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clc; n=4; // no of component A=[120*80,120*60/2,%pi*60*60/2,-%pi*40*40];//mm^2, Areas of Rectangle, triangle, Semicircle, and Circle respectively x=[60,40,60,60];//mm, x components of centroids of Rectangle, triangle, Semicircle, and Circle respectively y=[40,-20,105.46,80];//mm, y components of centroids of Rectan...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>Tri and Quad element channel Flow 2D</description> <executable>IncNavierStokesSolver</executable> <parameters>TriQuadChannel.xml</parameters> <files> <file description="Session File">TriQuadChannel.xml</file> </files> <metrics> ...
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clear txt = ['Hg';'Ga';'In';'Sn';'Zn';'Al'] txt2=['W(n)','t(n)'] sig = x_mdialog('Wprowadz wartosci w punktach',txt,txt2,['0.84347','-38.8344';'1.118138893','29.7646';'1.60980184811','156.5985';'1.89259628','231.928';'2.56855103','419.527';'3.37543469','660.323']) WHg =strtod(sig(1,1)) WGa =strtod(sig(2,1)) WIn=str...
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load DMux.hdl, output-file DMux.out, output-list in sel a b; set in 0, set sel 0, eval, output; set sel 1, eval, output; set in 1, set sel 0, eval, output; set sel 1, eval, output;
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//Problem 13.18: (a) Convert the circuit to the left of terminals AB in Figure 13.45(a) to an equivalent Th´evenin circuit by initially converting to a Norton equivalent circuit. (b) Determine the current flowing in the 1.8 ohm resistor. //initializing the variables: E1 = 12; // in volts E2 = 24; // in volts R1 =...
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clc clear //Input data n1=50.5;//Air standard efficiency in percentage n2=50;//Brake thermal efficiency in percentage N=3000;//Engine speed in rpm H=10500;//Heating value of fuel in kcal/kg T=7.2;//Torque developed in kgf*m B=6.3;//Bore diameter in cm S=0.095;//stroke in m //Calculations nbt=(n1/100)*(n2/1...
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//Chapter 4,Example 4.3 Page 145 clc clear d = 1 //mm V = 10^3 // V F = 5*10^-3 // pull between the plates in N E = 1/(36) // epselon A = 10^2/4 // Area of the plate d1 = sqrt((1/(2*F))*E*10^-9*V^2*A*10^-4) // calculation done in the text is wrong d21 = 1/(d1*10^4) d22 = 1/(d1*10^4+d) C = (V*E*10^-9*A*10^-4)*(d21-d22)...
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//Condições iniciais alfa = -%pi/6; s0 = 1; v0 = -1; dt = 0.1; t = linspace(0,10,1000); g = 9.8; r = 0.001; ro = 7850; volume = 4*%pi*(r^3)/3; m = ro*volume; x0=1; z0=2; x = linspace(1,25,1000); z = tan(alfa)*x - tan(alfa)*x0 funcprot(0); s = s0 + v0*t + (1/2)*(g*sin(alfa))*(t^2); v = v0 + g*sin(alfa)*t; t1 = linspac...
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//Caption:Scilab code to create motion blur //Fig6.1 //page 326 clc; close; a = imread('E:\DIP_JAYARAMAN\Chapter6\humm.jpg');//SIVP toolbox //filter coefficients of fspecial('motion',10,25) H =[0,0,0,0,0,0,0,0.0032,0.0449,0.0865,0.0072;... 0,0,0,0,0,0.0092,0.0509,0.0925,0.0629,0.0213,0;... 0,0,0,0.0152,0.0569,...
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clc //Initialization of variables W=500 //lb width=2 //ft len=4 //ft CGx=1.2 //ft CGy=0.9 //ft theta=30 //degrees gam=62.4 //lb/ft^3 //Calculations Fv=width*len //multiply by gam*x F=width/(2*cosd(theta)) //multiply by gam*x*x //function[y] =yp(x) // y=x/(2*cosd(theta)) + width*(x/cosd(theta))/(12*(cosd...
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clc; //page no //prob no. 20.3.1 //A silica fiber with A_max=25;A1=2;A2=0.3; //a)Determination of repeater dist at 0.9um wavelength z1=A_max/A1; disp('km',z1,'a)the repeater dist for 0.9um wavelength is'); //b)Determination of repeater dist at 1.5um wavelength z2=A_max/A2; disp('km',z2,'a)the repeater dist ...
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clc //Example 1.2 //Calculate the shear stress at the surface of the inner cylinder D1=25.15//mm D2=27.62//mm dr=0.5*(D2-D1)//mm f=10//rpm Vo=(%pi)*D1*f/60//mm/s //Let D denote d/dr DV=Vo/dr//s^-1 tow=0.005//Nm L=92.37//mm s=2*tow/D1^2/(%pi)/L*10^6//N/m^2 printf("The stress at the surface of the inner cyli...
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errcatch(-1,"stop");mode(2);//ex12.3 R_f=100*10^3; R_i=4.7*10^3; A_cl_NI=1+(R_f/R_i); disp(A_cl_NI,'d loop voltage gain') exit();
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function [cux, cuy, cuz]=curelation(nx,ny,nz,... uxx,uxy,uxz,uyy,uyz,uzz,... gxx,gxy,gxz,gyy,gyz,gzz,... dxuxx,dxuxy,dxuxz,dxuyy,dxuyz,dxuzz,... dyuxx,dyuxy,dyuxz,dyuyy,dyuyz,dyuzz,... dzuxx,dzuxy,dzuxz,dzuyy,dzuyz,dzuzz...
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clc clear //Initialization of variables x=0.97 hg=1187.2 //Btu/lb hf=298.40 //Btu/lb hfg=888.8 //Btu/lb //calculations hx1=x*hg+(1-x)*hf hx2=hf+x*hfg hx3=hg-(1-x)*hfg //results printf("\n In case 1, enthalpy = %.1f Btu/lb",hx1) printf("\n In case 2, enthalpy = %.1f Btu/lb",hx2) printf("\n In case 3, entha...
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//Chemical Engineering Thermodynamics //Chapter 3 //First Law of Thermodynamics //Example 3.6 clear; clc; //Given R = 1.98;//gas constant in kcal/Kgmole deg K T = 293;//Temperature in K M = 29;//Molecular weight of air //To calculate the flow work per kg of air //W=(P*V)=(R*T) W = R*T;//Flow work in K...
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#************************************************************ # Scenario of grande_salle # # date : Tue Nov 22 16:18:10 2011 #************************************************************ p3d_sel_desc_name P3D_ENV grande_salle p3d_sel_desc_name P3D_ROBOT MOVING_BOX p3d_set_robot_steering_method Linear p3d_set_robo...
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// Example 2.3:Numerical Aperture ,Acceptance Angle and criticle angke clc; clear; close; n1=1.46;//core Refractive Index d=1;// refractive index differnce in percentage NA=n1*(sqrt(2*(d/100)));// Numerical Aperture Sa= %pi*(NA)^2;//solid accepance angle in strad r=1-(d/100);//ratio of refractive index Oc=asi...
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// Example1.4 An aluminium wire 7.5 m long is connected in a parallel with a copper wire 6 m long. When a current of 5A is passed through the combination, it is found that the current in the aluminium wire is 3 A. The diameter of the aluminium wire is 1 mm. Determine the diameter of the copper wire. Resistivity of cop...
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// Theory and Problems of Thermodynamics // Chapter 6 // Thermodynamic Potentials and Availability // Example 11 clear ;clc; //Given data P1 = 1 // ideal gas pressure in MPa T0 = 300 // ideal gas temperature N = 1e3 // number of moles of ideal gas P2 = 0.1 ...
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JUMP late LOAD s0, s0 LOAD s0, s0 retk: LOAD&RETURN s0, 01 OUTPUT sF, 00 retz: ADD s6, s6 RETURN Z late: CALL Z, retk OUTPUT s0, 00 ADD s6, 01 CALL NZ, retz OUTPUT s6, 00 CALL Z, retz OUTPUT s6, 00 RETURN Z death: JUMP death
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function [w0,l]=specfact(a,b,c,d) r=d+d',w0=sqrt(d), p=ricc(a-b/r*c,b/r*b',-c'/r*c,'cont') l=w0\(c+b'*p)
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// Example 11.3: (a) Output voltage // (b) Input voltage clc, clear B1=36; // Fundamental output in volts B2=7*B1/100; // Second-harmonic distortion in volts Vs=0.028; // Input in volts A=B1/Vs; // Gain disp("Part (a)"); b=1.2/100; // Amount of feedback in volts B1f=B1/(1+b*A); // Fundamental o...
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clc // Given that N = 300 // Speed in RPM // Intake condition of compressor p1 = 0.98 // Pressure in bar T1 = 305 // Temperature in K p6 = 20// Delivery pressure in bar p3 = 5 // Intermediate pressure in bar C = .04 // Ratio of clearance volume to the stroke volume v = 3 // Volume flow rate of compressure in...
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//Example No. 5.17 clc; clear; close; format('v',7); //Given Data : V=220;//V f=50;//Hz L=0.012;//H Ra=0.72;//ohm K=2;//V/rad/s T=60;//N-m alfa=90;//degree Va=3*sqrt(3)*V*sqrt(2)/2/%pi*(1+cosd(alfa));//V Ia=5;//A disp(Ia,"Armature Current in A : "); T1=Ia*K;//N-m disp(T1,"Torque in N-m : "); Eb=Va-...
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q1=-1.6*10^(-19); q2=29*1.6*10^(-19); r=10^(-10); k=9*10^9; f=k*q1*q2/r^2; disp("the force of attraction (in N) is"); disp(f);
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canviar canvien V;IND;PL;3;PRS canviar canviïs V;SBJV;SG;2;PRS canviar canviaria V;COND;SG;1 canviar canviar V;NFIN canviar canviés V;SBJV;SG;1;PST canviar canviï V;IMP;SG;3;POS canviar canviàreu V;PFV;IND;PL;2;PST canviar canviarà V;IND;SG;3;FUT canviar canviessis V;SBJV;SG;2;PST canviar canviarien V;COND;PL;3 canviar...
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//Example 8.3, page no-508 clear clc i1=37 i2=42 i3=13 i4=6.7 Imax=(i1+i2)+(i1+i2)*(3/100)+(i3+i4)+(i3+i4)*(1/100) Imin=(i1+i2)-(i1+i2)*(3/100)+(i3+i4)-(i3+i4)*(1/100) printf("Maximum level of total supply current = %.3f mA\nMinimum level of total supply current = %.3f mA",Imax,Imin)
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clc; disp("Example A.9") dratio=10 uratio=1/dratio fratio=uratio*uratio*dratio*dratio disp(fratio,"The ratio of model force to prototype force is ")
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//Chapter 6:Induction Motor Drives //Example 9 clc; clf(); //Variable Initialization //Ratings of the star connected squirrel Induction motor f=50 // frequency in HZ Vl=400 // line voltage in V P=4 // number of poles N=1370 // rated speed //Frequency variation is from 10 Hz to 50 ...
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// to determine the Q factor // example 8-11 in page 221 clc; //Data given E=100D-3; R=[5 10]; XC=100; XL=XC; // supply resistance, capacitive reactance and inductive reactance respectively for the fig 8-17, all in ohm //calculation for n=1:2 I=E/R(n);// current in ampere V=I*XC;// VL=VC=V and XC=XL, vo...
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function [Num,Den,AllpassNum,AllpassDen] = iirlp2mb(varargin) B = varargin(1) A = varargin(2) Wo = varargin(3) Wt = varargin(4) rhs = argn(2) lhs = argn(1) if(rhs < 4 | rhs > 5) error("Wrong number of input arguments.") end if(rhs == 5) Pass = varargin(5); if(Pass == 'pass') pass_stop = -1 elseif(Pass ...
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// Example 3.20 // Computation of pulse power // Page no 485 clc; clear; close; // Given data L=0.1; // Length of laser R=0.8; // Mirror reflectance of end mirror E=1.7; // Laser pulse energy c=3*10^8; // Velocity of light t=L/((1-R)*c); // Ca...
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clc clear //Initalization of variables p=40000 //kW ef=0.98 rate=302000 //lb s3=1.6001 h2=1490.1 loss=600 v=400 //ft/s g=32.2 //ft/s^2 J=778 //calculations out=p/(0.746*ef) srate=rate/out X=-(s3-1.9782)/1.8456 h3=1106 - X*1036.3 theoturb=h2-h3 intturb=(out+loss)*2544/rate Ie=intturb/theoturb *100 h3...
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clc; clear all; c = 3e8; // Velocity of light in air m = 9.1e-31; // Mass of an atom in Kg h = 6.626e-34; // Planck's constant e = 1.6e-19; // Charge of an electron in culoumb V = 125; // Potential Difference in volts v = sqrt((2*e*V)/m); // Velocity of an electron disp('m/s',v,'The velocity of an electron is...
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function fourierTransform=FFT(inputMatrix) // This funtions returns discrete Fourier Transform of 2D input matrix // // Calling Sequence // fourierTransform=FFT(inputMatrix); // // Parameters // inputMatrix: Input matrix must be 2-D. // // Description // It returns the 2D discrete Fourier transform of two dimensional i...
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// Chapter 12 // Resolution of System // Page.No-445 // Example12_1 // Given clear;clc; V=2; //in V Bits=12; levels=2^Bits; //12 bit words step=V/levels; printf("\n The system can resolve = %.6f V\n",step); // Result Drange=20*log10(levels); printf("\n The Dynamic Range is = %.0f dB\n",Dran...
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//EX3_18 PG-3.56 clc Es=120;//rms value of input voltage f=50;//frequency Idc=50e-3; C=100e-6;//filter capacitor Esm=sqrt(2)*Es; Edc=Esm-Idc/(4*f*C); printf("\n DC output voltage is %.4f V \n",Edc) Vr=Idc/(4*sqrt(3)*f*C);//rms value of ripple voltage printf("\n rms value of ripple voltage is %.4f V \n ",Vr) ...
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//Checking the output of the function when more than one input argument is passed to the function y=[1000 1000 123 1098 1233 1456]; y2=[1000 1000;123 1098;1233 1456]; y1=pow2db(y,y2); disp(y1); //Output //Wrong number of input arguments.at line
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//scilab 5.4.1 clear; clc; printf("\t\t\tProblem Number 11.17\n\n\n"); // Chapter 11 : Heat Transfer // Problem 11.17 (page no. 578) // Solution //The first step is to check Reynolds number.It will be recalled that the Reynolds number is given by (D*V*rho)/mu and is dimensionless.Therefore,we can use D, ...
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ci=18 CI=10^((ci)/10) q=(6*(CI))^0.25 K=ceil(q*q/3)//cluster size disp(K,'minimum cluster size') k=7 q1=sqrt(3*k) c1i1=q1^4/6 C1I1=10*log10(c1i1) if (C1I1<20) then disp(,'cluster size cannot meet the desired C/I requirement') C2I2=10^(20/10) q2=(6*C2I2)^0.25 k1=ceil((q2)^2/3) disp(k1,'nearest valid cluster size K') els...
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clc; v=250; // rated voltage of dc shunt motor n1=1200; // no load speed N=1000; // turns per pole in shunt field winding n2=900; // reduced speed ia=100; // full load armature current rf=0.2; // series field resistance ra=0.1; // armature resistance ar=0.04; // armature reaction as afraction of main field m.m...
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N = 10 // taille de l'échantillon X = grand (1,N,"unf",50,86); // l'échantillon histplot(5,X) // on fait l'histogramme
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clear; clc; // RDMP-6.sce // A <=> B // Progresión óptima de temperatura // (a) // CONSTANTES kd0 = 1.94E15; ki0 = 6.26E19; // h-1 Ed = 44500; Ei = 59500; // cal/mol R = 1.987; // cal/(mol*K) Tmin = 500.0; dT = 0.1; Tmax = 650.0; T = Tmin:dT:Tmax; // K kd = kd0*exp(-Ed./(R*T)); // Ecuación de Arrhenius directa ki = ...
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//Ex:1.21 clc; clear; close; i=20*10^-3;//in amps r=1000;//in ohms p=(i^2)*r; printf("Power dissipated = %f watts",p);
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t=[0.004 0 0.004 0.005 0.004 0.005 0.005 0.005 0.005 0.005 0.006 0.006 0.012 0.012 0.049 0.046 0.377 0.354 10.131 7.550]; r=[0.004 0.004 0.004 0.004 0.004 0.006 0.018 0.106 1.042 26.654 ]; x=[2 4 8 16 32 64 128 256 512 1024 ]; plot(x,t,"-o",x,r,"-*"); hl=legend(['2 procesos';'4 procesos';'normal'],"in_upper_left"); t...
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function[xyz] = whitepoint(input_string) out = whitepoint(input_string) channels = size(out) for i = 1:channels xyz(:,:,1) = out(1) end endfunction
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clear // // dell=0.25 //mm //Instantaneous Extension //Bar-A b1=25 //mm //width of bar D1=500 //mm //Depth of bar //Bar-B b2_1=25 //mm //width of upper bar b2_2=15 //mm //Width of Lower Bar L2=200 //mm //Length of upper bar L1=300 //mm //Length of Lower bar E=2*10**5 //N/mm**2 //Youngs Modulus of bar //Calculatio...
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// calculate the per unit change in the value of spring for different temperature ranges clc; dG_pu=-240*10^-6; dD_pu=11.8*10^-6; disp('for temperature change of 20 degree C to 50 degree C (%) =') d_th=30; dK_pu=(dG_pu+dD_pu)*d_th*100; disp(dK_pu) disp('for temperature change of 20 degree C to -50 degree C (%) ...
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//Variable declaration mewn=0.3; //mobility of electrons(m**2/Vs) rho=0.25; //resistivity(ohm m) e=1.6*10**-19; //Calculation n=1/(rho*e*mewn); //number of donor atoms(per m**3) //Result printf('number of donor atoms is %0.3f *10**19 per m**3 \n',(n/10**19))
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(unwatch all) (clear) (dribble-on "dffctcmd.out") (batch "dffctcmd.bat") (dribble-off) (clear) (open "dffctcmd.rsl" dffctcmd "w") (load "compline.clp") (printout dffctcmd "dffctcmd.bat differences are as follows:" crlf) (compare-files dffctcmd.exp dffctcmd.out dffctcmd) (close dffctcmd)
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//Example 30.5 n=3;//Shell number_subshell=0;//To store value of number of subshells for i=0:1:n-1 number_subshell=number_subshell+1; end printf('Number of subshells in the nth shell = %d\n\n',number_subshell) Max=0;//To store value of Maximum number of electrons in a shell for l=0:1:2 electrons_in_sub...
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-- Fuzzy Logix, LLC: Functional Testing Script for DB Lytix functions on Netezza -- -- Copyright (c): 2014 Fuzzy Logix, LLC -- -- NOTICE: All information contained herein is, and remains the property of Fuzzy Logix, LLC. -- The intellectual and technical concepts contained herein are proprietary to Fuzzy Logix, LLC....
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function[y]=f2(t,u) y(1)=u(2); y(2)=-4*u(2)-3*u(1); endfunction N=101; t0=0; t=linspace(t0,5,N); h=(5-0)/(N-1); y2=zeros(2,N); y2(:,1)=[1;1]; for i=1:N-1 yd=y2(:,i)+h*f2(t(i),y2(:,i)); y2(:,i+1)=y2(:,i)+(h/2)*(f2(t(:,i),y2(:,i))+f2(t(:,i+1),yd)); end plot2d(t,y2(1,:),5) plot2d(t,y2(2,:),3) legend(['1'...
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@relation vowel @attribute TT integer[0,1] @attribute SpeakerNumber integer[0,14] @attribute Sex integer[0,1] @attribute F0 real[-5.211,-0.941] @attribute F1 real[-1.274,5.074] @attribute F2 real[-2.487,1.431] @attribute F3 real[-1.409,2.377] @attribute F4 real[-2.127,1.831] @attribute F5 real[-0.836,2.327] @attribute ...
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//fiber optic communications by joseph c. palais //example 8.5 //OS=Windows XP sp3 //Scilab version 5.4.1 //given clc clear all NA=0.2//numerical aperture dia=50*(10^(-6))//core diameter in m a=dia/2//core radius in m lateral_loss=0.5//allowable lateral loss in dB Beam_dai=2//beam daimeter in mm dby2a=0.09...
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//Series and Parallel Connection of Thyristors// //Example 4.2// Ed=20;//permissible difference in voltage across devices in Volts// Id=1*10^-3;//maximum difference in latching current across devices in Amperes// Qd=10;//difference in recovery charge in Micro coloumbs// Vd=20;//permissible difference in blocking v...
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//Example 8.9 clear; clc; rd=1*10^6; g1=2*10^(-3); R1=100*10^(3); g2=10*10^(-3); R2=50*10^3; ro=100; f1=100*10^3; f2=1*10^6; f3=10*10^6; PM=45; a0=g1*R1*g2*R2; C1=1/(2*%pi*f1*R1); b1=1; C21=1/(2*%pi*f2*R2); f2newap1=g2/[2*%pi*(C1+C21)]; fx1=f3; f1new1=f3/(b1*a0);...
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function [res] = kiks_p2mm(pulses) // Ouput variables initialisation (not found in input variables) res=[]; // Display mode mode(0); // Display warning for floating point exception ieee(1); // ----------------------------------------------------- // (c) 2000-2004 Theodor Storm <theodor@tstorm.se> // http://www.ts...
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// about the analytical integration for the analytical solution //Eg-13.4 //pg-529 clear clc x(1) = 0; yb(1) = 0; y(1) = 1; //Initial condition h = 0.1; deff('out = func(in1,in2)','out = 0.5*(1+in1)*in2^2') //Taking the exact values using the expression calculated analytically as y = 4/(4-2*x-x^2) ...
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epsilon=8.854D-12 AB=.05 BC=.07 AC=sqrt(.05^2+.07^2) V1=2D-10/(4*%pi*epsilon*.05)//potential at A due to charge at B V2=-8D-10/(4*%pi*epsilon*AC)//potential at A due to charge at C V3=4D-10/(4*%pi*epsilon*.07)//potential at A due to charge at D V=V1+V2+V3 mprintf("Potential at A due to charges at B, C and D=...
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function [a, b, c, d] = besself (n, w, varargin) //This function generates a Bessel filter. //Calling Sequence //[a, b] = besself(n, w) //[a, b] = besself (n, w, "high") //[a, b, c] = besself (…) //[a, b, c, d] = besself (…) //[…] = besself (…, "z") //Parameters //n: positive integer value //w: positive real value //D...
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ok=open_serial(1,2,115200); if ok~=0 then error('Unable to open serial port, please check'); end for i=1:10000 p=cmd_digital_in(1,5) q=cmd_digital_in(1,6) if p==0 & q==0 cmd_digital_out(1,9,0) sleep(5) else if p==1 & q==1 cmd_digital_out(1,9,0) sleep(5) els...
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//Calculate voltsge to be applied//Chapter 3 //Example 3.20 //page 226 clear; clc; disp("Example 3.20") kVA=100; V1=6600; //primary voltage in volts V2=330; //secondary voltage in volts f=50; //frequency in hertz V1sc=100; //short circuit...
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PL/SQL Developer Test script 3.0 80 declare a anydata; obj xxdoo.xxdoo_cntr_site_typ; coll xxdoo.xxdoo_cntr_sites_typ; l_dummy pls_integer; dao xxdoo.xxdoo_db_dao; l_start_time timestamp; -- function get_xml(a anydata) return xmltype is l_result xmltype; begin l_dummy := a.getObject(obj); ...
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clc clear //Initialization of variables nn=0.95 p1=50 //psia p2=30 //psia v1=8.515 m=1 //lbm //calculations cv=sqrt(nn) V2rev=1372 V2act=cv*V2rev n=1.283 v2=v1*(p1/p2)^(1/n) A=m*v2/V2act *144 D=sqrt(A*4/%pi) //results printf("Area = %.2f in^2",A) printf("\n diameter = %.3f in",D)
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// chapter 7 , Example7.9 , pg 213 ni=2.4*10^19 //intrinsic carrier density(in m^-3) Un=0.39 //electron mobility (in m^2/(V*s)) up=0.19 //hole mobility (in m^2/(V*s)) e=1.6*10^-19 //charge in electron (in C) sigma=ni*e*(Un+up) // electrical conductivity printf("Electrical conductivity\n") ...
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struct_initialization_runme.sci
exec("swigtest.start", -1); if StructC_x_get(instanceC1_get()) <> 10 then swigtesterror(); end if StructD_x_get(instanceD1_get()) <> 10 then swigtesterror(); end if StructD_x_get(instanceD2_get()) <> 20 then swigtesterror(); end if StructD_x_get(instanceD3_get()) <> 30 then swigtesterror(); end if StructE_x_get(in...
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ex4_2.sce
// Exa 4.2 clc; clear; close; // Given data N_D = 10^17 * 10^6;// in atoms/m^3 N_A = 0.5*10^16*10^6;// in atoms/m^3 Epsilon_r = 10; Epsilon_o = 8.85*10^-12; Epsilon = Epsilon_r*Epsilon_o;// in F/m e = 1.602*10^-19;// in C V = 0; V_B = 0.7;// in V W = sqrt( ((2*Epsilon*V_B)/e)*(1/N_A+1/N_D) );// in m disp(...
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2_23.sci
// 2.23 clc; Rth0=100; ath0=0.00392; dth=65-25; R65=Rth0*[1+ath0*dth]; printf("resistance at 65 degree C= %.2f ohm ",R65) th={[(150/100)-1]/ath0}+25; printf("\n Temperature = %.2f degree C ",th)
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CH02Exa2_2_5.sci
// Scilab code Exa2.2.5 To determine the most stable isotopes for A = 27, A = 118, A = 238 : Page 69 (2011) a_v = 15.5; // Volume energy, MeV a_s = 16.8; // Surface energy, MeV a_c = 0.7; // Coulomb energy, MeV a_a = 23.0; // Asymmetric energy, MeV a_p = 34.0; // Pairing energy, MeV z = poly(0, 'z') // For A =...
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clc; T1=15+273;//K p2!p1=8; y1=1.4; T2s=T1*([p2!p1]^[(y1-1)/y1]); T2=T1+(T2s-T1)/0.8; T3=800+273;//K p3!p4=p2!p1 y2=1.333; T4s=T3/[(p3!p4)^([y2-1]/y2)]; T4=T3-0.82*(T3-T4s) cv=1.11; cp=1.005; W=[cv*(T3-T4)-cp*(T2-T1)]; heat_supp=cv*(T3-T2); cycle_eff=W/heat_supp; disp("cycle efficiency is :"...
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ex9_1.sce
clc; r=8; // Compression ratio of an engine p1=100; // Pressure of air before compression in lPa T1=300; // Temperature air before compression in kelvin qH=1800; // Heat added to the air in kJ/kg k=1.4; // Index of reversible adiabatic process Cvo=0.7165; // Specific heat at constant volume in kJ/kg K Cpo=1.0035...
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pe5_12.sce
//example 5.12 clc; funcprot(0); // Initialization of Variable I=6;//current V=.6;//voltage D=.5;//duty cycle //calculation Rs=V/I; disp(Rs,"resistance in ohm") Pr=D*V*I; disp(Pr,"power in W:") Vp=28; Pm=D*Vp*I; disp(Pm,"MOSFET power in W") T=40;//temperature Tj=T+Pm*5.1; disp(round(Tj),"temperature in ...
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//Example 2.5 //Program to estimate total number of guided modes propagating in the fiber clear; clc ; close ; //Given data NA=0.2; //NUMERICAL APERTURE d=50*10^(-6); //metre - CORE DIAMETER lambda=1*10^(-6); //metre - OPERATING WAVELENGTH a=d/2; //CORE RADI...
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8_9.sce
clc //initialisation of variables Q= 60 //ft^3/sec v= 12 //m.p.h A= 3 //ft^2 D= 64 //lbs/ft^3 g= 32.2 //ft/sec^2 M= 64 //lbs //CALCULATIONS vr= Q/A u= v*44/30 v1= vr-u P= M*Q*v1/g //RESULTS printf ('propelling force= %.1f lbs',P)
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prbs_pp.sci
mode(0) function [temp] = prbs_pp(heat,fan, setpoint) global heatdisp fandisp tempdisp setpointdisp sampling_time m name temp = comm(heat,fan); plotting([heat fan temp setpoint],[0 0 20 0],[100 100 40 1000]) m=m+1; endfunction
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example1.sce
printf("\n trnsfer function of the given network ") printf("\n Vi(s)=R*I(s)+s*L*I(s)") printf("\n V0=s*L*I") printf("\n V0(s)/Vi(s)=s*L*I/(R*I(s)+s*L*I(s))") printf("V0(s)/Vi(s)=s*L/(R+s*L) is the required transfer function")
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8_5.sce
clc //initialisation of variables V= 2.5*10^4 //m/sec m= 30 //gms s= 10*10^-16 //cm^2 N= 6.023*10^23 //molecules T= 300 //K k= 8.3*10^7 //CALCULATIONS t= sqrt((m/(%pi*k*T)))*(V/(4*s*N)) //RESULTS printf (' lifetime = %.e sec',t)
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1_1.sce
clc //initialisation of variables L= 20 //ft angle= 30 //degrees //CALCULATIONS d= L*sind(angle) //RESULTS printf ('Desitance from foot of Ladder= %.2f ft',d)
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// Example 4.3, page no-123 clear clc m=2950 //initial mass of the satellite F=450 //required thrust T=10 // thrust for time period i=300 //specific impulse of a propellant g=9.807 // acceleration due to gravity mi=F*T/(i*g) printf("Mass of propellant that would be consumed is, ...
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//nequest theorem clc clear close ///////////////////////////////////////// ///////////////////////////////////////// a1 = input("amplitude of signal 1: ") a2 = input("amplitude of signal 2: ") a3 = input("amplitude of signal 3: ") f1 = input("freq. of signal 1: ") f2 = input("freq. of signal 2: ") f3 = input("fre...
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clc V1=300; //m/s p1=78; //kN/m^2 T1=313; //K p2=117; //kN/m^2 R=287; //J/kg K y=1.4; //Let r1=p1/rho1 r1=R*T1; V2=sqrt(2*(y/(y-1)*r1*(1-(p2/p1)^((y-1)/y)) + V1^2/2)); disp("Velocity of gas at section 2 =") disp(V2) disp("m/s")
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// abordagem 2 GH = (Kf*s)/(s*(s+5)*(s+15)) // malha secundaria // ponto de entrada e saida = -10 // assintotas // sigmaA = -10 // tetheA = pi/2 , 3pi/2, 5pi/2 // qsi = 0.8 (enunciado) // tetha1 = 37 // a = -10 + 7.5i // K = 81.25 // malha primaria // Tsec = G / 1+GH // Tsec = 1/(s*(s+5)*(s+15)+(Kf*s)) // ----> ...
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clc; clear; format('e',11); f=10*10^9; Pr=1*10^-6; D=10; r=5*10^3; sigma=10; c=3*10^8; lemda=c/f; Ae=lemda^2*D/(4*%pi); Pt=Pr*(4*%pi*5000)^2/(D*sigma*Ae); disp(Pt,"The transmitted power(in watt)=");
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// File name: projects/12/MemoryTest/MemoryTest.tst load, output-file MemoryTest.out, compare-to MemoryTest.cmp, output-list RAM[8000]%D2.6.1 RAM[8001]%D2.6.1 RAM[8002]%D2.6.1 RAM[8003]%D2.6.1 RAM[8004]%D2.6.1 RAM[8005]%D2.6.1; repeat 1000000 { vmstep; } output;
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SPlitter QP {} FILter WQ { } fILter s {PbT } Y -> z grouPeR y {mOduLE J{ } AgGreGATE BITor(U.uk) aS IWU ,Sum(P) AS f } UngRoUpeR b { } GroUPFiLteR Ce {BITOR (A:fD::c5aB:F, ) not biTaNd ( ) oR NoT A ( , BItANd ( BItOR (f, 7, ), , fdc8:d:Bd:0A:E:f:252.7.151.5/0, 15., e, c::DE, ), ::A:aC:b:7cb7:69.246.180.250...
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// exa 1.2 Pg 14 clc;clear;close; Pmax=100;// kW Pmin=10;// kW z=5;// no. of models //Rn=Pmax/Pmin=fi**(z-1) fi=(Pmax/Pmin)**(1/(z-1));// common ratio printf('The power of generating sets are:') P1=Pmin;// kW for i=1:z printf('\n\t\t\tP%d = %.1f kW',i,P1) P1=fi*P1;//kW end; printf('\nExpanding for 10 models....
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clc,clear printf('Example 3.21\n\n') V_avg = (220+190)/2 //average voltage across load I_avg=12,R_a=0.5,R_sh=250 W_dash=V_avg*I_avg //power absorbed t_1=30,t_2=5 W=W_dash*(t_2/(t_1-t_2)) V=250,I=22 //input current I_sh = V/R_sh I_a= I - I_sh arm_cu_loss = R_a*I_a^2 //armature copper loss shunt_field_cu...
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//Exa 7.4 clc; clear; close; //given data A=5;// in m^2 intensity=660;// in W/m^2 disp("alpha= 2*rho or rho=alpha/2") disp("alpha= 3*toh or toh=alpha/3") disp("as alpha + rho + toh =1") disp("then alpha+alpha/2+alpha/3 = 1") disp("alpha = 6/11") disp("rho = 6/22") disp("toh = 6/33") alpha=6/11...
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//Ex:3.23 clc; clear; close; n=80; // sinx=y/(nd) // sinx=y/(n*y/2)=2/n sinx=2/n; x=asin(sinx)*(180/%pi);// in degree dx=2*x;// the first nulls beam width in degree printf("The first nulls beam width = %f degree",dx);
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART III : SWITCHGEAR AND PROTECTION // CHAPTER 3: SYMMETRICAL COMPONENTS' ANALYSIS // EXAMPLE : 3.7 : // Page number 492-493 clear ; clc ; close ; // Clear the work space...
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// Variable Declaration r = 25.0 //Resistance/phase(ohm) x = 90.0 //Reactance/phase(ohm) V_S = 145.0 //Sending end voltage(kV) V_R = 132.0 //Receiving end voltage(kV) P_R_1 = 0 //Power(MW) P_R_2 = 50.0 //Power(MW) // Calculation Section A = 1.0*exp(%i*0*%pi/180) //Line constant B = comp...
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//ques-25.14 //Calculating pressure for ammonia gas using ideal gas equation and van der Waals equation clc n=0.6;//moles of NH3 V=3;//volume (in L) T=273+25;//temperature (in K) a=4.17;//(in L^2 atm/mol^2) b=0.0371;//(in L/mol) //Van der Waal's P1=(n*0.0821*T)/(V-n*b)-(a*n^2)/V^2; //Ideal Gas' P2=(n*0.0821*...
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// Scilab Code Ex1.15 Speed at total energy twice the rest mass energy: Pg: 25 (2008) c = 1; // Speed of light is assumed to be unity, m/s m0 = 1; // For convenience, rest mass of the particle is assumed to be unity, kg m = 2*m0; // Mass of the moving particle when m*c^2 = 2*m0*c^2, kg // As m = m0/sqrt(1 ...
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//Solutions to Problems In applied mechanics //A N Gobby clear all; clc //initialisation of variables h=3//in s=10.2//tonf/in^2 v=0.006//in d=0.5//in d1=0.75//in w=20//lbf q=v/8//tonf/in^2 x=0.029//in //CALCULATIONS M=s/q//tonf/in^2 E=M*(x)/(h*12)//tonf/in^2 //RESULTS printf('the corresponding stress=% f ...
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//Exa 2.55 clc; clear; close; //Given data : format('v',6); Output=3;//in H.P. Output=3*735.5;//in watts Efficiency=0.83;//unitless cosfi=0.8;//power factor Vl=500;//in volt Input=Output/Efficiency;//in watts //Formula : Input=sqrt(3)*Vl*Il*cosfi Il=Input/(sqrt(3)*Vl*cosfi);//in Ampere ISCbyIFL=3.5;//rati...
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clear clc //To find frictional force of the box on the cart // referrinf to same problem as 3-5 on page no.55 //Given : // mass of flat-bed cart mc =360 //kg // mass of box mb =150 //kg // magnitude of acceleration for cart ac =0.167 // m/s^2 // magnitude of acceleration for box ab =1...
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clear ; clc; printf("\t Example 9.7\n"); T1=373; //saturated temp.of water, K a=958 ; //desity difference,kg/m^3 s=0.0589; //surface tension,kg/s^2 Hfg=2257*1000; //latent heat,J/kg a2=0.597; //density of gas, kg/m^3 A=400*10^-4; //area of mettalic body,m^2 V...
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# -------------------------- Header Parameters -------------------------- scenario = "Vigilance"; write_codes = EXPARAM( "Send ERP Codes" ); default_font_size = EXPARAM( "Default Font Size" ); default_background_color = EXPARAM( "Default Background Color" ); default_text_color = EXPARAM( "Default Font Color" ); defa...