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clc clear clf(); // clear and reset a figure t=0:%pi/20:2*%pi; plot(t,sin(t),'ro-.',t,cos(t),'cya+',t,abs(sin(t)),'--mo')
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clc clear //Input data p=4//Pressure ratio T3=1000//Turbine inlet temperature in K T1=15+273//Inlet temperature in K p1=1//Inlet pressure in kg/cm^2 m=11//Mass flow rate of air in kg/s Cp=0.24//Specific heat at constant pressure in kJ/kg.K R=29.27//haracteristic gas constant in kg.m/kg.K g=1.4//Ratio of speci...
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codeblock readtextfile(ScriptDir+"\_TOOLS.sci"); sf=T_scene_create; sss=T_getscene; myviewport=T_getviewport; myviewport.focaldistance=7; sss.ambientlightcolor=color(0.05,0.05,0.05); rootframe=sss.Universe; createnew=true; tx=rootframe.createtexture("star",DataDir+"\textures\star2.bmp"); pe=rootframe.add("PEngine")...
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function result = check_mdaq_compiler() result = isfile(mdaq_toolbox_path() + "rt_templates"+filesep()+"target_paths.mk"); endfunction
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//Problem 32.03: Use the superposition theorem to obtain the current flowing in the (4 + i3) ohm impedance of Figure 32.16. //initializing the variables: rv1 = 30; // in volts rv2 = 30; // in volts thetav1 = 45; // in degrees thetav2 = -45; // in degrees R1 = 4; // in ohm R2 = 4; // in ohm R3 = %i*3; // in oh...
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clear; clc ; close ; t=linspace(0,1,2) x=ones(2,1) plot(t,x)
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clc; clear all; disp("heat transfer rate") La=0.22;//m Lb=0.22;//m kA=3.5;// W/(m*C) kB=0.65;// W/(m*C) thf=1300;// degree C tcf=40;// degree C hconvi=16.4;//W/(m^2*C) hconvo=11.5;//W/(m^2*C) hradi=17.5;//W/(m^2*C) hrado=7.2;//W/(m^2*C) //q= qconvi+qradi=qA+qB=qconvo+qrado //q=delT/Rtotal=(thf-tcf)/Rtotal...
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//chapter-3,Example3_1,pg 67 S=2*10^-6 T=2000 A=60.2*10^4 b=52400//Q/K e=1.6*10^-19 I=A*S*(T^2)*(%e^(-(b/T))) J=A*(T^2)*(%e^(-(b/T))) no=J/e printf("maximum obtainable electronic emission current\n") disp(I) printf("\nemission current density\n") printf("J=%.3f A/m2",J) printf("\n...
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//Ex6_7 clc VCC = 12 VBB = 3 IC = 12*10^-3 VCE = 5.5 beta = 100 VBE = 0.7 Re = 50 disp("VCC = "+string(VCC)+"V")//collector supply voltage disp("VBB = "+string(VBB)+"V")//base supply voltage disp("IC = "+string(IC)+"A")//collector current disp("VCE = "+string(VCE)+"V")//voltage across collector and emitter ...
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// SCILAB // // Funções de Entrada e Saída // whos; // Exibe as constantes do programa // FUNÇÕES DE SAÍDA // // Exibir variáveis na tela do console disp(%pi); // Imprime variáveis em um arquivo (a variável deve ser definida pelo usuário) piNumber = ...
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load IsZero16.hdl, output-file IsZero16.out, compare-to IsZero16.cmp, output-list in%B1.16.1 out%B3.1.3; set in %B0000000000000000, eval, output; set in %B0000000000000001, eval, output; set in %B1000000000000000, eval, output; set in %B1010101010101010, eval, output; set in %B00111100110000...
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//Ex10.2.8.2;calculate voltage output of cell,efficiency,electric work output,heat transfer to the surroundings //1] voltage output of cell del_G=-237.3*10^3;//Joules/gm-mole of H2 n=2; F=96500;//Faraday's constant E=-del_G/(n*F); printf(" E=%f volts",E); //2] Efficiency //nmax=del_Wmax/-(del_H)25 degree celc...
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//Draw trajectory close(); // Aquesta funció requereix l'execució de l'script inverseDelta.sce. Totes les // subrutines estan en aquest arxiu. Abans, però, cal definir els paràmetres de // la màquina al mateix inverseDelta.sce (els trobareu a la capçalera). L'usuari // ha de modificar el següent: startPoint = [-0.15, ...
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// Example 13.15 Vl1=3300; // The supply voltage Vph1=Vl1/1.732; // Primary phase voltage N1=840; // No.Of Turns in Primary winding N2=72; // No.Of Turns in secondary winding Vph2=Vph1*(N2/N1); // Secondary phase voltage Vl2=Vph...
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function [y1,y2,y3] = fn_f1(x1,x2,x3,x4); y1 = x1 + x2; y2 = x2 + x3; y3 = x3 + x4; endfunction
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function [x] = solinf(L, b) // L matrice carrée triangulaire inférieure dans Rnn // b un vecteur de Rn // Retour : x un vecteur de Rn qui résoud Lx = B n = size(b, 1); if (size(L, 1) <> n) | (size(L, 2) <> n) then error("Dimensions incohérentes"); end x = zero...
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//example 12.2 clc; funcprot(0); // Initialization of Variable rho=1.22;//density of air pi=3.1428; rhos=910;//density of polyethene d=3.4/1000;//dia of particles mu=1.73/10^5; g=9.81; dt=3.54/100;//dia of duct //calculation a=2*d^3*rho*g*(rhos-rho)/3/mu^2; disp(a,"R/rho/U^2*(Re^2)="); //using Chart ...
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clc clear //Inputs //The Values in the program are as follows: //Temperature in Celcius converted to Kelvin(by adding 273) //Pressure in bar converted to kPa (by multiplying 100) //Volume in m^3 //Value of R,Cp and Cv in kJ/kg K P1=100; V1=0.25; T1=100+273; V2=0.05; P2=750; G=1.4; R=0.298; n=(log(P2/P1...
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// ============================================================================= // gfx4scilab - ui // dgerod@xyz-lab.org.es // ============================================================================= //------------------------------------------------------------------------------ // MessageBox //---------...
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clear;lines(0); A=[1,2;3,4]; cosm(acosm(A))
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//Page Number: 22 //Example 1.9 clc; //Given ZL=75+(%i*100); //ohms Z0=50; //ohm //Normalized load impedance z=ZL/Z0; disp(z,'Normalized load impedance:'); //(i) 0.051*lam //From chart r=4.6; Zi1=r*Z0; disp('ohm',Zi1,'Input impedance at 0.051 lam:'); //(ii) 0.102*lam r1=1.5-(%i*2); Zi2=r1*Z0; dis...
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errcatch(-1,"stop");mode(2);//Initilization of variables v_pc=3.68 //ft/s l=2 //ft //Calculations w=v_pc/l //rad/s counterclockwise //Result printf('The angular velocity is %frad/s',w) exit();
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// Example 1.2: Gain of transistor amplifier // Amplifier has transfer characteristics v_O=10-(10^-11)*(exp^40*v_1) applies for v_1 is greater than or equal 0V and v_o is greater than or equal to 0.3V L_l = 0.3; // limit L_- disp(L_l,"The limit L_- (V) =") v_I=1/40*log((10-0.3)/10^-11); // from the transfer charact...
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// Example 7.3.f: fracture stress clc; clear; close; format('v',10) yl=40;//yeild load in kN ml=71.5;//maximum load in kN fl=50.5;//fracture load in kN glf=79.5;//gauge length of fratture in mm st=7.75*10^-4;//strain at load of 20kN d=12.5;//specimen diamtere in mm sl=62.5;//specimen length in mm A=(%pi*(d*10^-3)^2)/4;...
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// // Na teoria do transporte de nêutrons, // o comprimento crítico de uma barra de combustível nuclear (fuel rod) // é determinado pelas raízes da equação // cot(x) = (x^2 - 1)/(2*x) // Encontre a menor raiz positiva desta equação. // // Solução: // cot(x) = (x^2 - 1)/(2*x) => f(x) = (x^2 - 1)/(2*x) - cot(x) = 0 // ...
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// Ex20_2 Page:391 (2014) clc;clear; q = 1.6e-019; // Charge on an electron, C e = 1.6e-019; // Energy equivalent of 1 eV, J/eV m = 1.67e-027; // Mass of a proton, kg B = 2; // Applied magnetic field, T R = 0.25; // Maximum radius of cyclotron, m f = q*B/(2*%pi*m); // Frequency needed for apply...
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// calculating the closed loop gain clc; Rf=10; R1=1; Avol=200000; A=-(Rf/R1)*(1/[1+(1/Avol)*((R1+Rf)/R1)]); disp(A,'closed loop gain=')
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clear //Given r=3.4*10**-14 //m n=47 q=1.6*10**-19 //C m=9*10**9 //Calculation V=m*n*q/r //Result printf("\n Electric potential at the surface of silver nucleus is %0.2f *10**6 V",V*10**-6)
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/////////////////////////////////////////////////////////////////////////////// // Author: Jia Wu // Date: Feb. 2010 // Description: stepwise optimal hierarchical clustering // // Copyright (C) 2009 OpenPR // All rights reserved. // // Redistribution and use in source and binary forms, with or without /...
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//Example 3.3.1 page 3.25 clc; clear; r1= 0.32; r2= 0.32; alpha= 10; L= 500*10^-4; temp=log(1/(r1*r2)); Tgth = alpha + (temp/(2*L)); printf("The optical gain at threshold is %.2f /cm",Tgth);
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function [x,y,typ] = hart_sciencemode(job,arg1,arg2) //Stimulator Interface (RehaStim - Hasomed GmbH) // // Block Screenshot // // Description // // Current // // This input should be an array of values representing the currents desired on the channels specified in the block parameters. Thus if the specified...
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//SHM //r*sind(theta1)=0.2 //r*omega*cosd(theta1)=0.5 //r*sind(theta2)=0.3 //r*omega*cosd(theta2)=0.35 //thus theta1=asind(0.44) r=(0.2)/(sind(26.1)) //m omega=1.225 //rad/sec^2 vmax=0.454*1.225 //m/sec amax=-0.454*1.225^2 //m/sec^2 f=(1.225)/(2*%pi) //osc. per sec printf("\namax=%.3f m/sec^2\nf=%.3f o...
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clc p1=1*10^5; //Pa T1=293; //K d=6; //m; diameter of the spherical balloon p2=0.94*p1; T2=T1; cv=10400; //J/kg K R=8314/2; r=3; //m disp("(i) Mass of original gas escaped") //dm=m1-m2 //dm=(p1-p2)*V1/R/T1 //m1=p1*V1/R/T1 %mass_escaped=(p1-p2)/p1*100; disp("%mass_escaped =") disp(%mass_escaped) di...
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// Scilab code Ex5.13: Pg 163 (2008) clc; clear; R_c = 40; // Resistance of coil, ohm I_fsd = 5e-04; // Full-scale deflection current, A I = 3; // Current reading, A V_c = I_fsd*R_c; // Potential difference, V // Since ...
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//Fluid Systems - By - Shiv Kumar //Chapter 11- Centrifugal Pumps //Example 11.7 //To Determine the Impeller Speed and Torque produced by it. clc clear //Given Data:- Q=60; //Discharge, litres/s Ri=75; //Radius of the Impeller at Inlet, mm Ro=150; //Rad...
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//Determine the greatest number of half-waves of electric intensity which it will be possible to establish between the two walls and also determine the guide wavelength for this mode of propagation vc = 3e+10; f = 10e+9; d = 6; m1 = 1; m2 = 2; m3 = 3; m4 = 4; lambda = vc/f; lambda01 = (2*d)/m1; lambda02 =...
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clc //Given that b_e = 13.6 // Binding energy of electron to proton in eV c= 3e8 // speed of light in m/s // sample problem 15a page No. 306 printf("\n\n\n # Problem 15a # \n") printf("\n Standard formula used E = m*c^2") del_m = b_e * (1.6e-19) / c^2 * 1000 printf ("\n Loss in mass during formation of 1 ato...
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// Y.V.C.Rao ,1997.Chemical Engineering Thermodynamics.Universities Press,Hyderabad,India. //Chapter-7,Example 14,Page 262 //Title: Enthalpy of vaporization using Riedel's correlation //================================================================================================================ clear clc ...
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////Variable Declaration m = 0.5 //Mass of water, kg ms = 24.0 //Mass of solute, g Ms = 241.0 //Molecular wt of solute, g/mol Tfd = 0.359 //Freezinf point depression, °C or K kf = 1.86 //Constants for freezing point depression for water, K kg/mol //Calculations msolute = ms/(Ms*m) ...
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//Example 2.5.4 page 2.30 clc; clear; n2= 1.48; del = 0.2; lamda = 1320; Dw = -n2*del*0.26/(3*10^5*lamda); Dw=Dw*10^10; //converting in picosecs.... printf("The waveguide dispersion is %.3f picosec/nm.Km",Dw);
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//Ex:2.28 clc; clear; close; E=2.5;//energy in joules L=20*10^-3;//in henry I=sqrt(E/(0.5*L)); printf("Current = %f A",I);
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// funcao function y=f(x) y = 8*x^7 - 12*x^3 + 5 endfunction // derivada literal da funcao function y=fl(x) /* x=poly(0,'x') // cria um polinomio x * y=derivat(8*x^7 - 12*x^3 + 5) // calcula a derivada de f(x) */ y=8*7*x^6 - 12*3*x^2 endfunction /* grafico pra ver onde estao as raized de f(x) pa...
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// Copyright INRIA files=G_make(['/tmp/ex4fi.o'],'ex4f.dll'); addinter(files,'fdgemmentry','dgemm'); alfa=2;beta=3;m=3;n=4;C=ones(m,n);k=2;A=ones(m,k);B=ones(k,n); C1=dgemm(alfa,A,B,beta,C); if norm(C1-(alfa*A*B+beta*C)) > %eps then pause,end
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// Aplicação do método de Runge-Kutta 3/8 na resolução de um Sistema Massa-Mola com Amortecimento clear clc function F = f1(t, y, v, m, c, k) // Derivada de y em relação a t F = v; endfunction function F = f2(t, y, v, m, c, k) // Derivada de v em relação a t A = c/m; B = k/m; F = -(A*v +...
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//Chapter-5, Example 5.34, Page 197 //============================================================================= clc clear //INPUT DATA R=20;//resistance in ohms L=0.2;//inductance in H C=100;//capacitance in uF //resistance will be non-inductive only at reosnant frequency //CALCULATIONS fr=(1/(2*%pi*(sqr...
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// Copyright (C) 2012 - Prateek Papriwal // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCI...
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function mdaqDIOWrite(arg1, arg2, arg3) if argn(2) == 2 then dio = arg1; state = arg2; end if argn(2) == 3 then link_id = arg1; dio = arg2; state = arg3; if link_id < 0 then error("Invalid connection id!") end end if argn(2) > 3...
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clc //initialization of variables P=100 //lb/in^2 T=470 //F T2=500 //F T1=450 //F //calculations disp("From table 4 of appendix,") v1=5.268 v2=5.589 v=v1+2*(v2-v1)/5 //results printf("Specific volume at %d F = %.3f ft^3/lbm",T,v)
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// Additional solved examples , Example 6 , pg 332 n1=1.5//core refractive index n2=1.45//cladding refractive index n0=1//refractive index of air NA=sqrt(n1^2-n2^2)//numerical aperture alpha_m =asin(NA/n0)//angle of acceptance (in radian) phi_m=asin((n0*sin(alpha_m))/n1)// no*sin(alpha_m)=n1*sin(phi_m) (in ra...
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//chapter-9 page 412 example 9.5 //============================================================================== clc; clear; J=33000;//Current density in A/sqcm Na=2.5*10^16;//Doping Concentation in TRAPATT diode per cubic cm q=1.6*10^(-19);//Charge of an Electron in C //CALCULATION Vz=(J/(q*Na))/10^5;//Av...
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clc //initialisation of variables td3=15 //dew point temparature ps3=0.017039 //bar pressure phi3=0.55 //relative humidity p=1 //bar pressure ps4=0.029821 //bar pressure phi4=1 //relative humidity td4=24 //temp in degrees mw1=1000 //kg/min hf1=109 //kj/kg hf2=50.4 //kj/kg w4=0.01912 w3=0.00588 //CALCULATI...
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//Problem 9.13: A 750 turn coil of inductance 3 H carries a current of 2 A. Calculate the flux linking the coil and the e.m.f. induced in the coil when the current collapses to zero in 20 ms //initializing the variables: I1 = 2; // in Amperes I2 = 0; // in Amperes dt = 0.020; // in secs N = 750; //turns L = 3; ...
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global file_name path fname extension chip_num board_num brdtype macrocab_name folder_name bl_level; function dir_callback() disp(" "); endfunction function MC_folder_name_callback() global folder_name; folder_name_obj = findobj('tag','MC_folder_name'); folder_name = folder_name_obj.string; endfunct...
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//Ex:90 clc; clear; close; t_a=60;// antenna noise temp in k l1=1.075;//loss in waveguide in K t_o=290;// in K t_e2=160;// in K; t_e3=10000;// in k G2=10^6;// low noise ampr gain t_eq=(l1-1)*t_o+(t_e2*l1)+(t_e3*l1)/G2;// in K t_s1=t_a+t_eq;// in k T_s1=10*log(t_s1)/log(10);// in db G=66;// in db g_t1=G-T_...
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pathname=get_absolute_file_path('21_2.sce') filename=pathname+filesep()+'21_2data.sci' exec(filename) clear Mx=-Sy*(L-Lc);//moment at section L3=(L1*(L-Lc)+ L2*Lc)/L;//leangth of CS B3=(B1*(L-Lc)+ B2*Lc)/L;//breadth of CS Ixx=4*Aco*(B3/2)^2 + 2*Ace*(B3/2)^2; B=[Aco;Ace;Aco;Aco;Ace;Aco]; Y=[B3/2;B3/2;B3/2;-B3/2...
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showtime; comment some examples of the FOR statement; comment summing the squares of the even positive integers through 50; for i:=2 step 2 until 50 sum i**2; comment to set w to the factorial of 10; w := for i:=1:10 product i; comment alternatively, we could set the elements a(i) of the array ...
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//Example_a_4_12 page no:180 clc; f=10*10^3; Vrms=10; L=50*10^-3; Xl=2*%pi*f*L; Irms=Vrms/Xl; Irms=Irms*1000;//converting to mA disp(Irms,"the rms current is (in mA)");
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// Example 13.5: Supply voltage, Peak current drawn from each supply, Total supply power, Power conversion efficiency, Maximum power that each transistor can dissipate safely clc, clear P_ac=20; // Average power delivered in watts RL=8; // Load in ohms Vm=sqrt(2*P_ac*RL); // Peak output voltage in volts VCC=Vm+5; ...
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//Page Number: 11.27 //Example 11.25 clc; //Given p=0.9; Px=[p (1-p)]; n=1; //Average Code length //L=Summation(P(xi)ni) L=0; for i=1:2 L=L+(Px(i)*n); end //As H(X)=-Sum of[P(xi)log2P(xi)] //Where i=0 to n; HofX=0; for i=1:2 HofX=HofX+(Px(i)*log2(Px(i))); end //Efficiency=H(X)/L n=-H...
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function x=mpow(a,p) // mpow - A^p //%CALLING SEQUENCE // X=mpow(A) //%PARAMETERS // A : square hermitian or diagonalizable matrix // X : square hermitian matrix //%DESCRIPTION //This macro is called by the operation ^ to compute A^p //! [m,n]=size(a) if m<>n then error(20,1),end flag=or(a<>a') if ~flag the...
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// Exa 6.14 clc; clear; close; format('v',6) // Given data R1 = 100;// in ohm R2 = R1;// in ohm R3 = 3.9;// in k ohm R3 = R3 * 10^3;// in ohm R_F = R3;// in ohm Vx = -3.2;// in V Vy = -3;// in V // output voltage due to Vx, Vox = -(R_F/R1)*Vx and due to Vy, Voy = (R3/(R2+R3)) * (1+(R_F/R1))*Vy // Vo = Vox...
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## Test path rename capability with selection set read <sample1.fi :19..$ path README rename REAMDE write -
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//To Calculate the Capacitance of a parallel plate capacitor //Example 31.3 clear; clc; a=20*10^-2;//Length of Side of Parallel Plate Capacitor A=a^2;//Area of the Capacitor Plate d=1*10^-3;//Separation between the two plates e0=8.85*10^-12;//Permitivity in farad/meter C=e0*A/d;//Formula for fi...
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//Example 5.18 clc disp("The cascading of demultiplexers is similar to the cascading of decoder. Fig. 5.33 shows cascading of two 1 : 4 demultiplexers to form 1 : 8 demultiplexer.")
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//water and its treatment// //example 2.18.7// clc Hardness_ppm=304//ppm in terms of CaCO3// Cl=0.07*Hardness_ppm//0.07 °Clarke =1 ppm// Fr=0.1*Hardness_ppm//0.1 °French =1 ppm// mgperlit=Hardness_ppm printf("Hardness in terms of °Clarke %.2f °Cl",Cl); printf("\nHardness in terms of °French %.1f °Fr",Fr); prin...
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// 2.30 clc; Se_thermocouple=500-(-72); printf("Sensitivity of thermocouple= %.1f micro V/degree C",Se_thermocouple) Vo=Se_thermocouple*100*10^-6; printf("\nMaximum output voltage= %.2f V ",Vo)
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//example 11 //turbine inlet pressure clear clc hi=1757.3 //initial specific heat of enthalpy of air in kJ/kg si=8.6905 //initial specifc entropy of airin kJ/kg-K he=855.3 //final specific heat of enthalpy of air in kJ/kg w=hi-he //actual work done by turbine in kJ/kg n=0.85 //efficiency of turbine ws=w/n //...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Engineering Thermodynamics by Onkar Singh Chapter 9 Example 3") T1=(100+273.15);//temperature at beginning of compresssion in K P1=103;//pressure at beginning of compresssion in KPa Cp=1.003;//specific heat at c...
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clear // // // //Variable declaration lamda=6000*10**-8 //wavelength(cm) n=1 mew=1.5 //refractive index r=50*%pi/180 //angle of refraction(radian) //Calculation t=n*lamda/(2*mew*cos(r)) //least thickness of glass plate(cm) //Result printf("\n least thickness of glass plate is %0.2f *10**-5 cm",t...
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//Finding of Kinematic Viscosity //Given tau=0.2158; //Shear stress in N/m^2 vg=0.218; //Velocity Gradient in sec^-1 rho=959.5; //Density in Kg/m^3; //To Find mu=tau*1/vg; disp("Dynamic Viscosity ="+string(mu)+" Ns/m^2"); nu=mu/rho; disp("Kinematic Viscosity ="+...
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clc clear //Input data CO2=8.85//Percentage composition by volume CO=1.2//Percentage composition by volume O2=6.8//Percentage composition by volume N2=83.15//Percentage composition by volume C=84//Percentage composition by weight H2=14//Percentage composition by weight aO2=2//Percentage composition by weight ...
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// Problem no 2.1,Page no.29 clc;clear; close; //Rectangle-1 b_1=10 //cm //width of Rectangle-1 d_1=2 //cm //breadth of Rectangle-1 a_1=40 //cm**2 //Area of Rectangle-1 y_1=1 //cm //Distance of centroid-1 //Rectangle-2 b_2=2 //cm //width of Rectangle-2 d_2=10 //cm //breadth of Rectangle-2 a_2=20 //cm**2 //Area of ...
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//example 6.4 //calculate probable life of reservior clc;funcprot(0); //given asi=3.6; //annual sediment inflow(x10^6) gamma_s=12; //specific weigth of sediment vs=asi/12; ir=30; //initial reservior capacity fr=60; ...
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//Example 2.1 clc //Simple program to print "Welcome to c programming" printf("Welcome to c Programming\n"); //If new line character is used.. then program output will change scanf("%c"); clc printf("Welcome to \nc Programming\n");
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// Example 7.10.a;//inernal quantum efficiency and internal power level clc; clear; close; e=1.6*10^-19;//Electronic charge ht=6.62*10^-34;//Constt C=3*10^8;//sPPED OF LIGHT IN M/S h=1310*10^-9;//wavelength in meter tr=25;//radiative recombination time in nano second tnr=90;//non radiative recombination time i...
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// Example 1.23 clear; clc; close; format('v',7); // Given data VL=400;//in volt E1Line=VL;//in volt P=4;//no. of poles S=5;//in % f=50;//in Hz R2=0.15;//in ohm X2=1;//in ohm ratio=2;//ratio of stator to rotor turns //Calculations S=S/100;//slip E1ph=E1Line/sqrt(3);//in Volt K=1/ratio;//ratio of roto...
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//Example 16.3 clc k_e=8.99*10^9 //N.m^2/c^2 q1=5*10^-6// in C q2=-2*10^-6//in C r1=0.4 r2=0.5 V1=(k_e*q1)/(r1) V2=(k_e*q2)/(r2) disp("Solution a") disp(V1,"Magnitude of V1 in v") disp(V2,"Magnitude of V2 in v") disp("solution b") vp=V1+V2 disp(vp,"Magnitude of Vp in v") q3=4*10^-6//in C w=vp*q3 disp(w,"work done in Jo...
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function [L,U] =factorisation(A) [m,n]=size(A); for i= 1:n L(i,1) = A(i,1); end for j=1:m U(1,j)=A(1,j)/L(1,1); end for j=2:n for i=j:n res=0.0; for k= 1:(j-1) RES=RES+L(i,k)*U(k,j); ...
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// Grob's Basic Electronics 11e // Chapter No. 06 // Example No. 6_3 clc; clear; // Assume that the series-parallel circuit in Fig. 6–15a has failed. A technician troubleshooting the circuit has measured the following voltages: V1 = 10.8 V; VAB = 9 V; V4 = 16.2 V. These voltage readings are shown in Fig. 6–15b. Bas...
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// This file is part of www.nand2tetris.org // and the book "The Elements of Computing Systems" // by Nisan and Schocken, MIT Press. // File name: projects/12/MathTest/MathTest.tst load, output-file MathTest.out, compare-to MathTest.cmp, output-list RAM[8000]%D2.6.1 RAM[8001]%D2.6.1 RAM[8002]%D2.6.1 RAM[8003]%D2.6.1 R...
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// Scilab code Ex3.10 : Pg:113 (2008) clc;clear; omega1 = 0.02; // Dispersive power of the convex lens omega2 = 0.04; // Dispersive power of the concave lens f2 = -80; // Focakl length of the concave lens, cm // As omega1/omega2 = -f1/f2, solving for f1 f1 = -omega1/omega2*f2; // Focal length of the c...
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clc clear //Input data n=4//Four cylinder four stroke d=7.5//Bore in cm L=8.75//Stroke in cm r=6//Compression ratio n1=55//Efficiency in percent g=1.4//ratio of specific heats N=2400//Speed in r.p.m pm=7//Brake mean effective pressure in kg/cm^2 m=9//Mass of fuel per hour in kg CV=10500//Calorific Value in ...
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//Exa:9.5 clc; clear; close; //Given: //v1(t)=10cos(2000*pi*t)+4sin(200*pi*t); //BPF=800Hz to 1200Hz printf("Since v2=v1+0.1*v1^2 and"); printf("\n BPF=800Hz to 1200Hz "); printf("\n So,v3(t)=10*cos(2000*pi*t)+4*sin(2200*pi*t)-4*sin(1800*pi*t)");
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//chapter 4 //example 4.2 //page 153 printf("\n") printf("given") Ic=1*10^-3;Ib=25*10^-6; Bdc=Ic/Ib Ie=Ic+Ib Adc=Ic/Ie Ib=Ic/Bdc
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clear; clc; // Illustration 5.1 // Page: 114 printf('Illustration 5.1 - Page: 114\n\n'); // solution //***Data***// // a = NH3, b = H2O d = 2.54*10^(-2);// [m] Yag = 0.80; Xal = 0.05; T = 273+26.7;// [K] Kl = 2.87*10^(-5);// [kmol/square m.s.(kmol/cubic m)] Sh = 40; Da = 2.297*10^(-5);// [square m...
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clear;lines(0); S1=ssrand(2,2,3);S2=ssrand(2,2,2); W=S1/.S2; ss2tf(S1/.S2) //Same operation by LFT: ss2tf(lft([zeros(2,2),eye(2,2);eye(2,2),-S2],S1)) //Other approach: with constant feedback BigS=sysdiag(S1,S2); F=[zeros(2,2),eye(2,2);-eye(2,2),zeros(2,2)]; Bigclosed=BigS/.F; W1=Bigclosed(1:2,1:2); //W1=W (in state-s...
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//Chemical Engineering Thermodynamics //Chapter 7 //Ideal Gases //Example 7.5 clear; clc; //Given P1 = 1;//Initial pressure of air in atm T1 = 15+273;//Initial temperature in K P2 = 5;//Final pressure of air in atm T2 = 15+273;//Final temperature in K Cv = 5;//specific heat of air at constant volume in K...
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clc,clear //Example 6.11 //To determine product and ratio of complex numbers using formula //given values z1 = 6*(cosd(70)+ %i*sind(70)); z2 = 2*(cosd(31)+ %i*sind(31)); //arguements of complex numbers theta1=phasemag(z1); theta2=phasemag(z2); //modulus of complex numbers r1=abs(z1); r2=abs(z2); theta_...
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<?xml version="1.0" encoding="utf-8"?> <test> <description>Kovasznay Flow, expansion from restart file, par(2)</description> <executable>IncNavierStokesSolver</executable> <parameters>--use-scotch KovaFlow_expFromFile.xml</parameters> <processes>2</processes> <files> <file description="Sessi...
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clc T=300 //K k=8.617*10^-5 //eV/K q=1.6*10**-19 //C m0=0.91*10^-30//kg un=1300//m^2/Vs Nd=10^16//cm^3 n=Nd disp(n,"donors are ionized in cm^3 is") row=1/(q*n*un) disp(row,"resistivity in ohm cm is")
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run2"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monito...
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clc clear //Initialization of variables m=150000 //lb P1=1000 //psia Ts=900 //F Tf=200 //F //calculations disp("From mollier charts,") h2=1448.2 //Btu/lb hf=167.99 //Btu/lb correc=2.2 //Btu/lb hc=hf+correc Q=m*(h2-hc) output=Q/1000 //results printf("Output of the steam generating unit = %d kB/hr",output...
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function [f,g]=Simulador_f2(x) f = (1-x(1))^2 + 100*(x(2)-x(1)^2)^2 g_1 = -2*(1-x(1))-400*(x(2)-(x(1).^2))*x(1) g_2 = 200*(x(2)-(x(1)^2)) g = [g_1; g_2] endfunction
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<?xml version="1.0" encoding="utf-8"?> <test> <description>Kovasznay Flow P=8</description> <executable>IncNavierStokesSolver</executable> <parameters>KovaFlow_m8_short_HOBC_3D1H.xml</parameters> <files> <file description="Session File">KovaFlow_m8_short_HOBC_3D1H.xml</file> </files> <me...
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clear; clc; printf("\t\t\tProblem Number 6.9\n\n\n"); // Chapter 6: The Ideal Gas // Problem 6.9 (page no. 252) // Solution T2=500+460; //absolute final temperature //unit:R T1=80+460; //absolute initial temperature //unit:R //The equation cpbar= 0.338-(1.24*10^2/T)+(4.15*10^4)/T^2 has a form , cbar= Ada...