,50,255,0,0) ; Création des enfants ;CreerPanneau(-1001,83,"visuelle","aucun","aucune",150000,150000,0,0,100,1,1,"N2",FAUX,-30,VRAI,-200000,-1,180) ; enfants sur la N2 créés à 200m(-200000mm) du sujet (-1) et sur le bas côté droit (-30) CreerPanneau(-1001,0,"visuelle","aucun","aucune",150000,150000,0,0,100,1,1,"N2",FAUX,-50,VRAI,-200000,-1,0) ; petit garçon sur la N2 créés à 200m(-200000mm) du sujet (-1) et sur le bas côté droit (-50) JSQA Immediate() ALLER ESSAI(84) FINSI FIN INSTRUCTION(840,84,FAUX,FAUX,VRAI,VRAI) SI NumeroEssai() FAIRE ; Création du ballon ChangerEnvMessage(5,"Ballon_N2",50,50,255,0,0) ;CreerMobile ("Tram1","M1",-1000,"Asservi",130,VRAI,20,"N2",FAUX,-20,VRAI,3500,-25,0) ; ballon (-1000) qui roule à 2m/s(20) sur la N2 en sens indirect sur le bord de la voie (-20), créé à 350 de la 2RM21(-25) CreerMobile ("Tram1","M1",-1000,"Asservi",130,VRAI,20,"N2",FAUX,-30,VRAI,-1950,-1,5) ; ballon (-1000) qui roule à 2m/s(20) sur la N2 en sens indirect sur le bord de la voie (-30), créé à 195m(1950) du sujet(-1) et avec un cap de 5° JSQA Interdistance(-25,"mobile",-1,"mobile",2000,"<=") ; le 2RM21(-25) se trouve à 200m (2000) devant le sujet (-1) ALLER ESSAI(88) FINSI FIN INSTRUCTION(880,88,FAUX,FAUX,VRAI,VRAI) SI NumeroEssai() FAIRE ChangerIndicateur(-25,VRAI,"phares",1) ; ChangerIndicateur(-25,FAUX,"clignotant_gauche",1) RegulerVitesseRelative(-25,-102,FAUX,-200,0,56,VRAI,2) ;la 2RM21(-25) accélère en roulant à +20km/h (56) par rapport au fourgon(-102) RegulerAxiale(-25,0,0,VRAI,1) ; la 2RM21(-25) se déporte dans la voie de droite en 1s ChangerEnvMessage(5,"2RM12_N7",50,50,255,0,0) JSQA Interdistance(-25,"mobile",-102,"mobile",50,">") ; le 2RM21(-25) se trouve à 5m (50) devant le fourgon (-102) ALLER ESSAI(89) FINSI FIN ;-----------Suivi du sujet (-1) par un Fourgon (-20) sur la N3(12)--------- INSTRUCTION(890,89,FAUX,FAUX,VRAI,VRAI) SI NumeroEssai() FAIRE RegulerAxiale(-25,18,0,VRAI,3) ; la 2RM21(-25) se redéporte dans la voie de gauche en 3s devant le fourgon JSQA Position(-1,"mobile","N3",800,VRAI,VRAI,">") ; Sujet (-1) est sur la N3 80m après N3XN2: 0m+80=80(800) ALLER ESSAI(90) FINSI FIN INSTRUCTION(900,90,FAUX,FAUX,VRAI,VRAI) SI NumeroEssai() FAIRE CreerMobile ("C","M4",-20,"Asservi",14,VRAI,278,"N3",FAUX,18,FAUX,100,0) ; Création du Fourgon (-20) en sens direct sur N3,10m après N3XN2. Pk N3XN2: 0+10= 10(100). ; suit la trajectoire 2besafe.v14 et roule à 100km/h (278) JSQA Interdistance(-20,"mobile",-1,"mobile",250,"<") ; Attente que Jeep (-10) se retrouve à 25 m derrière le sujet (-1) ALLER ESSAI(91) FINSI FIN INSTRUCTION(910,91,FAUX,FAUX,VRAI,VRAI) SI NumeroEssai() FAIRE SupprimerParNumero("mobile",-10) ; suppression de la CitroenC4 (-10) créée sur N2 en sens indirect SupprimerParNumero("mobile",-12) ; suppression de la AudiTT créée sur la N2 en sens indirect SupprimerParNumero("mobile",-5) ; suppression de la AudiTT (-5) créée sur N2 en sens indirect SupprimerParNumero("mobile",-4) ; suppression de la C4Noire (-4) créée sur N2 en sens indirect SupprimerParNumero("mobile",-3) ; suppression de la RAV4Tex (-3) créée sur N2 en sens indirect SupprimerParNumero("mobile",-222) ; suppression de la Smart (-222) créée sur N2 en sens indirect SupprimerParNumero("mobile",-104) ; suppression du BusTex (-104) stationaire créé sur N2 après N2XN6 SupprimerParNumero("mobile",-103) ; suppression du BusTex (-103) stationaire créée sur N2 avant N2XN3 SupprimerParNumero("mobile",-106) ; suppression de la 2RM12 (-106) créée sur N2 en sens direct SupprimerParNumero("mobile",-102) ; suppression du Fourgon (-102) créé sur N2 en sens direct SupprimerParNumero("mobile",-25) ; suppression de la 2RM21(-25) créée sur N2 en sens direct SupprimerParNumero("mobile",-101) ; suppression du Pompier(-101) créé sur N2 en sens direct derrière Fourgon (-102) SupprimerParNumero("mobile",-100) ; suppression de la ModusNoire(-100) créé sur N2 en sens direct derrière Pompier (-101) RegulerVitesseRelative(-20,-1,FAUX,-200,0,0,VRAI,3) ; Fourgon (-20) roule à la même vitesse que le sujet (-1) JSQA Position(-1,"mobile","N3",23472,VRAI,VRAI,">") ; le sujet (-1) est à 110m avant N3XN5: 2457.2m-110= 2347.2(23472) ALLER ESSAI(92) FINSI FIN ;----------------------------Sujet (-1) tourne à gauche dans N3XN5---------------------------- ;--------------------------------Flot5 frontal sur la N3 (12)-------------------------------- ;------------Fourgon(-21),ModusNoire(-22),GolfTex(-23),Chrysler(-24),Modus(-25)----------- ;---------- 1er véhicule---2ème véhi---3eme véhi------4eme véhi------5eme véhi --------------- ;--------Sujet (-1) traverse le Flot5 frontal sur la N3 (12) et TAG sur N5-------------------- ;-----2RM14 (-105) arrive sur la N3 derrière le sujet (-1) et le dépasse par la droite ------- INSTRUCTION(920,92,FAUX,FAUX,VRAI,VRAI) SI NumeroEssai() FAIRE RegulerVitesseRelative(-20,-1,FAUX,-100,0,0,VRAI,3) ; Fourgon (-20) roule à 10m(-100) derrière le sujet (-1) à la même vitesse ;ChangerIndicateur(-20,VRAI,"clignotant_gauche",1) clignotant avant pas beau sur ce véhicule JSQA Position(-1,"mobile","N3",21572,VRAI,VRAI,">") ; le sujet (-1) est à 300m avant N3XN5: 2457.2m-300= 2157.2(21572) ALLER ESSAI(93) FINSI FIN ;----------------------------------Flot5 frontal sur N3--------------------------------------- INSTRUCTION(930,93,FAUX,FAUX,VRAI,VRAI) SI NumeroEssai() FAIRE RegulerVitesseRelative(-20,-1,FAUX,-200,0,0,VRAI,3) ; Fourgon (-20) roule à 70km/h(194) CreerMobile ("C","M2",-21,"Asservi",13,VRAI,194,"N3",FAUX,-18,FAUX,27372,180) ; Création Chrysler (-21) roulant en sens indirect sur la N3 (12) à 70 km/h (194). Trajectoire 2besafe.v13. ; Pk N3XN5:2457.2m,Chrysler à 280m après N3XN5=2457.2+280=2737.2m (27372) CreerMobile ("V2","M3",-22,"Asservi",13,VRAI,194,"N3",FAUX,-18,VRAI,600,-21,180) ; Création ModusNoire (-22) roulant en sens indirect sur la N3 à 70 km/h (194). ModusNoire est à 60 m derrière Chrysler (-21). ; ModusNoire (-22) suit la trajectoire 2besafe.v13 sur la N3 CreerMobile ("V1","M4",-23,"Asservi",13,VRAI,194,"N3",FAUX,-18,VRAI,800,-22,180) ; Création GolfTex (-23) roulant en sens indirect sur la N3 à 70 km/h (194). GolfTex est à 80 m derrière ModusNoire(-22). ; GolfTex(-23) suit la trajectoire 2besafe.v13 sur la N3 CreerMobile ("V3","M1",-24,"Asservi",13,VRAI,194,"N3",FAUX,-18,VRAI,1500,-23,180) ; Création AudiTT(-24) roulant en sens indirect sur la N3 à 70 km/h (194). AudiTT est à 150 m derrière GolfTex (-23). ; AudiTT (-24) suit la trajectoire 2besafe.v13 sur la N3 CreerMobile ("V1","M3",-25,"Asservi",13,VRAI,194,"N3",FAUX,-18,VRAI,1500,-24,180) ; Création Modus (-25) roulant en sens indirect sur la N3 à 70 km/h (194). Modus est à 150 m derrière AudiTT(-24). ; Modus (-25) suit la trajectoire 2besafe.v13 sur la N3 JSQA Immediate() ALLER ESSAI(94) FINSI FIN INSTRUCTION(940,94,FAUX,FAUX,VRAI,VRAI) SI NumeroEssai() FAIRE RegulerVitesseRelative(-20,-1,FAUX,-200,0,0,VRAI,3) ; Chrysler (-20) roule à la même vitesse que le sujet (-1) JSQA VitesseAbs(-1,"mobile",28,"<","") ; vitesse du sujet (-1)<10km/h(28dm/s) ; Sujet s'arrête pour laisser passer les véhicules du flot5 arrivant en face sur N3 en sens indirect ALLER ESSAI(95) FINSI FIN INSTRUCTION(950,95,FAUX,FAUX,VRAI,VRAI) SI NumeroEssai() FAIRE RegulerVitesseFixe(-20,28,0,VRAI,1) RegulerAxiale(-20,5,0,VRAI,2) ; le Fourgon(-20) derrière le sujet (-1) se met sur la voie médiane en 2s ChangerIndicateur(-20,VRAI,"clignotant_gauche",1) ; le Fourgon met son clignotant à gauche ; Chrysler (-20) roule à 20km/h(28) jusqu'à être à 6m derrière le sujet (-1) JSQA Interdistance(-20,"mobile",-1,"mobile",60,"<=") ALLER ESSAI(96) FINSI FIN ;-------------------2RM14 (-105) dépasse par la droite le sujet (-1) à N3XN5 ------------------------- INSTRUCTION(960,96,FAUX,FAUX,VRAI,VRAI) SI NumeroEssai() FAIRE RegulerVitesseRelative(-20,-1,FAUX,-200,0,0,VRAI,3) ; Chrysler (-20) roule à la même vitesse que le sujet (-1) ; Création de la 2RM14(-105) sur la N3 (12) à 3m (30) derrière le Chrysler (-20) ; 2RM14 (-105) se trouve à 10m+10m (200) derrière le sujet (-1) et elle déboite vers la droite immédiatement ; 2RM14 (-105) suit la trajectoire 2besafe.v14 et roule à 10km/h (28). CreerMobile ("M1","M1",-105,"Asservi",14,VRAI,56,"N3",FAUX,10,VRAI,-30,-20,0) RegulerAxiale(-105,30,0,FAUX,20) ; la 2RM14 (-105) se décalle dans la voie à droite de 3m(30) en dépassant à 20km/h(56) ChangerIndicateur(-105,VRAI,"phares",1) ChangerEnvMessage(5,"2RM14_N3",50,50,255,0,0) JSQA Interdistance(-1,"mobile",-105,"mobile",1,">") ; 2RM14 (-105) se trouve au niveau du sujet (-1) ALLER ESSAI(97) FINSI FIN INSTRUCTION(970,97,FAUX,FAUX,VRAI,VRAI) SI NumeroEssai() FAIRE RegulerVitesseRelative(-20,-1,FAUX,-200,0,0,VRAI,3) ; Chrysler (-20) roule à la même vitesse que le sujet (-1) RegulerVitesseFixe(-105,138,0,FAUX,50) ; 2RM14(-105) accélère jusqu'à 50km/h(138) JSQA Interdistance(-1,"mobile",-105,"mobile",50,">") ; 2RM14 (-105) se trouve à plus de 5m (50) devant le sujet (-1) ALLER ESSAI(98) FINSI FIN INSTRUCTION(980,98,FAUX,FAUX,VRAI,VRAI) SI NumeroEssai() FAIRE RegulerVitesseRelative(-20,-1,FAUX,-200,0,0,VRAI,3) ; Chrysler (-20) roule à la même vitesse que le sujet (-1) RegulerAxiale(-105,18,0,VRAI,5) ; 2RM14 (-105) se recentre dans la voie de droite en 2s aprés avoir doublé le sujet (-1) RegulerVitesseFixe(-105,138,0,VRAI,5) ; la 2RM14 (-105) accélère pour atteindre 50km/h (138) en 5s. JSQA Position(-1,"mobile","N5",12986,VRAI,FAUX,">") ; Sujet a tourné à gauche sur la N5 après avoir traversé le flot5 sur la N3 ; sujet (-1) se trouve sur N5 à 30m aprés N5XN3: 1328.6-30=1298.6(12986) ALLER ESSAI(99) FINSI FIN ;---------- 2RM15 (-106) arrive derrière le sujet (-1) sur N5 et le dépasse -------------------- INSTRUCTION(990,99,FAUX,FAUX,VRAI,VRAI) SI OU(NumeroEssai(),Position(-1,"mobile","N5",12986,VRAI,FAUX,">")) ; Sujet a tourné à gauche sur la N5 après avoir traversé le flot5 sur la N3 ; sujet (-1) se trouve sur N5 à 30m aprés N5XN3: 1328.6-30=1298.6(12986) FAIRE RegulerVitesseFixe(-20,138,0,VRAI,5) ; le Chrysler (-20) accélère pour atteindre 50km/h (138) en 5s. CreerMobile ("M1","M1",-106,"Asservi",15,VRAI,278,"N5",FAUX,-18,VRAI,200,-1,180) ChangerIndicateur(-106,VRAI,"phares",1) ChangerEnvMessage(5,"2RM15_N5",50,50,255,0,0) ; Création 2RM15 (-106) à 20m (200) derrière le sujet (-1), roulant en sens indirect sur la N5 (14) à 100 km/h (278). Trajectoire 2besafe.v15. JSQA Interdistance(-106,"mobile",-1,"mobile",110,"<=") ; le 2RM15(-106) se trouve à 11m (110) derrière le sujet (-1) ALLER ESSAI(100) FINSI FIN INSTRUCTION(1000,100,FAUX,FAUX,VRAI,VRAI) SI NumeroEssai() FAIRE ChangerIndicateur(-106,FAUX,"clignotant_gauche",1) RegulerVitesseRelative(-106,-1,FAUX,-200,0,28,VRAI,2) ; la 2RM15(-106) accélère en roulant à +10km/h par rapport au sujet (-1) RegulerAxiale(-106,16,0,VRAI,2) ; la 2RM15(-106) se déporte dans la voie de gauche en 2s SupprimerParNumero("mobile",-21) ; suppression Chrysler (-21) créée sur la N3 SupprimerParNumero("mobile",-22) ; suppression de la ModusNoire (-22) créée sur N3 SupprimerParNumero("mobile",-23) ; suppression de la GolfTex (-23) créée sur N3 SupprimerParNumero("mobile",-24) ; suppression de la Chrysler (-24) créée sur N3 SupprimerParNumero("mobile",-25) ; suppression de la Modus (-25) créée sur N3 SupprimerParNumero("mobile",-105) ; suppression de la 2RM14 (-105) créée sur N3 ChangerEnvMessage(5,"2RM2_B1",50,50,255,0,0) JSQA Interdistance(-106,"mobile",-1,"mobile",-50,"<") ; le 2RM15(-106) se trouve à 5m (50) devant le sujet (-1) ALLER ESSAI(101) FINSI FIN ;------------------- Sujet (-1) tourne à gauche dans N5XB1-------------------------------- ;-----------Sujet (-1) TAG et s'insère dans le Flot6 latéral Droit sur la B1 (17) ------- ;---------------------2RM15 (-106) latéral gauche sur la B1 (17)------------------------- ;-------------Flot6: Cam (-11),MercedesTaxi (-12),2RM2 (-13),Smart (-14),806 (-15)---- ;------------------ 1er véhi---2ème véhi-------3eme véhi------4eme véhi---5eme véhi------ INSTRUCTION(1010,101,FAUX,FAUX,VRAI,VRAI) SI NumeroEssai() FAIRE ChangerIndicateur(-106,FAUX,"clignotant_gauche",1) RegulerAxiale(-106,-18,0,VRAI,2) ; la 2RM15(-106) se déporte dans la voie de droite en 2s RegulerVitesseFixe(-106,278,0,VRAI,8) ; le 2RM15(-106) accélère pour atteindre 100km/h (278) en 8s. JSQA Position(-1,"mobile","N5",400,VRAI,FAUX,">") ; sujet (-1) se trouve sur N5 à 40m avant N5XB1: 0+40=40(400) ALLER ESSAI(102) FINSI FIN INSTRUCTION(1020,102,FAUX,FAUX,VRAI,VRAI) SI NumeroEssai() FAIRE CreerMobile ("PL3","M1",-11,"Asservi",05,VRAI,138,"B1",FAUX,18,FAUX,21662,0) ; Création d'un Camion (-11) roulant en sens direct sur la B1 (17) à 50 km/h (138). Trajectoire 2besafe.v05. ; le Camion (-11) à 60m de B1XN5:2226.2m,2226.2-60=2166.2m (21662) CreerMobile ("V3","M4",-12,"Asservi",05,VRAI,138,"B1",FAUX,18,VRAI,-550,-11,0) ; Création MercedesTaxi (-12) roulant en sens direct sur la B1 à 50 km/h (138). MercedesTaxi est à 55 m (-550) derrière le camion (-11). ; MercedesTaxi (-12) suit la trajectoire 2besafe.v05 sur la B1 CreerMobile ("M1","M1",-13,"Asservi",05,VRAI,138,"B1",FAUX,18,VRAI,-300,-12,0) ChangerIndicateur(-13,VRAI,"phares",1) ; Création 2RM2 (-13) roulant en sens direct sur la B1 à 50 km/h (138). 2RM2 est à 30 m (-300) derrière MercedesTaxi (-12) . ; 2RM2 (-13) suit la trajectoire 2besafe.v05 sur la B1 CreerMobile ("V1","M2",-14,"Asservi",05,VRAI,138,"B1",FAUX,18,VRAI,-1040,-13,0) ; Création Smart (-14) roulant en sens direct sur la B1 à 50 km/h (138). Smart est à 124 m (-1040) derrière ModusNoire (-13). ; Smart (-14) suit la trajectoire 2besafe.v05 sur la B1 CreerMobile ("V3","M2",-15,"Asservi",05,VRAI,138,"B1",FAUX,18,VRAI,-580,-14,0) ; Création Toledo (-15) roulant en sens direct sur la B1 à 50 km/h (138). Smart est à 58 m (-580) derrière la Smart (-14). ; Toledo (-15) suit la trajectoire 2besafe.v05 sur la B1 JSQA Position(-1,"mobile","B1",22342,VRAI,VRAI,">") ; le sujet (-1) a démarré et est à 10m après B1XN5: 2226.2m,2226.2+8=2234.2m (22342) ALLER ESSAI(103) FINSI FIN ;-------------Evitement de collision lors de l'insertion du sujet dans le Flot6--------------- ;-----------Flot6: Cam (-11),MercedesTaxi (-12),2RM2 (-13),Smart (-14),Toledo (-15)----------- ;----------------- 1er véhi---2ème véhi----3eme véhi----4eme véhi---5eme véhi------------ INSTRUCTION(1030,103,FAUX,FAUX,VRAI,VRAI) SI ET(Interdistance(-1,"mobile",-11,"mobile",-70,">"),Position(-1,"mobile","B1",26262,VRAI,VRAI,"<")) ; Sujet (-1) se trouve à moins de 7m (70) devant le cam(-10) ; Sujet et camion roulent en sens direct donc Pk(-11)-Pk(-1)<0,critère d'interdistance négatif ; Critère=-7m(-70) FAIRE RegulerVitesseRelative(-11,-1,FAUX,-200,0,-7,VRAI,2) ; le camion (-11) ralentit puis roule à -4km/h (7) par rapport au sujet (-1) en restant à 20m (200) de distance JSQA Position(-1,"mobile","B1",26262,VRAI,VRAI,">") ; le sujet (-1) est à 400m après B1XN5: 2226.2m +400=2626.2(26262) ALLER COURANT FINSI FIN INSTRUCTION(1031,103,FAUX,FAUX,VRAI,VRAI) SI ET(Enchaine(1030),Interdistance(-1,"mobile",-11,"mobile",-70,"<=")) ; le sujet ne s'insère pas devant le camion(-11) en étant trop près ; Sujet (-1) se trouve à plus de 7m (70) devant le cam (-10) FAIRE NeRienFaire() JSQA Immediate() ALLER ESSAI(108) FINSI FIN INSTRUCTION(1040,104,FAUX,FAUX,VRAI,VRAI) ; Insertion du sujet(-1) devant la MercedesTaxi(-12) SI ET(Interdistance(-1,"mobile",-12,"mobile",-70,">"),Position(-1,"mobile","B1",26262,VRAI,VRAI,"<")) ; Sujet (-1) se trouve à moins de 7m (70) devant la MercedesTaxi(-12) FAIRE RegulerVitesseRelative(-12,-1,FAUX,-200,0,-7,VRAI,2) ; le MercedesTaxi (-12) ralentit puis roule à -4km/h (7) par rapport au sujet (-1) en restant à 20m (200) de distance JSQA Position(-1,"mobile","B1",26262,VRAI,VRAI,">") ; le sujet (-1) est à 400m après B1XN5: 2226.2m +400=2626.2(26262) ALLER COURANT FINSI FIN INSTRUCTION(1041,104,FAUX,FAUX,VRAI,VRAI) SI ET(Enchaine(1040),Interdistance(-1,"mobile",-12,"mobile",-70,"<=")) ; le sujet ne s'insère pas devant la MercedesTaxi (-12) en étant trop près ; Sujet (-1) se trouve à plus de 7m (70) devant RAV4Tex (-3) FAIRE NeRienFaire() JSQA Immediate() ALLER ESSAI(108) FINSI FIN INSTRUCTION(1050,105,FAUX,FAUX,VRAI,VRAI) ; Insertion du sujet(-1) devant la 2RM2(-13) SI ET(Interdistance(-1,"mobile",-13,"mobile",-70,">"),Position(-1,"mobile","B1",26262,VRAI,VRAI,"<")) ; Sujet (-1) se trouve à moins de 7m (70) devant la 2RM2(-13) FAIRE RegulerVitesseRelative(-13,-1,FAUX,-200,0,-7,VRAI,2) ; la 2RM2 (-13) ralentit puis roule à -4km/h (7) par rapport au sujet (-1) en restant à 20m (200) de distance JSQA Position(-1,"mobile","B1",26262,VRAI,VRAI,">") ; le sujet (-1) est à 400m après B1XN5: 2226.2m +400=2626.2(26262) ALLER COURANT FINSI FIN INSTRUCTION(1051,105,FAUX,FAUX,VRAI,VRAI) SI ET(Enchaine(1050),Interdistance(-1,"mobile",-13,"mobile",-70,"<=")) ; le sujet ne s'insère pas devant la 2RM2(-13) en étant trop près ; Sujet (-1) se trouve à plus de 7m (70) devant la 2RM2(-3) FAIRE NeRienFaire() JSQA Immediate() ALLER ESSAI(108) FINSI FIN INSTRUCTION(1060,106,FAUX,FAUX,VRAI,VRAI) ; Insertion du sujet(-1) devant la Smart(-14) SI ET(Interdistance(-1,"mobile",-14,"mobile",-70,">"),Position(-1,"mobile","B1",26262,VRAI,VRAI,"<")) ; Sujet (-1) se trouve à moins de 7m (70) devant la Smart(-4) FAIRE RegulerVitesseRelative(-14,-1,FAUX,-200,0,-7,VRAI,2) ; la Smart(-14) ralentit puis roule à -4km/h (7) par rapport au sujet (-1) en restant à 20m (200) de distance JSQA Position(-1,"mobile","B1",26262,VRAI,VRAI,">") ; le sujet (-1) est à 400m après B1XN5: 2226.2m +400=2626.2(26262) ALLER COURANT FINSI FIN INSTRUCTION(1061,106,FAUX,FAUX,VRAI,VRAI) SI ET(Enchaine(1060),Interdistance(-1,"mobile",-14,"mobile",-70,"<=")) ; le sujet ne s'insère pas devant la Smart(-14) en étant trop près ; Sujet (-1) se trouve à plus de 7m (70) devant la Smart(-4) FAIRE NeRienFaire() JSQA Immediate() ALLER ESSAI(108) FINSI FIN INSTRUCTION(1070,107,FAUX,FAUX,VRAI,VRAI) ; Insertion du sujet(-1) devant la Toledo(-15) SI ET(Interdistance(-1,"mobile",-15,"mobile",-70,">"),Position(-1,"mobile","B1",26262,VRAI,VRAI,"<")) ; Sujet (-1) se trouve à moins de 7m (70) devant la Toledo(-5) FAIRE RegulerVitesseRelative(-15,-1,FAUX,-200,0,-7,VRAI,2) ; la Toledo (-15) ralentit puis roule à -4km/h (7) par rapport au sujet (-1) en restant à 20m (200) de distance JSQA Position(-1,"mobile","B1",26262,VRAI,VRAI,">") ; le sujet (-1) est à 400m après B1XN5: 2226.2m +400=2626.2(26262) ALLER COURANT FINSI FIN INSTRUCTION(1071,107,FAUX,FAUX,VRAI,VRAI) SI ET(Enchaine(1070),Interdistance(-1,"mobile",-15,"mobile",-70,"<=")) ; le sujet ne s'insère pas devant la Toledo(-15) en étant trop près ; Sujet (-1) se trouve à plus de 7m (70) devant la 806(-5) FAIRE NeRienFaire() JSQA Immediate() ALLER ESSAI(108) FINSI FIN ;-------------------------------fin insertion dans Flot6---------------------------- INSTRUCTION(1080,108,FAUX,FAUX,VRAI,VRAI) SI NumeroEssai() FAIRE SupprimerParNumero("mobile",-106) ; supression de la 2RM15(-106) créée sur N5 RegulerAxiale(-11,18,0,VRAI,3) ; le Camion(-11) se recentre dans la voie de droite en 2s RegulerAxiale(-12,18,0,VRAI,3) ; le MercedesTaxi (-12) se recentre dans la voie de droite en 2s RegulerAxiale(-13,18,0,VRAI,3) ; la 2RM2 (-13) se recentre dans la voie de droite en 2s RegulerAxiale(-14,18,0,VRAI,3) ; la Smart (-14) se recentre dans la voie de droite en 2s RegulerAxiale(-15,18,0,VRAI,3) ; la Toledo (-15) se recentre dans la voie de droite en 2s JSQA Position(-1,"mobile","B1",27262,VRAI,VRAI,">") ; le sujet (-1) est à 500m après B1XN5: 2226.2m + 500=2726.2(27262) ALLER ESSAI(109) FINSI FIN ;------------------ Conduite Flot6 sur la B1 (17) jusqu'au rond point d3(18)---------------------- ;-------------- Cam(-11),MercedesTaxi(-12),2RM2(-13),Smart(-14),arrêt Toledo(-15)------------------- INSTRUCTION(1090,109,FAUX,FAUX,VRAI,VRAI) SI OU(NumeroEssai(),Position(-1,"mobile","B1",27272,VRAI,VRAI,">")) ; le sujet (-1) est à 501m après B1XN5: 2226.2m + 501=2727.2(27272) FAIRE RegulerVitesseFixe(-11,194,0,VRAI,8) ; accélération du Camion(-11) à 70km/h(194) RegulerVitesseFixe(-12,194,0,VRAI,8) ; accélération de la MercedesTaxi(-12) à 70km/h(194) RegulerVitesseFixe(-13,194,0,VRAI,8) ; accélération de la 2RM2(-13) à 70km/h(194) RegulerVitesseFixe(-14,194,0,VRAI,8) ; accélération de la smart (-14) à 70km/h(194) RegulerVitesseFixe(-15,0,0,VRAI,10) ; déccélération de la Toledo (-15) à 0km/h(0) RegulerAxiale(-15,40,0,VRAI,5) ; Toledo(-15) s'arrête sur le bas coté de la B1(17) ChangerIndicateur(-13,VRAI,"warning",1) ; Allumage des warning de la 2RM2(-13) stationnaire JSQA Position(-11,"mobile","B1",43467,VRAI,VRAI,">") ; le camion (-11) se trouve sur la B1(17) à 750m avant le rond-point d3(18) ; Pk B1Xd3:5096.7m-750=4346.7(43467) ALLER ESSAI(110) FINSI FIN ;----------------- Cam(-11),MercedesTaxi(-12),arrêt 2RM2(-13),Smart(-14)------------------- INSTRUCTION(1100,110,FAUX,FAUX,VRAI,VRAI) SI OU(NumeroEssai(),Position(-1,"mobile","B1",27272,VRAI,VRAI,">")) ; le sujet (-1) est à 501m après B1XN5: 2226.2m + 501=2727.2(27272) FAIRE RegulerVitesseFixe(-11,194,0,VRAI,8) ; accélération du Camion(-11) à 70km/h(194) RegulerVitesseFixe(-12,194,0,VRAI,8) ; accélération de la MercedesTaxi(-12) à 70km/h(194) ChangerIndicateur(-13,VRAI,"clignotant_droit",1) RegulerVitesseFixe(-13,0,0,VRAI,10) ; déccélération de la 2RM2(-13) à 0km/h(0) RegulerAxiale(-13,40,0,VRAI,5) ; 2RM2(-13) s'arrête sur le bas coté de la B1(17) RegulerVitesseFixe(-14,194,0,VRAI,8) ; accélération de la smart (-14) à 70km/h(194) JSQA Position(-11,"mobile","B1",44467,VRAI,VRAI,">") ; le camion (-11) se trouve sur la B1(17) à 450m avant le rond-point d3(18) ; Pk B1Xd3:5096.7m-650=4446.7(44467) ALLER ESSAI(111) FINSI FIN ;----------------- Cam(-11),arret MercedesTaxi(-12),arret Smart (-14) ------------------- INSTRUCTION(1110,111,FAUX,FAUX,VRAI,VRAI) SI NumeroEssai() FAIRE RegulerVitesseFixe(-11,194,0,VRAI,8) ; accélération du Camion(-11) à 70km/h(194) RegulerVitesseFixe(-12,0,0,VRAI,10) ; déccélération de la MercedesTaxi(-12) à 0km/h(0) RegulerAxiale(-12,40,0,VRAI,10) ; MercédèsTaxi(-12) s'arrête sur le bas coté de la B1(17) ChangerIndicateur(-12,VRAI,"clignotant_droit",1) RegulerVitesseFixe(-14,0,0,VRAI,10) ; déccélération de la smart (-14) à 0km/h(0) RegulerAxiale(-14,40,0,VRAI,5) ; smart (-14) s'arrête sur le bas coté de la B1(17) JSQA Position(-11,"mobile","B1",47967,VRAI,VRAI,">") ; le camion (-11) se trouve sur la B1 à moins de 300m du rond-point d3(18) ; Pk B1Xd3:5096.7m-300=4796.7(47967) ALLER ESSAI(112) FINSI FIN INSTRUCTION(1120,112 ,FAUX ,FAUX ,VRAI ,VRAI) SI NumeroEssai() FAIRE RegulerVitesseFixe(-11,111,0,VRAI,5) ; déccélération du Camion(-11) à 40km/h(111) JSQA Position(-11,"mobile","B1",50467,VRAI,VRAI,">") ; le camion (-11) se trouve sur la B1 à 50m avant le rond-point d3(18), Pk B1Xd3:5096.7m-50=5046.7(50467) ALLER ESSAI(113) FINSI FIN INSTRUCTION(1130,113,FAUX,FAUX ,VRAI,VRAI) SI NumeroEssai() FAIRE RegulerVitesseFixe(-11,70,0,VRAI,2) ; déccélération du Camion(-11) à 25km/h(70) JSQA Position(-11,"mobile","B1",50667,VRAI,VRAI,">") ; le camion (-11) se trouve sur la B1 30m avant le rond-point d3(18), Pk B1Xd3:5096.7m-30=5066.7(50667) ALLER ESSAI(114) FINSI FIN INSTRUCTION(1140,114,FAUX,FAUX ,VRAI,VRAI) SI NumeroEssai() FAIRE CreerMobile ("PL3","M4",-103,"Asservi",-1,VRAI,0,"D9",FAUX,-18,FAUX,100,150) ChangerIndicateur(-103,VRAI,"warning",1) ; Pompier (-103) créé sur D9 à 10m du rond point d3: D9Xd3:0m+10=10(100) JSQA Immediate() ALLER ESSAI(115) FINSI FIN ;----------------Négociation du rond-point d3 (18) par le camion (-11) ------------------------- INSTRUCTION(1150,115,FAUX,FAUX,VRAI,VRAI) SI NumeroEssai() FAIRE RegulerVitesseFixe(-11,40,0,VRAI,5) ; déccélération du Camion(-11) à 15km/h(40) JSQA Position(-1,"mobile","d3",1126,VRAI,FAUX,">") ; le sujet(-1) se trouve sur le rond point d3(18) au niveau de la sortie D9, Pk d3XD9:112.6m (1126) ALLER ESSAI(117) FINSI FIN ;-----------2RM16 (-105) latéral droit dans rond-point d3 (18) et qui stop avant le rond-point----------- ;-------------Détection latérale Droite du 2RM16 (-105) à l'arrêt à l'entrée d'un rond point------------- INSTRUCTION(1170,117,FAUX,FAUX,VRAI,VRAI) SI NumeroEssai() FAIRE CreerMobile ("M1","M1",-105,"Asservi",16,VRAI,110,"D2",FAUX,18,FAUX,107265,0) ChangerIndicateur(-105,VRAI,"phares",1) ChangerEnvMessage(5,"2RM16_D2",50,50,255,0,0) ; Création 2RM16 (-105) roulant en sens direct sur la D2 (18) à la vitesse de 40km/h(110). ; 2RM16 créé à 80m du rond point: Pk D2Xd3:10806.5m-80=10726.5(107265) ; 2RM16 (-105) suit la trajectoire 2besafe.v16 JSQA Position(-105,"mobile","D2",107915,VRAI,VRAI,">") ; 2RM16(-105) se trouve sur la D2 à moins de 15m du rond-point d3(18) ; Pk D2Xd3:10806.5m-15=10791.5(107915) ALLER ESSAI(118) FINSI FIN INSTRUCTION(1180,118,FAUX,FAUX,VRAI,VRAI) SI NumeroEssai() FAIRE RegulerVitesseFixe(-105,0,0,FAUX,80) ; arret de la 2RM16 sur la D2(18) quand elle est à moins de 6m du rond-point d3(18) JSQA Attente(9) ; 2RM16 s'est arrêté avant le rond-point d3(18) ALLER ESSAI(119) FINSI FIN INSTRUCTION(1190,119,FAUX,FAUX,VRAI,VRAI) SI NumeroEssai() FAIRE NeRienFaire() JSQA Position(-1,"mobile","D2",106198,VRAI,FAUX,"<") ; sujet (-1) se trouve sur D2(2) à Pk=10619.8m(106198) ALLER ESSAI(120) FINSI FIN ;--------Supression du Flot6 et de la 2RM15,de la 2RM16 quand sujet (-1) sur N2 après N2XN3--------- ;----------Flot6: Cam (-11),MercedesTaxi (-12),2RM2 (-13),Smart (-14),806 (-15)------------------ INSTRUCTION(1200,120,FAUX,FAUX,VRAI,VRAI) SI NumeroEssai() FAIRE SupprimerParNumero("mobile",-11) ; suppression du cam (-11) créée sur la B1 SupprimerParNumero("mobile",-12) ; suppression de la MercedesTaxi (-12) créée sur B1 SupprimerParNumero("mobile",-13) ; suppression de la 2RM2 (-13) créée sur B1 SupprimerParNumero("mobile",-14) ; suppression de la Smart (-14) créée sur B1 SupprimerParNumero("mobile",-15) ; suppression de la Toledo (-15) créée sur B1 SupprimerParNumero("mobile",-106) ; suppression de la 2RM15 (-106) créée sur B1 SupprimerParNumero("mobile",-105) ; suppression de la 2RM16 (-105) créée sur D2 SupprimerParNumero("mobile",-103) ; suppression des pompiers (-103) stationaire créé sur D9 JSQA Immediate() ALLER ESSAI(250) FINSI FIN ;-------------------------------------------------------------------- ;-----------------------Avertissement fin scenario ------------------- ;--------------------------------------------------------------------- INSTRUCTION(2500,250,FAUX,FAUX,FAUX,FAUX) SI NumeroEssai() FAIRE ChangerEnvMessage(6,"TERMINE",50,50,255,0,0) JSQA Attente(5) ALLER COURANT FINSI FIN
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FOSSEE/Scilab-TBC-Uploads
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clear; clc; close; amp = 20; vi_t = -5;//transition voltage t = 0:0.1:2*%pi; vi = amp*sin(t); vo = vi+5; //output voltage disp(vi_t,'transition voltage : '); for i = 1:length(t) if(vo(i)<=0) vo(i)=0; end end plot(t,vo); xtitle('Ouptut voltage','t','vo');
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//Chapter-13, Example 13.16, Page 391 //============================================================================= clc clear //INPUT DATA deltaIe=1*10^-3;//change in emitter current in A deltaIc=0.995*10^-3;//change in collector current in A //CALCULATIONS a=deltaIc/deltaIe;//common-base DC current gain b=a/(1-a);//common-emitter DC current gain mprintf("Thus common-base DC current gain and common-emitter DC current gain are %1.3f and %1.0f respectively",a,b); //=================================END OF PROGRAM=======================================================================================================
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Engineering Thermodynamics by Onkar Singh Chapter 4 Example 15") T1=(500+273);//temperature of source in K T2=(200+273);//temperature of sink in K T3=(450+273);//temperature of body in K disp("let the output of heat engine be W.so W/3 is consumed for driving auxiliary and remaining 2*W/3 is consumed for driving heat pump for heat engine,") disp("n=W/Q1=1-(T2/T1)") n=1-(T2/T1) disp("so n=W/Q1=0.3881") disp("COP of heat pump=T3/(T3-T2)=Q3/(2*W/3)") COP=T3/(T3-T2) disp("so 2.892=3*Q3/2*W") disp("Q3/Q1=") 2*COP*n/3 disp("so ratio of heat rejected to body at 450 degree celcius to the heat supplied by the reservoir=0.7482")
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//Variable Declaration rI=-4685.3 //I component of radius vector from Example 2.16(km) rJ=5047.7 //J component of radius vector from Example 2.16(km) rK=-3289.1 //K component of radius vector from Example 2.16(km) aE=6378.1414 //Semimajor axis (km) eE=0.08182 //Eccentricity //Calculation r=sqrt(rI**2+rJ**2+rK**2) a=%pi //Guess value for LST(radians) b=atan(rK/rI) //Guess Value for latitude(radians) c=r-aE //Guess value for height(km) function [ans] = equations(p) L = p(1) h = p(2) LST = p(3) a = rI-((aE/sqrt(1-eE**2*sin(L)**2))+h)*cos(L)*cos(LST) b = rJ-((aE/sqrt(1-eE**2*sin(L)**2))+h)*cos(L)*sin(LST) c = rK-((aE*(1-eE**2)/sqrt(1-eE**2*sin(L)**2))+h)*sin(L) ans = [a;b;c] endfunction ans = fsolve([b;c;a],equations) L = ans(1) h = ans(2) LST = ans(3) L= L*180/3.142 //Converting L into degrees h=round(h) LST=LST*180/3.142 //Converting LST into degrees printf("The latitude of subsatellite is %.2f degrees",L) printf("\nThe height of subsatellite is %.2f km",h) printf("\nThe LST of subsatellite is %.1f degrees",LST)
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//Example 16.9 clc k=3.7 e0=8.85*10^-12//in c2/N.m2 A=6*10^-4//in m2 d=1*10^-3//in m c=(k*e0*A)/d disp("solution a") disp(c,"Capacitance in farad=") disp("solution b") E_max=16*10^6//in v/m delta_v_max=E_max*d disp(delta_v_max,"Voltage in volt") Q_max=delta_v_max*c disp(Q_max,"Maximum charge in columb=")
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so i want to talk to you today about aids in sub saharan africa and this is a pretty well educated audience so i imagine you all know something about aids you probably know that roughly 25 million people in africa are infected with the virus that aids is a disease of poverty and that if we can bring africa out of poverty we would decrease aids as well if you know something more you probably know that uganda to date is the only country in sub saharan africa that has had success in combating the epidemic using a campaign that encouraged people to abstain be faithful and use condoms the abc campaign they decreased their prevalence in the 1990s from about 15 percent to 6 percent over just a few years if you follow policy you probably know that a few years ago the president pledged 15 billion dollars to fight the epidemic over five years and a lot of that money is going to go to programs that try to replicate uganda and use behavior change to encourage people and decrease the epidemic so today i m going to talk about some things that you might not know about the epidemic and i m actually also going to challenge some of these things that you think that you do know to do that i m going to talk about my research as an economist on the epidemic and i m not really going to talk much about the economy i m not going to tell you about exports and prices but i m going to use tools and ideas that are familiar to economists to think about a problem that s more traditionally part of public health and epidemiology and i think in that sense this fits really nicely with this lateral thinking idea here i m really using the tools of one academic discipline to think about problems of another so we think first and foremost aids is a policy issue and probably for most people in this room that s how you think about it but this talk is going to be about understanding facts about the epidemic it s going to be about thinking about how it evolves and how people respond to it i think it may seem like i m ignoring the policy stuff which is really the most important but i m hoping that at the end of this talk you will conclude that we actually cannot develop effective policy unless we really understand how the epidemic works and the first thing that i want to talk about the first thing i think we need to understand is how do people respond to the epidemic so aids is a sexually transmitted infection and it kills you so this means that in a place with a lot of aids there s a really significant cost of sex if you re an uninfected man living in botswana where the hiv rate is 30 percent if you have one more partner this year a long term partner girlfriend mistress your chance of dying in 10 years increases by three percentage points that is a huge effect and so i think that we really feel like then people should have less sex and in fact among gay men in the us we did see that kind of change in the 1980s so if we look in this particularly high risk sample they re being asked did you have more than one unprotected sexual partner in the last two months over a period from 84 to 88 that share drops from about 85 percent to 55 percent it s a huge change in a very short period of time we did n t see anything like that in africa so we do n t have quite as good data but you can see here the share of single men having pre marital sex or married men having extra marital sex and how that changes from the early 90s to late 90s and late 90s to early 2000s the epidemic is getting worse people are learning more things about it we see almost no change in sexual behavior these are just tiny decreases two percentage points not significant this seems puzzling but i m going to argue that you should n t be surprised by this and that to understand this you need to think about health the way than an economist does as an investment so if you re a software engineer and you re trying to think about whether to add some new functionality to your program it s important to think about how much it costs it s also important to think about what the benefit is and one part of that benefit is how much longer you think this program is going to be active if version 10 is coming out next week there s no point in adding more functionality into version nine but your health decisions are the same every time you have a carrot instead of a cookie every time you go to the gym instead of going to the movies that s a costly investment in your health but how much you want to invest is going to depend on how much longer you expect to live in the future even if you do n t make those investments aids is the same kind of thing it s costly to avoid aids people really like to have sex but you know it has a benefit in terms of future longevity but life expectancy in africa even without aids is really really low 40 or 50 years in a lot of places i think it s possible if we think about that intuition and think about that fact that maybe that explains some of this low behavior change but we really need to test that and a great way to test that is to look across areas in africa and see do people with more life expectancy change their sexual behavior more and the way that i m going to do that is i m going to look across areas with different levels of malaria so malaria is a disease that kills you it s a disease that kills a lot of adults in africa in addition to a lot of children and so people who live in areas with a lot of malaria are going to have lower life expectancy than people who live in areas with limited malaria so one way to test to see whether we can explain some of this behavior change by differences in life expectancy is to look and see is there more behavior change in areas where there s less malaria so that s what this figure shows you this shows you in areas with low malaria medium malaria high malaria what happens to the number of sexual partners as you increase hiv prevalence if you look at the blue line the areas with low levels of malaria you can see in those areas actually the number of sexual partners is decreasing a lot as hiv prevalence goes up areas with medium levels of malaria it decreases some it does n t decrease as much and areas with high levels of malaria actually it s increasing a little bit although that s not significant this is not just through malaria young women who live in areas with high maternal mortality change their behavior less in response to hiv than young women who live in areas with low maternal mortality there s another risk and they respond less to this existing risk so by itself i think this tells a lot about how people behave it tells us something about why we see limited behavior change in africa but it also tells us something about policy even if you only cared about aids in africa it might still be a good idea to invest in malaria in combating poor indoor air quality in improving maternal mortality rates because if you improve those things then people are going to have an incentive to avoid aids on their own but it also tells us something about one of these facts that we talked about before education campaigns like the one that the president is focusing on in his funding may not be enough at least not alone if people have no incentive to avoid aids on their own even if they know everything about the disease they still may not change their behavior so the other thing that i think we learn here is that aids is not going to fix itself people are n t changing their behavior enough to decrease the growth in the epidemic so we re going to need to think about policy and what kind of policies might be effective and a great way to learn about policy is to look at what worked in the past the reason that we know that the abc campaign was effective in uganda is we have good data on prevalence over time in uganda we see the prevalence went down we know they had this campaign that s how we learn about what works it s not the only place we had any interventions other places have tried things so why do n t we look at those places and see what happened to their prevalence unfortunately there s almost no good data on hiv prevalence in the general population in africa until about 2003 so if i asked you why do n t you go and find me the prevalence in burkina faso in 1991 you get on google you google and you find actually the only people tested in burkina faso in 1991 are std patients and pregnant women which is not a terribly representative group of people then if you poked a little more you looked a little more at what was going on you d find that actually that was a pretty good year because in some years the only people tested are iv drug users but even worse some years it s only iv drug users some years it s only pregnant women we have no way to figure out what happened over time we have no consistent testing now in the last few years we actually have done some good testing in kenya in zambia and a bunch of countries there s been testing in random samples of the population but this leaves us with a big gap in our knowledge so i can tell you what the prevalence was in kenya in 2003 but i ca n t tell you anything about 1993 or 1983 so this is a problem for policy it was a problem for my research and i started thinking about how else might we figure out what the prevalence of hiv was in africa in the past and i think that the answer is we can look at mortality data and we can use mortality data to figure out what the prevalence was in the past to do this we re going to have to rely on the fact that aids is a very specific kind of disease it kills people in the prime of their lives not a lot of other diseases have that profile and you can see here this is a graph of death rates by age in botswana and egypt botswana is a place with a lot of aids egypt is a place without a lot of aids and you see they have pretty similar death rates among young kids and old people that suggests it s pretty similar levels of development but in this middle region between 20 and 45 the death rates in botswana are much much much higher than in egypt but since there are very few other diseases that kill people we can really attribute that mortality to hiv but because people who died this year of aids got it a few years ago we can use this data on mortality to figure out what hiv prevalence was in the past so it turns out if you use this technique actually your estimates of prevalence are very close to what we get from testing random samples in the population but they re very very different than what unaids tells us the prevalences are so this is a graph of prevalence estimated by unaids and prevalence based on the mortality data for the years in the late 1990s in nine countries in africa you can see almost without exception the unaids estimates are much higher than the mortality based estimates unaids tell us that the hiv rate in zambia is 20 percent and mortality estimates suggest it s only about 5 percent and these are not trivial differences in mortality rates so this is another way to see this you can see that for the prevalence to be as high as unaids says we have to really see 60 deaths per 10 000 rather than 20 deaths per 10 000 in this age group i m going to talk a little bit in a minute about how we can use this kind of information to learn something that s going to help us think about the world but this also tells us that one of these facts that i mentioned in the beginning may not be quite right if you think that 25 million people are infected if you think that the unaids numbers are much too high maybe that s more like 10 or 15 million it does n t mean that aids is n t a problem it s a gigantic problem but it does suggest that that number might be a little big what i really want to do is i want to use this new data to try to figure out what makes the hiv epidemic grow faster or slower and i said in the beginning i was n t going to tell you about exports when i started working on these projects i was not thinking at all about economics but eventually it kind of sucks you back in so i am going to talk about exports and prices and i want to talk about the relationship between economic activity in particular export volume and hiv infections so obviously as an economist i m deeply familiar with the fact that development that openness to trade is really good for developing countries it s good for improving people s lives but openness and inter connectedness it comes with a cost when we think about disease i do n t think this should be a surprise on wednesday i learned from laurie garrett that i m definitely going to get the bird flu and i would n t be at all worried about that if we never had any contact with asia and hiv is actually particularly closely linked to transit the epidemic was introduced to the us by actually one male steward on an airline flight who got the disease in africa and brought it back and that was the genesis of the entire epidemic in the us in africa epidemiologists have noted for a long time that truck drivers and migrants are more likely to be infected than other people areas with a lot of economic activity with a lot of roads with a lot of urbanization those areas have higher prevalence than others but that actually does n t mean at all that if we gave people more exports more trade that that would increase prevalence by using this new data using this information about prevalence over time we can actually test that and so it seems to be fortunately i think it seems to be the case that these things are positively related more exports means more aids and that effect is really big so the data that i have suggests that if you double export volume it will lead to a quadrupling of new hiv infections so this has important implications both for forecasting and for policy from a forecasting perspective if we know where trade is likely to change for example because of the african growth and opportunities act or other policies that encourage trade we can actually think about which areas are likely to be heavily infected with hiv and we can go and we can try to have pre emptive preventive measures there likewise as we re developing policies to try to encourage exports if we know there s this externality this extra thing that s going to happen as we increase exports we can think about what the right kinds of policies are but it also tells us something about one of these things that we think that we know even though it is the case that poverty is linked to aids in the sense that africa is poor and they have a lot of aids it s not necessarily the case that improving poverty at least in the short run that improving exports and improving development it s not necessarily the case that that s going to lead to a decline in hiv prevalence so throughout this talk i ve mentioned a few times the special case of uganda and the fact that it s the only country in sub saharan africa with successful prevention it s been widely heralded it s been replicated in kenya and tanzania and south africa and many other places but now i want to actually also question that because it is true that there was a decline in prevalence in uganda in the 1990s it s true that they had an education campaign but there was actually something else that happened in uganda in this period there was a big decline in coffee prices coffee is uganda s major export their exports went down a lot in the early 1990s and actually that decline lines up really really closely with this decline in new hiv infections so you can see that both of these series the black line is export value the red line is new hiv infections you can see they re both increasing starting about 1987 they re both going down a lot and then actually they track each other a little bit on the increase later in the decade so if you combine the intuition in this figure with some of the data that i talked about before it suggests that somewhere between 25 percent and 50 percent of the decline in prevalence in uganda actually would have happened even without any education campaign but that s enormously important for policy we re spending so much money to try to replicate this campaign and if it was only 50 percent as effective as we think that it was then there are all sorts of other things maybe we should be spending our money on instead trying to change transmission rates by treating other sexually transmitted diseases trying to change them by engaging in male circumcision there are tons of other things that we should think about doing and maybe this tells us that we should be thinking more about those things i hope that in the last 16 minutes i ve told you something that you did n t know about aids and i hope that i ve gotten you questioning a little bit some of the things that you did know and i hope that i ve convinced you maybe that it s important to understand things about the epidemic in order to think about policy but more than anything you know i m an academic and when i leave here i m going to go back and sit in my tiny office and my computer and my data and the thing that s most exciting about that is every time i think about research there are more questions there are more things that i think that i want to do and what s really really great about being here is i m sure that the questions that you guys have are very very different than the questions that i think up myself and i ca n t wait to hear about what they are so thank you very much
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// **** Purpose **** // This function lists all the sublattices within the assigned unit cell // range. // **** Variables **** // [lat_vec]: 3x3, real // <= lattice row vectors // [sublat]: nx3, real // <= cartisian row vectors of each sublattice // [vec_order]: 1x1, integer // <= the unit cell range: n1*a1+n2*a2+n3*a3. If vec_order=1, then // all ni's=-1 ~ +1 // [sublat_list]: tot_uc*tot_sublat x 7 // => sublattices within the assigned ranges. // [uc_index, x,y,z] // **** Version **** // 02/25/2016 first built // **** Comment **** function sublat_list=PIL_sublat_list(lat_vec, sublat, vec_order) uc_list=PIL_nest_loop([-vec_order,vec_order;.. -vec_order,vec_order;-vec_order,vec_order]).. tot_uc=length(uc_list(:,1)); tot_sublat=length(sublat(:,1)); sublat_list=zeros(tot_uc*tot_sublat,7) for n=1:tot_uc sublat_list((n-1)*tot_sublat+1:n*tot_sublat,:)=.. cat(2,cat(2,[1:tot_sublat]',repmat(uc_list(n,:),tot_sublat,1)),.. repmat(uc_list(n,:)*lat_vec,tot_sublat,1)+sublat) end endfunction
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// A Textbook of Fluid Mecahnics and Hydraulic Machines - By R K Bansal // Chapter 3-Hydrostatic Forces on surfaces // Problem 3.17 //Data given in the Problem l=5 w=2 theta=60 g=9.81 W=5000*g dens=1000 //Calculations h=poly(0,"h") //depth of the CG of the body AD=h/sin (theta*%pi/180) A=AD*w H=h/2 //depth of CG of the immersed area F0=dens*g*A*H IG=w*AD^3/(12) COP=IG*(sin(60/180*theta))^2/(A*H)+H //COP of the immersed surface //Using Geometry, CH=COP CD=CH/sin(theta/180*%pi) AC=AD-CD //Taking the moments about the hinge( function f=F(h) f=(W*l-(dens*g*w*h/sin(theta/180*%pi)*h/2*2/(3^1.5)*h)); endfunction h=1 y=fsolve(h,F) mprintf("The value of h is %f m \n",y)
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//Problem 6.11: //initializing the variables: T1 = 540; // in deg F T0 = 300; // in deg F T2 = 300; // in deg F T3 = 60; // in deg F TDDF = 0; m = 1; Cp = 1; //calculation: dShc = m*Cp*log((T0 + 460)/(T1 + 460)) dScc = m*Cp*log((T2 + 460)/(T3 + 460)) //for one exchanger dSc = dShc + dScc //exchanger D dSd = 0 dStot = dSc + dSd printf("\n\nResult\n\n") printf("\n total entropy change is %.4f Btu/deg R",dStot)
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//Chapter-3,Example3_17_1,pg 3-35 A=650*10^-6 //area d=4*10^-3 //seperation of plate Q=2*10^-10 //charge er=3.5 //relative permitivity e0=8.85*10^-12 //absolute permitivity V=(Q*d)/(e0*er*A) printf("voltage across capacitor =") disp(V) printf("Volt")
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clc; //page 229 n=3; // no of segment L=[600,650,250];//mm, Lengths of segment AB , BC and CA respectively x=[300,300,0];//mm, x components of centroids of segment AB , BC and CA respectively y=[0,125,125];//mm, y components of centroids of segment AB , BC and CA respectively sumL=0; sumxL=0; sumyL=0; for(i=1:n) sumL=sumL+L(i); sumxL=sumxL+x(i)*L(i); sumyL=sumyL+y(i)*L(i); end //Location of centre of gravity X=sumxL/sumL;// X co-ordinate Y=sumyL/sumL;// Y co=ordinate printf("Co-ordinates of centroid are X= %.0f mm and Y= %.0f mm \n",X,Y); //There is variation because of roundoff
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a=[1 2 3;1 2 34;2 3 54]; y=peak2peak(a,1); disp(y); //output // 1. 1. 51.
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PL/SQL Developer Test script 3.0 47 declare dateb date; datee date; start_weekb date; start_weeke date; holiday_count integer; week_days_count integer; days_count integer; begin --минимальная дата dateb := least(:date1, :date2); --максимальная дата datee := greatest(:date1, :date2); --число дней между двумя датами days_count := trunc(datee - dateb) + 1; --определяем начало недели для минимальной даты start_weekb := trunc(dateb, 'D'); --определяем начало следующей недели для максимальной даты start_weeke := trunc(datee, 'D') + 7; --число дней между двумя понедельниками (всегда кратно 7) week_days_count := trunc(start_weeke - start_weekb); --количество выходных дней между двумя понедельниками holiday_count := 2 * (week_days_count / 7); --минимальная дата является воскресеньем if (trunc(dateb - start_weekb) = 6) then holiday_count := holiday_days - 1; end if; --максимальная дата является субботой if (trunc(start_weeke - datee) = 2) then holiday_count := holiday_days - 1; --максимальная дата не выходной elsif (trunc(start_weeke - datee) > 2) then holiday_count := holiday_days - 2; end if; --вывод количества рабочих дней dbms_output.put_line(days_count - holiday_days); end; 2 date1 1 16.06.2014 12 date2 1 30.06.2014 12 0
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function [x,y,typ]=INTRPLBLK_f(job,arg1,arg2) x=[];y=[];typ=[]; select job case 'plot' then standard_draw(arg1) case 'getinputs' then [x,y,typ]=standard_inputs(arg1) case 'getoutputs' then [x,y,typ]=standard_outputs(arg1) case 'getorigin' then [x,y]=standard_origin(arg1) case 'set' then x=arg1; graphics=arg1(2);label=graphics(4) model=arg1(3); while %t do [ok,a,b,label]=getvalue('Set Interpolation block parameters',.. ['X coord.';'Y coord.'],list('vec',-1,'vec',-1),label) if ~ok then break,end if size(a,'*') <> size(b,'*') then message('X and Y must have the same size') elseif min(a(2:$)-a(1:$-1)) <=0 then message('X must be strictly increasing') else if ok then graphics(4)=label model(8)=[a(:);b(:)] x(2)=graphics;x(3)=model break end end end case 'define' then a=[0;1];b=[0;1] model=list('intrpl',1,1,[],[],[],[],[a;b],[],'c',[],[%t %f],' ',list()) label=[strcat(sci2exp(a));strcat(sci2exp(b))] gr_i=['xstringb(orig(1),orig(2),''interp'',sz(1),sz(2),''fill'');'] x=standard_define([2 2],model,label,gr_i) end
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//Calculate efficiency //Chapter 3 //Example 3.22 //page 231 clear; clc; disp("Example 3.22") kVA=200; //Rating of the transformer Pin=3.4; //power input to two transformer in watt Pin2=5.2; coreloss=Pin; //core loss of two transformers phi=acosd(0.8); printf("\nCore loss of two transformer=%fkW",Pin) printf("\nCore loss of each transformer=%fkW",(Pin/2)) printf("\nFull load copper loss of the two transformer=%fkW",Pin2) printf("Therefore,full load copper loss of each transformer=%fkW",(Pin2/2)); effi=(kVA*cosd(phi)*100)/((kVA*cosd(phi))+(Pin/2)+(Pin2/2)) printf("\nFull load efficiency at 0.8 p.f. lagging=%fpercent",effi);
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//pathname=get_absolute_file_path('3.16.sce') //filename=pathname+filesep()+'3.16-data.sci' //exec(filename) //Initial pressure(in MPa): pi=0.5 //Initial volume(in m^3): vi=0.5 //Final pressure(in MPa): pf=1 //Atmospheric pressure(in Pa): patm=1.013*10^5 //Final volume(in m^3): vf=3*vi //Work done(in J): W=(vf-vi)*(pi+pf)*10^5/2 printf("\nRESULT\n") printf("\nWork done = %d J",W)
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// Test #12 : For complex vector inputs including flag exec('./zpklp2mb.sci',-1); [z,p,k,n,d]=zpklp2mb([%i,4*%i],[3*%i,7*%i],4,0.6,[0.1 0.6],'stop'); disp(d); disp(n); disp(k); disp(p); disp(z); // //Scilab Output //d=1. - 0.5403505 - 0.1583844 //n=- 0.1583844 - 0.5403505 1. //k=0.7650736 - 0.0932510i //p=0.8086215 - 0.1432355i // -0.2792558 + 0.3513001i // 0.7646324 - 0.0715126i // -0.2263041 + 0.1608860i //z=0.9710158 - 0.2390153i // - 0.5273774 + 0.8496311i // 0.7874479 - 0.1156085i // - 0.2532839 + 0.2718469i // //Matlab Output //z = 0.9710 - 0.2390i // -0.5274 + 0.8496i // 0.7874 - 0.1156i // -0.2533 + 0.2718i //p = 0.8086 - 0.1432i // -0.2793 + 0.3513i // 0.7646 - 0.0715i // -0.2263 + 0.1609i //k = 0.7651 - 0.0933i //n = -0.1584 -0.5404 1.0000 //d = 1.0000 -0.5404 -0.1584
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Chapter3_Example11.sce
//Hougen O.A., Watson K.M., Ragatz R.A., 2004. Chemical process principles Part-1: Material and Energy Balances(II Edition). CBS Publishers & Distributors, New Delhi, pp 504 //Chapter-3, Illustration 11, Page 63 //Title: Calculation of volume change with change in composition //============================================================================= clear clc //INPUT v = 100; //Volume of gas entering in cu ft p = [59,0.5]; //Partial pressures of chlorine before entering and after leaving the absorption apparatus in mm Hg P = [740,743]; //Pressure of entering and leaving the apparatus in mm Hg T = [75,80]; //Temperature of the gas entering and leaving the apparatus in degree F T3 = 492; //Temperature at standard conditions in degree R P3 = 760; //Pressure at standard conditions in degree R MW = 71; //Molecular weight of chlorine in lb/lb mole //CALCULATIONS p1 = P(1)-p(1); //Partial pressure of inert gas entering in mm Hg p2 = P(2)-p(2); //Partial pressure of inert gas leaving in mm Hg T1 = T(1)+460; //Temperature of gas entering in degree R T2 = T(2)+460; //Temperature of gas leaving the apparatus in degree R v1 = v*(p1/p2)*(T2/T1); //Volume of inert gas leaving in cu ft v2 = v*(p(1)/P3)*(T3/T1); //Volume at standard conditions of chlorine entering in cu ft v3 = v*(p(2)/P3)*(T3/T2); //Volume at standard conditions of chlorine leaving in cu ft V = v2-v3; //Volume at standard conditions of chlorine absorbed in cu ft n = V/359; //No of moles of chlorine absorbed in lb mole W = n*MW; //Weight of chlorine absorbed in lb //OUTPUT mprintf('\n (a) Volume of gases leaving the apparatus per %3.0f cu ft entering is %3.1f cu ft \n (b) Weight of chlorine absorbed per %3.0f cu ft of gas entering is %3.2f lb',v,v1,v,W); //========================END OF PROGRAM=======================================
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clc; v=2300; // rated voltage of motor xs=12 ; // per phase synchronous reactance p=200000; // VA rating of motor l1=120000; // initial load l2=60000; // final load vt=v/sqrt(3); // rated per phase voltage ia=l1/(3*vt); // minimum armature current ia1=1.5*ia; // armature current at reduced load (50% increment) pf=1/1.5; // power factor Ef=sqrt((vt*pf)^2+(vt*sqrt(1-pf^2)+ia1*xs)^2); // excitation EMF de=asind((l2*xs)/(3*vt*Ef)); // new load angle ia2=(sqrt(vt^2+Ef^2-2*Ef*vt*cosd(de)))/xs; // new armature current printf('New value of armature current is %f A\n',ia2); pfn=l2/(3*vt*ia2); printf('Power factor at new armature current is %f leading',pfn);
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//Ex:92 clc; clear; close; b_c=72;//carrier BW in MHz f_c=1190;//Center freq in MHz f_i=140;// first intermediate freq in MHz f_smx=14500;//max uplink freq spectrum in MHz f_smn=14000;//min uplink freq spectrum in MHz f_l1=f_c-f_i;// in MHz; f_l1=f_c-f_i;// in MHz f_l2mx=f_smx-f_c;// in MHz f_l2mn=f_smn-f_c;// in MHz f_s1=f_smx-2*(f_l1+f_i); f_s2=f_smn-2*(f_l1+f_i); b_pf1=140;// in MHz b_pf2=500;// in MHz printf("The first local oscillator frequency=%f MHz", f_l1); printf("\n The max second oscillator frequency =%f GHz", f_l2mx/1000); printf("\n The min second oscillator frequency =%f GHz", f_l2mn/1000); printf("\n The max frequency spectrum =%f GHz", f_s1/1000); printf("\n The min frequency spectrum =%f GHz", f_s2/1000); printf("\n The BW of BPF-1=%f MHz", b_pf1); printf("\n The BW of BPF-1=%f MHz", b_pf2);