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clc;funcprot(0);//Example 5.5 //Initilisation of Variables x1=0.3;....//distance 1 in m x2=0.5;....//distance 2 in m L=1;...//Length of the flat plate in m T=300;...//Temperature of air in K p=1;.....//Air pressure in bar v=5;...//Velocity of air in m/s mu=1.85*10^-5;...//Viscosity of air in kg/m s R=0.287;.....
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// 6.2 clc; Vcc=4.76; t=50*10^-6; R=0.2*10^3; C=0.2*10^-6; tc=R*C; Vo=Vcc*[exp(-t/tc)]; printf("\nvoltage across the capacitor after 50 microsecond=%.2f V",Vo)
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clc clear //1iii function [f,df]= newtonraphsonFunc(x) f = (x^3)-(x)-3; df =(3*x^2)-1; endfunction //main x=[0.0]; maxIteration = 100; Iteration=[0]; tolerance = 0.000001; large = 10^200; difference = 1; while(1) if ((Iteration($)== maxIteration)||(difference<tolerance)||(abs(x($))>large)) th...
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s=%s; L=0.5; G0=1/((s+1)*(s+4)); DelayN=1-(L/2)*s+(1/10)*(L*s)^2-(1/120)*(L*s)^3; DelayD=1+(L/2)*s+(1/10)*(L*s)^2+(1/120)*(L*s)^3; Delay=DelayN/DelayD
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//ques-25.27 //Calculating coefficient of viscosity of benzene clc t1=46;//time taken by benzene (in s) t2=68;//time taken by water (in s) den1=0.8;//density of benzene (in g/mL) den2=0.998;//density of water (in g/mL) visc2=1.008;//coefficient of viscosity of water (in centipoise) visc1=(den1*t1*visc2)/(den2*t...
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clear; clc; close; f = 1000; T = 1/f; C = 0.1*10^(-6); R = 100*10^(3); Vk = 0.7; //between t1-->t2 vo_1 = 4.3; Vc = 25-0.7; //between t2-->t3 Rth = 0; Eth = 4.3; vo_2 =34.3; tau = R*C; discharge_time = 5*tau; //between t3-->t4 vo_3 = 5; disp(vo_1,'output voltage during t1-->t2 : '); disp(vo_2,'out...
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clear; clc; x=0:.1:11 f=0.2; plot(x,sin(2*%pi*x*f)); xtitle('Continuous Sine Signal') xlabel('x') ylabel('sin(x)')
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//Chapter-2,Example2_4_4,pg 2-25 wavelength=6328*10^-10 //wavelength of light m1=1 //for first order m2=2 //for second order N= 6000*10^2 //Number of lines per unit lengt...
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//Example 8.2 clear; clc; R=159*10^3; C=10*10^(-9); f0=1/(2*%pi*R*C); ft=10^6; fx=sqrt(f0*ft); Q=sqrt(ft/f0); d=-90-((180/%pi)*atan(fx/f0)); pm=180+d; printf("fx=%.2f kHz",fx*10^(-3)); printf("\nQ=%.f",Q); printf("\nPhase Margin (PM)=%.1f degrees",pm);
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function [w]=l2r(x) w=r2l(x')'
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clc clear //INPUT DATA x=6.40*10^7//electrical conductivity in mho m^-1 t=300//temperature of copper in k L=2.44*10^-8//Lorentz number in W ohm K^-2 //CALCULATION K=x*t*L//thermal conductivity of copper in W m^-1 K^-1 //OUTPUT printf('The thermal conductivity of copper is %3.2f W.m^-1.K^-1',K)
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A = imread("C:\Users\ADMIN\Documents\PHYSICS\6thYear\186\AP186\186A6\correlation\A.png"); A = rgb2gray(double(A)); B = imread("C:\Users\ADMIN\Documents\PHYSICS\6thYear\186\AP186\186A6\correlation\phrase.png"); B = rgb2gray(double(B)); //get FT of A & B ftA = fft2(A); f=scf(); imshow(fftshift(uint8(imnorm(abs(ftA))*25...
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//example6.4 clc disp("a) The drop across the shunt is same as drop across the coil.") disp("Therefore, [(I_sh)*(R_sh)]=400 mV") i=(400*10^-3)/0.01 disp(i,"Therefore, I_sh(in A)=(400*10^-3)/0.01= ") disp("b) The voltage across shunt for shunted current of 50 A is,") v=50*0.01 disp(v,"V_sh(in V)=[(I_sh)*(R_sh)]=...
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//Example 4.16 A random sample of 10 students of class II was selected from schools in a certain region clc; clear; x=[38 46 45 40 35 39 44 45 33 37]; n=10; m=sum(x)/n; s=sqrt(18.96); disp((m+2.26*(s/3)),"to",(m-2.26*(s/3)),"The 95% confidence limits for mean weight are "),
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function precisao = verifica(A,p) [l,c] = size(A) precisao = 0 //supoe verdadeira para dps verificar se é realmente ;) for i = 1 : l for j = 1 : c if (i > j) then //para elementos abaixo da diag if (abs(A(i,j)) > p) then precisao = 1 //nao atingiu o valor d...
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function set_linewidth(h,lw) // Does nothing endfunction
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clear;lines(0); bool2s([%t %t %f %t]) bool2s([2.3 0 10 -1])
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errcatch(-1,"stop");mode(2); disp('Data is not provided,only graph is provided') exit();
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// Example 4.1, page no-209 clear clc //(a) k=50 m=0.005 wn=sqrt(k/m) printf("(a)\nNatural frequency(wn)= %d rad/s",wn) //(b) Cc=2*sqrt(m*k) printf("\n(b)\nCc=%d",Cc)
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clear clc //Example 14.9 CENTRIFUGAL COMPRESSOR p1=100; //pressure [kPa] p2=200; //[kPa] k=1.4; Q1=1;//discharge [m^3/s] eta=0.65; //efficiency //Theoretical power Ptheo=(k/(k-1))*Q1*p1*[(p2/p1)^((k-1)/k)-1] //[kW] //Shaft power Pshaft=Ptheo/eta //[kW] printf("\nThe shaft power required to operate the compr...
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//Ex19_12 Pg-962 clc oct='257'; //binary input dec=oct2dec(oct) //decimal output disp("The decimal equivalent of 257 is") disp(dec)
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//Example6_34 // To design a phase shifter clc; clear; close; f = 2*10^3 ; PS = -135 ; // the phase shift // PS = -2*atand(2*%pi*R*C); //RC = 192.1*10^-6 ; C = 0.1*10^-6 ; R = (192.1*10^-6)/C disp('The value of resistance is = '+string(R)+ ' ohm');
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errcatch(-1,"stop");mode(2);//Part B Chapter 4 Example 9 ; ; d=120;//mm D1=120;//mm D2=60;//mm ThBYTs=(D1^4-D2^4)/d^4; WhBYWs=%pi/4*((D1^2-D2^2)/(%pi/4)/d^2); disp("Strength ratio, Th/Ts is "+string(ThBYTs)); disp("Weight ratio, Wh/Ws is "+string(WhBYWs)); exit();
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argc:7 Dataset: ../datasets/converted/football.net Nodes Edges Com Mod NMI Time seq async 115 1226 9 0.602529 -1 0.000248959 par async 115 1226 13 0.50171 -1 0.071628
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//find.. clc //soltuion //given d1=400//mm r1=200//mm d2=1600//mm r2=800//mm q1=2.5//rad q2=3.78//rad u1=0.3 u2=0.25 N1=700//rpm P=22.5*10^3//W t=0.005//mm f=2.3*10^6//N/m^2 //ref fig 18.19 v=%pi*N1*d1/60//m/s //let T1 and T2 be tneion on tight and slag side printf("the vel of belt is,%f m/s\n",v) ...
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clear clc //Example 11.6 disp('Example 11.6') //Drawing on example 11.4 s=%s; theta=1;tau=100;K=100; delay=(1-theta/2*s+theta^2/10*s^2-theta^3/120*s^3)/(1+theta/2*s+theta^2/10*s^2+theta^3/120*s^3);//Third order pade approx G=K*delay/(tau*s+1); Kc=0.556;taui=5; Gc=Kc.*(1+(1)./([taui]*s)) G_CL=syslin('c',Gc*G./(1+Gc*...
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function [f]=%ras(f,m) // f=%ras(f,m) <=> f = f+m //! [p,q]=size(m); if p+q=-2 then m=m*eye(f(3)); end; if p*q=1 then f(2)=f(2)+m*f(3);return;end f(2)=f(2)+m.*f(3)
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//COMO USAR: //A=[x0 x1 x2 ... xN] //D=[f[x0] f[x0 x1] ... f[x0...xN]] //N=grado del polinomio //horner(A,D,N,x) //Grafico f(x) //x=-10:0.1:10; //plot2d(x, f(x)); //xgrid(3,1,7); //muestra grilla function horner(X,d,N,x) // X=vector de raices, d=diferencias divididas, N=grado(P(x)) p=d(N+1); // es N+1 porque lo...
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//Given that lambda = 550*10^-9 //in m T = 300 //in K room temprature h = 6.62*10^-34 //in J-s c = 3*10^8 //in m/s e = 1.6*10^-19 K = 8.62*10^-5*e //Sample Problem 41-6a printf("**Sample Problem 41-6a**\n") deltaE = h*c/lambda ratio = %e^(-(deltaE)/(K*T)) printf("The ratio is equal to %e\n", ratio) ...
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// function [B,degB] = ext(A,degA,k,l) // EXTRACTS THE (k,l) ELEMENT OF A polynomial matrix A into B function [B,degB] = ext(A,degA,k,l) [rA,cA] = polsize(A,degA); degB = degA; B = zeros(1,degB+1); for m = 0:degB B(1,m+1) = A(k,(m*cA)+l); end [B,degB] = clcoef(B,degB); endfunction;
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errcatch(-1,"stop");mode(2);//Chapter 19,Example 2,page 667 //Determine the pumping pressure p0 = 30*10^-3 // C/m^3 V = 30*10^3 // V P = p0*V printf("\n The pumping pressure P = %f N/m^2",P) // Answers may vary due to round off error exit();
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//**************************** Min_detect ********************************** if (blk_name.entries(bl) == "Min_detect") then mputl("#Min_detect",fd_w); for ss=1:scs_m.objs(bl).model.ipar(1) Min_detect_str= '.subckt Min_detect'+' in[0]=net'+string(blk(blk_objs(bl),2))+'_'+string(ss)+' out[0]=net'+string(b...
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//Initilization of variables L=1000 //lb P=10 //lb //Calculations mu=log(L/P)/(4*2*%pi) //Result clc printf('The coefficient of friction is %f',mu)
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::::::::::::::::::::::::::: ::deep SHA256 round testing bitseal 64-bit Debian 7 vps passwd: 'Satoshi Nakamoto' sharnd: '0x93a4bfec9','39632764617' calctm: '17674 secs' prvkey: '26f8f2f71b246d21bf292d724648ff00452e32060c0ed8b7811f3817886d04c2' prvb58: '5J7T5dUirMX2LLJVoVy3gxxVBUFNrifK7hRaUbwvK89QxeAvNj5' pubb58: '1Dx6nf...
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clc // Given that theta = 13 // rotation of plane of polarization in degree s = 65 // specific rotation of sugar solution in degree per decimeter per unit concentration l = 2 // length of Polari meter in decimeter // Sample Problem 20 on page no. 221 printf("\n # PROBLEM 20 # \n") c = theta / (s * l) // calculation fo...
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errcatch(-1,"stop");mode(2);//Example 1.18.1: voltage of the capacitor ; ; format('v',7) r=10;//in ohms l=10;///inductance in mH c=10;//capacitance in micro farads v=100;//in volts t=((%pi)/(sqrt((1/(l*10^-3*c*10^-6))-(r^2/(4*(l*10^-3)^2)))));// time in seconds vc= v*(1-cosd(t/(sqrt(l*10^-3*c*10^-6))));//in volts disp...
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//x+2*y=5, 3*x-2*y=7 clear; clc; close; x=poly(0,'x'); //graph of x+2*y=5 x=[0 -1 2 5]; y=(5-x)/2; x_vs_y=[x;y]; plot(x,y,'b--.x') //graph of 3*x-2*y=7 x=[0 -1 7/8 4]; y=(3*x-7)/2; plot(x,y,'b--.o') for x=1:100 if((5-x)/2==(3*x-7)/2) break end end mprintf("the solution of the equation is")...
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clc; // Air conditioning unit TL=278; // Operating temperature in kelvin TH=318; // Operating temperature in kelvin COP1=TL/(TH-TL); // COP of Air conditioning unit QL=1; // For some calculation purpose W1=QL/COP1; // Work input of Air conditioning unit // Food refrigeration unit TL=258; // Operating temperatur...
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//simplify 3a(a^2-4ab+4b^2)/6a(a^2+3ab-10b^2) clear; clc; close; //the factors 3a(a-2b) are common to numerator & denominator. mprintf("\n the fraction is :\n") string('(a-2b)/(2a(a+5b))')
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clc; E=400; // supply voltage l1=200; // load connected across 75% tapping l2=400; // load connected between 25% and 100% tapping t1=25; // 25% tapping point t2=50; // 50% tapping point t3=75; // 75% tapping point V2=(t3/100)*E; // voltage across 200 ohm load I2=V2/l1; // current through 200 ohm load I1=(V2*I2...
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function [x,y,typ] = mdaq_dac(job,arg1,arg2) dac_desc = ["This block sets MicroDAQ analog outputs (AO)."; "DAC block allows to set terminate voltage which will be set at"; "the end of simulation in Ext mode."; ""; "User can use option Terminate all DACs with voltage to set"; "same voltage at al...
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//Variable declaration: D = 5 //Diameter of pipe (ft) V = 10 //Fluid velocity (ft/s) p = 50 //Fluid density (lb/ft^3) u = 0.65 //Fluid viscosity (lb/ft.s) F = 1.0/12.0 //Feet in an inch VCp = 6.72*10**-4 //Viscos...
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clear; clc; // Illustration 3.2 // Page: 56 printf('Illustration 3.2 - Page: 56\n\n'); // solution //***Data****// d = 0.025;// [m] avg_velocity = 3;// [m/s] viscosity = 8.937*10^(-4);// [kg/m.s] density = 997;// [kg/m^3] //*********// kinematic_viscosity = viscosity/density;// [square m/s] Re = ...
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G = zeros(3,3) d = [1 0 0]' x0 = [1 0 0]' for i=1:3 for j=1:3 if i==j then G(i,j) = 1/2 end if abs(i-j) == 1 then G(i,j) = 1/4 end end end cu = 0 x1 = 0 cont = 0 while cu~=69 x1 = G*x0+d if norm((x0-x1),1) < 10^(-2) then cu = 69...
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// Network Synthesis : example 12.6 : (pg 12.4) s=poly(0,'s'); p1=((2*(s^4))+(6*(s)^2)+1); p2=((5*(s^3))+(3*s)); [r,q]=pdiv(p1,p2); [r1,q1]=pdiv(p2,r); [r2,q2]=pdiv(r,r1); [r3,q3]=pdiv(r1,r2); printf("\nEven part of P(s) = ((2*s^4)+(6*(s)^2)+1)"); printf("\nOdd part of P(s) = ((5*s^3)+(3*s))"); printf("\nQ(s)...
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Name=Juggling Aimer PlayerCharacters=Juggler BotCharacters=Juggling Ball.bot IsChallenge=true Timelimit=60.0 PlayerProfile=Juggler AddedBots=Juggling Ball.bot;Juggling Ball.bot;Juggling Ball.bot PlayerMaxLives=1 BotMaxLives=0;0;0 PlayerTeam=1 BotTeams=2;2;2 MapName=juggling_arena.map MapScale=1.0 BlockProjectilePredict...
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clc //initialization of new variables clear u=12 //m/s w=10 //m L=4 //m rho=1.22 //kg/m^3 mu=1.8*10^-5 //calculations ReL=rho*u*L/mu Cd=0.0032 //from figure D=2*Cd*1/2*rho*u^2*(w*L) //results printf('Total drag on plates is %.2f N',D)
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//calculation of nuclear binding energy clear; clc; printf("\t Example 23.2\n"); NA=6.022*10^23;//avogadro number c=3*10^8;//speed of light, m/s p=1.007825;//mass of proton, amu n=1.008665;//mass of neutron, amu mI=126.9004;//atomic mass of I, amu pI=53*p+74*n;//estimated mass of I, amu deltam=mI-pI;//m...
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//Eg-8.3 //pg-369 clear clc A = [2 3 1 4 5]; n = length(A); for(i = 2:n) t = A(i); j = i; while((j > 1) & (A(j-1) > t)) A(j) = A(j-1); j = j-1; end A(j) = t; end printf('Using the insertion sort method the arranged form of the given array\n') disp(A)
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//Initilization of variables P=[4.82, -2.33, 5.47] //N Q=[-2.81,-6.09,1.12 ] //m //Calculations M=P*Q' //Nm //Results clc printf('Result is:%f N.m',M) //N-m
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syms G1 G2 G3 G4 G5 H5 //with X(s)=0 a= G2/(G2+1) b= a*G3*(G5/(1+G5*H5)) //G5 and H5 are in a loop c= b/(1+b) //unity feedback Y= G1*c disp(Y,"R/S=") //with R(s)=0 x=G2/(1+G2) y=G5/(1+G5*H5) z=x*(-G3) Y2=y/(1-(z)) disp(Y2,"X/C = ")
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clear; clc; //Example - 11.8 //Page number - 394 printf("Example - 11.8 and Page number - 394\n\n"); //This problem involves proving a relation in which no mathematics and no calculations are involved. //For prove refer to this example 11.8 on page number 394 of the book. printf(" This problem involves provi...
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clc(); clear; // To calculate the wavelength of an electron V=10; //potential in kV V=V*10^3; //potential in V lamda=12.26/sqrt(V); //wavelength printf("The wavelength is %f Armstrong",lamda);
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//caption:stability_using_Routh-hurwitz_criterion //example 7.5.3 //page 203 s=%s; A=s^5+4*1.5*s^4+4*s^3+4*s^2+5*s+10; C=2*s+5; CL=A/C; disp(CL,"C(s)/R(s)="); disp('=0',A,"characteristics eq is:") b=coeff(A) n=length(b) B=routh_t(A) disp(B,"routh table:"); c=0; r=1; for(i=1:n) if(B(i,1)<0) c=c+1;...
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clc //Initialization of variables Q=0.6 //m^3/s l1=1200 //m l2=800 //m d1=0.3 //m //calculations V1=1.02 //m/s d5= d1*l2*4^2 *Q^2 /(l1*%pi^2 *V1^2) d=d5^(1/5) //results printf("diameter of the single pipe = %.2f m",d)
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// Exercise A19 // ------------ // Find the relative and absolute error of // n! ~ sqrt(2·Pi·n)·(n/e)^n // for n = 1, ..., 10 MIN = 1 MAX = 10 STEP = 1 for n = MIN : STEP : MAX orig_val = factorial(n) appr_val = sqrt(2 * %pi * n) * (n / %e)^n abs_err = abs(orig_val - appr_val) rel_err = abs(abs_err / orig_val)...
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.341965D+00 ...
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clear// //Variables VS1 = 5 //Voltage source 1 (in volts) VS2 = 3 //Voltage source 2 (in volts) V6 = 0 //Voltage drop across 6 ohm resistor when AB is open (in volts) R1 = 6 //Resistor (in ohm) R2 = 4 //Resistor (in ohm) //Calculation I = 5.0/4 ...
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//Ex11_7 clc; //Given: density1=11.35;// density of copper l=6.022*10^23;// avogadro constant ue=0.211;// electron absorption coefficent in barn per electron // 1 b=10^(-24) cm^2 //solution: uPb=ue*82;//atomic absorbtion coefficient in b/atom umPb=(6.022*10^23*uPb*10^-24)/207.2; // mass absorbtion co...
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function LU(a,n) n = input('nº de equações' ) //matriz for k = 1,n - 1 for i = k + 1,n fator = a(i,k),k/a(k,k) a(i,k) = fator for j = k + 1,n a(i,j) = a(i,j) - fator * a(k,j) end endfunction
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// Exa 9.21 clc; clear; close; format('v',8) // Given data VA = 400*10^3;// in Mean Eta_fl = 98.77/100;// in % phi1= acosd(0.8);// in ° phi2= acosd(1);// in ° Eta_hl = 99.13/100;// in % n = 1/2; //For full load, Eta_f1 = ((VA*cosd(phi1))/( VA*cosd(phi1) + Pi + Pcu_f1 )) or Pi+Pcu_f1 = VA*cosd(phi1)*(1-Eta_...
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//Chapter 07: Discrete Probability clc; clear; max_integers=100 E1=100/2 //event that random integer is divisible by 2 E2=100/5 //event that random integer is divisible by 5 E1IE2=100/(5*2) //event that random integer is divisible by 5 and 2 pE1=E1/max_integers //probability of event E1 pE2=E2...
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// Scilab code Ex11.1: Pg 380 (2005) clc; clear; // Part (a) f = 1.15e+11; // Frequency of transitions, Hz omega = 2*(%pi)*f; // Angular frequency of absorbed radiations, Hz h_cross = 1.055e-34; // Reduced planks constant, J-s // Since E = (h_cross)^2/I_CM = h_cross*omega, solving for I_CM I_CM = h_cross/...
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//Chapter-5, Example 5.42, Page 209 //============================================================================= clc clear //INPUT DATA V1=400;//voltage in volts Z1=(3+((%i)*4));//impedance in ohms //CALCULATIONS //in star connected system,phase voltage=(line voltage) Ep=V1/(sqrt(3));//voltage in volts Ip=...
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//example 2.14 //aitken's process //page 36 clc,clear,close deff('x=f(x)','x=(3+cos(x))/2'); x0=1.5; y=0; e=0.0001; c=0; printf('successive iterations \tx0\t x1\t x2\t x3\t y\n') for i=1:10 x1=f(x0),x2=f(x1),x3=f(x2); y=x3-((x3-x2)^2)/(x3-2*x2+x1); d=y-x0; x0=y; if ...
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//Rodríguez Montiel Moises Ulises //2MN51 function X = jacobi(A, B, fx) [m,n] = size(A) iter = 0 if (m <> n) then error("La matriz no es cuadrada.") end e = 5*10^-fx X = zeros(n, 1); y=[]; fin=%F; while fin==%F fin=%T; for i=1:1:n y(i)=B(i); ...
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function [x,y,typ]=EVTGEN_f(job,arg1,arg2) x=[];y=[];typ=[]; select job case 'plot' then standard_draw(arg1) graphics=arg1(2); [orig,sz,label]=graphics([1:2 4]) model=arg1(3);tt=model(11) xstringb(orig(1),orig(2),['Event at';'time '+string(tt)],sz(1),sz(2),'fill') case 'getinputs' then [x,y,typ]=standard_inp...
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//find clc //solution //given b=6//mm t1=0.25//mm l=2500//mm t=800//N/mm^2 E=200*1000//N/mm^2 M=t*b*t1^2/(12)//N-mm printf("bending moment is,%f N-mm\n",M) q=12*M*l/(E*b*t1^2)//rad printf("angular def is,%f rad\n",q) U=0.5*M*q printf("energy stored is,%f N-mm",U)
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clear; clc; V_p=18; n=.72; V_BB=V_p/n; I_p=.6*10^-3; I_v=2.5*10^-3; V_v=1; R_max=V_BB*(1-n)/I_p; printf("R_max=%.2f kilo-ohm",R_max/1000); R_min=(V_BB-V_v)/I_v; printf("\nR_min=%.2f kilo-ohm",R_min/1000); C=.04*10^-6; f_min=1/(R_max*C*log(1/(1-n))); printf("\nf_min=%.3f kHz",f_min/1000); f_max=1/...
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//fonction : 'triGauss' //paremetre : A une matrcie ,b,un vecteur de reel //retour ; A un vecteur TS, b un vecteur de reel function [At,bt]=trigGauss(A,b) n = length(b); for k = 1:n-1 if A(k,k)=0 printf("erreur"); return 1; else for i = k+1:n ...
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clc clear //input vp=440;//primary voltage in volts vs=240;//secondary voltage in volts f=50;//supply voltage in hertz i0=0.5;//no load current in amperes pf=0.3;//lagging power factor //calculations ii=i0*pf;//in phase component in amperes r0=vp/(ii*1000);//resistance in ohms iq=((i0^2)-(ii^2))^0.5;//qu...
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clc // Given that B = 20 // Width of the cut in mm Z = 10 // No of teeth in milling cutter D = 75 // Diameter of the milling cutter in mm alpha = 10 // Radial rake angle in Degree f = 25 // Feed velocity of the table in mm/min N =60 // Rpm of the cutter t = 5 // Depth of cut in mm mu = 0.5 // Cofficient of friction T_...
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//Chapter 13, Problem 1, Figure 13.3, clc; //branch currents in figure 13.3 (a) I1=50-20; I2=20+15; I3=I1-120; I4=15-I3; I5=120-40; disp("(a) from Fig. 13.3(a)."); disp("For junction B:"); printf("I1 = %d A",I1); disp("For junction C:"); printf("I2 = %d A",I2); disp("For junction D:"); printf("I3 = %d ...
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// Example 9_16 clc;funcprot(0); // Given data T_3=-10+273;// K T_2=-40+273;// K r=10;// The compression ratio c_p=1.00// kJ/kg.K k=1.4;// The specific heat ratio // Calculation T_4=T_3*(r)^((k-1)/k);// K T_5=T_3;// K T_6=T_2;// K T_1=T_6*(1/r)^((k-1)/k);// K T_1C=T_1-273;// The minimum cycle temperature...
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## Regression test authors write format # Expected format: USER = Name <USER@DOMAIN> read <authorswrite.fi authors write
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V4.6 français commentaireManip= Manip training1 2010 rédigé par Joceline !! TACHE DE DETECTION NATIO2 nbreCoups= 251 numeroVhSujet= 0 autoriserHyperDepSgi= oui lancerMdv= non sautAleatoire= Oui INSTRUCTION_VARIABLES() DECLARE(dist,ENTIER) AFFECTE(dist,0) FIN INSTRUCTION(0,0,FAUX,FAUX,VRAI,VRAI) SI Immediate() ...
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clear; clc; close; amp = 20; vi_t = -5;//transition voltage t = 0:0.1:2*%pi; vi = amp*sin(t); vo = vi+5; //output voltage disp(vi_t,'transition voltage : '); for i = 1:length(t) if(vo(i)<=0) vo(i)=0; end end plot(t,vo); xtitle('Ouptut voltage','t','vo');
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//Chapter-13, Example 13.16, Page 391 //============================================================================= clc clear //INPUT DATA deltaIe=1*10^-3;//change in emitter current in A deltaIc=0.995*10^-3;//change in collector current in A //CALCULATIONS a=deltaIc/deltaIe;//common-base DC current gain b=a...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Engineering Thermodynamics by Onkar Singh Chapter 4 Example 15") T1=(500+273);//temperature of source in K T2=(200+273);//temperature of sink in K T3=(450+273);//temperature of body in K disp("let the output of...
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//Variable Declaration rI=-4685.3 //I component of radius vector from Example 2.16(km) rJ=5047.7 //J component of radius vector from Example 2.16(km) rK=-3289.1 //K component of radius vector from Example 2.16(km) aE=6378.1414 //Semimajor axis (km) eE=0.08182 //Eccentricity //Calculation r=sqrt(rI**2+rJ**2+rK...
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//Example 16.9 clc k=3.7 e0=8.85*10^-12//in c2/N.m2 A=6*10^-4//in m2 d=1*10^-3//in m c=(k*e0*A)/d disp("solution a") disp(c,"Capacitance in farad=") disp("solution b") E_max=16*10^6//in v/m delta_v_max=E_max*d disp(delta_v_max,"Voltage in volt") Q_max=delta_v_max*c disp(Q_max,"Maximum charge in columb=")
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so i want to talk to you today about aids in sub saharan africa and this is a pretty well educated audience so i imagine you all know something about aids you probably know that roughly 25 million people in africa are infected with the virus that aids is a disease of poverty and that if we can bring africa out of pover...
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// **** Purpose **** // This function lists all the sublattices within the assigned unit cell // range. // **** Variables **** // [lat_vec]: 3x3, real // <= lattice row vectors // [sublat]: nx3, real // <= cartisian row vectors of each sublattice // [vec_order]: 1x1, integer // <= the unit cell range: n1*a1+n2*a2+n3*...
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// A Textbook of Fluid Mecahnics and Hydraulic Machines - By R K Bansal // Chapter 3-Hydrostatic Forces on surfaces // Problem 3.17 //Data given in the Problem l=5 w=2 theta=60 g=9.81 W=5000*g dens=1000 //Calculations h=poly(0,"h") //depth of the CG of the body AD=h/sin (theta*%pi/180) A=AD*...
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//Problem 6.11: //initializing the variables: T1 = 540; // in deg F T0 = 300; // in deg F T2 = 300; // in deg F T3 = 60; // in deg F TDDF = 0; m = 1; Cp = 1; //calculation: dShc = m*Cp*log((T0 + 460)/(T1 + 460)) dScc = m*Cp*log((T2 + 460)/(T3 + 460)) //for one exchanger dSc = dShc + dScc //exchanger D...
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//Chapter-3,Example3_17_1,pg 3-35 A=650*10^-6 //area d=4*10^-3 //seperation of plate Q=2*10^-10 //charge er=3.5 //relative permitivity e0=8.85*10^-12 //absolute...
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clc; //page 229 n=3; // no of segment L=[600,650,250];//mm, Lengths of segment AB , BC and CA respectively x=[300,300,0];//mm, x components of centroids of segment AB , BC and CA respectively y=[0,125,125];//mm, y components of centroids of segment AB , BC and CA respectively sumL=0; sumxL=0; sumyL=0; for(...
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a=[1 2 3;1 2 34;2 3 54]; y=peak2peak(a,1); disp(y); //output // 1. 1. 51.
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PL/SQL Developer Test script 3.0 47 declare dateb date; datee date; start_weekb date; start_weeke date; holiday_count integer; week_days_count integer; days_count integer; begin --минимальная дата dateb := least(:date1, :date2); --максимальная дата datee := g...
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function [x,y,typ]=INTRPLBLK_f(job,arg1,arg2) x=[];y=[];typ=[]; select job case 'plot' then standard_draw(arg1) case 'getinputs' then [x,y,typ]=standard_inputs(arg1) case 'getoutputs' then [x,y,typ]=standard_outputs(arg1) case 'getorigin' then [x,y]=standard_origin(arg1) case 'set' then x=arg1; graphics=arg...
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//Calculate efficiency //Chapter 3 //Example 3.22 //page 231 clear; clc; disp("Example 3.22") kVA=200; //Rating of the transformer Pin=3.4; //power input to two transformer in watt Pin2=5.2; coreloss=Pin; //core loss of two transformers phi=acosd(0.8); printf("\nCore l...
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//pathname=get_absolute_file_path('3.16.sce') //filename=pathname+filesep()+'3.16-data.sci' //exec(filename) //Initial pressure(in MPa): pi=0.5 //Initial volume(in m^3): vi=0.5 //Final pressure(in MPa): pf=1 //Atmospheric pressure(in Pa): patm=1.013*10^5 //Final volume(in m^3): vf=3*vi //Work done(in J): ...
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// Test #12 : For complex vector inputs including flag exec('./zpklp2mb.sci',-1); [z,p,k,n,d]=zpklp2mb([%i,4*%i],[3*%i,7*%i],4,0.6,[0.1 0.6],'stop'); disp(d); disp(n); disp(k); disp(p); disp(z); // //Scilab Output //d=1. - 0.5403505 - 0.1583844 //n=- 0.1583844 - 0.5403505 1. //k=0.7650736 - 0.0932510i //p=0...
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//Hougen O.A., Watson K.M., Ragatz R.A., 2004. Chemical process principles Part-1: Material and Energy Balances(II Edition). CBS Publishers & Distributors, New Delhi, pp 504 //Chapter-3, Illustration 11, Page 63 //Title: Calculation of volume change with change in composition //====================================...
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clc; v=2300; // rated voltage of motor xs=12 ; // per phase synchronous reactance p=200000; // VA rating of motor l1=120000; // initial load l2=60000; // final load vt=v/sqrt(3); // rated per phase voltage ia=l1/(3*vt); // minimum armature current ia1=1.5*ia; // armature current at reduced load (50% increment) ...
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//Ex:92 clc; clear; close; b_c=72;//carrier BW in MHz f_c=1190;//Center freq in MHz f_i=140;// first intermediate freq in MHz f_smx=14500;//max uplink freq spectrum in MHz f_smn=14000;//min uplink freq spectrum in MHz f_l1=f_c-f_i;// in MHz; f_l1=f_c-f_i;// in MHz f_l2mx=f_smx-f_c;// in MHz f_l2mn=f_smn-f_c...