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clc; D=0.15; // Inlet eye diameter in m N=20000; // Speed in rpm ca1=107; // Axial velocity in m/s T01=294; // Inlet temperature in kelvin p01=1.03; // Inlet pressure in kg/cm^2 Cp=1.005; // specific heat at constant pressure in kJ/kg K r=1.4; // Specific heat ratio R=287; // Characteristic gas constant in J/kg...
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function [Tab]=tableau_initial(A,b,c) [m,n]=size(A); I=eye(n); Tab=[A,I,b;c',zeros(1,m+1)]; endfunction function [varS,varE,Pivot]=VarES_Pivot(Tab) [m,n]=size(A); [maxi,varE]=max(Tab(m,1:n)); tmp=Tab(1:m,varE); for (i=1:m) if (tmp(i)==0)tmp(i)=10^5;end end [maxi,varS]=min(Tab...
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enqueue 1 enqueue 2 enqueue 5 enqueue 8 enqueue 7 enqueue 15 enqueue 22 enqueue 11 dequeue dequeue enqueue 6 enqueue 9 dequeue dequeue dequeue dequeue enqueue 19 enqueue 20 enqueue 21 enqueue 23 enqueue 24 dequeue dequeue enqueue 3 enqueue 4 enqueue 5 enqueue 6 enqueue 18 enqueue 17 dequeue
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function block=dc_in_c(block,flag) if flag==1 then j = 1:block.ipar(1) block.outptr(1)(j)=block.rpar(j); end endfunction
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function potensio_demo() for x=1:10 p = cmd_analog_in(1,2); if(p>uint16(0) & p<uint16(320)) cmd_digital_out(1,11,1); sleep(1000); cmd_digital_out(1,11,0); elseif p>=uint16(320) & p<=uint16(900) cmd_digital_out(1,10,1); sleep(1000); ...
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clc //Example 14.5 //Plot ratio of friction radius to outer radius versus ratio of inside radius to outer radius [Rf/Ro vs Ri/Ro] //Assuming outer radius=100mm and a matrix r of multiplying constants r=[0.1,0.2,0.3,0.4,0.5,0.6,0.7,0.8,0.9] Ro=100 n=length(r) // Assuming uniform pressure for i=1:n Ri1(...
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// Scilab Code Ex5.7: Page:299 (2011) clc;clear; lambda = 5.0e-007;....// Wavelength of the monochromatic light, m D = 1;....// Distance between the silts and the screen, m d = 5e-004/2;....// Half of the distance between the two slits, m mu = 1.5;....// Refractive index of glass t = 1.5e-006;....// Thickness of ...
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description = Assume service states during program downtime logfile = assumed_states_during_program_downtime_service.log assumed service states during program downtime #1 { assumestatesduringnotrunning = true start_time = 1202684400 end_time = 1202770800 service_description { testhost;PING } correct { TIME_O...
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// Exa 3.17 format('v',7);clc;clear;close; // Given data Idc = 2;//dc current in mA Idc = Idc * 10^-3;// in A Rm = 500;//meter resistance in ohm Erms = 10;//r.m.s value in v Eav = 9;//average value in V Edc = 0.9*Erms;//dc voltage in V Rs = (Edc/Idc) - Rm;//multiplier resistance in ohm Rs = Rs * 10^-3;// in k...
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clear; clc; // Example: 5.6 // Page: 153 printf("Example: 5.6 - Page: 153\n\n"); // Solution //*****Data*****// W = 5;// [hp] Q = 7000;// [J/s] Th = 400 + 273;// [K] Tl = 24 + 273;// [K] //*************// W = 5*745.7;// [W] thermal_eta = W/Q; theoretical_eta = (Th - Tl)/Th; if theoretical_eta...
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//EXAMPLE 3-48 PG NO-202-203 Vao=186.7-%i*87.06; Vco=-38.5+%i*292.48; Vbo=-(Vao+Vco); disp('i) VOLTAGE (Vbo) is in rectangular form = '+string (Vbo) +' V '); Vab=Vao-Vbo; disp('i) VOLTAGE (Vab) is in rectangular form = '+string (Vab) +' V '); Van=201-%i*37.51; Von=Van-Vao; disp('i)...
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#set time slow #rele print CROUTPUT: #TITLE Test SYST/SORT/MERGE # Part 1 sets the FREIDEL pairs flag to NO in SYST, thus keeping # the pairs separate independent of what was set in LIST 13 # # After SORTing, the reflctions are first MERGED with TWIN set to YES, # thus only merging FOT for reflections with identical ...
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clc; warning("off"); printf("\n\n example6.1 - pg200"); // given q=50; //[gal/min] - volumetric flow rate d=2.067/12; //[ft] - diameter A=0.02330; //[ft^2] - flow area p=0.99568*62.43; //[lb/ft^3] - density of water at 86degF mu=0.8007*6.72*10^-4; //[lb/ft*sec] - viscosity of water at 86degF u=q/(60*7.48*...
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clear clc CAo=6;CM=0.4;//kg/m3 V=1;//m3 k=4; //From fig 29.5 N=sqrt(1+(CAo/CM)); kt_op=N/(N-1); C_by_A=0.1; t_op=kt_op/k; v_op=V/t_op; //The feed rate of glucose FAo=v_op*CAo; printf("\n The feed rate of glucose is %f",FAo) printf("kg/hr") //Max consumption rate of glucose is XA=N/(N+1); c_max=FAo*XA; printf("\n Max co...
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######################################################## ## ENVIRONMENT : TST ######################################################## # Enable/disable the JavaScript logger for this environment. env.javascript.logger.enabled=false
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clear// //Variable Declaration M_max=60*10**3 //Maximum Bending Moment in kN.m sigma_w=120*10**6 //Maximum Bending Stress allowed in Pa M_max_2=61.52*10**3 //max bending moment computed in N.m //Section details mass=38.7 //Mass in kg/m g=9.81 //Acceleration due to gravity in m/s^2 S=549*10**3 //Sectional m...
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//Example 4 // number of beats and time interval clc; clear; close; n1=300;//Hz n2=303;//Hz bfs=n2-n1;// disp(bfs,"beat frequency per second is,=") ti=1/bfs;//second disp(ti,"time interval is,(second)=")
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//Fluid system - By - Shiv Kumar //Chapter 2 - Impact of Jet //Example 2.3 clc clear //Given Data:- d=40; //Diameter of the Jet, mm V=60; //Velocity of the Jet, m/s AoD=125; //Angle of Deflection, degrees //Data Used:- rho=1000; //Density of water, kg/...
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clc //initialization of new variables clear h=380 //m T=300 //K g=9.81 //m/s^2 R=286.6 //m2/(s^2 K) //calculations Pr=exp(-g*h/(R*T)) //P2/P1 P1=1 //atm dP=(P1-Pr)*101325 //N/m^2 //result printf('The difference in pressure is %d N/m^2',dP)
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clc; P=100000; // VA of transformer nmax=0.98; // maximum efficiency of transformer pf=0.8; // power factor at which maximum efficiency occurs l=80; // percentage of full load at which maximum efficiency occurs po=P*pf*(l/100); // output at maximum efficiency pl=((1/nmax)-1)*po; // total losses pc=pl/2; // core...
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//(9.12) Air enters a turbojet engine at 0.8 bar, 240K, and an inlet velocity of 1000 km/h (278 m/s). The pressure ratio across the compressor is 8. The turbine inlet temperature is 1200K and the pressure at the nozzle exit is 0.8 bar. The work developed by the turbine equals the compressor work input. The diffuser,...
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//chpater22 //example22.1 //page491 I_DSS=12 // mA V_GS_off=-5 // V printf("I_D=%d*(1+V_GS/%d)^2 mA \n",I_DSS,-V_GS_off)
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; checks ite as a formula (set-logic QF_UF) (declare-fun a () Bool) (assert (ite true a a))
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// Scilab code Ex6.1: Pg 202 (2008) clc; clear; // Comparing alternating voltage v = 35*sin(314.2*t) with the standard Eq. // Part (a) V_m = 35; // Maximum value of alternating voltage, volt // Part (b) f = poly(0, "f"); // Declare a variable for freq. f = roots(2*%pi*f - 314.2); // Frequency of waveform, H...
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//Faults and Protection// //Example 16.6// V=230;//ac input voltage in volts// Vh=30;//each selenium plate handling voltage in volts// N=((V/Vh)1)+1;//number of plates in series in each direction in the ckt// printf('number of plates in series in each direction=N=%f',N); Nt=2*N;//total number of plates in series ...
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//to compute the generator induced emf when fully loaded in long shunt compound and short shunt compound clc; P=75000; V_t=250; I_L=P/V_t; R_a=.04; R_se=.004; R_f=100; disp('case of long shunt'); I_f=V_t/R_f; I_a=I_L+I_f; V_b=2; E_aLS=V_t+I_a*(R_a+R_se)+V_b; disp(E_aLS,'generator induced emf(V)'); dis...
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function [y] = taylor(t0,n,t, w0, r) h = t - t0 y = 0 for i =0:n-2 rest = modulo(i,4) if rest == 0 dev = r(2)*(-sin(w0*t0))*w0^(i+1) + r(3)*cos(w0*t0)*w0^(i+1) elseif rest == 1 dev = r(2)*(-cos(w0*t0))*w0^(i+1) + r(3)*(-sin(w0*t0))*w0^(i+1) elseif...
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//Example11.11 // to find the resolution and analog output voltage of 8-bit D/A converter clc; clear; close; VFS = 10 ; N = 8 ; BI = 10101111 ; BI = 11100011 ; BI = 00101001 ; BI = 01000110 // the resolution of 8-bit D/A converter is defined as Resolution = VFS/(2^N-1) ; // An analog output voltage of D/...
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+------------------------------------------------------------------------------+ | | | | | ...
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//Chapter 2 //Example 2.4 //Page 60 clear; clc; R1 = 120; R2 = 120; R3 = 120; R4 = 121; V=10; printf("Assuming detector impedance to be very high , we find the offset as \n") //Calculation of Delta Vd Del_Vd = V*(((R3*R2)-(R1*R4))/((R1+R3)*(R2+R4))) printf("Delta Vd = %f V",Del_Vd)
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// Exa 3.7 // To calculate L50 path loss for a PCS system using Okumura and COST231 models. clc; clear all; d=[1 2 3 4 5]; //in km hb=30; //Height of BS antenna in metres hm=2;// height of mobile antenna in matres fc=900;//carrier frequency in MHz W=15; //street width(m) b=30; // distance between buildi...
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clc; clear; //Example 2.5 printf("Example 2.5\nPage 2.23") //Given A=1; //let [sq m] x1=0.23; //thickness of fir brick layer[m] x2=0.115; // [m] x3=0.23; //[m] T1=1213; //Temperature of furnace [K] T2=318; //Temperature of furnace [K] dT=T1-T2; //[K] k1=6.047; //W/(m.K) (fire brick) k2=0.581;...
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//clc() mcoal = 100;//kg mC = 63;//kg mH = 12;//kg mO = 16;//kg mash =9;//kg mfixC = 39;//kg mH2O = 10;//kg mCvolatile = mC - mfixC; mHH2O = mH2O *2.016/18.016;//(mass of hydrogen in moisture) mHvolatile = mH - mHH2O; mOH2O = mH2O - mHH2O; mOvolatile = mO - mOH2O; mtvolatile = mCvolatile + mHvolatile + mO...
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function image = chargerImage(path, isRGB) if(isRGB == 0) then image = double(imread(path)); else image = double(rgb2gray(imread(path))); end endfunction
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clc mode(1) pause //Zadatak 1 //a) //Plotanje i definisanje funkcija deff('res=funct_1(x)','res=cos(x)-x'); x0 = 0; x = linspace(-2,2,51); y=cos(x); plot(x,y,'r-'); plot(x,x,'b-'); pause //Poziv fsolve xsol =fsolve(x0,funct_1) pause //b) //Plotanje i definisanje funkcija deff('res=funct_2(x)',['res(1)=x(2)-(x(1).^2+1)...
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//check o/p when i/p is a vector a = [1.0000 0.6149 0.9899 0.0000 0.0031 -0.0082]; lsf = poly2lsf(a); disp(lsf); //output // 0.7841731 // 1.5605415 // 1.8776459 // 1.8984313 // 2.3592523 //
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// Example 18_2 clc;funcprot(0); // Given data T=273;// K p=0.113;// MPa M=20.183;// kg/kg mole N_o=6.022*10^26;// molecules/kgmole k=1.380*10^-23;// J/(molecules.K) // Calculation m=M/N_o;// kg/molecule V_rms=((3*k*T)/m)^(1/2);// m/s r=1.3*10^-10;// The radius of the neon molecule in m sigma=4*%pi*r^2;...
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clear all; clc; disp("Scilab Code Ex 3.1 : ") //Given: offset = 0.2; //% a_x = 0.0016; //mm/mm a_y = 345; //Mpa //Refer to the given graph. //Calculations: //Modulus of Elasticity E = a_y/(a_x*10^3); //E is the slope in GPa. //Yield Strength: sigma_ys = 469; //Graphically, for a strain of 0.002mm...
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clear; clc; close; disp("Example2.12") M1=0.7; dpt=0.99; //pt2/pt1=dpt. gm=1.4; //gamma //A2=1.237A1. a=1/1.237; //Calculations: M2 = poly(0, "M2"); k=(1/dpt)*(a)*(M1/(1+(0.2*(M1)^2))^3) pol = k*(1+(0.2*(M2)^2))^3 -M2; W=roots(pol); //disp(W) i=1 while i<=6 z=W(i) if imag(z)==0 then if real(z)<...
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//i/p arg p is not specified and hence the default of p is taken as length(x)-1 x=[1 2 3 4 6 7 89 0 9]; [a,g] = lpc(x); disp(a); disp(g); //output // column 1 to 3 // // 1. - 0.0675779 - 0.1613922 // // column 4 to 6 // // - 0.0281914 - 0.0071025 - 0.0109020 // // column 7 to 9 // ...
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clc //Initialization of variables xc=[0 0.20 0.40 0.60 0.80 1] pc=[0 35 82 142 219 293] pa=[347 270 185 102 37 0] //calculations plot(xc,pc) plot(xc,pa) xlabel('Mole fraction xc') ylabel('Pressure /Torr') disp('From the graph it is clear that KA=175 torr and KC=165 torr. They are plotted with Raoults law lines')
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clc //initialisation of variables P= 7 //bar P1= 1.4 //bar T= 260 //C T1= 251 //C h= 2974.9 //J/gm //CALCULATIONS dT= T-T1 Mj= dT/(P-P1) //RESULTS printf ('Joule-Thomson coefficient= %.2f C/bar ',Mj)
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clc //Intitalisation of variables clear e= 5.6 //volts l= 9.8 //cm t= 1 //hr T= 25 //C A= 73.4 //ohm^-1 cm^2 F= 96500 //coloumbs //CALCULATIONS v= A/F pg= e/l v1= v*pg L= v1*t*3600 //RESULTS printf ('Mobility = %.2e cm/sec',v) printf ('\n Potential gradient = %.3f volt/cm',pg) printf ('\n Potential gra...
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clear //Given Il=4.0 //mA Vz=6 //V E=10.0 //V //Calculation Lz=5*Il L=Il+Lz Rs=E-Vz Rs1=Rs/(L*10**-3) //Result printf("\n The value of series resister Rs %0.0f ohm",Rs1)
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exec abc.sce header_var = printf("Hello World");
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//chapter 7 //example 7.6 //Calculate the electronic polarisability of Helium atoms //page 189-190 clear; clc; //given Er=1.0000684; // di-elecrtic constant of Helium gas at NTP Eo=8.85E-12; // in F/m (absolute permittivity) N=2.7E25; // number of atomsper unit volume //calculate // Since Er-1=(N/Eo)*alpha_e...
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function y=genf(p, t, a) //p:state reached by action a at time t y=zeros(ws,1); //cnt=2; //y(1)=k; //y(1)=0; if (p>0 & p<=gsize & t>0 & t<3*gsize) then //loadp should be executed first if (strcmp(part(grid(t+1),p+1),"X")==0) then y(1)=-1; elseif (strcmp(part(grid(t+2),p+1...
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clear; clc; // Example 5.2 printf('Example 5.2\n\n'); //Page no. 110 // Solution b_rd = 28.0 ;//[in. Hg] p_rd = 51.0 ;//[psia] p_atm = b_rd*14.7/29.92 ;//[psia] p_tnk = p_atm+p_rd ;//[psia] printf(' Pressure in tank in psia is %.1f psia\n',p_tnk);
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clear; clc; disp("--------------Example 8.3---------------") N=200; //input lines n=20; // lines in a group k=4; //number of crossbars in the middle stage crossbars1=N/n; // 1st stage crossbars2=k; // 2nd stage crossbars3=N/n; // 3rd stage size1a=n; // size of a crossbar in 1st stage size1b=k; size2=N/n; // ...
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funcprot(0); // Initialization of Variable function[dms]=degtodms(deg) d = int(deg) md = abs(deg - d) * 60 m = int(md) sd = (md - m) * 60 sd=round(sd*100)/100; if sd==60.0 then sd=0; m=m+1; end dms=[d m sd] endfunction alpha1=30+45.0/60+25.0/3600;//angle i...
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//Example 4.7 //calculatemthe inlet and outlet temp.of gas. //Given Q=38700 //kcal/h, heat duty W=2000 //kg/h gas flow rate cp=0.239 //kcal/kg C, specific heat of nitrogen A=10 //m^2 ,heat exchanger area U=70 //kcal/hm^2 C, overall heat transfer c...
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clear ; clc ; d = 1;//diameter of the steel bar in inches l = 12;//length of the steel bar in inches d1 = 3/2;//external diameter in inches d2 = 1;//internal diameter in inches P = 5;//axial pull in tons E_s = 30*10^6;//modulus of elasticity of steel in lb/in^2 E_b = 14*10^6;//modulus of elasticity of brass in ...
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errcatch(-1,"stop");mode(2);// given Qi(s)=0.04/s^2 Qi=0.04/s^2; e=limit(s*Qi*H,s,0) disp(e,"Steady stste eror=") exit();
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// Scilab Code Ex9.2: De-broglie wavelength of an electron from kinetic energy : Page-203 (2010) e = 1.6e-019; // Energy equivalent of 1 eV, J/eV h = 6.626e-034; // Planck's constant, Js m = 9.1e-031; // Mass of the electron, kg Ek = 10; // Kinetic energy of electron, eV // Ek = p^2/(2*m), solving for ...
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clear ; clc; // Example 6.10 printf('Example 6.10\n\n'); printf('Page No. 158\n\n'); // given //for Boiler-1 P_1 = 15;// Boiler pressure in bar Ts_1 = 300;// Steam temperature in degree celcius Tf_1 = 80;// Feed water temperature in degree celcius X_1 = 0;// Steam dryness fraction m_s1 = 9000;// steam rate...
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//Example 1.52://ARITHEMATIC MEAN,AVERAGE DEVIATION ,STANDARD DEVIATION AND VARAIANCE clc; clear; T=[197,198,199,200,201,202,203,204,205];//temperature in degree celsius f=[2,4,10,24,36,14,5,3,2];//frequency of occurence q=[T(1)*f(1),T(2)*f(2),T(3)*f(3),T(4)*f(4),T(5)*f(5),T(6)*f(6),T(7)*f(7),T(8)*f(8),T(9)*f(9)...
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function [stk,txt,top]=sci_qz() // Copyright INRIA txt=[] m=stk(top)(3) if m=='?' then m=stk(top-1)(3),end if lhs==1 then stk=list('gschur('+stk(top-1)(1)+','+stk(top)(1)+')','0',m,m,'1') else s=list('gschur('+stk(top-1)(1)+','+stk(top)(1)+')','-1',m,m,'1') if lhs==5 then [AA, BB, Q, Z, V]=lhsvarsnames() ...
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//scilab 5.4.1 clear; clc; printf("\t\t\tProblem Number 5.9\n\n\n"); // Chapter 5 : Properties Of Liquids And Gases // Problem 5.9 (page no. 193) // Solution //For the wet mixture,hx=hf+(x*hfg),solving for x gives us //Using table 1,we have, hx=900; //Btu/lbm //Enthalpy of wet mixture at 90F hf=58.07; //B...
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//Bolzano method by Rêmullo Costa function y = f(x) y = x^3-5*x+1; endfunction x = 0:0.1:3; y = f(x); plot(x,y); xgrid; a = 0.1; //ponto a avaliado por visualização grafica b = 0.3; // ponto b avaliado por visualização grafica x = a; //chute inicial erro = 1; //erro inicial iter = 1; while(erro > 10^-2) //A co...
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// Exa 6.36 format('v',7);clc;clear;close; // Given data C2 = 500;// capacitance in nF C2 = C2 * 10^-9;// in F f = 50;//frequency in Hz omega = 2*%pi*f;// in rad/sec C4 = 0.148;//capacitance in µF C4 = C4 * 10^-6;// in F R4 = 72.6;//resistance in ohm R3 = 300;//resistance in ohm C1 = C2*(R4/R3);// capacitanc...
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//Variable declaration Vcc=10 //supply voltage(V) Vce=10 Icq=140*10**-3 //Ic at Q point(A) Rl=8 //load resistance(ohms) vce=16 //instantaneous collector to emitter voltage(V) ic=235*10**-3 //instantaneous collector current(A) /...
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//=========================================================================== //chapter 4 example 6 clc; clear all; //Variable declaration I1 = 10; //current in A theta1 = 60; //deflection in ° theta2 = 40; //deflection in ° //calculations I2 = (I1)*(theta2/(theta1)); ...
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//Chapter 5:DC Motor Drives //Example 1 clc; //Variable Initialization //Motor ratings V1=200 //rated voltage in V Ia1=10.5 //rated current in A N1=2000 //speed in rpm Ra=0.5 //armature resistance in ohms Rs=400 //field resistance in ohms V2=175 //drop in source voltage in V //Solution flux2=V2...
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clc; clear; close; disp('a) Propagation delay for step case'); disp('Imax=Cl*(dVout/dt)=(Cl*Vdd)/(2*Tphl)'); disp('Tphl=Cl*Vdd/(2*Imax)'); disp('b) Propagation delay for ramp case'); disp('Imax=Cl*(dVout/dt)'); disp('Iout*dt=Cl*dVout'); disp('Integrating both sides,'); disp('(Imax*tr/4)+Imax*(Tphl-tr/2)=Cl*...
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//========================================================================================================== // chpter 3 example 14 clc; clear; //input data phi = 2*10^-5; //magnetic flux in Wb/m^2 H = 2*10^3; //in A/m A = 0.2*10^-4; //area in m^2 ...
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clc // initialization of variables clear E=200 //GPa h=102 //mm b=68 //mm Ix=2.53e+06 //mm^4 L1=4 //m ko=0.35 //N/mm^3 P=30.0 //kN //calculations E=E*10^3 P=P*10^3 L1=L1*10^3 k=b*ko Beta=(k/(4*E*Ix))^(1/4) if(L1>3*%pi/(2*Beta)) y_max=2*P*Beta/k M_max=-0.3224*P/Beta S_max=abs(M_max*h/(2*Ix))...
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//Chapter-4, Example 4.8, Page 136 //============================================================================= clc clear //let the current peak value of sinusoidal and rectangular waves are Im. //CALCULATIONS Im=1;//let im current value be 1(just for calculation purposes) rms1=sqrt(((Im)^2*%pi)/(%pi));//rms ...
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clear all clc close epsr=2.8;//Dielectric constant of plastic epso=8.84*1e-12;//Permittivity of air in F/m rho_s=25*1e-6;//Surface charge in C/m^3 a=25*1e-6;//Thickness of palstic in m b=75*1e-6;//distance in m //Calculation of electric stress in the foil/plastic laminate in MV/m Ea=b*rho_s/(a*epso+b*epso*...
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//chapter9 //example9.17 //page160 Vin=240 // V rms Rl=480 // ohm rf=1 // ohm Vm=Vin*2^0.5 // for bridge rectifier we know that Im=Vm/(2*rf+Rl) Idc=2*Im/%pi Irms=Im/2 P=Irms^2*rf printf("mean load current = %.3f A \n",Idc) printf("power dissipated in each diode = %.3f W \n",P) // the accurate answ...
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clc //Chapter6 //Ex_5 //Given A=10^-6 //in m2 Vo=0.856 //in V I=5*10^-3 // in Amperes Iso=0.176*10^-12 //in Amperes e=1.6*10^-19 // in coulombs Eo=8.85*10^-12 //in m-3 kg-1 s4 A2 Er=11.9 Th=417*10^-9 //in seconds Nd=10^22 //in m^-3 //let K=kT/e K=0.0259 //in V //Vo=(k*T/e)*log(I/Iso) V=(K)*log(I/Iso) ...
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// Ex4_24 clc; // Given: a1=6520;// c/min a2=4820;//c/min t=2;//min // Solution: k=log(a1/a2)/t; t1=0.693/k;// half life printf("The decay constant is %f min^-1 and the half life is %f min",k,t1)
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//Calculate percentage power savings when carrier and one of the sidebands are suppressed in a AM wave modulated to a depth of (a) 100% (b) 50% Pc = 10; m1 = 1; m2 = .5; Pt1 = Pc*(1+(m1^2/2)); Psb1 = Pc*(m1^2/4); s1 = (Pt1 - Psb1)/Pt1; s1a = s1 * 100; Pt2 = Pc*(1+(m2^2/2)); Psb2 = Pc*(m2^2/4); s2 = (P...
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//A Textbook of Chemical Engineering Thermodynamics //Chapter 5 //Some Applications of the Laws of Thermodynamics //Example 5 clear; clc; //Given: //The given problem is theoretical and does not involve any numerical computation //end
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clc k=8.617*10**-5//eV/K e=1.6*10**-19 //C Dp=10//cm^2/sec Lp=31.6*10**-4 //m g1taup0=10^14 //cm^-3 deltap0=10^13 //cm6-3 //deltap0=g1taup0*[g/((Dp/Lp)+s)] s=(Dp/Lp)*((g1taup0/deltap0)-1) disp(s,"surface recombination velocity in cm per sec is= ")
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- 10*w3v4*x^3 - 5*w3v4*y^4 - 10*z - z^2 - 25 ; vgcd=1; gcd=1; isZero=false; hasVariable=true; isBiased=true; mergeVariables= - 10*x_y_z - x_y_z^2 - 10*x_y_z^4 - 5*x_y_z^5 - 25; relation=EQ_0 ; evaluate=failure biased /01;10 -> - 10*z /02;1 -> - z^2 /03/01;10 -> - 10*w3v4*x^3 /04/01;5 -> - 5*w3v4*y^4 ;25 -> ...
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//Chapter 2 //Example 2_8 //Page 23 clear;clc; h=100; n_hydraulic=0.86; n_electrical=0.92; n_overall=n_hydraulic*n_electrical; w=9.81*1e3; printf("Weight of water available = %.1f N \n\n", w); power=w*h*n_overall; printf("Power produced = %.1f kW \n\n", power/1000); printf("Energy produced per hour = ...
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// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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//Chapter 2, Problem 12 clc; I=5; //Current in ampere R=100; //Resistance in ohms V=I*R; //Calculating voltage using Ohms law P=V*I; //Calculating power in watt printf("Potential difference across winding = %d V\n\n\n",V); printf("Power dis...
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clc; clear; close; LEnand=4/3; LEinv=1; LEnor=5/3; Cload=200;//in fF Cin=2;//in fF Pnand=1; Pinv=1/2; Pnor=3/2; Tinv=7.5;//in picoseconds path_effort=LEnand*LEinv*LEnor*Cload/Cin; disp(path_effort,'Total path effort='); Stage_effort=round(path_effort^(1/3)); disp(Stage_effort,'Stage effort='); D=3*Stage...
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(X (X (X (X a) (X (X Lorillard) (X spokewoman))) (X said)) (X (X ,) (X (X (X ``) (X (X This) (X (X is) (X (X an) (X old))))) (X (X story) (X .))))) (X (X (X (X there) (X is)) (X (X no) (X (X (X (X asbestos) (X (X in) (X our))) (X products)) (X (X now) (X .))))) (X '')) (X (X (X (X it) (X has)) (X no)) (X (X bearing) (X...
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// Wrapper function for calling C language routine ids_c from SciLab function Id = ids(Vds, Vgs, Vbs) l=link("/NFS1/yogesh/project/MNA/LUT/libids.so", "ids_c", "c") Id=0.0; sizeId=size(Id); Id=fort("ids_c",Vds, 1,"d",Vgs, 2, "d", Vbs, 3, "d", Id, 4, "d", "out",sizeId, 4, "d"); ulink(l); endfunction
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errcatch(-1,"stop");mode(2);// Exa 7.6 ; ; //given data R= 10;// in kohm R=R*10^3;// in ohm C= 100;// in pF C=C*10^-12;// in F f=1/(2*%pi*R*C);// in Hz disp(f*10^-3,"Frequency of the oscillation of the circuit in kHz") exit();
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// calculation of hysterisis and eddy current losses clc; P1=1500; f1=50; P2=3000; f2=75; A=[1 50;1 75]; //P/f=A+B*f B=[30;40]; v=A\B; disp('at 50Hz'); P_h=v(1)*f1;disp(P_h,'hysterisis loss(W)'); P_e=v(2)*f1^2;disp(P_e,'eddy current loss(W)'); disp('at 75Hz'); P_h=v(1)*f2;disp(P_h,'hysteri...
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# Copyright (C) 2017 Genome Research Ltd. # # Author: Robert Davies <rmd@sanger.ac.uk> # # Permission is hereby granted, free of charge, to any person obtaining a copy # of this software and associated documentation files (the "Software"), to deal # in the Software without restriction, including without limitatio...
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function [val, numiter] = puntofijo(p0, tol, iter) // Funcion que encuentra el punto fijo de una funcion g(x) = 1 + 0.5*sin(x) // Autor: Hector Gomez, Jorge Zavaleta //***************************************************************************** // ->Entrada // p0 (Real) - Numero real que denota el punto inicial de bu...
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clc disp("Example 5.53") printf("\n") disp("Design the value of L1,L2 & C for a hartley oscillator") printf("Given\n") //frequency of oscillation f=30*10^3 //then value of LC LC=1/(4*(%pi)^2*f^2) //select c as C=0.1*10^-6 //Total inductance L=LC/C //let L1=L2 L1=L/2 L2=L1 printf("The values of L1=\t%f h...
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//Example 4.8 clc; clear; close; format('v',9); //Given data : S1=0.9;//sp. gravity S2=13.6;//sp. gravity h1=12.5/100;//m P_AB=h1*(S2-S1);//meter of water disp("Difference in pressure head at the points A & B is "+string(P_AB)+" meter of water"); w=1000;//kg/m^3 P_diff=P_AB*w*9.81;//Pa or Nm^2 disp(P_diff,...
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//ques-18.24 //Finding vapour pressure of benzene at 300 K clc Hv=7413;//latent heat of vapourization (in cal/mol) T1=273+80; T2=273+27;//temperature (in K) P1=760;//mm Hg R=1.987;//cal/mol/K //On solving, log(P2/P1) = (Hv*(T2-T1))/(2.303*R*T1*T2) P2=P1/6.467; printf("The required vapour pressure is %.2f mm Hg...
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// 2.38 clc; b=0.02; t=0.004; I=(1/12)*b*t^3; F=25; l=0.25; E=200*10^9; x=(F*l^3)/(3*E*I); printf("deflection=%.2f m",x) DpF=x/F; Se=DpF*0.5*1000; Re=(10/1000)*(2/10); F_min=Re/Se; F_max=10/Se; printf("\nminimum force=%.2f N",F_min) printf("\nmaximum force=%.2f N",F_max)
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clc //initialisation of variables clear k1= 6.2 k2= 1.33*10^-3 k3= 6.78*10^4 T1= 800 //C T2= 300 //C //CALCULATIONS dS= k1*log(T1/T2)+k2*(T1-T2)-0.5*k3*(T1^-2-T2^-2) //RESULTS printf ('Entropy increase = %.2f cal deg^-1 g atom^-1',dS)
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function[f] = f1(x) f = cos(3.14*(x+1)/8)+0.148*x-0.9062 endfunction function[f] = f2(x) g = sin(0.3925*(x+1))+0.5405 endfunction function [raiz, x, iter, ea]=newtonraphson(x0,f,fp,tol,imax) iter = 0; // inicializa numero de iteracoes xr = x0; // inicializa raiz aproximada com a inicial x(iter+1)=...
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//Chapter 3, Problem 10 clc Zlo=0.2 //ratio of Zl/Zo impedance in ohm Zo=50 //output impedance in ohm //calculation of characteristic impedance Z0t=Zo*sqrt(Zlo) printf("Characteristic impedance, Z0t = %d ohm",Z0t)
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clear // // // //Variable declaration lamda=5890*10**-5 //wavelength(cm) dlamda=6*10**-5 //difference in wavelength(cm) k=2 //order w=2.5 //width(cm) //Calculation N=lamda/(k*dlamda*w) //minimum number of lines per cm //Result printf("\n minimum number of lines per c...
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//Example 8.2 //POWER GAIN AND RESULTANTT POWER GAIN clc; clear; g1=30;//ABSOLUTE GAIN FOR EACH STAGE N=5;// no. of stages Pdb=10*(log10(g1));//power gain in db Ndb= Pdb*N;//power gai of 5 stages in db Nfb=10;//NEGATIVE FEEDBACK IN DB Rpg=Ndb-Nfb;//RESULTANT POWER GAIN IN db disp(Ndb,"power gain in db") disp(Rpg,"resul...
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 18.17w //calculation of apparent depth of a air bubble inside a glass sphere //given data u=-4; //object distance (in cm) R=-10; //radius of curvature of the spherical glass sphere(in cm) mu1=1.5; //refractive index ...
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// // retiftoi=100 fplusd=0.15 s1=2.450-1.150 thetha1=5+(20/60) v1=(100*1300*sin(10+(40/60))/2)+(0.15*sin(5+(20/60))) s2=1.5 thetha2=8+(12/60) V2=21.197 d2=147.097 RL=750.500+1.8+12.045 RLD=RL+V2-1.5 printf("\n RL of instrument axis= %0.3f m",RL) printf("\n RL of D= %0.3f m", RLD) prin...
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function r = poly2ac(a,efinal) // Convert prediction polynomial to autocorrelation sequence. //Run rlevinson.sci before running this // Calling Sequence // R = poly2ac(a,efinal) // // Parameters // a: input prediction polynomial with 1st element 1 (if not, poly2ac normalizes it to 1 before proceeding). // efinal: inpu...
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clc; // page no 676 // prob no 18_2_2 //A drum scanner in eg.18.2.1 with pitch=0.26mm/line & diameter=68.4mm & drum rotate at 120rpm & scans lines=1075 D=68.4;P=0.26;rpm=120;n=1075; //Determination of no. of pixels scan Npx=(%pi)*(D/P); disp('pixels/line',Npx,'The no. of pixels in scan line is'); //Determinatio...
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// chapter 2 example 13 //------------------------------------------------------------------------------ clc; clear; // given data // E = 20π e^j(wt - βz)ax // H = Hm e^j(wt + βz)ay lamda = 1.8; // wavelength in m c = 3*10^8; // vel. in m/s er = 49; // relative permitivity ur = 1;...