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// run it this way: // $ scilab-adv-cli -f grayplot-accel.sce -args accelerometerdisplacementfile clear; exec('peak_detect.sci'); funcprot(0); // peaks() is redefined args= sciargs(); displacement=csvRead(args(5), ascii(9), 'double'); threshold_ratio= 32; sample_window= 240; // FFT sample_window window sample_time= 2...
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clc a=5*10^-8// a=5A = 5*10^-8cm h=1.054*10^-34// J*s Plank's constant m=9.11*10^-31// kg*m/s e=1.6*10^-19// eV n=1 En=(h^2*n^2*%pi^2)/(2*m*a^2) disp(En,"the value of En in J") En=(En/e) disp(En,"the value of En in eV") n=2 E2=(h^2*n^2*%pi^2)/(2*m*a^2) disp(En,"the value of E2 in J") E2=(E2/e) disp...
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//ques5 //adiabatic steady state processes clear clc //from table A.2 P1=20;//pressure at state 1 in MPa P2=2;//pressure at state 2 in MPa T1=203.2;//Temperature at state 1 in K Pr1=P1/3.39;//Reduced pressure at state 1 Pr2=P2/3.39;//Reduced pressure at state 2 Tr1=T1/126.2;//Reduced temperature //from compr...
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// sum 11-9 clc; clear; D=1200; p=2.5; sigba=110; Pa=%pi*D^2*p/4; nt=0.8; sigta=80; t=p*D/(2*sigta*nt); t=24; d=6*sqrt(t); d=30; Ta=55; Ps=%pi*(d^2)*Ta/4; Np=Pa/Ps; Np=74; nr=Np/2; p=%pi*(D+t)/nr; pb=2*d; m=1.5*d; Pt=(p-d)*t*sigta; Ps=2*Ps; Pb=2*d*t*sigba; Pp=p*t*sigta; n=Ps/Pp; n=n*100; ...
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clear; clc; // Illustration 6.5 // Page: 200 printf('Illustration 6.5 - Page: 200\n\n'); // solution // ****Data****// G = 0.80;// [cubic m/s] P = 10^2;// [kN/square m] XaG = 0.07; Temp = 273+30;// [K] L = 3.8;// [kg/s] Density_L = 1235;// [kg/cubic m] viscocity_L = 2.5*10^(-3);// [kg/m.s] //*****...
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FLAGS='-bi -p PA' STDIN='aaa,TH,ccc\n"a1","b1","c1"\n"a2","b2","c2"\n' STDOUT=$'PAaaa=\'a1\'; PAccc=\'c1\';\nPAaaa=\'a2\'; PAccc=\'c2\';\n' STDERR='' EXITVAL='0'
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function y = g(x) y = (10/(4+x))^0.5; endfunction function [x,h] = punto_fijo(x0,kmax,tol) h = zeros(kmax,1); x = x0; for i=1:kmax res = abs(g(x) - x); h(i) = res if(res < tol) return; end x = g(x); end disp("maximo iteraciones alcanzadas"); ...
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// Lecture des données dat = read("/home/Bart/Documents/M2SITN/POO/github/Tests/data1.txt" , -1 , 7) ; // Centrage des données dat_barre = sum(dat,1)/size(dat,1) ; dat = dat - dat_barre(ones(size(dat,1),:),:) ; // cor = dat'*dat/size(dat,1) ; valP = spec(cor) ; //valeur propre disp(valP) ; [Ab,vectP]=bdiag(cor) ; di...
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clc //initialisation of variables p2=6 //prressure in bar p1=1 //pressure in bar t1=313 //temp in k a1=45 //angle in degrees a2=10 //angle in degrees a3=55 //angle in degrees r=1.4 cp=1.005 //kj/kg ieff=0.85 //isentropic efficiency c=200 //m/s //CALCULATIONS t2s=(t1*(p2/p1)^((r-1)/r)) t2=(((t2s-t1)/ieff...
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<?xml version="1.0" encoding="utf-8" ?> <test> <description>Add composite ID to field</description> <executable python="true">compositeid.py</executable> <parameters></parameters> <files> <file description="Session File">compositeid.xml</file> </files> <metrics> <metric type="L2"...
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clc; disp("Example 9.4") reading=9.7e-3 // of manometer in m g=9.81 densitym=13600 /// in kg/m^3 density=1200 // of water in kg/m^3 delP=g*reading*(densitym-density) U=84/60 b=0.333 c=U*((density*(1-b^4)/(2*delP))^0.5) disp(c,"The venturi coefficient is ")
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heute AvTime ist VbSPr13 sein das ArDetmNomvSgNt das ArDetmAccvSgNt das PnReltNomvSgNt das PnReltAccvSgNt Wetter SbSgNtMeto Wetter SbSgNtMeto schön AjRoot und Cj wir VbSIm12 werden wir PnPlPersNomv1 wollen VbSIn0 wollen wollen VbSPr91 wollen wollen VbSPr93 wollen wollen VbSIm91 wollen wollen VbSCs91 wollen wolle...
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//Problem 45.04: In the circuit shown in Figure 45.8, a current of 5 A flows from the supply source. Switch S is then opened. Determine (a) the time for the current in the 2 H inductor to fall to 200 mA, and (b) the maximum voltage appearing across the resistor. //initializing the variables: i = 5; // in Amperes L = ...
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clc; //e.g 34.6 vs=30; rs=240; vz=12; rl=500; vl=vz; disp('V',vl,"vl="); Is=(vs-vz)/rs Vd=Is*rs; disp('V',Vd*1,"Vd="); Iz=Is-(vl/rl) disp('A',Iz*1,"Iz=");
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// Find currents and voltages // Basic Electronics // By Debashis De // First Edition, 2010 // Dorling Kindersley Pvt. Ltd. India // Example 3-27 in page 179 clear; clc; close; // Given data //Diode acts as short circuited.Both diodes are forward biased V1=0; // Voltage at junction 1 in V V2=0; // Voltage...
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//Calculate the max sag clear; clc; Wc=.85;//kg/m//Line conductor wieght L=275;//meter//span of the line U=8000;//kg//Ultimate strength sf=2;//safety factor P=39;//kg/m^2//Wind pressure T=U/sf;//kg//max allowable tension D=19.5;//mm//dia of copper r=13;//cm//Radial thickness of ice Wi=910*%pi*r*(D+r)*10^-6; ...
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//Example 15.9. clc format(5) fo=1/(2*3.142*10000*(0.01*10^-6)*sqrt(6+((4*2.2*10^3)/(10000)))) //in Hz disp("The frequency of oscillations of a RC phase shift oscillator is") disp(" fo = 1 / 2*pi*R*C*sqrt(6+(4*Rc/R))") disp("Substituting the given values, we get") disp(fo,"fo(Hz) =") disp("For sustained oscill...
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clear; clc; disp("--------------Example 4.11---------------") bandwidth = 200; // 200 kHz printf("\nThe minimum sampling rate cannot be determined in this case because we do not know where the bandwidth starts\nor ends or in order words we do not know the maximum frequency in the signal."); // display example
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function Zeq=parallel(Z1,Z2) Zeq=Z1*Z2/(Z1+Z2) endfunction V=12*%i Vth=4-12*%i/(4-12*%i+6+9*%i)*V Zth=parallel(4-12*%i,6+9*%i) I=Vth/(Zth+6+12*%i) S=V*conj(I) disp(S) Zl=conj(Zth) I=Vth/(Zth+Zl) S=V*conj(I) disp(Zth,S)
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ژېړ ژېړه ADJ;NOM;FEM;SG ژېړ ژېړو ADJ;non{NOM};MASC;PL ژېړ ژېړو ADJ;non{NOM};FEM;PL ژېړ ژېړ ADJ;NOM;MASC;PL ژېړ ژېړو ADJ;VOC;FEM;PL ژېړ ژېړه ADJ;VOC;MASC;SG ژېړ ژېړې ADJ;VOC;FEM;SG ژېړ ژېړ ADJ;NOM;MASC;SG ژېړ ژېړې ADJ;NOM;FEM;PL ژېړ ژېړ ADJ;non{NOM};MASC;SG ژېړ ژېړې ADJ;non{NOM};FEM;SG ژېړ ژېړو ADJ;VOC;MASC;PL کتاب کتاب...
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// Exa 5.4 // To find the number of calls per hour per cell site. clc; clear all; spectrum=12.5*10^6; //in Hz CHBW=200*10^3;//in Hz N=4;//reuse factor Blocking=0.02; // 2% callHT=120;//average call holding time in sec PPL=4;//propogation path loss coefficient CntrlCH=3; //No of control channels Ts=8; // ...
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a1 = [3 4 -2 2; 4 9 -3 5; -2 -3 7 6; 1 2 6 7] b = [2;8;10;2] a = [a1 b] [m,n]=size(a) for j = 1:m-1 for z = 2:m if a(j,j)==0 t=a(j,:) a(j,:)=a(z,:) a(z,:)=t end end for i = j-1:m a(i,:)=a(i,:)-a(j,:)*(a(i,j)/a(j,j)) end end fo...
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imgFile='imagenRGB_T2.txt'; Img=read_csv(imgFile, ' '); ImgIntegers= zeros(size(Img)); for i = 1 : size(Img,'r') for j = 1 : size(Img,'c') //Emplea el mapa de colores obtenido con getcolor() ImgIntegers(i,j) = strindex('.BG.R', Img(i,j)); end end //TODO set right custom colormap: https://help....
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//Finding of Slope //Given z=1; y=0.225; c=50; q=0.04; //To Find A=z*y^2; P=2*sqrt(2)*y; x=sqrt(0.225/(2*sqrt(2))); sb=q/(A*c*x); sb1=sb^(2); disp("Slope ="+string(sb1)+" no units");
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clear close clc s = poly(0,'s'); G = (10)/(s*(s/5 + 1 ) *(s/20 + 1) ); Gs = syslin('c',G); C = (s+3)/(s+1); GsCs = syslin('c' , G*C); nyquist([Gs ; GsCs], 0.1 , 1e3 ,["G(s)" ; "G(s)C(s)"] ); gm=g_margin(Gs); phm = p_margin(Gs); disp(gm,"Gain Margin of G(s)"); disp(phm ,"Phase Margin of G(s)"); gm2 = g_margin(GsCs)...
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART II : TRANSMISSION AND DISTRIBUTION // CHAPTER 10: POWER SYSTEM STABILITY // EXAMPLE : 10.9 : // Page number 275 clear ; clc ; close ; // Clear the work space and cons...
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function D=dftmtx(n) // Developed by: Ankur Mallick // Input arguments: Positive Integer n // Output arguments: DFT matrix D of size nxn such that D*x=fft(x) for any vector x of length n //Example for validation: //a=(1:256)'; //n=length(a); //D=dftmtx(n); //y1=fft(a); //y2=D*a; //disp(norm(y1-y2)); //Output: 9.576D-12...
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clc kw=400 //Assigning values to parameters pf=0.8 kva=kw/pf cl1=4.5 kw=300 pf=0.75 kva=kw/pf cl2=(kva/500)*(kva/500)*4.5 kw=400 pf=0.8 kva=kw/pf cl3=(kva/500)*(kva/500)*4.5 tec=cl1*6+cl2*10+cl3*4 tei=84 eo=5800 n=eo*100/(eo+tei+tec) disp(n,"The efficiency is")
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clc // Given that lambda = 5086 // Wavelength of light s = 29.73 // Specific rotation of fluid in deg/mm // Sample Problem 17 on page no. 219 printf("\n # PROBLEM 17 # \n") del_mu = lambda*1e-7*s/180 // Calculation of differences in refractive index printf("\n Standard formula used \n theta = pi*d*del_mu/lambda...
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echo 0a /u0/chip/microcosm/slur/slur regdir/0a.reg \ -o rdldir/0a.rdl \ -d FACE_WEST \ -r 0a \ -s 0f \ -n 0b \ -e 1a echo 0b /u0/chip/microcosm/slur/slur regdir/0b.reg \ -o rdldir/0b.rdl \ -d FACE_WEST \ -r capt_flag \ -s cave0 \ -n bar_int echo 0c /u0/chip/microcosm/slur/slur regdir/0c.reg \ -o r...
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clear; clc; //Example 13.10 Iref=100; Kn=80; Kp=40; //W/L=x x=25; //lambda=y y=0.02; Id=Iref/2; gm1=2*sqrt(Kp*x*Id/2); printf('\ntransconductance gm1=gm8=%.3f microA/V\n',gm1) gm6=2*sqrt(Kn*x*Id/2); printf('\ntransconductance=%.3f microA/V\n',gm6) ro1=1/(y*Id); ro8=ro1; ro6=ro1; ro10=ro1; printf('\no...
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A = input("Enter A: ") b = input("Enter b: ") n=size(A,1); for k=1:n-1 for i=k+1:n fa=A(i,k)/A(k,k); for j=k:n A(i,j)=A(i,j)-fa*A(k,j); disp(A(i,j)) end b(i)=b(i)-fa*b(k); disp([A b]) end end x(n)=b(n)/A(n,n); for i=n-1:-1:1 sum=0; for...
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//Perform Circular convolution of two sequences is x1={0.2,0.4,0.6,0.8,1.0,1.2,1.4,1.6} and x2(n)={0.1,0.3,0.5,0.7,0.9,1.1,1.3,1.5} clc; clear; n=1:1:16 x1={0.2,0.4,0.6,0.8,1.0,1.2,1.4,1.6,0.2,0.4,0.6,0.8,1.0,1.2,1.4,1.6}; x2={0.1,0.3,0.5,0.7,0.9,1.1,1.3,1.5,0.1,0.3,0.5,0.7,0.9,1.1,1.3,1.5}; subplot(1,3,1) plot2...
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clc //initialization of variables T1=500 //R T2=1060 //R w=1 //lbm //calculations function [cv]= v(T) cv=0.258-120/T +40000/T^2 endfunction Q=intg(T1,T2,v) cvm=Q/(T2-T1) //results printf("Mean specific heat = %.3f B/lbm F",cvm)
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clc;clear; //Example 12.3 //calculation of depth and wavelength //given values f=.07*10^6;//frequency in Hz t=.65;//time taken for pulse to return v=1700;//velocity of sound in sea water in m/s //calculation d=v*t/2;// disp(d,'the depth of sea(in m) is'); l=v/f;//wavelenght of pulse in m disp(l*10^2,'w...
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function jacobi(A,B,P,tol,itx) //A es una matriz no singular N X N //B es una matriz N x 1, osea el vector resultado //P es una matriz N x 1, los supuestos iniciales //err es la tolerancia para P //itx es el numero maximo de iteraciones N = length(B); for k = 1:itx for j = 1:N X(j) = (B(j) - A(j, [1:j-1,...
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Expanding for base=2, level=6, reasons+features=base,same,similiar invall,norm Refined variables=x,y [0+1x,0+1y]: unknown -> [1] [0,0] x²-y³+3 ---------------- level 0 expanding queue[0]^-1,meter=[2,2]: x²-y³+3 [1+2x,0+2y]: unknown -> [1] [1,0] x+x²-2y³+1 [0+2x,1+2y]: unknown -> [2] [0,1] 2x²-3y-6y²-4y³+1 endexp[0] ---...
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//chapter 40 //example 3 //clc() l=15.6//in cm n=8 lambda_g=(2*l)/n disp(lambda_g,"lambda_g in cm=") lambda=3.15//in cm f=9.5*10^9//cycles/sec c=lambda*f disp(c,"value of c in m/sec=")
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// Test # 2 : Excess Input Arguments exec('./zpkrateup.sci',-1); [z,p,k,n,d]=zpkrateup(3,7.2,8.7,5,6); //!--error 58 //Wrong number of input arguments
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// Example 5.19:corner frequency clc; clear; close; Rs=1;//series resistance in killo ohms Rl=3.7;//load resistance in killo ohms Rc=3.7;// Collector resistance in killo ohms R1= 200;// in kilo ohms R2= 200;// in kilo ohms Vbe=0.7;// Base to emitter voltage in volts Rb= (R1*R2)/(R1+R2); rpi=2.5;//resistance...
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clc clear //Input data f1=-12//Focal length of a converging lens in cm f2=25//Focal length of a diverging lens in cm d=8//Distance between the lens in cm //Calculations C=(1/f1)+(1/f2)+(d/(f1*f2))//Inverse of focal length in cm^-1 D=(d/f2)+1//Constant value A=(d/f1)+1//Constant value O1F1=(-D/C)//Poistion o...
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// Scilab ( http://www.scilab.org/ ) - This file is part of Scilab // Copyright (C) 2013 - Scilab Enterprises - Antoine ELIAS // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The...
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//scilab 5.4.1 //windows 7 operating system //chapter 7:Junction Transistor Characteristics clc; clear; //given data a=0.975;//a=fraction of the emitter current contributed by the carriers injected into the base and reaching the collector Ico=10*10^-6; //reverse saturation current in A Ib=250*10^-6; //bas...
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clear clc t=[0;2;4;6]; XA=[0.75;0.64;0.52;0.39]; t1=4000;//kg.s/m3 density_s=1500;//kg/m3 De=5*10^-10; d=2.4*10^-3; //Assuming -rA=kCA*a,-da/dt=kd*a //For this rate a plot of ln(CAo/CA-1)vs t should give a straight line for i=1:4 y(i)=log((1/(1-XA(i)))-1); end plot(y,t) xlabel('t') ylabel('ln(CAo/CA-...
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clc //Given that n = 2 // order lambda = 5.2e-11 // wavelength in Angstrom d = 2.98e-10 // interatomic separation in Angstrom //Sample Problem 10b page No. 139 printf("\n\n\n # Problem 10b # \n") printf("\n Standard formula Used \n 2 * d * sin(theta) = n * lambda ") theta_rad = asin ( (n * lambda) / ( 2 * d))...
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clc //initialisation of variables U= 30 //ft/sec g= 32.2 //ft/sec^2 l= 500//ft r= 1/25 //CALCULATIONS F=(U^2/(l*g)) R= sqrt(r) Um= U*R //RESULTS printf (' Froude number= %.4f ',F) printf (' \n speed= %.f ft/sec',Um)
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clc T1=300; //K p1=1; //bar rp=6.25; T3=1073; //K n_comp=0.8; n_turbine=0.8; cp=1.005; //kJ/kg K y=1.4; T2=T1*(rp)^((y-1)/y); //Let T2'=T2a T2a=(T2-T1)/n_comp + T1; W_comp=cp*(T2a-T1); disp("Compressor work =") disp(W_comp) disp("kJ/kg") T4=T3/rp^((y-1)/y); T4a=T3-n_turbine*(T3-T4); W_turbin...
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//Example 5.3 //Page 256 k=7//from equation 5.14 on page 256 disp('Using the value of k') disp('Using the value of k, the number of crosspoint determined are') 2*7*16 disp('The number of bits of memory can be determined are') N=[2*7*128*4]+[7*128*8]+[7*128*7] //Result //The composite implementation ...
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//To find force and power clc //Given: W=9*1000, T1=W //N d=300/1000 //m N=20 //rpm mu=0.25 //Solution: //Force required by the man: //Calculating the angle of contact theta=2.5*2*%pi //rad //Calculating the force required by the man T2=T1/exp(mu*theta) //N //Power to raise the casting: //Calculating the ...
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errcatch(-1,"stop");mode(2); //initialisation of variables w= 64 //lb h= 7 //miles //CALCULATIONS p= w*h*5280/(144*2240) //RESULTS printf (' pressure = %.2f tons/in^2',p) exit();
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//A Textbook of Chemical Engineering Thermodynamics //Chapter 9 //Chemical Reaction Equilibria //Example 10 clear; clc; //Given: //Reaction: CO(g) + 2H2(g) --> CH3OH(g) T = 600; //temperature in K R = 8.314; //ideal gas constant //Gibbs free energy at 600 K (J/mol K) Gc = -203.81; //for CO Gh = -1...
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// test of matsys functions clear // debug if debug()<>0 then pause,end debug(4) if debug()<>4 then pause,end debug(0) //who a=33;bbb=-1; vars=who('get'); if or(vars(1:2)<>['bbb';'a']) then pause,end //lines ln=lines();lines(30);ln1=lines(); if ln1(2)<>30 then pause,end lines(45,70);ln1=lines(); if or(ln1<>[70,45]) ...
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clc funcprot(0) format('v',10) mat1 = input("Enter matrix[NxN]:") function gauss_jordan(mat1) n = length(mat1(1,:)); aug_mat1 = [mat1,eye(n,n)]; //forward elimination for j=1:n-1 for i=j+1:n aug_mat1(i,j:2*n) = aug_mat1(i,j:2*n)-aug_mat1(i,j)/aug_mat1(j,j)*aug...
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clc //initialisation of variables A= 25 //miles^2 t= 24 //hr p= 50 //per cent l= 3 //in h= 4 //ft //CALCULATIONS A1= 5280^2*A V= A1*l/12 V1= V/(t*60*60) V2= V1/2 L= (V2/(3.33*h*2))+0.2*4 //RESULTS printf ('length of weir= %.1f ft',L)
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// Example 7.3:TRANSFORMER WINDING RATIO clc; clear; close; Vcc=12;//collector vltage Po=88;//power output in milli watt Ploss=8;//power losses in milli watt Pi= Po+Ploss;//input power in milli watt Ic= Pi/Vcc;//collector current in milli ampere gm=10;//transconductance in milli ampere per volt Vb= Ic/(gm);//...
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clc clear //Initalization of variables pa=14.7 //psia p1=12 //psia t1=560 //R n=1.4 //gamma J=778 //constant conversion g=32.2 //ft/s^2 cp=0.24 //heat capacity eff=0.7 //efficiency m1=1.8 m3=1 //calculations t5=t1*(pa/p1)^((n-1)/n) v4=sqrt(2*g*J*cp*(t5-t1)/eff) v3=(m1+m3)/m1 *v4 //results printf("V...
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//log50 to the base e clear; clc; close; log(50)//natural logarithm // or, log50_base_e=log10(50)*2.3026
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#Declaring parameters active_buttons = 1; # Number of Buttons Used button_codes = 1; # Button Code (Tag Number) #refering the PCL file associated with this scenario file pcl_file = "Audiovisual_Control_File_et.pcl"; #Duration of Port Code (Tag Number) in milliseconds pulse_width = 5; ...
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART II : TRANSMISSION AND DISTRIBUTION // CHAPTER 15: INSULATION CO-ORDINATION // EXAMPLE : 15.1 : // Page number 398-399 clear ; clc ; close ; // Clear the work space an...
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//chapter 3 //example 3.15 //page 105 printf("\n") printf("given") Eo=20 E0=20-19.7//load effect loadregulation =(E0*100)/Eo//percentage sourceeffect=20.2-20 lineregulation =(sourceeffect*100)/Eo
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// Hw 8------------------------------------------------------------------- // Close and clear all clc; clear; close; close; close; close; close; close; close; close; close; close; // Using the optimal bypass ratio of 5.9 found in problem 1--------------- // Independant Parameters-------------------------------------...
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//Variable declaration A=100. //high frquency response Af=100 //gain A1=A**2 //forward gain A1new=50 //gain reduces to 50% //Calculations beta=((A1/Af)-1)/A1 //feedback f...
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//Ex:2.30 clc; clear; close; //L=(L1*L2)/(L1+L2) L_eq=5;//in millihenry printf("Inductor of 10 mH wired in parallel would provide %d mH",L_eq);
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// ==========================S-parameter ToolBox======================= // ====================== Read and Write Test ========================= // // Simple function to test sptlbx_readtchstn() and sptlbx_writetchstn() // functions. // // (c)2010 L. Rayzman // // // Created : 02/06/2010 // Last Mo...
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//Initililization of variables m=6.12 //kg g=9.81//m/s^2 x1=3 //m x2=4 //m y=6 //m z1=2 //m z2=4 //m AB=5 //Calculations AD=sqrt(x1^2+y^2+z1^2) AC=sqrt(x2^2+z1^2) //Sum of forces in the y direction T1=(m*g*AD)/6 //N //sum of forces in the x and z direction //Matrix solution of the folllowing simultaneou...
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clc clear im=imread('bw1.jpg') a=im2double(im) [r c]=size(a) padded=zeros(r+2,c+2) a=padded(2:r+1,2:c+1) a=padded w=[1 1 1;1 1 1;1 1 1] aa=find(w==1) count=length(aa) [r c]=size(a) for i=2:r-1 for j=2:c-1 sum1=0 x=a(i-1:i+1,j-1:j+1) sum1=sum(x.*w) if sum1==count then ...
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i1=10; i2=0.5; i3=1.5; v=120; disp("Part a"); i=i1+i2+i3; disp("the total current (in A) supplied by the source is"); disp(i); disp("Part b"); disp("voltage (in V) across the lamp is"); disp(v); disp("Part c"); r=v/i; disp("the combined resistance (in Ω) is");disp(r); disp("Part d"); i4=15; r4=v/(i4-i); ...
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clc // Given that r = 150 // Radius of the circular disc of lead in mm Ti = 50 // Initial thickness of the disc in mm Tf = 25 // Reduced thickness of the disc in mm mu = 0.25// Cofficient of friction between the job and the dies K = 4 // Avg shear yield stress of the lead in N/mm^2 // Sample Problem 6 on page no. 122...
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// Grob's Basic Electronics 11e // Chapter No. 19 // Example No. 19_9 clc; clear; // Two 400-mH coils L1 and L2 have a coefficient of coupling k equal to 0.2. Calculate Lm. // Given data L1 = 400*10^-3; // L1=400 mH L2 = 400*10^-3; // L2=400 mH k = 0.2; // Coupling coefficient=0.2 Lm = k*sqrt(L1*L...
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clear;lines(0); [6.9,9.64; sqrt(-1) 0] [1 +%i 2 -%i 3] [] ['this is';'a string';'vector'] [u,s]=schur(rand(3,3))
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function [xy]=scaling(xy,factor,orig) // xy=xy*factor+orig // // xy : matrix with 2 rows // factor : factor // orig : origin, [0;0] if omitted //! // Copyright INRIA [lhs,rhs]=argn(0) select rhs case 2 then orig=[0;0]; case 3 then orig=matrix(orig,2,1); else error(39) end; // [m,n]=size(xy) if m<>2 then erro...
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// Exa 3.18 format('v',9); clc; clear; close; // Given data VBE= 0.76;// in V VT= 0.025;// in V I_C= 10*10^-3;// in A // Formula I_C= I_S*%e^(VBE/VT) I_S= I_C/(%e^(VBE/VT));// in A disp(I_S,"The value of I_S in amp is : ") // Part(a) for VBE = 0.7 V VBE= 0.7;// in V I_C= I_S*%e^(VBE/VT) disp(I_C*10^3,"...
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clc; o=16.00; //atomic mass of O h=1.008; //atomic mass of H mh2o=(o+2*h)*1.66*10^-27; //mass of H2O molecule disp(mh2o,"Mass of H20 molecule in kg = "); //displaying result c=12.01; //atomic mass of carbon m=((2*c)+o+(6*h))*1.66*10^-27; //mass of C2H6O molecule disp(m,"Mass of Ethyl Alcohol...
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//Chapter-2, Example 2.5, Page 92 //============================================================================= clc; clear; //INPUT DATA r=0.01;//radius in m lg=10^-3;//length of air gap in m Rm=(30/2)*10^-2;//mean radius in m ur=800;//relative permeability of iron ur2=1;//relative permeability of air gap N...
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//Example 6.1 //Program to Plot the Characteristics and //Determine Dynamic Plate Resistance clear; clc ; close ; //Given Circuit Data V=[0 0.5 1 1.5 2]; //V I=[0 1.6 4 6.7 9.8]; //mA //Plotting plot(V,I); a= gca (); xlabel ('Plate Voltage (in V)'); ylabel ('Plate Current (in mA)'); title ('STATIC CHARAC...
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function A=item_swap(A,r,s,col) // eseguo lo swap dell'elemento in posizione r,col con // con quello in posizione s,col tmp=A(r,col) A(r,col)=A(s,col) A(s,col)=tmp endfunction
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clc clear mprintf('Mechanical vibrations by G.K.Grover\n Example 1.7.1\n') //given data Po=25//amplitude of force in N Xo=0.05//ampliyude of displacement in m W=20*%pi //calculations //case 1 t0=0 t1=1 v1=integrate('sin(W*t)*cos(W*t-%pi/6)','t',t0,t1) WD1=Po*Xo*W*v1 //case 2 t0=0 t1=1/40 v2=integrate('s...
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//Magnet attributes Br = 13200 D = 1/2 t = 1/8 //Rotation Angle angle = 0 //Rotation Axis rotaxis = [1 0 0] //Translation tx = 0 ty = 0 tz = 0 //Points to plot x = linspace(-0.5,1,30); y = linspace(-0.5,1,30); z = linspace(-0.5,1,30); //Only 2D plots are possible the other dimension will be se...
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function x = subret(U, d, Exibe) // // Substituições sucessivas // n = length(d); x = zeros(n,1); x(n) = digitos(d(n) / U(n,n), Exibe); for i = n-1:-1:1 Soma = 0; for j = i+1:n Soma = Soma + digitos(U(i,j) * x(j), Exibe); end x(i) = digitos((d(i)...
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1_4.sce
clear; clc; //Example - 1.4 //Page number - 17 printf("Example - 1.4 and Page number - 17\n\n"); //(a) //Given V = 9;// [m/s] - velocity d = 1;//[m] - diameter A = 3.14*(d/2)^(2);//[m^(2)] - area P = 1;//[atm] - pressure P = 101325;// [N/m^(2)] T = 300;//[K] - Temperature R = 8.314;//[J/mol*K] - Unive...
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Ch05Ex21.sce
// Scilab Code Ex5.21: Page:307 (2011) clc;clear; lambda1 = 5890;....// Wavelength of the line, angstrom lambda2 = 5896;....// Wavelength of the line, angstrom d_lambda = lambda2 - lambda1;....// Wavelength difference, angstrom n = 2;....// Order of diffraction N = lambda2/(n*d_lambda); // Minimum no. of lines...
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Ex7_19.sce
clear // // // //Variable declaration d=3.04*10**-10 //lattice spacing(m) lamda=0.79*10**-10 //wavelength(m) n=3 //order //Calculation x=n*lamda/(2*d) theta=asin(x)*180/%pi //glancing angle(degrees) //Result printf("\n glancing angle is %0.3f degrees",theta)
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Example_4.sce
//Chapter-9,Example 4,Page 220 clc(); close(); R= 550 //resistance of the cell K=0.002768 //specific conductivity C_constant= R*K p= 72.18 //observed resistance Kv = C_constant*(1/p) C= 0.2 //concentration lamda_v= Kv*1000/C //equivalent conductivity M= 0.1 lamda_m= 1000*Kv/M ...
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Ex20_10.sce
clc // Given that d = 25 // Throat diameter in mm D = 1.2 // Main jet diameter in mm c_d = 0.85 // Cofficient of discharge for the venturi C_d = 0.65 // Cofficient of discharge for fuel jet h = 6 // Height of the throat from gasoline surface in mm p_1 = 1 // Ambient pressure in bar T = 300 // Ambient temperatu...
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basis.sce
function basis = basis(A) n = size(A, 'r') basis = [] for i=n:-1:1 if A(i, i) == 0 then for j=i-1:-1:1 if A(j, i) <> 0 & isequal(A(j, 1:i-1), zeros(1, n-j+1)) then A([j, i], :) = A([i, j], :) end end end end ...
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Ex12_8.sce
//example 12.8 clc; funcprot(0); qu=3000; Ds=3*12; L=15*12; FS=3; Ecore=0.36e6; f=min(2.5*qu^0.5,0.15*qu); Qu=%pi*Ds*L*f/1000; Emass=Ecore*(0.266*80-1.66); Ec=17.9*Emass; Ac=%pi/4*Ds^2; If=0.35; se=Qu*L/Ac/Ec+Qu*If/Ds/Emass; Qall=Qu/FS; disp(Qall,"allowed load in kN");
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Exa3_9.sce
//Exa 3.9 clc; clear; close; //Given Data : format('v',5); m=1/9;//unitless EL=33;//in KV EbyE1=1+(1+m)+(1+3*m+m^2);//assumed E=EL/sqrt(3);//in KV E1=E/EbyE1;//in KV disp(E1,"E1(in KV) :"); E2=(1+m)*E1;//in KV disp(E2,"E2(in KV) :"); E3=(1+3*m+m^2)*E1;//in KV disp(E3,"E3(in KV) :"); E=E1+E2+E3;//in KV ...
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/////////////////////////////////////////////////////////////////////////////// // // // DONNEES ASSOCIEES A LA RESOLUTION DES EQUATIONS D'UN RESEAU // // // ...
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Ex9_3.sce
//Chapter 9, Example 9.3, Page 245 clc clear //Find fluence and H Sp = 10**9 dt = 600 r = 1500 E = 0.03103 phi = Sp*dt/(4*%pi*r**2) H = 1.602*10**-10*E*phi printf("fluence = %e cm^2\n",phi) printf(" H = %f microSv\n",H*10**8) // Answer may vary due to round off error
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Example1_29.sce
clc // Given That theta = 60 // angle between plane of vibration of incident beam with optic axis //Sample Problem 29 Page No. 859 printf("\n # Problem 29 # \n ") printf("Standard formula used is \n I = A^2*cos^2(theta) \n") ratio = (tan(theta*%pi /180))^2 // ratio of extraordinary and aordinary intensites ...
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ex18.sce
//ques18 //Entropy Generation during a Throttling Process clear clc //state 1 P1=7;//MPa T1=450;//C //from table h1=3288.3;//kJ/kg s1=6.6353;//kJ/kg.K //state 2 P2=3;//MPa h2=3288.3;//h2=h1 s2=7.0046;//kJ/kg.K sgen=(s2-s1); printf('Entropy of generation per unit mass = %.4f kJ/kg.K',sgen);
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ok_globaldeclarations4.tst
; checks global declarations (set-option :global-declarations true) (set-logic QF_UF) (declare-fun a () Bool) (assert (not a)) (check-sat) (reset-assertions) (assert a) (check-sat)
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test_3.sce
// Test # 3 : Checking the type for Input Argument #3 exec('./zpklp2hp.sci',-1); [z,p,k,n,d]=zpklp2hp(0.3,0.2,[0.4 0.8],0.5,0.6); // !--error 10000 //K must be a scalar //at line 57 of function zpklp2hp called by : //[z,p,k,n,d]=zpklp2hp(0.3,0.2,[0.7,0.9],0.5,0.6)
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3_5_2.sce
clc //initialisation of variables p= 0.005 //lbf/in^2 w= 62.4 //lbf/ft^3 h= 1 //in //CALCULATIONS p= w*h/1728 //RESULTS printf (' pressure difference = %.4f lbf/in^2 ',p)
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spi_read.sci
function data = spi_read(addr,bytes) r = ftdi('SPI',[bitand(addr,127),zeros(1,bytes)]); data = r(2:bytes+1); endfunction
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ex_8_18_3.sce
//Example 8.18.3: alphas,speed and delay angle clc; clear; close; //given data : format('v',7) v1=208;// vsrms=v1/sqrt(3);// n=1000;//rpm w=n*(%pi/30);//in rad/s ang=0;// ef=((3*sqrt(3)*sqrt(2)*vsrms*cosd(ang))/%pi);//in volts rf=140;//in ohms If=ef/rf;//in amperes t=120;//N-m kv=1.2;// ia=(t)/(kv*If);//in amperes eg=...
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Example2_5_2.sce
// Example 2.5.2 clc; clear; delta = 1.2/100; // Relative refractive difference index n1=1.45; // Core refractive index NA= n1*sqrt(2*delta); //computing numerical aperture Acceptance_angle = asind(NA); //computing acceptance angle si = %pi * NA^2; //computing solid acceptance angle ...
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Ex5_1.sce
//Ex:5.1 clc; clear; close; t=0.1*10^-6;// pulse broading in sec d=12;// disance in km B=1/(2*t);// max bandwidth MHz ds=t/d;// dispersion in ns/km bl=B*d;// bandwidth length product printf("The max bandwidth =%d MHz", B/10^6); printf("\n The dispersion =%f ns/km", ds*10^9); printf("\n bandwidth length produ...
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Ch04Ex13.sce
// Scilab code Ex4.13: Pg 127-128 (2008) clc; clear; l_A = 0.25; // Mean length of cicuit A, m l_B = 0.15; // Mean length of cicuit A, m A_A = 11.5e-04; // Cross-sectional area of circuit A, metre-square A_B = 12e-04; // Cross-sectional area of circuit ...