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clc //initialisation of variables W= 800 //N A= 0.4 //cm^2 p= 0.611 //Mpa P1= 0.1 //Mpa T= 0.01 //C vs= 0.0010908 //m^3/kg hs= -333.40 //kJ/kg vf= 0.0010002 //m^3/kg hf= 0 //kJ/kg vg= 206.14 //m^3/kg hg= 2501.4 //kJ/kg //CALCULATIONS P2= P1+(W/A)*10^(4-6) dT= (273.15++T)*(vf-vs)*(P2*10^3-p)/(0-hs) Tmin=...
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//Finding fusing current //Example 2.17(pg. 29) clc clear I2=27.5//current of No.25 wire in Amperes d=1/2//since I1/I2=1/2 I1=I2*(d^(3/2)) printf('Thus fusing current of No.33 wire is %3.3f amperes \n',I1)
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[1,7]/3 * [1,7]/5 = [1/15,14/15,49/15] initial: [1/15,14/15,49/15] / [1/3,7/3], rem1=[1,14,49], div2=[5,35], lenq=2, len1=3, len2=2 expanded: lcm12=245, last1=245, last2=35, rem1=[5,70,245], rden=5, fac1=5 step end: quot=[0,0]/qden=1, rem1=[5,70,245]/rden=5, div2=[5,35], bquot=7, lenq=2, len1=3, len2=2 while en...
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clc; //page 381 //problem 6.6 //Given Bandwidth BW = 4 kHz BW = 4*10^3; //Given data rate is fb = 6 kbps fb = 6*10^3; //The roll off factor alpha is alpha = ((2*BW)/fb) - 1; disp('The roll off factor is '+string(alpha)); //////////////////////////////////////////////////////////////////////////////...
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function [x,ka,kb]=union(a,b) //Copyrigth INRIA // returns the union of unique components of vector a and b [lhs,rhs]=argn() if lhs==1 then [x,k]=unique([a(:);b(:)]) x=x';k=k' else na=size(a,'*') kab=[1:na,na+(1:size(b,'*'))] [x,k]=unique([a(:);b(:)]) x=x' kab=kab(k) ka=kab(kab<na+1) kb=kab(kab>na) ...
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// Find the maximum transconductance // Basic Electronics // By Debashis De // First Edition, 2010 // Dorling Kindersley Pvt. Ltd. India // Example 7-54 in page 358 clear; clc; close; // Given data Idss=1*10^-3; // Drain-source current in mA Vp=-5; // Pinch off voltage in V // Calculation gm=(2*Idss)/-Vp; printf("gm...
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//CHAPTER 2- STEADY-STATE ANALYSIS OF SINGLE-PHASE A.C. CIRCUIT //Example 51 clc; disp("CHAPTER 2"); disp("EXAMPLE 51"); //VARIABLE INITIALIZATION Y1=0.4+(%i*0.6); //admittance of 1st branch in Siemens Y2=0.1+(%i*0.4); //admittance of 2nd branch in Siemens Y3=0.06+(%i*0.23); //...
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//------------------------------------------------------------------------------ //FEDERAL UNIVERSITY OF UBERLANDIA //Discipline: Control II //Project 1: //Botan et al.: "Discrete Time Linear Quadratic Optimal Control for an Electrical Servo Drive System" //Authors: Andrei Nakagawa and Henrique Oyama //Last update: May...
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clc; sA=0.05; //slip //for part a disp('for part a '); //Torque is proportional to s/r2 //As per given conditions sB=a*sA a=4; sB=a*sA; mprintf('The slip is %d times previous slip and \n',a); //for part b disp('for part b '); //I2 is directly proportional to s/r2 //As per given conditions I2B=b*I2A b=s...
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clc // Given that q = 1.6e-19 // charge on a proton in C d = 1e-10 // distance of a point from proton in m e0 = 8.85e-12 // permittivity of space // Sample Problem 20 on page no. 10.44 printf("\n # PROBLEM 20 # \n") E = (1 / (4 * %pi * e0)) * (q / d^2) printf("Standard formula used \n E = (1 / (4 * pi * e0)) * (q / d^...
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//Ex 6.9 clc; clear; close; format('v',6); disp("Part (a)"); L1=25;//micro H L2=10;//micro H Rf=22;//kohm C=0.01;//micro F LT=L1+L2;//micro H fr=1/(2*%pi*sqrt(C*10^-6*LT*10^-6));//Hz fr=fr/1000;//kHz f0=fr;///kHz disp(f0,"Oscillation frequency(kHz)"); Ri=Rf/(L1/L2);//kohm disp(Ri,"Resistance Ri(kohm)");...
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clc; p=3*10^6; // rated power of alternator v=11000; // rated voltage of alternator r=0.4; // per phase effective resistance vl=12370; // line to line voltage at zero leading power factor i=100; // load current at zero power factor pf=0.8; // lagging power factor at which voltage regulation has to be determined...
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syms Kh s=%s; G=syslin('c',10*Kh*(s+0.04)*(s+1)/((s+0.5)*(s^2-(0.4*s)+0.2)*(s+8))); evans(G,3) Kh=kpure(G) K=10*Kh zeta=1/(2)^(1/2); wn=.575; sgrid(zeta,wn) K=-1/real((2*horner(G,[1 %i]*locate(1)))); printf("The zeta=1/(2)^1/2 line intersects the root locus at two points with K1=1.155 and K2=0.79") Kh1=0.156...
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function [r]=%por(l1,l2) //r=%por(l1,l2) <=> r=(l1==l2) l1 polynomial l2 rational //! r=degree(l2(3))==0 if r then r=l2(2)./coeff(l2(3))==l1,end
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clc printf("Example 2.9,Page 2.28\n"); //Given ID=50 //mm; dT=(573-303); printf("Internal diameter,ID=%f mm",ID); r1=ID/2 //mm r1=r1/1000 // metres OD=150 // mm printf("Outer diameter,OD=%f mm",OD); r2=OD/2 // mm r2=75/1000 // m //Thermal conductivity k=17.45 // W/(m.K) //Solution printf("Q/A=dT/(r2-r1)...
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// Function to read in Xgig trace and gathers packet counts // // (c)2009 L. Rayzman // Created : 01/07/2009 // Last Modified: 01/07/2009 - Added Eye Measurement Tool // // // inputfile = emptystr(); // Filename of trace input file matchstr1 = 'COMWAKE'; // Fi...
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clear; clc; S=250; V=3330; r=.25; x=3.5; pf=0.8; i=(S*1000)/(sqrt(3)*V); Il=i; Vp=(V/sqrt(3)); z=complex(r,x); Ia=complex(34.99,-26.24); E=Vp+(Ia*z); Vv=sqrt((real(E)^2)+(imag(E)^2)); reg=((Vv-Vp)/Vp)*100; mprintf("regulation=%f percent",reg);
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//Example 1.4 //Sketch the signal x(t)=Asin(t) clc; A=0.5; t=0:1/100:10 x=A*sin(t); plot(x); //since it is a periodic signal so it is power signal P=(integrate('((0.5)^2)*(sin(t)^2)','t',0,2*%pi))/(2*%pi);
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/////////////////////////////////////////////////////////////////////////////// // Author: Jia Wu // Version: 0.1 // Date: Nov 2009 // Description: Multiple Linear Discriminant Analysis(LDA) // // Copyright (C) 2009 OpenPR // All rights reserved. // // Redistribution and use in source and binary forms, with o...
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// Calculate the resistance and the temperature clc; Rth0=100; ath0=0.00392; dth=65-25; R65=Rth0*[1+ath0*dth]; disp(R65,'resistance at 65 degree C(ohm)=') th={[(150/100)-1]/ath0}+25; disp(th,'Temperature (degree C)')
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count=1; a=150; b=500; c=387; d=415; e=558; f=401; h=394; l=550; g=393; u=367; k=490; j=657; pin1x=0; pin1y=0; m=[]; //avi = moviein((8*pi+pi/2)); for theta=-%pi/6:%pi/12:%pi/6 pin2x=(pin1x-c)*cos(theta); pin2y=(pin1x-c)*sin(theta); i=0; figure(1); x=[]; y=[]; for the=0:0.1:2*%pi+%pi...
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close(); clear; clc; I1 = 10; //A I2 = 100; //A R1 = 5; //ohm R2 = 10; //ohm R3 = 20; //ohm R4 = 30; //ohm //applying KCL A = [(1/R1+1/R2) (-1/R2);(1/R2) (-1/R2-1/R4-1/R3)]; C = [I1;-I2/R4]; B = inv(A)*C; V1 = B(1,1); V2 = B(2,1); I1 = (V1-V2)/R2; I2 = (V2-I2)/R4; mprintf("I1 = %0.2f A\nI2 = %0.2f A",I...
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clc; warning("off"); printf("\n\n example12.3 - pg569"); U=3; //[m/sec] x1=1; //[m] x2=2; //[m] p=1/(1.001*10^-3); //[kg/m^3]; mu=1*10^-3; //[kg/m*sec] Nre1=(x1*U*p)/(mu); Nre2=(x2*p*U)/(mu); tauw=(1/2)*(p*(U^2))*((2*log10(Nre1)-0.65)^(-2.3)); B=1700; Cd=(0.455*(log10(Nre2))^-2.58)-(B/(Nre2)); Lb=2.0;...
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//Calculate the gain with and without feedback and feedback factor clear; clc; //soltion //given Vo_=5;//V //output voltage Vi=0.2;//V //input with feedback Vi_=0.05;//V //input without feedback A=Vo_/Vi_; Af=Vo_/Vi; printf("The gain without feedback is %.0f\n",A); printf("The gain with feedba...
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//chapter 8 //example 8.2 //Calculate change in magnetic moment //page 236 clear; clc; //given r=0.052; // in nm (radius of orbit) B=1; // in Wb/m^2 (magnetic field of induction) e=1.6E-19; // in C (charge of electron) m=9.1E-31; // in Kg (mass of electron) //calculate r=0.052*1E-9; // changing unit from nm...
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//Ex 12 clc; clear; close; Error=40; true_value=1000; gainPercent=(Error/(true_value-Error))*100; printf("The gain is %3.2f percent",gainPercent);
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syms f J K s t T=1/(J*(s^2+(f/J)*s+(K/J))) //Q/I omegaN=sqrt(K/J) Mp=6 //given zeta=0.667 omegaD=omegaN*sqrt(1-zeta^2) Tp=%pi/omegaD disp(Tp," Tp = ") I=laplace('10',t,s) Q=I*T x=limit(s*Q,s,0); disp(10/0.5," K = ") disp(K/omegaN^2," J= ") disp(zeta*(2*sqrt(K*J))," f = ")
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P=380;//pressure of 11g of CO2 at 273K in mm of Hg// T=273;//Initial temperature of 11g of CO2 in kelvin// V=11.2;//Volume occupied by 11g of CO2 in litres at 273K// P1=760;//changed pressure of 11g of CO2 at 546K in mm of Hg// T1=546;//Final temperature of 11g of CO2 in kelvin// V1=(P*V*T1)/(T*P1);//changed volum...
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// First stage // allows each file to be chosen for j = 1:num_of_samples number = string(j); // creates all the csv files with only the 501 trace values needed // A becomes a list of the comma seperated variables in the raw data file A = read_csv('C:\Program Files\Tektronix\SA2600PC\Results'+'/'+ band_na...
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clc(); clear; //To determine the displacement produced ,the angle made by the beam with the axis,velocity of electrons V=25; //deflecting voltage l=0.03; //length of deflecting planes in m d=0.75; //dist...
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clear // //applying kcl to circuit at node b i3+i4=6-4=2 vb=8 vba=2 //voltage drop across nodes b and a va=6 //potential of node a w.r.t note c i2=3 //applying kcl to node a isa=1 vs=va+2*isa printf("\n vse= %0.1f V",vs)
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clear; clc; close; Vm = 20; Vdc = -0.318*Vm; disp(Vdc,'Dc volatge for ideal diode :'); t = 0:0.1:4*%pi; x = 20*sin(t); for i=1:length(t) if(x(i)<=0) y(i) = x(i); else y(i)=0 end end plot(t,y) xtitle('output for ideal diode','t','Vo');
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xdel(winsid()) clear clc maxFreqBandaBase=10;//Hz freqDeMod=10*maxFreqBandaBase//Hz freqDeAmostragem = 20*freqDeMod;//sempre maior que 2X, Teorema de Nyquist tempoDeAmostragem = 1/maxFreqBandaBase; t=linspace(0,tempoDeAmostragem,((1/maxFreqBandaBase)/(1/freqDeMod))*((1/freqDeMod)/(1/freqDeAmostragem))+1);//segun...
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//example 1.1 clc(); funcprot(0); V=0.25; // ft^3 W=30.8; //lb Wd=28.2; // weight dried lb Gs=2.67; Gammaw=62.4; //lb/ft^3 Gamma=W/V; disp(Gamma, "moist unit weight in lb/ft^3") w=(W-Wd)/W; disp(w*100, "moisture content in %"); Gammad=Wd/V; disp(Gammad, "dry unit weight in lb/ft^3") Vs=Wd/Gs/Gammaw; Vv=V-...
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V12 = 0.4; // V12 = V1/V2 T1 = 38+273; n = 1.3; P3 = 112; // back pressure m = 1.25; R = 0.287; T2 = ((V12)^(n-1))*T1; P1 = 700; // in kPa P2 = P1*(V12)^n; V2 = (m*R*T2)/P2; v2 = V2/m ; A = R*T1 + R*(T1-T2)/(n-1) - P3*v2; // Area of indicator diagram IO = A*0.85*m; disp("kJ",IO,"Indicated output is")
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clc; clear all; C=2*1e-12;//given capacitance L=500*1e-9;//given inductance Z0=sqrt(L/C);//characteristic impedence for section disp(Z0,'characteristic impedence');
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//CHAPTER 8- DIRECT CURRENT MACHINES //Example 32 disp("CHAPTER 8"); disp("EXAMPLE 32"); //250 V series motor at 1000 rpm //VARIABLE INITIALIZATION v_t=250; //in Volts I=20; //in Amperes N1=1000; //in rpm P=4; //number of poles r_p...
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//Chapter-5,Example 16,Page 128 clc(); close(); t_half = 600 // half life K=0.693/t_half Ea=98600 //activation energy A= 4*10^13 //Arrhenius factor R=8.316 //gas constant T=Ea/(2.303*R*log10(A/K)) printf('temperature is %.f K',T) //mistake in textbook
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disp('the co-efficient matrix is:') a=[5 7;2 4] disp(a,'A=') disp('the RHS is:') b=[3;1] disp(b) disp('applying cramers rule') disp('replacing first column of matrix A by b') A1=[3 7;1 4] disp(A1,'A1=') disp('replacing second column of matrix A by b') A2=[5 3;2 1] disp(A2,'A2=') disp('x1=det(A1)/det(A)') ...
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// Exa 3.13 clc; clear; close; // Given data V_F= 0.2;// in V T=300;// in K V_T= T/11600;// in volt Io= 1;// in micro amp Io=Io*10^-6;// in amp Id= Io*(%e^(V_F/V_T)-1) I_F=Id; r_dc= V_F/I_F;// in ohm disp(r_dc,"Dynamic resistance in ohm is : ") r_ac= .026/I_F;// in ohm disp(r_ac,"Static resistance in ohm...
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clc; warning("off"); printf("\n\n example10.17 - pg477"); // given Uzmax=3.455; //[ft/sec] m=32; a1=-0.3527; a2=-0.6473; rbyro=0.880; UzbyUzmax=1+a1*(rbyro^2)+a2*(rbyro^(2*m)); Uz=Uzmax*(UzbyUzmax); Uzavg=(4/9)*Uzmax+(5/18)*(Uz+Uz); printf("\n\n the average velocity is \n Uzavg = %f ft/sec \n\n Thus, in th...
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function demo_welcome() // header: header of the variable to deploy // data: core of the data to deploy // herokuapp: name of heroku app to deploy (contained in the URL) M = ['A','B'; '1','2'; '3','4'] header = M(1,:) data = M(2:$,:) herokuapp=x_dialog('Name of the herokua...
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//Example_a_10_14 page no:475 clc; turn=700; mu_o=4*%pi*10^-7; mu_r=600; phi_g=1.8*10^-3; Ag=4*4&10^-4; Bg=(1.8*10^-3)/(16*10^-4); Ig=0.001; Hg=Bg/mu_o; mmf_gap=Hg*Ig; phi_c=1.8*10^-3; Ac=4*4*10^-4; Bc=1.125; Ic=0.24; Is=0.6; Hc=Bc/(mu_o*mu_r); mmf_central_limb=Hc*Ic; phi_s=(1/2)*phi_g; Bs=phi_s/(16*...
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clc; clear; Nf=15; //noise figure in dB F=31.62;//power ratio T=290; //Temperature in K T_em=(F-1)*T G1=10^(6); //power ratio N_t=80; //Noise temperature in K T_e=N_t+T_em/G1; disp("Noise temperature of receiver (in K)"); disp(T_em); // change in answer....the calculation in the book is wrong disp("...
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//Part A Chapter 7 Example 5 clc; clear; close; V=0.5;//m^3 T=100+273.15;//K v2=0.003155;//m^3/kg(at critical state) v1=v2;//constant volume process vf=0.001044;//m^3/kg(at 100 degree C) vg=1.6729;//m^3/kg(at 100 degree C) x1=(v1-vf)/vg;//dryness fraction m=V/v2;//kg mw=m*(1-x1);//kg Vw=mw*vf;//m^3 disp("...
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clc T=298 //temperature in kelvin T1=523 //temperature in kelvin T2=773 //temperature in kelvin mprintf("Fraction of available energy lost=%f",(T*((1/T1)-(1/T2)))/(1-(T/T2)))//ans vary due to roundoff error
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clear; clc; b=[1 -2 ;1 1]; c=[0;450]; a=inv(b)*c; p1=a(1); p2=a(2); ic1=2+.01*p1; ic2=2+.02*p2; printf("the incremental fuel cost of first generator is:%.2f Rs/MWh",ic1); printf("\n the incremental fuel cost of second generator is:%.2f Rs/MWh",ic2);
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//(Welded and Riveted Joints) Example 8.22 //Refer Fig.8.64 on page 317 //Inside diameter of the pressure vessel Di (m) Di = 1 //Internal steam pressure Pi (MPa) Pi = 2.5 //Efficiency of the riveted joint eta (%) eta = 70 //Permissible tensile stress in the plate and rivet sigmat (N/mm2) sigmat = 80 //Permi...
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clc //Example 4.6 //calculate the mass consumed in a nuclear reactor per unit time //let D=d/dt DQ=-13*10^8;//J/s DW=7*10^8;//J/s //Dm=(DQ-DW)/c^2 where c is velocity of light sice E=mc^2 c=3*10^8;//m/s c1=3;//velocity of light without power pow=8//power of 10 in speed of light Dm=(DW-DQ)/c/c1//kg/s printf(...
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//Clearing console clc clear x = poly(0,"x") //Intializing variables x0 = 0 x1 = 1 K = [integrate('x*(x-1)*(x^2-x+2)','x',x0,x1)] F = [integrate('x*(x-1)*3*x','x',x0,x1)] c = F/K S = c*x*(x-1)+x //Calculating solution for given differntial equation for t =1:11 P(1,t) = (c*(t-1)*(t-11)/100)+(t-1)/10 end //Co...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>Linear stability with coupled solver (LM with Arpack and Complex Shift): ChannelMax Ev = (0.00248682 -0.158348i) </description> <executable>IncNavierStokesSolver</executable> <parameters>PPF_R15000_3D.xml</parameters> <files> <file descr...
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// using KVL we get i(t)*R + 1/C * int(i(t)) = v(t) // taking laplace transform V(s)= I(s)*R + 1/C * (I(s)/s) R=10^6 C=10^-6 s=%s; F=1/R*(1/(s + (1)/(R*C))); disp(F) syms t s; y=ilaplace(F,s,t); disp(y,"i(t)=")
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clear clc //to find final velocity of combination of 1st and 2nd glider // GIVEN:: //refer to problem 6-5 from page no. 127 //we consider +ve x direction as initial motion of first glider //mass of first glider m1 = 1.25//in kg //initial velocity of first glider in +ve x direction v1ix = 3.62//in m/s ...
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clc //initialization of varaibles v2=15.7 //cu ft/lb T2=640 //R cv=0.172 T1=400+460 //R //calculations du=cv*(T2-T1) W=-du //results printf("Final specific volume = %.1f cu ft/lb",v2) printf("\n Final temperature = %d ",T2) printf("\n Work done = %.1f B/lb",W)
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errcatch(-1,"stop");mode(2);; ; Vcc = 12; Vbe = 0.7; Rx = 1.1*(10^(3)); Ix = (Vcc-Vbe)/Rx; disp(Ix,"Mirrored current :"); exit();
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// Exa 4.19 clc; clear; close; // Given data V_Dmin= 2.5;// in V V_Dmax= 5;// in V // Case First Vs= 25;// in V Rs= 250;// in Ω Imax= (Vs-V_Dmin)/Rs;// in A Imin= (Vs-V_Dmax)/Rs;// in A disp(Imax*10^3-Imin*10^3,"The variation in current in first case in mA is : ") // Case sec Vs= 10;// in V Rs= 130;// i...
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a=[0.1,0.2,0.3,0.4,0.5]; b=[0.4,0.5,0.6,0.7,0.8]; c=[1,1,1,1,1]; A=union(a,b); disp(A); subplot(4,4,1); plot(A,'r'); xtitle('union'); B=intersect(a,b); disp(B); subplot(4,4,2); plot(B,'g'); xtitle('intersection'); C=c-a; disp(C); subplot(4,4,3); plot(C,'b'); xtitle('a complement'); D=c-b; disp(D); s...
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donnees = [ 5 92 7.8; 4 64 9.5; 6 124 6.4; 5 97 7.5; 5 79 8.1; 5 76 9.0; 6 93 6.1; 6 63 8.7; 2 13 15.4; 7 111 6.4; 7 143 4.4]; // definition des variables r1=donnees(:,1); r2=donnees(:,2); X=donnees(:,3); // allure des nuages subplot(121), plot2d(r1,X,-2,"111","Age",[1,0,8,16]); subplot(122), plot2d(r...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>Transient Growth (Arpack): Backward-facing step</description> <executable>IncNavierStokesSolver</executable> <parameters>bfs_tg-AR.xml</parameters> <files> <file description="Session File">bfs_tg-AR.xml</file> <file description="Session...
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clc //initialization of varaibles disp("From psychrometric charts,") e=0.7 phi=0.5 g1=0.0131 //lb water/lb dry air h1=32.36 //B/lb of dry air g3=0.0073 h3=24.26 pg=0.3390 T3=528 //R V3=1000 Rw=85.8 //calculations pw3=phi*pg ww3=pw3*144*V3/(Rw*T3) wa3=ww3/g3 wa1=phi*wa3 wa2=phi*wa3 ww1=g1*wa1 ww2=ww3...
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(unwatch all) (clear) (load fctquery.clp) (dribble-on "Actual//fctquery.out") (batch "fctquery.bat") (dribble-off) (clear) (open "Results//fctquery.rsl" fctquery "w") (load "compline.clp") (printout fctquery "fctquery.clp differences are as follows:" crlf) (compare-files "Expected//fctquery.out" "Actual//fctquery.out" ...
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//Example 4.2(a) clear; clc; n=6; fc=13*10^3; //For a 1dB ripple Chebyshev low pass filter with n=6 requires 3 second order stages with : //f01=0.995*fc, Q1=8 //f02=0.747*fc, Q2=2.20 //f03=0.353*fc, Q3=0.761 f03=0.995*fc; Q1=0.761; f02=0.747*fc; Q2=2.20; f01=0.353*fc; Q3=8.00; n1=...
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//exapple 2.18 clc; funcprot(0); // Initialization of Variable H=600; f=150/1000; s=H/f; b=6.375/100; h1=0; h2=120;//height of chimney B=s*b;//datum elevation p1=B*f*1000/(H-h1); p2=B*f*1000/(H-h2); delp=p2-p1; delh=H*delp/1000/(b+delp/1000); disp(delh,"parallax height of the chimney in (m):"); clea...
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clear; clc; close; x=poly(0,'x'); p1=4*x-(x-2)/3; p2=5+(2*x+1)/4; p3=p1-p2; x=roots(p3) left=4*x-(x-2)/3;//substitution right=5+(2*x+1)/4; if(left==right) mprintf("satisfies the equation \n") end
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// Example 2.10: Calculate base resistance , Voltage between collector & ground and Stability factor Vcc=12;// Colector voltage in volts Ib= 0.3;// in mili ampere Beta=100;//Common emitter D.C. Current gain Rc=0.3;// Collector resistance in killo ohms Rb=Vcc/Ib; Ic= Beta*Ib; Vce=Vcc -(Ic*Rc); S=1+Beta ; disp(R...
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sum = 0; n = 10000; for i = 1:n sum = sum + 1/ sqrt(i); end
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> set 2 2 > div 3 0.666666666666666666 > mul 3 1.99999999999999999 > div 3 0.666666666666666663 > mul 3 1.99999999999999998 > div 3 0.66666666666666666 > mul 3 1.99999999999999998 > round 16 2.0000000000000000 > div 3 0.666666666666666666 > div 4 0.166666666666666666 > mul 4 0.666666666666666664 > mul 3 1.9...
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//Variable declaration L=5; //length(m) R=0.06; //resistance(ohm) I=15; //current(A) ne=3; //number of electrons rho=2.7*10**-8; //resistivity(ohm m) w=26.98; //atomic weight D=2.7*10**3; //density(kg/m**3) Na=6.025*10**26; //avagadro number(per k mol) e=1.6*10**-19; //Calculation n=...
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clc; E=10^6; //in volt/m e=8.85*10^-12; //constant in F/m v=10^-5; //volume in m cube en=(1/2)*e*E*E*v; //calculating energy disp(en,"Energy in Joule = "); //displaying result
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// Copyright (C) 2018 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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function x=%r_eye(a) // Copyright INRIA x=eye(a(2));
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//laplace// s=%s; H=syslin('c',(4*(s+2)*((s+2.5)^3))/((s+6)*((s+4)^2))); plzr(H)
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// Scilab Code Ex2.11: Page-64 (2013) clc; clear; q = 1.6e-019; // Charge on an electron, C V = 25e+003; // Accelerating potential, volt K = q*V; // Kinetic energy of electrons, J m = 9.11e-031; // Rest mass of an electron, kg c = 3.00e+08; // Speed of light, m/s // From relativistic kinetic energ...
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SIEMENLUKU 6666 PELAAJIA 2 IHMINEN Foo TIETOKONE Bar
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pathname=get_absolute_file_path('17_17.sce') filename=pathname+filesep()+'17_17_data.sci' exec(filename) //Swept volume(in cc/cylinder) Vs=0.25*%pi*D^2*L*10^6 //Compression ratio r=(Vs+Vc)/Vc //Air standard efficiency nas=1-(1/r^(y-1)) //Brake thermal effciency nbth=nrel*nas //Brake power(in kW) bp=(2*%pi*N...
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//Example 5.27 clc disp("") disp("A1 A0 B1 B0 A>B A=B A<B") disp("0 0 0 0 0 0 0") disp("0 0 0 1 0 0 1") disp("0 0 1 0 0 0 1") disp("0 0 1 1 0 0 1") disp("0 1 0 0 1 0 0") disp("0 1 0 1 0 1 0") disp("0 ...
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// Grob's Basic Electronics 11e // Chapter No. 22 // Example No. 22_4 clc; clear; // What is the time constant of a 0.01-uF capacitor in series with a 1-M Ohmsresistance? // Given data C = 0.01*10^-6; // Capacitor=0.01 uFarad R = 1*10^6; // Resistor=1 MOhms T = C*R; disp (T,'The Time Consta...
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disp("Part a"); p=0.2; v_1=1.5; v1_1=p*v_1; v2_1=v_1-v1_1; disp("the time taken to reduce the terminal voltage by 20 % is 5 h"); disp("Part b"); v_2=1.2; v1_2=p*v_2; v2_2=v_2-v1_2; disp("the time taken to reduce the terminal voltage by 20 % is 10 h"); disp("Part c"); v_3=1.4; v1_3=p*v_3; v2_3=v_3-v1_3; d...
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// function [B,degB,A,degA,Y,degY,X,degX] = ... // left_prm(N,degN,D,degD,job,gap) // // does three different things according to integers that 'job' takes // job = 1. // this is the default. It is always done for all jobs. // -1 -1 -1 // Given ND , returns coprime B...
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// Calculating the square. y = [1.2, 1, 1.9; 4, 2.6, 5; 2.3, 8, 7]; squareres = armaMat("square",y)
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clc clear //Initialization of variables disp("From table 1 of keenan and keynes,") h1=1351.1 //Btu/lb p1=600 //psia t1=700 //F p2=234 //psia h2=1.6865 h1=1.5875 t3=101.74 //calculations t2=660 //F loss= (h2-h1)*(t3+459.69) //results printf("Final state of steam is %d psia and %d F",p2,t2) printf("\n Los...
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//Problem 6.17: A capacitor is charged with 10 mC. If the energystored is 1.2 J find (a) the voltage and (b) the capacitance. //initializing the variables: W = 1.2; // in Joules Q = 10E-3; // in Coulomb //calculation: V = 2*W/Q C = Q/V printf("\n\nResult\n\n") printf("\n (a)P.d %.0f V",V) printf("\n (b)C...
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// ELECTRICAL MACHINES // R.K.Srivastava // First Impression 2011 // CENGAGE LEARNING INDIA PVT. LTD // CHAPTER : 5 : INDUCTION MACHINES // EXAMPLE : 5.28 clear ; clc ; close ; // Clear the work space and console // GIVEN DATA m = 3; // Total Number of phase in Induction M...
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// Example 5.3 : power factor clc; clear; // given : format('v',6) w1=2000;//power in watts w2=500;//power in watts an=atand(sqrt(3)*(((w1-w2)/(w1+w2))));//angle in degree disp("part (a)") pf=cosd(an);//power factor disp(pf,"power factor is ,=") disp("part (b)") w1=2000;//power in watts w2=-500;//power in watts an=atan...
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//Chapter 14 //Example 14.4 //Page 388 //onfault clear;clc; H = 5; Pm =1; Vt = 1;V_ib = 1; X1_g =0.2;X1_t = 0.1;X1_l1 = 0.4;X1_l2 = 0.4; X = X1_t + X1_l1 /2; a = asin(Pm * X / (Vt * V_ib)) * 180 / %pi; Vt1 = Vt * (cos(a * %pi / 180) + %i * sin(a * %pi / 180)); I = (Vt1 - V_ib) / (%i * X); E1 = Vt1 + (%i * X1_g * I); y1...
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//Exa:3.3 clc; clear; close; //Given: Bw=12;//in KHz Mod_mn=300; Mod_mx=3000; dev=6;//in KHz m1={(Bw-dev)*1000}/Mod_mn; m2={(Bw-dev)*1000}/Mod_mx; printf("\n 1)modulation indexat 300Hz = %f ",m1); printf("\n 2)modulation indexat 3000Hz = %f ",m2);
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Ex8_14.sce
clear // isc=150 //short circuit current iscp=25/1.732 //isc per phase where 1.732 is the value of root 3 pv=415/1.732 //per phase voltage ist=(iscp*pv)/150 ifl=(15*735.5)/((415*0.9*0.8*(3**0.5))) ratio=ist/ifl printf("\n ratio")
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Gauss_Jordan_1.sce
clear /////////////////////////////////////////////////////// // Gauss_Jordan_1.sce // // Este programa pide una serie de ecuaciones y obtiene // su solucion utilizando el método de Gauss-Jordan // // Armando Roque A01138717 // Marco Brown A00822215 // // 1 / OCT / 19 version 1.0 /////////////////////////...
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Ex10_6.sce
clear //Given d=6.4*10**6 //m B=0.4*10**-4 //T u=4*%pi*10**-7 //Calculation // M=(B*4*%pi*d**3)/u //Result printf("\n earths dipole moment is %0.2f *10**23 Am**2",M*10**-23)
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s=%s; A=[-0 1;-2 -3] B=[1;0] C=[1 0] D=0; TF=C*inv(s*eye(2,2)-A) *B disp(TF,"transfer function = ")
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Afford_Rating.sce
scenario = "Stimuli- Rating"; #randomize_trials = true; default_font_size = 36; default_background_color = 128,128,128; active_buttons =10; button_codes =1,2,3,4,5,6,7,8,9,10; begin; ################################################# fixation cross picture { box { height = 10; width = 40; color = 255, 25...
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// Author: Naga Kandasamy load Computer.hdl, output-file ComputerSeriesSum.out, // compare-to ComputerAdd.cmp, output-list time%S1.4.1 reset%B2.1.2 ARegister[0]%D1.7.1 DRegister[0]%D1.7.1 PC[]%D0.4.0 RAM16K[0]%D1.7.1 RAM16K[1]%D1.7.1 RAM16K[2]%D1.7.1; // Load a program written in the Hack machine language. //...
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clc // Given that d= 4 // Depth of cut in mm f = 0.25 // Feed in mm/stroke alpha = 10 // Rake angle in degree shi = 30 // Principal cutting edge angle in Degree mu =0.6 // Cofficient of friction between chip and tool T_s = 340 // Ultimate shear stress of cast iron in N/mm^2 N = 60 // Cutting stroke/min L = 200 // Leng...
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function gameoflife(rows,columns,iterations) matrix_1=zeros(rows,columns); matrix_2=zeros(rows,columns); table=[-1,-1,0,-1,1,-1,1,0,1,1,0,1,-1,1,-1,0]; for i=1:rows for j=1:columns matrix_1(i,j)=3*round(rand()); end end clf(); xtitle("Game of Life") f = gcf(); f.figure_name ...
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// Define the axes of the pictures x = 1; y = 1; // Set the picture into a matrice named "img" img = readpbm('Gliese 667Cc_surface.pbm'); // Scroll every pixels of the picture for y = 1:384 for x = 1:512 // Increase the value of the pixel depending on his initial value if img(x,y) <...
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; @Harness: simulator ; @Purpose: "Test instructions for reading/writing to IO registers" ; @Result: "r17 = 42, r18 = 106, $(59) = 106, $(0) = 0" start: ldi r17, 42 out 0x1b, r17 sbi 0x1b, 6 in r18, 0x1b end: break
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ch6_17.sce
clear; clc; E=200; I_o=20; R=.5; V_o=E+I_o*R; V_s=230; V_ml=sqrt(2)*V_s; a=acosd(V_o*%pi/(3*V_ml)); printf("firing angle delay=%.3f deg",a); th=120; I_s=sqrt((1/%pi)*I_o^2*th*%pi/180); P=E*I_o+I_o^2*R; pf=P/(sqrt(3)*V_s*I_s); printf("\npf=%.3f",pf); V_o=E-I_o*R; a=acosd(-V_o*%pi/(3*V_ml)); prin...
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clear //Given V=12 //V C=1.35*10**-10 //C //Calculation q=C //Result printf("\n Extra Charge supplied by battery is %0.3f C", q)