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12 12 <12> 11 11 <11> 10 10 <10> 9 9 <9> 8 8 <8> 7 7 <7> 6 6 <6> 5 5 <5> 4 4 <4> 3 3 <3> 2 2 <2> 0 1 <1> 7 05 <time> {---------------------------------1----------------------------------} 1) При помощи какого тега можно создать выпадающий список? & *<select> <input> <label> <list> <optgroup> & {------------------------...
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//Optical Fiber communication by A selvarajan //example 16.2 //OS=Windows XP sp3 //Scilab version 5.5.1 clc; clear all; lambda=1.55;//operating wavelength in um Beta2=-1//dispersion regime ps^2/Km B=10//bitrate in Gb/s two_qo=12//separation between two neighbouring solitons in normalized units LT=%pi*exp(two_...
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// Código resolución de sistemas no lineales function [p,iter,err] = NewtonSistemas(F,p,delta,max1)//opcional: retornar iteracion y el error //P lo ingresamos como fila. Entonces la F va a ser un sistema de ecuaciones, que va necesitar columnas Y=F(p) for k=1:max1 J=derivative(F,p'); Q= p - (J \ Y)'...
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//Finding of Specific speed,Power generated //Given H=30; N=300; Q=10; E=0.9; g=9.81; rho=1000; //To Find P=(E*rho*g*Q*H)/1000; Ns=(N*sqrt(P))/(H)^(5/4); disp("Power Developed ="+string(P)+" Kilowatts"); disp("Specific Speed ="+string(Ns)+" rpm");
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errcatch(-1,"stop");mode(2);//Ex:3.13 ; ; r=10*10^3;//in ohms t=1*10^-3; c=(0.1*t/r)*10^9; printf("Capacitor = %d nF",c); exit();
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// Exa 10.2 clc; clear; close; format('v',6) // Given data V_CC = 20;// in V V_BB = 20;// in V R_C2 = 1;// in k ohm R_C2 = R_C2 * 10^3;// in ohm R_C1 = R_C2;// in ohm f = 500;// in Hz h_fe = 50;// unit less PW = 0.2;// in ms PW = PW*10^-3;// in sec V_CEsat = 0.3;// in V V_BEsat = 0.7;// in V I_CEsat= ...
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// This file is part of www.nand2tetris.org // and the book "The Elements of Computing Systems" // by Nisan and Schocken, MIT Press. // File name: projects/07/StackArithmetic/StackTest/StackTest.tst load MultiTest.asm, output-file MultiTest.out, compare-to MultiTest.cmp, set RAM[0] 256, set RAM[1] 4096, se...
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//(12.4) A gas mixture consisting of CO2 and O2 with mole fractions 0.8 and 0.2, respectively, expands isentropically and at steady state through a nozzle from 700 K, 5 bars, 3 m/s to an exit pressure of 1 bar. Determine (a) the temperature at the nozzle exit, in K, (b) the entropy changes of the CO2 and O2 from inle...
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clc; R_=8314.5; m_=44; R=R_/m_; p2=8.3;//bar V2=0.004;//m^3 m=0.05; T2=p2*V2*10^5/(m*R); p2=8.3;//bar pA=1;//bar sA_s2=(R/1000)*log(p2/pA); cp=0.88; T2=351;//K T1=288;//K sA_s1=cp*log(T2/T1); dec_ent=m*(sA_s2-sA_s1); disp("decrease in entropy is:"); disp("kJ/K",dec_ent)
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("a^4 + b^4 - c^4 - d^4; a - w^2").getDependantMap() = {w=>a}
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clc syms r l x=r*cos(l) y=r*sin(l) a=diff(x,r) b=diff(x,l) c=diff(y,r) d=diff(y,l) A=[a b;c d] det(A)
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//Ex 2.7 clc;clear;close; format('v',6); c=400;//mm(circumference) A=500;//mm^2(Cross sectional area) N=200;//turns //Part (a) I=2;//A H=N*I/(c*10^-3);//A/m B=1.13;//T(Corresponding Flux density) fi=B*A*10^-6;//Wb(total flux) L=N*fi/I*1000;//mH disp(L,"(a) Inductance of coil(mH)"); //Part (a) I=10;//A H=...
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clc; v=60; //potential diff in volt r=5; //resistance in Ohm r1=5; //resistance in Ohm r2=5; //resistance in Ohm r3=5; //resistance in Ohm rp=(r1)^-1+(r2)^-1+(r3)^-1; //resistance in series disp((rp^-1),"Resistance in Parallel in Ohm = "); //displaying result i=v/r; ...
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function x = forwSub(A,b) n = length(b); x = zeros(n); if A(1,1)==0 then mprintf('No se puede resolver.\n\n') else x(1)=b(1)/A(1,1); for (i=2:n) x(i)=(b(i)-A(i,1:i-1)*x(1:i-1))/A(i,i); end end endfunction
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clc; //page no 195 //prob no. 6.6 //All frequencies in kHz fi=250; //input freq USB=[fi+1 fi+3 fi+5]; //from Ex 6.4 // fc=250; //carrier freq f0sum=fc+USB; f0diff=USB-fc; disp(f0sum,f0diff,'(a) The output frequencies (in kHz) are '); disp(f0diff,'(b) At low pass filter,the actual frequencies (in kHz) are...
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//Example 8.6 //Factorization of FIR Transfer Function clear; clc; z=%z; Hz=50.4+28.02/z+13.89/z^2+7.42/z^3+6.09/z^4+3/z^5+1/z^6; disp(factors(numer(Hz)),'The Factors of the FIR Transfer Function are = ');
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//exapple 8.3 clc; funcprot(0); // Initialization of Variable a=16/1000;//dV/dt J=0.0876;//mass fraction rho=999;//density of water rhoc=3470;//density of slurry mu=1.12/1000; rhos=1922;//density of dry filter cake t1=3*60; t2=8*60; V1=33.8/1000;//volume at t1 V2=33.8/1000+23.25/1000;//volume at t2 P=...
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// Aim:Refer Example 7-2 for Problem Description // Given: // volumetric displacement: V_D=5; //in^3 // pressure rating: p=1000; //psi // theoretical flow-rate of pump: Q_T=10; //gpm
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clear; clc; // Stoichiometry // Chapter 5 // Energy Balances // Example 5.39 // Page 284 printf("Example 5.39, Page 284 \n \n"); // solution To = 298.15 T1 = 483.15 // fi1 = intgr(from To to T1){12199.5+2241.4*10^-3*T+1557.7*10^-6*T^2-671.3*10^-9*T^3}dT fi1 = 2455874.6 // kJ/h dHr = 2*(-45.94) ...
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//lubricants// //page 3.36 example 6// clc wt_oil=3//weight f oil saponified(gms)// blank=36//volume blank titration reading(ml)// back=12//volume back titration reading(ml)// volume=blank-back//volume of alcoholic KOH consumed(ml)// normality_KOH=0.5//normality of KOH// S=volume*normality_KOH*56/wt_oil//formul...
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*Testcase TRTRE-02-performance (Test TRTRE instruction) # ------------------------------------------------------------------------------ # This ONLY tests the performance of the TRTRE instruction. # # The default is to NOT run performance tests. To enable this performance # test, uncomment the "#r 408=ff # (enabl...
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.data 8 ok: .c "ok" .code jmpi main name putr putr: prolog frame 160 arg $ac arg $auc arg $as arg $aus arg $ai #if __WORDSIZE == 64 arg $aui arg $al #endif arg_f $af arg_d $ad arg $a #if __WORDSIZE == 64 arg $_l arg $_ui #endif arg $_i arg $_us arg $_s arg $_uc arg $_c getarg_c %r0 $ac negr %r0...
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// Example 2.6, page no-117 clear clc A=1/20 p_diff=1500 printf("(a)\nAs Delta_h=A2/A1*h << h and normally negligiblefor well type manometer\nhence, p1-p2 = h = %d =111 mmHg",p_diff) printf("\n(b)\nh measured above the oriinal reference will be half of H, i.e. 111/2=55.5 mmHg\n(Since area of both legs are sam...
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//Ex:39 clc; clear; close; n_b=79-1;//no. of blocks in this system r_eff=n_b/79;//rate efficiency r_b=24*r_eff;//bit tkbits/sransmission rate in printf("Bit transmission rate =%f Kbits/s",r_b);
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COMMENT | ************************************************************* | COMMENT | * AUTHOR: Paolo Traverso | COMMENT | * | COMMENT | * SUBJECT: WFFIF and TERMIF rules | COMMENT | * ...
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clc // C + O2 → CO2 // 2H2 + O2 → 2H2O // S + O2 → SO2 O2_req=2.636; //kg AF=O2_req/0.233; disp("The stoichiometric A/F ratio =") disp(AF) disp("(i) Actual A/F ratio =") AF_act=AF+0.3*AF; disp(AF_act) disp("(ii) Wet and dry analyses of products of combustion by volume") // As per actual A/F rati...
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// example 2.13// //octal subtracttion// clc //clears the screen// clear //clears all existing variables// a=oct2dec('17'); //given numbers// b=oct2dec('21'); c=b-a; d=dec2bin(c,8) e=dec2oct(c) disp(c,'subtraction of given numbers in decimal form = ') disp(d,'subtraction of given numbers in binary form = '...
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// Example 4.6;all day efficiency clc; close; clear; //given format('v',5) ef=0.98;//efficiency in % kva=15;//kVA pf=1;//power factor op=kva*pf;//output power in kW ip=op/ef;//input power in kW loss=ip-op;//loss in kW cl=(loss*10^3)/2;//copper loss in W il=cl;//iron loss in W t1=12;//time in hours p1=2;//power in kW pf...
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//Example 7.5 clc clear function [f] = y(x) f = -1/x; endfunction H = [0.0128 0.0064 0.0032]; n = length(H); x = 0.05; h = H(1); Fh = (y(x+h) - y(x-h)) / (2*h); Fh2 = (y(x+h/2) - y(x-h/2)) / (h); Fh4 = (y(x+h/4) - y(x-h/4)) / (h/2); F1h2 = (4*Fh2 - Fh) / (4-1); F1h4 = (4*Fh4 - Fh2) / (4-1); F...
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// Initilization of variables d1=24 // cm // diameter of larger pulley d2=12 // cm // diameter of smaller pulley d=30 //cm // seperation betweem 1st & the 2nd pulley pie=3.14 // Calcuations r1=d1/2 //cm // radius of 1st pulley r2=d2/2 //cm // radius of 2nd pulley theta=asind((r1-r2)/d) //degrees // Angle of l...
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clear; clc; // Stoichiometry // Chapter 7 // Combustion // Example 7.13 // Page 479 printf("Example 7.13, Page 479 \n \n"); // solution // solving by alternate method on page 483 // basis 100 kmol of dry producer gas // using tables 7.38 and 7.39 fi7 = 6469.67*(833.15-298.15)*(27650/2672) // kJ/h...
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//example 11.1 //calculate compute the dynamic force on curved section clc;funcprot(0); //given h=1.2; //head of water Cd=2.2; //coefficient of discharge rho=1; //density of water gamma_w=9.81; //unit weigth of water q=Cd*h^1.5; //applying bernaulli's equation at u/s water surfa...
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clc clear //input w=250*10^3 s=0.00003//strain a=0.04//area w1=320*10^3 //calculation e=w/(a*s)//youngs module st=w1/a//stress //output printf("the youngs modulus is %3.3e N/m^2",e) printf("\n the stress is %3.0e N/m^2",st)
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//Graphical// //Example 5.2.1 and Example 5.2.2 //Performing Circular COnvolution //Using DFT clear; clc; close; L = 4; //Length of the Sequence N = 4; // N -point DFT x1 = [2,1,2,1]; x2 = [1,2,3,4]; //Computing DFT X1 = dft(x1,-1) X2 = dft(x2,-1) //Multiplication of 2 DFTs X3 = X1.*X2 //Circular Conv...
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// Example 1.19 clear; clc; close; format('v',8); // Given data P=4;//in poles Pout=37;//in HP f=50;//in Hz N=1425;//in rpm MechLoss=3;//in HP StatorLoss=2500;//in watts VL=500;//in volt cosfi=0.9;//power factor //Calculations Ns=120*f/P;//in rpm S=(Ns-N)/Ns;//slip disp(S,"(i) Slip is : "); Pout=Po...
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function [stop] = mpc(Tsp,fan) global fdfh fdt fncr fncw m err_count stop p q xk_old heat temp heat_old heat = mpc_run(temp,heat_old,Tsp); [stop,temp] = comm(heat,fan);//Never edit this line plotting([heat fan temp Tsp],[0 40 25 0],[100 70 50 1000]); heat_old = heat; return endfunction
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clc; //Example 9.4 //page no 89 fig 9.2 printf("Example 9.4 page no 89 fig. 9.2\n\n\n"); //water is discharged through a fire hose rho=1000//density of water meu=0.001//viscosity of water q=0.025//flow rate at section 1 D1=.1//diameter at section 1 D2=.03//diameter at section 2 printf("\n density rho=%f kg/...
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errcatch(-1,"stop");mode(2);//Theory Example exit();
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function mtlb_choices(nam,header,labels,callbacks,inter) // Copyright INRIA while %t num=x_choose(labels,header,'Close') if num==0 then break,end execstr(callbacks(num)) end
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@relation vowel @attribute TT integer[0,1] @attribute SpeakerNumber integer[0,14] @attribute Sex integer[0,1] @attribute F0 real[-5.211,-0.941] @attribute F1 real[-1.274,5.074] @attribute F2 real[-2.487,1.431] @attribute F3 real[-1.409,2.377] @attribute F4 real[-2.127,1.831] @attribute F5 real[-0.836,2.327] @attribute...
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//Example 19_7 clc(); clear; //To calculate the Back emf developed i=3 //Units in A r=2 //Units in Ohms v=110 //Units in Ohms e=v-(i*r) //Units in V printf("The back emf developed is EMF=%d V",e)
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FLAGS='--list --print NONE' STDIN='' STDOUT='' STDERR='!USAGE!' EXITVAL='1'
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//exa 1.16 clc;clear;close; format('v',8); L=[20 25 30 25 35 20];//MW T=[6 4 2 4 4 4];//Hours Lmax=max(L);//MW disp(Lmax,"(a) Maximum demand(MW)"); E=L(1)*sum(T)+(L(2)-L(1))*T(2)+(L(3)-L(1))*T(3)+(L(4)-L(1))*T(4)+(L(5)-L(1))*T(5)+(L(6)-L(1))*T(6);//MWh E=E*1000;//kWh disp(E,"(b) Units generated per day(kWh)");...
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(set-strategy depth) (unwatch all) ; modlmisc.bat test (clear) (open "modlmisc.rsl" modlmisc "w") (dribble-on "modlmisc.out") (batch "modlmisc.bat") (dribble-off) (load "compline.clp") (printout modlmisc "modlmisc.bat differences are as follows:" crlf) (compare-files modlmisc.exp modlmisc.out modlmisc) ; close result f...
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a=[36496.9223 35789.39199 35789.39199 36921.62197 36775.80237 36775.80237 35059.00885 36577.36389 36577.36389 33097.57061 33097.57061 33097.57061 33097.57061 33097.57061 33097.57061 33097.57061 31512.86422 35819.03979 31953.75477 30226.52452 38828.94203 38828.94203 38828.94203 33115.35681 30998.57361 30998.57361 32086....
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clc d2=0.06; // m d1=0.12; // m k=0.44; f=0.05; L1=500; // m g=9.81; // m/s^2 // v1=d2^2/d1^2*v2 // H_f=4*f*L1/16/d*v2^2/2/g // H_c=k*v2^2/2/g // H_f=4*f*L2/d*v2^2/2/g // H_exit=v2^2/2/g v2=sqrt(30*2*g/173.4); Q=%pi*d2^2/4*v2; disp("The rate of flow =") disp(Q) disp("m^3/s")
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// problem 2.13 s=2 w=340 v=0.5*s*s*s z=9810 w1=z*4 gb=s/4-s/8 i=s*s*s*s/(12) v=4 bm=i/v gm=bm+gb p=w/(w1*gm) theta=atand(p) disp(theta*60,"angle through which cube will tilt in minutes")
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//Caption:Calculate the breakdown power of circular waveguide //Exa:4.24 clc; clear; close; //Given: d=5;//in cm c=3*10^10;//in cm/s f=9*10^9;//inHz //Dominant mode is TE11: wl_o=c/f; wl_c=%pi*d/1.841; f_c=c/wl_c; P_bd_TE11=1790*(d/2)^2*[1-{f_c/f}^2]^0.5; disp(P_bd_TE11/1000,'Breakdown power (in kW) =');
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clc // Given that lambda = 5.893e-7 // wavelength of light in meter V = 0.36 // stopping potential for emitted electron in eV h = 6.62e-34 // Planck constant in J-sec c = 3e8 // speed of light in m/sec e = 1.6e-19 // charge on an electron in C m = 9.1e-31 // mass of an electron in kg // Sample Problem 14 on page no. ...
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//frequency shifting clear; clc; close; dt=.1; w0=1;//positive number t=-10:dt:10; x=exp(-%i*t*w0); a=gca(); plot(t,x); poly1=a.children.children; poly1.thickness=3; poly1.foreground=2; xtitle('x(t)','t') wmax=10; w=-wmax:0.1:wmax; Xw=x*exp(-%i*(w'*t))*dt; figure a=gca(); plot2d3(w,round(Xw/10)); po...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monito...
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clc //Chapter4 //Ex_5 //Given E_FO=7 //in eV e=1.6*10^-19 // in coulombs E_FO=E_FO*e //in Joules me=9.1*10^-31 //in Kg v_f=sqrt(2*E_FO/me) disp(v_f,"Speed of the conduction electrons in m/s is")
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{"title": "voyage", "source": "crip.com", "author": "cook", "entries": [{"number": 1, "date": "29 July 1768", "latitude": null, "longitude": null, "course_bearing": null, "distance": null, "text": "RIVER THAMES, Friday, May 27th 1768, to Friday, July 29th. Moderate and fair weather; at 11 a.m. hoisted the Pendant, and ...
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@relation flare @attribute LargestSpotSize{A,R,S,X,K,H} @attribute SpotDistribution{X,O,I,C} @attribute Activity{1,2} @attribute Evolution{1,2,3} @attribute Prev24Hour{1,2,3} @attribute HistComplex{1,2} @attribute BecomeHist{1,2} @attribute Area{1,2} @attribute C-class{0,1,2,3,4,5,6,7,8} @attribute M-class{0,1,2,3,4,5...
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h=openserial('COM3','115200'); for i=1:10000 answer=h.serialread(); answery=strtod(answer); plot2d3('gnn',i,answery); drawnow(); end h.close();
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clear clc exec('objective.sce'); disp('RUNNING...') rand('seed',getdate('s')) POPSIZE = 50 DIM = 2 UPPER = 1000 LOWER = -1000 MAXITER = 300 FQ = 3 PB = 0.9 // 0.8 - 1.0 C = 1.5 S = 1.5 A1 = 1 A2 = 1 FL = 0.7 // 0.5 - 0.9 BIRD = rand(POPSIZE,DIM).*(UPPER-LOWER)+LOWER FIT = F1(BIRD) [BESTFIT ...
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// Example 10-5 // Design of servo system without integrator in the plant clear; clc; xdel(winsid()); //close all windows mode(0); function smallplot(i) subplot(3,2,i);xgrid(color('gray')); plot(t,x(i,:)); endfunction // Plant A = [0 1 0 0; 20.601 0 0 0; 0 0 0 1; -0.4905 0 0 0]; B = [0; -1; 0; 0.5]; C = [0 0 1 ...
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#************************************************************ # Scenario of Test # # date : Fri Oct 31 16:55:16 2008 #************************************************************ p3d_sel_desc_name P3D_ENV Test p3d_sel_desc_name P3D_ROBOT superman p3d_set_robot_steering_method Linear p3d_set_robot_current 0.000000...
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//Chapter-2, Example 2.4, Page 2.7 //============================================================================= clc clear //INPUT DATA V1=2500;//primary voltage in V V2=200;//Secondary voltage in V e=(30*0.9);//Effective side of magnetic core in cm A=(30*30*0.9*0.9*10^-4);//Area of cross section of the lim...
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make08.tst
java -ea make.Main -f make-tests/make08.mk -D make-tests/file08 T1
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//Chapter 2 : Diffraction clear; //Variable declaration lamda=6.5*10**-7 //wavelength n=1 //first order theta=(15*%pi/180) //angle in radians //Calculations d=(n*lamda)/sin(theta)/10**-6 //Result mprintf("Grating element= %.3f*10**-6 m",d)
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//Variable declaration C=0.4*10**-12 //capacitance(pF/um^2) A=10**-12 //area of film(m^2) d=400*10**-10 //thickness of SiO2(amstrong) Eo=8.849*10**-12 //absolute electrical permitivity of free space //Calculations Er=(C*d)/(Eo*A) //relative dielectri...
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ex_12.sce
//Example 12// equation,frequency,amplitude ,wavelength and distance clc; clear; close; //y=6*(sin(2*%pi*x)/6)*cos(160*%pi*t);//given equation a=3;//cm T=(2*%pi)/(160*%pi);//sec h=((2*%pi*6)/(2*%pi));//cm disp("wave equation is 3*sin((160*%pi*t)+(2*%pi*x)/6)") disp(a,"amplitude is ,(cm)=") disp(1/T,"frequency is ,(Hz)=...
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//Example 3.8 v_0y=0;//Initial vertical velocity (m/s) g=9.8;//Acceleration due to gravity (m/s^2) y_0=0;//Initial position (m) y=-1.5;//Final position (m) v_y=-sqrt(v_0y^2-2*g*(y-y_0));//Final vertical velocity (m/s) //The negative root is taken as the velocity is directed downward printf('a.Velocity of the coi...
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//chapter 8 //example 8.6 //Calculate flux density, magnetic intensity and relative permeability //page 237 clear; clc; //given l=30; // in cm (length of solenoid) A=1; // in cm^2 (cross-sectional area) N=300; // number of turns i=0.032; // in A (current through the winding) phi_B=2E-6; // in Wb (magnetic fl...
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5_1.sce
clc //initialisation of variables clear w= 20 //lbm/sec sh= 0.004 m1= 0.12 //lbm/sec m2= 12.2 //lbm/sec m3= 0.130 //lbm/sec //CALCULATIONS mw1= w/((1/sh)+1) ma1= w-mw1 ma4= ma1-m2 mw4= mw1+m1-m3 mr= ma4+mw4 sh1= mw4/ma4 //RESULTS printf ('mw1 = %.4f lbm/sec',mw1) printf ('\n ma1 = %.2f lbm/sec',ma1) p...
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teste.sce
// format('v',7) // for i=1:5 strcat(string(matriz_AIC_ARMAX(i,1:8)/10000),' & ') end format('v'); for i=1:5 disp(string(i) + " & " + strcat(string(matriz_AIC_ARX(i,1:8)),' & ') + " \\"); end for i=1:5 disp(string(i) + " & " + strcat(string(matriz_AIC_ARMAX(i,1:8)),' & ') + " \\"); end
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//Example 17.5, page no 664 clc; Tz=(1-1)/2 //For K+ Q=1 B=0 S=1 Tz=1-0.5 printf("The value of Tz for K+ is %f \n",Tz) //For K- Q=-1 B=0 S=-1 Tz=-1+0.5 printf("The value of Tz for K- is %f\n",Tz) //For Ko Q=0 B=0 S=1 Tz=-0-0.5 printf("The value of Tz for Ko is %f \n",Tz) //For Ko_dash Tz=0+0.5 printf("The value of...
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//Fuels and Combustion// //Example 8.15// CR=7.8;//compression ratio for first case// E1=1-(1/CR)^0.258;//Energy efficiency corresponding to CR value 7.8// printf('Efficiency of the engine in the first case=E1=%f',E1); CR=9.5;//compreesion ratio for second case// E2=1-(1/CR)^0.258;//Energy efficiency correspondin...
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//Example 3.40:resistance and capacitance clc; clear; close; r2=1000;//ohms r4=100;//ohms c4=0.1;//micro farads c3=1000;//pF rs=((c4/(c3*10^-6))*r2);//M-ohm cs=((r4/r2)*(c3*10^-6));//micro farads disp(rs*10^-7,"resistance is,(M-ohm)=") disp(cs*10^6,"capacitance is,(micro-F)")
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clear RootFolder='C:\Users\Max Braun\Documents\Max_Braun_2017\05_Tools\LandingSim\BlueBook-DaLAT-3DoF\burst_container\'; //initialize the list BB_ascent = list(); step=25 tstart = 1 tend = 450 for i=tstart:step:tend file_01 = 'burstres_'; file_02 = '.txt'; number = string(i); file_x = "" ; file_x...
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clc disp("Problem 10.4") printf("\n") //For V1 Ro1=25 Theta1=143.13 //For V1 Ro2=11.2 Theta2=26.57 //We need to find V1/V2 //Let V=V1/V2 Vmag=(Ro1/Ro2) Vph=Theta1-Theta2 x=Vmag*cos((Vph*%pi)/180); y=Vmag*sin((Vph*%pi)/180); z=complex(x,y) //Let V1+V2=V12 x1=Ro1*cos((Theta1*%pi)/180); y1=Ro1*sin((Th...
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errcatch(-1,"stop");mode(2);; ; format('v',11); epsilone_r=80; theta_b=atand(sqrt(epsilone_r)); disp(theta_b,"the Brewster angle(in degree)="); exit();
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//Fluid Systems - By Shiv Kumar //Chapter 12- Reciprocating Pumps //Example 12.4 //To Find whether seperation will take place, and if so, at which section of pipe. clc clear //Given Data:- ld=60.96; //Length of Delivery Pipe, m a=1.83; //Acceleration of Plunger Pump, m/s^2...
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TranspositionSet={[1,0,2]} considerNonPrimitive Expanding for base=2, level=2, reasons+features=base,transpose,primitive,same,similiar igtriv,norm Refined variables=a,b,c [0+1a,0+1b,0+1c]: unknown -> [1] [0,0,0] a⁵+b⁵-c⁵ ---------------- level 0 expanding queue[0]^-1,meter=[2,2,2]: a⁵+b⁵-c⁵ [0+2a,0+2b,0+2c]: non-primit...
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clc clear //Input data m=2;//Mass flow rate of air in kg/s t1=20;//Initial temperature of the air in degree centigrade P=-30;//The amount of power consumed in kW c1=100;//The inlet velocity of air in m/s c2=150;//The outlet velocity of air in m/s R=0.287;//The gas constant for air in kJ/kg-K g=1.4;//It is the ...
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clc; clear; //Example 4.21 e1=0.3 e2=0.8 //Let sigma*(T1^4-T2^4)=z=1(const) z=1; //Let Q_by_A=z/(1/e1+1/e2-1) //W/sq m //Heat transfer with radiation shield e3=0.04 F13=1; F32=1; //The resistances are: R1=(1-e1)/e1 R2=1/F13 R3=(1-e3)/e3 R4=R3 R5=1/F32 R6=(1-e2)/e2 R=R1+R2+R3+R4+R5+R6 //Tot...
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errcatch(-1,"stop");mode(2);//example 2.1 //page 45 ; funcprot(0); //initialisation of variable pi=3.14; Ap=pi*1^2/4;//area of piston Ar=pi*10^2/4;//area of ram W=1000; F=W/Ar*Ap; disp(F,"force on piston(N)="); exit();
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clc; warning('off'); printf("\n\n example6.5 - pg232"); // given UzmaxbyU=24.83; roUbyv=2312; Re=100000; // using the formula Et/v=95.5*((r/ro)/slope)-1 // from fig 6.6 at Re=100000 rbyro=[0 0.040 0.100 0.200 0.300 0.4 0.5 0.6 0.7 0.8 0.9 0.960 1]; slope=[0 0.105 0.112 0.126 0.144 0.168 0.201 0.252 0.336 0.50...
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function [U,e] = trisup(A,b) tol = 1e-12; [n,m] = size(A); if (n <> m) | n <> size(b,1) then error("Dimensions incohérentes"); end U = A; e = b; for k = 1:n-1 if abs(U(k,k)) < tol then error('Pivot nul'); end for i = k+1:n c =...
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//Chapter 8 : Determinants //Example 8.11 //Scilab 6.0.1 //Windows 10 clear; clc; A=[1 -1 2 3;2 2 0 2;1 2 3 0;5 3 2 -1] disp(A,'A=') detA=det(A) disp(detA,'det A=') A(2,:)=A(2,:)-2*A(1,:) A(3,:)=A(3,:)-1*A(1,:) A(4,:)=A(4,:)-5*A(1,:) disp(A,'A=') detA=det(A) disp(detA,'det A=') A1=[4 -4 -4;3 1 -3;8 ...
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clc(); clear; //Given : mu_p = 1.2 ;// dipole moment in debye units T = 300 ; // Temperature in Kelvin ( 273+27 = 300 K) k = 1.38*10^-23 ; // in J/K per = 0.5/100 ; // percentage of saturated polarisation // 0.05*N*mu_p = (N*(mu_p)^2*E/(3*k*T)) E = (3*k*T*per)/(mu_p*3.33*10^-30); // External field in V/m prin...
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clc; clear all; disp("temperature of mixed sand") m=0.08/3600;// m^3/s sand feeding rate d=30/1000;// pipe diameter L=6;//m legth of pipe ts=100;// degree C inside temperature of pipe rho=1500;// kg/m^3 k=0.3;// W/m.C cp=840;// J/kg.K ta=20;//degree C temperature of sand entering disp("Q=h*A*(ts-(ti+to)/2)=m...
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clc //to find time t1 at which the ball reaches highest position of its trajectory //maximun height at which ball can reach //total time of flight and range of ball //velocity of ball when it strikes the ground // GIVEN:: //initial velocity of ball v0 =15.5//in m/s //angle made by the ball with hori...
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clc; clear all; Ir = 2; // Intensity ratio b = 10*log10(Ir); // Relative intensity disp('dB',b,'The increase in sound intensity level is')
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clc,clear printf('Example 10.3\n\n') I_1=36 //intensity of lamp1 I_2=16 //intensity of lamp2 //E_1 is illumination due to lamp 1 //E_1 = I_1 / x^2 //E_2 is illumination due to lamp 2 //E_2 = I_2 / (1-x)^2 //equating E_1 and E_2, and solving for x p=[5 -18 9] ans=roots(p) printf('The screen should be...
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//to determine armature current clc; n1=1600; Ia1=120; n2=400; Ia2=(n1*Ia1)/n2; //P=K*Ia*n disp(Ia2,'Ia(A)');
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//Example 7.8 k=250;//Force constant of spring (N/m) m=0.100;//Mass of car (kg) x_i=0.0400;//Initial compression of the sping (m) v_f_a=sqrt(k/m)*x_i;//Final velocity (m/s) printf('a.Final speed (before the start of the slope) = %0.2f m/s',v_f_a) h_f=0.180;//Final height (m) v_f_b=sqrt((k*x_i^2/m)-(2*g*h_f));//F...
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//Example18.6// a=8.9*10^4;//(amperes/m)(webers/m^2) // Area mprintf("a= %e (amperes.webers)/m^3",a) //one ampere weber is equal to 1joule. The area is then a volume density of energy ,or e=8.9*10^4//J/m^3 //energy loss b= 10^-3; //As 1Kilogram = 10^3 gram e1=e*b mprintf("\ne1 = %i kJ/m^3 (per cycle) (As 1Kilo...
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// Theory and Problems of Thermodynamics // Chapter 11 // Kinetic Theory of Gases // Example 6 clear ;clc; //Given data V = 1.2 // X-component velocity lower range // Caluclations // The fraction of molecules with positive x-component of velocity = 0.5 F_mol = 0.5 // F = (1/sqrt(%pi))in...
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//fiber optic communications by joseph c. palais //example 1.1 //OS=Windows XP sp3 //Scilab version 5.4.1 clc clear all //given LP1=-11// Loss in element 1 in dB LP2=-6// Loss in element 2 in dB LP3=-3// Loss in element 3 in dB //to find total_Loss=LP1+LP2+LP3//total Loss in dB mprintf("total Loss=%fdB",tot...
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//Ex7_3 Pg-369 clc Beta=250 //transistor gain Vcc=15 //supply voltage R1=2000 //resistor R1 in ohm R2=470 //resistor R2 in ohm Vce=0.7 //voltage drop in V Re=220 //emitter resistor in ohm Vb=(Vcc*R2)/(R1+R2) //base voltage in V disp("(1) Base voltage Vb") printf(" = %.2f V",Vb) Ve=Vb-Vce //emi...
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//chapter 9 example 4// clc clear //angular limit of the far field pattern=Am,length of the picture=l,numerical aperture=NA,distance of the fibre output end face from the screen=L// Am=26.1;//in degrees// NA=sind(Am);//numerical aperture// printf("\n numerical aperture=%f \n",NA) l=16.7;//in cm// L=(l/2)/(tand(...
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clc // Given that n = 2.5e28 // no. of free electron in per meter cube e = 1.6e-19 // charge on an electron in C m = 9.1e-31 // mass of electron in kg h = 6.62e-34 // Planck constant in J-sec // Sample Problem 3 on page no. 16.15 printf("\n # PROBLEM 3 # \n") printf("Standard formula used \n") printf("1/2 * m*v^2 = E...