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// Compute the feedback gain matrix using ackermanns formula function [K ,phiA] = ackermann(A,B,P) // construct charecteristic equation phi = poly(P,'x'); c = coeff(phi); phiA = eye(A)*c(1); powA = eye(A); for i=2:length(c) powA = powA * A; phiA = phiA + powA * c(i); end K = [zeros(1,le...
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function [wave]=triangle_wave(n) summ = 0 t=linspace(0,(4*%pi),1001) for (k = 0:n) summ = summ + ((((-1)^k) * sin((2*k+1)*t)) / ((2*k+1)^2)) end wave = [summ]' plot(t,wave,".r") endfunction
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// Example 7.5 clear all; clc; // Using the result of Example 7.3 reactivity = 0.001; // As the reactor is fueled with Uranium-235 bet = 0.0065; // Total delayed neutron fraction of all groups denoted by 'beta' printf(" \n A dollar is worth 0.0065 in reactivity for Uranium-235 reactor. \n"); ...
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clc clear //input p1=1.01*10^5//initial pressure t2=135+273//final temperature t1=273//initial temperature d=2.8 //density //calculation p2=p1*t2/t1//pressure law p=(3*p2/2.8)^0.5//kinetic theory //output printf("rms speed of gas molecule is %3.0f m/s",p)
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// Chapter 3 example 1 clc; clear; // Variable declaration r = 0.53*10^-10; // orbit radius m n = 6.6*10^15; // frequency of revolution of electronHz e = 1.6*10^-19 // charge of electron in coulombs h = 6.63*10^-34; // plancks constant in J.s m = 9.1*10^-31; ...
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extractHOGFeatures.sci
// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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// Theory and Problems of Thermodynamics // Chapter 6 // Thermodynamic Potentials and Availability // Example 5 clear ;clc; //Given data VA = 1 // volume of tank A in m^3 NA = 5 // number of moles of A in kmol TA = 600 // temperature of Tank A in K NB = 3 // number of mo...
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10_a.sce
//hex to decimal conversion// //example 10.a// clc //clears the command window// clear //clears// //hex to decimal conversion// x='7C9' a=hex2dec(x) disp('the number in decimal form is:') disp(a)
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java -ea make.Main -f make-tests/make07.mk -D make-tests/file07 T1
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//no i/p args are passsed to the function f=intfilt(); disp(f); ////output //!--error 4 //Undefined variable: L //at line 26 of function intfilt called by : //f=intfilt();
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x=[1 2 3 4 5 6 2 3 7]; p=3; fs=4e6; nfft=6; [S,f] = peig(x,p,nfft,fs) disp(S); disp(f); //output // 9.7899816 // 0.8200464 // 0.5423142 // 0.8341532 // // 0. // 666666.67 // 1333333.3 // 2000000.
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//Exa_1_14 //Graphical representation of fourier series clc; clear; A = 1; w = %pi; tau = 2; for i = 1: 101 t(i) = tau * (i-1)/100; x(i) = A * t(i) / tau; end subplot(231); plot(t,x); ylabel('x(t)'); xlabel('t'); title('x(t) = A*t/tau'); for i = 1: 101 x1(i) = A / 2; end subplot(232); plot(t,x1); xlabel('t'...
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//Ex19_16 Pg-963 clc oct='357' //octal input dec=oct2dec(oct) //decimal output bin=dec2bin(dec) //binary output disp("The binary equivalent of octal 34 is") disp(bin)
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* #-------------- defsym cmd abs #-------------- * defsym arch S/370 script $(testpath)/cmd-abs-2K.subtst * defsym arch S/390 script $(testpath)/cmd-abs-4K.subtst * defsym arch z/Arch script $(testpath)/cmd-abs-4K.subtst
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@relation yeast-4 @attribute Mcg real [0.11, 1.0] @attribute Gvh real [0.13, 1.0] @attribute Alm real [0.21, 1.0] @attribute Mit real [0.0, 1.0] @attribute Erl real [0.5, 1.0] @attribute Pox real [0.0, 0.83] @attribute Vac real [0.0, 0.73] @attribute Nuc real [0.0, 1.0] @attribute Class {MIT, NUC, CYT, ME1, ME2, ME3, E...
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// Example 16_14 clc;funcprot(0); // Given data p_inlet=456.2;// kN/m^2 T_inlet=283.7;// K p_exit=370.4;// kN/m^2 T_exit=260.1;// K V_exit=474.8;// m/s k=1.67;// The specific heat ratio for helium R=2077.0;// m^2/(s^2.K) g_c=1;// The gravitational constant // Calculation // (a) c_osi=sqrt(k*g_c*R*T_inlet...
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//9.16 clc; p =1; q =1; z =0; b =0; w =0; f =0; bin =11001.001011; // binary input d = modulo (bin ,1) ; d= d *10^10; a = floor ( bin ) ; while (a >0) r = modulo (a ,10) ; b(1,q) = r ; a=a /10; a= floor ( a ) ; q = q +1; end for m =1: q -1 c=m -1; f=f+b(1,m) *(2^ c); end while (...
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###TStar Version 05 Tree Description File ###USER=Unknown ###TIME=Sun Dec 13 03:50:22 2009 n=0;h=0;d=2; v:op=17;n=1;h=0;d=2; v:op=2;n=2;h=0;d=2; v:op=14;n=3;h=0;d=2; v:op=5;n=4;h=0;d=2; v:op=17;n=5;h=0;d=2; v:op=2;n=6;h=0;d=2; v:op=14;n=7;h=0;d=2; v:op=14;n=8;h=0;d=2; v:op=5;n=9;h=0;d=2; v:op=17;n=10;h=0;d=2; v:op=5;n=...
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roiPoly.sci
// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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//Chapter-1,Example1_4_1,pg 1-32 //let the diameter of nth dark ring be double the diameter of that of 40th ring //as Dn^2 = 4*R*n*wavelength n_1=40 //40 th dark ring n=4*n_1 //as diameter is double ...
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clear //Carregando arquivos contendo funcoes e tabelas exec('tabelas.sce',-1) //O parametro -1 suprime informacoes na tela exec('iluminacao.sce',-1) exec('paredes.sce',-1) exec('radiacaof.sce',-1) exec('ocupacao.sce',-1) exec('janelas.sce',-1) //Lista Valores de entrada entradas = [23.0 0.4 7 18 1 52 7 18 13 6.5 0 1...
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//Example (pg no.130) A=[3 0 2;1 2 0;0 1 1] B=[2 1;0 1;1 0] A*B
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# ATWM1 MRI Experiment scenario = "ATWM1_Working_Memory_MRI_nonsalient_cued_run1"; scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen #scenario_type = trials; scan_period = 2000; # TR pulses_per_scan = 1; pulse_code = 1; #pulse_width=6; default_monitor_sounds =...
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// Demo script for linear regression getd('../') M = csvRead('Salary_Data.csv'); M(or(isnan(M),'c'),:) = []; X = M(:, 1) y = M(:, 2) // machineLearn('linear_regression', M, 'fit_intercept=False'); machinePredict('attributes.p', X)
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//scilab 5.4.1 clear; clc; printf("\t\t\tProblem Number 11.24\n\n\n"); // Chapter 11 : Heat Transfer // Problem 11.24 (page no. 601) // Solution //A COUNTERFLOW HEAT EXCHANGER //Hot oil enters at 215 F and leaves at 125 F //Water enters the unit at 60 F and leaves at 90 F //Therefore,From figure 11.34, ...
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// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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//chapter 19 Ex 3 clc; clear; close; rUp=9; rDown=27; rStream=(rDown-rUp)/2; printf("The rate of stream is %d km/hr",rStream);
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//To find linear and angular velocity clc //Given: NBO1=40 //rpm O1O2=800/1000,O1B=300/1000,O2D=1300/1000,DR=400/1000 //m //Solution: //Refer Fig. 7.18 //Calculating the angular speed of the crank BO omegaBO1=2*%pi*NBO1/60 //rad/s //Calculating the velocity of B with respect to O1 vBO1=omegaBO1*O1B //m/s vB=...
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//Determine Resultant Force //From given data T=1200 //N F=100 //N N=500 //N W=1000 //N theta=60 //degree //Taking co-ordinate system parallel and perpendicular to plane as x and y axis and resolving the forces Fx=T-F-W*sind(theta) //N Fy=N-W*cosd(theta) //N R=sqrt(Fx^2+Fy^2) printf("The resultant has...
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clc; warning("off"); printf("\n\n example4.5 - pg105"); // given syms r; ro=0.5; //[inch] - outside radius ro=0.0127; //[m] - outside radius in m Tg=2*10^7; //[J/m^3*sec] - heat generated by electric current Tw=30; //[degC] - outside surface temperature km=17.3; //[W/m*K] - mean conductivity // using the...
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// Caption: Finding internal mechanical power clear; close; clc; I_f=11.26; R_f=16.46; //power delivered to forwaed field P_gf=2*I_f^2*R_f; I_b=4; R_b=0.451; //power delivered to the backward field P_gb=2*I_b^2*R_b; P=.95*(P_gf-P_gb); disp(P,'internal mechanical power=')
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//Variable declaration Rf=5 //forward resistance(ohms) Vo=20 //output voltage(V) Rs=10 //secondary resistance of transformer(ohm) //Calculations //Part a Idc=0.1 //dc current(A) Vm=Vo*(sqrt(2)) //mean voltage(V) Vdc=(2*Vm/(%p...
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function [A,b]=aff2ab(lme,dimX,D,flag) //Y,X,D are lists of matrices. //Y=lme(X,D)= affine fct of Xi's; //[A,b]=matrix representation of lme in canonical basis. // if flag=='sp' A matrix is return in sparse storage. [LHS,RHS]=argn(0) if RHS==3 then flag='f';end nvars=0; for k=dimX' nvars=nvars+prod(k); end if par...
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//Example 8.14, Page Number 404 //The Function fpround(dependency) is used to round a floating point number x to n decimal places //Fiber Couple Losses clc; d1=200*(10**-6) //Core Diameter in meters d2=250*(10**-6) //Core + Cladding Diameter in meters d3=3*d2//Mixing rod diameter in meters //Power Levels P...
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// Forced oscillations - variation of Amplitude A with frequency omega // scilab code to replicate plot in figure 6.7 in p.175 of ref[1] // theta --> amplitude of displacement // omega --> frequency of sinusoidal driving force // Author: Denny // Date: Sept 2019 // ref[1]: R G Takwale & P S Puranik, Introduction to ...
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//Book Name: Fundamentals of electrical drives by Mohamad A. El- Sharkawi //chapter 11 //example 11.3 //edition 1 //publishing place:Thomson Learning clc; clear; Ra=2;//armature resistance in ohm Tst1=2;//limited starting time in sec Kphi=3;//field constant in V sec Jm=1;//motor moment of inertia in Nm Jl=5;...
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////Given T=27 //temperature in degree c K=1.38*10**-23 //boltzmann constant in J/K h=6.63*10**-34 //Js m=1.67*10**-27 //Calculation // T1=T+273 v=h/(sqrt(2*m*K*T1)) //Result printf("\n de broglie wavelength is %0.2f A",v*10**10)
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clc clear //INPUT DATA pmb=15;//brake ean pressure in bar L=200;//Stroke in cm d=0.8;//bore daimeter in cm N=100;//speed in rpm nc=6;//number of cylinders bsfc=0.4;//brake specific fuel consumption cv=42000;//calorific value in kJ/kg //CALCULATIONS BP=(pmb*L*(3.14*0.8^2/4)*N*nc)/(60);//Brake power in kW m...
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s=%s; syms k; num=k*(s+1); den=(s^2+4*s+13); t=syslin('c',num,den); clf; evans(t)
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//Force P required to hold the system //Refer to fig. 2.28 (a),(b)&(c) //Applying Lami's Theorem at A we get C=4000*sind(180-60)/sind(60+90-15) //N //Applying equilibrium conditions B P=(-2000*cosd(45)+C*cosd(60))/cosd(15) //N printf("P=%.1f N is required to hold the system in given position.",P) ...
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//EXAMPLE 6.16 //Coefficients of Rational form clc; clear; z=%z; num = 18*z^3; den = 18*z^3 + 3*z^2 - 4*z - 1; disp(coeff(num)/18,'the Numerator polynomial coefficients are:'); disp(coeff(den)/18,'the denominator polynomial coefficients are:');
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//i/p arg x is a matrix x=[1 2 3 4; 5 7 4 62]; m=3; X = corrmtx(x,m); disp(X); //output // !--error 10000 //Input x must be a length n vector //at line 81 of function corrmtx called by : //X = corrmtx(x,m);
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//find clc //solution //given W1=400//N W2=250//N Di=25//mm l1=40//mm l2=50//mm t=400//N/mm^2 //D=25+d //T=W1*D/2=400*(25+d)/2=(5000+200*d)N-mm //T=(%pi/16)*t*d^3 //78.55*d^3=5000+200*d //by hit and trial,d=4.2//mm d=4.47//mm(standard value od diameter from table 23.2) D=25+d C=D/d K=(4*C-1)/(4*C-4)+(...
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//CHAPTER 1- D.C. CIRCUIT ANALYSIS AND NETWORK THEOREMS //Example 2 clc; disp("CHAPTER 1"); disp("EXAMPLE 2"); //VARIABLE INITIALIZATION //star values ra, rc and rd ra=2; //in Ohms rc=4; //in Ohms rd=3; //in Ohms r1=5; //...
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--CD2C11A.TST -- Grant of Unlimited Rights -- -- Under contracts F33600-87-D-0337, F33600-84-D-0280, MDA903-79-C-0687, -- F08630-91-C-0015, and DCA100-97-D-0025, the U.S. Government obtained -- unlimited rights in the software and documentation contained herein. -- Unlimite...
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clc clear //Input data x=0.3;//Thickness of the wall in degree centigrade t1=24;//Inside surface temperature of the wall in degree centigrade t2=-6;//Outside temperature of wall in degree centigrade h=2.75;//Height of the wall in m L=6.1;//Length of the wall in m K=2.6;//Coefficient of conductivity of brick in ...
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figure(1); clf; //2 6 a = 5; b = 1.5; t = linspace(0, 12*%pi, 300); //x = (a - b) * cos(t) + b * cos((a - b) / b * t); //y = (a - b) * sin(t) - b * sin((a - b) / b * t); x = (a - b) * cos(3 * t) + b * cos((a - b) / b * 3 * t); y = (a - b) * sin(2 * t) - b * sin((a - b) / b * 2 * t); plot(x, y);
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//Chapter 10, Example 10.3, Page 282 clc clear // Find the probability P = exp(-6.85*10**-4*368) Pnl = 1/(1+(578*6.85*10**-4)) printf("Fast-neutron nonleakage probability = %f \n",P) printf(" Thermal-neutron nonleakage probability = %f \n",Pnl) // Answer may vary due to round off error
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// Calculating the temperature clc; ET=27.07+0.8; disp(ET,'Required e.m.f.(mV)') disp('temperature corresponding to 27.87 mV is 620 degree C')
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exec("swigtest.start", -1); try x = makeFoo(); catch swigtesterror(); end if fooCount() <> 1 then swigtesterror(); end try y = makeFoo(); catch swigtesterror(); end if fooCount() <> 2 then swigtesterror(); end try delete_Foo(x); catch swigtesterror(); end if fooCount() <> 1 then swigtesterror...
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//ANALOG AND DIGITAL COMMUNICATION //BY Dr.SANJAY SHARMA //CHAPTER 7 //WAVEFORM CODING TECHNIQUES clear all; clc; printf("EXAMPLE 8.5(PAGENO 389)"); //given f_m = 3.4*10^3//maximum frequency in the signal N =24//number of voice signals r = 1.5*10^6//signaling rate v = 8//bits of encoder //calculations...
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// Electric Machinery and Transformers // Irving L kosow // Prentice Hall of India // 2nd editiom // Chapter 9: POLYPHASE INDUCTION (ASYNCHRONOUS) DYNAMOS // Example 9-10 clear; clc; close; // Clear the work space and console. // Given data P = 4 ; // Number of poles in WRIM f = 60 ; // Frequency in Hz ...
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clc //Chapter2 //Ex_2.10 //Given M_Au=197 w=0.1 M_Cu=63.55 p_exp=108 //n*ohm*m X=M_Au*w/((1-w)*M_Cu+(w*M_Au)) C=450//n*ohm*m p_Au=22.8 // resistivity in n*ohm*m p=p_Au+C*X*(1-X) //Nordheim rule x=((p-p_exp)/p)*100 disp(p,"resistivity of the alloy in n*ohm*m is") disp(x,"The difference in the value from ex...
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clc clear //DATA GIVEN D=0.075; //bore in m L=0.09; //stroke length in m n=4; //no. of cylinders erar=39/8; //engine to rear axle ratio =39:8 Dw=0.65; //wheel diameter with tyre fully inflated in m Fc=0.2...
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sys_ss = syslin('c',A,B,C); //The plant (continuous-time) sys_d = dscr(sys_ss, dt); Q = diag([100, 1, 10, 1]); R = 1.0E1; //Usual notations x'Qx + u'Ru Big=blockdiag(Q,R); //Now we calculate C1 and D12 [w,wp]=fullrf(Big);C1=wp(:,1:4);D12=wp(:,5:$); //[C1,D12]'*[C1,D12]=Big P=syslin('d',sys_d.a,sys_d.b,C1,...
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Original Data: [ 0 -1 -2 -3 -4 -5 -6] [ 0 0 0 0 0 0 0] [ 0 1 2 3 4 5 6] [ 0 2 4 6 8 10 12] Data as written with transform "x+1": [ 1 0 -1 -2 -3 -4 -5] [ 1 1 1 1 1 1 1] [ 1 2 3 4 5 6 7] [ 1 3 5 7 9 11 13] Data as w...
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function [data, result] = mdaqAIScanRead(arg1, arg2, arg3) link_id = -1; data = []; result = []; if argn(2) > 3 | argn(2) < 2 then mprintf("Description:\n"); mprintf("\tReads acquired data\n"); mprintf("Usage:\n"); mprintf("\t[data, result] = mdaqAIScanRead(linkID, ...
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// The code was developed under Horizon2020 Framework Programme // Project: 748767 — SIMFREE function Out=SSSoSourceGauss(Ppeak_mW,FWHM_ps,f0_GHz,Order) // Gaussian Pulse Train // // Calling Sequence // Out=SSSoSourceGauss(Ppeak_mW,FWHM_ps,f0_GHz,Order) // // Parameters // Ppeak_mW : Pe...
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clf() /*= Task 1 =*/ function X = my_dft(x) N = length(x) X = zeros(0:N-1) for k = 1:N for n = 1:N X(k) = X(k) + x(n) * exp(-2 * %i * %pi * (k-1) * (n-1) / N) end end endfunction function X = my_fft(x) N = length(x) if (N <= 1) then X = x elseif (modulo(N,2)>0...
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clc clear //Input data w=3//Wavelength of the light in Angstrom v=(3*10^8)//Velocity of light in m/s h=6.626*10^-34//Plancks constant in Js q=40//Scattering angle in degrees m=(9.11*10^-31)//Mass of electron in kg c=(1.6*10^-19)//Charge of the electron in coloumbs //Calculations dl=(h/(m*v))*(1-cosd(q))/10^...
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//chapter 10 //Vout and lower frequency //page no. 354 //Example10_1 //Figure 10.7 //Given clc; clear; t=0; Ri=10000; //in Ohm C=10^-8; //in farad Rf=100000; //in Ohm //Vout(t)=-1/(Ri*C)*int(Vi(t))dt Flow=1/(2*%pi*Rf*C); printf("\n Flow is %.0f Hz",Flow);
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// Scilab Code Ex14.11: Page-550(2014) clc; clear; m_p = 0.938; // Rest mass energy of the proton, GeV E_cm = 14000; // Centre of mass energy of colliding proton beams at LHC, GeV // As E_cm = sqrt(2*m_p^2+2*m_p*K), solving for K K = E_cm^2*1e+009/(2*m_p); // Approx. kinetic energy of the protons needed f...
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//Electric Power Generation, Transmission and Distribution by S.N.Singh //Publisher:PHI Learning Private Limited //Year: 2012 ; Edition - 2 //Example 4.4 //Scilab Version : 6.0.0 ; OS : Windows clc; clear; P=20; //Load in kW pf1=0.8; ...
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//Caption: Confidence Interval for Proportion //Example7.13 //Page217 clc; p = 0.40;// 40% of retailers enhance weekly sales q = 1-p; n = 64;// number of samples //pbar: proportion of success pbar = 32/n;//32 out of 64 are having enhanced sales after displaying advertisement Var = (p*q)/n; //variance Std ...
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function xdot=edsonjPap(u1,u2,u3,u4,u5) // This is nonlinear Pendulum Model // Load the parameters exec('edsonjParametersPap.sce', -1); // state variables x=u1; v=u2; theta=u3; vartheta=u4; // control variables F=u5; // fuerza // Modelo MoDiCA-X //Estado 1-posicion e1dot= v; //Estado 2-Velocidad lineal respecto ...
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function [Path]=choixvideo() Path=uigetfile([""],'C:\Users\thibault\Desktop\TIPE\video') endfunction function [T,samare2,samare1]=pointer(path) [samare1,samare2]=pointage(string(path)) tableau=0; compt=1; for i=1:max(size(samare1)) do if samare1(i,3)<>0 & samare2(i,3)<>0 then tableau(compt,1)...
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//Chapter-13, Example 13.14, Page 391 //============================================================================= clc clear //INPUT DATA deltaIe=1*10^-3;//change in emitter current in A deltaIc=0.99*10^-3;//change in collector current in A //CALCULATIONS a=(deltaIc/deltaIe);//current gain of the transistor ...
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function nim = vgg_warp_H(im, H, interp_mode, bbox_mode) // function nim = vgg_warp_H(im, H, interp_mode, bbox_mode); // // Image warping under plane homography. // // NEWIMAGE = VGG_WARP_H(IMAGE,HOMOGRAPHY) returns an interpolated warp of // IMAGE under HOMOGRAPHY. RGB or intensity images are...
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clc clear //INPUT DATA no=0.5;//Air standard efficiency in percenatge nr=0.7;//relative efficiency in percenatge nm=80;//mechanical efficiency in percenatge cv=45000;//calorific value in kJ/kg BP=75;//Brake power in kW Ra=0.287;//Gas constant Ta=300;//suction temperature in K pa=1*100;//pressure in kN/m^2 V...
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function y= ifftshift1(X,DIM) rhs= argn(2); if(rhs <1 | rhs >2) error('Wrong number of Input arguments'); end select(rhs) case 1 then y=callOctave("ifftshift",X); case 2 then y=callOctave("ifftshift",X,DIM); end endfunction
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clc disp("(ii) Mass of refrigerant circulated per minute") h2=352; //kJ/kg h3=374; //kJ/kg h4=221; //kJ/kg h1=h4; v2=0.08; //m^3/kg rpm=500; D=0.2; L=0.15; n_vol=0.85; RE=h2-h1; V=%pi/4*D^2*L*rpm*2*n_vol; m=V/v2; disp("Mass of refrigerant circulated per minute = ") disp(m) disp("kg/min") disp("(iii) Cooling capacity...
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clear clc //to find number of moles of oxygen //to find number of molecules of oxygen //to find approximate rate at which oxygen molecule strike one face of the box //Given: //refer to figure 22-2 from page no. 499 //length of edge of cubical box L = 10//in cm //pressure of oxygen p = 1.0//in atm //temper...
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clear clf // variables du modèles r = 1 ; A = 0.5 ; K = 2.5 ; B=0.5 ; C=0.3 ; x = linspace(0, 2.5, 301); function f = predation(x) // fonction qui calcule la vitesse d'accroissement f =r * x .* (1 - x / K) - B * (x.^2 ./ (x.^2 + C^2)) // opération vectorielle endfunction plot2d(x, predation(x), style = 2); // Tr...
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clear clc //to find final equilibrium temperature of the system //Given: //mass of copper cube mc = 75//in gram //temperature of oven T0 = 312//in degree celsius //mass of water mw = 220//in gram //heat capacity of beaker Cb = 190//in J/K //intial temperature of water and beaker Ti = 12.0//in degree cels...
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function b = QRhausholder3(n, M, M2, b)//b for i = 1:n b(n) = b(n)/M2(n) end sumMB=0; for j = i+1:n sumMB = M(i,j)*b(j); end for i = n-1:-1:1 if M2(i) == 0 then M2(i) = 0.000001; end b(i)=(b(i) - sumMB)/M2(i); end return b; endfunction
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// ResolveFrame.sci Find missing frame information in a closed loop kinematic // chain // www.controlsystemslab.com August 2012 // kc1 is the frame to be solved // kc2 must be a completed frame, or just a homogeneous matrix describing // the end frame of kc1 w.r.t base // return resolved kc1 as well as T_rel a...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_uncued_run2"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monit...
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//Chapter 8 //Example 8_22 //Page 192; clear;clc; l=150; area=2; us=5000; sf=5; sg=8.9; ww=1.5; mc=7; w=area*sg*100/1000; t=us*area/sf; wt=sqrt(w^2+ww^2); s=wt*l^2/8/t; vsag=s*w/wt; printf("Wt of conductor = %.2f kg \n\n", w); printf("Working tension = %.0f kg \n\n", t); printf("Total weight = %.2f kg \n\n", wt); p...
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//**************************** Adaptive_receptor ********************************** if (blk_name.entries(bl) == "Adaptive_receptor") then addvmm = %t; mputl("#Adaptive_receptor",fd_w); for ss=1:scs_m.objs(bl).model.ipar(1) l1_str= ".subckt Adaptive_receptor in[0]=net"+string(blk(blk_objs(bl),2))+"_"+str...
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clc clear //input data a=3 //exit area to throat area ratio T0=2973 //combustion chamber temperature in K P0=20*10^5 //combustion chamber pressure in Pa k=1.3 //adiabatic constant R=248 //gas constant in J/kg-K Pamb=1*10^5 //ambient pressure in Pa Me=2.52 //mach number for k=1.3 and a=3 using gas tables g...
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clear; clc; disp('Example 1.4'); // Given values P1 = 100; // initial pressure, [kN/m^2] V1 = .056; // initial volume, [m^3] V2 = .007; // final volume, [m^3] // To know P2 // since process is hyperbolic so, PV=constant // hence P2 = P1*V1/V2; // final pressure, [kN/m^2] mprintf('\n The final pres...
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// Example 13.12 // Calculating a Zero-Input Response L=2; R=20; C=1/200; s=%s; // for t<0 i_L_bef=6; v_C_bef=20*i_L_bef; // for t>0 ,figure 13.13(b) //Applying Mesh equation for I_L_s I_L_s=(12+120/s)/(2*s+20+100/s); // I_L_s has the form (Bs+C)/(s^2+2*alpha*s+omega_0^2) comparing these equations // we ...
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//Page Number: 236 //Example 4.18 clc; //Given C=10; //dB D=30; //dB //Parameters bet=10^(-C/20); x=bet/(10^(D/20)); a=sqrt(1-(bet*bet)); //Scattering matrix //Assuming symmetery s=[0 a x (bet*%i);a 0 (bet*%i) x;x (bet*%i) 0 a;(bet*%i) x a 0]; disp(s,'Scattering matrix:');
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//Diameter of windmill(in m): D=26; //Operating speed(in rpm): N=20; //Wind speed(in km/hr): V=36; //Power Output(in W): Po=41000; //Maximum efficiency occurs in following conditions: //Efficiency: Eff=0.593; //Inteference Factor: a=1/3; //Density of air(in kg/m^3): p=1.23;
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clear clc F=1000;//gm/min W=10000;//gm t_avg=W/F; F_50=300;F_100=400;F_200=300;//gm/min t_50=5;t_100=10;t_200=20;//min unconverted=((((1/4)*(t_50/t_avg))-((1/20)*(t_50/t_avg)^2)+((1/120)*(t_50/t_avg)^3))*(F_50/F))+((((1/4)*(t_100/t_avg))-((1/20)*(t_100/t_avg)^2)+((1/120)*(t_50/t_avg)^3))*(F_100/F))+((((1/4)*(t_2...
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// example no. 6.21, // caption: solving the IVP by implicit RK2 method // u'=f(t,u) // u'=-2tu^2 //u(0)=1,h=0.2; t0=0;h=0.2;tn=.4;u0=1; deff('[z]=f(t,u)','z=-2*t*u^2'); umaxAllowed = 1e+100; t = [t0:h:tn]; u = zeros(t); n = length(u); u(1) = u0; for j = 1:n-1 // k1=h*f(t(j)+h/2,u(j)+k1/2); // co...
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//Example 16.6 clc c1=3*10^-6 c2=6*10^-6 c3=12*10^-6 c4=24*10^-6 delta_v=18 disp("solution a") c_eq=1/((1/c1)+(1/c2)+(1/c3)+(1/c4)) disp(c_eq,"capacitance in farad=") q=delta_v*c_eq disp("solution b") disp(q,"voltage between battery in c=")
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1;e;0 5;- p1;-;-;-;2;1;- usePlayerAbility 1 status
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//Ex 5.6 clc; ws=1000*%pi; w=ws/2; disp(w,'Cont. time Frequency w ( rad/seconed )');
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// page no 628 // example no A.7 // SUBTRACTION OF UNSIGNED NUMBERS clc; printf('Part a \n \n') printf('Subtrahend= 62H \n'); printf('Minuend= FAH \n \n'); // finding 2's complement of subtrahend (62H); m=hex2dec(['FA']); x=hex2dec(['62']); y=bitcmp(x,8); // 1's compliment of 62H z=y+1; // 2's compliment of ...
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// Scilab Code Ex16.1: Page-581(2014) clc; clear; H0 = 22; // Value of Hubble constant, km/s per million ly parsec = 3.26; // The value of 1 parsec, light years printf("\nThe value of Hubble constant = %d km/s per Mpc", ceil(H0*parsec)); // Result // The value of Hubble constant = 72 km/s per Mpc
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//Mission B1 //On récupère l'image. pathname = "C:\Users\Jean-Guillaume P\Documents\Exia\A2\Projets\Imagerie\ExoLife\Images\Mission_B\Gliese 667Cc_surface.pbm"; img_in = readpbm(pathname); //Histogramme de l'image. histogramme = histogrammeFct(img_in); // Normalisation minHisto = debutHistogramme(histogramme); max...
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///////////////////////////////////////////////////////// //// Неделя 6. //// Использование байесовского подхода при //// различных значениях априорной неопределенности ///////////////////////////////////////////////////////// clear; deff('[numd] = roundd(num,n)','numd = round(num *10^n) / 10^n'); rand("seed",getdate("...
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//Calculations on four stroke petrol engine clc,clear //Given: bp=35 //Brake power in kW eta_m=80 //Mechanical efficiency in percent bsfc=0.4 //Brake specific fuel consumption in kg/kWh A_F=14/1 //Air-fuel ratio CV=43000 //Calorific value in kJ/kg //Solution: //(a) ip=bp*100/eta_m //Indicated power in kW //(...
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function pushbtn_demo1() for i = 1:10000 p = cmd_digital_in(1,12); if p==0 cmd_digital_out(1,9,0); else cmd_digital_out(1,9,1); end end endfunction
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clc // // // //Variable declaration T=31.4 //Time Period A=0.06 //Amplitude //Calculations W=((2*3.14)/T) Vmax=W*A //Result printf("\n The Maximum Velocity is %0.3f m/sec",Vmax)
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//Chapter 10 //Example 10_6 //Page 237 clear;clc; r=6; xl=8; pfr=0.9; vr=110*1000/sqrt(3); vs=120*1000/sqrt(3); i=(vs-vr)/(r*pfr+xl*sin(acos(pfr))); op=3*vr*i*pfr/1000; pfs=(vr*pfr+i*r)/vs; printf("Recieving end voltage = %.0f V \n\n", vr); printf("Sending end voltage = %.0f V \n\n", vs); printf("Load current = %.2...
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//Calculations on the Carnot cycle clc,clear //Given: T3=800+273,T1=15+273 //Temperature of a hot and cold reservoir in K P3=210,P1=1 //Maximum and minimum pressure in bar //Solution: //Refer fig 2.21 eta_carnot=1-(T1/T3) //Efficiency of Carnot cycle T4=T3 //Isothermal process 3-4 g=1.4 //Specific heat ratio(g...