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//Example 2.5.3 page 2.26 clc; clear; lamda = 850; sigma= 20; D_mat = 0.055/(3*10^5*lamda); sigma_m= sigma*1*D_mat; D_mat=D_mat*10^12; // in Ps... sigma_m=sigma_m*10^9; //in ns//// printf("The material Dispersion is %.2f Ps/nm-Km",D_mat); printf("\n\nThe Pulse spreading is %.4f ns/Km",sigma_m);
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clear; //clc(); // Example 8.14 // Page: 198 printf("Example-8.14 Page no.-198\n\n"); //***Data***// P = 100;//[psia] // Composition in liquid phase is x_a = 0.05;// Mole fraction of methane x_b = 0.40;// Mole fraction of butane x_c = 0.55;// mole fraction of pentane // We have to take the help ...
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//clear// clear; clc; //Example 15.4 //Given N = 28; xF = 0.5/12; // [ft] yF = 0.035/12; //[ft] km = 26; // [Btu/ft-h-F] AT = 2.830; //[ft^2/ft] Ab = 0.416; //[ft^2/ft] hi = 1500; //[Btu/ft^2-h-F] G = 5000; //[lb/h-ft^2] Tavg = 130; //[F] Tw = 250; //[F] mu = 0.046; //[lb/ft-h], from Appendix 8 Cp = ...
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# Depropanizer test (from old Hysim manual) units SI thermo = VirtualMaterials.Peng-Robinson thermo + propane isobutane n-butane isopentane n-pentane thermo + n-hexane n-heptane n-octane thermo + n-nonane n-decane thermo + water stab = Tower.Tower() stab.Stage_0 + 10 # twelve stages stab.LiquidPhases = 2 ...
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//variable initialization u=1.68*10^-27; //mass of hydrogen atom (kg) m1=16; //mass of oxygen atom in terms u m2=1; ...
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clc // Given that F = 680 // Net brake load in N N = 360 // d = 10// Bore in cm L = 15 // Stroke in cm T = 58 // Torque in Nm v = 300 // Speed in m/min n_m = 0.8 // Mechanical efficiency n_th = 0.4 // Indicated thermal efficiency c_v = 44 // Calorific value of gasoline in MJ/kg printf("\n Example 20.3\n") ...
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//Example 1.16 // order of dark band clc; clear; //given data : u=4/3;//referactive index of soap flim t=1.5D-6;//thickness of soap flim i=60;//incident angle in degree i=i*%pi/180;// incident angle in radian w=5D-7;// wavelength in m r=sin(i)/u;//sin of refracted angle R=asin(r);//refracted angle in radian ...
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// Example 9.4.4 page 9.14 clc; clear; output=-10; //laser output sensitivity=-25; //APD sensitivity L=2; //length in km sl=0.7; //loss correspond to one splice in dB fl=3.5; //fiber loss in dB/km connector_loss=1.6; saftey_margin=4; allowed_loss=output-sensitivity; splices_loss=L*sl; fi...
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function [sp]=%spasp(sp1,sp2) ij1=sp1(3);ij2=sp2(3);w1=sp1(2);w2=sp2(2); ij=[ij1;ij2];w=[w1,w2]; sp=sparse(w,ij);
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clc(); clear; //Given : m = 9.109*10^-31;// eletcron mass in kg e = 1.6*10^-19; // electron charge in C //T = (2*pi*m)/(B*e) , here B is not given T = (2*%pi*m)/e;// time in s printf("T = %.2f x 10^-11 / B ",T*10^11);
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SIEMENLUKU 123456 PELAAJIA 4 IHMINEN Spartacus TIETOKONE Batiatus TIETOKONE Glaber TIETOKONE Crassus
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errcatch(-1,"stop");mode(2);//caption:Find magnitude and phase angle of Z4 arm //Ex4.6 Z1=200//impedance of first arm(in ohm) Za=30//phase angle of first arm(in degree) Z2=250//impedance of second arm(in ohm) Zb=-40//phase angle of second arm(in degree) Z3=150//impedane of third arm(in ohm) Zc=0//phase ang...
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clear; clc; close; disp('x(-t) <--> X(-w)=X*(w)'); t=-10:0.1:10; u=[ones(1,find(t==0)) zeros(1,length(t)-find(t==0))]; a=gca(); plot(t,u); poly1=a.children.children; poly1.thickness=3; poly1.foreground=2; xtitle('u(-t)','t') w=-10:0.1:10; for i=1:length(w) if w(i)==0 then delta(i)=1; els...
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//generate a random permutation of the integers from 1 to n function idx = randperm(n) number = rand(1, n); [tmp, idx] = gsort(number); endfunction
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spLItTEr uWe {} FiLTer S { } fiLTer jiY {Bgw oR nOT yiqopr or nOT PWVD } mCNM -> f gRoUpER p {aGgrEGate hPQ.uA } unGRoUPer hi { } groUPfiLtER TN {} merGEr O { moDULE Gle { BRanCheS qI } MOdULe S { brANcHes v F <= ::a6:F28:2:F:CFAA:1.251.149.2/67 Not tOZjd ( 234.194.33.54/0 ) } EXporT k }
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//Optical Fiber communication by A selvarajan //example 5.2 //OS=Windows XP sp3 //Scilab version 5.5.1 clc; clear all; //given eta=0.6//quantum efficiency Po=10*10^-6//optical power in W q=1.6*10^-19//charge of an elctron in columb lambda=0.85*10^-6//wavelength in m h=6.6*10^-34//planck's constant c=3*10^8...
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//Problem 43.10: For the circuit shown in Figure 43.9, determine the value of the secondary current I2 if E1 = 2/_0° volts and the frequency is 1000/pi Hz. //initializing the variables: E1 = 2; // in Volts thetae1 = 0; // in degrees f = 1000/%pi; // in Hz R1 = 4; // in ohm R2 = 16; // in ohm R3 = 16; // in ohm...
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clear clc disp('Exa-2.1'); v1=60; v2=40 //Velocities of cars wrt to observer in km/hr vr=v1-v2; //relative velocity printf('The value of relative velocity is %4.f km/h.',vr);
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//Initilization of variables Wa=400 //lb Wb=200 //lb theta=30 //degrees //Calculations Ta=Wa*sind(theta) //lb Tb=Wb*sind(theta) //lb //Taking moment about point O P=(Tb*12+Ta*6)/24 //lb //Result clc printf('The value of Ta is %f lb and that of Tb is %f lb,also P is %f lb',Ta,Tb,P)
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//Example 3.30.B clc; syms s t; x=laplace(exp(-5*t)); y=laplace(1); z=x*y; f=ilaplace(z); disp(f);
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//Fluid Systems - By - Shiv Kumar //Chapter 12- Reciprocating Pumps //Example 12.12 //To Find the Maximum Speed at which the Pump may run without seperation. clc clear //Given Data:- D=10; //Plunger Diameter, cm L=20; //Stroke Length, cm H_s=4; //Suction H...
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// This file is part of www.nand2tetris.org // and the book "The Elements of Computing Systems" // by Nisan and Schocken, MIT Press. // File name: projects/02/Invert16.tst // File created by Matthew Walsh. load Invert16.hdl, output-file Invert16.out, compare-to Invert16.cmp, output-list in%B1.16.1 invert%B1.1.1 out%B...
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//Problem 8 //calculate the wavelength of X-rays used clear clc d=2.81//interplanar spacing in A n=1//order of beam x=10//angle of first order beam with the incident beam y=x/2//angle of incident w=2*d*sind(y)// wavelength of X-rays used in A printf('wavelength of X-rays used = %.2f A',w)
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clear clf clc y = [17 2; 25 3; 5 2; 8 7; 13 5; 4 35; 15 5] x = [1 2 3 4 5 6 7]; bar(x, y ); xgrid title([' Procentowy udział urazów wybranych części ciała podczas czyszczenia konia i jazdy konnej'], 'fontsize', 3) xlabel("strefa urazów gdzie: 1-głowa, 2-plecy, 3-brzuch, 4-dłoń, 5-ręka powyrzej dłoni, 6-stopa, 7...
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//computation of molality from mass percent clear; clc; printf("\t Example 12.5\n"); //considering 100g of solution percent=35.4;//mass percent of H3PO4 H3PO4=97.99;//mol mass of H3PO4 n=percent/H3PO4;//moles of H3PO4 mH2O=(100-percent)/1000;//mass of solvent m=n/mH2O;//molality of H3PO4, molal printf...
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// Test # 8 : For 1 output argument exec('./allpasslp2hp.sci',-1); [n]=allpasslp2hp(0.3,0.2); disp(n); //Scilab Output //n= 0.7159210 -1 //Matlab Output //n= 0.7159 -1.0000
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clc c=30 b=15 a=10 Ka=0.3872 // from table 13.8 H=4 G=15 Pa=G*H^2*Ka/2 printf('The active force per unit length Pa = %f kN/m\n',Pa) printf(' The resultant will act at a vertical distance equal to H/3 = 4/3 = 1.33 m above \n the bottom of the wall and will be inclined at an angle of 15to the back face of the w...
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clc clear //Input data v=6.5;//The volume of fuel in the barrel in cc d=0.3;//The dimeter of fuel pipe line in cm l=65;//The length of the fuel pipe line in cm vi=2.5;//The volume of fuel in the injection valve in cc K=78.5*10^-6;//The coefficient of compressibility of the oil per bar p1=1;//The atmospheric pr...
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funcprot(0); // Initialization of Variable function[dms]=degtodms(deg) d = int(deg) md = abs(deg - d) * 60 m = int(md) sd = (md - m) * 60 sd=round(sd*100)/100 dms=[d m sd] endfunction Long=75.0;//longitude in degrees GST=5+25.0/60+15.0/3600;//GST in hr LMT=5.0+40.0/60;//LMT in hr ...
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//Fiber-optics communication technology, by Djafer K. Mynbaev and Lowell L. Scheiner //Example 3.3.3 //windows 7 //Scilab version-6.0.0 clc; clear; //given L=5;//fiber length in km NA=0.275;//numerical aperture c=3E5;//speed of light in km n1=1.48;//refractive index p=2*c*n1; e=NA*NA; d=L*e; delt...
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fc=900*10^6 c=3*10^8 fdm=70 Yc=c/fc V=fdm*Yc//max. speed of the vehicle Vm=V*18/5//to convert max speed in kmph disp(Vm,'maximum speed of the vehicle in kmph')
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//(Welded and Riveted Joints) Example 8.7 //Refer Fig.8.17 on page 284 //ISA angle dimensions l1 x l2 x h (mm) l1 = 200 l2 = 100 h = 10 //Static force acting on the angle P (kN) P = 150 //Permissible shear stress for the weld tau (N/mm2) tau = 70 // //Distance of C.G. of weld2 from the C.G. of the angle y2...
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disp('In a college,120 mathematics students can opt for either French(F),German(G) or Russian(R)') n=120; //total number of students F=65; //number of students studying French G=45; //number of students studying German R=42; //number of students studying Russian FandG=20; //number of students studying French ...
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<<<<<<< HEAD // Copyright (C) 2018 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Li...
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// Exa 2.6 clc; clear; // Given data // Referring circuit shown in Fig. 2.11(a) B=200; // Current gain Icq = 100*10^-6; // Amperes ADM = 500; // Voltage gain for differential mode signal CMRR_db = 80; // in dB(Common mode rejection ratio) // Solution // Since gm = Icq/Vt therefore, gm = Icq/(25*10^...
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function ydot = f(t, y) ydot = 6 * t^4 + 5 * t^3 + 4 * exp(t); endfunction h = 0.01; y(1) = 0; t(1) = 0; for i=1:50 k1 = f(t(i), y(i)); k2 = f(t(i) + h/2, y(i) + h * k1 / 2); k3 = f(t(i) + 3*h/4, y(i) + 3*h*k2/4); k4 = f(t(i) + h, y(i) + 2*h*k1/9 + h*k2/3 + 4*h*k3/9); y(...
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function x=cosm(a) // cosm - computes the matrix cosine //%CALLING SEQUENCE // x=cosm(a) //%PARAMETERS // a : square hermitian or diagonalizable matrix // x : square hermitian matrix //! // Copyright INRIA if type(a)<>1 then error(53),end if a==[] then x=[],return,end if norm(imag(a),1)==0 then x=real(e...
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// Pole placement controller for magnetically suspended ball problem, discussed in Example 9.3 on page 331. // 9.1 exec('myc2d.sci',-1); exec('desired.sci',-1); exec('zpowk.sci',-1); exec('polsplit2.sci',-1); exec('polsize.sci',-1); exec('t1calc.sci',-1); exec('indep.sci',-1); exec('move_sci.sci',-1); exec(...
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clc; clear; n0=10^16 //donor atoms in cm^-3 q=1.6*10^-19 //electron charge in J ni=1.5*10^10 //in cm^-3 Nd=10^16 //Donors added to silicon to make it n-type) in cm^-3 GT=2.25*10^10 //Thermal generation rate of carriers under equilibrium cm^-3/s gop=10^21 //in cm^-3/s tau_n=10^-6 //in s tau_t=2.5*10^-3 //transi...
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//Rodríguez Montiel Moisés Ulises //2NM51 function y = interpolSplin(funcTab, x) [n, m] = size(funcTab) if(n <> 2) error("No es una función tabular") end if ~(isreal(funcTab)) error('Elementos no numericos o complejos en el arreglo.'); end if(~isreal(x)) error('El numero de...
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// sero.bas : demo de icse // calcul coefficients optimaux du modele simplifie 5ht-plaquette // ************************************************************** // // les doubles slash introduisent des commentaires // // contexte : tue les variables de nom reserve // Copyright INRIA exec('icse.contexte')...
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clc SG=0.9; h=1.2; //m g=9.81; //m/s^2 rho_w=1000; //kg/m^3 rho=SG*rho_w; //kg/m^3 P=rho*g*h/10^3; disp("Gauge pressure P=") disp(P) disp("kN/m^2")
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clc clear all; close; x1=[1,3,7,-2,5]; x2=[3,0,-1,2]; y=conv(x1,x2) x3=[2,-1,0,3]; z=xcorr(x1,x3) c=conv(x1,x3)
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//Example No. 3_05 //Decimal to binary //Pg No. 48 clear ; close ; clc ; d = 0.65 j = 1 ; while d ~= 0 fracp(j) = floor(d*2) //integral part of d*2 d = d*2 - floor(d*2) //Fractional part of d*2 j = j+1 ; decp(j-1) = d p = 1 for i = 1:j-2 if abs(d - decp(i))< 0.001...
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//ex10.6 B_ac=100; r_e=12; R1=62*10^3; R2=22*10^3; R_S=1*10^3; R_E=1*10^3; C2=100*10^-6; //Base circuit impedance= parallel combination of R1, R2, R_S R_th=(R1*R2*R_S)/(R1*R2+R2*R_S+R_S*R1); //Resistance looking at emitter R_in_emitter=r_e+(R_th/B_ac); //resistance of equivalent bypass RC is parallel combin...
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SplittEr Px {} fiLTEr ca { BiTAnD ( ) or nOT z NoT IN 130 } fIlTER kt {Not M nOt JA nOT THP Or noT w } m -> S gROUpeR zW {agGRegAte BItAnd(dP) AS GZWrb ,Q.R } ungRouPeR V { } gRoUpFILTeR ueWu {bd:fd:ec:Ec:ca:EE not IN AL Y ( W, 3.214.253.218, ) oR NOt biTor (181.220.0.213, bItoR (), ) 1B:da:D8:0A:fA:d...
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// Example 6.10 //power coupled clc; clear; close; tha=15;//in degree po=1;//in micro watt nc=(sind(tha))^2;// pf=nc*po*10^-6;//in watts disp(pf*10^9,"power coupled in nW is")
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//Example 17_10 clc(); clear; //To find the current in battery r1=3 //Units in Ohms r2=6 //Units in Ohms ra=(r1*r2)/(r1+r2) //Units in Ohms r3=2 //Units in Ohms r4=4 //Units in Ohms rb=r3+r4 //Units in Ohms r5=6 //Units in Ohms rc=(r5*rb)/(r5+rb) //Units in Ohms r6=9 ...
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clc t90=75*24*60*60 // time in sec T90=0.848 Hd=1.5*100 //in cm Cv=T90*Hd^2/t90 printf('Cv = %f cm^2/sec',Cv)
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//Example 3.8 //determine(a) maximum allowable current //(b) the corresponding remp. at the centre of wire and //at the outer surface of insulation //Given ri=1.3*10^-3 //m, radius of 10 gauge wire t=1.3*10^-3 //m, thickness of rubber insulation Ti=90 //C, temp. 0f insu...
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clc //Variable declaration lamda=0.842 n1=1 q=(8+(35/60))*(%pi/180) n2=3 d=1 //Calculations //n*lamda=2*d*sin(theta) //n1*0.842=2*d*sin(q) //n3*0.842=2*d*sin(theta3) //Dividing both the eauations, we get //(n2*lamda)/(n1*lamda)=2*d*sin(theta3)/2*d*sin(q) theta3=asin((((n2*lamda)/(n1*lamda))*(2*d*si...
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// Calculating the heat conducted across the former from winding to core clc; disp('Example 4.11, Page No. = 4.17') // Given Data t = 2.5;// Thickness of former (in mm) t_air = 1;// Thickness of air space (in mm) lw = 150*250;// The inner dimentions of the former of field coil (in mm square) h = 200;// Winding h...
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frame_left_estr.enable ="off" Apoios =[] // Escolha dos nós da estrutura nos = SelectNodesInMat(coord) // Apaga a restrição nos nós selecionados que eventualmente já tivessem apoiados if ~isempty(Restricoes) then JahApoiados = [] for i=1:size(nos,"*") JahApoiado = vectorfind(Restricoes.data...
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//x^2-13*x+36 clear; clc; close; x=poly(0,'x'); p=x^2-13*x+36; factors(p)
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// // Scilab ( http://www.scilab.org/ ) - This file is part of Scilab // Copyright (C) 2012-2012 - Scilab Enterprises - Bruno JOFRET // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distributio...
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// Scilab code Ex6.1: Pg:247 (2008) clc;clear; i_p = 60; // Angle of polarization, degree mu = tand(i_p); // Refractive index of the material r = 90-i_p; // Angle of refraction, degree printf("\nThe refractive index of the material = %5.3f ", mu); printf("\nThe angle of refraction = %2d degree", r); /...
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ZA=15+%i*15.708; ZB=20+%i*0; V=200+%i*0; IA=V/ZA; disp('i) CURRENT (IA) is = '+string (IA) +' A '); IB=V/ZB; disp('ii) CURRENT (IB) is = '+string (IB) +' A '); I=IA+IB; disp('vi) TOTAL CURRENT (I) is = '+string (I) +' A ');
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//Given that the temperature has the same value on both the centrigrade and fahrenheit scales //(C/100)=((F-32)/180) //Putting C=F C=(-32/180)/((1/100)-(1/180));//Centrigade temperature in degree C F=C;//Fahrenheit temperature in degree Fahrenheit printf('The temperature which has the same value on both the ce...
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//example1.32 clc disp("Use the loop analysis") disp("From the current source branch,") disp("I3=1 A") disp("Applying KVL to the loops without current source we get,") disp("-6(I1)-4-5(I1)+5(I2)=0 i.e. -11(I1)+5(I2)=4 ..(1)") disp("-5(I2)+5(I1)-6-4(I2)-4(I3)=0 i.e. 5(I1)-9(I2)=10 (2)") disp("Solving...
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// Example 9_2 clc;funcprot(0); // Given data // From Example 9_1 D=8;// The diameter of the steel pipe in inch z_in=100;// Elevation in m z_out=22;// Elevation in m L=2.2;// The distance in km g=9.807;// The acceleration due to gravity in m/s^2 nu=1.0*10^-6;// The kinematic viscosity in m/s^2 rho=1*10^3;// T...
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function s2=%sir(i,j,s1,s2) // %sir(i,j,M,r) <=> r(i,j)=M //! //s2(i,j)=s1 // if type(i)==10 then // s2('num'),s2('den'),sl('dt') [lhs,rhs]=argn(0) if rhs<>3 then error(21),end nams=['num','den','dt'] kf=find(i==nams) if kf==[] then error(21),end s2=s1;kf=kf+1 if size(s2(kf))<>size(j) then if kf<>...
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//Finding of Loss of Head //Given q1=200; d1=150; d2=300; g=9.81; //To Find v1=200*(4/%pi)*(100/150)^2; disp(v1); v2=200*(4/%pi)*(100/300)^2; disp(v2); h=((v1-v2)^2)/20*g; h1=h/1000; disp(" Loss of Head ="+string(h1)+" meter of water");
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function r = aantalrollen(t) r = ceil(t / 10) end plot(0:100, aantalrollen)
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clc //initialisation of variables g= 32.2 //ft/sec^2 Z= 36 //ft r= 4 //in r1= 12 //in //CALCULATIONS w= (sqrt(2*g*Z/((r1/12)^2-(r/12)^2)))*(60/(2*%pi)) //RESULTS printf (' minimum speed= %.f rev/min',w)
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std_dev = 2; //in [cm]. x = [-10:0.1:10]; f = erfc(abs(x/(std_dev*sqrt(2)))); figure('BackgroundColor',[1 1 1]); plot(x,f); ph = gca(); // handle ph.x_label.text = 'O^t_L-O^e_L'; ph.y_label.text = 'L(O^t_L)'; ph.axes_visible = ["on","on","off"] ph.grid = [1,1]; ph.auto_scale="on";
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-- The intellectual and technical concepts contained herein are proprietary to Fuzzy Logix, LLC. -- and may be covered by U.S. and Foreign Patents, patents in process, and are protected by trade -- secret or copyright law. Dissemination of this information or reproduction of this material is -- strictly forbidden unl...
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clc; close(); clear(); //page no 530 //prob no. 16.9 c=3*10^8; //speed of light in m/s Td=400*10^-6 //s d=c*Td/2 //in m mprintf(' d=%.0f Km ',d*10^-3);
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//Finding the Performance Parameters of a Three-Phase Induction Motor with frequency and voltage Control //Example 16.6(Page No- 714) clc clear //given data p = 4; Vl = 460; Va = Vl/sqrt(3); Vs = Va; f = 60;//Hz w = 2*%pi*f; w_b = 2*w/p; d = Va/w_b; R_r = 0.38; Rs = 0.66 Xs = 1.14; X_r = 1.71; //part...
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% Examples for the conversion of reaction equations to ordinary % differential equations. % Example taken from Feinberg (Chemical Engineering): species := {A1,A2,A3,A4,A5}; reac2ode { A1 + A4 <> 2A1, rho, beta, A1 + A2 <> A3, gamma, epsilon, A3 <> A2 + ...
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function [M]= impli(t,T,h,x) for i=1:x/h-1, u(i,1)=i*h*(1-i*h), end M=[0;u;0] A=2*eye(x/h-1,x/h-1) for j=1:x/h-2, A(j,j+1)=-1, A(j+1,j)=-1, end for k=1:T/t, plot([0;u;0]) halt() v=inv(eye(x/h-1,x/h-1)+t/h^2*A)*u M=[M [0...
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 3.3w //calculation of average velocity and average acceleration //given data A=1//given value of constant A B=4//given value of constant B C=-2//given value of constant C D=5//given value of constant D t=4//time(i...
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//To determine the best location of the substation for a given set of loads //Page 123 clc; clear; //Various loads and how they are positioned on the corners of a square of length 25km L1=5000; //(0,25) L2=8000; //(25,25) L3=3000; //(25,0) L4=6000; //(0,0) L=25;//Length of the square TL=L1+L2+L3+L4; //...
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clc // given data i=10/100.0 // rate Acost=90000 // cost of A in Rs Bcost=75000 // cost of B in Rs Acashfl=26000 // annual cash flow of A in Rs Bcashfl=26000 // annual cash flow of B in Rs nA=5 // useful life of A in years nB=4 // useful life of B in years NPVA=Acashfl*(((1+i)**nA) - 1)/(i*(1+i)**nA) - Acos...
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//Calculate the maximum voltage gain and bandwidth of multistage amplifier clear; clc; //soltion //FUNCTIONS function [z]=prll(r1,r2)//Function for the parallel combination of resistor z=r1*r2/(r1+r2); endfunction //given rin=10*10^6;//ohm //input resistance of JFET Rd=10*10^3;//ohm Rs=500;//...
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clear; clc; printf("\t\t\tExample Number 2.2\n\n\n"); // multilayer cylindrical system // illustration2.2 // solution ID = 0.02;// [m] inner diameter of steel OD = 0.04;//[m] outer diameter of steel t = 0.03;//[m] thickness of asbestos insulation // system is like three concentric cylinders T1 = 600;// [de...
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A= input("Enter Amplitude: "); theta = input("Enter theta in radian "); F= input("Enter Frequency "); Fs= input("Enter sampling frequency "); n= 0:1:((2*Fs)/F); // here time period T is 1/f and f is F/Fs and we want signal for 2 cycle so 2*Fs/F. Xn= A*cos(2*%pi *(F/Fs)*n + theta); figure(1); plot2d(n,Xn); ...
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//Example 4.3 The following observations constitute a random sample from an unknown population clear; clc; x=[14 19 17 20 25]; n=5; M=sum(x)/n; s_d=sqrt(sum((x-M)^2)/4); SE=s_d/sqrt(n); disp(SE,"Standard Error =",s_d,"Standard Mean",M,"Mean");
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Expanding for base=2, level=4, reasons+features=same Refined variables=a,b ReasonFactory: same, code="same" SameReason.consider( "2a²-2b+2", "4a²-4b+4") = same form as 4a²-4b+4
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clc; e=-1.6*10^-19; //charge on electron in Coulomb q=20*10^-6; //charge in Coulomb r1=0.1; //r1 in m r2=0.05; //r2 in m Va=9*10^9*(q/r1); //calculating voltage at A Vb=9*10^9*(q/r2); //calculating voltage at B V=Va-Vb; //potential difference W=V*e; //calculating work done in joule disp(W,"Work do...
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exec('electrostatics.sci', -1) //Given that q1 = +3.1*10^-9 //in C q4 = q1 q2 = -5.9*10^-9 //in C q5 = q2 q3 = -3.1*10^-9 //in C //Sample Problem 24-3 printf("**Sample Problem 24-3**\n") //Using gauss law flux = (q1+q2+q3)/Eo printf("The flux through the surface is equal to %fN.m^2/C", flux)
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// **** Purpose **** // This code performs dampped Fourier transform from t <--> omega. // **** Variables **** // [A]: real, Nx2 // <= input data as function of time. [time, value]. Time must be in // unit of hbar/eV (0.658fs) // [E_max]: real, 1x1 // <= max value of FT frequency, in unit of eV // [dE]: real, 1x...
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clear //Given h=6.625*10**-34 c=3*10**8 l=5600*10**-10 a=5 //Calculation E=(h*c)/l n=a/E //Result printf("\n Number of visible photons emitted per second is %0.2f *10**19 ",n*10**-19)
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//Chapter 15: Antennas for Special Applications //Example 15-26.1 clc; //Variable Initialization t1 = 0.3e-9 //Echo time off the top of pavement (s) t2 = 2.4e-9 //Echo time off bottom of pavement (s) t3 = 14.4e-9 //Echo time off bottom of water pocket (s) er_1 = 4 //Relative permittivity of pavement ...
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function out=a(n) if (n==0) out=2*lambda/%pi; else out=-2/(n*%pi)*sin(n*(%pi-lambda)); end endfunction N=1000; t=linspace(0.01,5,4); lambda=%pi/2; theta=linspace(0,2*%pi,1000); p=100; for i=1:N somme=a(0)/2; for n=1:p somme=somme+a(n)*cos(n*theta)*exp(-n^2*t(i)); end drawlater; ...
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Name=fuglaaOWDodgeTrack PlayerCharacters=ow-heavysurgerifle BotCharacters=ow-rotation.rot IsChallenge=true Timelimit=60.0 PlayerProfile=ow-heavysurgerifle AddedBots=ow-rotation.rot PlayerMaxLives=0 BotMaxLives=0 PlayerTeam=2 BotTeams=1 MapName=boxernobounds.map MapScale=2.0 BlockProjectilePredictors=true ...
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clc; p1=0.1; // pressure at state 1 in MPa p2=6; // Pressure at state 2 in MPa // (a).Pump work for water vf1=0.001043; // specific volume in m^3/kg wp=-vf1*(p2-p1)*10^3; // Pump work for water disp ("kJ",wp,"(a).Pump work for water ="); // (b).For steam h1=2675.5;// specific enthalpy in kJ/kg s1=7.3595;// sp...
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ok_getValue.tst
; get-value after sat (set-option :produce-models true) (set-logic QF_UF) (declare-fun x () Bool) (assert (= x false)) (check-sat) (get-value (x))
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//pathname=get_absolute_file_path('3.10.sce') //filename=pathname+filesep()+'3.10-data.sci' //exec(filename) //Seating capacity: c=500 //Heat requirement per person(in kcal/hr): q=50 //Enthalpy of water entering the pipe(in kcal/kg): h1=80 //Enthalpy of water leaving the pipe(in kcal/kg): h2=45 //Difference ...
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// Exa 5.6 clc; clear; close; // Given data N=8;// Number of bits f=1*10^6;// in Hz T=1/f; Tc= N*T;// in second disp(Tc*10^6,"Time of conversion in micro second")
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//Caption:time_response_and_peak_overshoot //example 12.8 //page 521 s=%s; syms t; num=sym('8*(s+1)'); den=sym('(s^2+2*s+2)'); CL=num/den; disp(CL,"C(s)/R(s)="); //for unit step response R(s)=1/s; d=CL*(1/s); disp(d,"C(s)="); c=ilaplace(d,s,t); disp(c,"c(t)="); //for peak time we get tp=%pi/2 t=%pi/2 a=s*d; a=simple(a...
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clc,clear printf('Example 1.29\n\n') P=8 //Poles A=2 //Wave wound armature Z=480 //number of armature conductors I_a=200 I=I_a/A //Part(i) theta_m=0 //Geometric nuetral axis amp_turns_PP_d=Z*I*theta_m/360 //De-magnetising ampere-turns per pole amp_turns_PP_c=Z*I*(1/(2*P)-theta_m/360) //Cross-magnetisin...
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W=2*10^-6; Dp=1.25*10^-3; Tp=10^-6; Lp=sqrt(Dp*Tp); a=(W^2)/(2*(Lp^2)); //to prove a<<1 printf('\n The value of (W^2)/(2*(Lp^2)) is %f which is <<1',a); W=2*10^-6; We=1*10^-6; c=1/0.0010; d=1/0.000010; disp("γ=1/(1+((σn*W)/(σp*We)))"); b=1/(1+((c*W)/(d*We))); //say γ=b printf('\n The value of γ is %f',b);
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PL/SQL Developer Test script 3.0 17 -- Created on 15.08.2014 by ZHURAVOV_VB declare -- Local variables here cursor l_obj_cur is select distinct o.name from xxdoo_db_schemes_t s, xxdoo_db_objects_t o where 1=1 and o.type in ('TYPE') and o.scheme_id = s.id and s.name =...
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clc clear disp("Example 8.8") printf("\n") disp("convert the following binary numbers to decimal") disp("a)11.101 b)0.0111 c)110.1101") //Given binary number i=1;w=1 bin=11.101 //separating integer part IP=floor(bin) IP1=IP //separating decimal part DP=modulo(bin,1) //converting decimal value to interge...
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// Exa 3.7 clc; clear; close; // Given data I_Z1 = 20;// in mA I_Z1= I_Z1*10^-3;// in A I_Z2 = 30;// in mA I_Z2= I_Z2*10^-3;// in A V_Z1 = 5.6;// in V V_Z2 = 5.75;// in V del_IZ = I_Z2-I_Z1;// in A del_VZ = V_Z2-V_Z1;// in V r_Z = del_VZ/del_IZ;// in ohm disp(r_Z,"Resistance of zener diode in ohm is");
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//Theory Example