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//creating the function of rosenbrock function function y= f(x) y=(100*((x(2)-(x(1)^2)))^2)+((1-x(1))^2); //eq of rosenbrock function endfunction //y=(100*((x2-(x1^2)))^2)+((1-x1)^2); function a=g(x1,y1) a=f([x1 y1]); endfunction x1=linspace(-2,15,200); x2=linspace(-2,15,200); //feval(x,y,f)returns th...
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// Aim:Refer Example 14-3 for Problem Description // Given: // air flow-rate: Q=270; //scfm // pressure at which compressor delivers air: p_out=100; //psig // overall efficiency of compressor: eff_o=75; //% // pressure at which compressor delivers air taking friction in account: p_out1=115; //psig // efficiency of elec...
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// Measure running time of Divide.asm // Requirement: set R4 to 1, just before INFINITE_LOOP(end of program) load DivideTime.asm, output-file DivideTime.out, output-list RAM[0]%D1.6.1 RAM[1]%D1.6.1 RAM[2]%D1.6.1 RAM[3]%D1.6.1 time%S1.5.1; set PC 0, set RAM[0] 17, set RAM[1] 3, set RAM[2] -1; set RAM[3] -1; set RAM[4]...
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// Scilab Code Ex1.14 Speed of an electron for an equivalent proton mass: Pg: 25 (2008) c = 3e+08; // Speed of light, m/s m0 = 1; // For convenience, rest mass of an electron is assumed to be unity m = 2000*m0; // Rest mass of a proton, units // As m = m0/sqrt(1 - (v/c)^2), solving for v v = sqrt(1 - (m0/...
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// ==================================================================== // Template toolbox_skeleton // This file is released under the 3-clause BSD license. See COPYING-BSD. // ==================================================================== // // function block = my_mean(block, flag) if flag == 1 then ...
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clc disp("Example 12.6") printf("\n") printf("Given") disp("The system CBA is WYE connected") disp("Maximum line voltage is 150V") disp("The three impedances are 6(0 deg),6(30 deg),5(45 deg)") ZAmag=6;ZAph=0; ZBmag=6;ZBph=30; ZCmag=5;ZCph=45; //Let maximum line voltage is Vmax Vmax=150 //Let the line to n...
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// Pergunta 1 // // Que o pivô (a1) é diferente de zero // // Pergunta 2 // // c = - aij/ajj, porque esse escalar multiplicado pela linha j e o // resultado somado à linha i, zera aij que é imediatamente anterior à diagonal // principal e é o primeiro elemento não-nulo da linha i // // // // function [E] = elementar(t...
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// Test # 1 : No Input Arguments exec('./tf2ca.sci',-1); [d1,d2,b]=tf2ca(); //!--error 10000 //Only 2 input arguments allowed //at line 37 of function tf2ca called by : //[d1,d2,b]=tf2ca();
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--> grados1=70 grados1 = 70. --> grados2=30 grados2 = 30. --> grados3=90 grados3 = 90. --> radianes1=grados1*%pi/180 radianes1 = 1.2217305 --> radianes2=grados2*%pi/180 radianes2 = 0.5235988 --> radianes3=grados3*%pi/180 radianes3 = 1....
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clear// //Variables V = 1.5 //Voltage (in Volts) E =7.5 //Energy produced (in Joules) //Calculation Q = E/V //Charge separated ( in Coulomb ) //Result printf("\n The Amount of charge separated by the battery is %0.3f C.",Q)
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//Variable declaration N=3*10**28; //number of atoms(per m**3) alpha_e=10**-40; //electronic polarizability(F m**2) epsilon0=8.85*10**-12; //Calculation epsilonr=(alpha_e*N/epsilon0)+1; //dielectric constant of material //Result printf('dielectric constant of material is %0.3f \n',(eps...
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function applymap() // Apply a function to a Dataframe elementwise. // // Syntax // dfr.applymap(input_string) // // Parameters // input_string : String containing the function to be passed. Scilab functions are not supported as of now. // // For additional information on parameters, see...
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clc //initialisation of variables H1= 9 //ft A= 2 //ft^2 H2= 4 //ft d= 2.25 //in t= 60 //sec g= 32.2 //ft/sec^2 //CALCULATIONS a= (d/12)^2 Cd= (A*H2*(H2-A))/(t*a*sqrt(2*g)) //RESULTS printf ('coefficient of dicharge = %.3f ',a) //ANSWER GIVEN IN THE TEXTBBOK IS WRONG..VERIFIED WITH CALCULATOR
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//Chapter 24 Ex 13 clc; clear; close; inc=3; dec=4; x=poly(0,'x'); y=(x-7); //from given condition 1 y=(3*x-12)/4; //from given condition 2 for x=1:99 if (x-7)==((3*x-12)/4) then break; end end y=x-7; area=2*(x+y); mprintf("The perimeter of the rectangle is %d cm.",area);
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//ANALOG AND DIGITAL COMMUNICATION //BY Dr.SANJAY SHARMA //CHAPTER 7 //SAMPLING THEORY AND PULSE MODULATION clear all; clc; printf("EXAMPLE 7.13(PAGENO 326)"); //given //x(t) = 8*cos(200*%pi*t) f= 100//highest frequency component of continuous time signal in hertz f_s2 = 400//sampling frequency in hertz for...
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clc //Initialization of variables hc=73.5 hb=26.28 hd=91.58 hc2=190.7 hd2=244.3 hb2=44.4 m1=1 //lbm m2=0.461 //lbm hc1=73.5 hd1=83.35 hc2=197.58 hd2=224 hb1=12.55 //Calculations w1=hc-hd qa1=hc-hb cop1=abs(qa1/(w1)) hp1=4.71/cop1 w2=hc2-hd2 qa2=hc2-hb2 cop2=abs(qa2/(w2)) hp2=4.71/cop2 qa3=m1*(hc...
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clc; //e.g 13.5 N=150; mur=3540; mu0=4*%pi*10**-7; l=0.05; A=5*10**-4; L=(mur*mu0*A*N*N)/l; disp('H',L*1,"L=");
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clc //initialisation of variables m=27*10^-3//N.s/m^2 sg=0.90 m1=27//cp v1=5.6*10^-4//lbf.sec/ft^2 v2=2.5*10^-2//m y=9802//N/m^3 g=9.8//m/s^2 Nr=4000 Nr1=2000 //CALCULATIONS P=(y*sg)/g//N.s^2/m^4 V1=(Nr*m)/(v2*P)//m/s V2=(Nr1*m)/(v2*P)//m/s //RESULTS printf('The critical velocity range is=% f m/s',V2)
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// Problem no 14.1,Page No.325 clc;clear; close; b=2 //m //width FOS=1.5 //Factor of safety //rho_mason=2.5*rho_w mu=0.5 //coeffeicient of friction //Calculations //Let L=1 m (length of dam) L=1 //W=b*H*L*rho //After substituting values and Further simplifying we get //W=2*H*rho //Total Pressure //P=W*H**2*2**-1 ...
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function a=inversa(u) [l,c]=size(u) np=1 //numero do pivo if l~=c then disp("A deve ser quadrada") a="erro" else e(:,:)=0 for i=1:l e(i,1:l)=u(i,1:l) end for i=1:l e(i,l+i)=1 end disp("[A | I]=") disp(e) for n=1:c // ...
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function [X,Y,gama]=fullstate(A,B1,B2,C1,D12,D11) // Copyright INRIA // Generated by lmitool on Thu Feb 09 11:30:44 MET 1995 Mbound = 1e3; abstol = 1e-10; nu = 10; maxiters = 100; reltol = 1e-10; options=[Mbound,abstol,nu,maxiters,reltol]; ///////////DEFINE INITIAL GUESS AND PRELIMINARY CAL...
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//Example 2.22 //Graeffe Method //Page no. 40 clc;clear;close; a=[1,-4,5,-2] k=0; for k=2:6 for i=1:4 a(k,i)=(-1)^(i-1)*(a(k-1,i))^2 j=1; while i+j<5 & i+j>2 a(k,i)=a(k,i)+(-1)^(i-j-1)*2*(a(k-1,i-j))*a(k-1,i+j) break j=j+1; end ...
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Tint 0 0 0 0 TintAlphaChange 100 1 Linear Wait 1 TintAlphaChange 0 1 Linear Wait 1 Loop
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// Exa 8.7 clc; clear; close; //given data R1= 150;// in ohm R2= 68;// in kohm R2=R2*10^3;// in ohm Vin= 500;// in mv V_sat= 14;//in volt V_pos= R1/(R1+R2)*V_sat;// in volt V_UT= V_pos;//in volt // In the same way when output is -14 volts and starts increasing in negative direcition V_sat=-14;//in volt V...
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//Chapter 12 //page no 494 //given clc; clear all; Voutp=28; //in dB Pin=1; //in mW R=800; //in V/W Vavg=10^(Voutp/20); //in m=Vavg*sqrt(2)/Pin/R; printf("\n The modulation depth ,m = %0.1f percent",m*100);
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# This test file was generated from offline assembler source # by bldhtc.rexx 16 Jan 2016 12:11:11 # Treat as object code. That is, modifications will be lost. # assemble and listing files are provided for information only. *Testcase ilc numcpu 1 sysclear archmode z r 60=00020000000000000000000000000000 r 70=0...
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figure(); mapped= read("MappedRevenue.txt",-1,2); time = mapped(20:1500,$-1); average= mapped(20:1500,$) ./ time; plot2d(time,average);
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delta_t = 0.01 plant_pvt_init_data = None # ideal X0 # initial_set = [[-0.1, -0.1, 0.0], [0.1, 0.1, 0.0]] # hardest #error_set = [[-1., -0.6, 5.40], [1., 0.6, 5.45]] # smaller X0 #initial_set = [[-0., -0., 0.0], [0.1, 0.1, 0.0]] #error_set = [????] # property: P1 [can make X0 bigger by extending into -ve direction] ...
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//Example No. 4_17 //Pg No. 83 disp('Theoritical Problem') disp('For Details go to page no. 83')
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clc disp("Example 1.27") printf("\n") disp("find the forward current in circuit of fig 1.22") //given V=9 Vd=0.3 R=3.3*10^3 //current I=(V-Vd)/R printf("forward current=%f Ampere",I)
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// Example 34_9 clc;funcprot(0); //Given data L=60;// MW L_0=0;// Zero load in MW // I=5*10^6*(8+8*L+0.4L^2) T_f=20;// Time in hours T_0=4;// Time in hours // Calculation E_g=(T_f*L)+(T_0*0);// Total energy generated by the power plant during 24 hoursbin MWh I_60=5*10^6*(8+(8*L)+(0.4*L^2))*20;// Input to th...
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clc; //e.g 18.5 Rb=400*10**3; Vcc=20; Rc=2*10**3; Re=1*10**3; beta=100; Ib=Vcc/(Rb+(beta*Re));//saturation current disp('mA',Ib*10**3,"Ib="); Ic=beta*Ib; disp('mA',Ic*10**3,"Ic="); Vce=Vcc-(Ic*(Rc+Re));//cut-off voltage disp('V',Vce*1,"Vce=");
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//Ex_2_11 clc; clear; close; format('v',6); //given data : lg=0.01/100;//m(airgap) li=39.99/100;//m(mean length) mur=2000;//relative permeability mu0=4*%pi*10^-7;//permeability N=1000;//turns A=9/10000;//m^2 fi=1;//mWb S=li/(mu0*mur*A)+lg/(mu0*A);//AT/Wb I=fi*10^-3*S/N;//A disp(I,"Current required(A)");...
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clc clear //INPUT t1=400;//inital temperature in K dv=2;//ratio of volumes final and inital r=8.31*10^7;//universal gas constant in ergs/kg.K //CALCULATIONS w=r*t1*log(2);//work done in expanding isothermally in ergs //OUTPUT mprintf('the work done in expanding isothermally is %3.2f ergs',w)
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clc //initialisation of variables d= 2 //ft l= 1000 //ft f= 0.0075 H1= 20 //ft A1= 100000 //ft^2 A2= 50000 //ft^2 g= 32.2 //ft/sec^2 //CALCULATIONS h= 2*A1/A2 H2= H1-h t= 2*A1*A2*sqrt(1.5+(4*f*l/2))*0.47/((A1+A2)*(%pi*d^2/4)*sqrt(2*g))/60 //RESULTS printf ('Time taken to lower the level of water = %.f mi...
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clc clear //Initalization of variables t1=45+460 //R th=70+460 //R t2=-200+460 //R th2=100+460 //R //calculations cp1=t1/(th-t1) cp2=th/(th-t1) cp3=t2/(th2-t2) cp4=th2/(th2-t2) //results printf("In case 1, Refrigerator cp = %.1f",cp1) printf("\n In case 1, Heat pump cp = %.1f",cp2) printf("\n In case 2, ...
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function data = load_rank(path,filename,score_idx) //load file all_data = csvRead(path+filename,",",".","string"); //concatenate name of technique (1st column) to the indexes to retrieve score_idx = [1, score_idx]; //extract the correct columns for each row of the file data=all_da...
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// Red Green Blue Red Green Blue verde = [ 3 20 15 2 14 8; 3 20 15 2 14 8; 3 20 15 2 14 8; 3 20 15 2 14 8; 3 19 15 2 14 8; 3 19 15 2 14 8; 3 19 15 2 14 8; 3 20 15 2 14 8; 3 20 15 2 14 8; 3 20 15 2 14 8; 3 20 15 2 14 8; 3 20 15 2 14 8; 3 20 15 2 14 8; 3 19 15 2 14 8; 3 19 15 2 14 8; 3 19 15 2 14 8; 3 19 15 2 14 8; 3 19 ...
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clc //initialisation of variables clear p2= 67.2 //lbf/in^2 p1= 63 //lbf/in62 r= 1.4 n= 0.6 T1= 870 //R ma1= 0.8 //ft/sec //CALCULATIONS dt= (p2/p1)^((r-1)/r)-1 dt1= dt/n T2= T1*(1+dt1) Ts1= T1*(1+0.5*(r-1)*ma1^2) ps1= p1*(1+0.5*(r-1)*ma1^2)^(r/(r-1)) ps2= p2*(Ts1/T2)^(r/(r-1)) dp= ps1-ps2 //RESULTS ...
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a.name = "Anshuman" a.age = 20 a.marks = 299 b.name = "Unknown" b.age = 20 b.marks = 150 c.name = "Unknown" c.age = 20 c.marks = 200 disp((a.marks+b.marks+c.marks)/3)
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% REORIENT_FACETS Reorient faces of a triangle mesh (V,F) so that the left-hand % rule normal of each face (consistently) points outward. % % [FF,I] = reorient_facets(V,F) % [FF,I] = reorient_facets(V,F,'ParameterName',ParameterValue, ...) % % Inputs: % V #V by 3 list of vertex positions % F #F by 3 list of trian...
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//to calculate m/c eff as a generator and max eff when generating and motoring. clc; Pop=10*1000; Vt=250; Ra=.8; Rf=275; Ia=3.91; Psh=Vt^2/Rf; Prot=Vt*Ia-Ia^2*Ra;disp(Prot,'rotational loss(W)'); I1=Pop/Vt; If=Vt/Rf; Ia=I1+If; Ploss=Prot+Psh+Ia^2*Ra; Eff_gen=(1-Ploss/(Ploss+Pop))*100;disp(Eff_gen,'gener...
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function update_compared() a=get("cases_plot_frame"); [header, data] = importdata(covid_getpath()+"\data\time_series_covid19_confirmed_global.csv"); confirmed = strtod(data(:,5:$)); country = data(:,2); // state = data(:,1); c = get("country"); my = confirmed(country == c.string(c.value),:)...
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//Example 1.6 // fringe width clc; //given data : a=0.10;// distance between source & prism in m c=1;// distance between prism & screen in m u=1.5;//referactive index of bi-prism al=%pi/180;//angle in radian d=2*a*(u-1)*al;// distance between slits in m w=5900D-10;// wavelength in m D=a+c;//distance between so...
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//clc(); clear; //To determine the angular seperation lambda=600*10^(-9); //wavelength of light in metres a=1*10^(-6); //slit width in metres n=1; theta=asind((n*lambda)/a); printf("the angular seperation between the first order minima and central maxima of either side is %f degrees",t...
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clc; //e.g 16.1 V1=230; //a=(N2/N1) b=(1/10); V2=V1*b; disp('V',V2*1,"V2="); Vm=sqrt(2)*V2; disp('V',Vm*1,"Vm="); Vdc=0.318*Vm; disp('V',Vdc*1,"Vdc="); PIV=Vm; disp('V',PIV*1,"PIV=");
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load Or8Way.hdl, output-file Or8Way.out, output-list in%B1.8.1 out%B1.3.1; set in %B00000000, eval, output; set in %B11111111, eval, output; set in %B00000001, eval, output;
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function block=mdaq_param_sim(block,flag) select flag case -5 // Error case 0 // Derivative State Update case 1 // Output Update global %microdaq; if %microdaq.dsp_loaded & %microdaq.private.has_mdaq_param_sim then if %microdaq.private.connection_id > -1 then ...
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clc;clear; //Example 16.4 //given data mo=9.1*10^-31;//mass of electron in kg m=1.67*10^-27;//mass of proton in kg c=3*10^8;//speed of light in m/s E=1;//given energy in MeV //calculations Eo=mo*c^2/(1.6*10^-13); mbymo=1+(E/Eo); disp(mbymo,'Ratio for electron'); Eo=m*c^2/(1.6*10^-13); mbymo=1+(E/Eo); d...
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//Find the number of ampere turns clc; clear; l=30*(10^-2); // Length of an iron path lag=2*(10^-3);//Length of air gap B=0.8; // Flux density H=700; m0=(4*%pi)*(10^-7); mr=B/(m0*H); A=poly(0,'A');//Area of the iron path R1=l/(m0*mr*A); R2=lag/(m0*A); R=R1+R2; phi=B*A;//Flux NI=phi*R; //To ...
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//AC Circuits : example 4.79 :(pg 4.64) R=10; L=0.01; C=100*10^-6; f0=(1/(2*%pi*sqrt(L*C))); BW=(R/(2*%pi*L)); f1=f0-(BW/2); f2=f0+(BW/2); printf("\nR=10 Ohm \nL=0.01H \nC=100uF"); printf("\nf0=1/2*pi*sqrt(L*C)=%.2f Hz",f0);//resonant frequency printf("\nBW=R/2*pi*L =%.2f Hz",BW); //bandwidth printf("\nf1=f0...
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.413318D+00 ...
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//Name: Ganesh Mode //Roll no.: ee14b083 // IIT Madras // Input arguments : 1. [n,d] or sos // n,d =numerator and denominator of a filter // sos = second order system array // with size(sos)=(k,6) where k>=2; // ...
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clc //Intitalisation of variables clear c= 0.01 //M T= 25 //C kw= 1.01*10^-14 ka= 1.75*10^-5 //CALCULATIONS x= sqrt(kw/(ka*c)) //RESULTS printf ('Degree of hydrolysis = %.1e ',x)
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//problem 1 pagenumber 2.86 //given rf=10*10^3;//ohm //vo=0.1v1+v2+10v3; 1 //determine r1,r1,r3 r1=rf/0.1;//from 1 r2=rf/1;//from 1 r3=rf/10;//from 1 format(6); disp('R1 = '+string(r1/10^3)+' Kohm'); disp('R2 = '+string(r2/10^3)+' Kohm'); disp('R3 = '+string(r3/10^3)+' Kohm'); disp('...
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# ATWM1_MRI_Localizer scenario = "ATWM1_Localizer_MRI"; scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen #scenario_type = trials; scan_period = 2000; # TR pulses_per_scan = 1; pulse_code = 1; #pulse_width=6; default_monitor_sounds = false; active_buttons ...
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// Aim:To compute horsepower across the unloading valve // Given: // pump pressure during unloading: p=25; //psi // pump flow to the tank: Q=20; //gpm
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clc //ex16.2 B=1; //magnetic flux density l=0.3; V_T=2; R_A=0.05; //CASE a //bar is stationary at t=0 u_ini=0; //initial velocity of bar is 0 e_A=B*l*u_ini; //induced voltage i_A_ini=(V_T-e_A)/R_A; //initial current F_ini=B*l*i_A_ini; //initial force on the bar //steady state condit...
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function y = jacobi(A,b,t)//t tolerancia x = zeros(1,length(b)) k = 0 delta=t+1 while k<1000 & t<delta xk=x for i = 1:length(x) s = 0 for j = 1:length(x) // mprintf("%d , %d\n", i ,j) if ...
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clear; clc; function [r,i]=d(mag,theta) r=mag*cosd(theta); i=mag*sind(theta); endfunction previousprot = funcprot(0) funcprot(0) //clc(); mag=0.98; theta=3; [r,i]=d(mag,theta); A=complex(r,i); D=A; mag=110; theta=75; [r,i]=d(mag,theta); B=complex(r,i); mag=0.0005; theta=88; [...
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//Example number 9.4, Page number 204 clc;clear; close; //Variable declaration RH=3.66*10**-4; //hall coefficient(m**3/c) rho=8.93*10**-3; //resistivity(m) e=1.6*10**-19; //charge(c) //Calculation mew=RH/rho; //mobility(m**2/Vs) n=1/(RH*e); //density of atoms(per m**3) //Result printf("mobility...
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//clear// clc clear exec("11.1data.sci"); WAZ1=DAB*CT0*(yAb-yAs)/s; WAZ2=c*DAB*CT0*log((1-yAs)/(1-yAb))/s; disp(WAZ1) disp(WAZ2)
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//Example 15.3 clc; //Design a 2nd order LPF having a cutoff frequency of 2 kHz fh=2000; //Cutoff frequency in Hz C2=3.3*10^-9; //Assumed value of capacitor C3=C2; R=invr(2*%pi*fh*C2); //Assume a std value of R R=22*10^3; R2=R; R3=R; R1=10000; //Assumed Rf=.560*R1; printf('\nAssumed...
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// problem 1.24 x=30 z=sin(3.142*x/180) d=1.4 h=3 b=1.5 h1=z+d a=0.5*h*b w=9810 p=w*a*h1 h11=((z*z*h*h*h*b)/(36*a*h1))+h1 disp(p,"total pressure on the plate") disp(h11,"position of centre of pressure")
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clear;lines(0); A=rand(5,5); [Ro,Theta]=polar(A); norm(A-Ro*expm(%i*Theta),1)
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//clear// //Example10.13:Inverse z tranform ofInFinite duration discrete sequence //Power Series Method (OR)//Long Division Method z = %z; a = 2; X = ldiv(z,z-a,5)
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//Ex:2.5 clc; clear; close; r=27*(10^3); printf("Resistor value = %d ohm",r); printf("\nTolerance = 5 %%");
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//To determine the current through all the branches of the given network clc; clear; L=1; R=1*(10^3); C=400*(10^-6); i=2; // 2 cos 50t w0=1/(sqrt(L*C)); v=i*R; // Voltage across the source Xl=%i*w0*L; // Inductive reactance Xc=-%i/(C*w0);// Capacitive reactance Il=v/Xl; // Inductor current Ic=v/...
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clc D1=127;................................//Array aperture D2=67; D3=335; f1=3*(10^6);..//frequency at 3MHz f2=30*(10^6);..//frequency at 30MHz c=3*(10^8); lambda1=c/f1; lambda2=c/f2; R1=2*(D1^3) ./lambda1; R2=2*(D2^3) ./lambda1; R3=2*(D3^3) ./lambda1; R4=2*(D1^3) ./lambda2; R5=2*(D2^3) ./lambda2; R6=2*(...
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//clear// //Caption: Optical Signal-to-noise ratio (OSNR) //Example11.6 //page 412 clear; close; clc; Q = 6; //Q factor of 6 OSNR = (1/2)*Q*(Q+sqrt(2)); disp(10*log10(OSNR),'Optical Signal-to-noise ratio in dB OSNR =') //Result //Optical Signal-to-noise ratio in dB OSNR = 13.471863
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// 2.17 clc; strain=-5*10^-6; Gf=-12.1; R=120; dR_nickel=Gf*R*strain; printf("Change in resistance of nickel = %.3f ohm",dR_nickel) Gf=2; R=120; dR_nicrome=Gf*R*strain; printf("\nChange in resistance of nicrome = %.3f ohm",dR_nicrome)
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//Ex4_33 clc; // Given: ax0 =1; //assume tx = 2; //hrs ty = 1; //hrs // Solution: // general equation connecting Ax and Ay is // Ax(n) = (ky * Ax(0) * (exp(-kx * t) - exp(-ky * t))/ (ky - kx)) + Ay(0) * exp(-ky * t) ax0 = 1; ay4 = (ax0 * (0.693/1) * ((1/4)-(1/16)))/((0.693/1)-(0.693/2)) + ax0 * (1/16); ...
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// Scilab code Ex2.6: Pg.79 (2008) clc; clear; R = 1.50e+011; // Radius of earth's orbit, m c = 3e+08; // Velocity of light, m/s sigma = 1.36e+03; // Solar constant, W/m^2 P = 4*%pi*R^2*(sigma); // Total power radiated by the sun, J/s t = 1; // Time, sec // Since P = E/t, solving for E, we get E...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run2"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monito...
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//AC Circuits : example 4.80 :(pg 4.65) R=10; L=0.2; C=40*10^-6; V=100; f0=(1/(2*%pi*sqrt(L*C))); I0=(V/R); P0=((I0^2)*R); pf=1; Vr=(R*I0); Vl=((2*%pi*f0*L)*I0); Vc=((1/(2*%pi*f0*C))*I0); Q=((1/R)*sqrt(L/C)); f1=(f0-(R/(4*%pi*L))); f2=(f0+(R/(4*%pi*L))); printf("\nR=10 Ohm \nL=0.2 H \nC=40uF \nV=100 V");...
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clear; clc; disp("To use Figure 9.8,with Qf=ΣU^2/delta_Hs=2*g_c*lambda^2*R_H") disp("The value of R_H can be estimated with equation 8.4.") disp("Using k=1.3 for steam and suusming ETA_p=0.90 we have ETAad=[1-(p_e/p_i)^(ETAp*(k-1)/k)]/[1-(p_e/p_i)^(k-1)/k]=0.931") ETA_ad=0.931 ETA_p=0.90 R_H=ETA_ad/ETA_p printf(" R_H...
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// Scilab Code Ex3.1: Page:132 (2011) clc;clear; m = 5.32e-26; // Mass of one oxygen molecule, kg k_B = 1.38e-23; // Boltzmann constant, J/K T = 200; // Temperature of the system, K v = 100; // Speed of the oxygen molecules, m/s dv = 1; // Increase in speed of the oxygen molecules, m/s P = 4*%pi*(m...
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Vin=2 //Volt Vosc=2 //Volt VPD=2 //volt Ein=0.75 Eosc=0.75 Vd=1 dW=2*%pi*10^7 Km=VPD/(Vin*Vosc) printf("\nKm=%.1f V^-1",Km) Kd=0.5*Km*Ein*Eosc Ko=dW/Vd //(a) qd=2*%pi*(11-10)*10^6/(Ko*Kd) printf("\n(a)qd=%.4f rad = %.4f degree\n",qd,qd*180/%pi) //(b) qd=2*%pi*(9-10)*10^6/(Ko*Kd) printf("\n(b)qd=%...
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// This file is released under the 3-clause BSD license. See COPYING-BSD. // Generated by builder.sce : Please, do not edit this file // ---------------------------------------------------------------------------- // if win64() then warning(_("This module requires a Windows x86 platform.")); return end // skeleton_...
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//control systems by Nagoor Kani A //Edition 3 //Year of publication 2015 //Scilab version 6.0.0 //operating systems windows 10 // Example 5.13 clc; clear; s=poly(0,'s')//defines s as poly nomial variable h=syslin('c',(230/(s*(s+2)*(s+10))))//the value of K lies between 0 to 240 .the given transfer function...
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clc //initialisation of variables P=12.5 //mole air n=47.0 //mole fuel p1=1//mole air a=28.95 //mole air m=114.2//mole fuel //CALCULATIONS AF=P+n/p1//mole air/mole fuel A=AF*a/m//lbm air /lbm fuel //RESULTS printf('The theoretical air fuel ratio for the combustion of octane=% f lbm air/mole fuel',A)
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//Example 3.8 // Phase retardation clc; clear; //given data : Uo=1.5508;//refractive index for O ray Ue=1.5418;//refractive index for E ray w=5D-7;// wavelength of light used in m t=.000032;// thickness of plate in m p=2*%pi*(Uo-Ue)*t/w;//phase retardation in radian disp(p,"phase retardation in radian")
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//page 283 //Example 8.13 clc; clear; close; A = rand(2,2); A(1,:) = A(1,:) + 1; //so b1 is not equal to zero a = A(1,1); b = A(1,2); c = A(2,1); d = A(2,2); b1 = A(1,:); b2 = A(2,:); disp(A,'A = '); disp(b1,'b1 = '); disp(b2,'b2 = '); disp('Applying the orthogonalization process to b1,b2:'); a1 = [a b...
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// The code was developed under Horizon2020 Framework Programme // Project: 748767 — SIMFREE function [Out1,Out2]=SSSoCoupler(In1,In2,Coupling) // Optical Coupler // // Calling Sequence // [Out1,Out2]=SSSoCoupler(In1,In2,Coupling) // // Parameters // In1 : Optical Input 1 // In2 :...
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// Scilab code Ex4.11: Pg:148 (2008) clc;clear; x0 = 12.34; // Position of zero order fringe, mm Lambda = 6000; // Wavelength of light, angstrom Lambda_prime = 5000; // New wavelength of light, angstrom omega = 0.239; // Fringe width, mm omega_prime = Lambda_prime/Lambda*omega; // New fringe width,...
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// Example 2.5, page no-44 clear clc Beta=100 R=20000 Vcc=5 Vbe=0.6 Iref=(Vcc-Vbe)/R N=3 Ic=Iref*(1+ 4/Beta) Ic1=Iref*(Beta)/(Beta+N+1) Ic2=Iref*(Beta)/(Beta+N+1) Ic3=Iref*(Beta)/(Beta+N+1) Iref=Iref/10^-3 printf("Iref= %.2f mA",Iref) Ic1=Ic1/10^-3 printf("\nIc1=Ic2=Ic3= %.3f mA",Ic1)
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# Adding to case 2 everything is stable and global information is correct # Drop one node from middle, now fix to update finger_table # Now add 1 again, stab and fix. everything should be consistent add 0 add 1 add 2 add 3 join 1 0 join 2 0 join 3 0 list show 0 show 1 show 2 show 3 # First cycle of stab fix stab 0 sta...
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[ "LGPL-3.0-only", "GPL-3.0-only", "GFDL-1.1-or-later", "GPL-1.0-or-later", "LicenseRef-scancode-other-copyleft", "GFDL-1.1-only", "MIT", "LGPL-2.1-only", "MPL-1.1", "LicenseRef-scancode-mame", "Zlib", "GPL-2.0-only", "LGPL-2.1-or-later", "MPL-2.0", "CC-PDDC", "LicenseRef-scancode-public...
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#include "alu.inc" .code prolog #define ADD(N, I0, I1, V) ALU(N, , add, I0, I1, V) ADD(0, 0x7fffffff, 1, 0x80000000) ADD(1, 1, 0x7fffffff, 0x80000000) ADD(2, 0x80000000, 1, 0x80000001) ADD(3, 1, 0x80000000, 0x80000001) ADD(4, 0x7fffffff, 0x80000000, 0xffffffff) ADD(5, 0x80000000, 0x7fffffff, 0xfffff...
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@relation vowel @attribute TT integer[0,1] @attribute SpeakerNumber integer[0,14] @attribute Sex integer[0,1] @attribute F0 real[-5.211,-0.941] @attribute F1 real[-1.274,5.074] @attribute F2 real[-2.487,1.431] @attribute F3 real[-1.409,2.377] @attribute F4 real[-2.127,1.831] @attribute F5 real[-0.836,2.327] @attribute...
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// calculate voltage gain // Electronic Principles // By Albert Malvino , David Bates // Seventh Edition // The McGraw-Hill Companies // Example 13-15, page 450 clear; clc; close; // Given data Rs1=220;// in ohms Rs2=780;// in ohms Rl=3*10^3;// in ohms gm=2000*10^-6;// transconductance in Seimen // ...
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A = [10 2 1; 1 5 1; 2 3 10]; b = [7 -8 6]; n = 3; x_new = zeros(1,n); x_old = zeros(1,n); NMAX = 20; tol = 0.0001; x_old = [0.7 -1.6 0.6]; for k=1:NMAX // iteracao do metodo de Jacobi for i=1:n soma = 0.0; for j=[1:i-1,i+1:n] soma = soma + A(i,j)*x_old(j); ...
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clear; clc; printf("\nEx1.4\n"); //page no.-8 //given a=3.61;.......//lattice constant in Angstrom r=(2^(0.5)*a)/4........//for F.C.C. structure radius is given by this printf("\nradius of copper atom is 12.8 angstrom\n");
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// Initilization of variables r=1 // m // radius of the cylinder v_c=20 // m/s // velocity of the cylinder at its centre // Calculations // The velocity of point E is given by using the triangle law as, v_e=sqrt(2)*v_c // m/s // Similarly the velocity at point F is given as, v_f=2*v_c // m/s // Results clc ...
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a=2.286*10^-2 b=1.016*10^-2 f=9.379*10^9 c=1/2/sqrt((9379/300)^2-(1/2/a)^2) printf("\nc=%.5f m = %.4f cm",c,c*100)
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clear; syms t s x=1/(s+1) f1=ilaplace(x) disp(f1*'u(t)',"a) x(t)=") y=-1/(s+1) f2=ilaplace(y) disp(f2*'u(-t)',"b) x(t)=") z=s/(s^2+4) f3=ilaplace(z) disp(f3*'u(t)',"c) x(t)=") zz=(s+1)/((s+1)^2+4) f4=ilaplace(zz) disp(f4*'u(t)',"d) x(t)=")
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clc //initialisation of variables v=60//m/sec v1=16.6//m/sec r=300//m g=9.8//m/sec //CALCULATIONS R=(v1^4)/((g^2)*(r^2))//km/hr //RESULTS printf('the ignored thus greatly simplifying the equation=% f km/hr',R)
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//Algoritmo Leverrier - Autor: Geraldo Laurentino da Silva Neto //Trabalho da disciplina de Modelagem Integrada UFRN //casos de teste A=[-1 0 0;0 0 -1;0 1 -1] //A = [0 -400;25 -250] //identifica a ordem da matriz y = length(diag(A)) //cria as variaveis que iram armazenar os valores de R e a(saida do trace) for i=0:(y-...