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node sort too; echo $? sort: No such file or directory 2
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load RegisterFile.hdl, output-file RegisterFile.out, compare-to RegisterFile.cmp, output-list time%S1.4.1 rr1%D1.2.1 rr2%D1.2.1 wr%D1.2.1 wd%D1.5.1 load%B2.1.2 rd1%D1.5.1 rd2%D1.5.1; set rr1 0, set rr2 1, set wr 0, set wd 10, set load 1, tick, output; tock, output; set rr1 0, set rr2 1, set wr 1, set wd 11, set ...
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welcome to my reflections R1 - First Week of PROGCON R2 - My First Flowcharts
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disp('Matrix A=') a=[sqrt(3) -1;1 sqrt(3)] disp(a) disp('Eigenvalues of A are:') eig=spec(a) disp(eig) disp('The scale factor associated with the transformation x to Ax is:') disp(abs(eig(1,1)))
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// Scilab code Ex5.4: Pg 149 (2008) clc; clear; v = 5; // Velocity, m^2 theta =(%pi/3); // Angle, degrees phi = 1.6e-03; // Flux, Wb l = 0.1; // Length of pole face, m d = 0.4; // ...
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//************************************************************************ // IPS - CALCUL D'UN PI // kerhoas@enib.fr //*********************************************************************** i=0; // index Figures //----------------------------------------------------------------------- // Définition du Gain ...
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//Example NO.12.4 //Page No.357 //To find critical current density. clc;clear; D=1*10^(-3);//Diameter of the wire -[m]. Tc = 7.18;//Critical temperature -[K]. Ho = 6.5*10^4;//Critical field -[A/m]. T = 4.2;//Temperature -[K]. R = 0.5*10^-3;//Radius. I = 134.33;//Current. Hc = Ho*(1-((T^(2))/(Tc^(2)))); pri...
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clc //to calculate number of electrons I=2*10^-3 //current in mA e=1.6*10^-19 n=I/e disp("number of electrons striking the target per second is n="+string(n)+"unitless") //to calculate speed m=9.1*10^-31 //mass of electron in kg V=12.4*10^3 //potential difference in V v=sqrt(2*V*e/m) disp("the speed with wh...
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//Chapter-6,Example6_1_3,pg 6-7 y=1.5 //deflection in the beam d=0.42 //distance between two plates D=28 //distance of screen from center of plates l=1.8 //length of plates ...
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//chapter 1 Ex 21 clc; clear; close; //let value to be found is x numerator=789*789*789+211*211*211; denominator=789*789-789*211+211*211; x=(numerator/denominator); mprintf("x=%.0f",x);
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clear; clc; close; Vdd = 20; Vdq = 12; Idq = 2.5*10^(-3); Vgsq = -1; Rd = (Vdd-Vdq)/Idq; Rs = -Vgsq/Idq; disp(Rd,'Rd(Ohms) = '); disp(Rs,'Rs(Ohms) = '); disp(3.3*10^(3),'Closest commercial value of Rd(Ohms) = '); disp(0.39*10^(3),'Closest commercial value of Rs(Ohms) = ');
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//example 19.1 //design an expansion transition for canal by Mitra's method clc;funcprot(0) //given Lf=16; //length of flume Bf=9; //width of throat Bo=15; //width of canal //width at any distance x from flumed section is given by //Bx=Bo*Bf*Lf/(Lf*Bo-(Bo-Bf)x) //on solvin...
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T=1; // a year S_0=100; r=0.05; // by year sigma=0.3; // by square root of year, sigma^2 * T has no dimension K=100; // Question 1 N=100000; W_T=sqrt(T)*rand(1,N,"gauss"); S_T=S_0*exp((r-sigma^2/2)*T + sigma*W_T); histplot(100,W_T); histplot(100,S_T);
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// Scilab file. // Funtion // Dilawar Singh, Sepp 19, 2010. // // This script will compute the matrices required to solve the electric circuit // as described in a text file. To generate the matrix we will use data // structure returned by a function defined in parseCircuitFile.sce file. // // matM : coefficient matr...
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function [d,p]=graph_diameter(g) // Copyright INRIA [lhs,rhs]=argn(0) if rhs<>1 then error(39), end // compute lp, la and ls ma=prod(size(g('tail'))) n=g('node_number') head=g('head'); if g('directed')==1 then [lp,la,ls]=m6ta2lpd(g('tail'),head,n+1,n) // compute fe, che, fn, chn [fe,che,fn,chn]=chain_struct(lp,la...
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twb1 = 15.2; twb2 = 26.7; tw3 = 30; h1 = 43; h2 = 83.5; hw = 84; mw = 1.15; W1 = 0.0088; W2 = 0.0213; hw3 = 125.8; hm = 84; G = 1; hw34 = (G/mw)*((h2-h1)-(W2-W1)*hw); // hw3-hw4 tw4 = tw3-(hw34/4.19); A = tw4-twb1; R = tw3-tw4; x = G*(W2-W1); disp("degree",tw4,"Temperature of water leaving the tower is") di...
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function [u,x,y,t] = heat_2d_ADI(a,D,T,ixy0,bxyt,Mx,My,N) // solve u_t = c(u_xx +u_yy) for D(1)<=x<=D(2), D(3)<=y<=D(4), 0<=t<=T // Initial Condition: u(x,y,0) = ixy0(x,y) // Boundary Condition: u(x,y,t) = bxyt(x,y,t) for (x,y)cB // Mx/My = # of subintervals along x/y-axis // N = # of subintervals along t-axis d...
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//Example5.22 // To determine input output miller capacitances clc; clear; close; A = 100 ; //gain Cm = 0.1 ; // uF // compensated capacitor // the input output miller capacitance are defined as Cin = Cm*(A+1); disp('The input miller capacitance Cin value is = '+string(Cin)+'uF '); Cout = (Cm*((A+1)/A)); ...
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const MAX = 12; type t = int; type t1 = array 12 of t; void theProcedure( ) { var x, y, z : t1; var i : int; int testProc() { return i * i; } i = 0; while (i < MAX) { x[i] = ::testProc(); } } main() { ::theProcedure(); }
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clc clear //Input data v=(5*10^6)//Velocity of the electron in m/s E=2000//Intensity of electric field in N/C d=0.06//Distance in m e=(1.6*10^-19)//Charge of the electron in C m=(9.1*10^-31)//Mass of the electron in kg //Calculations y=((-e*E*d^2)/(2*m*v^2))*100//Vertical displacement of the electron when ...
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//Compute process average and std. deviation //page no 112 clear clc; USL = 51; LSL = 45; UNTL=USL; LNTL=LSL; sd=1; X2=48; mprintf("\The process average = %.2f \n",X2); A2 = 0.73; d2 = 2.059; D3 = 0.0; D4 = 2.28; R2= sd*d2; //Control limits for R-chart UCL = D4*R2; mprintf("\UCL = %.2f \n",UCL); LC...
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//clc() funcprot(0) ft = 0.3048;//m lb = 0.4536;//kg P = ft*lb; disp("N",P,"1 poundal is 1 ft*lb/s^2 = ")
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// Example 5_3 clc;funcprot(0); // Given data Q_B=950*10^5;// kJ/h W_p=23.0;// kW Q_c=-600*10^5;// kJ/h // Calculation Q_net=(Q_B+Q_c);// kJ/h W_T_net=Q_net/3600;// kJ/h W_T_net=W_T_net/1000;// MW W_T_total=(W_T_net*10^3)+W_p;// kW printf("\nThe net power of the turbine,(W_T)_total=%4.0f kW(round off error...
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// Example 5.8;resolution clc; clear; format('v',6) // given : fsr=200;//full scale reading in volts d=100;//number of divisions sc=1/10;//scale sd1=fsr/d;//one sccale divisions R=sc*sd1;//resolution disp(R,"resolution is, (V)=")
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function F = laplace(s, T1, T2) //pulse: // f = u(t - T1) - u(t - T2) F = integrate('exp(-s*t)','t',T1,T2); //laplace transform of the pulse endfunction
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//Initilization of variables Wa=161 //lb Wb=193.2 //lb Wc=300 //lb ka=3 //ft kb=2.5 //ft theta1=30 //degrees theta2=45 //degrees g=32.2 //ft/s^2 //Calculations //Moment of inertia Calculations Ia=(Wa/g)*ka^2 //lb-s^2-ft Ib=(Wb/g)*kb^2 //lb-s^2-ft //Using equations of motion for A and B and C //Solving by ...
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clear clc CAo=2; //Since S is the desired Product //Q(S/A)=2CA/(1+CA)^2 //Part a //Csf=(CAo-CA)*2*CA/(1+CA)^2 //on differentiating this to get max Csf,we get max value at CA=0.5; Csf=(CAo-CA)*2*CA/(1+CA)^2; printf("\n Part a") printf("\n For Mixed Flow Reactor") printf("\n Maximum expected Cs is %f",Csf) /...
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//<f1>=%rmp(f1,n2) // %rmp(f1,n2) calcule le produit de la matrice de fractions ration- //nelles f1 par la matrice de polynomes n2 //Cette macro correspond a l'operation f1*n2 //! [n1,d1]=f1(2:3), [l1,m1]=size(n1);[l2,m2]=size(n2), // if mini([l1*m1,l2*m2])=1 then, num=n1*n2, den=d1*ones(l2,m2), else, if m1<>l...
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// Example 7_7 clc;funcprot(0); // Given data mdot=3.00;// kg/min x_in=0;// The quality of steam at inlet x_out=75;// The quality of steam at outlet T_in=100;// °C h_fg=2257;// kJ/kg // Solution Qdot=mdot*(x_out/100)*h_fg;// kJ/min S_T_Q=Qdot/(T_in+273.15);// kJ/min.K printf('\nThe heat transport rate of e...
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//Ex:4.4 clc; clear; close; d=6;// core diameter in m y=1.55;// wavelength in m a=0.5;// attenuation in dB/km v=0.4; Pb=4.4*10^-3*d^2*y^2*a*v;// threshold power for SBS Pr=5.9*10^-2*d^2*y*a;// threshold power for SRS printf("The threshold power for SBS =%d mw", Pb*10^3); printf("\n The threshold power for SR...
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u=[-1;2] disp('u=') disp(u) v=[-3;-1] disp('v=') disp(v) s=u-2*v disp('u-2v=') disp(s)
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clc //initialisation of variables h=4.8//ft m=13.4//ft k=10^-1//cm/sec k1=3.28*10^-3//fps n=7//ft n1=11//ft q=1.0*10^-2 //CALCULATIONS Q=k1*h*n/n1//cfs/ft Q1=2*q*10^2//cfs //RESULTS printf('A satisfactory orthogonal system the flow of into the collector =% f cfs',Q1)
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clc; clear all; disp("Total power required") L=50;//m D=5;//m U=8;//m/s ta=20;// degree C rho=1030;//kg/m^3 v=10^(-6);//m^2/s ReL=U*L/v; Rex=5*10^5; x=Rex*v/U; Cf=0.455/(log10(ReL))^2.58; A=%pi*D*L;//m^2 Fd=Cf*0.5*rho*A*U^2; P=Fd*U/1000;//kW disp("kW",P,"Power required =")
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čagar’ čagarilesai N;TERM;SG saged sagedoihe ADJ;IN+ALL;PL lainduz lainduselesai N;TERM;SG rida ridoilepäi N;PRP;PL kül’menzoitta kül’menzoitta V;NFIN allergine allergižen ADJ;ACC;SG avtozavod avtozavodoin N;FRML;PL konsonant konsonantoihepäi N;PRP;PL pakssil’mäine pakssil’mäiženno ADJ;APPRX;SG armahtuzkäsk armahtuzkäs...
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C=0.01;//concentration of Ca(NO3)2 solution// Ksp=3.2*10^-11;//Solubility product of Fe(OH)3// printf('CaF2 = Ca2+ + 2F-\n(Ca2+)(F-)^2 = 4*S^3 = 3.2*10^-11.'); printf('\nLet S1 be the solubility in 0.01M Ca(NO3)2\nCa(NO3)2 can be assumed to dissociate completely so that (Ca2+) from Ca(NO3)2 is 0.01M'); S=(Ksp/4)^0....
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clear; clc; //Example - 1.3 //Page number - 13 printf("Example - 1.3 and Page number - 13\n\n"); // Given P1 = 3;// [bar] - initial pressure V1 = 0.5;// [m^(3)] - initial volume V2 = 1.0;// [m^(3)] - final volume //(a) n = 1.5; //Let P*V^(n)=C //Given relation //W (work done per mole)= (integrate('...
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clc //initialisation of variables V=10 //ft^3 T=600//F v=200 //lbf/in^2 Sv=50 //lbf/in^2 p=200 //lbf/in^2 v1=8.515 //ft^3/lbm m1=V/v1//lbm hi=1322.1 //Btu/lbm u1=1095.3 //Btu/lbm m2=3.05 //lbm u2=V/m2 //ft^3/lbm he=1234.8 //Btu/lbm //CALCULATIONS m3=m1*(hi-u1)/(hi-he) //lbm M=m2-m1 //lbm //RESULTS p...
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//a's to o's x=ex9f('gaad'); if x<>'good' then pause,end
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errcatch(-1,"stop");mode(2);//Caption:Calculate the value of back emf //Exam:2.18 ; ; V=230;//applied voltage (in V) R_a=0.1;//armature resistance(in Ohm) I_a=60;//armature current (in Amp) E_b=V-I_a*R_a;//back emf(in Volts) disp(E_b,'back emf produced by machine in (in V)='); exit();
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clc; clear; //clears the console and all previously stored variables function [V0, epsilon] = BS_EuOption_MC_AV (S0, r, sigma, T, K, M, g) // Computing the 95% confidence interval for the european option price // via the MC approach with antithetic variables: V_hat(:) = g(S0*exp((r-sigma^2/2)*T+sigma...
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// Updated(24-7-07) // 7.5 w = linspace(0.001,%pi,1000); G = trfu([1 -0.8],[1 -0.24],-1); bode(G,w)
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//Chapter 2, Problem 8, Figure 2.8 clc; V1=20; //Voltage of resistor A I1=20*10^-3; //Current of resistor A V2=16; //Voltage of resistor B I2=5*10^-3; //Current of resistor B R1=V1/I1; //Calculating resistance of resistor A...
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 18.24w //calculation of new focal length of a lens on immersing in water //given data f=12; //focal length(in cm) of the lens mu1=1; //refractive index of air mu2=1.5; //refractive index of glass mu3=1.33; //refrac...
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// To determine thee Ac system voltage when the dc system is disconnected or shutdown clear clc; X=.625; P=1; Q=.6; V=1; Eth=V+(Q*X/V)+%i*(P*X/V); Phase_Eth=atand(imag(Eth)/real(Eth)); mprintf("Eth=%.2f at an angle %.0f degrees",abs(Eth),Phase_Eth);
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function [d,p]=ecart_pente_frenet(A,B,x) //Le repère de Frenet a A pour origine et B définit l'axe x //x est une position (ou bien une pose 2D) //d= ecart latéral signé //p= pente signée du segment [AB] //PhB nov 2015 M = x(1:2); xa=A(1);ya=A(2); xb=B(1);yb=B(2); alpha=atan(...
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// Example 8.12 clear all; clc; q_max = 539000; // Maximum heat flux Btu/hr-ft^2 F = 2.8; // Hot channel factor P = 3000; // Reactor thermal power in MW // Expressing in Btu/hr // According to Table 1.9, 1 k...
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close; clear; clc; disp("the system can be represented as Yc(s)=Xc(s)/(1+RCs)"); disp("therefore Hc(s)=1/(1+RCs) hence hc(t)=e^-t*u(t) by frequency shifting property") disp("therefore hd[n]=hc(t)=e^(-n*Ts)*u[n]"); disp("taking z-transform Hd(z)=1/(1-e^(-n*Ts)*z^-1)"); Ts=1; w=0:0.1:15; Hcw=ones(1,length(w)...
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.265035D+00 ...
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clc //initialisation of variables L= 16 //in H= 9 //in h= 18 //in g= 32.2 //ft/sec^2 w= 2 //ft Cd= 0.63 W= 62.4 //lbs/ft^3 //CALCULATIONS Q= 2*Cd*sqrt(2*g)*(L/12)*(H/12)^1.5/3 v= Q/(w*(h/12)) H1= v^2/(2*g) Q1= 2*Cd*sqrt(2*g)*(L/12)*(((H/12)+H1)^1.5-H1^1.5)*W*6/3 //RESULTS printf ('Discharge = %.f gpm ',...
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clear; clc; printf("\nEx2.17\n"); //page no.-65 //given p=2.2*10^-24;.................//momentum in kg*m/s m=9.1*10^-31;................//mass of electron in kg e=1.6*10^-19;................//charge _h=1.054*10^-34;...............//planck constant del_t=10^-8;..................//change in time in sec h=6.62*1...
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//Given that g = 9.8 //in m/s^2 Radius = 2.7 //in meter //Sample Problem 6-7 printf("**Sample Problem 6-7**\n") //The velocity at highest point is equal to sqrt(gR) velocity_topmost = sqrt(g * Radius) printf("The velocity of ball at the topmost point would be %f m/s", velocity_topmost)
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clear; clc; funcprot(0); //Example - 15.7 //Page number - 522 printf("Example - 15.7 and Page number - 522\n\n"); //Given P = 1;//[bar] - Pressure P = P*10^(2);//[kPa] // log(P_1_sat) = 13.8594 - 2773.78/(t + 220.07) // log(P_2_sat) = 14.0098 - 3103.01/(t + 219.79) // The bubble point equation is //...
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// calculating the pressure for a dial reading of 100 clc; disp('calculating the pressure for a dial reading of 100') P=((27.58-6.895)/150)*100+6.895; disp(P,'pressure for a dial reading of 100(kN/m2)=');
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//code for transpose ,addition , multiplication //matrix input- A=input('MATRIX A =') B=input('MATRIX B =') //matrix row and column input row_a=input('NO.OF row A =') column_a=input('NO OF column A =') row_b=input('NO OF row B =') column_b=input('NO OF COLUMN B=') ROW_A=row_a COLUMN_A=column_a ROW_B=row_b COLUMN_B=colu...
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//Page Number: 296 //Example 5.9 clc; //Given f=10D+9; //hz v0=15D+3; //V i0=2.5D-3; //A d=1; //cm d1=d/100; //m vrms=10; //V bet=1; p=1D-8; //C/m^3 rf=0.6; e=1.6D-19; m=9.1D-31; ee=8.854D-12; //(i) DC electron beam phase cobstant vv0=(0.593D+6*sqrt(v0)); w=2*%pi*f; bete=w/vv0; //rad/m disp('rad/m...
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//Example 20.3// a=1.21;//dollar/kg b=0.70;// fabrication yield rate phenolic=a/b mprintf("phenolic =$ %f /kg ",phenolic) a1=4.30;//dollar/kg b1=0.95;// fabrication yield rate polyester=a1/b1 mprintf("\npolyester $%f /kg",polyester) //Then the net materials cost per part is c=2.9;//g/part d=1;//kg //kilogram...
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//EX:5.8 clc; clear; close; //Given: R=90*10^3;//in Kohms C=100*10^-12;//in pF g1=2800*10^-6; g2=4300*10^-6; lv=g1*R*C; hv=g2*R*C; printf("\n lower value of capacitance = %f nf",lv*10^9); printf("\n higher value of capacitance = %f nF",hv*10^9);
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Ex10_5.sce
//chapter10 //example10.5 //page192 L=1d-3 // H C=100d-12 // F fr=1/(2*%pi*(L*C)^0.5) printf("resonant frequency = %.3f Hz or %.3f kHz",fr,fr/1000)
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//Ex 1.15 clc;clear;close; format('v',5); Iout=8;//micro A VBE=0.7;//V VCC=20;//V Beta=100;//unitless IREF=Iout*(1+2/Beta/(Beta+1));//micro A disp(IREF,"Reference current is(micro A) : "); R=(VCC-2*VBE)/(IREF);//Mohm disp(R,"Resistance is(Mohm) : ");
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C2P7.sce
clear clc //to find acceleration of partical //to find velocity of partical when it leaves the tube // GIVEN:: //length of the tube x = 2.0//in m //velocity of partical when it enters in the tube i.e.at t=0s v0x = 9.5*10^5//in m/s //time when the partical emerges out of the tube t = 8.0*10^-7//in m/s ...
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Ex14_1.sce
//EX14_1 Pg-14.25 clc clear printf(" (((A+B)C)'')D") printf("\n Given inputs are A,B,C and D") printf("\n\n (A+B)C then we take the complement ") printf("\n ((A+B)C)''") printf("\n Then we AND together with D") printf("\n Therefore Y = (((A+B)C)'')D")
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// chapter 4 // example 4.1 // Calculate the value of R and C // page-120-121 clear; clc; // given n_s=18; // number of thyristors connected is series E_D=500; // in V (maximum permissible blocking voltage) E_s=7500; // in V (string voltage) dI_b=1; // in mA (range of blocking current) dQ=30; // in uC (maximum permissi...
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1_7.sce
clc //initialisation of variables clear wdc= 3*sqrt(3) //ft wdo= sqrt(3) ac= 30 //degrees ao= 60 //degrees hob= 3 //ft haf= 2.6 //ft hfc= 3 //ft w= 62.4 //lb/ft^3 V= 5.63 //ft^3 h= 4.3 //ft y= 3.6 //ft //CALCULATIONS W1= wdc*hfc*w/2 Hbc= w*hob*(hob/2) W2= V*w W3= w*haf*h Vt= W1+W2 Vht= Hbc+W3 R...
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two_populations_ends_corr.sce
clear; lines(0); np=100; v=0; chi=-10; //sig=0.1; q=3; //s0 = '~/varvara/Documents/IMC/n='+string(np)+'/10.2015/add/q='+string(q)+'/cs=10-1/v='+string(v)+'/'; s0 = '~/varvara/Documents/IMC/n=' + string(np) + '/chi' + string(chi)+ '/cs10-4/sig0.01/q' + string(q)+ '/v' + string(v) + '/'; j=0; //for q=5:1:9 for sig=0.01...
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exa1_12.sce
clc; //Example 1.12 //Page no 25 //Solution V1=8; V2=0.2; V3=0.1; //(a) h1=2*1; disp('kHz',h1,"2nd harmonic = "); h2=3*1; disp('kHz',h2,"3rd harmonic = "); h3=12*1; disp('kHz',h3,"12th harmonic = "); //(b) disp("(b) ") p1=(V2/V1)*100; disp('%',p1,"%2nd order = "); p2=(V3/V1)*100; disp('%',p2,"%3nd orde...
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//A Textbook of Chemical Engineering Thermodynamics //Chapter 3 //P-V-T Behaviour and Heat Effects //Example 7 clear; clc; //To find Approx Value function[A]=approx(V,n) A=round(V*10^n)/10^n;//V-Value n-To what place funcprot(0) endfunction //Given: T = 300; //temperature(K) P = 100; //pre...
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example1_4.sce
// i be the current in amperes i=2A // it flows for time t=10s // q be the total charge given by q=i*t i=2; t=10; q=i*t; // total charge is 20 coulombs // energy is 2.3KJ ( kilo joules) w=2.3*10^3; // voltage drop v in volts given by= v=w/q v=w/q; disp("v=") disp(v) units=...
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0000*AA*5.0*52.0*dummy 0000*BB*6.0*52.0*dummy
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ex9_8.sce
clc; clear all; m = 9.1e-31; // Mass of electron in kg h = 6.62e-34; // Planck's constant in Js c = 3e8; // Velocity of light in vaccum lambda = 0.5e-10; // Wavelength of light in meters theta = 90; delta = (h*(1-cosd(theta)))/(m*c); Nlambda = lambda + delta; E = (h*c)*((1/lambda)-(1/Nlambda)) ; disp('J',E,'E...
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VP14_OneBack.sce
array <int> finalSeq[432] = {51,50,24,24,55,46,28,20,62,12,4,4,57,58,58,6,17,45,34,37,22,71,28,61,27,27,36,37,32,13,53,42,20,70,70,16,21,31,33,33,56,8,72,53,55,2,2,12,26,57,50,30,71,64,54,61,5,46,72,21,18,46,40,40,14,14,71,71,68,68,27,40,47,56,56,7,11,59,24,33,1,13,66,31,67,72,53,10,31,72,11,16,13,42,42,19,1,41,66,17,5...
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14_15.sce
clear; clc; //Example - 14.15 //Page number - 485 printf("Example - 14.15 and Page number - 485\n\n") //Given, T = 25 + 273.15;//[K] - Temperature mol_CaCl2 = 0.001;//[mol/kg] - Molality of HCl A = 0.510;//[(kg/mol)^(1/2)] Z_positive = 2;//Stoichiometric coefficient of 'Ca' ion Z_negative = -1;//Stoichiom...
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Ex4_1.sce
//Ex4_1 clc Irs = 0.2*10^-6 Vf = 0.1 VT = 26*10^-3 eta = 1//for germanium I = Irs*(exp(Vf/eta/VT)-1) disp("Irs = "+string(Irs)+"A")//reverse saturation current disp("Vf = "+string(Vf)+"V")//applied voltage disp("VT = "+string(VT)+"V")//voltage at room temperature disp("eta = "+string(eta)) disp("I = Irs*(exp...
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cceps.sci
function y = cceps (x,correct) //Return the complex cepstrum of the vector x //Calling Sequence //cceps (x) //cceps(x, correct) //Description //This function return the complex cepstrum of the vector x. If the optional argument correct has the value 1, a correction method is applied. The default is not to do this. func...
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10_32.sce
clear clc S=10 xg=.1 xe=.08 X1= 1/((1/.1) + 1/(xe + ((xg+xe)/2))) FMVA1=S* (1/X1) mprintf("When reactors are used, fault level=%.2f MVA", FMVA1) X2= xg/3 FMVA2=S* (1/X2) mprintf("\nWhen reactors are not used, fault level=%.0f MVA",FMVA2)
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// Scilab Code Ex18.4: Average absorption coefficient of the surfaces of the hall: Page-362 (2010) V = 25*20*8; // Volume of the hall, metre cube S = 2*(25*20+25*8+20*8); // Total surface area of the hall, metre square T = 4; // Reverbration time of the hall, s alpha = 0.167*V/(T*S); // Sabine Formule...
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load PriorityEncoder83.hdl, output-file PriorityEncoder83.out, //compare-to PriorityEncoder83.cmp, output-list x0%B3.1.3 x1%B3.1.3 x2%B3.1.3 x3%B3.1.3 x4%B3.1.3 x5%B3.1.3 x6%B3.1.3 x7%B3.1.3 y2%B3.1.3 y1%B3.1.3 y0%B3.1.3; set x0 1,set x1 0,set x2 0,set x3 0,set x4 0,set x5 0,set x6 0,set x7 0,eval,output; set x0 1,set...
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// Exa 2.12 clc; clear; close; // Given data format('v',9) IB1= 10;// in mA IB2= 7.5;// in mA I_in_bias= (IB1+IB2)/2;// in mA disp(I_in_bias,"Input bias current in mA") I_in_offset= IB1-IB2 ;// in mA disp(I_in_offset,"Input offset current in mA") // Note: Units in Answer in the book is wrong
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clear; clc; // Stoichiometry // Chapter 2 // Basic Chemical Calculations // Example 2.15 // Page 25 printf("Example 2.15, Page 25 \n \n"); // solution //(CH2OH)3 M = 92 // molar mass of glycerin C = 600 //[mg/l] glycerin conc. TOC = (3*12/92)*600 //[mg/l] // by combustion reaction we see 3.5 O2 i...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; //clf; clc; // Constants g = 9.81; u0 = 0; v0 = 0; b = 2; h0 = 5030; damp=0.0; force=0.1; forcefreq=0.1; k=2.5; // Define the x domain ni = 51; xmax = 1.0; dx = xmax/(ni-1); x = 0:dx:xmax; // Define the y domain nj = 51; y...
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errcatch(-1,"stop");mode(2);// To determine the ratio of CT on HV side ; Il=400*6.6/33;// line current on star side of PT(amps) Ic=5/sqrt(3);// current in CT secondary mprintf(" the CT ratio on HT will be %d : %.3f",Il,Ic); exit();
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// Test # 6 : Valid input case #2 exec('./tf2ca.sci',-1); [d1,d2,b]=tf2ca([0.03 -0.5 -0.5 0.03],[1 2.4 -33 22]); disp(b); disp(d2); disp(d1); // //Scilab Output //b=1.7290007 + 0.4817393i //d2= 1. -0.2593701 + 0.9083877i //d1= 1. 0.7406299 - 0.9083877i -0.2593701 - 0.9083877i // //Matlab Output //d...
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@relation @attribute Mcg real[0.11,1.0] @attribute Gvh real[0.13,1.0] @attribute Alm real[0.21,1.0] @attribute Mit real[0.0,1.0] @attribute Erl real[0.5,1.0] @attribute Pox real[0.0,0.83] @attribute Vac real[0.0,0.73] @attribute Nuc real[0.0,1.0] @attribute Class{positive,negative} @inputs Mcg,Gvh,Alm,Mit,Erl,Pox,Vac,...
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// 08.10.24 // 08.10.25 // 08.10.26 // 09.12.31 (gsort) // 13.10.22 ( __ added to varibles ) // 13.12.02 debugged function PtL__=Meetpoints(PtA__,PtB__,Fd__,Uveq__,Np__,Eps__) Eps__0=10^(-4); Vec__=PtB__-PtA__; Out__=[]; PtL__=[]; Tmp__=Mixop(2,Fd__); K__=mtlb_findstr(Tmp__,'='); Xname__=part(Tmp__,1:K_...
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A = input("Insert matrix A: ") b = input("Insert vector solution b: ") U = A L = [] [rA cA] = size(A) for p = 1:rA piv = A(p, p) L(p, p) = 1 for i = p+1: rA prim = A(i, p) l = prim/piv L(i, p) = l U(i, :) = U(i, :) - U(p, :)*l end end d = inv(L)*b x = inv(U)*d disp(x)
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function M=%hm_e(varargin) // Copyright INRIA //extract an sub_hypermatrix [lhs,rhs]=argn(0) M=varargin(rhs) dims=M('dims') v=M('entries');v=v(:) if rhs-1>size(dims,'*') then error('Too many subscripts') end dims1=[] I=0 for k=rhs-1:-1:1 ik=varargin(k) if type(ik)==2 |type(ik)==129 then // size implicit subscri...
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// Scilab Code Ex3d.12: Page-209 (2008) clc; clear; lambda = 5890e-008; // Wavelength of light, cm n = 2; // Order of diffraction d_lambda = 6e-008; // Difference in wavelengths of D1 and D2 lines, cm w = 2.5; // Width of the grating, cm N = lambda/(n*d_lambda); // Number of lines on grating print...
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// 頻度 lambda の指数分布を生成し、その確率分布を求め、図示する。 // (lambda > 0) clear // 乱数の生成 function x = exprand(lambda) y = rand(); // [0,1)での一様乱数を選ぶ // ***未完*** x = log(1 - y) / (-lambda); endfunction // 以下、この関数を用いたテストを行う。 n = 10000; // 生成する乱数の個数 lambda = 1.0; // 乱数のパラメタ fmin = 0; fmax = 20; // 度数分布を求める x の範...
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//Stone dropped into well //let //h=depth of well //t1=time tataken by stone to strike water //t2=time taken by sound to travel h //t1+t2=4 //h=(g*t1^2)/2 //h=335*t2 //solving //t1^2+68.30*t1-273.19=0 t1=3.79 //sec h=(9.81*t1^2)/2 //m printf("h=%.2f m",h)
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//Example 2-51// //multiplication of binary numbers// //this program requires functions binary2decimal.sci and decimal2binary.sci// clc //clears the window// clear //clears all existing variables// function x=binary2decimal(bin) p=1 q=1 z=0 b=0 w=0 f=0 //initialising// d=modulo(bin,1) //separating the d...
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//Exa:1.4 clc; clear; close; ang_d=215;//given ang_r=ang_d*%pi/180; printf("%f degree angle is %f radians",ang_d,ang_r);
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//chapter-3,Example3_4,pg 487 //Fabc=M7*M6 //Fabc=M7*M6=(a+b+c)(a+b+c') //Fabc=a+ab+ac'+ab+b+bc'+ac+bc+cc' //Fabc=(a+b)+(a+b)c'+(a+b)c+ab+ab+cc' //Fabc=((a+b)+c)((a+b)+c') //Fabc=(a+b)(a+b)+(a+b)c'+(a+b)c printf("boolean function in simplified form\n") printf("a+b")
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//Chapter 18, Problem 7 clc; //initializing the variables: C = 0.1E-6; //capacitance in farads R = 4000; //resistance in ohms V = 200; //supply voltage Vc1 = 2; // in volts //calculation: taw = R*C I = V/R t = -1*taw*log(Vc1/V) printf("\n (a)Initi...
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//Problem 43.04: Two coils, X and Y, having self inductances of 80 mH and 60 mH respectively, are magnetically coupled. Coil X has 200 turns and coil Y has 100 turns. When a current of 4A flows in coil X the change of flux in coil Y is 5 mWb. Determine (a) the mutual inductance between the coils, and (b) the coefficien...
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// Example 1.1: Electron concentration clc, clear V=0.1; // Voltage in volts I=5e-3; // Current in ampere l_a=7e8; // Length to cross-sectional area ratio in metre inverse mu=0.05; // Electron mobility in metre square per volt second q=1.6e-19; // Charge on an electron in coulombs n=(l_a*I)/(V*q*mu); //Electron ...
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