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mode(7); // Vetores N-dimensionais // simples definicao de um vetor n-dimensional M1(2,2,2) = 3 // redefinicao de elemento M1(:,:,1) = eye(2,2) // extracao de elemento M1(2,2,:) // obtem dimensoes size(M1) // qual a terceira dimensao de M? size(M1,3) // outra forma de definir uma tal matriz M1=hypermat([2,...
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% randpoly.tst % F.J.Wright@Maths.QMW.ac.uk, 14 July 1994 off allfac; on div, errcont; % Univariate: % ---------- randpoly x; % Equivalent to above: randpoly {x}; randpoly(x, dense); % univariate default already dense randpoly(x, degree=10, ord=5); % Bivariate: % --------- % Default is sparse randpoly {x,y}; rand...
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codeblock readtextfile(ScriptDir+"\_TOOLS.sci"); codeblock readtextfile(ScriptDir+"\_SSYS.sci"); codeblock readtextfile(ScriptDir+"\Astronomy\_SUB\LoadPlanetMoonsKepler.sci"); au2km=149598000; JID=0; ssysframe=ssys_create; showconstellations=true; ssys_showconstellations(showconstellations); root.SC.Universe.StarB...
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//Calculate frequency and impedance and current at resonance and current in coil and capacitor clear; clc; //soltion //given R=10;//ohm L=100*10^-6;//H C=100*10^-12;//F Vs=10;//V fo=1/(2*%pi*sqrt(L*C)); Zp=L/(C*R); //impedance printf("The Resonant frequency= %.3f MHz\n",fo/10^6); printf("The impedance...
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========================================================= Calculation Report PyQTST v2.0 Q. Lin, Wuhan University, 2020 ========================================================= d8888b. db db .d88b. d888888b .d8888. d888888b 88 `8D `8b d8' .8P Y8. ...
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clear; clc; // Illustration 3.4 // Page: 69 printf('Illustration 3.4 - Page: 69\n\n'); // solution //***Data****// // a = UF6 b = air // The average heat transfer coefficient: Nu_avg = 0.43+0.532(Re^0.5)(Pr^0.31) // The analogus expression for mass transfer coefficient: Sh_avg = 0.43+0.532(Re^0.5)(Sc^0...
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//Interpolação Quadratica clear clc x = [-1;0;2]; y = [4;1;-1]; n = size(x,1) A = [x^2 x ones(n,1)] Ab = [A y] disp(Ab) // Determina a triangulação superior for j = 1: (n-1) for i = (j+1):n //verifica se a diogonal não possui 0 if (Ab(j,j)== 0) then y=Ab(j,:) Ab(j,:...
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// Example 6.2, page no-371 clear clc //(a) b=20 a=4 op=16 p=(op-a)*2/(b-a) p_h=p*10 h=p_h-2-5 printf("(a)\nh = %dm",h) //(b) p1=1 t_op=((b-a)/2)*p1+4 printf("\n(b)\nTransmitter output =%d mA",t_op) //(c) p2=0.5 t_op1=((b-a)/2)*p2+4 printf("\n(c)\nTransmitter output =%d mA",t_op1)
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//example 11.4 clc; funcprot(0); FS=4; Ap=0.1295; Nc=9; cu2=100; Qp=Ap*Nc*cu2; D=[5, 10, 30]; avgD=[2.5, 7.5,20]; sigma=[45, 110.5, 228.5]; cu=[30, 30, 100]; alpha=[0.6 0.9 0.725]; L=[5, 5, 20]; p=%pi*0.406; Qs=0; disp(Qp,"bering capacity in kN"); printf("depth (m)\t avg Depth(m)\t avgVerticalStress(kN/...
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clear; clc; T=.1*10^-3; f=1/T; k=15*10^-6;//k=th/w; th=2*%pi*f*k; X_l=10; R=2; X_c=R*tan(th)+X_l; C=1/(2*%pi*f*X_c); printf("value of C=%.3f uF",C*10^6);
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// C-Exercise13 // Jurian Kahl // Nattawut Phanrattinon funcprot(0); function [VaR, ES] = VaR_ES_historic (x_data, l, alpha) l_data_sorted = gsort (l(x_data), "g","d"); n = length(l_data_sorted); VaR = l_data_sorted( floor(n*(1-alpha)) +1 ); ES = 1 / (floor(n*(1-alpha)) +1) * sum(l_data_sorted(1:floor...
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//example1.31 clc disp("Method 1: Kirchoffs laws") disp("Now apply KVL to the two loops without current source as effect of the currents in various branches.") disp("-2(I1-2)-I2+6=0 i.e. 2(I1)+I2=10 ..(1)") disp("-3(I1-2-I2)-12+I2=0 i.e. -3(I1)+4(I2)=6 ..(2)") disp("-3(I1)+4(10-2(I1))=6") i=34/11 ...
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clc //Example 6.18 //Verification of Reciprocity theorem I=10 //From figure 6.61 disp('The current divides between the two parallel impedances') //Let I2 be the current through 4 ohm I2=(10*5)/(4-%i*4+5) //Let Vx be the voltage across -i4 ohm capacitive reactance Vx=I2*(-%i*4) [Vxmag Vxang]=polar(Vx) printf...
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// A Textbook of Fluid Mecahnics and Hydraulic Machines - By R K Bansal // Chapter 1-Properties of Fluid // Problem 1.30 //Given Data Set in the Problem h=0.2*10^-3 st=0.0725 dens=1000 g=9.81 //Calculations //Using rise=4*surface tension/(density *g *diameter of capillary) d=4*st/(dens*g*h) mprintf("The ...
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clear; clc; close; Vcc = 20; Vc = 18; Vce = 8; Vbe = 0.7; Beta = 150; Ic = 10*10^(-3); Ie = Ic; R2 = 1.6*10^(3); Ve = 0.1*Vcc; Re = Ve/Ie; Rc = (Vcc-Vce-Ve)/Ic; Vb = Vbe + Ve; R1 = R2*Vcc/Vb - R2; disp(Re,'Value of Re(ohms) is : '); disp(Rc,'Value of Rc(ohms) is : '); disp(R1,'Value of R1(ohms) is...
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//pathname=get_absolute_file_path('8.25.sce') //filename=pathname+filesep()+'8.25-data.sci' //exec(filename) //Mass flow rate(in kg/s): mhp=2 mlp=1.5 //Expansion efficiency: n=0.90 //Power developed by the turbine(in kW): P=3000 //From steam tables: h1=3034.8 //kJ/kg s1=6.8844 //kJ/kg.K s3=s1 x3=0.9566 h...
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//Caption:expression_for_unit_step_response // example 11_11 //page 481 syms G1 G2 G3 H1 t; s=%s; G1=s+1; G2=1/(s+2); H2=1/(s*(s+1)); H1=1/(s+2); a=G1/(1+G1*H1); b=a/(1+a*H2) y=b*G2; disp(y,"C(s)/R(s)=") //for unit step response R(s)=1/s; C=y*(1/s) c=ilaplace(C,s,t) disp(c,"expression_for_unit_step_resp...
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// Ex19_1 Page:368 (2014) clc;clear; K_x = 10; // Energy of incident deutrons, MeV K_y = 15; // Energy of emitted neutrons. MeV m_H2 = 2.014102; // Atomic mass of deutrium, u m_n = 1.008665; // Mass of a neutron, u m_Cu63 = 62.929599; // Atomic mass of Cu-63, u m_Zn64 = 63.929144; // Atomic mas...
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5_23.sce
clc; clear; //Example 5.23 Cpo=2131; //Sp heat of oil in [J/kg.K] Cpw=4187; //Sp heat of water in [J/kg.K] mo_dot=0.10; //Oil flow rate in [kg/s] mw_dot=0.20; //Water flow rate in [kg/s] U=380; //Overall heat transfer coeff in [W/sq m.K] T1=373; //Initial temp of oil [K] T2=...
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DMux4way.tst
load DMux4Way.hdl, output-file DMux4Way.out, compare-to DMux4Way.cmp, output-list ip1%B2.1.2 s%B2.2.2 out1%B2.1.2 out2%B2.1.2 out3%B2.1.2 out4%B2.1.2; set ip1 0, set s %B00, eval, output; set s %B01, eval, output; set s %B10, eval, output; set s %B11, eval, output; set ip1 1, set s %B00, eval, output; set s %B01,...
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3_2.sce
//Example 3.2 //Gaussian Elimination Method //Page no. 54 clc;clear;close; A=[2,4,-6,-4;1,5,3,10;1,3,2,5]; //augmented matrix //triangularization for i=1:3 for j=1:4 if i==1 then B(i,j)=A(i,j) elseif i==2 B(i,j)=A(i,j)-A(i,1)*A(i-1,j)/A(1,1) ...
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//Chapter 7, Example 7.4, Page 186 clc clear // Flux density Sp = 1.295*10**13 r = 100 mew = 0.3222 phimax = 2*10**3 phi = Sp*10^-2/(4*%pi*r**2) t = -(1/mew)*log(phimax/phi) printf("phi = %e cm^-2/s^-1\n",phi) printf(" t = %f cm^-1",t) //Answers may vary due to round off error
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Ex16_7.sce
//Chapter 16,Example 6,page 561 //Determine the wave generated clear clc C1 = 0.125*10^-6 // F C2 = 1*10^-9 // F R1 = 360 // ohm R2 = 544 // ohm V0 = 100 // kV theta = sqrt(C1*C2*R1*R2) neta = 1/(1+R1/R2+C2/C1) alpha = R2*C1/(2*theta*neta) printf("\n Theta = %f micro S",theta*10^6) printf("\n Neta = %f",neta) printf("\...
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// Nemo airfoil selection script // // Diego Montero; Gustavo Violato; Fernando Valentini // First release: Oct. 2015 clc xdel(winsid()) clear NEMO_DIR = getenv('NEMO_ROOT'); AIRFOIL_DB = NEMO_DIR + '/dbfiles/airfoils'; // Physical variables // ================== GRAV = 9.80665; // gravity [m/s^2] // Water tempe...
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example5_19_TACC.sce
//example 5.19 clear; clc; disp("CH4(g)+2O2(g)-->CO2(g)+2H2O(l)"); //Given: S1=-242.98;//standard entropy change for the combustion reaction[J/K] Hf1=-74.81;//Enthalpy of formation of CH4(g)[KJ/mol] Hf2=-393.51;//Enthalpy of formation of CO2(g)[KJ/mol] Hf3=-285.83;//Enthalpy of formation of H2O(l)[KJ/mol]...
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極配置でS設計.sce
//A = [1 1 0;0 2 1;0 0 2]; //B = [0 0 1]'; // サブシステムの行列 A11 = [1 1;0 2]; A12 = [0;1]; S2 = eye(1); // 配置したい極を指定 p = [-10+0*sqrt(-1) -5+0*sqrt(-1)]; // 超平面の設計 K = ppol(A11,A12,p) S = S2*[K S2] disp("切換超平面:S=") disp(S) //切換超平面Sの値をコンソールに出力
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example_3_11.sce
// given gain of buffer amplifier is 1 s=%s I=1; R=10^6; C=10^-6 C2=0.5*10^-6; Vi=1/(C*s)*I + R*I V1=R * I disp(V1/Vi,"V1/Vi is ") V2=I/(C2*s) + I*R Vo= I*R disp(Vo/V2,"Vo/V2 is ") V1=V2 //because gain=1 (s/(s+1))*Vi == (s+2)/s * Vo // disp(s^2/((s+2)*(s+1)),"transfer function is")
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ScatProb.sce
clear N=100; theta = linspace(0,2*%pi,N); varphi = linspace(-1*%pi/2,%pi/2,N); x=[]; y=[]; z=zeros(N*N,N*N); for i=1:N for j=1:N x=[x; sin(theta(i))*cos(varphi(N))] y=[y; sin(theta(i))*sin(varphi(N))] z(i,j) = cos(theta(i)); end end theta0 = linspace(0,%pi,N); ftheta0 = cos(theta0/2)...
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UDPio.sce
// // // Example for a communication interface from ORTD using UDP datagrams to e.g. // nodejs. // The file webinterface/webappUDP.js is the counterpart that provides a // web-interface to control a oscillator-system in this example. // // For more details, please consider the readme-file. // // Rev...
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Exa14_5.sce
//Exa 14(v) clc; clear; close; //given data : inINV=50000;//initial investment in Rs. and equal for all projects life=5;//in years salvage=0;//in Rs. TaxRate=55;//in % //depreciation type :Straight line D=inINV/life;//in Rs //cash flows before tax of 1st,2nd,3rd,4th and 5th years CBFT1=10000;//in Rs. CBFT...
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//Ex 5.9 clc; clear; close; format('v',8); Vin=2;//V Rf=2*2/(2+2)+2;//kohm R1=1;//kohm Vout=-Rf/R1*Vin;//V disp(Vout,"Output Voltage(V)");
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//Chapter 3 Liquids clc; clear; //Initialisation of Variables W= 0.220 //gms g= 980.7 //cm per sec62 f= 0.98 l= 4 //cm //Calculations T= W*g/(2*l) Tc= T*f //Results mprintf("Apparent Surface Tension = %.1f dynes per cm",T); mprintf("\nExact Surface Tension = %.1f dynes per cm",Tc);
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clc B= 0.997 disp("B= "+string(B)) //initializing value of base transport factor Db = 10 disp("Db= "+string(Db)+"cm^2/s")//initializing value of diffusion coefficient in the base Tb = 10^-6 disp("Tb= "+string(Tb)+"s")//inializing value of electron lifetime Lb = sqrt(Db*Tb) disp("The electron carrier diffusion l...
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clear; clc; // Illustration 11.3 // Page: 602 printf('Illustration 11.3 - Page: 602\n\n'); // Solution //***Data***// T = 1; //[m] di = 0.203;// [m] n = 1;// [for one impeller] Density_S = 2300;// [kg/cubic m] Density_p = 2300;// [kg/cubic m] C = 0.150;// [m] S = 50;// [kg] g = 9.807;// [m/s] dp ...
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//Chapter 13 //page no 583 //given clc; clear all; Er=4.7; b=10; //in mils w=4; //in mils t=0.5; //in mils Z=60/sqrt(Er)*log(4*b/0.67/%pi/(0.8*w+t)); printf("\n Z = %0.2f ohm\n",Z); tpd=1.017*sqrt(Er); printf("\n tpd = %0.1f ns/ft\n",tpd); Tpd=tpd*1000/12; ...
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//Chapter 18 //Example 18_3 //Page 429 clear;clc; a=1*(cosd(120)+%i*sind(120)); Ir=12+%i*6; Iy=12+%i*-12; Ib=-15+%i*10; Ir0=1/3*(Ir+Iy+Ib); Ir1=1/3*(Ir+a*Iy+a^2*Ib); Ir2=1/3*(Ir+a^2*Iy+a*Ib); disp("RED PHASE:"); printf("Ir0 = %.2f+j(%.2f) A \n", real(Ir0), imag(Ir0)); printf("Ir1 = %.2f+j(%.2f) A \n"...
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function P=Ptend(Fig) P=Fig(size(Fig,1),:) endfunction
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clear all; clc; disp("Scilab Code Ex 10.7 : ") //Given: ep_x = -400;//(*10^-6) Normal Strain ep_y = 200; //*(10^-6) Normal Strain gamma_xy = 150; //*(10^-6) Shear Strain //Maximum in-plane Shear Strain: strain_avg = (ep_x+ ep_y)/2; tou = gamma_xy/2; R = sqrt((-ep_x + strain_avg)^2 + tou^2); strain_ma...
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//Example6.24 // To determine the output voltage clc; clear; close; Vin = 2.5 ; Rf = 100*10^3 ; R1 = 10*10^3 ; RI1 = 25*10^3 ; RI2 = 10*10^3 ; R2 = 100*10^3 ; // the output voltage of an inverting amplifier Vo1 = (1+(R2/R1))*Vin ; ; disp('The output voltage of an inverting amplifier is = '+string(Vo1)+ '...
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//**************************** DC_in *********************************** if (blk_name.entries(bl) =='dc_in') then mputl("# dc_in",fd_w); DC_in_char = [3.0e-06 2.4462;2.5e-06 2.4163;2.0e-06 2.2968;1.5e-06 2.0720;1.0e-06 1.7760;0.9e-06 1.7016;0.8e-06 1.6102;0.7e-06 1.5330;0.6e-06 1.4284;0.5e-06 1.3176;0.4e-06 1.1...
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// ------------------------------- // // // the kinect data results from the code // ./bin/testSaveFeetTrajectories [~/Documents/data/handibio/essai1/ 2000 10000 1] // // FOR PRENSENTATION PAL // // 1. Read data // 2. Synchro times : search the min time and start there as 0 // 3. Align Frames // --------------------...
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m=.05; //m=%pi.*a.^2.*I/c ring current I radius a len=0.1; b0=1.0; wid=1.0; shift=0.5; x=-1.0:0.05:1.0; y=0.1:0.1:2.0; [X1,Y1]=meshgrid(x-shift,y); [X2,Y2]=meshgrid(x+shift,y); //bx1=-0.1*(X1./sqrt(X1.^2))-2.0.*b0*X1.*exp(-wid.*(X1.^2)./len); bx1=-2.0.*b0*X1.*exp(-wid.*(X1.^2)./len); by1=+b0.*exp(-wid.*(X1.^2)./le...
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disp("Vp=σ*(a^2)/(2*μh*Єs)"); b=1/10; //say b=σ c=500; //say c=μh d=12*8.854*10^-14; //say d=Єs a=2*10^-4; Vp=b*(a^2)/(2*c*d); printf('\n The value of pinch-off voltege is %fV',Vp);
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//Example 7.4.b: emf generated clc; clear; close; // given data: W=20000;// in watt V=200; // in volts R=0.08; // in ohm Rs=0.02; // series field resistance in ohm I=W/V; // in A Rsh=42; // shunt ield resistance in ohm Ra=0.04; // armature resistance in ohm Vf=I*R; Vs=I*Rs; V1=Vf+Vs; // voltage drop of feeder and seri...
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clc(); clear; //Given : mu = 1.4;// refractive index of a thin film lambda = 5890; // Wavelength of sodium light in A deltalambda = 20; //line width in A // For observing interference pattern, t < lambda^2/(2*mu*deltalambda) t_max = lambda^2/(2*mu*deltalambda); //thickness of the film in A printf(" t_max : %1.3...
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// example 1.8(a)// //conversion hexadecimal number to octal number // clc //clears the screen // clear // clears already existing variables // x= hex2dec ('2F') //hexadecimal to decimal conversion // a= dec2oct (x) //decimal to octal conversion // disp ('conversion of given hexadecimal no to its octal form r...
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// Example : 4.58 v1=233.73-%i*8.934; vs=240+%i*0; r1=0.6+%i*0.8; i1=(vs-v1)/r1; disp('the value of I1 is = '+string(i1)+' Amp'); r2=0.5+%i*0.866; vs1=239.5-%i*14.359; i2=(vs1-v1)/r2; disp('the value of I1 is = '+string(i2)+' Amp'); r3=16+%i*12; il=i1/r3; disp('the value of I1 is = '+string(il)+' Amp...
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a={8,0,0, 0,0,0, 0,0,0; 0,0,3, 6,0,0, 0,0,0; 0,7,0, 0,9,0, 2,0,0; 0,5,0, 0,0,7, 0,0,0; 0,0,0, 0,4,5, 7,0,0; 0,0,0, 1,0,0, 0,3,0; 0,0,1, 0,0,0, 0,6,8; 0,0,8, 5,0,0, 0,1,0; 0,9,0, 0,0,0, 4,0,0;} b=a; function [z]=generate(a,x,y) z=%F; if x==9 & y==9 disp(a); ...
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<?xml version="1.0" encoding="utf-8" ?> <test> <description>Helmholtz 3D CG for Pyramid with LE preconditioner</description> <executable>Helmholtz3D</executable> <parameters>-I GlobalSysSoln=IterativeStaticCond -I Preconditioner=LowEnergyBlock Helmholtz3D_Pyr_VarP.xml</parameters> <files> <file ...
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//the electric field at Q1 needed to be determined. //given clc Q1=1d-9//at (-1,1,-3) Q2=5d-9//at (3,1,0) epsilon0=8.85D-12//the values may differ as i have used the exact value of permitivity R=[-1 1 -3]-[3 1 0]// r=norm(R)//magnitude of the vector r ar=R/r//unit vector E=(Q1/(4*%pi*epsilon0*(r^2)))*ar E=rou...
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clc; p1=3; // Pressure of fluid at inlet in bar T1=150; // Temperature of fluid at inlet in degree celcius V1=90; // Velocity of fluid at inlet in m/s eff_nozzle=0.85; // Nozzle efficiency k=1.4; // Index of reversible adiabatic process p2=1/3*p1; // (a).Steam // Following are taken from steam table h1=2761...
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// This file is released under the 3-clause BSD license. See COPYING-BSD. // Generated by builder.sce : Please, do not edit this file // ---------------------------------------------------------------------------- // libinherit_path = get_absolute_file_path('loader.sce'); // // ulink previous function with same name [b...
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//===================================================================================== //Chapter 13 example 4 clc;clear all; //variable declaration T0 = 4; //time of swing in seconds Ig =0.001; //current in A lamda = 0; theta = 50; //steady deflection in scale divisions theta1 =...
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function state = mdaq_dio_read(link_id, dio) if argn(2) <> 2 then disp("ERROR: Wrong input arguments!"); return; end if link_id < 0 then disp("ERROR: Wrong link ID!") return; end if dio > 32 | dio < 1 then disp("ERROR: Wrong DIO number!") return; ...
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function p = polynomeLagrange(i,n) p = 1; x=[0:1/n:1]; for j=1:n+1 if i <> j then p = p * poly([-x(j) 1],"x","coeff")*(x(i)-x(j))^(-1); end end endfunction function P = polyLagrangeBase(f,n) P = 0; x = [0:1/n:1]; for i=1:n+1 P=P+f(x(i))* polynomeLagrange(...
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// carregar variável do arquivo load("input.dat", "T1", "T2", "T3", "T4"); N = T1 + T2 + T3 + T4 - 3; // salvar o valor das variáveis em arquivo save("output.dat", "N");
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PL/SQL Developer Test script 3.0 11 -- Created on 09.12.2017 by V.ZHURAVOV declare -- Local variables here i integer; begin --dbms_session.reset_package; return; -- Test statements here dv_sr_lspv_docs_api.update_sp_tax_residents_t( p_process_id => 150 ); end; 0 0
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//exa 2.10 clc;clear;close; format('v',5); B11=0.001;//MW^-1 B22=0.0024;//MW^-1 B12=-0.0005;//MW^-1 //dC1/dP1=0.8*P1+16;//Rs./MWh //dC2/dP2=0.08*P2+12;//Rs./MWh lambda=20; //Iterations for calculating value P1(1)=0; P2=0; for i=2:1:10 P1(i)=(0.2+0.001*P2(i-1))/0.006; P2(i)=(0.4+0.001*P1(i))/0.0088...
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// Versão simplificada do algoritmo de valores próprios de Jacobi function [x] = Gauss_Jacobi(a,b,x0,tol,N) n = size(a,1) for iteracao = 1:N for k = 1:n-1 for i = k+1:n m = a(i,k)/a(k,k) for j = k:n a(i,j) = a(i,j) - m*a(k,j) ...
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//Chapter-13, Example 13.9, Page 569 //============================================================================= clc clear //INPUT DATA CAs=0.02;//Carbon mole fraction CAo=0.004;//Content of steel CA=0.012;//Percet of depth d=0.001;//Depth in m H=(6*10^-10);//Diffusivity of carbon in m^2/s //CALCULATI...
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clc disp("Example 3.7") printf("\n") printf("Given") disp("Total resistance of three resistors is 50 ohm") R=50; disp("Output voltage is 10 percent of the input voltage") //Let v be input voltage and v1 be output voltage //Let v1/v=V V=0.1; //As V=R1/(Total resistance) //Solving for R1 R1=V*R; //As R=R1+R2...
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// File name: Move.tst load Move.hack; echo "First, make sure that 'No Animation' is selected. Then, select the Keyboard, use the keyboard, and check the screen."; repeat { ticktock; }
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// Ejemplo de una ecuación diferencial parcial en 1D // -Uxx+Ux=0 // 0<U<1 // U(0)=0 y U(1)=1 // Resuelve Ax=b usando el metodo Jacobi function x=Jacobi(A,b,N) x=zeros(N,1); xt=zeros(N,1); eps = 1e-5; iter = 100; for it = 1: iter for i = 1: N sum = 0.0; for j = 1: N if i == j then ...
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//Variable Declaration n = 3 // No. of flips p = 0.5 // probability of head in one flip //Results printf ( "Mean Number of heads: %.2f",n*p)
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//Kunii D., Levenspiel O., 1991. Fluidization Engineering(II Edition). Butterworth-Heinemann, MA, pp 491 //Chapter-5, Example 2, Page 132 //Title: Initial Bubble Size at a Distributor //========================================================================================================== clear clc //INPUT...
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//Caption: Probability //Example 2.1.c //page no 43 //Find the probability clc; clear; redballs=3; whiteballs=4; blackballs=5; //Probability Getting black ball pb=blackballs/(redballs+whiteballs+blackballs); //Probability Getting white ball pw=whiteballs/(redballs+whiteballs+blackballs); //Probability Get...
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//Setup GaAs=1; Ge=2; Si=3; Eg = [1.42 0.66 1.12];//eV B = [2.1E14 1.66E15 5.23E15];//cm^{-3}K^{-3/2} k=86E-6;//eV/K //user selections T=300;//Kelvin material = Ge; ni = B(material) * T^1.5 * exp(-Eg(material) / (2*k*T)) // in cm^{-3}
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//Turn off the warning messages in the console previousprot = funcprot(1) //integer with possible values 0, 1, 2 returns previous value funcprot(0) //allows the user to specify what scilab do when such variables are redefined. 0=nothing, 1=warning, 2=error gui=figure('figure_position',[750,200],'figure_size',[300,...
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ex16c(); if Str<> "Pilgrim said he, where can it be this land of Eldorado" then pause;end
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Sy=10*10^3;//vertical load,given,in N B=[200;250;400;100;100;400;250;200];//boom area,given y=[30;100;100;50;-50;-100;-100;-30];//x-coordinate of each boom x=[120;240;240];//distences along x-axis between booms
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// Exa 11.1 clc; clear; close; format('v',6) // Given data P = 4; f = 50;// in Hz Ns = (120*f)/P;// in rpm disp(Ns,"The synchronous speed in rpm is"); s = 4; //s = ((Ns-N)/Ns)*100; N = Ns - ( (s*Ns)/100 );// in rpm disp(N,"The speed of the motor in rpm is"); N = 1000;// in rpm s = ((Ns-N)/Ns); f_desh= s...
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// Example 10_4 clc;funcprot(0); // Given data V_wbyomegaD_m=0.1; C_pm=0.50;// The power coefficient V_w=10;// The wind speed in m/s P_wtp=100;// kW rho=1.2;// The density of air in kg/m^3 // Calculation omega_p=sqrt((%pi*C_pm*rho*V_w^5)/(8*P_wtp*10^3*V_wbyomegaD_m^2));// s^-2 omega=omega_p*(60/(2*%pi));// ...
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clc clear //INPUT DATA p1=0.9;//initial pressure in bar pd=18;//delivery pressure in bar n=1.3;//index of compression R=0.287;//gas constant t1=303;//temperature in K t0=290;//temperature in K p11=1;//pressure in bar //CALCULATIONS p2=sqrt(p1*pd);//intermediate pressure in bar v0x=(p1/1)*(t0/t1)*0.891743;...
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//Example 4.3, Page number 4.32 clc;clear;close // variable declaration C=3*10**8 // Velocity of light m/s W=632.8*10**-9 // wavelength in m P=2.3 t=1 h=6.626*10**-34 // Planck constant S=1*10**-6 // Calculations V=C/W // Frequency n=((P*10**-3...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>Rossby modon, DG, P=9</description> <executable>ShallowWaterSolver</executable> <parameters>NonlinearSWE_RossbyModon_DG_P9.xml</parameters> <files> <file description="Session File">NonlinearSWE_RossbyModon_DG_P9.xml</file> </files> ...
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clear; clc; Voc2=100;I1=10;V2=25; Voc1=100;I2=20;V1=50; z11=Voc1/I1; z21=V2/I1; z22=Voc2/I2; z12=V1/I2; printf("(a)The driving point impedances are:\n"); printf(" z11 = %f ohms\n",z11); printf(" z22 = %f ohms\n\n",z22); printf(" The transfer impedances are:\n"); printf(" z12 = %f ohms\n",z12); printf("...
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clear //Initialisation c=100*10**-6 //capacitance in farad r=100*10**3 //resistance in ohm v=20 //volt t=25 //time in seconds e=2.71828 //mathematical constant //Calculation T=c*r //time in seconds v1=v*(1-e**...
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// Scilab code Ex4.14: Pg 129-130 (2008) clc; clear; A = 8e-04; // Cross-sectional area, metre-square d = 24e-02; // Mean diametre of iron ring, m phi = 1.2e-03; // Flux, Wb mew_r = 1200; // Relativ...
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For testing ftp, setup directory and try each command. First try each command line switches: -n suppress autologin -a startup in default ascii mode test for host-name prompt test all commands ? / help : no parameters allowed, summary ok ! : ok ascii/binary : ok bell/nobell : ok hash/nohash : o...
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clc // // // //Variable declaration W=(3.14/3) //Angular frequency in radian //Calculations t=((3.14)/(3*W)) //Result printf("\n The time taken to move from one end of its path to 0.025m from mean position is %i sec",t)
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/////////////////////////////////////////////////////////////////////////////// // Author: Jia Wu // Version: 0.1 // Date: Nov 2009 // Description: Principal Component Analysis(PCA) // // Copyright (C) 2009 OpenPR // All rights reserved. // // Redistribution and use in source and binary forms, with or without ...
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clc; s =%s; printf("Break in and Break away points satisy the relation:\n"); printf("sum(1/(real(s)+Zi)= sum(1/(real(s)+Pi)"); G = syslin('c',1/(s-3)+1/(s-5)-1/(s+2)-1/(s+1)); disp(G);x =roots(numer(G)); disp(x(2),"break-away point =",x(1),"break-in point =");
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//Chapter 4 Solutions Nonelectrolytes clc; clear; //Initialisation of Variables m= 164.2 //gms M= 60 //gms V= 0.8 //lit d= 1.026 //g/cc mw= 18.02 //gms //CALCULATIONS M1= m/M n= M1/V G= V*1000*d G1= G-m m1= M1*1000/G1 n1= G1/mw x= M1/(M1+n1) y= 1-x p= x*100 p1= y*100 P2= m*100/G //RESULTS mprintf("Molarity= %.3f M"...
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// Grob's Basic Electronics 11e // Chapter No. 01 // Example No. 1_8 clc; clear; // Calculate the resistance for the following conductance values: (a) 0.05 S (b) 0.1 S // Given data G1 = 0.05; // G1=0.05 Siemins G2 = 0.1; // G1=0.1 Siemins R1 = 1/G1; disp (R1,'The Resistance for Conductance val...
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clear; //clc(); //at point a pe=30; pmax=60; del1=asin(pe/pmax); //by hit and trial methid del2=60.4; p1=pmax*sind(del2); per_load=p1-pe; printf("The maximum permissible sudden increase of load is:%.2f MW",per_load);
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//pagenumber 582 example 7 clear voltag=800;//volt q=1.6*10^-19;//coulomb m=9.11*10^-31;//kilogram vox=sqrt(2*q*voltag/m); disp("max velocity "+string((vox))+"metre per second");
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empty_assoc(S), step(int, config([push(5)], [], S), NextConfig) :: NextConfig = config([], [5], S). empty_assoc(S), step(int, config([add], [5, 7], S), NextConfig) :: NextConfig = config([], [12], S). empty_assoc(S), step(int, config([sub], [5, 7], S), NextConfig) :: NextConfig = config([], [-2], S). empty_assoc(...
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//Example 4.17 //Program to find the IDFT of the Sequence using DIF Algorithm. //X[k]= [4,1-j2.414,0,1-j0.414,0,1+j0.414,0,1+j2.414] clear; clc ; close ; j=sqrt(-1); X= [4,1-j*2.414,0,1-j*0.414,0,1+j*0.414,0,1+j*2.414]; //Inverse FFT Computation x = fft (X , 1); disp(x,'x(n) = ');
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function [stk,txt,top]=sci_pow2() // Copyright INRIA txt=[] if lhs==1 then s1=stk(top)(1) if stk(top)(2)=='2'|stk(top)(2)=='3'|part(stk(top)(1),1)=='-' then s1='('+s1+')', end stk=list('2.^'+s1,'2',stk(top)(3),stk(top)(4),'1') else f=stk(top)(2);e=stk(top-1)(2);s1=stk(top-1)(1) if f=='2'|f=='3' then st...
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//Example 11.12.c // series equivalent arrangement of resistance and reactance clc; clear; close; V=200;// in volts L=0.04;// in henry C=100;//in micro fards f=50;// hertz Xl=2*%pi*f*L;//inductive reactance in ohms Xc=(1/(2*%pi*f*C*10^-6));//CAPACITIVE REACTANCE IN OHMS Z1=10;//ohms R1=10;// in ohms X1=0;// in ohms R2=...
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//Example 18.8 //ADI Method //Page no. 642 clc;clear;close; for i=1:4 for j=1:5 P(i,j)=20 end end r=1;k=0; for i=1:6 v1(i)=20 u1(i)=20 end P1=[25,30,35,50,60;35,0,0,0,70;45,0,0,0,80;60,70,80,100,90] for i=1:4 printf('\n') for j=1:5 printf('%i\t',P(i,j)) e...
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//Example 3.16 clear; clc; H0=2; f0=10*10^3; Q=4; nmin=4*(Q^2)*(1+H0); n=nmin+8;//Assuming n=nmin+8 C2=1*10^(-9);//Assuming C2 C1=C2*n; R3num1=nmin/n; R3num2=(1-R3num1)^(1/2); R3num=1+R3num2; R3den=2*2*%pi*f0*Q*C2; R3=R3num/R3den; R1=R3/H0; R2=1/(((2*%pi*f0)^2)*R3*C1*C2);...
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clc // Given that k = 81 // relative permittivity of water c = 3e8 // speed of light in meter/sec // Sample Problem 32 on page no. 10.49 printf("\n # PROBLEM 32 # \n") printf(" Standard formula used \n") printf(" mu_ = ( mu*epsilon /(mu_0/*psilon_0))^1/2 \n \n" ) mu = sqrt(k) v = c / mu printf(" Refractive index of ...
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a a t i s h আ ত ী শ a b a n i k u m a r অ ব ন ী ক ু ম া র a b d u l r a h i m আ ব দ ু ল র হ ি ম a b h a আ ভ া a b h i r u p অ ভ ি র ূ প a b i n g t o n আ ব ি ং ট ন a b u l h o s e n আ ব ু ল হ ো স ে ন a b u n d a n t আ ব ু ন ড া ন ্ ট a c h a l d a অ চ ল দ া a c k l a n d আ ক ল ্ য া ন ্ ড a c t i n i u m অ ্ য া ক ট ি ...
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//Exa 11.1 clc; clear; close; disp("Few steps are as follows : "); disp("Step 1 : The estimated future requirementt per year in terms of todays rupees from his age 61 through 70 is Rs. 24000."); disp("Step 2 : The formula which is given below is used to get future equivalent of Rs. 24000 with the inflation of 9% ...
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2017-05-25T21:09:20
2017-05-25T21:09:19
null
UTF-8
Scilab
false
false
386
sce
18_10.sce
T1 = 278; P21 = 2.5; // P2/P1 cp = 1.005; ns = 0.84; V2 = 120; T2s = T1*(P21)^((g-1)/g); T2 = T1 + (T2s-T1)/ns; mg = 0.04*(13+1); P = mg*cp*(T2-T1); T02 = T2 + V2^2/(2*cp*1000); P1 = 0.6; P2 = P21*0.6; P02 = P2*(T02/T2)^(g/(g-1)); disp("kW",P,"Power required to drive the compressor is") disp("K",T02,"Stagnat...