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clc //initialisation of variables clear vbm= 38 //ft/sec va= 17.94 //ft/sec a= 147.5 //degrees vwm= 10.37 //ft/sec C= 1430 //lbf/ft P= 763 //lbf/ft^2 //CALCULATIONS vwm1= vbm+va*cotd(a) p= (vwm-vwm1)/vwm C1= C*(1-p) P1= P*(1-p) //RESULTS printf ('Oulet Velocity = %.2f ft/sec',vwm1) printf ('\n Torque =...
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//determine the size of bolts clc //solution //given //ref fig 11.31 W=30000//N ft=60//N/mm^2 L1=80//mm L2=250//mm L=500//mm Wt1=W/4//N printf("the value of Wt1 is,%f N\n",Wt1) w=(W*L)/(2*(L1^2+L2^2))//N/mm printf("the value of w is,%f N/mm\n",w) Wt2=w*L2//N printf("the value of Wt2 is,%f N\n",Wt2) Wt=W...
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we we wy x1 x2 #d -9,697 9,175 Klasa1 -8,636 8,045 Klasa1 -7,991 7,259 Klasa1 -7,221 6,718 Klasa1 -6,076 5,613 Klasa1 -4,932 4,483 Klasa1 -3,912 3,034 Klasa1 -2,996 2,518 Klasa1 -2,143 1,462 Klasa1 -1,269 0,626 Klasa1 -1,748 -0,381 Klasa1 -3,371 -0,061 Klasa1 -4,62 0,872 Klasa1 -6,888 3,746 Klasa1 -8,262 3,992 Klasa1 -...
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// to determine the frequency // example 9-11 in page 269 clc; // Data Given C=3.5D-12; Rs=600; // capacitance in farad and source resistance in ohm //calculation printf("frequency=%.1f MHz",1/(2*%pi*C*Rs*10^6)); //result //frequency=75.8 MHz
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clc clear //Input data P1=1;//Pressure at the beginning of compression stroke of an oil engine working on a air standard dual cycle in bar T1=303;//Temperature at the beginning of compression stroke in K P3=40;//The maximum pressure reached in bar T4=1673;//Maximum temperature reached in K P4=P3;//Pressure at th...
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function Fontsize(Ookisa) global Wfile FID; Str='%'; Ucode=ascii(Ookisa); S=char(Ucode(1)); if S=='n' Str='\normalsize%'; end if S=='s' if length(Ucode)==1 Tmp=''; else Tmp=char(Ucode(2)); end if Tmp=='s' Str='\scriptsize%'; else Str='\small%'; end end...
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function y= f(x) y = sin(x) - 6 + x // função do problema endfunction a = -100 // início do intervalo b = 100 // fim do intervalo //obs: você pode alterar o intervalo para ficar mais próximo da raiz do função, caso você já a conheça. //plote a função no Geogebra para facilitar, caso queira. m = (a+b)/2 for i = ...
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// To calculate current in each branch using loop analysis and point voltages in a given network. clc; clear; // MESH Equations for the given network. //3.95*i1-3.75*i2+0*i3=120 //-3.75*i1+9.5*i2-5.45*i3=0 //0*i1-5.45*i2+5.55*i3=-110 // Positive of 120V DC supply connected to 0.2 ohm resistor // Positive ...
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//Problem 2.06: //initializing the variables: sg = 0.8 abvis = 0.02;// in cP pref = 62.43; // in lb/ft3 //calculation: p = sg*pref u = abvis*6.720E-4; // in lb/ft.sec v = u/p printf("\n\nResult\n\n") printf("\n kinematic viscosity of a gas is %.3E ft2/sec\n",v)
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//Example No. 4_16 //Condition and Stability //Pg No. 82 clear ; close ; clc ; C1 = 7.00 ; C2 = 3.00 ; m1 = 2.00 ; m2 = 2.01 ; x = (C1 - C2)/(m2 - m1) y = m1*((C1 - C2)/(m2 - m1)) + C1 disp(y,'y = ',x,'x = ') disp('Changing m2 from 2.01 to 2.005') m2 = 2.005 x = (C1 - C2)/(m2 - m1) y = m1*((C1 - C2)/(m2...
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// Function sigma // Example1 s=%s; sys=syslin('c',1/(1+s)); sigma(sys) sigma(sys,sys^2) sigma(sys,20:40) [V,w]=sigma(sys)
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clc clear //Initialization of variables m1=5.28 m2=1.28 m3=23.52 //calculations m=m1+m2+m3 x1=m1/m x2=m2/m x3=m3/m C=12/44 *m1/ m O=(32/44 *m1 + m2)/m N=m3/m sum1=(x1+x2+x3)*100 sum2=(C+N+O)*100 //results printf("From gravimetric analysis, co2 = %.1f percent , o2 = %.1f percent and n2 = %.1f percent"...
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// A => B, k // // A0 = 2 // B0 = 0 // y0 = [A0; B0] // t0 = 0 // k = 1e-3 // // How to calculate reaction time when [B] reaches 1.2 mol/L? function dy = model(t, y) A = y(1) B = y(2) dAdt = -k*A dBdt = k*A dy=[dAdt, dBdt] endfunction // integrate ODE (model) until end_of_calculations(t, y) = 0 function z = ...
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A = matrix(1:42,7,6); // vector of all the elements of A A(:) // the j-th column of A A(:,j) // the i-th row of A A(i,:) // elements of columns from j to k and all rows A(:,j:k) // elements of all columns and rows from j to k A(j:k,:) w = matrix(101:142,7,6); A(:) = w // if indices are not ...
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//Caption:Determine the (a)Equivalent resistance,leakage reactances and impedance reffered to high voltage side (b)Equivalent resistance,leakage reactances and impedance reffered to high voltage side (c)Total copper loss of transformer //Exa:3.7 clc; clear; close; f=50;//in Hz P=30*1000;//in watts E_1=3000;//in ...
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//Chapter 5,Ex5.12,Pg5.14 clc; E1=4400 //Primary EMF R1=3.45 //Primary resistance in ohms X1=5.2 //Primary reactance in ohms E2=220 //Secondary EMF R2=0.009 //Secondary resistance in ohms X2=0.015 //Secondary reactance in ohms K=E2/E1 I1=50*1000/E1 //Using the formula I1=kVA rating*1000/E printf("\n Full load...
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//chapter 20 //example 20.5 //page 651 clear; clc ; //given Eb=200;//battery voltage mV es=0;//signal voltage V Rl=80;//load resistance in ohm Ed=Eb+es; Id=2;//diode current mA Er=(Eb+es); Il1=Er/Rl;//load current mA Ib1=Id+Il1;//battery current mA es=100;//mV Ed=Eb+es; Id=1; Il2=Ed/Rl; Ib2=Id+Il2...
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clc //initialisation of variables P=135//bars Q=201//min p=448 //CALCULATIONS FPH=P*Q/p*0.1//hp //RESULTS printf('The fluid horsepower potential of the system is=% f hp',FPH)
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clear flag=1 mode(-1) clc printf("Example 1 : Show the method of showing all the type of process IDs \n") disp("****************************************************************") disp("Answer : ") disp("INSTRUCTIONS : ") halt(' ') disp("1.These programs are part of systems programming PURELY in...
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clear; // Fatoração LU COM pivotamento parcial function [L, U, P] = fatoracaoLU(A) [linhas colunas] = size(A); L = eye(linhas, colunas); // Matriz para as permutações de linhas de A e b -> A' = PA = LU; Ly = Pb; Ux = y P = eye(linhas, colunas); for j = 1:colunas pivo = A(j,j);...
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clc //solution //given //ref fig 15.27 As=15//mm^2 tu=400//N/mm^2 ft=80//N/mm^2 pb=20//N/mm^2 Ps=As*tu//N //let P1 be force in link LM P1=(Ps*100)/(350)//N //taking momnet abt N,we get P P=(P1*100)/(900)//N N=P1+P//N //let d be dia and l be length of pins //l=1.25d //N=d*l*pb=25*d^2 //d=sqrt(N/25)//mm printf("the dia ...
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//Chapter 12 : Solutions to the Exercises //Scilab 6.0.1 //Windows 10 clear; clc; //Solution for 7.8 A=[1 0 1 0;0 0 1 1;0 0 0 1;1 1 0 0] disp(A)
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// Ex10_13 clc; // Given: w=5;// in g ai=55;// counts per 10 min A0=15.8;// in dpm/g // Solution: cpm=55/10; dpm=cpm*100/10; // 10% efficient counting sa=dpm/w;// in dpm/g t=5730*log(A0/sa)/(0.693); // Age determination printf("The age of the sample is = %f years",t)
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monito...
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clc clear //For throttling H1=H2 //At 11 bar Hf=781.3; //in kJ/kg Hfg=2000.4; //in kJ/kg //At 1 bar Hg=2675.5; //in kJ/kg x=(Hg-Hf)/Hfg; printf('The Dryness Fraction: %3.3f kJ/kg',x); printf('\n');
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////Chapter 13 Steam Engines ////Example 13.2 Page No 283 ///Find Therotical mean effective pressure //Input data clc; clear; a=5/100; //Engine cylinder of the stroke valume in % P1=12; //Pressure of the stream rc=3; //Cut-off is one-third Pb=1.1; //Constant the back pressure in bar /...
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//teste2 clc clear qtd = input("Digite a Quantidade de elementos :") n=qtd for i=1:n f(i) = input("Digite a numero "); end for i=1:n printf('\nQuantidade = %d', f(i)) end
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//To Determine phasors and phasor diagrams when loaded with a balanced resistor //Page 154 clc; clear; R=2.77; //Resistance of the balanced load //From Phasor Diagram in Result file Vab=480*exp(%i*0); //Reference Voltage MVn=abs(Vab)/sqrt(3); //Magnitude of line to neutral voltages //Angles of Three phase vol...
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// // 2010.05.15 function Out=Texctr(N) if type(N)==1 Alpha='abcdefghijklmnopqrstuvwxyz'; Out='ketpicctr'+part(Alpha,N); else if part(N,1)=='\' Out=part(N,2:length(N)); else Out=N; end; end; endfunction
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//Chapter 5, Problem 14, Figure 5.27 clc; //Resistance R1 R2 R3 R4 R5 R1=2; R2=9; R3=1.4; R4=2; R5=8; V=17; R45=(R4*R5)/(R4+R5); R34=R3+R45; R23=(R2*R34)/(R2+R34); R=R1+R23; //the circuit is gradually reduced in stages as shown in Fig. 5.28(a)–(d). I=V/R; I1=(R2/(R2+R34))*I; Ix=(R1/(R1+R5))*I1; printf(...
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function [x,y,typ] = mdaq_encoder(job,arg1,arg2) encoder_desc = ["This block reads MicroDAQ quadrature encoder inputs."; "It uses x4 mode to decode quadrature signal."; "In case of high frequency signals (up to 2MHz) ENC1/ENC2"; "modules shall be used. ENC3/ENC4 are suitable for lower "; "frequency ...
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//Wing area(in ft^2): A=1600; //Aspect ratio: ar=6.5; //Groos weight of aircraft(in lbf): W=150000; //Coefficient of drag at zero lift : Cd0=0.0182; //Sonic speed at sea level(in mph): c=759; //Density of air(in slug/ft^3): p=0.00238; //Srall speed at sea level(in mph): Vssl=175;
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clc; p1=1.4; // Pressure at state 1 in bar T1=310; // Temperature at state 1 in kelvin rp=5; // Pressure ratio Tmax=1050; // Maximum temperatuer in kelvin WN=3000; // Net output in kW Cp=1.005; // Specific heat at constant pressure in kJ/kg K r=1.4; // Specific heat ratio R=287; // Characteristic gas constant i...
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//style.fontSize=12; //style.displayedLabel="<table> <tr> <td><b>In</b></td> <td>pfet_i2v</td> <td align=right><b>Out</b></td> </tr> </table>"; //pal5 = xcosPalAddBlock(pal5,"pfet_i2v",[],style);
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// problem 12.4 H=150 Q=6 N=400/60 D1=1.2 x1=20 x2=90 B1=0.1 u1=3.142*D1*N Vf1=Q/(3.142*D1*B1) Vw1=Vf1/tand(x1) Vw2=0 w=9810 g=9.81 P=w*Q*Vw1*u1/(g*1000) disp(P,Vw2,Vw1,"whirl component at inlet and outlet,power developed in Kw")
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//Example 7.1// width and length clc; clear; close; format('v',6) vph=400;//phase voltage in volts n=3;//number of phase kw=36;//power in kW r=((vph^2)/(n*((kw*10^3)/n)));//resistance in ohms p=1.016*10^-6;//resitivity t=0.3;//thickness in mm x=(((r*t*10^-3)/(p)));//variable t1=1000;//initial temperature in degree cel...
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/* Author: Jeferson Souza (thejefecomp) - jeferson.souza@udesc.br Source: Project Euler - https://projecteuler.net/problem=122 Description The most naive way of computing n15 requires fourteen multiplications: n × n × ... × n = n^15 But using a "binary" method you can compute it in six multiplications: n × n = ...
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// this is 8 vehicle clc clear rokl=1 x=8 z=25 pop=20 iter=10000 cap=[288 95 115 133 107 22 34 28 186 190 33 56 100 90 82 143 68 166 44 73 72 60 68 8 20 ] tim=[0 12 6.2 5.6 27 17 20 29 44 18 16 23 24 34 11 9 11 11 13 17 14 30 25 28 27; 12 0 5.2 9.9 39 29 32 40 52 29 27 34 36 46 23 20 23 15 18 24 21 37 32 36 34; 6.2 5...
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// fonction de soustraction // chargement des images // for d'analyse de pixels, soustraction function img_out=soustraction(matriceA,matriceB) img_inA = matriceA; img_inB = matriceB; SizeXa = size(matriceA,"r"); SizeYa = size(matriceA,"c"); SizeXb = size(matriceB,"r"); SizeYb = ...
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printf "a\nA\n8\n 8" > foo;cat foo | node sort; rm foo 8 8 A a
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//Given that M = 1.00 //in kg T = 100 //in degree C P = 1.01*10^5 //in Pascal Vi = 1.00*10^-3 //in m^3 Vf = 1.671 //in m^3 Lv = 2256*10^3 //in J/kg //Sample Problem 19-5a printf("**Sample Problem 19-5a**\n") W = P*(Vf - Vi) printf("The work done by the system during the process is %fkJ\n", W*10^-3) //Sample Pro...
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// Chapter 4 Additional Example 9 //============================================================================== clc; clear; // input data l = 10^-10; // side of one dimensional box h = 6.625*10^-34 // plancks constant in Jsec m = 9.11*10^-31 // mass of electron in...
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//Representacao de sistemas lineares load('data2') A= [-k12-k10 k21 ; k12 -k21] B= [1; 0] C= [1 0] t= 0:1:length(u)-1 [sl]=syslin([],A, B, C) m1 = csim(u, t, sl) C1 = m1/V1 figure subplot(2, 1, 1) plot2d(t, C1) subplot(2, 1, 2) plot2d(t, u)
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clear; clc; Pdc=1; Pac=1; phi=acosd(.9428); mprintf(" power factor angle in degree is %.3f ",phi); p=[0.7:0.1:1]; Pd=(.9428/(p)); disp(Pd); disp(p); plot(p,Pd);
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clc //initialisation of variables ps1=0.010720 //bar pressure phi1=0.3 //relative humidity td1=8 //temp in degrees td2=32 //temp in degrees td3=30 //temp in degrees ps3=0.042415 //bar pressure phi3=0.5 //relative humidity hf=762.6 //kj/kg hfg=2013.6 //kj/kg p=1.01325 //pressure in bar //CALCULATIONS pv1=ph...
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JONES 12398888W HOWES 13543KDPG SANDS 16746TR6D QUINN 18888ERFM ZACKES18889FGJ2 ROLLS 18890WERP BLACK 29839FOGH ALPOS 34567MONJ WHITE 34688YUES HOFFS 47832NYCU
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//Chapter 25 clc //Example 5 //given d=8 //diameter of objective mirror of reflecting telescope in inches fo=1500 //focal length of objective mirror of reflecting telescope in mm fe=18 //focal length of eyepiece m=fo/fe disp(m,"Angular magnification of the telescope is")
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 14.7 //calculation of the density of the liquid //given data h=.02*10^-2//height(in m) of the column of liquid R=7.5*10^-3//radius(in m) of the soap bubble S=.03//surface tension(in N/m) of the soap solution g=9.8//...
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// Example 1.11. smallest change which can be measured by this transducer clc, clear // given : F=200; // range of force in N R=.15/100; // resolution of full scale Sc=R*F; disp(Sc,"smallest change,Sc = (N)")
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Min_slow,2,1,7 2,1,2 5,3,4,5,6,7 num_of_blk,1,mblif_num,0,Min_slow_Min,1e-12,Min_slow_leak,5e-12,Min_slow_ota,50e-9,Min_slow_buf,10e-6,fix_loc',[0;0;0] num_of_blk,mblif_num,Min_slow_Min,Min_slow_leak,Min_slow_ota,Min_slow_buf,fix_loc 4,1,16,1,19,1,22,1,25 1,0,0 Min_slow,1,1,2,1,5,1,1,1,2,1,3,0,Min_slow_ls,0,1,Min_slow_...
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//chapter12 //example12.18 //page254 V_CC=10 // V V_BE=0.2 // V I_E=2 // mA I_B=50d-3 // mA R_E=1 // kilo ohm R2=10 // kilo ohm V2=V_BE+I_E*R_E I2=V2/R2 I1=I2+I_B V1=V_CC-V2 R1=V1/I1 printf("R1 = %.3f kilo ohm \n",R1)
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//========================================================================== //BlockProto : generate prototype // of a scicos block // // //16/06/07 Author : A.Layec //Copyright INRIA // Modified for RT purposes by Roberto Bucher - RTAI Team // roberto.bucher@supsi.ch function [txt]=BlockProto(bk) nin=...
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A=[1,1,1,1,1,1;-1,1,0.5,-0.5,-0.5,0.5;0,0,sqrt(3)/2,-sqrt(3)/2,sqrt(3)/2,-sqrt(3)/2;1,-1,1,-1,-1,1]; B=[1/6,-1/3,0,1/6;1/6,1/3,0,-1/6;1/6,1/6,1/(2*sqrt(3)),1/6;1/6,-1/6,-1/(2*sqrt(3)),-1/6;1/6,-1/6,1/(2*sqrt(3)),-1/6;1/6,1/6,-1/(2*sqrt(3)),1/6]; // // Attitude (Z), Speed (Z) e Accel (Z) sono espresse in m, m/sec e m/s...
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//Ex19_9 Pg-960 clc disp("Conversion of decimal number 31.65 base to its binary equivalent ") a=31.65; z=modulo(a,1) x=floor(a);//separating the decimal from the integer part b=0; c=0; d=0; while(x>0) //taking integer part into a matrix and convert to equivalent binary y=modulo(x,2); b=b+(10^c)*y; x=x/2; x=floor(x); c...
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//Example 12.11 //Program to determine the average incident optical power required at //the receiver clear; clc ; close ; //Given data k=1.38*10^(-23); //J/K - BOLTZMANN's CONSTANT e=1.602*10^(-19); //Coulumbs - CHARGE OF AN ELECTRON SNR_dB=55; //dB - SIGNAL POWER TO RMS NOIS...
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function [Zo, A, b] = minimizacao(matriz_aumentada) dim = size(matriz_aumentada);// vetor que tem a qnt de linhas por qnt de colunas A = matriz_aumentada(:,1:dim(2)-1);// Matriz de coeficientes b = matriz_aumentada(:,dim(2));// vetor de resultados linha1 = A(1,2:dim(2)-1);// primeira linha da matr...
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// model wektorowy spadku swobodnego (bez oporu powietrza) function prawa_strona = F(t,Y) prawa_strona(1)= -Y(2) prawa_strona(2)= g-0.5*Cx*d*S/m*Y(2)^2 endfunction //g - przyspieszenie ziemskie //Cx - wspólczynnik aerodynamiczny sily oporu //ρ - gestosc powietrza //v - predkosc ciaaa wzgledem powietr...
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clear //Given Imax=16 Imin=4 //Calculation r=Imax/Imin //Result printf("\n Deduce the ratio of intensity is %0.3f :1", r)
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clear; //clc(); // Example 9.6 // Page: 225 printf("Example-9.6 Page no.-225\n\n"); //***Data***// P_1 = 10;//[atm] x_a_1 = 0.1238;// mole fraction of ethanol at 10 atm pressure Temp = 273.15+85.3;//[K] R = 0.08206;//[(L*atm)/(mol*K)] P_0 = 1;//[atm] // so delta_P = (P_1-P_0);//[atm] // Molecular wei...
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//To find velocities and loss of KE clc //Given: m1=50,m2=25 //kg u1=3,u2=1.5 //m/s //Solution: //When the impact is inelastic //Calculating the common velocity after impact v=(m1*u1+m2*u2)/(m1+m2) //m/s //Calculating the loss of kinetic energy during impact EL=m1*m2/(2*(m1+m2))*(u1-u2)^2 //N-m //When the im...
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function f=funcx(x) f=(1.5-x(1)+x(1)*x(2))^2+(2.25-x(1)+x(1)*x(2)^2)^2+(2.625-x(1)+x(1)*(x(2)^3))^2; endfunction function g=grad(x) g=[2*((1.5-x(1)+x(1)*x(2))*(-1+x(2))+(2.25-x(1)+x(1)*x(2)^2)*(-1+x(2)^2)+(2.625-x(1)+x(1)*(x(2)^3))*(-1+x(2)^3)),2*((1.5-x(1)+x(1)*x(2))*x(1)+(2.25-x(1)+x(1)*x(2)^2)*(2*x(1)*x(2))+(2...
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// find closed-loop input impedance // Electronic Principles // By Albert Malvino , David Bates // Seventh Edition // The McGraw-Hill Companies // Example 19-2, page 713 clear; clc; close; // Given data R1=10^2;// in ohms from the given figure Rf=3.9*10^3;// in ohms from the given figure Avol=10^5;// Avol...
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//Chapter 3 //Example 3.6 //ParallelCircuit //Page 63 clear;clc; //Example 3.6 //Given f = 60;//in Hz //From Table A.1 D_s = 0.0229 //in ft //Distances from given figure 3.15 d_a_c = 18;d_c_a = d_a_c;d_b_b = 21; d = 10;//distance between conductors d_a_b = sqrt(d^2 + (d_b_b - 19.5)^2); d_a_b1 = sqrt(d^2 + (d_b_b - 1...
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// i/p args b,a,n are passed to the function b=[1 2 3 5 6 7 9]; a=[2 3 4 5 7 8 9]; n=10; [phi,w] = phasez(b,a,n); disp(phi); disp(w); //output //!--error 117 //List element number 1 is Undefined. //at line 69 of function phasez called by : //[phi,w] = phasez(b,a,n); // //matlab o/p //phi = // // 0 // ...
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Ex2_4.sce
clear all; clc; funcprot(0); //given data AR = 1.8;//Area ratio cp = 0.6;//coefficient of pressure N_R1 = 7.85; //calculations Theta = 2*(180/%pi)*atan((AR^0.5 - 1)/(N_R1));//included cone angle cpi = 1-(1/(AR^2)); Diff_eff = cp/cpi;//diffuser efficeincy //Results printf('The included cone angle can b...
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clc //Example 17.1 //Tangential and separating force //------------------------------------------------------------------------------ //Given data //Torque Mt=200 //Nm //Dimensions of gears dp=0.1 //m (pinion) rp=dp/2 dg=0.25 //m (gear) rg=dg/2 //Pressure angle phi=20 //degrees res1=mopen(TMPDIR+'1_...
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function [t]=asin(x) //Syntax : [t]=asin(x) // //Sine-inverse of x //Entries of vector x must be in [-1,+1] //Entries of t are in ]-pi/2,pi/2[ x ]-inf,+inf[ // -pi/2 x [0,+inf] and pi/2 x ]-inf,0] (real x imag) // //! if type(x)<>1 then error(53),end [m,n]=size(x) if m<>n then t=-%i*log(%i*x+sqrt(o...
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//Example_a_5_13 page no:214 clc; Vm=15; Im=8.5; omega=200; R=Vm/(Im*sqrt(2)); C=1/(omega*R); disp(R,"the resistance in the circuit is (in ohm)"); disp(C,"the capacitance in the circuit is (in F)");
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//Example 8.23 clc disp("Internal structure of 7490 ripple counter IC is as shown in fig. 8.50") disp("") disp("We know that, one IC can work as mod-10 (BCD) counter. Therefore, we need two ICs. The counter will go through states 0-19 and should be reset on state 20. i.e.") disp(" QD QC QB QA QD ...
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exec('AllStagesNoteEnergies.sci', -1) exec('LoadAudioSample.sci', -1) exec('CalcNoteFiltersEnergies.sci', -1) exec('Calc3NoteToSignalRatios.sci', -1) exec('CoeffsToHz.sci', -1) exec('Convert2DIndexTo1D.sci', -1) exec('PrepAudioForProcessing.sci', -1) exec('CreateChord.sci', -1) exec('StageFilter.sci', -1) exec...
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function s=%spasp(a,b) // %spas - adds 2 sparse matrices (special cases) //! if size(a)==[1 1] then a=full(a) if a==0 then s=b, else s=full(b)+a end elseif size(b)==[1 1] then b=full(b) if b==0 then s=a else s=b+full(a) end end
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// A Textbook of Fluid Mecahnics and Hydraulic Machines - By R K Bansal // Chapter 3-Hydrostatic Forces on surfaces // Problem 3.1 //Data given in the Problenm w=2 d=3 dens=1000 g=9.81 //Calculations //Upper edge coincides with water surface A=w*d H=d/2 F=dens*g*A*H I_G=w*d^3/12 //MOI about ...
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getd('./functions'); xdel(winsid()); exec setCases.sci; // Prepare arrays for multiple asynchronous simulations state = zeros(30, 30); state(1:10,:) = 1; blockadeChances = [.4 .35 .3 .25 .2 .15 .1 .05 .02]; states = []; iterations = zeros(1, length(blockadeChances)); noChange = zeros(1, length(blockadeChances)); for ...
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//ques3 syms c1 c2 c3 disp('Cumulative function is given by E^3-2*E^2-5*E+6 =0 '); E=poly(0,'E'); f=E^3-2*E^2-5*E+6; r=roots(f); disp(r); disp('There for the complete solution is :'); un=c1*(r(1))^n+c2*(r(2))^n+c3*(r(3))^n; disp('un='); disp(un);
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ex16_5.sce
clc; clear all; r = 1.54e-8; // Resistivity of silver in ohm per meter E = 100; // Electric field along wire in v/m cc = 5.8e28; // Carrier concentration of electron per cubic meter e = 1.6e-19; // Charge of an electron u = 1/(r*cc*e);// Mobility of electron vd = u*E;// Drift velocity disp('m^2/(V.s)',u,'The m...
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clear; clc(); xdel(winsid()); //----------------------------------------------------------------------------// //Paramètres------------------------------------------------------------------// //----------------------------------------------------------------------------// m = 0.9; f0 = 30; w0 = 2*%pi*f0; K0 = 0.8; p =...
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clear // r=100 c=50*10**-6 f=50 v=230 //case a xc=-1/(314*c) //314 is omega ir=v/r //with angle 0 ic=230/(xc) //with angle of 90 deg i=((ir**2)+(ic**2))**0.5 printf("\n current with a lead of 57.5 is obtained as= %0.1f A",i)
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//CHAPTER 1- D.C. CIRCUIT ANALYSIS AND NETWORK THEOREMS //Example 16 disp("CHAPTER 1"); disp("EXAMPLE 16"); //VARIABLE INITIALIZATION v=7; //voltage source in Volts I=7; //current source in Amperes r1=1; //in Ohms r2=2; ...
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//chapter 4 Ex 19 clc; clear; close; Length=(7*12+9); //converting into inches Length_part=Length/3; Length_part_ft=Length_part/12; Length_part_in=modulo(Length_part,12); printf("The length of each part is %d ft %d inches",Length_part_ft,Length_part_in);
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clc; clear all; X=2*1e-3;//magnetic suseptibility of material at room temp. H=1e3;//magnetic field intrnsity of piece of ferricoxide u0=4*%pi*1e-7; M=X*H;//magnetization disp('A/m',M,'magnetization is='); ur=X+1;//relative permiability B=u0*ur*H;//magnetic flux density disp('W/m^2',B,'magnetic flux density is=...
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.264179D+00 ...
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-- Fuzzy Logix, LLC: Functional Testing Script for DB Lytix functions on Netezza -- -- Copyright (c): 2014 Fuzzy Logix, LLC -- -- NOTICE: All information contained herein is, and remains the property of Fuzzy Logix, LLC. -- The intellectual and technical concepts contained herein are proprietary to Fuzzy Logix, LLC. -...
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clc disp("Example 3.15") printf("\n") disp("Find the value of alpha & beta of transistor and Ib for desired Ic") printf("Given\n") Ic=1.2*10^-3 Ib=20*10^-6 //the value of beta beta=Ic/Ib //the value of alpha alpha=beta/(1+beta) //the value of Ib for desired value of Ic=5mA Ic1=5*10^-3 Ib1=Ic1/beta printf(...
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// Scilab Code Ex5.37: Page:315 (2011) clc;clear; // Function to convert degrees to deg-min function [d,m] = deg2degmin(deg) d = int(deg); m = (deg-d)*60; endfunction lambda = 7.62e-07;....// Wavelength of the polarized light, m mu_R = 1.53914; // Refractive index of quartz for right-handed circula...
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//Chapter-15, Example 15.17, Page 513 //============================================================================= clc clear //CALCULATIONS disp('((((A+C''))''(BD''))''.((A+C'').(BD''))'')''')//------>step 1 disp('((A+C'')+((BD'')'').((A+C)''+(BD'')''))''')//------>step 2 disp('((A+C'')+(BD'')'').((A+C'')''+(...
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V=100 R=10 L=2E-3 C=200E-6 w0=1/sqrt(L*C) Xl=w0*L*%i Xc=1/(w0*C*%i) I=V/R Vl=I*Xl Vc=I*Xc Vlc=Vl+Vc disp(Vlc,Vc,Vl,I,w0)
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.484529D+00 ...
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//a function to create histograms needed to compute dispersion scores //it also computates associate dispersion scores to videos //scores and histograms are stored in the given file //inputs : // - path : the path to the folder where data are // - filename : the file name containing are (csv format with ';' separati...
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function [u,v]=eq2(a,b) delta=a*a-4*b if delta>=0 u=0.5*(-a+sqrt(delta)) v=0.5*(-a-sqrt(delta)) disp('Real roots') else u=-a/2 v=sqrt(-delta) disp('Complex conjugate roots') end endfunction
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// poly([A],"x") -> Retorna el polinomio carcaterístico. // det(lambda*I - A) = p(lambda) Polinomio característico. // roots(p) -> Raices del polinomio. // spec(A) -> Autovalores de la matriz. function gerschgorin(A) n = size(A,1)//Cambie size(A,'r') para version 5.5.2 scilab for i = 1:n suma = 0 ...
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disp("The plane illustrated in Fig. 1-5 has intercepts at 2a, 4b and lc along the three crystal axes. Taking the reciprocals of these intercepts, we get 1/4, 1/2,and 1. These three fractions have the same relationship to each other as the integers 2,1, and 4 (obtained by multiplying each fraction by 4).Thus the plane c...
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// Ex5_8 clc; // Given: Q1=1.2; M1=14; m1=4; // Solution: E1=Q1*((m1+M1)/M1); printf("The threshold energy is %f in MeV for O(17) reaction",E1)
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clc(); clear; //To compare the intensities of ordinary & extraordinary light //IE=A^2(cos^2(teta));IO=A^2(sin^2(teta)) //I0/IE=tan^2(teta) teta=40; //angle made between incident beam & optic axis a=tand(40)^2 //I0/IE printf("I0/IE=%f",a);
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clc m=10; // kg M=80; // kg OG=0.8333; // m rho=1026; // kg/m^3 g=9.81; // m/s^2 d=1; // m W=(m+M)*g; // W(OG) = (W + F)(OB + BM) = rho*g*%pi/4*d^2*h1*(h1/2+d^2/(16*h1)) h1=sqrt(2*(W*OG/(rho*g*%pi/4*d^2) - d^2/16)); F=rho*g*%pi/4*d^2*h1 - W; disp("Least vertical downward force =") disp(F) disp("N")...
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//developed in windows 8 operating system 64bit //platform Scilab 5.4.1 //example 23_3w clc;clear; //Given Data p1=80; //Pressure of the gas in melting ice(Unit : cm) p2=160; //Pressure of the gas in a liquid (Unit : cm) t1=273.15; //Temperature of melting ice in (Unit : kelvin) // Calculation t2=(t1*...
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//Example 4_14 clc;funcprot(0); //Given data p_a=755;// mm of Hg V_c=8;// m/sec V_d=3;// m/sec T_a=20;// °C g=9.81;// m/s^2 //Calculation // The minimum value of p_c corresponds to the saturation pressure of water vapour at 20°C. //From steam table, p_c=17.6;// mm of Hg h_f=0.0;// m p_b=760;// mm of Hg ...
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clc //initialization of variables h0=191.81 //B/lb Pr0=5.526 w=1 //lb/sec Pratio=0.53 k=1.4 T0=800 //R cp=0.24 P0=150 //psia P2=15 //psia Pt=79.5; //calculations Prt=Pratio*Pr0 disp("From keenan and kaye steam tables,") Pr=2.929 Tts=668 //R hts=159.9 //B/lb Vts=sqrt(2*32.2*778*(h0-hts)) vts=53.34*Tts/(Pt*144) at=w*vts/...
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load FloatMultiplier16.hdl, output-file FloatMultiplier16.out, output-list x%X1.4.1 y%X1.4.1 out%X1.4.1; //both positive and mantissa product between 1.0 and 2.0 set x %X40a0, set y %X40c0, eval, output; //one positive one negative and mantissa product between 1.0 and 2.0 set x %X40c0, set y %Xc0a0, eval,...
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####### INITIATION ####### # Initiation of the scenario and the main PCL-file scenario = "CSpeech"; scenario_type = fMRI_emulation;# set to fMRI at the scanner! pcl_file = "CSpeech_Session1_MAIN.pcl"; pulse_code = 255; pulses_per_scan = 1; scan_period = 2000; write_codes = true; default_output_port = 1; # !!!!!!!!!!!...
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//Example6_40 // Design an instrumentation amplifier clc; clear; close; //A = 5 to 500 ; adjustable gain VR = 100*10^3 ; // the maximum differential gain of instrumentation amplifier is 500 //Amax = (R4/R3)*(1+(2R2/R1)); //by solving above equation we get following equation // 2R2 -249R1f = 0 ...