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clear; //Apaga variáveis t = 0:0.01:1; //Tempo de 0 a 10seg com passo de 0.01seg // a a_k = 10; //Ganho a_p = 10; //Polo a_tau = 1/a_p; //Constante de tempo a_c = (a_k/a_p)*( 1 - exp(-t/a_tau) ); //Dinâmica do sistema (Resposta ao deg...
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exec('Load.sci'); m=fscanfMat('../result.dat'); n1=1; n=size(m,1); q=zeros(7,n); q(2:2:7,n1:n)=m(n1:n,2:2:7)'; Visu(q,q)
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//Example 1_27 clc; clear; close; format('v',4); //given data : V1=20;//V V2=4;//V R1=500;//ohm R2=1000;//ohm R3=100;//ohm R4=800;//ohm RL=1000;//ohm //solution VCB=-R2/(R4+R2)*V1;//V //writing KVL equation for the loop I=poly(0,'I'); eqn=V1-R1*I-V2-R3*I;//KVL equation I=roots(eqn);//A VCA=-I*R1;//V ...
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clc //To find force acting on crate //Given : //refer to figure 3-8(a) and3-8(b) from page no. 49 // mass m =360 //kg // initial velocity of crate vx1 =62//km/ph // final velocity of crate v0x1 = 105 //km/ph // time elapsed t =17 //seconds //solution: //calculating initial velocity in m/s vx =(...
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clc;clear; //Example 11.5 //given data hf=2.48*10^5;//half life in yrs k=8.88*10^-14//decay const in 1/s Mo=4;//intial mass in mg Na=6.02*10^23;//Avgraodo no. in 1/gm mole //calculations kt=0.693/hf*62000; M=Mo*(exp(-kt)); disp(M,'mass remain unchanged in mg'); N=M*10^-3*Na/234; A=k*N; disp(A,'Activity...
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//Chapter-12, Example 12.3, Page 509 //============================================================================= clc clear //INPUT DATA mh=10000;//Mass flow rate of oil in kg/h ch=2095;//Specific heat of oil J/kg.K Thi=80;//Inlet temperature of oil in degree C Tho=50;//Outlet temperature of oil in degree ...
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART IV : UTILIZATION AND TRACTION // CHAPTER 5: ELECTRIC TRACTION-SPEED TIME CURVES AND MECHANICS OF TRAIN MOVEMENT // EXAMPLE : 5.8 : // Page number 782-783 clear ; clc ...
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// chapter 16 // example 16.14 // Determine supply frequency // page-1041 clear; clc; // given C=5.3; // in uF V=600; // in V I=100; // in A // calculate C=C*1E-6; // changing unit from uF to F Xc=V/I; // since Xc=1/(2*%pi*f*C), therefore we get f=1/(2*%pi*C*Xc); // calculation of supply frequency printf("\nThe supply ...
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//i/p args are x,p and sampling frequency fs clc; clear; exec('/home/debdeep/Desktop/TEST NOW!!/rooteig/rooteig.sci'); x=[1 2 3 4 6 7 8 9]; p=2; fs=4e6; [f,pow] = rooteig(x,p,fs); disp(f); disp(pow); //output // 145392.21 // - 145392.21 // // 33.436048
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//Chapter-2, Example 2.17, Page 2.32 //============================================================================= clc clear //INPUT DATA R1=3.5;//Primary Resistance in ohm X1=5.2;//Primary reactance in ohm R2=0.01;//Secondary Resistance in ohm X2=0.02;//Secondary reactance in ohm Q=40000;//Rating of the t...
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// Ex4_4 Page:64 (2014) clc;clear; c = 3e+08; // Speed of the electron, m/s lambda = 4000e-010; // Wavelength of the spectral line, m delta_t = 1e-08; // Average lifetime of an excited atomic state, s delta_lambda = lambda^2/(4*%pi*c*delta_t); // Natural width of the spectral line, m printf("\nThe nat...
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// Example 2.11 //Calculation of (a) reflection and (b) loss of light signal at joint areas. // Page no 482 clc; clear; close; // Given data n1=1.5; // Refractive index of core n=1; // Refractive index of air // (a) Reflection at the fiber air interface R=((n1-n)/(...
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loadmatfile proj1; getf pacf.sci; getf plotacf.sci; getf label.sci; //y5 xset ('window',1) pacf(y5,21); //decay slowly (=0 from lag=9) => MA process xset ('window',2) plotacf(y5,1,21,1); //decay (=0 from lag=3) but not cut off => mixed process //we start with an ARMA(1,1) model and compute its residual ul=length(y5...
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//Torque delivered by the engine(in N-m) T=23.5; //Bore of the engine(in m) D=80*10^-3; //Stroke of the engine(in m) L=110*10^-3;
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// Example of solving hydrodynamics equation to advect fluid // Illustrates the problem of numerical instability // // Higher order terms for the finite element derivatives are n0t sufficient // to remove discontinuities // // // Use two step Lax-Wendroff method to stabilise solution // http://en.wikipedi...
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clc; clear all; D=0.1;//focal length of lens lemda=14400*1e-10;//wavelength in meters p=100*1e-3;//power of laser beam d=10*1e-3;//aperture in meter th=lemda/d;//angular speed disp('rad',th,'angular speed is='); aos=(D*th)^2;//area of spread disp('m^2',aos,'area of spread is='); I=p/aos;//'intensity disp('W...
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clear; clc; //Example11.8[Using the Effectiveness- NTU Method] //Given:- mc=1.2,mh=2;//Mass Flow rate of water and geothermal fluid[kg/s] U=640;//Overall Heat transfer Coefficient[W/m^2.degree Celcius] Di=0.015;//[m] Tc_out=80,Tc_in=20;//Outlet and Inlet temp of water[degree Celcius] Th_in=160;//Inlet temp of...
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function [x,y,typ] = SPAM_Motor(job,arg1,arg2) x=[];y=[];typ=[]; sensor = ''; port_no = ''; select job case 'plot' then graphics=arg1.graphics; ierr=execstr('(evstr(graphics.exprs(1))==1)','errcatch') if ierr<>0 then sensor = 'Custom Sensor'; ...
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//example 9.8 //page 326 clc; funcprot(0); //initialisation of variable Q=0.075; L=30; D=0.1; pi=3.14; k=0.5; K=10; g=9.81; nu=1.007*10^-6//kinematic viscosity A=pi*D^2/4; V=Q/A; R=V*D/nu; //using moody's chart f=0.025; hf1=f*L*V^2/2/g/D;//head loss by friction hf2=k*V^2/2/g;//head loss due to contr...
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function r=mtlb_length(a) //used by mfile2sci translator to emulate "length" when translator as no //type information on the length argument //You may replace this function call by // length(..) if argument is a character string // max(size(..)) else //! // Copyright INRIA if type(a)==10 then r=length(a) els...
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//gen random weights //get optimal policy //get new optimal policy , add to set of policies //--run for n times-- w=rand(ws,1); //w=[1;1;.1;.07;.3;.03]; w=w/norm(w,2); lmd=0.9; //ws,ns have size //pls=cell(); //pls(1).entries=qlearn(w); for ns=1:20 //compute Da // z1s=zeros((gsize+2),3*gsize,3*gsize); // //...
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//factorize (a+b)^2 - (c-a)^2 clear; clc; close; //using the formula, a^2-b^2=(a+b)(a-b) val=string('(b+c)(2a+b-c)')
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//Kunii D., Levenspiel O., 1991. Fluidization Engineering(II Edition). Butterworth-Heinemann, MA, pp 491 //Chapter-16, Example 5, Page 425 //Title: Solvent Recovery from Polymer Particles //========================================================================================================== clear clc /...
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clc; close(); clear(); //page no 644 //prob no. 21.2 mprintf('The percentage is %.0f ',483/525*100)
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// Author: Benjamin Fradet // To execute with Scilab 5.5.1 function[sequence] = generateMarkovSeq(transitionMatrix, ... initialProbs, ... seqLength) sequence = zeros(1:seqLength); // Cloudy = 1 // Rain = 2 // Snow = 3 //...
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//example1.1 clc disp("From the give waveform,") s=100/2 disp(s,"For 0<t<2, i(t) is a straight line slope=") disp("Therefore i(t)=50t and di(t)/dt=50 .. 0<t<2") disp("For 2<t<4, i(t)=100 and di(t)/dt=0") s=(-100)/2 disp(s,"For 4<t<6, i(t) is a straight line slope = ") disp("Therefore, i(t)= -50t and di(...
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clear // //Initilization of Variables F=12 //KN //Force at End of beam L=2 //m //span //Square section b=200 //mm //Width and depth of beam d=200 //Rectangular section b1=150 //mm //Width d1=300 //mm //Depth //Calculations //Max bending Moment M=F*L*10**6 //N-mm //M=sigma*b*d**2 sigma=M*6*(b*d**2)**-1 //N/mm**...
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//Example 9.2: Reduction of state table clc // Clears the console disp("Given State Table") disp("q | x=0 x=1 | z") disp('--------------------------------') disp("A | B D | 1") disp("B | D F | 1") disp("C | D A | 0") disp("D | D ...
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// Example No. 2.14 // To calculate the lower limit on the transmitter power in dBm and mW units. // Page No. 83 clc; clear; // Given data l=80; // Length of fiber in km F1=-0.2*l; // Fiber loss in dB F2=-0.5; ...
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// Exa 8.7 clc; clear; close; // Given data V_GS = -2;// in V V_P = -5;// in V V_DS = V_GS-V_P;// in V I_DSS = 8;// in mA disp(V_DS,"The minimum value of V_DS in V is"); I_D = I_DSS*((1-(V_GS/V_P))^2);// in mA disp(I_D,"The drain current in mA is");
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clc //Example 17.4 //Compound gear train //------------------------------------------------------------------------------ //Given data //power P=10000 //W //speed n=1440 //rpm w=(2*%pi*n)/60 //rad/s //Number of teeth Na=25 Nb=100 Nc=30 Nd=150 //modules ma=5 //mm mb=ma mc=6.5 //mm md=mc //pressur...
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clear; clc; printf("\t\t\tProblem Number 6.16\n\n\n"); // Chapter 6: The Ideal Gas // Problem 6.16 (page no. 260) // Solution //data cp=0.24; //Specific heat at constant pressure //Btu/lbm*R p2=15; //psia //final pressure p1=100; //psia //initial pressure T2=460+0; //absolute final temperature //unit:R ...
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clc clear printf("Example 12.11 | Page number 437 \n\n"); //Find standard delta_H for reaction //Given Data //Formation Enthalpies hf_CO2 = -393510 //kJ/kmol hf_H2O = -285838 //kJ/kmol hf_C3H8 = -104680 //kJ/kmol hf_O2 = 0 //kJ/kmol //Solution Hp = 3*hf_CO2 + 4*hf_H2O Hr = hf_C3H8 + 5*hf_O2 deltaH_std =...
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//Chapter-11, Example 11.3, Page 481 //============================================================================= clc clear //INPUT DATA D=0.0016;//Diameter of the wire in m T=255;//Temperature difference in degree C p1=957.9;//Density of liquid in kg/m^3 Cpl=4640;//Specific heat in J/kg.K u=(18.6*10^-6);...
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// Example 8_9 clc;funcprot(0); // Given data P_1=10;// kPa P_2=2;// MPa T_3=600;// °C n_T=80/100;// The efficiency of the turbine // Calculation // From the steam tables we find h_2=192;// kJ/kg h_1=h_2;// kJ/kg h_3=3690;// kJ/kg s_3=7.7032;// kJ/kg.K s_4a=s_3;// kJ/kg.K s_f4a=0.6491;// kJ/kg.K s_fg4a...
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//Chapter 21: Antenna Measurements //Example 21-5.2 clc; //Variable Initialization f = 1.4e9 //Frequency (Hz) Tant = 687 //Increase in antenna temperature (K) phy_ap = 2210 //Physical aperture (m^2) S = 1590 //Flux density of Cygnus A (Jy) k = 1.38e-23 //Boltzmann's constant (J/k) c = 3e8 ...
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main procedure rec(n); { if n == 0 then return fi; call outputnum(n); call rec(n - 1) }; { call rec(8) }.
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// Example 34_18 clc;funcprot(0); //Given data MD=80;// Maximum demand in MW F_l=35/100;// Load factor E_s=120*10^6;// Energy supplied by steam plant in kWh/year MD_s=50;// Maximum load in MW CC_s=18000;// Capital cost of steam plant in Rs./ kW installed CC_h=30000;// Capital cost of hydro plant in Rs./ kW inst...
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// Example 11_14 clc;funcprot(0); // Given data V=0.100;// m^3 p=20.0;// MPa m=15.6;// kg T=1000;// °C // Solution // From Table C.12b, we find the critical state properties of methane to be T_c=191.1;// K p_c=4.64;// MPa v=V/m;// m^3/kg v_1=v;// m^3/kg v_2=v_1;// m^3/kg // Table C.13b, gives the gas co...
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clc //initialization of variables P=80 //lb/in^2 T=120+460 //R R=53.3 //ft-lb/lbmR //calculations disp("From table 6,") h=138.66 //B/lbm P=P*144 //lb/ft^2 v=R*T/P //results printf("Specific volume = %.2f ft^3/lbm",v)
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Turbomachinery Design and Theory,Rama S. R. Gorla and Aijaz A. Khan, Chapter 6, Example 11") disp("Velocity triangles for this problem are shown in Fig.Ex611") disp("From the triangle ACD,") C1 = 700; alpha1 = ...
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clc // from figure 2.75 (a) r1 = 30 // radius in mm t = 10 // thickness in mm h1 = 300 // height in mm ir1 = r1-t // inner radius of bends in mm L1 = h1-(ir1+t) // mm alpha1 = 90 // degree r2 = 2*t // mm k = 0.33*t // mm L2 = alpha1*2*%pi*(r2+k)/360 // mm w = 200 // mm L3 = w-2*(t+ir1)// mm L4 = L2 //mm h...
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// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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getd(); /// définition de la géométrie P1=[0;0;0]; P2=[10;0;0]; P3=[5;6.6;0]; /// définition de la topologie t1 = [1;2;3]; /// tableaux noeuds=[P1 P2 P3]; elements=[t1]; /// On suppose qu'on connait le déplacement aux noeuds U1=[5;1.5;0]; U2=[4.5;-0.3;0]; U3=[5.3;1.2;0]; U_noeuds = [U1 U2 U3]; ...
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//Chemical Engineering Thermodynamics //Chapter 14 //Thermodynamics of Chemical Reactions //Example 14.6 clear; clc; //Given //SO2 + (1/2)O2 - SO3 //Basis: 1 Kgmole of SO2 n_SO2 = 1;// SO2 fed in Kgmole //From table 14.1 (page no 301) //alpha values for the following components are given as a_SO2 = 7.116; a_O2 = 6.14...
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// Ex 47 Page 391 clc;clear;close; // Given V=500;//V ns=60;//slots nc=20;//conductor/slot ra=1.31;//ohm Tmax=218;//N-m fi=23*10**-3;//Wb Tmin=Tmax/1.5//N-m Z=ns*nc;//no of conductors Ia=Tmax/(.159*fi*Z);//A Imax=1.5*Ia;//A I1=Imax;//A I2=Ia;//A R1=V/I1;//ohm n= log(R1/ra)/log(I1/I2)+1;//no of studs N=n-1;//no of sec...
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clc //initialization of new variables clear D=1 //m alpha=0.5 //degrees n=0.012 //calculations R=D/2 theta = 1:1:180; R_h = 0.5*R - (45*R/%pi)*(sin(2*theta*%pi/180))./(theta*180/%pi); Z = R*(1-cos(theta*%pi/180)); U_av = (1/n)*(R_h^(2/3))*sqrt(tan(alpha)); Q = U_av*%pi*R^2 .*(theta*180/%pi) - (0.5*R^2)*...
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clear all; clc; disp("Ex 5_12") disp("Refer to the free body diagram is as shown from fig 5-23a")
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V=400//phase voltage applied to motor //when started directly on line Iph=25//phase current Il=sqrt(3)*Iph mprintf("Line current drawn by the motor when started directly on line=%f A\n",Il) //when started with auto-transformer starter with a tapping percent of 60 percent Vl=.6*V//line voltage Vph=Vl//phase vol...
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clear;lines(0); x=[1+%i,-%i;%i,2*%i]; conj(x) x'-conj(x) //x' is conjugate transpose
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// Variable Declaration l = 10.0 //Length of 1-phase line(km) d = 100.0 //Spacing b/w conductors(cm) r = 0.3 //Radius(cm) u_r_1 = 1.0 //Relative permeability of copper u_r_2 = 100.0 //Relative permeability of steel // Calculation Section r_1 = 0.7788*r //Radius o...
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function CreateFigure(figframe,figsize) { bl=Blob; r2=0.3; bl.AddSphere(point(0,0,0.95),0.2,0.3); bl.AddSegment(point(0,0,0),point(0,0,1),0.23,r2+0.03); bl.AddSegment(point(0.22,0,-1),point(0.15,0,0.5),0.2,r2); bl.AddSegment(point(-0.22,0,-1),point(-0.15,0,0.5),0.2,r2); bl.AddSegment(point(0.26,0,0...
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function [ n , xn] = singular_fun(wave_type , start_index , end_index , del_adv) n = start_index:end_index; select wave_type case "unit_impulse" then xn = [zeros(1,abs(start_index) + del_adv) , 1 , zeros(1 , end_index - del_adv)]; case "unit_step" then xn = [zeros(1,abs(start_index...
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//Tested on Windows 7 Ultimate 32-bit //Chapter 12 Modulation and Demodulation Pg no. 394 clear; clc; //Given df=75D3;//maximum frequency deviation fm=20D3;//frequency of modulating wave in hertz //Solution BW=2*(df+fm);//bandwidth for FM wave printf("Bandwidth required in FM wave transmission B = %d k...
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clear // // // //Variable declaration ni=2.5*10^19; //concentration(per m^3) d=4.4*10^28; //density(per m^3) n=4*10^8; //number of Ge atoms //Calculation Na=d/n; //density of acceptor atoms np=ni^2/Na; npbyni=np/ni; //ratio of density of electrons //Result printf("\n ratio of...
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load InstructionDecoder.hdl, output-file InstructionDecoder.out, compare-to InstructionDecoder.cmp, output-list c%B1.6.1 outA%B1.9.1 outB%B1.9.1; set c %B101010, eval, output; set c %B111111, eval, output; set c %B111010, eval, output; set c %B001100, eval, output; set c %B110000, eval, output; set c %B001101, ev...
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clc; clear; Mt=2000;//kg g=9.8;//m/s^2 c0=200;//$ c1=56;//$/m c2=0.1;//$/m^2 vc=20;//m/s kc=3;//kg/(s*m^2) z0=500;//m t=27; r=2.943652; n=6; A=2*%pi*r*r; l=(2^0.5)*r; c=3*A; m=Mt/n; function y=f(t) y=(z0+g*m*m/(c*c)*(1-exp(-c*t/m)))*c/(g*m); endfunction while abs(f(t)-t)>0.00001 t...
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clear; clc; disp('Example 7.3'); // aim : To determine // the specific entropy of steam // Given values P = 1.5;//pressure,[MN/m^2] T = 273+300;//temperature,[K] // solution // (a) // from steam table cpl = 4.187;// [kJ/kg K] Tf = 471.3;// [K] hfg = 1946;// [kJ/kg] cpv = 2.093;// [kJ/kg ...
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//All the quantities are in SI units M_inf = 2; //freestream mach number p_inf = 101000; //freestream static pressure rho_inf = 1.23; //freestream density T_inf = 288; //freestream temperature R = 287; //gas constant of air a = 5; //angle of wedge in degrees p_upper = 131000; //pressure on upper surface p_lower...
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clc //initialisation of variables sm= 13.6 so= 0.8 di= 8 //in dt= 4 //in K= 0.98 v= 1//ft g= 32.2 //ft/sec^2 //CALCULATIONS s= sm/so dp= v*12*(s-1)/12 A= %pi*(di/12)^2/4 At= %pi*(dt/12)^2/4 C= A*sqrt(2*g)/(sqrt((A/At)^2-1)) Q= C*sqrt(v*12+dt)*K //RESULTS printf ('Discharge passing through the pipe= %....
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lines(0); ilib_verbose(0); ierr = exec('loader.sce', 'errcatch'); if ierr <> 0 then disp(lasterror()); exit(ierr); end // First create some objects using the pointer library. printf("Testing the pointer library\n") a = new_intp(); b = new_intp(); c = new_intp(); // Memory for result intp_assign(a, 37); intp_assig...
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; @Harness: disassembler ; @Result: PASS section .text size=0x00000020 vma=0x00000000 lma=0x00000000 offset=0x00000034 ;2**0 section .data size=0x00000000 vma=0x00000000 lma=0x00000000 offset=0x00000054 ;2**0 start .text: label 0x00000000 ".text": 0x0: 0x80 0x03 fmuls r16, r16 0x2: 0x90 0x03 ...
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//Example 9.17 //Particular Solution //Page no. 298 clc;clear;close; x=poly(0,'x') n=2; f=x^(n)-3*x^(n-1)+2*x^(n-2); z=roots(f) disp(z,f) printf('\t\t n\nC.F. = (c1+n*c2) (%g)',z(1)) A=[-4,0;2,-2]; B=[2;0]; C=inv(A)*B; printf('\n\n\t 2\nP.I = (%g)n+(%g)n',C(1),C(2))
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//Chapter-4,Example 13,Page 96 clc; close; q_rev= 12.19 //latent heat n= 32 //mols T= 273-182.9 //temperature in Kelvin dS= q_rev*n/T printf('the change of molar entropy is %.2f J/mol',dS)
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clc //initialization of varaibles h0=191.81 //B/lb Pr0=5.526 w=1 //lb/sec Pratio=0.53 k=1.4 T0=800 //R cp=0.24 P0=150 //psia P2=15 //psia //calculations Prt=Pratio*Pr0 disp("From keenan and kaye steam tables,") Pr=2.929 Tts=668 //R hts=159.9 //B/lb Vts=sqrt(2*32.2*778*(h0-hts)) vts=53.34*Tts/(Pt*144) ...
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// Three-Phase Circuits :example 6.29 :(pg 6.31) S=10*10^3; pf=0.342; x=(S/sqrt(3)); phi=acosd(pf); W1=x*cosd(30+phi); W2=x*cosd(30-phi); printf("\nS=10kVA \npf=0.342 \nS=sqrt(3)*VL*IL"); printf("\nVL*IL=%.f VA",x); printf("\ncos(phi)=%.3f",pf); printf("\nphi=%.f degrees",phi); //(i)when power factor is lead...
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sin1Data = read(get_absolute_file_path("LoadSinData.sce") + "..\Data\sin_log1pi.txt", -1, 2) sin1Data(:, 1) = sin1Data(:, 1)*%pi/180 sin2Data = read(get_absolute_file_path("LoadSinData.sce") + "..\Data\sin_log2pi.txt", -1, 2) sin2Data(:, 1) = sin2Data(:, 1)*%pi/180 sin3Data = read(get_absolute_file_path("LoadSinData....
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clear() x1= input("valor de x1: ") x2 = x1 function y=f(x1) y=(x1^7)-1000 endfunction for i = 0:9 x2 = x1-(f(x2)/numderivative(f,x2)) y1 = numderivative(f,x1) disp(x2,"el valor de"+ string(i)+ " :" ) x1 = x2 end exec("...
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clc //initialisation of variables E= 0.232 //v R= 0.0592 p= 1 //atm R1= 0.0296 P= 740 //atm //CALCULATIONS pH= E/R pH1= (E-R1*log10(P/760))/R e= pH1-pH //RESULTS printf (' error in pH of solution= %.3f ',e-0.002)
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// 08.05.19 // 08.05.20 debugged // 08.06.02 // Structure changed // 09.10.11 function M=Mixsub(Rg,PL) M=list(); N=Mixlength(PL); for I=Rg if I>N return; end; M($+1)=PL(I); end; endfunction
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//EXAMPLE 7-8 PG NO-442 Y11=0.5; Y21=-0.1; Z1=0.1; Z2=0.9; Z=(Z1*Z2)/(Z1+Z2); disp('i) Impedance (Z) is in rectangular form = '+string (Z) +'mho '); I1=10*Z; disp('ii) Current (I) is in rectangular form = '+string (I1) +'A '); V11=I1/I1; disp('i) VOLTA...
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//example 3.14// clc //clears the screen// clear //clears all existing variables// moh=10^-3; //maximum output HIGH state current// mol=20*10^-3; //maximum output LOW state current// mih=50*10^-6; //maximum input HIGH state current// mil=2*10^-3; //maximum input LOW state current// a=mol/mil; b=moh/mih; ...
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PL/SQL Developer Test script 3.0 17 --每次增加100元 -- Created on 2019/3/20 by J.Z declare -- Local variables here var_sal emp.sal%TYPE; var_moeny emp.sal%TYPE:=0; begin -- Test statements here SELECT SAL INTO var_sal FROM emp WHERE ename = 'SCOTT'; WHILE var_moeny < 10000 LOOP --工资每次增加100 ...
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//Caption:Find the (a)current supplied by each generator (b)output voltage (c) output KW of each machine //Exa:2.18 clc; clear; close; V_t1=280;//terminal voltage of generator-1 in volts V_nl1=240;//no-load voltage of generator-1 in volts V_t2=300;//terminal voltage of generator-2 in volts V_nl2=240;//no-load v...
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//chapter 12 //example 12.11 //page 498 printf("\n") printf("given") rs=600;Ie1=1*10^-3;hfe=50;R1=120*10^3;R2=47*10^3;f1=150;Ie2=2*10^-3;R5=3.3*10^3;R3=12*10^3;Rl=100; re=26*10^-3/Ie1 hie=(1+hfe)*re Zi=(R1*R2*hie)/(R1*R2+R1*hie+R2*hie) Xc1=(Zi+rs)/10 C1=1/(2*3.14*f1*Xc1)//use 6*10^-6 as standard value Xc2=.6...
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// ELECTRIC POWER TRANSMISSION SYSTEM ENGINEERING ANALYSIS AND DESIGN // TURAN GONEN // CRC PRESS // SECOND EDITION // CHAPTER : 13 : SAG AND TENSION ANALYSIS // EXAMPLE : 13.1 : clear ; clc ; close ; // Clear the work space and console // GIVEN DATA c = 1600 ; // Length of conductor in feet L = 500 ; //...
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getd ('../../libs/') img = readpbm('Encelade_surface.pbm'); xmax = size(img,1); ymax = size(img,2); xcoord = 0; ycoord = 0; value = 0; for x=1:xmax for y=1:ymax if(img(x,y) >= value) then value = uint8(img(x,y)); xcoord = x; ycoord = y; end end end disp(xco...
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function lcaGetEnumStrings // Retrieve the symbolic values of all ENUM states of a number of PVs. // // Calling Sequence // //enum_states = lcaGetEnumStrings(pvs) // // Description // // Retrieve the symbolic values of all ENUM states of a number of PVs. // Some PVs represent a selection of a particular value fro...
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//EXAMPLE 3.5 //DTFT of unit sample sequence clc; clear; //a=0.5; n=0:9; x = [1,zeros(1,9)]; disp(x,'x[n] = ') K = 4; k = 0:4/1000:4; W = k*2*%pi/K; X = (x)*exp(%i*n'*W); disp(X,'DTFT,x[n] --> ') X_mag = abs(X); X_phase = phasemag(X);//no phase exists figure(0); plot2d3(mtlb_fliplr(W),X_mag); xtitle('Magnitude plot...
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// Grob's Basic Electronics 11e // Chapter No. 09 // Example No. 9_1 clc; clear; // Apply Kirchhoff’s current law to solve for the unknown current, I3. // Given data I1 = 2.5; // Branch 1 Current=2.5 Amps I2 = 8; // Branch 2 Current=8 Amps I4 = 6; // Branch 3 Current=6 Amps I5 = 9; //...
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s=%s; r=%r; p=s^5+6*s^4+15*s^3+30*s^2+44*s+24 r=routh_t(p) m=coeff(p) l=length(m) c=0; for i=1:l if (r(i,1)<0) c=c+1; end end if(c>=1) printf("System is unstable") else("Sysem is stable") end
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// page no 438 //problem no 10.3 clc; m=input("enter the number of faces = ");// m = 6 n=input("enter the number of dice = ");// n = 2 l=m^n ;// j is total number of outcomes = 36 a=input("enter the number which is to be obtained as the sum of dice = ") // a=7 c=0 ; // counter value for favorable outcome for i...
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clc clear P1=1; P2=10; Vs=0.015; FAD=3; Vc=Vs*0.06; n=1.3; T1=20+273; IP=[n/(n-1)]*[P1*100*3]*[((P2/P1)^((n-1)/n))-1]; printf('Indicated Power= %2.1f kW',IP/60); printf('\n'); V4=Vc*[(P2/P1)^(1/n)]; V1=Vs+Vc; V14=0.0107; RS=3/V14; printf('Rotation Speed= %2.0f RPM',RS); printf('\n'); Tf=288; Pf...
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//Example 17.5// a=1.107;//eV //band gap b=2;//eV //given c=0.1;//eV //Fermi level shifted upward E=(a/b)-c mprintf("E = %f eV",E) k=86.2*10^-6;//eV k^-1//Boltazmann constant T=298;//K //Temperature fE=1/((%e^(E/(k*T)))+1) mprintf("\nfE = %e ",fE)
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function [y] = generaTempo() lambda = .2; y= -1/lambda * log(grand(1,1,'def')); endfunction function [y] = generaServizio() mu = .5; sigma = .1; y = mu + sigma * (sum(grand(12,1,'def')) - 6); endfunction Tmax = 10; function [A,D,Tp] = simulaCoda() tc = 0; // tempo corrente NA = 0; ...
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//exapple 13.6 clc; funcprot(0); // Initialization of Variable b=4.46*10^4; c=1.98*10^4; s=0; function[a]=intregrate() s=0; for i=1:10889 d=linspace(0,10000,10889); y=(1-exp(-b*d(i))*c*(1-exp(-c*d(i))))*0.69;; s=s+y; end a=y; endfunction a=intregrate...
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#----------------------------------------------------------------------------- # Position evaluation tests involving seki on the 9x9 board. # All these positions are win for white so the uct_value should be high. #----------------------------------------------------------------------------- #-------------------...
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// Exa 7.2 clc; clear; close; format('v',6) // Given data I_DSS = 30;// in mA V_GSoff = -8;// in V V_GS = -5;// in V // The value of drain current I_D = I_DSS * ((1-(V_GS/V_GSoff))^2);// in mA disp(I_D,"The value of drain current in mA is");
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//Example 11.3.1 // percentage of the reading and percentage of full scale clc; clear; close; //given data : a=10;//scale reading b=70;// full scale error1=-(0.5/10)*100; disp("step 1") disp(error1,"error of reading in %") error2=-(0.5/100)*100; disp(error2,"error of full scale in %") disp("step 2") error3=(2.5/70)*100...
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// Example 1.3: standard resistor clc, clear vf=1.8; // in volts if=16*10^-3; // in ampere vo=8; // in volts rs=(vo-vf)/if; // resistor in ohm disp(rs,"standard resistor (ohm) = ")
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function euler(x0,y0,xn,h) while(x0<=xn) printf("%f \t %f \t", x0,y0); y1= y0 +h*((y0-x0)/(y0+x0)); x0=x0+h; y0 =y1; end disp(y1); endfunction
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//Copyright INRIA Eps =1.e-5 // Example of use of ode function: // System to solve: // dy1/dt = -0.04*y1 + 1.e4*y2*y3 // dy2/dt = 0.04*y1 - 1.e4*y2*y3 - 3.e7*y2**2 // dy3/dt = 3.e7*y2**2 // on the interval from t = 0.0 to t = 4.e10, with initial conditions // y1 = 1.0, y2 = y3 = 0. the problem is s...
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function [avti_gt_mt, avti_gt_nt, op_gt_mt, op_gt_nt, ge_gt_delete_mt, ge_gt_delete_nt, ge_gt_delete_low] = global_test2(Q_mt, Q_nt, gamaMeasuremts, gamaNodal, runsize, rj, jac_col, jac_row) // GLOBAL TEST MEASUREMENT ERRORS //Q=0.1; P=1-Q_mt; xchi=cdfchi("X",rj,P,Q_mt); printf('xchi MT: %f \n', xch...
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//ex7.6 I_D=6.25*10^-3; V_GS=-5; R_G=abs((V_GS/I_D)) disp(R_G,'Gate resistance in Ohms')
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function distance = euclidianDistance(instance1, instance2, len) distance = 0 for x = 1:len distance = distance + (instance1(x) - instance2(x))^2 end distance = sqrt(distance) endfunction function sortedTable = msort(table, sortBy, direction) len = size(table, 1) sortedTable = [] [a, h] = gsort(table...
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a=10; b=4; function xd=linear832(t,x) xd(1)=a-x(1)-((4*x(1)*x(2))/(1+x(1)^2)); xd(2)=(b*x(1))*(1-(x(2)/(1+x(1)^2))); //x(dot); x(2) means y. //y(dot); x(1) means x.; endfunction bound=[0,0,4,10]; //Bounds of x-axis and y-axis as [xmin ymin xmax ymax], change t...
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function f=%r_f_s(f,m) // [f;m] [rational;constant] //! // Copyright INRIA f=rlist([f('num');m],[f('den');ones(m)],f('dt'))
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clear;lines(0); E=[1,2;3,4] E=[%T,%F;1==1,1~=1] s=poly(0,'s');E=[s,s^2;1,1+s] E=[1/s,0;s,1/(s+1)] E=['A11','A12';'A21','A22']