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//Exa 9.7 clc; clear; close; //Given data : P=100000;//in Rs F=20000;//in Rs n=8;//in years i=12;//in % per annum A=(P-F)*(i/100)/(((1+i/100)^n)-1);//in Rs. disp("In this method of depreciation, a fixed amount of Rs. "+string(A)+" will be depreciated at the end of every year from the earning of the asset. Th...
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//scilab 5.4.1 //Windows 7 operating system //chapter 17 Number Systems,Boolean Algebra,and Digital Circuits clc clear x=25 s=dec2bin(x) disp(,s,"1 Binary equivalent of 25 is ") y=576 s1=dec2bin(y) disp(,s1,"2 Binary equivalent of 576 is ")
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// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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style.fontSize=12; style.displayedLabel="<table> <tr><td align=center>DC<br>Voltage</td></tr></table>"; pal6 = xcosPalAddBlock(pal6,"dac",[],style);
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//chapter 24 Ex 27 clc; clear; close; rev=1000; distTotal=88; dist=(distTotal/1000)*rev; rad=dist/(2*(%pi)); mprintf("The radius of wheel is %d meter",rad);
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clc //initialisation of variables T= 298.16 //K M= 4.003 //gm S= 2.3151 //cal mol^-1 deg^-1 R= 1.987 //cal/molK //CALCULATIONS S1= 2.5*R*log(T)+1.5*R*log(M)-S //RESULTS printf (' Absolute Entropy= %.3f cal mol^-1 deg^-1',S1)
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clc;clear all;close; fd=1250; fs=10000; r=0.99; wd=%pi*2*fd/fs; i=1; for w=0:0.0001:2*%pi; Hejw(i)=((cos(2*w)+%i*sin(2*w))+1-(2*cos(wd)*(cos(w)+%i*sin(w))))/((cos(2*w)+%i*sin(2*w))+(r^2)-r*(2*cos(wd)*(cos(w)+%i*sin(w)))); i=i+1; end Hmag=20*log(abs(Hejw)); w1=0:0.0001:2*%pi; w2=w1*10000/(2*%pi); plot(w2, abs(Hejw)) ;
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//example 9.2 clc; funcprot(0); // Initialization of Variable T2=898.3; T1=300.0; T4=887.7; vr3=3.97; V1=0.861; R=8314;//gas constant u4=664.3; u1=214.07; h3=1999.1; h2=930.98; p1=0.1; k=18.0;//V1/V2 rc=2.0;//V3/V2 p2=k*p1*T2/T1; disp(p2,"pressure in atm"); T3=rc*T2; disp(T3,"temperature in K"); vr4...
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function result = iscatastrophic(trellis) // This function determines if a convolutional code is catastrophic or not // Calling Sequence // RESULT = ISCATASTROPHIC(TRELLIS) // Description // RESULT = ISCATASTROPHIC(TRELLIS) returns 1 if the specified // trellis corresponds to a catastrophic convolution...
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<cmd> ./main_test/lexer_tst "echo '42sh is strong';"</cmd> <ref> cat ./lexer/test4.ref</ref> <ret> 0</ret>
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//example 5.7 //page 204 clc; funcprot(0); //initialisation of variable V1=40;//velocity Vp=20;//velocity pi=3.14; th1=30/180*pi;//angle th2=20/80*pi;//angle g=9.81; th=atan(V1*sin(th1)/(V1*cos(th1)-Vp)); V1r=V1*sin(th1)/sin(th); V2r=V1r; //on solving phi=4/180*pi; V2=V2r*sin(phi)/sin(th2); V2w=V2*co...
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Start SERVICE(NSQKILL)
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clear; clc; Vm=200 //voltage in V Rf=500 //resistance in series in ohm Rl=1000 //load resistance in ohm //Calculation Im=Vm/(Rf+Rl) Idc=(2*Im)/%pi Irms=Im/sqrt(2) Y=sqrt((Irms/Idc)^2-1) mprintf("(a)Maximum current Im= %0.3f A\n",Im) mprintf("(b)dc component of current Idc= %1.4f A\n",Idc) mprintf("(c)...
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//Chapter 5, Problem 24, figure 5.72 clc Rs=10 //resistance in ohm Rl=50 //resistance in ohm Q=10 //Q factor //calculation Rv=Rs*(Q^2+1) Xs1=Q*Rs Xp1=Rv/Q Q2=sqrt((Rv/Rl)-1) Xp2=Rv/Q2 Xs2=Q2*Rl printf("Zs = %d ohm\nXp1 = %.3f ohm \nXs1 = ...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Introduction to heat transfer by S.K.Som, Chapter 7, Example 5") //A flat plate of width B=1m is maintained at a uniform surface temprtaure(Tw)=225°C Tw=225; B=1; //Heating is done by rectangular modules of thi...
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# io_write.tst # # Basic IO writing functionality # open "data2.tmp" expect 0x8000004C open "data2.tmp" write expect 0 read 0 0x100 1w.tmp portion expect 0 0 0 write 0 result1.dat expect 0 0x213 write 0x213 result2.dat expect 0 0x1EC write 0x1584 result3.dat expect 0 0xD0 get_size expect ...
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funcprot(0) function error_minimise() disp("-------------------------------------------------------------") disp("BEST FIT LINE") disp("-------------------------------------------------------------") n=input("Enter the number of lines/points : "); printf("\n") A(1,1)=0 b(1,1)=0 ...
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errcatch(-1,"stop");mode(2);//Example 11.4: ARRAYED GUIDE ; ; //given data : c=3*10^8; lamda_c=1.55*10^-6;// in m vc=c/lamda_c; n=16;// number of channel f=100*10^9;// in Hz delV_FSR=n*f; m=round(vc/delV_FSR); disp(m,"required order of the arrayed waveguide, = ") exit();
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s=6.9;// начальное расстояние от лодки до катера fi=3*%pi/4; //функция, описывающая движение катера береговой охраны function dr=f(tetha, r) dr=r/sqrt(3); endfunction; //начальные условия в случае 2 r0=3.63; tetha0=-%pi; tetha=0:0.01:2*%pi; r=ode(r0,tetha0,tetha,f); //функция, описывающая движение лодки брак...
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ex1_6.sce
clc; clear all; l = 0.4 // Length in meter A = 240e-4 // Area of slab in meter square F = 1e5 // Shaering force in newton n = 5.6e9 // Shear modulus in pa deltal = (F*l)/(n*A); disp('m',deltal,'The displacement is ')
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// Electric Machinery and Transformers // Irving L kosow // Prentice Hall of India // 2nd editiom // Chapter 6: AC DYNAMO VOLTAGE RELATIONS-ALTERNATORS // Example 6-5 clear; clc; close; // Clear the work space and console. // Given data kVA = 100 ; // kVA rating of the 3-phase alternator V_L = 1100 ; //...
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//data u=[1;2;3;4]; z=[2;4;7;14]; H=[u(1)*u(1) u(1) 1;u(2)*u(2) u(2) 1;u(3)*u(3) u(3) 1;u(4)*u(4) u(4) 1]; Cnz=[0.1 0 0 0;0 1 0 0; 0 0 1 0; 0 0 0 0.1]; //least squares solving s_ls = inv(H'*H)*H'*z; //weighted least squares solving s_wls = inv(H'*inv(Cnz)*H)*H'*inv(Cnz)*z; //plot r=[0:0.1:20]; plot(r, ( s_ls(1)*r...
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for n = 1000:1:1999 if (modulo(n,11)==5) then disp (n) n=n+1 else n=n+1 end end
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Ex9_7.sce
//example-9.7 //page no-289 //given //temp T=600 //degree C //tightenening stress sigmai=750 //kgf/cm^2 //minimum creep rate vcr=2.8*10^-8 //cm/cm/hour //stress sigma=300 //kgf/cm^2 //young's modulus E=2*10^6 //kgf/cm^2 //constant n=3 //we knnow that minimum creep rate //vcr=A*sigma^n //so A=...
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7_01.sce
//Problem 7.01: A magnetic pole face has a rectangular section having dimensions 200 mm by 100 mm. If the total flux emerging from the pole is 150 μWb, calculate the flux density. //initializing the variables: Phi = 150E-6; // in Wb l = 200E-3; // in m b = 100E-3; // in m //calculation: A = l*b B = Phi/A ...
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function [L,A,C] = fatoraLU(A) n = size(A,1) L = eye(n,n) C = 0 for j = 1:n-1 for i = j+1:n L(i,j) = A(i,j)/A(j,j) C = C + 1 A(i,j+1:n) = A(i,j+1:n) - L(i,j)*A(j,j+1:n) if(A(i,j+1:n) == 0) if(L(i,j) ~= 0 && A(j,j+1:n) ~= 0) ...
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Ex2_21.sce
//Ex:2.21 clc; clear; close; E_o=8.85*10^-12; E_r=5.4; C=1*10^-9; d=0.1*10^-3; A=(C*d)/(E_o*E_r)*10^4; printf("Required plate area = %f sq. cm",A);
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Ex11_5.sce
// Variable declaration l = [ 20 0.18; 60 0.37; 100 0.35; 140 0.78; 180 0.56; 220 0.75; 260 1.18; 300 1.36; 340 1.17; 380 1.65 ] alpha = 0.05 beta = 0.0 // Calculation x = l(:,1) y = l(:,2) s1 = sum((x.^2)) - (sum(x))^2/10.0 s2 = sum(x.*y) - (sum(x)*sum(y))/10.0 s3 = sum((y).^2) - (sum(y))^2/10.0 t_thr = 2.306 /...
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Example3_30.sce
//Example 3.30 //Program to Calculate N from given data //fm=5000Hz //df=50Hz //t=0.5sec clear; clc ; close ; fm=5000 //Hz df=50 //Hz t=0.5 //sec N1=2*fm/df; N=2; while N<=N1, N=N*2,end //Displaying the value of N in command window disp(N,"N=");
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// File name: projects/08/FunctionCalls/StaticsTest/StaticsTest.tst load StaticsTest.asm, output-file StaticsTest.out, compare-to StaticsTest.cmp, output-list RAM[0]%D1.6.1 RAM[261]%D1.6.1 RAM[262]%D1.6.1; set RAM[0] 256, repeat 2500 { ticktock; } output;
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9_3.sce
clc //initialisation of variables p=40//ft d=56//ft d1=140//ft p1=30//ft w=3.28*10^-4//fps //CALCULATIONS Q=w*(p/d1)*2*d*p//cfs q=Q/p//cfs K=w*(p/d1)//fps x0=q/(2*%pi*K)//ft Z=2*%pi*x0//ft //RESULTS printf('the yield of the well if the coefficient of permeability=% f ft',x0) printf('the distance of the p...
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Ex5_22.sce
//example 22 clear rb1=7.5*10^3;//ohm rb2=6.8*10^3;//ohm rb3=3.3*10^3;//ohm re=1.3*10^3;//ohm colres=2.2*10^3;//ohm beta1=120; vcc=18;//volt vb1=rb3*vcc/(rb3+rb2+rb1); ie1=(vb1-0.7)/(re); re1=0.026/ie1; re2=0.026/ie1; volgai=colres/re2; disp("voltage gain = "+string((volgai)));
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Ch5_5_36.sce
clc disp("Example 5.36") printf("\n") disp("calculate open loop cut-off frequency if the open loop gain is 200000") printf("Given\n") //open loop gain Av=200000 //closed loop gain Acl=250 //upper cut-off frequency with feedback F2CL=4*10^6 //upper cut-off frequency without feedback F2OL=F2CL/(Av/Acl) prin...
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Ex7_9.sce
clc clear //Input data V1=1000//Speed in m/s Vb=400//Peripheral velocity in m/s a=20//Nozzle angle in degree m=0.75//Mass flow in kg/s f=80//Percentage reduction of relative velocity //Calculations b1=atand((V1*sind(a))/((V1*cosd(a))-Vb))//Blade angle in degree V=342//Velocity from E7.9 in m/s Vr1=V/sind(...
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clc e=1.6*10^-19 disp("e = "+string(e)+" columb") //initializing the value of electronic charge. Ef=0.4065 disp("Ef = "+string(Ef)+" eV") //initializing the value of fermi level. n=10^17 disp("n = "+string(n)+" /cm^3") //initializing value of number of electrons per cm^3. T=300 disp("T = "+string(T)+" K") //ini...
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//Exa:1.31 clc; clear; close; f=50;//in hertz P1=6;//No. of poles P2=4;//No.of poles N_s1=120*f/P1;//Synchronous Speed of 6-pole motor N_s2=120*f/P2;//Synchronous Speed of 4-pole motor N_sc1=120*f/(P1+P2);//Concantenated Speed of set when cumulatively compounded (in rpm) N_sc2=120*f/(P1-P2);//Concantenated Sp...
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//Example 5.17 // fluxmeter clc; clear; close; //given data : N1=800;// turns I=5;// in A l=1;// in m A=5*10^-4;// in m^2 N=500;// turns theta=25;// divisions H=(N1*I)/l; B=(4*%pi*10^-7*H); fi=B*A*10^8; K=((2*N*fi*10^-8)/(theta)); disp(K*10^-3,"Constant is,(Wb-turn/scale-div)=")
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errcatch(-1,"stop");mode(2);//Example 3_1 ; ; //To calculate the thickness of a half wave plate lemda=500*10^-9 //units in meters ue=1.553 u0=1.544 t=(lemda/(2*(ue-u0)))*10^3 printf("Thickness of quartz half wave plate is %.4f mm",t) exit();
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population = [7333253 3448613 2731743 1702086 1524249 1151977 1048949 1022830 998905 992038 816884 752279 734676 702979 665070 635913 617044 614289 579307 567094 547727 520947 514013 504505 493559]; disp(perctl(population, 10), "The sample 10 percentile is") disp(perctl(population, 80), "The sample 80 percentile is")...
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clc //initialisation of variables t=12//hp N=1500//rpm p=44760//N m //CALCULATIONS T=(t*p)/((2*%pi)*(N))//N.m //RESULTS printf('The fluid power motor turning at=% f N.m',T)
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//Example 2.12://power factor and capacitance clc; clear; close; w1=-2000;//watts w2=4000;//watts ph=atand((sqrt(3)*(w2-w1))/(w2+w1));//in degree pf=cosd(ph);// disp(pf,"power factor of the system is") w=w1+w2;//total power v=400;//volts vp=(v/sqrt(3));//phase voltage pp=w/3;//power per phase pi=(pp)/(vp*pf);//phase cu...
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Norm_Dis_Diff_Two_Mean.sci
function [Z]= Norm_Dis_Diff_Two_Mean(X1,X2,Sigma1,Sigma2,n1,n2) u1 =0; u2 =0; Sigma12 = (Sigma1/n1)+(Sigma2/n2); Z = ((X1-X2)-(u1-u2))/(sqrt(Sigma12)); endfunction
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inseparable.tst
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ex_2_17.sce
//example 2.17// //division in binary// clc //clears the window// clear //clears already existing variables// x=bin2dec('1110101') //x is the first number// //binary to decimal conversion// y=bin2dec('1001') //y is the second number w/c is to be divided// z=x/y //division// a=dec2bin(z) //decimal to binar...
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9_7.sce
//Example 9.7 //Givens QR Method //Page no. 303 clc;clear;close; A=[4,2,1;2,5,-2;1,-2,7] deff('y=c(i,j)','y=A(j,j)/sqrt((A(i,j)^2+A(j,j)^2))') deff('y=s(i,j)','y=A(i,j)/sqrt((A(i,j)^2+A(j,j)^2))') disp(A,'A=') R=A;Q=eye(3,3); m=1; for j=1:2 for i=j+1:3 for k=1:3 //C matrix evaluati...
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//Exa 4.5 clc; clear; close; format('v',8); //Given Data : mc=0.5;//Kg Tc=100+273;//K Cpc=0.393;//KJ/KgK Tw=10+273;//K Cpw=4.2;//KJ/KgK Q=integrate('mc*Cpc','T',Tc,Tw);//KJ deltaSc=integrate('mc*Cpc/T','T',Tc,Tw);//KJ/K deltaSw=abs(Q)/Tw;//KJ/K deltaSuniverse=deltaSc+deltaSw;//Kj/K disp(deltaSuniverse,...
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//EXAMPLE 2-111 PG NO-147 VCB=2.49-%i*12.50; R=4+%i*2; I1=VCB/R; disp('i) CURRENT (I1) is in polar form = '+string (I1) +' A '); I2=2.5+%i*0; I=I1+I2; disp('i) CURRENT (I) is in polar form = '+string (I) +' A '); VAC=11.8-%i*0.12; VCB=2.5-%i*12.5; VAB=VAC+VCB; disp('i)...
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9_2.sce
clc //initialisation of variables m= 10000 //kg/h P= 2.5 //Mpa P1= 100 //kPa v= 0.001003 //m^3 //CALCULATIONS W= -m*v*(P*10^3-P1)/3600 //RESULTS printf (' work of the pump = %.3f kW',W)
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ex89.sce
clc; // Define the polynomial z=poly(0,"z"); p=5+3*z+2*z^2+2*z^3+z^4+z^5; // Calculate the routh of above polynomial r=routh_t(p);
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EXAMPLE11_47.SCE
//ANALOG AND DIGITAL COMMUNICATION //BY Dr.SANJAY SHARMA //CHAPTER 11 //Information Theory clear all; clc; printf("EXAMPLE 11.44(PAGENO 532)"); //given P_x1 = .05//probability of first signal P_x2 = .15//probability of second signal P_x3 = .2//probability of third signal P_x4 = .05//probability of fourth s...
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//Section-12,Example-7,Page no.-SS.61 //To find the no.of charge carriers essential to get te given conductivity and the no. of Antimony dopant atoms to be added to germanium. clc; C=100 e=1.6*10^-19 u_e=2800 N_D=C/(e*u_e) disp(N_D,'No.of charge carriers essential to get the given conductivity(per cm^3)') a=5.6...
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ex12_9.sce
//ex12.9 f_c=100; f=1; theta=phase_shift(f,f_c); disp(theta,'phase lag when f=1Hz (in degrees)') f=10; theta=phase_shift(f,f_c); disp(theta,'phase lag when f=10Hz (in degrees)') f=100; theta=phase_shift(f,f_c); disp(theta,'phase lag when f=100Hz (in degrees)') f=1000; theta=phase_shift(f,f_c); disp(theta,'...
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Ex4_2.sce
//Harriot P.,2003,Chemical Reactor Design (I-Edition) Marcel Dekker,Inc.,USA,pp 436. //Chapter-4 Ex4.2 Pg No. 140 //Title:Effective diffusivity of O2 in air //============================================================================================================ clear clc // COMMON INPUT S_g=150;//Total sur...
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run3_VisMMN.sce
scenario = "run3_VisoddballPlusMMN_pronetSZAMP_09042021"; #======================================== # #Visual Task: # #Tone1 16 #Tone2 18 #Response 17 #Standard 32 #Target 64 #Novel 128 # #======================================== #attenuation updated for ER1 insert earphones and X-fi gamer card pcl_file = "nvMMNComman...
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global chip_num board_num brdtype; diode_ivdd25V=csvRead("~/rasp30/prog_assembly/libs/scilab_code/characterization/char_diodeADC/data_diodeADC_chip"+chip_num+brdtype+"_ivdd25V"); //polyfit [p1,S1]=polyfit(diode_ivdd25V(:,4), log(diode_ivdd25V(:,2)),10); //coefficients of polynomial that correspond to current //[p_i2v...
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//Exa 11.5 clc; clear; close; //Given Data : format('v',9); Energy=25*10^6;//in kwh MaxDemand=1600;//in KW //(i) Rs. 70/KW max demand plus 2 paise per kwh C1=70;//in Rs.year/KW C2=2;//in paisa/unit AnnualCost=MaxDemand*C1+(C2/100)*Energy;//in Rs. disp(AnnualCost,"Case (i) Annual cost of energy(in Rs.) :"); ...
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0069.tst
SPLiTTeR Z {} filTEr P { } FILTEr RD {x oR O EGo OR Not X Or nOT js OR NOT FuPRo or o OR v Or not R Or NOt gk OR noT CW OR not n OR m } I -> D groUpER pK {AGgrEgATE Bitand(xw.g) as Z ,D } UNgrOUPER C { } gROupFiLTeR L {not 6 >> i } mergEr byWm { exPORt S }
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17_1.sce
errcatch(-1,"stop");mode(2);//Calculate molecular weight //Ex:17.1 ; ; mc=12;//mol wt of carbon mh=1;;//mol wt of hydrogen m=8*(mc+mh);//mol wt of C8H8 DOP=10000;//degree of polarization , given mp=DOP*m; disp(mp,"Molecualr weight of Styrene polymer = "); exit();
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//1ère étape - Load path_name = "..\images\Mars_Surface.pbm"; img_in = readpbm(path_name); //Step 2 - Show display_gray(img_in); //Etape N°3 - Save writepbm(img_in, '..\images\Première Création.pbm');
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9_2.sce
//Centroid of angle //refer fig. 9.11 //the given figure can be divided into two rectangles A1=150*12 //mm^2 A2=(200-12)*12 //mm^2 //total area A=A1+A2 //mm^2 xbar=(1800*75+2256*6)/(4056) //mm ybar=(1800*6+2256*106)/(4056) //mm printf("The centroid is at \nxbar=%.2f mm\nybar=%.2f mm ",xbar,ybar)
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5_25.sce
clc //initialisation of variables l= 2 //miles Q= 2*10^6 //gal/day d= 12 //in t= 16 //sec w= 62.4 //lb/ft^3 g= 32.2 //ft/sec^2 //CALCULATIO Q1=Q*10/(w*24*60*60) hi= l*5280*Q1/((%pi*(d/12)^2/4)*(g*t)) //RESULTS printf ('height = %.1f ft ',hi)
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Example6_5c.sce
clear; clc; //Caption:If input is high in NAND gate //Given Data //For transistor Vbesat=0.8;//in V Vy=0.5;//in V R = 5;//in K Rc = 2.2;//in K //For diode Vyd=0.6;//in V Vdrop=0.7;//in V //The logic levels are Vcesato=0.2V for 0 state Vcesato=0.2;//in V Vp = Vdrop + Vdrop + Vbesat;//Voltage at poi...
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//Exa 2.13 clc; clear; close; //Given data : format('v',5) n1=1.52;//unitless fi_o=8;//in Degree //Formula : sin(fi_o)=n1*sqrt(2*delta) delta=(sind(fi_o)/n1)^2/2;//Relative refractive index disp("The value of relative refractive index difference is "+string(delta*100)+"%");
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HydrauliqueP.sci
function [q,z,f,p]=HydrauliqueP(qc) /////////////////////////////////////////////////////////////////////////////// // // // CALCUL DES VARIABLES HYDRAULIQUES DU RESEAU A PARTIR DU DEBIT DU CO-ARBRE // // ...
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ii_1.sce
// Computing Induced EMF clc; clear; l=0.5; v=50; b=1; // Angles x=90; y=30; z=0; // EMFs e1=b*l*v*(sind(x)); e2=b*l*v*(sind(y)); e3=b*l*v*(sind(z)); disp('volts',e1,'i) The Induced EMF perpendicular to the field') disp('volts',e2,'ii) The Induced EMF at an angle 30 degrees to the field') dis...
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example2.sce
// find output voltage,load,collector current // Electronic Principles // By Albert Malvino , David Bates // Seventh Edition // The McGraw-Hill Companies // Example 24-2, page 954 clear; clc; close; // Given data Vin=15;// input voltage Rs=10;// in ohms Vz=6.2;// in volts Vbe=0.81;// in volts Rl=40;// i...
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Ex2_9.sce
// A Textbook of Fluid Mecahnics and Hydraulic Machines - By R K Bansal // Chapter 2 - Pressure and its measurements // Problem 2.9 //Given Data Set in the Problem SG1=0.9 SG2=13.6 g=9.81 //Calculations dens1=SG1*1000 dens2=SG2*1000 h2=20/100 h1=h2-12/100 //Equating pressure at 20 cm below th right arm ...
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FactorizacionLU.sci
function [x,L,U,P] = factLU(A,b) [m,n] = size(A); tol = 1e-9; indx = [1:n]; P=eye(m,n); for k = 1 : n-1 aux = [k:n] [max_pivot,indxmax] = max(abs(A(indx(aux),k))); // control de pivot if(max_pivot < tol) disp("No se puede segu...
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Example12_8.sce
clear; clc; // Illustration 12.8 // Page: 705 printf('Illustration 12.8 - Page: 705\n\n'); // Solution //***Data***// x1 = 8;// [percent moisture] x2 = 0.5;// [percent moisture] Rate_prod = 0.63;// [kg/s] // Drying Gas: xCO2 = 0.025;// [mole fraction] xO2 = 0.147;// [mole fraction] xN2 = 0.760;// ...
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Ex7_4.sce
//pagenumber 372 example 4 clear ids=4*10^-3;//ampere vp=4;//volt r=1.3*10^3//ohm r1=200*10^3;//ohm vdd=60;//volt drares=18*10^3;//ohm soresi=4*10^3;//ohm rth=(r*r1)/(r+r1); vth=r1*(1-vdd)/(1500*10^3); id=-2.25*10^-3; vds=-vdd-(drares+soresi)*id; disp("id = "+string(abs(id))+"ampere"); disp("vds = ...
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bpgf3err.tst
(unwatch all) (clear) (set-strategy depth) (open "bpgf3err.rsl" bpgf3err "w") (dribble-on "bpgf3err.out") (batch "bpgf3err.bat") (dribble-off) (load "compline.clp") (printout bpgf3err "bpgf3err.bat differences are as follows:" crlf) (compare-files bpgf3err.exp bpgf3err.out bpgf3err) ; close result file (close bpgf3err)...
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10_20.sce
P=25000 n=1600 V=250 If=1.5 Rf=V/If disp(Rf) Ra=0.1 V=220 Ia=P/V Ea=V-Ia*Ra If=0.875 disp(If) Rf=V/If disp(Rf) Pdev=Ea*Ia disp(Pdev) Tdev=Pdev/2/%pi/n*60 disp(Tdev)
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Example7_29.sce
//Chapter-7,Example7_29,pg 7-88 Im=90 Ic=40 delta=28*(%pi/180)//in radians Is=5 Ns=400 Np=1 n=Ns/Np Kn=n R=n+((Im*sin(delta)+Ic*cos(delta))/Is) Ip=R*Is//actual primary current err=(Kn-R)/R err=err*100 printf("percentage ratio error\n") printf("err=%.2f ",err)
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78.sce
// problem 7.8 b=1.4 d=1.4 n=1/4 i=1/700 N=0.025 a=d*(b+(n*d)) p=b+(2*d*((n*n+1)^0.5)) m=a/p q=(a*(m^0.6666)*(i^0.5))/N disp(q*1000,"discharge from the trapezoidal channel in litres/sec")
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Ex7_8.sce
// Example 7_8 clc;funcprot(0); // Given data V=2.50*10^-3;// m^3 Sigma_Q=53.7;// W/k.m^3 tau=30.0;// min // Solution S_pQ=Sigma_Q*V*tau*60;// J/K printf('\nThe heat production of entropy inside this motor,(S_p)_Q=%3.0f J/K',S_pQ);
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Ex11_16.sce
// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Engineering Thermodynamics by Onkar Singh Chapter 11 Example 16") m1=3;//rate at which moist air enter in heating coil in m^3/s disp("The type of heating involved is sensible heating.Locating satte 1 on psychrome...
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2Ex8.sce
//chapter 2 Ex 8 clc; clear; close; n1=2; n2=8; n3=16; n4=10; d1=3; d2=9; d3=81; d4=27; VN=int32([n1 n2 n3 n4]); VD=int32([d1 d2 d3 d4]); HcfNum=gcd(VN); LcmNum=lcm(VN); HcfDen=gcd(VD); LcmDen=lcm(VD); mprintf("The HCF of fractions is %d/%.d.",HcfNum,LcmDen); mprintf("The LCM of fractions is %.d/%d.",Lcm...
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ex17_2.sce
clc;clear; //Example 17.2 //calculation of velocity of e //given values e=1.6*10^-19;//charge of e in C E=2.1*e;//fermi level in J m=9.1*10^-31;//mass of e in kg //calculation v=sqrt(2*E/m); disp(v,'velocity of e(in m/s)');
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gradientev.sce
// erro minimo vetorial function eminimov() clf();clc p=[7;9] [p,g] = gradiente(p) disp(p, 'ponto') disp(f(p(1),p(2)), 'valor minimo') disp(g(1),g(2), 'gradiente') endfunction function z = f(x, y) z = x.^2 + y.^2 + sin(x).*(x+y) + 10 endfunction function dp = dz(p) d=0.0000001 dp =...
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//Page Number: 455 //Example 9.6 clc; //Given S11=0.60; S12=0.045; S21=2.50; S22=0.50 TS=0.5; TL=0.4; Vrms=10; //V Z0=50; //ohm //(i)Reflection coefficients of input and output Tin=S11+((S12*S21*TL)/(1-(S22*TL))); Tout=S22+((S12*S21*TS)/(1-(S22*TS))); disp(Tin,'Reflection coefficients of input:'); dis...
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// 08.08.17 // 08.09.16 // 10.01.02 // 13.10.21 ( __ added to varibles ) // 14.06.09 ( debugged -- the cause unknown ) function Out__=Phcutdata(VL__,FaceL__,PlaneD__) global PHCUTPOINTL Out__=[]; EL__=[]; Eps__=10^(-4); for I__=1:Mixlength(FaceL__) Face__=Mixop(I__,FaceL__); for J__=1:length(Face__) ...
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clc //Given that mu = 1.5 // refractive index of plane glass prism theta = %pi / 180 // angle of prism y1 = 10 // separation between slit and biprism in cm y2 = 100 //separation sbetween biprism and screen in cm lambda = 0.00005893// wavelength of incident light in cm //Sample Problem 6 Page No. 48 printf("\...
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//ch-1 page -40 pb-1 // // a=23 b=16.5 c=12 t1=acos((a*a+b*b-(c*c))/(2*a*b)) t1=t1*(180/%pi) printf("\n theta1= %0.3f ",t1) t2=acos((c*c+b*b-(a*a))/(2*c*b)) t2=t2*(180/%pi) dg=int(t2) mi=t2-int(t2) mi=(mi*60) printf("\n theta2= %0.3f degrees %0.3f minutes",dg,mi)
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// Сохранение графиков function[]=save_graphics(b) b_ = 0 for i=2:length(b) b_ = b_ + (i-1)*b(i) end b_ = 1/b_ a = 0.001:0.001:b_-0.001 l = length(a) step = 0 for i=1:l a_ = 1 - a(i) tmp = a_ / (1+a_) if (get_bz(a_,b) > tmp) then ...
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// chapter 9 // example 9.3 // find the resistance of intrinsic germanium // page 272-273 // given clear; clc; ni=2.5E13; // in /cm^3 (intrinsic carrier density) ue=3900; // in cm^2/(V-s) (electron mobilities) uh=1900; // in cm^2/(V-s) (hole mobilities) e=1.6E-19; // in C (charge of electron) l=1; // in cm (...
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errcatch(-1,"stop");mode(2); //Variable declaration syms t //symbol defined et1 = complex(50,86.6) //defining complex number //calculations et = (real(et1)*sqrt(2)*cos(314*t))+imag(et1)*sqrt(2)*cos(314*t+90) //expression //Result disp ( et) exit();
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//(Power Screws) Example 6.3 //Refer Fig. 6.12 on page 197 //Number of starts n n = 1 //Nominal diameter of the screw d (mm) d = 22 //Pitch of the screw p (mm) p = 5 //Outer diameter of the friction collar Do (mm) Do = 55 //Inner diameter of the friction collar Di (mm) Di = 45 //Coefficient of friction fo...
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//CHAPTER 2- STEADY-STATE ANALYSIS OF SINGLE-PHASE A.C. CIRCUIT //Example 31 // read it as example 30 in the book on page 2.84 clc; disp("CHAPTER 2"); disp("EXAMPLE 31"); //VARIABLE INITIALIZATION //function of the waveform is deduced to be y=10+10.t/T //SOLUTION //Yav=(1/T).Integral(ydt) from 0 to T //say T=1; ...
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clc // Variable Initialization Vm=230//Supply Voltage in Volts Ra=0.75//Armature circuit resistance in Ohm I=8 //Armature current in Amp Nr=1200 //Motor speed in Rpm Va=220//Rated voltage of motor in Volts a=45//firing angle in Degree T=8 //Motor torque in N-m Nr1=800 //Speed in Rpm //Solution N=(Nr*2*%...
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main begin int a; int b; int[] array1; int[] array2; a = 0; b = 0; array1 = new int [3]; array2 = new int [3]; array1[0] = 0; array1[1] = 10; array1[2] = 100; array2[0] = 1; array2[1] = 11; array2[2] = 101; do begin do begin if (b < 1) then begin print(array1[...
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errcatch(-1,"stop");mode(2);//As the entire question is theoritical //theta is directly computed theta=acosd(2/3) //degrees //result printf('The value of theta is %f degrees',theta) exit();
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clear; clc; disp("--------------Example 3.35---------------") L=4; //number of levels bandwidth=3000; // Hz max_bitrate=2*bandwidth*log2(L); // formula to calculate maximum bit rate printf("The maximum bit rate of the noiseless channel is %d bps.",max_bitrate); // display result
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clear ; clc; // Example 18.2 printf('Example 18.2\n\n'); //Page no. 541 // Solution // Data from steam table psat_H2O = 31.8 ;// Saturation pressure -[mm of Hg] //(c) H = .0055 ;// Humidity mw_H2O = 18 ;// Molecular wt. of water-[lb] mw_air = 29 ;// Molecular wt. of air -[lb] P = 750 ;// Pressure total -[mm of H...
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clc //Initialization of variables HH2O=-241.82 //kJ/mol T1=25 //C T2=100 //C CpH2O=33.58 //J/K mol CpH2=28.84 //J/K mol CpO2=29.37 //J/K mol //calculations dCp=CpH2O-CpH2-0.5*CpO2 dH=HH2O+dCp*(T2-T1)/1000. //results printf('Enthalpy of fromation of water at 100 C is %.2f kJ/mol',dH)
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function [outputImg]=wiener2(inputImage,filtsize,sigma) inputList=mattolist(inputImage); outputList=opencv_wiener2(inputList,filtsize,sigma); for i=1:size(outputList) outputImg(:,:,i)=outputList(i) end endfunction
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//ques-22.16 //Calculating lattice energy of KCl crystal clc S=90.9; IE=418.7; EA=-348.7; D=240; H=-440.3;//(in kJ/mol) Uo=H-S-IE-D/2-EA; printf("The lattice energy of KCl crystal is %.1f kJ/mol.",Uo);
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//EX13_8 PG-13.7 clc clear printf("conversion of octal no 634 to binary equivalent is :") a=['634'] x=oct2dec(a)//first we convert to decimal y=dec2bin(x) printf("%s",y)