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//example 2.1.d //check the signal is periodic or not clc ; t =-15:0.01:15; y =3*(cos((5*t)+(%pi/6))); plot(t,y); disp ( 'Plot shows that given signal is periodic with periodicity=2%pi/5' ) ;
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clc //Chapter 1 //Ex1.12, page no 43 //Given mprintf('The given function is:\n sgn(t)=1 (for t>0\n =-1 (for t<0)\n')// displaying the given function disp('sgn(t)=2u(t)-1') disp('the fourier transform can be given as:'),disp(' F[sgn[(t)]= 2/j*w')// displaying the fourier Transform of the given function
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my title queerer than we can suppose the strangeness of science queerer than we can suppose comes from j b s haldane the famous biologist who said now my own suspicion is that the universe is not only queerer than we suppose but queerer than we can suppose i suspect that there are more things in heaven and earth than a...
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//Example 8.31 clc disp("The fig. 8.63 shows the cascaded connection of 4-bit binary counters. Let us see the circuit operation. The counter IC1 operates as a counter for countion in the UP direction since CLEAR = LOAD = 1. When the count reaches the maximum value (1111) its RC (Ripple Carry Output) goes HIGH which m...
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/* Etideur: Jinshan GUO Objectif: Fonction à resoudre le problème de Ux=y Containtes: U est une matrice carrée triangulaire supérieur y est un vecteur colonne Valeur retour: x */ function [x]=slosup(U,y) nb_lignes = size(U)(1); //Nombre lignes de matrice for i=nb_lignes:-1:1 ...
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// Determine current through various values of RL clc; clear; Rl=[0 2 5]; // Resistance Vector //Resistances of the circuit in order from the 40V side. R1=4; R2=6; R3=5; //Voltage Source V=40; i=V/(R1+R2); Vth=i*R2; Rth=R3+(R1*R2/(R1+R2)); Cur=(Rth+Rl)/Vth; // Reciprocal of current print...
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//to find the rate of stiffness of the spring and the equilibrium speed clc //given w=3//lb g=32.2 N2=300 w2=(N2*%pi/30) r2=3/12//ft N1=1.06*N2 r1=4.5/12//ft a=4//in b=2//in ro=3.5/12//ft F2=w*w2^2*r2/g F1=F2*N1^2*r1/(N2^2*r2) p=2*a^2*(F1-F2)/(b^2*(r1-r2)) Fc=F2+(F1-F2)*(.5/1.5) N=(Fc*g/(ro*w))^(1/2)*3...
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//example 15.5 clc; disp('Assuming the counter began at 0000, the display would read 200 at the end of the first measurment period.It will read 400,then 600 and so on at the end of succeeding periods. This is because the counter capacity is exceeded each time, and it simply recycles through 0000.');
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// sum 28-1 clc; clear; Z1=1; Z2=30; q=10; m=5; d=q*m; D=m*Z2; //let the speed reduction ratio be G G=Z2/Z1; CD=(d+D)/2; // printing data in scilab o/p window printf("G is %0.0f ",G); printf("\n CD is %0.0f mm ",CD); printf("\n d is %0.0f mm ",d); printf("\n D is %0.0f mm ",D);
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S11=0.75*exp(-%i*120*%pi/180) S22=0.6*exp(-%i*70*%pi/180) S21=2.5*exp(%i*80*%pi/180) function x=mod(n) r=real(n) i=imag(n) x=sqrt(r^2+i^2) endfunction GSmax=1/(1-mod(S11)^2) GLmax=1/(1-mod(S22)^2) Go=mod(S21)^2 disp(GSmax,"GSmax=") disp(10*log10(GSmax),"GSmax in dB=") disp(GLmax,"GLmax=") di...
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// To find the voltage at the load end of the transformer when load is drawing transformer current clc; I=20/2; //rated load current(hv side) Z1=[.25,1.4]; //impedence of feeder (REAL,IMAGINERY) Z2=[.82,1.02]; //impedence of transformer (REAL,IMAGI...
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clc clear //input data Cj=2700 //average effective jet velocity in m/s u=1350 //forward flight velocity in m/s mp=78.6 //propellant mass flow in kg/s //calculation s=u/Cj //effective jet speed ratio np=(2*s)/(1+s^2) //propulsive efficiency F=Cj*mp*10^-3 //thrust in kN Pt=F*u*10^-3 //Thrust power in MW, F...
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@relation vehicle @attribute COMPACTNESS integer[73,119] @attribute CIRCULARITY integer[33,59] @attribute DISTANCECIRCULARITY integer[40,112] @attribute RADIUSRATIO integer[104,333] @attribute PRAXISASPECTRATIO integer[47,138] @attribute MAXLENGTHASPECTRATIO integer[2,55] @attribute SCATTERRATIO integer[112,265] @attr...
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//Written by Maitreyee Mordekar, FOSSEE, IIT Bombay. x=[1:12]; disp(x, "The input is ") y=matintrlv(x,3,4); disp(y, "The interleaved output is ")
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load MHalfAdder.hdl, output-file MHalfAdder.out, output-list a b sum carry; set a 0, set b 0, eval, output; set a 0, set b 1, eval, output; set a 1, set b 0, eval, output; set a 1, set b 1, eval, output;
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clc(); clear; // To compute the hydrogen loss per unit pipe by diffusion ri=3/96; // Inner radius of pipe in ft ro=1/24; // Outer radius of pipe in ft Ca1=0.0003; // Concentration at the inner hose of pipe in lb-mol/ft^2 Ca2=0; ...
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// Electric Machinery and Transformers // Irving L kosow // Prentice Hall of India // 2nd editiom // Chapter 14: TRANSFORMERS // Example 14-22 clear; clc; close; // Clear the work space and console. // Given data V_1 = 2300 ; // Primary voltage in volt V_2 = 230 ; // Secondary voltage in volt P = 20 ; ...
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//chapter 2 Ex 12 clc; clear; close; l1=1657; l2=2037; r1=6; r2=5; //given values V=int32([(l1-r1) (l2-r2)]); Hcf=gcd(V); mprintf("The required number is %d",Hcf);
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//variable initialization a=0.51 //Value of m0*c^2 (Mev) //Calculation of kinetic energy of electron T=a*(sqrt(2)-1); //Kinetic energy (MeV) printf("\n Kinetic energy of electr...
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clc //Initialization of variables T=-150+460 //R v=0.6 //ft^3/lbm vc=1.44 Tc=227 //R Pc=482 //psia //calculations disp("From tables of z") vr=v/vc Tr=T/Tc Pr=1.75 P=Pr*Pc //results printf("Final pressure = %d psia",P)
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clc clear printf("Example 8.8 | Page number 222 \n\n"); //This is a theoritical question.Refer textbook for solution printf("This is a theoritical question.Refer textbook for solution")
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// Exa 11.2 clc; clear; close; format('v',5) // Given data Av= 29; I_Bmax = 0.5*10^-6;// in A I1= 100*I_Bmax Vo_sat = 0.9;// in V V_CC = 9.0;// in V V_EE= -9;// in V V1= 9/Av;// in V R1= V1/I1;// in ohm R1= 5.6*10^3;// in ohm (standard value) Rf= Av*R1;// in ohm Rf= 180*10^3;// in ohm R3= Rf;// in ohm ...
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dispost V;PST enlay V.PTCP;PST prefixe V.PTCP;PRS beclap V;NFIN circumference V;NFIN hopple V;PST overthrow V;NFIN FOIL V.PTCP;PRS hyperextend V.PTCP;PRS vent V;SG;3;PRS ensheathe V.PTCP;PRS poetise V;SG;3;PRS gentrify V.PTCP;PST theatricalize V;NFIN abastardize V.PTCP;PST hard-boil V;NFIN behope V;PST ...
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// ----------------------------------------------------------------------------- // QUELQUES MATRICES UTILES DANS LES CALCULS // ----------------------------------------------------------------------------- // vecteurs pour construire des matrices one = ones(M,1); // vecteur colonne à M lignes qui ne contient que de...
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// Example 1.4 // Current and power calculation with help of i-v curve i=5; // i-v curve of Headlight and battery intersects at a point where i=5A v=12; //i-v curve of headlight and battery intersects at a point where v=12V p=v*i;//Power comsumed by the Headlight disp(p,"Power consumed by the Headlight (in Watt)="...
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errcatch(-1,"stop");mode(2);//caption:find frequency time period of the system //Ex7.22 n=30//reading of digital frequency counter F=10^6//gate time period(in second) T=1/F t=n*T disp(t,'frequency time period of the system(in second)=') exit();
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// //given BB_AB=330+(15/60) BB_BC=200+(30/60) BB_CD=115+(45/60) BB_DE=38+(0/60) BB_EA=300+(30/60) //calculations exteriorA=BB_EA-(150+(15/60)) interiorA=360-exteriorA exteriorB=BB_AB-(20+(30/60)) interiorB=360-exteriorB interiorC=(295+(45/60))-BB_BC interiorD=218-BB_CD interiorE=(120.5)-BB_DE //convert into mins ...
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//Section-14,Example-5,Page no.-PC.114 //To calculate the pH of a solution obtained in the given condition. clc; M_1=0.1 M_2=0.2 V_1=10 V_2=40 V=V_1+V_2 m_eq=(M_1*V_1)+(M_2*V_2*2) //mgm. equivalents of [H3O+] C_1=m_eq/V //[H3O+] pH=-log10(C_1) disp(pH,'pH of the given solution')
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// Scilab Code Ex3.18:: Page-3.30 (2009) clc; clear; a = 0.019e-003; // Width of each slit, m b = 2.0e-004; // Width of opacity between two slits, m lambda = 5000e-010; // Wavelengh of light used, m D = 0.6; // Distance between slit and the screen, m // As angular separation, theta = x/D = lambda...
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//example 8.7(a)// clc //clears the screen// clear //clears all variables// close //closes all existing files// disp('A positive edge triggered D flip flop, as shown in figure can be used for the purpose. Waveform A is applied to the D input and waveform B is applied to the clock input. If we examine the two wav...
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clear; clc; //Caption:To find parameters of Current series Fwwdback Amplifier //Given Data Gmf=-1;//Transconductance in mA/V D=50;//Desensivity Avf=-4;//Voltage Gain Rs=1;//in K hfe=150; Vt=0.026;//in V Gm=Gmf*D; disp('mA/V',Gm,'Gm='); //B=-Re, D = 1+B*Gm = 1-B*Gm Re=(1-D)/Gm;//in K disp('K',Re,'Re=...
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// Exa 1.34 clc; clear; close; format('v',6) // Given data D = 0.102;// in cm A = (%pi*(D^2))/4;// in cm^2 sigma_p = 0.286;// in (ohm-cm)^-1 q = 1.6*10^-19;// in C miu_p = 500; // Formula used, sigma_p = q*miu_p*N_A; N_A = sigma_p/(q*miu_p);// in atoms/cm^3 V1 = 5;// in V V2 = 0.35;// in V Vb = V1+V2;//...
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function string = conVecToStr(vector) string = "" for i = 1:1:size(vector, 1) string = string + vector(i, 1) end endfunction function i = ibin2dec(istring) to = 1; if part(istring,1)=='.' then to = 2; end i = 0; for si = length(istring):-1:to i = (i+strtod(part(istring,si)))/2 ...
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clear clc //Example 13.5 MASS FLOW RATE OF NATURAL GAS d0=0.07; //[m] d1=0.1; //[m] A0=%pi*d0^2/4 //area[m^2] A1=%pi*d1^2/4 //area[m^2] rho=0.678; //density of methane[kg/m^3] k=1.31; v=1.59*10^-5; //[m^2/s] p1=101000; //pressure[Pa] delp=10000; //difference in pressure[Pa] p2=p1-delp //[Pa] ReK=(d0/v)*sqr...
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//fiber optic communications by joseph c. palais //example 11.8 //given //OS=Windows XP sp3 //Scilab version 5.4.1 clc clear all //given TA=300//Ambient temperature in Kelvin T=454//noise temperature in Kelvin //to find F=1+(T/TA)//Noise figure Fdb=10*log10(F)//Noise figure in dB mprintf("Noise figure =%f ...
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// Question 5 function []=test_call_girsanov(S_0,K,sigma,r,T, lambda,NumberOfDrawings) W_T = sqrt(T)*rand(1,NumberOfDrawings,"gauss"); S_T = S_0*exp((r-sigma^2/2)*T + sigma*(W_T+lambda* T)); payoff = exp(-r*T) * call(S_T,K); importance = exp(-lambda * W_T - ((lambda^2*T) /2.0)); payoff = importance .* payoff;...
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//Example 10-9 Laminar or Turbulent Boundary Layer? V = 10 //velocity of water over the fin [km/h] T = 5 //temperature of water [C] c = 0.5 //chord length of the fin [m] rho_water = 999.9 //density of water at 5 C [kg/m^3] mu = 1.519 * 10**-3 //viscosity of water at 5 C [kg/m.s] Re_cr = 5 * 10**5 //critical Reynolds nu...
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// Test # 1 : No Input Arguments exec('./allpasslp2bsc.sci',-1); [n,d]=allpasslp2bsc(); //!--error 10000 //Number of input arguments should be 2 //at line 28 of function allpasslp2bsc called by : //[n,d]=allpasslp2bsc();
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//Keith Tayzon a = -2 // Initial Guess b = 0 // Initial Guess tol = 1 * 10 ^ -10 // Maximum Error i = 0 // Iteration // The equation f(x) = x^3 + 2*tan(x) + 4 function[y] = f(x) y = x^3 + 2*tan(x) + 4 endfunction // The derivative of f(x) function[y] = f1(x) y = 3*x^2 ...
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clear //Given V=200 //V Vp=200 //V n=200.0 Ip=2 //A //Calculation Vs=Vp*n Is=(Ip*V)/Vs //Result printf("\n (i) Voltage developed in the secondary is %0.3f V", Vs) printf("\n (ii) The current in the secondary is %0.3f A",Is )
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//Electric Drives:concepts and applications by V.subrahmanyam //Publisher:Tata McGraw-Hill //Edition:Second //Ex5_3 clc; clear; Alpha=0.4;//Angle in rad T1=100;//Temperature rise of motor in degree T2=150;//Temperature rise of motor in degree P=125;//Power in KW t1=15;//Time in hour t2=30;//Time in hour x...
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//example 8 //An Ideal Cogeneration Plant clear clc v8=0.001005 //specific volume for state 3 in m3/kg P9=7000 //pressure at state9 in kPa P8=5//pressure at state 8 in kPa wpumpin1=v8*(P9-P8) //work done by pump 1 in kJ/kg v7=0.001093 //specific volume for state 7 in m3>kg P10=7000 //pressure for state 10 in ...
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//Exa 6.29 clc; clear; close; format('v',5); //Given Data : p1=1;//MPa p2=100;//KPa p1=p1*10^6/10^5;//bar p2=p2*10^3/10^5;//bar hf1=762.5;//KJ/Kg(from steam table) hfg2=2013.6;//KJ/Kg(from steam table) hg2=2675.5;//KJ/Kg(from steam table) //hg2=hf1+x1*hfg2;//KJ/Kg x1=(hg2-hf1)/hfg2;// disp(x1,"Dryness ...
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clear// //Variable Declaration W=24*10**3 //Load in kips E=29*10**6 //Youngs Modulus in psi L=72 //length in inches theta=30 //Angle in degrees //Calculations L_ab=L/sin(theta*%pi*180**-1) //Length of AB in inches L_ac=L/sin((90-theta)*%pi*180**-1) //Length of AC in inches //Applying the forces in x and...
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// Example 6_3 clc;funcprot(0); // Given data T_1=20;// °C P_1=200;// kPa W=720;// kJ V_1=2;// m^3 R=0.287;// kJ/kg.K c_v=0.717;// kJ/kg.K // Calculation m=(P_1*V_1)/(R*(T_1+273));// The mass in kg u_1=209.1;// kJ/kg u_2=-(W/m)+u_1;// kJ/kg T_2=501.2;// K phi_2=2.222;// The relative humidity at state 2 ...
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//scilab 5.4.1 clear; clc; printf("\t\t\tProblem Number 10.4\n\n\n"); // Chapter 10 : Refrigeration // Problem 10.4 (page no. 506) // Solution COP=4.5; //Coefficient of performance //From problem 10.1 HPperTOR=4.717/COP; //Horsepower per ton of refrigeration //Unit:hp/ton Qremoved=1000; //Unit:Btu/min //Fr...
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// Example 7.5.2 clc; clear; R=0.6; //responsivity Pin=15; //optical power in microwatt Ip=R*Pin; //computing photocurrent printf("\nPhotocurrent generated is %d microAmpere.",Ip);
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<cmd> ../build/42sh</cmd> <ref> bash</ref> <stdin> echo toto; echo tata; echo titi; </stdin>
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//EX13_58 Pg-33 clc clear printf("8''s complement (346)_8 is : ") x=['346']; y=oct2dec(x);//octal to decimal conversion// z=bitcmp(y,9);//one's complement of the number// z=z+1; z2=dec2oct(z)//8's complement of the number// printf("%s\n",z2)
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//Chapter 3, Exmaple 12, page 107 //Binding energy clc clear h = 4.15*10**-15 c = 3*10**8 Imax = 1000*10**-10 We = h*c/Imax printf("\nBinding Energy = %e eV ",We) //Answer may vary due to round off errorS
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//Example 6.11// current per phase and power factor clc; clear; close; format('v',6) v1=100;//emf in volts vi=v1/sqrt(3);//induced emf in volts r1=1;//rotor resistance ohms per phase r2=4;//rotor reactance ohms per phase r=sqrt(r1^2+r2^2);//rotor impedence per phase rcp=(vi/r);//rotor current per phase pf=(1/r);//power...
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clear clc S=100 V=11 Z=V*V/S SCA=1000 SCB=650 xa=S/SCA xb=S/SCB Xc=.5 xc=Xc/Z X=round(((xa *(xb+xc))/(xa+xb+xc))*1000)/1000 FS=S/X mprintf("Fault MVA= %.2f MVA",FS)
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//ques11 disp('To find the inverse laplace transform of the function'); syms s t f=(s^2-3*s+4)/s^3; il=ilaplace(f,s,t); disp(il);
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//Chapter-2, Example 2.5, Page 2.10 //============================================================================= clc clear //INPUT DATA Io=0.8;//No load primary current in A Wo=75;//No load primary poewr in W V1=220;//Primary voltage in V f=50;//Supply frequency in Hz //CALCULATIONS Iw=(Wo/V1);//Iron l...
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//Graphical// //Example 12.5.1 //Determination of power, frequency and varaince of //Additive noise clear; clc; close; ryy = [0,1,3,1,0];//Autocorrelation of signal cen_ter_value = ceil(length(ryy)/2);//center value of autocorrelation //Method1 //TO find out the variance of the additive Noise C = ryy(ceil(le...
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// to calculate the equivalent parallel capacitance and resistance // example 8-5 in page 204 clc; //Given dATA R3=10e+3;// resistance R3 in ohm f=100;//frequency in hertz Cs=0.068e-6; Rs=183.8; // series capacitance in farad and resistance in ohm //Calculation Xs=1/(2*%pi*f*Cs);// series capacitive reactance in ohm Rp...
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function []=fplot3d1(xr,yr,f,teta,alpha,leg,flag,ebox) // Trace la surface d\'efinie par un external f ( ex macro [z]=f(x,y)) // on calcule d'abord f sur la grille definie par xr.yr // xr et yr sont des vecteurs implicites donnant les // abscisses et les ordonn\'ees des points de la grille // -teta, alpha : sont les an...
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//example 14.6 PG-14.38 clc clear printf(" Given=> ABCD+AB''CD = ACD(B+B'') .......Distributive property\n\n") printf(" ABCD+AB''CD = ACD.1 ........ ..Since A+A''=1\n\n") printf(" ABCD+AB''CD = ACD .......... Since A.1=A")
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clc clear printf("Example 1.2 | Page number 6 \n\n"); //find the force. //Given Data mass = 120 //in kg acceleration = 10 //in m/s^2 printf("Mass = %.2f kg \n",mass); printf("Acceleration = %.2f m/s^2 \n\n",acceleration); //Solution force = mass * acceleration * 0.001 //in kN printf("Force = %.2f kN \n"...
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clc clear //Page number 473 //Input data p1=80;//The initial pressure of a gas in cm of Hg p2=60;//The final pressure of a gas in cm of Hg v2=1190;//The final volume occupied by a gas in cc v1=1000;//The initial volume occupied by a gas in cc //Calculations g=(log10(p1/p2))/(log10(v2/v1));//The adiab...
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// Exa 5.5 format('v',7);clc;clear;close; // Given data' R1 = 100;// in ohm R2 = 1000;// in ohm R3 = 200;// in ohm R4 = 2000;// in ohm Rg = 200;// in ohm S = 12;// in mm/µA R = 5;// in ohm R4 = R4 + R;// in ohm E = 10;// in V // By Thevenin's equivalent V_TH = E*( (R3/(R1+R3)) - (R4/(R2+R4)) );// in V Req...
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// The Gram-Schmidt Orthogonalization clear;close;clc; nn=input("Enter n value ") disp("Enter elements for matrix A") for i=1:nn for j=1:nn A(i,j)=input("Enter element ") end end disp('The given matrix ') disp(A,'A='); [m,n]=size(A); for k=1:n V(:,k)=A(:,k); for j=1:k-1 ...
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const c = 6; var n: int , f: real, e:real; procedure fak; var i : int, k:real; begin f := 2.23+ k *i ; i := 2; while i <=n do begin f := f+k; i := i+1 end end; procedure xyz; n := 3; begin n := c; call fak end.
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// Grob's Basic Electronics 11e // Chapter No. 33 // Example No. 33_1 clc; clear; // Calculate the differential voltage gain, Ad, and the ac output voltage, Vout. // Given data Vin = 10*10^-3; // Input voltage=10 mVolts(p-p) Rc = 10*10^3; // Collector resistance=10 kOhms Ie = 715*10^-6; // Emitte...
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//x(t) = del(t) syms t s; L =laplace('delta(t)',t,s) disp(L) // x(t) = u(t) L1 =laplace('1',t,s); disp(L1) //x(t) = sin(w0*t)u(t) L2 =laplace('sin(w0*t)',t,s); disp(L2)
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clc clear //Input data H=10^4//Magnetic field intensity in A/m s=3.7*10^-3//Susceptibility uo=(4*3.14)*10^-7//Permeability of free space in H/m //Calculations M=s*H//Magnetization n A/m. The textbook answer is given as 370 A/m which is wrong. B=(uo*(M+H))/10^-2//Flux density in Wb/m^2 *10^-2 //Output prin...
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% polynomial Inequality (Example where another system returned {1 <= x}) ineq_solve( (2*x^2+x-1)/(x-1) >= (x+1/2)^2 ,x); ineq_solve({(2*x^2+x-1)/(x-1) >= (x+1/2)^2, x>0}); ineq_solve({(2*x^2+x-1)/(x-1) >= (x+1/2)^2, x<-1}); % Systems for determining indices of Jacobi polynomials (Winfried Neun). re...
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// A Textbook of Fluid Mecahnics and Hydraulic Machines - By R K Bansal // Chapter 3-Hydrostatic Forces on surfaces // Problem 3.25 //Data given in the Problem R=4 dens=1000 g=9.81 theta=45 AO=4 BO=4 //calculations A=2*R*sin(theta*%pi/180) h=(2*4*sin(theta/180*%pi))/2 //h=Ab/2 and AB=2AD where AD...
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t=2.5;//skin thickness,given in mm St=1.2;//straps thickness,given in mm d=4;//rivets diameter,given in mm Lt=125;//limit tensile stress Ls=120;//limit shear stress
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clear; clc; a=0.005;f=1000;al=0.05;att=10 //att=given attenuation in db lo=att/(a*8.686); printf("-For the open wire line the required length is lo = %f km\n",round(lo*10)/10); lc=att/(al*8.686); printf("-For the cable the required length is lc = %f km",fix(lc*100)/100);
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schincar schincasi V;IPFV;SBJV;SG;2;PST sparagnar sparagnòn V;IND;PL;1;PRS;LGSPEC2 oxar oxé V;SBJV;PL;2;PRS trincar trincarìa V;COND;SG;3 pontar ponte V;IMP;SG;3;LGSPEC2 aprovar aprovarisi V;COND;SG;2 pestar pestava V;IPFV;IND;SG;3;PST anoverar anoveri V;IND;SG;2;PRS remenar remenavi V;IPFV;IND;SG;2;PST pasar pasarìsim...
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load Not16.hdl, output-file Not16.out, output-list a%B1.16.1 out%B1.16.1; set a %B0000000000000000, eval, output; set a %B1001111000010010, eval, output; set a %B1111111100001010, eval, output;
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function listOutput = ExtendLevelToZ(listInput, fExtendTo, iLevel) endfunction
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clc h1=3456.2//in kJ/kg v1=0.11608//in metre-cube P1=3//in MPa u1=(h1*10^3)-(P1*10^6*v1) mprintf("u1=%fkJ/kg\n",u1/1000) P2=100//in kPa sf=1.3027//in kJ/kg K sg=7.3598//in kJ/kg K s2=7.2345//in kJ/kg K s1=s2//isentropic process X2=(s1-sf)/(sg-sf)//entropy equation using quality factor mprintf("X2=%f\n",X2)...
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clc clear //input g=4;//mutual conductance of a triode in millisiemens u=25;//amplification factor l=20;//load in kilo ohms //calculations ra=u/g;//slope resistance in kilo ohms av=(u*l)/(ra+l);//voltage gain //output mprintf('with aload resistance of 20 kilo ohms this triode will give a voltage amplifi...
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//Problem 4.03: The p.d. at the terminals of a battery is 25 V when no load is connected and 24 V when a load taking 10 A is connected. Determine the internal resistance of the battery. //initializing the variables: e1 = 25; // in volts e2 = 24; // in volts I2 = 10; // in Amperes //calculation: r = (e1 - e2)/...
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//CHAPTER 7- SINGLE PHASE TRANSFORMER //Example 10 disp("CHAPTER 7"); disp("EXAMPLE 10"); //VARIABLE INITIALIZATION v1=6600; //primary voltage in Volts v2=220; //secondary voltage in Volts coreA=0.05; //core section m^2 fluxD=1.2; ...
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pathname=get_absolute_file_path('5_05.sce') filename=pathname+filesep()+'5_05data.sci' exec(filename) Cp=Cpo/(sqrt(1-M^2));disp(Cp,"Cp=","Cp=Cpo/(sqrt(1-M^2))","pressure coefficient Cp :") printf("\Answer:\n") printf("\n\pressure coefficient : %f \n\n",Cp)
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Time = 0.000 Temperature = 302.00 Volume = 0.00 Pressure = 5.55E+07 Energy = 0.000E+00 Time = 0.002 Temperature = 298.70 Volume = 15.70 Pressure = 5.94E+07 Energy = -1.878E+04 Time = ...
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//Power of a locomotive //refer fig.16.7 (a) and (b) v=(56*1000)/(60*60) //m/sec F=5*420/1000 //kN W=420 //kN P=F+W*(1/120) //kN //Power of Locomotive Pw Pw=P*v //kW (mistake in book) u=15.556 //m/sec //Resultant force parallel to the plane R R=F+W*sind(theta) //kN (Down the plane) s=((420*(15.556^2))...
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clc; clear; close; printf('\n\n Name - Syeda Reeha Quasar \n Enrolment No. - 14114802719 \n Group - C7 \n\n') deff ('z = f(x,y)','z = (y-x)/(y+x)') x0 = 0; y0 = 1; xn = 0.1; h = 0.02; x = x0; y = y0; while x ~= xn y = y + h * f(x,y); x=x+h; printf("\n When x = %g, y = %g\n" ,x ,y) end
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//Example No.2.4; //Page No.60; clc;clear; E1 = 3.2;//Value of higher energy level E1 -[eV]. E2 = 1.6;//Value of lower energy level E2 -[eV]. E = (E1-E2);//Energy difference. printf("\nThe energy difference is %.1f eV", E); h = 6.626*10^(-34);//Planck's constant c = 3*10^(8);//Velocity of light. E = 1.6*1.6*...
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clc; pathname=get_absolute_file_path('4_10_soln.sce') filename=pathname+filesep()+'4_10_data.sci' exec(filename) // Solution: // specific weight of oil, gamma1=SG_oil*9800; //N/m^3 // acceleration due to gravity, g=9.80; //m/s^2 // Since, There is no hydraulic motor, Hm=0; //m // oil in tank is at rest, v1=0; //m/s //...
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clc;clear; //Example 11.2 //calculation of average absorption coefficient //given values V=10*8*6;//volume of hall in m^3 t=1.5;//reverberation time of empty hall in sec A=20;//area of curtain cloth in m^2 t1=1;//new reverberation time in sec //calculation a1=.161*V/t;//total absorption of empty hall a2...
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//variable initialization v=10000 //speed of object (meter/second) accu_v=0.0001 //accuracy of speed of object m_b=0.05 ...
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// Universidad Católica del Uruguay // Cálculo Numérico // Eduardo Senturión, Federico González // Laboratorio 1 // Se debe cambiar X por su número function nombre=nombreDeGrupo8() nombre="Grupo_Torterolo_DaRosa_Fernandez"; endfunction // Se debe cambiar X por su número function numero=numeroDeGrupo8...
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//-->x=ode(x0,t0,t,list(sdotx,p,yold)) function [cmdott]=cmdott(t,c,lap3d,dif,sink,source,specid,nspecies,concm, inconsts) cmdott=dif*lap3d-sink+source+compfunc(concm,specid,nspecies,inconsts, t); endfunction
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//Exa 1.23.11 clc; clear; close; //Given data T = 300;// in K n_o = 10^15;// in cm^-3 n_i = 10^10;// in cm^-3 p_o = 10^5;// in cm^-3 del_n = 10^13;// in cm^-3 del_p = del_n;// in cm^-3 KT = 0.0259;// in eV delta_E1= KT*log(n_o/n_i);// value of E_F-E_Fi in eV delta_E2= KT*log((n_o+del_n)/n_i);// value of E_...
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clc //Given that M = 20 // Mass of ball in Kg V = 5 // velocity of of ball in m/s m = 9.1e-31 //Mass of electron in Kg v = 1e6 // velocity of of electron in m/s h = 6.62e-34 // Plank constant printf("Example 1.17") lambda_b = h/(M*V) // calculation of de Broglie wavelength for ball lambda_e = h/(m*v) // cal...
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check_installed: module_and_function: pkg.version args: - firewalld assertion: assertNotEmpty
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// Example 4_18 clc;funcprot(0); // Given data P_2=4000;// kPa T_2=600;// °C P_1=20;// kPa v=0.001;// m^3/kg m=1;// kg h_1=251.4;// kJ/kg // Calculation w_P=(P_2-P_1)*v;// kJ/kg h_2=w_P+h_1;// kJ/kg // From steam tables h_3=3674;// kJ/kg h_4=2610;// kJ/kg q_B=h_3-h_2;// kJ/kg w_T=h_3-h_4;// The work o...
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Hb=2.4;//rise of the benzene solution in mm// Db=0.88;//Density of Benzene solution in g per cm^3// Dm=13.6;//Density of mercury solution in g per cm^3// Hm=(Hb*Db)/Dm;//Rise of mercury solution in mm// printf('The Osmatic pressure given in terms of the height of a liquid column must be converted into an equivalent...
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// Scilab code Ex1.3: : Pg:19 (2008) clc;clear; m = 1.67e-027; // Mass of proton, kg h = 6.62e-034; // Planck's constant, joule-sec c = 3e+08; // Velocity of light, m/s v = c/20; // Velocity of proton, m/sec Lambda = h/(m*v); // de-Broglie wavelength of a proton, m printf("\nThe de-Broglie wavelen...
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// example:-3.5,page no.-91. // program to find out load admittance and input admittance of the line syms lamda; Zl=100+50*%i; Zo=50; le=0.15; //electrical length(l/lamda). b=(2*%pi); tao=reflection_coefficient(Zl,Zo); Zin=input_impedence(tao,b,le,Zo); Yin=1/Zin; Yl=1/Zl; // result disp(Yin,'input admittan...
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//Engineering and Chemical Thermodynamics //Example 2.3 //Page no :38 clear ; clc //External pressure is constant P_ex = 1*10^5 ; //[Pa]} //To calculte work done function y = f(x),y = 1,endfunction I = intg(10,15.2,f) ; W = -P_ex * I * 10^-3 ; //[J] disp(" Example: 2.1 Page no : 33") ; printf('\n ...
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//Chapter 6 Solutions of Electrolytes clc; clear; //Initialisation of Variables Na=0.001 //molar NaCl= 0.001 //molar BaCl= 0.002 //molar Cl= 0.004 //molar n= 1 //moles n1= 2 //moles v= 0.509 //CALCULATIONS Is= 0.5*(Na*n**2+NaCl*n**2+Cl*n**2+BaCl*n1**2) r= 10**(-v*n**2*sqrt(Is))*Na r1= 10**(-v*n1**2*sqrt(Is))*BaCl ...
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response_matching = simple_matching; active_buttons = 2; default_font_size = 0.6; default_font = "Arial"; no_logfile = false; # screen dimensions in pixels screen_width = 1280; screen_height = 1024; screen_bit_depth = 32; screen_width_distance = 38; screen_height_distance = 30; screen_distance ...