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// scilab Code Exa 18.22 Isentropic or Stage Terminal Velocity for Turbines T01=1273; // in Kelvin funcprot(0); p01=5; // Initial Pressure in bar p02=3.5; // exit gas Pressure in bar cp=1.005; // Specific Heat at Constant Pressure in kJ/(kgK) gamma=1.4; // Specific Heat Ratio m=28; // mass flow rate of the...
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// Error Check c = [-1,-1/3]'; A = [1,1;1,1/4;1,-1;-1/4,-1;-1,-1;-1,1]; b = [2,1,2,1,-1,2]; Aeq = [1,1/4]; beq = [1/2]; x = cbcintlinprog(c, [],A, b, Aeq, Aeq) // !--error 6 //Inconsistent row/column dimensions. //at line 208 of function cbcmatrixintlinprog called by : //at line 186 of function cbcintlinpr...
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//=========================================================// // DEMO_MODE // //=========================================================// fegui(); //---------------------------------------------------------// // 1. Geometry declaration with femesh /...
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clc //initialisation of variables T=373//k L=537000*4.2//J dp=0.0212*13600*9.81 dv=1.673//m^3 //CALCULATIONS dT=dp*T*dv/L //results printf(' \n change in temperature of boiling water= % 1f c',dT)
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clc; clear; G=41;//Mass P=110;//Total loss S=0.1;//Cooling surface area lamda=29;//Emissivity Cp=420;//Specific heat of the machine theta_m=P/(S*lamda); disp(theta_m,'Final steady temperature rise:') Tow=(G*Cp)/(S*lamda); disp(Tow,'Time constant is:') t=[1:0.01:8]; T=((-t)/(Tow/3600)); theta=38*(1-exp(T));...
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function x = VelocityMatching(birds, velocities) [a,b] = size(velocities); Nears = Nearest(birds); x = zeros(a,b); for i=1:b x(1,i) = velocities(1,Nears(i)); x(2,i) = velocities(2,Nears(i)); x(3,i) = velocities(3,Nears(i)); end endfunction
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GOOGLE CLOUD VISION API "vision_labels": [ "clothing", "jacket", "leather", "outerwear", "leather jacket", "textile", "blazer", "material", "formal wear", "collar" ] } GOOGLE CLOUD NLP API "sentiment": { ...
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// Scilab code Ex7.12: Pg:307 (2008) clc;clear; c = 3e+08; // Velocity of light, m/s delta_m =0.1/100*1; // Mass lost in one kg of substance, kg delta_E = delta_m*c^2; // Energy liberated by the fission of one kg of substance, joule // Since 1kWh = 1000 watt*3600 sec = 3.6e+06 joule delta_E = delta_m*c^2...
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clear; clc; // Stoichiometry // Chapter 5 // Energy Balances // Example 5.24 // Page 256 printf("Example 5.24, Page 256 \n \n"); // solution // fi1 = integr (from 304.15 to 313.15) {11831.6+24997.4*10T^-3-5979.8*10^-6T^2-31.7*10^-9T3}dt fi1 = 170787.7 // kJ/h fi2 = 535.4*12086 - [344.36*8743.2+168....
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exec('idpoli.sci',-1) exec('typecheck.sci',-1) //define output-error model B = [0.6,-0.2]; F1 = [1 -0.5]; ioDelay = 2; Ts = 0.1; mod_oe = idpoli(1,B,1,1,F1,ioDelay,Ts) // define box-jenkins model B1 = [0.6,-0.2]; C = [1,-0.3]; D = [1,1.5,0.7]; F2 = [1,-0.5] ioDelay = 1; mod_bj = idpoli(1,B1,C,D,...
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function [g1]=arc_graph(g) // Copyright INRIA [lhs,rhs]=argn(0) if rhs<>1 then error(39), end // check g if g('directed')<>1 then error('The graph must be directed') end ma=prod(size(g('tail'))); ta=g('tail');he=g('head'); ta1=[];he1=[]; for i=1:ma, ist=ta(i);iar=he(i); ij=find(ta==iar); ka=i*ones(ij); ta1=[t...
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//example 5.13 clear; clc; //Given: T=300;//temperature[K] n=4;//no. of moles of an ideal gas P1=2.02*10^5;//initial pressure[N/m2] P2=4.04*10^5;//final pressure[N/m2] R=8.314;//Universal gas constant[J/K/mol] //To find the value of Gibb's free energy G=n*R*T*log(P2/P1);//[J] printf(" The change in Gib...
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//Example 7.33 // DC servo system redesign with modified with dominant second // order pole locations. xdel(winsid())//close all graphics Windows clear; clc; //------------------------------------------------------------------ // State space representation //Transfer function model for DC Servo s=poly(0,'s'); num=10;...
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border.left: 14 border.top: 12 border.bottom: 14 border.right: 15 source: search_background.png horizontalTileRule: Repeat verticalTileRule: Repeat
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A=[-6,3;3,-10.5] //Matrix of I1,I2 Coeffecients by Mesh analysis B=[-12.5;0]; [I]=inv(A)*B; disp("Amperes",I(1,1),"Current in 1 Ohm resistor");
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//pagenumber 109 example 14 clear voltag=40;//volt i1=0.2;//ampere c1=40*10^-6;//farad c2=c1; induct=2;//henry //(1) ripple vdc=2*sqrt(2)*voltag/3.14; r1=vdc/i1; induc1=r1/1130; v1=voltag/(3*3.14^3*120^2*4*induct*c1); disp("ripple voltage = "+string((v1))+"volt"); //(2) with two filter v1=4*voltag/((3...
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// Copyright (C) 2016 - Corporation - Author // // About your license if you have any // // Date of creation: 26 oct. 2016 // //// Copyright (C) 2016 - Corporation - Author //// //// About your license if you have any //// //// Date of creation: 10 oct. 2016 //// Anntenne SMA //chdir('D:\Golf\portaudio_0.2\portaudio_0...
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// SAMPLE PROBLEM 6/9 clc;funcprot(0); // Given data F=100;// N m=40;// kg k=0.150;// m theta=15;// degree r_i=0.100;// m r_o=0.200;// m l=3;// The distance in m g=9.81;// The acceleration due to gravity in m/s^2 // Calculation W=m*g;// N l=(r_o+r_i)/r_i;// m U_12=(F*((r_o+r_i)/r_i)*l)-((W*sind(theta)*l...
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//determine dia of the shaft clc //solution //given P=20000//W N=200//rpm W=900//N L=2500//mm t=42//N/mm^2 fb=56//N/mm^2 T=P*60000/(2*%pi*200)//N-mm M=W*L/4//N-mm//max monet Te=sqrt(T^2 + M^2)//N-mm //Te=(%pi/16)*t*d^3 d1=(Te/8.25)^(1/3)//mm printf("the dia of shaft is,%f mm",d1) Me=0.5[M + sqrt(M^2 + T...
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clc; clear; clf(); function yp=vanderpol1(t,y) yp=[y(2);1000*(1-y(1)^2)*y(2)-y(1)] endfunction t=0:3000; yo=[1 1]; sol=ode(y0,0,t,vanderpol1); count=1; for i=1:2:6001 z(count)=sol(i)*-1; count=count+1; end plot(t,z) xtitle("y vs t","t","y")
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// Scilab Code Ex2.31:: Page-2.22 (2009) clc; clear; mu1 = 1.55; // Refractive index of mica mu2 = 1.52; // Refractive index of glass t = 0.75e-003; // Thickness of the sheets, m d = 0.25e-02; // Separation between the slits, m lambda = 5896e-010; // Wavelength of light used, m D = 1.5; // Distance...
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// Exa 5.8.1 clc; clear; close; // Given data V_EE = 8;// in V V_BE = 0.7;// in V R_E = 1.5;// in k ohm I_E = (V_EE - V_BE)/R_E;// in mA I_C = I_E;// in mA disp(I_C,"The value of I_C in mA is"); V_CC = 18;// in V R_C = 1.2;// in kΩ V_CB = V_CC - (I_C * R_C);// in V disp(V_CB,"The value of V_CB in V is"); ...
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//draw function machine for n^2+5 clear; clc; close; mprintf("the first five terms of the sequence are: \n"); for n=1:5 disp(n^2+5) end
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clc //initialisation of variables T1= 40 //degrees T2= 30 //degrees //CALCULATIONS d1= (T1-T2)*(9/5) d2= d1 //RESULTS printf ('T= %.2f F',d1) printf (' \n T= %.2f R',d2)
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clc //initialisation of variables dH= -687.982 //kcal HCO2= -94.0518 //kcal HH2O= -68.3174 //kcal //CALCULATIONS H= -dH+4*HCO2+5*HH2O //RESULTSn printf ('Enthalpy of formation of n butane= %.3f kcal mole^-1',H)
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ESTIMATED COVARIANCE MATRIX FOR PARAMETER ESTIMATES 1 2 3 4 5 ________ ________ ________ ________ ________ 1 0.359255D+00 2 -0.334497D-01 0.374420D-01 3 -0.293948D-02 0.11846...
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//Given that K = 35*10^3 //in ev e = 1.6*10^-19 //in coulomb h = 6.62*10^-34 //in J-s c = 3*10^8 //in m/s //Sample Problem 41-4 printf("**Sample Problem 41-4**\n") lambdaMin = h*c/(K*e) printf("The cutoff wavelength is %em", lambdaMin)
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//Calculate the charging current clear; clc; //soltion //given C1=14*10^-6;//farad C2=8*10^-6;//farad Ce=C1/3; Cc=(C2-Ce)/2; Vph=66*10^3/sqrt(3); f=50;//Hz Cn=Ce+3*Cc; Ic=2*%pi*f*Vph*Cn; printf("Charging current= %.2f A",Ic); //In book it is 115.82 A due to some printing mistake
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clear; clc; close; Vcc = 20; Vb = 4; Ve = 3.3; Ic = 0; disp('Drop across transistor is : '); disp('This suggests that transistor is in on state.',Vb-Ve); disp('Ic is : ') disp('This suggest 2 things.',Ic) disp('Either there is poor connection between Rc & terminal'); disp('or the transistor has an open base...
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//1.1 clc; Ic=8*10^-3; //let dv/dt =A A=190*10^6; C=Ic/A*10^12; printf("Equivalent capacitance of depletion layer = %.1f uF", C)
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// calculate voltage gain of ac amplifier // Electronic Principles // By Albert Malvino , David Bates // Seventh Edition // The McGraw-Hill Companies // Example 16-1, page 567 clear; clc; close; // Given data f1=20;// cutoff frequency in hertz f2=20*10^3;// cutoff frequency in hertz fin1=5;// input freque...
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// Example 3.17 clear all; clc; // Given data E_max = 1.39; // Maximum energy of beta rays in MeV // Calculation R_max = 0.412*E_max^(1.265-(0.0954*log(E_max))); // Result printf('\n Maximum distance of beta rays traversed = %4.3f cm \n',R_max);
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 18.13w //calculation angle of minimum deviation for equilateral prism of silicate flint glass from known vlue of wavelength //given data A=60; //angle of prism(in degree) mu1=1.66; //refractive index of silicate flin...
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//caption:stability_using_Nyquist_criterion //example 11_25 //page 497 clf(); s=%s; s1=-s; g=(2.2/(s*(s+1)*(s^2+2*s+2))) g1=(2.2/(s1*(s1+1)*(s1^2+2*s1+2))) GH=syslin('c',g); GH1=syslin('c',g1); nyquist(GH); nyquist(GH1); mtlb_axis([-2.5 0.2 -75 75]); disp("as the nyquist plot passes through the point -1+%i*0, so system...
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Name=Fortnite Flyers Infantry PlayerCharacters=FortniteMain BotCharacters=fnflyerbot.bot IsChallenge=true Timelimit=60.0 PlayerProfile=FortniteMain AddedBots=fnflyerbot.bot;fnflyerbot.bot PlayerMaxLives=0 BotMaxLives=0;0 PlayerTeam=1 BotTeams=2;2 MapName=boxerflyer.map MapScale=4.2 BlockProjectilePredictor...
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clc clear disp('example 14.19') zaa=3;zbb=9 //impedence given between line pas=1 //power at two units are equal to 1p.u par=1 pbs=1.05 //power at sending end is 1.05 and power at receiving end is 1p.u pbr=1 i=1 //assume current is 1p.u los=i*complex(zaa/100,zbb/100) csd=((abs(los)^2)-pas^2-par^2)/(2...
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clc clear IP=30; N=2500; Pm=800; Em=0.8; LD=1.5; Ebth=0.28; CV=44000; BP=IP*Em; printf('Brake Power= %3.2f kW',BP); printf('\n'); Mf=(BP/(Ebth*CV)); printf('Mass Flow Rate= %3.2f kg/hr',Mf*3600); printf('\n');
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//example-19.19 //page no-586 //given //wavelength of the edge of the absorption edge of a semiconductor material is lambda=1771*10^-9 //m //plank's constant h=6.626*10^-34 //speed of light c=3*10^8 //m/s //band gap energy Eg=h*c/lambda //J //charge on electron e=1.602*10^-19 //C //energy in eV E=Eg/...
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// Scilab code Ex11.27: Pg.544 (2008) clc; clear; t_half = 5730; // Half life-time of C-14, y lamda = log(2)/t_half; // Decay constant, per y N_A = 6.02e+023; // Avagadros number, atoms/mole M = 12; // Molar mass of C-12, g N_C_12 = N_A/M // Number of C-12 nuclei r = 1.35e-12; // Ratio of C-14 ...
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// Scilab Code Ex3.5 : Page-72 (2010) lambda = 5893e-008; // Wavelength of monochromatic lihgt used, m n = 10; // Number of fringe that are found in the distnace of 1 cm d = 1; // Distance of 10 fringes, cm beta = d/n; // Fringe width, cm theta = lambda/(2*beta); // Angle of the wedge, rad printf("...
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mode(0) in2cm = 2.54; rad2deg = 180/%pi; // span b_leco_in = 33 + 5/8; // span at leading edge of chord, in b_teco_in = 33; // span at trailing edge o chord, in b_in = (b_leco_in + b_teco_in)/2; b_cm = b_in*in2cm; b_cm_2 = b_cm/2 // chord c_i_angled_in = 10; // inner chord, along wing angle, in c_o_angled_in = 5 + 6/...
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//ex16.1 R1=10*10^3; R2=R1; R=R1; C1=0.01*10^-6; C2=C1; C=C1; R3=1*10^3; r_ds=500; f_r=1/(2*%pi*R*C); disp(f_r,'resonant frequency of the Wein-bridge oscillator in Hertz') //closed loop gain A_v=3 to sustain oscillations A_v=3; //A_v=(R_f+R_i)+1 where R_i is composed of R3 and r_ds R_f=(A_v-1)*(R3+r_ds);...
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// Internal Voltage drop in an alternator clc; clear; If=10; Voc=900; // Open Circuit Voltage Isc=150; // Short Circuit Current Zs=Voc/Isc; I=60; // Load current Vd=I*Zs; // Internal Voltage Drop printf('The internal voltage drop with a load current of 60 A = %g V \n',Vd)
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function [screw_P] = screw_move(screw_O, PO) R = screw_getResultant(screw_O); M = screw_getMoment(screw_O); screw_P = screw_new( ... R, ... M + vect_crossProd(PO, R) ... ); endfunction
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// Procesamiento (Doneshot45) (20180327) clear //mclose('all') //path='/home/jul/git/jwist/nmr-dosy-scilab/gradient_calibration/' path='/run/media/jul/44B6-1E16/data/summer-school-test/' path2=path + '60/' n1=60 // Gradients values 80% max, ramp (5%-80%) 8-pts // Calibration H2O_doneshot_2d_laura (2018...
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// Chapter 1 //Ordinary power gain //page 15 //Example no 1-3 //Given clc; G1=23; //in dB G=10^(G1/10); printf("\n The ordinary power gain is %.4f \n",G); // Result Pin=10^-3; //in mW Pout=Pin*G; printf("\n The output power is %.4f mW \n",Pout); // Result
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function y=erf(x) //erf - The error function. //%Syntax // y = erf(x). //%Parameters // x : real vector // y : real vector (of same size) //%Description // erf computes the error function: // // /x // y = 2/sqrt(pi) *| exp(-t^2) dt // /0 //%See also // erfc erfcx caler...
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//problem 2.16 clc; clear; close; //given data : format('v',6); Eff=0.8;//unitless Load=20;//in HP Load=Load*735.5;//in watts //IronLoss=K;//assumed //MechLoss=K/3; //RotorCuLoss=StatorCuLoss=IronLoss=K; //TotLoss=K+K+K+K/3=10*K/3;// Input=Load/Eff;//in watts TotLoss=Input-Load;//in watts K=TotLoss*3/10;...
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//Book Name:Fundamentals of Electrical Engineering //Author:Rajendra Prasad //Publisher: PHI Learning Private Limited //Edition:Third ,2014 //Ex10_7.sce clc; clear; Vl_not=400; //No load voltage in volt Vl_sc=50; //Blocked rotor voltage in volt I_not=20; //No load current in Ampere Isc=60; ...
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//Chemical Engineering Thermodynamics //Chapter 12 //Refrigeration //Example 12.3 clear; clc; //Given //Consider the figure 12.4 (page no 226) m = 5;//tonnes of refrigeration T1 = 273-10;//temperature of the saturated vapour in K T2 = 273+35;//temperature of the super heated vapour in K T3 = 273+25;//te...
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//example 11.1(c)// clc //clears the screen// clear //clears all existing variables// a=4+4+1+1; //given no of inputs// o=4+1; //given no of outputs// s=2^a*o; //size of prom// disp(s,'size of PROM =')
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clc disp("Example 5.56") printf("\n") disp("calculate the frequency of oscillation,feedback factor & gain required for sustained oscillation") printf("Given\n") //Capacitance C1=40*10^-12 C2=10*10^-12 //inductance L=3*10^-3 //total effective capacitance C=C1*C2/(C1+C2) //frequency of oscillation f=1/(2*%pi...
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//Problem 18.11: In the differential amplifier shown in Figure 18.16, R1 = 10 kohm, R2 = 10 kohm, R3 = 100 kohm and Rf = 100 kohm. Determine the output voltage Vo if: //(a) V1 = 5 mV and V2 = 0 //(b) V1 = 0 and V2 = 5mV //(c) V1 = 50 mV and V2 = 25mV //(d) V1 = 25 mV and V2 = 50mV //initializing the vari...
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//Calculate the Most probable speed ,Mean speed and Root mean square speed for Oxygen molecule //Example 3.1 clc; clear; R=8.314; //Gas constant in J K^-1 mol^-1 T=300; //Temperature in kelvin mew=0.03200; //Molar mass of Oxygen kg mol^-1 Cmp=sqrt((2*R*T)/(mew))//Most probable speed in m s^-1 ...
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main array[3][3][3] a, b; var i, j, k; { let i <- 0; while i < 3 do let j <- 0; while j < 3 do let k <- 0; while k < 3 do let a[i][j][k] <- i + 2 * j + i * k; let k <- k + 1 od; let j <- j + 1 od; let i <- i + 1 od; let i <- 0; while i < 3 do let ...
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printf('This is a spontaneous process.Since dS is independent of the manner in which the processes are conducted,\nthe above irreversible process can be considered to take place reversibly.') T1=300;//initial temperature in kelvin// T2=370;//final temperature in kelvin// Cv=18;//molar heat capacity in cal per deg// ...
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clear //Given a=200 b=50 c=17 d=5 e=4000 //Calculation Ib=(a-b)*10**-3 Ic=c-d B=Ic/Ib D=e/B Ap=B**2*D //Result printf("\n The value of power gain is %0.3f *10**5",Ap*10**-5)
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function [g1]=split_edge(i,j,g,name) [lhs,rhs]=argn(0) // check name if rhs==3 then name=0 else if rhs<>4 then error(39), end if type(name)<>10|prod(size(name))<>1 then error('Fourth argument must be a string') end end // split the edge from node i to node j by // adding a new node between i and j ta=g('t...
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Ex8_11.sce
errcatch(-1,"stop");mode(2);//Example 8_11 ; ; //To calculate the capacitance v=10^6 //units in Hz L=1 //units in henry C=1/(4*%pi^2*v^2*L) C=C*10^12 //units in PF printf("Capacitance C=%.3f PF",C) exit();
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ex10_16.sce
// Exa 10.16 clc; clear; close; format('v',6) // Given data P_L = 20;// in kW P_L = P_L * 10^3;// in W V = 200;// in V Ra = 0.05;// in ohm Rsh = 200;// in ohm // P_L = V*I_L; I_L = P_L/V;// in A Ish = V/Rsh;// in A Ia = I_L+Ish;// in A Eg = V + (Ia*Ra);// in V Pa = Eg*Ia;// in W Pa = Pa * 10^-3;// in k...
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ex2_3.sce
w=942; //Assigning values to parameters Vm=10; V=6; t=asin(V/Vm)/w; f=w/(2*%pi); T=1/f; t2=t+T; disp("Seconds",t2,"Time taken to reach 6V second time");
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Geometric-Mean-Filter.sce
clc;clear; a=imread('gtw.jpg'); d=double(a); me=d(:,:,1); hi=d(:,:,2); bi=d(:,:,3); m=3; n=3; cme=log(me); chi=log(hi); cbi=log(bi); Fme=imfilter(cme,ones(m,n), 'replicate'); Fhi=imfilter(chi,ones(m,n), 'replicate'); Fbi=imfilter(cbi,ones(m,n), 'replicate'); fme=exp(Fme).^(1/m/m); fhi=exp(Fhi).^(1/m/m); fbi=exp(Fbi).^(...
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char_diodeADC.sce
// Shift 2, 20th Jan //vchar id i2vout adc diode_ivdd25V=[ // 2.10 0.005e-9 0.688 hex2dec('0969'); 2.15 0.152e-9 0.985 hex2dec('0bea'); 2.18 1.573e-9 1.072 hex2dec('0de4'); 2.20 2.723e-9 1.105 hex2dec('14b1'); 2.25 11.83e-9 1.204 hex2dec('157e'); 2.30 13.41e-9 1.338 hex2dec('1760'); 2.35 62.54e-9 1.404 hex2dec('1...
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ex5_15.sce
// Exa 5.15 clc; clear; close; // Given data R = 15;// in k ohm R = R *10^3;// in ohm C = 0.01;// in µF C = C * 10^-6;// in F f_c = 1/(2*%pi*R*C);// in Hz f_c= round(f_c); disp(f_c,"Cut off frequency in Hz is"); Omega_c = 2*%pi*f_c;// in rad/sec disp(Omega_c*10^-3,"The value of omega_c in k rad/sec is"); ...
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ch8_18.sce
clear; clc; f=5000; w=2*%pi*f; R=3; L=60*10^-6; xie=R/(2*L); C=7.5*10^-6; w_o=1/sqrt(L*C); w_r=sqrt(w_o^2-xie^2); t1=%pi/(2*w_r); V_s=220; V_co=80; I_omx=(V_s+V_co)*exp(-xie*t1)/(w_r*L); I_rms=I_omx/sqrt(2); P=I_rms^2*R; printf("load power=%.2f W",P); printf("\nrms value of thyristor current=%.3f A",...
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Ex3_10.sce
// // //(a) magneticbearing=175+(30/60) magneticdeclination=180-magneticbearing deg=int(magneticdeclination) mins=(magneticdeclination-deg)*60 printf("\n %0.3f degrees %0.3f minutes W",deg,mins) //(b) magneticdeclination=5+(45/60) deg=int(magneticdeclination) mins=(magneticdeclination-deg)*60 printf("\n %0.3f degree...
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Ex3_8.sce
//Example 3_8 page no:125 clc Rs=25//resistance in ohm Rl=Rs//according to maximum power transfet theorem I=50/(Rl+Rs) P=I^2*Rl disp(P,"the maximum power delivered to the load is (in watts)")
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TECI.prev.tst
Expanding for base=6, level=2, reasons+features=base,same,similiar Refined variables=c,r [0+1c,0+1r]: unknown -> [1] [0,0] -3c-12c²-16c³+5r+27r² -> solution [0,0],trivial(3) ---------------- level 0 expanding queue[0]^-1,meter=[6,6]: -3c-12c²-16c³+5r+27r² [0+6c,0+6r]: same -18c-432c²-3456c³+30r+972r² map {c=>c/6,r=>r/...
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ex9_13.sce
//Page Number: 9.20 //Example 9.13 clc; //Given Mf1=0.003; //for f<=1.5D+3 Hz f1=1.5D+3; //Hz Mf2=0.001; //for 1.5D+3 <=f<=3D+3 Hz f2=3D+3; //Hz Mf3=0; //for f>3D+3 Hz //(a) Ac that power transmitted is 100mW St=100D-3; //W //As St=2*[{f1*(Mf1*Ac/2)^2}+{f1*(Mf2*Ac/2)^2}+{f2*(Mf3*Ac/2)^2}] //Negle...
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Ex1_9.sce
//CHAPTER 1- D.C. CIRCUIT ANALYSIS AND NETWORK THEOREMS //Example 9 clc; disp("CHAPTER 1"); disp("EXAMPLE 9"); //VARIABLE INITIALIZATION r1=1; //in Ohms r2=2; //in Ohms r3=3; //in Ohms r4=1; //in Ohms //SOLUTION ...
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20_09.sce
//Chapter 20, Problem 9 clc; P=5000; //power Vl=400; //line voltage Il=8.6; //line current pf=P/(sqrt(3)*Vl*Il); //power factor printf("Power factor = %.3f ",pf);
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Ex5_32.sce
//Example 5_32 clc; clear; close; format('v',6); //given data : Vz=5;//V Pmax=250;//mW Vs=15;//V(Supply voltage) PL=50;//W(Load) Imax=Pmax/Vz;//mA(Maximum permissible current) //Minimum current to maintain constant voltage Imin=Imax-Imax*10/100;//mA Rmin=Vs/Imax;//kohm Rmax=Vs/Imin;//kohm disp("For main...
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ex14_1.sce
clear; //clc(); // Example 14.1 // Page: 379 printf("Example-14.1 Page no.-379\n\n"); //***Data***// T = 300;//[K] Temperature of the natural gas well R = 8.314;//[J/(mol*K)] universal gas constant z_1 = 0;//[m] // At the surface of the well mole fraction of the components are y_methane_surf = 85/100;//[...
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9_22w.sce
//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 9.22w //calculation of the loss of kinetic energy due to the collision //given data m=1.2//mass(in kg) of the block1 v=20*10^-2//velocity(in m/s) of the approach e=3/5//value of coefficient of restitution vdash=e*v/...
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Ex5_10.sce
// Exa 5.10 clc; clear; // Given Va = 2000; // voltage applied to anodes(V) l = 50*10^-3; // length of horizontal plates(m) m = 9.1*10^-31; // mass of electron in kg e = 1.6*10^-19; // velocity of electron in m/s // Max transit time is T/4 // Solution V = sqrt(2*Va*e/m); Fc = V/(4*l); printf(' Th...
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Ex1_4.sce
clc// // // //Variable declaration A=1.748; //madelung constant n=9; //born repulsive exponent e=1.602*10^-19; //charge of electron(c) epsilon0=8.85*10^-12; //permittivity(C/Nm) r0=0.281*10^-9; //seperation(m) IE=5.14; //ionisation energy of A(kJ/mol) EA=3.61; //electron affinity f...
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2016-09-27T05:12:48
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lsf2poly1.sce
//check o/p when i/p is a row 1*5 matrix containing line spectral frequency values lsf = [0.7842 1.5605 1.8776 1.8984 2.3593]; a = lsf2poly(lsf) disp(a); //output //1. 0.6148378 0.9898850 0.0000932 0.0031371 - 0.0081200
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ex2_32.sce
//chapter 2 //part a printf("\n"); c=3*10^8; frequency=20*10^9; lamda=c/frequency; printf("the wavelength is %gm",lamda); //part b //Ae=G*(lamda)^2/4*pi r=0.61; Aep=(%pi)*r^2; printf("\nthe effective physical aperture is %gm^2",Aep); Ae=0.55*Aep; Ga=(Ae*4*(%pi))/(lamda)^2; Gdb=10*log10(Ga); printf("\nthe...
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//Example 8.44 clc disp("Johnson counter is basically a twisted ring counter. The fig.8.104(a) shows the basic circuit for a Johnson counter. The table shows the states of a 4-bit Johnson counter.") disp("") disp("States of 4-bit Johnson counter") disp("State name Q3 Q2 Q1 Q0") disp(" S1 0 0 0...
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clear; clc; //Example - 8.2 //Page number - 288 printf("Example - 8.2 and Page number - 288\n\n"); //Given T_max = 700+273.15;//[K] - Maximum temperature. P_boiler = 10*10^(6);//[Pa] - Constant pressure in the boiler P_condenser = 10*10^(3);//[Pa] - Constant pressure in the condenser //At state 2 i.e, at...
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global file_name; //get filename, path and extension [path,fname,extension] = fileparts(file_name); hid_dir = path + '.' + fname; exec("~/rasp30/prog_assembly/libs/scilab_code/characterization/char_diodeADC.sce",-1); target_list_info=fscanfMat(hid_dir+'/target_list') n_target_tunnel_revtun=target_list_info(1,1); n_ta...
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// Scilab code Ex1.12: Pg:37 (2008) clc;clear; Lambda = 1e-010; // Wavelength of X-rays, cm c = 3e+08; // Velocity of light, m/s m = 9.13e-031; // Mass of an electron, kg h = 6.62e-034; // Planck's constant, joule-sec e = 1.6e-019; // Charge of electron, coulomb f = c/Lambda; // Frequency of X...
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//Example 11.7.d // angle of phase differnce clc; clear; close; R=40;//in ohms L=0.07;//IN HENRY V=223;//IN VOLTS F=50;// IN HERTS Xl=2*%pi*F*L;// inductive reactance in ohms Z=sqrt(R^2+Xl^2);//IMPEDENCE IN OHMS I=V/Z;//in amperes csp=R/Z;//pf phi=acosd(csp);//angle of phase differnce in degree x=floor(phi);// y=phi-x...
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clc(); clear; //Given: //(a) Marble h = 6.625*10^-34; //planck's constant in Js m1 = 10; // mass in g L1 = 10; // width in cm // m1 = 10*10^-3 kg , 1 g = 1.0*10^-3 kg and L1 = 10*10^-2 m , 1 cm = 1.0*10^-2 m printf("(a)Marble \n\n"); for n1 = 1:3 En1 = (n1^2*h^2)/(8*m1*10^-3*(L1*10^-2)^2); // Energry in...
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//ex14.7 V_in=0; I_B_max=100*10^-9; //maximum bias current I_os_max=40*10^-9; //maximum offset current magnitude V_os_max=2*10^-3; //maximum offset voltage R_1=10*10^3; R_2=100*10^3; //we approach in such a way to calculate output voltage due to each of dc sources and using superposition //1)OFFS...
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errcatch(-1,"stop");mode(2);//Example 1.20.1: Turn Off Time ; ; //given data : format('v',6) Vs=200;//in volts R1=10;// in ohm R2=R1; C=5;// in micro-farad Tc=(R1*C)/1.44; disp(Tc,"The Circuit Turn Off Time,Tc(micro-sec) = ") exit();
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// Example 4.8:refrative index clc; clear; close; alpha=0.46;//attenuation in Db/Km L=1;// dISTANCE IN kM h=1;//in micro meter Tf=758;//Temperature in kelvin p=0.245;//photoelastic coefficient of silica Bc=8.4*10^-11;//isothermal compersebility in in Metere square per N K=1.38*10^-23;// bOLTZMAN CONSTT. IN JU...
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function M=%s_1_hm(s,M) // Copyright INRIA //s<M if size(s,'*')<> 1 then error('< : arguments have incompatible dimensions') end M('entries')=s<M('entries')
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// Exa 3.2 clc; clear; close; format('v',7) // Given data Im = 141.4;// in A t = 3;// in ms t = t * 10^-3;// in sec disp(Im,"The maximum value of current in A is"); omega = 314;// in rad/sec // omega = 2*%pi*f; f = round(omega/(2*%pi));// in Hz disp(f,"The frequency in Hz is"); T = 1/f;// in sec disp(T,"...
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// POWER CIRCUIT 1 ASSIGNMENT D = 12/380; // Duty Cycle RL = 5; // Load Resistance L = 12.12e-06; // Inductor C = 19.5e-06; // Capacitor fs = 400e03; // Switching Frequency
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// 09.09.10 function Setcounter(varargin) global GCOUNTER; Nargs=length(varargin); if Nargs==0 N=1; else N=varargin(1); end; GCOUNTER=N; endfunction;
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// Author: Michelle Sagnelli D'urzo // Create an augmented matrix using two given matrices. AUGM = [A B] X = AUGM VARIABLES = [] ERRORS = [] // Display the complete matrix disp("Augmented Matrix") disp(X) // Applying Gauss-Jordan X = rref(X); // Display Gauss-Jordan matrix disp(X) // Adding varia...
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clear; clc; Zc=400 ef=20 z1=150; z2=200 z=round((z1*z2/(z1+z2))*100)/100 et=2*ef*z/(Zc+z) mprintf("\nSurge Voltage Transmitted= %.4f kV",et) it1=et*1000/z1; mprintf("\nSurge Current Transmitted in line 1= %.3f A",it1) it2=et*1000/z2; mprintf("\nSurge Current Transmitted in line 2= %.2f A",it2) er...
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n = 1000; x = rand(2,n); v = 3*%pi/2*(0.1 + 2*x(1,:)); X = zeros(3,n); X(2,:) = 20*x(2,:); X(1,:) = -cos(v).*v; X(3,:) = sin(v).*v; ms = 50; lw = 1.5; v1 = -15; v2 = 20; clf; scatter3(X(1,:),X(2,:),X(3,:), ms, v, 'filled'); view(v1,v2);axis('equal');axis('off');
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//======================================================================= //chapter 1 example 14 clc; clear; //input data lamda = 1.4*10^-10; //wavelength in angstroms a = 2*10^-10; //lattice parameter in angstroms h = 1; //miller indices ...
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SET SERVEROUTPUT ON FORMAT WRAPPED CREATE OR REPLACE PROCEDURE assoc_array_index_test ( iterations_in IN PLS_INTEGER DEFAULT 10000 , length_in IN PLS_INTEGER DEFAULT 100 ) IS TYPE tab_bynum_tabtype IS TABLE OF employees%ROWTYPE INDEX BY PLS_INTEGER; TYPE tab_byvc_tabtype IS TABLE OF employ...
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clear; xdel(winsid()); t=linspace (0,1E-2,1E4); p=poly(0,'p'); K=0.47; Taum=0.034; Taue=0.0005; M3=syslin('c',K/(1+Taum*p)); m3=csim('step',t,M3); M2=syslin('c',K/((1+Taum*p)*(1+Taue*p))); m2=csim('step',t,M2); M1=syslin('c',K/(1+Taum*p+Taum*Taue*p*p)); m1=csim('step',t,M1); C=syslin('c',(1+Taum*p)/(Ta...
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// Caption: Finding terminal voltage clear; close; clc; V=274;//voltage when Ia=0 E_a=274*1150/1200;//actual emf V_t=E_a-405*(0.025+0.005);//terminal voltage