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realter realtered V.PTCP;PST realter realter V;NFIN realter realters V;SG;3;PRS realter realtering V.PTCP;PRS realter realtered V;PST birl birls V;SG;3;PRS birl birled V.PTCP;PST birl birling V.PTCP;PRS birl birl V;NFIN birl birled V;PST abscond absconds V;SG;3;PRS abscond absconding V.PTCP;PRS abscond abscond V;NFIN a...
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clc //initialisation of variables T= 120 //F T1= 1500 //F A= 64/144 F= 0.86 Fe= 1 s= 0.173 //BTU s^-1 in^-2 R^-4 //CALCULATIONS q= (A/10^6)*F*Fe*s*(((T1+460)^4/100)-((T+460)^4/100)) //RESULTS printf ('Heat loss= %.f Btu/hr',q)
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//chapter 4 Ex 23 clc; clear; close; bruised=1/30; unsalable=3/4; unsalableMangoes=12; totalMangoes=unsalableMangoes/(unsalable*bruised); mprintf("The total number of mangoes are %0.0f",totalMangoes);
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// Exa 6.8 clc; clear; close; // Given data x = 0.88;// dryness fraction h_fg = 2392.7;// in kJ/kg H_wet = x * h_fg;// in kJ/kg Vs = 14.67;// Specific volume in m^3/kg V_wet = x * Vs;// in m^3/kg Q = H_wet/V_wet;// in kJ/m^3 disp(Q,"Heat to be extracted in kJ/m^3 is");
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function N=normir(s) //Функция номирует входной массив //s - входной массив //N - нормированный массив N = s/max(s); endfunction
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clc; m=0.934; //v=(v/c)^2 (given) v=2.9*10^8; //velocity in m/sec t0=2.2*10^-6; //initial velocity in m/sec t=t0/sqrt(1-m); //calculating t using t=t0/sqrt(1-(v/c)^2) disp(t,"Time in sec = "); //displaying result
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clc;funcprot(0);//Example 9.11 //Initilisation of Variables dA1=4*(10^-4);.....//Area of 1st small surface in m^2 dA2=8*(10^-4);.....//Area of 2nd small surface in m^2 r=1;.....//Distance between dA1 and dA2 in m teta1=60;...// teta2=30;....// dFA1_2=(cos(teta1*(%pi/180))*cos(teta2*(%pi/180))*dA2)/(%pi*(r^2));.....
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clear clc RT_F=0.05915;//in V Ecell=0.0295;//in V A=0.1;// B=0.01;// n=(RT_F/Ecell)*(log10(A/B));// printf('n=%.1f',n) //page 459
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x = [-3 -2 -1 0 1 2 4]; y = [-1 -1 -1 0 1 1 1]; t = -3:.01:3; p = pchip(x,y,t); disp(p); //output //!--error 15 //Submatrix incorrectly defined. //at line 46 of function pchip called by : //p = pchip(x,y,t); //corresponding MATLAB o/p // MATLAB returns p as a vector of dimensions 1X601
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basis=100 //mol pf product gas xCO=0.015 xCO2=0.060 xO2=0.082 xN2=0.843
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clc; disp("Principles of Heat Transfer, 7th Ed. Frank Kreith et. al Chapter - 8 Example # 8.1 ") //Outer dia in m d = 0.0254; //mass flow rate of hot fluid in kg/s mh = 6.93; //Specific heat of hot fluid n J/kgK ch = ...
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//Example 8.5 clc;clear;close; s=poly(0,'s'); z=poly(0,'z'); T=1; Hs=1/(s+1)/(s+2); Hz=horner(Hs,(1-1/z)/T); disp('Using Impulse Invariant Technique:') disp(Hs,'H(s)='); disp(Hz,'H(z)=');
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function rst = a(t) rst = sin(t); endfunction function rst = b(t) rst = cos(t); endfunction function rst = c(t) rst = -cos(t); endfunction function rst = d(t) rst = sin(t); endfunction function m = A(t) m = [a(t),b(t);c(t),d(t)]; endfunction
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function [m,n,nx]=%lss_size(x,flag) // only to be called by size function for dynamical systems //! // Copyright INRIA [lhs,rhs]=argn(0) [a,b,c,d]=x(2:5);[m,w]=size([c,d]),[w,n]=size([b;d]); if lhs==1 if rhs==1 then m=[m,n] elseif flag==1|part(flag,1)=='r' then m=m elseif flag==2|part(flag,1)=='2' then ...
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// FUNDAMENTALS OF ELECTICAL MACHINES // M.A.SALAM // NAROSA PUBLISHING HOUSE // SECOND EDITION // Chapter 9 : SYNCHRONOUS GENERATOR // Example : 9.6 clc;clear; // clears the console and command history // Given data P = 4 // number of poles m = 3 // number of phase f = 50 // fr...
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// To calculate the maximum Sag clear clc; D=1.95 + 2.6;// overall diameter(cm) A=4.55*(10^-2);// area(m_2) d=19.5;//diameter of conductor(mm) r=d/2;//radius of conductor(mm) Wp=A*39;//wind pressure(kg/m_2) t=13;//ice coating(mm) US=8000;// ultimate strength(kg) Aice=%pi*(10^-6)*((r+t)^2 - r^2);//area section...
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clc; m = input('enter row'); n = input('enter col'); a = zeros(m,n); b = zeros(m,n); c = zeros(m,n); disp('enter elements'); for i = 1:m for j = 1:n a(i,j) = input(''); end end disp('enter elements'); for i = 1:m for j = 1:n b(i,j) = input(''); end end for i = 1:n for j = 1:m ...
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clc; clear; y='y'; i=1; //Takes the equivalent decimal value of the min terms for eg: x^yz=011=3 while(y=='y') disp("enter the minterm of a 3 variable function"); x(i)=input(": "); while(x(i)>7) disp("enter a valid minterm"); end disp("press y if you want to enter more min terms e...
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//Chapter 6, Example 6.1 clc //Initialisation w=1000 //angular frequency L=10**-3 //inudctance in henry //Calculation Xl=w*L //reactance in ohm //Results printf("Reactance, Xl = %d Ohm",Xl)
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clear// //Variables R1 = 1.0 * 10**3 //Resistance (in volts) R2 = 10.0 * 10**3 //Resistance (in volts) vinmin = 0.1 //Input voltage minimum (in volts) vinmax = 0.4 //Input voltage maximum (in volts) //Calculation ACL = R2 / R1 ...
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collocation_anal_least_galerkin_cubic.sce
// // AEROSPACE STRUCTURES II // Assignment 1 //--------------------------------------------------------// // Created : 3-02-2017 // Weighted Residual Methods : Comparing Least-Square_Collocation_Galerkin_analytical // Ref: P.Seshu // Author: Partha Surve (SC14B036, Aerospace Engineering 3rd Year, IIST) //analytic...
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// Scilab code Ex8.8 Page:249 (2006) clc; clear; mu = 5.78e-005; // Bohr magneton, eV/T NE_F = 0.826; // Density of states at fermi level, electrons/atom-J chi_Pauli = mu^2*NE_F/1e-004; // Pauli diamagnetism, cgs units chi_Core = -4.2e-06; // Core diamagnetism, cgs units chi_Landau = -1/3*chi_Pauli; ...
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clc S=5 //in Al=6 //in alphaS=6.5*10^(-6) //in/in/F alphaAl=13.1*10^(-6) //in/in/F Es=30*10^6 //psi EAl=10*10^6 //psi As=1 //in^2 AAl=2 //in^2 T=50 //F dia=1 //in disp("From the figure, it is evident that DeltaPs+DeltaPAl=DeltaTs+DeltaTAl") P=(alphaS*S*12*T + alphaAl*Al*12*T)/(S*12/(Es*As) + Al*12/(EAl*AAl)...
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//Chapter-3,Example 7,Page 58 clc; close; M = 214 // molecular mass of RaB lamda= 4.31*10^-4 //for 1 rd activity (dN/dt) = 10^6 dis/sec // -(dN/dt)= lamda*N //N = m * 6.023*10^23/ M m=(10^6)*214/(lamda*6.023*10^23) printf('the mass of RaB is ') disp(m) printf(' gram')
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//Ex9_7 clc; // Given: k1=3.78; k2=2.79; t1=298;// in K t2=353;// in K R=8.314// Gas constant // Formula: log(k1/k2)=(H/R)*((t2-t1)t1*t2) // Solution: H=R*log(k1/k2)/((t2-t1)/(t1*t2)); printf("The enthalpy for the exchange reaction is = %f J",H)
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pathname=get_absolute_file_path('5_02.sce') filename=pathname+filesep()+'5_02data.sci' exec(filename) printf("\Answer:\n") printf("\n\angle of attack for 700 N lift: %f degree\n\n",a) printf("\n\angle of attack for zero lift:: %f degree\n\n",a1)
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clc; clear; ni=1.5*10^10 //in cm^-3 epsilon_si=11.7 //in F/cm epsilon_0=8.85*10^-14 //in F/cm e=1.6*10^-19 //in J Na=10^16 //in cm^-3 Nd=5*10^16 //in cm^-3 tau_p0=4*10^-7 //in s tau_n0=2*10^-7 //in s //Calculation W=(((2*epsilon_si*epsilon_0)*(Na+Nd)*4)/(e*Na*Nd))^0.5 //in micro-m tau_m=(tau_p0+tau_n0)/2...
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clear; clc; T_on=800*10^-6; V_s=220; I_o=80; C=50*10^-6; T=T_on+2*V_s*C/I_o; printf("effective on period=%.0f us",T*10^6); L=20*10^-6; C=50*10^-6; i_T1=I_o+V_s*sqrt(C/L); printf("\npeak current through main thyristor=%.2f A",i_T1); i_TA=I_o; printf("\npeak current through auxillery thyristor=%.0f A...
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function block=newblock_c(block,flag) if flag==1 //Output(s) of Block are updated //Variables block.outptr(1)(1)=block.inptr(1)*4; elseif flag==0 //ODEs are detailed //variables and ODE //where abc is some index //block.xd(abc)= something end endfunction //Reference ...
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clc //initialisation of variables d= 6 //ft l= 4 //ft W= 2500 //lb Wt= 500 //lb cg= 1.5 //ft d1= 64 //lb/ft^3 //CALCULATIONS w1= W+Wt V= w1/d1 D= V/(%pi*(d^2/4)) hb= D/2 BG= (%pi*d^4)/(64*V) hg= BG+hb x= ((w1*hg)-(W*cg))/Wt //RESULTS printf (' Maximum height c.g above the bottom= %.2f ft ',x)
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//time spacing T = 1 ; dt = 0.0000005; // dt à varier Niter = T/dt ; //space spacing J = 60 ; dx = 1/J ; // J à varier xx = linspace(dx,1,J) ; // probabilities alpha = 1; //coeff destruction D = 1; //coeff diffusion V = 1; //coeff advection pdest = alpha*dt; //destruction pminus = D*dt/dx/dx; //à j-1 pplus = V*dt/d...
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tab=ascii('Scilab-5.5.0') str=ascii(tab)
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clc clear //DATA GIVEN m=0.3; //mass of nitrogen in kg p1=0.1; //pressure in MPa T1=40+273; //temperature before compression in K p2=1; //pressure in MPa T2=160+273; //temperature after compression...
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//Caption: SNR //Example 9.36iii //page no 427 //Find SNR //assume that succeissive samples are statistically independent clear; clc; C=8*10^4; B=10^4; SN=2^(C/B)-1; SNR=10*log10(SN);//SNR disp("dB",SNR,"SNR =");//required SNR is greater that 24.064
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//Example 2.13://power factor and line current clc; clear; close; x=1;// w2=2*x;// w1=x;// ph=atand((sqrt(3)*(w2-w1))/(w2+w1));//in degree pf=cosd(ph);//power factor disp(pf,"power factor is") w=50;//kW v=400;//volts il=((w/(sqrt(3)*v*pf)))*10^3;//in amperes disp(il,"line current is,(A)=")
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//clc() //f1(x) = f0(x) +(f(x1) - f(x0) *(x - x0)/ (x1 - x0) x = 2; x0 = 1; x1 = 6; m = 1.791759; n = 0; r = log(2); f = 0 + (m - n) * (x - x0) / (x1 - x0); disp(f,"value of ln2 for interpolation region 1 to 6 =") e = (r - f) * 100/r; disp("%",e,"error by interpolation for interval[1,6] =") x2 = 4; p = 1.3...
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function do_exit() // Copyright INRIA r=0 if edited then if ~super_block then r=message(['Diagram has not been saved'; 'Save it before leaving?'],['Save';'Exit']) end end if r==1 then ok=do_save() if ~ok then do_SaveAs(),end end if ~super_block&~pal_mode then if alreadyran then do_terminate(),end end ...
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Special first line #2 test text Some text Other text
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function I = cuadraturaGauss(funcion,a,b) // Cuadratura de gauss con seis puntos c = [0.171324492379170 0.360761573048139 0.467913934572691 0.467913934572691 0.360761573048139 0.171324492379170]; xd = [-0.932469514203152 -0.661209386466265 -0.238619186083197 0.238619186083197 0.661209386466265 0.932469514203152]; x = (...
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// find.. clc //solution //given P=35000//W N=240//rpm L=0.350//mm u=0.25 t=10//mm n=6 q=%pi fts=80//N/mm^2 ftk=80//N/mm^2 ts=50//N/mm^2 tk=50//N/mm^2 f=2.5//N/mm^2 ft=4.5//N/mm^2 fb=15//N/mm^2 rho=7200//kg/m^3 //fb*10^6=rho*v^2 v=sqrt(ft*10^6/rho)//m/s printf("the speed is,%f m/s\n",v) D=(v*60)/(...
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// Shift 2, 20th Jan //vchar id i2vout adc diode_ivdd25V=[ 2.15 0.020e-9 0.760 hex2dec('0e26'); 2.18 0.050e-9 0.850 hex2dec('10e2'); 2.20 0.100e-9 0.890 hex2dec('11b8'); 2.25 0.400e-9 1.020 hex2dec('1553'); 2.30 2.900e-9 1.170 hex2dec('19b3'); 2.35 13.00e-9 1.260 hex2dec('1bfb'); 2.40 62.00e-9 1.360 hex2dec('1f3...
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//EXAMPLE 2-53 PG NO=97 R=15; //RESISTANCE V=240+%i*0; //VOLTAGE I=22.1; Ir=V/R; //CURENT disp('i) CURRENT (Ir) is = '+string (Ir) +' A '); IL=[I^2-Ir^2]^0.5; disp('i) CURRENT (IL) is = '+string (IL) +' A '); XL=V/IL; disp('i) INDUCTANCE (XL) is ...
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//Exam:3.12 clc; clear; close; Density=2.7;//(in g/cm^3) n=4; m=26.98;//atomic weight of Al N_a=6.023*10^(23);//avogadro number a=((n*m/(Density*N_a))^(1/3));//Lattice parameter(in Cm) A=a*10^(8);//Lattice parameter(in A) disp(A,'radius(in A)='); r=A/(2*1.414);//radius for fcp structure disp(2*r,'Diameter(i...
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function lcaPutNoWait // lcaPutNoWait is a variant of lcaPut that does not wait for the channel access put request to complete on the server prior to returning control to the command line. // // Calling Sequence // //lcaPutNoWait(pvs, value, type) // // Description // // lcaPutNoWait is a variant of lcaPut th...
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clc; R1=220; R2=1500; Vo=1.25*(1+(R2/R1)); disp('V',Vo*1,"Vo=");//answer given in book is wrong
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// IMC design for viscosity control problem // 10.6 exec('imc_stable1.sci',-1); exec('zpowk.sci',-1); exec('imcsplit.sci',-1); exec('flip.sci',-1); B = [0.51 1.21]; A = [1 -0.44]; k = 1; alpha = 0.5; [k,GiN,GiD] = imc_stable1(B,A,k,alpha); [zk,dzk] = zpowk(k); Bp = B; Ap = A; Ts = 0.1; t0 = 0; tf ...
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//Function to obtaint the transfer functions form a converter using the canonical model // Pag 253 Maksimovic //Hv is the control to output voltage transfer function, Hi the control to inductor current //Vg input voltage, vo output voltage, Rl load, L and C reactives //converterType is a string "buck","boost","buckbo...
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// exa 4.5 Pg 107 clc;clear;close; // Given Data Sut=650;//MPa N=10**5;// cycles Se_dash = 0.5*Sut;// MPa of=5;// unit ob=6;//unit bf=ob-of;// unit be=3;//unit // calculating endurance section wise OE=log10(Se_dash); OA=log10(0.9*Sut); AE=OA-OE; //log10_Sf=OD=OE+ED=OE+FC log10_Sf=OE+(bf/be)*AE; Sf=10**log10_Sf; // (M...
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//Scilab Code for Example 7.23 of Signals and systems by //P.Ramakrishna Rao //Convolution of two signals clc; clear; function [y]=u(t) if t>=0 y=1 else y=0 end endfunction for n=0:10; x(n+1)=(0.5)^n*u(n-2); end c = gca(); c.y_location = "origin"; c.x_location = "origin"; n=0:10; plot2d3(n,x,-4); title(...
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//Chapter 15: Antennas for Special Applications //Example 15-4.1 clc; //Variable Initialization eps_r1 = 16 //Real part of relative permittivity of ground (unitless) sigma = 1e-2 //conductivity of ground (mho per meter) eps_0 = 8.85e-12 //Air permittivity (F/m) f1 = 1e6 //Frequency (Hz) f2 = 100e6 /...
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//Ex:5.43 clc; clear; close; u=0.5;// refractive index N=3.25*10^4;// electron/m^3 f=sqrt(81*N/(1-u^2));// frequency in Hz printf("The frequency = %f KHz", f/1000);
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clc //solution //given //refer fig 15.17 x=190//mm y=140//mm m=2.7//kg r2=170//mm=0.17//m N2=300//rpm h=12//mm ft=80//N/nn^2 pb=8//N/mm^2 w2=(2*%pi*N2)/60//rad/s w1=w2+(0.6/100)*w2//rad/s r1=r2+(h*x/y)//mm Fc1=m*w1^2*r1/1000 Fc2=m*w2^2*r2/1000 //s1 is spring force at max speed w1 //s2 is spring force at max speed w2 /...
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//desing joint clc //solution //given P=50*10^3//N d=75//mm ft=25//N/mm^2 t=20//N/mm^2 //let B1 be the width of strap //B1=d B1=75//mm //t11=B1/4//mm printf("the thickness is,%f mm\n",B1/4) printf("the thickness can be taken as 20mm\n ") t11=20//mm //let t1 be thickness of strap at thnner side //P=2*B1*...
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//Ex 6.3 clc;clear;close; format('v',6); Asys=1520;//km^2 Ch=1140;//no. of channels Acell=4;//km^2 i=3;j=2;//For hexagon cells N=i^2+i*j+j^2;//cells in a cluster disp(N,"(a) No. of cells in a cluster"); Acluster=N*Acell;//km^2 cluster=Asys/Acluster;//no. of clusters disp(cluster,"(b) Number of clusters"); d...
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THE OPTIMIZATION ALGORITHM HAS CHANGED TO THE EM ALGORITHM. ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.302581D+00 ...
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clc clear m=3 n=3 disp("Enter elements of first matrix:") for i=1:3 for j=1:3 A(i,j)=input("\") end end for i=1:3 for j=1:3 P(i,j)=A(i,j); end end for i=1:3 for j=4:6 if(i==(j-3)) then P(i,j)=1; else P(i,j)=0; end end ...
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node sort too sort: No such file or directory
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//Exa 10.4 clc; clear; close; //given data : H=200;//in Km D=4000;//in Km fc=5;//in MHz f_muf=fc*sqrt(1+(D/(2*H))^2);//in MHz disp(f_muf,"MUF for the given path in MHz : "); //Note : Answer in the book is wrong.
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function EE_get_diagram_info(name,XX) blocks_list = []; symbols_list = []; functions_list = []; blocks_list_mk = []; symbols_list_mk = []; app_mk = []; symbols_aux = []; txt = ["Compilation optimization"; "Enjoy"; ""; "Current directory: " + pwd(); ""]; FUNCS_DEP_DIR = SCI+'/contrib/s...
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clc;funcprot(0);//Example 3.16 //Initilisation of Variables Ti=30;...//Initial temparature of potato in degrees celcius Ta=100;...//Temparature of boilled water in degrees celcius ro=0.05;....//Radius of potato in m h=6000;...//heat transfer coefficient on surface of the potato in W/m*degrees celcius To=95;....//...
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clc; d=figure();//создаем окно set(d,'position',[250,250,800,500]);//местоположение и размеры окна set(d,'figure_name','Лабораторные работы по ПВИСУ');//заголовок окна set(d,'BackgroundColor',[0.9,0.7,0.5]);//цвет окна button1=uicontrol(d,'style','pushbutton','string','Лаб 1.','position',[100,300,100,40],'Backgrou...
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clc,clear printf('Example 7.1\n\n') V_l=400 R_a=0.2,X_s=2 //armature resistance and synchronous reactance I_L=25 I_aph=I_L V_ph=V_l/sqrt(3) Z_s=complex(R_a,X_s) //synchronous impedance theta=(%pi/180)*phasemag(Z_s) //Phasemag returns the angle in degrees not radians E_Rph=I_aph*abs(Z_s) //case 1 phi=acos(0.8) //lagg...
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function x=integrate(expr,var,x0,x1,ea,er) // x=integrate(expr,v,x0,x1 [,ea [,er]]) computes // /x1 // [ // x = I f(v)dv // ] // /x0 // // //examples: //integrate('sin(x)','x',0,%pi) //integrate(['if x==0 then 1,'; // ...
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function Sl2=bilin(Sl1,v) // Copyright INRIA [A,B,C,D]=abcd(Sl1); dom=Sl1('dt'); [ra,ca] = size(A); a=v(1);d=v(2);c=v(3);b=v(4); i=inv(a*eye(ra,ra)-c*A); AB=(b*A-d*eye(ra,ra))*i; BB=(a*b-c*d)*i*B; CB=C*i; DB=D+c*C*i*B; if dom=='c' then Sl2=syslin('d',AB,BB,CB,DB); else Sl2=syslin('c',AB,BB,CB,DB);end
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clc; R=0.274; T1=1000+273; v1!v2=1/7; n=1.25; T2=T1*(v1!v2)^(n-1); sA_s1=R*log(1/v1!v2); cv=0.925; sA_s2=cv*log(T1/T2); disp("change of entropy of mixture is:"); disp("kJ/kg K",sA_s1-sA_s2);
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clc; clear; // r = p*a + q*b + s*c p=1 q=2 s=3 //Calculation LCM=lcm({p,q,s}) //LCM for computing miller indices rx=1/p*LCM //reciprocals ry=1/q*LCM rz=1/s*LCM mprintf("The plane depicted in the figure is denoted by (%i,%i,%i)",rx,ry,rz)
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T=10*10^3;//given,in N.mm G1=20000;//laminate shear modulus of flanges,given,in N/mm^2 G2=15000;//laminate shear modulus of web,given,in N/mm^2 a=25; b=50; t1=1.5; t2=2.5;
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// Variable Declaration d = 3.0 //Diameter of conductor(cm) D = 8.5 //Sheath diameter(cm) e_r1 = 5.0 //Permittivity of inner dielectric e_r2 = 3.0 //Permittivity of outer dielectric E_c = 30.0 //Safe working stress(kV/cm) rms // Calculation Section E_i = E_c D_1 = e_r1/e_r2*d thick_1 = (...
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//ques3 //Isothermal Compression of an Ideal Gas clc P1=100//Initial Pressure in kPa V1=0.4;//Initial Volume in m^3 V2=0.1;//final Volume in m^3 w=P1*V1*log(V2/V1);//work done for Isothermal process in kJ printf('Work done = %.1f kJ',w);
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//Example 5_15 //Fourier Transform of x(t)=exp(-t)*sin(wc*t)*u(t) clear; clc; wc=1; Dt=0.005; t=0:Dt:10; xt=(exp(t*(-1+wc))-exp(t*(-1-wc)))/(2*%i); Wmax=2*%pi*1; K=4; k=0:(K/1000):K; W=k*Wmax/K; XW=xt*exp(-sqrt(-1)*t'*W)*Dt; XW_Mag=abs(XW); W=[-mtlb_fliplr(W),W(2:1001)]; XW_Mag=[mtlb_fliplr(XW_Mag),XW_Ma...
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// // Scilab ( http://www.scilab.org/ ) - This file is part of Scilab // Copyright (C) 2011-2011 - DIGITEO - Bruno JOFRET // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The ter...
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like N;NOM;INDF;PL offra V;NFIN;ACT posta V;NFIN;ACT krater N;NOM;DEF;SG subtil ADJ;DEF köksö N;GEN;INDF;SG städa V;NFIN;PASS lagra V.CVB;ACT kongruens N;GEN;INDF;PL friktion N;NOM;DEF;SG konselj N;NOM;DEF;PL undgå V.PTCP;PRS nalkas V;NFIN;ACT statare N;NOM;DEF;PL sädesblåsa N;GEN;DEF;PL levnad N;NOM;IND...
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V = input("Введите номер вида: ") disp("1."+string(V)+" = "+"0 + 1."+string(V - 1)) q = 2 .^(V - 2) for i = 2:1:q if modulo(i,2) ~= 0 then G = i + 1 F = i - 1 else G = i F = i end M = F n = 0 while modulo(M,2) == 0 M = M ./2 n = n + 1 end f1 = (F + (2 .^n))./(2 .*(2 .^n)) v1...
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clear //given //its a statistally indeterminant //we will take of one of the support //Given T_ab = 0 //N.m - torsion in AB T_bc = 150 //N.m - torsion in BC T_cd = 150 //N.m - torsion in CD T_de = 1150 //N.m - torsion in DE l_ab = 250 //mm - length of AB l_bc = 200 //mm - length of BC l_cd = 300 //mm - length o...
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// Exa 7.23 clc; clear; close; // Given data fr= 2;// in MHz fr=fr*10^6;// in Hz C=230+8;// in pF C=C*10^-12;// in F // Formula fr= 1/(2*%pi*sqrt(L*C)) L= 1/((2*%pi*fr)^2*C);// in H disp(L*10^6,"Value of L in µH") // From the first set of data fr= 1;// in MHz fr=fr*10^6;// in Hz\ C= 1/((2*%pi*fr)^2*L);//...
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Syms s t disp('given') disp('i(s)=V/R/s+(1/RC) for t>=0') z=ilt('(V/R*s^0+0)/(s+(1/RC))',s,t) disp(z,"z(t)=")
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x1=input("informe o primeiro valor: "); x2=input("informe o segundo valor: "); x3=input("informe o terceiro valor: "); L=[]; L($+1)=x1; L($+1)=x2; L($+1)=x3; disp(min(L))
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//EXAMPLE 2-74 PG NO-112 ZA=10+%i*7.226; //IMPEDANCE ZB=5+%i*10.99; //IMPEDANCE V=200+%i*0; //VOLTAGE IA=V/ZA; //CURRENT disp('i) CURRENT (IA) is in polar form = '+string (IA) +' A '); IB=V/ZB; disp('ii) CURRENT (IB) i...
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scilab_functions =[... "view"; "matmul"; ]; auxiliary=""; files=G_make(["tutorial_gateway.o","tutorial.a", auxiliary],"void(Win)"); addinter(files,"tutorial_gateway",scilab_functions); //same as "exec tutorial.sce" A=ones(2,2);B=ones(2,2); C=matmul(A,B); if norm(A*B-matmul(A,B)) > %eps then pause,end
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clc //initialisation of variables h1= 238.431 //kJ/kg h4= 109.777 //kJ/kg Qc= 6 //kW h2= 295.835 //kJ/kg n= 0.88 Tin= 33 //C Tout= 20 //C cp= 4.186 //J/mol K //CALCULATIONS qc= h1-h4 m= Qc/qc w= h2-h1 W= m*w/n COP= Qc/W qh= h2-h4 mcw= m*qh/(cp*(Tin-Tout)) //RESULTS printf (' compressor power= %.2f kW...
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//calculating Kc //Example 6.7 clc clear //E'cell=0.0591*logKc/n Eag=0.8 Ecu=0.34 Ecell=Eag-Ecu n=2 Kc=10^(n*Ecell/0.059)//equilibrium constant printf('Thus the equilibrium constant for the reaction = %e',Kc)
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// Grob's Basic Electronics 11e // Chapter No. 21 // Example No. 21_4 clc; clear; // A 200 uH coil has a Q of 40 at 0.5 MHz. Find Re. // Given data L = 200*10^-6; // L of coil=200 uHenry Q = 40; // Q=40 f = 0.5*10^6; // Frequency=0.5 MHz pi = 3.14; Xl = 2*pi*L*f; Re = Xl/Q; disp (Re,'The...
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// Calculating the inductance clc; disp('Example 16.2, Page No. = 16.6') // Given Data N = 25;// Number of turns Ac = 1;// Cross sectional area of the core (in cm square) u0 = 4*%pi*10^(-7);// Permeability of free space ur = 200;// Relative permeability lc = 15;// (in cm) // Calculation of the inductance L = ...
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clear// //Variables Ptrdc = 100.0 * 10**-3 //Maximum collector dissipated power (in watt) VCC = 10.0 //Source voltage (in volts) RL = 16.0 //Load resistance (in ohm) no=0.5;nc=0.5; //Calculation Poac = no * Ptrdc //Maximum undistorted...
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printf("\t example 5.5 \n"); printf("\t approximate values are mentioned in the book \n"); printf("\t for inlet \n"); t1=99.1; // temperature of inlet,F t2=129.2; // temperature of outlet,F c=.478; // Btu/(hr)*(ft)*(F/ft) mu=2.95*2.42; // lb/(ft)(hr) k=0.078; // Btu/(hr)*(ft)*(F/ft) G=854000; // mass velocity,l...
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t01 = [cosd(60) -sind(60) 0 10*cosd(60); sind(60) cosd(60) 0 10*sind(60); 0 0 1 0; 0 0 0 1 ]; t12 = [cosd(30) -sind(30) 0 5*cosd(30); sind(30) cosd(30) 0 5*sind(30); 0 0 1 0; 0 0 0 ...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run2"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monito...
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//Exa 5.5 clc; clear; close; // given data P_e1=1600;// in watts B_max1=1.2;// in T f1=50;// in Hz B_max2=1.5;// in T f2=60;// in Hz // P_e propotional to B_max^2*f^2, so P_e2=P_e1*(B_max2/B_max1)^2*(f2/f1)^2 disp("Eddy current loss is : "+string(P_e2)+" watts");
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//Chapter 14: Water Treatment //Problem: 4 clc; //Initialisation of Variables i1 = 180 //in mg/L for CaCl2 i2 = 210 //in mg/L for Ca(NO3)2 i3 = 123 //in mg/L for MgSO4 i4 = 90 //in mg/L for Mg(HCO3)2 //Solution i1_req = i1 * 100 / 111. i2_req = i2 * 100 / 164. i3_req = i3 * 100 / 120. i...
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// Scilab Code Ex1.33:: Page-1.46 (2009) clc; clear; h = 6.6e-034; // Planck's constant, Js m = 9.1e-031; // Electronic mass, kg e = 1.6e-019; // Energy equivalent of 1 eV, J/eV n = 1; // For simplicity assume principle quantum number to be unity l = 2.1e-010; // Length of one dimensional potential box, m ...
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//Chapter-1, Example 1.51, Page 56 //============================================================================= clc; clear; //INPUT DATA V1=100;//source1 voltage in volts V2=50;//source2 voltage in volts R1=10;//Resistance in ohms R2=20;//resistance in ohms R3=30;//resistance in ohms R4=40;//resistance in ...
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clc; //Example 22.16 //page no 317 printf("\n Example 22.16 page no 317\n\n"); //a power plant employs steam to generate power //adiabatic conditions z1=0//steam vertical position at inlet,ft z2=-20//steam vertical position at outlet,ft v1=120//steam velocity at inlet,ft/s v2=330//steam velocity at outlet,ft/...
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//Ex 4.31 clc; fm=10*10^3; df=100; N=2*fm/df; l=log2(N); l1=ceil(l); N1=2^l1; fs=N1*df; disp(fs,'Required Sampling Freq');
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clc clear //Initialization of variables mdot=8000 //lb/min A1=1 //sq ft A2=3/4 //sq ft P2=50 //psi P1=10 //psi gam=62.4 //lb/ft^3 y2=-2 //ft y1=-4 //ft g=32.2 //ft/s^2 eff=0.7 //calculations v=1/gam cap=mdot/8.33 V1=mdot*v/A1 /60 V2=mdot*v/A2 /60 ht= (y2-y1) + (V2^2 -V1^2)/(2*g) + (P2-P1)*144/gam Hhp...
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clear// //Variables vin = 2.0 * 10**-3 //Input voltage (in volts) gm = 5500.0 * 10**-6 //Transconductance (in Siemen) R1=1.0*10**6;R2=1.0*10**6; RS = 5.0 * 10**3 //Source resistance (in ohm) RL = 2.0 * 10**3 //Load resistanc...
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A=[2 0 3;0 0 1]; GA=A'*inv(A*A'); Ans=A*GA; disp(A) disp(GA) disp(Ans) //A=[2 0;1 0;1 1]; //GA=inv(A'*A)*A'; //Ans=A*GA; //disp(A) //disp(GA) //disp(Ans)
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//write xml //functions for writing xml function [xmlfile]=xmlfile(filename, schemaname, schemahyperlink) xmlfile=mfopen(filename, 'w') xmlfile endfunction function openxml(fd, ) mfprintf(fd, '<%s/>', elementname); endfunction
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//Eg-13.9 //pg-546 clear clc close() //Note that the subscripts of the variables y have been increased by 1 since the subscript 0 is not possible in scilab! deff('out = f1(in1,in2,in3)','out = -0.08*in1^0.5 - 2*in1^0.2*in2') deff('out = f2(in1,in2,in3)','out = -3.5*10^-6*in1^0.2*in2 + 1.6*10^-6*in3^0.3')...
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//page 550 //problem 12.5 // Sm(w)=k*e^(-w2/26^2) this is given // let us the assume the value of constant 6^2/4(pi^2) =3 // thus the variance can be calculated as clc; f0=0;f1=15; y=integrate('(f^2)*(%e^(-(f^2)/6))','f',f0,f1); g=integrate('%e^(-(f^2)/6)','f',f0,f1); v=y/g; disp(v,'Bm2');
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clear; clc; printf("\t\t\tProblem Number 6.4\n\n\n"); // Chapter 6: The Ideal Gas // Problem 6.4 (page no. 242) // Solution //If for this process T2=1.25*T1, // T2/T1 = 1.25 //Therefore, // p2/p1 = T2/T1 //Charles's law(volume constant) //Thus, printf("The absolute gas pressure increases by 25 percent\n")...