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function [x,y,typ] = BRO_Controller(job,arg1,arg2) x=[];y=[];typ=[]; select job case 'plot' then exprs=arg1.graphics.exprs; standard_draw(arg1) case 'getinputs' then [x,y,typ]=standard_inputs(arg1) case 'getoutputs' then [x,y,typ]=standard_outputs(arg1) case 'get...
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//================================== // Bathymetry map for Exercise 22 //================================== f = gcf(); f.pixmap='on'; // reverse grayscale map map = 1-graycolormap(64); f.color_map = map; f.figure_size = [1000,500]; // set size of graphic window // read bathymetry data h1=read("topo.d...
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//Example 6.1, Page 208 clc m=4*10^-14//in kg v=10^-2//in m/s KE=(0.5*m*v^2) h=10^-34 printf("\n Kinetic energy(Vo-E) at %e Joule",KE) delta_x=(h)/sqrt(2*m*KE) printf("\n Value of penetration distance is %e m ",delta_x)
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//===================================================================================== //Chapter 14 example 1 clc; clear all; //variable declaration VREF =10; //reference voltage in V //calculations W1 = VREF/2; //the second MSB weight in V W2 = VREF/4; //the third MSB weig...
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clc //Example 5.1 //Calculate the increase in temperature due to falling water of waterfall g=9.81;//m/s^2 acc. due to gravity dz=100;//m Height of waterfall du=g*dz;//J/kg Change in internal energy Cv=4184;//J/kg/K; dT=du/Cv//K Change in temperature printf("Change in temperature is %f K or degree centigrade",d...
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//Chapter 2: Antenna Basics //Example 2-3.2 clc; //Variable Initialization e_half_power = 1/sqrt(2) //E(theta) at half power(unitless) e_null = 0 //E(theta) = 0 at null points (unitless) theta_1 = 0 //theta' (degrees) theta = 1 //theta (degrees) //Calculation for x=0:2 //loop untill theta = i th...
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// Exa 3.18 clc; clear; close; // Given data R_f=10;// in k ohm R1=1;// in k ohm V_d= 5;// in mV v_cm= 2;// in mV A_d= -R_f/R1; Vout= A_d*V_d;// in mV disp(abs(Vout),"Output voltage in mV : ") CMRR_dB= 90;// in dB CMRR= 10^(CMRR_dB/20); A_cm= abs(A_d)/CMRR Mag= A_cm*v_cm;// magnitude of the induced 60 Hz...
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q=poly([0 10 1],'s','coeff'); G=k/q H=1 T=G/(1+G*H) zeta=0.5 k=100/(4*zeta^2) disp(k," k = ") omegaN=sqrt(k) disp(omegaN,"omegaN = ") Ts=4/(zeta*omegaN) disp(Ts," Ts = ") omegaD=omegaN*(sqrt(1-zeta^2)) Tp=%pi/omegaD disp(Tp," Tp = ") disp(%e^(-%pi*zeta/sqrt(1-zeta^2))," Mp = ")
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// Exa 3.33 clc; clear; close; // Given data V_T= 0.025;// in V // Part(a) disp("Part (a)") V_BE= 690;// in mV V_BE=V_BE*10^-3;// in V I_C= 1;// in mA I_B= 50;// in µA I_C=I_C*10^-3;// in A I_B=I_B*10^-6;// in A bita= I_C/I_B; alpha= bita/(1+bita); I_E= I_C/alpha;// in A // I_C= I_S*%e^(V_BE/V_T) I_S=...
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function [kr, R0]=poly2rc(a, efinal) //poly2rc function convert prediction polynomial to reflection coefficients. // Calling Sequence // kr = poly2rc(a) // [kr, R0] = rc2poly(a, efinal) // Parameters // a: prediction polynomial. // efinal: final prediction error. // kr: Return refelection coefficient. // R0: Re...
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//Exa 12 clc; clear; close; // given data : ST=10;//in hours AT=8;//in hours SR=9;//in Rs/Hour AR=10;//in Rs/Hour //Labour Cost variance LCV=(ST*SR)-(AT*AR) //Labour Efficiency variance LEV=SR*(ST-AT);// in Rs //Labour Rate variance LRV=AT*(SR-AR);// in Rs disp(LCV,"Labour Cost variance : ") disp(LEV,"L...
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// example 6.17 // error estimate in evaluation of the integral // page 236 clc;clear;close; deff('z=f(a,b)','z=cos(a)+4*cos((a+b)/2)+cos(b)') a=0,b=%pi/2,c=%pi/4; I(1)=(f(a,b)*((b-a)/2)/3) I(2)=(f(a,c)*((c-a)/2)/3) I(3)=(f(c,b)*((b-c)/2)/3) Area=I(2)+I(3); Error_estimate=((I(1)-I(2)-I(3))/15); Actual_area=i...
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clc clear printf("Example 3.3 | Page number 74 \n\n"); //find temperature in °C T = 250 //K t = T - 273.15 //°C printf("Temperature in °C = %.2f °C",t)
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// Exa 11.9 clc; clear all; // Given data // Refering Fig. 11.26(page no.328) - an AC bridge(SCHERING'S BRIDGE) R1= 1; // k Ohms C1=0.5; // micro farads R2=2; // k Ohms C3=0.5; // micro farads f= 1000; // Hz // Solution // Using Equations 11.20(a) and 11.20(b) given on page no. 328 we get value Rx...
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//Given that Mc = 75 //in g To = 312 //in degree C Mw = 220 //in g Cb = 45 //in cal/K Ti = 12 //in degree C Sc = 0.0923 //in cal/g.K Cb = 45 //in cal/K Sw = 1 //in cal/g.K //Sample Problem 19-4 printf("**Sample Problem 19-4**\n") Tf = (Sc*Mc*To + Cb*Ti + Sw*Mw*Ti)/(Sw*Mw + Cb + Sc*Mc) printf("The final tempratu...
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//utile pour le calcul de e (troisieme point) function K=rotation(theta) K=[cos(theta), -sin(theta) sin(theta), cos(theta)]; endfunction function koch(n,a,b) if n<1 plot([a(1),b(1)],[a(2),b(2)]); else //calcul des nouveaux points c=a+(b-a)/3; d=b-(b-a)/3; e=c+...
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function [surface_central_normalise,surface_ouest_normalise,surface_est_normalise,surface_sud_normalise,surface_nord_normalise]=cavite(Image) A1=Image; A2=Image; A3=Image; A4=Image; [row, column] = size(Image); for i=1:row for j=1:column if A1(i,j) == %T then A1(i,1:j) = %T; end ...
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clc; // data taken from Ex A.7, fig A.16 N1=200; // number of turns in coil 1 f1=53.97*10^-3; // flux in outer limb containing coil 1 m1=5000; // mmf for coil 1 I1=m1/N1; // current in coil 1 N2=100; // number of turns in coil 2 f2=43.97*10^-3; // flux in outer limb containing coil 2 m2=1102; // mmf for coil 2 ...
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//Book Name:Fundamentals of Electrical Engineering //Author:Rajendra Prasad //Publisher: PHI Learning Private Limited //Edition:Third ,2014 //Ex9_2.sce clc; clear; V=3.6e3; phase=3 f=50; N=500; m=3; c=10; printf("\n (a)") p=(120*f)/N; printf("\n The number of poles=%d",p) printf("\n (b)") slo...
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function []=chaina(yt) th=xget("thickness"); [n1,n2]=size(yt); x=ones(n1/2,n2); y=ones(n1/2,n2); x(1,:)=2*r(1)*cos(yt(1,:)); y(1,:)=2*r(1)*sin(yt(1,:)); for i=2:n1/2, x(i,:)=x(i-1,:)+2*r(i)*cos(yt(i,:)); y(i,:)=y(i-1,:)+2*r(i)*sin(yt(i,:)); end x=[0*ones(1,n2);x]; y=[0*ones(1,n2);y]; rr=r(1)/(n1+1); rect=2*[...
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// Variable Declaration r = 1.5 //Radius of each conductor(cm) D_a1a2 = 0.3 //Distance b/w conductor a1 & a2(m) D_a2a1 = 0.3 //Distance b/w conductor a2 & a1(m) D_a1b1 = 15.3 //Distance b/w conductor a1 & b1(m) D_a1b2 = 15.6 //Distance b/w conductor a1 & b2(m) D_a2b1 = 15.0 //Distance b/w conductor a2 & ...
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//Example 4.3 F_floor=150;//Backward force exerted (N) f=24;//Net opposing force (N) m=65+12+7;//Total mass of System 1, mass of professor+mass of cart+mass of equipment, (kg) F_net=F_floor-f;//Net force (N) a=F_net/m;//Acceleration (m/s^2) printf('Acceleration = %0.1f m/s^2',a) //Openstax - College Physics //D...
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clear //Given a=45 //Degree b=60 //Degree //Calculation // A=tan(a*3.14/180.0)/(cos(b*3.14/180.0)) a=atan(A)*180/3.14 //Result printf("\n Apparant dip is %0.1f Degree",a)
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// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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Name=Counter-Striker Test PlayerCharacters=Counter-Striker BotCharacters=Counter-Striker Bot.bot IsChallenge=true Timelimit=60.0 PlayerProfile=Counter-Striker AddedBots=Counter-Striker Bot.bot;Counter-Striker Bot.bot PlayerMaxLives=0 BotMaxLives=0;0 PlayerTeam=2 BotTeams=1;1 MapName=dust2-A.map MapScale=4.0...
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clear clc //to find time required for room temperature to be 21 degree celsius //Given: //room temperature T = 0//in degree celsius //length of room l = 6//in meters //breadth of room b = 4//in meters //height of room h = 3//in meters //power of heater p = 2//in KW //final air temperature T1 = 21//in d...
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//Chapter 2 //Example 2_12 //Page 25 clear;clc; md=10; h=20; n_overall=0.8; lf=0.4; //river discharge ugpw=md*lf*24*7*1e3; printf("(i) Units generated per week =%.1f kWh \n\n", ugpw); app=1e3*9.81*h*n_overall/1000; upw=app*24*7; q=ugpw/upw; printf("\t River dishcharge required = %.2f m^3/sec", q); //load factor fl...
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//example 14.5 PG-14.38 clc clear printf(" Given=> ABCD+ABD = ABD(C+1)..... Distributive property\n\n") printf(" ABCD+ABD = ABD.1........ Since A+1=1\n\n") printf(" ABCD+ABD = ABD ......... Since A.1=A")
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// A Textbook of Fluid Mecahnics and Hydraulic Machines - By R K Bansal // Chapter 3-Hydrostatic Forces on surfaces // Problem 3.6 //Data given in the Problem b=4 h=4 A=b*h/2 SG=0.9 g=9.81 dens=SG*1000 //Calculations H=1/3*h //Distance of CG from the free surface of the oil F=dens*g*A*H ,printf("Th...
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clc A=[-3 6 9;1/6 1/2 1/3] disp('first row of A displays the value of x') disp('the second row of x displays the probability of corresponding to x') disp('E(x)=') c=A(1,1)*A(2,1)+A(1,2)*A(2,2)+A(1,3)*A(2,3) disp('E(x)^2=') b=A(1,1)^2*A(2,1)+A(1,2)^2*A(2,2)+A(1,3)^2*A(2,3) disp('E(2*x+1)^2=E(4*x^2+4*x+1)') 4*b+4*c+1
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Name=Shifty's QC warmup mode PlayerCharacters=my QC Quaker BotCharacters=Random Quaker Bot.rot IsChallenge=true Timelimit=180.0 PlayerProfile=my QC Quaker AddedBots=Random Quaker Bot.rot PlayerMaxLives=3 BotMaxLives=0 PlayerTeam=0 BotTeams=0 MapName=kovaim1.map MapScale=4.5 BlockProjectilePredictors=true ...
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//Example 3.13(a) clear; clc; C=10*10^(-9);//Assumed C1=C; C2=C; f0=1*10^3; BW=100; R=(2^(1/2))/(2*%pi*f0*C); R1=R; R2=R; R3=R; Q=f0/BW; K=4-((2^(1/2))/Q); RA=10*10^3; RB=(K-1)*RA; RG=K/(4-K); printf("Designed KRC Second Order Band Pass filter"); printf("\nR1=R2=R3=...
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//scilab 5.4.1 //Windows 7 operating system //chapter 19 VLSI Technology and Circuits clc clear ID=50*10^-6//ID=drain current in amperes k=25*10^-6//k=ue/D in A/V^2 VDEP=3 l=(k*((-VDEP)^2))/(2*ID)//l=(L/W)=aspect ratio of the pull-up disp(l,"Pull-up (L/W)=") VGS=5//VGS=gate-to-source voltage VTH=1//VTH=thres...
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function[f] = f1(x) f = 2*x*sin(x)-1 endfunction count = 1; for i=-2:50 //printf("%f = %f\n", i, f1(i)); if f1(i)<0 && f1(i+1)>0 then vaux(count)=i; count = count + 1; vaux(count)=i+1; count = count + 1; else if f1(i)>0 && f1(i+1)<0 then ...
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clear; clc; f1=12000;f2=16000;Rk=600; C1=(f2-f1)/(4*%pi*Rk*f1*f2); L1=Rk/(%pi*(f2-f1)); C2=1/(%pi*Rk*(f2-f1)); L2=Rk*(f2-f1)/(4*%pi*f1*f2); printf("The elements of the prototype band pass filter are:\n"); printf(" L1 = %f mH\n",round(L1*(10^5))/100); printf(" C1 = %f picofarads\n",round(C1*(10^12))); printf...
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// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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clc; //Example 8.5 //page no 81 fig 8.3 printf(" Example 8.5 page no 81 fig 8.3\n\n\n"); //a cylindrical tank filled with water //applying bernoulli equation z1=9//elevation head at section 1 h2=1//height at section 2 D1=3//diameter of cylindrical tank D2=.3//diameter of outlet hole of tank g=9.807//gravitat...
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# ATWM1_MRI_Localizer scenario = "ATWM1_Localizer_MRI"; scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen #scenario_type = trials; scan_period = 2000; # TR pulses_per_scan = 1; pulse_code = 1; #pulse_width=6; default_monitor_sounds = false; active_buttons ...
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function W1 = point_distance_vector(A, X, r0) [xrows,xcols] = size(X); [arows,acols] = size(A); W1 = zeros(arows, xrows); for i = 1:arows for j = 1:xrows W1(i,j) = radial_distance(A(i,:), X(j,:)); end end W1 = multiquadratic(W1, r0); endfunction
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errcatch(-1,"stop");mode(2);//Initialisation of variables m=9e-31//mass of electron e=1.6e-19//charge of electron V=5000//volts v=sqrt(2*V*e/m) printf('maximum speed of electron is %e metre per second \n',v) exit();
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clc // Given that p1 = 1.013 // Inlet pressure in bar r = 1.5 // Pressure ratio Vs = 0.03 // Induce volume of air in m^3/rev gama = 1.4 printf("\n Example 19.14\n") p2 = p1*r W = (p2-p1)*Vs*100 pi = (p1+p2)/2 A_A = (gama/(gama-1))*(p1*Vs)*((pi/p1)^((gama-1)/gama)-1)*100 Vb = Vs *((p1/pi)^(1/gama)) A_B = (p...
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function paraquedas() // skydiving p=800 // Peso em Newton g=9.8 // Aceleração da gravidade m/s2 k=13 // Coeficiente de atrito viscoso dt=0.1 // intervalo de tempo em segundos m=p/g // massa v(1)=0 // Condições iniciais t(1)=0 // T inicial h(1)=1400 // Altura inicial em metros ...
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// Scilab Code Ex3a.a.7:Page-136 (2008) clc; clear; phi1 = 0; // Phase of the first SHM, degree phi2 = 45; // Phase of the second SHM, degree a1 = 0.005; // Amplitude of the first SHM, m a2 = 0.002; // Amplitude of the second SHM, m A = sqrt((a1 + a2*cosd(phi2))^2 + (a2*sind(phi2))^2); // Resultant...
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//A Textbook of Chemical Engineering Thermodynamics //Chapter 6 //Thermodynamic Properties of Pure Fluids //Example 26 clear; clc; //Given: T = 623; //temperature in K //Data from steam tables: H = 3159; //enthalpy at 1000 kPa and 623 K (kJ/kg) S = 7.3; //entropy at 1000 kPa and 623 K (kJ/kg K) Ho ...
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//Multiplication Image function image_out=multiplicationImage(img1,img2) img1SizeX = size(img1,1); img1SizeY = size(img1,2); img2SizeX = size(img2,1); img2SizeY = size(img2,2); image_out = zeros(img1SizeX,img1SizeY); //On crée une matrice nulle de même dimension que la première image. ...
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//Caption:transfer_function // example 12.1 //page 515 // we are solving this problem from signal flow graph approach syms G H; // forward path denoted by P1,P2 and so on and loop by L1,L2 and so on //path factor by D1,D2 and so on and graph determinant by D P1=1*G*1 P2=1; L1=-G; L2=-G*H; L3=G*H; D1=1; D2...
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function h = hilbert(n) h = zeros(n, n) for i = 1:n for j = 1:n h(i, j) = 1/(i + j - 1) end end endfunction
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clear; clc; // Illustration 3.1 // Page: 53 printf('Illustration 3.1 - Page: 53\n\n'); // solution //****Data*****// // a = CO2 b = H2O Ca0 = 0;//[kmol/cubic m] Cai = 0.0336;//[kmol/cubic m] Dab = 1.96*10^(-9);// [square m/s] //*******// density = 998;// [kg/cubic m] viscosity = 8.94*10^(-4);//[k...
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// example 4-7 in page 107 clc; // Given data Iav=1e-3;//for, FSD the average meter current is 1 mA Rm=1.2e+3;// coil resistance 1.2 K-ohm E=100e-3;// ac input rms voltage=100 mV //calculations Ip=(2/0.637)*Iav;// peak current for half wave rectifier Ep=E/0.707;// input peak voltage R3=Ep/Ip; printf("R3=%d ohm\n\n",R3...
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//To find pitch diameter and the circular pitch clc //given T=48//teeth pd=4//diametral pitch D=T/pd//pitch diameter p=%pi/pd//the circular pitch printf("\nThe pitch diameter = %.f in\nThe circular pitch = %.4f in\n",D,p)
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//Example 3.13 clear; clc; //Given delHfNaOH = -470.7;//heat of formation in kJ of NaOH delHfOH = -228.8;//heat of formation of OH- ions in kJ //To determine the heat of formation of sodium ions delHNa = delHfNaOH-delHfOH;//heat of formation of sodium ions in kJ mprintf('heat of formation of sodium ions =...
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clc;clear; //Example 1.10 //constants used g=9.81;//acceleration due to gravity in m/s^2; //given values p=1040; h1=0.8; H=4; x0=0; x1=4;// x0 & x1 are limits of integration //calculation P1=p*g*h1/1000;//standard pressure determination formula P2=integrate('p*g*(sqrt(1+(tan(3.14*z/4/H)^2)))','z',x0,...
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/* Objetivo: Avaliar qual será o melhor plano de financiamento analisando a taxa de juros de cada um Autor: Pierre Vieira */ exec('juros_secante.sci'); a = 0.05; b = 1; Toler = 0.01; IterMax = 100; printf("\n==================================================== PLANO 1 ===========================================...
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// Exa 1.5 clc; clear; close; // Given data format('v',13) e= 1.6*10^-19;// in C ni= 1.5*10^16; miu_n= 0.13; miu_p= 0.05; atomicDensity= 5*10^28;//atomic density of Si in /m^3 C= 1/(2*10^8);// concentration N_D= atomicDensity*C;// in /m^3 n=N_D; p= ni^2/N_D;// in /m^3 sigma= e*(n*miu_n+p*miu_p);// in s...
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# @Harness: probes # @Result: # @Program: array.asm # @Purpose: Tests whether probe inserted from within watch (on same instruction) works correctly watch A { insert B 0x08; | | | } probe B { | } main { insert A 0x10e; } result { 102 A.beforeRead; 102 A.afterRead; 109 B.before; 111 B.after; }
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//Variable Declaration CNR=87.3 //Downlink Carrier to noise ratio(dBHz) BER=10**-5 //Bit Error Rate Required R=0.2 //Roll off factor EbN0R=9.5 //Eb/N0 ratio(dB) //Calculation Rb=CNR-EbN0R //Maximum Transmission Rate(dBb/s) Rb1=10**(Rb/10) //Maximum Transmission Rate(b/s) BIF=Rb1*1.2*10**-6/2 //IF Bandwith r...
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clear; clc; printf("\t Example 2.18\n"); pa1=0.418*10^5; //partial pressure initially pa2=0; //partial pressure of pure air r=10/2; //radius of tank in which benzene is stored T=(350); //temperature in kelvin pt=1*1.013*10^5; ...
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## Broadlink Climate HASS Module ## Original forum thread: https://github.com/vpnmaster/homeassistant-custom-components ## Official repo: https://community.home-assistant.io/t/broadlink-ir-climate-component/27406 ################################################## ## Component ##########################################...
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function [] = kiks_setdiod(id,dnr,status) // Display mode mode(0); // Display warning for floating point exception ieee(1); // ----------------------------------------------------- // (c) 2000-2004 Theodor Storm <theodor@tstorm.se> // http://www.tstorm.se // ----------------------------------------------------- g...
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// ELECTRIC POWER TRANSMISSION SYSTEM ENGINEERING ANALYSIS AND DESIGN // TURAN GONEN // CRC PRESS // SECOND EDITION // CHAPTER : 7 : TRANSIENT OVERVOLTAGES AND INSULATION COORDINATION // EXAMPLE : 7.6 : clear ; clc ; close ; // Clear the work space and console // GIVEN DATA v = 1000 ; // ideal dc voltage ...
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//Chapter 6, Example 6.6 clc //Initialisation C=3*10**-8 //capacitance in farad pi=3.14 //pi f=10**3 //frequency in hertz V=10 //voltage R=10**4 //resistance in ohm i=5 ...
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// Chapter8 // Page.No-335, Figure.No-8.14(a) // Example_8_4 // Output voltage // Given clear;clc; Vo=2.8; // At Finmax of 10kHz Vo1=Vo/10; // Output voltage at Fin=1kHz printf("\n Output voltage is = %.2f V \n",Vo1) // Result
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//Example 4.8 clc; Ifsd=50*10^-6; //Full Scale Current S=1/Ifsd; //Sensitivity Rm=1000; //Internal resistance of movement disp(S,'Sensitivity of 50 uA meter') //Case I: For Range 0-5 V V=5; //Full range voltage of the instrument Rs=S*V-Rm; //Multiplier resistence disp(Rs,'V...
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// Example 4.2 clc; clear; close; // Given data alpha= 0.97; I_E=1;// in mA // Formula alpha = I_C/I_E; I_C= alpha*I_E;// in mA // Formula I_E= I_B+I_C I_B= I_E-I_C;// in mA disp(I_B,"The base current in mA is : ")
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printf( "Hello,Tolik" );
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// Example 10.1 format('v',6) clc; clear; close; // given data V_CEQ= 7.5;// in V R_L= 50;// in Ω I_Csat= V_CEQ/R_L;// in A I_CQ= 0.01*I_Csat;// in A P_DQ= V_CEQ*I_CQ;// in W PP= 2*V_CEQ;// in V P_Dmax= PP^2/(40*R_L);// in W P_Lmax= PP^2/(8*R_L);// in W // The value of P_DQ P_DQ= P_DQ*10^3;// in mW // ...
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clear; close; clc; T0=4; t=-7.99:0.01:8; t_temp=0.01:0.01:T0; s=length(t)/length(t_temp); dx=[]; x=[]; for i=1:s x=[x 0.5*t_temp($:-1:1)]; end for i=1:length(t) if modulo(t(i),T0)==0 then dx(i)=1; else dx(i)=0; end end dx1=-1/T0; figure a=gca(); plot2d(t,x,6) poly...
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///Chapter No 11 Steam Boilers ////Example 11.8 Page No 236 ///Find Equivalent mass evaporation //Input data clc; clear; ms=6000; //Steam generated in Kg/h mf=700; //Coal burnt in Kg/h CV=31500; //Cv of coal in KJ/Kg x=0.92; ...
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//Example 4 //equation of wave propogation clc; clear; close; amp=0.02;//m fr=110;//Hz v=330;//m/s w=2*%pi*fr;//s^-1 k=w/v;//constant //y=a*sin(w*t-k*x);//refrence equation disp("equation of wave is "+string(amp)+"*sin("+string(w)+"*t-"+string(k)+"*x)")
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function [res]=valueByRequest(handle, chanelName, t,u1) SOCKET_write(handle, chanelName); res= SOCKET_read(handle); res=strtod(res(1)); endfunction
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// This demo show how to use MicroDAQ macros to access // MicroDAQ peripherals. This example uses PID algorithm // to control DC motor. The DC motor is driven by H-bridge // which is controlled by PWM and DIO. // // MicroDAQ DIO15, DIO16 are used to control H-bridge // enable and direction pins. MicroDAQ PWM is us...
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//Example 7.11 //Poles and Zeros of Tape Drive System. //Also, Transform the system into modal form xdel(winsid())//close all graphics Windows clear; clc; //------------------------------------------------------------------ // State space matrices of Tape Drive System F=[0 2 0 0 0; -0.1 -0.35 0.1 0.1 0.75; 0 0 0 2 0;...
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;+ ; 06-Jun-1989 ml Created this. ; ; 19-Jul-1989 ml Added in check for existence of SCSI on system. ; If SCSI doesn't exist, don't look for SCSI drives. ; This enable a TT bootable cartridge bootable on an ; ST also. ; ; Added in check for existence of cache on CPU. ; If cache doesn't exist, don't need to fl...
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//Chapter 2,Ex2.59,Pg2.75 clc; disp("Refer to the diagram shown in the figure") A=[70 -20;-20 20] B=[40;0] I=A\B printf("\n I1=%.0f A \n",I(1)) printf("\n I2 =%.1f A \n",I(2)) printf("\n In = %.1f A \n",I(2)) //Calculation of Rn Rn=(50*20/(50+20)) //Resistance of 40 ohms gets shorted because it is connected a...
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clc //initialisation of variables v=105// T1=210//F T2=100//F //CALCULATIONS T=T2-T1//F //RESULTS printf('The high value of the viscosity in the temperature is=% f F',T)
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clc; funcprot(0); //Example 8.9 Polar Curve // Initialisation of variables Cl_clark = 0.43; //Values from fig 8.18 Cd_clark = 0.020; //Values from fig 8.18 Cl_USA = 0.55; //Values from fig 8.19 Cd_USA = 0.03; //Values from fig 8.19 // Calculations LbyD_clark = Cl_clark/Cd_clark; ...
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splitTEr cPT {} FIlTEr FW { } fIlter Xv {nOt Dc oR mt or Ntp NOT Nn Or not qeX or Mm Or p oR NoT r OR Not s or not d } X -> t -> i gRouper KO {aGGrEGaTe CouNt(dJe.k) aS L } UNGrOuPeR c { } grouPFilteR gm {NoT bitor (::c:fb:f:d:d:B0aa:0, ) o << ::eD3:c/2 Or 231.5.8.53 >> 50.235.227.155 oR NoT Z >> XtOr ( ) ...
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//Chapter 6 //Example 6_5 //Page 111 clear;clc; f=50; v=400; op=74.6; pf1=0.75; n=0.93; pf2=0.95; nc=4; vc=100; p=op/n; phi1=acos(pf1); phi2=acos(pf2); lead=p*(tan(phi1)-tan(phi2)); lead_each=lead/3; icp=2*%pi*f*v; kvar=v*icp/1000; c=lead_each/kvar; c_each=c*nc; printf("Leading kVAR taken by the condensor bank = %....
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//Checking if error message pops up when wrong number of arguments are entered inImage = imread("chessboard3.png"); [found coordinates ] = findChessboardCorners(inImage,12,"CV_CALIB_CB_ADAPTIVE_THRESH"); //output-> //!--error 77 //findChessboardCorners: Wrong number of input argument(s): 4 expected.
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z1=4+%i*2; z2=-%i*3; z=z1*z2/(z1+z2); disp("the total impedance (in Ω) is"); disp(z);
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clc //Cada esfera terá dois arrays com as coordenadas x e y de suas posições. E vão ser separadas pela cor. x_azul = [708 574 571 570] y_azul = [528 520 520 519] x_vermelha = [603 423 417 396] y_vermelha = [481 394 394 385] x_verde = [636 1225 1242 1273] y_verde = [468 420 426 438] tempo = [2.008 2.976 3.013 3.095...
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; rred5.tst ; ; Copyright (c) 1999-2018, Arm Limited. ; SPDX-License-Identifier: MIT func=rred op1=6e8a55a8.e86a3a97 result=3cc88942.65ed745f.705 res2=00000001 errno=0 func=rred op1=6e8d9233.0c3288a5 result=bc97e750.acd8c3df.9e9 res2=00000003 errno=0 func=rred op1=6e95c615.04acdcba result=3c93315f.f3cbf3e7.5a8 res2=00...
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clc bs = 100 // basic size in mm s1 = 120// diameter of step1 in mm s2 = 80 // diameter of step2 in mm d = (s1*s2)^(1/2) // mm d = ceil(d) i = (0.45*(d)^(1/3)+0.001*d)/10^3 // mm t1 = 16*i // tolerence for hole in mm t2 = 25*i // tolerence for shaft in mm G = (2.5*(d)^0.34)/10^3 // fundamental deviation for ho...
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//Exa 3.6 clc; clear; close; format('v',6); //Given Data : T1=23+273;//K COP_HP=2.5; HeatLost=60000;//KJ/hr HeatGenerated=4000;//KJ/hr Q1=HeatLost-HeatGenerated;//KJ/hr W=Q1/COP_HP;//KJ/hr W=W/3600;//KJ/s or KW disp(W,"Power input in KW : ");
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function[F]=aliasfrequency(f,s,s1) if (s>2*f) then disp("alias has not occured") else disp("alias has occured") end F=f/s; for i=1:100 if (abs(F)>0.5) F=F-i; end end fa=F*s1; disp(fa,"frequency of reconstructed signal is") endfunction
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//CHAPTER 7- SINGLE PHASE TRANSFORMER //Example 32 disp("CHAPTER 7"); disp("EXAMPLE 32"); //VARIABLE INITIALIZATION va=50000; v1=4400; //primary voltage in Volts v2=220; //secondary voltage in Volts f=50; R1=3.45; X1=5.2; R2=0.0009; X2=0.015; //SOLUTION // ...
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warning('off'); //Input numbers in values.dat file fp=mopen('values.dat','w'); printf("Enter Numbers:") for k=1:5 n=scanf("%f"); mfprintf(fp,'%f\n',n ); end mclose(fp); //Calculate the average of numbers of values.dat file fpin=mopen('values.dat','r'); if(fp>0) , sum1=0;count=0; ...
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//To find axial force and face width clc //Given: P=45*1000 //W N=1000 //rpm alpha=12.5 //degrees D=500/1000, R=D/2 //m mu=0.2 pn=0.1 //N/mm^2 //Solution: //Calculating the angular speed of the shaft omega=2*%pi*N/60 //rad/s //Calculating the torque developed by the clutch T=P/omega //N-m //Calculating th...
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function [A, B] = pgm10() i=1; A(1) = 1; B(i) = 1.25; while(A(i) < B(i)) A(i+1) = 1.06 * A(i); B(i+1) = 1.02 * B(i); i = i + 1; end endfunction
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//Chapter 7, Problem 3 clc; H=8000; //Magnetic field strength d=30*10^-2; //Diameter of coil l=%pi*d; //Length N=750; //No of turns I=(H*l)/N; //Calculating current in the coil printf("Curren...
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function [R,S] = dio_s(B,A,Ac,I) // Löser für die Diophantische Gleichung // Löst: R*A+B*S=Ac (I=0) oder // R*A*s+B*S=Ac (I=1) // // Ohne Integrator I=0; degree Acl: 2*degree A -1 // Mit Integrator I=1; degree Acl: 2*degree A // Der resultierende Regler hat gleichen Zähler und Nennergrad!!! R=[]; S=[]; ieee...
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//EX2_3 Simplify Z = (AB + C)(B'D + C'E') + (AB + C)' //clears the screen clc //clears already existing variables clear disp('Z = (AB + C)(B''D + C''E'') + (AB + C)''') disp('Let X = (AB + C)'' X'' = AB + C') disp('and Y = B''D + C''E''') disp('Z = X''Y + X') //By the elimination theorem i.e. X + X'Y ...
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clear; clc; n=3; a=-0.5; b=2*%pi; X=[0;%pi/4;%pi/2;3/2*%pi]; x_bar=9/10*%pi; r=2; function y=f(X); y=sin(X); endfunction for i=0:n Y(i+1)=f(X(i+1)); end function y=phi(j,x,X,n); for i=0:(j-1) L(i+1)=x-X(i+1); end; for i=(j+1):n L(i)=x-X(i+1); end; ...
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function[tree1]=binary(tree,x) p=1; while(tree(p)~=-1&tree(p)~=-2) q=p; if(tree(p)>x) p=2*p; else p=2*p+1; end end if(tree(q)>x) if(tree(2*q)==-2) tree(2*q)=x; tree(2*q+1)=-2; else tree(2*q)=x; end else if(tree(2*q+1)==-2) ...