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// Exa 4.28 clc; clear; close; // Given data V_out = 3;// in V V_in2 = 5;// in mV V_in1 = 2;// in mV V1 = V_in2-V_in1;// in mV V1 = V1 * 10^-3;// in V A = V_out/V1; R_F = 15;// in k ohm R1 = 1;// in k ohm R2 = 2;// in k ohm R = R2/R1;// in k ohm R_G = (2*R_F)/((A/R)-1);//in k ohm R_G = R_G * 10^3;/...
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sPlItTER sPd {} fiLteR KO { 254.83.253.3/39556 > 1 or 5 = f NoT Cs ( ) oR D:5:f:D:d:B:217.252.251.251 >= 7 NOT bitOr (r, 9, O, wu, 9B, ) not 8f:AD:db:EC:82:3B NOt iN v } fIlter h {BzV or not QUn oR not NHk OR nOT xoS Q OR v OR XCU } bzMN -> j gRouPeR v {AggREgaTe bITAnd(rN) As v } UngroUPeR DbUh { } GR...
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clc; clear; B=0.50;//Mean gap flux density Ys=40;//Slot spacing Cs=(35*12);//Conductor section J=33;//Current density //case:1 disp('To find the tangential force per length of gap periphery and per unit axial length of the machine:') A=(Cs*J*1000)/Ys; disp(A,'The specific electric loadings is:') Fe=B*A; disp...
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function [x, y, b]= PAM_bin(palavra) [l,m] = size(palavra) //conversão dos bits da palavra pcm em um numero binario for i=1:m soma = 0; for j=1:l soma = soma + palavra(j,i)*10^(j-1) end b(i) = bin2dec(string(soma)); end //adicionando um ruíd...
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// Exa 2.6 clc; clear; close; // Given data N = 6.02*10^23; A = 63.5;// atomic weight Rho = 1.7*10^-6;// in ohm cm d = 8.96;// in gm/cc n = (N/A)*d;// in /cc e = 1.6*10^-19;// in C Miu_e = 1/(Rho*n*e);// in cm^2/volt-sec disp(Miu_e,"The mobility of electron in cm^2/volt.sec is");
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clc // Given that m_0 = 9.11e-31 // mass of electron in kg c = 3e8 // speed of light in m/sec KE = 1e5 // kinetic energy of electron in volts E_rest = 512000 // rest mass energy of electron in eV // Sample Problem 34 on page no. 60 printf("\n # PROBLEM 34 # \n") printf(" Standard formula used \n") printf("\n KE = m*v^...
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//Example 10.5 r=0.350;//Radius of wheel (m) alpha=0.250;//Angular acceleration (rad/s^2) theta=200;//Revolutions (rev) theta=theta*2*%pi;//Angle taken through (rad) x=r*theta;//Distance (m) printf('a.Distance the train has moved = %0.1f',x) omega_0=0;//Initial angular velocity (rad/s) omega=sqrt(omega_0^2+2*al...
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//magnitude condition for GH=K/s*(s=2)*(s+4) s=-0.75 k=-s*(4+s)*(2+s) disp(k)
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//ques-24.5 //Calculating Henrys constant clc n=2*10^-2/28;//moles of nitrogen N=1000/18;//moles of water X2=n/(n+N); p2=1;//pressure (in atm) KH=p2/X2; printf("The value of Henrys constant is %d atm.",KH);
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//developed in windows XP operating system //platform Scilab 5.4.1 clc;clear; //example 2.4 //calculation of breakdown voltage of a spark gap //given data A=15//value of A(in per cm) B=360//value of B(in per cm) d=0.1//spark gap(in cm) gama=1.5*10^-4//value of gama p=760//value of pressure of gas(in torr) ...
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load ParityGen8.hdl, output-file ParityGen8.out, compare-to ParityGen8.cmp, output-list x%B2.8.2 p; set x %B00000000, eval, output; set x %B10000000, eval, output; set x %B01000000, eval, output; set x %B11000000, eval, output; set x %B00100000, eval, output; set x %B10100000, eval, output; set x %B01100000, eval, out...
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//Program to find value of integral using Trapezoidal rule clc; clear; close; deff('y=f(x)','y=1/(9+x)') x0=0; xn=6; n=6; h=(xn-x0)/n; s=0; for i=1:n s=s+f(x0+(i-1)*h)+f(x0+i*h); end integral=(h*s)/2; printf('\nThe value of integral is=%g\n',integral)
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//Finding of (Vm/Vp) and (Np/Nm) //Given L1=1/5000; L2=1/256; Qr=1/(2*10^7); //To Find Vr=(1/L1)*(1/L2)*Qr; Nr=Vr*((L2)^-(2/3)*(L2)^-(1/2)*(1/L1)^-(1/2)); disp("Vm/Vp ="+string(Vr)+" m/sec"); disp("Np/Nm ="+string(Nr)+" No units");
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// to calculATE REYNOLD'S NUMBER IN SI UNITS clc S=0.91 // specfic gravity d=1000 // density of water d1=25e-3 //diameter of pipe v=2.6 //volume u=0.38 // viscosity Ns/m2 p=(S*d) mprintf('\n fluid density specific gravity %f Kg/m3',p) Re=(p*d1*v)/u mprintf('\n Reynold s value Re= %f',Re) mprintf('Reynolds value is d...
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/ /rss //rss /rss/channel //link //image/* //link[2] //link[last()] rss/channel/link[last()] rss/channel/item/link[last()] rss/channel/item/link[1] rss/channel/item[@x='1'] rss/channel/item[@x] //item[@x] //item[normalize-space(@name)='x']...
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// Scilab code Ex13.5: Pg.659 (2008) clc; clear; v = 1200; // Recession velocity, km/s H0 = 21e-06; // Hubble constant, per second r = v/H0; // Distance of galaxy from Virgo, c.y printf("\nThe distance of galaxy from virgo = %3.1e c.y or %4.1f Mpc", r, r/3.26/1e+006); // Result // The distance of gala...
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//Chapter 19,Example 5,page 672 //Determine the electric stress and charge density clear clc a = 25*10^-6 // m b = 75*10^-6 // m Er = 2.8 ps = 25*10^-6 // C/m^3 E0 = 8.84*10^-12 Ea = (b*ps)/(ps*E0+b*Er*E0) Eb = (a*ps)/(ps*E0+b*Er*E0) // the negative noation is removed to obtain positive answer as in the book psc = E0...
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// Example 4.1 page no-203 clear clc vcc=12 //V rl=4 // Ohm ic=vcc/rl alfa=0.98 B=alfa/(1-alfa) ibmin=ic/B printf("\nIc(saturation)= %d mA\nBeta = %.0f \nIb(min) = %.1f micro A",ic,B,ibmin*1000)
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clear clc //to find minimum speed of muon in the Earth's fram of reference //to find minimum speed of muon in the muon's fram of reference //Given: //refer to figure 20-8(a)and (b) from page no. 457 //lifetime of muon delta_t0 = 2.2//in microsesonds //height of atmosphere L0 = 100//in Km //speed of light c...
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//Example 1_13 clc; clear;close; //Given data: V=130;//V R=100;//ohm theta1=60;//degree theta2=45;//degree v=sqrt(2)*V;// Irms=sqrt(1/2/%pi*integrate('(3.25*sin(omega_t))^2','omega_t',theta1*%pi/180,%pi));//A P=Irms^2*R;//W disp(P,"(a) Power supplied to load (in W) : "); Irms=sqrt(1/2/%pi*integrate('(3.2...
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########################################################################################################################################################### # fMRI compatible somatosensory moving-dot-paradigm using the piezoelectric vibratory stimulation system build by Mag Design & Engineering # # ...
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// Example 3.16, page no-136 clear clc A=50 slew=0.5 Vid=20*10^-3 Vm=A*Vid fmax=(slew*10^6)/(2*%pi*Vm) fmax=fmax/1000 printf('Fmax= %.1f kHz', fmax)
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//Exa 4.5 clc; clear; close; //Given Data : format('v',7); d1=3;//in meter d2=3;//in meter d3=d1+d2;//in meter d=378;//in cm dia=2.5;//in cm r=dia/2;//in cm epsilon_o=8.854*10^-12;//constnt L=(0.5+2*log10(d/r))*10^-7;//in H/m disp(L*60*1000*1000,"Inductance for 60 km line(in mH) :"); C=2*%pi*epsilon_o/lo...
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//ques-1.4 //Calculating temporary and total hardness in given sample of water clc A=73;//content of Magnesium hydrogencarbonate (in mg/L) B=162;//content of Calcium hydrogencarbonate (in mg/L) C=95;//content of Magnesium chloride (in mg/L) D=136;//content of Calcium Sulphate (in mg/L) a1=(A/146)*100;//CaCO3 equ...
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function [r]=%polss(s1,s2) //r=%polss(s1,s2) <=> r=(s1==s2) polynomail==state-space syslin list //! r=%f
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// Example 12_1 clc;funcprot(0); // Given data T=300;// Temperature in K R_a=287.0;// Gas constant for air in J/kg.K C_pbyR_a=3.5; R_h=2077;// Gas constant for helium in J/kg.K C_pbyR_h=2.5; // Calculation // (a) a=sqrt((C_pbyR_a/(C_pbyR_a-1))*R_a*T);// m/s printf("\n(a)The speed of sound in air,a=%3.1f m/...
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// Copyright (C) 2010 - DIGITEO - Michael Baudin // Copyright (C) 1993 - 1995 - Anders Holtsberg // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available ...
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//Initilization of variables F1=50 //N F2=100 //N F3=30 //N //Calculation //The book has a misprint for squareroot of 1^2 F1x=F1/sqrt(2) //N F1y=F1/sqrt(2) //N F2x=-(F2*3)/sqrt(10) //N F2y=(-F2)/sqrt(10) //N F3x=F3/sqrt(5) //N F3y=(-F3*2)/sqrt(5) //N Fx=F1x+F2x+F3x //N Fy=F1y+F2y+F3y //N R=sqrt(Fx^2+Fy^2...
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//Tested on Windows 7 Ultimate 32-bit //Chapter 12 Modulation and Demodulation Pg no. 378 clear; clc; //Given Emax=10;//maximum peak to peak voltage of an AM signal Emin=3;//minimum peak to peak voltage of an AM signal //Solution m=(Emax-Emin)/(Emax+Emin);//modulation index m printf("Percent modulation...
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//clc() //f(x) = -0.1*x^4 - 0.15*x^3 - 0.5 * x^2 - 0.25 *x + 1.2 h = 0.25; t = -0.9125; x = 0:h:1; disp(x,"x = ") fx = -0.1*x^4 - 0.15*x^3 - 0.5 * x^2 - 0.25 *x + 1.2; disp(fx,"f(x) = ") fd = (- fx(5) + 4*fx(4) - 3 * fx(3))/(2 * h); efd = (t - fd) * 100 / t; disp(fd,"by forward difference") disp("%",efd,"err...
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clear; clc; disp('Example 10.1'); // aim : To determine // the equivalent evaporation // Given P = 1.4;// [MN/m^2] m = 8;// mass of water,[kg] T1 = 39;// entering temperature,[C] T2 = 100;// [C] x = .95;//dryness fraction // solution hf = 830.1;// [kJ/kg] hfg = 1957.7;// [kJ/kg] // stea...
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//Tested on Windows 7 Ultimate 32-bit //Chapter 1 Introduction to Electronics Pg no. 33 //Solved Problem 2 clear; clc; //Given Data I=6;//current in amperes R=36;//resistance in ohms //Solution P=I^2*R;//power in watts printf("P=%d W.",P);
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clc //initialisation of variables K= 1.25*10^6 m= 1000 //gms M= 18.02 //gms //CALCULATIONS nco2= 760*m/(M*K) //RESULTS printf ('moles of carbon dioxide= % 2e mole litre^-1',nco2)
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// Example 13.5 f=50; // Frequency N1=30; // No.Of turns in Primary Coil N2=66; // No.Of turns in Secondary Coil A=0.015; // Area of the Core Zl=4; // Load I...
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scenario = "szAMP_resting_eyes_closed"; no_logfile = false; default_background_color = 0,0,0; pulse_width = 10; write_codes = true; default_trial_type = fixed; begin; picture { text { caption = "+"; font_size = 36; font_color = 255,255,255; ...
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clear; clc; m=.847; g=9.81; dia=1.95e-2; l=244; T=3.56e4; Th_ice=.96e-2; F_wind= 382; W_ice=8920; h=7.62; L=1.43; //(a) w=m*g; S= (w*l*l)/(8*T); mprintf("\n (a)Sag= %.2f m", S); //(b) D=dia+Th_ice+Th_ice; Fw=F_wind * D; Wice = W_ice * (%pi/4) * ((D*D)-(dia*dia)); F=((w+Wice)^2 + Fw^2)^.5; s=(...
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// Scilab ( http://www.scilab.org/ ) - This file is part of Scilab // Copyright (C) 2008 - INRIA - Allan CORNET // // This file is released under the 3-clause BSD license. See COPYING-BSD. demopath = get_absolute_file_path("toolbox_skeleton.dem.gateway.sce"); subdemolist = ["demo scilab_sum" ,"scil...
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// Scilab code Ex17.10 : Pg:894 (2011) clc;clear; e = 1.6e-019; // Energy equivalent of 1 eV, J/eV E = 3.2e+07; // Energy released per second by the reactor, J E_f = 200*1e+06*e; // Energy released per fission, J N = E/E_f; // Number of fissions per second of U235, per second printf("\nThe number of U...
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clc // initialization of variables clear a=100/2 //mm Y=1500 //MPa t=6 //mm w=800 //mmm c=200 //mm a_c=a/c fl=1.045 w=w*10^-3 t=t*10^-3 a=a*10^-3 A=w*t Sigma=1/A K_I=Sigma*sqrt(%pi*a)*fl printf('part (a)') printf('\n K_I = %.2f MPa sqrt(m)',K_I)
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//Block in contact with level plane //refer fig. 17.3 //Normal reaction N=1500 //N mu=0.1 F=mu*N //N //Applying impulse momentum equation in the horizontal direction t=(1500*(16-0))/(9.81*(300-150)) //sec //If force is then removed, the only horizontal force is F=150 N //Applying impulse momentum equation ...
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//check o/p for i/p of type char k=['a' 'b' 'a' 'c']; a=rc2is(k); dips(a); //output //!--error 10000 //All reflection coefficients should have magnitude less than unity. //at line 43 of function rc2is called by : //a=rc2is(k);
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// example 7.11 // solve the boundary value problem u''=u'+1; // u(0)=1; u(x=1)=2(%e-1); h=1/3; // we know; u''=(u(j-1)-2*u(j)+u(j+1))/h^2; // we know; u'=(u(j+1)-u(j-1))/2h; // 1) second order method; x=0:1/3:1; u= rand(1,4);; // hence; disp('(u(j-1)-2*...
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Rf=100;Lf=25;Ra=0.25;Laq=0.02; Kg=100;Ll=0.15;V=200;Rl=1; tow=Lf/Kg log(0.1) t=2.30/4 Towat=(Ll+Laq)/(Rl+Ra)
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// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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exec("alaqiltest.start", -1); p = getnull(); checkequal(alaqil_this(p), 0, "alaqil_this(p)"); checkequal(funk(p), %T, "funk(p)"); exec("alaqiltest.quit", -1);
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//Example 3.6: clc; clear; close; //given data : Ie=5;// in mA alfa=0.99; I_co=0.005;// in mA Ic=((alfa*Ie)+I_co); Ib=(Ie-Ic); Beta=alfa/(1-alfa); I_CEO=I_co/(1-alfa); format('v',6) disp(Ic,"Ic,(mA) = ") format('v',4) disp(Ib*10^3,"Ib,(micro-A) = ") disp(Beta,"Beta = ") format('v',6) disp(I_CEO*10^3,"I_CEO(micro-A) = ...
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clear // // // //Variable declaration lamda=3*10**-10 //wavelength(m) h=1 k=0 l=0 //miller indices theta=40*%pi/180 //glancing angle(radian) n=1 //order //Calculation d=n*lamda/(2*sin(theta)) //space of reflecting plane(m) a=d*sqrt(h**2+k**2+l**2) V=a**3 ...
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// Scilab Code Ex9.17: Mobility and no of Charge carrier : Page-9.48 ; (2004) clc;clear; RH = 3.66e-4; // Hall Coefficient, metrcube/C e = 1.6e-19; // Electronic charge, C rho = 8.93e-3; // Resistivity of sample, ohm meter n = 1/(RH*e); // Number of charge carrier, per metre cube mu_e = RH/rho; // Mo...
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//Variable declaration: n = 1200.0 //Flow rate of air in a molar flow rate (lbmol/min) Cp = 0.26 //Average heat capacity (Btu/lbmol.°F) T1 = 200.0 //Initial temperature (°F) T2 = 1200.0 //Final temperature (°F) //Calculation: DT = T2 - T1 ...
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// Example 2.7.9 page 2.28 clc; clear; delta=1/100; //relative refractive index n1=1.5; //refractive index of core M=1100; //Guided modes lamda=1.3d-6; //wavelength v=sqrt(2*M); //computing normalized frequecy a=(v*lamda)/(2*3.14*n1*sqrt(2*delta)); //computing radius of core d...
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// Grob's Basic Electronics 11e // Chapter No. 33 // Example No. 33_5 clc; clear; // If Avol equals 100,000, calculate the value of Vid. // Given data Avol = 100000; // Open loop voltage gain=100,000 Vo = 10; // Output voltage=10 Volts(p-p) Vid = Vo/Avol; disp (Vid,'The Differential Input Voltage...
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//Chapter-5,Example5_7_2,pg 5-27 delta_x=10*10^-9 //position is located within this distance h=6.63*10^-34 //plancks constant delta_px=h/(4*%pi*delta_x) //By Heisenberg's uncertainty pricip...
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:============================================================================== : Product PBH v10.04 : Patch Name FUJENQ.TST : Author Toshi Aoki (NIS.AOKI) : Date 27-SEP-1990 : Description Fujitsu model K series host is designed to respond to a : Forward Abort from the PBH not only with an EOT but also : with...
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function num = parseInt (t) tic(); for i=1:1:t n = rand (1.2147483646); disp(n); s = dec2hex(n); m = hex2dec(s); assert (m == n); end t = toc(); disp(t); endfunction
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 13.2w //calculation of the height of the atmosphere to exert the same pressure as at the surface of the earth //given data P0=1*10^5//atmospheric pressure(in Pa) rho=1.3//density of air(in kg/m^3) g=9.8//gravitationa...
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//******************************************* // This is the Scilab script for Exercise 4. // // Use the help facility for more information // on individual functions used. // // Author: J. Kaempf, 2015 (update) //******************************************** // Animation of the Coriolis force clf; scf(0); a...
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// método de gauss para escalonamento de matriz //metodo de gauss clear;clc; format (25) //A = [1 1 1 6;2 -1 1 3;1 0 1 4]; B = [4 8 4; 2 1 -4; 3 -1 2] b = [80 7 22]; function x = eliminacao_gauss(A,b) n = length(b); x = zeros(n,1); //eliminação for k = 1: n-1 for i = k+1:n xmu...
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//Chapter-5,Example 9,Page 125 clc(); close(); //final concentration is half of initial concentration //therefore t =t_half t= 60 //time in minutes t_half=t k=5.2*10^-3 //rste constant a=1/(k*t_half) //for 2nd order reaction printf('the initial concentration is %.2f mol/litre',a)
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// PG (351) // dy/dx = -y + 2 * cos(x) deff('[y]=g(x,y)','y=-y+2*cos(x)') y0=1; x0=0; xn=5; // execute the function euler1 , so as to call it to evaluate the value of y, [y,x] = Euler1(y0,x0,xn,0.04,g) // h = 0.04 [y,x] = Euler1(y0,x0,xn,0.02,g) // h = 0.02 [y,x] = Euler1(y0,x0,xn,0.01,g...
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clc // Intialization of variables Q = 30 // ft^3/s Dm = 3/12 //ft D = 2 //ft //Calculations Qm = Q*Dm/D // cfs //Results printf("The required flow rate is %.2f cfs",Qm)
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// Example 5.3 clc; clear; close; // Given data format('v',6); C= 0.01;// in µF C= C*10^-6;// in F f= 1;// in kHz f= f*10^3;// in Hz // For 50% duty cycle, Ton= Toff = T/2 and R_A= R_B // From equation, f= 1.44/((R_A+R_B)*C)= 1.44/(2*R_A*C) R_A= 1.44/(2*f*C);// in Ω R_A= R_A*10^-3;// in kΩ R_B= R_A;// in ...
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//Example 3.11 clc disp("From O.C. test we can write,") disp(" Wo = P1 = 50 W = Iron loss") disp("From S.C. test we can find the parameters of eqivalent circuit. Now S.C. test is conducted on H.V. side i.e. meters are on H.V. side which is tranformer secondary. Hence parameters from S.C. test results will be refer...
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//EXAMPLE 2.30 //Convolution of two sided sequences clear; clc; g=[3 -2 4];//originating at n=-1 h=[4 2 -1];//originating at n=0 q=length(g); w=length(h); z=q+w-1; y0=0; for i=1:z; y(i)=0; for k=1:i; if k>q g(k)=0; else if (i-k+1)>w h(i-k+1)=0; ...
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java -ea trip.Main -m trip-tests/map03 trip-tests/request03
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//Problem 12.12: //initializing the variables: //Antoine Eq Coeff for Methanol Am = 16.5938; Bm = 3644.3; Cm = 239.76; //Antoine Eq Coeff for water Aw = 16.262; Bw = 3799.89; Cw = 226.35; R = 1.987; T = 40; //in degC //calculation: xm = 0.3 xw = 0.7 pdm = %e^(Am - (Bm/(T + Cm))) pdw = %e^(Aw - (Bw...
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function [stk,txt,top]=sci_qr() // Copyright INRIA txt=[] if rhs==1 then s=stk(top) if lhs==1 then set_infos('No scilab eqivalent to qr with only one lhs arg using mtlb_qr',1) stk=list('mtlb_qr('+s(1)+')','0',s(3),s(4),'1') elseif lhs==2 then stk=list(list('qr('+s(1)+')','-1',s(3),s(3),'1'),.. list('...
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consulta_por_email.tst
PL/SQL Developer Test script 3.0 5 begin -- Call the procedure personas_por_email(pemail => :pemail, p_recordset => :p_recordset); end; 2 pemail 1 bsjc96@gmail.com 5 p_recordset 1 <Cursor> 116 0
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DTOTemplate.tst
// This file was autogenerated by http://frhagn.github.io/Typewriter/ ${ using Typewriter.Extensions.WebApi; using Typewriter.Extensions.Types; using System.Text; Template(Settings settings) { settings .IncludeProject("SharedKernel") .IncludeProject("TestCreation...
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clc clear P2=44; //in bar P3=P2; T3=1600+273; //in K P1=1; //in bar T1=27+273; //in K G=1.4; T2=T1*[(P2/P1)^((G-1)/G)]; R=0.287; V1=(R*T1)/(P1*100); r=(P2/P1)^(1/G); Z=T3/T2; Eff=100*(1-((1/(r^(G-1)))*(1/G)*((Z^G)-1)/(Z-1))); printf('Efficiency is %2.1f Percent',Eff); pri...
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clc clear //Initalization of variables pa=14.7 pv=0.0356 pv2=0.04 cp=0.24 t1=70 //F t2=15 //F R=53.35 V=8000 //ft^3 //calculations sh=0.622*pv/(pa-pv2) hm2=cp*t1+ sh*1092.3 hm1=cp*t2+sh*1068.4 Q=hm2-hm1 m=144*(pa-pv2)*V/(R*(t2+460)) Q2=Q*m //results printf("Heat added per min = %d Btu/min",Q2) disp(...
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//example-10.5 //page no-321 //given //dimension of steel specimen l=75 //mm b=10 //mm t=10 //mm //depth of V-notch is t/5 //in the absence of specimen, frictional and windage loss L1=0.1 //kg f.m //in the presence ofspecimen, which is placed on support breaks L2=5.9 //kg f m //rupture energy U=L2-L1 ...
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// Exa 3.6 clc; clear; close; // Given data B=0.1;// in T C= 100*10^-7;// in Nm/radian theta= 120;// in ° theta=theta*%pi/180; Tc= C*theta;// in N-m N=200;// number of turns A=2.5*2;// in cm^2 A=A*10^-4;// in m^2 // Formula Tc= Td= B*i*A*N; i= Tc/(B*A*N);// in amp disp(i*10^3,"Current in the coil in mA")...
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//Chapter 6 //Example 6_18 //Page 123 clear;clc; pf1=0.7; pf2=0.85; add_cost=800; //Referring to figure 6.15, //The initial capacity of the plant is OB kVA at pf = pf1 a1=pf2/pf1; BD=a1-1; tc=BD*add_cost; phi1=(acosd(pf1)); phi2=(acosd(pf2)); lead=a1*sind(phi1)-sind(phi2); cost=tc/lead; disp("COST OF INCREASING PL...
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// Effect of porosity on properties clc UTS0 = 125 // in MPa E0 = 500 // Youngs modulus in GPa k0 = 0.6 // thermal conductivity in W/m-K n = 6 // given p = 0.15 // given printf("\n Example 11.7") UTS = UTS0*exp(-5*p) E = E0*(1-1.9*p+0.9*p^2) k = k0*(1-p) printf("\n Due to %d%% porosity", p*100) printf("\n ...
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//clear// clear; clc; //Exapmle 9.7 //Given Dt = 2; //[m] Da = 0.667; //[m] n = 180/60; //[rps] T = 20; //[C] qg = 100; //[m^3/h] rho = 1000; //[kg/m^3] mu = 10^-3; //[kg/m-s] ut = 0.2; //[m/s] At = %pi/4*Dt^2; //[m^2] //Using values form Example 7.6 //Assuming Pg/Po decresaes to 0.25 PgbyV = 0.25*20...
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 10.1w //calculation of the number of revolutions made by the wheel //given data wzero=0//initial angular velocity(in rad/s) of the wheel alpha=2//angular acceleration(in rad/s^2) t=10//time(in s) interval //calc...
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//Realiza la eliminacion de gauss para una matriz A y un vector b // Devuelve: B matriz triangular superior resultado de aplicar eliminación // Gaussiana a A. NO REALIZA PIVOTEO. function [B] = elimGauss(A,b) n = size(A,1); A = [A b]; for i=1:(n-1) for j=(i+1):n if(A(i,i) == 0) ...
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clear// //Variables Idc = 0.2 //Average value of current (in Ampere) Vdc = 30.0 //Average value of voltage (in volts) C1=100.0;C2=100.0; L = 5.0 //Inductance (in Henry) f = 50.0 //Frequency (in Hertz)...
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clc; h3=2716.4;//kJ/kg hf2=640; h_fg2=2109; x2=(h3-hf2)/(h_fg2); flow_rate=9; m_w2=(1-x2)*(flow_rate); mass_water=0.5; m_w1=m_w2+mass_water flow_rate_dry=mass_water+flow_rate-m_w1; x1=flow_rate_dry/(mass_water+flow_rate); disp("fraction is:"); disp(x1)
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clear // // // //Variable declaration d=2 //diffraction observed(m) lamda=500*10**-9 //wavelength(m) x=5*10**-3 //width of central maxima(m) //Calculation a=d*lamda/x //slit width(m) //Result printf("\n slit width is %0.3f mm",a*10**3)
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function [x,k]=unique(x) //Copyrigth INRIA // extract unique components of a vector if size(x,'*')==1 then k=1 else [lhs,rhs]=argn() if lhs==2 then [x,k]=sort(x); if type(x)==1 then x=x($:-1:1);k=k($:-1:1);end keq=find(x(2:$)==x(1:$-1)) x(keq)=[] k(keq)=[] else x=sort(x);x=x($:-1:1); ...
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// 08.10.24 function Out=CrvsfHiddenData() global CRVSFHIDDENDATA Out=CRVSFHIDDENDATA; endfunction;
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//Initial pressure(in bar) p1=1; //Compression ratio r=16; //Cutoff ratio rc=2; //Ratio of specific heats y=1.4;
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clf(); // insert LaTeX formulas xstring(0.5,1,'$\LaTeX $') xstring(0.75,0.75,'${\pi\over 2}=\int_{0}^\infty {\sin(x)\over x}\; dx$') xstring(0.25,0.75,'$${\pi^2\over 6}=\sum_{n=1}^\infty {1\over n^2}$$') xstring(0.25,0.25,prettyprint(eye(4,4))) xstring(0.75,0.25,'$g(x)=$ '+prettyprint(poly(1,'x')/(2*poly(0,'x')-1))) x...
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//example1.11 clc disp("Redrawing the circuit,") disp("R1 and R2 are in series from fig. 1.59(b)") r=150/25 disp(r,"R1(in ohm)=(15*10)/(15+10)=") r=24/10 disp(r,"R2(in ohm)=(6*4)/(6+4)=") disp("then, R_ab=R1+R2") r=6+2.4 disp(r,"Therefore, R_ab(in ohm)=6+2.4=")
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//ques14 disp('To find the inverse laplace transform of the function'); syms s t a f=(s+3)/((s^2-4*s+13)); il=ilaplace(f,s,t); disp(il);
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// Scilab code Exa6.4.1 : To calculate the kinetic energy of protons passing through the carbon stripper foil : Page 266 (2011) q = 2; // Number of proton, V = 15; // Voltage applied to the dome, MV E = q*V; // The kinetic energy of proton,MeV printf("\nThe kinetic energy of proton : %d MeV", E); // Result...
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//Problem 33.04:For the network shown in Figure 33.22, use Th´evenin’s theorem to determine the current flowing in the 80 ohm resistor. //initializing the variables: V = 100; // in volts R1 = 5; // in ohm R2 = 20; // in ohm R3 = 46; // in ohm R4 = 50; // in ohm R5 = 15; // in ohm R6 = 60; // in ohm R7 = 16; ...
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//Part A Chapter 3 Example 2 clc; clear; close; format('v',7); t_ice=0;//degree C p_ice=3;//thermometric property t_steam=100;//degree C p_steam=8;//thermometric property //t=a*log(p)+b/2 //solving by matrix multiplication for a and b A=[log(p_ice) 1/2;log(p_steam) 1/2]; B=[t_ice;t_steam]; X=A^-1*B; a=X(1...
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// Test # 7 : Input Argument #2 range test exec('./allpassshift.sci',-1); [n,d]=allpassshift(0.6,3.1); //!--error 10000 //Wt must lie between 0 and 1 //at line 43 of function allpassshift called by : //[n,d]=allpassshift(0.6,3.1);
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//Example6.28 // to determine the hysteresis width of a schmitt trigger clc; clear; close; R1 = 15*10^3 ; // ohm R2 = 90*10^3 ; // ohm VTH = 10 ; // V VTL = -10 ; // V // the upper crossover voltage of schmitt trigger is defined as VU = (R1/(R1+R2))*VTH; disp('the upper crossover voltage of schmitt trigger...
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//Exa 6.4 clc; clear; close; //Given data Q = 88;// in MJ Q=Q*10^3;// in kJ T1 = 190;// in °C T1 = T1 + 273;// in K T3 = -15;// in °C T3 = T3 + 273;// in K Eta_carnot = (T1 - T3)/T1; Wnet= Eta_carnot * Q;// in kJ CarnotPower= Wnet/3600;// in kWh disp(CarnotPower,"The value of Carnot Power in kWh is : ") ...
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//Solve the system of equations 2x + 5y + z = 0 , 4x + 8y + z = 2, y –z = 3 using Gaussian Elimination. Also, identify the pivots. clc; clear; close; A=[2,5,1;4,8,1;0,1,-1], b= [0;2;3]; A_aug=[A b] a=A_aug n=3; for i=2:n for j=2:n+1 a(i,j)=a(i,j)-a(1,j)*a(i,1)/a(1,1); end a(i,1...
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// Test # 12 : Valid inputs exec('./allpassrateup.sci',-1); [n,d]=allpassrateup(4); disp(d); disp(n); // //Scilab Output //d= 1. 0. 0. 0. 0. //n= 0. 0. 0. 0. 1. // //Matlab Output //n= 0 0 0 0 1 //d= 1 0 0 0 0
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// chapter 8 // example 8.26 // fig. 8.45 // Compute average output voltage, peak-to-peak output ripple voltage, peak-to-peak current of the inductor and peak current of the device // page-522-523 clear; clc; // given Edc=14; // in V (dc source) alpha=0.6; // duty cycle f=25; // in KHz (switching frequency) L=180; // i...