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m = [1;2;3]; K = [2,1,3;1,4,-2;3,-2,8]; C = chol(K)'; Z = zeros(3,1); i=1; while i<4 U1 = rand(); U2 = rand(); Z(i,1) = sqrt(-2*log(U2))*cos(2*%pi*U1); i=i+1; if (i<3) then Z(i,1) = sqrt(-2*log(U2))*sin(2*%pi*U1); i=i+1; end end X = C*Z+m;
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//exmaple7.23 clc disp("E_p(rms) = 230V, N2/N1 = 1/15, R_L=50 ohm") disp("R_f = R_s = 0 ohm as ideal") disp("Now, E_p(rms)/E_s(rms) = N1/N2") e=230/15 format(7) disp(e,"Therefore, E_s(rms)[in V] = N2*E_p(rms)/N1 = 230/15 = ") e=15.333*sqrt(2) disp(e,"Therefore, E_sm(in V) = ") i=21.684/50 disp(i,"Therefore, ...
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//clc(); clear; //To calculate angle of refraction at the interface n1=1.6; //refractive index of medium n2=1.55; //refractive index of core theta1=60; //angle of incidence in degrees A=sind(theta1); disp(A); theta2=asind(n1*A/n2); printf("angle of refraction is %f degrees",theta2); /...
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function Newlength(varargin) if length(varargin)==0 Kyorihensuu(); else FL=varargin(1); Kyorihensuu(FL); end endfunction
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load BasicIf.asm, output-file BasicIf.out, compare-to BasicIf.cmp, output-list RAM[0]%D1.6.1 RAM[256]%D1.6.1; set RAM[0] 256, repeat 600 { ticktock; } output;
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run2"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monito...
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clear clc disp('Exa-12.10(a)'); m40K=39.963999; //mass of various particles m40Ca=39.962591; c2=931.5; //value of c^2 in MeV Qb1=(m40K-m40Ca)*c2; //Q value of the reaction printf('The Q value for -VE beta emission is %.3f Mev \n',Qb1); disp('Exa-12.10(b)'); m40K=39.963999; ...
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clc //initialization of variables clear w=10 //cm s=2.8 //m P=1 //tonne Ft=1.4 //cm Wt=0.8 //cm Ix=13989.5 //cm^4 Z=699.5 //cm^3 // calculations BM= 2.8 T=P*1000*8.21 SF=P*1000 BS=BM*10^5/(Z) sigmaXA=BS*18.6/20 K=w*Ft*19.3+18.6*Wt*9.3 tau_xy_C=SF/(Ix*Wt)*K tau_xy_A=tau_xy_C*(w*Ft*19.3)/K tau_xy...
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//Initilization of variables F1=-100 //lb F2=200 //lb F3=-200 //lb F4=400 //lb F5=-300 //lb //Distance with respect to point O x1=0 //ft x2=2 //ft x3=5 //ft x4=9 //ft x5=11 //ft //Calculation R=F1+F2+F3+F4+F5 //lb M_O=(F1*x1)+(F2*x2)+(F3*x3)+(F4*x4)+(F5*x5) //N-m //Result clc printf('The resultant of t...
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clc; Ef=1.4; // p.u excitation EMF xs=1.2; // p.u synchronous reactance p=0.5; // p.u synchronous power being delivered i=1; // percentage increment in prime mover torque vt=1; // rated per phase voltage de=asind((p*xs)/(Ef*vt)); // load angle dp=(i*p)/100; // increase in p.u real power ip=(dp/p)*100; printf...
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// Variable declaration Mean = 50 // Mean of normal distribution std_dev = 5 // standard deviation of normal distribution // Calculation // Computer generates 2 values 0.253 and 0.531 from uniform distribution(can be obtained by reading 3 digits at a time in TABLE-7 u1 = 0.253 u2 = 0.531 // As we know z...
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clc; clear all; //variable declaration Am = 25.34; //measured value in watts dA = -0.11; //absolute error in watts //calculations A = Am-dA; //True value in wtts //result mprintf("abslotue error = %3.2f watts",A);
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7q8.sce
clc //initialisation of variables e= 0.6 D10= 0.09 //mm //calculations k= 2.4622*(D10^2*(e^3/(1+e)))^0.7825 //results printf ('hydraulic conductivity = % 4f cm/sec ',k)
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//Chapter 16_Bipolar and MOS Digital Gate Circuits //Caption : NMOS operating region //Example 16.12: A NMOS transistor with K=20uA/V^2 and Vth=1.5V is operated at Vgs=5V and Ids=100uA. Determine the region of the operation on I-V characteristics and find Vds. //Solution: clear; clc; K=20*10^-6; Vgs=5; Vth=1.5;...
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clear all; clc; disp("Scilab Code Ex 8.6 : ") //Given: P = 40; //kN l_ab = 0.4; //m l_bc = 0.8; //m //Stress Components: //Normal Force: A = l_ab*l_bc; sigma = P/A; //Bendng Moments: M_x = P*l_ab/2; cy = l_ab/2; Ix = (1/12)*(l_bc*l_ab^3); //I = (1/12)*(bh^3) sigma_max_1 = (M_x*cy)/Ix; //sigma = ...
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Example8_5.sce
//Example 8.5 //Program to find the Gain of the Amplifier clear; clc ; close ; //Given Circuit Data gm=3000*10^(-6); //S Rl=22*10^3; //Ohms rp=300*10^3; //Ohms //Calculation //A=-(gm*Rl/(1+(Rl/rp))), For rp>>Rl we get A=gm*Rl; //with Phase of 180 degrees //Displaying The Results in Command Window printf("\...
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example13_4cpp.sce
clc clear disp('example 13.4') pa=50;xgb=0.5;xb=0.1;//given power,reactance of generator x1=xgb+xb; x=x1*x1*xgb/(x1*x1+x1*xgb+x1*xgb) f=pa/x printf(" total reactance %.4f.p.u \n fault MVA %.1fMVA",x,f)
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clc //Example 16.3 disp('Given') disp('R=10 ohm L=2mH C=200 nF w=48 krad/s vs=100*cos(wt) mV') R=10; L=2*10^-3; C=200*10^-9; w=48*10^3; vsamp=100; w0=1/sqrt(L*C) printf("w0= %3.1f krad/s \n",w0*10^-3); Q0=w0*L/R printf("Q0=%d \n",Q0) B=w0/Q0 printf("Bandwidth= %3.1f krad/s \n",B*10^-3); //Number of half ban...
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clear; clc; printf("\t\t\tExample Number 6.12\n\n\n"); // heating of liquid bismuth in tube // example 6.11 (page no.-305-6) // solution m_dot = 4.5;// [Kg/s] flow rate of bismuth d = 0.05;// [m] diameter of steel tube Ti = 415;// [degree celsius] initial temperature of bismuth Tf = 440;// [degree celsius]...
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//check o/p when i/p is an empty null vector x=[0 0 0 0]; [d]=falltime(x); disp(d); //output ////!--error 10000 //BOUNDS must be strictly increasing. //at line 173 of function statelevels called by : //at line 51 of function falltime called by : //[d]=falltime(x);
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clc pathname=get_absolute_file_path('9_5_1.sce') filename=pathname+filesep()+'951.sci' exec(filename) printf(" All the values in the textbook are Approximated hence the values in this code differ from those of Textbook") function[Cp]=fun(T) Cp=29.50*10^(-3)+ T*0.8188*10^(-5) - T^2 * 0.2925 *10^(-8) + T^3 * 0....
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clc; //e.g 29.2 R1=2*10**3; R2=20*10**3; C1=0.01*10**-6; C2=0.05*10**-6; T=0.69*(R1*C1+R2*C2) disp('ms',T*10**3,"T="); f=1/T; disp('kHZ',f*10**-3,"f=");
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//Exa 7.8 clc; clear; close; //Given data : format('v',5) L=0.3;//in mm L=L*10^-3;//in meter n=3.6;//Refractive Index(unitless) c=3*10^8;//speed of light in m/s lambda=0.82;//in um lambda=lambda*10^-6;//in meter deltaNEU=c/(2*n*L);//in Hz disp(deltaNEU*10^-9,"Frequency spread between longitudinal modes in ...
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//find clc //solution //given U=1000//N-m D=0.100//m d=0.02//m n=30 G=85*10^9//N/m^2 C=D/d K=(4*C-1)/(4*C-4)+(0.615/C) V=(%pi*D*n)*[%pi/4*d^2]//volume//m^3 t=(U*4*K^2*G/V)^(0.5)//N/m^2 printf("max shear stress acting is,%f N/m^2\n",t) dx=%pi*t*D^2*n/(K*d*G) printf("deflection produced is,%f m",dx)
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//problem 6 pagenumber 5.100 //given c=10e-6;//farad w=6;format(6); //determine R r=w/(1.11*c); format(6); disp('R = '+string(r/10^3)+' Kohm'); disp('C1 = '+string(c*1e6)+' μfarad');
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welcome to my activities: A1 - Flowcharts & Pseudocodes A2 - Flow-charting Exercise A3 - Pseudo-code Exercises
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15 6:0.5 12:0.5 16:0.04878048780487805 18:1.0 28:1.0 69:2.0 70:0.5 186:1.0 244:1.0 668:1.0 699:1.0 850:1.0 15 18:1.0 33:0.05555555555555555 67:1.0 90:1.0 112:0.25 138:1.0 146:1.0 502:0.5 958:1.0 1057:1.0 1118:1.0 15 1:0.2 4:0.5 12:2.0 18:3.0 24:1.0 33:0.05555555555555555 35:0.25 44:1.0 59:4.0 63:0.25 68:1.0 70:0.5 90:1...
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//Chapter-7, Example 7.12, Page 302 //============================================================================= clc clear //INPUT DATA n=7;//Number of rows of tube Ta=15;//Temperature of air in degree C v=6;//Velocity of air in m/s ST=0.0205;//Transverse pitch in m SD=0.0205;//Longitudinal pitch in m D...
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//Example 3.2.1 Page 51 //Non-Linear Dynamics and Chaos, First Indian Edition, Print-2007 //Steven H. Strogatz clear; clc; close; // General INTRODUCTION disp("To show their is Transcritical Bifurcation show :") disp("1. Their are always two fixed points ,") disp("And they change their Stability around Bif...
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disp("Ei=((Ec+Ev)/2)+((3*K*T/4)*log(mh/me))"); disp("me=(0.328)m0 & mh=(0.55)mo"); b=1.12; //say b=(Ec+Ev)=1.12eV c=0.0259; //say c=(K*T)=0.0259 d=1.6768; //say d=(mh/me) a=((b)/2)+(((3*c)/4)*log(d)); printf('\n The value of Ei = %f eV',a); disp("Ef=Ei+((K*T)*log(Nd/ni))"); e=10^17; //say e=Nd f=10^10; //...
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// Scilab Code Ex10.3.2 Energy released in the fusion of deuterium: Pg:220 (2008) e = 1.6e-019; // Energy equivalent of 1 eV, J/eV Q = 43; // Energy released in fusion of six deuterium atoms, MeV N = 6.023e+026; // Avogadro's number, No. of atoms per kg n = N/2; // Number of atoms contained in 1 kg of d...
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// Initilization of variables M_1=10 // kg // mass of the 1st block M_2=5 // kg // mass of the 2nd block mu=0.25 // coefficient of friction between the blocks and the surface g=9.81 // m/s^2 // acc due to gravity // Calculations a=g*(M_2-(mu*M_1))/(M_1+M_2) // m/s^2 // from eq'n 5 T=M_1*M_2*g*(1+mu)/(M_1+M_2) //...
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//Initialisation of variables clc Z=2 m=9.11e-31//kg e=1.6e-19//coulomb o=8.85e-12//farad per metre h=6.625e-34//joule sec V=Z^2*m*e^3/(8*o^2*h^2) printf('second ionization potential is %f volts \n',V)
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## Test the branch delete command read <deleteall.fi branch samplebranch delete write -
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// Example 8.6 // Comparison of a real and ideal Transformer // form figure 8.21 omegaL_1=100; omegaM=490; omegaL_2=2500; Z=200; N=sqrt(omegaL_2/omegaL_1) // since omegaL_2>>|Z| and k=0.98 the transformer will act almost like an ideal transformer k=omegaM/sqrt(omegaL_1*omegaL_2); // Let us denote I_out/I_in =...
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# The input is truncated after 2/3 of a rightwards arrow U2192 -> e2 86 92 FLAGS='--strip --expect UTF-8 --utf8' STDIN='\xef\xbb\xbfpartial arrow: \xe2\x86' STDOUT='' STDERR='bom: invalid UTF-8 byte sequence at file offset 18\n' EXITVAL='3'
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//Exa 6.10 clc; clear; close; //given data VP=-6;//in Volt IDSS=8;//in mA disp("We have ID=IDSS*[1-VGS/VP]^2"); disp("Mutual conductance, gm=(delID/delVGS)=IDSS*2*[1-VGS/VP]*(-1/VP)=(-2*IDSS/VP)*[1-VGS/VP]"); //For VGS=0 VGS=0;//in Volt IDSS=1:8;//in mA for i=1:8 gm(i)=-2*IDSS(i)/VP end title('gm ver...
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//Initilization of variables L=14 //feet W=18 //lb theta1=60 //degrees theta2=30 //degrees L1=10 //ft //Calculations //Taking moment about point B Rd=(W*(L/2)*cosd(theta1)*cosd(theta2))/L1 //lb //Summing all the forces in the horizontal direction T=Rd*cosd(theta2) //lb //Result clc printf('The value of Rd ...
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// Scilab code Ex14.9 : Pg:723(2011) clc;clear; R_L = 1000; // Load resistance across HWR, ohm V_rms = 200; // Rms value of voltage supply, V V0 = sqrt(2)*V_rms; // Peak value of voltage, V I0 = V0/(R_L*1e-03); // Peak value of current, mA I_dc = I0/%pi; // Average value of current, mA I_rms = I0/2; // ...
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// clear all xdel(winsid()); clear; //mclose('all'); //opens file fd_gt=mopen('/home/andreu/dataSets/people_tracking/reem/ground_truth/20140925_twoPeople.txt','r'); fd_tracks=mopen('/home/andreu/dataSets/people_tracking/reem/tracker_results/20140925_twoPeople_1_tree_all.txt','r'); //GROUND TRUTH PARSING gt = list()...
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// exa 7.11 format('v',5);clc;clear;close; // Given data Rin = 2;//resistance in Mohm Cin = 50;//capacitance in pF Cin = Cin * 10^-12;// in F // (R1+Rin)/Rin = 10; R1 = 9*Rin;//resistance in Mohm disp(R1,"The value of R1 in MΩ is"); R1 = R1*10^6;// in ohm Rin = Rin * 10^6;// in ohm // While balance equation ...
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// Scilab code Ex5.30: Pg:236 (2008) clc;clear; L_1 = 5e-05; // Limit of resolution of microscope, cm l = 25; // Least distance of distiinct vision, cm theta_1 = 1.5; // Angular limit of resolution of eye, minute theta_2 = theta_1/60*%pi/180; // Angular limit of resolution of eye, radian L_2 = l*theta...
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//Chapter 10 //Example 10_2 //Page 235 clear;clc; area=0.775; pr=200; pf=1; v=3300; n=0.9; sr=1.725*1e-6; ps=pr*1000/n; loss=ps-pr*1000; i=pr*1000/v; r=loss/2/i^2; l=r*area/sr; printf("Sending end power = %.0f W \n\n", ps); printf("Line losses = %.0f W \n\n", loss); printf("Line current = %.1f A \n\n", i); printf("...
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//Example 7.1 //Gauss-Jordan Two Array Method //Page no. 254 clc;clear;close; A=[2,6,1;3,9,2;0,-1,3]; //matrix C=eye(3,3); //Unit Matrix for i=1:3 //interchange of row 1 and 2 B(1,i)=A(1,i); A(1,i)=A(2,i); A(2,i)=B(1,i); B(2,i)=C(1,i); C(1,i)=C(2,i); ...
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// Y.V.C.Rao ,1997.Chemical Engineering Thermodynamics.Universities Press,Hyderabad,India. //Chapter-12,Example 2,Page 427 //Title: van Laar parameters and t-x-y data //================================================================================================================ clear clc //INPUT //For co...
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//19MCMI07 //Rohan Yadav x = 0:5; y = [0 10 25 36 52 59]; x_new = 0:.01:5; y_new = interp1(x,y,x_new,'spline'); plot(x,y,'d') legend off plot(x_new,y_new) title('Velocity versus Time','fontsize',5) ylabel('Miles per Hour','fontsize',5) xlabel('Time, seconds','fontsize',5) legend('Data Points','Cubic Spline Interpolati...
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clc(); clear; //Given : h = 1.05*10^-34; //planck's constant in Js m = 9.1*10^-31; //electron rest mass in kg c = 3*10^8; //Speed of light in m/s b = 1.7*10^-15; // range of nuclear force in m m_pi = h/(b*c); // rest mass of a pion in kg t = m_pi/m; // times the rest mass of an electron printf("Rest mass of a ...
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clc;clear; A = [1 0;0 1;1 1]; b = [1;1;0]; disp("The given matrix A is:") disp(A); disp(b, "b: "); x = (A'*A)\(A'*b) C = x(1,1); D = x(2,1); disp(C,"C: "); disp(D,"D: "); disp("The best fit line is b = C+Dt")
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//** INRIA / SCILAB / Roberto Bucher / Simone Mannori / Paolo Gai //** 16 Jan 2008 //** // Modified by Roberto Bucher roberto.bucher@supsi.ch from the original // CodeGeneration_.sci // // Input editor function of Scicos code generator // // //** 10 Set 2007 : cleaner startup code by Simone Mannori //** 15 Aug 2009 : H...
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units VMG /LiquidPhases = 2 $thermo = VirtualMaterials.Advanced_Peng-Robinson / -> $thermo commonproperties VapFrac T P MoleFlow MassFlow Energy H S MolecularWeight MassDensity Cp ThermalConductivity Viscosity molarV ZFactor displayproperties VapFrac T P MoleFlow MassFlow Energy H S MolecularWeight MassDensity Cp ...
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//example 13 //Calculating mass flow of steam in tank clear clc vf1=0.001725 //in m^3/kg vf2=0.0016 //in m^3/kg uf1=368.7 //in kJ/kg uf2=226 //in kJ/kg vg1=0.08313 //in m^3/kg vfg2=0.20381 ug1=1341 //in kJ/kg ufg2=1099.7 //in kJ/kg Vf=1 //initial volume of liquid in m^3 Vg=1 //initial volume of vapor in m^...
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clc //initialisation of variables S= 5 //ft F= 70 //lbf a= 4 //degrees l= 1 //ft d= 0.002378 //slug/ft^3 u= 120 //ft/sec //CALCULATIONS L= F*cosd(a) D=F*sind(a) S1= S*l p= 0.5*d*u^2 Cl= L/(p*S1) Cd= D/(p*S1) //RESULTS printf (' coefficient of lift= %.2f',Cl) printf (' \n coefficient of drag= %.4f',Cd) ...
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//exapple 4.3 clc; funcprot(0); // Initialization of Variable pi=3.14; Cd=0.61; rho=999; rhoo=877;//density of oil g=9.81; h=75/100; d=12.4/100;//dia of orifice d1=15/100;//inside diameter nuo=1/rhoo;//specific volume of oil //calculation //part1 delP=h*(rho-rhoo)*g; A=pi*d^2/4; G=Cd*A/nuo*sqrt(2*n...
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// Example 12_11 clc;funcprot(0); // Given data T_DB1=35.0;// °C phi_1=80/100;// The relative humidity T_DB3=20.0;// °C phi_2=40.0/100;// The relative humidity // Calculation h_1=110;// kJ/kg dry air h_3=35;// kJ/kg dry air Qbym_a=h_3-h_1;// kJ/kg dry air printf("\n The heat transfer rate per unit mass flo...
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//Problem 6.11: What capacitance must be connected in series with a 30 μF capacitor for the equivalent capacitance to be 12 μF? //initializing the variables: C1 = 30E-6; // in Farads Cs = 12E-6; // in Farads //calculation: // in Series C2 = 1/[(1/Cs) - (1/C1)] printf("\n\nResult\n\n") printf("\n (a)Capaci...
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@relation banana @attribute At1 real[-3.09,2.81] @attribute At2 real[-2.39,3.19] @attribute Class{-1.0,1.0} @inputs At1,At2 @outputs Class @data 1.0 1.0 -1.0 -1.0 1.0 -1.0 1.0 -1.0 -1.0 -1.0 -1.0 -1.0 -1.0 -1.0 -1.0 -1.0 1.0 1.0 -1.0 -1.0 -1.0 -1.0 -1.0 -1.0 1.0 1.0 1.0 1.0 -1.0 -1.0 -1.0 -1.0 1.0 -1.0 1.0 1.0 -1.0 -1...
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function [filter] = create_lowpass_filter(N, cutoff, thres) N = (N - modulo(N, 2)) / 2 cutoff = floor(2 * N * cutoff) filter = ones(1, N) * thres filter(1, 1 : cutoff) = 1.0 filter = [1. filter flipdim(filter, 2)] endfunction function [filter] = create_highpass_filter(N, cutoff, thres) N = (N -...
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function c = interpnewton(x,f) // Autores: Hector E. Gomez Morales // Funcion que realiza la interpolacion de Newton dado un conjuntos de puntos y sus imagenes. //***************************************************************************** //->Entrada // x (Vector Real) - Vector columna que contiene los numeros x(i) /...
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//Example7.7 // to design an active high pass filter with cut-off frequency 25KHz clc; clear; close; fc = 25 ; // KHz C = 0.1 ; //nF // we assume // the cut-off frequency of active high pass filter is given by // fc = 2*%pi*R3*C; // R3 can be calculated as R3 = (1/(2*%pi*fc*C)); disp('The resistance R3 is =...
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// Scilab code Exa13.3 : : Page-600 (2011) clc; clear; N_0_235 = 1; // Number of uranium 235 per 238 N_0_238 = 20; // Number of uranium 238 for one uranium 235 sigma_a_235 = 683; // Absorption cross section for uranium 235, barn sigma_a_238 = 2.73; // Absorption cross section for uranium 238, barn...
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clc //Initialization of variables p1=100 //psi p2=10 //psia pa=14.7 //psi T2=468 //R T2r=528 //R R=1.986 M=29 //calculations disp("From air tables,") phi1=0.06657 phi2=0.03762 ds=phi1-phi2 phi11=0.19569 phi12=0.06657 ds2= phi12-phi11 - R/M *log(p2/p1) //results printf("In case 1, change in entropy = %...
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-- Fuzzy Logix, LLC: Functional Testing Script for DB Lytix functions on Netezza -- -- Copyright (c): 2014 Fuzzy Logix, LLC -- -- NOTICE: All information contained herein is, and remains the property of Fuzzy Logix, LLC. -- The intellectual and technical concepts contained herein are proprietary to Fuzzy Logix, LLC. -...
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// Transformation between vector and matrix function v = mat2vec( mat ) v = mat(:); endfunction function mat = vec2mat( v, n ) mat = matrix(v,n,n); endfunction // KBF differential equation function dX = KBF_de(t,X,ndim,y,A,D,C,Q,R,A2) xMean = X( 1:ndim ); //推定値(期待値)成分 xCov = X( (ndim+1):$ ); //共分散成分 ...
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clc //initialisation of variables Cd= 0.95 m= 300 //ft V= 8 //ft/sec d= 6 //ft n= 6 s= 40 //ft g= 32.2 //ft/sec^2 dh= 0.11 //CALCULATIONS h= (V^2/(g+(d/3)))*(1.1*(m/(s*n))^2-1) h1= (V^2/(2*g))*(1.1*(m/(s*n))^2-(d/(s/n)))+dh //RESULTS printf ('afflux upstream= %.2f ft',h1)
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sqrt(2^3): 2;1,4,*...4 sqrt(3^3): 5;5,10,*...10 sqrt(4^3): 8; sqrt(5^3): 11;5,1,1,/...22 sqrt(6^3): 14;1,2,3,2,*...28 sqrt(7^3): 18;1,1,11,1,5,3,1,17,1,*...36 sqrt(8^3): 22;1,1,1,2,6,11,6,*...44 sqrt(9^3): 27; sqrt(10^3): 31;1,1,1,1,1,6,2,2,15,2,*...62 sqrt(11^3): 36;2,14,10,2,1,4,1,1,6,1,2,1,35,1,*...72 sqrt(12^3): 41...
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X= [2.2 3.4 1.6 0.8 2.7 3.3 1.6 2.8 2.5 1.9] upperlimX = 3 lowerlimX = 2; upperlimlogX= log(upperlimX); lowerlimlogX = log(lowerlimX); logX = log(X) samplemean= mean(logX) samplesd= sqrt(variance(logX)) //disp(samplemean) //disp(samplesd) prob = cdfnor("PQ", upperlimlogX, samplemean, samplesd) - cdfnor("PQ"...
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//Example 10_33 //Find the inverse Z-transform clc; clear; z=poly(0,'z'); x=ldiv((z+1),(z-1/3),4); disp(x,'x[n]=');
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//Variable declaration Vbb=5 //base voltage of bipolar transistor(V) Vbe=0.7 //base emitter voltage drop(V) in active region Rb=50 //base resistance(ohm) beeta=50 //current gain Re=1.8 //emitter resistance(k ohms) Vcc=10 //su...
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//design knucle joint clc //solution //given P=70*10^3//N ftur=420//N/mm^2//for rod//ultimate point stress ftup=510//N/mm^2//for pin tu=396//N/mm^2 Fs=6 ftr=ftur/Fs//N/mm^2//yeild t=tu/Fs//N/mm^2 pi=3.14 //let d be dia of rod //P=(pi/4)*d^2*ftr=55*d^2 //d=sqrt(P/55)//mm printf("the diameter of bolt is,%f...
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//Exa 5.2 clc; clear; close; format('v',6); //Given Data : m=2;//Kg T1=300+273;//Kelvin T2=150+273;//Kelvin T0=20+273;//Kelvin Cp=0.45;//KJ/KgK deltaQ=m*Cp*(T1-T2);//KJ deltaS=m*Cp*log(T1/T2);//KJ/K A=deltaQ-T0*deltaS;//KJ disp(A,"Reversible work or Available energy in KJ : "); UA=T0*deltaS;//KJ disp(...
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8_3.sce
clc; h1=3442.6; h2=2713; h6=3487; h7=2535; h3=112; TW=(h1-h2)+(h6-h7); Q=(h1-h3)+(h6-h2); Ceff=TW/Q; disp(Ceff,"cycle efficiency is:"); ssc=1/TW; disp("kg/kW h",ssc,"specific steam consuption is:")
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example26_6.sce
r=300; x_l=400; i=2.6; disp("Part a"); p=i^2*r; disp("the true power (in W) is"); disp(p); disp("Part b"); q=i^2*x_l; disp("the inductive reactive power (in VAr) is"); disp(q); disp("Part c"); s=sqrt(p^2+q^2); disp("the apparent power (in kVA) is"); disp(s*10^(-3));
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//Example 19.5 clc q=1.6*10^-19 B=.35 r=14*10^-2//in m m=1.67*10^-27//kg v=(q*B*r)/m disp(v,"Velocity in m/s=")
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//chapter 6 //example 6.9 //page 267 printf("\n") printf("given") hie=2.1*10^3;hfe=75;R1=10*10^3;R2=10*10^3;Re=4.7*10^3;Rl=12*10^3;rs=1*10^3; disp(" Rl is not connected") hic=hie hfc=1+hfe Zb=hic+hfc*(Re) Zi=(R1*R2*Zb)/(R1+R2+Zb) Ze=(hic+(R1*R2*rs)/(R1+R2+rs))/hfc Z0=(Ze*Re)/(Ze+Re) disp(" when Rl is conne...
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9_4.sce
clc //Initialization of variables g=32.2 A=0.0218 //ft^2 P1=25.6 //psia T1=540 //K k=1.4 R=1715 //calculations G=g*A*P1*144/sqrt(T1) *sqrt(k/R *(2/(k+1))^((k+1)/(k-1))) //results printf("Flow rate = %.2f lb/s",G)
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//Example 11.7: potential drop and capacity if booster clc; clear; close; //given data : format('v',8) ix=250;//amperes vb=2;//in volts r=0.02;//in ohms x=poly(0,"x"); p=-27.6+16*x+0*x^2;// y=roots(p);//km pc=vb+(ix*r*(1.6)^2)/2;//in volts pd=((ix*r*(y^2))/2);//in volts tcurr= (1.6*ix)+((ix*(3.2-y)));//in amperes vnf=r...
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//Example 9.6 //find ampere-hour capacity of a batery clc; clear; close; I=20;// in amperes t=15;// in hours Ah=I*t;// ampere hour capacity of the battery disp(Ah,"ampere hour capacity of the battery in A-h")
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//Tested on Windows 7 Ultimate 32-bit //Chapter 11 Oscillators and Multivibrators Pg no. 355 and 356 clear; clc; //Given //Figure E 11.1 L=20D-3;//colpitts inductance in henry C1=0.2D-6;//colpitts capacitor C1 in farads C2=0.02D-6;//colpitts capacitor C2 in farads //Solution Ce=C1*C2/(C1+C2);//equival...
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function [rvecs tvecs] = calibrateCamera(list_size,obPts,impts,width,cols,camera1,dist) [rvecs tvecs] = opencv_calibrateCamera(list_size,obPts,impts,width,cols,camera1,dist) endfunction
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Name=LDDH Goated PlayerCharacters=EGODEATH BotCharacters=WHW.bot IsChallenge=true Timelimit=60.0 PlayerProfile=EGODEATH AddedBots=WHW.bot PlayerMaxLives=0 BotMaxLives=1 PlayerTeam=1 BotTeams=2 MapName=boxer.map MapScale=6.0 BlockProjectilePredictors=true BlockCheats=true InvinciblePlayer=false InvincibleBots=false Time...
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//EXAMPLE 4-57 PG N 265-266 Z1=[200 +%i*4;0 5+%i*10]; Z2=[2+%i*5 %i*4;%i*4 5+%i*10]; I1=det(Z1/Z2); disp('i) Current (I1) is = '+string (I1) +' A '); Z3=[2+%i*5 %i*4;%i*4 5+%i*10]; Z4=[2+%i*5 %i*4;%i*4 5+%i*10]; I2=det(Z3/Z4); disp('ii) Current (I2) is ...
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// Ex16_1 Page:306 (2014) clc;clear; n1 = 1.43; // Refractive index of core n2 = 1.40; // Refractive index of cladding theta_c = acosd(n2/n1); // Propagation angle, degree NA = sqrt(n1^2 - n2^2); // Numerical aperture theta_a = asind(NA); // Acceptance angle, degree printf("\nPropagation angle = %...
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//Chapter 1: Structure and Bonding //Problem: 2 clc; //Declaration of Constant c = 3 * 10 ** 8 // speed of light,in m/sec //Declaration of Variable f = 5 * 10 ** 16 // frequency,in cycles/sec // Solution v = f / c mprintf("The wave number is %.2e cycles/m",v)
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calibSimplexMeanSquares_04:01:41.170 PM 07-juin-2013.sci
ms=[];incomemean=[];bref=[];bnorm=[]; ms(1)=5.404009726410362E7; incomemean(1)=17000; bref(1)=12000; bnorm(1)=30000; ms(2)=4.734768931743491E7; incomemean(2)=17000; bref(2)=13000; bnorm(2)=30000; ms(3)=5.385240457007288E7; incomemean(3)=17000; bref(3)=12000; bnorm(3)=31000; ms(4)=1.7077150873775084E7; incomemean(4)=180...
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clear //Given m=9*10**-31 v=3*10**7 q=1.6*10**-19 //C B=6*10**-4 //Calculation // r=m*v/(q*B) f=q*B/(2.0*%pi*m) E=(0.5*m*v**2)/1.6*10**-16 //Result printf("\n Energy is %0.2f Kev",E*10**32)
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clc T1=303; //K p1=1; //bar rc=9; re=5; n=1.25; D=0.25; //m L=0.4; //m R=287; cv=0.71; cp=1; num=8; //no. 0f cycles/sec disp("(i) Pressure and temperatures at all salient points =") p2=p1*(rc)^n; disp("p2=") disp(p2) disp("bar") T2=T1*(rc)^(n-1); disp("T2=") disp(T2) disp("K") //T4=1.8*T3 //...
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clear //Given R=30 //ohm u=-10.0 h1=5 //Calculation f=R/2.0 v=1/((1/f)-(1/u)) h2=(-v*h1)/u //Result printf("\n Position of the image is %0.3f cm", v) printf("\n Size of the image is %0.3f cm",h2) printf("\n The image is virtual")
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clc //a) INELASTIC //for sphere 1 ,mass=m1 and initial velocity=u1 //for sphere 2 ,mass=m2 and initial velocity=u2 m1=100//lb u1=10//ft/s m2=50//lb u2=5//ft/s v=(m1*u1+m2*u2)/(m1+m2) //change in kinetic energy //initial kinetic energy = ke1 ke1=(m1*(u1^2)+m2*(u2^2))/(2*32.2) //Kinetic Energy after inelas...
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pathname=get_absolute_file_path('3_2.sce') filename=pathname+filesep()+'3_2data.sci' exec(filename) clear J= (%pi*a^3 *b^3)/(a^2 +b^2); twistrate= T/(G*J);//rate of twist x=poly(0,"x"); y=poly(0,"y"); deff("[Tzy]=f(x)","Tzy=2*T*x/(%pi*b*a^3)");//τzy deff("[Tzx]=f1(y)","Tzx=-2*T*y/(%pi*a*b^3)");//τzx function ...
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//Example 5_6 clc(); clear; //To calculate the interplanar spacing and wavelength n1=1 theta1=23 //units in degrees n2=3 theta2=60 //units in degrees lamda1=97 //units in pm lamda2=(n2*lamda1*sin(theta1*(%pi/180)))/(sin(theta2*(%pi/180))) //units in pm d=(n2*lamda1)/(2*sin...
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curl "localhost/recipes/rate.php?username=lmitchell&author_name=nloison&recipe_name=mac%20and%20cheese&rating=5"
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//Problem 18.05: The op amp shown in Figure 18.6 has an input bias current of 100 nA at 20°C. Calculate (a) the voltage gain, and (b) the output offset voltage due to the input bias current. (c) How can the effect of input bias current be minimised? //initializing the variables: Ii = 100E-9; // in Amperes T = 20; ...
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//determine dia of the wheel clc //solution //given d=50//mm p=12.5//mm W=10000//N D=60//mm R=30//mm u=0.15//tan(q)=u u1=0.18 P1=100//N //tan(a)=p/(%pi/d)=b=0.08 b=0.08 //P=W*tan(u+a) //P=W*[(tan(a)+tan(q))/(1-tan(a)*tan(q))] P=W*[(b+u)/(1-(b*u))]//N T=(P*d/2)+(u1*W*R)//N-mm //let D1 be dia of wheel ...
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clc clear //Initialization of variables k=1.4 R=53.3 //lb-ft/lb R p0=100 //psia T0=534.6 //R g=32.2 //ft/s^2 d=0.5 //in Nm1=1 A=2/144 //ft^2 //calculations disp("Exit mach number is found using trial and error") Nme=2.44 rho0=p0*144/(g*R*T0) G= A*sqrt(k*p0*144*rho0) *(2/(k+1))^((k+1)/(2*(k-1))) pe=p0*(1...
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//Chapter 3: Thermodynamic and Chemical Equilibrium //Problem: 16 clc; //Declaration of Constant R = 8.314 //in J per K mol //Declaration of Variables n = 5 // moles T = 27 // C V1 = 50.0 // L, Initial Volume V2 = 1000 // L, Final Volume //Solution T = T +...
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// Exa 8.16 clc; clear; close; //given data Vin= 2;//in volt Vout= 10;//in volt R=100;// in kohm R=R*10^3;//in ohm C=0.1;// in micro F C=C*10^-6;//in F // Formula Vout = -1/(R*C)*integrate('Vin','t',0,t) = -Vin*t/(R*C) t= Vout*R*C/Vin;// in sec disp(t,"The maximum time upto which the reference voltage can...
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S1=0.86//specifc gravity of liquid in pipe A S2=1//Specifc gravity of manometric liquid h1=150//mm h2=90//mm H=720//mm of Hg