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//Initialisation of variables clc m=9.1*10^(-28)//mass on electron e=4.8*10^(-10)//charge on electron ev=1.6e-12//electron volt in ergs v=10^9//cms/sec E=0.5*m*v^2//energy in ergs Ev=E/ev printf('energy is %e ergs \n',E) printf('energy is %f electron volt \n',Ev)
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errcatch(-1,"stop");mode(2);// Exa 4.30 ; ; // Given data I_C = 10;// in mA I_B = 0.1;// in mA bita = I_C/I_B; disp(bita,"The current gain is"); exit();
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//Example 22.5 N=100;//Number of turns I=15;//Current (A) A=(10*10^-2)^2;//Area of square loop of side 10cm (m^2) B=2;//Magnetic field strength (T) theta=90;//Angle for maximum torque (deg) tau_max=N*I*A*B*sind(theta);//Maximum torque (N.m) printf('Maximum torque = %0.1f N.m',tau_max) //Openstax - College Physi...
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//Calculating the running speed and frequency of the rotor magnet current //Chapter 4 //Example 4.9 //page 299 clear; clc; disp("Example 4.9") fr=2;.............................//frequency of motor induced emf in hertz f=50;.............................//frequency of induction motor in hertz S=(fr/f)*100;.......
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//Ex14_13 Pg-700 clc del=1/100 //fractional difference of refractive indices lamda=1.3*10^(-6) //cutoff wavelength in m n1=1.5 //refractive index d=6.6*10^(-6) //diameter of the core alpha=2 //loss in fiber disp(" We have for a GRIN , maximum value of normalized frequency for single mode operation is give...
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//Chapter 6, Problem 8 clc id=2e-3 //drain current in ampere vds=12 //drain to source voltage vcc=24 //supply voltage idss=8e-3 //drain–source current when the gate and source are shorted vp=-6 ...
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style.displayedLabel="ladder_filter" pal5=xcosPalAddBlock(pal5,"ladder_filter",[],style); style.displayedLabel="common_drain" pal5=xcosPalAddBlock(pal5,"common_drain",[],style); style.displayedLabel="mux4_1" pal5=xcosPalAddBlock(pal5,"mux4_1",[],style); style.displayedLabel="tgate_vec" pal5=xcosPalAddBlock(pal5,"tg...
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//Calculates 3x3x£ matrix of nearest neighbour elements for a value function [getconcsub]=getconcsub(conc, i1,i2,i3, n1, n2, n3) if n3<2 nsub3=1; else nsub3=3; end; testconcs...
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clc; clear; m=68.1;//kg v=40;//m/s t=10;//s g=9.8;//m/s^2 function y=f(c) y=g*m*(1-exp(-c*t/m))/c - v; endfunction x1=12; x2=16; xt=14.7802;//true value e=input("enter the tolerable approximate error=") xr=(x1+x2)/2; i=1; et=abs(xr-xt)/xt*100;//error disp(i,"Iteration:") disp(x1,"xl:") disp(x2,"xu...
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//zad 1.a asin(-0.45) //zad 1.b x=[7 -2 3;1 2 4;-2 5 8;6 -1 0] rank(x) //zad 1.c v=20 r=20 a=v^2/r //zad 1.d n=1:40 a=(n-3).*(k^3)^(-1) sum(a) //zad 2 clear clc clf x=[1:0.01:5]; y=log(2*x) z=2*x^2-3*x+(1/x) plot(x,y,'r','LineWidth',2) plot(x,y,'g','LineWidth',2) xgrid xlable('Argument Funckji') ...
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close(); clear; clc; //Maximum voltage of 'Vsm', angular frequency 'w' of vs, ratio of ripple voltage and average output voltage 'Fs' Rl = 1000; //ohm Vsm = 90; //V w = 2000; //rad/s Fs = 0.05; f = w/(2*%pi); C = 1/(f*Rl*Fs); //F //average value of vl 'Vlavg' Vlavg = Vsm*(1 -1/(2*f*Rl*C)); //V mprintf("Ave...
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function x = resoltrsup(A, b) n = size(A,1) x(n)= b(n)/A(n,n) for i=n-1:-1:1 x(i) = (b(i)-A(i, i+1:n)*x(i+1:n))/A(i, i) end endfunction function [T, c] = gauss(A, b) //SIN PIVOTEO n = size(A,1) for k = 1:n-1 // para cada pivote for j = k+1:n // para cada elemento debajo del pivote ...
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nx = 50; ny = 50; x = linspace(-1,1,nx); y = linspace(-1,1,ny); [X,Y] = ndgrid(x,y); A = zeros (nx,ny); A (find(abs(X)<0.7 & abs(Y)<0.7) ) = 1; //E = edge(A,'canny') //imshow(E); A = double(A); fftA = fft2(A); fftA = uint8(imnorm(fftshift(abs(fftA)))*255); f=scf(); imshow(fftA); //f = scf(); //grayplot(x,y,A); //f.co...
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//EX3_21 PG-3.58 clc Idc=100e-3;//average current C=500e-6;//filter capacitor Esm=18;//peak voltage f=50;//frequency of the supply in Hz Edc=Esm-Idc/(4*f*C); Rl=Edc/Idc;//load resistance Rf=(4*sqrt(3)*f*C*Rl)^(-1)*100;//ripple factor printf("\n ripple factor is %.2f %% \n",Rf)
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clc //initialisation of variables v=400//Btu per lb t=1698//R c=0.1715//ft p=0.24//ft v1=15//ft v2=1.414//V p1=560//R q=800//ft h=401600//ft-lb per lb s=13.63//ft //CALCULATIONS T=(v/(1*c))//R T1=t+T//R T2=v/(1*p)//R T3=T1+T2//R V=v1/v2//ft T4=T3/(V)^0.4//R Q=1*c*(T4-p1)//Btu per lb Q1=q-Q//Btu per...
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array <int> finalSeq[432] = {41,36,11,24,55,2,66,25,2,7,47,72,48,2,54,14,35,61,26,28,67,36,66,66,7,48,10,10,17,17,32,52,52,40,52,52,34,50,50,60,65,42,53,59,13,64,25,4,51,51,42,29,29,38,30,30,27,27,38,28,69,60,5,47,15,7,27,10,63,58,68,68,63,63,53,48,28,31,70,6,1,15,33,54,13,61,61,17,24,18,57,8,12,43,23,10,1,70,70,16,21,...
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global storedRandom global ret global aCongr global cCongr global mCongr function setCongruentialGenerator(a,c,m) global aCongr global cCongr global mCongr aCongr=a; cCongr=c; mCongr=m; endfunction function setCongruentialSeed(s) global storedRandom storedRandom=s; endfunction function [ret]=nextRand...
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//Introduction to Fiber Optics by A. Ghatak and K. Thyagarajan, Cambridge, New Delhi, 1999 //Example 17.7 //OS=Windows XP sp3 //Scilab version 5.5.2 clc; clear; //given //Since the peak reflectivity of fiber is 0.93%, R=0.93;//Reflection coefficient of fiber L=4.8e-3;//Length of fiber in m lambdaB=1532.1e-9;/...
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// Exa 3.12 clc; clear; close; format('v',6) // Given data V_CC = 20;// in V bita = 50; R_C = 2;// in k ohm R_E = 0.1;// in k ohm R1 = 100;// in k ohm R2 = 5;// in k ohm R_Th = (R1*R2)/(R1+R2);// in k ohm R_B = R_Th;// in k ohm V_BE = 0.7;// in V V_Th = (V_CC*R2)/(R1+R2);// in V // Applying KVL to the b...
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//Chapter-1, Example 1.52, Page 57 //============================================================================= clc; clear; //INPUT DATA V1=10;//source1 voltage in volts V2=5;//source2 voltage in volts V3=5;//source3 voltage in volts RAH=2;//Resistance in ohms RAB=3;//resistance in ohms RBE=5;//resistance ...
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// CALLING EXTERNAL ROUTINE foo=[' subroutine foo(a,b,c)'; ' double precision a,b,c'; ' c=a+b '; ' return'; ' end']; if getenv('WIN32','NO')=='OK' & getenv('COMPILER','NO')=='VC++' then unix_s('del foo.f') write('foo.f',foo); WSCI=getenv('WSCI'); cmd='nmake /f ""...
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clc; funcprot(0); //-----------------------Important Note-------------------------------// // Please keep intersectFunc.sci in the same folder in which this file// // is kept and change the current working directory to the directory // // in which both the files are kept using chdir "absolute path" // //-...
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//ex9.1 V_CC=15; R_C=1*10^3; R_1=20*10^3; R_2=5.1*10^3; R_3=5.1*10^3; R_4=15*10^3; R_E_1=47; R_E_2=330; R_E_3=16; R_L=16; //SPEAKER IS THE LOAD; B_ac_Q1=200; B_ac_Q2=B_ac_Q1; B_ac_Q3=50; //R_c1=R_C||[R_3||R_4||B_acQ2*B_ac_Q3*(R_E_3||R_L)] is ac collector resistance R=(R_E_3*R_L)/(R_E_3+R_L); R=B_ac_Q...
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//chapter23 //example23.5 //page515 Vm=400 // V v=150 // V R_L=200 // ohm // since v=Vm*sin(theta), we get theta=asin(v/Vm)*180/%pi // in terms of degrees V_av=Vm*(1+cos(theta*%pi/180))/(2*%pi) I_av=V_av/R_L P=V_av*I_av printf("firing angle = %.2f degrees \n",theta) printf("average output voltage ...
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clc; m=1500; //mass in kg F=3000; //force in Newton t=5; //time in sec a=F/m; //calculating acc. (Newton's Law) disp(a,"Accelaration in m/sec square = "); //displaying result v=a*t; //kinematical equation disp(v,"Velocity in m/sec = "); //displaying result
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// determine flow rate,theoretical head required power,pressure across the impeller clc b1=44 r1=21e-3 // mm B=11e-3 // mm r2=66e-3 //mm b2=5e-3//mm N=2500 //rpm h1=0 g=9.8 alpha=90 // degree D1=2 D2=2 u1=(2*%pi*N*r1)/60 gamm1=9800 p1=1000 mprintf('\n peripherial velocity at inlet u1=wR1 =%f m/s',u1) ...
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// Scilab Code Ex13.10 Forward current of a p-n diode in terms of reverse saturation current using diode equation: Page-450 (2010) e = 1.6e-019; // Charge on an electron, coulomb k = 1.38e-023; // Boltzmann constant, J/mol/K V = 0.35; // Potential difference applied across a Ge diode, volt T = 300; // R...
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void main() { int i = 1; while(i > 1) { print("ERROR_WHILE"), } }
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//To find width of the belt clc //Given: t=9.75/1000, d1=300/1000, x=3 //m P=15*1000 //W N1=900, N2=300 //rpm rho=1000 //kg/m^3 sigma=2.5*10^6 //N/m^2 mu=0.3 //Solution: //Calculating the diameter of the driven pulley d2=d1*(N1/N2) //m //Calculating the velocity of the belt v=%pi*d1*N1/60 //m/s //Calculat...
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clear close clc s = poly(0,'s'); G = (s+50)*(s+60)*(s+70)*(s+80)/((s+6)*((s+5)^2+4)*((s+5)^2+1)); Glin = syslin('c',G); clf(); evans(Glin,1000);
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//Example 6.20 //Program to Plot Magnitude Responce of given L.P.F. with specifications: //N=13,w=pi/6 //Using Hamming Window clear; clc ; close ; N=13; alpha=6; U=1; h_hamm=window('hm',N); for n=0+U:1:12+U if n==7 hd(n)=0.167; else hd(n)=(sin(%pi*(n-U-alpha)/6))/(%pi*(n-U-alpha)); end h(n)=hd(...
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p0 = 10^15; ni = 10^6; n0 = ni^2/p0; disp(n0,"Minority electron concentration (in per cubic centimeter)=" ) dn = 10^14; dp = 10^14; tn = 10; //in nanoseconds tp = tn; t = 0:10:50; del_n = dn*exp(-t/tn); del_p = dp*exp(-t/tp); p = p0 + del_p; n = del_n; //since n0 is negligible subplot(121); plot(t,log(p))...
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clear; clc; //Example - 7.29 //Page number - 263 printf("Example - 7.29 and Page number - 263\n\n"); //This problem involves proving a relation in which no numerical components are involved. //For prove refer to this example 7.29 on page number 263 of the book. printf(" This problem involves proving a relati...
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ok=open_serial(1,2,115200); if ok~=0 then error('Unable to open serial port, please check'); end J=0; K=0; //assuming initially, Q=0 & Qbar=1 Q=0; Qbar=1; temp=0; pre=0; clr=0; JPin=5;//input J is given to pin 5 KPin=6;// input K is given to pin 6 QPin=9;//output Q is seen at pin 9 QbarPin=10;/...
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//var 6 i = 0; k = 4; fd = mopen('D:\mis_labs\a.txt', 'wt'); result = [0. 0. 0. 0]; result2 = [0 0 0 0 0 0; 0 0 0 0 0 0; 0 0 0 0 0 0; 0 0 0 0 0 0]; count = 1; while i < 400 message = " тип"; tmp = rand(); tmp2 = rand(); if tmp < 0.28 then message = "1" + message; //.....................
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clc //initialisation of variables s= 13.6 h= 12 //in u= 0.04 k= 1 d= 6 //in g= 32.2 //ft/sec^2 w= 62.4 //lbs/ft^3 //CALCULATIONS h1= h*(s-1)/12 hf= u*h1 hn= h1-hf Q= k*(%pi*(d/12)^2)*sqrt(2*g)*sqrt(hn)*w*60/(10*4*sqrt(15)) //RESULTS printf ('discharge through flow= %.f ft G.P.M',Q)
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clc //initialisation of variables ps1=0.006566 //bar pressure phi1=0.6 //relative humidity td2=21 //temp in degrees td1=1 //temp in degrees ps2=0.02486 //pressure in bar td3=26 //temp in degrees p=1.013 //pressure in bar //CALCULATIONS pv1=(phi1*ps1) w=0.622*(pv1/(p-pv1)) q=(td2-td1)*(1.005+(1.86*w)) phi2=...
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//Chapter 13 Thermodynamics Entropy and Free Energy clc; clear; //Initialisation of Variables F= -51180 //cal T= 25 //C R= 1.99 //cal/mole K //CALCULATIONS K= 10**(-F/(R*(273+T)*2.303)) //RESULTS mprintf("Equilibrium constant = %.2e",K)
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// Example 2.10 clear all; clc; // Using standard data table of mass and the coefficients of mass equation for Silver-107 N = 60; // Number of neutrons Z = 47; // Atomic number A = 107; // Atomic mas...
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clear all; clc; disp("Ex 19_8") //Referring figure 19-12b and 19-12c //Using the principle of Conservation of Angular Momenutum and since (v_G)2=0.5*w_2 //Equation 1 becomes : 5.0=0.5*(v_B)2+1.67*w_2 //Using the coefficient of restitution theory, we have 4.0=0.5*w_2-(v_B)2 //Solving the above two equatons, disp("(v_B)2...
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function x=logm(a) // logm - log(A) //%CALLING SEQUENCE // X=logm(A) //%PARAMETERS // A : square hermitian or diagonalizable matrix // X : square matrix //%DESCRIPTION //computes X=logm(A), matrix log of A //! [m,n]=size(a) if m<>n then error(20,1),end flag=or(a<>a') if ~flag then //Hermitian matrix r=an...
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// Scilab code Ex15.5: Pg 570 (2005) clc; clear; m_pi = 135; // Mass of pion, MeV/c^2 m_p = 938.3; // Mass op proton, MeV/c^2 // For simplification, let velocity of light be unity c = 1; // Velocity of light, m/s // Simplifying K_th = (m_3 + m_4 + m_5 + ....)^2*c^2 - (m_1 + m_2)^2*c^2, we get K_th...
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// Scilab Code Ex 1.18 Angle between two directions of cubic crystal: Page-23(2010) h1 = 1; k1 = 1; l1 = 1 // Miller indices for first set of planes h2 = -1; k2 = -1; l2 = 1; // Miller indices for second set of planes // We know that // cos(theta) = (h1*h2+k1*k2+l1*l2)/(sqrt(h1^2+k1^2+l1^2)*sqrt(h2^2+k2^2+l2^2))...
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//(b)overlap-save method xn=[1 2 3 3 4 5]; hn=[1 1 1]; xon=[0 0 1 2 3]; x1n=[2 3 3 4 5]; x2n=[4 5 0 0 0]; yon=convol(xon,hn); y1n=convol(x1n,hn); y2n=convol(x2n,hn); yno=yon(3:5); yn1=y1n(3:5); yn2=y2n(3:5); yn=[yno yn1 yn2] YN=convol(xn,hn)
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// Aim:To find how many cfm of free air compressor must be provided // Given: // flow-rate of air from receiver: Q2=30; //cfm // temperature of air from receiver: T2=90; //deg F // pressure of air coming from receiver: p2=125; //psig // atmospheric temperature: T1=70; //deg F // atmospheric pressure: p1=14.7; //psig
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//Scilab Code for Example 10.1 of Signals and systems by //P.Ramakrishna Rao //Cross Correlation clear; clc; x=[2,-1,1,0,2]; y=[0,1,0,-1,2]; //computation of cross correlation sequence; n1 = max(size(y))-1; n2 = max(size(x))-1; r = xcorr(x,y,n1); n=-4:4; a=gca(); a.x_location="origin"; a.y_location="origi...
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clear; clc; //Example - 15.17 //Page number - 536 printf("Example - 15.17 and Page number - 536\n\n"); //Given T = 25;//[C] - Temperature P = [118.05,124.95,137.90,145.00,172.90,207.70,227.70,237.85,253.90,259.40,261.10,262.00,258.70,252.00,243.80];//[mm Hg] x_1 = [0.0115,0.0160,0.0250,0.0300,0.0575,0.1125,...
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART II : TRANSMISSION AND DISTRIBUTION // CHAPTER 3: STEADY STATE CHARACTERISTICS AND PERFORMANCE OF TRANSMISSION LINES // EXAMPLE : 3.5 : // Page number 130 clear ; clc ...
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clear clc // f(3.0, 2.0) = 0.0 // f(-2.805118, 3.131312) = 0.0 // f(-3.779310, -3.283186) = 0.0 // f(3.584428, -1.848126) = 0.0 function y = f(x) y = (x(1).^2 + x(2) - 11).^2 + (x(1) + x(2).^2 - 7).^2; endfunction function pop = initPop(N_0, dim, Lb, Ub) Lb_array = Lb .* ones(1, dim); Ub_array = Ub .* one...
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//particle in motion //v=t^3-t^2-2*t+2 //a=3*t^2-2*t-2 //acceleration after 4 seconds a=3*4^2-2*4-2 //m/sec^2 //s=(t^4)/4-(t^3)/3-(t^2)+2*t+C //c is constant of acceleration //applying given condition C=4/3 s=(4^4)/4-(4^3)/3-(4^2)+2*4+(4/3) //m //using maxima and minima principle //minimum value of acceler...
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//Fluid Systems - By - Shiv Kumar //Chapter 11- Centrifugal Pumps //Example 11.21 //To Find the Manometric Efficiency clc clear //Given Data:- n=4; //Number of Pumps N=400; //Speed, rpm H_Tm=40; //Total Manometric Head, m Q=0.2; //Dis...
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h1 = 82; h2 = 52; h3 = 47; h4 = 40; W1 = 0.020; W2 = 0.0115; W3 = W2; v1 = 0.887; v = 3.33; // amount of free sir circulated G = v/v1; CC = (G*(h1-h3)*3600)/14000; // in tonns R = G*(W1-W3); disp("tonnes",CC,"Capacity of the cooling coil in tonnes") disp("kg/s",R,"Rate of water vapour removed is")
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a = input("Digitar o vetor linha a = "); n = size(a); soma = 0; for i = 1:n(2) soma = soma+a(i) end m = soma/n(2); for i = 1:n(2) if a(i)<(m) then disp(i) end end disp(p);
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//(12.1) The molar analysis of the gaseous products of combustion of a certain hydrocarbon fuel is CO2, 0.08; H2O, 0.11; O2, 0.07; N2, 0.74. (a) Determine the apparent molecular weight of the mixture. (b) Determine the composition in terms of mass fractions (gravimetric analysis). //solution //variable initializ...
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//Ex 5.9 clc; disp('x(t)=cos(200%pi*t+theta)'); w=200*%pi; f=w/(2*%pi); nyquist_rate=2*f; disp(nyquist_rate,'Minimum sampling frequency to avoid aliasing is');
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//Ex:4.42 clc; clear; close; D=10;// beam width y=30.54;// wavelength in cm X=(58*y)/D;// 3-dB beam width Ar=(%pi*X^2)/4;// area of the cross section in m^2 G=(4*%pi*Ar)/y^2;// the gain for y=30.54 cm G1=10*log(G)/log(10);// the gain for y=30.54 cm in dB y1=3.054;// wavelength in cm X1=(58*y1)/D;// 3-dB beam...
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clear clc dat = csvRead("C:\Users\Immanuel\Documents\SCILAB\EDL.csv"); frange = dat(2:41,1) Mdb = dat(2:41,12) phdeg = dat(2:41,16) f1 = 100; f2 = 1000; eta1 = 0.1; eta2 = 1; //comp = 10*((1+%i.*frange./f2)./(1+%i.*frange./f1))^2; comp = 2.5*((1+2.*eta2.*%i.*frange./f2 - (frange./f2)^2)./(1+2.*eta1.*%i.*fr...
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inputCount = input("Enter how many elements:") printf("\nEnter %i random integers:",inputCount) //input elements for i=1:inputCount numArray(i) = input("") end printf("Initial:") for i=1:inputCount printf("%i ",numArray(i)) end printf("\n") swapped = 1 //set swapped to true loopNum = 0 //this is where ...
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//chapter 24 Ex 21 clc; clear; close; area=72; h=sqrt(area/2); mprintf("The height of parallelogram is %d cm",h);
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//EX3_33 PG-3.70 clc disp("Refer to the figure-3.45 shown") Vz=6.1;//zener voltage Iz_min=2.5e-3;//minimum zener current Iz_max=25e-3;//maximum zener current rZ=0;//ideal zener diode R=2.2e3; Rl=1e3;//loadd resistance Il=Vz/Rl; //For minimum input voltage(Vin_min) Iz=Iz_min I=Iz_min+Il; Vin_min=Vz+I*R; pr...
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function [K,X,err]=leqr(P12,Vx) //H-infinity lqr gain for full-state LQ problem //(discrete or continuous) // discrete continuous // |I -Vx 0| | A 0 B| |I 0 0| | A Vx B | // z|0 A' 0| - |-C'C I -S| s|0 I 0| - |-C'C -A' -S | ...
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T1: T2 T4 T7 T2: T3 T5 T3: T4:: T5 T6 T5: T6: T5 T7: T6
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//Exa 2.2 clc; clear; close; //given data J=2.4;//in A/mm^2 J=J*10^6;//in A/m^2 n=5*10^28;//electrons/m^3 e=1.6*10^-19;//constant //Formula : J=e*n*v v=J/(e*n);//in m/s disp(v*10^3,"Velocity of electron at fermi level in mm/s : ");
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//Chapter 14: Water Treatment //Problem: 8 clc; //Initialisation of Variables //EDTA=Ethylenediaminetetraacetic acid v1_water = 50 //in ml for water w1_CaCO3 = 1.5 //in mg for pure CaCO3 v1_EDTA = 44 //in ml for EDTA v2_EDTA = 40 //in ml for EDTA v2_water = 20 //in ml for water //Solution ...
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//Function migration (image list to matrix) for: getStructuringElement //Generated by migrate.cpp //Author: Anirudh Katoch function res = getStructuringElement(varargin) select length(varargin) case 05 then res = raw_getStructuringElement(varargin(01), varargin(02), varargin(03), varargin(04), varargin(05)) els...
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n=['a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O','U'] lenofn =(size(n)) for i=lenofn(1):lenofn(2) //printf("%s\n", n(i)) end arrayofvowels=['A', 'E', 'I', 'O', 'U'] lenofarr=size(arrayofvowels) for j=lenofarr(1):lenofarr(2) data=(ascii(arrayofvowels(j))) //disp(data) end a="HELLO WORLD" txt=asciimat(...
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clear clc //to find density and displacement amplitude // GIVEN: //maximum pressure variation delta_pm = 28//in Pa //frequency f = 1000//in Hz //pressure amplitude delta_p1 = 2.8e-5//in Pa //bulk modulus of air B = 1.4e5//in Pa //speed of sound in air v = 343//in m/s //density of air rho_0 = 1.21//in K...
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clc; warning("off"); printf("\n\n example5.9 - pg166"); // given v=1; //[cm/sec] - volume velocity or bulk velocity vol=1; //[cm^3] - volume na=2; // moles of a nb=3; // moles of b nc=4; // moles of c mma=2; //molecular weight of a mmb=3; //molecular weight of b mmc=4; //molecular weight of c ma=na*...
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clc clear //Input data d=13596;//Density of Hg in kg/m^3 g=9.806;//gravity in m/sec^2 z=760;//Barometer pressure in mm of Hg Pv=40;//Vaccum pressure in cm dw=1000;//Density of water in kg/m^3 Zw=1.5;//Level of water in m //Calculations p=(d*g*z)/10^6;//Pressure in kPa p1=(80/76)*p;//Pressure in kPa Pa=p-P...
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function [F, G, ind]=OraclePG(qc, ind) v_qc = q0 + B * qc; v_qc_abs = abs(v_qc); v_rqc = r .* v_qc .* v_qc_abs; F = 0; G = 0; if ind == 2 then F = 1/3 * v_qc' * vr_qc + pr' * (Ar * v_qc); return; elseif ind == 3 then G = B' * (v_rqc + Ar' * pr); return; elseif ind == 4 then F = 1/...
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function [ident,info]=testqp(n,irand,idef,imi,icota,nul,eps,modo) //Syntax : [ident,info]=testqp(n,irand,idef,imi,icota,nul,eps,modo) // // test problems for quapro and linpro // //%inputs // n : dimension of the problem // irand : seed for starting the generation of random numbers. // For...
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clc //initialisation of variables u=250 //blade speed in m/s theta=80 //angle in degrees alpha=20 //angle in degrees oed=786.7 //overall enthalpic drop in kj/kg sp=3000 //rotational speed of an impulse turbine wheel in revolutions p=6000 //power developed in kw rf=1.04 //reheat factor ie=2993.4 //kj/kg vs=9.2...
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clc; g=9.8; //gravitational constant in m/sec square m=100; //mass in kg disp(m*g,"Weight in Newton = ");
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function akar = iterasitetap (x0, eps) x(1) = x0; g(1) = 100; r = 1; /*for r = 1 : 11 //Fungsi //x(r+1) = sqrt(4*x(r)+20); //x(r+1) = (x(r)^2-20)/4; //x(r+1) = 20/(x(r)-4); x(r+1) = (20/x(r))+4; //Galat g(r+1) = x(r+1)-x(r); end*/ ...
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//Chapter 2,Ex2.56,Pg2.71 clc; disp("Refer to the diagram shown in the question") //Remove the 1 ohm resistor from the meshes 1 and 2, then we can say the following about the current I1=-3 //Current in amperes I2=1 //Current in amperes printf("\n I1=%.0f A \n",I1) printf("\n I2=%.0f A \n",I2) //Calculation of V...
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clc; //page no 472 //prob no. 14.5 //Standard coaxial cable RG-8/U with 45 degree phase shift at 200MHz p=45;f=200*10^6;c=3*10^8;//Speed of light in m/s vf=0.66;//velo. factor for this line vp=vf*c;//Determination of propagation velo. wav=vp/f;//Determination of wavelength of signal //Determination of reqd leng...
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Nx = 80; Ny = 40; x= linspace(-6,6,Nx); y = linspace(-3,3,Ny); z = zeros(Ny, Nx); for i=1:Nx for j=1:Ny z(j,i) = cos(x(i))*sin(y(j)); end end surf(z); mesh(z); clf(); surf(x,y,z); clf(); surf(x,y,z); h = gce(); h.color_flag = 3; fg = gcf(); fg.color_map = rainbovcolormap(256); fg.f...
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clc; pathname=get_absolute_file_path('2_3_soln.sce') filename=pathname+filesep()+'2_3_data.sci' exec(filename) // Solution: // we know, // specific gravity of air=(specific weight of air/specific weight of water) // also we know,specific weight of water at 68 degF, gamma_water=62.4; //lb/ft^3 SG_air=gamma_air/gamma_wa...
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ex4_25.sce
clc kva=5 //Assigning values to parameters e2=400 r02=0.85 x02=1.236 i2f=kva*1000/e2 t=acosd(0.8) pr1=(i2f*r02*cosd(t)+i2f*x02*sind(t))*100/e2 pr2=(i2f*r02*cosd(t)-i2f*x02*sind(t))*100/e2 disp(pr1,"The percentage regulation at full load 0.8 pf lagging is"); disp(pr2,"The percentage regulation a...
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pathname=get_absolute_file_path('19_2.sce') filename=pathname+filesep()+'19_2data.sci' exec(filename) GJcl=((4*A*A*G*t12)/(L12+L34)); GJo=((L34+L13)*G*t^3)/3 GJ=GJcl+GJo; Dtheta=T/GJ; qcl=GJcl*Dtheta/(2*A); tmaxcl=qcl/t12; tmaxo=G*t13*Dtheta; printf("\nτmax,cl: %f N/mm^2",tmaxcl); printf("\nτmax,op: %f N/mm^...
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b=[-3 -3 -5 -6]; a=[-1 2 3 -5]; z=tf2zpk(b,a); disp(z); //output // // 0.0572940 + 1.3383208i // 0.0572940 - 1.3383208i // - 1.114588 //
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clear; clc; V_s=230; V_m=sqrt(2)*V_s; a=45; R=10; V_o=(V_m/%pi)*(1+cosd(a)); I_o=V_o/R; V_or=V_s*sqrt((1/%pi)*((%pi-a*%pi/180)+sind(2*a)/2)); I_or=I_o; P_dc=V_o*I_o; P_ac=V_or*I_or; RE=P_dc/P_ac; printf("rectification efficiency=%.4f",RE); FF=V_or/V_o; printf("\nform factor=%.3f",FF); VRF=sqrt(FF^2-...
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// Initilization of variables a_T=0.18 // m/s^2 // acc of trolley // Calculations a_B=-a_T/3 // m/s^2 // from eq'n 4 t=4 // seconds v_T=a_T*t // m/s // velocity of trolley after 4 seconds v_B=-v_T/3 // m/s // from eq'n 3 S_T=(1/2)*a_T*t^2 // m // distance moved by trolley in 4 sec S_B=-S_T/3 // m // from eq'n 2...
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index.html test1.txt test2.txt test3.txt test4.tst test5.tst
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Método de Simpson.sci
function y=simpson(f,a,b,n) // Metodo de Simpson com n repeticoes // f: funcao, a,b: intervalo de integracao h=(b-a)/(2*n); Soma=f(a)+f(b); for i=1:n-1 Soma=Soma + 4*f(a+h*(2*i -1)) + 2*f(a+h*2*i); end; Soma=Soma+4*f(a+(2*n-1)*h); y=(h/3)*Soma; endfunction
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5_4.sce
clear; clc; m=2.292; g=9.81; l=152; Pw=39.063; dia=2.068e-2; ar=3.065; stress=1054.63; //(a) w=m*g; T=stress * ar *g; Fw=Pw* g * dia; Ft= sqrt(w^2 + Fw^2); S=Ft * l *l /(8* T); mprintf("\n Sag= %.2f m", S); Sy= S * w/Ft; mprintf("\n Vertical Component of Sag= %.3f m", fix(Sy*1000)/1000);
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hydrate.tst
units SI $thermo = VirtualMaterials.Peng-Robinson / -> $thermo thermo + NITROGEN WATER METHANE ETHANE PROPANE ISOBUTANE CARBON_DIOXIDE HYDROGEN_SULFIDE n-BUTANE Feed = Stream.Stream_Material() Out = Stream.Stream_Material() Hydrate = Hydrate.Hydrate() Feed.Out -> Hydrate.In Hydrate.Out -> Out.In Feed.In....
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exec('~/rasp30/prog_assembly/libs/scilab_code/read_tar_pgm_result.sce',-1); time_scale=1e-2; //1e-5; // Time unit : 10us m_graph=3; kapa_constant_or_not=1; vdd=2.5; //cd("/home/ubuntu/RASP_Workspace/data_for_calibration_paper/data_char_Scurve_chip16"); cd("/home/ubuntu/RASP_Workspace/data_for_calibration_paper/data_ch...
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//To Find The Probability on the reliability of transformers //Page 614 clc; clear; //Reliabilities of The Three Transformers Pa=0.9; Pb=0.95; Pc=0.99; //Faliures of Three Transformers Qa=1-Pa; Qb=1-Pb; Qc=1-Pc; //Probability of NO Transformer Failing Pnf=Pa*Pb*Pc; PfA=Qa*Pb*Pc//Probability of Tra...
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clc; clear; function z=f(x,y) z=x*y*y endfunction p1=[2 2]; elevation=f(p1(1),p1(2)); dfx=p1(1)*p1(1); dfy=2*p1(1)*p1(2); theta=atan(dfy/dfx); slope=(dfx^2 + dfy^2)^0.5; disp(elevation,"Elevation:") disp(theta,"Theta:") disp(slope,"slope:")
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//Page Number: 5.31 //Example 5.14 clc; //Given, Rb=36000; // (b/s) fM=3200; //Hz fs=2*fM; n=Rb/fs; //As n should be less than Rs/fs nn=round(n)-1; disp(nn,'Binary digits'); L=2^nn; disp(L,'Quantizing level'); fs=Rb/nn; disp('Hz',fs,'Sampling Rate');
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//Problem 2.05: //initializing the variables: sgm = 0.92; dw = 62.4; // in lb/ft3 //calculation: dm = sgm*dw printf("\n\nResult\n\n") printf("\n the density of methanol is %.1f lb/ft3\n",dm)
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pgm13.sci
function [y] = pgm13(x) // y = x-cos(x); y = 2 - x + log(x); endfunction
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clc; g=32; //gravitational constant in ft/sec square w=160; //weight in lb m=w/g //calculating mass in slugs. disp(m,"Mass in slugs = "); //displaying result
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clc; close; clear; p1=string('(a+b+1)^2=a^2+b^2+1+2ab+2a+2b') p2=string('(x-y+z)^2=x^2+y^2+z^2-2xy+2xz-2yz') p3=string('(a-b-c)^2=a^2+b^2+c^2-2ab-2ac+2bc') p4=string('(x+y-5)^2=x^2+y^2+25-10x-10y+2xy')
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clc; clear all; h = 6.62*1e-34; // Plancl's constant in J.s c = 3*1e8; // Velocity of light in vacccum in m/s m = 9.1*1e-31; // Mass of electron in Kg lambda = 0.7078*1e-10 // Wavelength in meter theta = 90; delta = (h*(1-cosd(theta))/(m*c)); Nlambda = lambda + delta; disp('meter',Nlambda,'The wavelength of s...
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atmosphere_model.tst
//<-- NO CHECK REF --> exec('models/atmos_constants.sci'); isa_ref_csv = read_csv('tests/isa_atm_sample.csv'); nlin = size(isa_ref_csv)(1); for i = 2:nlin h_ref = strtod(isa_ref_csv(i,1)); T_ref = strtod(isa_ref_csv(i,3)); rho_ref = strtod(isa_ref_csv(i,5)); p_ref = strtod(isa_ref_csv(i,6)); importX...