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clear; clc; l = 3;// feet b = 3;// inches t = 3/8;// inches W = 1500;// lb. f = 12;// tons/in^2 E = 30*10^6;// tons/in^2 M_max = W*l*12/4 ;// lb-inches M_r = f*(1/6)*b*t^2 *2240;// lb-inches n = M_max/M_r ;// no. of plates n = round(n+1); f = M_max/(n*(1/6)*b*t^2);// lb/in^2 R = E/(2*f/t) ;// inches delta...
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// Test # 9 : Valid input test case #1 exec('./allpasslp2bp.sci',-1); [n,d]=allpasslp2bp(0.7,[0.49,0.78]); disp(d); disp(n); // //Scilab Output //d=1. 0.7334144 0.6004943 //n=- 0.6004943 - 0.7334144 -1. //Matlab Output //n= -0.6005 -0.7334 -1.0000 //d= 1.0000 0.7334 0....
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clc; //page no 654 // problem no 17.11 //for a square patch antenna f=2*10^6;// freq of operation in Hz Er=2;// relative permittivity c=3*10^8;// velo of light //wavelength is given as wl=c/(f*sqrt(Er)); //The antenna width and length are each approximately half of this. w=wl/2; l=wl/2; disp('m',w,'The ante...
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clear; clc; //Example - 15.10 //Page number - 527 printf("Example - 15.10 and Page number - 527\n\n"); //Given T = 50;//[C] - Temperature P = 64;//[kPa] - Pressure z_1 = 0.7; z_2 = 0.3; // log(P_sat) = A - B/(t + C) // For acetone A_1 = 14.37824; B_1 = 2787.498; C_1 = 229.664; // For acetonitrile...
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clear// //Variables I0 = 2 * 10**-7 //Current (in Ampere) VF = 0.1 //Forward voltage (in volts) //Calculation I = I0 * (exp(40*VF)-1) //Current through diode (in Ampere) //Result printf("\n Current throrough diode is %0.2f micro-Ampere.",I*10**6)
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//AC Circuits : example 4.4 :pg(4.5) pi=3.14; Vm=200; disp("v=200sin314t"); disp("v=Vmsin(2*pi*f*t)"); disp("(2*pi*f)=314"); f=(314/(2*pi)); printf("f=%.f Hz",f); Vavg=((2*Vm)/pi); Vrms=(Vm/sqrt(2)); mprintf('\nFor a sinusoidal waveform, \nVavg=(2*Vm/pi) \nVrms=(Vm/sqrt(2))'); kf=(Vrms/Vavg); kc=(Vm/Vrms); ...
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Different folders contains the outputs of RF method and Deep learning methods.
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clc; clear; T1=[1 2 1]; T2=[0 1 1]; n=max(size(T1)); a=n-1; b=a; T3=zeros(1,a+b+1); for i=1:n b=n-1; for j=1:n T3(a+b+1)=T3(a+b+1)+(T1(i)*T2(j)); b=b-1; end a=a-1; end m=max(size(T3)); i=1; j=m; while(i<=floor(m/2) & j>=(ceil(m/2)+1)) t=T3(i); T3(i)=modulo(T3(j),3); ...
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//example 4.1 clc; funcprot(0); // Initialization of Variable V=0.5;//volume P1=1;//pressure P2=0.5; vf1=1.0432/1000; vf2=1.0582/1000; x=0.5; T1=99.63; v1=vf1+0.5*(1.694-vf1); v2=v1; T2=111.4;//from table disp(T2,"temperature in degree celcius"); m=V/v1; mg1=x*m; disp(mg1,"mass of vapor in kg"); x2=(v1...
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//Caption:K-Samples Tests //K-samples Median Test //Example9.21 //Page347 //Ho: There is no significant difference between the percentagge absenteeism of the //employees in different months //H1: There is significant difference between the percentage absenteeism of the //employees in different months clear; cl...
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// chapter 12 // example 12.5 // calculate numerical aperture,acceptance angle and the critical angle of the optical fibre // page 361 clear; clc; // given u1=1.50; // refractive index of core u2=1.45; // refractive index of cladding //calculate d=(u1-u2)/u1; // calculation of fractional index change NA=u1*...
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clc //initialisation of variables T= 296 //K T1= 250 //K T2= 300 //K v= 0.1257 //m^3/kg v1= 0.11144 //m^3/kg u1= 27772.6 //kJ/kg u2= 2679.6 //kJ/kg h1= 3023.5 //kJ/kg h2= 2902.5 //kJ/kg s1= 6.7664 //kJ/kg K s2= 6.5433 //kJ/kg K //CALCULATIONS a1= (T-T1)/(T2-T1) a2= 1-a1 V= a1*v+a2*v1 U= a1*u1+a2*u2 H=...
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rinc rincas N;NOM;PL rinc rinc N;ACC;SG rinc rinca N;GEN;PL rinc rince N;DAT;SG rinc rincum N;DAT;PL rinc rinc N;NOM;SG rinc rincas N;ACC;PL rinc rinces N;GEN;SG gebedda ġebeddan N;NOM;PL gebedda ġebeddan N;ACC;SG gebedda ġebedda N;NOM;SG gebedda ġebeddan N;GEN;SG gebedda ġebeddum N;DAT;PL gebedda ġebeddena N;GEN;PL ge...
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// This file is part of www.nand2tetris.org // and the book "The Elements of Computing Systems" // by Nisan and Schocken, MIT Press. // File name: projects/08/ProgramFlow/FibonacciSeries/FibonacciSeries.tst load FibonacciSeries.asm, output-file FibonacciSeries.out, compare-to FibonacciSeries.cmp, output-list R...
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//scilab 5.4.1 //Windows 7 operating system //chapter 17 Number Systems,Boolean Algebra,and Digital Circuits clc clear hFE=30//hFE=dc current gain of given silicon transistor VBE=0.8//VBE=base-emitter voltage drop at saturation VCE=0.2//VCE=collector-emitter voltage drop at saturation R1=15*1000//resistance at ...
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clc; delta_t=277-17; d=0.15; alpha=1.32*(delta_t/d)^0.25; disp("heat transfer coefficient="); disp("W/m^2 K",alpha);
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//(6.3) Refrigerant 134a is compressed adiabatically in a piston–cylinder assembly from saturated vapor at 0C to a final pressure of 0.7 MPa. Determine the minimum theoretical work input required per unit mass of refrigerant, in kJ/kg. //solution //variable initialization T1 = 273 ...
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clc disp("Example 3.18") printf("\n") disp("calculate the value of Ic,Ie for a transistor.Find beta for transistor") printf("Given\n") //For old transistor alpha=0.97 Ib=50*10^-6 //value of collector current Ic=alpha*Ib/(1-alpha) //value of emitter current Ie=Ic/alpha //value of beta beta=Ic/Ib printf("co...
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clc; re=25; //Ohm Hfe=200; Zbase=Hfe*re; //Ohm rE=200; //Ohm Zbase=Hfe*(re+rE); //Ohm disp('kohm',Zbase/1000,"Zbase=");//The answers vary due to round off error
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; tests get-proof without :produce-proofs (set-logic QF_UF) (get-proof) (get-proof xxx)
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//3º trabalho de Inteligência Computacional, rede neural //autor: Lais de Fátima Sousa Gomes, Matrícula 504405 clear; clc; //_____Algumas funções auxiliares________________ //função de rosenbrock function [z] = rosenbrock(x, y) z = (1 - x)^2 + 100*(y - x^2)^2; endfunction //converte para o valor real function [...
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clear; clc; R=48.7; X=80.2; Z=complex(R,X); c=8.42e-9; l=200; C=c*l; Y=complex(0,(C* 100*%pi)); Vr=88e3/sqrt(3); Pr=13.5e6; pf=.9; pfa=-1* acos(pf); Irm=Pr/(3*Vr*pf); Ir=complex(Irm *pf, Irm * sin(pfa)); Vs=(Vr*(1+((Z*Y)/2)))+ (Ir*Z*(1+(Z*Y/4))); V=abs(Vs); vs=sqrt(3)*V*1e-3; phi=atan(imag(Vs)/r...
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Name=ammomod PlayerCharacters=CPM BotCharacters=All Strafes.bot IsChallenge=true Timelimit=120.0 PlayerProfile=CPM AddedBots=All Strafes.bot PlayerMaxLives=0 BotMaxLives=0 PlayerTeam=2 BotTeams=1 MapName=ammomod.map MapScale=3.8125 BlockProjectilePredictors=true BlockCheats=true InvinciblePlayer=true In...
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clear //Given H=0.40 a=18 //degree //Calculation // R=H/(cos(a*3.14/180.0)) //Result printf("\n Magnitude of earths magnetic field is %0.2f G",R)
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//Exaample2.21 //Given k1=0.7 //common brick W/((m.K) k2=0.48 //gypsum layer [W/(m.K) k3=0.065 //Rockwool [W/m.K] //Heat loss with insulatiob will be 20% of without insulation A=1 //sq m x1=0.1 //[m] x2=0.04 //[m] R1=x1/(k1*A) //K/W R2=x2/(k2*A) //K/W R=R1+R2 //K/W //R3=x3/(k3*A) QbyQd=0.2 sig...
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// Problem 5.14,Page no.136 clc;clear; close; B=10 //cm //width of timber section D=15 //cm //depth of timber section b=10 //cm //width of steel plate t=12 //mm //thickness w=3 //KN/m //Uniformly distributed Load L=4 //m //Span of beam m=20 //Ratio of modulus of elasticity of steel to timber W=3 //KN/m //Load //Ca...
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clc; //Example 33.10 //page no 532 printf("Example 33.10 page no 532\n\n"); //the flow of blood from the arota to the atrium is reprsented by a vessel meu=1.1*6.72e-4//viscosity of blood L=0.3//length of vessel,mile g_c=32.2//grav. acc rho=62.4//density of blood D=2.53/30.48//diameter of vessel,ft P_drop=32*...
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function Funcion1(x, y) // Autores: Hector E. Gomez Morales // Funcion que grafica la funcion // // f1(x) = 4*x^2 + y^2 // // para un conjunto de argumentos dados x, y //************************************************************************ //-> Entrada // x (Vector Real) - Define los puntos donde se evaluara y ...
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V1=250 V2=480 Vol2_by_Vol1=V1/V2 sav=(1-Vol2_by_Vol1)*100 disp(sav)
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// final flux = 0.8*initial flux Ia1 = 73; //initial armature current (in amps) Vt = 230; //(in volts) Ra = 0.188; //armature circuit resistance n1 = 1150; //initial rotor speed (in rpm) Ea1 = 216.3; //initial armature voltage Ia2 = (1/0.8)*Ia1 ; //final armature current Ea2 = Vt - (Ia2*Ra); //final armatur...
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// Example 3_3 clc;clear;funcprot(0); // Constants used g=9.81;//The acceleration due to gravity in m/s^2 // Given values h=1400;//m h_1=0.1;//m h_2=0.2;//m h_3=0.35;// respective heights in m P_atm=85.6; // The atmosphereic pressure in kPa; rho_w=1000;// kg/m^3 rho_o=850;// kg/m^3 rho_m=13600; // The den...
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clc // Given that lambda = 6e-7 // wavelength of light in meter theta = 2.44e-6 // separation angle of stars in radian // Sample Problem 42 on page no. 2.54 printf("\n # PROBLEM 42 # \n") a = (1.22 * lambda) / theta // calculation for diameter of telescope objective printf("\n Standard formula used \n a = (1.22 * lamb...
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//Example 1_3 clc; clear;close; //Given data RG=2000;//ohm VCC=20;//V VT=0.75;//V Vthy=0.7;//V(Voltage across thyristor) R=200;//ohm IT=7*10^-3;//A Ih=5*10^-3;//A //Solution : //part (a) Vo=VCC;//V////thyristor not conducting disp(Vo,"(a) When thyristor is in off state, Output voltage in V") //part...
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// Example 9.12 format('v',6) clc; clear; close; // given data Ta= 70;// ambient temperature in °C P= 30;// in power dissipation in W theta_CS= 0.5;// in °C/W theta_SA= 1.5;// in °C/W // The case temperature Tc= Ta+P*(theta_CS+theta_SA);// in °C // The power rating P_Dmax= 60;// in W disp(Tc,"The case tem...
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clear; clc; // Illustration 7.5 // Page: 228 printf('Illustration 7.5 - Page: 228\n\n'); printf('Illustration 7.5 (a)\n\n'); // solution(a) //****Data****// // A = benzene vapour; B = Nitrogen Gas P = 1;// [atm] //*****// MA = 78.05;// [kg/kmol] MB = 28.02;// [kg/kmol] // Since gas is saturated, ...
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clc clear //INPUT DATA d=0.26;//bore of the engine in m L=0.38;//stroke of the engine in m vc=0.0025;//clearence volume in m^3 p1=1;//pressure in bar t1=313;//temperature in K p3=25;//pressure in bar v12=9.07;//volume in m^3 //CALCULATIONS vs=(3.14*d^2*L)/4;//swept volume in m^3 Rc=((vs+vc)/vc);//compress...
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//Chemical Engineering Thermodynamics //Chapter 13 //Thermodynamics in Phase Equilibria //Example 13.1 clear; clc; //Given //N2 obeys the relation : Z = 1+(2.11*10^-4*P) Tc = 126;//Critical temperature in K Pc = 33.5;//Critical pressure in atm T = 373;//in K P = 100;//in atm //To Calculate the fugacit...
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rows = 3; cols = 3; A = zeros(rows,cols); disp("Inputs to all matrices to be sequential left to right, top to bottom"); disp("Inputs to A begin"); for i = 1:rows for j = 1:cols A(i,j) = input("value for A:") end end n = length(A(1,:)); Aug = [A,eye(n,n)]; for j = 1:n-1 for i = j+1:n ...
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// SS SCILAB EXPT 5 PART 2 //clc; //i=sqrt(-1); //h_mag1=[]; //w1=[]; //for w=-2*%pi:0.01:2*%pi // h=1/(1-0.5*exp(-i*w)); // h_mag=abs(h); // h_mag1=[h_mag1 h_mag]; // w1=[w1 w]; //end //plot(w1,h_mag1); // //figure; //i=sqrt(-1); //h_mag1=[]; //w1=[]; //for w=-2*%pi:0.01:2*%pi // h...
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function [x]=poincare(orbit,NbrIti,Dim,Delai, CrossDirect, CrossAxe, Crosspos) // Initialisation Commandline=''; NbrComp=size(orbit,2); if isdef('NbrIti','local')... then Commandline=Commandline+' -l'+string(NbrIti), end; if isdef('Dim','local')... then Commandline=Commandline+' -m'+string(Dim), end; if isde...
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clear k = 24.0*(10**12) //N.sq.mm Flexure rigidity E = 200.0 //GPa - Youngs modulus of the string l = 5000.0 //mm - The length of the string C_A = 300.0 //sq.mm - crossection area P = 50.0 //KN - The force applies at the end a = 2000.0 //mm - The distance C-F x =...
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//chapter 16 Ex 1 clc; clear; close; t1=36; t2=45; //time taken by A and B to fill tank individually A1hour=1/t1; B1hour=1/t2; //part filled by A and B in 1 hour each AB1hour=A1hour+B1hour; //part filled by both in 1 hour mprintf("Thus the time taken by both pipes together to fill the tank is %d hours",1/AB1h...
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clc clear //Input data C=250 //Velocity of air in m/s D=10 //Diameter in duct in cm T=5+273 //Static temperature in K P=40 //Static pressure in kPa k=1.4 //Adiabatic constant Cp=1005 //Specific heat capacity at constant pressure in J/kg-K R=287 //Specific gas constant in J/kg-k //Calculation To=T+(C^2/(...
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//clc() //N2 + 3H2 = 2NH3 V1 = 100;//m^3 ( 1 = N2) V2 = V1 * 3;// ( According to Avagadros principle, equal volumes of all gases under similar condition contains same no. of moles) disp("m^3",V2,"(a)Volume of hydrogen required at same condition = ") P1 = 20;//bar T1 = 350;//K P2 = 5;//bar T2 = 290;//K V3 = 3 *...
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//Attitude Definition and Beta Angle // Authours: Matthieu D. Jessie A. Arvin T. clear; clc; clf; // Remove at implementation function [outx, outy, outz] = xRot(vec,theta) R1 = [1,0,0;0,cos(theta),sin(theta);0,-sin(theta),cos(theta)]; out = vec*R1; outx = out(1); outy = out(2); outz = out(3); endfunction fu...
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function M = f(n, a, b) A = eye(n, n) * (a - b); B = ones(n, n) * b; M = A + B; endfunction function M = g(n, a, b, c) A = eye(n, n) * a; B = diag(ones(n - 1, 1), -1) * b; C = diag(ones(n - 1, 1), 1) * c; M = A + B + C; endfunction function M = h(x) l = length(x) - 1; A = ones(x)' ...
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clc// // // //Variable declaration c=3*10^8; //velocity of light(m/s) m=1.67*10^-27; //mass of proton(kg) h=6.626*10^-34; //planck's constant //Calculation lamda=h*10/(m*c); //de broglie wavelength(m) //Result printf("\n de broglie wavelength is %0.3f *10^-14 m",lamda*10^14)
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// Example A-8-7-1 // PID Design with Frequency Response clear; clc; xdel(winsid()); //close all windows mode(0); // please edit the path // cd "<your code directory>"; // exec("plotresp.sci"); s = %s; Gp = syslin('c',s + 0.1,s^2 + 1); Kv = 4; K = Kv / abs(horner(Gp,0)) // Step 1 : Gain adjust G1 = Gp * K / s G1w...
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clc //initialisation of variables l20=0.1//m l1=0.0999//m s=0.000011//1/c t1=20 //CALCULATIONS t=((l1-l20)/(l20*s))+20 //results printf(' temperature the rod must be reduced is= % 1f C',t)
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// Scilab code Exa1.1 : : Page 51 (2011) clc; clear; Z = 79; // Atomic number of Gold z = 1; // Atomic number of Hydrogen e = 1.60218e-019; // Charge of an electron, coulomb K = 9e+09; // Coulomb constant, newton metre square per coulomb square E = 2*1.60218e-013; // Energy...
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// Aim:Refer Example 4-3 for Problem Description // Given: // Kinematic viscosity of oil: nu=100; //cS // velocity of oil: v=10; //ft/s // Pipe diameter: D=1; //in // Length of pipe: L=100; //ft // specific gravity of oil: SG_oil=0.9;
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//clear// clear; clc; //Example 26.1 //Given alpha = 5; per = 0.2; //[scf/ft^2-h-atm] Pf = 150; //[lbf/in.^2] Pp = 15; //[lbf/in.^2] //Solution //(a) R = Pp/Pf; //At the feed inlet xin = 0.209; //Using Eq.(26.17) A = alpha-1; B = 1-alpha-1/R-xin*(alpha-1)/R; C = alpha*xin/R; yi_in = (-B-sqrt(B^2-...
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exec('plates.sci') [N, B] = plates(6, 1.25, 1.2) printf('N:\n') disp(N) printf('\n') printf('B:\n') disp(B) printf('\n')
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clc; //Example 26.10 //page no 395 printf("Example 26.10 page no 395\n\n"); //a bed of 200 mesh particles is fluidized with air d_b=0.2//diameter of bed,m d_p=7.4e-5//particle diameter L_mf=0.3//bed height at minimum fludization e_mf=0.45//bed porosity at min. fluidization L_o=L_mf*(1-e_mf)//the zero porosity ...
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warning('off'); fp=mopen('lines.dat','w'); for i=1:100 mfprintf(fp,'\n' ); end mclose(fp);
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//chapter 28 //Example 3 clc //Given r=1*10^-10 //radius of the atom in meter Z=79 //gold atomic number e=1.6*10^-19 //charge in coul q=Z*e //total positive charge in coul E=(9.0*10^9)*q/r^2 disp(E,"Electric field strength at the surface of the gold atom in nt/coul is")
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Na = 10^19; Nd = 10^16; E1 = 4*10^5; E2 = 10^7; eps0 = 8.84*10^-14; //in F/m eps = 11.9*eps0; q = 1.6*10^-19; V1 = eps*E1^2/(2*Nd*q); disp(V1,"breakdown voltage for Si = ") V2 = eps*E2^2/(2*Nd*q); disp(V2,"breakdown voltage for diamond = ")
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unit Main; interface uses Winapi.Windows, Winapi.Messages, System.SysUtils, System.Variants, System.Classes, Vcl.Graphics, Vcl.Controls, Vcl.Forms, Vcl.Dialogs, Vcl.StdCtrls, VirtualTrees, VirtualExplorerTree; type TForm1 = class(TForm) Memo1: TMemo; Button1: TButton; procedure Butto...
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//Example 3.2.5 page 3.14 clc; clear; nx= 3.6; TF= 0.68; n= 0.3; //Pe=Pint*TF*1/(4*nx^2); //ne= Pe/Px*100 ..eq0 //Pe = 0.013*Pint //Eq 1 //Pint = n*P; //Eq 2 //substitute eq2 and eq1 in eq0 ne = 0.013*0.3*100; printf("The external Power efficiency is %.2f %%",ne); // Wrongly printed in textboo...
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errcatch(-1,"stop");mode(2);//Example 5.11 // Fluxmeter deflection ; ; //given data : l=5*10^-2;// in m N=40;// turns B=5*10^-3;// in Wb/m^2 b=1.5*10^-2;// in m cs=2*10^-4;// in m^2 B1=0.05;// in Wb/m^2 fi=B1*cs; del_fi=2*fi; theta=(del_fi*10)/(N*B*l*b); disp((theta*(180/%pi)),"Fluxmeter deflection,(degree) = ") exi...
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//Лаба 14 clc disp('********Задание 1********') format(8) x=1:.01:5 y=(2*(sin(x).^2)) J1=inttrap(x,y) disp(J1,'* * * *Метод трапеций* * * * *') J2=intsplin(x,y) disp(J2,'* * * *Метод сплайн-интерполяций* * *') disp('') disp('********Задание 2********') x=[0 1 3 4 6 9 10] y=[1 3 2 3 5 3 4] J=inttrap(x,y) disp(J,'* * *...
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//===================================================================================== //Chapter 13 example 1 clc;clear all; //variable declaration l = 0.6; //length of solenoid in m N = 600; //number of turns I = 2; //current passing through solenoid in A ur = 1; //air coiled so...
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<?xml version="1.0" encoding="utf-8"?> <test> <description> Process 2D vorticity output </description> <executable>FieldConvert</executable> <parameters> -f -m vorticity -e bfs_tg.xml bfs_tg.fld bfs_tg_vort.fld</parameters> <files> <file description="Session File">bfs_tg.xml</file> <file descri...
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clear all; clc; //This numerical is Ex 1_3E,page 11. H=295//net head in ft Q=148//water flow rate n=1800//rpm E=0.87//efficiency a=62.4//product of density and accelaration due to gravity omega=(n*2*%pi)/60 dp=a*H printf('The pressure is %g lb/ft^2',dp) Ps=E*Q*dp printf('\n Output power is equal to %0.3f lb-...
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// SAMPLE PROBLEM 3/29 clc;funcprot(0); // Given data v_1=50;// m/s v_2=0;// m/s e=0.5;// The effective coefficient of restitution theta=30;// degree // Calculation v_1an=e*v_1*sind(theta);// ft/sec v_1at=v_1*cosd(theta);// ft/sec // Assume ' as a v_a=sqrt((v_1an)**2+(v_1at)**2);// ft/sec theta_a=atand((v...
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function [y]=gauspuls(t,fc,bw) // Generates Gaussian-modulated sinusoidal pulses // Calling Sequence // [y]=gauspuls(t,fc,bw) // [y]=gauspuls(t,fc) // [y]=gauspuls(t) // Parameters // t: Real or complex valued vector or matrix // fc: Real non negative number or complex number // bw: Real positive number or complex numb...
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clear; clf; // constant variables frequency = 0.1; // Hz omega = 2 * %pi * frequency; sigma_0 = 6; // MPa E = 3; // elastic modulus (MPa) eta = 5; // viscosity (MPa/s) dt1 = 0.01; // s dt2 = dt1 * 10; dt3 = dt1 * 100; function sigma_t = Stress(t) sigma_t = sigma_0 * sin(omega * t); endfunction function epsilon ...
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function M1=%hm_s_s(M1,M2) // Copyright INRIA // hypermatrix - scalar if and(size(M2)==[1 1]) then M1('entries')=M1('entries')-M2 else dims=M1('dims')(:) dims(find(dims==1))=[] if and(dims'==size(M2)) then M1('entries')=M1('entries')-M2(:) else error(9) end end
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//example 8 //Mixing of Conditioned Air with Outdoor Air clear clc disp('The properties of each inlet stream are determined from the psychrometric chart to be') v2=0.889 //Specific volume of outside air in m3/kg dry air w2=0.0182 //properties of stream 2 in kg water/kg dry air h2=79.0 //Specific enthalpy of out...
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// Ex5_2 clc; // Given: E0=5;// in MeV m=1; M=7 // Solution: Erecoil=(4*5*m*M*((sin(45*3.14/180))^(2)))/((m+M)^2); Escat=E0-Erecoil; printf("\n The energy of protons scattered through an angle of 90 deg. is = %f MeV",Escat) Eresi=E0-0.48; Erecoil2=(14/64)*Eresi; Escat2=Eresi-Erecoil2; printf(...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monito...
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//i/p args contain imaginary elements b = [(1/3)*%i 1/4 1/5 1]; a = b(:,$:-1:1); flag = ismaxphase(b,a); disp(flag); //output //!--error 246 //Function not defined for given argument type(s), // check arguments or define function %p_bezout for overloading. //at line 31 of function gcd called by : //at line ...
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DS1(1): Parting DS1(2): is such DS1(3): sweet DS1(4): sorrow.
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m=100; n=10; dt=1/(m*n); maxSec=3 A=[ 0, 0, 0; -1/dt, 0, 0; -1/dt^2,-1/dt, 0 ]; B=[1; 1/dt; 1/dt^2 ]; function U = ingresso(amplitude, phase) T=[1:m*maxSec+1]; P=sin((T-1)*2*%pi/250+phase)*amplitude; // Funzione di ingresso (sinusoidale con periodo 250*n e max=amplitude (deg) ) for j...
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//chapter 7 Ex14 clc; close; //Let one number be x, tbhus other is 50-x; according to given conditions forming the polynomial p=x^2-50*x+600; solving it we get mycoeff=[600 -50 1]; p=poly(mycoeff,"x","coeff"); r=roots(p); printf("The two parts are: %d and %d",r(1),r(2));
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clc clear //INPUT DATA l=1*10^-2//length of the intrinsic Ge rod in m b=1*10^-3//breadth of the intrinsic Ge rod in m t=1*10^-3//thickness of the intrinsic Ge rod in m T=300//temperature of the intrinsic Ge rod in K me=0.39//The electron mobility in m^2 V^-1 s^-1 mh=0.19//The hole mobility in m^2 V^-1 s^-1 ni=...
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//exapple 2.1 clc; funcprot(0); // Initialization of Variable pi=3.14259; f=120.80//focal length a=-35.52//elevation of A b=8.48//elevation of B c=48.26//elevation of C alphaa=atan(a/f); alphab=atan(b/f); alphac=atan(c/f); phi=(354+30/60)*pi/180;//azimuth of camera phia=phi-alphaa-360*pi/180;//azimuth ...
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 2.6w //calculation of angle //given data xcompOA=4; //magnitude(in m) of x component of OA vector //xcompOB=6*cos(theta) magnitude(in m) of x component of OB vector //calculation theta=acosd(-xcompOA/6);//since x...
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N=32 Rkm=1.6 Acell=(3*sqrt(3)/2)*(Rkm^2) TA=N*Acell//total service area Tc=336 n=7 Ncpc=Tc/n//number of channels per cell TSC=Ncpc*N//total sysytem capacity N1=128 Ahex=TA/N1 R=sqrt(Ahex/(1.5*sqrt(2))) NCap=Ncpc*N1 disp(TA,'total service area in kmsqr') disp(Ncpc,'number of channels per cell') disp(TSC,'total sysytem c...
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matriz = input("Digite a matriz") matrizY = zeros(matriz) y = matrizY(:,1) y(1,1) = 1 matrizY(:,size(matriz,'c'))=y for i= size(matriz,'c')-1:-1:1 matrizY(:,i) = matriz * y y = matrizY(:,i) end y = -(matriz * y) p = matrizY\y id_a = eye(matriz) pi = [id_a(:,1)] pi(1,1) = 0 for j = 0: size(matriz,'c')-1 ...
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kissinamukun kitta wẻ kissinamukỏkepun V;IPFV;SBJV+POT+OPT kissinamukun ā kẻ kissinamukủkepun V;PFV;SBJV kissinamukun ā kissinamukủkepunā V;IPFV;ADM kissinamukun kẻ kissinamukunotookwā V;PRF;COND+IND kissinamukun kitta kẻ kissinamukunookopun V;PFV;COND+POT kissinamukun kitta kẻ wẻ kissinamukunookopun V;PFV;COND+POT+OPT...
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// Résolution numérique d'une équation différentielle // y' + b y = c // on cherche la solution y(x) // méthode utilisée : la fonction ode de Scilab // plus d'info en tapant help ode dans Scilab // S. Celles // 09/02/2007 clear b = 1; // MODIFIABLE c = 1; // MODIFIABLE // on réécrit l'équa diff sous la forme // y' =...
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// Example no B.1 // To determine SNR at the detector output stage // Page no. 613 clc; clear all; // Given data SNRin=20; // SNR at the receiver antenna input terminal in dB F=6; // Noise figure in dB // SNR at the detec...
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clear all; clc; //This numerical is Ex 3_7E,page 54. //Velocity diagrams are not drawn. This is with Scilab team's permission. //The numerical part of the question has been solved. r_t=5.2 r_h=3.5 N=4500 A=%pi*(r_t^2-r_h^2) printf(" A is equal to %0.2f in^2",A) disp("On converting to feet we get A= 0.322...
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//clc() //CO(g) + 2H2(g) = CH3OH(g) T1 = 298;//K T2 = 1073;//K //Cp(CH3OH) = 18.382 + 101.564 * 10^-3 * T - 28.683 * 10^-6 * T^2 //Cp(CO) = 28.068 + 4.631 * 10^-3 * T - 2.5773 * 10^4 * T^-2 //Cp(H2) = 27.012 + 3.509 * 10^-3 * T + 6.9006 * 10^4 * T^-2 //for reactants, H1 = integrate('28.068 + 4.631 * 10^-3 * T ...
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printf("\t example 16.5 \n"); printf("\t approximate values are mentioned in the book \n"); T1=250; // inlet hot fluid,F T2=200; // outlet hot fluid,F t1=150; // inlet cold fluid,F t2=190; // outlet cold fluid,F W=100000; // lb/hr w=31200; // lb/hr printf("\t 1.for heat balance \n") C=0.25; // Btu/(lb)*(F) Q=...
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Xbar = [3.01 2.97 3.12 2.99 3.03 3.02 3.10 3.14 3.09 3.20]; S = [0.12 0.14 0.08 0.11 0.09 0.08 0.15 0.16 0.13 0.16]; c = [0.7978849 0.8862266 0.9213181 0.9399851 0.9515332 0.9593684 0.9650309 0.9693103 0.9726596]; n=4; Xbarbar= mean(Xbar); Sbar =mean(S); lcl = Xbarbar - (3*Sbar/(sqrt(n)*c(n-1))); ucl = Xbarbar +...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Engineering Thermodynamics by Onkar Singh Chapter 7 Example 8") m=5;//steam flow rate in kg/s p1=5*1000;//initial pressure of steam in Kpa T1=(500+273.15);//initial temperature of steam in K p2=0.2*1000;//fina...
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// // This file is part of Arduino toolbox // Copyright (C) 2012-2012 - DEMOSCIENCES - Alain CAIGNOT // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also availa...
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[aws_csm_1] csm_enabled = true csm_host = bar1 csm_port = 1234 csm_client_id = foo [aws_csm_2] csm_enabled = false csm_host = bar2 csm_port = 5678 csm_client_id = bar
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART IV : UTILIZATION AND TRACTION // CHAPTER 2: HEATING AND WELDING // EXAMPLE : 2.1 : // Page number 724-725 clear ; clc ; close ; // Clear the work space and console ...
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function f=%p_e(i,j,f) // f=%p_e(i,j,f) <=> f=f(i,j) , i,j integers (or booleans f(i,j) is f(find(i),find(j)) //! // Copyright INRIA [lhs,rhs]=argn(0) if rhs==2 then if type(i)==4 then i=find(i),end f=j(i) else if type(i)==4 then i=find(i),end if type(j)==4 then j=find(j),end f=f(i,j) end
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2_a: (a^2 + b^2)^2 = (a^2 - b^2)^2 + (2*a*b)^2 2_b: (a^2 + b^2)^2 = (a^2 + b^2)^2 + (0)^2 2_c: 1 - 1; 2; 2_d: 1 + 1; 0; 3_a: (a^2 + b^2)^3 = (a^3 - 3*a*b^2)^2 + (3*a^2*b - b^3)^2 3_b: (a^2 + b^2)^3 = (a^3 + a*b^2)^2 + ( - a^2*b - b^3)^2 3_c: 1 - 3; 3 - 1; 3_d: 1 + 1; - 1 - 1; ...
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clear; clc; close; Vcc = 6; Vbe = 0.7; Rx = 1.3*(10^(3)); Ix = (Vcc-Vbe)/Rx; disp(Ix,"Current through each transistor :");
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// This script produces a graph of the bathymetry created with "BathCreator.f95". clf; scf(0); a=gcf(); a.figure_size= [500,350]; h1=read("topo.dat",-1,51); // read input data x = (0:0.1:5)'; y = (0:0.1:5)'; // location vectors hzero = max(h1,0.0); plot3d(x,y,-hzero',alpha=5,theta=-70,flag=[7,2,3]);
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// This code perform complex Fourier transform of the input data clear; clc; exec(PiLib); xdel(winsid()) // Parameters ========================================================== work_dir='C:\MyDrive\Work\CO_junc\E_kick\EL' // folder of tot_charge.sod E_max=5 // E max data_ini=1; // initial row to perform FT dE...
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close(); clear; clc; V = 400; //V f = 60; //Hz p = 4; R1 = 0.2; //ohm X1 = 0.5; //ohm Xm = 20; //ohm X2_ = 0.2; //ohm R2_ = 4; //ohm loss = 800; //W n = 1755; //rpm ns = 120*f/p; s = (ns-n)/ns; Z = R1 + %i*X1 + (%i*Xm)*(R2_ + %i*X2_)/(R2_ + %i*(Xm+X2_)); Zr = real(Z); Zi = imag(Z); Zarg = 180/%pi * ...
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-- VectorCAST 6.4d (02/29/16) -- Test Case Script -- -- Environment : THREAD -- Unit(s) Under Test: sysApi sysCfg sysMsg sysQueue sysTime -- -- Script Features TEST.SCRIPT_FEATURE:C_DIRECT_ARRAY_INDEXING TEST.SCRIPT_FEATURE:CPP_CLASS_OBJECT_REVISION TEST.SCRIPT_FEATURE:MULTIPLE_UUT_SUPPORT TEST.SCRIPT_FEATURE:MIXE...
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//Chapter 16, Problem 7, Fig.16.8 clc; L=0.12; //inductance in henry R=3000; //resistance in ohm C=0.02e-6; //capacitance in farad V=40; //voltage f=5000; //frequency Xl=2*%pi*f*L; ...