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clear;clc maior = 0;menor = 0;escolha = 1; while(escolha == 1) printf("Sua idade: \n") idade = input("") if(idade < 18) menor = menor + 1 else maior = maior + 1 end escolha = input(" Continuar?[1 - Sim /2 - Não]") end printf("menor = %g e maior= %g", menor, maior) pri...
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clc // Fundamental of Electric Circuit // Charles K. Alexander and Matthew N.O Sadiku // Mc Graw Hill of New York // 5th Edition // Part 2 : AC Circuits // Chapter 9 : Sinusoids and Phasors // Example 9 - 11 clear; clc; close; // // Given data L = 5.0000; C = 0.0100; w = 4.0000...
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T1=[1/3 0;0 1/3]; T2=[1/3;0]; T3=[0;1/3]; function Y=f1(X) Y=T1*X; endfunction function Y=f2(X) Y=T1*X+T2; endfunction function Y=f3(X) Y=T1*X+2*T2; endfunction function Y=f4(X) Y=T1*X+T3; endfunction function Y=f5(X) Y=T1*X+2*T2+T3; endfunction function Y=f6(X) Y=T1*X+2*T3; endfunction funct...
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clc // Fundamental of Electric Circuit // Charles K. Alexander and Matthew N.O Sadiku // Mc Graw Hill of New York // 5th Edition // Part 1 : DC Circuits // Chapter 1 : Basic Concepts // Example 1 - 1 clear; clc; close; // // Given data C = 4600; Q = -1.6020 * 10^(-19); /...
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// 10.01.21 function Texrenewcmd(varargin) Nargs=length(varargin); Str=varargin(1); S='\renewcommand{'+Str+'}'; if Nargs>1 Tmp=string(varargin(2)); S=S+'['+Tmp+']'; end; if Nargs>2 Tmp=varargin(3); if type(Tmp)==1 Tmp=string(Tmp); end; S=S+'['+Tmp+']'; end; S=S+'{'; Texc...
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clc T0 = 300 // Atmospheric temperature in K Tg1_ = 300 // Higher temperature of combustion product in degree Celcius Tg2_ = 200 // Lower temperature of combustion product in degree Celcius Ta1 = 40 // Initial air temperature in K cpg = 1.09 // Specific heat capacity of combustion gas in kJ/kgK cpa = 1.005// Specific ...
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//Ex 7.8 clc;clear;close; format('v',6); C=680;//pF f=50;//kHz(Square wave frequency) D=75/100;//duty cycle T=1/f*1000;//micro seconds tHIGH=D*T;//micro seconds tLOW=T-tHIGH;//micro seconds RB=(tLOW*10^-6)/(0.69*C*10^-12);//ohm RA=(tHIGH*10^-6)/(0.695*C*10^-12)-RB;//ohm disp(RA/1000,"Value of RA(kohm)"); di...
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// Example 9.8 I1=10+%i*0; // Current i1=14.14 sin(wt) A I2=10+%i*17.32; // Current i2=28.28 sin(wt+60) A I=I1+I2; // Summation of 2 Current disp(' Summation of 2 Current is = '+string(I)+' Amp or 37.42<40.9 '); // I= 20+i17.32 i.e I= 3...
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//Ex 9 clc; clear; close; cp_33=33;cp_22=22; //let cp of each meter be Rs.1 sp_22=cp_33; //given gain=11; gainPercent=(gain/cp_22)*100; mprintf("The profit percent is %d percent",gainPercent);
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//Example 2.6.1 //Doppler Shift for A leo Satellite //Part1 Velocity of Satellite in Orbit //Variables re=6378 //radius of earth in km h=1000 //altitude in km a=re+h u=(3.986004418*10^5) //Calculation //Part1 Velocity of Satellite in Orbit T=sqrt((4*(%pi^2)*(a^3)/u)) ...
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number1 = input("Give a number: ") number2 = input("Give another number: ") // Return the greater of two numbers if number1>number2 printf("The number %g is greater.", number1) else printf("The number %g is greater.", number2) end
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// Fourier Series Personal Project // Code by mtxslv // In the book "Numerical Analysis", by Burden&Faires, chapter 8, // The Fourier Series are introduced using the Least Squares approach. // One of the examples given is to approximate the function f(x) = |x|. // Now let's see if the derived result using code. funct...
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//Chapter 11 //Example 11.7 //page 423 //To find short circuit currents clc;clear; v_pf=1; //prefault voltage a=0.5+0.8660254*%i; //according to the fig.11.28 we can write Z-bus matrix for positive and negative phase sequence printf('\nstep by step for finding Z1_bus\n') //Bus1 to referance bus Z1_bus=[0.15]; printf(...
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clear; clc; printf("\t\t\tExample Number 7.8\n\n\n"); // heat transfer across vertical air gap // Example 7.8 (page no.-345) // solution L = 0.5;// [m] side length vertical square plate d = 0.015;// [m] distance between plates p = 101325;// [Pa] pressure of air R = 287;// [] universal gas constant T1 = 100...
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//Caption:Find the (a) motor speed (b) power loss in external resistance (c) efficiency //Exa:6.4 clc; clear; close; V=120 N_mfL=2400;//full load speed of motor R_a=0.4;//armature resistance (in ohms) R_sh=160;//shunt field winding resistance I_fL=14.75;//current drawn at full load (in Amperes) I_nL=2;//curr...
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clc; //page no 631 //prob no. 17.7 //A signal with level of 20dBm &amp; insertion loss=1dB &amp; coupling =20dB,directivity=40dB sig_in=20;loss=1;couple=20;direct=40; //Determination of signal level in main guide sig_level_main=sig_in-loss; disp('dBm',sig_level_main,'The signal level in main guide is'); //Determination...
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//Example 3.2 // voltage clc; clear; close; //given data : R1=0.5; // minimum value of resistance in ohm R2=20; // maximum value of resistance in ohm I=1.2; // current in A V1=I*R1; V2=I*R2; disp(V1,"voltage drop in Ist case,V1(V) = ") disp(V2,"voltage drop in IInd case,V2(V) = ")
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//chapter 14 //example 14.7 //page 302 Ao_db=70 // db Av_db=67 // db Rout=1.5 // kilo ohm // since 20*log(Ao)-20*log(Av)=Ao_db-Av_db we get // 20*log(Ao/Av) = Ao_db-Av_db so // Ao/Av = 10^((Ao_db-Av_db)/20) // and also Ao/Av=1+Rout/Rl since Av/Ao=Rl/(Rl+Rout) // so making Rl as subject we get Rl=Rout/...
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// Test # 4 : Input Argument #1 is of complex type exec('./allpasslp2hp.sci',-1); [n,d]=allpasslp2hp(%i,0.3); //!--error 10000 //Wo must be real ,numeric and scalar //at line 37 of function allpasslp2hp called by : //[n,d]= allpasslp2hp(%i,0.3)
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//Problem 43.05: Two coils connected in series have self inductance of 40 mH and 10 mH respectively. The total inductance of the circuit is found to be 60 mH. Determine (a) the mutual inductance between the two coils, and (b) the coefficient of coupling. //initializing the variables: La = 40E-3; // in Henry Lb = 1...
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curDir = get_absolute_file_path('Valaquio_MP2.sce') getd(curDir + '/functions') //============================= Number 1 function item = number1() num = [100.0 154.2349 -12.32157 -(2/3)] for i = 1:1:size(num, 2) disp('=========================='); printf("Input: %f\n\n", num(i)) printf("Double Precision: \n")...
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//Exa 6.32 clc; clear; close; format('v',7); //Given Data : p1=1.5;//MPa p1=p1*10^6/10^5;//bar p_gauge=7;//bar p_at=1;//bar p2=p_gauge+p_at;//bar p3=1;//bar Tsup3=110;//degree C mw=3.5;//Kg ms=48;//Kg Cp=2.1;//KJ/KgK x1=ms/(ms+mw);//dryness hf2=720.9;//KJ/Kg(from steam table) hfg2=2059.3;//KJ/Kg(fro...
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// Example 1.1, page no-53 clear clc c=-40 k=c+273 printf("\nK=%d°K", k) F=((9/5)*c)+32 printf("\nF=%d°F",F) R=((9/5)*c)+492 printf("\nR=%d°R",R)
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var tem3x3 = require("./tem3x3") var gaia = require("./gaia") var layouts = gaia.getAll3X3Layouts() var nlayouts = gaia.rmDuplicated(layouts) var tem3x3 = require("./tem3x3") var clslmat = require("./lmat") var clsz = require("./z") lmat = new clslmat.Lmat() lmat.initLayOutMat() gaia.setZ3X3BG(lmat) // var gaia ...
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V1=42.43+%i*0; //Defining voltage equations in rectangular form V2=14.14+%i*24.49; Va=V1+V2; [Ro,Theta]=polar(Va); Vm=Ro*sqrt(2); disp("Volts",Vm,"Maximum value of voltage considering addition of voltages") function y=f(t), y=Ro*sin(t+Theta),endfunction //Defining voltage equation Vb=V1-V2; [R...
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//To calculate the Time Period //Example 34.2 clear; clc; m=10*10^-6;//Mass of the particle in kg q=100*10^-6;//Charge of the particle in Coloumbs B=25*10^-3;//Magnetic Field Strength in Tesla T=2*%pi*m/(q*B);//Time Period in seconds printf("Time Period of the charge = %d seconds",T);
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//Chapter-11 example 39 //============================================================================= clc; clear; //Given data lamda = 0.06; // wavelength in m Vr = 100 ; // Radial velocity of target in kmph //Calculations Vr1 = Vr*(5/18); //Radial vel. in m/s fd = (2*V...
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clc //Initialization of variables disp("From steam tables,") T1=355.21 //F T2=500 //F hg=1193.4 //Btu/lbm h=1274.8 //Btu/lbm //calculations Qrev=h-hg //results printf("Heat transferred = %.1f Btu/lbm",Qrev)
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clc //ex11.10 t=[0:0.000001:0.002]; V_i=3*cos(2000*%pi*t)-2*cos(6000*%pi*t); //for A A_1000_A_peak=10; A_1000_A_phi=0; A_3000_A_peak=10; A_3000_A_phi=0; V_o_A=A_1000_A_peak*3*cos(2000*%pi*t+A_1000_A_phi)-A_3000_A_peak*2*cos(6000*%pi*t+A_3000_A_phi); //for B A_1000_B_peak=10; A_1000_B_phi=-%pi/4; A_3000_B_p...
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clear clc disp("3*x^2+5*y^2+3*z^2-2*y*z+2*z*x-2*x*y") disp("The matrix of the given quadratic form is ") A=[3 -1 1;-1 5 -1;1 -1 3] disp("let R represents the matrix of transformation and P represents a diagonal matrix whose values are the eigen values of A.then ") [R P]=spec(A) disp("so,canonical form is 2*x^2+3...
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function [y]=integ(P,a,b) for (i=1:length(P)) y(i) = P(i)/ (length(P) - i + 1); end y = [y;0]; endfunction function [y]=avalia(P,x) y = 0; for (i=1:length(P)) y = y + P(i) * x^(length(P)-i); end endfunction function y=ortogonal(a,b,n,x) auxA = [1]; auxB = [1; ...
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//Network Theorem 2 //pg no 3.23 //example 3.20 disp("removing the 30 Ohm resistor from the network"); disp("Applying KVL to supermesh "); disp("-I1+I2=13");....//equation 1 disp("15*I1+100*I2=150");....//equation 2 //Calculation of Vth (Thevenin's voltage) a=3; v=(40*a)-50; printf("\nWriting Vth equation, \n...
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//Ex:7.1 clc; clear; close; I_i=4; V_o=2; V_i=50*10^-3; I_o=200; A_v=V_o/V_i; A_i=I_o/I_i; printf(" Volt gain = %f ",A_v); printf("\n Current gain = %f ",A_i); printf("\n Power gain = %f ",A_i*A_v);
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//Example 5-1 Water Flow through a Garden Hose Nozzle V = 10 //volume of bucket [gal] d_hose = 2 //inner diameter of hose [cm] d_e = 0.8 //diameter of nozzle at exit [cm] dt = 50 //time required to fill the bucket [s] rho = 1 //density of water in [kg/L]
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 18.1w //calculation of position and nature of the image of an object placed at a distance from a concave mirror //given data u=-8; //object distance(in cm) f=-10; //focal length of the concave mirror(in cm) //calcu...
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//check o/p when i/p arg beta is greater than 1 beta=0.3; span=-6; sps=4; h=rcosdesign(beta,span,sps); //output //!--error 10000 //Input should be positive //at line 43 of function checkIpValidity called by : //at line 30 of function rcosdesign called by : //h=rcosdesign(beta,span,sps);
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clc; clear; s = poly(0, 's'); g = 1 / (s * (s^2 + 4*s + 8)); // ---------------------------- // Part a K = 0:0.01:100; k_req = 0; gms = []; pms = []; for i=1:size(K, 2) k = K(i); tf = 1 + k * g; T = syslin('c', tf); gm = g_margin(T); pm = p_margin(T); gms = [gms, gm]; pms = [pms, pm]; if...
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load Mux4Way16.hdl, output-file Mux4Way16.out, output-list a%B1.16.1 b%B1.16.1 c%B1.16.1 d%B1.16.1 sel%B1.2.1 out%B1.16.1; set a %B1000000000000000, set b %B0100000000000000, set c %B0000000000000010, set d %B0000000000000001, set sel %B00, eval, output; set a %B1000000000000000, set b %B0100000000000000, set c %B00000...
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// Example 4.4 clear; clc; close; format('v',7); // Given data ke=0.12;//in Nm/A V=48;//in volt Rph=0.15;//in Ω Vdd=2;//in volt //Calculations omega_mo=V/ke//in radian/sec No=omega_mo*60/(2*%pi)//in rpm disp(No,"No load speed in rpm = "); Ist=(V-Vdd)/(2*Rph);//in Ampere Tst=ke*Ist; // in N-m disp...
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agahlandurmaq V;SG;3;PST agahlandurmaq V;PROG;PL;1;PRS agahlandurmaq V;PRF;PL;3;NEG;PST agahlandurmaq V;FRML;SG;2;PST agahlandurmaq V;PROG;SG;2;INFM;PST agahlandurmaq V;IPFV;PL;3;PRS agahlandurmaq V;IPFV;SG;3;PST agahlandurmaq V;INTEN;SG;3;PST agahlandurmaq V;IPFV;PL;2;PRS agahlandurmaq V;INTEN;SG;3;PRS agahlandurmaq V...
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function [x,y]=polar_to_cart(r,theta) theta=theta/180*%pi x=r*cos(theta) y=r*sin(theta) endfunction Vl=400 [Ir,Ic]=polar_to_cart(20,-30) Iab=complex(Ir,Ic) omega=exp(%i*120/180*%pi) Ibc=Iab/omega Ica=Iab*omega IAa=Iab-Ica Pab=Vl*norm(Iab)*cos(30/180*%pi) Ptotal=3*Pab Zp=Vl/Iab Rp=real...
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T = 0.25; y12 = 2 * sin(2 * T); y22 = 3 * cos(5 * T); k12 = 2 * cos(2 * T); k22 = 2 * cos(5*T);
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// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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clc; cp_CO=29.27;//kJ/kmol K cp_H=28.89;//kJ/kmol K cp_CH4=35.80;//kJ/kmol K cp_CO2=37.22;//kJ/kmol K cp_N=29.14;//kJ/kmol K niCO=0.29; niH=0.12; niCH4=0.03; niCO2=0.04; niN=0.52; cp_=cp_CO*niCO+cp_H*niH+cp_CH4*niCH4+cp_CO2*niCO2+cp_N*niN; R_=8.3145; cv_=cp_-R_; m_CO=28; m_H=2; m_CH4=16; m_CO2=...
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clc clear //Input data wf=1.9//Workfunction of the material in eV w=3000//Wavelength of the light in Angstrom units v=(3*10^8)//Velocity of light in m/s c=(1.6*10^-19)//Charge of the electron in coloumbs h=6.626*10^-34//Plancks constant in Js //Calculations V=(1/c)*(((h*v)/(w*10^-10))-(wf*c))//Stopping poten...
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clear// // //Variable Declaration w=60 //Continous Load in lb/ft L1=3 //Length in ft L2=9 //Length in ft //Calculations //After carrying out the variable computations we get A=([[1,1,0,0;(L1+L2),0,1,1;0.5*(L1+L2)**2,0,-(L1+L2),0;6**-1*(L1+L2)**3,0,-0.5*(L1+L2)**2,0]]) B=([w*L2;w*L2*0.5*L2;L2**3*10;L2**4*2...
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clear clc c = 0 function [tf, tf2]=haar(fx) n = size(fx, "*") if modulo(n, 2) == 1 then n = n - 1 //Ignore last element end tn = n / 2 tf = zeros(1, tn) tf2 = zeros(1, tn) i = 1 j = 1 while( i < n ) tf(j) = sqrt(2)*(fx(i) + fx(i + 1)) / 2 tf2(j) = ...
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// Scilab code Exa1.3.1 Momentum determination for a neutron using de-Broglie relation : Page 31 (2011) h = 6.626e-034; // Planck's constant, Js e = 1.602e-019; // Charge on an electron, C red_h = h/(2*%pi*e*1e+06); // Reduced Planck's constant, MeV lambda = 5.0e-015; // de_Broglie wavelength of neutron...
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errcatch(-1,"stop");mode(2);// Example 1.2, page no-8 r=1.25*10^-3 //m L=3 //m F=4900 //Newton e=2.05*10^11 //Pa s=F/(%pi*r^2*e) printf("strain = %.3f\nTherefore, extension = %.3f",s,s*3) exit();
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//Chapter 6, Problem 16 clc //transistor Y parameter yi=(16+%i*11.78)*10^-3 //in complex form yf_mag=45e-3 yf_ang=285 yr_mag=1.55e-3 yr_ang=258 yo=0.19+%i*5.97 //in complex form gi=16e-3 //input conductance in siemens go=0.19e-3 ...
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function[x]= mylu_sol(L,U,P,b) bb=P*b; y = lsolve(L,bb); x= uslove(U,y); endfunction
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a=imread('milkeway.jpg'); b=double(a); [m,n]=size(b); T=100; for i=1:m for j=1:n if (b(i,j)<T) c(i,j)=0; else c(i,j)=255; end end end imshow(c);
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clc v = 15000 // vertical magnification h = 100 // horizontal magnification l = 0.8 // sampling length in mm a1 = 160 // area above datum line in mm^2 a2 = 90 // area above datum line in mm^2 a3 = 180 // area above datum line in mm^2 a4 = 50 // area above datum line in mm^2 a5 = 95 // area below datum line in m...
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global A b U A = [ 2 -1 4 -7 0 3 -1 1 -1 2 0 -5 1 0 -5 2 ] b = [ 1 -2 0 4 ] U = [A, b] //augmented matrix function [] = row_multiply(row, k) global U U(row, :) = U(row, :) * k endfunction function [] = row_swap(row1, row2) gl...
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function ijacobi(A,b,xo,tol) M=[A b]; [m,n]=size(M); x(1)=0;i=1; g=1; //Inisialisasi Nilai Galat galat=%T; jum=0; while galat==%T for k=1:n-1 jum=0; for j=1:n-1 if k~=j then jum=jum+A(k,j)*xo(j); end...
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clc wi=1000 //Assigning values to parameters kva=50 e1=2200 ifl=kva*1000/e1 x=1 pf=0.8 wcf=(ifl/20)*(ifl/20)*500 n1=x*kva*pf*100/((x*kva*pf)+(wi*0.001)+(x*x*wcf*0.001)) x=sqrt(wi/wcf) n2=x*kva*pf*100/((x*kva*pf)+(2*wi*0.001)) disp(n1,"Efficiency at full node 0.8pf is") disp(n2,"Maximum Effice...
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clc //initialisation of variables HR=14087 //Btu HRC=3952 //Btu x1=0.9 x2=0.05 //Calculations HR1=x1*HR HR2=x2*HRC e=(HR2+HR1)/HR //Results printf ('Efficiency = %.3f',e)
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clc; clear; r=5*10^-2 //outer radius of copper sphere in m T1=10^3//temperature in K T2=300 //temperature in K c=4*10^3 //specific heat in J/kg rho=9*10^3 //density of copper in kg/m^3 sigma=5.67*10^-8 // Stefan-Boltzmann Constant in J/m^2sK^4 //calculation t=((rho*r*c)/(9*sigma))*((1/T2^3)-(1/T1^3)) mpri...
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//variable initialization l_dash=1 //length of the rod in frame s' (meter) Theta_dash_degree=45 //angle of the rod with x-axis in frame s' (...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monito...
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lambda=2; t=linspace(0,5,101); N0=60; plot2d(t,N0*exp(-lambda*t),2); lambda=5; plot2d(t,N0*exp(-lambda*t),5);
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//EX5_7 PG-5.13 clc Vbe=0.7;//base emitter voltage for silicon Vcc=12;//supply voltage R1=10e3; R2=2e3 Re=470; Rc=2e3 hFE_min=50; hFE_max=60; Vb=R2*Vcc/(R1+R2);//base voltage printf("\n Vb=%.0f V\n",Vb) Ve=Vb-Vbe;//emitter voltage printf("\n Ve=%.1f V \n",Ve) Ie=Ve/Re; printf("\n Ie=%.2f mA \n",Ie*1e3) ...
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clc clear //INPUT DATA //C2H2+3O2=2CO2+2H2O ;//Chemical equation t1=298;//initial temperature in K t2=800;//Final temperature in K R=0.287;//gas constant in kJ/kgK dhCO2=22815;//From tables enthalpy of CO2 kJ/kmol dhH2O=17991;//From tables enthalpy of H2O kJ/kmol hfCO2=-393520;//From tables enthalpy of CO2 kJ/...
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART II : TRANSMISSION AND DISTRIBUTION // CHAPTER 7: UNDERGROUND CABLES // EXAMPLE : 7.7 : // Page number 214 clear ; clc ; close ; // Clear the work space and console ...
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clc clear //Page number 485 //Input data t=-1;//The pressure required to lower the melting point of ice in K l=79.6;//The latent heat of ice in cal/g V1=1;//The specific volumes of water at 0 degree centigrade in cm^2 V2=1.091;//The specific volumes of ice at 0 degree centigrade in cm^2 p=1.013*10^6;//One a...
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E=118.5*10^3*4.2*10^7;//energy of ions in ergs// C=3*10^10;//velocity of light in cm/sec// L=6.023*10^23;//Avagadro number// h=6.625*10^-27;//plank's constant// l=(L*h*C*10^8)/E; printf('wavelength required to cause ionization=l=%fAngstrums',l);
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function [co,u,g,itv,dtv]=icse(u,simu,nap,imp) //Calcul du controle optimal sans mise a l'echelle du //controle et ponderation egale des observations //variables d'entree : //u(nu) : parametres initiaux //simu : chaine de caracteres donnant le nom du sous programme // decrivant le probleme //nap ...
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//example 4.8 //page 174 clc; funcprot(0); //initialisation of variable d1=2/100; d2=6/100; pi=3.14; g=9.81; V2=40; effi=0.8; V1=V2*d1^2/d2^2; A1=pi*d1^2/4;//area A2=pi*d2^2/4;//area Gamma=9810; P1=-50; z2=100; hs=V2^2/2/g-V1^2/2/g-P1/Gamma+z2+30; Q=A1*V1; P=Gamma*Q*hs; Pi=P/effi; disp(Pi/100,"Pow...
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clc //initialisation of variables a=60//cu ft per min p=14.0//psia t1=75//F t2=275//F m=6//in h=144//ft w=53.35//cu ft t3=535//F h1=0.24//ft k=33000//ft t4=778//R //CALCULATIONS W=(h*p*a)/(w*t3)//lb per min H=W*h1*(t1-t2)//Btu per min J=m*(k/t4)//Btu per min Q=H+J//Btu per min //RESULTS printf('The r...
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// Dado que tenemos que tanto e^x - 1 y x tienden a cero cuando x tiende a cero podemos aplicar L'Hopital con lo que obtenemos lim x->0 e^x / 1 = lim x->0 e^x asi obtenemos que el limite de la expresion original es igual a 1. // Los resultados concuerdan con la teoria tanto Funcion como FuncionR se ve que los valores ...
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བཤུད། བཤུད། V;PRS བཤུད། བཤུད། V;FUT བཤུད། བཤུད། V;PST རྙིད། རྙིད། V;FUT རྙིད། རྙིད། V;PST རྙིད། རྙིད། V;PRS ཟེར། ཟེར། V;FUT ཟེར། ཟེར། V;PRS ཟེར། ཟེར། V;PST སྙམ། སྙམས། V;PRS སྙམ། སྙམ། V;FUT སྙམ། སྙམ། V;PST འབག། འབག། V;PST འབག། འབག། V;FUT འབག། འབགས། V;PRS ཚོམ། ཚོམ། V;PRS ཚོམ། ཚོམ། V;FUT ཚོམ། ཚོམ། V;PST འཚོག། འཚོག། V;FUT ...
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a a l l i b o n e 阿 利 本 a b b i e 阿 比 a b b o t t 阿 伯 特 a b b u h l 阿 布 尔 a b e g g l e n 阿 贝 格 伦 a b e l e 阿 伯 利 a b e r c o n w a y 阿 伯 康 韦 a b l e r 阿 布 勒 a b l i n 阿 布 林 a b o r n 阿 伯 恩 a b o y n e 阿 伯 因 a b r a m s 艾 布 拉 姆 斯 a b t h o r p e 阿 布 索 普 a c a d o r y 阿 卡 多 里 a c h t e r 阿 赫 特 a c t o n 阿 克 顿 a c w o r ...
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//////////////////////////////////////////////// ///Variáveis de entrada: /// f = função a ser aproximada /// e = limite inferior do intervalo /// d = limite superior do intervalo /// m = grau do polinômio da aproximação //////////////////////////////////////////////// ///Variáveis de saída: /// v = vetor de ...
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// Exa 4.19 clc; clear; close; format('v',6) // Given data h_ie = 2;// in k ohm h_ie = h_ie * 10^3;// in ohm h_re = 2*10^-4;// unit less h_fe = 50;// unit less h_oe = 20*10^-6;// in A/V R_L = 4;// in k ohm R_L = R_L * 10^3;// in ohm Rs = 200;// in ohm Ai = -h_fe/( 1+(h_oe*R_L) );// unit less disp(Ai,"The...
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//Example 1.25 X and Y are seated at random at a round table clear; clc; N=(12*11); disp(N,"total no. of ways in X and Y can occupy seats="); M= (12*2); disp(M,"No. of favourable cases such that there are 3 people between X and Y at a round table = "); // M= (1,5),(2,6),(3,7),(4,8),(5.9),(6,10),(7,11),(8,12),(9,...
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//EXAMPLE 2-24 PG NO 71 //integration of is=1008sinQ^2=0.5 I=150 //CURRENT disp('i) CURRENT (I^2) is = '+string (I) +' A '); disp('ii) CURRENT (I) is = '+string (sqrt(I)) +' A ');
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l1=8; l2=4; v=120; f=60; x_l1=2*%pi*f*l1; x_l2=2*%pi*f*l2; x_l=1/(1/x_l1+1/x_l2); i=v/x_l; disp("the total current (in mA) drawn from the supply is"); disp(i*10^3);
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//**Données du moteur**// //Plage de fonctionnement (tr/min): miniR = 800; maxiR = 2500; //Couple fourni (Nm): miniCouple = 0; maxiCouple = 1800; //Puissance fourni (W): miniP = 0; maxiP = 266000; //Consommation (g/kWh): miniConso = 180; maxiConso = 210; n = 10; //intervalle dans lequel l'échantillonnage a été réal...
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//clear// //Caption:Signal-to-Quantization Noise Ratio of PCM //Example5.3:Signal-to-Quantization noise ratio //Channel Bandwidth B clear; clc; n = input('Enter no. of bits used to encode:') W = input('Enter the message signal banwidth in Hz:') B = n*W; disp(B,'Channel width in Hz:') SNRo = 6*n - 7.2; disp(S...
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//check o/p when only one i/p arg is passed to the function k = [0.3090 0.9800 0.0031 0.0082 -0.0082]; r0 = 0.1; a = rc2ac(k); disp(a); //output // !--error 10000 //Not enough input argument, define zero lag autocorrelation, R0. //at line 29 of function rc2ac called by : //a = rc2ac(k);
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ModuleName="plot_both_se_files"; Version="0.01"; DateModified="01-Jul-2015"; DateOfCreation="01-Jul-2015"; Author="Rob Eccleston"; Description="Function to plot both parts from SE development spectrometer."; mprintf("Loading " + ModuleName + " V" + Version + ", Last Modified: " + DateModified + "\n"); funct...
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function[R] = cholesky(A) n = size(A) for k=1:n A(k,k)=sqrt(A(k,k)) A(k+1:n,k)=A(k+1:n,k)/A(k,k) for j = k+1 :n A(j:n,j)=A(j:n,j)-A(j,k)*A(j:n,k) end end for i=1 : n for j=1 : n if i<j then R(i,j)=0 end ...
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function initialized_mdaqBlock = mdaqBlock() initialized_mdaqBlock = struct('name',['new_block'],'desc',['Set new_block parameters'] ,'param_name', ['param1'; 'param2'], 'param_size', [1;1], 'param_def_val', list([0;0]), 'in', [1], 'out', [1], 'use_sim_script', %T); endfunction
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//The ac Motor Control// //Example 15.2// Imr=50;//motor field rating in amp// Icr=1.5*Imr;//converter rated current in amp// printf('value of converter rated current=Icr=%famp',Icr); Vdc=100;//converter dc rating in volts// Vac=Vdc/1.35;//converter ac rating voltage required// printf('\nvalue of converter rated...
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clc // Fundamental of Electric Circuit // Charles K. Alexander and Matthew N.O Sadiku // Mc Graw Hill of New York // 5th Edition // Part 1 : DC Circuits // Chapter 2: Basic Laws // Example 2 - 11 clear; clc; close; // // Given data G12 = 12.00; G8 = 8.00; G5 = 5.00; G6 = 6.00; ...
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//Exa 9.8 clc; clear; close; //given data : HT=50;//in meter HR=5;//in meter d=4.12*(sqrt(HT)+sqrt(HR));//in Km disp(d,"Range of LOS system in Km : ");
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//Testing for logical errors (no exception handling required) a=[rand(1,2), -rand(1,2), 1+2*%i] ; disp(a); disp(db2mag(a)); //Output // 0.5664249 0.4826472 - 0.3321719 - 0.5935095 1. + 2.i // // // column 1 to 4 // // 1.0673854 1.0571396 0.9624793 0.9339519 // // column 5...
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//Example 10.3 //Page 488 disp('Assuming the access link is 90% utilized on average.') disp('The queuing theory is provided in Chapter 12. It involves determining the probability that the DSI access queue contains enough cells to represent 10msec of transmission time') tm=[(53*8)/(192*8000)] disp('Therefore...
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// Copyright (C) 2018 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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//Problem 13.06: For the circuit shown in Figure 13.16, find, using the superposition theorem, (a) the current flowing in and the pd across the 18 ohm resistor, (b) the current in the 8 V battery and (c) the current in the 3 V battery. //initializing the variables: E1 = 8; // in volts E2 = 3; // in volts R1 = 3; ...
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function mindemo() g_bb = uint8([6,17,8;12,10,11]); min_g_bb = min(g_bb,'c'); disp(min_g_bb); /////////////////////////// d2==>d0 ///////////////////////////////////// // aaa = ([1,2,3;10,11,90]); // d2->d0 // //////////////////////////////////////////...
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//Exa3.19 clc; clear; close; // given data Resistivity=9.23*10^-3;// in ohm-m R_H=3.84*10^-4;//in m^3/C (Hall Coefficient) sigma=1/Resistivity; rho=1/R_H; e=1.6*10^-19;// in C (electron charge) n=rho/e; disp("Density of charge carriers is : "+string(n)+" /m^2"); miu=sigma*R_H; disp("Mobility is : "+strin...
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// Chapter 2_Introduction to the quantum theory of solids //Caption_The Distribution function and the Fermi Energy //Ex_6//page 71 T=300 // Temperature in kelvin x=3 //x= (E-Ef)/kT fE=100/(1+%e^x); printf('Probability that an energy level 3kT above the Fermi energy is occupied by an electron is %1.2fd%%\...
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//Example 5.3: Implementation of Boolean logic using Decoders clc // Clears the console disp("f(a,b,c) = Summation(0,2,3,7)") disp("g(a,b,c) = Summation(1,4,6,7)") disp("Truth Table") disp("a b c | f g") disp("0 0 0 | 1 0") disp("0 0 1 | 0 1") disp("0 1 0 | 1 0") ...
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// Example A-8-13 // Design of system with two degrees of freedom clear; clc; xdel(winsid()); //close all windows mode(0); // please edit the path // cd "<path to dependencies"; // exec("plotresp.sci"); s = %s; Gp = 100 /(s*(s + 1)) dp = -5 + %i*5; // Step 1: Design of Gc1 using root locus approach angdef = 180 - p...
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clc clear disp('example13_5') vb=33 pb=20;zb=vb^2/pb //base voltage and base power pa1=10;pa2=10;xa1=0.08;xa2=0.08; //given power and reactance for different branches pbb=20;xb=0.06;pc=15;xc=0.12;pd=20;xd=0.08; xab=2.17;xbc=3.26;xcd=1.63;xda=4.35; xap1=xa1*pb/pa1; xap2=xa2*pb/pa2;xap=xap1*xap2/(xap1+xap2) ...
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clc; clear all; disp("heat transfer rate") d=300/1000;//m diameter L=3.5;//m delT=40;//degree C =ts-ti f=0.022;// friction factor St=f/2; disp("The energy balance yields Q=h*A*(ts-ta)=m*cp*(to-ti)") disp("h*(%pi*D*L)*(ts-(to+ti)/2)=rho*(%pi*D^2*U/4)*cp(to-ti)") disp("(h/(rho*U*cp))*L*(ts-to+ts-ti)/2=D/4*(to-t...