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// Scilab code Ex13.8: Pg 486 (2005) clc; clear; M_X = 226.025406; // Atomic mass of Ra-226, u M_Y = 222.017574; // Atomic mass of Rn-222, u M_alpha = 4.002603; // Mass of alpha particle, u Q = (M_X - M_Y - M_alpha)*931.494; // Q-value for Radium Decay, MeV/u printf("\nThe Q-value for Radium Decay = %4.2f Me...
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// Scilab code Ex17.11 : Pg:894 (2011) clc;clear; e = 1.6e-019; // Energy equivalent of 1 eV, J/eV N_A = 6.023e+026; // Avogadro's number, per kmol P = 2; // Power produced by the fission of U235, watt E_f = 200*1e+06*e; // Energy released per fission, J FR = P/E_f; // Fission rate of U235, fission...
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//=============================================================================================== // chapter 1 example 9 clc; clear; // Variable Declaration r = 0.175*10^-9; //radius in m h = 2; //miller indices k = 3; //miller ...
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A000008 sage 1 - x - x^2 + x^3 - x^5 + x^6 + x^7 - x^8 - x^10 + x^11 + x^12 - x^13 + x^15 - x^16 - x^17 + x^18 + 1 A000008 vect [1],[1,-1,-1,1,0,-1,1,1,-1,0,-1,1,1,-1,0,1,-1,-1,1] A000008 coef [1,1,2,2,3,4,5,6,7,8,11,12,15,16,19,22] A000012 sage 1 - x + 1 A000012 vect [1],[1,-1] A000012 coef [1,1,1,1,1,1,1,1,1,1...
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// Ex4_35 clc; // Given: t1=2.7;// h t2=3.6;// h // Solution: k1=0.693/t1; k2=.693/t2; tmax=(log(k2/k1))/(k2-k1); printf("The time when daughter activity reaches maximum is %f and this is same when activities of both are equal.",tmax)
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scenario = "WM fMRI expt"; #scenario_type = trials; scenario_type = fMRI; #scenario_type = fMRI_emulation; scan_period = 2000; pulses_per_scan = 1; pulse_code = 7; pcl_file="WMfmri.pcl"; active_buttons = 3; button_codes = 1, 2, 9; #left mouse button, right mouse button #write_codes=true; # use if sending codes ou...
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//Ex 3.3 clc;clear;close; G=-10;//Gain Ri=100;//kohm(input resistance) R1=Ri;//kohm R2=-G*R1;//kohm disp(R1,"Value of R1(kohm)"); disp(R2/1000,"Value of R2(Mohm)");
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Chapter6_example2.sce
clc clear //Input data n=181*10^-6//Coefficient of viscosity of a gas in p v=3*10^4//Average speed of molecules in cm/s d=1.2929*10^-3//Density in g/cm^3 //Calculations lemda=((3*n)/(d*v))/10^-6//Mean free path in cm*10^-6 //Output printf('Mean free path is %3.0f * 10^-6 cm',lemda)
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//Example 1.9://error clc; clear; close; v=95;//volts r=40;//ohms i=v/r;//amperes err=-0.2;//error in resistance err1=(err/r)*100;//percentage error evv=0.95;//error in voltage evv1=(evv/v)*100;//percentage error x=evv1-err1;// ei=(x/100)*i;// disp(i,"current in the circuit is,(A)=") disp(ei,"error in current is,(A)="...
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17_1.sce
//chapter 17 //example 17.1 //page 518 clear; clc ; //given //dc load line Vcc=13;//supply voltage R1=4.7;R2=3.7;RE=1; Rpy=40; N1=74;N2=14; Rl=56; //plot point A(Vce,Ic)=(Vcc,0) VB=Vcc*R2/(R1+R2); VE=VB; VBE=VB-0.7; IE=VE/RE; IC=IE; VCE=Vcc-IC*(Rpy+RE);//plot point Q(VCE,IC)=(8,5) VCE=[13,8]; IC=[...
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example13.sce
clc clear //input data b2=10//Rotor blade air angle at exit in degree Dt=0.6//The tip diameter in m Dh=0.3//The hub diameter in m N=960//The speed of the fan in rpm P=1//Power required by the fan in kW pi=0.245//The flow coefficient P1=1.02//The inlet pressure in bar T1=316//The inlet temperature in K R=287/...
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Ex9_7.sce
//EX9_7 PG-9.21 clc C=1000e-12; C1=C; C2=C; f=500e3; Ceq=(C1*C2)/(C1+C2); L=1/(4*%pi^2*f^2*Ceq);//since f=1/(2*%pi*sqrt(L*Ceq)); L=L*1e6; printf("\n Therefore L=%.3f micro H \n",L)
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4_12.sce
clear; clc; close; Re = 1.2*10^(3); Rc = 4.7*10^(3); Rb = 250*10^(3); Vcc = 10; Vbe = 0.7; Beta = 135; Ib = (Vcc - Vbe)/(Rb + (Beta)*(Re+Rc)); Icq = Beta*Ib; Vceq = Vcc - Icq*(Rc+Re); disp(Icq,'Value of Icq(Amperes) is : '); disp(Vceq,'Value of Vceq(Volts) : ');
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//Ex:46 clc; clear; close; p_ts=10*log(20)/log(10);//saturated transponder power in dbw b=2;//back_off in db p_b=p_ts-b;//power becomes with back_off in db p_B=floor(p_b); P_b=10^(p_B/10);//Power becomes with back_off n_c=P_b/1;//no. of channels n_cs=floor(n_c); printf("The max no. of VSAT channels=%f",n_cs)...
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Ex3_1.sce
clc; clear all; //chapter 3 //page no 75 //example 3.1 A=1 //arbitrary value provided T=10 //T represents tau (arbitrary value provided) //plot for non periodic pulse t=-2*T:.001:2*T; vt=[zeros(-2*T:.001:-T/2) A*ones(-T/2+.001:.001:T/2-.001) zeros(T/2:.001:2*T)] clf subplot(211) plot2d(t,vt,[2],rect=[...
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// Exa 5.4 clc; clear; close; // given data Ton=100;//in mSEC Toff=200;//in mSEC BETA=0.2;//unitless //Let R1=1 Kohm R1=1;//in Kohm R2=R1*(1-BETA)/BETA;//in Kohm // Assuming C=10 uF C=10;//in uF R3=Ton*10^-3/(C*10^-6*0.41);//in Kohm R4=Toff*10^-3/(C*10^-6*0.41);// in Kohm disp(R1,"Value of R1 in Kohm is...
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//Hougen O.A., Watson K.M., Ragatz R.A., 2004. Chemical process principles Part-1: Material and Energy Balances(II Edition). CBS Publishers & Distributors, New Delhi, pp 504 //Chapter-5, Illustration 9, Page 124 //Title: Estimation of dry bulb and wet bulb temperature //============================================...
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//Calculate current and power input //Chapter 3 //Example 3.13 //page 216 clear; clc; disp("Example 3.13") R1=0.21; //primary resistance in ohms X1=1; //primary reactance in ohms R2=2.72*10^(-4); //secondary resistance in ohms X2=1.3*10^(-3); ...
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// Prob 1.18 clc; clear; close; format('v',6); // Given data : Poles=2;//no. of poles m=3;//no. of phase f=50;//in Hz Ep=5700;//in volt Xs=1.5;//in ohm/phase Iphase=Ep/Xs;//in Ampere IL=Iphase;//in Ampere disp(IL,"Line current in Ampere : ");
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function x1 = metodoJacobi(A, x0, b, eps) [m, n] = size(A) x1 = zeros(n, 1) for i = 1:n suma = 0 for j = 1:n if j <> i then suma = suma + A(i, j)*x0(j) end end x1(i) = (b(i) - suma)/A(i,i) end while (norm(x0 - x1) > eps) ...
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//clear// clear; clc; //Example 21.2 //Given K = 273.16 T = 100+K ; //[K] P = 10; //[atm] //From Table 21.1 TcA = 198+K; //[K] TcB = -147+K; //[K] rho_cA = 0.552; //[g/cm^3] rho_cB = 0.311; //[g/cm^3] MA = 137.5; MB = 28; //Solution VcA = MA/rho_cA //[cm^3/g mol] VcB = MB/rho_cB //[cm^3/g mol] //S...
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clc; clear; Wb=0.5*10^-6 //width of base region in m Dp=15*10^-4 // in m^2/s //Calculation tau_n=Wb^2/(2*Dp) //in s tau_B=tau_n //in s fT=1/(2*%pi*tau_B) mprintf("a) upper frequency limit= %1.2e Hz",fT)
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clear ; clc; // Example 4.2 printf('Example 4.2\n\n'); // Page no. 93 // Solution // Given // Heat capacity = 139.1 + (1.56*10^-1)Tc J/(g mol* degree C), T is in degree C // First convert Tc (Temperature in degree celsius) to TR (in degree R) to get c + dTR, where c = 139.1 + (1.56*10^-1)*(-460-32)/1.8 ; ...
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//Exa 4.3 clc;clear;close; format('v',5); P=5;//MVA V=1000;//V speed=1500;//rpm//speed ns=speed/60;//rps f=50;//Hz pf=0.8;//Power factor Lagging Xs=20;//%//synchronous reluctance Xs=Xs/100;///p.u. disp("Part(a)"); V=1;//p.u.//on no load E=1;//p.u.//on no load Ps=V*E/Xs;//p.u. Ps=Ps*P;//MW per elect. radi...
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//pagenumber 288 example 5 clear av=12480; fedbac=8;//decibel volgai=20*log10(av);//gain without fedback volga1=volgai-fedbac; beta1=((av/5000)-1)/av; disp("voltage gain with fedback = "+string((volga1))+"decibel"); disp("beta = "+string((beta1)));
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//Example 10.15 m=50*10^-3;//Mass of the disc (kg) v=30;//Initial velocity of the disc (m/s) M=2;//Mass of the stick (kg) r=1.2;//Length of the stick (m) I_prime=(m+M/3)*r^2;//Moment of inertia of the stick and disc stuck together, See Equation 10.128 (kg.m^2) omega_prime=m*v*r/I_prime;//Angular velocity (rad/s) ...
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void main () { int i = 1 ; print ("i " , i , "\n"); }
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// Problema 2 function [x, ea, iter] = GaussSeidelR(A,b,lambda,es,maxit) //GaussSeidel: Gauss Seidel method //x = GaussSeidel(A,b): Gauss Seidel without relaxation //input: //A = coefficient matrix //b = right hand side vector //es = stop criterion (default = 0.00001%) //maxit = max iterations (default = 50) /...
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// convert into norton circuit // Electronic Principles // By Albert Malvino , David Bates // Seventh Edition // The McGraw-Hill Companies // Example 1-6, page 19 clear;clc; close; // Given data Vth=10;// Thevenin voltage in volts Rth=2000;// Thevenin resistance in ohms // Calculations In=Vth/Rth;// Norton current i...
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// Exa 2.25 format('v',7);clc;clear;close; // Given data Wrange= 500;//wattmeter range in W del_A= 1.5*Wrange/100;//limiting error at full scale in W P= 50;//power in W Pmin= P-del_A;// minimum power in W Pmax= P+del_A;// maximum power in W disp("The range of the reading is : "+string(Pmin)+" watts to "+string(...
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clc;clear; //Example 13.7 //calculation of uncertainty in position //1)given values h=6.626*10^-34;//Planck's constant in Js v1=220;//velocity of e in m/s m=9.1*10^-31;//mass of e in kg A=0.065/100;//accuracy //1)calculation v2=v1*A;//uncertainty in speed x1=h/(2*%pi*m*v2);// disp(x1,'uncertainty in ...
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7_3.sce
clc //Initialization of variables L=50 Fm=0.02 //N Vm=1 //m/s //calculations Fp=L^3 *Fm Fp=Fp*0.2248 Vp=sqrt(L) *Vm Vp=Vp*3.28 Hp=Fp*Vp/550 //results printf("Required horsepower = %.1f hp",Hp)
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function[] = realimentador(A, B, C, polos) U = zeros(length(polos), length(polos)); for i=1:length(polos), U(:,i) = (A^(i-1))*B; end printf("Matriz U/Wc ------------------------\n"); disp(U); if(rank(U) == size(U, 'r')) then printf("\nSistema é controlável\n"); ...
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// Scilab Code Ex3c.7: Page-185 (2008) clc; clear; D = 1.2; // Distance between the source and the slit, m d = 7.5e-004; // Separation between the two slits, cm n = 20; // Number of fringes crossed in the field of view bita = 1.888e-002/n; // Fringe width, cm lambda = bita*d/D; // Wavelength of ligh...
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//Example 2-16, page No-49 clear clc fr=28*10^6 Q=70 bandwidth = fr/Q printf('The bandwidth is %.3f Khz',bandwidth/10^3)
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clc; warning('off'); printf("\n\n example2.3 - pg30"); // given tauyx=-0.003; //[N/m^2] - momentum flux dely=0.1; //[m] - distance between two parralel plates mu=0.01; //[kg/m*sec] - viscosity // using the formula tauyx=F/A=-mu*(delUx/dely) delUx=-((tauyx*dely)/mu)*100; printf("\n\n Velocity of the top plat...
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//Chapter7,Pg7.4,Ex7.2 clc; Bdc=90 // Ic=15 //Collector current Ib=Ic/Bdc printf("\n Ib=%.2f uA \n",Ib*10^3) Ie=Ib+Ic printf("\n Emitter current Ie=%.2f mA \n",Ie) Adc=Bdc/(Bdc+1) printf("\n Adc=%.2f \n",Adc)
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clc clear //INPUT d=0.35;//diameter of the mirror in m t=5;//time in min T=16;//temperature of water found to be in deg.C m=60;//mass of water in gm mc=30;//mass of calorimeter in gm cp=0.1;//specific heat of copper in cal/gm/deg.C //CALCULATIONS q=(m+cp*mc)*T*4/(5*3.14*d^2);//amount of heat received by e...
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clc //initialisation of variables h1= 3892.2 //kJ/kg h2= 4102.2 //kJ/kg dh= 1015.4 //kJ/kg dh1= 448 //kJ/kg h3= 2151.1 //kJ/kg h4= 3081.1 //kJ/kg //RESULTS printf (' Specific Enthalpy= %.1f kJ/kg',h1) printf (' \n Specific Enthalpy= %.1f kJ/kg',h2) printf (' \n Specific Enthalpy= %.1f kJ/kg',h3) printf (' \...
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// Example1.3. A coil consists of 2000 turns of copper wire having a cross sectional area of 0.8 mm^2. The mean length per turn is 80 cm and resistivity of copper is 0.02 micro-ohm- metre. Find the resistance of the coil and power absorbed by the coil when connected across 110 V d.c. supply. //1 millimetre = 10^-3 me...
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//Chemical Engineering Thermodynamics //Chapter 13 //Thermodynamics in Phase Equilibria //Example 13.15 clear; clc; //Given T = [146.2 142.3 126.1 115.9 95.0 98.0 100];//Temperature in deg cel P1 = [760.0 685.0 450.3 313.0];//Vapour pressure of 1,1,2,2-tetrachloroethane at the coressponding temperature in m...
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// Implementation of example 7.2 // Basic and Applied Thermodynamics by P.K.Nag clc clear // T for temperature,m for mass,S for entropy,dS is change in entropy t1=273 // K t2=373 // K m=1 // kg c=4.187 // (a) dSw=m*c*log(t2/t1); // reservoir's temperature remains constant so dS=Q/T Q=m*c*(t2-t1); dSr=-...
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clc; v1=10; // voltage applied to primary when secondary is short circuited ip=60; // primary current when secondary is short circuited k=0.8; // turns ratio E1=250; // input voltage for load voltage has to be calculated E2=200; // rated voltage of secondary il=100; // load current pfo=0.24; // power factor duri...
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function [y,y1]=convol(h,x,y0) [lhs,rhs]=argn(0), n=prod(size(x)), m=prod(size(h)), m1=n+m-1; x(m1)=0;h(m1)=0; if norm(imag(x))==0&norm(imag(h))==0 then y=real(fft(fft(matrix(x,1,m1),-1).*fft(matrix(h,1,m1),-1),1)), else y=fft(fft(matrix(x,1,m1),-1).*fft(matrix(h,1,m1),-1),1), end i...
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// // "vib-res2.sce" // clear; clf(); load("vib_res.dat","om1","xxmax"); // vib-res.sce で保存したデータ m=1; c=0.2; k=1; P=1; zeta = c/( 2*sqrt(m*k) ); // 表3.1 omn = sqrt(k/m); // 表3.1 function y = K(Om) global zeta; y=1/sqrt((1-Om^2)^2 +(2*zeta*Om)^2); endfunction om2 = linspace(0.2,1.6,100); A = P/(m*omn^2); f...
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ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.309980D+00 2 -0.179830D-02 0.283944D-02 3 -0.898948D-04 -0.23799...
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function y =fa(x) y = -481 +408 +589.64 * x + (-2349.163 * x^2)/2 endfunction a = 0 b = 0.3 x= a contador = 0 while(1) xOld = x; x= (a+b)/2; Er = abs((x-xOld)/x) contador = contador + 1 if (Er < 10^-4) then break end if(fa(a)*fa(x) < 0) b= x ...
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clear all; clc; disp("Scilab Code Ex 13.12 : ") //Given: L = 1600; //mm K = 2; l = 80; //mm b = 40; //mm e = 20; //mm c = 40; //mm //Calculations: I1 = (1/12)*(l*b^3); A = l*b; r = sqrt(I1/A); sl_ratio = (K*L)/(r); //Eqn 13.26: sigma_allow = (378125)/(sl_ratio^2); I2 = (1/12)*(b*l^3); coeffic...
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load Larc.hdl, set RAM16K[0] %X8101, // 1. li R1 1 R1 <-- 1 set RAM16K[1] %X8202, // 2. li R2 2 R2 <-- 2 set RAM16K[2] %X9FFF, // 3. lui R15 -1 R15 <-- -256 set RAM16K[3] %X0312, // 4. add R3 R1 R2 R3 <-- 3 set RAM16K[4] %X141F, // 5. sub R4 R1 R15 ...
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// Example 7.6, page no-272 clear clc L=1.778 //Loss factor of the feeder 2.5dB equivalent ts=30 //Noise temperature of sattelite receiver in K t=50 //Noise temperature in K ti=290 // reference temperature in K x=t/L y=ti*(L-1)/L Te=x+y+ts F1=1+(ts/ti) F2=1+(Te...
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 13.3w //calculation of the height of the water coloumn //given data h1=2*10^-2//difference in the height(in m) s=13.6//specific gravity of mercury //calculation //P = P0 + (h*rho*g)........using this equation h=h...
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errcatch(-1,"stop");mode(2);//Example 4.16 (b) //Program to Evaluate and Compare the 8-point DFT of the given Sequence //x2[n]=1, 0<=n<=6 using DIT-FFT Algorithm. ; ; ; x2=[1,1,1,1,1,1,1,0]; //FFT Computation X2 = fft (x2 , -1); disp(X2,'X2(k) = '); exit();
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clear ; clc; // Example 10.6 printf('Example 10.6\n\n'); // Page no. 281 // Solution // Basis: P=100 // Product from the reactor-[g mol] P=100 ;//Product from the reactor-[g mol] // Composition of product C3H8 = 0.195*P ;// [g mol] C4H10 = 0.594*P ;// [g mol] C5H12 = 0.211*P;// [g mol] n_un = 3 ;// Number of unknowns...
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clc(); clear; // To calculate the relaxation time of conduction electrons rho=1.54*10^-8; //resistivity in ohm-m n=5.8*10^28; //electron/m^3 m=9.108*10^-31; //mass in kg e=1.602*10^-19; //charge in coulomb tow=m/(n*(e^2)*rho); printf("relaxation time of conduction electrons in sec is"); disp(tow);
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//debug clc; V1=420; //supply voltage r1=2.95; x1=6.82; r2=2.08; x2=4.11; Iml=6.7; //magnetizing line current Pw=269; //core loss s=0.03; //slip P=12; f=50; N=(120*f)/P; Ns=(120*f)/P; Im=Iml/sqrt(3); //V1=E1+Im(r1+jx1) //Above equation on solving gives the solution as E1*E1+52.8E1-175572.65 Q=[1 52.8...
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// Calculating the amount of oil and amount of water clc; disp('Example 4.25, Page No. = 4.51') // Given Data MVA = 40;// MVA rating of transformer Q = 200;// Total losses (in kW) Q_oil = 0.8*Q;// Since 20% of losses are dissipated by tank walls Heat taken up by oil (in kW) // Calculation of the amount of oil ...
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//All the quantities are expressed in SI units M = 2.79; //Mach number T = 320; //static temperature from ex. 7.3 p = 1; //static pressure in atm gam = 1.4; //from eq. (8.40) T0 = T*(1+((gam-1)/2*M*M)); //from eq. (8.42) p0 = p*((1+((gam-1)/2*M*M))^(gam/(gam-1))); printf("\nRES...
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clc clear //input c=4*(10^-6);//capacitance of a capacitor by which a resistive-inductive load is shunted in farad v=2;//supply voltage in volts f=5000;//supply frequency in hertz q=10;//Q factor of the circuit //calculations vwc=2*2*%pi*f*c;//capacitor current in amperes it=vwc/q;//total current in amper...
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//program to solve differential equation using euler's method function []=euler(x0,y0,xn,h) deff('y1=f(x,y)','y1=(y-x)/(y+x)') y1=y0+(h)*f(x0,y0) x0=x0+h y0=y1 while x0<xn y1=y0+(h)*f(x0,y0) x0=x0+h y0=y1 end disp(y1) endfunction
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//Chapter 12 : Solutions to the Exercises //Scilab 6.0.1 //Windows 10 clear; clc; //Solution for 1.18 A=[0 1;0 1] B=[-1 -1;0 0] AB=A*B disp(AB,'AB=') A2=A^2 disp(A2,'A^2=') B2=B^2 disp(B2,'B^2=') AB2=(A+B)^2 disp(AB2,'(A+B)^2=') e1=A2+2*AB+B2 disp(e1,'A2+2*AB+B2=') e2=(A+B)*((A+B)^2) disp(e2,'(A+...
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clc; m=30; // mass flow rate in kg/s N=15000; // Speed in rpm r2=0.3; // Radius in m D2=r2*2; // Diameter in m w2=100; // Relative velocity in m/s beta_1=80; // in degrees p01=1; // Inlet pressure in bar T01=300 // Inlet temperature in kelvin Cp=1.005; // specific heat at constant pressure in kJ/kg K r=1.4; /...
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clc //initialisation of variables Dp= 1 //in Dr= 10 //in R= 12 W= 15 //tons //CALCULATIONS Ar= %pi*Dr^2/4 Ap= %pi*Dp^2/4 P= W*2240/((Ar/Ap)*R) //RESULTS printf ('power applied to lever = %.f lbs',P)
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// 6.5 clc; R=10*10^3; Ri=100*10^3; Rt=100*10^3; Rp=(Ri*R)/(Ri+R); Attenuation=Rp/Rt; Attenuation_factor=1/Attenuation; printf("\nAttenuation factor=%.1f ",Attenuation_factor)
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clc //to calculate strength of solution theta=11 //degree l=20 //length in cm alpha=66 //specific rotation of sugar in degree c=10*theta/(l*alpha) disp("strength of solution is c="+string(c)+"gm/cm^3")
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errcatch(-1,"stop");mode(2);//Chapter 8, Problem 7 ; Q=1.6*10^-19; //charge in coulombs v=3*10^7; //velocity of charge B=18.5*10^-6; //flux density F=Q*v*B; //Calculating force printf("Force = %f x10^−17 N",F*10^17); exit();
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//Exam:3.27 clc; clear; close; //Miller indices of plane h=1; k=1; l=1; wavelength=0.54;//in angstrom a=3.57;//size of a cube n=1; d_111=a/(h^2+k^2+l^2)^(1/2);//interplanar spacing(in Angstrom) angle=asind(n*wavelength/(2*d_111)); disp(angle,'Bragg angle(in degree)=');
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//Example 1.7 clc; clear; close; t =0:0.01:10 F=1000; x=sin(2*%pi*F*t); P={integrate('(sin(2*180*F*t)^2)','t',-0.001,+0.001)}/(2*1/F); disp(P,"Power of signal= "); disp("Since the given signal has a finite power, it is a POWER signal");
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//Scilab Code for Example 1.7 of Signals and systems by //P.Ramakrishna Rao clear; clc; n=1; for t=-10:0.1:10; //Function for Even signal y1(n)=0.5*(exp(-t)*u(t)+exp(t)*u(-t)); n=n+1; end a=gca(); a.x_location="origin"; a.y_location="origin"; t=-10:0.1:10; //Plot of Even Signal plot(t,y1); t...
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//Example 2.6 //Integration //Page no. 36 clc;clear;close; disp(integrate('1/x','x',exp(-4),1),'Integration Value='); //performing integration with respect to dx
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//Example 13_4 clc;clear; // Given values S_0=0.003;// Bottom slope n_1=0.030; n_2=0.050; // Calculation s=sqrt(3^2+3^2); //Then the flow area, perimeter, and hydraulic radius for each subsection and the entire channel become // Subsection 1: A_c1=21;// m^2 p_1=10.486; // m R_h1=A_c1/p_1;// m // Subsect...
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function [out]=grayconnected(input1,input2,input3,varargin) inputn=mattolist(input1); [lhs rhs] = argn(0) if rhs>4 then error(msprintf("Too many input arguments")) elseif rhs==4 then a=opencv_grayconnected(inputn,input2,input3,varargin(1)); dimension=...
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//i/p arg x is a vector x=[1 2 3 4 5 7 89 8]; fc=100; fs=500; y = modulate(x,fc,fs,'pwm'); disp(y); //output //!--error 10000 //x must lie between 0 and 1 //at line 115 of function modulate called by : //y = modulate(x,fc,fs,'pwm');
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clc; //e.g 27.15 hfe=100; hie=2*10**3; Rc=470; Re1=100; Re2=100; R1=15000; R2=5600; AV=(hfe*Rc)/hie; disp(AV); a=((R1*R2)/(R1+R2)); Ri=(a*hie)/(a+hie); disp('ohm',Ri*1,"Ri="); b=Re1/Rc; AV1=AV/(1+b*AV); disp(AV1); Ri1=Ri*(1+b*AV); disp('OHM',Ri1*1,"Ri1=");
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//Calculating additional resistance required //Chapter 4 //Example 4.23 //page 320 clear; clc; disp("Example 4.23") // we know (Ts/Tm)=((2*a)/(1+a^2)) //where a=(R2/X20) //at starting contion since Tm=Ts disp("At starting contion since Tm=Ts") a=1 //we obtain from the relations R2=0.05; ...
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syms m11 m12 m13 m21 m22 m23 m31 m32 m33 ^ s=%s; poly(0,"l"); A=[0 1 0;3 0 2;-12 -7 -6] [r c]=size(A) I=eye(r,c); p=l*I-A; q=det(p); // determinant of li-p // roots of q are l1=-1; l2=-2; l3=-3; x1=[m11;m21;m31]; q1=(l1*I-A)*1 // on solving we find m11=1 m21=-1 31=-1 m11=1;m21=-1;m31=-1; x2=[m12;m22;m32...
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function [m,n,nx]=g_size(x,flag) // only to be called by size function for dynamical systems //! [lhs,rhs]=argn(0) x1=x(1); if x1(1)=='r' then if lhs==1 then if rhs==1 then m=size(x(2)); else m=size(x(2),flag); end elseif lhs==2 then if rhs<>1 then error(41),end [m,n]=size(x(2)); ...
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//example 7 //Second-Law Analysis of an Ideal Rankine Cycle clear clc xdest12=0 //irreversibility during the process 1 to 2 in kJ/kg xdest34=0 //irreversibility during the process 3 to 4 in kJ/kg s2=1.2132 //specific entropy for state 2 in kJ/kg-K s4=6.7450 //specific entropy for state 4 in kJ/kg-K s1=s2 //sp...
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// chapter 10 , Example10 2 , pg 290 Er=1.0024 //Dielectric constant N=2.7*10^25 //(in atoms/m^3) E0=8.85*10^-12 //permittivity of free space (in F/m) Alpha_e=(E0*(Er-1))/N //electronic polarization printf("Electronic polarization (in F*m^2)\n") disp(Alpha_e)
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//Example 2_7 clc(); clear; //To Calculate highest power of spectrum seen with mono chromaic light lamda=6000 //units in armstrongs lamda=lamda*10^-8 //units in cm n=5000 e=1/n //units in cm k=e/lamda printf("The highest order spectrum Seen with monochromatic light is %.2f",k)
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clear;lines(0); plot2d([0;1],[0;1],0) xstring(0.5,0.5,["Scilab" "is"; "not" "esilaB"]) //Other example alphabet=["a" "b" "c" "d" "e" "f" "g" .. "h" "i" "j" "k" "l" "m" "n" .. "o" "p" "q" "r" "s" "t" "u" .. "v" "w" "x" "y" "z"]; xbasc() plot2d([0;1],[0;2],0) xstring(0.1,1.8,alphabet) //...
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//Determine the moment //Refer fig. 3.5 //Take clockwise moment as positive //Apply Varignon's Theorem MA=100*300*cosd(60)-100*500*sind(60) //N-mm printf("MA=%f N-mm,Anticlockwise",-MA)
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clc;funcprot(0);//Example 2.1 //Initilisation of Variables T1=1300;.........//outermost tempatarure of composite wall in degrees celcius T3=115;.........//outermost tempatarure of composite wall in degrees celcius L1=500;.........//thickness of first slab in mm L2=161;.........//thickness of second slab in mm K1=...
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clc,clear printf('Example 5.10\n\n') VA=125*10^3 V_L=400,V_ph=V_L/sqrt(3) I_L=VA/(sqrt(3)*V_L) I_aph=I_L I_f=4,I_asc=I_aph/2 //for half load.. refer to graph V_OC_line=140 V_OC_ph=V_OC_line/sqrt(3) I_asc_ph=I_asc Z_s= V_OC_ph/I_asc_ph R_a=0.1,X_s=sqrt(Z_s^2-R_a^2) //armature resistance and synchronous re...
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function XcosDesSet() global bOK; bOK = %f; screen_area = get(0, "screensize_px") XcosDesUI_wight = 540; XcosDesUI_high = 465; XcosDesUI_x = (screen_area(3)-XcosDesUI_wight)/2; XcosDesUI_y = (screen_area(4)-XcosDesUI_high)/2; //R = 255;G = 233; B = 220; R = 28;G = 120; B = 135; ...
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function [txt,ilst,vnms,vtps,lcount]=cod2sci(lst,ilst,vnms,vtps) // //! // Copyright INRIA nlst=size(lst) txt=[] ilst=ilst-1 while ilst<nlst then ilst=ilst+1 op=lst(ilst) if type(op)==15 then return,end select op(1) case '1' then //stackp // write(6,'stackp '+op(2)); prev=lst(ilst-1) if size(prev,'...
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function [stk,txt,top]=sci_islogical() // Copyright INRIA txt=[] stk=list('or(type('+stk(top)(1)+'==[4,6])','0','1','1','4')
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function s=%s_s_sp(a,b) // %s_s_sp - substract a sparse matrix b to a scalar matrix a //! // Copyright INRIA if size(a)==[-1,-1] then //eye+b [m,n]=size(b) s=(0+a)*speye(m,n)-b else s=a-full(b) end
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% Entering a vector and displaying it x = [1 2 3 4]; y = 10 + x;
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function [s_alp,s_cux,s_cuy,s_cuz,... s_uxx,s_uxy,s_uxz,s_uyy,s_uyz,s_uzz,... s_qxx,s_qxy,s_qxz,s_qyy,s_qyz,s_qzz... ]=sources_parts(... nx,ny,nz,... x,y,z,r,psi,... alp,cux,cuy,cuz,rg,... uxx,uxy,uxz,uyy,uyz,uzz,... gxx,gxy,gxz,gyy,gyz,gzz,... ...
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v1=10; fsd1=0.03; v2=5; i1=50*10^(-6); r1=20*10^3; fsd2=0.02; i2=10*10^(-6); disp("Part a"); r=v2/i2-r1; disp("The resistance (in kΩ) is"); disp(r/1000); disp("Part b"); e1=fsd1*v1*100/v2; e2=fsd2*i1*100/i2; e=e1+e2; disp("The maximum possible error is"); disp(e);
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clc // // // //Variable declaration n=2 //order of spectral line theta=30 //Angular Width invde=5000 //Inverse of diffraction element //Calculations thetarad=(%pi/180)*(theta) sinetheta=sin(thetarad) lambdaa=((sinetheta)/(n*invde))*10**8 //Result printf("\n The Wavelength is %i...
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clc //initialisation of variables No= 0.979889 v= 2989.74 //cm^-1 rc= 1.2746 //A T= 25 //C E1= 6.8635 //cal deg^-1 mole^-1 E2= 11.4392 //cal deg^-1 mole^-1 E3= 7.2820 //cal deg^-1 mole^-1 E4= 4.5757 //cal deg^-1 mole^-1 E5= 2.7676 //cal deg^-1 mole^-1 r1= 0.265 //A r= 35.99 //A //CALCULATIONS Et= E1*log...
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// Exa 5.12 clc; clear; close; // Given data f=2.5;// in kHz f=f*10^3;// in Hz // Part (i) when t=0.1;// in sec count= f*t; disp(count,"When GATE ENABLE time is 0.1 sec then the counter will count or display") // Part (ii) when t=1;// in sec count= f*t; disp(count,"When GATE ENABLE time is 1 sec then the ...
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clear; clc; //Example1.5 (The cost of Heat loss through a Roof) //(a) k=0.8;//The thermal conductivity of the roof[W/m.degree.C] A=6*8;//Area of the roof[m^2] t1=15;//temperature of inner surface roof[degree C] t2=4;//temperature of outer surface roof[degree C] L=0.25;//thickness of roof[m] Q_=k*A*(t1-t2)/...
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// Example 4.6 page no-207 clear clc vbb=-1 //V Rb=50 //K-Ohm vbe=-0.1 Icbo=(vbe-vbb)/Rb printf("\nIcbo =%.0f micro A",Icbo*1000) t=log(Icbo*1000/2)*10/(log(2)) printf("\nDelta_T = %d°C \nHence, T=%d°C",ceil(t),ceil(t)+25)
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clc; pathname=get_absolute_file_path('3_12_soln.sce') filename=pathname+filesep()+'3_12_data.sci' exec(filename) // Solution: // Acceleration due to gravity, g=32.2; //ft/s^2 // Jet velocity through siphon, v2=sqrt(2*g*(h-Hl)); //ft/s // rounding off the above answer v2=fix(v2)+(fix(floor((v2-fix(v2))*10))/10); //ft/s...
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