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codeblock readtextfile(ScriptDir+"\_TOOLS.sci"); codeblock readtextfile(ScriptDir+"\_SSYS.sci"); mu=398600.4418; sats=list; gravforce=ForceField; gval=6.6742/1E11; emass=5.9736E24; gravforce.AddCentralGravity(point(0,0,0),mu); gravforce.SetAccuracy(100000000,10); function addsat(dst,spd,ang) { sat=satsetframe.adds...
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//chapter12,Example12_2,pg 357 lam=1*10^-6//wavelength n1=1.53 n2=1.5 NA=sqrt((n1^2)-(n2^2)) a=(2.405*lam)/(2*%pi*NA) printf("core radius\n") printf("a=%.8f m",a)
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errcatch(-1,"stop");mode(2);//Exa:1.6 ; ; i_amp=0.075;//given i_milamp=i_amp*1000;//current in milliamp. printf("%f amp current is %f mA",i_amp,i_milamp); exit();
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//Effects of leakage n1=0:0.005:0.1; n2=0:0.005:0.125; n3=0:0.005:1.125; xt1=(2*cos(20*%pi*n1')+5*cos(100*%pi*n1')); xt2=(2*cos(20*%pi*n2')+5*cos(100*%pi*n2')); xt3=(2*cos(20*%pi*n3')+5*cos(100*%pi*n3')); XDFS1=abs(fft(xt1,-1))/20; XDFS2=abs(fft(xt2,-1))/25; XDFS3=abs(fft(xt3,-1))/225; f1=0:5:100; f2=0:4:100; f3=0:100/...
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@relation led7digit @attribute Led1 real[0.0,1.0] @attribute Led2 real[0.0,1.0] @attribute Led3 real[0.0,1.0] @attribute Led4 real[0.0,1.0] @attribute Led5 real[0.0,1.0] @attribute Led6 real[0.0,1.0] @attribute Led7 real[0.0,1.0] @attribute number{0,1,2,3,4,5,6,7,8,9} @inputs Led1,Led2,Led3,Led4,Led5,Led6,Led7 @output...
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clear; clc; printf("\nEx-6.24\n"); //page no.-195 //given rho=1.73*10^-8;......//resistivity in ohm m M=63.5;...........//atomic weight d=8.92*10^3;......//density in Kg/m^3 N=6.023*10^23;......//avagadro no. e=1.6*10^-19;.......//charge m=9.11*10^-31;......//mass of e no=(N*d)/M........//no of electrons p...
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clear; clc; ZR=300;s=9;d=0.1 r=d/2; Zof=276*log10(s/r); Zoq=sqrt(ZR*Zof); do=(s*2)/10^(Zoq/276); printf("Diameter of wire used = %f cm",fix(do*10)/10);
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clear;lines(0); A=[1,2;3,4]; trace(A)-sum(diag(A)) sum(A,'c')-A*ones(2,1) sum(A+%i) A=sparse(A);sum(A,'c')-A*ones(2,1) s=poly(0,'s'); M=[s,%i+s;s^2,1]; sum(M),sum(M,2)
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//example 10 //exergy destruction during heat conduction clear clc To=273 //temperature of outdoor in K Tin=293 //temperature of inner surface of brick wall in K Tout=278 //temperature of outer surface of brick wall in K Q=1035 //rate of heat transfer through wall in W Xdestroyed=Q*(1-To/Tin)-Q*(1-To/Tout) //ex...
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//value// s=%s; H=syslin('c',(s+6)/((s+1)*(s+3))); plzr(H) printf("There are two adjacent placed poles at s=-3 &s=-1 \n") printf("One breakaway point exists between s=-3 & s=-1 \n") printf("One breakin point exists to the left of zeros at s=-6 \n")
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//Example12.2// Na=22.99;//amu //atomic mass of sodium O=16.00;//amu //atomic mass of Oxygen a=2;//Number of atoms c = 2; Na2O=c*Na+O mprintf("Na2O = %f amu",Na2O) d=3;//Number of atoms C=12.00;//amu //atomic mass of Carbon Na2CO3=c*Na+C+d*O mprintf("\nNa2CO3 = %f amu",Na2CO3) Ca=40.08;//amu //atomic mass of calcium Ca...
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// Ex13_2 Page:258 (2014) clc;clear; mu_0 = 4*%pi*1e-007; // Magnetic permeability, T-m/A e = 1.6e-019; // Charge on an electron, C m = 9.1e-031; // Mass of an electron, kg Z = 2; // Atomic number of He N = 28e+026; // Number of He atoms per unit volume of the sample, per metre-cube r_bar = 0.6e-0...
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//Function to round-up a value such that it is divisible by 5 function[v] = round_five(w) v = ceil(w) rem = pmodulo(v,5) if (rem ~= 0) v = v + (5 - rem) end endfunction //Obtain path of solution file path = get_absolute_file_path('solution4_5.sce') //Obtain path of data file datap...
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// Initilization of variables M=750 // kg // mass of hammer m=200 // kg // mass of the pile h=1.2 // m // height of fall of the hammer delta=0.1 // m // distance upto which the pile is driven into the ground g=9.81 // m/s^2 // acc due to gravity // Caculations // The resistance to penetration to the pile is give...
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clear; clc; // Stoichiometry // Chapter 6 // Stoichiometry and Unit Operations // Example 6.16 // Page 387 printf("Example 6.16, Page 387 \n \n"); // solution // M = E+B+W Tav = (45+32)/2 +273.15 //K avg cooling water T // using steam tables (Appendix A IV.1) lamda = 2410.5 //kJ/kg E = 530/la...
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// chapter 2 // example 2.2 // Find the stress and deformation of the cylinder // page-16 clear; clc; // given l=2; //.in m (length of the cylinder) D=50; // in mm (outer diameter of cylinder) d=30; // in mm (inside diameter of cylinder) P=25; // in kN (Load on the cylinder) E=100; // in GPa (Modulus of elasticity for ...
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//example 5.21 //calculate transmissibility //drawdown at pumping well clc; //given rw=0.15; //radius of well b=40; //depth of acquifer Q=1500; //discharge(lpm) s1=3.5; //drawdown of first well s2=2; //drawdown of second well H=40; r1=25; ...
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//magnitude of the reflection coefficent //given clc zl=10*%i//ohm z0=100//ohm row=(zl-z0)/(zl+z0)//reflection coefficent mag_row=norm(row)//magnitude of reflection coefficent disp(mag_row,'the magnitude of the reflection coefficent:')
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errcatch(-1,"stop");mode(2); //example 4-5 in page 98 ; //data given E=1;// E=1 V Im=1e-3;//FSD=1 mA Rm=100;// Rm in ohm //calculation R3=E/Im; printf("R3=%d K-ohm\n",R3/1000); printf("Vout=%.1f V\n",Im*(R3+Rm)); //result //R3=1 K-ohm //Vout=1.1 V exit();
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clc(); clear; // To calculate the wavelength associated with electron M=9.1*10^-31; //mass of electron in kg h=6.66*10^(-34); E=2000; //energy in eV Ej=E*1.6*10^-19; //energy in J lamda=h/sqrt(2*M*Ej); //wavelength in m lamda_nm=lamda*10^9; //converting lamda from m to nm printf("The wavelength ass...
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//Mission A2 //On prend l'image donnée path = "C:\Users\Jean-Guillaume P\Documents\Exia\A2\Projets\Imagerie\ExoLife\Images\Mission_A\Mars_surface.pbm" img_in = readpbm(path); //On utilise l'histogramme de cette image histo = histogrammeFct(img_in); //On utilise la fonction pourcentage qui calcule la moyenne de cha...
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funcprot(0) clf() // Ex.1 cd("/home/6im2/ylecoq/prog/tds/signal_s1/td3"); load("flute.dat"); x=flute; N=length(x); disp("N = " + string(N)); // plot(x) // Ex.2 function ret = petit_gamma(x) ret = convol(x,x(length(x):-1:1)); endfunction function ret = GAMMA_L(x, L) gamma_x = petit_gamma(x); for i=1:L ...
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output_file OutputFile = new output_file; sub CreateHeaderOutputFile(string sFilename) begin string sTrialData; ### Adapt this part to your own experiment (add/remove/change column names) sTrialData.append("TrialNo" + "\t"); sTrialData.append("StimulusTime" + "\t"); sTrialData.append("ButtonPressed" +...
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// chapter 12 // example 12.2 // calculate numerical aperture and the acceptance angle of an optical fibre // page 360 clear; clc; // given u1=1.55; // refractive index of core u2=1.50; // refractive index of cladding //calculate d=(u1-u2)/u1; // calculation of fractional index change NA=u1*sqrt(2*d); // ca...
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clear// //Vairable Declaration sigma_x=40 //Stress in x in MPa sigma_y=20 //Stress in y in MPa tau_xy=16 //Shear in xy in MPa //Calculations sigma=(sigma_x+sigma_y)*0.5 //Normal Stress in MPa R=sqrt(((sigma_x-sigma_y)*0.5)**2+tau_xy**2) //Resultant Stress in MPa //Part 1 sigma1=sigma+R //Principal Stres...
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//// write_obj // Write mesh data to OBJ format mesh file // //// Syntax // write_obj(filename,face,vertex) // //// Description // filename : string, file to read. // face : double array, nf x 3 array specifying the connectivity of the mesh. // vertex : double array, nv x 3 array specifying the position of the...
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clc clear //INPUT DATA g=1.4;//for isentropic compression n=1.3;//for polytropic compression p1=1;//pressure in bar v1=0.05;//piston displacement in m^3 R=0.287;//gas constant Rp=6;//compression ratio at constant pressure t1=293;//temperature in K //CALCULATIONS //Isentropic copression m=(p1*10^5*v1)/(100...
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//uCol = num_state + num_invar; //yCol = uCol + num_outvar; // using new functions ReOrderStateEqns // it brings all the state eqn to top polymat = ReOrderStateEqns(polymat, num_state); Rcols = [1:(num_state + num_invar + num_outvar)]; Mcols = [(num_state + num_invar + num_outvar + 1) :size(polymat,'c')]; //Mcols =...
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T= 2.7; //blackbody temperature, K Lambda= 2.898*10^(-3)/T; //using wein's displacement law, Eqn 9.40, m Lambda= Lambda*10^(3); //converting to mm disp(Lambda,"The wavelength for maximum radiation, in mm, is: ") //Result // The wavelength for maximum radiation, in mm, is: // 1.0733333
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//Example 1.11.1: peak reverse recovery current clc; clear; close; //given data : itt=10;// time in micro seconds qtt=150;//charge in micro colums prrc=((2*qtt)/itt);//peak reverse recovery current in amperes disp(prrc,"peak reverse recovery current in amperes")
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function [x,y,typ]=HH_RG_3s(job,arg1,arg2) x=[];y=[];typ=[]; select job case 'plot' then standard_draw(arg1) case 'getinputs' then [x,y,typ]=standard_inputs(arg1) case 'getoutputs' then [x,y,typ]=standard_outputs(arg1) case 'getorigin' then [x,y]=standard_origin(arg1) case 'set' then ...
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//Problem 5.07: //initializing the variables: P = 1; // in atm tm = 68.6; pS = 0.005; W = 112.5; MWS = 32; //calculation: wS = pS*W nS = wS/MWS perSO2bymol = nS*100/tm ppSO2 = perSO2bymol/100 printf("\n\nResult\n\n") printf("\n patial pressures for SO2 = %.2E atm ",ppSO2)
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> storage_restore ciyam Creating table T_Meta_User... Inserted 2 rows into table T_Meta_User... Creating indexes for table T_Meta_User... Creating table T_Meta_Workgroup... Inserted 1 rows into table T_Meta_Workgroup... Creating indexes for table T_Meta_Workgroup... Creating table T_Meta_Type... Inserted 58 rows into ...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Introduction to heat transfer by S.K.Som, Chapter 8, Example 1") //Water is heated by a vertical flat plate length(L=200mm or .2m )by breadth(B=200mm) which is maintained at temprature,Tw=60°C Tw=60; L=.2; B=....
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//clear// // Example10.33:Differentiation Property of Unilateral Ztransform // x[n] = (a)^(n+1).u[n+1] syms n z; a = 0.5; x =(a)^(n+1) X = symsum(x*(z^(-n)),n,-1,%inf) disp(X,"ans=") //Result //X(z)= 0.5*(2^(-%inf-1)*z^(-%inf-1)-2*z)/(1/(2*z)-1) //Equivalent to z/(1-0.5*z^-1)
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//To Determine the Continous Rating of the Motor for Suitable Conditions //Page 229 clc; clear; T=120; //Total Time t1=0; //Power Rise to 1050 t2=15; //Constant Power of 600 t3=85; //Regenerative Breaking at 200 t4=95; //Motor At Rest t5=120; //End //Note Power Rating are in Horse Power HP1=1050; //First Ri...
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//clear// //Example 4.12:Continuous Time Fourier Transform: //Derivative property clear; clc; close; // CTFT t = -1:0.1:1; x1 = ones(1,length(t)); x2 = [-1,zeros(1,length(t)-2),-1]; x = t; //differentiation of x can be expressed as //summation of x1 and x2 subplot(3,1,1) a = gca(); a.x_location = "origi...
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i = imread('test1.jpg'); corners = detectMinEigenFeatures(i,'MinQuality',1.1); disp(corners);
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//Exa 3.5 clc; close; clear; // given: f=500 //frequency in mega hertz f=500*10^6 //frequency in hertz c=3*10^8 //speed of light in m/s Gdmax=1.644 // directivity of a half wave dipole lambda=c/f //wavelength in meter Ae=((lambda)^2*Gdmax)/(4*(%pi)) // Effective area in m^2 disp(Ae,"effective area of half wa...
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clear; clc; //Example 7.4 fL=20*10^-3;//KHz Rd=6.7; Rl=10; Ts=1/(2*%pi*fL); printf('\ntime constant=%.3f ms\n',Ts) Cc=Ts/(Rd+Rl); printf('\ncoupling capacitance=%.3f microF\n',Cc)
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load Inc16.hdl, output-file Inc16.out, compare-to Inc16.cmp, output-list in%B1.16.1 out%B1.16.1; set in %B0000000000000000, eval, output; set in %B1111111111111111, eval, output; set in %B1010101010101010, eval, output; set in %B0001001000110100, eval, output;
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pathname=get_absolute_file_path('9_03.sce') filename=pathname+filesep()+'9_03data.sci' exec(filename) T=Mdot*(Ve-V)+(Pe-P)*Ae; disp(T,"T=","T=Mdot*(Ve-V)+(Pe-P)*Ae","Thrust of the turbojet T:") printf("\Answer:\n") printf("\n\Mean effective pressure : %f N\n\n",T)
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s=poly(0,'s') h=syslin('c',((10*s+1000)/(s^2+2*s+100))) clf();bode(h,0.1,100);
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// mode(-1); lines(0); my_handle = scf(100001); clf(my_handle,"reset"); demo_viewCode("wpca.dem.sce"); // DEMO START my_plot_desc = "wpca"; my_handle.figure_name = my_plot_desc; rotation = [7 -cos(3.14/4);sin(3.14/4) 1]; Train_Patterns = rand(2,100); Train_Patterns = rotation* Train_Patterns; ...
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clear; clc; close; Vcc = 12; Vbe = 0.7; Rx = 1.1*(10^(3)); Ix = (Vcc-Vbe)/Rx; disp(Ix,"Mirrored current :");
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clc T1=373; //K p1=1; //bar p3=65; //bar p4=p3; Vs=0.0085; //m^3 ratio=21; //Air fuel ratio r=15; C=43890; //kJ/kg cp=1; cv=0.71; V2=0.0006; //m^3 V1=0.009; //m^3 y=1.41; V5=V1; V3=V2; R=287; p2=p1*(r)^y; T2=T1*r^(y-1); T3=T2*p3/p2; m=p1*10^5*V1/R/T1; Q1=m*cv*(T3-T2); //Heat added during consta...
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10_15.sce
clc; clear; lambda1=400*10^-9 //wavelength in m lambda2=300*10^-9 //wavelength in m V1=0.82 //stopping potential in V V2=1.85 //stopping potential in V c=3*10^8 //velocity of light in m/s e=1.6*10^-19 //charge in C //calculation h=(e*(V1-V2)*(lambda1)*(lambda2))/(c*(lambda2-lambda1)) mprintf("\nThe Planck...
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//Ex14_4 Pg-696 clc NA=0.5 //numerical apperture n1=1.54 //core refractive index n2=sqrt(n1^2-NA^2) //cladding refractive index printf("(1) Cladding refractive index = %.3f \n",n2) RI=(n1-n2)/n1 //change in core cladding refractive index printf(" (2) RI of the core = %.4f",RI)
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clc clear //INPUT DATA Tl=20;//engine temprature in Degree C Th=500;//engine temprature in Degree C g=1.4;//gas constant v13=25;//expansion ratio //CALCULATIONS v14=((Th+273)/(Tl+273))^(1/(g-1));//Isentropic volume expansion v43=v13/v14;//Overall expansion ratio //OUTPUT printf('(a)Isentropic volume expa...
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//Example 5.21 clear; clc; //Given delHtrans=13.4;//latent heat of fusion in J g^-1 delVm=0.0126;//change in volume due to transition in cm^3 g^-1 T=368.5;//temperature in K //To determine the increase in the transition point between 2 forms of sulphur for increase in atmospheric pressure a=(delHtrans*10)/(...
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ex12_7.sce
clc; e=1.6*10^-19; //charge on an electron in coulomb q=10^-12; //charge on pith ball in coulomb n=q/e; //calculating no of electrons disp(n,"No. of electrons = "); //displaying result
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fht.sci
function y=fht(d,n,dim) funcprot(0); rhs=argn(2); if(rhs<1 | rhs>3) error("Wrong number of input arguments.") end select(rhs) case 1 then y=callOctave("fht",d) case 2 then y=callOctave("fht",d,n) case 3 then y=callOctave("fht",d,n,dim) end endfunction
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clc clear //input data n=3//Number of stages D2=0.4//Outlet impeller diameter in m b2=0.02//Outlet impeller width in m b22=45//Backward vanes angle at outlet in degree dA=0.1//Reduction in circumferential area nm=0.9//Manometric efficiency of the pump Q=0.05//Discharge of the pump in m^3/s N=1000//Running sp...
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clc;funcprot(0);//Example 2.39 //Initilisation of Variables K=250;....//thermal conductivity of fin in W/m*degrees celcius h=30;....//heat transfer coefficient between fin and surrounding of air in W/m^2*degrees celcius d=0.015;....//diameter of fin in m Tb=250;...//base temparature of fin in degrees celcius Ta=2...
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clear; clc; //Example - 1.13 //Page number - 30 printf("Example - 1.13 and Page number - 30\n\n"); //Given // Cp0=7.7+(0.04594*10^(-2)*T)+(0.2521*10^(-5)*T^(2))-(0.8587*10^(-9)*T^(3)) T_1 = 400;//[K] T_2 = 500;//[K] //(C)avg = q/(T_2 - T_1) = 1/(T_2 - T_1)*{(integrate('C','T',T_1,T_2))} //(Cp0)avg = 1/(...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monitor...
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a b a c o แ อ บ า โ ก a b a t e อ เ บ ต a b b e y แ อ บ บ ี ย ์ a b d a l อ ั บ ด ั ล a b d e l l a h แ อ ็ บ เ ด ล ล ่ า a b e g g เ อ อ บ ิ ก a b e n d แ อ ็ ป เ บ ็ น ด ์ a b e r d o u r แ อ เ บ อ ร ์ ด อ ร ์ a b i l e n e แ อ บ ิ ล ี น a b i n g d o n แ อ บ ิ ง เ ด ิ น a b l a k o v อ ั บ ล า ค อ ฟ a b o y n e เ อ ...
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tek koteka V;FUT tindik tindikaki V;PST yeb yebaki V;PST yeb koyeba V;NFIN vand vandi V;PRS mem memi V;PRS yamb koyamba V;NFIN bom koboma V;NFIN lob lobaki V;PST kende kendei V;PRS mel komela V;NFIN ling lingaki V;PST luk koluka V;NFIN lamb kolamba V;NFIN tek koteka V;NFIN tun tunaki V;PST tang kotanga V;FUT telem tele...
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// Example 6-8-1 // Design of a lag lead compensator using root locus 1 // zeta ~= gamma (not equal to) clear; clc; xdel(winsid()); //close all windows // please edit the path // cd "/<your code directory>/"; // exec("rootl.sci"); s = %s; G = syslin('c',4 , s * (s + 0.5)); //open loop system Kv = 80; // d...
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path=sci+'/demos/bike/' // compile if necessary host("cd "+path+"; make simul"); // link if necessary deff('[]=linkif(fname)',['if ~c_link(fname) then'; 'link(''/tmp/''+fname+''.o'',fname);end']); linkif('gjx'); linkif('constr'); linkif('ii'); linkif('h'); // Macros made by Maple getf(path+'src/'+'...
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clf; //dx xx = [0.0142857, 0.0153846, 0.0166667, 0.0181818, 0.02, 0.0222222, 0.025, 0.0285714, 0.0333333, 0.04 ] //dt = 0.000125 y1 = [0.0012024973109042714, 0.0012809568647734193, 0.0013707805543214935, 0.0014749791114914146, 0.0015934183529330292, 0.001738576916200718, 0.0019061696251357896, 0.002111793916791005, 0....
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//chapter-5 page 174 example 5.1 //============================================================================== clc; clear; //For a circular waveguide a=3;//radius in cm f0=10*10^9;//resonant frequency of a circular resonator in Hz disp('Given the mode of operator is TM011 so here n=0,m=1,p=1'); c=3*10^10;...
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// Example 4.10 // find alpha that maximizes (4.77) mode(0) function gMC = gMC(alfa) // Mohr-Coulomb activation function sn = s2*cosd(alfa)^2//normal stress tauT = -s2*sind(alfa)*cosd(alfa)//transverse shear on the fracture plane tauL = s6*cosd(alfa)//longitudinal shear on the fracture plane gMC = (...
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clc; pathname=get_absolute_file_path('9_5_soln.sce') filename=pathname+filesep()+'9_5_data.sci' exec(filename) // Solution: // acceleration due to gravity, g=32.2; //ft/s^2 // pump's theoretical flow-rate, Q_T_pump=(V_D_pump*Np)/231; //gpm // pump's actual flow-rate, Q_A_pump=(Q_T_pump*eff_v_pump)/100; //gpm // veloci...
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//Example 16.5. //let input wave be V_in=V_p_in*sin(2*%pi*f*t) f=1; //Frequency is 1Hz T=1/f; V_p_in=10; //Peak input voltage V_th=0.7; //knee voltage of diode clf(); //let n be double the number of cycles of output shown in graph for n=0:1:1 t=T.*n/2:0.0005:T.*(n+1)/2 //time for each half cyc...
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clc; printf("Given problem is theoritical and no mathematical solving required for this problem");
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//Chapter-12, Example 12.5, Page 344 //============================================================================= clc clear //INPUT DATA Imax=400*10^-3;//maximum value of current in mA Iav=150*10^-3;//average value of current in mA Vs=100;//maximum value of secondary voltage in V //CALCULATIONS //we know th...
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lab1.sce
f = scf(); // Cria uma nova figura f.background = color("white") // Define o fundo da figura na cor branca // Plotar uma senoide t = 0:0.01:10; // gerar um conjunto de pontos no tempo T = 2; // período da onda A = 1; // amplitude da onda y = A*sin(2*%pi*t/T); plot(t,y) // *** Exemple: To=T/8, t=0 *** //T0 = T/8; //t_...
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//Ex11_5 clc VCC = 9//collector voltage Vp = 5//output peak voltage VQ = VCC//operating point VCEmax = VQ + Vp// maximum value of collector emitter voltage VCEmin = VQ - Vp// minimum value of collector emitter voltage disp("VCC = "+string(VCC)+"V") disp("Vp = "+string(Vp)+"V") disp("VQ = VCC = "+string(VQ)+"V"...
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//Initilization of variables F1=-20 //N F2=30 //N F3=5 //N F4=-40 //N //Distances with respect to point O x1=6 //m x2=0 //m x3=8 //m x4=13 //m //Calculations R=F1+F2+F3+F4 //N //Applying moment about point O equal to zero M_O=-(F1*x1)+(F2*x2)+(F3*x3)+(F4*x4) //N-m //Applying moment about point O equal to ...
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//Book name: Fundamentals of electrical drives by Mohamad A. El- Sharkawi //chapter 3 //example 3.4 //edition 1 //publisher and place:Nelson Engineering clc; clear; Vrms=110; //The voltage on the ac side in volts R=10; //Resistance value of the resistive load...
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6_13.sce
clear; clc; // Illustration 6.13 // Page: 380 printf('Illustration 6.13 - Page: 380\n\n'); // solution //*****Data*****// // A-benzene B-toluene C-1,2,3-trimethylbenzene // From example 6.10 Nmin = 4.32; // [stages] // From example 6.11 Rmin = 0.717; // [minimum reflux ratio] // For R = 1 R = 1; X ...
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clear; clc; close; yos = 20*10^(-6); Idss = 10*10^(-3); Idq = 10*10^(-3); Vp = -4; Vdsq = Vp/4; Rg = 10*10^(6); Av = -8; Vdd = 20; Vgsq = Vp/4; Id = Idss*(1-(Vgsq/Vp))^2; gmo = 2*Idss/abs(Vp); gm = gmo*(1-(Vgsq/Vp)); //let Rd||rd = x x = abs(Av)/gm; rd = 1/yos; Rd = 106.5*10^(3)/47.87; Rs = -Vgs...
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clc; clear; x=[0.05 0.12 0.15 0.3 0.45 0.7 0.84 1.05]; y=[0.957 0.851 0.832 0.72 0.583 0.378 0.295 0.156]; sx=sum(x); sxx=sum(x.*x); sx3=sum(x.*x.*x); sx4=sum(x.*x.*x.*x); sx5=sum(x.*x.*x.*x.*x); sx6=sum(x.*x.*x.*x.*x.*x); n=8; sy=sum(y); sxy=sum(x.*y); sx2y=sum(x.*x.*y); sx3y=sum(x.*x.*x.*y); m=[n sx sx...
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//СРС clc disp('Календрарь на сегодня:') disp(calendar()); disp('****************************************') disp('Календрарь') disp(calendar(2018,9)); disp('****************************************') disp('Дата:') disp(date()); disp('****************************************') disp('Количество дней:') disp(datenum())...
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//Example 2-8, Page No- 38 clear clc gain_dB = 40 pout_W= 100 pin_W = pout_W/10^4 printf('The input power is %.2f watt',pin_W);
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clc clear //Input data R=[3,5,6,7]//Resistances from circuit diagram 12.36(a) on page no. 193 in ohms V=12//Voltage in V from circuit diagram 12.36(a) on page no. 193 //Calculations Vth=(V*R(3))/(R(3)+R(4)+R(2))//Equivalent voltage in V Rth=R(1)+(((R(2)+R(4))*R(3))/(R(2)+R(4)+R(3)))//Equivalent resistance in o...
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function [xlow, x2, fx2, x1, fx1, xup, d, xopt, ea] = golden(funcion, xlow, xup, niter) phi = (1 + sqrt(5))/2; for i=1:niter d = (xup - xlow)/phi; x1 = xlow + d; x2 = xup - d; fx1 = funcion(x1); fx2 = funcion(x2); if (fx1 < fx2) then ...
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//chapter_no.-8, page_no.-346 //Example_no.8-5-1 clc; //(a)Calculate_the_power_gain R=25;//R=f0/fs ,ratio_of_output_frequency_over_signal_frequency rQ=10;//figure_of_merit x=((rQ)^2)/R; PG=(R*x)/((1+sqrt(1+x))^2); PG=10*log10(PG);//calculating_in_dB disp(PG,'Up-converter_power_gain_(in dB)is ='); //(b)Calculate_the...
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//Simpson's (1/3)rd Rule deff('y=f(x)','y=x^4') a=input("Enter Lower Limit: ") b=input("Enter Upper Limit: ") n=input("Enter number of sum intervals: ") h=(b-a)/n add1=0 add2=0 add3=0 for i=0:n x=a+i*h y=f(x) disp([x y]) if (i==0)|(i==n) then add1=add1+y else if (modulo(...
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//Chapter 14 Determination of Hydroniumion Concentrations clc; clear; //Initialisation of Variables e= 0.266 //v R= 0.0592 //CALCULATIONS pH= e/R //RESULTS mprintf("pH of the unkown solution= %.2f",pH)
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//fiber optic communications by joseph c. palais //example 8.4 //OS=Windows XP sp3 //Scilab version 5.4.1 //given clc clear all loss=0.25//loss for each type of misalignment in dB a=50//core radius in um NA=0.24//numerical aperture dby2a=0.045//lateral offset from given plots for loss of 0.25dB theta=2.4//an...
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//Example 2.2<i> //Find whether the given signal is causal or not. clear all; clc; n=10;x1(1)=1;x2(1)=1; for i=2:length(n) x1(i)=i; x2(i)=i-1; y(i)=x1(i)+1 ./x2(i); end causal=%t; for i=1:length(n) if n(i)<0 &y(i)~=0 then causal=%f; end end disp(causal,"The statement that th...
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//example 11.7 clc; funcprot(0); Ep=207e6; Ip=123e-6; nh=12000; //from table xz=0.008; Ax=2.435; T=(Ep*Ip/nh)^0.2; Qg1=xz*Ep*Ip/Ax/T^3; //part2 Fy=248000; d1=0.254; Am=0.772; Mzmax=Fy*Ip*2/d1; Qg2=Mzmax/Am/T; if Qg2>Qg1 then Qg=Qg1; disp(Qg,"lateral load in kN"); end
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//Calculating the value of primary current //Chapter 3 //Example 3.6 //page 207 clear; clc; disp("Example 3.6") I0=1.5; //no-load current phi0=acosd(0.2) I2=40; //secondary current in amperes phi2=acosd(0.8) r=3; //ratio of primary and secondary turns I1=I2...
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clc //given s=1.125//inch e=0.25//inch t=2.25//inch alpha=35//degrees //from 5.2, we know theta+alpha=sininverse(s/t) x=asind(s/t) y=180-x//sin(x)=sin(180-x)=sin(y) //at admission p=x-alpha //at cutoff q=y-alpha //from 5.3, theta+alpha=sininnverse(-e/t) ang=asind(-e/t) angle=abs(ang) a=180+angle//lies...
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x=[0.3:0.3:10] y1=3 .*sin(x)-1 .*(cos(x)^2) scf(0) //subplot(221) plot(x,y1,'LineStyle','--','Color','r','Thickness',1,... 'Marker','s','MarkerEdgeColor','b','MarkerFaceColor','y',... 'MarkerSize',2) xtitle('График функции y1(x)','X','Y') legend('y1(x)',1) xgrid y2=(3 .*(1+(x.^2))^0.5)./(x+5) //subplot(223) scf(1) plot...
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//Page Number: 42 //Example 1.17 clc; //Given c=3D+8; //m/s f=10D+9;//hz er=6; tandel=2D-4; vp=c/er;//m/sec disp('m/sec',vp,'Phase velocity:'); al=(%pi*f*tandel)/vp;//Np/m disp('Np/m',al,'Attenuation constant:'); //Answer for velocity is calculated wrong in book, hence answers dont match for both
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// anim_block_rotate.sce clear; xdel(winsid()); exec('Euler2R.sci',-1); exec('GeoVerMakeBlock.sci',-1); exec('GeoPatMakeBlock.sci',-1); // Block specification Lx = 0.15; Ly = 0.05; Lz = 0.30; // Motion data t = [0:0.001:1]'; // Time data r = [0*t, 0*t, 0*t]; // Position data A = [2*%pi*t,...
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// Calculating Difference mode gain and output voltage clc; V2=5*10^-3; V1=3*10^-3; Vo=300*10^-3; Vd=V2-V1; Ad=Vo/Vd; disp(Ad,'difference mode gain=') V2=155*10^-3; V1=153*10^-3; Vo=Ad*(V2-V1); disp(Vo,'output voltage (V)=')
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//chapter 14 //example 14.4 //page 302 gain_abs=30 n=5 Ap1=10*log10(gain_abs) // db Ap_tot=Ap1*n Ap_f=Ap_tot-10 // db printf("total power gain = %.3f db \n",Ap_tot) printf("power gain with negative feedback = %.3f db \n",Ap_f)
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clc; //ex3.10 Vlpk=20.5; //volt RL=5100; //ohm Ilpk=Vlpk/RL; //Ampere// from v=r*i Vave=13.1; //volt//from v=r*i Iave=Vave/RL; //Ampere disp('mA',Ilpk*1000,"Ilpk="); //The answers vary due to round off error disp('mA',Iave*1000,"Iave="); //The answers vary due to round off error
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// Name and UIN load Add6.hdl, output-file Add6.out, compare-to Add6.cmp, output-list a%B1.6.1 b%B1.6.1 out%B1.6.1 carry%B3.1.3; set a %B000001, set b %B000001, eval, output; set a %B000000, set b %B111111, eval, output; set a %B101010, set b %B010101, eval, output; set a %B001100, set b %B110011, eval, output; ...
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clc rk = 14 // Compression ratio k = 6 // cutoff percentage ratio rc = k/100*(rk-1)+1 g = 1.4 // Heat capacity ratio n_diesel = 1-((1/g))*(1/rk^(g-1))*((rc^(g-1))/(rc-1)) // Cycle efficiency printf("\n Example 13.2\n") printf("\n Air standard efficiency is %f percent",n_diesel*100) //The answers vary due to rou...
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clf(); clear all S=0:10:100; t=100; Y=grand(1,10000,'exp',2); G=grand(1,10000,'exp',2); s=10^(S/10); for i=1:1:length(S); K=(S(i)*(Y^2+G^2)); X(i)=sum(K<t)/10000; end plot(S,X); xlabel("power"); ylabel("probability of error"); title("MRC Simulation");
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clc //Chapter 1 Signals //Example 1.5, page no 19 //given T=1,t0=0,wo=2*%pi P=1 t=0:0.001:1 f=P*t //The trigonometric Fourier series coeff for given function a0=(1/T)*inttrap(t,f) for n=1:10 f1=(P*t).*cos(wo*n*t) a(n)=(2/T)*inttrap(t,f1) if a(n)<0.01 then a(n)=0 end end for n=...
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#************************************************************ # Scenario of Ikea # # date : Wed Feb 8 19:58:29 2012 #************************************************************ p3d_sel_desc_name P3D_ENV Ikea p3d_sel_desc_name P3D_ROBOT Lampe p3d_set_robot_steering_method Linear p3d_set_robot_current 0.000000 0....
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 10.5 //calculation of the moment of inertia of the wheel //given data r=10*10^-2//radius(in m) of the wheel F=5//force(in N) of pulling aplha=2//angular acceleration(in rad/s^2) of the wheel //calculation tau=F*r...
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//Example 7.9 //Newtons Backward Formula //Page no. 243 clc;close;clear; printf(' x\t y\t d\t d2\t d3\t d4\t d5\t d6\n') printf('---------------------------------------------------------------') h=0.1; deff('y=f2(x)','y=(z(x-2,4)+z(x-3,5)+z(x-4,6))/h^2') z=[1,7.989;1.1,8.403;1.2,8.781;1.3,9.129;1.4,9.4...