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//(Cylinders and Pressure Vessels) Example 22.3 //Force exerted by the piston rod F (kN) F = 10 //Friction force due to piston packing as a percentage of operating force frac(%) frac = 10 //Pressure inside the cylinder Pi (MPa) Pi = 10 //Ultimate tensile strength of the cylinder material Sut (N/mm2) Sut = 200...
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clear clc //to find spring compression // GIVEN:: //mass of body m = 3.63//in kg //speed of block v = 1.22//in m/s //force constant for spring k = 135//in // SOLUTION: //using work-energy principle //spring compression d = v*sqrt(m/k)//in meters d1 = d*10^2//in printf ("\n\n Spring compression d...
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///Chapter No 11 Steam Boilers ////Example 11.22 Page No 256 ///Find Efficeincy of chimney draught ///Input data clc; clear; H=45; //Chimney height in m Tg=370+273; //Temperature of flue gases in degree celsius T1=150+273; //Temperature of flue gases in degree celsius ma=25; //Mass of th...
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clear; clc; //Example 14.2 R2=10000; Ri=10000; Aol=10^5; Rif=1/(1/Ri+(1+Aol)/R2); printf('\nclosed loop input resistance =%.2fOhm\n',Rif)
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Dt(2) = Dt(1); for i=2:3 // Atualização do instante de tempo t(i) = t(i-1) + Dt(i-1); // Vetor de Carga efetiva incremental, dado pela equação XXX p(:,i) = Carregamento(n,nc,opC,desC,t0,t1,w1,F,t(i)); Dp = p(:,i) - p(:,i-1); Dp_ = Dp + ... + M*((1/(Beta*Dt(i-1)))*...
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//To find linear and agular velocity and acceleration clc //Given: NBO=300 //rpm OB=150/1000,BA=600/1000 //m //Solution: //Refer Fig. 8.4 //Calculating the angular velocity of BO omegaBO=2*%pi*NBO/60 //rad/s //Calculating the linear velocity of B with respect to O vBO=omegaBO*OB //m/s vB=vBO //By measuremen...
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clear; clc; disp('Example 8.24'); // aim : To determine // the mass of air supplied/kg of fuel burnt // given values // gas composition in the fuel C = 84;// %age mass composition of Carbon in the fuel H2 = 14;// %age mass composition of H2 in the fuel O2f = 2;// %age mass composition of O2 in the fuel ...
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//Ex4_12 Refer fig 4.9(a)and fig 4.9(b) clc VDD=(5) disp("VDD= "+string(VDD)+" volts") // Drain voltage supply RL1=125*10^(3) disp("RL1= "+string(RL1)+ " ohm") //Load resistance RL2=200*10^(3) disp("RL2= "+string(RL2)+ " ohm") //Load resistance IDON1=34.88*10^(-6) disp("IDON1 ="+string(IDON1)+" A")//Drain cu...
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function y=fea(x) y=(%e)^x+2 - x^3 endfunction //REGULA FALSI: Combinación del método de la secante y el método de la bisección function c=reg_falsi(f,a,b,delta,epsilon,maxit) // f función // a y b aproximaciones iniciales tales que f(a)f(b)<0 // maxit: cantidad máxima de iteraciones permitida /...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>Channel Flow Vel P=8 Pre P=7 dumping average field </description> <executable>IncNavierStokesSolver</executable> <parameters>ChanFlow_V8P7_Avg.xml</parameters> <files> <file description="Session File">ChanFlow_V8P7_Avg.xml</file> </f...
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clc; //ex3.15 IL=0.02; //Ampere t=[0.0167 0.00833]; //seceond c=0.0005; // Farad Vr1=(IL*t(1,1))/c; //peakvolt Vr2=(IL*t(1,2))/c; //peakvolt disp('mVpp',Vr1*1000,"Vr1="); disp('mVpp',Vr2*1000,"Vr2="); ////The answers vary due to round off error
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 18.7 //calculation of the size of the image of an object placed at a distance from the spherical concave surface //given data u=-40; //object distance(in cm) R=-20; //radius of curvature of the spherical concave surfa...
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function x = descenso(A,b,x0,iter,e) i=1 x=x0' x0=x v=b'-A*x t=(v'*v)/(v'*(A*v)) x=x+t*v while i<=iter & (norm(x-x0,'inf'))>=e x0=x v=b'-A*x t=(v'*v)/(v'*(A*v)) x=x+t*v i=i+1 end endfunction function [v,r] = potencia(A,v,iter,e) k=1 v=v' ...
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clc // Fundamental of Electric Circuit // Charles K. Alexander and Matthew N.O Sadiku // Mc Graw Hill of New York // 5th Edition // Part 2 : AC Circuits // Chapter 14 : Frequency Response // Example 14 - 14 clear; clc; close; // // Given data L1 = 1.8480; L2 = 0.7650; C1 = 0.7650; C2 ...
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//Chapter-6,Example 6_10,Page 6-30 clc() //Given Values: B=2.5 //Magnetic field in tesla u0=4*%pi*10^-7 //Permeability in free space i0=0.7 //current in the core ri=11*10^-2 //inner radii of core ro=12*10^-2 //outer radii of core //Calculations: r=(ri+ro)/2 ...
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clear; clc; //Example 6.6 Vtn=0.8; Kn=1;//(mA/V^2) Idq=0.5; Vdd=5; Rd=7;//(Kohm) Vgsq=sqrt(Idq/Kn)+Vtn; printf('\nVgsq=%.2f V\n',Vgsq) Vs=-Vgsq Vdsq=Vdd-Idq*Rd-Vs; printf('\nVdsq=%.2f V\n',Vdsq) g_m=2*Kn*(Vgsq-Vtn); printf('\ntransconductance=%.3f mA/V\n',g_m) Av=-g_m*Rd; printf('\nsmall signal voltage ...
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clear x=[2 3]' // 4 pontos -> curva com 4-1 pontos (tinha 4 pontos, botei 2 do meio pq pediu) y=[7 10]' n=length(x); // size(x,1) plot(x,y,'ro-'),xgrid // Faz grafico dos pontos // Monta a matriz de Vandermonde for i=1:n for j=1:n V(i,j)= x(i)^(j-1); end end // a: coefiecientes do polinomio que da for...
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clear; clc; // Illustration 4.4 // Page: 237 printf('Illustration 4.4 - Page: 237\n\n'); // solution //*****Data*****// // a-ethanol b- gas(CO2 rich vapor) c-liquid water P = 110; // [kPa] T = 303; // [K] R = 8.314; Vb = 180; // [kmole/h] xab = 0.02; // [molar composition of ethanol in gas] Vc ...
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// Test # 11 : Valid input test case #1 exec('./allpasslp2hp.sci',-1); [n,d]=allpasslp2hp(0.3,0.6); disp(d); disp(n); // //Scilab Output //d= 1 -0.1755705 //n= 0.1755705 -1 //Matlab Output //d = 1.0000 -0.1756 //n = 0.1756 -1.0000
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//histograma clear n = 10; U = rand(1,n); //distribuição uniforme X = zeros(1,n); for i=1:n if U(i)<0.5 X(i) = 1; end end barrasU = 10; barrasX = 2; [NU,Uhist] = histc(barrasU, U); [NX,Xhist] = histc(barrasX, X); figure subplot(2,1,1) histplot(barrasU, U) subplot(2,1,2) histplot(b...
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function v=cross(a,b) // Produit vectoriel entre a et b v=[a(2)*b(3)-b(2)*a(3);a(3)*b(1)-b(3)*a(1);a(1)*b(2)-b(1)*a(2)]; s=size(a); // On remet le vecteur initial à la forme du vecteur a v=matrix(v,s(1),s(2)); endfunction
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//---------------------------------------// // compute the interaction matrix // associated to a point // and for a 6ddl control // Typically, a free 6ddl camera // author : Claire Dune // date : decembre 2009 //---------------------------------------// function L = matIntPoint6ddl(x,y,Z) // compute the interaction mat...
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//EXAMPLE 6.16 //Partial fraction expansion clc; clear; z=%z; num = z^3; den = 18*z^3 + 3*z^2 - 4*z - 1; elts=factors(den); disp(elts,'the factors are :') ; func = num/den; //the partial fraction gives: p1 = horner((1/(1+0.3333333/z)^2),0.5); disp(p1,'p1 = '); p2 = horner(1/((1-0.5/z)),-0.3333333); disp(p2,'p2 = '); p...
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//Fluid Systems - By Shiv Kumar //Chapter 12- Reciprocating Pumps //Example 12.5 //To Determine the Pressure Head on Piston at Begining, Middle and End of Suction Stroke. clc clear //Given Data:- L=150; //Length of Stroke, mm l_s=7; //Length of Suction Pipe, m d...
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//2. Schubild von f(x,y) clf() x = -2:0.05:2; y = 0:.05:4; //x = linspace(-2, 2); //y = linspace(0, 4); [X, Y] = meshgrid(x, y) F = X.^2 + Y.^2; surf(X, Y, F); //Achsenbeschriftung a = gca(); // a.font_size = 2; //Schriftgröße für x,y,z scala xlabel('x-Achse', 'fontsize', 5) ylabe...
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//Variable declaration: uC = 3.7*10**-4 //Viscosity of benzene (lb/ft.s) uH = 2.05*10**-4 //Viscosity of water @200 . (lb/ft.s) u2 = 2.16*10**-4 //Viscosity of water @192 . (lb/ft.s) pC = 54.8 //Dens...
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//Example 8.15 clear; clc; //Given T=298;//temperature in K R=8.314;//gas constant in J K^-1 mol^-1 delGfoH2Ol=-237.2;//standard enthalpy of formation of water in kJ mol^-1 pH2O=23.7;//vapour pressure of water in mm Hg P=760;//standard pressure in mm Hg //To determine delGfoH2Og Kp=pH2O/P;//equillibrium c...
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// This file is released under the 3-clause BSD license. See COPYING-BSD. function builder_gw_cpp() copyfile("../common.h",TMPDIR); copyfile("../common.cpp",TMPDIR); WITHOUT_AUTO_PUTLHSVAR = %t; tbx_build_gateway("skeleton_cpp3451", .. ["warpaffine","warpaffine"], .. ["warpaffine.cpp"], .. get_a...
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//Exa 10.2 clc; clear; close; //Given data : W=680;//kg/km L=260;//m U_strength=3100;//kg SF=2;//safety factor Clearance=10;//m T=U_strength/SF;//kg w=W/1000;//kg S=w*L^2/(8*T);//,m h=Clearance+S;//m disp(h,"Height above the ground(m) :");
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//Example 6.4 clc; clear; close; format('v',5); //Given data : Q=180/62;//litres/sec Q=Q/1000;//cumec Dc=25/1000;//m H=1.9;//m ac=%pi/4*Dc^2;//m^2 g=9.81;//constant Cv=Q/sqrt(2*g*H)/ac; disp(Cv,"Coefficient of velocity : ");
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<?xml version="1.0" encoding="UTF-8"?> <Project Name="map2102" Width="13" Height="15" CellSize="40" BackgroundSize="1" Background="13plus.png"> <Cell Name="木箱" X="4" Y="1" /> <Cell Name="树" X="5" Y="1" /> <Cell Name="仓鼠-bt" X="8" Y="1" arg0="44" /> <Cell Name="丛林图腾2" X="9" Y="1" /> <Cell Name="出生点" X="1" Y="...
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//Chapter-1, Example 1.21, Page 1.49 //============================================================================= clc clear clc clear //INPUT DATA N1=1500;//Initial speed in rpm N2=1200;//Final speed in rpm Ia1=30;//Initial armature current in A V=300;//Terminal voltage in V Ra1=0.5;//Initial armature r...
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function y=f(x) y=exp(x) endfunction x=linspace(0,6) plot(x,f) xlabel('t') ylabel('y') xtitle('Continuous Exponential Signal')
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clc // From table h1 = 2792.2 // Enthalpy at state 1 in kJ/kg h4 = 122.96// Enthalpy at state 4 in kJ/kg hb = 254.88 // Enthalpy at state b in kJ/kg hc = 29.98// Enthalpy at state c in kJ/kg ha = 355.98 // Enthalpy at state a in kJ/kg hd = hc // Isenthalpic process h2 = 1949.27 // // Enthalpy at state 2 i...
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//TEST CASES FOR LOGICAL OPERATIONS(NOP,AND,OR,XOR) load ALU.hdl; output-file logicalop.out, compare-to logicalop.cmp, output-list x%B1.8.1 y%B1.8.1 z%B1.8.1 OF%B3.1.3 EQ%B3.1.3; //1 pair of operand with X not equal to Y for NOP set x 12, set y 24, set c %B000, eval, output; //1 pair of operand with X e...
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clear; clc; printf("\n Example 12.1"); //Overall liquid transfer coefficient KLa = 0.003 kmol/s.m^3(kmol/m^3) //(1/KLa)=(1/kLa)+(1/HkGa) // let (KLa)=x x = 0.003; overall = 1/x; //For the absorption of a moderately soluble gas it is reasonable to assume that the liquid and gas phase resistances are of the s...
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pathname=get_absolute_file_path('2_5.sce') filename=pathname+filesep()+'2_5data.sci' exec(filename) function[unit]=Conversion(SI) unit=(9.8*(0.3048)^2)*(SI)/4.448; endfunction disp("1lb/ft^2=(9.8*(0.3048)^2)*/4.448)kgf/m^2") disp(Conversion(280.8),"wing loading in lb/ft^2 for F-117A stealth fighter");
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disp("example1.1") printf("\n") disp("given") printf("\n") disp("C=C0(1-coswt)") disp("angular frequency=500rad/sec") w=500; t=0:0.001:0.015 disp("initial capacitance=1 micro farad") disp("i=d(CV)/dt") disp("supply voltage=3V") C0=1*(10^-6) C=C0*(1-cos(w*t)) V=3; i= w*C0*V*sin(w*t)//differentiating CV wrt...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Engineering Thermodynamics by Onkar Singh,Chapter 1,Example 8") d=15*10^-2;//diameter of cylinder in m h=12*10^-2;//manometer height difference in m of mercury rho=13.6*10^3;//density of mercury in kg/m^3 g=9.8...
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clc //initialisation of variables clear W= [0 2000 4000 6000 8000 10000 12000 14000] V= [4 3.76 3.48 3.18 2.86 2.48 2.02 1.47] //CALCULATIONS plot (V,W)
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function x=g_xnode(g) [lhs,rhs]=argn(0), if rhs=0 then g=the_g, end x=g(16)
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% DECIMATE_LIBIGL Decimate a closed manifold mesh (V,F) % % [W,G] = decimate_libigl(V,F,ratio) % [W,G,J,I] = decimate_libigl(V,F,ratio,'ParameterName',ParameterValue, ...) % % Inputs: % V #V by 3 list of vertex positions % F #F by 3 list of triangle indices into V % ratio either a 1<number<#F of max faces, o...
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//Chapter 2,Ex2.16,Pg2.24 clc; disp("Refer to the diagram shown in the figure") a=[15 -10 -5;0 1 -1;-15 12 6] b=[50;2;0] i=a\b printf("\n I1 = %.0f A\n",i(1)) printf("\n I2 = %.2f A\n",i(2)) printf("\ I3=%.2f A\n",i(3)) printf("\n Current through 5 ohms resistor = %.1f A\n",i(1)-i(3))
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//hex to binary,octal and decimal conversion// //example 12// clc //clears the command window// clear //clears// //decimal conversion// x='100' d=hex2dec(x);//hex to decimal conversion// b=dec2bin(d);//decimal to binary conversion// o=dec2oct(d);//decimal to octal conversion// disp(d);//answer in decimal for...
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clc; p=101.325; // Atmospheric pressure in kPa // The complete combustion equation for actane // yC8H18+ x (O2+3.76N2) → n1 CO2+n2 H2O+n3 O2+n3 N2 x=12.5*1.5; y=1; n1=8; n2=9; n3=6.28; n4=70.5; n=n1+n2+n3+n4; // Total number of moles of the products AFm=(x+x*3.76)/y ;// Air fuel ratio m=28.84; M=116; // Mole...
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@relation abalone @attribute Sex{M,F,I} @attribute Length real[0.075,0.815] @attribute Diameter real[0.055,0.65] @attribute Height real[0.0,1.13] @attribute Whole_weight real[0.002,2.8255] @attribute Shucked_weight real[0.001,1.488] @attribute Viscera_weight real[5.0E-4,0.76] @attribute Shell_weight real[0.0015,1.005]...
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clc; warning("off"); printf("\n\n example1.2 - pg9"); // given // the three unknowns are x,y,z // the three equations are- // x+y+z=1500 // (1) 0.05*x+0.15*y+0.40*z=1500*0.25 // (2) 0.95*x+0.00*y+0.452*z=1500*0.50 a=[1 1 1;0.05 0.15 0.40;0.95 0 0.452]; d=[1500;1500*0.25;1500*0.50]; ainv=inv(a); sol=ainv*d; ...
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clc; F=2000; //force in lb s=80; //distance inft W=F*s; //calculating weight disp(W,"Weight in ft.lb = "); //displaying result disp(W,"Potential Energy in ft.lb = "); //displaying result
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clc //initialisation of variables F= 1 //Pouunda m= 1 //lbm g= 1 //fts^-2 //CALCULATIONS gc= m*g/F //RESULTS printf ('gc= %.2f lbm ft/poundal^2',gc)
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Introduction to heat transfer by S.K.Som, Chapter 7, Example 3") //Air at a pressure of 101kPa and temprature,Tinf=20°C flows with a velocity(Uinf) of 5m/s over a flat plate whose temprature is kept constant at Tw...
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//e=100*sin(100*%pi*t) //calculating rate of change of voltage at t=.0025 sec t=.0025 r1=10000*%pi*cos(100*%pi*t) mprintf("Rate of change of voltage at .0025 sec=%f V/sec\n",r1) //calculating rate of change of voltage at t=.005 sec t=.005 r2=10000*%pi*cos(100*%pi*t) mprintf("Rate of change of voltage at .005 ...
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// Example 12_2 clc;funcprot(0); // Given data T=20;// °C SPL=20;// Sound Pressure level in dB // From table 1.1, rho_0=1.204;// kg/m^3 gamma=3.5/2.5;// Specific heat ratio // Calculation // (a) Inverting equation 12.18, Pa=2*10^-5*(1*10^(20/10));// Pa // (b) From equation 12.17, a=(gamma*1.013*10^5*rho_0...
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//Example 4.5 //Jacobi Method //Page no. 95 clc;close;clear; A=[10,7,8,7;7,5,6,5;8,6,10,9;7,5,9,10]; n=4; for k=1:14 max1=0 for i=1:n for j=1:n if A(i,j)>max1 & i~=j then max1=A(i,j) i1=i;j1=j; end end end fi=(atan((2*A(i1,j1))/(A(i1,i1)-A(j1,j1)+10^...
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// Chapter 10_Fundamentals of the Metal Oxide Semiconductor Field Effect Transistor //Caption_The two terminal MOS structure //Ex_1//page 434 Na=10^16 T=300 eps=11.7*8.85*10^-14 e=1.6*10^-19 ni=1.5*10^10 //intrinsic carrier concentration phi_fp=0.0259*log(Na/ni) xdT=10^4*(4*eps*phi_fp/(e*Na))^0.5 printf('...
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*Testcase FAC5861: Quick Test of Misc. Instr. Ext. 2 & 3 mainsize 2 numcpu 1 sysclear archlvl z/Arch loadcore "$(testpath)/FAC5861.core" runtest 1.0 *Done
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// Implementation of example 3.3 // Basic and Applied Thermodynamics by P.K.Nag // page 55 clc clear p=101.325 // (atmospheric pressure in kN/m^2) N=10000 // no. of revolutions T=1.275 // (torque in Nm) d=0.6 //(diameter in m) l=0.8 //(distance moved in m) w1=(2*%pi*T*N)/1000; // work done by stirring d...
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function resu=lmm_swpt_stovol_sci(period , nb_fac , swpt_mat , swp_mat , perct) list_file=[ "lmm_swpt_stovol_sci.o", "lmm_volatility.o" , "lmm_zero_bond.o" , "lmm_stochastic_volatility.o" , "lmm_random_generator.o" , "lmm_products.o" , "lmm_numerical.o" , "lmm_mathtools.o" , "lmm_libor.o" , "premia_files/complex.o "...
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clc //initialisation of variables h= 75 //ft e= 0.75 k= 0.01 Q= 3000 //gal/min k1= 1.2 N= 1500 g= 32.2 //ft/sec^2 D= 0.836 //ft //CALCULATIONS W= h/e v1= sqrt((W-h)/k) Q1= Q/374.06 f1= Q1/(k1*D^2) u1= %pi*D*N/60 w1= W*g/u1 B= atand(f1/(u1-w1)) //RESULTS printf ('Diameter of impeller = %.3f ft ',D) ...
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// Scilab Code Ex2.13: Page-80 (2008) clc; clear; x = poly(0, 'x'); y = x^2-4; F = [x*y (x^2 + y^2)]; // Force acting on the particle, N x1 = 2; // lower limit x2 = 4; // upper limit dr = [derivat(x); derivat(y);]; // Infinitesimal displacement, m dW = F*dr; // Work done or infinitesimally small displcem...
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// Grob's Basic Electronics 11e // Chapter No. 13 // Example No. 13_1 clc; clear; // Make the following conversions: (a) 25,000 Mx to Wb; (b) 0.005 Wb to Mx. // Given data A = 25000; // A=25000 Maxwell B = 0.005; // B=0.005 Wabers C = 1*10^8; // Conversion Factor Wb = A*(1/C); ...
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function [p]= biseccion(f,a,b,n,e) //n:cantidad de iteraciones ; e: error i=1 p=(a+b)/2 while i<=n & abs (f(p))>e if f(a)*f(p)>0 then a=p; else b=p; end i=i+1 p=(a+b)/2 end if i>n then printf("No converge") else printf("Raiz: %f",p) end...
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//Example 6.6 //Program to calculate the external power efficiency of the device clear; clc ; close ; //Given data eeta_t=0.18; //*100 percent - TOTAL EFFICIENCY Eg=1.43; //eV - ENERGY BAND GAP OF GaAs V=2.5; //Volts - APPLIED VOLTAGE //External power efficiency of t...
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//Chapter 3: Thermodynamic and Chemical Equilibrium //Problem: 8 clc; //Declaration of Constant R = 1.987 // cal per K per mol //Declaration of Variables m = 5 Vo = 4 //in litres, Initial Volume Vf = 40 //in litres, Final Volume T = 27 //in de...
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Name=FortBox Tracking PlayerCharacters=Player BotCharacters=Pigeon Jumper.bot IsChallenge=true Timelimit=60.0 PlayerProfile=Player AddedBots=Pigeon Jumper.bot;Pigeon Jumper.bot;Pigeon Jumper.bot PlayerMaxLives=0 BotMaxLives=0;0;0 PlayerTeam=1 BotTeams=2;2;2 MapName=box_v4.map MapScale=3.15 BlockProjectileP...
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// problem 6.1 Rn=1700 v=0.744*(10^-4) d=0.05 V=(Rn*v)/d Vmax=2*V x=0.00625 r=(d/2)-x V1=Vmax*(1-(2*r/d)^2) disp(V1,"velocity at the point 6.25 mm from the wall in m/sec")
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//clc(); clear; // To determine the slit seperation in Young's double slit experiment lambda=5100*10^(-8); //A source of light in centimetres D=200; // Seperation between screen and slit in centimetres beeta=0.01; // Overall seperation from double slit in metres d=(lambda*D)/beeta; ...
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// Example 7.5.a //photocurrent clc; clear; close; R=0.85;//in AW^-1 pi=1.5;//in mW po=1;//in mW ip=po*R;//in mA disp(ip,"photocurrent in mA is")
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# camera: eye-point, look-at-point, up, fovy, width, height camera 0 16 50 0 12 -1 0 1 0 30 600 300 # recursion depth depth 1 # background color background 0.5 0.7 1.0 # global ambient light ambience 0.2 0.2 0.2 # light: position and color light 5 20 0 1.0 1.0 1.0 25 # meshes: filename, shading, material (...
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convol.sce
//Linear Convolution n=1:4 x=[1,2,3,4]; h=[1,1,1]; y=convol(x,h) subplot(311) plot(x) xtitle("Input Sequence [x]") subplot(312) plot(h) xtitle("h") subplot(313) plot2d3('gnn',y) xtitle("Convolution")
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// Example 6_5 // Root locus of system in state space clear; clc; xdel(winsid()); //close all windows // please edit the path // cd "/<your code directory>/"; exec("rootl.sci"); A = [0 1 0; 0 0 1; -160 -56 -14]; B = [0; 1; -14]; C = [1 0 0]; D = [0]; G = syslin('c',A,B,C,D); H = clean(ss2tf(G)); disp(H,' transfer f...
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//Calculate the Standard Reduction Potential for the Half reaction Fe(three positive)(aq)+3 electron =Fe(s). //Example 10.2 clc; clear; v1=2; //Number of electron in first reaction v2=1; //Number of electron in second reaction v3=3; //Number of electron in third reaction E1=-0.447; //Stan...
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AbstractOrbit.tst
import { AbstractParameter } from "../AbstractParameter"; import { Position } from "../../../blacksheep-geometry/lib"; import { SimpleParameter } from "../SimpleParameter"; export class AbstractOrbit extends AbstractParameter < Position[] > { speed: SimpleParameter; distance: SimpleParameter; ...
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//Exa 2.11 clc; clear; close; //given data ni=2.5*10^13;//in cm^-3 e=1.6*10^-19;//in coulamb MUh=1800;//in cm^2/V-s MUe=3800;//in cm^2/V-s SIGMAi=ni*e*(MUe+MUh);//in (ohm-cm)^-1 GeAtoms=4.41*10^22;//in cm^-1 DonorImpurity=1/10^7;//in per Ge Atom Nd=4.41*10^22*DonorImpurity;//in cm^-1 n=Nd;//in cm^-1 p=ni^...
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//--------------------------------------------------// // main program // test the functions defined in // src/asserVisu/predictiveControl.sci // // author Claire Dune // date 28/01/2010 // Pour tester les fonctions de cout // ;exec('testAsserVisuTous.sce'); //--------------------------------------------------// clea...
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//f=x^y^z+wxz+xy+v^w^yz^ clc; n=4; k=[0 0 0 0; 1 0 1 1; 0 1 1 0; 1 1 1 0]; k(:,:,2)=[0 0 0 0; 1 0 1 1; 0 1 1 0; 0 1 1 0]; //k=[1 0 0 0; // 0 0 0 0; // 0 0 0 0; // 0 0 1 0]; //k(:,:,2)=[1 0 0 0; // 0 0 0 0; // 0 0 0 0; // 1 0 0 0];...
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snr pcm.sce
//Find Signal to Noise Ratio (SNR)& Probability of Error of Pulse Code Modulation (PCM) System clc clear all n = input('Enter the Number of Bits : '); snrdb = 4.8+6*n; print(%io(2),snrdb,'in db'); xmax = input('Enter XMAX : '); pb = input('Enter the Input Power : '); snr = ((pb*3*(2^2*n))/(xmax^2)); print(%io(2),snr);...
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//Example 10.4 clc disp("R1 = 5 k-ohm, R2 = 10 k-ohm") disp("The IC is 7808 i.e. V_reg = +8 V") vt=8*(3) format(3) disp(vt,"Therefore, V_out(in V) = V_reg*[1 + R2/R1] =") disp("Now R2 = 1 k-ohm then,") vo=8*(1+(1/5)) format(4) disp(vo,"V_out(in V) = 8*[1 + 1/5] =") disp("Thus the V_out can be varied from ...
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//Problem 15.22: A coil of negligible resistance and inductance 100 mH is connected in series with a capacitance of 2 μF and a resistance of 10  across a 50 V, variable frequency supply. Determine (a) the resonant frequency, (b) the current at resonance, (c) the voltages across the coil and the capacitor at resonance,...
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//exa 1.12 clc;clear;close; format('v',5); //Arranging data for Load Duration Curve //week days 5-9pm load L1=350;//MW t1=4*5;//hours //week days 8-12am & 1-5pm load L2=250;//MW t2=t1+8*5;//hours //saturday & sunday 5-9pm load L3=200;//MW t3=t2+4*2;//hours //All days 150MW load L4=150;//MW t4=t3+6*5+15*2...
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clear; clc; ef=3000; Zc=300; ea=1700; iF=ef/Zc mprintf("\nCurrent in line= %d kA",iF) Ia=((2*ef)-ea)/Zc mprintf("\nCurrent through Arrester= %.3f kA",Ia) Ia=round(Ia *1000)/1000 R=ea/Ia mprintf("\nresistance of arrester= %.2f ohm",R) er=ea-ef; mprintf("\nSurge Voltage Reflected= %.0f kV",er) Cr=er/ef; ...
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//Exa 1.12 clc; clear; close; //given data : r=10;//in Km Erms=10;//in mV/m r1=20;//in Km //Formula : Erms=sqrt(90*W)/r;//in V/m //Let swrt(90*W)=a a=Erms*r; Erms1=a/r1;//in mV/m disp(Erms1,"Field strength at 20Km distace in mV/m: ");
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function d = pchips(x,y,delta) //Piecewise Cubic Hermite Interpolating Polynomial (PCHIP) //Parameters // x: a vector // y: is Y is vector then it must have the same length as x and Y is matrix then the last dimension of Y must equal //length(X). // delta: Points for interpolation // d: vector of interpolantant at d...
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clear; clf; dn = 1; n = 0 : dn : 10; x = sin(2*%pi*(1/11)*n); plot2d3(n, x); y = sum(x) / 11; disp(y);
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// Example 2.26, page no-46 clear clc theta=27.5/2//in degrees a=0.563*10^-9 n=1 h=1 k=1 l=1 d=a/sqrt(h^2+k^2+l^2) printf("\nThe lattice spacing for the plane (111) is %.2f * 10^-10 m",d*10^10) lam=2*d*sin(theta*%pi/180)/n printf("\nThe deBroglie wavelength of the neutrons is %.3f *10^-10 m",lam*10^10)
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//Example 1.49b //Determine whether the signal x(n)=cos(pi*n/2)cos(pi*n/4) clc; n=0:1/100:100 x0=cos((%pi*n/2)+(%pi*n/4)) x1=cos((%pi*n/2)-(%pi*n/4)) x=(x0+x1)/2; plot(x); disp('plot shows that this is a periodic signal');
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//Programming Example 8.13 //simple compound interest problem function[]=mainCI() //read input data(including prompts) printf("Please enter a value for the principle:(p)"); p=scanf("%f"); printf("Please Enter a value for the interest rate(r): ") r=scanf("%f"); printf("Please Enter a v...
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clear; clc; close; Vcc = 12; Vbe = 0.7; Vt = 26*(10^(-3)); Rc = 3*(10^(3)); Rf1 = 120*(10^(3)); Rf2 = 68*(10^(3)); Rf = Rf1 + Rf2; ro = 30*(10^(3)); Beta = 140; Ib = (Vcc-Vbe)/(Rf+Beta*Rc); Ie = (1+Beta)*Ib; re = Vt/Ie; disp(re,"Value of diode resistive element(re) :"); Zb = Beta*re; Zi = (Rf1*Zb)/...
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//SCI2C: DEFAULT_PRECISION= FLOAT function mattrace() a = uint16([1,2,3;4,5,6;7,8,9]); disp(trace(a)); endfunction
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clear; clc; close; hfe = 120; hie = 900; Re = 510; Rc = 2.2*10^(3); re = 7.5; A = -hfe/(hie+Re); Beta = -Re; Af = A/(1+Beta*A); Avf = Af*Rc; Av = -Rc/re; disp(Avf,'Voltage gain with feedback = '); disp(Av,'Voltage gain without feedback = ');
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clc //Chapter10 //Example10.4 //Given //b ht=3e3,hr=5e3 // Antenna height d=4100*(sqrt(ht)+sqrt(hr))//distance mprintf('Max possible distance for efective point to point\n communication is %f km',d*1e-3)
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clear; clc; //Example 2.30 //Given hi=75 //[W/sq m.K) x1=0.2 //m x2=0.1 //[m] x3=0.1 //[m] T1=1943 //[K] k1=1.25 //W/m.K k2=0.074 ///W/m.K k3=0.555 //W/m.K T2=343 //K A=1 //assume [sq m] sigma_R=1/(hi*A)+x1/(k1*A)+x2/(k2*A)+x3/(k3*A); //Heat loss per i sq m Q=(T1-T2)/sigma_R //[W] ...
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// EXERCISE 6 - QUESTION 2 // Change values of p and q to (2, 4), (5, 5) or (5, 10) p = 2; q = 4; // Define some parameters a = 0.1; // a(k)=0.1 b = 0.4; // b(k)=0.4 omega = -%pi:2*%pi/100:%pi; // omega=[-pi:pi] // Initialize B(e^jw) and A(e^jw) B = zeros(1,length(omega)); A = zeros(1,length(omega)); ...
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Example20_2.sce
//Example 20.2. clc format(6) sr=20/(4) // in V/us disp(" The slew rate, SR = dVo / dt") disp(sr," SR(in V/us) =")
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tspCityInput.sce
clear; exec tspGetCoordFromName.sci; exec tspDistOnSphere.sci; exec tspDraw.sci; exec tspLength.sci; exec tsp2Opt.sci; global name dist pos; disp "wieviele städte:" anzahl = scanf("%d"); name = []; for i = 1:anzahl disp "Name der Stadt oder exit:\n" text = scanf("%s"); if strcmp(text,'exit...
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Ex8_5.sce
clc; N=12500; // Speed in rpm m=15; // Mass flow rate in kg/s rp=4; // Pressure ratio eff_c=0.75; // Isentropic efficiency mu=0.9; // Slip factor pi=0.3; // Flow coefficient at impeller exit D=0.15; // Hub diameter in m ca2=150; // Axial velocity in m/s T01=275; // Inlet temperature in kelvin p01=1; // Inlet...
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function[ans] = linear_interpolarion(x,x0,y0,x1,y1) b0 = y0; b1 = (y1 - y0) / (x1-x0); ans = b0 + b1*(x-x0); endfunction
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clc //initialisation of variables V= 30 //mph //CALCULATIONS Vinfps= V*5280*(1/60)*(1/60) //RESULTS printf ('v = %.f fps',Vinfps)
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//Problem 36.15: A voltage wave has an amplitude of 800 V at the fundamental frequency of 50 Hz and its nth harmonic has an amplitude 1.5% of the fundamental. The voltage is applied to a series circuit containing resistance 5 ohm, inductance 0.369 H and capacitance 0.122 μF. Resonance occurs at the nth harmonic. Determ...
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clc //initialisation of variables pl= 122.5 // ft Hw= 1225 //ft g= 32.2 //ft/sec^2 Cd= 0.98 Cd1= 0.45 N= 500 //r.p.m P= 6800 //h.p n= 0.86 w= 62.4 //lb/ft^2 l= 5450 //ft f= 0.005 A= 18 //ft^2 //CALCULATIONS Ah= Hw-pl js= Cd*sqrt(2*g*Ah) bs= Cd1*js D= bs*60*2/(N*2*%pi) a= P*2*g*550*144/(n*w*js^3*...
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//Example6.10 // To determine the range of the differential voltage gain clc; clear; close; //R1 = 1 K ohm to 25 K ohm ; R2 = 50 ; // K ohm R3 = 10 ; // K ohm R4 = 10 ; // K ohm // the output of instrumentation amplifier is given by //Vo = (R4/R3)*(1+(2*R2/R1))*(VI@-VI1); // the differential voltage gai...