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//We build a function ex17c with 3 input parameters X,Y,f and //1 output parameter Z: Z=ex17c(X,Y,f). //The third input parameter of ex17c (f) is a function. //This function, which is passed to ex17c as an argument, //is called a "argument function". //This function can be a Scilab function or a C function. //In both ...
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//Example 12.3.b // motor generator in each phase clc; clear; close; Vl=1100;//line voltage in volts n=99;//motor efficiency in percentage Mo=n*735.5;//output of the motor Mi=(Mo*100)/75;// INPUT OF THE MOTOR IN WATTS pf= 0.8;//power factor Il=(Mi)/(sqrt(3)*Vl*pf);//line current in amperes Ip=Il/(sqrt(3));//phase curr...
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* #------------ defsym cmd r #------------ * defsym arch S/370 script $(testpath)/cmd-rv-2K.subtst * defsym arch S/390 script $(testpath)/cmd-rv-4K-32.subtst * defsym arch z/Arch script $(testpath)/cmd-rv-4K-64.subtst * #------------ defsym cmd v #------------ * defsym arch S/370 script $(testpath)/cmd-rv-2K.subtst * d...
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//DFS of sampled periodic signals xn=[0 ones(2:16) 0 -ones(18:32)]; XDFS=0.032*dft(xn,-1); for i=1:length(XDFS) if (abs(XDFS(i))<0.000001) then XDFS(i)=0; end end disp(XDFS,'The DFS of x[n] is');
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clc // from figure 4.4 v = 100 // cutting speed in m/min D = 50 // mm l1 = 76 // mm f = 7.5 // feed in mm/rev. // Case 1 , time to turn 38 mm diameter by 76 mm length of cut N1 = (1000*v)/(%pi*D)// r.p.m tm1 = l1*10/(f*N1) // min. // Case 2 , time to turn 25 mm by 38 mm length N2 = (1000*v)/(%pi*38) // r.p.m ...
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clear// //Variables r1e = 8.0 //a.c. load resistance (in ohm) RC = 220.0 //Collector resistance (in ohm) RE = 47.0 //Emitter resistance (in ohm) R1 = 4.7 * 10**3 //Resistance (in ohm) R2 = 470.0 //Resistance ...
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//Initialisation of variables clc C=20/(9*10^11)//converting cms to farads F=154-100//fall in potential R=F/60//rate of fall in potential I=C*R//ionization current printf('ionization current is %e amp \n',I)//correction applied
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errcatch(-1,"stop");mode(2);// Exa 5.9.2 ; ; // Given data alpha = 0.9; I_E = 1;// mA I_C = alpha * I_E;// in mA I_B = I_E - I_C;// in mA disp(I_B,"The value of base current in mA is"); exit();
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clc //initialisation of variables f=5//cm d=10//cm r=150//liters p=4//in A2=7.84*10^-3//m^2 //CALCULATIONS A=((%pi)*(f*10^-2)^2)/p//m^2 V1=(r*10^-3)*(1/60)/A//m/s V2=(A*V1)/A2//m/s //RESULTS printf('The velocity of the fluid in both pipes=% f m/s',V2)
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.data 12 ok: .c "ok\n" #if __WORDSIZE == 32 # define w7f 0x7fffffff # define w80 0x80000000 # define w81 0x80000001 # define wff 0xffffffff # define LEXTII2(N, R0, R1) # define LEXTIC2(N, R0) #else # define w7f 0x7fffffffffffffff # define w80 0x8000000000000000 # define w81 0x8000000000000001 # define...
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example11_5.sce
s=2*10^(-2); a=s^2; phi=5.2*10^(-4); b=phi/a; h=800;...........//from the B-H curve l=4*6*10^(-2); n=600; i=h*l/n; disp("the current required (in A) is"); disp(i);
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clc; //page 17 //ex-1.11 P=5; //In mW N=100*10^-6; //in mW S2N=P/N; disp(S2N,'(a) Absolute signal to noise ratio :'); S2NdB=10*log10(S2N); disp('dB',S2NdB,'(b) dB signal to noise ratio is:') PdBm=10*log10(P/1); disp('dBm',PdBm,'(c) Signal Power is'); NdBm=10*log10(N/1); disp('dBm',NdBm,'Noise p...
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clc //initialisation of variables a=0.139//m/sec^2 h=12.5//m/sec t=120//m/sec //CALCULATIONS V=h+a*t//m/sec //RESULTS printf('The acceleration level trackage it was travelling at speed=% f m/sec',V)
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//Policy for Inventory Control function bestpolicy(p, q) C = 0.0//Cost S = 115//Stock I = 1//Day UD = 0//Units Due DD = 0//Due Date for I = 1:180//Loop for 6 months or 180 days if DD == I then//Is today due date? S = S + q//Add q to stock UD = 0//units due = 0 end dem = int(abs(g...
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clc //initialisation of variables n=1500//rpm d1=180//mm d2=540//mm d3=160//mm d4=400//mm //CALCULATIONS M=(d1/d2)*(d3/d4)//mm N=n*M//rpm //RESULTS printf('the total speed ratio=% f rpm',N)
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:@computed_region_cbhk_fwbd,:@computed_region_nnqa_25f4,fall,geolocation,id,mass,name,nametype,recclass,reclat,reclong,year ,,Fell,"{'type': 'Point', 'coordinates': [6.08333, 50.775]}",1,21.0,Aachen,Valid,L5,50.775,6.08333,1880-01-01T00:00:00.000 ,,Fell,"{'type': 'Point', 'coordinates': [10.23333, 56.18333]}",2,720.0,A...
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clc //initialisation of variables mr= 2.01474 //amu mH= 0.00237 //amu mD= 1.00814 //amu //CALCULATIONS mn= mr+mH-mD //RESULTS printf ('mass of neutron = %.5f amu',mn)
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example812.sce
//Example 8.12 //For the given x[n] determine X[k] using FFT algorithm clc; x=[0,1,2,3,4,5,6,7]; X=fft(x,-1); disp(X,'X[k]=');
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//Exa 4.2 clc; clear; close; //Given data Omega_P1=10^4;//in Radian/sec Omega_P2=2*10^4;//in Radian/sec Omega_Z1=10^5;//in Radian/sec omegaH=1/sqrt(1/Omega_P1^2+1/Omega_P2^2-2/Omega_Z1^2);//in radian/sec disp(round(omegaH),"Approximate value of lower 3dB Frequency in radian/sec : ");
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//Eliminação Gaussiana: //Implementação destinada à resolução de um sistema linear Ax=b. //Entrada: A (matriz mxn), b (vetor mx1) clear //limpa a memoria do scilab clc //limpa a tela do console //A = [1 0 -1; 0 3 7; 5 -2 1]; //linhas espaçadas por ponto e vírgula //A = [0 0 -2; 2 4 -10; 2 5 1]; //A = [0 3 1; 2 -2 1; ...
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// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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clc // Given that m = 1 // Mass flow rate in kg/s r = 2 // Prssure ratio of blower t1 = 70 // Inlet temperature in degree centigrade p1 = 1 // Inlet pressure in bar R = 0.29 // Gas constant in kJ/kgK x = 0.7 // Reduction in pressure ratio and intake volume gama = 1.4 printf("\n Example 19.15\n") T1 = t1+273...
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clc //initialization of variabes clear cA=10 //cm^2 wA=5 //cm^2 P=1 //tonne E=2*10^6 //kg/cm^2 P=P*1000 //kg // calculations U_up=P^2*200/(2*E*cA)*1/sqrt(3)*(2+4+6+8+10+12) U_do=P^2*200/(2*E*cA)*1/sqrt(3)*(1+3+5+7+9+11+13/2) U_web=P^2*200/(2*E*wA)*1/sqrt(3)*(2*13) U=U_up+U_do+U_web delta=U*2/(P) // result...
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//water and its treatment// //example 2.18.32// clc Purity_Lime=.97 Purity_soda=.91 W1=24;//amount of Mg2+ in ppm// W2=20;//amount of Ca2+ in ppm// W3=30;//amount of CO2 in ppm// W4=150;//amount of HCO3- in ppm// W5=40;//amount of K+ in ppm// M1=100/24;//multiplication factor of Mg2+// M2=100/40;//multip...
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clear; clc; V=700; E2=V; N_s=1500; N=1200; s=(N_s-N)/N_s; V1=415; a_T=s*E2/V1; printf("voltage ratio of the transformer=%.4f",a_T);
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//Example No. 4_13 //Pg No. 78 disp('Theoritical Problem') disp('For Details go to page no. 78')
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//Example 2_2_u2 clc(); clear; //To corresponding mean free path and compare with experimental value row=6.87*10^7 m=9.11*10^-31 n=5.86*10^28 e=1.6*10^-19 t=(row*m)/(n*e^2) //units in s printf("The mean free path is t=") disp(t) printf("sec") kb=1.381*10^-23 T=300 m=9.11*10^-31 v=(sqrt(3*kb*T))/s...
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M1=35.6 //g/mol M2=18 //g/mol x=0.2 mdot=1000 //kg/h T1=25 //C T2=100 //C T3=40 //C
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//Example 8.1: Motor speed clc; clear; close; v=230;//in volts rm=0.3;//in ohms Ia=[5;10;15;20;25;30;35;40];//in amperes T=[20;50;100;155;215;290;360;430];// for i=1:8 eb(i)= v-(Ia(i))*rm;// N(i)=(9.55*eb(i)*Ia(i))/(T(i));// disp("speed in rpm is for current "+string(Ia(i))+" amperes "+string(round(N(i)))...
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9 Что делает оператор «%» Возвращает процент от суммы 0 Возвращает остаток от деления 1 Возвращает тригонометрическую функцию 0 Ничего из выше перечисленного 0 Что сделает программа выполнив следующий код: Console.WriteLine(«Hello, World!»); Напишет на новой строчке Hello, World! 1 Напишет Hello, World! ...
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#estinet scenario file $node_(1) set 362.000000 199.000000 0 0.0 0.0 0.0 $node_(2) set 235.000000 195.000000 0 0.0 0.0 0.0 $node_(3) set 541.000000 98.000000 0 0.0 0.0 0.0 $node_(4) set 558.000000 230.000000 0 0.0 0.0 0.0 $node_(5) set 541.000000 284.000000 0 0.0 0.0 0.0 $node_(6) set 503.000000 319.000000 0 0.0 0.0 0....
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Wnls = [] for i=1:10 data = read(get_absolute_file_path("FindOmegaNls.sce") + "..\Data\log" + string(-i * 10) + ".txt", -1, 2); angle = data(:, 1)*%pi/180; time = data(:, 2); aim = [time, angle]'; deff('e=curve(k, z)', 'e=z(2)-k(1)*(z(1) - k(2) * (1-exp(-z(1)/k(2))))'); att=[-15;0.06]; ...
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/////////////////////////////////////////////////////////////////////////////// //// Неделя 1.1 //// Случайные величины и методы их описания. /////////////////////////////////////////////////////////////////////////////// clear; deff('[numd] = roundd(num,n)','numd = round(num *10^n) / 10^n'); rand("seed",getdate("s")...
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clc; close(); clear(); //page no 277 //prob no. 8.3 W=5000; //Hz fs=1.25*2*W; tp=30*60; //seconds N=fs*tp; //samples mprintf('Total number of samples is %i ',N);
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//calculating regulation at full load at unity pf V=3300//line voltage Vph=V/sqrt(3) P=500D+3//output Ia=P/(sqrt(3)*V) Ra=.4//resistance per phase Xs=3.8//reactance per phase pf=1//power factor Ef=[(Vph*1+Ia*Ra)^2+(Vph*0+Ia*Xs)^2]^.5//open circuit voltage per phase VR=(Ef-Vph)/Vph*100 mprintf("Regulation at...
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i = imread('test1.jpg'); corners = detectHarrisFeatures(i); disp(corners);
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clc clear //Input data mol=4 //Molecular weight of gas in kg/mol k=1.3 //Adiabatic constant C1=150 //Gas Velocity at section-1 in m/s P1=100 //Pressure of duct at section-1 in kPa T1=15+273 //Temperature at section-1 in K T2=-10+273 //Temperature at section-2 in K Ri=8314 //Ideal gas constant in J/mol-K /...
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clc //initialization of variables D =2*10^-6 // cm^2/sec nu = 0.036 // cm^2/sec d1 = 1.59 // cm d2 = 1 // cm deltap = 1*10^-5 // g/cc ( change in density) p = 1 // g/cc Re = 11200 // Reynolds number g = 980 // cm/sec^2 dis = 5.37*10^-9 // g/cm^2-sec // Dissolution rate sol = 1.48*10^-3 // g/cc //Calcul...
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//A program to illustrate the use of Nested functions. function y=outer_fun(x) a=x+1; disp ("executing outer_fun"); function y=inner_fun1(x) z=x+2; whereami (); // a library function to return the current line of the program function y=inner_fun2(x), y=x^2, disp ("Executing in...
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clc //initialisation of variables Hv= 9720 //cal mole^-1 Hv1= 30900 //cal mole^-1 Tb= 373 //K Tb1= 1029 //K //CALCULATIONS Sv= Hv/Tb Sv1= Hv1/Tb1 //RESULTS printf (' Entropy= %.f cal mole deg^-1',Sv) printf (' \n Entropy = %.f cal mole deg^-1',Sv1)
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\begin{document} The second part of the semester project focuses on gaining experience with lex (flex) and yacc (bison), coupled with continued design (and redesign) skills for context free grammars (CFGs). The second part of the project is divided into two major tasks, and is worth a total of 50 points: \begin{enumer...
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//Chapter 2,Ex2.67,Pg2.84 clc; disp("Refer to the diagram shown in the question") A=[1 0;5 -10] B=[50;0] I=A\B printf("\n I1=%.0f A \n",I(1)) printf("\n I2=%.0f A \n",I(2)) Vth=3*I(2) printf("\n Vth=%.0f V \n",Vth) //Calculation of Rth Rth=(7*3/(7+3)) printf("\n Rth=%.1f \n",Rth) //For maximum power transf...
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//Number of Vacancies Computation at a Specified temperature clear; clc; printf("\tExample 4.1\n"); Na=6.023*10^23; //Avogadro No. den=8.4D+06; //Density of Copper A=63.5; //Atomic weight of Copper //No. of atomic site per cubic meter N=Na*den/A; //No. of vacancies at 1000 C...
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clc clear //Initalization of variables lhs=8.5 //moles of reactants rhs=6 //moles of CO2 n=3 //moles of H2O R=1545 //Universal gas constant R2=18.016 //molar mass of water J=778 //Work conversion constant T=537 //R T2=1050.4 //R T3=991.3 //R Qhp=1417041 //Btu/mol //calculations Qhpv=(lhs-rhs)*R*T/J Qhv=Q...
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clear; clc; //page no. 266 Tw = 32;// degreeF d1 = 3;// in v = 10;//fps delp = 2;//psi h1 = 30;// ft Tb = 68;//degreeF d2 = 1;//in h2 = 10;//ft V = v*(d1/12)*0.0000137/((d2/12)*0.88*0.0000375); del_p = delp/h2^2 *0.88*V^2; printf('V = %.2f fps\n del_p = %.2f psi',V,del_p);
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//Harmonic and Powerfactor with the Converter system// //Example 8.6// printf('For six pulse converter most effective harmonic is 6th and for worst case a=90 degree\n'); h=6; Wv=24.1;//voltage ripple in percentage// printf('voltage ripple=Wv=%fpercent',Wv); Edc=460;//dc voltage in volts// W=2*3.14*50; Ldc=6;//t...
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clc // Given that V = 0.12 // Volume of tank in m^3 p = 1 // Pressure in MPa T = 150 // Temperature in degree centigrade P = 0.1 // Power to peddle wheel in kW printf("\n Example 5.8") u0 = 0.718*273 // Internal energy at 0 degree Celsius // Function for internal energy of gas t=poly(0,"t") u = u0+(0.718*t) ...
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clear; clc; stacksize('max'); data = read_csv('../getdata/Data/master.csv'); //split headers and data headers = data(1,:); data = data(2:$,:); hg = round(strtod(data(:,5))); ag = round(strtod(data(:,6))); hgh = round(strtod(data(:,8))); agh = round(strtod(data(:,9))); tg = hg + ag; tgh = hgh + agh; //Fix some things...
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//Chapter3 //Example 3_3 //PAge 50 clear;clc; max_dem =100; p1=100; t1=2; p2=50; t2=6; no_operation =45; //Annual load factor e_per_day=(p1*t1)+(p2*t2); printf("Energy per day = %.2f MWh \n\n", e_per_day) operation_days=365-no_operation; e_per_year = e_per_day*operation_days; printf("energy per year = %.2f MWh\n\n...
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errcatch(-1,"stop");mode(2);//Example5.9 //to determine open loop gain ; ; beta = 0.0120 ; // Feedback transfer function Af = 80 ; //d loop gain A = (Af)/(1-beta*Af) ; disp('open loop gain is = '+string(A)+''); exit();
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clear // // //Initilization of Variables //Let X=(P*A**-1) //Average Stress at Failure Lamda_1=70 //Slenderness Ratio Lamda_2=170 //Slenderness Ratio X1=200 //N/mm**2 X2=69 //N/mm**2 //Rectangular section b=60 //mm //width t=20 //mm //Thickness L=1250 //mm //Length of strut FOS=4 //Factor of safety //Calculatio...
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PL/SQL Developer Test script 3.0 161 --select lower(name), body from xxdoo.xxdoo_db_scripts_t order by id /*declare l_result clob; cursor l_scripts_cur is select lower(name) name from xxdoo.xxdoo_db_scripts_t order by id; begin dbms_lob.createtemporary(l_result, true); -- for s in l_scripts_cur loop ...
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subplot(224); a = gca(); a.axes_bounds = bottom_axes_bounds; a.tight_limits="on"; a.axes_reverse = ['on', 'off', 'off']; a.grid=[-1, color("darkgrey")] a.tag = "sensor2Axes"; plot2d(0:timeBuffer2, zeros(1,timeBuffer2 + 1)-50, color("red")); a.title.text="Temperature variations of the sensor 2"; a.data_bounds = [0, minT...
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//Exa 1.4 clc; clear; close; //Given data : format('v',9); n=1.33;//refractive index //Formula : velocity_of_light_in_medium=velocity_of_light_in_free_space/Refractive_Index; c=3*10^8;//in m/s v=c/n;//in m/s disp(v,"velocity of light in medium in m/s : ");
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function []=mvcr(x,y,theta,phi) ///////////////%% BEGIN OF SCRIPT-FILE mvcr %%%%%%%%%%%%%%% // // CAR PACKING VIA FLATNESS AND FRENET FORMULAS // // explicit computation and visualisation of the motions. // // February 1993 // // ............................................................ // : pierre RO...
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Name=Stairmaster 2 PlayerCharacters=Tony Hawk BotCharacters=Nyjah Huston.bot IsChallenge=true Timelimit=120.0 PlayerProfile=Tony Hawk AddedBots=Nyjah Huston.bot PlayerMaxLives=0 BotMaxLives=0 PlayerTeam=1 BotTeams=2 MapName=rightstair.map MapScale=2.0 BlockProjectilePredictors=true BlockCheats=true InvinciblePlayer=fal...
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// Variable declaration alpha = 0.05 // level of significance semi = [] failures = [] // Calculation // null hypothesis: if p1=p2=p3=p4 , Alternative hypothesis if p1,p2,p3,p4 all are not equal chi_sq_thr = 7.815 // theoritical value of chi square at alpha = 0.05 with v =...
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clc // Given that n = 1 // no. of order lambda1 = 5.89e-7 // wavelength of light in first case in meter lambda2 = 5.896e-7 // wavelength of light in second case in meter // Sample Problem 38 on page no. 2.53 printf("\n # PROBLEM 38 # \n") N = lambda1 / (n * (lambda2 - lambda1)) // calculation for minimum no. of lines ...
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clc(); clear; // To calculate the flux density at centre and dipole moment r=6.1*10^-11; //radius of H atom in m new=8.8*10^15; //frequency in rev/sec e=1.6*10^-19; mew0=4*%pi*10^-7; i=e*new; B=(mew0*i)/(2*r); mew=i*%pi*(r^2); printf("current is %f amp",i); printf("magnetic induction is %f weber/m^2",...
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clc; e=1.6*10^-19; //charge on an electron in coulomb E=5*10^3; //electric field in V/m m=3.3*10^-26; //mass of neon ion in kg F=E*e; //calculating foece in Newton using F=Q*E a=F/m; //calculating accelaration in m/sec square using Newton's Law(F=m*a) disp(F,"Force on neon Ion in ...
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///Chapter No 7 Fluid Mechanics ////Example 7.14 Page No:126 ////Find Total energy per unit weight //Input data clc; clear; V=13; //Velocity of water flowing throgh pipe in m/s P=200*10^3; //Pressure of water in Kpa Z=25; //Height above the datum in m g=9.81; rho=1000; ...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run2"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monito...
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// Y.V.C.Rao ,1997.Chemical Engineering Thermodynamics.Universities Press,Hyderabad,India. //Chapter-9,Example 12,Page 335 //Title: Molar volume of mixture using van der Waals equation of state //================================================================================================================ clear...
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.378518D+00 ...
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clear; clc; printf("\nEx2.34\n"); //page no.-73 //given h=6.63*10^-34;............//planck's constant in J-sec t=2.5*10^-14;.............//time required in sec //By Heisenberg's uncertainty principle, E*t=h del_E=h/(2*%pi*t).............//error in energy in joule printf("\nminimum error in energy is 4.22...
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//chapter 17 //example 17.5 //page 7 printf("\n") printf("given") f=12*10^3;C1=1000*10^-12; disp("butterworth second order filter") C2=C1; R2=(sqrt(2))/(2*3.14*f*C1) R1=.5*R2 R3=R2; fc=1/(2*3.14*(sqrt(R1*R2*C1*C2))); printf("actual cutoff frequency is %dHz\n",fc)
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clear; printf('\n'); printf('************** mt_1.sci Start! ****************'); printf('\n'); printf('Enter a File Name of UNIT SPACE Material'); UnitSpaceFile = input('File Name(.xls)?: ',"string"); printf('./' +UnitSpaceFile+'.xls\n'); MT_Mat_Sheets = readxls('./' + UnitSpaceFile + '.xls'); // EXELファイルの読み出し S...
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clc;funcprot(0);//Example 1.4 //Initilisation of Variables T1=500;.........//tempatarure of plate 1 in K T2=350;.........//tempatarure of plate 2 in K d=0.15;.........//diameter of the rod in m L=1.5;.........//Length of the rod in m K=0.4;.........//thermal conductivity in W/(m*K) //Calculations A=(%pi/4)*d^2;...
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//Ex6_5 // For class-AB BJT amplifier clc VCC=(10) disp("VCC= "+string(VCC)+" volts") // Collector voltage supply VEE=VCC disp("VEE=VCC= "+string(VEE)+" volts") // Emitter supply voltage ICQ_0=10*10^(-3) disp("ICQ_0 = "+string(ICQ_0)+" ampere") // Zero signal collector current RL=5 disp("RL= "+string(RL)+ ...
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clear ; clc; // Example 21.6 printf('Example 21.6\n\n'); //page no. 632 // Solution printf('\n As we know that enthalpy(H) is state variable , therefore change in enthalpy(del_H) depends only on initial and final state , independent of the path taken for process.\n Hence, change in enthalpy for both paths A-B-D and A-...
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clc; //Example 12.5 //Page No 514 //solution Ei=5; Er=3; disp("Substituting into equation 12-33 yield"); r=Er/Ei; disp(r,"r = "); disp("Substituting into equation 12-37 yield"); swr=(Ei+Er)/(Ei-Er); disp(swr,"SWR = "); disp("Substituting into equation 12-45 yield"); r1=(swr-1)/(swr+1); disp(r1,"r = ");
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clc //initialization of new variables clear m=250 //tonne Weight b=64.4 //m wing span S=541 //m^2 Wing area c=8.4 //m Wing chord r=1.1 //kg/m^3 Air density u=600 //km/h air speed g=9.8 //m/s^2 Acceleration due to gravity //calculations u=u/3.6 Cl=m*g*1000/(0.5*r*u^2*S) AR=b^2/S Cla=2*%pi/(1...
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// Example 8.2 R=0.8; // Resistance L=1.6; // Inductor t1=L/R; // Time // Instantaneous current is ( it= Io*e(-t/2) ) Io=20/exp (0.5); // The current ( at t= -1 & i= 20A ) disp(' The value of current at t...
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clc; funcprot(0); //Example 14.5 //Initializing the variables D = 0.3; Q = 0.8; rho = 1.2; f = 0.008; L_entry = 10; L_exit = 30; Lt = 20*D;//Transition may be represented by a separation loss equivalent length of 20 × the approach duct diameter K_entry = 4; K_exit = 10 l = 0.4; // length of cross s...
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// Calculate the value of resistance after 15s clc; R0=29.44; Rs=100; t=15; tc=5.5; R_15=Rs+R0*[1-exp(-t/tc)]; disp(R_15,'value of resistance after 15s(ohm)')
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function y = f(x) y = 2* x(1)**4 + (x(1) + x(2) - 1)**2 endfunction function Optimo = minSol(a,b,e,m,f,x,d) dif = b - a while(dif >= e) h = dif/(m+1) u = [a:h:b] mini = a + h for i = a:h:m t_i = a + i *h if f(x + mini*d) > f(x + t_i* d) then ...
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clc clear //Input data n=30//Efficiency of the reactor in percent Ef=200//Energy released per fission in MeV E=200//Energy needed to the city in MW e=1.6*10^-19//Charge of electron in Coulumb A=6.023*10^23//Avagadros number a=235//U235 //Calculations E1=E*10^6//Energy required to the city in J/s E2=E1*24*...
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Vm=1; //Assuming Vm=1 function y=f(t),y=Vm*Vm*sin(t)*sin(t),endfunction //Defining Voltage Equation T=2*%pi; Res=sqrt(intg(0,%pi,f)/(T)); disp("Volts",Res,"Rms value of voltage");
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function sampletry() // unix('wish /home/codestation/sample_im.tcl'); //exec('/home/codestation/sc.sh'); TCL_EvalFile('/home/codestation/sample_im.tcl'); endfunction
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Vl = 380 Vf = Vl/sqrt(3) Zc1 = 36+%i*32.5 I = Vf/Zc1 S = 3*Vf*I' modS = polar(S) Fp = real(S)/modS Qc = imag(S) -real(S)/0.92*sqrt(1-0.92^2) S = S - Qc*%i I = (S/(3*Vf))' //W1 = Vf*I*expm((acosd(0.92) + 30)*%pi/180) W1 = (Vl*expm(30*%pi/180*%i))*I' W2 = (Vl*expm(-30*%pi/180*%i))*I' Zcap = - abs(Vf)^2/(2*%pi*60*Qc/...
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clc //Intitalisation of variables clear v= 240 //ml p= 1.25 //atm p1= 0.75 //atm n= 2 //CALCULATIONS v1= v*p/p1 dv= v1-v V= n*v1 //RESULTS printf ('Increase in volume = %.f ml',dv) printf ('\n Final volume = %.f ml',V)
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//Variable declaration: T1 = 400.0 //Temperature of fluid entering the shell ( F) T2 = 250.0 //Temperature of fluid leaving the shell ( F) t1 = 100.0 //Temperature of fluid entering the tube ( F) t2 = 175.0 //Temperature of fluid leavin...
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//chapter 5 example 1// clc clear //band gap energy=Eg,voltage applied=V,total effeciency of an injection laser=nT// Eg=1.43;//in ev// V=2.5;//in volts// nT=0.18; ne=((nT*Eg)/V)*100; printf("\n external power efficiency=%f percent\n",ne)
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//Example 6.3 //Least Square Method //Page no. 217 clc;close;clear; x=[1,2,3,4,5,6,7,8]; y=[3,3,4,5,5,6,6,7];n=1; printf('\t 2\t\t 2\n n\tx\tx\ty\txy\ty\n--------------------------------------------\n') x1=0;x2=0;x3=0;x4=0;x5=0;x6=0; for i=1:8 printf(' %i\t%i\t%i\t%i\t%i\t%i\n',n,x(i),x(i)^2,y(i),x(i)*y(...
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errcatch(-1,"stop");mode(2);//Caption:Find the armature voltage drop //Exa:2.44 ; ; V=440;//in volts N_1=1000;//in rpm N_2=1050;//in rpm r=N_1/N_2; V_drop=2*(V-V*r) disp(V_drop,'Armature voltage drop (in volts)=') exit();
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//Chapter-8, Example 8.6, Page 346 //============================================================================= clc clear //INPUT DATA L=0.3;//Height of the duct in m W=0.6;//Width of the duct in m Ts=15;//Surface temperature in degree C Ta=25;//Temeprature of air in degree C //CALCULATIONS Tb=(Ts+Ta)/...
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// Caption: Finding peak mmf and flux clear; close; clc; function [F_peak]=mmf(k,N,p,I) F_peak=(4*k*N*I)/(%pi*p); endfunction f=mmf(.9,46,2,1500);//peaf fundamental mmf B_peak=(4*%pi*10^-7*f)/(7.5*10^-2);//peak flux density phy=2*B_peak*4*0.5;//flux per pole E_rms=sqrt(2)*%pi*60*.833*24*2.64;//rms vol...
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function [yout,last] = pid_calculate(pid_cfg, pre, cur, trg)//,u_last) _dt = pid_cfg(1); _max = pid_cfg(2); _min = pid_cfg(3); _Kp = pid_cfg(4); _Ki = pid_cfg(5); _Kd = pid_cfg(6); _pre_error = pre(1,:); _integral = pre(2,:); size(_integral) input_size = size(trg); nums ...
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//Chapter 6:Induction Motor Drives //Example 2 clc; //Variable Initialization //Ratings of the Delta connected Induction motor f=50 //frequency in HZ Vl=2200 //line voltage in V P=8 //number of poles N=735 //rated speed in rpm //Parameters referred to the stator Xr_=0.55 //...
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clc G=16 H=7 c=30 Ta=0.65*G*H*(tand(45-c/2))^2 A=Ta*3*3/4 B1=Ta*3-54.61 C=Ta*4*4/4 B2=Ta*4-97.08 s=2 As=A*s Bs=(B1+B2)*s Cs=C*s printf( 'The strut loads at level A = %f kN\n',As) printf( ' The strut loads at level B = %f kN\n',Bs) printf( ' The strut loads at level C = %f kN',Cs)
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// To determine the current in the 2 ohm resistor using superposition theorem clc; clear; // Voltage Sources V1=5; V2=10; // Since both Voltage sources are connected in parallel and are unequal R1=%inf; // As seen by 5V Source R2=%inf; // As seen by 10V Source I1=V1/R1; // Current Drawn from 5V supply ...
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function dX = Montante(MAT) //Inicializar el pivote en 1 dPivAnt = 1 //Recorrido por renglones for i = 1: size(MAT, 1) //Recorrido por columnas for k = 1: size(MAT, 1) if i <> k //Recorrido por columnas (Las qu...
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//Eg-4.11 //pg-163 clear clc // Secant Method clear ; close ; clc ; deff('[z]=f(x)','z=1.55*x^(-0.5)-7.2*x+8.1*x^2-4*x^3-1.3'); iter=1; eps=10^(-10); x1=0.5; x2=1; imax=20; Abserr=100; while Abserr>eps&iter<imax //printf('iteration number %i\n',iter); xnew1=x2-feval(x2,f)*(x2-x1)/(fev...
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//EX6_4 PG-6.34 clc Vbb=20; Ct=0.1e-6;//capacitance Rt=10e3;//resistance Vv=1.5;//valley potential Vd=0.7;//cut in voltage of diode n=0.6;//stand off ratio Vp=n*Vbb+Vd; disp("We know that Vp=Vbb(1-exp(-T/(Rt*Ct)))") x=(Vp-Vv)/Vbb;//x=(1-exp(-T/(Rt*Ct)) y=1-x;//y=exp(-T/(Rt*Ct) z=Rt*Ct; T=-log(y)*z;//time...
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clc // given that E=110*10^3 //Young's modulus of Copper in MPa sigma=276 //Applied stress in MPa l_o=305 //Original length in mm printf("Example 9.1\n") del_l=sigma*l_o/E //Deformation printf("\n Elongation obtained is %.2f mm \n",del_l)
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// ==================================================================== // Copyright DIGITEO 2010 // Allan CORNET // ==================================================================== demopath = get_absolute_file_path("xls_link.dem.gateway.sce"); subdemolist = ["demo xls_link set/get datas" ,"xls_link_setget_d...
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//Width of gate(in m): w=5; //Depth of water(in m): D=4; //Density of water(in kg/m^3); d=999; //Accelration deto gravity(in m/sec^2): g=9.81; //Value of a (in m): a=4; //Point where force acts(in m): l=5;
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@relation unknow @attribute left-weight real[1.0,5.0] @attribute left-distance real[1.0,5.0] @attribute right-weight real[1.0,5.0] @attribute right-distance real[1.0,5.0] @attribute class{L,B,R} @inputs left-weight,left-distance,right-weight,right-distance @outputs class @data R R R R R R R R R R R R R R L L B L R R R...
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# header scenario = "spatial attention block"; write_codes = true; # send codes to output port active_buttons = 2; button_codes = 4, 8; default_font_size = 30; default_text_color = 255,255,255; # white default_background_color = 0,0,0; # black $set_comb = 4; $eye_cond ...
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//example 4.64 //calculate flood magnitude with return period of 500 years clc;funcprot(0); //given T1=50;T2=100; //Return period F1=20600;F2=22150; //Peak flood y100=-(2.303*log10(2.303*log10(T2/(T2-1)))); y50=-(2.303*log10(2.303*log10(T1/(T1-1)))); y=(F2-F1)/(y100-y50); T=500; y500=-(2.3...