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//Chapter5,Ex5.6,Pg5.6 clc; //Given: kVA rating=250kVA f=50Hz N2/N1=0.1 E2=240V //(i) E1=240/0.1 //E2/E1=N2/N1 printf("\n Primary EMF E1=%.0f V \n",E1) //(ii) I1=250*1000/2400 //Using the formula I=kVA rating*1000/V printf("\n I1=%.2f A \n",I1) I2=250*1000/240 printf("\n I2=%.2f A \n",I2)
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function Ksettings() // This program is free software; you can redistribute it and/or modify // it under the terms of the GNU General Public License as published by // the Free Software Foundation; either version 2 of the License, or // (at your option) any later version. // // This program is distributed in...
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clear all; clc; sigma = 20;//ultimate sheat stress in tons/in^2 d = 1/2;//diameter of the hole in inches t = 3/8;//thickness of the plate in inches A = 0.25*%pi*d^2;//area of the cross-section of the punch in^2 P = %pi*d*t*sigma;//necessary force in tons sigma_comp = P/A;//compressive stress on the punch printf...
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load Prog2.vm, output-file Prog2.out, compare-to Prog2.cmp, output-list RAM[39]%D2.6.2, set RAM[0] 256, set RAM[16] 8, set RAM[17] 5, set RAM[18] 3, repeat 50 { vmstep; } output; load Prog2.vm, set RAM[0] 256, set RAM[16] -1, set RAM[17] 5, set RAM[18] 0, repeat 50 { vmstep; } output; load Prog2.vm, set RAM[0] 2...
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[[i= partials/header ]] [[i= partials/navbar ]] <div class="container"> <div class="flex row product"> <div class="container center productImg"> <img src="/assets/img/products/[[item.products_image]]" alt="img"> </div> <div class="container center productData" style="wid...
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%!function r = f1 () %! ls = svd (1); %! r = eval ("ls -1;"); %!endfunction %!function r = f2 () %! [u,ls,v] = svd (1); %! r = eval ("ls -1;"); %!endfunction %!function r = f3 (ls) %! r = eval ("ls -1;"); %!endfunction %!test %! ## Windows systems can't run "ls -1" %! if (! ispc ()) %! assert (f1 (), 0); %! a...
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// Scilab Code Ex3c.5: Page-185 (2008) clc; clear; D = 80; // Distance between the source and the slit, cm lambda = 5890e-008; // Wavelength of light, cm bita = 9.424e-002; // Fringe width, cm d = lambda*D/bita; // Separation between the two slits, cm printf("\nThe distance between the two coherent so...
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//Example 8.8 clear; clc; //Given T=298;//temperature in K R=8.314;//gas constant in J K^-1 mol^-1 delGfoC2H4=68.12;//standard free energy change in the formation of ethylene in kJ mol^-1 delGfoC2H6=-32.89;//standard free energy change in the formation of ethane in kJ mol^-1 //To determine the value of delG...
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function z = f(t,w) z = w - t^2 + 1; endfunction function [w] = runge_kutta4(a,b,n,alfa) h = (b-a)/n; w = zeros(n+1,1); w(1) = alfa; t = a; for i=2:(n+1) wi = w(i-1); k1 = h*f(t,wi); k2 = h*f(t+h/2,wi+k1/2); k3 = h*f(t+h/2,wi+k2/2); k4 = h*f(t+h,wi+k3); ...
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//Example 8.2, page no-508 clear clc i=10*10^-3 R=1000 P=(i^2)*R err_R=10 err_I=(2/100)*25*100/10 err_I2=2*err_I err_p=err_I2+err_R printf("%% error in I^2 = ± %d%%\n%% error in Power = ± %d%%",err_I2,err_p)
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clear; clc; n=4; Z=0; z=[ 4 1 .5*%i 1; 4 2 .4*%i 1; 1 3 .2*%i 2; 2 3 .1*%i 4]; for(i=1:n) mcase=z(i,4) znew=z(i,3) n1=real(z(i,1)) n2=real(z(i,2)) dim=max(size(Z)) select mcase case 1 then if Z(1,1)==0 then dim=dim-1 end ...
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asdf same dnove veci takze TOTO je nove!!! original remote branch
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clc;funcprot(0);//EXAMPLE 12.3 // Initialisation of Variables n=1;............//No of cylinders N=650;............//Engine rpm theta=28;...........//Crank Travel in degree fc=2.2;...........//Fuel consumption in kg/h spgr=0.875;............//Specific Gravity ip=150;................//Injection Pressure in bar cp...
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//scilab 5.4.1 //Windows 7 operating system //chapter 12 Modulation and Demodulation clc clear df=30//df=maximum frequency deviation in kilohertz(kHz) fm=15//fm=modulation frequency of a sinusoidal audio signal in kilohertz(kHz) mf=df/fm//mf=frequency modulation index disp(mf,"1.The modulation index is mf=") f...
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27_5.sce
clear// //Variables Pcdc = 10.0 //dc power (in watt) ne = 0.32 //efficiency //Calculation Poac = ne * Pcdc / (1 - ne) //a.c. power output (in watt) //Result printf("\n The a.c. power output is %0.1f W.",Poac)
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//Section-14,Example-1,Page no.-PC.118 //To estimate the pH of the given solutions. clc; A_NH4Cl=0.01 K_aNH4Cl=(5.6*10^-10) A_NHCH3_3Cl=0.0025 K_aNHCH3_3Cl=(1.5*10^-10) pH1=-(1/2*log10(A_NH4Cl))-(1/2*log10(K_aNH4Cl)) disp(pH1,'pH of NH(CH3)3') pH2=-(1/2*log10(A_NHCH3_3Cl))-(1/2*log10(K_aNHCH3_3Cl)) disp(pH2,'...
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test_8.sce
// Test #8 : When output arguments are less than 5 exec('./zpklp2xn.sci',-1); [z,p,k]=zpklp2xn(8,2,0.5,[0.1 0.5],[0.5,0.75]); disp(k); disp(p); disp(z); // //Scilab Output //k =2.1009558 //p = 0.1427731 + 0.6153536i // 0.1427731 - 0.6153536i //z= 0.2093027 // -0.0054340 // //Matlab Output //z = 0.209...
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sos2zp.sci
function [z,p,k] = sos2zp (sos, g) //This function converts series second-order sections to zeros, poles, and gains (pole residues). //Calling Sequence //z = sos2zp (sos) //z = sos2zp (sos, g) //[z, p] = sos2zp (...) //[z, p, k] = sos2zp (...) //Parameters //sos: matrix of real or complex numbers //g: real or complex ...
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clear all; clc; disp("Scilab Code Ex 12.24 : ") //Given: l_ab = 4; //m l = l_ab/2; w = 9; //kN/m //Compatibility Equations: EI_thetaB = (w*l_ab^3)/(48); //thetaB = (wL^3)/(48EI) EI_nuB = (7*w*l_ab^4)/(384); //nuB = (7wl^4)/(384EI) //Only redundant By applied: EI_thetaB_by_By = (l_ab^2)/(2); //thetaB...
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CC = g++ INCLUDE = . CFLAGS = -g -Wall -ansi MSGLIB = msglib.a all:test test:test.o command.o sys.o $(CC) -o test command.o test.o -l pthread test.o:test.cpp command.h $(CC) -I$(INCLUDE) $(CFLAGS) -c test.cpp command.o:command.cpp command.h ../sys.h $(CC) -I$(INCLUDE) $(CFLAGS) -c command.cpp sys.o:../sys.h ../sys....
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// Scilab code Ex5.19: Pg 176 (2008) clc; clear; e = 30; // Induced emf, V // For simplicity, let rate of change of current i.e delta_I/delta_t = k k = 200; // Rate of change of current, ampere-second // Since e = ((-L)*delta_I)/(delta_t), solving for L L = e/k; ...
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nFET_IdVg=csvRead('PFET_temp.csv') K=1.38064852e-23; q=1.60217662e-19; //nFET_IdVg=PMOS_current exec('/home/ubuntu/rasp30/prog_assembly/libs/scilab_code/linefit.sce', -1) exec('/home/ubuntu/rasp30/prog_assembly/libs/scilab_code/ekvfit_nfet.sce', -1) nFET_IdVg(12,4)=(nFET_IdVg(13,4)+nFET_IdVg(11,4))./2 i_loop=1; tem...
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clc //Chapter3 //Ex_13 //Given h=6.6*10^-34 //in J s c=3*10^8 //in m/s m=9.1*10^-31 //in Kg e=1.6*10^-19 // in coulombs v=2.1*10^6 // in m/s E=m*v^2/2 //in J E=E/e // in eV E1=-13.6 // in eV //change in the energy is E=En-E1 n=sqrt(-13.6/(E+E1)) printf(" the electron gets excited to %d level",n) n=3 E3=...
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//area of triangle, heron's formula clc; clear; a=25; b=32; c=12; //sides of triangle s=(a+b+c)/2; sqrt(s*(s-a)*(s-b)*(s-c))
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clear; clc; printf("\t Example 6.14\n"); d=450; //density of dry pulp in kg/m^3; thickness=0.05; //thickness in m^2 Ls=d*thickness; //mass of bone dry solid ais the drying surface A=1; //area in m^2 v=1*5*10^-2; //volume of mater...
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s = %s; A = [0 1 0;0 0 1;-24 -26 -9]; B = [0;0;1]; C = [1 1 0]; x0 = [1;0;2]; I = eye(3,3); syms t ; U = syslin('c', 1/(s+1)); disp(U,"U(s)="); L = inv(s*I-A)*(x0+B*U);disp(L,"x1,x2 and x3 are :"); Y = C*L; disp(Y,"Y(s)="); y = ilaplace(Y,s,t);disp(y,"output y(t)="); D = det(s*I-A); printf("Roots are the ...
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//check o/p when more than one argument is passed as an i/p to the function y=[10 12;12 34;24 23]; t=[10 12;12 34;24 23]; ydb=db2pow(y,t); disp(ydb); //output // !--error 58 //Wrong number of input arguments.at line 4 of exec file called
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//Caption:Adequate frequency response conditions for first order instruments //Example 7 //Page 103 // To measure qi given by // qi=sin2t+0.3sin20t // timeconstant=0.2s H=1/((0.16+1)^0.5); //H(jw)=qo/qiK phi=((atan(-2*0.2))*180)/%pi ; H2=1/((16+1)^0.5); phi2=((atan(-20*0.2))*180)/%pi; printf("sinusoida...
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clc; clear all; d=25*1e-3;// outside diameter of outer copper tubing t=1.6*1e-3;//thickness of tubing d1=d-(2*t); d2=6*1e-3;//outer diameter of inner tubing Z0=138*log10(d1/d2);//characteristic impedence of copp disp(Z0,'characteristic impedence of line is');
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//Fluid Systems- By Shiv Kumar //Chapter 5- Francis Turbine //Example 5.3 //To Find (a)The Absolute Velocity of Water at Inlet of Runner (b)The Velocity of Whirl at Inlet (c) The Relative Velocity at Inlet //(d) The Runner Blade Angles (e)Width of Runner at Outlet (f)Weight of Water flowing through t...
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a a c h a r y n a n d a n a आ च ा र ् य न ं द न ा a a d a t s e m a j b o o r आ द त स े म ज ब ू र a a d h i y u g आ ध ी य ु ग a a d i k a v i आ द ि क व ि a a d i t y a k e s h a v आ द ि त ् य क े श व a a g k a g o l a आ ग क ा ग ो ल ा a a g k e s h o l a y आ ग क े श ो ल े a a h a t आ ह ट a a ...
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//Chapter -4 //EXAMPLE: 4-5-1 PAGE NO. 170 //(a)program_to_find_the_amount_of_the_power_delivered_in_the_load_Zl PT4=8; //Given.Transmitted_power_to_Bolometer_1_at_port_4 s=2; //Given.VSWR_of_2.0_is_introduced_on_a...
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// Scilab Code Ex4.20:: Page-4.35 (2009) clc; clear; theta = 8; // Angle through which plane of polarization is rotated, degrees M = 10; // Amount of sugar, g l = 14; // Length of the tube, cm V = 44; // Volume of sugar solution, cc c = M/V; // Concentration of sugar, g/cc S = 10*theta/(l*c); /...
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//Ex11_1 clc tsu=20*10^(-9) disp("tsu= "+string(tsu)+" seconds") // Input set-up time of second flip flop tpd=30*10^(-9) disp("tpd= "+string(tpd)+" seconds") // Input set-up time of first flip flop Tmin=tpd+tsu disp("Tmin=tpd+tsu= "+string(Tmin)+" seconds") // Minimum allowed time interval b/w threshold levels o...
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clc clear //Input data mf=(6/3600);//The mass flow rate of fuel in kg/s df=750;//The density of fuel in kg/m^3 Z=0.003;//The level in the float chamber below the top of the jet in m p=1.013;//The ambient pressure in bar T=294;//The ambient temperature in K dj=0.0012;//The jet diameter in m Cdf=0.65;//The disch...
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clc; clear; format('e',11); a=0.001; b=0.0047; L=4*3.14*10^-7*log(b/a)/(2*3.14); disp(L,"The inductance per meter of the coaxial line,L(in H)=");
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// ErturkMe - Copyright 2011 - 2022 // http://erturk.me // ierturk@ieee.org // See license.txt function builder_src() src_path = get_absolute_file_path("builder_src.sce"); tbx_builder_src_lang("c", src_path); endfunction builder_src(); clear builder_src; // remove builder_src on stack
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//Controllers and Their Optimisation// //Example 12.2// P=1.8;//permanent error of p controller in percent// V=100/1.8-1;//gain of the controller in volts// printf('gain of the controller=V=%fvolts',V); G=8;//sum of all time constants in milliseconds// T1=2*G*V;//motor armature time constant// printf('\nMotor ar...
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//Page Number: 556 //Example 10.3 clc; //Given, er=5.23; w=10; //mils t=2.8; //mils h=7; //mils dc=((er+1)/2)+(((er-1)/2)*(1/sqrt(1+12*h/w))); disp(dc,'Dielectric constant:'); //As w/h>1 ci=(120*%pi)/(sqrt(dc)*((w/h)+1.393+0.667*log((w/h)+1.444))); disp('ohm',ci,'Characterstic impedance:');
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clc;clear; //Example 24.4 //calculation of normailsed frequency and no of modes //given values n=1.52;//core refractive index d=29*10^-6;//core diametre in m l=1.3*10^-6;//wavelength of light x=.0007;//fractional refractive index //calculation u=n*(1-x);//index of glass fibre V=%pi*d*sqrt(n^2-u^2)/l; dis...
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//Problem 21.22: A 220 V, d.c. shunt-wound motor runs at 800 rev/min and the armature current is 30 A. The armature circuit resistance is 0.4 ohm. Determine (a) the maximum value of armature current if the flux is suddenly reduced by 10% and (b) the steady state value of the armature current at the new value of flux, ...
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Ex2_13.sce
clc // // // //Variable declaration lambdaa=5000*10**-8 //Wavelength theta=30 //Angular Width //Calculations thetarad=((%pi/180)*(theta)) invde=((2*lambdaa)/(sin(thetarad)))**-1 //Result printf("\n The number of line cm in grating is %0.3f ",invde)
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4_3.sce
clc //initialisation of variables x= 11.5 //in y= 1.2 //in H= 29 //in q= 6.24 //gallons per minute d= 1 //in g= 32.2 //ft/sec^2 Q= 16 //gallons per min //CALCULATIONS Cv= sqrt(x^2/(4*H*y)) Q1= %pi*(d/12)^2*sqrt(2*g*H/12)*q*60/4 Cd= Q/Q1 Cc= Cd/Cv Cr= (1/Cv^2)-1 //RESULTS printf ('Coefficient of resista...
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@relation flare @attribute LargestSpotSize{A,R,S,X,K,H} @attribute SpotDistribution{X,O,I,C} @attribute Activity{1,2} @attribute Evolution{1,2,3} @attribute Prev24Hour{1,2,3} @attribute HistComplex{1,2} @attribute BecomeHist{1,2} @attribute Area{1,2} @attribute C-class{0,1,2,3,4,5,6,7,8} @attribute M-class{0,1,2,3,4,5...
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16 5:0.16666666666666666 14:0.3333333333333333 34:0.5 38:0.6666666666666666 39:0.07142857142857142 48:1.0 56:0.046511627906976744 59:0.06666666666666667 64:0.16666666666666666 72:0.5 75:2.0 85:0.1111111111111111 88:1.0 95:0.3333333333333333 113:0.3333333333333333 146:0.5 180:0.5 201:0.3333333333333333 209:0.4 229:0.333...
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// This file is part of www.nand2tetris.org load Divide.asm, output-file Divide.out, compare-to Divide.cmp, output-list RAM[15]%D2.6.2; set RAM[13] 90, set RAM[14] 15, repeat 1000 { ticktock; } output; set PC 0, set RAM[13] 1001, set RAM[14] 11, repeat 1000 { ticktock; } output; set PC 0, set RAM[13] 1001, ...
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Ch4_4_74.sce
clc disp("Example 4.74") printf("\n") disp("plot the drain characteristics of JFET") //given Vds=[0 1 2 2.5 3 4 6 8] Id=[0 2 4.5 5.3 5.5 5.5 5.5 5.5] plot2d(Vds,Id) xlabel("Vds(V)") ylabel("Id(mA)") xtitle("Plot of Vds V/s Id")
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Ex5_7.sce
// exa 5.7 Pg 155 clc;clear;close; // Given Data t=6;//mm sigma_t=220;// MPa tau=100;// MPa sigma_c=150;// MPa n=2;// no. of rivets / pitch length //Ps=n*%pi/4**d0**2*tau;// shearing strength of rivets //Pc=2*d0*t*sigma_c;// Crushing strength of rivets d0=2*t*sigma_c/(n*%pi/4*tau);// mm (equating Ps=Pc) printf('Diamet...
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Ex5_19.sce
// Ex5_19 clc; // Given: E1=6;// MeV mAl=26.981535; malpha=4.002604; mP=30.973763; // Solution: KE=E1*(27/31);// in MeV BE=(mAl+malpha-mP)*931;// in MeV Ex=KE+BE; printf("\n The excitation energy of compound nucleus is = %f MeV",Ex)
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//Example 8.11 //Integration by Various Methods //Page no 276 clc;clear;close; deff('y=f(x)','y=1/(1+x^2)') a=0;b=1; S=0;h=1/4; n=(b-a)/h+1 for i=1:n x(i)=(i-1)*h y(i)=f(x(i)) end c=['x','f(x)'] for i=1:2 printf('\n%s :\t ',c(i)) for j=1:n if i==1 then printf('%g\t',...
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ex5_13.sce
clc; m=10; // mass flow rate of chilled water in kg/s V1=50; //velocity of chilled water at section 1 in m/s z1=30; // Elevation of section 1 in m V2=10; //velocity of chilled water at section 2 in m/s z2=60; // Elevation of section 2 in m h1=21; // Enthalpy of chilled water at section 1 in kJ/kg h2=43; // Entha...
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clc; // page no 20 // prob no 1.5 // In the given problem B=6MHz, Tk=293, k=1.38*10^-23 B=6*10^6; Tk=293; k=1.38*10^-23;R=300; Pn=k*Tk*B; disp('W',Pn,'The noise power is'); // Th noise voltage is given by Vn=sqrt(4*k*Tk*B*R) Vn=sqrt(4*k*Tk*B*R); disp('volts',Vn,'Th noise voltage is'); // only one-half of this...
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// 09.11.26 function Putrecmark(TbL,Nrg,Mrg,Dt) if type(Dt)==10 N=1; Pos=Dt; Str=''; else N=length(Dt); Pos='l'; Str='\hspace*{2mm}'; end; for I=1:N Str=Str+'\recmark'; if I<N Str=Str+'\hspace{3mm}'; end; end; Putcell(TbL,Nrg,Mrg,Pos,Str); endfunction;
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testIROS2013.sce
//---------------------------// // Compute a cost function over a time horizon // With a free 3d camera // Created 11/12 updated 27 july 2012 // Etude pour ICRA 2012 // Dune // Note : // On etudie le lien entre dx/dt=(dotp dotu) et v=(v, w) //---------------------------// getd("src/transformation") // pose reelle...
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ESL.tst
yield boast scorn submit challenge submit haste ear hurry anger spite hurry twist curl fasten intertwine clip intertwine substance level posture thing score thing stiff drunk dark firm cooked firm brass plastic metal stone wood metal barrel bottle box cask case cask ...
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Ex10_8.sce
clear // // // //Variable declaration d=5*10**-6 //diameter(m) n2=1.447 //refractive index of cladding n1=1.45 //refractive index of core lamda=1*10**-6 //wavelength(m) //Calculation NA=sqrt(n1**2-n2**2) //numerical aperture N=4.9*(d*NA/lamda)**2 //total number of guided modes //Resul...
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2021-09-12T15:30:30.076790
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Questão000.sce
matricula = input("Digite os 3 ultimos digitos da sua matricula") M=matricula/100 aux=modulo(valor,100) MM= aux/10 MMM= modulo(aux,10) x=10*M+MM y= x+MMM z=modulo(y,MM) printf(" o valor eh: %.2f ",z)
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Ch3Exa2.sci
a=10^(-15); //de Broglie wavelength, mts Eo= 0.938; //proton rest energy, GeV h= 4.136*(10^(-15)); //Planck's constant, eV.s c= 2.998*(10^8); //velocity of light, m/s p= h/a; // p is momentum, kg.m/s pc= (h*c)/a; //Photon's energy, ev pc=pc*(10^(-9)); //convert to GeV //pc>E0, relativistic calculation E=...
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21_10.sce
//Chapter 21, Problem 10 clc; f=50; //frequency n1=25; //primary turns n2=300; //secondary turns A=300e-4; //cross-sectional area of the core v1=250; //primary voltage phim=v1/(4.44*f*n1); //flux Bm=phim/...
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EX27_1.sce
//EXAMPLE 27.1 //4-POLE GENERATOR clc; funcprot(0); //Variable Initialisation P=4;......//Total number of poles Z=722;.....//Total number of conductors Ia=100;...//Armature current in Amperes b=8;......//Brush lead in degrees Aw=2;...//Number of parallel paths in a wave wound generator I=Ia/Aw;............
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clc; clear all; pCu=8.96e3;//density of copper in kg*m^-3 pZn=7.14e3;//density of Zn in kg*m^-3 pAl=2.70e3;//density of Al in kg*m^-3 MCu=63.55;//atomic weight of Cu MZn=65.38;//atomic weight of Zn MAl=27.0;//atomic weight of Al N=6.022*1e26;//avogadro's constant x=1;//no of free electrons per atom h=6.626e-3...
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//Tested on Windows 7 Ultimate 32-bit //Chapter 6 Single Staje BJT Amplifiers Pg no. 207 clear; clc; //Given Data //Figure 6.31 VCC=18;//collector supply voltage in volts RB=3.9D6;//base resistance in ohms RE=470;//emitter resistance in ohms VBE=1.6;//forward voltage drop of emitter diode of darlington pai...
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disp("E=(pi^2)*(h^2)/(2*me*Lx^2)+(pi^2)*(h^2)/(2*me*Ly^2)+(pi^2)*(h^2)/(2*me*Lz^2)"); pi=3.14; h=1.055; me=0.04*9.1; L=50; E=(pi^2)*(h^2)/(2*me*L^2); printf('\n The value of E in Joules is %f *(10^-17)',E); f=E/1.6*10^2; printf('\n The value of E in eV is %f',f);
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<<<<<<< .mine //To use these functions make sure the location of the IOME iogs application //is on the path //Linux export IOME_HOME=PATHTOIOME //Linux export PATH=$PATH":$IOME_HOME/bin" //Windows set IOME_HOME=PATHTOIOME //Windows set PATH=%PATH%;$IOME_HOME/bin //senv_iome_home=getenv('IOME_HOME'); senv_iome_home='/...
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clc; clf; x = input("enter the first sequence: "); h = input("enter the second sequence: "); m = length(x); n = length(h); l = m + n - 1; for i = 1:l conv_sum = 0; for j = 1:i if (((i-j+1 <=n ) & (j <= m))) then conv_sum = conv_sum + x(j)*h(i-j+1); end y(i) = conv_sum; ...
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; test scope of declare-fun (set-logic QF_UF) (declare-fun x () Bool) (push 1) (declare-fun y () Bool) (assert (and x y)) (pop 1) (assert x) (declare-fun y () Bool)
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// Ex4_3 clc; // Given: L=6.022*10^23; // Solution: // 1 mCi= 3.7*10^7 dis/s k1=0.693/(15*3600); N1=3.7*10^7/k1; m1=(24*N1*10^10)/L; printf("\n The no. of atoms of Na(24) are = %f",N1) printf("\n The mass of Na(24) is %f * 10^-10 g",m1) k2=0.693/(14.3*24*3600); N2=3.7*10^7/k2; m2=(32*N2*10^9)/L; pri...
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//Example 15.1 //Ordinary Differential Equation //Page no. 503 clc;clear;close; s=log(2)/log(1.02) disp(s,'Time Taken = ')
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//Chapter-4, Illustration 4, Page 135 //Title: Gears and Gear Drivers //============================================================================= clc clear //INPUT DATA x=3.5;//Ratio of teeth of wheels C=1.2;//Centre distance between axes in m DP=4.4;//Diametrical pitch in cm //CALCULATIONS D=2*C*100;...
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clear;lines(0); s=poly(0,'s'); H=[1/(s+0.5);2/(s-0.4)] //strictly proper np=20;w=ldiv(H('num'),H('den'),np); rep=[w(1:np)';w(np+1:2*np)']; //The impulse response H1=ss2tf(imrep2ss(rep)) z=poly(0,'z'); H=(2*z^2-3.4*z+1.5)/(z^2-1.6*z+0.8) //Proper transfer function u=zeros(1,20);u(1)=1; rep=rtitr(H('num'),H('den'...
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// Scilab Code Ex10.3.5 Energy released during fusion of two deuterons: Pg: 221 (2008) e = 1.6e-019; // Energy equivalent of 1 eV, J/eV x = 1.1; // Binding energy per nucleon of deuterium, MeV y = 7.0; // Binding energy per nucleon of helium-4, MeV E = (y - 2*x)*1e+06*e; // Energy released when two deut...
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function y=Euler_explicite(n) y0=1; dx=3*%pi/2/n; //(condition CFL)) for i=1:n+1 x(i)=(i-1)*dx; y(i)=(1+dx*sin((i-1)*dx))^i; end x=[0;x]; y=[1;y]; plot(x,y) t=0:0.1:5; z=exp(1-cos(t)); plot(t,z,'r') endfunction
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// This code plots the band structures of elk code // To use this code, please download BAND.OUT, BANDLINES.OUT clear; clc; xdel(winsid()); exec(PiLib); // Parameters ========================================================== work_dir=[]//['C:\MyDrive\Work\Eu-metal\elk\NSOC']; E_bound=[-3,+3] k_label=['$\Gamma$','M','K...
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//Page Number: 10.43 //Example 10.27 clc; //Given Rb=4.8D+3; //b/s bw=3.2D+3; //Hz //BPSK can give maximum spectral efficiency of 1bps/Hz, therefore not suitable //QPSK can give twice spectral efficiency,2bps/Hz, therefore qpsk=2*bw; //PSK can give thrice spectral efficiency,3bps/Hz, therefore psk=3*bw; ...
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//Calculate the control limits for the p-chart using 3σ limits //page no 143 clear clc; d=20; n=4000; P1=0.116; //Control limits for p-chart mprintf("\P1 = %.4f \n",P1); UCL=P1+3*sqrt((P1*(1-P1))/n); mprintf("\UCL = %.2f \n",UCL); LCL=P1-3*sqrt((P1*(1-P1))/n); mprintf("\LCL = %.2f \n",LCL); CL=P1; mprintf...
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//clear// //Caption: Program to find Magnetic Susceptibility, H,Magentization M //Example9.5 //page 279 clc; ur = 50; //relative permeability of ferrite material u0 = 4*%pi*1e-07; //free space permeability in H/m chim = ur-1; //magnetic susceptibility B = 0.05; //magnetic flux density in tesla u = u0*ur; H = ...
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clc clear //INPUT DATA BP=50;//Brake power in kW bmepp=700;//mean effective pressure pickup van bmept=850;//mean effective pressure typical nc=4;//4-stroke cylinder n=2;//for 4 cyliners Sp=8;//mean piston speed N=3000;//speed in rpm L=0.107;//stroke in m //CALCULATIONS Nm=Sp/(2*L);//Design speed in rps ...
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//Exa2.1 clc; clear; close; //given data : J=2.4; //in A/mm^2 J=2.4*10^6; //in A/m^2 n=5*10^28; //unitless e=1.6*10^-19; // in coulomb //Formula : J=e*n*v v=J/(e*n);//in m/s disp("Drift velocity is : "+string(v)+" m/s or "+string(v*10^3)+" mm/s")
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//check the o/p when the i/p vector contains only negative values a = [-1.0000 -0.6149 -0.9899 -0.0000 -0.0031 -0.0082]; k = poly2rc(a); disp(k); //output // 0.3114919 // 0.9961981 // - 0.0069234 // - 0.0019423 // 0.0082
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clc clear //Initialization of variables n1=8 //Moles of CO2 n2=9 //Moles of H2O n3=1 //Moles of Octane n4=12.5 //Moles of Oxygen disp("From Table B-10,") U11=3852 //Internal energy at 1000 R of CO2 U12=115 //Internal energy at 537 R of CO2 U21=3009 //Internal energy at 1000 R of H2O U22=101 //Internal energy...
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clc clear //DATA GIVEN Tfw=50; //mean feed water temp. in deg celsius p=5; //mean steam pressure in bar x=0.95; //dryness fraction of steam Mc=600; //coal consumption kg/hr C=30400; //calorific value of coal in kJ/kg Ms=4800; //feed water...
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//Engineering and Chemical Thermodynamics //Example 4.4 //Page no :185 clear ; clc ; //Given Psat_wat_25 = 3.169 * 10^3 ;// From steam table Psat_wat_50 = 1.235 * 10^4 ;// From steam table Psat_wat_100 = 1.014 * 10^5 ;// From steam table A =11.9673 ; B = 3626.55 ; C = -34.29 ; T1 = 25 ; //[*C] T2 = 50 ; ...
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clc disp("the soln of eg 10.1-->2-D steady heat conduction-Gauss Seidel method "); for i=1:9,tnew(i)=101,e(i)=1 //assumed values end t=1e-6 //since all the nodes are interior nodes so discretized eqn used is eqn 10.10 while e(1)>t&e(2)>t&e(3)>t&e(4)>t&e(5)>t &e(6)>t& e(7)>t& e(8)>t & e(9)>t ...
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// Scilab Code Ex1.2 Primitive unit cell: Page-4 (2010) a = 3, b = 3; // Lattice translation vectors along X and Y direction, angstrom c_bar = 3; // Assumed translation vector along Z direction, angstrom c = 1.5*(a+b+c_bar); // Real translation vector along Z direction, angstrom printf("\n%3.1f is the bod...
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Name=funscenario-invincible PlayerCharacters=A_air_lg_frozen;MovingTarget BotCharacters=MovingTarget.bot IsChallenge=true Timelimit=30.0 PlayerProfile=A_air_lg_frozen AddedBots=MovingTarget.bot PlayerMaxLives=0 BotMaxLives=0 PlayerTeam=1 BotTeams=2 MapName=square_1wall_clip_med_1spawn.map MapScale=1.0 Bloc...
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errcatch(-1,"stop");mode(2);//Example 1_25 ; ; //To find the value of the slit width lemda=6500 //units in angstroam theta=30 //units in degrees a=lemda/sin(theta*%pi/180) printf("The value of the slit is %.0f angstroam",a) exit();
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//angular and rotation// pathname=get_absolute_file_path('5.07.sce') filename=pathname+filesep()+'5.07-data.sci' exec(filename) //At point b, u=3 mm/sec u=3; //Displacemet of b(in mm): xb=u*t //Rate of angular deformation(in s^-1): def=U/h //Rate of rotation(in s^-1): rot=-0.5*U/h printf("\n\nRSULTS\n\n") ...
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clc; clear; // Primeira Fase da corrida a = 0 b = 1.5 m = 3 h = (b-a)/m ti = [0 0.5 1 1.5] // Intervalos de tempo. Ati = [0 0.35 0.55 0.9] // Aceleracao valorAcumulado = 0 // Guardar a soma da multiplicação dos coeficientes com a aceleração aux = 1; // Controlar a multiplicação dos coeficientes da Segunda Regra de Si...
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//Example 5.45 //Inverse Lagrange Method //Page no. 192 clc;close;clear; x=[30,34,38,42]; y=[-30,-13,3,18]; P=0; y1=0; for k=0:3 p=1 for j=0:3 if(j~=k) p=p*((y1-y(j+1))/(y(k+1)-y(j+1))) end end printf('\n L%i(f) = %g\n',k,p) p=p*x(k+1) P=P+p; end ...
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//<h2>=cheb1mag(n,omegac,epsilon,sample) //<h2>=cheb1mag(n,omegac,epsilon,sample) //Square magnitude response of a type 1 Chebyshev filter //omegac=passband edge //epsilon such that 1/(1+epsilon**2)=passband ripple //sample vector of frequencies where the square magnitude //is desired. // n :Filter order // ome...
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// @Harness: verifier // @Purpose: "Test for variable resolution" // @Result: "UnresolvedVariable @ 7:11" architecture unr_var_02 { subroutine foo(e: int): void { e = a[0]; } }
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//JEFFERSON BEZERRA clear clf() axis=gca() axis.thickness = 3 //-------------------------------------- //DADOS DE ENTRADA m = 10 //módulo z = 25 //número de dentes alfa = 13 //ângulo de pressão em graus xc = 0.05 //correção n = 250 // número de pontos //-------------------------------------- alfa = alfa * (%pi/180) ...
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a^2 + b^2 - c^2; a - A11*m^2 - A12*m*n - A13*n^2; b - A21*m^2 - A22*m*n - A23*n^2; c - A31*m^2 - A32*m*n - A33*n^2 isolated Signature: /c.01 isolated variable: c with Coefficient 1 remaining RelationSet: a^2 + b^2 - c^2; a - A11*m^2 - A12*m*n - A13*n^2; b - A21*m^2 - A22*m*n - A23*n^2 substitute by Polynomial: - A...
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function [f]=polfact(p) // Minmal factors of p // f=polfact(p) // // p : polynomila // f : vector [f0 f1 ... fn] such that p=prod(f) // - f0 constant // - fi polynomial //! // if size(p,'*')<>1 then error('polynomial argument required!'),end if norm(imag(coeff(p)))<>0 then error('real case only!'),end n=degre...
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// Exa 10.13 clc; clear; close; // Given data Q = 1100;// in kW m=1;// in kg p1 = 15;// in bar p1 = p1 * 10^5;// in Pa p1 = p1 * 10^-3;// in kPa p2 = 0.05 * 10^2;// in kPa v1 = 0.16;// m^3 per kg v2 = 26;// in m^3 per kg V1 = 110;// in m per s V2 = 120;// in m per s u1 = 2935;// in kJ per kg u2 = 1885;/...
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// Copyright (C) 2012 - Prateek Papriwal // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_V2-...
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 16.22w //calculation of the speed of the car //given data nudash=440//frequency(in Hz) emitted by the wall nudashdash=480//frequency(in Hz) heard by the car driver v=330//speed(in m/s) of the sound in the air //ca...
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//chapter-4 page 149 example 4.12 //============================================================================== clc; clear; //For an air filled circular Waveguide in the dominant mode D=4;//Inner diameter of an air filled circular Waveguide in cm c=3*10^10;//Velocity of Light in cm/sec //CALCULATION disp...
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clc; v=400; // balanced supply voltage i=10; // line current f=50; // frequency of supply m=3; // number of phases pf=0.8; // lagging power factor pfn=0.9; // improved power factor disp('staor in star'); i=i*(pf-%i*sqrt(1-pf^2)); // complex form of line current il=real(i)/pfn; // line current at improved powe...