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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 16.11w //calculation of the minimum distance between the source and the detector for maximum sound detection //given data nu=180//frequency(in Hz) d=2//distance(in m) v=360//speed(in m/s) of the sound wave in air ...
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clc // Given That lambda = 5.896e-7 // wavelength of light in meter D = 4e-3 // diameter of 7th brighter fringe in m R = 1 // radius of curvature in m // Sample Problem 39 on page no. 1.54 printf("\n # PROBLEM 39 # \n") n = 7 // for seventh brighter fringe mu = 2*(2*n-1)*lambda*R / D^2 // calculation for refractive i...
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// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the BSD. // This source file is licensed as described in the file LICENSE, which // you should have received as part of this distribution. The terms // are also available at // https://opensource.org/licenses/BSD-3-Clause // Au...
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//7.17 clc; Vm=400*2^0.5; alph=30; Vavg=3*3^0.5*Vm/(2*%pi*3^0.5)*(1+cosd(alph)); I=5; R=0.1; Eb=Vavg-I*R; N=Eb/0.3; printf("Speed at no load=%.0f rpm",N) N=1600; Eb=N*0.3; I=50; V=Eb+I*R; alph=acosd(3^0.5*2*%pi*V/(Vm*3*3^0.5)-1) printf("\nFiring angle =%.2f degree",alph)
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//Optoelectronics - An Introduction, 2nd Edition by J. Wilson and J.F.B. Hawkes //Example 10.4 //OS=Windows XP sp3 //Scilab version 5.5.2 clc; clear; //given N=1000;//Number of turns of fiber r=0.1;//Radius of fiber in m Omega=15*%pi/(180*3600);//Multiplying by %pi/180 & Dividing by 3600 to convert the earth...
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//Ex 1.40.8 clc;clear;close; format('v',7); //Given : T=300;//K rho_i=45;//ohm-cm //part (i) mu_n=3800;//cm^2/V-s mu_p=1800;//cm^2/V-s ni=2.5*10^13;//per cm^3 q=1.6*10^-19;//Coulomb sigma=ni*q*(mu_n+mu_p);//(ohm-cm)^-1 rho=1/sigma;//ohm-cm disp(round(rho),"Resistivity of intrinsic Ge at 300K(ohm-cm) : "...
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// Example 1.6 // Computation of (a) Frequency (b) Pole flux // Page No. 27 clc; clear; close; // Given data w=36; // Angular frequency E=24.2; // Voltage pi=3.14; N=6; // Number of turns of rotor // (a) frequency f=w/(2*pi); // Rela...
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lomaittua V;IND;PL;3;POS;PRS lomaittua V;NFIN lomaittua V;IND;SG;3;POS;PRS lomaittua V;IND;SG;1;POS;PRS yhteiskundupoliitiekalline ADJ;NOM;SG yhteiskundupoliitiekalline ADJ;GEN;SG yhteiskundupoliitiekalline ADJ;PRT;PL yhteiskundupoliitiekalline ADJ;PRT;SG gektuaru N;NOM;SG gektuaru N;PRT;PL gektuaru N;PRT;SG gektuaru N...
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//Exa9 clc; clear; close; disp(" Amount Units"); disp("Production Units % Equivalent % Equivalent"); disp(" Completion Units Completion Units"); disp("Finished & Transfered ...
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// (z-1)/t function[der] = ZDerivative(u,t) z = poly(0,'z'); der = (z -1)/t; endfunction
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//Determine force P //refer fig.5.21 //From FBD theta=250*%pi/180 //radians r=250 //mm mu=0.3 //from rope friction equation //T2=T1*%e^(mu*theta) //also (T2-T2)*r=M //solving we get T1=(300*1000)/(250*(3.7025-1)) //N T2=3.7025*T1 //N //Consider the equilibrium of lever arm, P=(T2*50)/300 //N printf(...
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// Exa 6.35 format('v',7);clc;clear;close; // Given data R3 = 260;//resistance in ohm C4 = 0.5;// in µF C4 = C4 * 10^-6;// in F C2 = 106;// in pF C2 = C2 * 10^-12;// in F R4 = 1000/%pi;//resistance in ohm r1 = (C4/C2)*R3;//resistance in ohm C1 = (R4/R3)*C2;// in F Epsilon_o = 8.854*10^-12; d = 4.5// in mm ...
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// Exa 6.14 clc; clear; close; // Given data P1 = 14;// in bar P2 = 1.2;// in bar h_f1 = 830; h_fg1 = 1958; h_g2 = 2684.9; x = (h_g2-h_f1)/h_fg1; disp(x,"Dryness fraction of steam is");
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(sorting.tst AllSort.java Ins_sort_ops.java Ins_sort_ops_typed.java Ins_sort_simple.java Ins_sort_typed.java Intlist_insertion_sort.java Makefile MergeSort.java old S08.bsh sorting.tst String_insertion_sort.java tmp Typed_list_functions.java (section (Overview) ( String_insertion_sort.java - string...
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చూపించు V;SG;2;PST అనుగ్రహించు V;FEM;SG;3;PST అతిక్రమించు V;FEM;PL;3;PST విప్పు V;FEM;PL;3;PST అపహరించు V;MASC;SG;3;FUT కోయు V;FEM;SG;3;PST వ్రాయు V;PL;2;PST ప్రయత్నించు V;SG;2;PST ప్రేమించు V;PL;1;PST నిర్మించు V;MASC;PL;3;PST చేయు V;SG;2;FUT అసురుడు N;INS;PL కట్టు V;FEM;PL;3;PST పుట్టు V;DUR;PL;2;PRS వరుణుడు N;NOM;SG...
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//Exa 5.8 clc; clear; close; //Given Data : format('v',7); d=1*100;//in cm dia=1;//in cm r=dia/2;//in cm Length=20;//in km V=33;//in KV P=10;//in MW cosfi=0.8;//unitless f=50;//in Hz R=0.19;//in ohm/km/phase //Part (i) : L=2*10^-7*log(d/r);//in H/m L20=L*Length*10^3;//in H XL=2*%pi*f*L20;//in ohm R20...
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// Test #10 : Valid case #2 exec('./zpklp2xn.sci',-1); [z,p,k,n,d]=zpklp2xn([3 6],5*%i,2,[0.6 0.9],[0.3,0.5],'stop'); disp(d); disp(n); disp(k); disp(p); disp(z); // //Scilab Output //d=1. 0.1830462 - 0.1557084 //n= - 0.1557084 0.1830462 1. //k=-0.2417442 + 7.7627201i //p=-0.5518990 + 0.1861402i // ...
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clc; f=50; y=0.05; RL=100; L=RL/(y*3*sqrt(2)*2*%pi*f); disp('H',L*1,"L="); f=400; y=0.05; L=RL/(y*3*sqrt(2)*2*%pi*f); disp('H',L*1,"L=");
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//Chapter 2 //Example 2-2 //ProbOnPWM //Page 34 clear;clc; //Given f=50;//in Hz Vtemp=4; //input signal in volts Ecm=10; //maximum peak voltage of sawtooth carrier wave in volts //Example 2-2(a) T=1/f; Th=(Vtemp*T)/Ecm;//High time in seconds printf("\n\n High Time = %.4f s \n\n",Th) //Example 2-2(b) d=(Th/T)*100;//...
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//Chapter 7, Problem 5 clc; B=0.25; //Magnetic flux density u0=4*%pi*10^-7; //permeability of free space l=12*10^-3; //Length H=B/u0; //Calculating magnetic field strength mmf=H*l; //Calculating magnetomotiv...
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v= 6.12*(10^7); //receding velocity with respect to Earth, m/s c= 3*(10^8); //velocity of light, m/s L0= 500; //initial wavelength of spectral line, nm L= L0*sqrt(((1+(v/c))/(1-(v/c)))); //final wavelength of spectral light, nm Ls= L-L0; //shift in wavelength, nm disp(Ls,"Shift in Green spectral line (in nm) is:...
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errcatch(-1,"stop");mode(2);//Initialisation of variables v=3e9//cms per second X=.06//e.s unit R=300//cms //(m*v^2/r)=X*e electronbymass=v^2/(R*X) printf('e/m ratio is %e esu \n',electronbymass) exit();
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Mmax=440 Mmin=-220 sigmay=410*10^6 sigmau=550*10^6 sigmae=0.5*sigmau FS=2 syms d Tmax=330 Tmin=-110 Tm=(Tmax+Tmin)/2 taum=(16*Tm)/(%pi*d^3) disp(taum,"Mean shear stress=") Tv=(Tmax-Tmin)/2 tauv=(16*Tv)/(%pi*d^3) disp(tauv,"Variable shear stress=") taue=0.55*sigmae Ksur=0.62 Ksz=0.85 Kfs=1 tauy=o.5*si...
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#************************************************************ # Scenario of test # # date : Wed Jun 3 13:36:50 2009 #************************************************************ p3d_sel_desc_name P3D_ENV test p3d_sel_desc_name P3D_ROBOT CylinderRob p3d_set_robot_steering_method Linear p3d_set_robot_current 0.000...
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Ex1_40_12.sce
//Ex 1.40.12 clc;clear;close; format('v',9); //Given : NA=2*10^16;//per cm^3 ND=10^16;//per cm^3 p=NA-ND;//per cm^3 disp(p,"Material is p-type & Carrier concentration(holes per cm^3) : ");
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4_5.sce
clc; R_=8314.5; m_=28; R=R_/m_ p1=1.05;//bar p2=4.2;//bar s2=R*log(p1)/1000; s1=R*log(p2)/1000; disp("change of entropy is:"); disp("kJ/kg K",s2-s1); T=15+273; V=0.03; m=p1*V*10^5/(R*T); S1=m*s1; S2=m*s2; Q=T*(S1-S2); disp("heat rejected is:"); disp("kJ/kg",Q); W=-Q; disp("work done is:"); disp("kJ",W)
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////Variable Declaration E0r1 = -0.877 //Std Electrod potential for Rx2 : Al3+ + 3e- ------> Al (s) E0r2 = -1.660 //Std Electrod potential for Rx2 : Al3+ + 3e- ------> Al (s) E0r3 = +0.071 //Std Electrod potential for Rx3 : AgBr (s) + e- ------> Ag(s) +Br- (aq.) //Calculations...
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//Example 6.2, Page 579 clc x=log(exp(.827)) t=(log(143))/x printf("\n The elapsed time is %f *10^9 year",t)
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// RESOLUÇÃO NUMÉRICA DE SISTEMAS LINEARES (AX=b) // MÉTODO ITERATIVO DE GAUSS - JACOB function w=gaussjacob(A,b,X0,eps1) // A: matriz dos coeficientes do sistema de equações lineares. // b: vetor b dos termos independentes // X0: vetor solucao inicial //eps1: precisao utilizada no criterio de parada ...
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example18_18.sce
clc // Given that H = 600 // magnetic flux in A/m a = 0.2e-4 // area of cross section of rod in m^2 phi = 2.4e-5 // flux in weber mu_ = 4*%pi * 1e-7 // permeability of space in N/A^2 // Sample Problem 18 on page no. 18.27 printf("\n # PROBLEM 18 # \n") printf("Standard formula used \n ") printf(" mu_r = 1 + Chi \n") ...
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clc clear Vc=5*(10^-4); D=0.15; L=0.2; Vs=(22/7)*D*D*L*(1/4); r=(Vc+Vs)/Vc; G=1.4; Ea=[1-(1/(r^(G-1)))]; Eith=0.3; Erel=Eith/Ea; printf('Erel= %3.2f Percent',Erel*100); printf('\n'); Pm=500; //in kPa n=1000/2; IP=(Pm*Vs*n)/60; printf('IP= %3.2f kW',IP); printf('\n');
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clear// //Variables VCC = 12.0 //Source voltage (in volts) R1 = 100.0 * 10**3 //Resistance (in ohm) R2 = 20.0 * 10**3 //Resistance (in ohm) R3 = 10.0 * 10**3 //Resistance (in ohm) R4 = 2.0 * 10**3 //Resistance (in ohm)...
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clear; clc; syms n z X; x=[5 3 -2 0 4 -3] X=0; for i=-2:3; X=X+x(i+3)*z^-i end
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clear; clc; syms z n ; x=(1/3)^n; X=symsum(x*z^-n,n,0,%inf) disp(X,"X(z)=") Xz=z/(z-1/3); Yz=z/(2*(z-1/2))+z^2/((z-1/3)*(z-1/2)); //y[-1]=1 Y1=z/(z-1/2); Y2=z^2/((z-1/3)*(z-1/2)); FY1=Y1*z^(n-1)*(z-1/2); y1n= limit(FY1,z,1/2); FY21 = Y2*(z^(n-1))*(z-1/2); FY22 = Y2*(z^(n-1))*(z-1/3); y21n = limit(FY21,z,...
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clc //initialisation of variables T= 250 //F hg= 1164.0 //Btu/lb P= 29.825 //Psia Vg= 13.821 //cu ft/lb //CALCULATIONS ug= hg-(P*Vg*144/778) //RESULTS printf ('Internal energy= %.1f Btu/lb',ug)
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clear; clc; disp('Example 4.19'); // aim : To determine the condition of the steam after // (a) isothermal compression to half its initial volume,heat rejected // (b) hyperbolic compression to half its initial volume // Given values V1 = .3951;// initial volume,[m^3] P1 = 1.5;// initial pressure,[MN/...
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 16.1w //calculation of the depth of the sea and wavelength of the signal in the water //given data nu=50*10^3//frequency(in Hz) of the given signal t=0.8//time(in s)requires for reflected wave to return v=1500//speed...
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clc; L=0.001; C=0.0000000001; f0=1/(2*3.14*(L*C)^0.5); disp('Hz',floor(f0/1000),"f0=");//The answers vary due to round off error
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// Scilab code Ex9.7: Pg.404 (2008) clc; clear; T = 300; // Room temperature, K k = 1.38e-023; // Boltzmann constant, J/K e = 1.6e-019; // Energy equivalent of 1 eV, J h = 6.626e-034; // Planck's constant, Js f = 4.83e+014; // average frequency of visible light, Hz // Part (a) kT = k*T/e; // E...
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//Chapter 05: Induction and Recursion clc; clear; function res=greatestcommondivisior(a,b) if a==0 then res=b else res=greatestcommondivisior(modulo(b,a),a) end return res endfunction num1=input("Enter the first number:") num2=input("Enter the second number:") res_gcd=greatestcommondivisior(num1,num2) mp...
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//Example 2-19, Page No - 52 clear clc Q= 150 Vs=3*10^-6 Vc= Q*Vs printf('The voltage across capacitor is %.1f microvolt',Vc*10^6)
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s = 100; rand("seed"); xdata = [10:10:100]; for n= xdata i=n/10; A=rand(n,n); L=tril(A); U=triu(A); xex=rand(n,1); b = U*xex; x= usolve(U,b); fErrorU(i) = norm(xex-x,2)/norm(xex,2); bErrorU(i) = norm(b-U*x,2)/norm(b,2); b = L*xex; x = usolve(L,b); fErrorL(i) = norm(xex-x,2)/norm(xex,2); bErrorL(...
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// Chapter 6 example 17 //------------------------------------------------------------------------------ clc; clear; // Given data p = 0.1*10^-2; // resistivity in ohm-m t = 100*10^-6; // thickness in m AR = 10/1; // aspect ratio // Calculations ps = p/t R = ps*AR; ...
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function unix_x(cmd) //unix_x - shell command execution, results redirected in an xless window //%Syntax // unix_x(cmd) //%Parameters // cmd - a character string //%Description // cmd instruction is passed to shell, the standard output is redirected // to a background xless window //%Examples // unix_x("ls") //%See a...
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//Voltage V, Resistances R1 and R2, Capacitive reactance Xc close(); clear; clc; R1 = 10;//ohm R2 = 20; Xc = -11.55*%i; V = 173.2;//V //By Nodal analysis V1 = V/(R1*((1/R1)+(1/R2)+(1/Xc))); V1r = polar(V1); V1arg = atan(imag(V1),real(V1))*180/%pi; V2 = V-V1; V2r = polar(V2); V2arg = atan(imag(V2),real(V2)...
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[ma i] = max(y) [mi j] = min(y) Tpi = x(j-1) - x(i); arg = [0:0.01:Tpi]; newy = ma*sin(arg / Tpi * %pi); arg2 = arg + Tpi; newy2 = ma*sin(arg2 / Tpi * %pi); plot(x, y); plot(arg,newy); plot(arg2,newy2);
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clc; //Armature reaction is neglected. Vt=250;//Supply voltage P=4;//No of poles A=2;//No of parallel paths for armature conductors Z=500;//No of armature conductors Ra=0.25;//armature circuit resistance in ohm Rf=125;//field resistance in ohm phi=0.02;//flux per pole in weber Il=14;//current drawn by motor fr...
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//To find speed lost clc //Given: d1=1, d2=2.25 //m N1=200 //rpm sigma1=1.4*10^6, sigma2=0.5*10^6, E=100*10^6 //N/m^2 //Solution: //Calculating the speed of the driven pulley N21=N1*(d1/d2) //rpm //Calculating the speed of the shaft considering creep N22=N1*(d1/d2)*(E+sqrt(sigma2))/(E+sqrt(sigma1)) //rpm //C...
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clc clear //Input data Vs=0.003;//Swept volume in m^3 bmep=9;//Brake mean effective pressure in bar N=4000;//The speed of the engine in rpm ni=30;//Indicated thermal efficiency in percent nm=90;//Mechanical efficiency in percent bmep1=12;//The brake mean effective pressure of other engine in bar N1=4000;//The ...
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clc //given u=.3 theta=270*%pi/180 l=18//in a=4//in Di=15//in Do=21//in w=.5//tons W=w*2204//lb Q=W*Di/Do//required tangential braking force on the drum k=%e^(u*theta)//k=T1/T2 p=Q*a/(l*(k-1)) printf("Least force required, P = %.f lb",p)
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// Exa 8.8 clc; clear; close; // Given data R_f = 1;// in Mohm R_f = R_f * 10^6;// in ohm Ri= 1*10^6;// in ohm R1 = Ri;// in ohm A_VF = -(R_f/R1); disp(A_VF,"The Voltage gain is");
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clc Nc=2.8*10^(19) disp("Nc = "+string(Nc)+"cm^-3") Nv=1.04*10^(19) disp("Nv = "+string(Nv)+"cm^-3") //NOTE: Ec-Ev = forbidden band gap energy = Eg Eg = 1.1 e = 1.6*10^-19 disp("e= "+string(e)+"C")//initializing value of charge of electron kbT = 0.026 disp("kbT = "+string(kbT)+"eV") //initializing value of ...
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//example 13.2// clc //clears the screen// clear //clears all existing variables// mi=125; //minimum time period in ns// ma=100 //maximum time period in ms// f=1000/mi; //frequency in MHz// disp(f,'frequency of microcontroller (in MHz) = ')
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errcatch(-1,"stop");mode(2);// Example 1.6, page no-54 ref_jun=100 mV_100=0.645 mV_1000=9.585 mV_1200=11.947 op1=mV_1000-mV_100 op2=mV_1200-mV_100 printf("Millivolt to be fed checking 1000 C = %.3f mV",op1) printf("\nMillivolt to be fed checking 1200 C = %.3f mV",op2) exit();
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//Chapter-1,Example1_5_4,pg 1-31 //a tetrahedron CAEH can be considered with C as the apex of the tetrahedron. //the edges AE,AH and EH of the tetrahedron will then be the face of the cube faces ABEF,ADHF,EFHG resp. //from fig //AO=ra+rc and AJ=ra //AE=root(2)*a and AG=root(3)*a //AO/AJ=AG/AE=(ra+rc)/...
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//=========================================================================== //chapter 5 example 13 clc;clear all; //variable declaration V1 = 50*10^-3; //voltage in V I1 = 5; //current in A I2 = 10; //current in A v1 =4; v2 =4.2; //calculations //v1 ...
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clc //initialisation of variables k= 0.01 l= 24 //ft g= 32.2 //ft/sec^2 w= 15.6 //lbs/in^2 W= 62.4 //lbs/ft^3 h= 12 //ft l1= 100 //ft //CALCULATIONS f= k*(1+(1/(h/l))) C= sqrt(2*g/f) L= w*144/(W) i= h/l1 v= C*sqrt(k*h/(4*l)) Q= v*60*%pi*(1/l)^2/4 v1= sqrt(h*2*g*(1/l)/(4*f*3*l1)) Q1= v1*60*%pi*(1/l)^2/...
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clc;funcprot(0);//EXAMPLE 11.7 // Initialisation of Variables as=6;........................//Air supply in kg/min fs=0.45;..........................//Fuel supply in kg/min p1=1.013;.......................//Atmospheric pressure in bar t1=300;......................//Atmospheric temperature in Kelvin rhof=740;.........
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clc clear //Initialization of variables disp("From Table B-4,") h=1187.2 //Btu/lbm t=328 //F //calculations p2=100 //psia u2=1187.2 //Btu/lbm t2=540 //F dt=t2-t //results printf("Final temperature of steam = %d F",t2) printf("\n Final pressure = %d psia",p2) printf("\n Change in temperature = %d F",dt)
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//Ex10.2.8.1;Find Reversible voltage for hydrogen oxygen fuel cell del_G=-237.3*10^3;//Joules/gm-mole of H2 //Reversible voltafe E of a cell is given by =del_Wrev/nF=-del_G/nF //since 2 electrons are transferred per molecule of H2.thus n=2; F=96500;//Faraday's constant E=-del_G/(n*F); printf("Reversible voltage=...
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// @Harness: verifier // @Purpose: "Test for extra operand in addressing mode unification" // @Result: "MissingOperandInAddrModeUnification @ 9:22" architecture extra_op_02 { operand-type A[5]: int [0,31]; addr-mode A1 a: A { } addr-mode A2 a: A, b: A { } addr-set AS { A2, A1 } }
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//Ex:4.8 clc; clear; close; V=240; c=100*10^-9; f=50; X_c=1/(2*%pi*f*c); I_c=V/X_c; printf("Current flow = %f A",I_c);
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clc;clear; //Example 2.8 //constants used g=9.81;//acceleration due to gravity in m/s^2; //given values m=1200; V=90/3.6;//converting km/h into m/s d=30; //calculation Vver=V*sind(d);//velocity in vertical direction Wg=m*g*Vver/1000; disp(Wg,'the addtional power in kW')
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// Ex8_7 clc; // Given: ma=9728;// cpm mb=11008;// cpm mab=20032;// cpm // Solution: t1=(ma+mb-mab)/(mab^2-ma^2-mb^2);// in min t2=t1*60;// in seconds t=t2*1000000;// in microseconds printf("\n The resolving time of the given system in microseconds is = %f",t) //From true count rate equation we...
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clc; funcprot(0); //Example 8.7 Lift Drag Ratio // Initialisation of variables W = 5000; LD_Max = 21.5; // Calculations D = W/LD_Max; //Results disp(D,"Minimum drag on clark Y wing (lb)");
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run2"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monito...
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//Chapter 5: Chemical Kinetics and Catalysis //Problem: 3 clc; //Declaration of Variables t0 = 37.0 //in cm cube of KMnO4 t5 = 29.8 //in cm cube of KMnO4 t15 = 19.6 //in cm cube of KMnO4 t25 = 12.3 //in cm cube of KMnO4 t45 = 5.00 ...
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w0=1000 wd=997 Yin=1.2E-3 zeta=sqrt(1-(wd/w0)^2) alpha=zeta*w0 R=1/Yin C=1/(2*alpha*R) L=1/(w0*w0*C) disp(C,L,R)
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mode( -1 ) unit = input("Выберите единицу длины L: дм, км, м, мм или см: ") L = input("Введите значение длины L в выбранных единицах: ") select unit case "дм" then L = L / 10; case "км" then L = L * 1000; case "м" then L = L; case "мм" then L = L / 1000; case "см" then L = L / 100; else ...
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clc clear printf("Example 10.8 | Page number 355 \n\n"); //Find all thermodynamic property of steam //Given data p = 10e6 //Pa t = 550 //°C //Solution //From superheated property table v_500 = 0.03279 //m^3/kg v_600 = 0.03837 //m^3/kg v_550 = v_500 + (v_500-v_600)/(500-600)*(550-500) //m^3/kg h_500 = 3373.6...
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10000 ab+cde 10000 ab-cde
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roy gould less than a year from now the world is going to celebrate the international year of astronomy which marks the 400th anniversary of galileo s first glimpse of the night sky through a telescope in a few months the world is also going to celebrate the launch of a new invention from microsoft research which i thi...
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//(Welded and Riveted Joints) Example 8.24 //Refer Fig.8.67 on page 322 //Eccentric force acting on the bracket P (kN) P = 25 //Eccentricity e (mm) e = 100 //Permissible shear stress tau (N/mm2) tau = 60 //Number of rivets n n = 4 //Distance between two rivet centres dist (mm) dist = 100
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//Example_a_4_1 page no:175 clc; V2=100-50-20; V5=100-50; V2ohm=sqrt(2)*30; V5ohm=sqrt(2)*50; Va2ohm=V2ohm*0.637; Va5ohm=V5ohm*0.637; disp(V2,"the voltage across 2 ohm resistor is (in V)"); disp(V5,"the voltage across 5 ohm resistor is (in V)"); disp(V2ohm,"peak value of voltage across 2 ohm resistor is (in V...
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lambda=0.16666666667; // 1/6 np=100; // number of units in the brush q=2; f=q+1; h2n=0.25; M=(%pi*np/2)/acos(sqrt((f-1)/f)); // // Считаем потенциал по формуле for k=1:2*np+5 if k < h2n*2*np then V(k)= -3*log(cos(h2n*%pi/2))-((3*%pi^2/8)*((h2n)^2-(h2n*2*np/M)^2))-(-3*log(cos((%pi/2)*(k/200)))-((3*%pi^2/8)*...
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clear; clc; //To find Approx Value function[A]=approx(V,n) A=round(V*10^n)/10^n;//V-Value n-To what place funcprot(0) endfunction //Example 6.9 //Caption : Program to Find Residual Enthalpy and Entropy and V by Lee/Kesler //Given Values T=450;//[K] P=140;//[bar] //pseudo parameters Tc1=3...
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function y = moc_logical (x) //Convert x to a logical value // Calling Sequence // y=moc_logical(x) // Parameters // y: boolean vector or matrix // A:vector or matrix // Description // Convert x to a boolean values // // Authors // H. Nahrstaedt - 2014 [nargout,nargin]=argn(0); if (nargin == 1) if (moc_islogical (x)...
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//Ex11_4 clc //according to the given eqution for output current, we have: I1 = 5.0 I2 = 0.9 I3 = 0.6 I4 = 0.3 I5 = 0.01 D2 = I2/I1// second harmonic distortion D3 = I3/I1//third harmonic distortion D4 = I4/I1//fourth harmonic distortion D5 = I5/I1//fifth harmonic distortion disp("I1 = "+string(I1)+"A") di...
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clc; clear; p=0.4;//kW dia=0.6;//m v2=12;//m/s v1=0;//m/s //energy equation Wuseful=(v2^2)/2; //wshaftin= Wshaftin/m wshaftin=(p*1000)/(1.23*%pi*(0.6^2)*12/4); eff=Wuseful/wshaftin; disp("N.m/kg",Wuseful,"The work to air which provides useful effect-=") disp(eff,"Fluid mechanical efficiency of this fan=")
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sp=x1'; st=x2; in4=ones(1,15); for i=1:m, for j=1:m, in4=[1,xx(1,i),yy(1,j),xx(1,i)^2,xx(1,i)*yy(1,j),yy(1,j)^2,xx(1,i)^3,xx(1,i)^2*yy(1,j),xx(1,i)*yy(1,j)^2,yy(1,j)^3,xx(1,i)^4,xx(1,i)^3*yy(1,j),xx(1,i)^2*yy(1,j)^2,xx(1,i)*yy(1,j)^3,yy(1,j)^4]; in3=in4(1,1:10); in2=in3(1,1:6); in1=in2(1,1:3); ...
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exec("alaqiltest.start", -1); try // This call must fail because the constructor does not exist Spam = new_Spam() alaqiltesterror(); catch end exec("alaqiltest.quit", -1);
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// Exp1 : erreur en translation et mouvement de translation pathSave = "results/Exp1"; Delta = [-0.04 0.07 0.0 0.00*%pi/180 0.0*%pi/180 0.00*%pi/180]; Uc_m = [0.1; 0; 0.0; 0; 0; 0]; // init velocity FlagNoise = 0; // Exp2 : erreur en translation et trans rot pathSave = "results...
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clc; clear; close; deff('y=f(x)','y=sin(x)') x0=0; xn=%pi; n=10; //n should be even h=(xn-x0)/n; s=0; for i=1:2:n s=s+f(x0+(i-1)*h)+4*f(x0+i*h)+f(x0+(i+1)*h); end integral=(h*s)/3; printf('\nThe value of integral is=%g\n',integral)
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//Example 14.1// //(a)=The mass of each component will be a=1.00;//m^3 //composite b=0.70;//m^3 //Vol % E-glass fibers c=a-b mprintf("c = %f m^3",c) d=2.54;//Mg/m^3 //density Of E-glass mg=d*b mprintf("\nmg = %f Mg",mg) e=1.1;//Mg/m^3 //density of epoxy me=e*c mprintf("\nme = %f Mg",me) w=(mg/(mg+me))*100...
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clear; clc; close; Vcc = 22; Vbe = 0.7; Vt = 26*(10^(-3)); R1 = 56*(10^(3)); R2 = 8.2*(10^(3)); Re = 1.5*(10^(3)); Rc = 6.8*(10^(3)); ro = 50*(10^(3)); Beta = 90; Vb = (R2/(R1+R2))*Vcc; Ve = Vb - Vbe; Ie = Ve/Re; re = Vt/Ie; disp(re,"Value of diode resistive element is :"); disp("At ro=infinity,t...
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clear; clc; funcprot(0); //given data D2 = 23.76;//diameter of rotor in cm N = 38140;//rotational speed in rev/min alpha2 = 72;//absolute flow angle in deg d = 0.5*D2;//rotor mean exit diameter //Calcultaions U2 = %pi*N*D2/(100*60); w2 = U2/tan(alpha2*%pi/180); c2 = U2*sin(alpha2*%pi/180); w3 = 2*w2; U...
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// calculate current through the motor winding // Electronic Principles // By Albert Malvino , David Bates // Seventh Edition // The McGraw-Hill Companies // Example 14-9, page 502 clear; clc; close; // Given data // MTP4N80E Vgson=10 ;// gate-source on-voltage in volts Idon=2; // on-state drain current ...
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//Chapter-2, Example 2.15, Page 2.23 //============================================================================= clc clear //INPUT DATA V1=6000;//Primary volatge in V V2=500;//Secondary voltage in V Z2=complex(4,3) //CALCULATIONS K=(V2/V1);//Voltage transformation ratio I2=(V2/Z2);//Secondary current ...
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# blinky_b.tst Test the blinky example: >>> import blinky_examples >>> test2 = blinky_examples.test_compile('blinky', False) >>> test2 == blinky_examples.target_blinky True
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morning i am working on what i am going to make because there are so many different types you can use. afernoon i have add so many different things i plan on links my pages up and using different types of code,imgs,and backgrounds,buttons, and maybe try and use a game and i will be adding some sound 02-13-2019 mo...
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clc; Vsmin=8; Vsmax=12; Rs=2.2*10**3; Vz=5; RL=10*10**3; Ismin=(Vsmin-Vz)/Rs; Ismax=(Vsmax-Vz)/Rs; IL=Vz/RL; Izmin=Ismin-IL; disp('mA',Izmin*10**3,"Izmin="); Izmax=Ismax-IL; disp('mA',Izmax*10**3,"Izmax=");
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function HELPplzr() // This program is free software; you can redistribute it and/or modify // it under the terms of the GNU General Public License as published by // the Free Software Foundation; either version 2 of the License, or // (at your option) any later version. // // This program is distributed in ...
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clc L=10*10^-3; //ASssigning values to parameters Im=5; w=2000; function y=f(t), y=Im*sin(w*t+%pi/2),endfunction I=Im/sqrt(2); Xl=2*%pi*L; Vm=L*Im*w; Vl=Vm/sqrt(2); disp("Volts",Vl,"Voltage Vl");
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//Chapter-11 example 34 //============================================================================= clc; clear; //input data Pt = 500*10^3;//peal pulse power in watts Pmin = 1*10^-12;//minimum receivable power Ac = 5;//area of capture in m^s RCS = 16;//radar cross sectional area in m^2 F = 10*10^9;//...
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% Problem: Calculate the PDE's for the isovector of the heat equation. % -------- % (c.f. B.K. Harrison, f.B. Estabrook, "Geometric Approach...", % J. Math. Phys. 12, 653, 1971) % The heat equation @ psi = @ psi is equivalent to the set of exterior % xx t % equati...
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//Caption: step size //Example 4.30i //page no 202 //Find step size clear; clc; fs=64000; // samples/sec Amax=1; fm=3500; //A=del/(2*%pi*fm*Ts) del=(2*%pi*fm*Amax)/fs; disp("mV",del*1000,"Step Size ");
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-- Fuzzy Logix, LLC: Functional Testing Script for DB Lytix functions on Netezza -- -- Copyright (c): 2016 Fuzzy Logix, LLC -- -- NOTICE: All information contained herein is, and remains the property of Fuzzy Logix, LLC. -- The intellectual and technical concepts contained herein are proprietary to Fuzzy Logix, LLC. -...