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ac2rc7.sce
//check o/p when as zero vector is passed to the function t=[0]; z=[5]; [k,R0] = ac2rc(t); disp(k); //output //[]
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ex3_11.sce
// Exa 3.11 clc; clear; close; // Given data n_i = 1.5*10^10;// in /cm^3 n_n = 2.25*10^15;//in /cm^3 p_n = ((n_i)^2)/n_n;// in /cm^3 disp(p_n,"The concentration of holes per cm^3 is"); disp(n_n,"Donor impurity per cm^3 is");
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format.sce
mode(-1) R = csvRead("./input_data.log"," ") [T,N] = size(R) T = min(7000, T) t = [1:T]' position = 0.617 * (R(t,3) - 512) / 1024 voltage = R(t,2) clf plot2d(t, voltage , style=2) plot2d(t, position, style=5) D = [t,voltage,position] csvWrite(D, "./input_data_formatted.log", " ")
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Parabola&Hyperbola.sce
clear; clf; dt = 1; t = -5 : dt : 5; x = t.*t; subplot(211); plot(t, x); xgrid(1); xlabel("t", "fontsize", 4); ylabel("x", "fontsize", 4); title("Parabola x = t^2", "fontsize", 4); // x = sqrt(t^2 - 1); x = 1./t; subplot(212); plot(t, x); xgrid(1); xlabel("t", "fontsize", 4); ylabel("x", "fontsize", 4); title("Hyperbol...
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clc //initialization of variables R=53.34 T1=540 //R n=1.4 g=n n2=1.3 P2=90 //psia P1=15 //psia cv=0.171 cp=0.24; eta=0.95 //calculations pv=R*T1 Wk=n*R*T1*((P2/P1)^((g-1)/g) -1) /(n-1) Wn=n2*R*T1*((P2/P1)^((n2-1)/n2) -1) /(n2-1) Wt=R*T1*log(P2/P1) Wx=-Wk/eta dh=cp*T1*(1.52 - 1) Q=dh+Wx/778 //results printf("Heat trans...
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//example 7.6 clc clear //rb=input('Enter the value of the resistance RB in Kohms :'); //dc =input('Enter required duty cycle in % :'); //clk = input('Enter the provided clock frequency in MHz:'); rb=0.75//taking the given values for input dc=25 clk=1 ra = (rb*100/dc) - 2*rb;//mking neccesary calculations ...
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//routh hurwitz criterion for system transfer function given by: // g(s)=1000/(s^3+10*s^2+31*s+1030) s = poly(0,'s'); po = syslin('c',1000/(s^3+10*s^2+31*s+1030));//creates LTI system m = denom(po);//extracts the denominator of the transfer function co = coeff(m);//extracts the coefficients of the denominator ...
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9_3.sce
clc; p2!p1=8; T1=290; y=1.4; T2s=T1*({p2!p1}^[(y-1)/y]); nc=0.8; T2=[(T2s-T1)/nc]+T1; cps=1.005; T3=923; Wi=cps*(T2-T1); Wo=Wi; cps2=1.15; T4=T3-[Wo/cps2] nt=0.85; T4s=T3-[(T3-T4)/nt]; p3=8*1.01; y2=1.333; p4=p3/[(T3/T4s)^{y2/(y2-1)}]; disp("bar",p4,"pressure at entry of the LP."); disp("K",T4,"temperature at the en...
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ex8.sce
//example 3 //calculating increase in entropy clear clc m=1 //mass of saturated water vapour sfg=6.0480 //in kJ/K T=25 //temperature of surrounding air in celsius dScm=-m*sfg //change in entropy of control mass in kJ/K hfg=2257.0 //in kJ/kg Qtosurroundings=m*hfg //heat transferred to surroundings in kJ dSsurr...
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addBlocks.sce
f_addNewBlock = figure("dockable", "off", "infobar_visible", "off", "toolbar_visible", "off", ... "toolbar", "none", "menubar_visible", "on", "menubar", "none", "default_axes", "off", ... "layout", "border", "figure_name", gettext(prodName),... "visible", "on",'closerequestfcn','save(baseDir+''\...
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//Given that N1 = 1200 //turns N2 = N1 R2 = 1.1*10^-2 //in meter R1 = 15*10^-2 //in meter uo = 4*%pi*10^-7 //Sample Problem 31-9 printf("**Sample Problem 31-9**\n") //let's assume i = 1 //in amp B1 = uo*N1*i/(2*R1) phi2 = B1*%pi*R2^2*N2 M = phi2/i printf("The mutual inductance of the two coil is equ...
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example3_20.sce
//example3.20 clc disp("150 kVA, P_i=1.4 kW, P_cu(FL)=1.6 kW") k=150*sqrt(1.4/1.6) format(9) disp(k,"a) kVA for eta_max = kVA*sqrt(P_i/P_cu(FL))= ") disp("For maximum efficieny, P_cu=P_i=1.4kW and cos(phi)=1") disp("Therefore, %eta_max=(VA for eta_max *cos(phi))/(VA for eta_max*cos(phi)+2P_i *100") n=(140.3121*...
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ex9_15.sce
// Exa 9.15 clc; clear; close; format('v',6) // Given data Rating = 8*10^3;// in VA phi= acosd(0.8);// in ° V1 = 400;// in V V2 = 100;// in V f = 50;// in Hz Pi = 60;// in W Wo = Pi;// in W Pcu = 100;// in W // The full load efficiency Eta_f1 = ((Rating*cosd(phi))/((Rating*cosd(phi)) + Pi + Pcu))*100;//...
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Example_3_1.sce
//Caption: Program to determine the Arithmetic Mean //Example 3.1 //Page 40 clc; x = input('Monthly Salaries of Employees'); n = length(x); //Number of Observations X = sum(x)/n; disp(X,'Arithmetic mean of salaries of the employees =') //Result //Monthly Salaries of Employees [12000,14500,8500,13500,13500,17500,11500];...
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7_2.sci
//Inverter Circuits// //Example 7.2// C=1*10^-6;//Capacitance of series inverter circuit in Farads// f=5*10^3;//operating Frequency of series Inverter in Hertz// L=1/(C*(f^2));//value of Inductance under Resonance condition in Henry// printf('value of Inductance at resonance=L=%fHenry',L);
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Ex5_11.sce
clear; clc; disp('Example 5.11'); // aim : To determine the // (a) original and final volume of the gas // (b) final pressure of the gas // (c) final temperature of the gas // Given values m = .675;// mass of the gas,[kg] P1 = 1.4;// original pressure,[MN/m^2] T1 = 273+280;// original temperature,...
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Example9_1.sce
clear; clc; //Caption:To find Q point //Given Data Vcc=22.5//in V Rc=5.6;//in K Re=1;//in K R2=10;//in K R1=90;//in K B=55;//beta V=(R2*Vcc)/(R2+R1);//Thevenin Equivallent Voltage Rb=(R2*R1)/(R2+R1);//Thevenin Equivallent Resistance disp('Volts',V,'The equivallent Vbb ='); disp('ohm',Rb,'The equivall...
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// exa 3.12 Pg 72 clc;clear;close; // Given Data sigma_w=60;// MPa F=10;// kN alfa=30;// degree FH=F*sind(alfa);// kN FV=F*cosd(alfa);// kN t=poly(0,'t');// mm A=t*t;// mm.sq. sigma_d=FV*10**3/A M=FV*10**3*120+FH*10**3*150;// N.mm I=t*(2*t)**3/12;// mm^4 sigma_t=M*t/I;// N/mm.sq. // Tensile stress at A=sigma_d+sigma...
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TestSortedCollection.tst
2127135785=0 978402736="Jingyuan" 1180449268="Omar" 27322186="The Harrowing of Hell" 319044975="The Desperate Man" 105019561=true 1866459795="Jingyuan" 988370360="Omar" 1076862205="Potsdamer Platz" 29737522="Fitz" 570352297=2 353461707="Jingyuan" 840018027=true 1300594462="Jingyuan" 948989387="Bobby"
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2020-04-09T02:43:26.499817
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6_6.sce
clc //initialisation of variables p=9.5//lb p1=120//lb e=0.88//in p2=80//lb/in^2 d=25//in d1=0.125//in t=14//degree C T=e*19//C.H.U/lb D=0.975//in V=sqrt(2*32.2*1400*T)//ft/sec S=5.467//ft^3 //CALCULATIONS V1=p*S*D//ft^3 T1=(V1*144/V)//in^2 C=25*%pi//in N=C/2.5//in P=C/31//in W=d1/sind(t)//in L=P-W/...
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sce
116ex2.sce
//3/(a-b)-(2a+b)/(a^2-b^2) clear; clc; close; mprintf("\n on factorizing, the expression becomes \n"); //3/(a-b)-(2a+b)/(a+b)(a-b) => (3a+3b-2a-b)/(a+b)(a-b) string('(a+2b)/((a+b)(a-b))')
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Ex2_4.sce
clear p_app = 3 //kips - applied force P_A = 2.23 //kips p_B = -2.83 //kips - compressive force l_ab = 6.71 //inch l_bc = 8.29 //inch s_ab = 17.8 //ksi - tensile stress s_bc = -12.9 //ksi - compressive stress E = 10.6 * (10**3) //ksi -youngs modulus e_ab = s_ab*l_ab/E //elongation e_bc = s_bc*l_bc/E //contraction x = ...
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2023-03-18T23:30:49.653812
2020-09-23T06:26:05
2020-09-23T06:26:05
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sce
Zaey_Wingman_Short.sce
Name=Zaey_Wingman_Short PlayerCharacters=Training Apex Zaey BotCharacters=Apex 200hp dodge hard.bot IsChallenge=false Timelimit=60.0 PlayerProfile=Training Apex Zaey AddedBots=Apex 200hp dodge hard.bot;Apex 200hp dodge hard.bot;Apex 200hp dodge hard.bot;Apex 200hp dodge hard.bot PlayerMaxLives=0 BotMaxLives=0;0;0;0 Pla...
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sce
example13_2.sce
clear; clc; //Example13.2[Fraction of Radiation Leaving through an Opening] //Given:- r1=0.1;//Radius of enclosure[m] L=0.1;//Length of Enclosure[m] r2=0.05,r3=0.08;//Inner and outer radii of the ring[m] //Solution:- //Using Chart in Fig 13.7 F12=0.11; F13=0.28; F1_ring=F13-F12; disp(F1_ring,"The fraction...
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sce
Ex1_7.sce
clc; clear; R=8 //resistance in ohm L=0.03 //inductance in H V=240 //voltage in Volts f=50 //frequency in Hz reactance_RLC=9.42 //reactance of total RLC circuit in ohm in case(2) //calculation //for (1) X_L=2*%pi*f*L // inductive reactance in ohm Z=sqrt(R^2+X_L^2) //in ohm I=V/Z P=I^2*R pf=R/Z //for ...
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/Reconstruction_surface/Tp2/crust.sce
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2016-08-12T16:29:55.570039
2016-03-31T10:28:47
2016-03-31T10:28:47
43,129,610
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2,067
sce
crust.sce
function Crust(S) // **** A MODIFIER/COMPLETER **** // R should contain a list of pair of indices connecting the initial points in S // for instance: // R = [R ; [1,2]] adds the edge connecting points 1 and 2 in the array R R = []; // Triangle de Delaunay sur les sommets initiaux [T,C,r] = delaunay(S)...
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/2561/CH1/EX1.4/Ex1_4.sce
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sce
Ex1_4.sce
//Ex-1.4 clc q=1.6*10^(-19) disp("q = "+string(q)+"coulomb") //charge on an electron I=10 disp("I = "+string(I)+"Ampere") //initializing value of current r=64.25 disp("radius,r = "+string(r)+" mils")//initializing value of radius of wire function[metres]=mils2metres(mils) metres=(mils*2.54)/(1000*100) endfunc...
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Ex3_7.sce
clc; //page 185 //problem 3.7 //Given input inmedance of matching networkis R1 = 10 ohm & output impedance of matching networ is R2 = 50 ohm & carrier frequency is fc = 500 KHz R1 = 10 R2 = 50 fc = 500000 //Wc = 2*pi*fc Wc = 2*%pi*fc //AS R1 = R2*(X2^2)/[(R2^2)+(X2^2)], X2 = 25ohm X2 = 25 //AS X1 = (...
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sce
Ex2_14.sce
clear // // // //Variable declaration N=6000*10**2 //number of lines/m m=3 //order lamda1=500*10**-9 //wavelength(m) lamda2=510*10**-9 //wavelength(m) //Calculation sintheta1=m*N*lamda1 theta1=asin(sintheta1)*180/%pi //angle(degrees) sintheta2=m*N*lamda2 theta2=asi...
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2020-05-20T13:36:05.842840
2013-07-31T06:53:59
2013-07-31T06:53:59
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bow.15_3.tst
15 4:1.0 14:0.07547169811320754 20:1.0 31:1.0 39:1.0 50:2.0 64:0.2857142857142857 125:1.0 126:1.0 230:1.0 450:1.0 553:1.0 15 4:1.0 13:0.058823529411764705 16:0.25 119:1.0 133:1.0 169:0.5 369:1.0 1220:1.0 1316:1.0 1319:1.0 1371:1.0 15 4:3.0 5:0.2857142857142857 13:0.058823529411764705 17:0.09523809523809523 20:4.0 22:0....
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11_12.sce
clear; clc; close; disp("Example 11.12") Tg=2750 //in K Ttg=Tg Tc=300 // coolant bulk temp. in K tw=0.002 //Wall thickness in m kw=43 //thermal conductivity of the wall in W/m.C hg=657 //Gas side film coefficient in W/m^2K hc=26000 //Coolant side film coefficient in W/m^2K eg=0.05 //emissivity of the gas s...
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2017-04-01T22:15:18
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graph.sce
Vto_mismatch_data1=csvRead('Vto_mismatch_data_CAB_10_1_row0_27_vdd_in12_before'); Vto_mismatch_data2=csvRead('Vto_mismatch_data_CAB_10_1_row0_27_vdd_in12_after'); histogram_edges = -0.05:0.0005:0.05; scf(1);clf(1); histo(Vto_mismatch_data1(:,3),histogram_edges);p = get("hdl"); p.children.thickness = 3; p.children.line_...
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6_21.sce
clear; clc; Ymin=18*(10^-2);S=2.5;dmin=20*(10^-2);l=52*(10^-2);Zo=300; //dmin=distance betweeen adjacent voltage minimas ampK=round(((S-1)/(S+1))*100)/100; ZR=fix(Zo*(1+ampK)/(1-ampK)); printf("Input impedance = %f ohms\n",ZR); lo=2*dmin; //lo=wavelength b=(2*%pi)/lo; phi=(2*b*Ymin)-%pi; theta=-fix((phi-(2*b*...
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12_17.sce
clear; clc; f=5*(10^6);C=400*(10^-12);R=10*(10^3); w=2*%pi*f; L=2/(w*w*C); r=1/(w*w*C*C*R); printf("-Effective resistance of the coil = %f ohms\n",round(r*100)/100); printf("-Inductance of effective resistance of the coil = %f mH",round(L*(10^3)*1000)/1000);
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ex48.sce
clear clc A=[-1 2 -2;1 2 1;-1 -1 0] disp("R is matrix of transformation and D is a diagonal matrix ") [R D]=spec(A)
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clc clear //INPUT a1=0*10^-4;//first horizontal displacement in cm a2=5.6*10^-4;//second horizontal displacement in cm a3=-4.7*10^-4;//third horzontal displacement in cm a4=-10.8*10^-4;//fourth horizontal displacement in cm a5=6.6*10^-4;//fifth horizontal displacement displacement in cm a6=-9.8*10^-4;//sixth ...
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erosionBinaire.sci
//Dilatation function image_out=erosionBinaire(image, calque, centerX, centerY) image1 = inversionCouleurs(image); SizeCalcX = size(calque, 1); SizeCalcY = size(calque, 2); calque2 = zeros(SizeCalcX, SizeCalcY); //Application de l'effet Miroir à l'aide de boucle for for...
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4_7.sce
clear// //Variables R2 = 100 //Resistance R2 (in ohm) I = 0.3 //Current (in Ampere) VT = 120 //Voltage (in volts) //Calculation RT = VT / I //Total Resistance (in ohm) R1 = RT - R2 //Resistance R1 (in ohm) P1 = I**2 * R1 //Power dissipate...
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//<s>=%lsslr(s1,s2) // //! [s1,s2]=sysconv(s1,s2) s=s1\s2 //end
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// Example 4.6 format('v',5) clc; clear; close; // given data Vdc= 56.6;// in V R_L= 100;// in Ω f=120;// in Hz C= 1000;// in µF C= C*10^-6;// in F V2peak= Vdc;// in V Idc= Vdc/R_L;// in A // The peak-to-peak ripple Vrip= Idc/(f*C);// in V // The dc load voltage Vdc= V2peak-Vrip/2;// in V disp(Vrip,"...
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clear() // Le but de ce script est de simuler le sysTtème solaire (et dans un premier // temps, la rotation de la terre autour du soleil). La structure initiale // est la même que le projet précédent avec le billard. //Définition des variables utilisé dans tout le programme G = 6.67408e-11 // La constante de gravitT...
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//Caption:Calculate the value of reflected power //Exa:7.4 clc; clear; close; //Given: P_i=4.5;//in mW S=2;//VSWR C=30;//in dB p=(S-1)/(S+1); P_f=P_i/(10^(C/10)); P_r=p^2*P_i; disp(P_r,'Reflected power (in watts) =');
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// sum 19-1 clc; clear; R=1200; b=300; t=150; N=500; m=7100*10^-9*b*t; Ar=b*t; Aa=Ar/4; C=(20280/t^2)+0.957+(Ar/Aa); w=2*%pi*N/60; V=w*R*10^-3; siga=2*10^3*m*V^2/(C*Aa*3); theta=30*%pi/180; alpha=30*%pi/180; x1=10^3*m*(V^2)/(b*t); y1=cos(theta)/(3*C*sin(alpha)); z1=2000*R*10^-3/(C*t)*((1/alpha)-(cos(t...
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errcatch(-1,"stop");mode(2);//example1.18 disp("Rearrange the circuit as shown below.") disp("The 3.333ohm and 3.6ohm resistors are in series in fig 1.87(c).") r=3.333+3.6 format(8) disp(r,"Therefore, the equivalent resistance R_yz(in ohm)=") exit();
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function [Es] = r2l(Fs) //Kwakernaak's r2l : a left kernel to Fs [F,degF]=pol2mat(Fs); [rF,cF] = size(Fs); if cF > rF then error('r2l: Input has more columns than rows'); end [roF,coF] = size(F); to = 1e-6; // tolerance // INITIALIZE rs = coF; SS = []; rowsS = 0; normF = norm(F,'inf'); j = 0; ...
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clc // Given that k = 4 // maximum kinetic energy of electron in eV w = 2.2 // work function of sodium in eV h = 6.62e-34 // Planck constant in J-sec c = 3e8 // speed of light in m/sec e = 1.6e-19 // charge on an electron in C // Sample Problem 20 on page no. 14.27 printf("\n # PROBLEM 20 # \n") printf("Standard formu...
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// Exa 3.2 clc; clear; close; // Given data P = 350;// in kN/m^2 P = P * 10^3;// in N/m^2 m = 1;// in kg m = m * 10^3;// in gram V = 0.35;// in m^3 C_p = 1.005;// in kJ/kg-K C_v = 0.710;// in kJ/kg-K R = C_p - C_v;// in kJ/kg-K T = (P*V)/(m*R);// in K T = T - 273;// in degree C disp(T,"The intial tempera...
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clear // // // //Variable declaration x=4.2*10**-3 //distance(m) D=60*10**-2 //screen slit distance(m) lamda=6000*10**-10 //wavelength(m) //Calculation d=D*lamda/x //slit width(m) //Result printf("\n slit width is %0.3f *10**-4 m",d*10**4)
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//CHAPTER 8- DIRECT CURRENT MACHINES //Example 18 disp("CHAPTER 8"); disp("EXAMPLE 18"); //460 V 10 HP motor //VARIABLE INITIALIZATION v_t=460; //in Volts p_o=10*736; //in Watts (1 metric H.P=735.5 W) ratio=85/100; //as given in the question eff=84/100; ...
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//Example 4.10 clc fs=(1/(2*%pi*sqrt(0.4*0.085*10^-12)))*10^-6 // in MHz format(6) disp(fs,"(i) f_s(in MHz) = 1 / 2*pi*sqrt(L*C) =") ceq=0.085/1.085 // in pF disp(ceq,"(ii) C_eq(in pF) = C*C_M / C+C_M =") fp=(1/(2*%pi*sqrt(0.4*0.078*10^-12)))*10^-6 // in MHz (the answer in textbook is wrong) disp(fp,"Ther...
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clc; clear; R=100 //radius of curvature in cm D_5=0.3 //diameter of the 5th dark ring in cm D_25=0.8 //diameter of the 25th dark ring in cm n5=5 //fifth dark ring n25=25 //twenty fifth ring //calculation p = n25 - n5 //difference in no of fringes lambda=((D_25^2)-(D_5^2))/(4*p*R) mprintf("The wavelength o...
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//(Threaded Joints) Example 7.20 //Number of bolts N N = 2 //Engine speed n (rpm) n = 2000 //Length of stroke l (mm) l = 100 //Length of connecting rod c (mm) c = 200 //Mass of reciprocating parts m (kg) m = 5 //Overload percentage load (%) load = 50 //Assume the stiffness of the bolts to be 1N/mm kb kb...
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function [regulator,fz1,fp1,fp0]= typeII(plant,fc,pm) //Function to calculate the Type II (Integrator, zero, pole) that can provide the phase margin (pm) at the desired crossover frequecncy(fc)) //Definition of the Laplace variable s=poly(0,'s'); //Get the plant mag and phase response at fc ...
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// Example 10_14 clc;funcprot(0); // Given data T_L=20+273.15;// K T_0=T_L;// K T_H=35.0+273.15;// K COP_act=8.92;// Actual Coefficient of Performance // Calculation COP_Carnot=T_L/(T_H-T_L);// The coefficient of performance of a Carnot refrigerator or air conditioner epsilon_RAC=(COP_act/COP_Carnot)*100;//...
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A = cat(3,[1 2; 3 4],[9 10; 11 12],[5 6; 7 8]); M = cummin(A,3,'reverse'); //output //-->M(:,:,1) // ans = // // 1. 2. // 3. 4. // //-->M(:,:,2) // ans = // // 5. 6. // 7. 8. // //-->M(:,:,3) // ans = // // 5. 6. // 7. 8. //
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//Ex:2.31 clc; clear; close; L1=60;//in mH L2=60;//in mH L_a=L1+L2; L3=120;//in mH L_b=L_a*L3/(L_a+L3); L4=50;//in mH L_eq=L4+L_b; printf("Equivalent Inductance = %d mH",L_eq);
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clc //initialisation of variables u1= 1111.9 //Btu/lb p= 170 //psia v1= 2.675 //cu ft/lb V1= 6000 //ft/min g0= 32.2 //ft/sec^2 g= 32.2 //ft/sec^2 z= 10 //ft Q= 1000//Btu/hr u2= 914.6 //Btu/lb p1= 3 //psia v2= 100.9 //cu ft/lb V2= 300 //ft/sec g0= 32.2 //ft/sec^2 g= 32.2 //ft/sec^2 z1= 0 //ft //CALCULAT...
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//Chapter-5, Example 5.2, Page 157 //============================================================================= clc clear function [polar] = r2p(x,y)//function to convert rectangular to polar polar = ones(1,2) polar(1) = sqrt ((x ^2) +(y^2)) polar(2) = atan (y/x) polar(2) =(polar (2)*180)/%pi endfunct...
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// Example 4.22;//TOTAL RMS Pulse broadning clc; clear; close; M=30;//dispersion parametr picosecond per nano meter per kilometer Sa=25;//spectral width in nm NA=0.4;//nUMERICAL aPERTURE n1=1.48;// Core refractibve index n2=1.47;//cleadding refrative index C=2.998*10^8;//Speed of light in m/s d=n1-n2; L=1;/...
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//Example 4.2, page 107 clc disp('Part a') N=10^4//in rad, Number of atoms tarversed theta=(2*10^-2)/sqrt(N) printf("\n Average deflection %e rad ",theta)
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clear// //Variables VCC = 10.0 //Source voltage (in volts) RC = 2.0 * 10**3 //Collector resistance (in ohm) RB = 100.0 * 10**3 //Base Resistance (in ohm) beta = 50.0 //Common-Emitter current gain VBE = 0.7 //E...
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//Chemical Engineering Thermodynamics //Chapter 3 //First Law of Thermodynamics //Example 3.4 clear; clc; //Given W = 0;//work done during the process P1 = 1;//Initial pressure in atm P2 = 10;//Final pressure in atm V2 = V1;//Initial & final volume are equal Cv = 0.23//specific heat at constant volume in...
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clc m1=3; //kg m2=4; //kg T0=273; //K T1=80+273; //K T2=15+273; //K c_pw=4.187; //kJ/kgK tm=(m1*T1 + m2*T2)/(m1+m2); Si=m1*c_pw*log(T1/T0) + m2*c_pw*log(T2/T0); Sf=(m1+m2)*c_pw*log(tm/T0); dS=Sf-Si; disp("Net change in entropy =") disp(dS) disp("kJ/K")
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//Initilization of variables m=90 //kg k=450 //N/m lo=0.6 //m r=0.15 //m x=0.9 //m y=0.4 //m //Calculations //Initial KE=0 I=0.5*m*r^2 //kg.m^2 s1=sqrt((lo^2)+(x^2)) //m s2=sqrt((lo^2)+(y^2)) //m V1=0.5*k*(s1-lo)^2 //N.m V2=0.5*k*(s2-lo)^2 //N.m //Applying Conservation of Energy w=sqrt((V1-V2)/(0.5*m*r^...
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// FUNDAMENTALS OF ELECTICAL MACHINES // M.A.SALAM // NAROSA PUBLISHING HOUSE // SECOND EDITION // Chapter 2 : BESICS OF MAGNETIC CIRCUITS // Example : 2.6 clc;clear; // clears the console and command history // Given data N = 200 // number of turns d_in = 7 // inner diameter of wooden toro...
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clear; clc; x=.05; vs=1; vr=1; p=10; d=asind(p*x); mprintf("the power angle=/_%d degrees",d);
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errcatch(-1,"stop");mode(2);//Example 2_13 ; ; //deduce the missing order of a double slit a=0.16*10^-3 //units in m b=0.8*10^-3 //units in m n_p=(a+b)/a for j=1:3 printf("For p=%d n=%d\n",j,j*n_p); end exit();
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// Copyright (C) 2018 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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//Example 6.6 clc; clear; close; format('v',7); //Given data : g=9.81;//constant a=9*10^-4;//m^2 H=3;//meter x=2.5;//meter y=54/100;//meter Qactual=250*10^-3/60;//Cumec Qth=a*sqrt(2*g*H);//Cumec Cd=Qactual/Qth;//coeff. of discharge disp(Cd,"Coefficient of discharge : "); Cv=sqrt(x^2)/sqrt(4*H*y);//veloci...
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//Eg-12.3 //pg-511 clear clc x = 1; h1 = 0.1; h2 = h1/2; deff('out = func(in)','out = exp(in)') //Using central difference formula Dh1 = (func(x+h1)-func(x-h1))/(2*h1); Dh2 = (func(x+h2)-func(x-h2))/(2*h2); //Using equation [16], Dnew = 4/3*Dh2 - 1/3*Dh1; printf('The value of the derivati...
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clear ; clc; // Example 23.9 printf('Example 23.9\n\n'); //page no. 704 // Solution //Given mv = 1 ;// Mass of saturated vapour - [lb] P1 = 2 ;// Initial pressure -[atm] P2 = 20 ;// Final pressure -[atm] // Additional data is obtained from figure 23.6 of the book on page no. 703 H_2 = 179 ;// Specific enthalpy at 2 ...
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//clc() P = 10^7;//Pa; T = 500;//K R = 8.314;//Pa * L / mol K V = N * R * T / ( P * 1000); disp("m^3",V,"(a)Volume of CO2 calculated using ideal gas equation = ")
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//Example 1.1(a) clear; clc; Ri=100*10^3;//Input Resistance Aoc=100;//Open Circuit Gain Ro=1;//Output Resistance Rs=25*10^3;//Source Resistance RL=3;//Load Resistance Av=(Ri/(Rs+Ri))*Aoc*(RL/(Ro+RL));//Overall Gain Vredin=(Ri/(Ri+Rs))*100;//Percentage Reduction in Source Voltage due to Input ...
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//Example 9.2. clc RC=2*10^3 hie=1300 hre=2*10^-4 hfe=55 hoe=22*10^-6 disp("(i) For RE = 200 ohm,") format(7) RE=200 x=hoe*(RE+RC) disp(x," hoe*(RE + RC) =") disp("Since hoe*(RE+RC) < 0.1, the approximate model is permissible.") format(6) AI=-hfe disp(" AI = -hfe = -55") Ri=hie+((1+hfe)*RE) x...
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function f=%pqs(p1,p2) // f=%pqs(p,m) <=> f=p.\m //! if size(p1,'*')==1 then p1=p1*ones(p2) elseif size(p2,'*')==1 then p2=p2*ones(p1) end f=tlist(['r','num','den','dt'],p2,p1,[])
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//Example 2.7 //Program to estimate the maximum core diameter of an optical fiber //which allows single mode operation clear; clc ; close ; //Given data alpha=2; //Parabolic Profile lambda=1.3*10^(-6); //metre - OPERATING WAVELENGTH n1=1.5; //CORE REFRACTIVE INDEX delt...
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// Scilab code Ex4.4: Pg 121 (2005) clc; clear; // Part (b) // For easy calculations, assume all variables to be unity m_p = 1; // Mass of proton, a.m.u m_a = 4*m_p; // Mass of alpha particle, a.m.u Valpha = 1; // Velocity of alpha particle before collision, m/s v_p = (2*m_a*Valpha)/(m_a + m_p); //...
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clc clear //Input data F=11;//Fuel used per hour observed during the trial of a single cylinder four stroke diesel engine in kg mc=85;//Carbon present in the fuel in percent mh=14;//Hydrogen present in the fuel in percent mn=1;//Non combustibles present in the fuel in percent CV=50000;//Calorific value of fuel i...
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scope= grant_type=password_credentials # ionapi pu attribute access_token_url=https://mingle-sso.inforcloudsuite.com:443/ONEONCOLOGY_TST/as/token.oauth2 # ionapi ci attribute client_id=ONEONCOLOGY_TST~ynkZwSoWycgApD0JD12Y4uZ0cdEc0YbJ8-keBxwIru0 # ionapi cs attribute client_secret=ZTgBqPitkoqNRGk7_9N9TEvMK58l0pcREYaqTA1...
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//Optoelectronics - An Introduction, 2nd Edition by J. Wilson and J.F.B. Hawkes //Example 8.6 //OS=Windows XP sp3 //Scilab version 5.5.2 clc; clear; //given n1=1.48;//Dimensionless refractive index of fiber core n2=1.46;//Dimensionless refractive index of fiber cladding L=1e3;//Length of fiber in m c=3e8;//...
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{ Profiler-Testversion zu G:\PROFILER.SYS\DEMOS.PAS\MENDEL.PAS } CONST ___ = 46; ___2 =6; VAR __ : INTEGER ; VAR _ : ARRAY [1..___] OF REAL ; VAR _2 : ARRAY [1..___2] OF REAL ; VAR _h : STRING; VAR _f : TEXT; { 7. Bundeswettbewerb Informatik 1988/1989 } { 1. Runde, Aufgabe 5 ; Autor M. Berger }...
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// Scilab Code Ex 1.26 Lattice parameter of a cubic crystal: Page-33 (2010) h = 1; k = 1; l = 1; // Miller Indices for planes in a cubic crystal d = 2D-10; // Interplanar spacing, m // For cubic crystals, the interplanar spacing is given by // d = a/(h^2+k^2+l^2)^1/2; // Solving for a a = (h^2+k^2+l^2)^(1/2)*d...
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-- Fuzzy Logix, LLC: Functional Testing Script for DB Lytix functions on Netezza -- -- Copyright (c): 2016 Fuzzy Logix, LLC -- -- NOTICE: All information contained herein is, and remains the property of Fuzzy Logix, LLC. -- The intellectual and technical concepts contained herein are proprietary to Fuzzy Logix, LLC. -...
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errcatch(-1,"stop");mode(2);//Example 6.1(a) ; ; R1=2*10^3; R2=18*10^3; b=0.1; fb=100*10^3; emmax=0.01; fmax=((((1/(1-emmax))^2)-1)*(fb^2))^(1/2); printf("f<=%.1f kHz",fmax*10^(-3)); exit();
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//Calculate the change in Enternal energy and change in Enthalpy for heating of Xenon //Example4.5 clc; clear; T1=300; //Initial temperature in K T2=400; //Final temperature in K m=55.40; //Mass of Xenon in g M=131.29; //Molecular mass of Xenon n=m/M; //Number of mole of Xenon in mol R=...
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function [v]=v(r,sigma,epsilon) //epsilon=5.9;//meV H-Kr interaction //sigma=3.57;//Angstrom v=10*epsilon*( (sigma/r)^12-2*(sigma/r)^6); endfunction
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errcatch(-1,"stop");mode(2);//Caption:Find the magnetic flux //Exa:12.2 ; ; N_m=1500;//speed of motor (in rpm) R_a=2;//armature resistance (in ohms) V_s=100; P_o=200;//rated power K_a=85;//machine constant P_rot=15;//rotational loss w_m=(2*%pi*N_m)/60; P_d=P_o+P_rot;//power developed T_d=P_d/w_m;//torque...
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//EXAMPLE 5-51 PG NO-338 I=10; //CURRENT R1=1; R2=1; R3=1; VTH=(I*R1)/(R1+R2+R3); RTH=(R1*(R1+R2))/(R1+R2+R3); P=(VTH/(RTH+RTH))^2*(RTH); disp('i) Voltage (VTH) is = '+string (VTH) +' V '); disp('i) Resistance (RTH) is = '+string (RTH) +' ohms '); disp('i) Power (P...
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 17.10w //calculation of the wavelengths in the visible region that are strongly reflected //given data d=.5*10^-6//thickness(in m) of the glass plate mu=1.5//refractive index of the medium lambda1=400*10^-9//minimum ...
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clc L=0.25; //m D=0.15; //m V2=0.0004; //m^3 Vs=%pi/4*D^2*L; V_total=Vs+V2; y=1.4; V3=V2+5/100*Vs; rho=V3/V2; r=(Vs+V2)/V2; //V1=Vs+V2 n_diesel=1-1/y/r^(y-1)*((rho^y-1)/(rho-1)); disp("efficiency =") disp(n_diesel)
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Vc_0m=10 Vc_0p=Vc_0m disp(Vc_0p) //KVL i1_0p=(10-Vc_0p)/20 i2_0p=Vc_0p/20 //KCL iC_0p=i1_0p-i2_0p disp(iC_0p) iC_inf=0 //capacitor is open circuit disp(iC_inf) VC_inf=10*20/(20+20) disp(VC_inf)
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//Problem 45.03: A coil of inductance 50 mH and resistance 5 ohm is connected to a 110 V, d.c. supply. Determine (a) the final value of current, (b) the value of current after 4 ms, (c) the value of the voltage across the resistor after 6 ms, (d) the value of the voltage across the inductance after 6 ms, and (e) the ti...
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clc clear close // dy/dt=y^2-y sin(t)-cos(t), y(0)=0 function ydot=f(t,y) ydot=y^2-y*sin(t)-cos(t); endfunction y0=0; // valor inicial de y no tempo inicial t0=0; // tempo inicial t=0:0.1:%pi; //escla de tempo y=ode(y0,t0,t,f); plot(t,y)
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rinc N;NOM;PL rinc N;ACC;SG rinc N;GEN;PL rinc N;DAT;SG rinc N;DAT;PL rinc N;NOM;SG rinc N;ACC;PL rinc N;GEN;SG gebedda N;NOM;PL gebedda N;ACC;SG gebedda N;NOM;SG gebedda N;GEN;SG gebedda N;DAT;PL gebedda N;GEN;PL gebedda N;DAT;SG gebedda N;ACC;PL flowan V;SBJV;PL;PRS flowan V;IND;SG;1;PST flowan V;IND;SG;3;PST flowan ...
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clc R=287; //J/kg K y=1.4; p_atm=100; //kN/m^2 p1=284+p_atm; //kN/m^2 T1=297; //K D=0.02; //m A2=%pi/4*D^2; rho_1=p1*10^3/R/T1; m_max=0.685*A2*sqrt(p1*10^3*rho_1); disp("Maximum flow rate =") disp(m_max) disp("kg/s")
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spLiTtEr y {} fIlter Gt { a8:aE:d5:dA:df:CC >= fE:7B5e::aB:4F:Af:159.224.4.241 OR bitAnd ( ) nOt BITAND ( D, ) or 253.0.3.254/63 >= 7 or ::Cb:acDe:d5:Bb:cD:cC:F/6 = h OR H ( -7.e86, ) oR 252.0.204.252 >> Jp } FIlter Bxk {C } KR -> ZAYin GroUPEr WNRQrP {MODuLE r{ } AGGrEgatE Min(z.a) aS N ,D.w } uNGROUPe...
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clc; clear; KE=0.04*1.6*10^-19 //energy in J m=1.675*10^-27 //mass of neutron in kg h=6.63*10^-34 //Plancks constant in J-s c=3*10^8 //velocity of light in m/s //calculation lambda=(h/sqrt(2*m*KE))/10^-9 mprintf("The de-Broglie wavelength is = %1.3f nm\n",lambda) v_g=h/(lambda*10^-9*m) mprintf("The group ve...
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clear; clc; //page no. 302 p = 14.7;//psia T = 60;// degreeF l = 2000;//ft b = 18;//in h = 12;// in v = 10;// fps R_h = (b*h)/(2*12*(b+h)); Re = v*4*R_h*0.0763/(32.2*0.000000375); f = 0.019; h_L = f*(l/(4*R_h))*v^2 /(2*32.2); del_p = 0.0763*h_L; printf('loss of head = %.1f ft of air\n and the pressure...
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Ex3_6.sce
// Example 3_6 clc;funcprot(0); // Given data T_1=20;// °C T_2=100;// °C p_1=0.100;// MPa p_2=1.00;// MPa rho=515;// kg/m^3 c=1.76;// kJ/kg.K. // Solution deltau=c*((T_2+273.15)-(T_1+273.15));// The change in specific internal energy in kJ/kg v=1/rho;// The specific volume in m^3/kg deltah=deltau+(v*((p_2...
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/3557/CH14/EX14.4/Ex14_4.sce
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sce
Ex14_4.sce
//Example 14.4// a0=1.0;//m^3 // composite d=a0-a mprintf("d= %f m^3",d) pA=2.70;//Mg/m^3 //density of aluminium (at 20degree C) a1=3.97;//Mg/m^3 //density of Al2O3 a=0.1;//m^3 //meter //For 1m^3 we shall have 0.1m^3 of Al2O3 ma=a1*a mprintf("\nma = %f Mg",ma) b=0.9;//m^3 //cubic meter ma1=pA*b mprintf("\n...