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load HackComputer.hdl; output-file TestCaseLoop.out; //Loading program into Instruction memory ROM32K load TestCaseLoop.hack; //Calculating the sum of the first 99 natural numbers=1+2+..+99 //Result is stored at address 17 output-list RAM64[17]%D1.9.1; set reset 1; tick,tock; set reset 0; output; rep...
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<session design_hash="00000000000000000000" m_completed_compilation="false"> <stp_instance is_hdl_type="false" m4k_usage="0" m512_usage="0" mram_usage="0"> <sci_design_instance entity_name="" instance_hpath="" instance_name="auto_signaltap_0" ir_bits="0" is_auto_index="false" is_imported_from_partition="false" is...
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// Example 10.9 // Design of quadratic optimal regulator system clear; clc; xdel(winsid()); //close all windows mode(0); A = [0 1;0 0]; B = [0;1]; Q = [1 0; 0 1]; R = [1]; // solve the riccati equation P = riccati(A, B*inv(R)*B', Q,'c') K = inv(R)*B'*P E = spec(A - B*K) // eigen values
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<?xml version="1.0" encoding="UTF-8" standalone="yes"?> <TestCase> <Step> <EventId>e16</EventId> <ReachingStep>false</ReachingStep> </Step> <Step> <EventId>e25</EventId> <ReachingStep>false</ReachingStep> </Step> <Step> <EventId>e54</EventId> <Reaching...
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// Exa 2.3 clc; clear; close; // Given data R1 = 2.2*10^3;// in ohm R2 = 4.7*10^3;// in ohm R_AB = (R1*R2)/(R1+R2);// in ohm Vi = 20;// in V V_o = (Vi * R_AB)/(R_AB+R1);// in V PIV= Vi;// in volts disp(V_o,"The output voltage in V is"); disp(PIV,"Peak inverse voltage in volts is : ")
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// A Textbook of Fluid Mecahnics and Hydraulic Machines - By R K Bansal // Chapter 1-Properties of Fluid // Problem 1.12 //Given Data Set in the Problem kin_visc=6*10^-4 SG=1.9 dens_water=1000 //Calculations dens_liquid=SG*dens_water visc=dens_liquid*kin_visc //Kinematic viscosity=Dynam...
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clear all; clc; //This numerical is Ex 2_1,page 18. //These are examples given in the book,they are used to teach conversions from one unit to another rho=0.075//lbm/ft^3 V=120 RHO_c=rho/32.2//rho conerted to slug/ft^3 disp("The initial value of rho was given in lb/ft^3. In order to convert it to slug/f...
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// exa 5.6 Pg 153 clc;clear;close; // Given Data n=5;// no. of rivets P=45;// kN alfa=30;// degree tau=120;// MPa Pd=P/n*1000;// N (direct shear load in rivet) // C.G. of rivet group // values below are collected direct from figure x_bar=(3*200)/5;// mm y_bar=(1*50+1*150+1*100+1*200)/5;// mm ex=300+x_bar+y_bar;//mm ...
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// Example 2.29, page no-48 clear clc h=1 k=1 l=1 a=3*10^-10 d=a/sqrt(h^2+k^2+l^2) printf("\nThe interplanar spacing for the plane(101) is %.3f*10^-10 m",d*10^10)
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// Example 7.4, page no-162 clear clc r=1.85*10^-10//m t=3.4*10^-14//s m=9.11*10^-31//Kg e=1.6*10^-19//C n=5.8*10^28//per m^3 rho=m/(n*t*e^2) printf("\nThe electric resistivity of material is %.3f*10^-8 Ohm-m",rho*10^8) mu=e*t/m printf("\nThe mobility of the electron in a metal is %.2f*10^-3 m^2/v-s",mu*10...
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run.sci
clear; warning off; exec('geragauss.sce',-1); exec('../Plota_Dados_E_Reta/plotdata.sce',-1); exec('../Treinamento_Perceptron/treina_perceptron.sce',-1); exec('../Perceptron/perceptron.sci',-1); W = [rand() rand()]; b = rand(); nc = 2; npc = [20 50]; mc = [3.6 2.1; 6.7 5.2]; varc = [ 0.1 0.2 ; 0.3 0.4]; [X Yd] = gera...
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FIRfilter.sce
clear,xdel(winsid()),clc f0=500 fm=10 Fm=fm/f0 L=52 typ='hn' n=-L/2:L/2 hn=wfir('lp',L,[Fm 0],typ,[0 0]) [H1,F]=frmag(hn,1000) hn=wfir('lp',L,[Fm 0],typ,[0 0])/H1(1) disp(round(hn*2^15)) [H,F]=frmag(hn,1000) scf() subplot(211) plot(hn,'o') subplot(212) plot(F*f0,H) x=[ones(n)*1023 ones(n)*500 ones(n)*100 ones(n)*(-50...
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// This file is part of www.nand2tetris.org // and the book "The Elements of Computing Systems" // by Nisan and Schocken, MIT Press. // File name: projects/03/RightArithmeticBitshift.tst load RightArithmeticBitshift.hdl, output-file RightArithmeticBitshift.out, compare-to RightArithmeticBitshift.cmp, output-li...
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time_rev.sce
//B.) Time Reversal property clear function[X] = dft_s(x) N = length(x) n = 0:1:N-1 w = exp(-1*%i*2*%pi/N) z = n'*n TF = w.^z X = x*TF endfunction clc disp("To Verify : DFT[x(-n)] == X(-k)") x = input("Enter a sequence x(n)=") X = dft_s(x) disp(X,"X(k) = ") N = length(x) n = ...
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clc clear //Initialization of variables disp("From table 1 of keenan and keynes,") p=400 //psia t1=700 //F p2=85 //psia //calculations s2=1.6398 //units/lb t2=350 //F //results printf("Final state of steam is %d psia and %d F",p2,t2)
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function [stk,txt,top]=sci_roots() // Copyright INRIA temp=gettempvar() txt=temp+' = '+stk(top)(1) stk=list('roots(poly('+temp+'($:-1:1),''x''))','0','?','1','1')
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clc; close(); //page no 230 //prob no. 7.2 //v(t)=80*cos[(2*%pi*10^8*t)+20*sin(2*%pi*10^3*t)] --eq //v(t)=A*cos[Wc*t+Bsin(Wm*t)] --eq7-27 //comparing the above 2 equations we get A=80; //volts fc=10^8; //Hz fm=10^3; //Hz B=20; disp('Hz',fc,'(a) The carrier cyclic frequency is '); disp('Hz',fm,...
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//Example 3.1: Combining minterms in karnaugh map clc; //clears the console clear; //clears all existing variables disp(' The given function is having three input variables A , B and C') disp(' the minterms in adjacent squares can always be combined using the adjacency property') disp(' m0 + m1 : A''B''C''+ A''B''...
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//Ex:9.12 clc; clear; close; Vs=3*10^4;// saturation in m/s W=25*10^-6;// depletion layer width in m tr=W/Vs;// transit time in sec f=0.35/tr;// max 3 dB bandwidth Hz f1=f/10^6;// max 3 dB bandwidth Hz printf("The max 3 dB bandwidth =%d MHz", f1); printf("\n The answer is wrong in the textbook");
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clc; // page no 753 // prob no 20.2.1 // An optic fiber is made of glass with following details n1=1.55;//RI of glass n2=1.51;//RI of clad // NA of the fibe is given as NA=n1*sqrt(2*(n1-n2)/n1); disp(NA,'The numerical aperture is'); // Acceptance angle is given as acc_angle=asind(NA); disp(acc_angle,'The acc...
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B=100; R=0:10:100; S=3; P=10; l=20; O=1-exp((-l*(2^(R/B)-1)*S^2)/P); plot(R,O); xlabel("rate of transmission"); ylabel("probability of outage"); title("Outage probability");
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printf("\t example 7.5 \n"); printf("\t approximate values are mentioned in the book \n"); T1=175; // inlet hot fluid,F T2=150; // outlet hot fluid,F t1=85; // inlet cold fluid,F delt1=T2-t1; //F printf("\t delt1 is : %.0f F \n",delt1); U=15; // assumption,Btu/(hr)*(ft^2)*(F) theta=8000; // operating hours,hr ...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Engineering Thermodynamics by Onkar Singh Chapter 4 Example 17") disp("NOTE=>In question no. 17 expression for (minimum theoretical ratio of heat supplied from source to heat absorbed from cold body) is derived wh...
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// Scilab Code Ex2.17: Page-72 (2013) clc; clear u = 931.5; // Energy equivalent of 1 amu, MeV/u c = 1; // For simplicity assume speed of light in vacuum to be unity, m/s E_B = 4.24; // The dissociationenergy of the NaCl molecule, MeV M = 58.44*u; // Energy corresponding to molecular mass of NaCl, MeV ...
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clear all; clc; disp("Scilab Code Ex 7.3 : ") //Given: udl = 6.5; //kN l_bc = 8; //m l = 150/1000;//m t = 30/1000;//m //Internal Shear: w = udl*l_bc/2; l_wc = l_bc/4; l_bw = l_bc - l_wc; V = (w*l_bw)/l_bc; R_b = w - V; //Section Properties: y1= l/2; A = (l*t); y2= l+(t/2); y_dash = (y1*A + y2*A...
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// The code was developed under Horizon2020 Framework Programme // Project: 748767 — SIMFREE function [y,s] = SSSeQAMcoder(x,M) xM = 0:M-1; b = sqrt(M); L = log2(M); Kmod = 1/sqrt(2*(M-1)/3); yM = zeros(M,L); A=ones(1,L); B=2.^(L-1:-1:0) for n = 1:M yM(n,:) = [bitand(xM(n)*A,B)...
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//(6.5) A 0.3 kg metal bar initially at 1200K is removed from an oven and quenched by immersing it in a closed tank containing 9 kg of water initially at 300K. Each substance can be modeled as incompressible. An appropriate constant specific heat value for the water is cw = 4.2 kJ/kg. K, and an appropriate value ...
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printf "a\nA\n8\n 8" > foo;cat foo | node sort -r; rm foo a A 8 8
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//EXAMPLE 3.14 //ENERGY OF LP DISCREET TIME SIGNAL //PROGRAM REQUIRES MAXIMA SCILAB TOOLBOX clc; clear; syms n wc w; wc = input("the value of wc ( less than %pi)= "); n = -5:0.05:5; for i =0:length (n) hlp(i+1) = (wc/%pi)*sinc((wc*i)/%pi); E(i+1)=(abs(hlp(i+1)))^2; end Energy = sum(E); if (Energy<%inf ) the...
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clc clear //INPUT vl=1;//volume of water in cc vs=1.0908;//volume of ice in cc t=273;//temperature in k p=76*13.6*981;//pressure in dynes/sq.cm l=80;//latent heat of fusion in cal j=4.2*10^7;//joules constant in erg/cal //CALCULATIONS v=vl-vs;//change in volume T=(v*t*p)/(j*l);//change in melting point o...
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Hethane= -1559.9 //Kj/mol Hethene= -1411 //Kj/mol Hhydrogen= -285.84 //Kj/mol
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function[za]=ztransfer(sequence,n) z=poly(0,'z','r') za=sequence*(1/z)^n' endfunction x1=[2 1 -5 4]; n=-1:length(x1)-2; ztransfer(x1,n)
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clc // Given that P = 2e5 // radiated power in W f = 98e6 // frequency in Hz h = 6.62e-34 // Planck constant in J-sec c = 3e8 // speed of light in m/sec e = 1.6e-19 // charge on an electron in C // Sample Problem 2 on page no. 14.20 printf("\n # PROBLEM 2 # \n") printf("Standard formula used \n") printf(" E = h*mu \...
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load, repeat { vmstep; }
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//Chapter-8,Example8_5,pg 8_35 Z2=250 Z3=200 Z1=50 Z4=Z2*Z3/Z1//magnitude condition theta1=80 theta2=0 theta3=30 theta4=theta2+theta3-theta1//angle condition theta4=theta4*%pi/180//in radians Rx=Z4*cos(theta4)//real part Ry=Z4*sin(theta4)//imag. part Z4=Rx+%i*Ry printf("unknown impedance\n") disp(Z4)
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//2x+3y=42, 5x-y=20 clear; clc; close; x=poly(0,'x'); y=(42-2*x)/3; //equation 1 y=5*x-20; //equation 2 for x=1:20 if((42-2*x)/3==5*x-20) mprintf("x=%i ",x) break end end //substitute the x value in any one of the above equations y=5*x-20;mprintf("y=%i",y) printf("\n the solution is ...
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clc,clear //Example 6.19 //to express an equation in polar coordinates //Given equation is : y=x y_by_x =1; //ratio of y and x tan_theta = y_by_x; theta=atand(tan_theta); //azimuth angle printf('The given equation in polar coordinates is : theta = %.0f degree\n',theta) printf('\nNote: Polar form is same re...
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// Plot of PSD for ideal pulse // (c)2008 Lenny Rayzman //////////SPECIFY///////////////////// samplerate=1000; // Number of points per period (must be multiple of 2) trf=0.4; // Rise and fall time ////////////////////////////////////// tofn=[0:1/(samplerate/2):3]; pps...
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//Example 4.2 //Find DTFT of x[n]=(a^n)u[-(n+1)] clc; syms w a n; x=a^n; X=symsum(x*exp(-%i*w*n),n,-%inf,-1);
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//Ex12_4 clc VI=-15 disp("VI= "+string(VI)+" volts") // Input voltage TSW=2*10^(-3) disp("TSW= "+string(TSW)+" seconds")// triangular wave Sweep time R=10*10^(3) disp("R= "+string(R)+ " ohm") // resistance as ckt. parameter C=0.5*10^(-6) disp("C= "+string(C)+" farad") // capacitance as ckt. parameter S=-VI...
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clc // //Variable declaration t=0.160 // thickness(in) T=24 // Torque(kip.in) //Calculation // Case(a) Area=3.84*2.34 // Area bounded by centre line(in**2) t=(T)/(2*t*Area)...
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//A Textbook of Chemical Engineering Thermodynamics //Chapter 4 //Second Law of Thermodynamics //Example 12 clear; clc; //Given //This is a theoretical question and does not involve any numerical computation //end
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function x = GAUSS (a,b) n=size (a, "c") x=zeros(n,1) //a. Forward elimination for k= 1: n-1 for i = k + 1: n fact = a(i,k)/a(k,k); for j = k + 1: n a(i,j) = a(i,j) - fact * a (k,j); end b(i) = b(i) - fact * b(k); end ...
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function update_checkbox() c = get("compare").Value; if c==0 then set("country_compared","enable","off") else set("country_compared","enable","on") end endfunction
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disp( 'a license plate contains two letters followed by three digits where first digit can not be zero') n =26;//number of english letters n*n; //number of ways of choosing two letters in the license plate p =10;//number of digits (0-9) (p -1) *p*p; // number of ways to select the three digits with the first digit ...
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// Computation of pH in a titration of weak acid and strong base clear; clc; printf("\t Example 16.5\n"); InitCH3COOH=0.1;//Initial concentration of CH3COOH solution, M VCH3COOH=25;//volumeof CH3COOH, mL nCH3COOH=InitCH3COOH*VCH3COOH/1000; Ka=1.8*10^-5;//equilibrium constant of acid, M Kb=5.6*10^-10;//equ...
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INCIDENCE DU SEPA POUR LES ACTEURS CONCERNÉS >P O U R L E S C O N S O M M AT E U R S Les instruments de paiement SEPA seront disponibles dans l' ensemble de la zone euro , ce qui facilitera la vie des consommateurs . Courtiers en valeurs mobilières et produits financiers dérivés ( 12 séries au total ) . 6 Titres en eur...
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clc; clear; s = poly(0, 's'); K2 = [0.001, 0.01, 0.1, 1, 10, 20]; K1 = 5 * K2; t = 0:0.01:10; plotcolors = ["scilabred4", "scilab blue2", "scilab green4","scilabmagenta4", "black", "royalblue"]; scf(); for i=1:size(K2, 2) k2 = K2(i); k1 = K1(i); g = (s + k1) / (s + k2); G = syslin('c', g); plot2d(t,...
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Filter type is: H5Z_FILTER_NBIT Maximum value in DS1 is: 1890
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// 4.8 clc; n=5; Ql=2^n; Range=(Ql-1)*1; disp('range is 0-31 V with each step representing 1V') Qe=27.39-27; printf("\nquattization error =%.1f V",Qe)
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clc(); clear; // To calculate the average film coefficient of heat transfer D=0.0752; // Outer diameter in ft T1=61.4; // Pipe surface temperature in degF T2=69.9; // Air temperature in degF Tf=(T1+T2)/2; ...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run2"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monitor...
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Td=1*10^(-1*6) Delf=1*10^6//difference in frequency printf("\nDelf= %.f MHz",Delf*10^(-6)); Bc=1/(2*%pi*Td)//coherence bandwidth printf('\ncoherence bandwidth= %.2f kHz',Bc*10^(-3)) if Delf>Bc then disp(,'Correlative fading fading will not be experienced as Delf>Bc') else disp(,'Correlative fading fading will...
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// SAMPLE PROBLEM 6/4 clc;funcprot(0); // Given data m=7.5;// kg rbar=250/1000;// m k_o=295/1000;// m theta_1=0;// degree theta_2=60;// degree g=9.81;// The acceleration due to gravity in m/s^2 // Calculation // SigmaM_o=I_o*alpha; // alpha=28.2*cos(theta); wsquare=48.8;// (rad/s)^2 // SigmaF_n=m*rbar*om...
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//ex5.3 B_DC=100; R1=10*10^3; R2=5.6*10^3; R_C=1*10^3; R_E=560; V_CC=10; V_BE=0.7 R_IN_base=B_DC*R_E; //We can neglect R_IN_base as it is equal to 10*R2 disp(R_IN_base,'input resistance seen from base, which can be neglected as it is 10 times R2') V_B=(R2/(R1+R2))*V_CC; V_E=V_B-V_BE; I_E=V_E/R_E; I_C=I_E;...
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clear; clc; //Example9.8[Heat Loss through Aluminium Framed Windows] //Given:- H=1.2;//Height[m] w=1.8;//Width[m] Ti=22;//Inside temp[degree Celcius] To=-10;//Outside temp[degree Celcius] U_a=6.63,U_b=3.51,U_c=1.92,hi=8.3;//[W/m^.degree Celcius] //Solution:- A_win=h*w;//[m^2] Q_win_a=U_a*A_win*(Ti-To);//[W...
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// Scilab code Ex3.13: Pg 96 (2008) clc; clear; N = 20; // Number of plates in a capacitor A = 6400e-06; // Cross - sectional area of plate, m^2 d = 1.5e-03; // Distance between plates, m epsilon_r = 6.4; // Relative permittivity for mica epsilon_o = 8.854e-12; ...
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//Example 8.3 (a) //Program to find the Voltage Gain of the Amplifier clear; clc ; close ; //Given Circuit Data Bac=150; rin=2*10^3; //Ohms R1=4.7*10^3; //Ohms R2=12*10^3; //Ohms //Calculation Rac=R1*R2/(R1+R2); Av=Bac*Rac/rin; //Displaying The Results in Command Window printf("\n\t The Voltage Gain of th...
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// Exa 8.3 clc; clear; close; format('v',7) // Given data I_Don = 5;// in mA V_GS = 8;// in V V_GST = 4;// in V K = I_Don/((V_GS-V_GST)^2);// in mA/V^2 // Drain current when V_GS= 6 V V_GS= 6;// in V I_D = K*((V_GS-V_GST)^2);// in mA disp(I_D,"The drain current in mA is");
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//example-9.5 //page no-280 //given //stress sigmamean=70 //MPa //stress range sigmarange=210 //MPa //as we know that //sigmamean=(sigmamax+sigmamin)/2 //from this we get //sigmamax+sigmamin=140 -----------(1) //also //sigmarange=sigmamax-sigmamin //so we get //sigmamax-sigmamin=210 ----------(2) /...
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clc; q1=(2*10^-8); //charge in coulomb q2=(-2*10^-8); //charge in coulomb q3=(3*10^-8); //charge in coulomb q4=(6*10^-8); //charge in coulomb s=1; //side in m V=(9*10^9)*(1/s)*(q1+q2+q3+q4); //calculating voltage disp(V,"Voltage in Volts = "); //displaying result
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function [s]=%r_s_lss(s1,s2) //s=%r_s_lss(s1,s2) ou s=s1-s2 // s1 : transfer // s2 : state-space //! // Copyright INRIA [s1,s2]=sysconv(s1,s2) s=s1-s2
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//<la,lb,sig,resid>=armax(r,s,y,u,b0f,prf) //<la,lb,sig,resid>=armax(r,s,y,u,[b0f,prf]) // Identification ARX // Calcule les coefficients d'un ARX n-dimensionnel // A(z^-1)y= B(z^-1)u + sig*e(t) // e(t) est un bruit blanc de variance Id n-dimenssionnel // sig: est une matrice (n,n) // A(...
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load Mux4Way.hdl, output-file Mux4Way.out, compare-to Mux4Way.cmp, output-list a%B3.1.3 b%B3.1.3 c%B3.1.3 d%B3.1.3 sel%B2.2.2 out%B3.1.3; set a 0, set b 0, set c 0, set d 0, set sel %B00, eval, output; set d 1, eval, output; set c 1, set d 0, eval, output; set d 1, eval, output; set b 1, set c 0, set d 0, eval, o...
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//Марчук Л.Б. 5307 подгруппа 3 //Модуль построения графиков АЧХ и ФЧХ function [] = Frequency(Hs) //S = jw //Исследуемый отрезок частот w = 0:0.01:30; Values = freq(numer(Hs), denom(Hs), %i*w); //АЧХ A = sqrt(real(Values)^2 + imag(Values)^2); plot2d(w, A); //Находим...
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clear ; clc; // Example 9.7 printf('Example 9.7\n\n'); // Page no. 243 // Solution //Basis: 3 g mol H2 by reaction (a) // 0.50 g mol C2H4 by reaction (b) // by analysing reaction (a) 0.50 g mol C2H4 corresponds to 0.50 g mol H2 produced in reaction (b) // By using reaction (a) H2_a = 3-0.50 ;// H2 produced in reactio...
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num=10; X= [0.123 0.133 0.124 0.126 0.120 0.130 0.125 0.128 0.124 0.126]; //disp(variance(X)) s2 = variance(X); chi1 = cdfchi("X",num-1,0.95, 0.05 ); chi2 = cdfchi("X",num-1,0.05, 0.95 ); //disp(chi1, chi2) lowerlim = (num-1)*s2/chi2; upperlim = (num-1)*s2/chi1; disp(sqrt(upperlim), "to ",sqrt(lowerlim),"The...
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function [n] = solve(ns) // Dit is een moeilijkere 2D-versie van vpw-posters1d. // // Je begint met een lege muur met onbeperkte afmetingen. // Op deze muur plak je een aantal posters. Deze posters kunnen overlappen. // De vraag is om uit te rekenen hoeveel posters nog zichtbaar zijn // nadat j...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_uncued_run2"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monit...
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//Exa 5.7 clc; clear; close; format('v',7); //Given Data : deltaQ=850;//KJ T=180+273;//Kelvin T0=22+273;//Kelvin deltaS=deltaQ/T;//KJ/K A=deltaQ-T0*deltaS;//KJ disp(A,"Available energy in KJ : ");
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// Examle 3.13 // From Diagram (3.26) Apply KVL to get 24-4I-2I+18I= 0 I=(-24/12); // Current disp(' The value of Current = '+string(I)+' Amp'); V1=4*I; // Voltage across 4 Ohm Resistor p=-(4.5*V1*I); // Power absorbed ...
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exec("projection.sci") exec("Rmat.sci") // theta debe estar en grados function [A, B, C, D] = rotE(u, theta, d) [_A _B _C _D] = projection(d) [R] = Rmat(u, theta) A=R*_A B=R*_B C=R*_C D=R*_D endfunction
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//Example 2.20 //Given //for clay k1=0.533 //[W/(m.K)] //for red brick k2=0.7 //[W/m.K] //Case 1 A=1 //Area x1=0.125 //[m] x2=0.5 //[m] //Resistances r1=x1/(k1*A) //Res of fire clay [K/W] r2=x2/(k2*A) //Res of red brick[K/W] r=r1+r2 //Temperatures T1=1373 //[K] T2=323 //[...
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// Scilab code Ex7.4: Pg.294 (2008) clc; clear; delta_E = 4.5e-05; // Energy splitting, eV mew_B = 5.79e-05; // Bohr magneton, eV/T B = delta_E/(2*mew_B); // Magnetic field, T printf("\nThe magnetic field experienced by 2p electron in hydrogen= %4.2f T", B); // Result // The magnetic field experienced...
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clc; clf; disp "Hello World";
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// PG (489) A = [1 -2;-3 4] norm(A,1) norm(A,2) norm(A,'inf') lam = spec(A) r = max(abs(lam)) //r < = norm(A,2)
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clear // // // //Variable declaration A=100*10**-4 //area(m**2) epsilon0=8.85*10**-12 d=1*10**-2 //seperation(m) V=100 //potential(V) //Calculation C=A*epsilon0/d //capacitance(PF) Q=C*V //charge on plates(C) //Result printf("\n capacitance is %e F",C) printf("\n charge on plates is %e ...
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2 3 2 100 3 5 7 4 8 16 1 20 5 2 ~~~~~~~~~~~~~~~~~~~~~~~~~~ Case #1: NO Case #2: 10
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// Mission U2 // Obtention de l'image pathname = "C:\Users\Jean-Guillaume P\Documents\Exia\A2\Projets\Imagerie\ExoLife\Images\Mission_U\U2_surface.pbm"; img_in = readpbm(pathname); // Application du filtre de sobel afin de ne garder que les contours img_out = filtreSobel(img_in); // Affichage figure; display_gray(im...
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clear; clc; //Example - 7.27 //Page number - 261 printf("Example - 7.27 and Page number - 261\n\n"); //(a) //This part involves proving a relation in which no numerical components are involved. //For prove refer to this example 7.27 on page number 261 of the book. //(b) //This part involves proving a rel...
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//Chapter-9,Example9_5,pg 9_24 P=4 A=P Z=480 phi=20*10^-3//flux(in Wb) Ia=50 Ta=0.159*phi*Ia*(P*Z/A) printf("gross torque\n") printf("Ta=%.3f N",Ta)
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//PCA das imagens de colônias de S. cerevisiae irradiadas com 2Gy e do controle. clear, clear all, clearglobal() //stacksize(2e7) //------------- compressao por Wavelet ------------------- n= 34;// numero de dados totais n1 = 12; //numero de amostras da classe 1 = controle n2 = 8; //numero de amostras da cl...
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clear; clc; // Illustration 8.5 // Page: 299 printf('Illustration 8.5 - Page: 299\n\n'); // solution //****Data****// // a = NH3 b = H2 c = N2 w = water P = 2;// [bars] Temp = 30;// [OC] L = 6.38;// [kg/s] W = 0.53;// [weir length,m] pitch = 12.5/1000;// [m] D = 0.75;// [Tower diameter,m] hW = 0.0...
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clc // // // //Variable declaration s=2.143*10**-3 mu=1.542 //refractive index lambdaa=5893*10**-10 //Wavelength Beta=0.347*10**-3 //Calculations t=(s*lambdaa*10**6)/(Beta*(mu-1)) //Result printf("\n The refractive index is %0.2f mu m",t)
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// Example A-6-6 // Root locus clear; clc; xdel(winsid()); //close all windows // please edit the path // cd "/<your code directory>/"; // exec("rootl.sci"); s = %s; G = syslin('c',1,s * (s + 1) * (s^2 + 4*s + 13)); rootl(G,[-6 -5; 6 5],'Root locus plot for 1/ [s * (s + 1) * (s^2 + 4*s + 13]'); // the same method ...
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fid=mopen("main.dat","r") // skip header header=mfscanf(fid,"%s") // read up to eof [N,tick,n1,dat,tim,f1,f2,f3,f4]=mfscanf(-1,fid,"%6s,%d,%d,%d,%f,%f,%f,%f\n") mclose(fid)
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clc //initialization of varaibles h1=1183.2 //B/lb hg=1198.4 //B/lb hfg=843 //calculations x=1- (hg-h1)/hfg //results printf("Quality = %.3f",x)
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<?xml version="1.0" encoding="UTF-8" standalone="yes"?> <AutoTestC version="2.0.0"> <Pulse>CUSTOM WAVE</Pulse> <Title>Test</Title> <Organization>FIAT</Organization> <Standard>9.90111-01 2012</Standard> <Item>4.2.2 Supply Voltage Drop Out</Item> <voltage>13.5</voltage> <count>5</count> <w...
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//Problem 16.03: A capacitor C is connected in parallel with a resistor R across a 120 V, 200 Hz supply. The supply current is 2 A at a power factor of 0.6 leading. Determine the values of C and R. //initializing the variables: pf = 0.6; // power factor V = 120; // in Volts f = 200; // in Hz I = 2; // in Amperes...
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//Initilization of variables w=50 //lb wind load W=60 //lb weight of door //Calculations //Calculation as system of linear equations A=[0 0 33;1 1 -1;28 10 -28] B=[50*18;-50;-50*24] C=inv(A)*B P=C(3)/cosd(20) D=[-28 -10;1 1] E=[1080-(28*(P*sind(20)));P*sind(20)] F=inv(D)*E By=60 //Result clc printf('The ...
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//clear// //Caption:Program to determine the phasor of forward propagating field //Example12.1 //page400 clc; close; Eyzt = sym('100*exp(%i*10^8*t-%i*0.5*z+30)'); Eysz = sym('100*exp(%i*10^8*t-%i*0.5*z+30)*exp(-%i*10^8*t)'); disp(Eyzt) disp(Eysz,'Forward Propagating Field in phasor form =') //Result //100*ex...
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clc; pathname=get_absolute_file_path('10_5_soln.sce') filename=pathname+filesep()+'10_5_data.sci' exec(filename) // Solutions: // minimum required pipe flow area, A=(Q/v); //m^2 // minimum inside diameter, ID=sqrt((4*A)/(%pi))*1000; //mm // wall thickness, t1=1; t2=2; //mm // tube inside diameter, D1=20; D2=24; //mm /...
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clc //initialization of varaibles k=1.3 P=250 //psia h0=1263.4 //B/lb w=10000 cv=0.949 vts=3.415 //cu ft/lb //calculations Pratio=(2/(k+1))^(k/(k-1)) Pt=Pratio*P hts=1208.2 //B/lb h2s=891 //B/lb Vts=sqrt(2*32.2*778*(h0-hts)) w=w/3600 //lb/sec at=w*vts/(Vts) V2=cv*sqrt(2*32.2*778*(h0-h2s)) etan=cv^2 h2...
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// calculate medium source resistance, drain voltage // Electronic Principles // By Albert Malvino , David Bates // Seventh Edition // The McGraw-Hill Companies // Example 13-6, page 436 clear; clc; close; // Given data Vp=4 ;// pinchoff voltage in volts Idss=10*10^-3 ;// maximum drain current in amperes ...
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//Caption:Two-tailed Test Concerning the Difference between Two Proportions //Example8.28 //Page281 clc; n1= 150; //sample size w.r.to City-Y n2 = 160; //sample size w.r.to City-X N1 = 135;//number of credit card holders in City-X N2 = 133;//number of creedit card holders in City-Y p1 = N1/n1; // proportion ...
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-- Fuzzy Logix, LLC: Functional Testing Script for DB Lytix functions on Netezza -- -- Copyright (c): 2014 Fuzzy Logix, LLC -- -- NOTICE: All information contained herein is, and remains the property of Fuzzy Logix, LLC. -- The intellectual and technical concepts contained herein are proprietary to Fuzzy Logix, LLC. -...
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clc //initialisation of variables pN2= 79 //percent VN2= 82.3 //m^3 VCO2= 8 //m^3 VCO= 0.9 //m^3 M= 32 //gms M1= 28 //gms //CALCULATIONS P= (pN2/(100-pN2)) z= VN2/P x= VCO2+VCO w= VCO2+(VCO/2)+(VCO2/10) y= 2*w r= y/x TO= x+(y/4) X= (z/TO)-1 AF= z*(M+P*M1)/(12*x+y) //RESULTS printf (' fuel ratio= %.3f...
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clc,clear printf('Example 2.15\n\n') shaft_output = 80*746 //coverted to watts eta= 80/100 //efficiency V=250 N_1=1200 R_a=0.04,R_sh = 250 //armature and shunt field resistance power_input = shaft_output/eta I_L= power_input /V I_sh= V / R_sh I_a = I_L - I_sh E_b1 = V - I_a*R_a gross_mechanical_power= E...