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function y=f(x) //y=exp(x)/2-1-x/2 //y=9*x^2-2*x //y=3*x^3-x^2+1 //y=(x.*cos(x))./(log(x)) //y=2*x-%e^(-x) //y=%e^(-2*x)+x-1 //y=x^3-7*x^2+14*x-6 //y=3*x^3-x^2-1 //y=x^4-3*x^2-3; //y=(x+1)./x^2; //y=2 ./(3*x)+(2/3)*x; //y=(3*x-3)^(1/4); //y=(1 ./x)-(x*3)/3 //y=%pi...
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//3 bit SISO shift register //in a SISO shift register, input is given to the MSB, it shifts rightwards with positive clock pulses and output is seen at LSB ok=open_serial(1,2,115200); if ok~=0 then error('Unable to open serial port, please check'); end D2=0; //serial data input to FF2 (MSB FF) //Pin 2 D1=0; //D...
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function [stk,txt,top]=sci_fwrite() // Copyright INRIA txt=[] RHS=[] for k=1:rhs RHS=[RHS,stk(top-rhs+k)(1)] end stk=list('mtlb_fwrite'+rhsargs(RHS),'0','1','1','1')
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//====================================================================================================== // Chapter 8 example 4 clc; clear; // variable declaration mh = 0.56; //masses interms of m0 me = 1.08; //masses interms of m0 t = 27; //temperature in °C k ...
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clc; //page no 199 // prob no 6.3.1 // RC phase shift scillator // In the given problem small-signal o/p resistance Rc=40kohm // collector bias resistor, rc=10kohm,f=400 Hz; // all resistances are in Kohm and freq in Hz f=400;rc= 10; Rc= 40; // Minimum value of beta is given by Bomin= 23+(4*Ro/R)+(29*R/Ro) // ...
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//example 5.22 clear; clc; disp("C6H12O6(s)+6O2(g)-->6CO2(g)+6H2O(l)"); //Given: mass=25;//mass of glucose for combustion under standard condition[gm] T=298;//temperature[K] Gf1=-910;//Standard Gibbs free energy of formation for C6H12O6[KJ/mol] Gf2=-394.4;//Standard Gibbs free energy of formation for CO2(g)...
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//Enemy ship location //refer fig. 14.10 //taking north as y direction and west as x direction //vAy=36*cosd(theta) //vAx=36*sind(theta) //Components of velocity of enemy ship vBy=18*cosd(30) //kmph vBx=-18*sind(30) //kmph //then //vrx=36*sind(theta)+9 //vry=36*cosd(theta)-15.588 //solving x=0.2777 theta...
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//Kunii D., Levenspiel O., 1991. Fluidization Engineering(II Edition). Butterworth-Heinemann, MA, pp 491 //Chapter-8, Example 1, Page 206 //Title: Performance of a Fast Fluidized Vessel //========================================================================================================== clear clc //INPUT Lmf=2...
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clear clc xx = linspace(-3, 3, 100); yy = linspace(-3, 3, 100); n = length(xx); m = length(yy); for i=1:n for j=1:m z(i,j) = -(xx(i)^2) - (yy(j)^2); end end plot3d1(xx, yy, z); f=get("current_figure"); f.color_map = jetcolormap(64);
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Introduction to heat transfer by S.K.Som, Chapter 1, Example 5") //The average heat transfer coefficient(hbr) is 800 W/(m^2°C) //The surface temprature of heat exchanger is 75°C and air temprature is 25°C so delt...
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disp hello_world!
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function t = test_premier(n) t = ones(1, n) > 0; t(1) = %f; for i = 2:sqrt(n) if(t(i)) t(2*i:i:n) = %F; end end endfunction function l = premiers(n) l = (1:n); t = test_premier(n); l = l(t); endfunction function N = compte_premiers(n) N = cumsum(test_premier...
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clear; clc; //To find Approx Value function[A]=approx(V,n) A=round(V*10^n)/10^n;//V-Value n-To what place funcprot(0) endfunction //Example 9.2 //Caption : Program to Find Power Requirement For Various seasons //Given Values Qh_Winter=30;//[KW] Qc_Summer=60;//[KW] Tc_Winter=283.15;//[K] Th_Win...
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clc clear printf("example 7.14 page number 317\n\n") //to find the initial concentration and shift in equilibrium Ce_N2 = 3; //equilibrium conc of N2 Ce_H2 = 9; //equilibrium conc of H2 Ce_NH3 = 4; //equilibrium conc oh NH3 C_N2 = Ce_N2 + 0.5*Ce_NH3; C_H2 = Ce_H2 + 1.5*Ce_NH3; printf("concentration...
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//(6.12) A turbine operating at steady state receives air at a pressure of p1 = 3.0 bar and a temperature of T1=  390 K. Air exits the turbine at a pressure of p2 = 1.0 bar. The work developed is measured as 74 kJ per kg of air flowing through the turbine. The turbine operates adiabatically, and changes in kineti...
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//Determining nyquist rate for the signals clc clear close Wb1=4*%pi; Wb2=10*%pi; Wbs=max(Wb1,Wb2); Ws=2*Wbs; //Bandlimited frequency doesnt change by Amplitude scaling //(a) 2*x1(t) Wa=2*Wb1 disp("Wa=") disp(Wa) //Timing shifting doesnt affect the magnitude spectrum //(b) x1(t-1) Wb=2*Wb1 disp("Wb=") ...
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clear; close; clc; T1=10; wM=100; N=ceil(wM*T1/%pi); dw=2*wM/N; dt=%pi/wM; WN=exp(-%i*2*%pi/N); n=0:N-1; x=%e^-(n*dt); k=0:10; Xk=dt*x*exp(-%i*2*%pi*n'*k/N); disp(Xk(find(k==0)),Xk(find(k==1)),Xk(find(k==10)),"X[0] X[1] X[10] from X[k]") w=0:dw:10*dw; Xw=ones(1,length(w))./(%i*w+1); disp(Xw(find(w==0)),...
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clc; clear; printf("\t\t\tChapter5_example1\n\n\n"); // properties of CO at 300K from appendix table D2 Cp=871; Gamma=1.3; Cv=Cp/Gamma; printf("\nThe specific heat at constant volume is %d J/(kg.K)",Cv); dT=20; m=5; Qp=m*Cp*dT; Qv=m*Cv*dT; printf("\n The heat required at constant pressure is %.1f kJ",Qp/1000); printf("...
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//example 1.6 //absolute error and relative error //page 10 clc;clear;close; s=sqrt(3)+sqrt(5)+sqrt(7);//the sum square root of 3,5,7 n=4; Ea=3*((10^-n)/2);//absolute error R_E=Ea/s; printf('the sum of square roots is %0.4g \n',s ); printf('the absolute error is %f \n',Ea); printf('the relative error is %f '...
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//Example 8.2 //Find the response of an FIR filter with impulse response h[n]=[1,2,4] //to the input sequence x[n]=[1,2] clc; x=[1,2]; h=[1,2,4]; Y=convol(x,h); disp(Y,'y[n]=');
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// Examle 3.8 // for the extreme value of Rl voltage (Vl) & Current (Il) E=3; // Supply voltage Ri=1; // I/p Resistance Rl1=100; // Minimum load resistance Il1=E/(Rl1+Ri); // Current a...
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//Variable Declaration pi = %pi n=14.2171401*2*%pi/86400 //Mean motion (rad/sec) M=204.9779+0.001*180*5/pi //Mean anomaly(rad) e=9.5981*10**-3 //Eccentricity a=7194.9 //Semimajor axis(km) //Calculation v=(M*pi/180)+2*e*sin(M*pi/180)+(5*e**2*sin(2*M*pi)/(4*180)) //True Anomaly (radians) v=v*180/%pi //True anoma...
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//ques11 disp('To find the inverse laplace transform of the function'); syms s t f=(5*s+3)/((s-1)*(s^2+2*s+5)); il=ilaplace(f,s,t); disp(il);
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before x, phead=0, pbody= - 2*y + 4*z, ptail=2*y^2 - 7*z^2, mlead= + x^2, flead=1, root2=1, widev=1 after x, phead=x^2, pbody= - 2*y + 4*z, ptail= - 2*y^2 + 16*y*z - 23*z^2, vmapt={x=> - 2*y + 4*z+x,y=>y,z=>z} before y, phead=x^2, pbody= - 4*z, ptail= - 23*z^2, mlead= + y^2, flead=1, root2=1, widev=1 after y, ph...
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name = input("Введите имя: ","string") day = input("Введите день рождения: ") month = input("Введите номер месяца рождения: ") year = input("Введите год рождения: ") select month case 1 then days = 30 case 2 then if modulo(year,4) == 0 & modulo(year,100) ...
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clear clc //to find total energy stored in the system //to find maximum speed and magnitude of maximum acceleration of block //to find position,velocity and acceleration of block at t = 0.215s // GIVEN: //refer to problem 17-1 //mass of boby M = 1.65//in Kg //increase in length y = 7.33//in cm //mass of bl...
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totals=[zeros(7,1);3 24 63 120 193 282 387 508 645 798 967 1152 1353 1571 1811 2051 2291 2531 2771 3011 3251 3491 3731 3971 4211 4451 4691 4931 5171 5411 5651 5891 6131 6371 6611 6851 7091 7331 7571 7811 8051 8291 8531 8752 8955 9140 9307 9456 9587 9700 9795 9872 9931 9972 9995 10000 ]; totals1=totals maxcap=40*6; n=s...
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//Example number 2.7, Page number 2.34 clc;clear;close // Variable declaration m=1 // unitless lamda_l=6000*10**-10 // in m theta=0.046*(%pi/180) // radian n=2*10**6// unitless // Calculation lamda_s=(m*lamda_l)/(sin(theta)) // in m v=n*lamda_s // in m/s // Result printf("Ultrasonic wavelength,lamda s =%0.2e m",(l...
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//Throat area of nozzle(in m^2): Ae=0.001; //Back pressure of air(in kPa): pb=591; //Stagnation pressure(in kPa): p0=1000; //Stagnation temperature(in K): T0=333; //Gas Constant(in N-m/kg-K): R=287; //Value of k: k=1.4;
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//pathname=get_absolute_file_path('1.25.sce') //filename=pathname+filesep()+'1.25-data.sci' //exec(filename) //Mass of hydrogen taken(in kg): mh=2 //Mass of helium taken(in kg): mhe=3 //Specific heat at constant pressure for hydrogen(in kJ/kg-K): Ch=11.23 //Specific heat at constant pressure for helium(in kJ/k...
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//Ex13.2.1.;Peltier heats absorbed and rejected //peltier coefficients at these junctions are aplha_p_1-2=alpha_s_1-2*T //Let A=alpha_s_1-2 at 373 k=55*10^-6 v/degree_k and B=alpha_s_1-2 at 273 k=50*10^-6 v/degree_k A=(55*10^-6); B=(50*10^-6); T1=373;//k T2=273;//k I=10*10^-3;//current;unit=Ampere alpha_p_1_2_a...
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clear;lines(0); u=prbs_a(50,10); plot2d2("onn",(1:50)',u',1,"151",' ',[0,-1.5,50,1.5]);
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clear all; clc; disp("Ex 8_7") // Summing moments about A and equating to zero a=7*%pi/180//angle in radian NB=(4905*0.5)/(cos(a)+(0.3*sin(a))) printf('\n\n NB = %0.1f N',NB) //Summing forces in Y direction NC=(NB*cos(a))+(0.3*NB*sin(a)) printf('\n\n NC = %0.1f N',NC) //Summing forces in X direction P=(0.3*NC)+(0.3*NB*...
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clc; clear; //Example 4.23 sigma=5.67*10^-8 //[W/sq m.K^4] e1=0.7; e2=0.7; T1=866.5 //[K] T2=588.8 //[K] Q_by_A=sigma*(T1^4-T2^4)/((1/e1)+(1/e2)-1) //[W/sq m] e1=0.7; e2=e1; e3=e1; e4=e1; e=e1; //Q with n shells =1/(n+1) n=2 Q_shield=1/(n+1); es1=e1; es2=e1; Q_by_A=sigma*(T1^4-T2^4)/((1/e1)...
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clc clear //INPUT DATA AW=63.5//atomic weight of copper D=8.93*10^3//density of copper in kg m^-3 t=2.48*10^-14//relaxation time of copper in s AV=6.023*10^26//avagadro no in mole^-1 e=1.6*10^-19//charge of electron in coulombs m=9.11*10^-31//mass of a electron in kg //CALCULATION n=(AV*D)/AW//density of el...
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// Scilab code Ex2.12: Pg.90 (2008) clc; clear; E_1 = 5; // Energy of first photon, MeV E_2 = 2; // Energy of second photon, MeV p_1 = 5; // Momentum of first photon, MeV/c p_2 = -2; // Momentum of second photon, MeV/c E = E_1 + E_2; // Total energy of the system, MeV p = p_1 + p_2; // Total mo...
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//CHAPTER 1 ILLUSRTATION 1 PAGE NO 15 //TITLE:Basic kinematics //Figure 1.14 //Figure 1.14 test code clc clc clear pi=3.141 AO=200// distance between fixed centres in mm OB1=100// length of driving crank in mm AP=400// length of slotter bar in mm //=======================...
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//Exa 2.9 clc; clear; close; //given data SIGMAi=2.12766;//in S/m RHOi=0.47;//in ohm-m MUh=0.19;//in m^2/V-s MUe=0.39;//in m^2/V-s e=1.6*10^-19;//in coulamb //Formula : SIGMAi=ni*e*(MUe+MUh) ni=SIGMAi/(e*(MUe+MUh));//in m^-3 E=10^4;//in V/m vn=MUe*E;//in m/s vh=MUh*E;//in m/s disp(ni,"Density of electron...
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0 ; vgcd=1; gcd=1; isZero=true; hasVariable=false; isBiased=true; mergeVariables=0; relation=EQ_0 ; evaluate=success =0
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//variable declaration n1=1.53 delta=0.0196 //Calculations N_a=n1*(2*delta)**(1/2) A_a=asin(N_a) //Result printf('Numerical aperture =%0.3f \n',(N_a)) printf('Acceptance angle =%0.3f degrees \n',(A_a*180/%pi))
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format(25) function y = f(x) y = cos(10*x) - exp(-x) endfunction function y = fl(x) y = -10*sin(10*x) + exp(-x) endfunction //Ver gráfico para dar o chute inicial x = -1:0.1:10 plot(x,f(x),'r.-') xgrid x = 1.5 x = 1.15 x = 0.5 x_ant = x continuar = 1 for i = 1:10 x = x - (f(x)/fl(x)) disp(x) end
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# A000000 generated by Sequence # Table of n, a(n) for n = 0..5 0 5 1 6 2 7 3 34 4 66 5 155
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// Grob's Basic Electronics 11e // Chapter No. 19 // Example No. 19_21 clc; clear; // A current of 1.2 A flows in a coil with an inductance of 0.4 H. How much energy is stored in the magnetic field? // Given data l1 = 0.4; // Coil Inductance 1=0.4 H I = 1.2; // Current=1.2 Amps E = (l1*I*I)/2; d...
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//A Textbook of Chemical Engineering Thermodynamics //Chapter 4 //Second Law of Thermodynamics //Example 3 clear; clc; //Given: P_out = 4.5; //output power(hp) P_in = 6.25; //input power(kW) T1 = 1000; //source temperature(K) T2 = 500; //sink temperature(K) //To determine efficiency of proposed eng...
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////Chapter No 14 Air Standard Cycles ////Example No 14.7 Page No 309 ///Find Swept volume //Input data clc; clear; D=200*10^-3; //Otto cycle cylindrical bore in mm L=450*10^-3; //Otto cycle Stroke in mm vc=2*10^-3; //Clearance volume in mm^3 gamma1=1.4; ...
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clear; clc; disp('Example 8.22'); // aim : To determine // the percentage gravimetric analysis of the total products of combustion // given values CO = 12;// %age volume composition of CO H2 = 41;// %age volume composition of H2 CH4 = 27;// %age volume composition of CH4 O2 = 2;// %age volume compositi...
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//value// s=%s; H=syslin('c',1/(s*((s+3)^2))); evans(H,100) K=25; y=K*H; //-----eq 1) disp(K*H,"G(s)H(s)="); disp('=1',K*H,"mod(G(s)H(s))"); //on solving eq 1 for s=%i*w this we get an equation m w=poly(0,'w'); m=w^3+9*w-25 n=roots(m) s=%i*n(1) p=horner(y,s) [R,Theta]=polar(p) PM=180+Theta
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//Example : clc; clear; close; format('v',8); //Given Data : p1=0.02;//bar hg1=2535.5;//KJ/Kg(at 0.02 bar) p2=0.03;//bar hg2=2545.6;//KJ/Kg(at 0.03 bar) delta_h12=hg2-hg1;//KJ/KgK p3=0.024;//bar p4=0.02;//bar delta_h=delta_h12/0.01*(p3-p4);//KJ/KgK hg_dash=hg1+delta_h;//KJ/Kg disp(hg_dash,"Specific en...
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clear; clc; close; Vcc = 12; Rc = 2.2*10^(3); Icsat = Vcc/Rc; disp(Icsat,'saturation current(Amperes) for network is :');
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//Exa 6.21 clc; clear; close; format('v',7); //Given Data : m1=5;//Kg p1=5;//bar Tsup1=200;//degree C p2=0.1;//bar h1=2855;//KJ/Kg(from molliers diagram) h2=2235;//KJ/Kg(from molliers diagram) W=m1*(h1-h2);//KJ disp(W,"Workdone in KJ : "); //Steam table is used to get some data.
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// The code was developed under Horizon2020 Framework Programme // Project: 748767 — SIMFREE function Out=SSSoWavePlate(In,Retardation_deg) // Wave Plate // // Calling Sequence // Out=SSSoWavePlate(In,Retardation_deg) // // Parameters // In : Optical Input // Retardation_deg : Ret...
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//clc() disp("f(x,y) = 4*exp(0.8*x) - 0.5*y") //f'(x,y) = 4*exp(0.8*x) - 0.5*y h = 1; x = -3:h:4; y(1) = -4.547302; y(2) = -2.306160; y(3) = -0.3929953; y(4) = 2; y1(4) = 2; for i = 4:7; y(i+1) = y(i-3) + 4*h*(2*(4*exp(0.8*x(i)) - 0.5*y(i)) - 4*exp(0.8*x(i-1)) + 0.5*y(i-1) + 2*(4*exp(0.8*x(i-2)) - 0.5*y...
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//chapter15 //example15.10 //page333 P_total=4 // W T_Jmax=90 // degree celcius theta=10 // degree celcius per watt // P_total=(T_Jmax-Tamb)/theta so making Tamb as subject we get Tamb=T_Jmax-P_total*theta printf("maximum ambient temperature at which transistor can be operated = %.3f degree C \n",Tamb)
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function [x, d, k, r] =GaussSeidel_inv(A, b, x0, E, M, n) Linv = inv(tril(A)); U = triu(A, 1); Mg = -Linv*U; cg = Linv*b; x = Mg*x0 + cg; k = 0; while((norm(x-x0, n)>=E) && (k<M)) x0 = x; x = Mg*x0 + cg; k = k + 1; end d = norm(x-x0, n); r = norm(b-A*x, n); endfunction
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//example 1.6b clc; funcprot(0); // Initialization of Variable Vin=4;//V Vs=1.8;//V Rf=10000;//ohm Ri=1100;//ohm Rl=2;//ohm Rs=0.1;//ohm //calculation Irf=Vin/(Rf+Ri); disp(Irf*1e6,"input resistor current in microamp:") Vni=Irf*Ri; disp(Vni*1000,"inverting voltage 1 & 2 in mV:") Ir=Vni/Rs; disp(Ir,"curre...
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//A Textbook of Chemical Engineering Thermodynamics //Chapter 2 //First Law of Thermodynamics //Example 7 clear; clc; //Given: I = 0.5; //current in Amperes V = 12; //voltage in volts t = 5*60; //time in sec m = 0.798; //mass of water vaporised in g M = 18; //molecular mass of water in g //To calc...
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clear // // // //Variable declaration NA=0.40; //numerical aperture delta=1/100; //relative difference //Calculations i0=asin(NA); //acceptance angle(radians) i0=i0*180/%pi ; //acceptance angle(degrees) N=1-delta; thetac=asin(N); //critical angle(radians) thetac=thetac*180/%pi ; ...
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// Example 6.4, Page No-275 clear clc N=2 fh=2*10^3 C=0.1*10^-6 R=1/(2*%pi*fh*C) Rkohm=R/1000 printf('R= %.1f kohm', Rkohm) alpha=1.414 A=3-alpha RfbyRi=A-1 printf('\nRf/Ri= %.3f', RfbyRi) printf('\nHence, take Rf=5.86 kohm and Ri=10 kohm')
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clc clear mprintf('Mechanical vibrations by G.K.Grover\n Example 1.6.2\n') //given data //Z=r*e^(i*theta) is represented as Z=r*cos(theta) + i*r*sin(theta)= x +i*y //where r*cos(theta)=x and r*sin(theta)=y //case 1 //V=5*e^(j*0.10) r1=5 theta1=0.1 x1=r1*cos(theta1) y1=r1*sin(theta1) v1=complex(x1,y1) //cas...
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clear; clc; // RDMP-MULT-1.sce // 1) A => B // 2) B => C // 3) C => B // 4) B => D // Isotermo // SISTEMA DE ECUACIONES DIFERENCIALES function dxdt = f(t,x) // Variables diferenciales CA = x(1) CB = x(2) CC = x(3) CD = x(4) // Velocidades de reacción r1 = k1*CA r2 = k2*CB r3 = k3*C...
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global Z0; Z0=50; //define the S-parameters of the transistor s11=0.3*exp(%i*(+30)/180*%pi); s12=0.2*exp(%i*(-60)/180*%pi); s21=2.5*exp(%i*(-80)/180*%pi); s22=0.2*exp(%i*(-15)/180*%pi); //pick the noise parameters of the transistor Fmin_dB=1.5 Fmin=10^(Fmin_dB/10); Rn=4; Gopt=0.5*exp(%i*45/180*%pi); //compute a nois...
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clear;lines(0); [m,n]=max([1,3,1]) [m,n]=max([3,1,1],[1,3,1],[1,1,3]) [m,n]=max([3,-2,1],1) [m,n]=max(list([3,1,1],[1,3,1],[1,1,3])) [m,n]=max(list(1,3,1))
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clc clear //Input data A1=465.125 //Cross sectional area at entry in cm^2 T1=26.66+273 //Static temperature at section-1 in K P1=3.4473 //Static Pressure at section-1 in bar C1=152.5 //Velocity at section-1 in m/s P2=2.06838 //Static Pressure at section-2 in bar T2=277.44 //Static temperature at section-2 in ...
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//Chapter-3, Example 3.5, Page 3.13 //============================================================================= clc clear //INPUT DATA P=6;//Number of poles f=50;//Supply frequency in Hz Tm=120;//Shaft torque in N.m f1=2;//Rotor current frequency in Hz L=5;//Amount of constant losses in N.m C=500;//Amou...
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-- VectorCAST 21.sp3 (08/04/21) -- Test Case Script -- -- Environment : MANAGER4 -- Unit(s) Under Test: manager_Rev -- -- Script Features TEST.SCRIPT_FEATURE:C_DIRECT_ARRAY_INDEXING TEST.SCRIPT_FEATURE:CPP_CLASS_OBJECT_REVISION TEST.SCRIPT_FEATURE:MULTIPLE_UUT_SUPPORT TEST.SCRIPT_FEATURE:REMOVED_CL_PREFIX TEST.SCRIP...
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669468710=4 101440296=4 1697572491="KING of HEARTS" 366962618=1 2030470944=7 857860171=-1 1008905993=0 2132967278="TEN of HEARTS" 1039364098="ACE of DIAMONDS" 1117409005=5 1559315561=1 1381188138=7 1196842474=2 1776074497=7 1021459996=4
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// Scilab code Exa13.6 : : Page-601 (2011) clc; clear; r = 1/2; // Radius of the tube, metre a = %pi*r^2; // Area of the torus, square metre V = 3*%pi*a; // Volume of the torus, cubic metre P = 10^-5*13.6e+3*9.81; // Pressure of the gas, newton per square metre C = 1200e-6; // Capacit...
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clear all; clc; disp("1.Convert the system specification to Qdash=10000cfm with the correesponding total pressure loss") delta_p_ldash=0.5*((10000/5000)^2) printf("\n delta(pl)dash= %0.0f in.wg.",delta_p_ldash) disp("2. Draw a system line(which is a straight line with slope of 2 on a log-log chart)passing this ...
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clc clear //input data To1=300 //Total stagnation temperature at inlet in K To2=310 //Stagnation exit temperation in K G=1300 //Mass velocity in kg/m^2-s P1=105*10^3 //Static Pressure at entry in Pa Cp=1.005 //Specific heat of dry air in kJ/kg-K R=287 //Gas constant in J/kg-K //calculation T1=(((-2*P1^2*C...
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x=[0.107533427909220; 0.663644537348001; 0.970587221665023; 0.608390883863076; -0.293540506673764; -1.42787086899790; -2.19233932281606; -1.88376277475872; 0.351621088370924; 4.20456888982602; 7.02440717036035; 6.65058196622351; 2.57013250348360; -3.50487012663216; -8.16852139220758; -8.56013313698647; -4.2042820915121...
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Pl = 396; //wattmeter reading on open circuit test Vl = 120; //voltmeter reading on open circuit test Il = 9.65; //ammeter reading o open circuit test a = 2400/120; //turns ratio theata = acos(Pl/(Vl*Il)); //phase difference between voltage and current Irl = Il*cos(theata); //resistive part of Im Ixl = Il...
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clc disp("the solution of ex 2.2 --> Pressure Drop in Pipe"); meu=1.79*10^-5 rough=.0000015 //roughness dia=.004 e_by_D=rough/dia rho=1.23 v=50 //velocity of air l=1 Re=(rho*v*dia)/meu //Reynold's number ffnew=0.01 e=1 t1=e_by_D/3.7 //term 1 of eqn. t2=2.51/Re ...
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clf; clear; clc; load('C:\Users\tangu\OneDrive\Documents\GitHub\Modelisation\TD4\NetworkData.sod') // Extraction des temps inter-arrivées t_ia = data(2:$, 2) - data(1:1237, 2); tab = tabul(t_ia, 'i'); // construction du tableau des effectifs tab(:,2) = tab(:,2)/length(t_ia); // calcul des fréquences F = cumsum(tab(:,...
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// Example 6_7 clc;funcprot(0); // Solution // P_out=(3*%pi*mu*W*omega^2*D^3)/(16*h); // P_in=(5*%pi*mu*W*omega^2*D^3)/(8*h); // n_p=P_out/P_in; n_p=(((3*%pi)/16)/((5*%pi)/8))*100;//The pump efficiency in % printf("\nThe pump efficiency,n_p=%0.0f percentage",n_p);
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a a c h a a r y a n a n d a n a a आ च ा र ् य न ं द न ा a a c h a a r y n a n d a n आ च ा र ् य न ं द न a a d i n a r a a y a n आ द ि न ा र ा य ण a a d i t y a आ द ि त ् य a a f i y a आ फ ि य ा a a j k a h i n d u s t a n आ ज क ा ह ि ं द ु स ् त ा न a a j k i a u r a t आ ज क ी औ र त a a k h r i c h e ...
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//Example 20.4. clc format(5) disp("The 741C has typical slew rate of 0.5 V/us. Using Eq.(20.8), the slew rate is,") disp(" SR = 2*pi*f*Vm / 10^6 = 0.5 V/us") vm=(0.5*10^6)/(2*%pi*(40*10^3)) // in volts disp(" = 3.98 V peak-to-peak",vm,"The maximum output voltage, Vm(V peak-to-peak) = SR*10^6 / 2*pi*f ="...
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//Exa3.1 clc; clear; close; // given data E=2.1;//in eV E=E*1.602*10^-19;// in J m=9.107*10^-31;// in kg (mass of electron) // Formula E=1/2*m*v^2 v=sqrt(2*E/m); disp(" Velocity of electron at Fermi-level is : "+string(v)+" m/s")
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//Example No. 6_11 //Fixed point method //Pg No. 161 clear ; close ; clc ; //Coefficients of polynomial in increasing order of power of x A = [ -2 1 1 ]; B = [ 2 0 -1 ]; gx = poly(B,'x','c'); x(1) = 0 ;//initial guess x0 = 0 for i = 2:10 x(i) = horner(gx,x(i-1)); printf('\n x%i = %f\n',i-1,x(i)) ...
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//clc(); clear; // To determine the order that will be visible at a point n1=21; lambda1=6000*10^(-8); // The 21st order maximum is observed for source of light in centimetres lambda2=4500*10^(-8); n2=(n1*lambda1)/(lambda2); printf("The order that will be visible if the source is replaced by 4500 Arms...
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clc; clear; a=3;//amplitude in volts Dev_sen=4;// deviation sensitivity in KHz/volts fm=1.5;// frequency modulating signal in KHz f=Dev_sen*10^(3)*3;//peak frequency deviation B=f/(fm*10^3); disp(f,"Peak Frequency Deviation( in Hz) "); disp(B,"modulation index ");
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clc; clear all; disp("Depth and Temperature") a=0.044;//m^2/h n=1400*60;// h^-1 theta=2/100; x=-((a/(3.1416*n))^0.5)*log (theta); disp("mm",x*1000,"depth x =")
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// Exa 7.14 clc; clear; close; // Given data R2= 1000;// in ohm R3= 1000;//in ohm R4= 1000;//in ohm C4= 0.5;// in miu F C4= C4*10^-6;// in F R1= R2*R3/R4;// in ohm disp(R1,"Resistance of inductor in ohm") L1= C4*R2*R3;// in H disp(L1,"Inductance of inductor in H")
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//check o/p for vector i/p k = [0.3090 0.9801 0.0031 0.0082 -0.0082]; isin = rc2is(k); disp(isin); //output // // column 1 to 4 // // 0.1999886 0.8727832 0.0019735 0.0052203 // // column 5 // // - 0.0052203
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// Copyright (C) 2012 - Prateek Papriwal // Copyright (C) 2012 - Michael Baudin // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www....
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function metPotencia() A = [-1, -4, 0, -3; 0, 2, 0, 0; 1, 4, 2, 0; 18, 10, 16, 1] e=0.0001 y0=[1;1;1;1] disp(A) interacoes = 1 //Número de Interações erro=1 alphaAntigo=0; while (erro>...
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//scilab 5.4.1 clear; clc; printf("\t\t\tProblem Number 11.25\n\n\n"); // Chapter 11 : Heat Transfer // Problem 11.25 (page no. 602) // Solution //In problem 11.24, A COUNTERFLOW HEAT EXCHANGER is operated in the parallel flow //Hot oil enters at 215 F and leaves at 125 F //Water enters the unit at 60 F an...
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// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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A=[0 0 0 1;1 0 1 1;1 0 0 1;1 0 1 0]; disp(A,'adjacency matrix of graph G is') A2=A^2 A3=A^3 disp('the number of ones in A is equal to the number of edges in the graph i.e 8')
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// Muratcan İTAP Sezgisel yöntemler ve uygulamaları dersi projesi // Sinyal iletim katsayıları matrisinin oluşturulmasını yapan fonksiyon // Minimum ve Maximum değerler arasından rastgele seçilmiştir. // Minimum ve Maximum değerler denemeler sonrası optimum olanları alınmıştır. function Coefficient_Matrix = coeffi...
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// Exa 9.1 clc; clear; close; // Given data V_TN = 0.7;// in V W = 45*10^-4;// in cm L = 4;// in µm L = L * 10^-4;// in cm t_ox = 450;// in Å t_ox = t_ox*10^-8;// in cm V_GS = 1.4;// in V Miu_n = 700;// in cm^2/V-s Epsilon_ox = (8.85*10^-14)*(3.9);// in F/cm k_n = (W*Miu_n*Epsilon_ox)/(2*L*t_ox);// A/V^2 ...
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Power=(modE*sin(w.*t+thetaE)).*(modI*sin(w.*t+thetaI)); plot(t,Power);
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clc //initialisation of variables e= 0.266 //v R= 0.0592 //CALCULATIONS pH= e/R //RESULTS printf (' pH of the unkown solution= %.2f ',pH)
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anjary nanjary V;PST amoy hamoy V;FUT andrakaraka handrakaraka V;FUT anamasina anamasina V;NFIN ifindra nifindra V;PST ankatelina mankatelina V;PRS ifarimbona hifarimbona V;FUT iondrana hiondrana V;FUT ifanila hifanila V;FUT angarika hangarika V;FUT anafy anafy V;NFIN ikororosy ikororosy V;NFIN andetsy andetsy V;NFIN i...
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clc clear x=[0 0.1 0.2 0.3 0.4 0.5 0.6] for i=1:7 A(1,i)=-1+1.*x(1,i)-1.5.*x(1,i).*x(1,i)+0.5.*x(1,i).*x(1,i).*x(1,i)-0.125.*x(1,i).*x(1,i).*x(1,i).*x(1,i) B(1,i)=-3.*exp(-x(1,i))-2*x(1,i)+2 end for i=1:7 T=[x(1,i), A(1,i), B(1,i), B(1,i)-A(1,i)] disp(T) end
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clc cp = 1.005 // Specific heat capacity of air in kJ/kgK T2 = 160 // Compressed air temperature in degree Celsius T1 = 25 // Ambient temperature T0 = 25 // Ambient temperature R = 0.287 // Gas constant P2 = 8 // Pressure ratio P1 = 1 // Initial pressure of gas in bar Q = -100 // Heat loss to surrounding in kW...
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function shallowwaterviz() //Executed from scilab using format and system boxes //with the command: // /usr/bin/scilex -nw -nb -f run_wave2d_dx.sce //tdp=getenv('SCILAB_HOME')+'/share/scilab/contrib/iome_toolbox/loader.sce'; //tdp='/usr/share/scilab/contrib/iome_toolbox/loader.sce'; tdp=getenv('SCILAB_...
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function image_out=filtre_median(matrice) SizeX = size(matrice,1); SizeY = size(matrice,2); // création d'un tableau de zeros image_out = zeros(SizeX,SizeY); // for chaque pixels for i = 1:SizeX, for j = 1:SizeY if i == 1 & j == 1 then matrice_median = [matrice(i,j),matrice(i,j),matrice(i...
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//This is script to define a fuction function y = func(t) y = cos(t)*sin(t) - tan(t) + 1 endfunction