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//Scilab Code for Example 4.1 of Signals and systems by //P.Ramakrishna Rao //Plotting Magnitude and Phase spectrum clc; clear; A=8; Dt=0.005; T1=4; t=-T1/2:Dt:T1/2; q=length(t) for i=-(q/2)+1:q/2 if i>-q/4 & i<q/4 then xt(i+(q/2))=A; else xt(i+(q/2))=0; end end Wmax = 2*%pi*1; ...
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function trans_stnc = identify_transition(STNC1,STNC2) //Author : Maxens ACHIEPI //Space Robotics Laboratory - Tohoku University //Description: // //INPUT // //OUTPUT // //----------------------------------------------------------------------------// leg = -1; ...
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# Copyright (C) 2020 Genome Research Ltd. # # Author: James Bonfield <jkb@sanger.ac.uk> # # Permission is hereby granted, free of charge, to any person obtaining a copy # of this software and associated documentation files (the "Software"), to deal # in the Software without restriction, including without limitati...
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//Example 13.1: plot clc; clear; close; lod=[0;20;40;60;80;100;160];//in micro meter slong=[1.0;0.95;0.92;0.89;0.86;0.83;0.80];// lad=[0;10;20;30;40;50;60;70;80;90;100];//in micro meter slat=[0;0.1;0.2;0.3;0.4;0.5;0.6;0.7;0.8;0.9;1.0];// add=[0;1;2;3;4;5;6;7;8;9;10];// sang=[0;0.5;0.6;0.7;0.8;0.9;1.0;1.1;.12];// t=0:20...
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Arquivo = uiputfile(["*.dinam","Arquivos de Análise Dinâmica"], ... fileparts(pwd()),"Salvar dados da análise"); if ~isempty(Arquivo) then [Path,Name,Extension] = fileparts(Arquivo); Arquivo = Path + Name + ".dinam" EditBoxData = [] Campos = {MaterialData SectionDat...
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//Ex:8.12 clc; clear; close; ni=0.09;// normal efficiency d=2*2.54;// separation distance in cm x=0.2;// divergence angle in radians vf=2.0;// forward voltage in volts i_f=65*10^-3;// forward current in amp pi=vf*i_f;// input power in Watt po=ni*pi;// output power in Watt H=4*po/(3.14*d^2*x^2);// irradiance ...
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// Given:- nN2 = 0.79 // initial moles of nitrogen in kmol pN2 = 2.0 // initial pressure of nitrogen in bars TN2 = 250.0 ...
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// SEGUNDO TRABALHO DE INTELIGÊNCIA COMPUTACIONAL // Questão 2 (ELM) // Aluno: José Lopes de Souza Filho // Matrícula: 389097 // Aplicação: Scilab, versão 6.0.2 // SO: Linux Mint 19.2 Tina //----------------------------------------------------------------------------- clear; clc; base = fscanfMat('iris_log.dat'); X = ...
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v2=5 i2=v2/1000 v1=-i2/5 vs=v1 disp(vs)
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//Example 4.19 clc disp("For a Clapp oscillator,") disp(" f = 1 / 2*pi*sqrt(L*C3)") disp("where C3 = 63 pF") f=(1/(2*%pi*sqrt(315*10^-18)))*10^-6 // in MHz format(6) disp(f,"Therefore, f(in MHz) =")
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function [intervalA, intervalB] = GetNewInterval(f, a, b) C0 = ( a + b ) / 2; if ( f( a ) * f( C0 ) < 0 ) then intervalA = a; intervalB = C0; elseif( f( b ) * f( C0 ) < 0) then intervalA = C0; intervalB = b; else disp( "Invalid interval specified" ) end e...
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//Find pythagorean triplets till 100 Count no of triplets function[]=triplet() count=1 for(i=1:100) for(j=i:100) for(k=j:100) a=i b=j c=k if c*c==a*a+b*b then disp("Triplet no =") disp(co...
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//calculate the value of RESISTANCE AND CAPACITANCE I=2.5;//amps V=150;//volts f=50;//hetz Z=V/I; P=100;//watt..power R=P/(I*I) Xc=sqrt(Z^2-R^2) C=1/(2*3.14*f*Xc);// capacitance disp('find tha value of capacitance='+string(C)+'farad');
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usage: java -cp dist/ramath.jar org.teherba.ramath.linear.RationalTriangle "[vect1] oper [vect2]" oper= + - * / |
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m = 1.5; P1 = 5.6; V1 = 0.06; T2 = 273+240; a = 0.946; b = 0.662; k = 0.0001; // Part (b) R = a-b; T1 = (P1*1e03*V1)/(m*R); W12 = -integrate('m*(b+k*T)','T',T1,T2); disp("kJ",W12,"The work done in the expansion is")
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//Example 1.18: add 7 to -5 clc//clears the console clear //clears all existing variables x=bitcmp(5,4) //finds complement of 5 y=1; u=x+y //1 is added to the complement v=7; w=u+v a=dec2bin(w) //binary conversion of the decimal number disp(' binary form of the number obtained by adding 7 to -5 ') disp(a) //r...
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/** * Classifies a given column-vector into a class in 'model_labels' * according to the minimum distance given by 'fn_distance' between the x and * each row in 'model' * * x: image to be classified * model: matrix of all known images as column-vectors * model_labels: vector where the ith element corresponds to ...
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// Scilab code Exa. 3.9.4 : To calculate the number of nuclei at t = 0, initial activity and age of Pu-239 which emit alpha particle : Page no. 145 : (2011) t_h = 24000*365*24*3600; // Half life of Pu-239, s D_c = 0.6931/t_h; // Decay constant of Pu-239, s^-1 N = 6.023e+023*10/239; // Number of nuclei at t = 0, nuclei ...
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// ==================================================================== // // ====================================================================
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/* tslint:disable:max-line-length */ <#? it.inputs #>/* tslint:disable:use-input-property-decorator */ <#?#> import { Component,<#? !it.isCollection #> OnInit, OnDestroy,<#?#> NgModule, Host,<#? it.hasTemplate #> ElementRef, Renderer2, Inject, AfterViewInit,<#?#> SkipSelf<#? it....
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// Chapter 18 Example 1// clc clear //line to ground capacitance= c,supply frequency=f// //inductance of the coil =l// f=50; c=0.2*10^-6; l=1/(3*(2*%pi*f)^2*c); printf("\n Inductance of the coil %.2f H\n",l); //kVA rating of the coil = kVA,operating voltage =v// v=132; // in kV// vph=v*10^3/sqrt(3); kVA=vph...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clc; disp("Principles of Heat Transfer, 7th Ed. Frank Kreith et. al Chapter - 6 Example # 6.5 ") //Velocity in ft/s U = 10; //Outer diameter in inches D = 1.5; //Inner diameter in inches d = 1; //Temperature of wat...
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m = 9.11*10^-31; //mass of electron ml = 0.98*m; mt = 0.19*m; mninverse = (1/3) * ((1/ml)+(2/mt)); mn = 1/mninverse; mn0 = mn/m; disp(mn0,"Conductivity effective mass in proportion to mass of an electron =")
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n = 11 ; //numero de imagens salvas for i=1:n nome = 'C:\Users\Isaac de Lyra Jr\Downloads\prints-20190616T040115Z-001\prints\'+string(i)+'.jpg'; img = imread(nome); figure(); matplot(img,'f') x = x0 - cos(a)*d(w*(i-1)+1) y = y0 + sin(a)*d(w*...
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// Example 7.6 // responsivity clc; clear; close; e=1.6*10^-19;//elecronic charge eg=0.75;//eV n=0.7;// R=(n*e)/(eg*e);// disp(R,"Responsivity is in Ampere per Watt")
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//Chapter 14 Determination of Hydroniumion Concentrations clc; clear; //Initialisation of Variables E= 0.034 //v E1= -0.280 //v E2= -0.699 //v E3= 0.0592 //CALCULATIONS pH= (E1-E-E2)/E3 pH1= (E-E2+E1)/E3 //RESULTS mprintf("pH of the unkown solution= %.1f",pH) mprintf("\npH of the unkown solution= %.2f",pH1)
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function pretty_print(x) printf("[") for i=1:length(x) printf("%e", x(i)) if i ~= length(x) then printf(", ") end end printf("]") endfunction function [res]=to_list(arr) res = list() for i=1:length(arr) res($ + 1) = arr(i) end endfunction function [res]=simple_proj(...
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clear // Variable declaration T_c1=30// Condensing temperature for larger condenser in °C T_c2=35// Condensing temperature for smaller condenser in °C Rc_1=242// Rated capacity of plant for larger condenser in kW Rc_2=218// Rated capacity of plant for smaller condenser in kW Rt_1=1802// Running time (kW-h) Rt_2=2000// ...
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clear //Given E0=8*10**-4 //v c=3.0*10**8 w=6*10**6 //Calculation // B0=E0/c f=w/(2.0*%pi) l=c/f //Result printf("\n Wavelength of the wave is %0.4f m",l*10**-4) printf("\n Frequency is %0.3f *10**10 Hz",f*10**-6)
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//<-function-- function tspDraw(tour,closed) // // INPUT: // tour ... 1 x n permutation of 1:n // closed ... flag for closed tour (optional = %T) global name pos; if argn(2) == 1 then closed = %T; end drawlater() clf(); plot(pos(:,1),pos(:,2),'.k','markersize',10...
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// Function Name = Frequency sampling // Inputs = Frequency response Hd; frequency vectors f1, f2; dimension [m n] // Output = matrix h of dimension m x n, stores the filter coeff function[h] = fsamp2(Hd, varargin) [lhs, rhs] = argn(0) select rhs case 1 then out = opencv_fsamp2(Hd) case 2 then out =...
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// ============================================================================= // Scilab ( http://www.scilab.org/ ) - This file is part of Scilab // Copyright (C) 2018 - ESI Group - Clement DAVID // // This file is distributed under the same license as the Scilab package. // =========================================...
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clear // // //Initilization of Variables P=45*10**3 //N //Load E=200*10**3 //N/mm**2 //Modulus of elasticity of rod L=500 //mm //Length of rod d=20 //mm //Diameter of rod //Calculations A=%pi*d**2*4**-1 //mm**2 //Area of circular rod p=P*A**-1 //N/mm**2 //stress e=p*E**-1 //strain dell_l=(P*L)*(A*E)**-1 //Result p...
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Name=OW Train PlayerCharacters=OWPlayer BotCharacters=Random Bot Watcher.rot;Shinji Bot.bot;McCoy Bot.bot;Sergeant Bot.bot;Racer Bot.bot IsChallenge=true Timelimit=120.0 PlayerProfile=OWPlayer AddedBots=Random Bot Watcher1.rot;Random Bot Watcher2.rot PlayerMaxLives=0 BotMaxLives=0 PlayerTeam=1 BotTeams=2 MapName=kovaim...
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//Chapter-2,Example2_4_7,pg 2-27 m=1 //first ordr spectrum wavelength=6560*10^-8 //wavelength of light angle=16.2 //angle of diffraction N=2*sind(angle)/(m*wavelength) printf('\nNumber of lines per 2 cm is N ...
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// Scilab code Ex5.10: Pg 155 (2008) clc; clear; N = 80; // Number of turns l = 0.02; // Length of coil, m r = 0.012; // Radius of coil, m I = 45e-06; // Current in coil, A T = 1.4e-06; ...
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## Test readlimit set relax set echo readlimit 3 read <simpletag.svn prefer git write - # This should yield an EOF message. read <binary.svn prefer git write - # This should not read <bs.fi prefer git write - # This should read <utf8.fi prefer git write -
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 17.5 //calculation of the angular divergence for most of the light getting diffracted //given data lambda=450*10^-9//wavelength(in m) of the light used b=0.2*10^-3//width(in m) of the slit //calculation //for thet...
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//Example 2.3 clc s=%s; xs=2/(s+3); disp(xs,'x(s)=') syms t; xt=ilaplace(xs,s,t); disp(xt,'x(t)=')
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//程式L2_2.m: 矩陣的直積% A=[1 1;-1 1]; B=[1 2;3 4]; A1=A'; B1=B'; //將矩陣轉置 A2=inv(A); B2=inv(B); //求反矩陣 kron1=kron(A,B); //求右直接乘積 kron2=kron(A1,B1); kron3=kron(A2,B2); kron_left=kron1'; kron_right=kron2; invert_left=inv(kron1); invert_right=kron3; kron_left kron_right invert_left invert_right y...
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//Caption: Median of grouped data //Example3.8 //Page45 clear; clc; X = [0,8;8,10;10,12;12,14;14,16;16,18;18,20;20,22;22,24]; f = [5,10,15,20,35,40,45,20,15,11]; cum_f = 0; for i = 1:length(f) cum_f = cum_f+f(i); sigmaf(i) = cum_f; end N = cum_f; //total number of salesman cen = N/2; for i = 1:length(f) if...
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clc //Example 8.1 //Calculate the speed of sound in water amd steel at 20 C //for steel K_steel=1.94*10^11//Pa rho_steel=7800//Kg.m^3 c_steel=(K_steel/rho_steel)^0.5/1000//Km/s printf("the speed of sound in steel at 20 C is %f km/s\n",c_steel); //for water K_water=3.14*10^5//lbf/in^2 rho_water=62.3//lbm/ft^3 ...
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clc Qv=90; //kJ Qp=-95; //kJ W=-18; //kJ U_l=105; //kJ W_lm=0; Q_lm=90; U_m=U_l+90; dU_mn=Qp-W; U_n=U_m+dU_mn; dQ=Qv+Qp; dW=dQ; W_nl=dW-W; disp("W_nl(in kJ)=") disp(W_nl) disp("U_l in kJ =") disp(U_l) disp("U_m in kJ =") disp(U_m) disp("U_n in kJ") disp(U_n)
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//Example 8.5.b // copper losses clc; clear; close; V=230;// in volts I=60;// in amperes rpm=955;//turns ra=0.2;//resistance of armature in ihms rsh=0.15;//shunt field in ohms sl=604;//stray losses in watts Rm=ra+rsh;// in ohms Eb=(V-I*Rm);// back emf in volts Dp=Eb*I;//driving power in watts mi=V*I;//input po...
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clear; clc; printf("\t\t\tProblem Number 3.12\n\n\n"); // Chapter 3 : The First Law Of Thermodynamics // Problem 3.12 (page no. 112) // Solution Z1=2; //Unit:m //Inlet position g=9.81 //Unit:m/s^2 //g=The local gravity V1=40; //Unit:m/s //Inlet velocity h1=3433.8; //Unit:kJ/kg //Inlet enthalpy q=1 //Unit:k...
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//clc(); clear; //To calculate the angle at which third order reflection can occur n=3; //diffraction order lambda=0.79*10^-10; //wavelength in m d=3.04*10^-10; //spacing in m theta=asind((n*lambda)/(2*d)); printf("braggs angle in degrees is"); disp(theta);
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//for the jet power executive aircraft(CJ-1): b=16.25;//wingspan(meter) S=29.54;//wingarea(m^2) AR=b^2/S;//aspect ratio Cdo=0.02;//parasite drag coefficient e=0.81;//oswald efficiency factor
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// Scilab code Ex8.3: Pg.321 (2008) clc; clear; k = 1.38e-23; // Boltzmann constant, J/K T = 300; // Temperature, K m = 4.68e-26; // Mass of N_2 molecule, kg v = sqrt((8*k*T)/(%pi*m)); // Average speed of N_2 molecule, m/s printf("\nThe average speed of N_2 molecule = %5.1f m/s or = %4d km/h", v, v*3....
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global file_name path fname extension chip_num board_num brdtype hex_1nA hex_1na; global dac_array dac_array_map number_samples period; chip_num="16"; board_num=2; brdtype = ''; // 2: 3.0, 3: 3.0a, '':3.0 '_30a':3.0a cd("~/RASP_Workspace/test_20150819_onchipTSMCadc"); path = pwd(); file_name = path + "/test_20150819_o...
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//acids and bases// //example 2.23// OH=0.0025;//OH- concentration// K=1*10^-14//water ionization constant// H=K/OH; H=H/10^-12; printf("The concentration of H+ ions is %f*10^-12M",H); printf("\nThe concentration of OH- ions is %fM",OH); printf("\nAs concentration of H+ is lesser than the concentration of OH- t...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monito...
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clc; n=12*10^6; //frequency in Hz v=3*10^8; //velocity in m/sec l=v/n; //calculating wavelength disp(l,"Wavelength in m = "); //displaying result
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// Exa 4.9 clc; clear; // Given data // To generate a sinusoidal signal 10 sin 3t. // Solution printf('Let us first obtain a differential equation whose solution is 10 sin 3t.\n'); printf(' Let x(t) = 10 sin 3t ------eq(1)\n'); printf(' The first derivative of this i.e. dx(t) = 30 cos 3t ----eq(2)\n')...
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//sum 13-1 clc; clear; F=25*10^3; sigat=50; Ta=40; pa=80; d=sqrt((4*F)/(%pi*sigat)); d=26; t=d/4; t=7; d1=1.2*d; d1=32; pc=F/(d1*t); t=10; c=0.75*d; c=20; d2=44; tw=(d2-d1)/2; b=F/(2*t*Ta); b=34; a=0.5*d; d3=(F/(pa*t))+d1; d3=64; e=F/(Ta*(d3-d1)); d4=sqrt((F*4/(%pi*pa))+d1^2); d4=40; f=0.5*d;...
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clc; h1=2846; h2=2682; x2=0.98; vg=0.6057; v2=x2*vg; C2=[2*(h1-h2)*10^3]^0.5; m=0.1; A2=m*v2*10^6/C2; disp("mm^2",A2,"Exit area is:"); //part II p1=7; p2=3; k=1.3; v1=0.3001; vr=v1*[(p1/p2)^(1/k)]; y=1.3; Cr=[2*(y*10^5)/(y-1)*{(p1*v1)-(p2*vr)}]^0.5; A2=m*vr*10^6/Cr; disp("mm^2",A2,"Exit area in sup...
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//[f]=%rfp(f,p) // %rfp(f,p) calcule la concatenation en ligne de la matrice de fractions //rationnelles f avec la matrice de polynomes p [f;p] //! f(3)=[f(3);ones(p)] f(2)=[f(2);p] //end
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errcatch(-1,"stop");mode(2);//Chapter 12 //page no 486 //given ; all; Ncso=50; a=3.6*10^-3; m=0.05; CSO=10*log10(Ncso*(a*m)^2); printf("\n CSO distortion for 50 channel optical system = %0.1f dB\n",CSO); exit();
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clc; //e.g 34.2 LR=1.4*10**-6; VS=10; //LR=VL/VS; VL=LR*VS disp('microV',VL*10**6,"VL=");
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// Copyright INRIA while %t //Infinite loop [buf,info] = pvm_recv(pvm_parent(), -1)//get new variable or instruction if info<0 then break,end if type(buf)==10 then //an instruction if execstr(buf,'errcatch') then break,end//execute it write(%io(2),'Instruction: '+buf+' done') else //a variable %va...
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L=10;//in m W=1000;//FORCE ON POINT 2 M=100;//MOMENT ON POINT 2 EI=20000;
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errcatch(-1,"stop");mode(2);//example 1 //weight of a person m=1 //kg g=9.75 //acc.due to gravity in m/s^2 F=m*g //weight of 1 kg mass in N printf("\n hence,weight of person is F = %.3f N. \n",F) exit();
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// Scilab Code Ex1.13 Velocity of one atomic mass unit: Pg: 24 (2008) c = 1; // For convenience, speed of light is assumed to be unity, m/s m0 = 1; // For convenience, rest mass is assumed to be unity // Here 2*m0*c^2 = m*c^2 - m0*c^2 = KE which gives m = 3*m0; // Atomic mass in motion, kg // As m = m0/sq...
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clear; clc; printf("\n Example 12.3"); //as the system are dilute mole fractions are approximately equal to mole ratios. //At the bottom of the tower y1 =0.015; //mole fraction G = 1; //Gas flow rate is in kg/m^2sec //At the top of the tower y2 = 0.00015; //mole fraction x2 = ...
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function [selectedBbox,selectedScore,varargout]=selectStrongestBbox(bBox,score,varargin) // Selecting strongest bounding boxes // // Calling Sequence // [selectedBbox, selectedScore]= selectStrongestBbox(bBox,score); // [selectedBbox, selectedScore]= selectStrongestBbox(bBox,score,Name,Value); // [selectedBbox, s...
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function nGregoryMaju(x,fx,xtaksir,jp) //x matriks 1 x n //fx matriks 1 x n i=1;L=0;Lt=0;b=1; [n,m]=size(x); [ny,my]=size(fx); A(m,m)=0;//initialisasi matriks mt=m; j=1;xs=mt; //memasukan nilai fx ke matriks if m==my then if jp~=m-1 then disp ('Polinom...
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//Chapter 8 //Example 8_9 //Page 177 clear;clc; ins=4; k=1/5; v1=1; v2=v1*(1+k); v3=v1*(1+3*k+k^2); v4=v1*(1+6*k+5*k^2+k^3); v=v1+v2+v3+v4; pv1=v1/v*100; pv2=v2/v*100; pv3=v3/v*100; pv4=v4/v*100; n=v/ins/v4*100; printf("\n(i) V1 = %.2f V \n", v1); printf("V2 = %.2f V \n", v2); printf("V3 = %.2f V \n", v3); printf...
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//EXAMPLE 2.27, convolution of an exponential sequence clear; clc; n=0:.5:5 c=0.5; b=0.4; clf(); figure(0); a=gca(); a.x_location="origin"; x = c^n; subplot(2,2,1); plot2d3(n,x,2); plot(n,x,'.r'); xtitle('','n','x'); h = b^n ; subplot(2,2,2); plot2d3(n,h,2) plot(n,h,'.r') xtitle('','n','h'); N=0:.5:10; y = convol (x , ...
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//ques-2.3 //Calculating HCV of fuel clc x=0.72;//Weight of fuel (in g) C=80;//Percentage of Carbon t1=27.3;//Initial temperature t2=29.1//Final temperature W=250;//Water of water in calorimeter (in g) w=150;//Water equivalent (in g) HCV=((W+w)*(t2-t1))/x;//HCV of fuel (in kcal/kg) HCV=HCV*4.2;//HCV of fuel (...
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// Functions for performing the in-, out- operations // ======= DATA READING ======= function [reg_all, dtm_all] = importSteadyPoints(path, dirSep, fileName) //******************************************************* // //******************************************************* filePathName = path + dirSep + fileName...
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//what range of forward voltage drop vD can (2.1) be approximated //Solved Example Ex2.1 page no 48 clear clc printf("\n what range of forward voltage drop vD can (2.1) be approximated") n=1 k=1.38//x 10^-23 T=25+273 q=1.6//x 10^-19 vd=((k*T)/(1.6*(10^4))*4.6151) printf("\n vd = %0.4f V",vd)
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s=0; for i=1:10 s=s+i end disp('s=',s) //while loop d=0; j=1 while j<=10 d=d+j; j=j+1 end disp('d=',d)
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//water and its treatment// //example 2.18.39// clc Purity_Lime=.90 Purity_soda=1 W1=136;//amount of CaSO4 in ppm// W2=49;//amount of H2SO4 in ppm// W3=95;//amount of MgCl2 in ppm// W4=60;//amount of MgSO4 in ppm// W5=50;//amount of SiO2 in ppm// M1=100/136;//multiplication factor of CaSO4// M2=100/98;//...
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//check o/p when a and b are of equal length a = [2 1 2 1]; b = [1 2 3 4]; c = cconv(a,b,4); disp(c); //output //14. 16. 14. 16.
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//i/p arg data is a vector data=[1 2 3 4 6 7 9]; freq_indices = 3; dft_data = goertzel(data,freq_indices); disp(dft_data); //output //- 4.2225209 + 3.5252975i
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// Given:- P1 = 30.0 // pressure of steam entering the turbine in bar T1 = 400.0 // temperature of steam entering the turbine in degree celcius V1 = 160.0 // velocity of steam entering the turb...
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example5_35.sce
clear; clc; // Stoichiometry // Chapter 5 // Energy Balances // Example 5.35 // Page 273 printf("Example 5.35, Page 273 \n \n"); // solution T2 = 800 T1 = 298.15 fi1 = 3614.577*(T2-T1)+305.561*10^-3*(T2^2-T2^2)/2+836.881*10^-6*(T2^3-T1^3)/3-393.707*10^-9*(T2^4-T1^4)/4 // kW T3 = 875 fi2 = 3480.7...
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//Finding of volume and specific gravity //given w=490.5; //In Air in Newton w1=196.2; //In Water in Newton rho=1000; g=9.81; rho1=5000; //To Find wd=w-w1; vd=wd/(rho*g); rho2=(w/g)/vd; spgr=rho1/(rho*3); disp("Volume = "+string(rho2)+" Kg/m^3"); disp("Specific Gravity is= "+string...
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clc;clear; //Example 12.11 //given data T1=220; P1=5; T2=300; P2=10; //constants used Ru=8.314;//on kJ/kmol- K //from Table A–1 Tcr=154.8; Pcr=5.08; //calculations //part - a disp('part - a'); //by assuming ideal-gas behavior //from Table A–19 h1=6404; h2=8736; s2=205.213; s1=196.171; h21...
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//(12.11) Moist air at 30C and 50% relative humidity enters a dehumidifier operating at steady state with a volumetric flow rate of 280 m3/min. The moist air passes over a cooling coil and water vapor condenses. Condensate exits the dehumidifier saturated at 10C. Saturated moist air exits in a separate stream at the...
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// Example 6.2 // Calculation of the variance of the signal–ASE beat noise // Page no 255 clc; clear; close; //Given data a=1.3*10^-16; // PSD of an amplifier f=7*10^9; // Cut off frequency Pi=10*10^-6; // Input power R=0.8; // Resp...
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clear // // // //Variable declaration w=72.6 //atomic weight d=5400 //density(kg/m**3) Na=6.025*10**26 //avagadro number mew_e=0.4 //mobility of electron(m**2/Vs) mew_h=0.2 //mobility of holes(m**2/Vs) e=1.6*10**-19 m=9.108*10**-31 //mass(kg) ni=2.1*10**19 //number of electron hole pairs Eg=0.7 ...
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//Variable declaration N=6.023*10**26 deltaHv=120 B=1.38*10**-23 k=6.023*10**23 //Calculations n0=0 // 0 in denominator n300=N*exp(-deltaHv*10**3/(k*B*300)) //The number of vacancies per kilomole of copper n900=N*exp(-(deltaHv*10**3)/(k*B*900)) //Results printf...
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// Test # 2 : Excess Input Arguments exec('./allpassshiftc.sci',-1); [n,d]=allpassshiftc(0.3,0.24,0.16); //!--error 58 //Wrong number of input arguments
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function T = pertambahan(bil1,bil2); T = bil1+bil2; endfunction
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// Data Reconciliation Benchmark Problems From Lietrature Review // Author: Edson Cordeiro do Valle // Contact - edsoncv@{gmail.com}{vrtech.com.br} // Skype: edson.cv //C.C. David Pai, Gary D. Fisher //Application of Broyden's Method to Reconciliation of Nonlinearly Constrained Data // AICHE Journal 1988, V 34 No. 5 -...
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//Strength Of Material By G.H.Ryder //Chapter 1 //Example 11 // To Calculate thermal Stress in rod & tube SteelOD=2.4; //External diameter of steel tube, Unit in cm SteelID=1.8; //Internal diameter of steel tube, Unit in cm CopperDia=1.5; //Diameter of copper rod, unit in mm Es=210,000; //Young's Modulus fo...
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clc(); clear; // To calculate the heat loss per square foot from an uninsulated 2 inch sch. pipe D=2.375/12; // Outer diameter of pipe in ft k=0.035; // Thermal conductivity in Btu/hr-ft-degF T1=400; ...
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#************************************************************ # Scenario of humanTestEnv # # date : Thu Oct 16 14:15:52 2014 #************************************************************ p3d_sel_desc_name P3D_ENV humanTestEnv p3d_sel_desc_name P3D_ROBOT HERAKLES_HUMAN p3d_set_robot_steering_method Linear p3d_set_...
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enroll.txt enroll2.tst master.txt test1.txt
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clc clear exec fat.sci; //listing 5.1.2 disp(fat(5))
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// Chapter 11 example 5 //------------------------------------------------------------------------------ clc; clear; // Given data h = 13622; // ht of circular orbit from earth's surface Re = 6378; // Radius of earth in km // Calculations R = Re+h; // Radius of circular...
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errcatch(-1,"stop");mode(2);//ex6.2 I_E=2*10^-3; r_e=25*10^-3/I_E; disp(r_e,'ac emitter resistance in ohms') exit();
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//Example 16.4 //Finite Difference Method //Page no. 582 clc;close;clear; x=0;h=0.25;q=-1;Y(1)=-2;Y(5)=1; printf('\n i\txi\tYi\tpi\tqi\tri\n-----------------------------------------------\n') for i=1:5 r(i)=-x^2 if i>1 & i<5 then printf(' %i\t%g\t%s\t%g\t%i\t%g\n',i-1,x,"?",x,q,r(i)) els...
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function a=%sp_c_s(a,b) // [a b] a sparse b full // Copyright INRIA a=[a sparse(b)]
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//Aula 11 function P=Warshall(A) //Devolve a matriz de caminhos de um grafo a partir da sua matriz de adjacências A L = size(A,1); P=A for k=1:L for i=1:L for j=1:L P(i,j)=P(i,j)|(P(i,k)&P(k,j)); end end disp('Matriz P na iterada k='+...
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function high(x) function f(y) 3+y end end puts(high(3)(2))
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m=.05; //m=%pi.*a.^2.*I/c ring current I radius a len=1.0; b0=1.0; x=0:0.05:1.0; y=0.1:0.1:2.0; [X,Y]=meshgrid(x,y); bx=b0*cos(%pi*X./len).*exp(-%pi*Y./len); by=-b0*sin(%pi*X./len).*exp(-%pi*Y./len); bmag=sqrt(bx.^2+by.^2); //contour(x,y,bmag',[0.005 0.006 0.007 0.008 0.009 0.01 0.05 0.1 0.1...