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//Example No. 15.8.2 clc; clear; close; format('v',6); Nm_D=400;//electron/cm^3(Maximum electron density) Nm_E=5*10^5;//electron/cm^3(Maximum electron density) Nm_F=2*10^6;//electron/cm^3(Maximum electron density) fc_D=9*sqrt(Nm_D);//kHz(critical frequency of D-layer) disp(fc_D,"Critical frequency for D-layer ...
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clear data_00;clear data_01;clear data_02;clear data_03;clear data_04; data_00 = fscanfMat('./DATA_storage_experiment1/Figure4_experiment1_case00.txt'); // time Vout Vin data_01 = fscanfMat('./DATA_storage_experiment1/Figure4_experiment1_case01.txt'); data_02 = fscanfMat('./DATA_storage_experiment1/Figure4_experiment1...
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// Initialisations ... s = poly(0,'s'); s = syslin('c',s*s/s); // approx(G,ll) returns approximation of G by elts in ll deff('res=approx(G,ll)',... ['res=0'; 'n=length(ll)'; 'for k=1:n,res=res+ll(k);end'; 'res=res+horner(clean(G-res),0)']) // W3dg1(p) returns p(0) (p degree one) deff('res=w3dg1(p)','res=horner(p,...
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clc P1 = 0.5 // Initial pressure in MPa V1 = 0.2 // Initial volume in m^3 V2 = 0.05 // Final volume in m^3 n = 1.3 // Polytropic index printf("\n Example 7.7") P2 = P1*(V1/V2)^n function y = f(p) y = ((P1*V1^n)/p)^(1/n) endfunction H = integrate('f','p',P1,P2) // H = H2-H1 U = H-(P2*V2-P1*V1) W12...
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//Basic Circuit Concepts //page no-1.10 //example1.2 disp("from the given fig:") disp("I2-I3=13"); disp("-20*I1+8*I2=0"); disp("-12*I1-16*I3=0"); //solving these equations in the matrix form A=[0 1 -1;-20 8 0;-12 0 -16] B=[13 0 0]' disp("A=") disp(A) disp("B=") disp(B) X=inv(A)*B disp("X=") disp(X) dis...
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clc; clear all; disp("Boundary layer thickness") //uU=X //y/delta=Y //X=2*Y-Y^2; L=1.1;//m length of plate w=0.9;// m width of plate Re=2*10^5;// Reynold's number v=0.15*10^(-4);//m^2/s stokes kinematic viscocity U=12;//m/s velocity ofair x=Re*v/U; disp("m",x,"Maximum distance from the leading edge upto whi...
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clear; clc; exec('genqammod.sci') exec('oqpskmod.sci') exec('intdump.sci') exec('oqpskdemod.sci') exec('genqamdemod.sci') clc; M =4; x =0:M-1; y = oqpskmod(x) disp(y,'QPSK modulated output=') z = oqpskdemod(y) disp(z,'QPSK demodulated output=') //RESULT //QPSK modulated output= //column 1 to 2 //0.7071068 0.70710...
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clc BE=60 //in m GD=BE GH=40 HB=80 HD=GH+GD CB=48/0.4// by solving similar triangles CHD and CBE printf('CB = %f m',CB)
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clc; clear; mprintf('MACHINE DESIGN \n Timothy H. Wentzell, P.E. \n EXAMPLE-3.5 Page No.53\n'); L=30; //[in] Length of link d=5/8; //[in] Diameter of link I=%pi*d^4/64; //[in^4] Moment of inertia A=%pi*d^2/4; //[in^2] Area of cross section E=30*10^6; ...
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; defining a sort with the same name (set-logic QF_UF) (declare-sort A 0) (define-sort A () Bool)
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funcprot(0); // Initialization of Variable function[dms]=degtodms(deg) d = int(deg) md = abs(deg - d) * 60 m = int(md) sd = (md - m) * 60 sd=round(sd*100)/100 dms=[d m sd] endfunction MST=12+32.0/60+15.0/3600//mean sidereal time in hr RA=15+45.0/60+10.0/3600;//RA in hr theta=55+14....
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//Chapter-1,Example1_2,pg 1_18 Eav=9 Erms=10 Rm=500 Idc=2*10^-3 Edc=0.9*Erms Rs=(Edc/Idc)-Rm printf("required multiplier resistance") printf("Rs=%.2f ohm \n",Rs )
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//ques14 disp('To find the inverse laplace transform of the function'); syms s t a f=s^2/(s-2)^3; il=ilaplace(f,s,t); disp(il);
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.443402D+00 ...
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clear //Given t=5000 //Days t1=2000.0 a=0.693 //Calculation // dt=(a*t)/t1 N=log10(dt) l=a*N/(t1) //Result printf("\n (i) The fraction remaining after 5000 days is %0.3f ",N) printf("\n (ii) The activity of sample after 5000 days is %0.1f *10**8 Bq",l*10**5)
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block_doc_gen_fcn.sce
global block_doc_name block_doc_list block_doc_ni block_doc_no block_doc_pl block_doc_bdt block_doc_bdf; function dir_callback() disp(" "); endfunction function block_doc_name_callback() global block_doc_name block_doc_list; block_name_obj = findobj('tag','block_doc_name'); block_doc_name = block_name_obj.s...
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//To calculate the free volume per unit cell r = 0.1249; //atomic radius, nm a = 4*r/sqrt(3); //lattice constant, nm a_m = a*10^-9; //lattice constant, m V = a_m^3; //volume of unit cell, m^3 PF = 0.68; //packing factor for BCC FV = 1 - PF; //free volume FV1 = FV*V; //free vol...
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clc// // // //Variable declaration V=9500; //volume(m^3) T=1.5; //time(s) x=100; //absorption(sabines) //Calculation sigma_as=0.165*V/T; //total absorption in the hall(OWU) T=0.165*V/(sigma_as+x); //new period of reverberation(s) //Result printf("\n total absorption in the hall i...
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//Exa 7.1 clc; clear; close; //Given data : Ii=100000;//in Rs Ar=30000;//in Rs n=5;//in years //Formula : (P/A,i,n)=(((1+i/100)^n)-1)/((i/100)*(1+i/100)^n) // when i=10 % i1=10;//in % per annum PW1=-Ii+Ar*(((1+i1/100)^n)-1)/((i1/100)*(1+i1/100)^n);//in RS disp(PW1,"The present worth for i=10% in RS. : "); ...
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//Book Name:Fundamentals of Electrical Engineering //Author:Rajendra Prasad //Publisher: PHI Learning Private Limited //Edition:Third ,2014 //Ex5_7.sce. clc; clear; A=5e-4; l=0.4; N=200; mew_r=380; mew_not=4e-7*%pi; mew=mew_r*mew_not; printf("\n (a)") R=(l*1e-6)/(mew*A); printf("\n Reluctance of t...
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// Ex4_2 clc; // Given: t1=1.3*10^9;// in years w=0.0119;// wt % // Solution: N=(w*6.022*10^23)/(40*100); k=(0.693*60)/(t1*3.16*10^7); sa=N*k;// specific activity printf("The specific activity is = %f dis min^-1 g^-1",sa)
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//What will be the equivalent radius of bundle conductor having its part conductors 'r' on the periphery of circle of dia'd' if the number of conductors is 2,3,4 ,6 ? clear clc; r=poly(0,"r"); D11=r^1; D12=2*r; D14=4*r D13=sqrt(16-4)*r; Ds1=((1*2*2*sqrt(3)*4*2*sqrt(3)*2*2)^(1/7))*r; Ds7=((2*1*2*2**2*2*2)^(1...
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// ELECTRIC POWER TRANSMISSION SYSTEM ENGINEERING ANALYSIS AND DESIGN // TURAN GONEN // CRC PRESS // SECOND EDITION // CHAPTER : 12 : CONSTRUCTION OF OVERHEAD LINES // EXAMPLE : 12.4 : clear ; clc ; close ; // Clear the work space and console // GIVEN DATA T1 = 3000 ; // Bending moments in lb T2 = 2500 ;...
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clear; clc; printf("\t\t\tProblem Number 6.8\n\n\n"); // Chapter 6: The Ideal Gas // Problem 6.8 (page no. 246) // Solution //For CO2, R=8.314/44; //Unit:kJ/kg*K //constant of proportionality //Molecular weight of CO2=44 p=500; //Unit:kPa //pressure V=0.5; //Unit:m^3 //volume T=(100+273); //Unit:K //Celsiu...
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clc // initialization of variables clear // Material properties and dimensions E=72 //G Pa P=10 //kN Q=5 //kN Aab=150 //mm^2 Abc=900 //mm^2 Acd=900 //mm^2 Ade=900 //mm^2 Abd=150 //mm^2 Abe=150 //mm^2 Lab=2 //m Lbc=2.5 //m Lbd=1.5 //m Lbe=2.5 //m Lcd=2 //m Lde=2 //m //calculations E=E*10^9 P=P*10^3 ...
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clc; clear; mtlb_close all; function stairs(x, y) n=length(x); x_indices=int((1:2*n-1)/2)+1; // gives 1,2,2,3,3,...,2n-1,2n-1 x_ss=x(x_indices); // the stair step graph's x values y_indices=int((2:2*n)/2); // gives 1,1,2,2,...,2n-2,2n-2,2n-1 y_ss=y(y_indices) plot2d(x_ss,y_ss) endfunction function gflim(lim) ...
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clc; clear; printf("\t\t\tChapter2_example9\n\n\n"); // determination of heat transferred k=136; // thermal conductivity of aluminium in BTU/(hr.ft.degree Rankine)from appendix table B1 L=9/(8*12); W=9/(4*12); delta=1/(32*12); printf("\nLength=%.5f ft, Width=%.4f ft, Delta=%.6f ft",L,W,delta); hc=0.8; // the c...
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// Function Name: norm // Compute the p-norm // 3rd parameter : "-inf"=1, "inf"=2, "fro"=default // "-inf" is the minimum norm, "inf" is the maximum norm, while "fro" is the Frobenius norm // Calculating the norm inputvec1 = [1, 2, 3]; result = armaVec("norm",inputvec1)
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// here is an example use of the while statement // which is used for finding the root of a polynomial // which is known to lie within a certain interval. // a is the lower value of the range // b is the upper value of the range a= 0; fa = -%inf; b =3 ; fb = %inf ; while abs(b-a) > %eps*b x = ( a + b ) ...
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//Ex 1.15 clc;clear;close; format('v',6); E1=10;//V V2=6;//V V3=8;//V //E1=V1+V2;//KCL for left loop V1=E1-V2;//V //-E2=-V2-V3;//KCL for right loop E2=V2+V3;//V disp(V1,"Voltage V1(V)"); disp(E2,"Voltage E2(V)");
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//Caption: Program to find the phase angle between two vectors //Example1.2 //page 11 clc; clear Q = [4,5,2]; //point Q x = Q(1); y = Q(2); z = Q(3); G = [y,-2.5*x,3]; //vector field disp(G,'G(rQ) =') aN = [2/3,1/3,-2/3]; //unit vector- direction of Q G_dot_aN = sum(G.*aN); //dot product of G and aN disp(G_dot_aN,'G.aN...
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// Test #5 : Valid Input Arguments exec('./iirpowcomp.sci',-1); [b,p]=iirpowcomp([3.3 0.43],[1.21 0.12]; disp(a); disp(b); // //Scilab Output //a=1.21 0.12 //b=- 4.2513585 // 4.2513585 // //Matlab Output //b= -4.2514 4.2514 //a= 1.2100 0.1200
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// Scilab Code Ex1.24: : Page-1.31 (2009) clc; clear; h = 6.6e-034; // Planck's constant, Js h_cross = h/(2*%pi); // Reduced Planck's constant, Js delta_t = 1e-010; // Uncertainty in time, s // From Energy-time uncertainty, // delta_E*delta_t = h_cross/2, solving for delta_E delta_E = h_cross/(2*delta_t...
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clc; Tmin=5+273; // Minimum operating temperature in kelvin Tmax=839+273; // Maximum operating temperature in kelvin Cp=1.005; // Specific heat at constant pressure in kJ/kg K r=1.4; // Specific heat ratio eff_carnot=1-Tmin/Tmax; // Efficiency of the carnot cycle c=1/(1-eff_carnot); p2_p1=c^(r/(r-1)); // Pres...
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im=imread('C:\Users\sir\Downloads\td3.jpg'); //Execution: chargement de l'image im=imread('C:\Users\sir\Downloads\td3.jpg'); //c=[10,10,12]; Message un nombre = une letre ou un chiffre //R=titi(im,c); R=toto(R); tata(R); function bool=v(X,c) taille_A=length(c) [y,x,coul]= size(X); if y<x then ...
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//chapter20 //example20.5 //page441 Vin=24 // V Vout=12 // V Rs=160 // ohm Rl_min=200 // ohm Is=(Vin-Vout)/Rs // in ampere // minimum load occurs when Rl tends to infinity so Il_min=0 // maximum load occurs when Rl=200 ohm Il_max=Vout/Rl_min // in ampere Iz_min=Is-Il_max // in ampere Iz_max=I...
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clc clear //Input data m1=50;//Mass of water at 15 degree centigrade in g m2=80;//Mass of water at 40 degree centigrade in g t1=15;//The temperature of water in degree centigrade t2=40;//The temperature of water in degree centigrade //Calculations T1=t1+273;//Temperature of water in K T2=t2+273;//Temp...
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//required effort //differential axle diameters d1=300 //mm d2=250 //mm //wheel diameter D=800 //mm //load W=20000 //N eta=0.55 VR=(2*D)/(d2-d1) MA=eta*VR P=W/MA //N printf("Required effort =%0.1f N",-P)
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//Chapter 8 Chemical Equlibrium clc; clear; //Initialisation of Variables k= 1.1*10**-5 V= 600 //ml n= 0.4 //mole //CALCULATIONS m= n*1000/V x= (-k+sqrt(k**2+4*4*0.67*k))/(2*4) M= 2*x P= x*100/m //RESULTS mprintf("Molar concentration of NO2= %.2e mol per litre",M) mprintf("\nPer cent dissociation= %.2f percent",P)
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//Example_a_8_6 page no:328 clc; V=100; I=0.7; Vc=200; omega=2*%pi*200; C=I/(omega*200); C=C*10^6;//converting to microFarad Xc=200/0.7; Xl=Xc; L=Xl/(2*%pi*200); R=(V/I)-50; disp(C,"the capacitance is (in microFarad)"); disp(L,"the inductanc is (in H)"); disp(R,"the resistance is (in ohm)");
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// Exa 7.8 clc; clear; close; format('v',5) // Given data I_D = 12*10^-3;// in A V_DS = 6;// in V V_P = 3;// in V R_SS= 1*10^3;// in ohm I_DSS = 20*10^-3;// in A V_GS= poly(0,'V_GS'); V_GS= I_D-I_DSS*(1-V_GS/V_P)^2; V_GS= roots(V_GS);// in V V_GS= V_GS(1);// in V disp(V_GS,"The value of V_GS in volts is ...
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clc; clear; dia1=16;//mm h=30;//mm dia2=5;//mm Q=0.6;//litre/sec mass=0.1;//kg p1=464;//kPa d=999;//kg/m^3 m=d*Q/1000;//kg/s A1=%pi*((dia1/1000)^2)/4;//m^2 w1=Q/(A1*1000);//m/s A2=%pi*((dia2/1000)^2)/4;//m^2 w2=Q/(A2*1000);//m/s Wnozzle=mass*9.81;//N volwater=((1/12)*(%pi)*(h)*((dia1^2)+(dia2^2)+(dia1*di...
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//Example 2.12 //To determine if a triangle can be formed with given dimension clc,clear c=9 //side oposite to vertex C a=6 //side opposite to vertex A b=7 //side opposite to vertex B A=55 //angle at vertex A B=60 //angle at vertex B C=65 //angle at vertex C printf('Sum of angles=180\n') printf('Smallest ...
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clc; r=100; //resistance in Ohm v=10; //in volt d=10; //distance in feet c=10*10^-6; //capacitor in Farad i=v/r; //current disp(i,"The wave travels the length of the line in 20 ns. The current that flows in the capacitor is the short-circuit current = "); //displaying result ch=40*10^-9*0.1; //charge dis...
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errcatch(-1,"stop");mode(2); //Initialization of variables Gf=11.57 //lb per lb of fuel tg=500 //F ta=70 //F //calculations Q1=0.24*Gf*(tg-ta) //results printf("Heat loss = %d Btu per lb of fuel",Q1) exit();
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//Optoelectronics - An Introduction, 2nd Edition by J. Wilson and J.F.B. Hawkes //Example 9.1 //OS=Windows XP sp3 //Scilab version 5.5.2 clc; clear; //given eta=0.6;//Dimensionless Quantum Efficiency of photodiode Lambda0=1.3e-6;//Wavelength in m e=1.6e-19;//Electronic charge in C P=10e-6;//Optical power i...
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clear;lines(0); plot(hilb(51))
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// Scilab code Ex6.5: Pg 202 (2005) clc; clear; h = 6.626e-034; // Planck's constant, Js m = 1e-06; // Mass of the object, kg n = 1; // Quantum number for minimum energy level L = 1e-02; // Distance between two rigid walls, m E1 = n^2*h^2/(8*m*L^2); // Minimum energy of the object, J v1 = sqrt(2*E...
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clear;lines(0); s=poly(0,'s'); h=syslin('c',(s-1)/(1+5*s+s^2+s^3)) xbasc();evans(h) g=kpure(h) hf=h/.g(1) roots(denom(hf))
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//Chapter 8 //Example 8-3 //ProbOnVoltageGain //Page 223 clear;clc; R = 25*10^3 ; aR = 50 ; a = aR / R ; Gain = 1 + (2/a) ; printf ( "\n\n Voltage Gain = %.4f " , Gain )
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// Exa 1.6 clc; clear; close; // Given data T = 287;// in degree C T = T + 273;// in K disp(T,"The temperature on absolute scale in K is");
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function [x,y,typ] = mdaq_mem_write(job,arg1,arg2) mem_write_desc = ["This block writes data to MicroDAQ memory."; "Data written by this block must be accessed with "; "mdaqMemRead function. It can be used in Ext and"; "Standalone mode to access DSP data. Up to 250000"; "values can be stored with th...
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// Demo script data = input('Name of processed dataset : ',"string") algorithm = input('Algorithm to run : ',"string") toolbox_basedir = input('Base directory for toolbox : ', "string") getd('..') machineLearn(algorithm, data, toolbox_basedir, '');
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matriz=zeros(4,5) soma=0 disp("Digite a matriz:") for i=1 :1:4 for j=1:1:5 matriz(i,j)=input("Digite o elemento ") disp("Lido com sucesso") soma=soma+matriz(i,j) end end disp(soma)
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clc // given that del_D = 300 // Separation in distance in m del_t = 4e-7 // separation in time in sec c = 3e8 // speed of light in m/s // Problem 7 on page 25 printf("\n # Problem 7 # \n") v = del_t*c^2/del_D // velocity of one w.r.t other in m/s printf("\n Velocity of one w.r.t other is %f*c m/s.",v/c)
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clc clf() n = 10 // number of samples A2 = 0.577 D3 = 0 D4 = 2.115 // number of defectives x1 = 11.274 x2 = 11.246 x3 = 11.204 x4 = 11.294 x5 = 11.252 x6 = 11.238 x7 = 11.230 x8 = 11.276 x9 = 11.208 x10 = 11.266 r1 = 0.15 r2 = 0.20 r3 = 0.33 r4 = 0.46 r5 = 0.10 r6 = 0.15 r7 = 0.20 r8 = 0.23 r9 ...
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load Nand2DMux8Way.hdl, output-file Nand2DMux8Way.out, compare-to Nand2DMux8Way.cmp, output-list in sel%B1.3.1 a b c d e f g h; set in 1, set sel %B000, eval, output; set in 1, set sel %B001, eval, output; set in 1, set sel %B010, eval, output; set in 1, set sel %B011, eval, output; set in 1, set sel %B100, eval, ...
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clc e=1.6*10^-19 disp(" Electron charge = "+string(e)+"columns") //initializing the value of electron charge. no=2.5*10^13 disp("Number of free electrons/cm^3 in Ge ,n=2.5*10^13)= "+string(no)+"electrons/cm^3")//calculation n=(1/e) disp("Number of free electrons in 1 columns ,n=(1/e))= "+string(n))//calculation ...
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/* Andressa Gomes Moreira - 402305 Trabalho 02 - Questão 02 Inteligência Computacional */ clear; clc; // Carregando a base de dados data = fscanfMat("aerogerador.dat"); x = data(:, 1)' // Variável de entrada x: Velocidade do vento - Todas as linhas da coluna 1 y = data(:, 2)' // Variável de saída y: P...
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clear; clc; dia=1.04e-2; r=dia/2; m=.85; d=2.44; P=74; temp=21; del=round((3.86*P/(273+temp))*1000)/1000; Vv=(3e6/sqrt(2))*r*del*m* log(d/r)* (1+(.03/sqrt(del*r))) *1e-3; mprintf("\nVisual local voltage = %.2f KV/phase", Vv)
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// Function Name: accumulate // Returns the accumulated value of input matrix // Calculating the accumulate. inputMat = [1.2, 1, 1.9; 4, 2.6, 5; 2.3, 8, 7]; result = armaMatFunc("accumulate",inputMat)
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// Ex18_6 Page:356 (2014) clc;clear; m_U232 = 232.037131; // Atomic mass of U-232, u m_He4 = 4.002603; // Atomic mass of He-4, u KE_alpha = 5.32; // Kinetic energy of alpha-particle, MeV m_Th228 = m_U232 - m_He4 - KE_alpha/931.5; // Atomic mass of Th-228, u printf("\nThe atomic mass of Th-228 = %10.6f...
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cd /Users/rfabbri/lib/data/synthcurves-multiview-3d-dataset/ascii-20_views-olympus-turntable clear; format(20) // show 20 digits disp '/////////////////////////' disp 'You should only see zeros, if all works (result of lines without semicolon).' disp '/////////////////////////' // chose 3 arbitrary points (do multipl...
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clc Er=11.9 disp("Er = "+string(Er)) //initializing value of relative dielectric permittivity constant. Eo=8.854*10^-14 disp("Eo = "+string(Eo)+" F/cm") //initializing value of permittivity of free space. e=1.6*10^-19 disp("e = "+string(e)+" columns") //initializing value of charge of electrons. no=1.5*10^10 di...
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clc //Initialization of variables R=1.987 //cal/deg/mol k1=4.45*10^-5 k2=2.52*10^-6 T1=283+273.2 //K T2=356+273.2 //K //calculations Ea=2.303*R*1.7530 /(1/T1 - 1/T2) logZ= log10(k1) +Ea/(2.303*R*T1) Z=10^logZ //results printf("Activation energy = %d cal/mol",Ea) printf("\n Z = %.1e lt /mol sec",Z)
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clc clear P1=1; P2=16; n=1.3; LN=100; N=350; IP=30; Ev=0.95; L=LN/N; x=[((P2/P1)^((n-1)/n))-1]; V14=[IP*(n-1)*60]/[n*P1*100*x*N]; Vs=V14/Ev; D2=Vs*4/[(22/7)*L]; D=D2^0.5; printf('D= %2.0f mm',D*1000); printf('\n'); printf('L= %2.0f mm',L*1000); printf('\n');
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//Page Number: 9.24 //Example 9.18 clc; //(b)Modulation index b //Given SNdB=30; //dB SNRO=10^(SNdB/10); //As SNRO=30*b^2*(b+1) //Therefore p2=poly(0,'x'); p3 =30*(p2^3)+30*(p2^2)-1000; r=roots(p3); t=r(3,1); disp(t,'Modulation index:');
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//Example No. 5.32 clc; clear; close; format('v',9); //Given Data : V=230;//V N1=1000;//rpm Ia1=100;//A Ra=0.1;//ohm Rf=0.1;//ohm N2=800;//rpm Ia2=sqrt(2)*Ia1;//A(As T2=2*T1 & T proportional to Ia^2) Eb1=V-Ia1*(Ra+Rf);//V Eb2=N2*Ia2/(N1*Ia1)*Eb1;//V //Eb2=Ia2*(Ra+Rf+Rbraking) Rbraking=Eb2/Ia2-Ra-Rf;/...
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function [valor, vector] = potencia(A,x0, Tol) vector = x0 A = inv(A) error = 1 while error> Tol x1 = A*x0 [maxi,pos] = max(abs(vector)) valor = 1/x1(pos) x1 = x1 /valor valor = 1/valor error=norm(x1-x0)/norm(x1) //disp(error, "error") ...
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// Example16_9_pg617.sce // Effect of phase control // Theory of Alternating Current Machinery by Alexander Langsdorf // First Edition 1999, Thirty Second reprint // Tata McGraw Hill Publishing Company // Example in Page 617 clear; clc; close; // Given data phi = 20; alpha1 = 30; alpha2 = 0; // Calculations ans1 ...
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//Chapter 5_Monolithic Components //Caption : Capacitance per unit area //Example5.4: Determine the capacitance per unit area of the 400 armstrong gate oxide of a MOSFET device relative permittivity of silicon dioxide=3.9. //Solution: clear; clc; Eo=8.86*10^-14;//permittivity of free space in F/cm Er=3.9;//relat...
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clc(); clear; //Given : Na = 6.023*10^23 ; // Avogadro constant in atoms/mole LE = 200 ; // liberated energy in MeV mm = 235; // molar mass of U 235 in gm/mole // 1 eV = 1.6*10^-19 J , 1 MeV = 1.0*10^6 eV RE = (Na*LE*1.6*10^-19*10^6)/mm ; //released energy in J // 1 cal = 4.187 J EC = RE/4.187 ; // energy in...
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// Example1_6_pg14.sce // To find secondary resistance and reactance // Theory of Alternating Current Machinery by Alexander Langsdorf // First Edition 1999, Thirty Second reprint // Tata McGraw Hill Publishing Company // Example in Page 14 clear; clc; close; // Given data volt_amp = 10e+3; // Volt Ampere rating of ...
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clf; clear; clc; load('C:\Users\tangu\OneDrive\Documents\GitHub\Modelisation\TD4\NetworkData.sod') // Extraction des temps de service index_bool = ( data(:, 3) == 3 ) tabS3 = data(index_bool, :) t_s3 = tabS3(1:$,4); deciles=perctl(t_s3,10:10:90); for i=2:10 ClassesDeciles(i)=deciles(i-1) end ClassesDeciles(1)=min...
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function refs=ref_update_2s(node_stat) d2r = 3.1416 / 180 refs = zeros(2,12); refs(1,5) = node_stat(2,6) * d2r; //refs(1,11) = node_stat(2,12); refs(2,1) = const_val(1,2); refs(2,5) = [node_stat(3,6) - node_stat(2,6)] * d2r; //refs(2,11) = node_stat(3,12) - node_stat(2,12); //x...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>Standing Wave, DG, P=8</description> <executable>ShallowWaterSolver</executable> <parameters>LinearSWE_StandingWave_WallBC_DG_P8.xml</parameters> <files> <file description="Session File">LinearSWE_StandingWave_WallBC_DG_P8.xml</file> ...
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clc g=9.8; //m/s^2 m=4500/3600; //kg/s C1=2800/60; //m/s Z1=5.5; //m h1=2800; //kJ/g C2=5600/60; //m/s Z2=1.5; //m h2=2300; //kJ/kg Q=-16000/3600; //kJ/s W=Q-m*[(h1-h2) + (C2^2 - C1^2)/2/1000 + (Z2-Z1)*g/1000]; disp("Power output of the turbine = ") disp(-W) disp("kW")
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//CARRETTE Kathlyn //BREGERE Anastasia v0=zeros(1, 50) v1=10*ones(1, 50) v2=[0:0.3:10] v5=[-3:0.204:7] function r=fnct(x) r= (1+x).*sin(%pi.*x) endfunction x=linspace(-2,2,100) y=fnct(x) plot2d(y, style=[color("pink")]); plot2d(x, style=[color("green")]); plot2d(%pi.*x+%pi.*x^2, style=[color("red")]); plot2d(%...
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clear data_00;clear data_01;clear data_02;clear data_03;clear data_04;clear data_05;clear data_06;clear data_07;clear data_08; data_00 = fscanfMat('./DATA_storage_experiment2/Figure4_experiment2_case00.txt'); // time Vout Vin data_01 = fscanfMat('./DATA_storage_experiment2/Figure4_experiment2_case01.txt'); data_02 = fs...
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clc; w=3; //weight in lb v=15; //velocity in ft/sec g=32; //g in ft/sec square s=(1/24); //s in ft F=(w*v*v)/(2*g*s); //calculating force exerted in lb disp(F,"Force exerted in lb = "); //displaying result
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v1=120; v2=12.6; r=10; disp("Part a"); n=v1/v2; disp("the turns ratio is"); disp(n); disp("Part b"); i2=v2/r; disp("the secondary current (in A) is"); disp(i2); disp("Part c"); i1=v1/r; disp("the primary current (in A) is"); disp(i1);
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//Example 6_3 clc; clear; close; format('v',5); //given data : r1BYr2=10000;//multipying factor //r=Eta*VT/I0*eps^(-V/Eta/VT) //log(r1BYr2)=(-V1/Eta/VT)/(-V2/Eta/VT)=delV/Eta/VT VT=26;//mV Eta=2;//for silicon delV=log(r1BYr2)*Eta*VT; disp(delV,"Break region for Si(mV)"); Eta=1;//for Germenium delV=log(r1...
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Total index levels = 3 Total number of nodes = 37 Total number of items = 78 Dumping level #0 [Node 31] flags = 0, dge_link = 30 lft_link = -1, rgt_link = -1 Item #0, data = bn, link = 9 Dumping level #1 [Node 9] flags = 0, dge_link = -1 lft_link = -1, rgt_link = 30 Item #0, data = am, link = 2 Item...
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clc //Initialization of variables E=22*10^3 //kJ/mol T=293 //K //calculations ratio=%e^(-E/(8.31451*T)) //results printf("Relative populations of boat and chair conformations is %.1e",ratio)
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Name=1v1 new PlayerCharacters=air1 BotCharacters=QC Mix.rot IsChallenge=false Timelimit=60.0 PlayerProfile= AddedBots= PlayerMaxLives=0 BotMaxLives= PlayerTeam=0 BotTeams= MapName= MapScale=3.8125 BlockProjectilePredictors=true BlockCheats=true InvinciblePlayer=false InvincibleBots=false Timescale=1.0...
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clc T2=300 //temperature in Kelvin T1=420 //temperature in Kelvin Eta=1-(T2/T1) mprintf("maximum possible efficiency=%f",Eta)//ans vary due to roundoff error
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//[]=fcontour_(xr,yr,f,nz,teta,alpha,legend,flag,bbox,zlev) //[]=fcontour_(xr,yr,f,nz,[teta,alpha,legend,flag,bbox,zlev]) // Trace des courbes de niveau de la surface // d\'efinie par un external f ( ex macro [y]=f(x)) // on calcule d'abord f sur la grille definie par xr.yr // xr et yr sont des vecteurs implicites don...
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clear; clc; vl=132000; s=50000000; pf=.85; l=80; function [r,i]=d(mag,theta) r=mag*cosd(theta); i=mag*sind(theta); endfunction previousprot = funcprot(0) funcprot(0) mag=96; theta=78; [r,i]=d(mag,theta); z=complex(r,i); mag=.001; theta=90; [r,i]=d(mag,theta); y=complex(r,i...
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clear// //Variables VGS1 = -3.1 //Gate-Source voltage (in volts) VGS2 = -3.0 //Gate-Source voltage (in volts) ID1 = 1.0 //Drain current (in milli-Ampere) ID2 = 1.3 //Drain current (in milli...
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//Example14.7 // determine the duty cycle of the switching regulator circuit clc; clear; close; ton = 12 ; //msec // on time of pulse // ton = 2*toff ; given // T = ton + toff ; toff = ton/2 ; T = ton+toff ; // total time // The duty cycle of switching regulator circuit is given by d = ton/T; disp('The o...
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//Example_a_8_12 page no:332 clc; //variables cannot be used without initialization and hence the equation cannot be derived like in the text book, the capacitance value can be calculated using the derived values by substituting known values in the equation C=15/(2*%pi*10^6*1256*80); C=C*10^12;//converting to pico ...
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function [den]=denom(r) //returns the denominator of a rational matrix //%Syntax: den=denom(r) //with //r: rational function matrix (may be polynomial or scalar matrix) //den: polynomial matrix //! select type(r) case 1 then den=ones(r); case 2 then den=ones(r); case 15 then if r(1)<>'r' then error(92,1),end d...
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errcatch(-1,"stop");mode(2);//calculating hardness //Example 1.1 //100gm of CaCO3 = 136gm of CaSO4 m=204//mass of the substance wt=136//molecular mass Eq=(m*100)/wt//Equivalents of CaCO3 printf('Thus Equivalents of CaCO3 = %3.2f mg/L or ppm',Eq) exit();
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function curva(x,y,dim,pos) //x,y é a posição do nó //dim é a dimensão da matriz de adjacências //pos representa a posição no vetor angle beta=0.5; a=get("current_axes")//get the handle of the newly created axes a.data_bounds=[-2,-2;15,15]; t=2*%pi*(0:19)/20; xx=[x+beta*cos(t)+beta*cos(pos);y+beta*sin(t)+be...
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//Example 14.1 //Program to determine the attenuation per kilometer for the fiber //and estimate the accuracy of the result clear; clc ; close ; //Given data L1=2*10^3; //metres - INITIAL LENGTH L2=2; //metres - FINAL LENGTH V1=2.1; //volts - INITIAL OUTPUT VOLTAGE V2=1...
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//check o/p for a vector i/p r=[1 2 3 4 5]; y=schurrc(r); disp(y); //output // // - 2. // - 0.3333333 // - 0.25 // - 0.2