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clc //Initialization of variables angle =45 //degrees p1=150*10^3 //N/m^2 Q=0.5 //m^3/s d1=60 //cm d2=30 //cm rho=1000 //kg/m^3 g=9.81 //m/s^2 //calculations V1=Q/(%pi/4 *(d1/100)^2) V2=V1*(d1/d2)^2 P2=rho*g*(p1/(rho*g) + V1^2 /(2*g) -V2^2 /(2*g)) Rx=p1*%pi/4*(d1/100)^2 - P2*%pi/4 *(d2/100)^2 *cosd(angle) ...
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// Data Reconciliation Benchmark Problems From Literature Review // Author: Edson Cordeiro do Valle // Contact - edsoncv@{gmail.com}{vrtech.com.br} // Skype: edson.cv // aux functions to weighted least squares functions function c = confun(x) //flowsheet_residuals is it's own file c = flowsheet_residuals(x,K_coef, ...
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clc clear //INPUT y=1.4;//coefficent of exapnsion p1=1;//standard pressure in atm dv=50;//ratio of initial volume to final volume t1=273;//standard temperature in K //CALCULATIONS p2=p1*dv;//final pressure when slowly compressed in atm p3=p1*(dv)^(y);//final pressure when suddenly compressed in atm t2=t1*...
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Tint 255 255 255 255 TintAlphaChange 0 2 StartSlowEndFast Wait 2 Label Here1 TintChange 255 255 255 255 0.5 Linear Wait 1 TintChange 0 0 0 255 0.5 Linear Wait 0.5 Goto Here1
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//pathname=get_absolute_file_path('19.01.sce') //filename=pathname+filesep()+'19.01-data.sci' //exec(filename) //Specific heat of gases(in kJ/kg.K): Cpg=1.13 //kJ/kg.K Cpa=1.005 //kJ/kg.K rg=1.33 ra=1.4 C=41.84*10^3 //kJ/kg of fuel //Temperatures(in K): T1=272 T3=1000 //Compression efficiency: nc=0.84 p3=...
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////////////////////////////////////////////////////////////////////////////// // Author: Jia Wu // Version: 0.1 // Date: Dec. 2009 // // // Copyright (C) 2009 OpenPR // All rights reserved. // // Redistribution and use in source and binary forms, with or without // modification, are permitted provided that...
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phomolo uzophomolo V;SG;3;PST phomolo siyaphomolo V;PL;2;PRS phomolo niphomolo V;SG;2;FUT phomolo bayaphomolo V;SG;1;PST phomolo uyaphomolo V;PL;1;PRS phomolo uzophomolo V;PL;1;PST phomolo bazophomolo V;PL;3;PST phomolo ngiyaphomolo V;SG;1;PRS phomolo uyaphomolo V;SG;3;PRS phomolo ngizophomolo V;SG;2;PST phomolo niyaph...
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pathname=get_absolute_file_path('5_2.sce') filename=pathname+filesep()+'5_2data.sci' exec(filename) delB=(119*w*L^4)/(24576*EI); delC=(5*w*L^4)/(384*EI); printf("\ndelB: %f m",delB); printf("\ndelC: %f m",delC);
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clc;clear;close; wavread("ibat.wav","size") [y,Fs,bits]=wavread("ibat.wav"); figure; //plot(y(1,:)); xtitle('Vowel a'); xlabel('bits'); ylabel('recorded signal'); y=wavread("ibat.wav") plot(y(1,:)); yconj=conj(y); l=length(y); N=2*l-1; y=[y zeros(1,N-l)]; yconj=[yconj zeros(1,N-l)]; for lag=1:N; R(lag)=0; for i...
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clc;funcprot(0);//EXAMPLE 10.10 // Initialisation of Variables Ma=10;.........//Mass of alloy to be produced in Kg %Ni=35;........//Percentage of Nickel in Cu-35% Ni Wn=3.5;.......//total nickel in the 35% alloy being produced %Cu=20;.......// Percentage of Copper in Cu-35% Ni //CALCULATIONS Mn=Ma*(%Ni/100);.......
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function xs() // Return cross-section from the Series/DataFrame. // // Syntax // dfr.xs(input_string) // // Parameters // input_string : String containing the multiindex label to access the data. // For additional information on parameters, see https://pandas.pydata.org/docs/reference/ap...
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//Example 16.4 m=900;//Mass of the car and load (kg) k=6.53*10^4;//Force constant (N/m) f=1/(2*%pi)*sqrt(k/m);//Frequency (Hz) printf('Frequency of oscillation = %0.2f Hz',f) T=1/f;//Time period (s) printf('\nTime period of oscillation = %0.3f s',T) //Openstax - College Physics //Download for free at http://cnx...
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# ATWM1 MRI Experiment scenario = "ATWM1_Working_Memory_MRI_nonsalient_cued_run1"; scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen #scenario_type = trials; scan_period = 2000; # TR pulses_per_scan = 1; pulse_code = 1; #pulse_width=6; default_monitor_sounds =...
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; log2f.tst - Directed test cases for log2f ; ; Copyright (C) 2017, ARM Limited, All Rights Reserved ; SPDX-License-Identifier: Apache-2.0 ; ; Licensed under the Apache License, Version 2.0 (the "License"); you may ; not use this file except in compliance with the License. ; You may obtain a copy of the License at ; ; ...
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funcprot(0);clc; //Example 9.6 //Initializing the variables Qa = 2; Na = 1400; rhoA = 0.92; rhoS = 1.3; DaByDs = 1; dPa = 200; //Calculations Ns = Na*(rhoA/rhoS)*(DaByDs); Qs = Qa*(Ns/Na); dPs = dPa *(rhoS/rhoA)*(Ns/Na)^2*(1/DaByDs)^2; disp(dPs,"Pressure rise(N/m2 ) :",Qs, "Flow rate (m3/s):",Ns,"Fa...
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function new_image = roifill(image, mask_orig, varargin) [ lhs, rhs ] = argn(0) if rhs < 2 then error(msprintf("Too less input arguments")) elseif rhs > 3 then error(msprintf("Too many input arguments")) end image_list = mattolist(image) select rhs case 2 out = opencv_roifill(image_list, mask...
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clc;clear; //Example 17.5 //given data Vi=150; Ti=600+273; Pi=1; At=50/10000;//converted into m^2 //from Table A-2a R=0.287;//in kJ/kg-K cp=1.005;//in kJ/kg-K k=1.4; //calculations Toi=Ti+Vi^2/(2*cp*1000);//factor of 1000 to convert kJ to J Poi=Pi*(Toi/Ti)^(k/(k-1)); //flow is isentropic //stagnat...
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//Exa 4.4 clc; clear; close; //Given Data : format('v',6); Cs=1/3;//in uF Cc=(0.6-Cs)/2;//in uF //Part (a) : C1=(3/2)*Cc+(1/2)*Cs;//in uF(between any two conductor) disp(C1,"Capacitance between any two conductor(in uF) :"); //Part (b) : C2=2*Cc+2*Cs/3 disp(C2,"Capacitance between any shorted onductors(in u...
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# REFERENCE: # EMSOFT paper inf = float('inf') plant_pvt_init_data = None # Property initial_set = [[4.0, 21.0, -1.0, -1.0], [5.0, 22.0, 1.0, 1.0]] ROI = [[-1, -1, -5,-5], [26, 26, 5, 5]] P = [[6., 7., -inf, -inf], [7., 8., inf, inf]] error_set = P T = 20.0 # Working set for P, Q # ...
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//locating error in hamming code and correcting it// //example 29// clc //clears the command window// clear //clears// a=1111001 b=0;c=0;d=0;e=0; for i=1:7 x(8-i)=modulo(a,10) a=a/10 a=floor(a) end //checking even parity at positions 4,5,6,7// for i=4:7 if (x(i)==1) then b=b+...
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ABCDE 1 ABCDE 2 ABCDE 3 ABCDE 4 ABCDE 5 ABCDE 6 ABCDE 7 ABCDE 8 ABCDE 9 ABCDE 10 ABCDE 11 ABCDE 12 ABCDE 13 ABCDE 14 ABCDE 15 ABCDE 16 ABCDE 17 ABCDE 18 ABCDE 19 ABCDE 20 ...
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//Chapter 11 //Example 11_15 //Page 285 clear;clc; d_in=2; d1=3.1; d2=4.2; d_out=5.3; v=66; vp=v*sqrt(2/3); g1_max=1/(d_in/2)/log(d1/d_in); g2_max=1/(d1/2)/log(d2/d1); g3_max=1/(d2/2)/log(d_out/d2); v2=g1_max/g2_max; v3=g1_max/g3_max; vd=1+v2+v3; va1=vp/vd; va2=v2*va1; vf=vp-va1; vs=vp-va1-va2; printf("g1_max =...
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P0 = 1000; T0 = 3; V0 = 0.001; R = 287; n = (P0*V0)/(R*T0); // Number of moles // Process ab Wab = 0; cv = (3/2)*R; Ta = T0; Tb = 300; Qab = n*cv*(Tb-Ta); Ua = 0; // Given internal energy Ub = Qab+Ua; Uab = Ub-Ua; // Process bc Qbc = 0; Uc = 0; Ubc = Uc-Ub; Wbc = -Ubc; // Process ca Tc = Ta; g = 5/3; // gamma Vcb = (T...
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// Example 16.3 format('v',6) clc; clear; close; // given data A=100000; R1= 100*10^3;// in Ω R2= 100;// in Ω r_in= 2*10^6;// in Ω r_out= 75;// in Ω B= R2/(R1+R2);// unit less // The closed loop input impedence r_in_CL= (1+A*B)*r_in;// in Ω // The closed loop output impedence r_out_CL= r_out/(1+A*B);//...
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l=10//span, in m sigma_cbc=5//in MPa sigma_st=140//in MPa fy=250//in MPa m=18.66//modular ratio Df=100//slab thickness, in mm D=l*10^3/12//in mm D=850//approximately, in mm d=D-100//cover=100 mm bw=300//in mm bf=l*10^3/6+bw+6*Df//>2500 mm c/c distance of beams bf=2500//in mm W1=(bw/10^3)*(d-Df)/10^3*25//in...
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clc clear //INPUT DATA ec=4*10^-4//electrical conductivity of intrinsic silicon at room temperature in ohm^-1 m^-1 me=0.14//The electron mobility in m^2 V^-1 s^-1 mh=0.04//The hole mobility in m^2 V^-1 s^-1 e=1.6*10^-19//charge of electron in coulombs //CALCULATION ni=(ec/(e*(me+mh)))/10^16//The intrinsic car...
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// ELECTRICAL MACHINES // R.K.Srivastava // First Impression 2011 // CENGAGE LEARNING INDIA PVT. LTD // CHAPTER : 6 : SYNCHRONOUS MACHINES // EXAMPLE : 6.10 clear ; clc ; close ; // Clear the work space and console // GIVEN DATA m = 3; // Total Number of Phase in Alternator...
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//Tested on Windows 7 Ultimate 32-bit //Chapter 3 Semiconductor Diodes and Miscellaneous Devices Pg no. 90 and 91 clear; clc; //Given Data //Taken as in Example 3.4 esp=50;//Input signal voltage magnitude in volts peak esf=314/(2*%pi);//Input signal frequncy in hertz Vr_to_Vdc=6/100;//Ratio of peak to peak ri...
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like likar N;NOM;INDF;PL offra offra V;NFIN;ACT posta posta V;NFIN;ACT krater kratern N;NOM;DEF;SG subtil subtila ADJ;DEF köksö köksös N;GEN;INDF;SG städa städas V;NFIN;PASS lagra lagrat V.CVB;ACT kongruens kongruensers N;GEN;INDF;PL friktion friktionen N;NOM;DEF;SG konselj konseljerna N;NOM;DEF;PL undgå undgående V.PT...
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//Example 2.2 //To solve the triangle when 2 sides and one opposite angle is given clc,clear a=18 //side oposite to vertex A A=25 //angle at vertex A b=30 //side opposite to vertex B sin_B=(b/a)*sind(A) //law of sines //case 1 B=asind(sin_B) //law of sines C=180-(A+B) c=a*sind(C)/sind(A) //law of sine...
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i=linspace(0,3.5,8) V=[0 60 120 138 145 149 151 152] plot2d(i,V) xtitle("Magnetization curve for example 18.2","Field Current","Generated emf") //refer Fig. 18.5 in the textbook Rsh=60//shunt field resistance //line OA is field resistance line Voc=149//voltage corresponding to point A mprintf("Open circuit ...
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// Copyright (C) 2012 - Prateek Papriwal // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCI...
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//This is just for the instructor //Create occupancy maps clear all OccupancyMap = zeros(100, 100); //Walls OccupancyMap(1,:) = 1; OccupancyMap(end,:) = 1; OccupancyMap(:,1) = 1; OccupancyMap(:,end) = 1; //Obstacles v1 // OccupancyMap(30, 1:70) = 1; // OccupancyMap(70, 1:35) = 1; // OccupancyMap(70, 65:end) = 1; Occupa...
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/*Température critique : T_c théorique ~ 2.269*/ N = 4; T = linspace(0.01,5); n = length(T); tic(); U = ising_energy_std(N); t = toc(); printf("Énergie calculée en "+string(t)+"s\n"); p = zeros(T); for k = 1:n temp = exp(-U/T(k)); p(k) = temp(length(U))/sum(temp); end scf(1); clf(1); plot(T,p); title("Probab...
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function []=evans(n,d,kmax) //seuil maxi et mini (relatifs) de discretisation // en espace smax=0.01;smin=smax/3; nptmax=500 //nbre maxi de pt de discretisation en k // //analyse de la liste d'appel [lhs,rhs]=argn(0) if rhs<=0 then //demo s_mat=['xbasc();n=real(poly([0.1-%i 0.1+%i,-10],''s''));'; ' d=real(poly([-1...
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start with [19,-3,-10,-18] [41,-6,-32,-33] <= [19,-3,-18,-10] by [[5,4,4,-3],[0,2,0,0],[3,-4,4,3],[-4,-4,-4,4]],det=64 [145,-12,-81,-136] <= [41,-6,-33,-32] by [[5,4,4,-3],[0,2,0,0],[3,-4,4,3],[-4,-4,-4,4]],det=64 [761,-24,-249,-752] <= [145,-12,-81,-136] by [[5,4,4,-3],[0,2,0,0],[3,-4,4,3],[-4,-4,-4,4]],det=64 [49...
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clc;funcprot(0);//Example 2.17 //Initilisation of Variables d1=0.04;....//inner diameter of hallow sphere in m d2=0.12;....//outer diameter of hallow sphere in m T1=383;....//inner surface temparature of hallow sphere in K T2=323;....//outer surface temparature of hallow sphere in K d=0.08;.......//diameter of h...
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exec("degree_rad.sci",-1) //Given that m = 2.0 //in kg v1 = [0, -0.50] v2 = [0.40, 0] //Sample Problem 9-4 printf("**Sample Problem 9-4**\n") deltaP = m* (v2 - v1) printf("The change in mometum vactor in kg.m/sec is %1.1fi + %1.1fj", deltaP(1), deltaP(2))
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//Chemical Engineering Thermodynamics //Chapter 7 //Ideal Gases //Example 7.4 clear; clc; //Given //The given example is a theoretical problem and it does not involve any numerical computation //end
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exec("degree_rad.sci",-1) //Given that gr_height = 3 //in m theta = dtor(53) g = -9.8 //in m/s^2 v0 = 26.5 //in m/s tower_height = 18 //in m //Sample Problem 4-8a printf("**Sample Problem 4-8a**\n") x = poly(0,'x') y = x * tan(theta) + g * x * x /(2* v0^2) * sec(theta)^2 y_tower1 = horner(y,23) ...
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// calculate the output voltage of bridge clc; dP=(7000*10^3)-(100*10^3); b=25*10^-12; R1=100; dR=R1*b*dP; ei=5; deo=dR*ei/(4*R1) disp(deo,'output voltage of bridge(V)')
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//chapter 1 Ex 8 clc; clear; close; //let value to be found is x x=475*475+125*125; mprintf("x=%.0f",x);
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// Exa 4.2 clc; clear; close; format('v',6) // Given data R = 100;// in ohm i= '3*cos(omega*t)';// in A A= R*3^2;// assumed disp("Instantaneous power taken by resistor in watts is : ") disp(string(A/2)+" (1+cos(2*omega*t))") P= R*3^2/2*(1+cos(%pi/2));// in watts disp(P,"The average power in watts is : ")
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clc //Variable Initialisation Ea=230//Input Voltage of motor in volts d1=0.8//Duty Ratio d2=0.75//Duty Ratio Ia1=80//Armature Current in Ampere Ra=0.25//Armature resistance in ohm N2=750//Rated Speed of Motor in rpm N3=600//Rated Speed of Motor in rpm Ia2=70 Eb2=210//Average Value of Back EMF //Solution E01...
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// Copyright (C) 2018 - Mykhayl Puzanov // // Date of creation: 24.04.2018 // // This is Scilab script. // See https://www.scilab.org/download // // The script calculates the parameters for // the state-space controller and Kalman filter. // The reason why the SS-controller with KF has been used is // demand to very a...
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//find x which satisfies 3*x+2>8 & 5*x-3<27 clear; clc; close; x=poly(0,'x'); for x=1:100 if(3*x+2>8) mprintf("x>%i\n\nand",x)//solving the first we get break end end x=1; while(5*x-3<27) //on solving the second we get x=x+1; continue end mprintf("x<%i \n",x); x=string(0:...
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clc clear //Input data T1=7;//Inside temperature of refrigerator in degree centigrade T0=28;//Temperature in the kitchen in degree centigrade K1=40;//Thermal conductivity of mild steel in W/mC x1=0.03;//Thickness of mild sheets in m K3=40;//Thermal conductivity of the mild steel in W/mC x3=0.03;//Thickness of ...
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funcprot(0) // évite l'avertissement réécrire fonction //function nouveau=suivant(actuel) // alea = grand(1,1,"uin",1,4) // if (alea>actuel) // nouveau=actuel+1 // else // nouveau=actuel-1 // end //endfunction function nouveau=suivant(actuel) [Nech,_]=size(actuel) alea = grand(Nech,1,"uin",1,n) nouvea...
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1 Montag 2 Dienstag 3 Mittwoch 4 Donnerstag 5 Freitag 6 Samstag 7 Sonntag
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//i/p arg k is negative k=[-0.2 -0.3 -0.4 -1]; x=[1 2 3 4 5 6 7] [f,g] = latcfilt(k,x); disp(f); disp(g); //output // !--error 10000 //dimension mis-match between k and v //at line 46 of function latcfilt called by : //[f,g] = latcfilt(k,x); //matlab // Columns 1 through 6 // // 1.0000 2.3800 3.7600 ...
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//Example 6.6.2 clc; clear; close; n=4;//(No. of elements) //d=lambda/2;(Spacing) dBYlambda=1/2;//(Spacing/wavelength) alfa=0;//degree(angle) N=1;//(For first null) disp("Part (i)"); theta01=[acosd(+N/2) acosd(-N/2)];//degree(Angle) N=2;//(For second null) theta02=[acosd(+N/2) acosd(-N/2)];//degree(angle) ...
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//https://github.com/moueza/isbn-9-782729-879488-la-physique-avec-MAPLE p17 Gms=1 Gmt=.5 Xs=0 Ys=0 Xt=1 Yt=0 //start Maple //x0=2;y0=0;vx0=0;vy0=.25 //ds=sqrt((x-Xs)^2+(y-Ys)^2) //ds=sqrt((y(1)-Xs)^2+(y(3)-Ys)^2) //deff https://github.com/moueza/isbn-2-287-59731-X-introduction-a-Scilab p166 deff("yyy=ds","yyy=sqrt((y...
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//Caption: entropy ,information rate //Example 9.50 //Pge no 441 //Find entropy ,information rate //If there are 16 outcomes per second clear; clc; P1=1/2; P2=1/4; P3=1/8 P4=1/16; P5=1/32; P6=1/32; r=16;//message rate H=P1*log2(1/P1)+P2*log2(1/P2)+P3*log2(1/P3)+P4*log2(1/P4)+P5*log2(1/P5)+P6*log2(1/P6...
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// Example 1.7.1 page 1.14 //To calculate the angel of refraction if the angle of incidence is 30 clc; clear; n1= 1.5; // for glass n2= 1.33; // for water phi1= (%pi/6); // phi1 is the angel of incidence // According to Snell's law... // n1*sin(phi1)= n2*sin(phi2); sinphi2= (n1/n2)*sin(phi1); // ph...
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function f=%r_r_p(f1,p2) // //! // Copyright INRIA if prod(size(p2)) <>1 then f=f1*invr(p2),return,end [n1,p2]=simp(f1('num'),p2*f1('den')) f=rlist(n1,p2,f1('dt'))
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function a=%sisp(i,j,b,a) // %spis(i,j,b,a) insert full matrix b into sparse matrix a for some special cases // a(i,j)=b //! [lhs,rhs]=argn(0) if rhs==3 then a=b; b=j; [m,n]=size(a) a=a(:) a(i)=b end [ij,v]=spget(a) j=int(ij(:,1)/m)+1 i=ij(:,1)-m*(j-1) a=sparse([i j],v,[m,n])
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// Scilab code Ex3.7: Pg 86 (2008) clc; clear; C = 4.7e-08; //Capacitance, F A = 4e-04; // Cross-sectional area of plates, m^2 d = 1e-04; // Thickness of dielectric, m Epsilon_0 = 8.854e-12; // Permittivity of Free Space // Since absolute permittivit...
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clear; clc; s=1; xt=5; m=s/xt*100; n=2*s/xt*100; mprintf("fault level on lt side=%dMVA\n fault level on HT side=%dMVA",m,n);
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// Exa 5.17 clc; clear; close; // given data fo=1;// in KHz // choose C=.01 uF C=.01;// in uF R=1/(2*%pi*fo*1000*C*10^-6);// in ohm // choosing R1=10 Kohm R1=10;// in Kohm RF=2*R1;//in Kohm disp("Hence desired components values are :"); disp(C,"Value of C in uF is ; "); disp(R/1000,"Value of R in Kohm is...
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//Book Name:Fundamentals of Electrical Engineering //Author:Rajendra Prasad //Publisher: PHI Learning Private Limited //Edition:Third ,2014 //Ex9_8.sce. clc; clear; VI1=10e6; phi1=acosd(0.75); phip=acosd(0.9); phic=90-asind(7/100); //given loss is 7% of KVA output KVAc=VI1*(((sind(phi1)*cosd(...
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//Obtain path of solution file path = get_absolute_file_path('solution10_1.sce') //Obtain path of data file datapath = path + filesep() + 'data10_1.sci' //Obtain path of function file funcpath = path + filesep() + 'functions10_1.sci' //Clear all clc //Execute the data file exec(datapath) exec(funcpath,[-1])...
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clear clc disp('MATEMÁTICAS III - CICLO 2020-1') disp('Sección 1.01') disp('TAP 01') disp('Profesor: Hermes Pantoja') disp('Integrantes:') disp('Gino Camizán 100%') disp('Mayra Díaz 100%') disp('José Porres 100%') disp('Joaquín Ramírez 100%') disp('') function bool = frobenius(A,b) //Toma la ...
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clc // Given that T=2.6//in mm wall thickness USL=3.2//in mm upper specification limit LSL=2//in mm lower specification limit Y=2.6//in mm mean s=0.2//in mm standard deviation C1=10//in dollar shipping included cost C2=50000//in dollars improvement cost n=10000//sections of tube per month // Sample Probl...
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// Exa 10.12 clc; clear; close; format('v',5) // Given data Ao = 100; f_L = 20;// in Hz f_H = 40;// in kHz f_H = f_H*10^3;// in Hz Beta = 0.1; Af = Ao/(1 + (Beta*Ao)); disp(Af,"The overall gain at mid frequency is"); f_Hf = f_H*(1+(Ao*Beta));// in Hz f_Hf = f_Hf * 10^-3;// in kHz disp(f_Hf,"The upper cut...
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clc clear //input p=6;//number of poles n=72;//number of slots n1=10;//conductors per slot b=0.01;//flux per pole in weber f=50;//frequency in hertz phi=170;//pitch of coil in electrical degrees kf=1.11;//form factor for sinusoidal forms //calcultions n2=n/p;//number of slots per pole n3=n2/3;//number o...
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//Example 3.9 //(a) calculate the temp. at the surface of slab A. //what is the maximum Temp. in A. //(b)determine the temp. gradient at both the //surfaces of each of the slabs A,B and C. //(c)calculate the value of h1 & h2. //Given tA=0.25 //m, thickness of slab A tB=0.1 //m, thickness ...
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Tarefa 1 - Grupo 11.sce
clc clear // TAREFA 1 // Gabriel de Sousa Araujo - 9299341 // Gustavo Lopes Oliveira - 10335490 // Herval Pereira de Castro Junior - 10335792 // Leonardo Silva Almeida Serra - 1033656 // Lucas Hideki Takeuchi Okamura - 9274315 // Parte 1 fa = 100 // frequência de amostragem t0 = 0 // instante de tempo inicial tf = 4 ...
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clear clc //Example 13.7 FLOW RATE FOR A RECTANGULAR WEIR H=0.21; //head on weir[m] P=0.6; //height of weir[m] L=1.3; //width[m] g=9.81; //acceleration due to gravity[m/s^2] //Flow coefficient K=0.4+0.05*(H/P) //Discharge Q=K*L*sqrt(2*g*H^3) //[m^3/s] printf("\nThe discharge of water over the weir = %.2f m^...
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clc clear Ms=20; //in kg Mw=2; //in kg Cps=2.1; //in kJ/kg K x1=Ms/(Ms+Mw); //Dryness fraction //At 12 bar pressure Hf1=798.6; //in kJ/kg Hfg1=1986.2; //in kJ/kg //At 1 bar pressure Hg2=2675.5; //in kJ/kg Tsup=110+273; //in K Tsat=99+273; ...
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//Chapter 12 : Solutions to the Exercises //Scilab 6.0.1 //Windows 10 clear; clc; //Solution for 8.3 //(a) A=[] A(1,:)=1:8 A(2,:)=[8 6 2 3 1 4 5 7] B=[] B(1,:)=1:8 B(2,:)=[5 6 7 1 8 4 3 2] C=[] C(1,:)=1:8 C(2,:)=[1 4 5 8 7 3 2 6] disp(C) //(b) A=[] A(1,:)=1:8 A(2,:)=[8 6 2 3 1 4 5 7] B=[] B(...
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//Exa 11.15 clc; clear; close; //Given data : Vs=66;//kV Vmax=Vs*sqrt(2)/sqrt(3);//kV D=6;//cm d=2.5;//cm d1=%e*d;//cm gmax=2*Vmax/d/log(D/d);//kV/cm disp(gmax,"Maximum stress without intersheath(kV/cm)"); //d1/d=d2/d1=D/d2=alfa(say) alfa=(D/d)^(1/3); d1=alfa*d;//cm d2=alfa*d1;//cm gmax=Vmax/(d/2*log(d1...
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# - Header - # # - Disc Threshold One - # scenario = "17_March_2015"; active_buttons=3; # button press button_codes=251,252,253; # - Screen Parameters - # default_font_size = 26 ; default_font = "Arial"; default_text_color = 0, 0, 0; screen_width = 1024; screen_height = 768; screen_bit_depth = 32; de...
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//Exa 8.5 clc; clear; close; //given data d=2;//in cm D=2.5*2;//in cm d1=(5/4)*d;//in cm d2=(5/3)*d;//in cm gmax=40;//in KV/cm PeakVoltage=(gmax/2)*[d*log(d1/d)+d1*log(d2/d1)+d2*log(D/d2)];//in KV disp(PeakVoltage/sqrt(2),"The safe Working Potential in KV : ");
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.356401D+00 ...
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//Calculations on gas turbine clc,clear //Given: P1=1,P2=6.20 //Pressure at entering and leaving of compressor in bar T1=300 //Temperature at entering in K eta_C=88,eta_T=90 //Isentropic efficiencies of compressor and turbine in percent CV=44186 //Calorific value of fuel in kJ/kg F_A=0.017 //Fuel air ratio cp_a=1.005 /...
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clear; clc; //Example 12.7 Ri=50; R1=10; R2=90; Av=10^4; bv=1/(1+R2/R1); printf('\nfeedback transfer function=%.2f\n',bv) Rif=Ri*(1+bv*Av); Rif=Rif*0.001;//Mohm printf('\ninput resistance=%.2f MOhm\n',Rif)
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clear; clc; n=4; m=4; y=zeros(n,m); z12=.25+(%i)*1.0; z13=.20+(%i)*.8; z14=.30+(%i)*1.2; z23=.20+(%i)*.8; z34=.15+(%i)*.6; y(1,2)=1/z12; y(1,3)=1/z13; y(1,4)=1/z14; y(2,3)=1/z23; y(3,4)=1/z34; for i=1:1:n for j=1:1:m y(j,i)=(y(i,j)+y(i,j))/2; end end Y=y; for i=1:1:n ...
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clear; n=4; // 4 secondes f1=6000; // frq fondamental fmin=20 fmax=20000 rate=44100; t=soundsec(n, rate); s=cos(2*%pi*f1*t); plot(t(1:100),s(1:100)); halt(); xbasc(); playsnd(s); //savewave("son_sans_repliement.wav",s,rate); analyze(s,fmin,fmax,rate); halt(); xbasc(); rate=22050; t=soundsec(n, rate); s=cos(2*%pi...
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s=%s; syms k; num=s+1; den=(s^2)*(s^2+5*s+6); t=syslin('c',num,den); clf; evans(t)
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//Mass flow// pathname=get_absolute_file_path('4.02.sce') filename=pathname+filesep()+'4.02-data.sci' exec(filename) //If I=integral of(pV.dA): //For system: ICS=Iab+Ibc+Icd+Ida //But ICS=0 //For Aab: function p=f(y),p=-d*U*w*y^0,endfunction IAab=intg(0,t,f) //For Acd: function q=g(y),q=d*U*w*(2*y/t-(y/t...
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//Delta figure for n=-5:5 if n==0 then y=1 else y=0 end disp(y) plot2d3(n,y) end //Ramp Function figure for n=0:5 y=n disp(y) plot2d3(n,y) end //Unit Step figure for n=-5:5 y=1 disp(y) plot2d3(n,y) end //2^n * u(n-1) figure for n=[-3:3] if n<1 then y=0 else y=2...
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clc D = 0.1 // cm^2/sec l = 10 // cm C10 = 1 C1l = 0 C1 = 0.5 V1 = (D/l)*(C10 - C1l)/C1 // Cm/sec V2 = -V1 M1 = 28 M2 = 2 omeg1 = C1*M1/(C1*M1 + C1*M2) omeg2 = C1*M2/(C1*M1 + C1*M2) V = omeg1*V1 + omeg2*V2 printf("The mass average velocity is %.5f cm/s",V)
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//Caption: Kolmogorov-Smirnov Test //Example9.9 //Page323 //Ho: The given set of observations follows normal distribution //H1: The given set of observations does not follow the normal distribution clear; clc; X =[0,5;5,10;10,15;15,20;20,25;25,30;30,35]; //Demand o = [4,9,15,20,18,7,5]; //Observed frequency al...
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@relation vehicle @attribute COMPACTNESS integer[73,119] @attribute CIRCULARITY integer[33,59] @attribute DISTANCECIRCULARITY integer[40,112] @attribute RADIUSRATIO integer[104,333] @attribute PRAXISASPECTRATIO integer[47,138] @attribute MAXLENGTHASPECTRATIO integer[2,55] @attribute SCATTERRATIO integer[112,265] @attr...
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// ErturkMe - Copyright 2011 - 2022 // http://erturk.me // ierturk@ieee.org // See license.txt function [x, y, typ] = xcpl_BLDC(job, arg1, arg2) x = []; y = []; typ = []; select job case 'plot' then standard_draw(arg1) case 'getinputs' then [x, y, typ] = standard_inputs(arg1) case 'getout...
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//Chapter 3, Exmaple 18, page 110 //Determine the diameter clc clear //Based on the equation 3.40 k = 1.38*10**-23 T = 293 z2z1 = 0.05 e = 1.6*10**-19 E = 250 r1 = 0.09*10**-6 r1r2 = (6*k*T*z2z1)/(e*E) r2 = sqrt(r1+r1r2) printf("\n r1^2-r2^2 = %e ",r1r2) printf("\n r2 = %e m ",r2) //answers may vary due to round off e...
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// Exa 3.6 clc; clear; close; // Given data J=10^4;// in A/m^2 Jo=200;// in mA/m^2 Jo= Jo*10^-3;// in A/m^2 T=300;// in K V_T= T/11600;// in V e=1.6*10^-19;// electrone charge k= 1.38*10^-23; n=1;// assuming value //Formula I= Io*(%e^(e*V/(n*k*T))-1) and after dividing both the sides by area of the junctio...
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// Ex3_11 clc; // Given: mH=1.007825; mn=1.008665; M1=22.98977;// mass of Na 23 M2=21.994435;// mass of Na 22 M3=21.991385;// mass of Ne 22 // Solution: m1=((11*1.007825+12*1.008665)-M1); m2=((11*1.007825+11*1.008665)-M2); m3=((10*1.007825+12*1.008665)-M3); Sn=(m1-m2)*931;// neutron seperation energ...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monito...
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function [LMAG,Peq7]=lm(u,Np) uo=4*%pi*1e-7; A1=(1.9/100)*(4.6/100); A2=(3.8/100)*(4.6/100); l1=4.75/100; l2=7.6/100; PTadyizq=0.0; PTadyder=0.0; PTvizq=0.0; PTvder=0.0; Pyoke=(l1/(u*A1))^-1; Pleg=(l2/(u*A1))^-1; Pmleg=(l2/(u*A2))^-1; ...
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clc; fc1 = input("Enter higher frequency:"); fc2 = input("Enter low carrier frequency:"); fp = input("Enter the no of pilses:"); t = 0:0.001:1 c1 = sin(2*3.14*fc1*t) c2 = sin(2*3.14*fc2*t) m = (squarewave(2*3.14*fp*t)+1)*0.5 for i=0:1000; if m(i+1) == 0 mm(i+1) = c2(i+1) else mm(i+1) = c1(i+...
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clear; clc; // Example 21.7 printf('Example 21.7\n\n'); //page no. 633 // Solution //Given //Constant pressure process mol_air = 10 ;// Moles of air-[kg mol] T1 = 60+273 ;// Initial temperature of air-[K] T2 = 30+273 ;// final temperature of air-[K] // Additional data needed Cp = 2.9*10^4 ;// Specific heat capacity ...
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//lubricants// //example 3.7.13// clc volume_oil=5//volume of oil titrated(ml)// density_oil=0.92//density of oil titrated// wt_oil=volume_oil*density_oil//weight f oil saponified(gms)// volume=2//volume of alcoholic KOH consumed to neutralize fatty acids(ml)// normality_KOH=0.01//normality of KOH // A=volume*n...
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// Chapter 11 example 4 //------------------------------------------------------------------------------ clc; clear; // Given data h = 35800; // height of satellite orbit from earth in km G = 6.67*10^-11; // Gravitational constant M = 5.98*10^24; // mass of the earth in ...
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clc; clear; format('v',11); epsilone_r=80; theta_b=atand(sqrt(epsilone_r)); disp(theta_b,"the Brewster angle(in degree)=");
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//Example 2.7.2.b://deviation from mean clc; clear; format('v',6) q=[101.2,101.4,101.7,101.3,101.3,101.2,101.0,101.3,101.5,101.1];// AM= mean(q);//arithematic mean in mm for i= 1:10 qb(i)= q(i)-AM; disp(qb(i),"deviation in "+string (q(i))+" is") end
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clc // initialization of variables P1=8000 // initial pressure in kPa T1=300 // temperature in degree celsius P2=2000 // final pressure in kPa //solution h1=2785 // specific enthalpy of steam in kJ/kg @ 8000 kPa and 300 degree celsius from steam table h2=h1 // throttling process thus enthalpy is constant T2=...
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ok_regularOutput.tst
; test changing the regular output channel (set-logic QF_UF) (get-option :regular-output-channel) (set-option :regular-output-channel "tempout") (get-option :regular-output-channel) (assert true) (set-option :regular-output-channel "stdout") (get-option :regular-output-channel) (assert true)
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/1673/CH7/EX7.16/7_16.sce
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FOSSEE/Scilab-TBC-Uploads
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refs/heads/master
2020-04-09T02:43:26.499817
2018-02-03T05:31:52
2018-02-03T05:31:52
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7_16.sce
//largest eigenvalue and eigenvectors //example 7.16 //page 286 clc;clear;close; A=[1 6 1;1 2 0;0 0 3]; I=[1;0;0];//initial eigen vector X0=A*I disp(X0,'X0=') X1=A*X0; disp(X1,'X1=') X2=A*X1; disp(X2,'X2=') X3=X2/3; disp(X3,'X3=') X4=A*X3; X5=X4/4; disp(X5,'X5='); X6=A*X5; X7=X6/(4*4); disp(X7,'X7=')...