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// Exa 5.4 clc; clear; close; format('v',6) // Given data R = 5;// in ohm L =0.02;// in H V_L = 440;// in V f = 50;// in Hz X_L = 2*%pi*f*L;// in ohm Z_Ph = sqrt( (R^2)+(X_L^2) );// in ohm V_Ph = V_L;// in V I_Ph = V_Ph/Z_Ph;// in A I_L = sqrt(3)*I_Ph;// in A disp(I_L,"The line current in A is"); phi =...
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6_4.sce
clc //initialisation of variables clear h= 1.439 T= 300 //K w= 4405 //cm^-1 w1= 565 //cm^-1 //CALCULATIONS Qv1= (1-%e^(-h*w/T))^-1 Qv2= (1-%e^(-h*w1/T))^-1 //RESULTS printf ('Vibrational Partition = %.3f ',Qv1) printf ('\n Vibrational Partition = %.3f ',Qv2)
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clc; funcprot(0); // Initialization of Variable T=273+25.0;//temperature in K p=752.0;//pressure mm Hg No=294.0e-6; ns=1.000284; D1=1438.254;//recorded distance in m h=263.42-243.25;//height difference in m R=6370e3;//radius of earth in m //calculation n=1+No*(273/T)*(p/760); D=D1*ns/n; cg=-h**2/2/D; Hm=...
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uencode.sci
function y=uencode(u,n,v,signflag) //Performs uniform quantization of the input into 2^n levels //Calling Sequence //y=uencode(u,n,v,'signflag') //Parameters //u //A vector, matrix or n-dimensional array //n //An integer between 2 and 32 //v //A positive real scalar //'signf...
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clc;clear; //example 1.16 //calculation of new radius of ring when lens is raised //given data R=40; //radius of curvature of lens (in cm) r_dn=2.5; //radius of ring (in mm) del_h=5.0; //distance of lens raised from plate (in micrometer) //calculation r_d1n=sqrt(r_dn^2-2*del_h*10^-3*R*10^1); //new radius of rin...
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// matrix A is [1,2,3;7,5,4;2,2,9] clc;clear; A = [1 2 3;7 5 4;2 2 9]; n = length (A(1,:)); Aug=[A,eye(n,n)]; for j = 1: n-1 for i = j+1: n Aug(i,j:2*n)=Aug(i,j:2*n)-Aug(i,j)/Aug(j,j)*Aug(j,j:2*n); end end for j=n:-1:2 Aug(1:j-1,:)=Aug(1:j-1,:)-Aug(1:j-1,j)/Aug(j,j)*Aug(j,:); end for j=...
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Vbi=0.74; Vg=0.5; c=13.2*8.854*10^-14; //say c=Єs q=1.6*10^-19; Nd=5*10^16; b=(2*c*(Vbi-Vg)/(q*Nd))^(1/2); printf('\n The value of depletion width near drain is %f*10^-2 μm',b*10^6); d=0.8-(b*10^4); printf('\n The maximum undepleted channel width is near the drain end of the gate is %f μm',d);
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clc; clear; format('v',20) d=input("Enter the diameter of the conductors in cm: ") dab=input("Enter the spacing of A and B in ms: ") dbc=input("Enter the spacing of B and C in ms: ") dca=input("Enter the spacing of C and A in ms: ") r=(d/2)*10^-2 D=(dab*dbc*dca)^(1/3) L=(0.5+2*log(D/r))*10^-7 Lkm=L*1000 disp...
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//Ex:30 clc; clear; close; t_a=35;//antenna noise temp in K f=12;//receiver noise figure in db F=10^(12/10);//receiver noise figure l_c=10^(5/10);//cable loss g_lna=10^5;//LNA gain t_lna=150;//noise temp in K t_o=290;// in K t_s=t_a+t_lna+(l_c-1)*t_o/g_lna+l_c*(F-1)*t_o/g_lna; printf("Gain=%d K",t_s);
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18 214:2 288:1 300:1 706:1 756:1 919:1 938:1 1527:2 1557:1 1559:1 1596:1 1994:1 2230:2 2449:1 2762:1 2799:1 2838:1 2874:2 2895:1 3011:2 3103:1 3141:1 3183:1 3190:1 3368:1 3637:1 3901:1 4113:1 4776:1 4789:1 4816:1 4872:1 4930:1 4932:1 5553:1 5672:1 5761:1 6188:1 6587:1 6591:1 6862:1 7037:1 7483:1 7792:1 7820:1 7853:1 80...
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x=2 while x < 10D6 disp(x) x=x^2 end
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s=%s; t=0:0.01:3; G=10/((s+5)*(s+2)); C=1*(1+0.1*s); sys=syslin("c",G*C/(1+G*C)); y1=csim("step",t,sys); C=10*(1+0.1*s); sys=syslin("c",G*C/(1+G*C)); y2=csim("step",t,sys); C=100*(1+0.1*s); sys=syslin("c",G*C/(1+G*C)); y3=csim("step",t,sys); clf();plot2d(t',[y1',y2',y3'])
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//Fonction dilatation matrice de point binaire function [ImgE]= Dilatation(Img) [TailleX,TailleY]=size(Img) //TailleY=size(Img(1)) ImgE=Img for i= 2:TailleX-1 for j = 2:TailleY-1 for k = i-1:i+1 for l = j-1:j+1 if(Img(i,j)==1) ...
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v=[1 2 3 4 5 6]; m=cummin(v,2,'reverse',2); disp(m); //output // !--error 77 //cummin: Wrong number of input argument; 1-6 expected //at line 50 of function cummin called by : //m=cummin(v,2,'reverse',2);
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<?xml version="1.0" encoding="utf-8"?> <test> <description>Euler, Subsonic Cylinder P=3</description> <executable>CompressibleFlowSolver</executable> <parameters>CylinderSubsonic_P3.xml</parameters> <files> <file description="Session File">CylinderSubsonic_P3.xml</file> <file description...
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// Grob's Basic Electronics 11e // Chapter No. 14 // Example No. 14_5 clc; clear; // A magnetic material has a ur of 500. Calculate the absolute u as B/H (a) in CGS units and (b) in SI units. // Given data ur = 500; // ur=500 uoa = 1; // uo for CGS Units=1 uob = 1.26*10^-6; // uo for SI U...
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//Example 3.2 //This code utilises dependency file 'Compute_Angle.sci' exec Compute_Angle.sci;//Execute dependency file //To find the position of the boat subplot(2,1,1) //To draw vector A x=0; y=0;//x and y are the starting point coordinates magnitude=27.5; theta=66; x_end=magnitude*cosd(theta); y_end=...
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4_1.sci
// 4.1 clc; fc=1000; disp('In addition to carrier frequency of 1000kHz the other upeer and lower frequencies are') fs1=0.3; fu1=fc+fs1; printf("\nUpper side band frequency for modulating frequency of 300 Hz =%.1f kHz",fu1) fl1=fc-fs1; printf("\nLower side band frequency for modulating frequency of 300 Hz =%.1f ...
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function [y] = tripuls(t,w,skew) //This function generates a triangular pulse over the interval [-w/2,w/2] sampled at times t //Calling Sequence //[y] = tripuls(t) //[y] = tripuls(t,w) //[y] = tripuls(t,w,skew) //Parameters //t: vector of real or complex numbers //w: real or complex number //skew: real number, -1 ...
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afstriiskuoi afstriiskuoile ADJ;AT+ALL;SG univermag univermagas N;IN+ESS;SG tazavald tazavaldan N;GEN;SG akke akkannu N;FRML;SG poige poige N;NOM;SG poige poigal N;AT+ESS;SG homm hommad N;NOM;PL kiškoi kiškojat N;NOM;PL tütar tütärtte N;PRT;SG kuccuda kucun V;IND;SG;1;POS;PRS teatr teatran N;GEN;SG teatr teatras N;IN+E...
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测试游标之动态游标[强类型游标].tst
PL/SQL Developer Test script 3.0 30 -- 测试游标之动态游标[强类型游标] -- 动态游标 需要先定义类型 再定义变量 declare -- 声明类型 -- 语法: type 类型名称 is ref cursor retrun 行类型 type v_cursor_type is ref cursor return emp%rowtype; -- 声明变量 v_cursor v_cursor_type; -- 行变量 v_row v_cursor%rowtype; begin -- 打开游标 open v_cursor for sel...
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//info about 2D homogeneous lines and points: http://homepages.inf.ed.ac.uk/rbf/CVonline/LOCAL_COPIES/BEARDSLEY/node2.html // clear all xdel(winsid()); clear; //scan params: Ns = 720; //scan rays aperture = %pi; //scan aperture [rad] azimuth_step = aperture/Ns; //User Tunning params Nw = 8; //window size theta_th =...
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clear all; clc; disp("Ex 2_4") printf('\nPart(a)') //Figure 2-13b vector addition according to parallelogram law //We use figure 2-13c to find F1 and F2 by using law of sines a=1000//Magnitude of resultant force in N p1=30//given angle theta in degrees p=p1*%pi/180//angle in radian q1=130//angle in degrees q=q1*%pi/180...
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clear; clc; // Input P0 = 34; // g/L G0 = 1; // g/L L0 = 50; // g/L AL0 = 0; // g/L M0 = 1; // ad LB0 = 0; // // U/L T0 = 20; // ºC // (1) Mixer exec mix.sci i1 = [P0; G0; L0; AL0; M0; LB0; T0] o1 = mix(i1) // (2)Heater (steam) exec fsolvehexs.sci exec hexs.sci i2 = o1 o2 = hexs(i2) // (3)Hold...
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clc clear //Input data x=3//Petrol stands 3 mm below Ta=15.5+273//Temperature of air in K pa=1.027//Pressure of air in kg/cm^2 R=29.27//Characteristic gas constant in kg.m/kg.K sg=0.76//Specific gravity of fuel fc=6.4//Consumption of fuel in kg/hour jd=1.27//Jet diameter in mm Cd=0.6//Nozzle discharge coeffi...
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// Scilab Code Ex 5.11 : Page-5.24 (2004) clc;clear; h = 6.626e-34; // Planck's const, Js m = 9.1e-31; // Mass of electron in kg L = 1e-10; // Side of the box in m n1 = 1; // Ground state quantum number n2 = 2; // first quantum number n3 = 3; // second quantum number e = 1.6e-19; // charge on ele...
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function [w]=fskmod(data,Ac,fc1,fc2) //fc1 - carrier signal frequency for binary 1 in Hz //fc2 - carrier signal frequency for binary 0 in Hz //Ac - carrier signal amplitude in volts //data - digital information signal //w -BFSK modulated signal t = 0:0.001:1; x = Ac*sin(2*%pi*fc1*t); y...
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function[r,theta]=rect2pol(A) x=real(A) y=imag(A) r=sqrt(x^2+y^2) theta=atand(y/x) endfunction function[z]=pol2rect(r,theta) x=r*cos(theta*%pi/180) y=r*sin(theta*%pi/180) z=x+y*%i endfunction function[r]=mag(A) x=real(A) y=imag(A) r=sqrt(x^2+y^2) endfunction j=%...
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// From https://fr.wikipedia.org/wiki/Algorithme_de_Remez a = 0 b = 1 - %eps format('v',21) dispall=%f for n = 2:10 if dispall printf("N = %d\n",n) end //////////////////////////////////////////////: xk = zeros(n+2,1) for k = 1:(n+2) xk(k) = ((a+b)/2) + ((a-b)/2) * cos(((...
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//Example 9.18 clc disp("The required pulse width is,") disp(" W = 10 ms") disp("The pulse width is given by,") disp(" W = 1.1*R*C") disp("Therefore, 10*10^-3 = 1.1*R*C") disp("Therefore, RC = 9.0909*10^-3") disp("Choose C = 0.1 uF") disp("Therefore, R = 90.909 k-ohm ~ 91 k-ohm") disp("The designed circ...
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clear // // // //Variable declaration V=1500; //volume(m^3) A1=112; //area of plastered walls(m^2) A2=130; //area of wooden floor(m^2) A3=170; //area of plastered ceiling(m^2) A4=20; //area of wooden door(m^2) n=100; //number of cushioned chairs A5=120; //area of audien...
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clc; clear; //Example 2.46 dia=3 //[mm] dia=dia/1000 //[m] r=dia/2 //radius in[m] k=150 //W/(m.K) h=300 //W/(sq m.K) T0=413 //[K] T_inf=288 //[K] A=%pi*(r^2) //Area in [sq m] P=%pi*dia //[W/sq m.K] Q=(T0-T_inf)*sqrt(h*P*k*A) //Heat dissipated in [W] printf("Heat dissipated by the rod...
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%Generated from '../examples/alcoholic/na10.dig'. query(instances(aconcept('Alcoholic')), []). query(instances(not(aconcept('Alcoholic'))), [i0, i1, i2, i3, i4, i5, i6, i7, i8, i9]). concept('Alcoholic'). role(hasFriend). role(hasParent). implies(some(arole(hasParent), not(aconcept('Alcoholic'))), not(a...
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function nilai=newtonrapson(xo,tol) i=1; x(1)=xo;g(1)=1;r(1)=1;fx=0; while g(r)>tol x(r+1)=x(r)-f(x(r))/faksen(x(r)); g(r+1)=abs(x(r+1)-x(r)); r=r+1; i=i+1; fx=f(x); disp(i); end nilai=[x g]; endfunction function nf=f(x) //nf= x^3+5*x^2-10*x-5; ...
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function sys = armaX(varargin) // Parameters Estimation of ARMAX model using Input Output time-domain data // // Calling Sequence // sys = armaX(ioData,[na nb nc nk]) // // Parameters // ioData : iddata or [outputData inputData] ,matrix of nx2 dimensions, type plant data // na : non-negative integer number specified...
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//%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% //CONSTANTES //Esses valores tem de ser inseridos para cada componente e deixarão de ser constantes nesse momento dia = 21 mes = 8 lon = -41.93 //Gov Valadares (longitude 41.93E Latitude 18.85S) TZ = -5 lat = -18.85 //lsm = latatitude,...
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//Eg-3.1 //pg-67 clear clc // Matrices A and B from set of equations for i=1:3 if i==1 then a=[1 1 -1;1 2 -0.5;1.5 1 1]; b=[5;-1;2]; elseif i==2 then a=[-1 2.5 3.5;-1 1 2;.5 1 .5]; b=[3;1;1.5]; elseif i==3 then a=[1 2 0;1 3 0;2 5 0]; b=[3;2.5;1.6]; end //size of...
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//Variable declaration C=0.01 //capacitance(uF) R2=15 //resistance(k ohms) Va2=4 //voltage(V) Vcc=15. //supply voltage(V) R1=33 //resistance(k ohms) //Calculations Va1=0.67*Vcc //voltage(V) Vamax=Va1+V...
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clear // // //Initilization of Variables I=4.085*10**8 //mm**4 //M.I A=20732.0 //mm**2 //area of column f_y=250 //N/mm**2 L=6000 //mm //Length of column //Calculations k=(I*A**-1)**0.5 //mm lamda=L*k**-1 //Slenderness ratro //From Indian standard table lamda_1=40 sigma_a_c_1=139 //N/mm**2 lamda_2=50 sigma_a_c_2...
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ac2poly6.sce
//check o/p when char is given as i/p r = 'hash'; [a,efinal] = ac2poly(r); disp(a); disp(efinal);
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exam.sce
function An = calcul(F,n) somme = sum(F((1:(n - 1)) / n)) An = 1 / (2 * n) * (F(0) + F(1) + 2 * somme) endfunction function v = morse(n) v(1) = 0 for i = 2:n reste = modulo(i, 2); if reste == 0 then k = (i - 2) / 2 v(1, i) = 1 - v(1, k + 1) else ...
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clc; pa=0.7; // Ambient pressure in bar Ta=1+273; // Ambient temperature in kelvin Ci=800*1000/3600; // Speed of the aircraft in m/s rp=5;// Pressure ratio eff_ram=1.00; // Intake duct efficiency eff_c=0.85; // Compressor efficiency eff_T=0.90; // Turbine efficiency eff_comb=0.98; //Combustion efficiency eff_...
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//Example 1.74// kWh & percentage error clc; clear; I= (40*225)/600;//current in amperes I1=14;//current in ampere V=230;//volts pf=1;//power factor n=225;//no. of revolutions t=360;//total time in seconds E=((V*I*pf*10)/(60*1000));//energy recorded in 1 hour in kWh Er=((V*I1*pf*10)/(60*1000));//energy consumed in 1 ...
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-- VectorCAST 22.sp7 (12/04/22) -- Test Case Script -- -- Environment : ENV_MANAGER -- Unit(s) Under Test: manager -- -- Script Features TEST.SCRIPT_FEATURE:C_DIRECT_ARRAY_INDEXING TEST.SCRIPT_FEATURE:CPP_CLASS_OBJECT_REVISION TEST.SCRIPT_FEATURE:MULTIPLE_UUT_SUPPORT TEST.SCRIPT_FEATURE:REMOVED_CL_PREFIX TEST.SCRIPT...
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//Example7.3 // Design active low filter with cut-off frequency 20 KHz clc; clear; close; fc = 20 ; // KHz f = 100 ; // frequency of filter Af = 10 ; // desired pass band gain C = 0.05 ; //nF // we assume // the cut-off frequency of active low pass filter is defined as // fc = (1/2*%pi*R3*C); // R3 can...
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function inserted = insert_waveform_in_scene(waveform, scene) [nrows, ncols] = size(scene); wavesize = size(waveform, '*'); inserted = zeros(nrows, ncols); for i = [1:wavesize] inserted(nrows/2-wavesize/2+i, ncols/2) = waveform(1, i); end endfunction
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load isNegative32.hdl, output-file isNegative32.out, compare-to isNegative32.cmp, output-list in1%B1.16.1 in2%B1.16.1 out%B3.1.3; set in1 %B1100110101110011, set in2 %B0000000000000000, eval, output; set in1 %B0001110101100010, set in2 %B1001101010111000, eval, output; set in1 %B0010000100100010, s...
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exec('C:\Users\Arthur\Documents\GitHub\Projet_scientifique\Fonctions\display_gray.sci', -1) exec('C:\Users\Arthur\Documents\GitHub\Projet_scientifique\Fonctions\Histogramme.sci', -1) exec('C:\Users\Arthur\Documents\GitHub\Projet_scientifique\Fonctions\readpbm.sci', -1) exec('C:\Users\Arthur\Documents\GitHub\Projet_s...
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detectTone.sce
//read wav file sample_rate = 22050; //sampling rate N = 74304; //sampling number w = wavread("**.wav") //read wave file //plot(w) //fft f = sample_rate*(0:(N/2))/N; //create x-axis point number n = size(f,'*') //half of number of sampling X = fft(w); //FFT plot...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Engineering Thermodynamics by Onkar Singh Chapter 6 Example 8") x=.10;//quality is 10% disp("at 0.15Mpa,from steam table;") disp("hf=467.11 KJ/kg,hg=2693.6 KJ/kg") hf=467.11; hg=2693.6; disp("and hfg=hg-hf in...
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clc pathname=get_absolute_file_path('7_5_1.sce') filename=pathname+filesep()+'751.sci' exec(filename) printf(" All the values in the textbook are Approximated hence the values in this code differ from those of Textbook") deltaH=H0-H50 deltaU=deltaH+((Pfinal*Vfinal-Pinitial*Vinitial)*1.987/10.73) printf(" \n chan...
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//total cross section function [sigma]=sigma(k,e) lupper=10; sumdelta=0; delta=0.1*(10^(-10)); sumouter=0; totsum=0; sigma=0; nr=50; u1=zeros(nr,lupper+1); u2=zeros(nr,lupper+1); u3=zeros(nr,lupper+1); //outer loop integration over r for j=1:nr, u1=0; //inner loop summation over l ...
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clc clear //Initialization of variables y1=13.5 x1=0.135 x2=0.056 veca=[66 1.5 1.1 5.6 5.9 19.9] //calculations vecb=[veca y1] vecb(5) = vecb(5) - 1/9*y1 vecb(6) = vecb(6) - 8/9*y1 vecc=vecb/(1-x1) vecd=vecb/(1-x1-x2) vecd(4)=0 vecd(7)=0 vecc(7)=0 s1=sum(vecc) s2=sum(vecd) //results printf("With mois...
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//Problem 5.12: For the circuit shown in Figure 5.21 calculate (a) the value of resistor Rx such that the total power dissipated in the circuit is 2.5 kW, and (b) the current flowing in each of the four resistors. //initializing the variables: R1 = 15; // in ohms R2 = 10; // in ohms R3 = 38; // in ohms Vt = 250;...
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//Example 15_9 clc(); clear; //To find the speed just before the field strikes e=6000 //Units in N/C q=1.6*10^-19 //Units in C f=e*q //Units in N m=1.67*10^-27 //Units in Kg a=f/m //Units in meters/sec^2 vo=0 //Units in meters/sec x=2*10^-3 //Units in meters v=sqrt(vo^2+(2*a*...
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//chapter8,Example8_5,pg 182 //since both reflections occur at surface of denser medium //condition for brightness for min thickness, n=1 //for normal incidence r=0, cos(r)=1 lam=5500*10^-8 V=0.2 A=100*100//converting into cm2 t=V/A u=lam/(2*t) printf("RI of oil\n") printf("u=%.2f",u)
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Gs=10^0.5 S11=2.27*exp(-%i*%pi/180*120) S21=4*exp(%i*%pi/180*50) S12=0 S22=0.6*exp(-%i*%pi/180*80) Ss11=2.27*exp(%i*%pi/180*120) function x=mod(n) r=real(n) i=imag(n) x=sqrt(r^2+i^2) endfunction //(b) gs=Gs*(1-mod(S11)^2) Rs=(1-mod(S11)^2)*sqrt(1-gs)/(1-(1-gs)*mod(S11)^2) ds=gs*(Ss11)/(1-(1-...
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clear all; xdel(winsid()); //Images utiles imgRectangle = [ 0,0,0,0,0,0,0,0,0,0; 0,0,0,0,0,0,0,0,0,0; 0,0,1,1,1,1,1,1,0,0; 0,0,1,1,1,1,1,1,0,0; 0,0,1,1,1,1,1,1,0,0; 0,0,1,1,1,1,1,1,0,0; 0,0,1,1,1,1,1,1,0,0; 0,0,1,1,1,1,1,1,0,0; 0,0,1,1,1,1,1,1,0,0; 0,0,1,1,1,1,1,1,0,0; 0,0,1,1,1,1,1,1,0,0; 0,0,1,1,1,1,1,1,0,0; 0,0,1,...
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clc clear //INPUT DATA vs=0.015;//swept volume in m^3 vc=0.0008;//clearence volume in m^3 p3=500;//discharging pressure p1=100;//air pressure in kPa m=1.4;//isentropic expansion constant n=1.3;//polytropic index constant //CALCULATIONS v1=vs+vc;//volume in m^3 v4=vc*((p3/p1)^(1/m));//volume in m^3 wn=((...
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clc; clear all; n0 = 1.76; // Refractive index of the ruby rod v0 = 4.3e14; // Frequency in Hz deltav0 = 1.5e11; // The doppler broadening in Hz tsp = 4.3e-3; // Lifetime of the spontanous emission in seconds tphoton = 6e-9; // Lifetime of photon in seconds c = 3e8; // Velocity of air d = ((4*%pi^2*v0^2*n0^3*t...
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//Chapter 10 //Example 10_15 //Page 254 clear;clc; ll=200; r=0.16; xl=0.25; y=1.5*1e-6; pd=20*1e6; pfr=0.8; v_r=110*1e3; tr=r*ll; ty=y*ll; txl=xl*ll; z=tr+%i*txl; vr=v_r/sqrt(3); ir=pd/sqrt(3)/v_r/pfr; vs=vr*cosh(ty*z)+ir*sqrt(z/ty)*sinh(z*ty); is=vr*sqrt(ty/z)*sinh(ty*z)+ir*cosh(ty*z); printf("Recieving end volt...
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// problem 10.9 Q=0.05 p=392.4*1000 n=0.65 s=0.8 w1=9810 Hw=p/w1 Hoil=p/(w1*s) Pw=(w1*Q*Hw)/(n*1000) Poil=(w1*s*Q*Hoil)/(n*1000) disp(Pw,Poil,"power in Kw to drive the pump with water and oil of s,p=0.8")
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//Example 13.9 P=7*10^5;//Pressure (Pa) V=2*10^-3;//Volume (m^3) T=18;//Temperature (C) T=T+273;//Temperature (K) R=8.31;//Ideal gas constant (J/(mol.K)) n=(P*V)/(R*T);//Moles (mol) printf('Number of moles = %0.3f mol',n) //Openstax - College Physics //Download for free at http://cnx.org/content/col11406/lates...
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// Electric Machinery and Transformers // Irving L kosow // Prentice Hall of India // 2nd editiom // Chapter 14: TRANSFORMERS // Example 14-11 clear; clc; close; // Clear the work space and console. // Given data kVA = 500 ; // kVA rating of the step-down transformer V_1 = 2300 ; // Primary voltage in v...
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errcatch(-1,"stop");mode(2); //Example 7.5 //Calculate the force exerted on the flange when the valve of the nozzle is d //Let the gauge pressure be denoted by Pg Pg=100//lbf/in^2 A=10//in^2 //F_bolts = -F_liq-F_atm //F_bolts = -(Pg + P_atm)A - (-P_atm.A) //F_bolts = -Pg.A F_bolts=-Pg*A printf("The force exer...
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monito...
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//chapter 7 printf("\n"); ht=100; hr=50; d=1.4142*(sqrt(ht)+sqrt(hr)); printf("the maximum range is %gmiles",d);
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//Chapter 13 //Example 13_13 //Page 324 clear;clc; l=6; va=600; vb=590; i=300; r=0.04; x=3.425; ia=341.7-50*x; ib=i-ia; printf("(i) x = %.3f km \n", x); printf("(ii) Current suplied by A = %.2f A \n", ia); printf(" Current suplied by B = %.2f A \n", ib);
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threshold = 150; pingGyroQuanti = quantization(PingGyro,threshold); //figure("Figure_name", "Ping pong Gyroscope X-Axis");plot(pingGyroQuanti(:,1)); //figure("Figure_name", "Ping pong Gyroscope Y-Axis");plot(pingGyroQuanti(:,2)); //figure("Figure_name", "Ping pong Gyroscope Z-Axis");plot(pingGyroQuanti(:,3)); peaks =...
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## Rest graph-generation code read <roundup.fi graph
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Q = [0, 0; 0, 2; 2, 2; 2, 0; 0, 0]; plot(Q(:, 1), Q(:, 2)); // para visualizar melhor o quadrado plot(-2, -2); plot(4, 4); /* To change the size of an object, scaling transformation is used. In the scaling process, you either expand or compress the dimensions of the object. Scaling can be achieved by multiplyin...
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; valid declare-sort (set-logic QF_UF) (declare-sort A 0) (declare-sort B 2)
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// Scilab code Exa4.5.3: To calculate Q-value and threshold energy for the given reaction : Page 183 (2011) // Pb_208(Fe_56, Fe_54)Pb_210 M_Pb_208 = 207.976641; // Mass of Pb-208, amu M_Fe_56 = 55.934939; // Mass of Fe-56, amu M_Pb_210 = 209.984178; // Mass of Pb-210, amu M_Fe_54 = 53.939612; // Mass of Fe-54, amu...
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//Section-5,Example-2,Page no.-D.124 //To calculate the number of molecules of HCl produced per joule of radiant energy absorbed clc; h=6.626*10^-34 c=3*10^8 lm=480*10^-9 E=(h*c)/lm N_A=6.023*10^23 E_2=E*N_A //Energy per mole q_eff=1.0*10^6 //Quantum efficiency n_HCl=2*q_eff ...
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clc,clear printf('Example 3.22\n\n') I_avg=10 V_avg=(220+190)/2 //average voltage across load W_dash = V_avg*I_avg //power absorbed t_1=30,t_2=20 W=W_dash * (t_2/(t_1-t_2)) //stray losses printf('Stray losses of motor is %.1f kW\n\n\n',W/1000) printf('Answers mismatch because V_average is 205 volts but it i...
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clc; clear; Freq_dev=6; //Frequency Deviation in kHz Vm=3; //Modulating Voltage in V Dev=Freq_dev*10^(3)/Vm; // for Vm=6V Vm=6; Freq_dev_new=Dev*Vm; disp(Freq_dev_new,"the new deviation( in Hz)");
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// Electric Machinery and Transformers // Irving L kosow // Prentice Hall of India // 2nd editiom // Chapter 1: Electromechanical Fundamentals // Example 1-7 clear; clc; close; // Clear the work space and console. // Given data N = 1; // no. of turns phi = 6.48 * 10 ^ 8; // Magnetic flux in lines s = 3...
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//Chemical Engineering Thermodynamics //Chapter 14 //Thermodynamics of Chemical Reactions //Example 14.8 clear; clc; //Given //The given example is a theoretical problem and it does not involve any numerical computation. //end
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// Example 7.5:oscillation frequency clc; clear; close; C1=500;//capacitance of tunned circuit in PICO farad C2=500;//capacitance of tunned circuit in pico farad C=(C1*C2)/(C1+C2);//total capacitance in micro farad L=1;//INDUCTANCE of tunned circuit in milli henry fo=(1/(2*%pi*sqrt(L*10^-3*C*10^-12)))*10^-3;//...
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#************************************************************ # Scenario of Ikea # # date : Wed Jan 4 16:10:05 2012 #************************************************************ p3d_sel_desc_name P3D_ENV Ikea p3d_sel_desc_name P3D_ROBOT HERAKLES_HUMAN1 p3d_set_robot_steering_method Linear p3d_set_robot_current 0...
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clc //to calculate kinetic energy of an electron h=6.63*10^-34 //plank's constant mo=9.1*10^-31 //rest mass of an electron in kg lambda=5896*10^-10 //wavelength in angstrom K=(h^2)/(2*mo*(lambda^2)*1.6*10^-19) disp("kinetic energy of an electron is K="+string(K)+"eV")
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deff('p=mypoly(x)','p=poly(x,''z'',''coeffs'')') c=[1,2,3]; P1=ex12f(2,c); if P1<>poly(c*2,'z','coeffs') then pause,end
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//Chapter 1: Structure and Bonding //Problem: 19 clc; B_O1 = (10 - 6) / 2 // Bond Order for O2 B_O2 = (10 - 7) / 2 // Bond Order for O2- r=B_O1 > B_O2 if r==%t then disp("Bond length of O2- > O2 as Bond order of O2 > Bond order of O2-") end mprintf(" Both are paramagnetic, becaus...
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//cal dia of piston clc //soltuion //given D=1500//mm p=0.2//N/mm^2 E=200*1000//N/mm^2 l=3000//mm W=(%pi/4)*D^2*p//N Fs=8 Wcr=W*Fs//N L=l/2; d=(Wcr/0.043)^(1/4)//mm; //let d be dia and I be moment of inertia I=(%pi/64)*d^4 //acc to euler's formula //Wcr=%pi^2*E*I/L^2//N //Wcr=0.043*d^4 //acc to rankine's formula //Wcr...
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//Chapter-2, Example 2.33, Page 2.64 //============================================================================= clc clear //INPUT DATA L=400;//Constant or Iron losses in W C=700;//Full load copper loss in W Q=40000;//Rating of transformer in VA cosq=0.85;//Load power factor //CALCULATIONS P=(Q*cosq);...
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clc //initialisation of variables HV=4344 //Btu/lb m=56 //lb R=1.986 //Btu/lb mol R Tb=530 //R //Calculations HR=m*HV Eb=-HR-R*Tb*(2-3) printf ('Constant pressure heating value = %.1f Btu/lb formula wt',Eb)
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clc; pathname=get_absolute_file_path('8_4_soln.sce') filename=pathname+filesep()+'8_4_data.sci' exec(filename) // Solution: // flow-rate through orifice, Q=38.1*C*((%pi*(D^2))/4)*sqrt(del_p/SG_oil); //gpm // Results: printf("\n Results: ") printf("\n The flow-rate through orifice is %.0f gpm.",Q)
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l=100*10^(-6); c=50*10^(-12); r=100*10^3; v=50*10^(-3); disp("Part a"); f=1/(2*%pi*sqrt(l*c)); disp("the resonant frequency (in MHz) is"); disp(f*10^6); disp("Part b"); ir=v/r; x_l=2*%pi*f*l; x_c=1/(2*%pi*f*c); il=v/x_l; ic=v/x_c; disp("current through the resistor (in μA) is"); disp(ir*10^6); disp("curre...
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//To find greatest power transmitted clc //Given: theta=120*%pi/180 //radians b=100/1000, t=6/1000 //m rho=1000 //kg/m^3 mu=0.3 sigma=2*10^6 //N/m^2 //Solution: //Speed of the belt for greatest power: //Calculating the maximum tension in the belt T=sigma*b*t //N //Calculating the mass of the belt per metre ...
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function [water_sequence, theta_sequence, light_sequence, GC_index] = gl_env(Flag_environment, Flag_sumt, Omega, aux_paras,THETA_BASE, KSUMT, N,envLoc); // Control of irrigation, betalaw parameters a,b, initial irrigation date datH2O, irrigation frequence freq water_sequence = []; theta_sequence = []; ligh...
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//(sI−A)の行列式を求める A=[1 0;0 2]; b=[1;1]; c=[1 1]; s=%s; sA=s*eye(2,2)-A; detsA=det(sA)
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//Calculations on Otto cycle clc,clear //Given: CV=42000 //Calorific value of the fuel in kJ/kg a=30/100,b=70/100 //Fraction of compression stroke at point a, b P_a=1.33,P_b=2.66 //Pressure at point a, b n=1.33 //Polytropic index eta_cycle=50/100 //Air standard cycle efficiency //Solution: //Refer fig 2.25 //...
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clc clear //input v=3 //voltage c1=2.5*10^-6 //capacitance c2=2.5*10^-6 c3=2.5*10^-6 //calculation q=v/((1/c1)+(1/c2)+(1/c3))//capacitors in series q1=c1*v//capacitors in parallel //output printf("the pd when capacitors are in series is %3.3e C",q) printf("\n the pd when capacitors are in parallel is %3.3e ...
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java trip.Main -m trip-tests/trip3.txt trip-tests/trip3.request
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;; Source: Steel's Book, Chapter 12, Section 2, page 196 ;; Created by: John Park ;; Creation Date: May 1, 86 ;; Predicate: The evenp predicate is true if integer is even and is false otherwise. ;; Syntax Format: (evenp integer) ;; Input: integer ;; Output: T or NIL (do-test evenp-test (and (evenp 2) (evenp ...
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x=[1 2 2+3*%i 4 5 6 7 89 9]; strips(x); //plot matches that of matlab
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//To find the number of teeth clc //Given: rAD=12 //Speed ratio, NA/ND mA=3.125, mB=mA, mC=2.5, mD=mC, x=200 //mm //Solution: //Calculating the speed ratio between the gears A and B, and C and D rAB=sqrt(rAD) //Speed ratio between the gears A and B rCD=sqrt(rAB) //Speed ratio between the gears C and D //Calcul...
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kT = 26*10^-3; //in eV t = 10^-6; q = 1.6*10^-19; A = 10^-3; //in square cm ni = 1.5*10^10; eE = 3.2*10^4; Igr0 = q*ni*A*%pi*kT/(2*t*eE); disp(Igr0,"prefactor of the generation-recombination current (in Ampere) =") V1 = 0.2; Igr1 = Igr0*(exp(0.5*V1/kT)-1); disp(Igr1,"generation-recombination current (in A) at...
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welcon fssfsfsff sfs f sf sf sf