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5_28.sce
clc,clear printf('Example 5.28\n\n') V_L=2000,V_ph=V_L/sqrt(3) VA=1000*10^3 I_L=VA/(sqrt(3)*V_L) //because VA=sqrt(3)*V_L*I_L I_aph=I_L I_f=28.5//for this I_aph=288.67513 as obtained from SCC graph V_oc_ph=1060//for I_f=28.5 as obtained fromOCC graph Z_s=V_oc_ph/I_aph R_a=0.2 //armature effective resistance X_s=sqrt( Z_s^2-R_a^2 ) //Part(i) phi1=acos(0.8)//lagging E_ph1=sqrt((V_ph*cos(phi1)+I_aph*R_a)^2+(V_ph*sin(phi1)+I_aph*X_s)^2) regulation1=100*(E_ph1-V_ph)/V_ph printf("(i)Full-load percentage regulation at 0.8 pf lagging is %.2f percent",regulation1) //Part(ii) phi2=acos(0.8)//leading E_ph2=sqrt((V_ph*cos(phi2)+I_aph*R_a)^2+(V_ph*sin(phi2)-I_aph*X_s)^2) regulation2=100*(E_ph2-V_ph)/V_ph printf("\n(ii)Full-load percentage regulation at 0.8 pf leading is %.2f percent\n\n",regulation2) printf('Note that the answer mismatches because of calculation mistake done in the last step of part 1')
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/lab02/TwoBit4To1LinePriorityMUX/TwoBit4To1LinePriorityMUX.tst
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Vineeth-Kada/Computer-Systems-Design
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TwoBit4To1LinePriorityMUX.tst
load TwoBit4To1LinePriorityMUX.hdl, output-file TwoBit4To1LinePriorityMUX.out, compare-to TwoBit4To1LinePriorityMUX.cmp, output-list R0%B2.1.2 R1%B2.1.2 R2%B2.1.2 R3%B2.1.2 X01%B2.1.2 X00%B2.1.2 X11%B2.1.2 X10%B2.1.2 X21%B2.1.2 X20%B2.1.2 X31%B2.1.2 X30%B2.1.2 Y1%B2.1.2 Y0%B2.1.2; /*Only one request input to the priority encoder is active*/ set R0 1, set R1 0, set R2 0, set R3 0, set X01 1, set X00 0, set X11 0, set X10 1, set X21 0, set X20 0, set X31 1, set X30 1, eval, output; set R0 1, set R1 0, set R2 0, set R3 0, set X01 0, set X00 1, set X11 0, set X10 0, set X21 1, set X20 1, set X31 1, set X30 0, eval, output; set R0 1, set R1 0, set R2 0, set R3 0, set X01 1, set X00 1, set X11 1, set X10 0, set X21 0, set X20 1, set X31 0, set X30 0, eval, output; set R0 1, set R1 0, set R2 0, set R3 0, set X01 0, set X00 0, set X11 1, set X10 1, set X21 1, set X20 0, set X31 0, set X30 1, eval, output; set R0 0, set R1 1, set R2 0, set R3 0, set X01 1, set X00 0, set X11 0, set X10 1, set X21 0, set X20 0, set X31 1, set X30 1, eval, output; set R0 0, set R1 1, set R2 0, set R3 0, set X01 0, set X00 1, set X11 0, set X10 0, set X21 1, set X20 1, set X31 1, set X30 0, eval, output; set R0 0, set R1 1, set R2 0, set R3 0, set X01 1, set X00 1, set X11 1, set X10 0, set X21 0, set X20 1, set X31 0, set X30 0, eval, output; set R0 0, set R1 1, set R2 0, set R3 0, set X01 0, set X00 0, set X11 1, set X10 1, set X21 1, set X20 0, set X31 0, set X30 1, eval, output; set R0 0, set R1 0, set R2 1, set R3 0, set X01 1, set X00 0, set X11 0, set X10 1, set X21 0, set X20 0, set X31 1, set X30 1, eval, output; set R0 0, set R1 0, set R2 1, set R3 0, set X01 0, set X00 1, set X11 0, set X10 0, set X21 1, set X20 1, set X31 1, set X30 0, eval, output; set R0 0, set R1 0, set R2 1, set R3 0, set X01 1, set X00 1, set X11 1, set X10 0, set X21 0, set X20 1, set X31 0, set X30 0, eval, output; set R0 0, set R1 0, set R2 1, set R3 0, set X01 0, set X00 0, set X11 1, set X10 1, set X21 1, set X20 0, set X31 0, set X30 1, eval, output; set R0 0, set R1 0, set R2 0, set R3 1, set X01 1, set X00 0, set X11 0, set X10 1, set X21 0, set X20 0, set X31 1, set X30 1, eval, output; set R0 0, set R1 0, set R2 0, set R3 1, set X01 0, set X00 1, set X11 0, set X10 0, set X21 1, set X20 1, set X31 1, set X30 0, eval, output; set R0 0, set R1 0, set R2 0, set R3 1, set X01 1, set X00 1, set X11 1, set X10 0, set X21 0, set X20 1, set X31 0, set X30 0, eval, output; set R0 0, set R1 0, set R2 0, set R3 1, set X01 0, set X00 0, set X11 1, set X10 1, set X21 1, set X20 0, set X31 0, set X30 1, eval, output; /*Atleast 2 request inputs to the priority encoder are active*/ set R0 1, set R1 0, set R2 0, set R3 1, set X01 0, set X00 0, set X11 1, set X10 0, set X21 0, set X20 0, set X31 1, set X30 1, eval, output; set R0 0, set R1 1, set R2 1, set R3 0, set X01 0, set X00 1, set X11 1, set X10 1, set X21 1, set X20 1, set X31 0, set X30 0, eval, output; set R0 0, set R1 0, set R2 1, set R3 1, set X01 1, set X00 0, set X11 0, set X10 0, set X21 1, set X20 0, set X31 1, set X30 0, eval, output; set R0 0, set R1 1, set R2 0, set R3 1, set X01 1, set X00 1, set X11 0, set X10 1, set X21 0, set X20 1, set X31 0, set X30 1, eval, output;
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Ex2_12.sce
//Example 2-12, Page No - 40 clear clc gain1 = 6.8 gain2 = 14.3 attenuation1 = -16.4 attenuation2 = -2.9 vout = 800*10^-3 At = gain1+gain2+attenuation1+attenuation2 vin = vout/10^(At/20) printf('The input voltage is %.1f mV',vin*10^3)
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<?xml version="1.0" encoding="UTF-8"?> <Project Name="map1312" Width="13" Height="15" CellSize="40" BackgroundSize="1" Background="13plus.png"> <Cell Name="冰块" X="1" Y="1" /> <Cell Name="冰块" X="2" Y="1" /> <Cell Name="冰块" X="3" Y="1" /> <Cell Name="冰块" X="4" Y="1" /> <Cell Name="bc-雪球-下" X="6" Y="1" arg0="70" arg1="1.00" arg2="1,4" /> <Cell Name="冰块" X="8" Y="1" /> <Cell Name="冰块" X="9" Y="1" /> <Cell Name="冰块" X="10" Y="1" /> <Cell Name="冰块" X="11" Y="1" /> <Cell Name="通关点-1" X="6" Y="3" /> <Cell Name="雪树" X="2" Y="4" /> <Cell Name="冰雕" X="3" Y="4" /> <Cell Name="雪树" X="4" Y="4" /> <Cell Name="bc-冰面" X="5" Y="4" /> <Cell Name="bc-冰面" X="6" Y="4" /> <Cell Name="bc-冰面" X="7" Y="4" /> <Cell Name="雪树" X="8" Y="4" /> <Cell Name="冰雕" X="9" Y="4" /> <Cell Name="雪树" X="10" Y="4" /> <Cell Name="雪树" X="3" Y="5" /> <Cell Name="bc-冰面" X="4" Y="5" /> <Cell Name="bc-冰面" X="5" Y="5" /> <Cell Name="bc-冰面" X="6" Y="5" /> <Cell Name="bc-冰面" X="7" Y="5" /> <Cell Name="bc-冰面" X="8" Y="5" /> <Cell Name="雪树" X="9" Y="5" /> <Cell Name="bc-冰面" X="3" Y="6" /> <Cell Name="bc-冰面" X="4" Y="6" /> <Cell Name="bc-冰面" X="5" Y="6" /> <Cell Name="bc-冰面" X="7" Y="6" /> <Cell Name="bc-冰面" X="8" Y="6" /> <Cell Name="bc-冰面" X="9" Y="6" /> <Cell Name="bc-雪球-右" X="1" Y="7" arg0="70" arg1="2.00,1" arg2="3,4" /> <Cell Name="bc-冰面" X="3" Y="7" /> <Cell Name="bc-冰面" X="4" Y="7" /> <Cell Name="bc-冰面" X="5" Y="7" /> <Cell Name="章鱼(Boss)" X="6" Y="7" arg0="19" /> <Cell Name="bc-冰面" X="7" Y="7" /> <Cell Name="bc-冰面" X="8" Y="7" /> <Cell Name="bc-冰面" X="9" Y="7" /> <Cell Name="bc-雪球-左" X="11" Y="7" arg0="75" arg1="3.00,2" arg2="2,4" /> <Cell Name="bc-冰面" X="3" Y="8" /> <Cell Name="bc-冰面" X="4" Y="8" /> <Cell Name="bc-冰面" X="5" Y="8" /> <Cell Name="bc-冰面" X="6" Y="8" /> <Cell Name="bc-冰面" X="7" Y="8" /> <Cell Name="bc-冰面" X="8" Y="8" /> <Cell Name="bc-冰面" X="9" Y="8" /> <Cell Name="雪树" X="2" Y="9" /> <Cell Name="冰雕" X="3" Y="9" /> <Cell Name="雪树" X="4" Y="9" /> <Cell Name="bc-冰面" X="5" Y="9" /> <Cell Name="bc-冰面" X="6" Y="9" /> <Cell Name="bc-冰面" X="7" Y="9" /> <Cell Name="雪树" X="8" Y="9" /> <Cell Name="冰雕" X="9" Y="9" /> <Cell Name="雪树" X="10" Y="9" /> <Cell Name="雪树" X="3" Y="10" /> <Cell Name="bc-冰面" X="4" Y="10" /> <Cell Name="bc-冰面" X="5" Y="10" /> <Cell Name="bc-冰面" X="6" Y="10" /> <Cell Name="bc-冰面" X="7" Y="10" /> <Cell Name="bc-冰面" X="8" Y="10" /> <Cell Name="雪树" X="9" Y="10" /> <Cell Name="bc-雪球-右" X="1" Y="11" arg0="75" arg1="3.00,2" arg2="3,4" /> <Cell Name="bc-雪球-左" X="11" Y="11" arg0="80" arg1="2.00,1" arg2="2,4" /> <Cell Name="出生点" X="6" Y="12" /> </Project>
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7_21.sce
clc; m_EtOH=46; aof=1/m_EtOH; m_a=28.96; AF=8.957; aoa=AF/m_a; Total=aof+aoa; R=8314.5; T=288; p=1.013*10^5; V=Total*R*T/p; NCVf=27.8; NCVm=NCVf/V; disp("MJ/m^3",NCVm,"calorific value of the combustion mixture is:");
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Ex20_7.sce
//chapter20 //example20.7 //page442 Vz=10 // V Vbe=0.5 // V Rl=1000 // ohm Vout=Vz-Vbe Il=Vout/Rl printf("load voltage = %.3f V \n",Vout) printf("load current = %.3f mA \n",Il*1000)
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x=input('Compute 1/x for x=?'); try 1/x catch disp('An error occurred!') end disp('The end of the script still gets executed.')
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example6_10.sce
clear; clc; // Stoichiometry // Chapter 6 // Stoichiometry and Unit Operations // Example 6.10 // Page 368 printf("Example 6.10, Page 368 \n \n"); // solution // basis 100kg free water in original sol // initial T = 353K W1 = (126/120.3)*64.2 //kg Wfree1 = 100-W1 MS1 = ((64.20+W1)*100)/32.76 // MgSO4.7H2O in 100kg free water // 4% of original sol evaporates E = (MS1 + 100)*.04 Wfree2 = 100-E // free water in mother liquor // at 303.15 K W2 = (126/120.3)*40.8 Wfree3 = 100-W2 MS2 = (W2+40.80)*Wfree2/Wfree3 // crystals of MgSO4.7H2O y = MS1-MS2 //kg q = 501.2*1000/284.6 // quantity of original sol to be fed printf(" Quantity if original solution to be fed to the crystallizer per 1000kg crystals of MgSO4.7H2O = "+string(q)+"kg.")
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FT task1.sce
clc; t=-1:0.02:1; w=2*%pi; n_har=5; n=1:1:n_har b=2 ./(n*%pi) x=0.5+b*sin(w*n'*t) plot(x) figure; n_har=10; n=1:1:n_har b=2 ./(n*%pi) x=0.5+b*sin(w*n'*t) plot(x) figure; n_har=15; n=1:1:n_har b=2 ./(n*%pi) x=0.5+b*sin(w*n'*t) plot(x)
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ex5_10.sce
// Exa 5.10 clc; clear; close; // Given data R_L = 10;// in kohm R_L= R_L*10^3;// in ohm R_C = 3.6;// in kohm R_C= R_C*10^3;// in ohm r_e_desh = 22.73;// in ohm R_L_desh = R_L/2;// in ohm A_v = ( (R_C*R_L_desh)/(R_C+R_L_desh))/r_e_desh; disp(A_v,"The voltage gain is");
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Ex9_25.sce
//chapter9 //example9.25 //page173 Ei=45 // V Vz1=15 // V Vz2=15 // V Iz=200d-3 // current rating for each zener in ampere Eo=Vz1+Vz2 R=(Ei-Eo)/Iz printf("regulated output voltage = %.3f V \n",Eo) printf("required series resistance = %.3f ohm \n",R)
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example3_15.sce
//example3-15 in page 63 clc; //Given data R1=15e+3; // resistance R1=15 K-ohm Rm=50;// coil resistance in ohm R2=50;// resistance R2 in ohm Im=50e-6;// FSD=50 micro-ampere //calculations printf("at Rx=0 &amp; Eb=1.3 V,\n"); Rx=0; Eb=1.3; Ib=Eb/(Rx+R1); I2=Ib-Im; Vm=Im*Rm; R21=Vm/I2;// the resistance R2 in ohm printf("R2=%.2f ohm\n",R21); for Eb=1.5:-0.2:1.3,// To find Rx Vm=0.5*Im*Rm; if Eb==1.3 R2=R21; end I2=Vm/R2; Ib=I2+Im*0.5; Rx=(Eb/Ib)-R1; printf("At 0.5 FSD with Eb=%.1f V,\n",Eb); printf("Rx=%d K-ohm \n",Rx/1000); end //result //at Rx=0 &amp; Eb=1.3 V //R2=68.181818 ohm //At 0.5 FSD with Eb=1.5V, //Rx=15 K-ohm //At 0.5 FSD with Eb=1.3 V, //Rx=15 K-ohm
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instantInsolation.sce
clc clear latitudeDirection = "N"; degreesLat = 29; minutesLat = 39; secondsLat = 7.19; longitudeDirection = "W"; degreesLong = 82; minutesLong = 19; secondsLong = 29.97; standardMeridian = 75; month = 2; day = 1; localTime = 12; // enter in integers (hourly) panelTiltAngle = 30; panelAzimuthAngle = 10; groundReflectance = 0.2; exec('convertGlobal.sce'); exec('convertLst.sce'); exec('calcSunCoordinates.sce'); exec('NumberDays.sce'); exec('calcInsolation.sce'); daysPassed = numberDays(month,day); [latitude, longitude] = convertGlobal(degreesLat, minutesLat, secondsLat, latitudeDirection, degreesLong, minutesLong, secondsLong, longitudeDirection); solarHourAngle = convertLst(localTime, longitude, standardMeridian,daysPassed) [solarAltitudeAngle,solarAzimuthAngle] = calcSunCoordinates(latitude, daysPassed,solarHourAngle); [insolationTotal] = calcInsolation(solarAltitudeAngle,solarAzimuthAngle, panelTiltAngle, panelAzimuthAngle, groundReflectance, month, daysPassed);
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Ex11_3.sce
clear// // //Variable Declaration M=32 //Moment in kN.m Iy=4.73*10**6 //Moment of inertia in y-axis in mm^4 Iz=48.9*10**6 //Moment of inertia in z-axis in mm^4 Sy=64.7*10**3 //Sectional Modulus in y-axis in mm^3 Sz=379*10**3 //Sectional Modulus in z-axis in mm^3 theta=16.2 //Angle between moment and z-axis in degrees //Calculations //Part 1 alpha=atan((Iz*Iy**-1)*tan(theta*%pi*180**-1))*180*%pi**-1 //Angle between NA and z-axis in degrees //Part 2 My=-M*sin(theta*%pi*180**-1) //Bending Moment in y in kN.m Mz=-M*cos(theta*%pi*180**-1) //Bending Moment in z in kN.m sigma_max=My*Sy**-1+Mz*Sz**-1 //Largest Bending Stress in MPa //Result printf("\n The angle between the Neutral Axis and Z-Axis is %0.1f degrees",alpha) printf("\n The maximum Bending Moment is %0.0f MPa",-sigma_max*10**6)
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appariement.sci
function [X1_ap,X2_ap,n_ap]=appariement(X1,X2,dmin) [n1,l1]=size(X1); [n2,l2]=size(X2); X1_ap = X1; [n_ap l_ap] = size(X1); X2_ap = []; for i = 1:n_ap p_diff = []; // matrix of points that includes all the points cloest possible // and their distance to original points. for j = 1:n2 dist = distance(X1_ap(i,:),X2(j,:)) // calcule distance entre point origin and point decalage if dist<dmin then // if their distance is les than dmin then add it to matrix p_diff p_diff = [p_diff;X2(j,:) dist] end end [X index] = min(p_diff(:,4));//find the point that has least distance to point original. X2_ap(i,:)=p_diff(index,1:3); end endfunction
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Ex17_3.sce
//Example 17_3 page no:831 clc; //given k=400; fc=1000; fx=1100; //calculating m,L,C m=sqrt(1-(fc/fx)^2) L=k/(%pi*fc); C=1/(%pi*k*fc); //calculating T-section elements are L1=m*L/2; L1=L1*1000;//converting to milliHenry C1=m*C; C1=C1*10^6;//converting to microFarad L2=(1-(m^2))*L/(4*m); L2=L2*1000;//converting to milliHenry disp("the values of T-section elements are"); disp(L1,"the inductance between which capacitance is connected is (in mH)"); disp(C1,"the capacitance connected between inductor is (in microFarad)"); disp(L2,"the inductance connected in series with capacitance is (in mH)"); //calculating the pi section elements are C1=m*C/2; C1=C1*10^6;//converting to microFarad C2=(1-m^2)*C/(4*m); C2=C2*10^6;//converting to microFarad L1=m*L; L1=L1*1000;//converting to milliHenry disp("the values of pi section elements are"); disp(C1,"the capacitance connected in parallel is (in microFarad)"); disp(C2,"the capacitance connected in parallel to inductor is (in microFarad)"); disp(L1,"the inductor connected in parallel to capacitance is (in mH)");
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foncjaclap.sci
function [F,J] = foncjac_lap(v) alpha = 5; bet = 5; n = length(v)+1; h = 1/n; x = h*[1:n-1]'; F = zeros(n-1,1); A =2*diag(ones(n-1,1))-diag(ones(n-2,1),+1)-diag(ones(n-2,1),-1); deff('[b]=rhs(x)','b=-x.*(x-1)'); deff('[b]=g(x)','b=10*x./(1+x)'); deff('[b]=gp(x)','b=(10.)./((1+x)^2)'); F = A*v + h^2*g(v) - h^2*rhs(x); F(1) = F(1) - alpha; F(n-1) = F(n-1) - bet; J = A+diag(gp(v))*h^2; endfunction
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//pathname=get_absolute_file_path('19.04.sce') //filename=pathname+filesep()+'19.04-data.sci' //exec(filename) //Velociy of turbojet plane(in m/s): Ca=277.78 //Thrust to velocity ratio: r1=0.5 //Rate at which air enters(in kg/s): m=50 //Air fuel ratio: r=52 //Lower calorific value of fuel: LCV=43100 //Jet velocity(in m/s): Ce=Ca/r1 printf("\n RESULT \n") printf("\nJet velocity = %f m/s",Ce) //Thrust(in N): T=(m+m/r)*Ce-m*Ca printf("\nThrust = %f kN",T/10^3) //Specific thrust(in N/kg/s): St=T/m printf("\nSpecific thrust = %f N/kg/s",St) //Thrust power(in kW): P=T*Ca/10^3 printf("\nThrust power = %f kW",P) //Propulsive efficiency: np=2/(1+1/r1)*100 printf("\nPropulsive efficiency = %f percent",np) //Thermal efficiency: nt=((1+1/r)*Ce^2-Ca^2)/(2*1/r*LCV)/10 printf("\nThermal efficiency = %f percent",nt) //Overall efficiency: no=np*nt/100 printf("\nOverall efficiency = %f percent",no) //Specific fuel consumption(in kg/h.N): sfc=m/r*3600/(T) printf("\nSpecific fuel consumption = %f kg/h.N",sfc)
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2016-04-29T07:01:39
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Ex1_12.sce
errcatch(-1,"stop");mode(2);//Example 1_13 ; ; //To calculate the fringe width dist1=0.005 //units in mm dist2=15 //units in cm alpha=dist1/dist2 //units in radians lamda=6000*10^-9 //units in cm betaa=(lamda)/(2*alpha) //units in printf("Fringe width beta=%.3fcm",betaa) //In text book answer is printed wrong as 0.09 cm answer is 0.009 cm exit();
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2020-04-09T02:43:26.499817
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clc clear //Input data D=0.15;//Diameter of a cylinder of a single acting reciprocating air compressor in m L=0.2;//Length of the stroke in m P1=1;//The pressure at which compressor sucks air in bar P2=10;//Final pressure in bar T1=298;//Initial Temperature in K N=150;//Operating speed of the compressor in rpm n=1.3;//Polytropic index of the process //Calculations V1=((3.14*D^2*L)/4);//Volume of air before compression in m^3 W=((n/(n-1))*P1*10^5*V1*((P2/P1)^((n-1)/n)-1));//Work done by the compressor for a polytropic compression of air in Nm Pi=((W*N)/60)/1000;//Indicated power of the compressor in kW //Output printf('The indicated power of the compressor is %3.3f kW',Pi)
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/microdaq/macros/microdaq_macros/mdaqAOScanInit.sci
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microdaq/Scilab
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mdaqAOScanInit.sci
function result = mdaqAOScanInit(arg1, arg2, arg3, arg4, arg5, arg6, arg7) global %microdaq; result = [] link_id = -1; channelNames = []; if argn(2) == 1 then channels = arg1.Channels; data = []; ao_range = arg1.Range; continuous = arg1.isContinuous; scan_freq = arg1.Rate; scan_time = arg1.DurationInSeconds; channelNames = arg1.Name elseif argn(2) == 2 then channels = arg2.Channels; data = []; ao_range = arg2.Range; continuous = arg2.isContinuous; scan_freq = arg2.Rate; scan_time = arg2.DurationInSeconds; channelNames = arg2.Name elseif argn(2) == 6 then channels = arg1; data = arg2; ao_range = arg3; continuous = arg4; scan_freq = arg5; scan_time = arg6; elseif argn(2) == 7 then link_id = arg1; channels = arg2; data = arg3; ao_range = arg4; continuous = arg5; scan_freq = arg6; scan_time = arg7; if link_id < 0 then error("Invalid connection id!") end end global %microdaq; if %microdaq.private.mdaq_hwid <> [] then if %microdaq.private.mdaq_hwid(3) == 0 then error("Unable to detect MicroDAQ configuration. Run mdaqHWInfo() function."); end dac_info = get_dac_info(%microdaq.private.mdaq_hwid); if find([1 2 6 7] == argn(2)) == [] then mprintf("Description:\n"); mprintf("\tInitiates analog signal generation\n"); mprintf("Usage:\n"); mprintf("\tmdaqAOScanInit(linkID, channels, initialData, range, isStreamMode, rate, duration)\n") mprintf("\tlinkID - connection id (optional)\n"); mprintf("\tchannels - analog output channels\n"); mprintf("\tinitialData - initial output data\n"); mprintf("\trange - analog output range\n"); mprintf("\t [-10,10] - single range argument applied for all used channels\n"); mprintf("\t [-10,10; -5,5] - multi-range argument for two channels\n"); mprintf("\tisStreamMode - mode of operation (%s - stream, %s - periodic)\n", "%T", "%F"); mprintf("\trate - update per second per channel rate\n"); mprintf("\tduration - duration in seconds (-1 - infinity)\n"); return; end else error('Unable to detect MicroDAQ configuration. Run mdaqHWInfo() function.'); end ch_count = size(channels, "c"); dac_ch_count = strtod(dac_info.channel); if size(channels, 'r') > 1 then error("Wrong channel - single row vector expected!") end if ch_count < 1 | ch_count > dac_ch_count then error("Wrong AO channel selected!") end if max(channels) > dac_ch_count | min(channels) < 1 then error("Wrong AO channel selected!") end if size(data, "c") <> ch_count & data <> [] then error("Wrong output data - colums should match selected channels!") end if size(ao_range, 'c') <> 2 then error("Vector range [low,high;low,high;...] expected!") return; end if size(ao_range, 'r') == 1 then range_tmp = ao_range; ao_range = ones(ch_count,2); ao_range(:,1) = range_tmp(1); ao_range(:,2) = range_tmp(2); end range_tmp = ao_range; ao_range = matrix(ao_range', 1, ch_count*2); if data <> [] then data_size = size(data, "*"); else data_size = 0; end if type(continuous) == 1 then if size(find(continuous>1), '*') > 0 error('Wrong isContinuous - boolean value expected (%T/1, %F/0)'); end end if continuous == %T | continuous == 1 then continuous = 1; else continuous = 0; end if scan_time < 0 & scan_time <> -1 then warning("For infinite AO scan operation use -1 as a duration parameter.\n"); scan_time = -1; end %microdaq.private.ao_scan_ch_count = ch_count; if argn(2) == 6 | argn(2) == 1 then link_id = mdaqOpen(); if link_id < 0 then error("Unable to connect to MicroDAQ device!"); end end result = []; result = call("sci_mlink_ao_scan_init",.. link_id, 1, "i",.. channels, 2, "i",.. ch_count, 3, "i",.. data, 4, "d",.. data_size, 5, "i",.. ao_range, 6, "d",.. continuous, 7, "i", .. scan_freq, 8, "d",.. scan_time, 9, "d",.. "out",.. [1, 1], 10, "i"); if argn(2) == 6 | argn(2) == 1 then mdaqClose(link_id); end if result < 0 then error(mdaq_error2(result), 10000 + abs(result)); else if result == 1 then mprintf("\nWARNING: Your MicroDAQ device does not support running AI and AO scan simultaneously.\n") end dac_res = strtod(part(dac_info.resolution, 1:2)) for j=1:ch_count if continuous == 1 then isContinous = %t else isContinous = %f end dataSize = size(data); result = tlist(["mdaqao",.. "Rate","DurationInSeconds","_ChannelCount","_DACResolution","Range", "Channels", "isContinuous", "BufferSize", "Name"],.. scan_freq, scan_time, ch_count, dac_res, matrix(ao_range, 2, ch_count)', channels, isContinous, dataSize, channelNames); end end endfunction
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Diferenciacion numerica.sce
//ofprietoc@unal.edu.co //angarciariv@unal.edu.co //Desarrollo profesor function demoSegundaDer() vv = -sin(0.8) disp("Cálculo de f''''(0.8)") disp(vv) disp(["H" "VA" "EV" "EA"]) h1 = 0.1 d1 = derivada2(f, 0.8, h1) ev1 = abs(vv-d1) disp([h1 d1 ev1]) h01 = 0.01 d01 = derivada2(f, 0.8, h01) ev01 = abs(vv-d01) disp([h01 d01 ev01 abs(ev01-ev1)]) h001 = 0.001 d001 = derivada2(f, 0.8, h001) ev001 = abs(vv-d001) disp([h001 d001 ev001 abs(ev001-ev01)]) endfunction function [y]=f(x) y = cos(x) endfunction function [f2] = derivada2(f, xi, h) f2 = (feval(xi-h, f)-2*feval(xi, f)+feval(xi+h, f))/(h^2) endfunction //Desarrollo adicional. //Realiza la prueba para un arreglo de valores que se generan con //función seno y luego de eso revisa los errores. function realizarPrueba(h, x_inicial, x_final) x = x_inicial:h:x_final y = cos(x') derivadaReal = -sin(x') derivadaAproximada = diferencia_n_vector(y, h, 1) errorAproximacion = abs(derivadaReal-derivadaAproximada) disp("Valores de x usados") disp(x') disp("Valores calculados de la función cos(x)") disp(y) disp("Valores reales de la derivada d/dx(cos(x)) = -sin(x)") disp(derivadaReal) disp("Valores aproximados de la derivada d/dx(cos(x)) = -sin(x)") disp(derivadaAproximada) disp("Error de la aproximación") disp(errorAproximacion) disp("Promedio de los errores") disp(mean(errorAproximacion)) plot(x, derivadaReal', '-', x, derivadaAproximada', '-', x, errorAproximacion', '-') endfunction //Retonar un vecotr con los valores aproximados de la derivada enésima //de una función de valores dados con respecto al tamaño del salto. //n: Grado de la derivada que se quiere obtener. function vector_diferenciado=diferencia_n_vector(y_conocidos, h, n) vec = y_conocidos for i=1:n vec = diferenciar_vector(vec, h) disp("Derivada de orden") disp(i) disp(vec) end vector_diferenciado = vec endfunction //Retorna un vector con los valores aproximados de la derivada de //una función de valores dados con respecto al tamaño del salto. //y_conocidos: Datos medidos para cada punto xi igualmente separado //otros //h: Espacio entre cada uno de los puntos xi function vector_diferenciado=diferenciar_vector(y_conocidos, h) //Tamaño mínimo del vector: 3 //Derivadas centradas en el centro del vector //Derivadas progresivas en el inicio //Derivadas regresivas en el final //yi = f(xi) n = length(y_conocidos) if n>=3 then dif = [] //Diferencia progresiva al inicio del vector dif(1) = (-3*y_conocidos(1)+4*y_conocidos(2)-y_conocidos(3))/(2*h) //Diferencias centradas for i=2:(n-1) dif(i) = (y_conocidos(i+1) - y_conocidos(i-1))/(2*h) end //Diferencia regresiva al final de vector //dfx(j,5)=(fx(j,3)-2*fx(j,2)+fx(j,1))/(h(1,j)^2); dif(n) = (3*y_conocidos(n)-4*y_conocidos(n-1)+y_conocidos(n-2))/(2*h) vector_diferenciado = dif else disp("Datos erróneos.") vector_diferenciado = [] end endfunction //Ejercicio derivadas direccionales. //Función multivariable function z=fmulti(x, y) z = x*x+y*y endfunction //Recibe dos vectores de valores //X contiene los valores x a usar para calcular los valores z //Y contiene los valores y a usar para calcular los valores z //dibujar tiene la instrucción de dibujar los valores en pantalla o no. //Devuelve una matriz con los valores evaluados después de function z=evalFMulti(valores_x, valores_y, dibujar) z_mat = [] m = length(valores_x) n = length(valores_y) for i = 1:m for j = 1:n z_mat(i,j) = fmulti(valores_x(i), valores_y(j)) end end if dibujar then plot3d(valores_x, valores_y, z_mat) end z = z_mat endfunction //Demostración de la derivada direccional //origen: vector desde dónde se quiere empezar a caminar //pasos: Cantidad de pasos que queremos dar //dv: Vector direccional //h: Distancia del paso que queremos dar //n: Orden de la derivada a calcular function demoDerivadaDireccional(origen, pasos, dv, h, n) //Sólo dibujamos evalFMulti(-5:h:5, -5:h:5, %t) //Convertir el vector dirección en vector unitario dvu = (1.0/norm(dv))*dv //Nuestro vector de movimiento (h en versión de vectores) hv = h*dvu vectorDiferenciar = [] puntosEvaluados = [] actual = origen //Calculamos los valores de la función sobre la línea del vector dirección. for i=1:pasos vectorDiferenciar(i) = fmulti(actual(1), actual(2)) puntosEvaluados(i, 1) = actual(1) puntosEvaluados(i, 2) = actual(2) actual = actual + hv end disp("Puntos en donde se evaluó fmult") disp(puntosEvaluados) disp("Valores evaluados sobre el vector de dirección") disp(vectorDiferenciar) vector_diferenciado = diferencia_n_vector(vectorDiferenciar, h, n) endfunction
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/////////Chapter 10 Properties Of Steam ///Example 10.24 Page No:204 ///Find Enthalpy of steam of first boiler clc; clear; //Input data; FB=15; //First boiler in bar SB=15; //Second boiler in bar tsup1=300; //Temperature of the steam in degree celsius tsup2=200; //Temperature of the steam in degree celsius //From steam table (pressure basis at 15 bar ) ts=198.3; //In degree celsius hf=844.7; //In KJ/Kg hfg=1945.2; //In KJ/Kg hg=2789.9; //In KJ/I Cps=2.3; //Calculation h1=hg+Cps*(tsup1-ts); //Enthalpy of steam of first boiler in KJ/Kg h3=hg+Cps*(tsup2-ts); //Enthalpy of steam in steam main in KJ/Kg h2=2*h3-h1; //Energy balance in KJ/Kg x2=(h2-hf)/hfg; //Enthalpy of wet steam //OUTPUT printf('Enthalpy of steam of first boiler= %f KJ/Kg\n',h1); printf('Enthalpy of steam in steam main=%f KJ/Kg \n ',h3); printf('Energy balance=%f KJ/Kg \n ',h2); printf('Enthalpy of wet steam= %f \n ',x2);
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PL/SQL Developer Test script 3.0 28 DECLARE c utl_tcp.connection; -- TCP/IP connection to the Web server ret_val pls_integer; BEGIN c := utl_tcp.open_connection(remote_host => '192.168.100.2', remote_port => 8084, charset => 'US7ASCII'); -- open connection --ret_val := utl_tcp.write_line(c, 'OPTIONS /svn/ORA_VER/trunk/$svn/act/exp/ HTTP/1.1'); -- send HTTP request ret_val := utl_tcp.write_line(c, 'CHECKOUT /svn/ORA_VER/trunk/exp/EXP.log HTTP/1.1'); --MKACTIVITY http://www.example.com/repos/foo/$svn/act/01234567-89ab-cdef-0123-45789abcdef ret_val := utl_tcp.write_line(c, 'Host: 192.168.100.2'); -- send HTTP request ret_val := utl_tcp.write_line(c, 'Authorization: Basic bWFkY2FwOkdmaGprbTgy'); -- send HTTP request ret_val := utl_tcp.write_line(c, 'Content-Length: 0'); -- send HTTP request ret_val := utl_tcp.write_line(c); --CHECKOUT /his/12/ver/V3 HTTP/1.1 --Host: repo.webdav.org --Content-Length: 0 BEGIN LOOP dbms_output.put_line(utl_tcp.get_line(c, TRUE)); -- read result END LOOP; EXCEPTION WHEN utl_tcp.end_of_input THEN NULL; -- end of input END; utl_tcp.close_connection(c); END; 0 0
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Ex1_5.sce
clear all; clc; disp("Scilab Code Ex 1.5 :") // Given: f_a = 50; //N m_a = 70; // Moment at A in Nm l_ad = 1.25; //Length of AD in m. l_bd = 0.5; //Length of BD in m. l_cb = 0.75; //Length of BC in m. w_l = 2; //Kg/m g = 9.81; //N/kg- acceleration due to gravity //Free Body Diagram : w_bd = w_l*l_bd*g; //in N. Weight of each segment of pipe that acts through the centre of gravity of each segment. w_ad = w_l*l_ad*g; // Equations of Equilibrium //Balancing forces in the x direction: f_b_x = 0; // N //Balncing forces in the y direction: f_b_y = 0; //N //Balncing forces in the z direction: f_b_z = g + w_ad + f_a; //N // Balancing Moments in the x direction: m_b_x = - m_a + (f_a*l_bd) + (w_ad*l_bd) + (l_bd/2)*g; //Nm // Balancing Moments in the y direction: m_b_y = - (w_ad*(l_ad/2)) - (f_a*l_ad); //Nm // Balancing Moments in the z direction: m_b_z = 0; //Nm v_b_shear = sqrt(f_b_z ^2 + 0); //Shear Force in N t_b = - m_b_y; //Torsional Moment in Nm m_b = sqrt(m_b_x ^2+ 0); // Bending moment in Nm //Display // Displaying results: printf('\n\n The weight of segment BD = %.1f N',w_bd); printf('\n The weight of segment AD = %.1f N',w_ad); printf('\n The force at B in the Z direction = %.1f N',f_b_z); printf('\n The moment about B in the X direction = %.1f Nm',m_b_x); printf('\n The moment about G in the Y direction = %.1f Nm',m_b_y); printf('\n The Shear Force at B = %.1f N',v_b_shear); printf('\n The Torsional Moment at B = %.1f Nm',t_b); printf('\n The Bending Moment at B = %.1f Nm',m_b); //-----------------------------------------------------END-----------------------------------------------------------------------------
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Ex19_3.sce
Po=60D+3//full load output of the motor e=0.905//efficiency of the motor Pin=Po/e V=400//applied voltage I=Pin/V//line current drawn by the motor Rsh=200//resistance of the shunt field winding Ish=V/Rsh Ia=I-Ish Ra=0.1//armature resistance Eb=V-Ia*Ra A=2//no. of parallel paths in armature winding P=4//no. of poles phi=45D-3//flux per pole Z=450//total number of conductors N=round(60*Eb*A/(P*phi*Z)) mprintf("Full load speed=%d rpm\n",N) //calculating armature torque Ta=0.159*P*phi*Ia*Z/A mprintf("Torque developed by the armature of the DC motor=%f N-m\n",Ta) //calculating useful torque Psh=60D+3//shaft power Tsh=60*Psh/(2*%pi*N) mprintf("Useful torque=%f N-m",Tsh) //error in the textbook answer for useful torque
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example1.sce
clc clear //input data P01=1//initial pressure of a fluid in bar P02=10//final pressure of a fliud in bar T01=283//initial total temperature in K ntt=0.75//total-to-total efficiency d=1000//density of water in kg/m^3 r=1.4//ratio of specific heats for air Cp=1.005//specific at heat at constant pressure in kJ/kg.K //calculations h0s1=(1/d)*(P02-P01)*10^2//enthalpy in kJ/kg h01=(h0s1/ntt)//enthalpy in kJ/kg T02s=T01*(P02/P01)^((r-1)/r)//temperature in K h0s2=(Cp*(T02s-T01))//enthalpy in kJ/kg h02=(h0s2/ntt)//enthalpy in kJ/kg //output printf('The work of compression for adiabatic steady flow per kg of fliud if \n(a)The fliud is liquid water is %3.1f kJ/kg\n(b)The fliud is air as a perfect gas is %3.2f kJ/kg',h01,h02)
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4_25.sce
clear; clc; close; Vcc = 20; Vbe = 0.7; Beta = 100; Rb = 250*10^(3); Re = 2*10^(3); Vrb = 19.85; Ic = 0; Irb = Vcc/(Rb+Re); Ib = (Vcc-Vbe)/(Rb+(Beta+1)*Re); disp(Irb,'The base current(amperes) obtained is : '); disp(Ib,'Ideally Ib(Amperes) should be :'); disp('Hence the transistor is in a damaged state,'); disp('with short-circuit between base and emitter.');
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function [f,g]=Simulador_f1(x) n = size(x,1) f = [1:n]*(x.^2) g = 2*[1:n]'.*x endfunction
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example_15.sce
printf('example 1.15 page number 46') disp ("this is a theoritical question, book shall be referred for solution")
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functions5_11.sci
//Function for plotting S-N Curve function[a, b, c, d]= SNplot(Sut,Se) //Initialise e e = 4 //Initialise all given values a = log10(0.9 * Sut) b = log10(Se) c = log10(Nmin) d = log10(Nmax) //Calculate the values of y-coordinate when x = 4 and 5 using linear interpolation for i = 1:1:4 if(i == 1) s(i) = c l(i) = a elseif(i == 4) s(i) = d l(i) = b else s(i) = log10(10^e) l(i) = b + (((a - b)/(c - d))*(s(i) - d)) e = e + 1 end end //Plot S-N Curve y = {l(1), l(2), l(3), l(4)} x = {s(1), s(2), s(3), s(4)} plot(x,y,'-*') plot2d3(x,y) //Get the handle of current axes g = gca() //Give labels and set label properties g.labels_font_color=5 g.font_size=3 g.grid=[1,1] g.box="off" title('S-N Curve (Example 5.11)') xlabel('log10N') ylabel('log10Sf') endfunction
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global A F Tm Fd T k Signal //A = evstr(x_dialog("Введи значение Амплитуды от 1-3",'')); //F = evstr(x_dialog("Введи значение Частота сигнала (Гц)",'')); //Tm = evstr(x_dialog("Введи значение Длительность сигнала (с)",'')); //Fd = evstr(x_dialog("Введи значение Частоты дискретизации(8000) (Гц)",'')); k = 0; A = 10; Tm = 48; // От 15 иначе кодер не работает // кратное 8 должно быть F = 400; Fd = 8000; T = 1:Tm; Is = A * sin(2 * %pi * T / (Fd/F)); f1=figure(); clf; // Создаём окно для вывода графиков set(f1,'figure_name','FIRST WINDOW'); f1.figure_position=[200,200] f1.figure_size=[1500,700] subplot(3,1,1); plot(T,Is); xtitle("Человеческий голос"); a=gca(); a.children //Косметическая часть для графика poly1= a.children(1).children(1); poly1.thickness = 2; poly1.foreground = 2; a.title.font_size=5; xgrid(); xlabel("t (c)"); //Задаем название осям ylabel("Amplitude (dB)") sleep(3000); //fs = evstr(x_dialog("Введи значение Fs, чтобы высчитать интервал дискретизации",'')); fs = 4000; // Расчёт для вывода дискретизированного сигнала b=Fd/fs; //По этой формуле мы высчитываем интервал дискретизации samp = zeros(1,Tm); for p = 1 : b : Tm samp(p) = Is(p); end subplot(3,1,1); plot2d3(samp); //Вывод Дискретизированного сигнала title("Дискретный вид сигнала"); a=gca(); a.children //Косметическая часть для графика poly1= a.children(1).children(1); poly1.thickness = 2; a.title.font_size=5; sleep(3000); //Ra = evstr(x_dialog("Введи значение Разрядность АЦП (3)",'')); // Рассчёт для вывода квантованого сигнала Ra=13; Ru = Ra^2; Koef = Ru / (2*A); N = length(T); for i = 1:N; Signal(:,i) = round(Is(T(i)) * Koef) / Koef; end; subplot(3,1,2); plot2d2(T, Signal); //Вывод цифрового сигнала xtitle("Квантованный сигнал","t","Amplitude"); a=gca(); a.children //Косметическая часть для графика poly1= a.children(1).children(1); poly1.foreground = 5; poly1.thickness = 2; a.title.font_size=5; xgrid(); xlabel("t"); //Задаем название осям ylabel("Amplitude") // Расчёт для вывода FFT аналогового сигнала T = 1: 1/Fd : Tm; //Не работало FFT потому что не было этой строки N_T = size(T,'*'); FFT = abs(fft(Is(T))); FFT_Hz = Fd*(0:(Tm/2))/Tm; n_Hz = size(FFT_Hz,'*') subplot(3,1,3); plot(FFT_Hz,FFT(1:n_Hz)) xtitle("FFT"); a=gca(); a.children //Косметическая часть для графика poly1= a.children(1).children(1); poly1.thickness = 1; poly1.foreground = 2; a.title.font_size = 5; xgrid(); xlabel("Гц"); ylabel("dB"),
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load High4.hdl, output-file High4.out, compare-to High4.cmp, output-list in%B1.4.1 out%B1.2.1; set in %B0000, eval, output; set in %B0001, eval, output; set in %B0010, eval, output; set in %B0011, eval, output; set in %B0100, eval, output; set in %B0101, eval, output; set in %B0110, eval, output; set in %B0111, eval, output; set in %B1000, eval, output; set in %B1001, eval, output; set in %B1010, eval, output; set in %B1011, eval, output; set in %B1100, eval, output; set in %B1101, eval, output; set in %B1110, eval, output; set in %B1111, eval, output;
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Exa6_8.sce
//Exa 6.8 clc; clear; close; //Given Data: f=5000;//in MHz f=f*10^6;//in Hz d=10;//in feet d=d*0.3048;//in meter c=3*10^8;//Speed of light in m/s lambda=c/f;//in meter r=2*d^2/lambda;//in meter disp(r,"Minimum distance between primary and secondary antenna in meter :");
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//Example number 1.13, Page number 1.38 clc;clear;close //Variable declaration a2=1 // amplitude a1=2*a2 // amplitude //Calculation r=a1/a2 // ratio //Result printf("r=%.f/1",r) //r = r/1 = r:1 printf("\nHence the ratio of the amplitudes= 2:1")
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PL/SQL Developer Test script 3.0 35 begin pdb_pub.clone( p_creator => 'PDB_ROOT', p_pdb_name => 'WEEKLY', p_pdb_parent => 'WEEKLY_CLONE' ); pdb_pub.clone( p_creator => 'PDB_ROOT', p_pdb_name => 'WEEKLY_VBZ', p_pdb_parent => 'WEEKLY_CLONE' ); --pdb_pub.clone(p_creator => 'VBZ', p_pdb_name => 'TSTDB_TTS', p_pdb_parent => 'TSTDB'); --pdb_pub.unfreeze_(p_pdb_name => 'TSTDB'); -- pdb_pub.clone(p_creator => 'VBZ', p_pdb_name => 'TSTDB_TTS2', p_pdb_parent => 'TSTDB'); --pdb_pub.open_(p_pdb_name => 'TSTDB'); --pdb_pub.freeze_(p_pdb_name => 'TSTDB'); --pdb_pub.clone(p_creator => 'VBZ', p_pdb_name => 'TSTDB_TTS2_1', p_pdb_parent => 'TSTDB_TTS2'); /*--Размораживаем PDB источник pdb_pub.unfreeze_(p_pdb_name => 'VBZ_TSTDB'); --создаем клон pdb_pub.clone(p_creator => 'VBZ', p_pdb_name => 'VBZ_TSTDB_01', p_pdb_parent => 'VBZ_TSTDB'); --открываем и замораживаем PDB-источник pdb_pub.open_(p_pdb_name => 'VBZ_TSTDB'); pdb_pub.freeze_(p_pdb_name => 'VBZ_TSTDB'); */ --pdb_pub.open_(p_pdb_name => ''); --pdb_pub.unfreeze_(p_pdb_name => 'VBZ_TSTDB'); --pdb_pub.close_(p_pdb_name => 'VBZ_TSTDB'); --pdb_pub.request_drop(p_pdb_name => 'VBZ_TSTDB_01'); /* pdb_api.action(p_action => pdb_api.GC_ACT_CLONE, p_pdb_name => 'VBZ_TSTDB2', p_creator => 'VBZ', p_planned_at => sysdate + 1 ); --*/ end; 0 0
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//Initilization of variables m=7 //kg g=9.8 //m/s^2 r=0.5 //m I=0.875 //kg.m^2 //Calculations //Solving for alpha and T alpha=(m*g*r)/(I+m*r*0.5) //rad/s^2 T=(I*alpha)/r //N //Result clc printf('The soultion is alpha =%f rad/s^2 and T=%f N',alpha,T)
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// Theory and Problems of Thermodynamics // Chapter 9 // Air_water Vapor Mixtures // Example 13 clear ;clc; //Given data mw3 = 1000 // cooling tower supply rate in kg/min T1 = 303.15 // Temp of air entering cooling tower in K RH1 = 0.3 // relative humidity of air entering cooler T2 = 308.15 // Temp of air leaving cooling tower in K RH2 = 0.8 // relative humidity of air leaving cooler T3 = 318.15 // Temp of water entering cooling tower in K T4 = 300.15 // Temp of water leaving cooling tower in K // subscript 1 and 2 denotes the state of air entering and leaving the cooling tower respectively // subscript 3 and 4 denotes the state of water entering and leaving the cooling tower respectively // data from psychometric chart for T = 30 degree C and RH = 0.3 SH1 = 0.0078 // in kg H2O/kg air h1 = 51 // in kJ/kg air // data from psychometric chart for T = 35 degree C and RH = 0.8 SH2 = 0.029 // in kg H2O/kg air h2 = 110 // in kJ/kg air hw3 = 188.45 // in kJ/kg hw4 = 113.25 // in kJ/kg // mass balance for H2O: //mw3-mw4 = ma*(SH2-SH1) // energy balance gives: // mw3*hw3 - mw4*hw4 = ma*(h2-h1) // x(1) = ma; x(2)= mw4; function[f] =F(x) f(1) = mw3-x(2)-x(1)*(SH2-SH1); f(2) = mw3*hw3 - x(2)*hw4 -x(1)*(h2-h1); endfunction x = [10 10]; y = fsolve(x,F) ma = y(1); // air flow rate in kg/min mw4 = y(2); wat_mak = mw3-mw4; // make up water required // Output Results mprintf('Make up water required = %4.2f kg/min' , wat_mak); mprintf('\n Air flow rate = %4.1f kg/min' , ma);
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clc //initialization of variables L=6.5 //in thick=1 //in k=0.06 //B/hr-ft-F T1=350 //F T2=110 //F //calculations QbyL=2*%pi*k*(T1-T2)/log(1+2/L) //results printf("heat flow = %d B/hr-ft",QbyL) //The answer given in textbook is wrong. Please calculate using a calculator
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//Example 2.32: error clc; clear; close; //given data : V=20*10^3;// in V v1=2*10^3;// in V R=10*10^3;// in ohm r=R*v1/V; f=50;// in Hz w=2*%pi*f; C=0.60*10^-6;// in F v=V/((R/r)*sqrt(1+((w^2*C^2*r^2*(R-r)^2)/R^2))); Error=((v1-v)/v1)*100; disp(Error,"Error,(%) = ")
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clear clc disp('Ex-4.2'); // w=wavelength; consider k=2*(pi/w); // differentiate k w.r.t w and replace del(k)/del(w) = 1 for equation.4.3 // which gives del(w)= w^2 /(2*pi*del(x)), hence w=20; delx=200; // delx=200cm and w=20cm delw=(w^2)/(delx*2*%pi); printf('Hence uncertainity in length is %1.2f cm',delw);
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//appeler les scripts nécessaires pour pouvoir utiliser toutes les méthodes exec('exo5_initialise_grille.sci',-1) exec('exo9_modele_complet.sci',-1) exec('exo10_correctif.sci',-1) exec('exo12_splitting.sci',-1) exec('exo16_splitting_problem.sci',-1) //Cout exo5(initialisation de grille) val=0 T=100 //T t0=0 //Temps initial dt=0.01 //Pas de temps e0=1.0 //e initial r0=0.0 //r initial for n=2:2:4 timer() main_initialise(T,t0,dt,e0,r0,n) time1=timer() //--tableau de temps de calcul selon n (n = 0,2,4,6) val= [val, time1] end //Cout exo9(problème modèle complet) val=0 D=1 //Constant conductivité T=50 //T t0=0 //Temps initial dt=0.01 //Pas de temps for n=2:2:4 //--les vecteurs (condition) initiaux de taille n*n e0=ones(n*n,1) r0=zeros(n*n,1) timer() main_modele_complet(t0,dt,T,e0,r0,D,n) time1=timer() //--tableau de temps de calcul selon n (n = 0,2,4,6) val= [val, time1] end //Cout exo10(problème modèle complet avec fonctions correctives) val=0 D=1 //Constant conductivité T=50 //T t0=0 //Temps initial dt=0.01 //Pas de temps for n=2:2:4 //--les vecteurs (condition) initiaux de taille n*n : //--Ici, c'est de la solution corrigé au t0 pour tester [x,y]=genere_xy(n) [e0,r0]=grille_solution(x,y,t0) timer() main_correctif(t0,dt,T,e0,r0,D,n) time1=timer() //--tableau de temps de calcul selon n (n = 0,2,4,6) val= [val, time1] end //Cout exo12(problème modèle complet avec splitting façon 1) val=0 D=1 //Constant conductivité T=50 //T t0=0 //Temps initial dt=0.01 //Pas de temps for n=2:2:4 //--les vecteurs (condition) initiaux de taille n*n e0=ones(n*n,1) r0=zeros(n*n,1) timer() main_splitting(t0,dt,T,e0,r0,D,n) time1=timer() //--tableau de temps de calcul selon n (n = 0,2,4,6) val= [val, time1] end //Cout exo16(problème modèle complet avec splitting façon 2 avec rk2,cn2) val=0 D=1 //Constant conductivité T=50 //T t0=0 //Temps initial dt=0.01 //Pas de temps for n=2:2:4 //--les vecteurs (condition) initiaux de taille n*n e0=ones(n*n,1) r0=zeros(n*n,1) timer() main_splitting_problem(t0,dt,T,e0,r0,D,n) time1=timer() //--tableau de temps de calcul selon n (n = 0,2,4,6) val= [val, time1] end
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// Updated(1-8-07) // Operations: // Polynomial definition // Flipping of coefficients // Variables ------- passed as input argument (either 's' or 'z') // Both num and den are used mostly used in scicos files, // to get rid of negative powers of z // Polynomials with powers of s need to // be flipped only function [polynu,polyde] = polyno(zc,a) zc = clean(zc); polynu = poly(zc(length(zc):-1:1),a,'coeff'); if a == 'z' polyde = %z^(length(zc) - 1); else polyde = 1; end // Scicos(4.1) Filter block shouldn't have constant/constant if type(polynu)==1 & type(polyde)==1 if a == 'z' polynu = %z; polyde = %z; else polynu = %s; polyde = %s; end; end; endfunction
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clc //Given that Beta=0.10//fringe width in cm D=200// separation between source and screen in cm lambda=0.00055// wavelength of incident light in cm //Sample Problem 1 Page No. 46 printf ("\n # Problem 1 # \n") d= (D*lambda)/ (10*Beta) printf (" \n Standard formula used \n beta= lambda*D/d \n") printf ("\n Separation between sources is %f cm. \n",d)
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kiks_siminfo_robotdist.sci
function [res] = kiks_siminfo_robotdist() // Ouput variables initialisation (not found in input variables) res=[]; // Display mode mode(0); // Display warning for floating point exception ieee(1); // function res=kiks_siminfo_robotdist // returns the distance the simulated robot has travelled: // [FWD BWD STRAIGHT] // FWD: total distance moved forwards // BWK: total distance moved backwards // STRAIGHT: the distance, in a straight line, from // the starting position (when kiks_kopen was called) // to the current position of the Khepera. // ----------------------------------------------------- // (c) 2000-2004 Theodor Storm <theodor@tstorm.se> // http://www.tstorm.se // ----------------------------------------------------- global("KIKS_DIST_FWD"); global("KIKS_DIST_BWD"); global("KIKS_DIST_STRAIGHT"); res = [KIKS_DIST_FWD,KIKS_DIST_BWD,KIKS_DIST_STRAIGHT]; endfunction
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//variable declaration d=50 //diameter N_a=0.2 //Numerical aperture lamda=1 //wavelength //Calculations N=4.9*(((d*10**-6*N_a)/(lamda*10**-6))**2) //Result printf('N =%0.3f \n',N) printf('Fiber can support%0.3f guided modes \n',N) printf('In graded index fiber, No.of modes propogated inside the fiber =%0.3f only',N/2)
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Ex9_4.sce
//Finding of discharge through Trapezoidal Notch //Given H=0.3; Cd1=0.62; Cd2=0.6; d=0.4; w1=1.2; w2=0.5; h=0.4; g=9.81; //To Find theta=((w1-w2)/2)/h;disp(theta); q1=((2/3)*Cd1*sqrt(2*g)*H^(3/2)); q2=((8/15)*Cd2*sqrt(2*g)*theta*H^(5/2)); q=q1+q2;disp(q1);disp(q2); disp("discharge through Trapezoidal Notch ="+string(q)+" m^3/sec");
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Ex2_22.sce
clear // // // //Variable declaration rho=6250; //density(kg/m^3) M=60.2; //molecular weight N=6.02*10^26; //avagadro number n=4; //number of atoms //Calculations a=(n*M/(rho*N))^(1/3); //lattice constant(m) //Result printf("\n lattice constant is %0.0f angstrom",a*10^10)
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EX13_2.sce
//Finding of Boundary layer thickness , Drag Force //Given x=1; L=1.5; b=1.2; vs=0.25; mu=0.001; rho=1000; x2=1.2; L2=1.2; //To Find A=L*b; R=(rho*vs*x)/mu; t=(5.477*x)/sqrt(R); tau=(0.365*mu*vs*sqrt(R))/x; R1=(rho*vs*L)/mu; Cd=1.46/sqrt(R1); Fd=(1/2)*Cd*rho*(vs)^2*A; disp("Boundary Layer Thickness ="+string(t)+" meter"); disp("Drag Force ="+string(Fd)+" Newtons");
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0039.tst
sPLittEr c {} FILTEr D { } FILTeR w {h Sfu OR Ibx } S -> YdxG GrOuper lC {aGGreGaTE BItOr(i) As fBTh } UnGROupeR m { } GRouPFILTeR c {} MErGeR o { EXpoRT QY }
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test1-19.tst
main var a, b, c, d; { let a <- 424; let b <- 4920; let c <- 9302; let d <- 2391; if a != b then if b != c then if c != d then call outputnum(a) else call outputnum(a) fi else call outputnum(a) fi else call outputnum(a) fi; call outputnewline() }.
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TranspositionSet={[0,2,1,3],[1,0,2,3],[1,2,0,3],[2,1,0,3],[2,0,1,3]} considerNonPrimitive Expanding for base=4, level=1, reasons+features=base,transpose,primitive,same,similiar Refined variables=a,b,c,d [0+1a,0+1b,0+1c,0+1d]: unknown -> [1] [0,0,0,0] a³+b³+c³-d³ -> solution [0,0,0,0],trivial(3) [1,0,0,1],trivial(3) [0,1,0,1],trivial(3) [0,0,1,1],trivial(3) ---------------- level 0 expanding queue[0]^-1,meter=[4,4,4,4]: a³+b³+c³-d³ [0+4a,0+4b,0+4c,0+4d]: non-primitive -> solution [0,0,0,0],trivial(3) [4,0,0,4],trivial(3) [0,4,0,4],trivial(3) [0,0,4,4],trivial(3) [3+4a,1+4b,0+4c,0+4d]: unknown -> [1] [3,1,0,0] 108a+144a²+64a³+12b+48b²+64b³+64c³-64d³+28 [2+4a,2+4b,0+4c,0+4d]: non-primitive [1+4a,3+4b,0+4c,0+4d]: transposed [1] by [1,0,2,3] [3+4a,0+4b,1+4c,0+4d]: transposed [1] by [0,2,1,3] [3+4a,2+4b,1+4c,0+4d]: unknown -> [2] [3,2,1,0] 108a+144a²+64a³+48b+96b²+64b³+12c+48c²+64c³-64d³+36 [0+4a,3+4b,1+4c,0+4d]: transposed [1] by [2,0,1,3] [2+4a,3+4b,1+4c,0+4d]: transposed [2] by [1,0,2,3] [2+4a,0+4b,2+4c,0+4d]: non-primitive [3+4a,1+4b,2+4c,0+4d]: transposed [2] by [0,2,1,3] [0+4a,2+4b,2+4c,0+4d]: non-primitive [1+4a,3+4b,2+4c,0+4d]: transposed [2] by [2,0,1,3] [1+4a,0+4b,3+4c,0+4d]: transposed [1] by [1,2,0,3] [0+4a,1+4b,3+4c,0+4d]: transposed [1] by [2,1,0,3] [2+4a,1+4b,3+4c,0+4d]: transposed [2] by [1,2,0,3] [1+4a,2+4b,3+4c,0+4d]: transposed [2] by [2,1,0,3] [1+4a,0+4b,0+4c,1+4d]: unknown -> [3] [1,0,0,1] 12a+48a²+64a³+64b³+64c³-12d-48d²-64d³ -> solution [1,0,0,1],trivial(3) [5,0,0,5],trivial(3) [0+4a,1+4b,0+4c,1+4d]: transposed [3] by [2,0,1,3] [2+4a,1+4b,0+4c,1+4d]: unknown -> [4] [2,1,0,1] 48a+96a²+64a³+12b+48b²+64b³+64c³-12d-48d²-64d³+8 [1+4a,2+4b,0+4c,1+4d]: transposed [4] by [1,0,2,3] [0+4a,0+4b,1+4c,1+4d]: transposed [3] by [2,1,0,3] [2+4a,0+4b,1+4c,1+4d]: transposed [4] by [0,2,1,3] [3+4a,1+4b,1+4c,1+4d]: unknown -> [5] [3,1,1,1] 108a+144a²+64a³+12b+48b²+64b³+12c+48c²+64c³-12d-48d²-64d³+28 [0+4a,2+4b,1+4c,1+4d]: transposed [4] by [2,0,1,3] [2+4a,2+4b,1+4c,1+4d]: unknown -> [6] [2,2,1,1] 48a+96a²+64a³+48b+96b²+64b³+12c+48c²+64c³-12d-48d²-64d³+16 [1+4a,3+4b,1+4c,1+4d]: transposed [5] by [2,0,1,3] [1+4a,0+4b,2+4c,1+4d]: transposed [4] by [1,2,0,3] [0+4a,1+4b,2+4c,1+4d]: transposed [4] by [2,1,0,3] [2+4a,1+4b,2+4c,1+4d]: transposed [6] by [1,2,0,3] [1+4a,2+4b,2+4c,1+4d]: transposed [6] by [2,0,1,3] [1+4a,1+4b,3+4c,1+4d]: transposed [5] by [2,1,0,3] [3+4a,3+4b,3+4c,1+4d]: unknown -> [7] [3,3,3,1] 108a+144a²+64a³+108b+144b²+64b³+108c+144c²+64c³-12d-48d²-64d³+80 [2+4a,0+4b,0+4c,2+4d]: non-primitive -> solution [2,0,0,2],trivial(3) [6,0,0,6],trivial(3) [3+4a,1+4b,0+4c,2+4d]: unknown -> [8] [3,1,0,2] 108a+144a²+64a³+12b+48b²+64b³+64c³-48d-96d²-64d³+20 -> solution [3,5,4,6],NONTRIVIAL [0+4a,2+4b,0+4c,2+4d]: non-primitive -> solution [0,2,0,2],trivial(3) [0,6,0,6],trivial(3) [1+4a,3+4b,0+4c,2+4d]: transposed [8] by [1,0,2,3] [3+4a,0+4b,1+4c,2+4d]: transposed [8] by [0,2,1,3] [3+4a,2+4b,1+4c,2+4d]: unknown -> [9] [3,2,1,2] 108a+144a²+64a³+48b+96b²+64b³+12c+48c²+64c³-48d-96d²-64d³+28 [0+4a,3+4b,1+4c,2+4d]: transposed [8] by [2,0,1,3] [2+4a,3+4b,1+4c,2+4d]: transposed [9] by [1,0,2,3] [0+4a,0+4b,2+4c,2+4d]: non-primitive -> solution [0,0,2,2],trivial(3) [0,0,6,6],trivial(3) [3+4a,1+4b,2+4c,2+4d]: transposed [9] by [0,2,1,3] [2+4a,2+4b,2+4c,2+4d]: non-primitive [1+4a,3+4b,2+4c,2+4d]: transposed [9] by [2,0,1,3] [1+4a,0+4b,3+4c,2+4d]: transposed [8] by [1,2,0,3] [0+4a,1+4b,3+4c,2+4d]: transposed [8] by [2,1,0,3] [2+4a,1+4b,3+4c,2+4d]: transposed [9] by [1,2,0,3] [1+4a,2+4b,3+4c,2+4d]: transposed [9] by [2,1,0,3] [3+4a,0+4b,0+4c,3+4d]: unknown -> [10] [3,0,0,3] 108a+144a²+64a³+64b³+64c³-108d-144d²-64d³ -> solution [3,0,0,3],trivial(3) [7,0,0,7],trivial(3) [3+4a,2+4b,0+4c,3+4d]: unknown -> [11] [3,2,0,3] 108a+144a²+64a³+48b+96b²+64b³+64c³-108d-144d²-64d³+8 [0+4a,3+4b,0+4c,3+4d]: transposed [10] by [2,0,1,3] [2+4a,3+4b,0+4c,3+4d]: transposed [11] by [1,0,2,3] [1+4a,1+4b,1+4c,3+4d]: unknown -> [12] [1,1,1,3] 12a+48a²+64a³+12b+48b²+64b³+12c+48c²+64c³-108d-144d²-64d³-24 [3+4a,3+4b,1+4c,3+4d]: unknown -> [13] [3,3,1,3] 108a+144a²+64a³+108b+144b²+64b³+12c+48c²+64c³-108d-144d²-64d³+28 [3+4a,0+4b,2+4c,3+4d]: transposed [11] by [0,2,1,3] [3+4a,2+4b,2+4c,3+4d]: unknown -> [14] [3,2,2,3] 108a+144a²+64a³+48b+96b²+64b³+48c+96c²+64c³-108d-144d²-64d³+16 [0+4a,3+4b,2+4c,3+4d]: transposed [11] by [2,0,1,3] [2+4a,3+4b,2+4c,3+4d]: transposed [14] by [2,0,1,3] [0+4a,0+4b,3+4c,3+4d]: transposed [10] by [2,1,0,3] [2+4a,0+4b,3+4c,3+4d]: transposed [11] by [1,2,0,3] [3+4a,1+4b,3+4c,3+4d]: transposed [13] by [1,2,0,3] [0+4a,2+4b,3+4c,3+4d]: transposed [11] by [2,1,0,3] [2+4a,2+4b,3+4c,3+4d]: transposed [14] by [2,1,0,3] [1+4a,3+4b,3+4c,3+4d]: transposed [13] by [2,0,1,3] endexp[0] ---------------- level 1 Maximum level 1 [15] mod 4: a³+b³+c³-d³
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//Example 9.4// xfe3c=6.69;//wt % //Fe3C composition x=0.77;//wt % //x is the overall composition xa=0;//wt % //composition of two phases a=1;//kg ma=((xfe3c-x)/(xfe3c-xa))*a mprintf("ma = %f kg ",ma) b=10^3;//g //As 1kg = 10^3grams ma1=ma*b mprintf("\nma1 = %i g ",ma1) mfe3c=((x-xa)/(xfe3c-xa))*a mprintf("\nmfe3c = %f kg ",mfe3c) mfe3c1=mfe3c*b mprintf("\nmfe3c1 = %i g",mfe3c1)
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Ch04Exa14.sce
// Scilab code Exa4.14 : : Page 181 (2011) clc; clear; m_p = 0.938; // Mass of the proton, GeV E = 1.4; // Total energy of proton, GeV gama = E/m_p; // Boost parameter bta = sqrt(1-1/gama^2); // Relativistic factor d = 10; // Distance between two counters,m C = 3e+08; // Velocity of light ,m/s t_p = d/(bta*C); // Time of flight of proton ,sec T_e = d/C; // Time of flight of electron, sec printf("\nTime of flight of proton: %4.2f ns \nTime of flight of electron : %4.2f ns ", t_p/1e-009, T_e/1e-009); // Result // Time of flight of proton: 44.90 ns // Time of flight of electron : 33.33 ns
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Ch01Ex24.sci
// Scilab Code Ex1.24 Relativistic speed form relativistic mass: Pg: 30 (2008) c = 3e+08; // Speed of light, m/s m0 = 1/2; // Rest mass of the particle, MeV/c^2 m = 1/sqrt(2); // Relativistic mass of the particle, MeV/c^2 // As m = m0/sqrt(1 - (v/c)^2), Relativistic mass of electron, kg, solving for v, we have v = sqrt(1 - (m0/m)^2)*c; // Relativistic velocity of particle, m/s printf("\nThe relativistic velocity of particle = %4.2e m/s", v); // Result // The relativistic velocity of particle = 2.12e+008 m/s
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Example_4_10_b.sce
// Chapter4 // Page.No-141, Figure.No-4.26 // Example_4_10_b // Error voltage and output voltage // Given clear;clc; delta_Vio=(30*10^-6); // Change in input offset voltage delta_T=1; // Unit change in temperature delta_Iio=(300*10^-12); // Change in input offset current Vs=15; R1=1*10^3;Rf=100*10^3;Rl=10*10^3; Vin=10*10^-3; // Input voltage k=25; // Amplifier is nulled at 25 deg T=35-k; // Change in temperature Ev=(1+Rf/R1)*(delta_Vio/delta_T)*T + Rf*(delta_Iio/delta_T)*T; // Error voltage printf("\n Error voltage is = %.4f V dc \n",Ev) // Result Vo=(1+Rf/R1)*Vin+Ev; // Output voltage printf("\n Output voltage is = %.4f V dc \n",Vo) // Result // (OR) Vo=(1+Rf/R1)*Vin-Ev; // Output voltage printf("\n Output voltage is = %.4f V dc \n",Vo) // Result
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART II : TRANSMISSION AND DISTRIBUTION // CHAPTER 10: POWER SYSTEM STABILITY // EXAMPLE : 10.14 : // Page number 304 clear ; clc ; close ; // Clear the work space and console // Given data Power = 20.0*10**3 // Rating of generator(kVA) PF = 0.8 // Lagging power factor fault = 0.5 // Reduction in output under fault P = 4.0 // Number of poles f = 50.0 // Frequency(Hz) // Calculations P_m = Power*PF // Output power before fault(kW) P_e = fault*P_m // Output after fault(kW) P_a = P_m-P_e // Accelerating power(kW) w_s = 4.0*%pi*f/P // Speed T_a = P_a*10**3/w_s // Accelerating torque at the time the fault occurs(N-m) // Results disp("PART II - EXAMPLE : 10.14 : SOLUTION :-") printf("\nAccelerating torque at the time the fault occurs, T_a = %.2f N-m", T_a)
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Ex7_9.sce
// Given:- T0 = 273.00 // in kelvin pricerate = 0.08 // exergy value at $0.08 per kw.h // From example 6.8 sigmadotComp = 17.5e-4 // in kw/k sigmadotValve = 9.94e-4 // in kw/k sigmadotcond = 7.95e-4 // in kw/k // Calculations // The rates of exergy destruction EddotComp = T0*sigmadotComp // in kw EddotValve = T0*sigmadotValve // in kw Eddotcond = T0*sigmadotcond // in kw mCP = 3.11 // From the solution to Example 6.14, the magnitude of the compressor power in kW // Results printf( ' Daily cost in dollars of exergy destruction due to compressor irreversibilities = %.3f',EddotComp*pricerate*24) printf( ' Daily cost in dollars of exergy destruction due to irreversibilities in the throttling valve = %.3f',EddotValve*pricerate*24) printf( ' Daily cost in dollars of exergy destruction due to irreversibilities in the condenser = %.3f ',Eddotcond*pricerate*24) printf( ' Daily cost in dollars of electricity to operate compressor = %.3f',mCP*pricerate*24)
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clc ; clear ; m=0.1 // mass in kg K=100 //spring constant in N/m c=1 //resistive force in Nsm^-1 F0=2 //force in N omega=50 //frequency in rad/s //calculation omega_n=sqrt(K/m) //in rad/s r=omega/omega_n delta_st=F0/K //in m damp_ratio=c/(2*m*omega_n) A=delta_st/(sqrt((1-r^2)^2+(2*r*damp_ratio)^2)) tan_phi=(2*r*damp_ratio)/(1-r^2) //in degree phi=180+atand(tan_phi) //converting degree to postive form mprintf("Amplitude of oscillation = %1.2e m\n",A) mprintf("Phase relative to the applied force is = %1.1f degree",phi) //The answers vary due to round of errors
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exaA_7_23.sce
// Example A-7-23 // Nichols plot clear; clc; xdel(winsid()); //close all windows s = %s; G = syslin('c',9 , s*(s+0.5)*(s^2 + 0.6*s + 10) ); black(G); chart([8 -4],[],list(1,0)); xgrid(color('gray'));
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//Ex1_2 clc; //Given: energy=2*10^-6; c=2.5*10^-8;// velocity of light //solution: v=energy/c;// potential printf("The potential in V is = %f ",v)
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kiks_server_request.sci
function [res] = kiks_server_request(id) // Ouput variables initialisation (not found in input variables) res=[]; // Display mode mode(0); // Display warning for floating point exception ieee(1); // ----------------------------------------------------- // (c) 2000-2003 Theodor Storm (Theodor.Storm@home.se) // http://www.kiks.net // ----------------------------------------------------- global("KIKS_SPDC","KIKS_GUI_HDL","KIKS_KIKSNET_PING","KIKS_KIKSNET_PING_COUNT","KIKS_NET_BUFSIZ","KIKS_FID","KIKS_ROBOT_MATRIX","KIKS_MMPERPIXEL","KIKS_KIKSNET_COMMAND","KIKS_KIKSNET_REPLY"); res = ""; KIKS_KIKSNET_REPLY = ""; if ~isempty(KIKS_KIKSNET_COMMAND) then KIKS_KIKSNET_COMMAND = "CMD:"+KIKS_KIKSNET_COMMAND;end; if mtlb_logic(mtlb_double(KIKS_FID),">",-1) then tic; // !! L.14: Matlab function sprintf not yet converted, original calling sequence used req = sprintf("R 1 %.3f %.3f %.3f %.3f %.3f %.3f %.3f %s",KIKS_ROBOT_MATRIX(id,1,1),KIKS_ROBOT_MATRIX(id,1,2),KIKS_ROBOT_MATRIX(id,1,3),mtlb_double(KIKS_ROBOT_MATRIX(id,6,7))*mtlb_double(KIKS_SPDC),mtlb_double(KIKS_ROBOT_MATRIX(id,6,8))*mtlb_double(KIKS_SPDC),KIKS_ROBOT_MATRIX(id,2,2),KIKS_ROBOT_MATRIX(id,2,1),KIKS_KIKSNET_COMMAND); // !! L.15: Unknown function kiks_transmit_string not converted, original calling sequence used kiks_transmit_string(KIKS_FID,req); res = kiks_recieve_string(KIKS_FID); if ~isempty(KIKS_KIKSNET_COMMAND) then // !! L.18: Matlab function deblank not yet converted, original calling sequence used KIKS_KIKSNET_REPLY = deblank(kiks_recieve_string(KIKS_FID)); end; KIKS_KIKSNET_PING = mtlb_a(mtlb_double(KIKS_KIKSNET_PING),toc()); KIKS_KIKSNET_PING_COUNT = mtlb_a(mtlb_double(KIKS_KIKSNET_PING_COUNT),1); if bool2s(isempty(KIKS_KIKSNET_PING_COUNT))|bool2s(mtlb_logic(KIKS_KIKSNET_PING_COUNT,">",10)) then // !! L.22: Matlab function findobj not yet converted, original calling sequence used // L.22: Name conflict: function name changed from findobj to %findobj h = findobj("tag","t_kiksnet_text_ping"); if ~isempty(KIKS_KIKSNET_PING_COUNT) then t = floor((KIKS_KIKSNET_PING*1000)/KIKS_KIKSNET_PING_COUNT); else t = floor(KIKS_KIKSNET_PING*1000); end; if mtlb_logic(t,">=",10) then // !! L.28: Matlab function sprintf not yet converted, original calling sequence used // !! L.28: Matlab function set not yet converted, original calling sequence used // L.28: Name conflict: function name changed from set to %set set(h,"String",sprintf("%d ms",t));else // !! L.28: Matlab function set not yet converted, original calling sequence used // L.28: Name conflict: function name changed from set to %set set(h,"String","<10 ms");end; KIKS_KIKSNET_PING = 0; KIKS_KIKSNET_PING_COUNT = 0; end; end; KIKS_KIKSNET_COMMAND = ""; endfunction
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ex_3_4.sce
//find limits of shaft and bearing and maximum and minimum clearance clc //solution //given //75 mm basic size //since 75 lies betweenn 50 and 80 D=sqrt(50*80)//mm i=0.45*(D)^0.33+0.001*D//standard tolerance unit IT8=25*i*0.001//mm IT7=16*i*0.001//mm es=-2.5*(D)^0.34//mm//upper deviation of shaft ei=es-IT7//mm//lower deviation fot hole bs=75//mm//basic size uh=75+IT8//upper limit of hole us=75-0.01//mm//upper limit of shft ls=us-0.03//mm MxC=uh-ls//mm//maximum clearance miC=75-us//mm printf("maximum clearance is,%f mm\n",MxC) printf("minimum clearance is,%f mm",miC)
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noof1.sci
function res=noof1(a,z) //this function returns both the no of zeros and ones in given matrix res=0; for i=1:max(size(a(:,1))) for j=1:max(size(a(1,:))) if(a(i,j)==z) res=res+1; end end end endfunction
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Ex_10_4_b.sce
// Example 10.4.b;//Thermal noise clc; clear; close; T=293;//TEMPRATURE IN KELVIN K=1.38*10^-23;//boltzman constt C=3*10^8;//SPEED of light in meter per second e=1.6*10^-19;//elecronic charge ht=6.62*10^-34;//plank constt. Id=3;//dark current in nano ampere n=0.60;//efficiency Rl=4;//load resistance in killo ohms h=0.9;//wavelength in micro meter Po=200;// ouput power in nano wat B=5;// bandwidth in mega hertz it=(((4*K*T*B*10^6)/(Rl*10^3)));//thermal noise itr=sqrt(it);//rms thermal noise disp(it,"total thermal noise is") disp(itr,"RMS thermal noise current in ampere is")
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result6s0.tst
@relation flare @attribute LargestSpotSize{A,R,S,X,K,H} @attribute SpotDistribution{X,O,I,C} @attribute Activity{1,2} @attribute Evolution{1,2,3} @attribute Prev24Hour{1,2,3} @attribute HistComplex{1,2} @attribute BecomeHist{1,2} @attribute Area{1,2} @attribute C-class{0,1,2,3,4,5,6,7,8} @attribute M-class{0,1,2,3,4,5} @attribute X-class{0,1,2} @attribute Class{H,D,C,B,E,F} @inputs LargestSpotSize,SpotDistribution,Activity,Evolution,Prev24Hour,HistComplex,BecomeHist,Area,C-class,M-class,X-class @outputs Class @data B B B B C D H H E D B B C C D E B B D D E C H H C C E C H H E E H H C C H H D D B B D D C C D D H H C D D C C D D C B B B B D C D D H H H H D D B B H H H H D D B B D C D C C D H H H H C C H H B B D C D D C D D D B B H H F D B B H H H H F D H H H H H H H H H H H H H H C C D D H H C C E D H H C C D D E D E D H H H H E E F D E E D D H H H H H H B B D D C C C C H H D C C C B B C D C D C C F D D D C C B B C D D C H H D C H H
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// Exa 2.20 format('v',4); clc; clear; close; // Given data unCox= 20*10^-6;//in A/V^2 upCox= unCox/2.5;// in A/V^2 V_DD= 3;//in V Vt= 1;// in V W= 30;// in µm L= 10;// in µm // V_GS1= V_GS2 // Formula V_DD= V_GS1+V_GS2 V_GS1= V_DD/2;//in V V_GS2= V_GS1;// in V V2= V_GS1;// inV I1= 1/2*unCox*W/L*(V_GS1-Vt)^2;// in A // Both transistor have V_D = V_G and therefore they are operating in saturation //1/2*unCox*W/L*(V4-Vt)^2 = 1/2*upCox*W/L*(V_DD-V4-Vt) V4= (V_DD-Vt+sqrt(unCox/upCox))/(1+sqrt(unCox/upCox)); I3= 1/2*unCox*W/L*(1.39-Vt)^2 disp(V2,"The value of V2 in volt is : ") I1= I1*10^6;// in µA disp(I1,"The value of I1 in µAis : ") disp(V4,"The value of V4 in volt is : ") I3= I3*10^6;// in µA disp(I3,"The value of I3 in µAis : ")
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// 4.3 clc; Pc=50; m=0.85; Pt=Pc*(1+(m^2/2)) printf("Radiation Power =%.2f kW",Pt)
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Interfaces.tst
import * as enums from '../enums'; declare global { namespace models { ${ private const string IncludeClassAttribute = "TsClassModule"; private static readonly string[] IgnorePropertyAttribute = {"IgnoreDataMember", "TsIgnore"}; private const string OptionalMemberPropertyAttribute = "TsOptionalMember"; private const string CanBeNullPropertyAttribute = "CanBeNull"; private const string IncludeEnumAttribute = "TsEnumModule"; Template(Settings settings) { settings.IncludeProject("ChoreStorefront") .IncludeProject("ChoreStorefront.Core") .IncludeProject("ChoreStorefront.Model") .IncludeProject("ChoreStorefront.Api"); settings.OutputExtension = ".d.ts"; } IEnumerable<Property> GetProperties(Class c) { var result = c.Properties.Where(m=>!m.Attributes.Any(a=>IgnorePropertyAttribute.Contains(a.Name))); if (c.BaseClass!=null && !c.BaseClass.Attributes.Any(a=>a.Name==IncludeClassAttribute)) { result = result.Concat(GetProperties(c.BaseClass)); } return result; } IEnumerable<Property> GetProperties(Interface c) { var result = c.Properties.Where(m=>!m.Attributes.Any(a=>IgnorePropertyAttribute.Contains(a.Name))); return result; } bool IncludeClass(Class c) { return c.Attributes.Any(a => a.Name==IncludeClassAttribute); //var c2 = c; //while (c2!=null) { // if (c2.Attributes.Any(a => a.Name==IncludeClassAttribute)) { // return true; // } // c2 = c2.BaseClass; // if (c2 !=null && c2.Name=="DefaultCommandResult") { // return false; // } //} //return false; } string ClassNameWithExtends(Class c) { var name = c.Name; if (c.TypeParameters.Any()) { name += c.TypeParameters.ToString(); } var extends = new List<string>(); if (c.BaseClass!=null && c.BaseClass.Attributes.Any(a=>a.Name==IncludeClassAttribute)) { var s = c.BaseClass.Name; if (c.BaseClass.TypeParameters.Any()) { s += c.BaseClass.TypeArguments.ToString(); } extends.Add(s); } foreach (var i in c.Interfaces.Where(m=>m.Attributes.Any(a=>a.Name==IncludeClassAttribute))) { if (!i.TypeParameters.Any()) { var s = i.Name; extends.Add(s); //s += i.TypeParameters.ToString(); } } if (extends.Any()) { name += " extends " + string.Join(", ", extends); } return name; } string ClassNameWithExtends(Interface c) { var name = c.Name; if (c.TypeParameters.Any()) { name += c.TypeParameters.ToString(); } var extends = new List<string>(); foreach (var i in c.Interfaces.Where(m=>m.Attributes.Any(a=>a.Name==IncludeClassAttribute))) { if (!i.TypeParameters.Any()) { var s = i.Name; //s += i.TypeParameters.ToString(); extends.Add(s); } } if (extends.Any()) { name += " extends " + string.Join(", ", extends); } return name; } string BaseClassNotIncludedWarning(Class c) { if (c.BaseClass!=null && !c.BaseClass.Attributes.Any(a=>a.Name==IncludeClassAttribute)) { return "// WARNING: Base Class " + c.BaseClass.Name + " not marked with " + IncludeClassAttribute + " - so including base class properties inline instead of extending base class.\n// You should really decorate the " + c.BaseClass.Name + " class with the " + IncludeClassAttribute + " attribute."; } return ""; } string PropertyName(Property p) { var name = p.name; //var cls = p.Parent as Class; //if (cls!=null && cls.Attributes.Any(m=>m.Name=="JsonObject" && m.Value.Contains("CamelCaseNamingStrategy"))) { //name = p.name; //} var isOptional = p.Type.IsNullable || p.Attributes.Any(a => a.Name==OptionalMemberPropertyAttribute || a.Name==CanBeNullPropertyAttribute); if (isOptional) { return name + '?'; } if (p.Parent is Class c) { var baseClass = c.BaseClass; if (baseClass!=null) { var baseProperty = baseClass.Properties.FirstOrDefault(m=>m.Name==p.Name); if (baseProperty!=null) { return PropertyName(baseProperty); } } } return name; } string EnumType(Property p) { var constAttribute = p.Attributes.FirstOrDefault(m=>m.Name=="TsConstant"); if (constAttribute!=null) { return "enums." + constAttribute.Value; } if (!p.Type.Attributes.Any(a=>a.Name=="JsonConverter" && a.Value.Contains("StringEnumConverter"))) { var parentClass = p.Parent as Class; var baseClass = parentClass?.BaseClass; if (baseClass!=null) { var baseProperty = baseClass.Properties.FirstOrDefault(m=>m.Name==p.Name); if (baseProperty!=null) { return EnumType(baseProperty); } } } if (p.Type.IsEnumerable) { return "readonly enums." + p.Type.ToString(); } return "enums." + p.Type.ToString(); } string PropertyType(Property p) { var type = p.Attributes.FirstOrDefault(m=>m.Name=="TsType"); if (type!=null) { return GetType(type.Arguments[0].TypeValue); } if (p.Type.IsEnum && p.Type.Attributes.Any(a => a.Name ==IncludeEnumAttribute)) { return EnumType(p); } if (p.Type.IsEnumerable && p.Type.TypeArguments.Count==1) { var t = p.Type.TypeArguments[0]; if (t.IsEnum && t.Attributes.Any(a => a.Name ==IncludeEnumAttribute)) { return EnumType(p); //return "enums." + type.ToString(); } } return GetType(p.Type); } string GetType(Type type) { if ((type.OriginalName.StartsWith("Dictionary") || type.OriginalName.StartsWith("IReadOnlyDictionary")) && type.TypeArguments.Count==2) { var keyType = type.TypeArguments[0]; var valueType = type.TypeArguments[1]; var keyTypeStr = keyType.IsEnum ? "number" : keyType.ToString(); return "{ [key: " + keyTypeStr +"]: " + valueType.ToString() +"; }"; } if (type.ToString()=="Date") { return "string"; } if (type.ToString()=="Date[]") { return "readonly string[]"; } if (type.OriginalName.StartsWith("IReadOnlyCollection") && type.TypeArguments.Count==1) { var keyType = type.TypeArguments[0]; return "readonly " + keyType + "[]"; } if ((type.IsEnumerable) && !type.OriginalName.StartsWith("Dictionary") && (type.BaseClass==null || !type.BaseClass.Name.StartsWith("Dictionary"))) { return "readonly " + type.ToString(); } //var isOptional = p.Type.IsNullable || p.Attributes.Any(a => a.Name==OptionalMemberPropertyAttribute || a.Name==CanBeNullPropertyAttribute); //if (isOptional) { //return p.Type.ToString() + " | null"; //} //return "Test: " + type.OriginalName; return type.ToString(); } string DisplayValuePropertyType(Property p) { if (p.Type.Name=="string") { return "{ display: string }"; } if (p.Type.IsPrimitive) { return "{ display: string; value: " + PropertyType(p) + "; }"; } return p.Type.ToString(); } string DocCommentFormatted(Item i) { var dc = (i as Class)?.DocComment ?? (i as Interface)?.DocComment ?? (i as Property)?.DocComment ?? (i as Constant)?.DocComment; var summary = string.Empty; if (dc != null) { summary = dc.Summary; } if (i is Property p && p.Type.IsDate) { var kindAttrib = p.Attributes.FirstOrDefault(a=>a.Name=="DateTimeKind"); if (kindAttrib!=null) { if (!string.IsNullOrEmpty(summary)) { summary+="\n"; } if (kindAttrib.Value=="System.DateTimeKind.Utc") { summary += "DateTime in UTC"; } else if (kindAttrib.Value=="System.DateTimeKind.Local") { summary += "DateTime in PST"; } } } if (!string.IsNullOrEmpty(summary)) { return @"/** * " + summary + @" */"; } return null; } } $Classes(c => IncludeClass(c) && !c.Attributes.Any(a=>a.Name=="SerializeDisplayValue") && c.Name!="DefaultCommandResult")[ $DocCommentFormatted export interface $ClassNameWithExtends { $GetProperties()[ $DocCommentFormatted $PropertyName: $PropertyType; ] } $NestedClasses(c => c.Attributes.Any(a => a.Name==IncludeClassAttribute))[ $DocCommentFormatted export interface $ClassNameWithExtends { $GetProperties()[ $DocCommentFormatted $PropertyName: $PropertyType; ] } ] ] $Classes(c => c.Attributes.Any(a => a.Name==IncludeClassAttribute) && c.Attributes.Any(a=>a.Name=="SerializeDisplayValue"))[ $DocCommentFormatted export interface $ClassNameWithExtends { $GetProperties()[ $DocCommentFormatted $PropertyName: $DisplayValuePropertyType ] } ] $Interfaces(c => c.Attributes.Any(a => a.Name==IncludeClassAttribute) )[ $DocCommentFormatted export interface $ClassNameWithExtends { $GetProperties()[ $DocCommentFormatted $PropertyName: $PropertyType; ] } ] } }
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// Example 9_14 clc;funcprot(0); // Given data P_1=10;// kPa P_3=4;// MPa P_5=100;// kPa W_ST=100;// The power output from the turbine in MW T_5=25+273;// K r_p=5;// The pressure ratio T_7=850+273;// K T_9=350;// K c_p=1.00// kJ/kg.K k=1.4;// The specific heat ratio // Calculation h_1=192;// kJ/kg h_2=h_1;// kJ/kg // At 400°C and 4 MPa h_3=3214;// kJ/kg s_3=6.7698;// kJ/kg.K s_4=s_3;// kJ/kg.K s_f4=0.6491;// kJ/kg.K s_fg4=7.5019;// kJ/kg.K x=(s_4-s_f4)/s_fg4;// The quality of steam h_f4=192;// kJ/kg h_fg4=2393;// kJ/kg h_4=h_f4+(x*h_fg4);// kJ/kg h_3=3214;// kJ/kg m_s=(W_ST*10^3)/(h_3-h_4);// kg/s T_6=T_5*(r_p)^((k-1)/k);// K T_8=T_7*(1/r_p)^((k-1)/k);// K h_2=192;// kJ/kg m_a=(m_s*(h_3-h_2))/(c_p*(T_8-T_9));// kg/s W_turb=m_a*c_p*(T_7-T_8);// kJ/kg W_comp=m_a*c_p*(T_6-T_5);// kJ/kg W_GT=(W_turb-W_comp)/10^3;// The net gas turbine output in MW Q_in=(m_a*c_p*(T_7-T_6))/10^3;// MW n=(W_ST+W_GT)/Q_in;// The combined cycle efficiency printf("\nThe efficiency of the combined Brayton-Rankine cycle,n=%0.3f or %2.1f percentage.",n,n*100);
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clc; b=0.228; a=1-b; c=[1+(2*0.455)-b-2*a]/2 n2=a+b+c+1.709; p1=8.28; T2=555; n1=1+0.455+1.709; T1=2968; p2=p1*(n2/n1)*(T1/T2); p=1; K=a/b*[n2*p/(c*p2)]^0.5; disp(log(K),"log(K) is:"); disp("2968","from tables it is proved that temperatur is:")
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// Convolution spatiale : Filtre Moyenneur 3*3 function image_out = filtreMoyenneur(image) SizeX = size(image, 1); //On récupère la longueur de l'image à modifier. SizeY = size(image, 2); //On récupère la largeur de l'image à modifier. image_out = zeros(SizeX, SizeY); //On crée une matrice nulle qui va contenir l'image modifiée. for X = 2 : SizeX-1 //On parcourt la matrice en évitant les extrémités. for Y = 2 : SizeY-1 image_out(X, Y) = round((image(X-1, Y-1)+image(X, Y-1)+image(X+1, Y-1)+image(X-1, Y)+image(X, Y)+image(X+1, Y)+image(X-1, Y+1)+image(X, Y+1)+image(X+1, Y+1))/9); //On arrondit les coefficients. end end endfunction
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 2.4w //calculation of direction of resultant vector //given data //OA=OB=OC=F all the three vectors have same magnitude //xcompOA=F*cos30=(F*(sqrt(3)))/2 //xcompOB=F*cos360=F/2 //xcompOC=F*cos135=-F/(sqrt(2)) //xcompr=xcompOA + xcompOB + xcompOC //ycompOA=F*cos60=F/2 //ycompOB=F*cos360=-(F*(sqrt(3)))/2 //ycompOC=F*cos135=F/(sqrt(2)) //ycompr=ycompOA + ycompOB + ycompOC //calculation theta=atand((1-sqrt(3)-sqrt(2))/(1+sqrt(3)+sqrt(2))); disp(theta,'the angle(in degree) made by OA+OB-OC vector with X axis is');
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clc; clear; Np1=60; // Noise-Power ratio of first system in dB Np2=40; // Noise-Power ratio of second system in dB Np3=30; // Noise-Power ratio of third system in dB Np4=50; // Noise-Power ratio of fourth system in dB P1=10^(-6); //power ratio of first system P2=10^(-4); //power ratio of second system P3=10^(-3); //power ratio of third system P4=10^(-5);//power ratio of fourth system SNR=(P1+P2+P3+P4); // Overall Signal to Noise ratio disp("SNR ratio is"); disp(SNR); N_final=30; //since SNR is 10^(-3) disp("overall SNR (in dB)is"); disp(N_final); disp("the overall SNR is equal to that of the worst system")
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// Scilab Code Ex3.17: Page-103 (2006) clc; clear; h = 6.624e-034; // Planck's constant, Js k = 1.38e-023; // Boltzmann constant, J/mol/K q = 1.486e+011; // Young's modulus of diamond, N/metre-square rho = 3500; // Density of diamond, kg/metre-cube c = sqrt(q/rho); // Speed of transverse wave through diamond, m/s m = 12*1.66e-027; // Atomic weight of carbon, kg theta_D = (h/k)*c*(3*rho/(4*%pi*m))^(1/3); // Debye temperature for diamond, K printf("\nThe Debye temperature for diamond = %4d K", theta_D); // Result // The Debye temperature for diamond = 1086 K
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//ques-1.2 //Calculating hardness in three samples clc A=168;//mass of MgCO3/L (in mg) B1=820;//mass of Calcium Nitrate (in mg) B2=2;//mass of Si/L (in mg) C1=20;//mass of Potassium nitrate/500mL (in g) C2=2;//mass of CaCO3/500mL (in g) m1=(A/84)*100;//CaCO3 equivalent of A (in mg/L) m2=(B1/164)*100;//CaCO3 equivalent of B1 (in mg/L) m3=2*(1000/500)*1000*(100/100);//CaCO3 equivalent of C1 (in mg/L) printf("The hardness of sample A, B and C in ppm are %d, %d and %d\n",m1,m2,m3); //1 ppm = 0.07 grains/gallon printf(" and hardness in grains/gallon are %d, %d and %d respectively.",m1*0.07,m2*0.07,m3*0.07);
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//clear// //Caption:PN sequence generation //Example9.1 and Figure9.1: Maximum-length sequence generator //Program to generate Maximum Length Pseudo Noise Sequence //Period of PN Sequence N = 7 clc; //Assign Initial value for PN generator x0= 1; x1= 0; x2 =0; x3 =0; N = input('Enter the period of the signal') for i =1:N x3 =x2; x2 =x1; x1 = x0; x0 =xor(x1,x3); disp(i,'The PN sequence at step') x = [x1 x2 x3]; disp(x,'x=') end m = [7,8,9,10,11,12,13,17,19]; N = 2^m-1; disp('Table 9.1 Range of PN Sequence lengths') disp('_________________________________________________________') disp('Length of shift register (m)') disp(m) disp('PN sequence Length (N)') disp(N) disp('_________________________________________________________') //RESULTEnter the period of the signal 7 // The PN sequence at step 1. // x= 1. 0. 0. // The PN sequence at step 2. // x= 1. 1. 0. // The PN sequence at step 3. // x= 1. 1. 1. // The PN sequence at step 4. // x= 0. 1. 1. // The PN sequence at step 5. // x= 1. 0. 1. // The PN sequence at step 6. // x= 0. 1. 0. // The PN sequence at step 7. // x= 0. 0. 1.
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a^3 + b^3 + c^3 - d^3; a - m^4 + 2*m*n^3; b - m^3*n - n^4; c - 2*m^3*n + n^4; d - m^4 - m*n^3 isolated Signature: /d.01 isolated variable: d with Coefficient 1 remaining RelationSet: a^3 + b^3 + c^3 - d^3; a - m^4 + 2*m*n^3; b - m^3*n - n^4; c - 2*m^3*n + n^4 substitute by Polynomial: - m^4 - m*n^3 isolated Signature: /c.01 isolated variable: c with Coefficient 1 remaining RelationSet: a^3 + b^3 + c^3 + m^12 + 3*m^9*n^3 + 3*m^6*n^6 + m^3*n^9; a - m^4 + 2*m*n^3; b - m^3*n - n^4 substitute by Polynomial: - 2*m^3*n + n^4 isolated Signature: /b.01 isolated variable: b with Coefficient 1 remaining RelationSet: a^3 + b^3 + m^12 - 5*m^9*n^3 + 15*m^6*n^6 - 5*m^3*n^9 + n^12; a - m^4 + 2*m*n^3 substitute by Polynomial: - m^3*n - n^4 isolated Signature: /a.01 isolated variable: a with Coefficient 1 remaining RelationSet: a^3 + m^12 - 6*m^9*n^3 + 12*m^6*n^6 - 8*m^3*n^9 substitute by Polynomial: - m^4 + 2*m*n^3 simplified and grouped: + 1*(0)
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clc //Chapter 5:High Frequency Amplifiers and Automatic Gain Control //example 5.3 page no 153 //given gm=2*10^-3//transconductance Cgs=5*10^-12//equivalent Miller's input capacitance Cgd=1*10^-12//equivalent Miller's output capacitance Cds=1*10^-12 rd=13*10^3 R=5*10^3//source resistance RL=(6*10^3*13*10^3)/(6*10^3+13*10^3)//total load resistance Av=-gm*RL//voltage gain R_L=RL*rd/(RL+rd) CT=Cgs+Cgd*(1+gm*R_L)//total capacitance Co=Cds+(Cgd*(1+gm*R_L)/(gm*R_L))//output capacitance w1=(R*CT)^-1//pole due to input circuit w2=(RL*Co)^-1//pole due to output circuit mprintf('the voltage gain is %f \n the total capacitance is %3.2e pF \n the output capacitance is %3.2e pF \n the pole due to input circuit is %3.2e rad/s \n the pole due to output circuit is %3.2e rad/s ',Av,CT,Co,w1,w2)
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Ch03Ex19.sce
// Scilab Code Ex3.19:: Page-3.31 (2009) clc; clear; f = 150; // Distance between screen and slit, cm a = 0.005; // Slit width, cm b = 0.06; // Distance between slits, cm lambda = 5500e-008; // Wavelength of light used, cm // As half angular separation, theta1 = x1/f = lambda/(2*(a+b)), solving for x1 x1 = f*lambda/(2*(a+b)); // Distance between central maxima and first minima, cm delta_theta = lambda/(2*(a+b)); // Angular separation between two consecutive minima, radians printf("\nThe distance between central maxima and first minima = %4.2e cm", x1); printf("\nThe angular separation between two consecutive minima = %3.1e radians", delta_theta); // Result // The distance between central maxima and first minima = 6.35e-002 cm // The angular separation between two consecutive minima = 4.2e-004 radians
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Ex2_30.sce
//CHAPTER 2- STEADY-STATE ANALYSIS OF SINGLE-PHASE A.C. CIRCUIT //Example 30 // read it as example 29 in the book on page 2.83 clc; disp("CHAPTER 2"); disp("EXAMPLE 30"); //VARIABLE INITIALIZATION f=50; //Hz rms=20; //in Amp t1=0.0025; //in sec time to find amplitude t2=0.0125; //in sec, to find amp after passing through +ve maximum i3=14.14; //in Amps, to find time when will it occur after passing through +ve maxima //SOLUTION //i=Isin(wt) //solution (a) w=2*%pi*f; Im=rms*sqrt(2); disp(sprintf("The equation would be i=%f. sin(%f.t)", Im,w)); t0=(asin(1)/w); //time to reach maxima in +ve direction i=Im*sin(w*t1); disp("SOLUTION (a)"); disp(sprintf("The amplitude at time %f sec is %f Amp", t1,i)); //solution (b) tx=t0+t2; i2=Im*sin(w*tx); disp("SOLUTION (b)"); disp(sprintf("The amplitude at time %f sec is %f Amp", t2,i2)); //solution (c) ty=(asin(i3/Im))/w; t3=t0-ty; //since ty is the time starting from 0, the origin needs to be shifted to maxima disp("SOLUTION (c)"); disp(sprintf("The amplitude of %f Amp would be reached in %f Sec", i3,t3)); disp(" "); // //END
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example9.sce
clear; close; clc; A=[1 0 1;1 0 0; 2 1 0]; disp('A=',A); [m,n]=size(A); for k=1:n V(:,k)=A(:,k); for j=1:k-1 R(j,k)=V(:,j)'*A(:,k); V(:,k)=V(:,k)-R(j,k)*V(:,j); end R(k,k)=norm(V(:,k)); V(:,k)=V(:,k)/R(k,k); end disp('Q=',V);
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EX4_9.sce
//EXAMPLE 4-9 PG NO-232-233 X=[40 -8 -20;-8 18 -6;-20 -6 36]; Y=[24 -8 -20;0 18 -6;0 -6 36]; Z=[40 24 -20;-8 0 -6;-20 0 36]; U=[40 -8 24;-8 18 0;-20 -6 0] I1=det(Y/X); disp('CURRENT = '+string((I1))+' A'); I2=det(Z/X); disp(' CURRENT = '+string(I2)+' A'); I3=det(U/X); disp(' CURRENT is = '+string(I3)+' A'); IR3=I2; disp(' CURRENT is = '+string(IR3)+' A'); IR4=0; disp(' CURRENT is = '+string(IR4)+' A'); IR5=I1-I3; disp(' CURRENT is = '+string(IR5)+' A'); IR6=I3; disp(' CURRENT is = '+string(IR6)+' A');
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ex_7.sce
// Chapter 7_The pn junction Diode //Caption_Generation Recombination currents //Ex_7//page 277 T=300 tau_o=5*10^-7 tau_po=5*10^-7 tau_no=5*10^-7 Na=10^16 //acceptor impurity Nd=10^16 // donor impurity ni=1.5*10^10 //intrinsic concentration epsr=11.7 eps=epsr*8.85*10^-14 V=5 //V=Vbi+VR e=1.6*10^-19 W=((2*eps/e)*((Na+Nd)/(Na*Nd))*(V))^0.5 Jgen=e*ni*10^9*W/(2*tau_o) printf('The ideal reverse saturation current density was calculated in example 2 and it was 4.15810^-11 A/cm^2 and the generation current density calculated here is %f nA/cm^2',Jgen)
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example_10_1.sce
//Chapter 10 //Example 10.1 //Page 253 //unloadedfault //run clear command then execute dependancy file and then the source file //dependency file is pucalc.sci clc; //Given P_g1 = 50e6; V_g1 = 13.8e3; P_g2 = 25e6; V_g2 = 13.8e3; P_t = 75e6; V_t_lt = 13.8e3; V_t_ht = 69e3; X11_g = 0.25; X11_t = 0.10; Vbase = 69e3; Pbase = 75e6; Vbase_lt = 13.8e3; V_ht = 66e3; X11_d_g1 = pucalc(X11_g,V_t_lt,Vbase_lt,Pbase,P_g1); X11_d_g2 = pucalc(X11_g,V_t_lt,Vbase_lt,Pbase,P_g2); E_g1 = V_ht / Vbase; E_g2 = V_ht / Vbase; disp('For Generator 1') printf("Xd11 = %.3f per unit \n Eg1 = %.3f per unit \n",X11_d_g1,E_g1) disp('For Generator 2') printf("Xd11 = %.3f per unit \n Eg2 = %.3f per unit \n",X11_d_g2,E_g2) X_g12 = (X11_d_g1 * X11_d_g2) / (X11_d_g1 + X11_d_g2); I11 = E_g1 / (%i*(X_g12 + X11_t)); disp(I11,'Subtransient current in the short circuit in per unit is') Vdt = I11 * (%i*X11_t); disp(Vdt,'Voltage on the delta side of the transformer in per unit is') I11_g1 = (E_g1 - Vdt) / (%i*X11_d_g1); I11_g2 = (E_g2 - Vdt) / (%i*X11_d_g2); disp('Subtransient current in generator 1 and 2 in per unit respectively') disp(I11_g1) disp(I11_g2) Ibase = Pbase / (sqrt(3) * Vbase_lt); I11_1 = abs(I11_g1) * Ibase; I11_2 = abs(I11_g2) * Ibase; disp('Subtransient current in generator 1 and 2 in Amperes respectively') disp(I11_1) disp(I11_2)
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const var procedure call begin end if fi then while do := = != < <= > >= + - * / ( ) , ; $ identifiertest 1233444 234.56 50000.23
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ex_3_73.sce
//Example 3.73: inductance clc; clear; close; l1=4;//H r1=1;//ohm r2=1;//ohm r3=2;//ohm l4=2;//H r4=2;//ohm M=((r3*l1)-(r2*l4))/(r2+r3);//H disp(M,"M is ,(H)=")
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EX2_32.sce
//EXAMPLE 2-32 PG NO-83 cos30=0.866; sin30=0.5; E1=141.42+%i*0; E2=144.566+%i*11.976; V=E1+141.42*(cos30 * sin30 ); disp('1) Voltage is in rectangular form = '+string(V)+' W'); Z=8+%i*6; //IMPEDANCE I=V/Z; disp('1) Current is in rectangular form = '+string(I)+' A'); P=I*V*0.743; disp(' POWER is in rectangular form = '+string(P)+' W');
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exa_6_15.sce
// Exa 6.15 clc; clear; close; // Given Data format('v',7) f= 2;// in kHz f=f*10^3;// in Hz C= 0.01;// in micro F C=C*10^-6;// in F R= 15;// in kohm R=R*10^3;// in ohm fie= -2*atand(2*%pi*f*R*C); fie= ceil(fie); disp(fie,"Phase shift in °"); disp("i.e. "+string(abs(fie))+"° (lagging)")
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Ex2_8.sce
clc clear //Input data Pl=5.6//Power load in MW Hl=1.163//Heat load in MW p1=40//Pressure in bar T1=500+273//Temperature in K p2=0.06//Pressure in bar p3=2//Pressure in bar CV=25//Calorific value in MJ/kg n=88//Boiler efficiency in percent T=6//Temperature rise in degree C //Calculations h1=3445.3//Enthalpy in kJ/kg s1=7.0901//Entropy in kJ/kg.K s2=s1//Entropy in kJ/kg.K s3=s1//Entropy in kJ/kg.K x2=(s2-1.5301)/5.5970//Dryness fraction h2=2706.7//Enthalpy in kJ/kg h26=2201.9//Difference in enthalpy in kJ/kg w=(Hl*10^3)/h26//Rate of steam extraction in kg/h x3=(s1-0.52)/7.815//Dryness fraction h3=(149.79+x3*2416)//Enthalpy in kJ/kg h4=149.79//Enthalpy in kJ/kg ws=((Pl*10^3+(w*(h2-h3)))/((h1-h2)+(h2-h3)))//Steam generation capacity in kg/s ws1=(ws*3600)/1000//Steam generation capacity in t/h h7=(504.7+(1.061*10^-3*(p1-p3)*100))//Enthalpy in kJ/kg h5=(149.79+(1.006*100*p1*10^-3))//Enthalpy in kJ/kg Q1=(((ws-w)*(h1-h5))+(w*(h1-h7)))//Heat input in kW wf=((Q1/1000)/((n/100)*CV))*(3600/1000)//Fuel burning rate in t/h Q2=((ws-w)*(h3-h4))//Heat rejected to the condensor in kW wc=(Q2/(4.187*T))/1000//Rate of flow of cooling water in m^3/s //Output printf('(a) the steam generation capacity of the bolier is %3.2f t/h \n (b) the heat input to the boiler is %3.1f kW \n (c) the fuel burning rate of the bolier is %3.3f t/h \n (d) the heat rejected to the condensor is %3.0f kW \n (e) the rate of flow of cooling water in the condensor is %3.3f m^3/s',ws1,Q1,wf,Q2,wc)
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EX3_7.sce
clc;funcprot(0);//EXAMPLE 3.7 // Initialisation of Variables etaotto=0.6;............//Efficiency of otto engine ga=1.5;.................//Ratio of specific heats //Calculations r=(1/(1-etaotto))^(1/(ga-1));................//Compression ratio disp(r,"The compression ratio of the engine is:")
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Turbomachinery Design and Theory,Rama S. R. Gorla and Aijaz A. Khan, Chapter 3, Example 6") disp("Refering Figure") disp("Hydraulic Efficiency etah = Power output/Energy available in the jet = P/(0.5mC1^2)") disp("At entry to nozzle") H = 610-46//in m Cv = 0.98; g = 9.81; disp("Using nozzle velocity coefficient C1") C1 = Cv * (2*g*H)^0.5 disp("Now W/m = U1Cw1 - U2Cw2 =U {(U + V1)-[U-V2cos(180 -alpha)]}= U[(C1 - U)(1 - k cos (alpha))] where V2 = kV1") disp("Therefore W/m") Wm = 0.46*C1*(C1-0.46*C1)*(1-0.99*cos(165*%pi/180)) etah = Wm/(0.5*103*103) disp("Actual hydraulic efficiency") etaha = 0.91*etah disp("Wheel bucket speed") s = 0.46*C1 disp("Wheel rotational speed N") N = s*60/(0.445*2*%pi) disp("Actual hydraulic efficiency") disp("¼ Actual power/energy in the jet = (1260 * 10^3)/(0.5mC1^2)") disp("Therefore") m = 1260*1000/(0.882*0.5*103*103) disp("For one nozzle,m") mone = m/2 disp("For nozzle diameter, using continuity equation, m") disp("m = rho*C1*A = rho*C1*pi*d^2/4") disp("Hence, d in mm") d = (mone*4/(%pi*103*1000))^0.5 *1000
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clc;funcprot(0);//EXAMPLE 3.24 // Initialisation of Variables r=14;......................//Compression ratio Beta=1.4;................//Explosion ratio co=6;..................//Cut off percentage ga=1.4;.................//Ratio of specific heats //Calculation rho=((co/100)*(r-1))+1;...............//Cut off ratio etadual=1-[(1/(r^(ga-1)))*((Beta*(rho^ga))-1)*(1/((Beta-1)+(Beta*ga*(rho-1))))];............//Efficiency of dual cycle disp(etadual*100,"Efficiency of dual cycle:")
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Example25_1.sce
clear ; clc; // Example 25.1 printf('Example 25.1\n\n'); //page no. 766 // Solution Fig. E25.1 // Given // C(s) + O2(g) --> CO2(g) (A) // CO(g) + (1/2)(O2)(g) --> CO2 (g) (B) Qa = -393.51 ;// Heat of reaction of reaction (a) - [kJ/g mol C] Qb = -282.99 ;// Heat of reaction of reaction (b) - [kJ/g mol CO] del_Ha = Qa ;// Change in enthalpy of reaction A - [kJ/g mol C] del_Hb = Qb ;// Change in enthalpy of reaction B - [kJ/g mol CO] // According to Hess's Law , subtract reaction (B) from reaction (A) , subtract corresponding del_H's to get enthalpy of formation of reaction (C)- C(s) + (1/2)*O2 --> CO(g) , therefore del_Hfc = del_Ha - del_Hb ;// Standard heat of formation of CO - [kJ/g mol C] printf('Standard heat of formation of CO is %.2f kJ/g mol C.',del_Hfc) ;
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// traverses the SLP gate graph constructed in dag.sce // outputs vectorized form of the operations. // 1- traverse graph and build all leaf nodes / without any incoming edges // insert these nodes in Q+ and Q- stacks exec tsort_ini.sce; // exec tsort_queue.sce;
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@relation abalone @attribute Sex{M,F,I} @attribute Length real[0.075,0.815] @attribute Diameter real[0.055,0.65] @attribute Height real[0.0,1.13] @attribute Whole_weight real[0.002,2.8255] @attribute Shucked_weight real[0.001,1.488] @attribute Viscera_weight real[5.0E-4,0.76] @attribute Shell_weight real[0.0015,1.005] @attribute Rings{15,7,9,10,8,20,16,19,14,11,12,18,13,5,4,6,21,17,22,1,3,26,23,29,2,27,25,24} @inputs Sex,Length,Diameter,Height,Whole_weight,Shucked_weight,Viscera_weight,Shell_weight @outputs Rings @data 10 8 7 7 19 10 16 10 4 5 10 11 14 12 10 9 15 10 7 8 7 7 7 6 10 13 10 11 10 12 15 11 7 8 8 10 5 4 13 13 10 16 9 8 18 19 8 7 16 13 15 12 14 13 16 11 16 10 10 10 8 12 19 16 13 8 14 8 9 12 13 20 16 16 11 9 9 7 6 5 5 6 5 4 17 11 13 10 11 11 15 20 12 10 16 8 3 5 13 8 17 15 13 10 13 9 11 9 20 11 14 8 14 10 9 7 12 10 12 8 9 7 7 7 9 7 11 8 6 7 13 19 22 17 11 9 11 13 15 17 14 19 10 8 9 15 13 12 9 6 9 8 15 12 8 12 9 9 9 17 11 11 10 9 17 15 9 11 7 7 8 7 9 9 8 12 8 14 7 6 7 9 8 11 11 8 11 7 9 11 10 10 6 9 8 11 4 5 7 4 6 7 7 7 6 15 7 9 7 8 8 8 9 9 8 7 8 9 9 8 9 9 10 9 12 20 9 11 12 9 6 7 6 7 5 7 7 7 9 7 8 7 8 7 8 8 8 7 8 8 7 7 9 8 10 14 10 10 10 9 11 9 12 10 10 10 11 9 9 9 11 10 10 9 10 9 13 11 8 8 6 8 9 8 9 8 8 8 9 10 9 10 10 9 8 10 10 12 12 9 11 11 13 12 6 6 7 7 7 7 9 10 8 15 7 8 9 9 9 9 10 10 9 11 9 9 8 11 10 12 9 9 8 9 10 10 10 11 11 11 11 15 11 10 9 10 11 9 14 9 12 10 11 9 10 11 11 11 11 11 12 11 12 11 6 7 10 9 11 14 9 10 10 11 11 10 7 10 11 11 9 11 12 10 12 9 6 5 7 6 7 6 10 8 9 10 9 8 9 9 8 10 7 14 12 11 10 13 10 6 13 9 7 7 10 11 7 10 6 7 8 13 12 9 10 12 10 7 5 7 27 13 7 11 11 11 14 10 14 15 11 9 15 16 9 8 17 11 20 13 13 12 8 9 11 8 12 7 11 8 10 7 17 9 12 10 18 8 6 6 14 19 23 13 14 12 9 9 13 13 11 11 6 7 7 8 9 8 10 8 6 8 8 8 8 10 6 7 7 11 9 10 9 9 13 13 10 11 9 8 11 11 9 8 11 9 13 10 8 7 7 10 8 10 10 9 9 10 10 9 9 9 10 10 11 10 5 5 5 6 9 8 9 9 10 8 9 9 8 10 11 12 7 8 9 9 8 9 8 8 8 7 10 10 9 12 13 10 11 11 12 10 13 11 9 12 12 10 8 15 7 8 8 11 11 10 7 7 8 6 9 7 8 8 10 11 10 9 11 15 9 11 10 6 11 9 8 11 5 5 5 9 10 9 11 10 10 12 21 11 13 14 18 17 8 8 19 13 11 8 14 7 12 7 11 17 15 10 12 11 17 11 10 6 12 8 8 7 12 12 13 12 11 8 12 8 16 13 18 9 9 7 4 4 7 9 7 6 10 12 10 12 9 10 4 4 4 6 6 7 8 8 9 8 9 9 9 9 9 10 10 9 8 9 9 9 12 9 5 6 8 8 8 6 7 10 6 6 9 11 8 9 10 9 10 8 10 10 11 9 11 9 10 13 9 8 10 11 6 7 8 8 9 9 10 10 7 6 6 13 8 6 8 8 9 10 10 10 10 9 11 11 6 7 14 10 9 9 15 15 15 11 7 6 12 14 13 10 12 15 5 7 11 11 10 13 6 6 8 11 8 10 6 16 6 6 8 9 11 10 8 8 7 7 11 10 10 9 9 10 10 9 8 8 6 6 7 7 7 8 8 10 9 11 9 9 11 13 4 5 10 14 11 10 10 17 11 10 6 6 8 10 8 6
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// Exa 6.12 clc; clear; close; // Given data V_DD= 20;// in V I_DSS= 9;// in mA V_BB= -10;// in V R_S= 1.5;// in kΩ R_D= 1.8;// in kΩ V_P= -3;// in V V_G=0; // V_S= I_D*R_S+V_BB; // V_GS= V_G-V_S or // V_GS= V_G-(I_D*R_S+V_BB) // I_D= I_DSS*(1-V_GS/V_P)^2 or // I_D^2*R_S^2 + I_D*[2*R_S*V_BB+2*V_P*R_S-V_P^2/I_DSS]+[V_P^2+V_BB^2+2*V_BB*V_P] root= [R_S^2 2*R_S*V_BB+2*V_P*R_S-V_P^2/I_DSS V_P^2+V_BB^2+2*V_BB*V_P] I_D= roots(root);// in mA I_D= I_D(2);// discarding maximum value as it will be less than I_DSS I_DQ= I_D;// in mA disp(I_DQ,"The value of I_DQ in mA is : ") V_GS= V_G-(I_D*R_S+V_BB);// in V V_GSQ= V_GS;// in V disp(V_GSQ,"The value of V_GSQ in volts is : ") V_DS= V_DD-I_D*(R_D+R_S)-V_BB;// in V disp(V_DS,"The value of V_DS in volts is : ") V_S= I_D*R_S+V_BB;// in V disp(V_S,"The value of V_S in volts is : "); V_D= V_S+V_DS;// in V disp(V_D,"The value of V_D in volts is : ")
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Chapter74.sce
// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Introduction to heat transfer by S.K.Som, Chapter 7, Example 4") //Castor oil at temprature,Tinf=36°C flows over a heated plate of length,L=6m and breadth,B=1m at velocity,Uinf=0.06m/s Tinf=36; L=6; B=1; Uinf=0.06; //For a surface temprature at Tw=96°C Tw=96; //The properties at film temprature 66°C conductivity(k=0.21W/(m*K)),kinematic viscosity(nu=6*10^-5m^2/s),Thermal diffusivity(alpha=7.22*10^-8 m^2/s) nu=6*10^-5; k=0.21; alpha=7.22*10^-8; //ReL is reynolds number disp("(a)Reynolds number is") ReL=(Uinf*L)/nu //Therefore the boundary layer is laminar over the entire plate. //delta is the boundary layer thickness disp("The boundary layer thickness in m is") delta=(5*L)/(ReL)^0.5 //Pr is prandtl number. disp("Prandtl no. is") Pr=nu/alpha //deltaT is thermal boundary layer thickness disp("The thermal boundary layer thickness in m is") deltaT=delta/(Pr^(1/3))//NOTE:Answer in the book is incorrect(calculation mistake) //NuL is the nusselt number disp("(b)Since the prandtl number is high So Nusselt no. is") NuL=0.339*(ReL)^0.5*Pr^(1/3) //Heat flux is given by hL=(k/L)*NuL disp("Heat flux in W/(m^2*K) is") hL=(k/L)*NuL //hbarL is the average heat flux over length L disp("hbarL in W/(m^2*K) is") hbarL=2*hL //The rate of heat transfer is Q=h*A*(Tinf-Tw) //Area(A)=L*B A=L*B; disp("(c)The rate of heat transfer in W is") Q=hbarL*A*(Tw-Tinf)
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lab1.sce
not_pas = 0; l_1 = []; l_2 = []; l_3 = []; max_l_1 = 0; max_l_2 = 0; max_l_3 = 0; min_l_1 = 0; min_l_2 = 0; min_l_3 = 0; max_flag = 0; min_flag = 0; mod_flag = 0; mod_l_1 = []; mod_l_2 = []; mod_l_3 = []; n = 20; min_xopt = []; max_xopt = []; for lambd_1 = 0:1:n for lambd_2 = 0:1:n for lambd_3 = 0:1:n c = [38; -60; -1; -4; -8]; A = [lambd_1 4 2 0 -12 0.4 3 -4.2 2 -lambd_3]; Aeq = [0 lambd_2 19 -7 10 2.1 13 -20 6 0]; b = [86; 34]; beq = [130; 18]; lb = [0; 0; 0; 0; 0]; [xopt,fopt, exitflag, iter, yopt] = karmarkar(Aeq, beq, c, [], [], [], [],[], A, b, lb); if (lambd_1 == 0) if (lambd_2 == 0) if (lambd_3 == 0) max_flag = fopt; max_l_1 = lambd_1; max_l_2 = lambd_2; max_l_3 = lambd_3; max_xopt = xopt; min_flag = fopt; min_l_1 = lambd_1; min_l_2 = lambd_2; min_l_3 = lambd_3; min_xopt = xopt; end end end if exitflag <> 1 not_pas = not_pas + 1; l_1(not_pas) = lambd_1; l_2(not_pas) = lambd_2; l_3(not_pas) = lambd_3; end if exitflag == 1 if max_flag < fopt then max_flag = fopt; max_l_1 = lambd_1; max_l_2 = lambd_2; max_l_3 = lambd_3; max_xopt = xopt; end if min_flag > fopt then min_flag = fopt; min_l_1 = lambd_1; min_l_2 = lambd_2; min_l_3 = lambd_3; min_xopt = xopt; end end if pmodulo(fopt, 1) == 0 then mod_flag = mod_flag +1; mod_l_1(mod_flag) = lambd_1; mod_l_2(mod_flag) = lambd_2; mod_l_3(mod_flag) = lambd_3; end end end end printf('Набор параметров, при которых функция не имеет решения:\n'); if not_pas > 0 then for i = 1:1:not_pas printf(' ----------------------------------------\n'); printf(' %f\t', l_1(i)); printf('%f\t', l_2(i)); printf('%f\t', l_3(i)); printf('\n'); end printf(' ----------------------------------------\n'); else printf('not search.\n'); end printf('\nПри минимальном значении функции %f ', min_flag); printf('значения параметров:\n'); printf('lambda_1 = %f, ', min_l_1); printf('lambda_2 = %f, ', min_l_2); printf('lambda_3 = %f.\n', min_l_3); for i = 1:1:5 printf('Значения X_%f = %f.\n', i, min_xopt(i)); end printf('\nПри максимальном значении функции %f ', max_flag); printf('значения параметров:\n'); printf('lambda_1 = %f, ', max_l_1); printf('lambda_2 = %f, ', max_l_2); printf('lambda_3 = %f.\n', max_l_3); for i = 1:1:5 printf('Значения X_%f = %f.\n', i, max_xopt(i)); end if mod_flag > 0 then if mod_flag == 1 then printf('lambda_1 = %f,\n', mod_l_1(1)); printf('lambda_1 = %f,\n', mod_l_2(1)); printf('lambda_1 = %f.\n', mod_l_3(1)); printf('\n'); else printf('\nПараметры, при которых функция возвращает целочисленные значения: '); printf('\n'); for i = 1:1:mod_flag printf(' -------------------------------------------------------\n'); printf('\t%f\t', mod_l_1(i)); printf('%f\t', mod_l_2(i)); printf('%f\t', mod_l_3(i)); printf('\n'); end printf(' -------------------------------------------------------\n'); end else printf('\nЦелочисленных решений нет'); end