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clc() clear all clf() function result = solucionAnalitica(t) result = (4/1.3)*(exp(0.8*t)-exp(-0.5*t))+2*exp(-0.5*t) endfunction function result= eqdiff(y,t) result = 4*exp(0.8*t)-0.5*y endfunction function [result,points]=metodoRungeKuttaMedio(stepsize,y0, t0, tf, eqf) points = t0:stepsize:tf res...
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clear;lines(0); A=sprand(10,12,0.1); sp=spones(A) B = A~=0 bool2s(B)
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//chapter_no.-3, page_no.-84 //Example_no.3-1-1 clc; //(a)Calculate_the_line_Characteristic_Impedance R=2; L=8*(10^-9); C=.23*(10^-12); f=1*(10^9); G=.5*(10^-3); w=2*%pi*f; Z0=sqrt((R+(%i*w*L))/(G+(%i*w*C))); x=real(Z0); y=imag(Z0); o=atand(y,x); disp(o,'the_phase_of_Z0_is ='); M=abs(Z0);//magintue_of_Z0 disp(M...
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Name=VALORANT Anti Peek Training PlayerCharacters=Dodgey BotCharacters=Quaker Bot Easy.bot IsChallenge=true Timelimit=120.0 PlayerProfile=Dodgey AddedBots=Quaker Bot Easy.bot;Quaker Bot Easy.bot;Quaker Bot Easy.bot;Quaker Bot Easy.bot PlayerMaxLives=0 BotMaxLives=0;0;0;0 PlayerTeam=1 BotTeams=0;0;0;0 MapName...
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//2.17 clc; Vm=230*2^0.5; alph=40; Io=((2*Vm/%pi*cosd(alph))-50)/5; printf("Average value of load current = %.2f A", Io)
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//page 271 //Example 8.1 clc; clear; close; n = round(rand() * 10 + 2); a = round(rand(1,n) * 10) b = round(rand(1,n) * 10) disp(n,'n = '); disp(a,'a = '); disp(b,'b = '); disp(a*b','Then, (a|b) = '); //end
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clc T1=673; //K T2=473; //K T0=303; //K T1a=T2; //dSa/dS=T1/T1a // W=(T1-T0)*dS; Work done by the power cycle when there was no temperature difference between the vapour condensing and vapour evaporating // Wa=(T1-T0)*dSa; Work done by the power cycle when the vapour condenses at 400°C and vapour evaporates ...
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//ques6 clc disp('definite integral'); syms x a n=input('Enter n :'); g=exp(a*x)*(sin(x))^n; f=integ(g,x); disp(f);
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[1,2] * [1,2,-5] = [1,4,-1,-10] initial: [1,4,-1,-10] / [1,2], rem1=[1,4,-1,-10], div2=[1,2], lenq=3, len1=4, len2=2 step end: quot=[0,0,0]/qden=1, rem1=[1,4,-1,-10]/rden=1, div2=[1,2], bquot=-5, lenq=3, len1=4, len2=2 while end: quot=[0,0,-5]/1, rem1=[1,4,4]/1 step end: quot=[0,0,-5]/qden=1, rem1=[1,4,4]/rden=...
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// Scilab Code Ex6.7: Page-372 (2011) clc;clear; phi = %pi/2; // Scattering angle, degrees m0 = 9.1e-031;....// Rest mass of an electron, kg h = 6.62e-034;....// Planck's constant, J-s c = 3e+008;....// Speed of light in vacuum, m/s E = 8.16e-014;....// Energy of gamma radiation, J lambda = h*c/(E*1e-010); ...
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load isZero.hdl, output-file isZero.out, compare-to isZero.cmp, output-list in%B1.8.1 zero%B3.1.3; set in %B00000000, eval, output; set in %B00000001, eval, output; set in %B00000010, eval, output; set in %B00000100, eval, output; set in %B00001000, eval, output; set in %B00010000, eval, output; set in %B0010000...
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//Example 5.6// x=0.75*10^-3;//m //meter //given t=3.6*10^4;//s //seconds //time a=0.95;//given D=(x^2)/((a^2)*(t)) mprintf("D = %e m^2/s",D) b=20*10^-6;//m^2/s //preexponential constant c=142000;//J/mol //activation energy for defect motion d=8.314;//J/(mol.K)//universal gas constant e=c/d //mprintf("\ne = ...
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//Chapter-6, Illustration 1, Page 308 //Title: Refrigeration cycles //============================================================================= clc clear //INPUT DATA COP=8.5;//Co-efficient of performance T1=300;//Room temperature in K T2=267;//Refrigeration temperature in K //CALCULATIONS COPmax=T2/(...
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// FUNDAMENTALS OF ELECTICAL MACHINES // M.A.SALAM // NAROSA PUBLISHING HOUSE // SECOND EDITION // Chapter 7 : THREE-PHASE INDUCTION MOTOR // Example : 7.7 clc;clear; // clears the console and command history // Given data V = 440 // supply voltage in V P = 6 // number of poles f =...
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// código modelo de hidrolise enzimática de amido brandam et al (2003) anexado a otimização por enxame de partículas clear clc tic() format(10) // valores dos parâmetros // gelatinização, T < Tg k_g1 = 5.7*10^31 // s^-1 E_g1 = 220.6 // kJ/mol // gelatinização, T > Tg k_g2 = 3.1*10^14 // s^...
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function x=%r_inv(a) // Copyright INRIA x=invr(a)
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//Find x in R^6 such that: //Check for the size of constraints conMatrix= [-1,1,0,3,1; -1,0,-3,-4,5; 2,5,3,0,1 0,1,0,1,2; -1,0,2,1,1]; conLB=[1;2;3;-%inf;-%inf]; conUB = [1;2;3;-1;2.5]; lb=[-1000;-10000; 0; -1000; -1000; -1000]; ub=[10000; 100; 1.5; 100; 100; 1000]; //and minimize 0.5*x'*Q*x + p'*x with p=[1; 2; 3; 4; ...
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function c=str2code(str) // str2code - return scilab integer codes associated with a character string //! if prod(size(str))<>1 then error('Not implemented for vector of strings') end alpha=['0','1','2','3','4','5','6','7','8','9',.. 'a','b','c','d','e','f','g','h','i','j',.. 'k','l','m','n','o','p','q...
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// Scilab Code Ex7.7: Page-255 (2014) clc; clear; e = 1.602e-019; // Charge on an electron, C h = 6.62e-034; // Planck's constant, Js h_bar = h/(2*%pi); // Reduced Planck's constant, Js m = 9.11e-031; // Electron mass, kg B = 2.00; // External magnetic field, T m_l1 = 0; // Lower orbial magneti...
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// Exa 7.5 clc; clear; // Given data // A wide-band pass filter fL=400; // Lower cutoff frequency(Hz) fH=2000; // Higher cutoff frequency(Hz) A0=4; // passband gain // Solution printf('Since, the pass band gain is 4. so each of LPF and HPF section may be designed to give gain of 2,\n that is Ao=1+ (R...
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s=poly(0,'s'); F=syslin('c',[80000/((2+s)*s*(s+50)*(s+200))]) //without k fmin=0.1; //Min freq in Hz fmax=20; //Max freq in Hz scf(1);clf; bode(F,fmin,fmax); //Plots frequency respon...
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function [y]=gauspuls(t,fc,bw) // Generates Gaussian-modulated sinusoidal pulses // Calling Sequence // [y]=gauspuls(t,fc,bw) // [y]=gauspuls(t,fc) // [y]=gauspuls(t) // Parameters // t: Real or complex valued vector or matrix // fc: Real non negative number or complex number // bw: Real positive number or complex num...
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clc clear //Input data s=0.005//Delay in sec d=30//Bore in cm N=600//Speed in r.p.m dx=[10,15,20]//Bore diameters in cm //Calculations t=(s/d)*dx//Time of delay in sec. In textbook, t(2) is given wrong as 0.00025 sec instead of 0.0025 sec //Output printf('The delay time for %i cm diameter bore is %3.5f se...
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// Example 34_1 clc;funcprot(0); //Given data P=120000;// The cost of the water softner plant in rupees S=(8/100)*P;// The salvage value of the plant in rupees r=8/100;//Interest on sinking fund n=12;//The life of the plant in years RMLc=8000;//Repair,maintainence and labour costs Cc=5000;// Chemical cost //...
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//Exam:3.31 clc; clear; close; //Miller indices of plane n=1; h=1; k=1; l=1; angle=30;//in degree wavelength=2;//in angstrom d=n*wavelength/(2*sind(angle));//interplanar spacing a=d*(h^2+k^2+l^2)^(1/2);//interatomic spacing disp(a,'interatomic spacing(in angstrom)=');
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//Ex 7.2 clc;clear;close; format('v',5); Zs=240;//no. of conductors in stator winding Zr=48;//no. of conductors in rotor winding Rr=0.013;//ohm/phase(resstance rotor windig) XL=0.048;//ohm/phase(leakega reactance) Vs=400;//V //(a) Eo=Vs*Zr/Zs;//V(rotor emf) disp(Eo,"(a) Rotor emf(V)"); //(b) S=4/100;//slip ...
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// Exa 7.7 format('v',6);clc;clear;close; // Given data Cin = 35;// in pF // (R1+Rin)/Rin = 10; RinBYR1= 1/9; //while balance equation with compensating capacitor // R1*C1 = Rin*(C2+Cin); C1= Cin*RinBYR1;//compansating capacitor in pF disp(C1,"The compansating capacitor in pF is");
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//Problem 10.04: An ammeter has a f.s.d. of 100 mA and a resistance of 50 ohms. The ammeter is used to measure the current in a load of resistance 500 ohms when the supply voltage is 10 V. Calculate (a) the ammeter reading expected (neglecting its resistance), (b) the actual current in the circuit, (c) the power diss...
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//Problem 2.03: The current flowing through a resistor is 0.8 A when a p.d. of 20 V is applied. Determine the value of the resistance. //initializing the variables: I = 0.8; // in Ampere V = 20; // in Volts //calculation: R = V/I printf("\n\nResult\n\n") printf("\nResistance(R): %.0f Ohms\n",R)
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clear; clc; disp(' Example 14.1'); // aim : To determine // (a) the free air delivered // (b) the volumetric efficiency // (c) the air delivery temperature // (d) the cycle power // (e) the isothermal efficiency // given values d = 200*10^-3;// bore, [m] L = 300*10^-3;// stroke, [m] N = 500;// speed, [...
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.254973D+00 ...
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//Chapter 9 //Example 9.6 //page 352 //To calculate short circuit solution using algorithm for short circuit studies clear;clc; Y11=1/(0.15*%i)+1/(0.15*%i)+1/(0.1*%i)+1/(0.2*%i); Y12=-1/(0.2*%i); Y21=Y12; Y13=-1/(0.15*%i); Y31=Y13; Y14=-1/(0.1*%i); Y41=Y14; Y22=1/(0.15*%i)+1/(0.15*%i)+1/(0.1*%i)+1/(0.2*%i); Y23=-1/(0....
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clear clc //Example 8.2 disp('Example 8.2') //Eqn 8-6 //Pump characteristics q=0:0.1:240; Phe=30*(q/200).^2; plot2d(q,Phe,rect=[0,0,240,40]); xgrid() xtitle("Fig 8.13 Pump characteristics","q,gal/min","P,psi") scf(); q=200;//Flow rate in gal/min Phe=30*(q/200).^2; Pv=40-Phe; //Eqn 8-8 //(a) l=0.5;Pv=10; Cv=q/l/sq...
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angulo = input("Entre com um valor de ângulo em graus de 0° a 90°:"); seno = sind(angulo); disp(seno);
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//Given that deltaP = 9.3*10^3 //in N/m^2 density_water = 998 //in kg/m^3 g = 9.8 //in m/s^2 //Sample Problem 15-2 printf("**Sample Problem 15-2**\n") //deltaP = density_water*g*L //therefore L = deltaP/(density_water*g) printf("The diver started at a depth of %fm", L)
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// * * * * * * * * * * * * * * * * * * * * // // -- Auswertung Winkelregelung -- // // * * * * * * * * * * * * * * * * * * * * // // Boris: cd "/Users/borishenckell/Documents/eclipse workspace/PR_Regelungsrtechnik_-_Versuch_2a/PR Regelungsrechnik - V...
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//Chapter2 //Page.No-46, Figure.No-2.10 //Example_2_2_a //Output voltage for inverting amplifier //Given: clear;clc; vin=20*10^-3; // Input voltage in volts A=200000; // Voltage gain vo=-(A*vin); // Output voltage in volts printf("\n Output voltage is vo = %.f V \n",vo) // Result
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clear all clc f=input('Enter frequency in Hz:') t=0:0.0001:1 x1=cos(2*%pi*f*t); x2=cos(2*%pi*(2*f)*t) message=[]; carrier1=[]; carrier2=[]; I=input('Enter binary data:') for i=1:length(I) if(I(i))==1 m_s=ones(1,length(t)); else m_s=zeros(1,length(t)); end message=[message...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>Double Bifurcation, P=5</description> <executable>PulseWaveSolver</executable> <parameters>TwoBifurcations.xml</parameters> <files> <file description="Session File">TwoBifurcations.xml</file> </files> <metrics> <metric ty...
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function dayDateTime() today = datenum(); [dayNumber,dayString] = weekday(today,'long'); mprintf("\nToday is %s, the %dth day of the week.\n", dayString, dayNumber); mprintf("The date is: %s\n", date()); t = clock(); mprintf("The time is: %d:%d:%d\n",t(4), t(5), t(6)); endfunction dayDateTime()
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Example4_12.sce
//example 4.12. clc disp("From the given information we can write,") disp(" A = -16*10^6/j*omega and beta = 10^3/[2*10^3+j*omega]^2") disp("To verify the Barkhausen condition means to verify whether |A*beta| = 1 at a frequency for which A*beta = 0 degree. Let us express, A*beta in its rectangluar form.") disp...
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13_8.sce
nc = 0.87; nt = 0.9; T1 = 311; rp = 8; // P2/P1 P1 = 1; P2 = 8; P3 = 0.95*P2; P4 = 1; g = 1.4; cv = 0.718; cp = 1.005; R = 0.287; // With no cooling T2s = T1*((P2/P1)^((g-1)/g)); T2 = T1 + (T2s-T1)/0.87; T4s = T3*(P4/P3)^((g-1)/g); n = (((T3-T4s)*nt)-((T2s-T1)/nc))/(T3-T2); // With cooling n_cycle = n-0.05; ...
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function [Q, T]=Questao3(A) //extrai dimensoes [l,c] = size(A) //tira o mínimo e armazena em p p=min(l,c) //inicia a matriz Q como identidade Q=eye(l,l) // e = eye(l,l) for k=1:p-1 //pega o vetor coluna de A x=A(k:l,k) //calcula...
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Undefined index: service Неизвестный индекс под названием 'service' в массиве
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//chapter 4 //broadside array printf("\n"); n=4; lamda=0.1 d=0.5 i=0.25 Rrad=73; //part a Prad=n*(i^2*Rrad); printf("the radiated power is %gW",Prad); //part b L=n*d; printf("\nthe length is %dm",L); BWFN=2*lamda/L; HPBW=BWFN/2; printf("\nthe Beam width first null is %g radians",BWFN); printf("\nthe ha...
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8_8.sci
clc(); clear; // To determine e/m ratio //e/m=(deltalambda*4*pi*c)/(B*(lambda)^2) deltalambda=0.01*10^-9; //Zeeman shift c=3*(10^8); //speed of light in vacuum in m/s B=0.78; //magnetic field lambda=550*(10^-9...
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TESTNODE_qmgr_default.tst
*************************************************** * Run the following command to create the queues * * runmqsc <queue manager name> <TESTNODE_qmgr_default.tst * *************************************************** DEFINE QL('BACKEND1')
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2020-01-25T19:20:10
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tradeoffPIP.sce
clear //T < +∞ exec('C:\Users\Julien Guégan\Documents\Cours\MAM4\STAGE\2 cohorts\Tfini\Fonctions 2 cohorts - T fini.sci',-1) T = 40 t = 0:T // CI M01 = 400 M02 = 400 n1 = 100 n2 = 1 n = n1+n2 Mee = fsolve(0,eqnM) τee = fsolve(0,list(lambda,Mee)) disp(" M** = "+string(Mee)+" , τ** = "+string(τee)) gagnants = [] /...
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[ "BSD-3-Clause" ]
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sce
builder_gateway_plsi.sce
gateway_path = get_absolute_file_path("builder_gateway_plsi.sce"); cur_path = pwd(); chdir(gateway_path); libname = 'openpr_plsi'; names = ['plsiread','int_readdata'; 'plsitrain','int_plsitrain']; files = (listfiles(['*.cpp']))' if ~MSDOS then hfiles = (listfiles('*.h'))'; files = [hfiles, files]; end tbx_build...
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//Example No. 10.10.2 clc; clear; close; format('v',7); tau=0.895;//scale factor sigma=0.166;//(spacing factor) fU=30;//MHz(Upper frequency) fL=10;//MHz(Lower frequency) c=3*10^8;//m/s(Speed of light) lambdaU=c/(fU*10^6);//m(Upper wavelength) lambdaL=c/(fL*10^6);//m(Lower wavelength) l1=lambdaU/2;//m(Length...
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Ex3_6.sce
clear ; clc; // Example 3.6 printf('Example 3.6\n\n'); printf('Page No. 67\n\n'); // given P = 9000;// Capital Cost in Pound n = 5;// Project lifetime Less_dep = 8000;// Less Depreciation //For Project A d1 = [4500 3750 3000 1500 750 ]// Saving in every year (before depreciation) dT1 = sum (d1) Net_S1 =...
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//Chapter 10 //Example 10_4 //Page 236 clear;clc; load_kw=15000; pf=0.8; r=1; vr=132; loss=0.05; i=load_kw*1000/sqrt(3)/vr/1000/pf; l_loss=loss*load_kw; r=l_loss*1000/3/i^2; l=r; printf("Line current = %.0f A \n\n", i); printf("Line losses = %.0f kW \n\n", l_loss); printf("R = %.2f ohm \n\n", r); printf("Length of ...
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clc // Given That rotation=13.2// in degree conc=0.1// gram per cubic cm l=2// length of tube in dm //Sample Problem 33 Page No. 60 printf("\n # Problem 33 # \n ") printf(" \n Standard formula used \n delta=pi*d*del_mu/lambda \n") s= (rotation*(%pi/180))/ (l*conc) specific_rotation=s*180/%pi printf("Specifi...
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P1 = 101.3e03; P4 = P1; // in Pa P2 = 8*P1; P3 = P2; T1 = 288; Vs = 2000; V3 = 100; Vc = V3; V1 = Vs + Vc ; n = 1.25; R = 287; V4 = ((P3/P4)^(1/n))*V3; W = ((n*P1*(V1-V4)*1e-06)/(n-1))*(((P2/P1)^((n-1)/n))-1); P = (W*800*0.001)/60 ; disp("kW",P,"Indicated poer is") disp("%",100*(V1-V4)/Vs,"Volumetric effici...
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clear all; clc; disp("Ex 6_2") //Calculations // At joint C: //Applying summation of forces along all axes and equating them to zero //We get two equations and we solve for each component //Solving by matrix method to obtain solution disp("At joint C:") a1=30 a=a1*%pi/180 b1=45 b=b1*%pi/180 A=[-cos(a),sin(b);sin(a),...
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<?xml version="1.0" encoding="UTF-8" standalone="yes"?> <AutoTestC version="2.0.0"> <Pulse>CUSTOM WAVE</Pulse> <Title>Pulse A1 Mode 1</Title> <Organization>Ford</Organization> <Standard>ES-XW7T-1A278-AC 2003</Standard> <Item>14.0 Immunity from Transient Disturbances CI 220</Item> <voltage>13</vo...
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@relation magic @attribute a1 real [4.2835, 334.177] @attribute a2 real [0.0, 256.382] @attribute a3 real [1.9413, 5.3233] @attribute a4 real [0.0131, 0.893] @attribute a5 real [3.0E-4, 0.6752] @attribute a6 real [-457.9161, 575.2407] @attribute a7 real [-331.78, 238.321] @attribute a8 real [-205.8947, 179.851] @attr...
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test2.sce
clear;close();getd(".");getd("./kNN");getd("./RLG");getd("./RLG/Geometry");getd("./Pruning_strategy") //stance = [-2.3750e-1,-4.3146e-1,+1.9095e-2;-2.3750e-1,+4.3146e-1,+1.9097e-2;+2.3750e-1,-4.3146e-1,+1.9097e-2;+2.3750e-1,+4.3146e-1,+1.9095e-2]; stance = [-2.3750e-1,0,-4.3146e-1;-2.3750e-1,0,+4.3146e-1;+2.3750e-1,0,...
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ex3_5.sce
//Chapter-3, Example 3.5, Page 111 //============================================================================= clc clear //INPUT DATA L1=0.25;//self inductance of coil in henry(H) N1=500;//no of turns of coil 1 N2=10500;//no of turns of coil 2 phi2=0.6*L1;//60 % of flux of first coil(m1) is linked with se...
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wtperct=0.5 Dwater=0.998 //g/cm^3 Dsulfuric=1.834 //g/cm^3
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clc // Given that E = 5e-19 // energy of photon in J h = 6.62e-34 // Planck constant in J-sec c = 3e8 // speed of light in m/sec e = 1.6e-19 // charge on an electron in C // Sample Problem 5 on page no. 14.21 printf("\n # PROBLEM 5 # \n") printf("Standard formula used \n") printf(" E = h*c/lambda \n") lambda = c * h /...
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function y = ifftn(A, varargin) //Compute the inverse N-dimensional discrete Fourier transform of A using a Fast Fourier Transform (FFT) algorithm. //Calling Sequence //Y = ifftn(A) //Y = ifftn(A, size) //Parameters //A: Matrix //Description //Compute the inverse N-dimensional discrete Fourier transform of A using a F...
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<scriptConfig name="RR" script="RR"> <params> <param name="invt.pretest_delay" type="int">0</param> <param name="rr.RRnorm_up_min" type="float">2.0</param> <param name="rr.MSARR" type="float">2.5</param> <param name="rr.t_dwell" type="float">3.0</param> <param name="comm.slave_id" type="int">5</pa...
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//Ex4_13 clc IDSS=10*10^(-3) disp("IDSS = "+string(IDSS)+" ampere") // maximum drain current for n-channel DEMOSFET ID=IDSS // since VGS=0V, so ID=maximum VP=(-4) disp("VP= "+string(VP)+" volts") // pinch off voltage VGS=(0) disp("VGS= "+string(VGS)+" volts") // Gate to source voltage VDD=(10) disp("VDD= "...
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f_am=10; fr_am=455; fr_fm=10.7; f_fm=0.2; q_am=fr_am/f_am; q_fm=fr_fm/f_fm; disp("for AM the necessary Q value is"); disp(q_am); disp("for FM the necessary Q value is"); disp(q_fm);
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// Scilab Code Ex10.8 Maximum height of the potential barrier for alpha penetration: Pg:222 (2008) epsilon_0 = 8.854e-12; // Absolute electrical permittivity of free space, coulomb square per newton per metre square Z = 92; // Atomic number of U-92 nucleus z = 2; // Atomic number of He nucleus e = 1.6e-019...
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//Exa 14(iv) clc; clear; close; //given data : inINV=50000;//initial investment in Rs. and equal for all projects life=5;//in years salvage=0;//in Rs. TaxRate=55;//in % //depreciation type :Straight line D=inINV/life;//in Rs //cash flows before tax of 1st,2nd,3rd,4th and 5th years CBFT1=10000;//in Rs. CBFT2=11000;//in...
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ADD s0, 01 OUTPUT s0, 00 loop: CALL NZ, loop OUTPUT sF, 00 death: JUMP death
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function [sr]=%lsslp(s,p) //sr=%lsslp(s,p) <=> sr=s\p // p matrice de polynomes // s representation d'etat d'un systeme lineaire //! //origine S Steer INRIA 1992 sr=s\tlist('lss',[],[],[],p,[],[])
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clear ; clc; // Example 25.10 printf('Example 25.10\n\n'); //page no. 788 // Solution // Given Ex_hv = 29770.0 ;// Experimental heating value of given coal - [kJ/kg] // Coal analysis C = 71.0/100 ;//Fraction of C in coal H2 = 5.6/100 ;// Fraction of H2 in coal N2 = 1.6/100 ;// Fraction of N2 in coal S = 2.7/100 ...
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clc //initialization of variables clear b=2 //cm h=2 //cm T=2000 //kg-cm V=250 //kg M=2000 //kg-cm // calculations Mmax=M*6/(b*h*b) Vmax=3*V/(2*b*h) Zt=0.208*b^2*h Tmax=T/(Zt) sigma=Mmax printf('points A,B,') printf('\n sigma=%d kg/cm^2 (tension)',sigma) printf('\n points C,D,') printf('\n sigma=%d k...
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//Introduction to Fiber Optics by A. Ghatak and K. Thyagarajan, Cambridge, New Delhi, 1999 //Example 2.4 //OS=Windows XP sp3 //Scilab version 5.5.2 clc; clear; //given Case(1) n1=1;//refractive index of air n2=1.45;//refractive index of silica R=[(n1-n2)/(n1+n2)]^2;//corresponding energy reflection coefficient...
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clc //calc thickness of liquid strip at the bottom of the industrial centrifuge //Let difference between heights at bottom and top be d d=20;//in r_a=14;//in f=1000/60;//rps g=32.2;//ft/s^2 r_b=[(r_a)^2-2*(d)*g*12/(2*(%pi)*f)^2]^0.5;//in disp("The thickness of water strip at bottom of industrial centrifuge") d...
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import {StagePhaser} from "../phasers/StagePhaser"; import MathJs from 'mathjs'; import {Position} from "../../../../../blacksheep-geometry/lib"; import { Parameter } from "../../../Parameter"; export class GoldenRectanglePositioner { speed: Parameter; distance: Parameter; center: Position; stagePhaser: ...
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function y = qei_sim2(u1) in = u1; out = u1; out = modulo(in, 2*%pi); out = out * (500/%pi); y = out; endfunction
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//Example 4_17 clc(); clear; //To find the lattice parameter of Lead lemda=1.5*10^-10 //units in meters theta=34 //units in degrees n=1 h=2 k=0 l=2 a=(n*lemda)/(2*sin(theta))*sqrt(h^2+k^2+l^2)*10^10 printf("the lattice parameter of the Lead is %.3f angstrom"...
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V=11;Phase=3;F=60;IncExe=150;DecExe=50;Xs=10; Power=80000; Vt=V/sqrt(Phase) Vt=Vt*1000 Ef=IncExe/100 Ef1=DecExe/100 Ia=(Vt-(Ef*Vt))/(Xs) Pf=cos(90/90*%pi/2) Ia1=(Vt-(Ef1*Vt))/(Xs) Pf1=cos(90/90*%pi/2) Ia=Power/(Phase*Vt) function[x,y]=polar2rect(r,theta) x=r*cos(theta*%pi/180); ...
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//Variable Declaration p1=0.87 // probability of Repair on the engine p2=0.36 // probability of drive train p3=0.29 // probability of rapair as well as drive train //Calculation P = p1+p2-p3 // Required probability //Results printf ( "probability of at least one kind of repair: %.2f",P)
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//chapter 21 Ex 8 clc; clear; close; SI=4/9; rate=sqrt(SI*100); t=rate; //since both are numerfically equal mprintf("The rate is %.2f percent and the time is %.2f years",rate,t);
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clc,clear printf('Example 5.21\n\n') V_ph=2000 R_a=0.8 I_sc=100,I_a=I_sc V_OC=500 I_f=2.5 Z_s=V_OC/I_sc X_s=sqrt(Z_s^2- R_a^2) I_a_FL=100 //Part(i) phi1=acos(1) //and lagging E_ph1=sqrt((V_ph*cos(phi1)+I_a*R_a)^2+(V_ph*sin(phi1)+I_a*X_s)^2) regulation1=100*(E_ph1-V_ph)/V_ph printf('Regulation at upf...
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//Chapter 3 : Systems of Linear Equations //Example 3.22 //Scilab 6.0.1 //Windows 10 clear; clc; A=[1 2 0 0; 2 1 -1 1; 5 4 -2 2]; disp(A,'A=') mprintf('the rows of the matrix are linearly dependent\n') t=A(1,:)+2*A(2,:); mprintf('this follows from the fact that\n') mprintf('A3=A1+2A2') disp(t)
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//scilab 5.4.1 clear; clc; printf("\t\t\tProblem Number 7.23\n\n\n"); // Chapter 7 : Mixtures Of Ideal Gases // Problem 7.23 (page no. 358) // Solution //The cooling tower //From the Steam tables, //For water: h100F=68.05; //Btu/lbm //enthalpy at 100 F h70F=38.09; //Btu/lbm //enthalpy at 70 F //For ...
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function data = mdaq_ai_read(link_id, channels, ai_range, bipolar) data = []; if argn(2) <> 4 then disp("ERROR: Wrong input arguments!"); return; end if link_id < 0 then disp("ERROR: Wrong link ID!") return; end ch_count = max(size(channels)); if ch...
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// Ex 75 Page 414 clc;clear;close; // Given Ebb=400;//V Emm=250;//V Ibb=25;//A Po=2.5*10**3;//W m=Emm/Ebb;//modulation index Pbb=Ebb*Ibb eta=Po/Pbb*100;//% P=Po*(1+m**2/2);//W Pdo=Pbb-Po;//W Pd=Pdo*(1+m**2/2);//W printf("\n carrier power under modulated condition = %0.2f kW",P/1000) printf("\n plate circuit efficienc...
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//Finding resistance and cost //Example 15.39(pg. 418) clc clear m=2//weight of water to be heated in kg t2=98,t1=15//temp in degreeC s=1//specific heat of water V=200//voltage in volts H=m*s*(t2-t1)//energy required to raise the temp of water in kcal H1=H*4200//energy in Watt-sec or Joules e=0.85//efficiency...
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function Px = poly_Gregory_Newton(varargin) // // Polinomio de Gregory-Newton usando dispositivo pratico // // parametros de entrada: // x: vetor contendo as abscissas, // y: vetor contendo as ordenadas, // [Exibe]: Parâmetro opcional de exibição da tabela de Dif. finitas /...
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//Chapter 5 //Example 5.6 //page 149 //to find incident and reflected voltages clear;clc; R=0.125; X=0.4; y=%i*2.8*10^(-6); z=R+%i*X; r=sqrt(y*z); //propogation constant a=real(r); //attenuation constant b=imag(r); //phase constant //(a) At the receiving-end; Vr=220000; Inci_vol=Vr/(sqrt(3)*2); Refl_vol=Vr/(sqrt(3)*...
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// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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clc; A=2;//No of parallel paths for armature conductors P=6;//No. of poles If=2;//Field current Il=148;//Line current Ia=If+Il;//Armature current Z=480;//No of conductors //brushes on GNA, theta=0 ATd1=0//demagnetizing ampere turns ATc1=((Ia*Z)/(2*A*P))//Cross magnetizing ampere turns printf('When brushes are...
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function signal = pskdemod(psk, m, phi, datatype) // //Function Description //pskdemod: This function demodulates a matrix of psk modulated //baseband signals (constellation points or complex numbers) into integers. // //Calling sequence:- //signal = pskdemod(psk, m) //signal = pskdemod(psk, m, phi) //...
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clc //initialization of variables v=600 //ft/sec T=60+460 //R P=14.7 //lb/in^2 Pratio=6 Tin=1540+460 //R cp=0.264 cpratio=1.35 //calculations Pt2byP1=(1+ (cpratio-1)*v^2 /(cpratio*2*32.2*53.3*T))^(3.86) Pt3byP1=Pt2byP1*Pratio eta=1- 1/(Pt3byP1)^0.259 Tt3=T*(Pt3byP1)^((cpratio-1)/cpratio) Q=cp*(Tin-Tt3) V...
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clc;clear; //Example 25.13 //conversion of binary to decimal //given values X=10.101;//binary number //calculation Z=(1*2^1)+(0*2^0)+(1*2^-1)+(0*2^-2)+(1*2^-3); disp(Z,'decimal equivalent of the given binary number is')
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// Scilab code Ex3.18: Pg 101 (2008) clc; clear; V = 400; // Supply voltage, V E = 0.5e06; // Dielectric strength, V/m // Since E = V/d, solving for d d = V/E; // Thickness of dielectric, m printf("\nThe minimum thickness of dielectric required = %3.1fmm", d/1e-03); // Re...
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//clear// //Caption: Program to find the work involved 'W' in moving a charge 'Q' along shorter arc of a circle //Example4.1 //page 84 clc; x = sym('x'); y = sym('y'); z = sym('z'); y1 = sym('y1'); y = sqrt(1-x^2); Q = 2; //charge in coulombs Edot_dL1 = integ(y,x); disp(Edot_dL1,'E.dx*ax =') Edot_dL1 = lim...
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exec("histcFix.sci",-1) N = 10^3 // taille de l'échantillon // parametres de la loi B(n,p) n = 100 // valeur max de n p = .5 clf() // fixer les axes a = gca() a.data_bounds = [0,0;1,.4*sqrt(n/p/(1-p))] a.auto_scale = "off" for k = floor(linspace(2,n)) // frame par frame ech = grand(1,N,"bin",k,p) x = linspace(0,...
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clear;lines(0); A=[1,2,10;7,7.1,7.01]; mean(A) mean(A,'r') mean(A,'c')
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// sum 3-28 clc; clear; rho=0.0078*9.81*10^-6; sigc=150; g=9.81; V=sqrt(sigc*g/rho)*10^-3; R=1; w=V/R; N=w*60/(2*%pi); // printing data in scilab o/p window printf("N is %0.3f rpm ",N);
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//Example 3.1 clear; clc; R=10; C=40*10^(-6); L=5*10^(-3); Hsnum=(R/L)*%s; Hsden=((%s^(2))+(R/L)*%s+(1/(L*C))); Hs=Hsnum/Hsden;//Transfer Function h=syslin('c',Hs); plzr(h); zeroes=roots(Hsnum); poles=roots(Hsden);