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// this code convert the band structure data to column format. // so other user can use it easier. clear; clc; exec(PiLib); // Parameter =========================================================== work_dir='C:\MyDrive\Work\PiLab_projects\Sn_AlO_single' project_name='Sn_AlO' // Main ===================================...
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// Electric Machinery and Transformers // Irving L kosow // Prentice Hall of India // 2nd editiom // Chapter 1: Electromechanical Fundamentals // Example 1-5 clear; clc; close; // Clear the work space and console. // Given data no_of_conductors = 40; A = 2; // A = Parallel paths path = A; flux_per_pol...
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s = poly(0,'s'); G = 1/((s+3)*(s+4)*(s+12)); //z = 3; for z = 0:0.01:3 K = G*(s+z)/s evans(K); end
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TESTA, Pietro (1611-1650) Baroque Italian painter (Rome) TARAVAL, Louis-Gustave (1738-1794) Neoclassicism French graphic artist KOBELL, Jan I (1755-1833) Rococo Dutch graphic artist (Rotterdam) TAUNAY, Nicolas Antoine (1755-1830) Rococo French painter TERBRUGGHEN, Hendrick (1588-1629) Baroque Dutch painter (Utrecht) AG...
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clc,clear printf('Example 2.27\n\n') V=230 N_1=1000,N_2=950 R_a=0.5, R_sh=230 //armature and shunt field resistance I_L1=10 I_sh = V/R_sh I_a1 = I_L1 - I_sh //T (prop.) phi*I_a (prop.) I_a with phi constant and T is constant due to full-load I_a2=I_a1 E_b1 = V - I_a1*R_a E_b2=E_b1*(N_2/N_1) //N (pro...
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[[3,1,2,-1],[1,3,-1,2],[-1,-2,1,-1],[-2,-1,-1,1]] * [a,b,c,d] = 19*a^3+18*a^2*b+18*a*b^2+19*b^3+42*a^2*c+18*a*b*c-12*b^2*c+30*a*c^2+12*b*c^2+7*c^3-12*a^2*d+18*a*b*d+42*b^2*d-30*a*c*d-30*b*c*d-6*c^2*d+12*a*d^2+30*b*d^2-6*c*d^2+7*d^3
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// chapter 10 // example 10.5 // calculate critical current at 5K // page 314 // given clear; clc; T=5; // in K (given temperature) d=3; // in mm (diameter of the wire) Tc=8; // in K (critical temperature for Pb) H0=5E4; // in A/m (critical magnetic field at 0K) pi=3.14; // value of pi used in the solution...
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//Example 4.5 clear; clc; //Given n=1;//moles of ice Ttrans=286;//melting temperature in K P=1;//pressure in atm; delHtrans=2090;// enthalpy of transformation in J mol^-1 Tb=373;//boiling temperature in K delHv=40850;// enthalpy of fusion in J mol^-1 //to calculate the change in entropy delSv=delHv/Tb;//...
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clc;funcprot(0);......//Example 4.23 //Initialization of variables D=3*10^-3;.........//Diameter of the capillary holes in m L=0.5;...........//Length of the capillary holes in m U=0.3;.......//Velocity of water in kg/s T=355;...........//Temperature of devise casing in K T1=333;........//Inlet Temperature of wat...
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//Example 31.2 m_parent=239.052157;//Atomic mass of parent nucleus (Pu 239)(u), See Appendix A m_final=235.043924+4.002603;//Final atomic mass of products of decay (U 235 and He 4)(u), See Appendix A delta_m=m_parent-m_final;//Difference in mass (u) E=delta_m*931.5;//Energy emitted in decay (MeV) //E=delta_m*c^2, ...
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clc; //Example 5.1 //Page no 159 //solution Brf=200; //kHz Bif=10; //kHz //Bandwidth improvement is found by substituting into equati BI=(Brf/Bif); disp(BI,"BI = "); disp("and noise figure improvement is found by substituting into equation 5-3 (refer pgno 157)"); NF=10*log10(BI); disp('dB',NF,"NF = ")
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# -*- coding: utf-8 -*- # vim: ft=sls {%- set package_name = 'cronie' %} {%- if grains.os_family in ['Debian'] %} {%- set package_name = 'cron' %} {%- endif %} verify_cron.package: module_and_function: pkg.version args: - {{ package_name }} assertion: assertNotEmpty
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// Variable declaration alpha = 0.05 // level of significance x = 48 n = 60 p0 = 0.70 // Calculation // null hypothesis: if p=0.70 , Alternative hypothesis if p>0.70 Z_thr = 1.645 // theoritical value of Z Z_prt = (x - n*p0)/ sqrt(n*p0*(1-p0)) // practical value of Z // Result printf ( ...
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//caption:stability_using_Nyquist_criterion //example 12_23_iii //page 535 disp("for K=10") g=(10*(s+10)*(s+40))/(s*(s+1)*(s+4)); g1=(10*(s1+10)*(s1+40))/(s1*(s1+1)*(s1+4)); GH=syslin('c',g); GH1=syslin('c',g1); nyquist(GH); nyquist(GH1); //mtlb_axis([-1.5 0.2 -0.3 0.3]); xtitle('Nyquist plot of (0.1*(s+10)*(s+40))/(s*...
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// Exa 2.15 clc; clear; close; format('v',6) // Given data bita = 50; V_CC = 25;// in V V_BB = 10;// in V R_C = 15 * 10^3;// in ohm R_B = 40 * 10^3;// in ohm R_E = 5 * 10^3;// in ohm V_BE = 0.7;// in V I_B= poly(0,'I_B'); I_E= (1+bita)*I_B;// in A // Applying KVL to Base-Emitter loop, // V_BB = I_B*R_B ...
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//Fabrication and Thermal characteristics //Example 3.2 Xa=50;//Ambient temperature// P20=25;//on state power loss at 20%load in Watts// P200=350;//on state power loss at 200%load in Watts// Rjc=0.02;//junction_case thermal resistance// Rcs=0.05;//case_sink thermal resistance// Rsa=0.12;//sink_atmosphere thermal...
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clc // Given that x1 = 1 // coordinate on x axis for first plane y1 = 0 // coordinate on y axis for first plane z1 = 0 // coordinate on z axis for first plane x2 = 1 // coordinate on x axis for second plane y2 = 1 // coordinate on y axis for second plane z2 = 1 // coordinate on z axis for second plane // Sample Proble...
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clc //initialization of variables Rat1 = (6.5/3)*(1-0.47)// as Rat = x0/y0 m = 0.14 H = (6.5*10^3)/3600 // Extract flow in g/sec L = (3*10^3)/3600// Solvent flow in g/sec d= 10 // cm A = 0.25*%pi*d^2 // cm^2 l = 65 // cm //Calculations and Results Kya = ((H/(l*A))*(1/(1-((m*H)/L)))*(log((1-0.14*Rat1)/(0.47)...
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//chapter-8 page 339 example 8.5 //============================================================================== clc; clear; //For a 2 cavity klystron amplifier V0=1200;//Beam voltage in V I0=0.028;//Beam current in A f=8*10^9;//frequency in Hz d=0.001;//gap spacing in either cavity in m L=0.04;//spacing be...
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// SAMPLE PROBLEM 3/30 clc;funcprot(0); // Given data v_1=6;// m/s v_2=0;// m/s e=0.6;// The coefficient-of-restitution theta=30;// degree // Calculation // Assume a for ' v_1n=v_1*cosd(theta);// m/s v_1t=v_1*sind(theta);// m/s v_2n=0;// m/s v_2t=v_2n;// m/s function[X]=velocity(y) X(1)=(v_1n+v_2n)-...
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//Example 3.19 //Gauss Seidel Method //Page no. 75 clc;clear;close; x0=0;y0=0;z0=0; deff('x=f1(y,z)','x=(32-4*y+z)/28') deff('y=f2(x,z)','y=(35-2*x-4*z)/17') deff('z=f3(x,y)','z=(24-x-3*y)/10') for i=1:6 x0=f1(y0,z0); y0=f2(x0,z0); z0=f3(x0,y0); printf('\tx(%i) = %g\n\n\ty(%i) = %g\n\n\tz(...
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clc clear //Input data P1=1.03;//Pressure at the beginning of compression stroke in bar T1=303;//Initial temperature in K P2=40;//Maximum pressure in the cycle in bar Q=550;//The heat supplied during the cycle in kJ/kg r=1.4;//Isentropic compression ratio Cp=1.004;//Specific heat at constant pressure in kJ/kg K...
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x f(xs) -2.000000 -0.000000
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clear; clc; //page no. 198 D = 6;//ft d = 2;//in V1 = 200;//fps rpm = 250; theta = 150;//degrees u = (rpm/60)*2*%pi*0.5*D; v1 = V1-u; v2 = v1; V_2x = v1*cos(theta*%pi/180) + u; V_2y = v2*sin(theta*%pi/180); V2 = sqrt(V_2x^2 + V_2y^2); Q = 0.25*%pi*(d/12)^2 *V1; F_x = Q*1.935*(V_2x-V1); P = F_x*u/5...
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// Example 10_13 clc;funcprot(0); // Given data Q_H=30.0*10^3;// Btu/h W_in=1.50;// hp T_0=30.0+459.67;// K T_H=70.0+459.67;// K // Calculation // (a) COP_act_hp=Q_H/(W_in*2545);// The actual COP of heat pump n_T=COP_act_hp;// The first law thermal efficiency of the heat pump // (b) E_HP=((1-(T_0/T_H))*CO...
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load HackALU16Bit.hdl; output-file HackALU16Bit.out; output-list X%B1.16.1 Y%B1.16.1 zx%B3.1.3 nx%B3.1.3 zy%B3.1.3 ny%B3.1.3 f%B3.1.3 no%B3.1.3 Z%B1.16.1 zr%B3.1.3 ng%B3.1.3; set X 17383, set Y 6792, set zx 1, set nx 0, set zy 1, set ny 0, set f 1, set no 0, eval, output; set X 17383, set Y 6792, set zx 1, s...
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10_03.sci
//Rate of flow in gm: Q=[0 500 800 1000 1100 1200 1400 1500]; //Suction pressure in psig: ps=[ 0.65 0.25 -0.35 -0.92 -1.24 -1.62 -2.42 -2.89]; //Discharge pressure in psig: pd=[53.3 48.3 42.3 36.9 33 27.8 15.3 7.3]; //Motor Current in amps: I=[18 26.2 31 33.9 35.2 36.3 38 39]; //Acceleration due to gravity in f...
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//Chapter 29 Ex7 clc; clear; close; facevalue=10; //since the stock is calculated over 100 discount=3/4; brokerage=1/4; shares=96; cost1share=facevalue-discount+brokerage; //cash required to purchase Rs.100 stock costshares= cost1share*shares; mprintf("The cost of %.0f shares is Rs.%.0f",shares,costshares...
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//Ex_2_20 clc; clear; close; format('e',9); //given data : I1=100;//A I2=10;//A l=20/100;//m r1=1/100;//m r2=11/100;//m mu0=4*%pi*10^-7;//permeability of air //Force of attraction between Conductor & AB F1=mu0*I1*I2*l/2/%pi/r1;//N //Force of repulsion between Conductor & CD F2=mu0*I1*I2*l/2/%pi/r2;//N /...
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Title: TestName: Проверка примитива SoftChoice; Difficulty: A1; FullTime: 0; Questions: 1; EndTitle. StartTest: Question: 1; Weight: 1; BeginText: Укажите цвет, наиболее близкаий к красному. При правильном функционировании системы Ваша оценка составит 1. EndText; SoftChoice: AtX: 8; AtY: 8; Width: 500; Height:...
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clc //Chapter1 //Ex_1.8 //Given a=1/%inf b=-1/1 c=2/1 p = int32([1,1,1]) // 1/%inf = 0 ; (0/1 -1/1 2/1) hence lcm is taken for [1 1 1] LCM = lcm(p) h=a*double(LCM) k=b*double(LCM) l=c*double(LCM) mprintf('miller indices = %d %d %d',h,k,l)
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//Page Number: 4.21 //Example 4.23 clc; //Given, delfd1=50; //Hz f1=120; //Hz delfd2=20000; //Hz f2=240; //Hz //(a)PM delf1=(f2/f1)*delfd1; n1=delfd2/delf1; disp(n1,'Frequency multiplication factor in PM'); //(b)FM n2=delfd2/delfd1; disp(n2,'Frequency multiplication factor in FM');
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lteZadoffChuSeq.sci
function seq = lteZadoffChuSeq(R, N) // LTEZADOFFCHUSEQ generates root Zadoff-Chu sequence of complex symbols as per LTE specifications. // // SEQ = LTEZADOFFCHUSEQ(R, N) generates the Rth root Zadoff-Chu sequence (SEQ) // of length N. // Reference: // 3rd Generation Partnership Project, Technical Specifica...
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clc clear //input ra=0.05;//armature resistance of a d.c. shunt generator in ohms rf=120;//feild resistance of a d.c. shunt generator in ohms li=98;//load current in amperes lv=240;//load voltage in volts ia2=60;//reduced current in armature in amperes //calculations //generated e.m.f. remains constant i...
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N1=100 N2=1000 N3 = 10000 tol = 10^-7 //ex1 A1 = [-2.5 -4.5 -1; -16 -5 -8; 11 9 5] xa1 = [0 1 -1]' xb1 = [1 1 1 ]' xc1 = [1 0 -2]' xd1 = [10^-16 1 2]' //ex2 A2 = [1 7 4; 3 5 4; -13 -3 8]/4 xa2 = [1 2 3]' xb2 = [1 -1 1]' //ex3 A3 = [-1.48 1.5 -0.99; 7.98 2 3.99; -1.02 -3 -0.01] xa3 = [1 1 1]' function [vp,vecp, kk]...
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26_01.sce
clear clc //Lets say F(Ri)/F=F_ri F_50=0.3;F_100=0.4;F_200=0.3; //The time required(min)for 3 size of particles is t_50=5;t_100=10;t_200=20; //Cosidering solids to be in plug flow with tp=8 min tp=8; //1-XBavg=[1-XB(50 um)]F(50 um)/F+ [1-XB(100 um)]F(100 um)/F+....... //Because for 3 sizes of particles,R1:R2:R...
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// exa 8.1 Pg 227 clc;clear;close; // Given Data Fmin=250;// N Fmax=300;// N del=8;// mm C=8;// spring index tau_d=420;// MPa G=84;// GPa // 1. Wahl's correction factor Kw=(4*C-1)/(4*C-4)+0.615/C;// Wahl's correction factor printf("\n Wahl''s correction factor = %.3f ",Kw) // 2. Wire diameter // tau_d=Kw*8*Fmax*C/%pi...
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main.sci
A = [4, 2, 3, 0; -2, 3, -1, 1; 1, 3, -4, 2; 1, 0, 1, -1; 3, 1, 3, -2] Q = [[]] R = [[]] H_set = [[[]]] //[Q, R] = classicalGramSchmidt(A) //[H_set, Q, R] = Householder(A) b = [10; 0; 2; 0; 5] [x, norm2error] = getSolution_Error(A, b)
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clear; clc; printf("\t Example 6.17\n"); //moisture content reduces from 25 to 2 r=7.5*10^-5; //constant drying rate in kg/s A1=.3*.3**2; // area of the sppecimen Nc=r/A1; //drying rate Xcr=.15/0.85; //.15 is the critic...
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//what is the resistance of each coil V=200 I=25 P1=1500 R1=(V*V)/P1 R=V/I //total resistance R2=R*R1/(R1-R) disp('R2='+string(R2)+' ohms' )
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// Example 11.3 // Frequency-Response Calcuations s=%s; num=20*(s+25) den=s^2+20*s+500; omega=[0:1:1000]; // diffrent value of frequency for frequency respose plot H_s=num/den; // Given transfer function H_omega=horner(H_s,%i*omega); a_omega=abs(H_omega); theta=atan(imag(H_omega),real(H_omega))*(180/%pi); sub...
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// Scilab Code Ex3c.4: Page-184 (2008) clc; clear; d = 0.3; // Separation between the two slits, cm D = 60; // Distance between the source and the slit, cm lambda = 59e-006; // Wavelength of light, cm bita = lambda*D/d; // Fringe width, cm printf("\nThe fringe width = %4.2e cm", bita); // Result /...
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// At 25 bar, 350 degree h1 = 3125.87; s1 = 6.8481; // 30 degree h0 = 125.79; s0 = 0.4369; // At 3 bar, 200 degree h2 = 2865.5; s2 = 7.3115; // At 0.2 bar 0.95 dry hf = 251.4; hfg = 2358.3; sf = 0.8320; sg = 7.0765; h3 = hf+0.92*hfg; s3 = sf+(0.92*sg); // Part (a) T0 = 303; f1 = (h1-h0)-(T0*(s1-s0)); f2 =...
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clear; clc; close; //part a Ie = 3*10^(-3); Vcb = 10; Ic = Ie; disp(Ic,'Ic (A):'); //part b Vcb = 2; Ie = 3*10^(-3); Ic = Ie; disp(Ic,'No effect of changing Vcb & Ic remains same, Ic(A) is : '); //part c Ic = 4*10^(-3); Vcb = 20; Ie = Ic; Vbe = 0.74; disp(Vbe,'Vbe(volts) is :'); //part d Ic = 4*1...
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clc; clear all d1=input("Enter Distance: ") if d1>10 then: hre=input('Enter the receiver antenna height 3m < hre< 10m : '); for i=1:1:5 frequency=input('Enter Frequency of operation in MHz: '); dist=10:1:100 f=20*log10(frequency); Lo=(32.45+ 20*log10(dist)+20*log10(f)-((1.1* log10(f...
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//chapter 2 //broadside array printf("\n"); Gdmax=5.01108;//antilog[7/10] n=10; lamda=1; d=Gdmax/(20*lamda); printf("the minimum distance between array is %gm",d);
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clear // //Given //Variable declaration L=3*1000 //Length in mm W=50*1000 //Point load in N a=2*1000 //Distance between the load and fixed end in mm I=1e8 //Moment of Inertia in mm^4 E=2e5 //Youngs modulus in N/sq.mm //Calculation //case(i):Slope at the free end ...
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//Example 9_1 clc(); clear; //To find its mass and how large a cube of ice has the same mass pu=18680 //units in Kg/meter^3 s=2*10^-2 //units in meters vu=s^3 //units in meter^3 mu=pu*vu //units in Kg printf("Mass Mu=%.3f Kg\n",mu) pi=920 //units in Kg/meter^3 vi=mu/pi //units in meter^3 ss=vi^(...
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//Rosenbrock Function or Banana Function function f = funcx(x) f = 100*((x(2) - x(1).^2).^2) + (x(1) - 1).^2;; endfunction function g = grad(x) g = [-400*x(1)*(x(2) - x(1).^2) + 2*(x(1) - 1);200 * (x(2) - x(1).^2)];; endfunction xnew=[4;4]; beta1=.9; beta2=.99; alpha=.01; t=0; mprev=0; vprev=0;...
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clc; clear; x1=[4.888889 3.888889]; x2=[7 11]; x3=[10 8]; x4=[150 175]; x5=[77 80 9 6]; profit=[x1(1)*x4(1) x1(2)*x4(2)]; total=[x1(1)*x3(1)+x1(2)*x3(2) x1(1)*x3(1)+x1(2)*x3(2) x1(1) x1(2) profit(1)+profit(2)]; e=1000; while e>total(5) if total(1)<=x5(1) then if total(2)<=x5(2) then ...
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// Example no 6.5 // To determine the analog bandwidth, output SNR improvement if modulation index is increased from 3 to 5 and tradeoff bandwidth for this improvement. // Page no. 277 clc; clear all; // Given data fm=5*10^3; // Audio bandwidth of FM signal betaf1=3; ...
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clc; clear all; l = 2 ; // Length in meters a = 6.25e-5; // Cross Sectional area in square meter inverse deltal = 3e-3; // Increase in length in meters f = 1e3; // Tension in Newtons Y = (f*l)/(a*deltal); // Young's modulus disp('N/m^2',Y,'The youngs modulus of the wire is'); // Slight variation in answer.. the...
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// Problema 5 //x = [1 4 6 5]'; //y = log(x); //interpolacionNewton(x,y,2) function yint = interpolacionNewton(x,y,xx) //Newtint: Newton interpolating polynomial //yint = Newtint(x,y,xx): Uses an (n - 1)-order Newton //interpolating polynomial based on n data points (x, y) //to determine a value of the dependen...
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//Example 2.23: Reduce expression using Boolean laws clc // Clears the console disp('A''BCD + A''BC''D + B''EF + CDE''G + A''DEF + A''B''EF') disp('= A''BD + B''EF + CDE''G + A''DEF') disp('But A''BD $ B''EF = A''DEF and this reduces to ') disp('= A''BD + B''EF + CDE''G') //the reduced expression is displayed.
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clc // initialization of variables P1=2000 // initial pressure in kPa T1=600 // initial temperature in degree celsius p2=600 // final pressure in kPa T2=200 // final temperature in degree celsius d1=0.06 // diameter of inlet pipe in metre d2=0.120 // diameter of outlet pipe in metre V1=20 // velocity at inlet...
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xname('ЗАДАНИЕ 12.1') clc x=-5:.1:5; y=x^3/3-x^2/2-6*x+1; plot2d(x,y,axesflag=5); xgrid() xtitle('График функции: y=x^3/3-x^2/2-6*x+1', 'x', 'y'), clc function y= gg(x) if q==1 then y=x.^3/3-x.^2/2-6*x+1 else y=-(x.^3/3-x.^2/2-6*x+1) end endfunction funcprot(0); function [f,g,r]=z(x,r) f=gg(x) g=num...
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int getOne() { return 1; } main { int s; int[] array; array := new int [3]; array[0] := 0; array[1] := 1; array[2] := 2; s := getOne(array); return s; }
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//Variable declaration: T1 = 99.0 //Mean film temperature (°C) T2 = 98.0 //Plate surface temperature (°C) g = 9.807 //Gravitational acceleration (m/s^2) //From Appendix: T3 = 100.0 //Saturation temperatre (°C) h_vap1 ...
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//To find number of teeth clc //Given: G=4 phi=14.5 //degrees //Solution: //Least number of teeth on each wheel: //Calculating the least number of teeth on the pinion t=2*%pi/tand(phi) //Calculating the least number of teeth on the gear T=G*t //Results: printf("\n\n Least number of teeth on the pinion, t = ...
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clc T = 273.15 - 30;//K R = 8.314; //lnPs = 14.2410 - 2137.72 / (T-26.72) //dlnPs/dT = Hv / RT2 Hv = 2137.72 * R * T^2 / ( T - 26.72 )^2; disp("kJ/kmol",Hv,"Heat of vaporization = ")
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x=[0; 0.0112910099304681; 0.0375437844553138; -0.0502505723940154; 0.0237536810920502; 0.00286337692936232; -0.0268585407773543; -0.00670100836859748; 0.00681025234400021; 0.0743232780915911]; fs=4e6; [R LT]=risetime(x,fs); disp(R); disp(LT); //output //0.0000002 // // 0.0000008
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//Optoelectronics - An Introduction, 2nd Edition by J. Wilson and J.F.B. Hawkes //Example 6.7 //OS=Windows XP sp3 //Scilab version 5.5.2 clc; clear; //given Lambda=10.6e-6;//Wavelength of the laser in m f=200e-3;//Focal length of the lens in m D=50e-3;//Diameter of aperture of focusing lens rs=2*Lambda*f/...
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clear// //Variable Declaration //Say the ratio of stress in steel to concrete is R R=14.286 sigma_co=6*10**6 //Stress in concrete in Pa Ast=3.6*10**-3 //Area of steel in m^2 Aco=86.4*10**-3 //Area of Concrete in m^2 //Calculation sigma_st=R*sigma_co //Stress in steel in Pa //Here stress is below the allo...
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//Chemical Engineering Thermodynamics //Chapter 13 //Thermodynamics in Phase Equilibria //Example 13.6 clear; clc; //Given x1 = 0.1;//Mole fraction of dichloromethane (CCl2H2) x2 = 0.9;//Mole fraction of methyl acetate (C3H6O2) M1 = 85;//Molecular weight of CCl2H2 M2 = 74;//Molecular weight of C3H602 D1 ...
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//Example 6_6 clc(); clear; //To calculate the speed of the pellet before collision h=0.30 //units in meters g=9.8 //units in meters/sec^2 v=sqrt(2*g*h) //units in meters/sec m1=2 //units in Kgs m2=0.010 //units in kgs v10=((m1+m2)*v)/m2 //units in meters/sec printf("The speed of the pel...
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//simplify 12a-2[3a-(4-2(a-3))] clear; clc; close; a=poly(0,'a'); p=12*a-2*[3*a-{4-2*(a-3)}]
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// Chapter 3 example 15 //------------------------------------------------------------------------------ clc; clear; // Given data a = 4*10^-2; // width of waveguide b = 2*10^-2; // narrow dimension of waveguide c = 3*10^8; // velocity of EM wave in m/s m1 = 1; // for TE10 m2 ...
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//Ex:12 clc; clear; close; p_t=13;//Tranponder output power in db w b_t=1;//Transponder output backoff in db g_t=30;//satellite antenna gain in db g_r=59.2;//Earth station antenna gain in db l_fs=195;//Free space loss in db l_a=-2;//Edge of beam loss in db l_air=0.2;//Air atmospheric loss in db l_o=0.4;//Oth...
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//Determine the percent increase of busbar voltage clear clc; vx=3;// percent reactance of the series element sinr=.6; V=vx*sinr; mprintf("Percent drop of volts=%.1f percent\n",V);
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function f3=objfun3(x) f3(1)=x(1)+x(2)-9*x(1)*x(2) f3(2)=x(3)-87*x(4)+x(1) f3(3)=x(5)-6*x(4)*x(3) endfunction x0=[1,3,2,5,4]; A=[-3,7,6,1,2]; b=[9]; Aeq=[1,2,3,4,5]; beq=[3]; goal=[-6,8,-2]; weight=[7,0,3]; [z,gval,attainfactor,exitflag,output,lambda]=fgoalattain(objfun3,x0,goal,weight,A,b,Aeq,beq)
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// 08.09.15 // 09.09.10 registered function Out=WirePt() global WIREPT Out=WIREPT; endfunction;
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// calculate transistor power dissipation and efficiency // Electronic Principles // By Albert Malvino , David Bates // Seventh Edition // The McGraw-Hill Companies // Example 12-4, page 387 clear;clc; close; // Given data R1=490;// in ohms R2=68;// in ohms Rc=120;// in ohms Re=20;// in ohms Vcc=30;// in volts Rl=18...
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//Example 3.5 //calculate //(a)effective thickness of air and liquid films. //(b)the overall heat transfer coefficient based on i.d of pipe. //(c)the overall heat transfer coefficient based on od of insulation. //(d)the percentage of total resistance offered by air film. //(e)the rate of heat loss per meter leng...
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//example 7.4(c)// clc //clears the screen// clear //clears all variables// disp('D7 is active. Since D7 has the highest priority, it will be encoded irrespective of the logic status of other inputs. Therefore, the output bits are A=0, B=0 and C=0')
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clc //initialisation of variables g=1.4 R=96//ft-lb p1=140//lb/in^2 p2=130//lb/in^2 T=288//k r=6//in g1=32.2//ft/sec^2 //CALCULATIONS v1=R*T/(144*p1) v2=v1*(p1/p2)^(1/g) k=g/(g-1) k1=p2/p1 w=(%pi*sqrt((2*g1*k*v1*p1*144*(1-(k1)^(1/k)))/(1-((k1)^2/g)/81)))/(v2*4*r*r) //RESULTS printf (' weight of air fl...
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//find stress after putting the system in lathe clc //soluton //given Ds=18//mm//diameter of steel Dc1=24//mm//inner diameter of copper rod initially Dc2=40//mm//outer diametr of copper Fs=10//N/mm^2//stress in steel rod pi=3.14 As=(pi*Ds^2)/4//mm^2//area of steel rod Ac=(pi*(Dc2^2-Dc1^2))/4//mm^2//area of c...
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// Case Study:-Chapter 3,Page No:77 // 2.Solution of the Quadratic equation printf("Input values of a, b, and c \n"); a=input("a ="); b=input("b ="); c=input("c ="); discriminant = b^2-4*a*c; if(discriminant<0) printf("\n\nROOTS ARE IMAGINARY\n"); else //Computes root1 and root2 ...
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// Grob's Basic Electronics 11e // Chapter No. 33 // Example No. 33_21 clc; clear; // Iin is 1.5 mA, R is 1 kOhms, and Rl is 10 kOhms. Calculate Vout. // Given data Iin = 1.5*10^-3; // Input votage=5 Volts Ri = 1*10^3; // Input resistance=1 kOhms Rl = 100; // Load resistance=100 Ohm...
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clc ; n=0:1:100; fs=0.02; T=1/fs; t=n*T; x = cos(2* %pi * 0.02*(n/fs) ) ; plot2d3(n ,x) ; figure; n=0:1:100; fs=0.04; T=1/fs; t=n*T; x = cos(2* %pi * 0.02*(n/fs) ) ; plot2d3(n ,x) ; figure; n=0:1:100; fs=0.4; T=1/fs; t=n*T; x = cos(2* %pi *0.02*(n/fs) ) ; plot2d3(n ,x) ; figure;
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//Solutions to Problems In applied mechanics //A N Gobby clear all; clc //initialisation of variables h=5//ft h1=3//ft r=200//ft f=0.5//ft v=60//ft/s w=62.0//ft/s q=1.5//ft/s g=32.2//ft //CALCULATIONS V=sqrt(q)/(w/(g*r))/2//ft/s F=sqrt(f*g*r)//ft/s T=(v)^2/(g*r)//degree //RESULTS printf('The value of t...
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// MÉTODO DE NEWMARK COM CONSTANTES TIME STEPS Gama = evstr(NewmarkBeta(1).string) Beta = evstr(NewmarkBeta(2).string) if Beta>=Gama/2; Dtmax = evstr(NewmarkBeta(3).string); end T1 = evstr(NewmarkBeta(4).string) Dt(1) = evstr(DeltaT_CTS.string) // Valores crítico, máximo e mínimo para o passo de tempo if B...
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clc T=300 //K k=8.617*10^-5 //eV/K q=1.6*10**-19 //C m0=0.91*10^-30//kg x=1//cm t=100*10^-6//sec epsilon=50//V/cm vp=x/t disp(vp,"drift velocity in cm/s is") up=vp/epsilon disp(up,"mobility in cm^2/Vs is") Dp=(k*T*up) disp(Dp,"diffusivity of minority carriers in cm^2/sec is")
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// Exa 5.22 clc; clear; close; format('v',8) // Given data A = 10000; Beta = 0.02; Zi = 1;// in k ohm Zi = Zi * 10^3;// in ohm Zo = 10;// in k ohm Zo = Zo * 10^3;// in ohm // The input impedance Zif = Zi*(1+(A*Beta));// in ohm Zif= Zif*10^-3;// in k ohm disp(Zif,"The input impedance in k ohm is"); // T...
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clc; g1=1.5; // gain factor of amplifier g2=80; // gain factor of generator vo=250; // output voltage at no load s=0.2; // feedback potentiometer setting // for generated voltage= 80V field current is 1 A ifl=vo/g2; // field current for generated voltage= 250V vi=ifl/g1; // amplifier input voltage for field curr...
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//Ex3_5 // A Simple Illustration of Histogram Equalization // Version : Scilab 5.4.1 // Operating System : Window-xp, Window-7 //Toolbox: Image Processing Design 8.3.1-1 //Toolbox: SIVP 0.5.3.1-2 //Reference book name : Digital Image Processing //book author: Rafael C. Gonzalez and Richard E. Woods clc; ...
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clear // // // //Variable declaration D4=0.4 //diameter of 4th ring(cm) D12=0.7 //diameter of 12th ring(cm) p1=16 p2=8 n=4 //Calculation x=n*p1/(n*p2) D20=sqrt((D4**2)+(x*((D12**2)-(D4**2)))) //diameter of 20th dark ring(cm) //Result printf("\n diameter of 20th dark ring is %0.3f cm"...
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[SourceDisksFiles] @@:testroot.cer = 1,,,,,,,,3,3 ; copied specially by syssetup (BUGBUG--SHOULD NOT BE IN A BUILD RELEASED EXTERNALLY!)
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//clc() //C2H4(g) + H2O(g) = C2H5OH(g) //2CO2(g) + 3H2O(l) = C2H5OH(l) + 3O2(g) H = 1366.91kJ (A) Hc2h4 = -1410.99;//kJ/mol Hvap = 44.04;//kJ/mol Hc2h5oh = 42.37;//kJ/mol //C2H4(g) + 3H2O(l) = C2H5OH(l) + 3O2(g) H = -1410.99kJ (B) //H2O(l) = H2O(g) H = 44.04kJ (C) //C2H5OH...
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function I = trapecio_compuesto_puntos(x, y) n = length(x) h = (x(n)-x(1))/(n-1) I = (h/2)*(y(1)+2*sum(y(2:n-1))+y(n)) endfunction
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PL/SQL Developer Test script 3.0 8 -- Created on 18.05.2017 by OLEG declare -- Local variables here i integer; begin -- Test statements here dbms_stats.gather_schema_stats (ownname => 'EDU'); end; 0 0
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function y = medfilt1(x,n,blksz,DIM) funcprot(0); if(argn(2)<1|argn(2)>4) error('Incorrect number of input arguments.'); else y=zeros(x) x1=[0, x, 0]; for i=2:length(x)+1 y(i)=median([x1(i-1),x1(i),x1(i+1)]) end endfunction
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clc(); clear; // To calculate the thickness of turbulent boundary layer at a distance of 12 inch x = 12/12; // Distance from leading edge in ft v = 33; // Stream flowing velocity in ft n = 15.4*10^(-5); // kinematic viscosity, feet^2/s ...
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ex_4_7.sce
////Ex 4.7 clc; clear; close; format('v',5); AOL=500;//unitless Rio=300;//kohm Ro=100;//ohm ACL=AOL/(1+AOL);//unitless Rif=Rio*(1+AOL)/1000;//Mohm Rof=Ro/(1+AOL);//ohm disp(ACL,"Close loop gain, ACL"); disp(Rif,"Value of Rif(Mohm)"); disp(Rof,"Value of Rof(ohm)");
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//Example 1.67// percentage error clc; clear; close; //given data : f=100; // in Hz V1=250; // in volts I1=0.05; // in A L=1; // in H R=V1/I1; V=250; // in volts XL=2*%pi*f*L; Z=sqrt(R^2+XL^2); Vr=(V1*R)/Z; Ve=Vr-V; Pe=abs(Ve/V)*100; disp(Pe,"percentage error,Pe = ")
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// Scilab Code Ex 6.10: Page-6.18 (2004) clc;clear; k = 1.38e-23; // Boltzmann constant, joule per kelvin T = 300; // For simplicity room temperature is taken, kelvin e = 1.6e-19; // Charge on electron, C EF = 5.5; // Fermi Energy, eV E = EF+(EF/100); // New energy, eV F_E = 0.1; // Fermi fu...
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// ELECTRICAL MACHINES // R.K.Srivastava // First Impression 2011 // CENGAGE LEARNING INDIA PVT. LTD // CHAPTER : 4 : DIRECT CURRENT MACHINES // EXAMPLE : 4.16 clear ; clc ; close ; // Clear the work space and console // GIVEN DATA Out_hp = 20; // Output of the Motor in HP eta...
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clc clear //input data N=9000//The rotational speed in rpm dT0=20//The stagnation temperature rise in K DhDt=0.6//The hub to tip ratio l=0.94//The work donee factor ns=0.9//The isentropic efficiency of the stage C1=150//Inlet velocity in m/s P01=1//The ambient pressure in bar T01=300//The ambient temperature ...
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//Exa 2.32 clc; clear; close; format('v',6); //Given Data : p1=5;//bar p2=50;//bar V=0.001;//m^3/Kg m_dot=10;//Kg/s wsf=integrate('-V',"p",p1*10^5,p2*10^5);//J/kg wsf=wsf/1000;//KJ/Kg Wsf=abs(wsf)*m_dot;//KW(leaving -ve sign as it is to indiacte heat is supplied) disp(Wsf,"Power required in KW : ");
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getd(); global noeuds; global g ; global m ; global k; global dt; global segments; global L0; global _MYDATA_; //dv = vt - vt-1 //at = dv/dt //vt = vt-1 + dv //xt = xt-1 + vt * dt //xt = xt-1 + (vt-1+dv)*dt //m.at = mg + F(xt) //m.dv/dt = mg + F[xt-1 + (vt-...