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errcatch(-1,"stop");mode(2);//Caption:Find the efficiency of the motor //Exa:9.3 ; ; //Refer to data of Exa:9.2 R_1=0.5;//in ohms R_2=0.25;//in ohms X_1=0.75;//in ohms X_2=0.5;//in ohms R_c=500;//in ohms s=0.025;//slip I_c=132.791/500;//Core-loss currrent (in Amperes) I_m=-%i*132.791/100;//Magnetization c...
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//Example 5.23 clc; clear; close; format('v',6); //Given data : D1=300/1000;//meter D2=150/1000;//meter Q=50/1000;//m^3/sec A1=%pi/4*D1^2;//m^2 A2=%pi/4*D2^2;//m^2 delpBYw=3;//p1/w-p2/w=3;//m v1BYv2=A2/A1; Z1=0;//meter Z2=0;//meter g=9.81;//gravity constant //HeadLoss=1/8*v^2/2/g //Z1+p1/w+v1^2/2/g=Z2+...
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clc p_atm=101.3*10^3; // N/m^2 rho=1000; // kg/m^3 g=9.81; // m/s^2 H1=3; //m a=0.073; // N/m r1=5*10^(-4); //m p1=p_atm+rho*g*H1+2*a/r1; // p2=p_atm+rho*g*H2+2*a/r2; // p1*4/3*%pi*r1^3=p2*4/3*%pi*r2^3 // Solving above two equations we get r2=0.053; //mm disp("Radius of the bubble =") disp(r2) dis...
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//Chapter 10:Traction Drives //Example 2 clc; //Variable Initialization M=100 //mass of each motor armature in tonne Me=100 Tm=5000 //torque of each motor in N-m Da=0.5 //average diameter of each motor in m m=450 //mass of each wheel in kg R=0.54 //radius of each wheel tread in m N=4 ...
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// Example 3.4, page no-164 clear clc L=20 W=2000 db=0.02 Wb=100 dG=0.5 S=L/(2*W*db+Wb*dG) printf("S = %.3f rad/g",S) fi=0.2 DeltaW=fi*3.14/(180*S) printf("\nDeltaW = %.3f g",DeltaW)
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//Find the Four Fundamental Subspaces of a Matrix A disp('Please enter the matrix A'); //Taking input of Matrix A a11=input("Enter a11: "); a12=input("Enter a12: "); a13=input("Enter a13: "); a21=input("Enter a21: "); a22=input("Enter a22: "); a23=input("Enter a23: "); a31=input("Enter a31: "); a32=input("Enter a32: ")...
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// pidgui.sce // Graphical User Interface for PID controller // Dew Toochinda, August 2014 funcprot(0); xdel(winsid()); global kp ki kd setPoint stepValue; global eb_kp sl_kp eb_ki sl_ki eb_kd sl_kd ; global eb_stepValue sl_stepValue eb_setPoint sl_setPoint; global NumGc DenGc; global z TimeValue; global eb...
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function [raiz, i]=bissecao(funcao, xl, xu, es) // Cálculo das raizes pelo processo da bisseção // function [raiz,iter]=bissecao(funcao, xl, xu, es) // onde raiz é a raiz procurada de funcao // i é o num de iterações para o erro especificado // funcao é a função de entrada literal em x // ...
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clc //Chapter7 //Example7.5, page no 283 //Given Fif=15// Noise figure of IF amplifier Ap1=10// Gain of Preamplifier Fpa=6//Noise figure of preamplifier F2=10^(Fif/10) F1=10^(Fpa/10) F=F1+((F2-1)/Ap1)//overall noise figure mprintf('The overall noise figure is: %f',F)
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//Example 3.13 //Program to determine fiber birefringence for given beat lengths //(1)Lb = 0.7 mm //(2)Lb = 80 m clear; clc ; close ; //Given data lambda=1.3*10^(-6); //metre - OPERATING WAVELENGTH //Part (1) Lb1=0.7*10^(-3); //metre - BEAT LENGTH Bf1=lambda/Lb1; //Part (2) Lb2=80; ...
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-- Fuzzy Logix, LLC: Functional Testing Script for DB Lytix functions on Netezza -- -- Copyright (c): 2016 Fuzzy Logix, LLC -- -- NOTICE: All information contained herein is, and remains the property of Fuzzy Logix, LLC. -- The intellectual and technical concepts contained herein are proprietary to Fuzzy Logix, LLC. -...
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//example 2 //heat transfer in a given process clear clc u1=87.94 //specific internal energy of R-12 at state 1 in kJ/kg u2=276.44 //specific internal energy of R-12 at state 2 in kJ/kg s1=0.3357 //specific entropy at state 1 in kJ/kg-K s2=1.2108 //specific entropy at state 2 in kJ/kg-K V=0.001 //volume of sat...
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sexo = input("Digite o numero 1 para Homem e 2 para Mulher"); altura = input("Digite a altura"); if sexo==1 then peso= (72.2*altura)-58; printf(" O peso ideal para homens é : %g", peso); elseif sexo==2 then peso= (62.1*altura)-44.7; printf(" O peso ideal para mulheres é : %g", peso); else printf("Op...
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clc;funcprot(0);//EXAMPLE 20.11 // Initialisation of Variables v=30;.............//Suction volume in m^3/min p1=1;...........//Suction pressure in bar t1=300;.........//Suction temperature in K p2=16;...........//Delivery pressure in bar N=320;..........//Compressor rpm k=0.04;.........//Clearance ratio rld=1.2...
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cdir = pwd(); exec(cdir+'/utils.sce',-1); exec(cdir+'/dist_mat.sce',-1); exec(cdir+'/examples.sce',-1);
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// Scilab Code Ex7.1:: Page-7.7 (2009) clc; clear; n1 = 1.6; // Refractive index of core material of fibre n2 = 1.3; // Refractive index of cladding material of fibre phi_C = asind(n2/n1); // Critical angle of optical fibre, degrees theta_Q = asind(sqrt(n1^2-n2^2)); // Acceptance angle of optical f...
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//Chapter-11, Example 11.7, Page 491 //============================================================================= clc clear //INPUT DATA D=0.05;//Diameter of the tube in m L=2;//Length of the tube in m Ts=84;//Outer surface temperature in degree C Tsat=100;//Saturation temperature of water in degree C Tf=...
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clc //Initialization of variables P1=200 //psia P2=100 //psia T1=300+460 //R g=1.4 cp=0.24 //calculations T2=(T1)*(P2/P1)^((g-1)/g) V2=sqrt(2*32.2*778*cp*(T1-T2)) //results printf("Final velocity = %d ft/sec",V2)
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//chapter16 //example16.20 //page361 R1=3d3 // ohm R2=4.7d3 // ohm Rs=600 // ohm re_dash=20// ohm gain_beta=200 Rin_dash=R1*(R2*Rs/(R2+Rs))/(R1+(R2*Rs/(R2+Rs))) Zout=re_dash+Rin_dash/gain_beta printf("output impedence = %.1f ohm \n",Zout)
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clc //initialisation of variables kf= 1.86 dT= 0.402 //K T= 310 //K R= 0.08205 //cal/mol K //CALCULATIONS P= dT*T*R/kf //RESULTS printf (' osmotic pressure = %.2f atm',P)
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disp("A box contains 12 items of which three are defective") disp("A sample of three items is selected from the box") s=factorial(12)/(factorial(12-3)*factorial(3)); disp(s,'number of elements in the sample space where samples are of size 3') //X denotes the number of defective items in the sample x=[0,1,2,3]; ...
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//The Gerchgorin circle clc; clear; close(); format('v',9); x = [0:.1:14]; plot2d(0,0,-1,"031"," ",[0,-5,14,5]); plot(x,zeros(length(x),1)); A = [5 1 0;-1 3 1;-2 1 10]; disp(A,'A = '); for i=1:3 disp(A(i,i),'Centers are : '); radius = 0; for j=1:3 if j~=i then radius = radius + abs(A(i,j)...
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//(a)Quantisation effects sig=0.005; D=4; B=log2(D/(sig*sqrt(12)));//no.of samples //value of B to ensure quantisation error to 5mv //(b)Quantisation error and noise xn=0:0.2:2.0; xqn=[0 0 0.5 0.5 1 1 1 1.5 1.5 2 2]; en=xn-xqn;//quantization error //Quantisation signal top noise ratio x=0;e=0; for i=1:length...
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A=[ 52.00000, 11640, 1136, 11544, 904, 11576, 7928; 52.00000, 11640, 1032, 11632, 904, 11632, 1048; 52.00000, 11648, 1032, 11640, 888, 11632, 1040; 52.00000, 11648, 1056, 11640, 896, 11632, 1040; 52.00000, 11648, 1056, 11640, 896, 11632, 1032; 52.00000, 11648, 1016, 11640, 896, 11632, 1032; 52.00000, 11648, 1000, 11640...
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function [r]=%lssor(s1,s2) //%lssor(s1,s2) <=> s1==s2 r=%f
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errcatch(-1,"stop");mode(2);// Exa 3.19 format('v',5) ; ; // Given data t_d = 3;// total depletion in µm // The depletion width , D = t_d/9;// in µm disp(D,"Depletion width in µm is"); exit();
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//example2.19 clc disp("No load current = I_L0 = 4 A") s=250/250 disp(s,"I_sh[in A]=V/(R_sh)=") a=4-1 disp(a,"Therefore, I_a0(in A)=(I_L0)-(I_sh)=") r=0.3*(3)^2 disp(r,"Therefore, No. load armature copper loss(in W)=[(I_a0)^2*(R_a)]=") o=250*4 disp(o,"No load input(in W) = V*I_L0 =") c=1000-2.7 disp(c,"...
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// @Harness: verifier // @Purpose: "Test for redefinitions of operands" // @Result: "RedefinedOperand @ 8:27" architecture redef_op_02 { operand-type A[5]: int [0, 31]; instruction "I" foo: A, foo: A { } }
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//(12.10) Moist air enters a duct at 10C, 80% relative humidity, and a volumetric flow rate of 150 m3/min. The mixture is heated as it flows through the duct and exits at 30C. No moisture is added or removed, and the mixture pressure remains approximately constant at 1 bar. For steady-state operation, determine (a) ...
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// Updated(18-7-07) // 5.3 w = 0:0.01:%pi; subplot(2,1,1); plot2d1("gll",w,abs(1+2*cos(w))/3,style = 2); label('',4,' ','Magnitude',4); subplot(2,1,2); plot2d1("gln",w,phasemag(1+2*cos(w)),style = 2,rect =[0.01 -0.5 10 200]); label('',4,'w','Phase',4)
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clc;funcprot(0);//Example 8.23 //Initilisation of Variables Tw=100;.....//Temparature at water continusly evoperate in degrees celcius LH=2255;.....//Latent heat of vapourisation in kJ/kg ma=600/3600;....//Flow rate of hot air in kg/s Tai=200;......//Inlet temparature of hot air in K Tao=125;......//Outlet tempar...
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//CHAPTER 1- D.C. CIRCUIT ANALYSIS AND NETWORK THEOREMS //Example 18 clc; disp("CHAPTER 1"); disp("EXAMPLE 18"); //VARIABLE INITIALIZATION v=7; //voltage source in Volts I=7; //current source in Amperes r1=1; //in Ohms r2=2; ...
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clc;clear; //Example 3.10 //constants used R=0.287// in kPa m^3/kg K //given values l=4; b=5; h=6; P=100; T=25+273;//in Kelvin //calculation V=l*b*h; m=P*V/R/T; disp(m,'the mass of the air in kg')
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function sensor(t) global R n = 1024; tmax = 21000; ts = zeros(n,1); gx = zeros(n,1); gy = zeros(n,1); gz = zeros(n,1); ax = zeros(n,1); ay = zeros(n,1); az = zeros(n,1); figure(1); clf() subplot(211) plot2d([],rect=[0,-2^15,tmax,2^15]) xpoly([],[]); line_gx = gce(); line_gx.foreground = 2; xpoly([],[]); line_gy = ...
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Elevator Verification Test,Mon Aug 23 23:39:59 2021 0,StartTest 0,AbortTest
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//Ex1.4 clc A=0.5189*10^-6//wire cross sectional area rho=1.725*10^-8//resistivity l=100 //wire length disp("A ="+string(A)+"merer square") disp("rho ="+string(rho)+"ohm-m") disp("l ="+string(l)+"m") disp("R = rho*l/A = "+string(rho*l/A)+"ohm") //resistance
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//Example 2.17a clc; disp(' y[n]=3x[n-2]+3x[n+2] '); disp('THE GIVEN SYSTEM IS NON-CAUSAL'); disp('Since the value of output depends on future input');
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errcatch(-1,"stop");mode(2);//Example 1_36 ; ; //To find the order which will be visible at this point lemda1=6000 //units in angstroam lemda1=6000*10^-8 //units in cm lemda2=4500 //units in angstroam lemda2=4500*10^-8 //units in cm ...
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module rstar_h record geometry { dimensions, mbr, value }
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Ex12_12.sce
clc; close(); clear(); //page no 413 //prob no. 12.12 T0=290; //K Fdb=9; F=10^(Fdb/10); mprintf('Absolute Noise figure, F=%.3f=8(Approx)\n',F); F=8; //Approximate Te=(F-1)*T0; mprintf(' Noise Temperature , Te=%i K \n',Te); Ti=T0; k=1.38*10^-23; //Boltzmann's Constant B=2*10^6; //Hz Ni=k*Ti*B; //W ...
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// Example 2.1, page no-116 clear clc //(a) //1kg/cm^2=10000 mmWG x=10000*10 printf("(a)\n 10kg/cm^2 = %d mmWG",x) //(b) onemm_Hg=13.546 y=10^5/onemm_Hg y=y/10^3 printf("\n(b)\n10kg/cm^2 = 10^5 mmWG = %.2f * 10^3 mmHg",y) //(c) onebar=1.03 z=10/onebar printf("\n(c)\n10kg/cm^2 = %.2f bars",z)
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//Example 3.10 : largest diameter clc; clear; close; //given data : format('v',6) a=3.61; // edge length in angstrum r=(a*sqrt(2))/4; d=2*r; disp(d,"largest diameter,d(angstrom) = ")
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// EMF Induced between wing tips. clc; clear; l=6.1; vel=800; v=vel*1000/3600; b=(50)*(10^-6); e=b*l*v; disp('volts',e,'The EMF induced between the wing tips=')
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clc; printf("Example 1.2\n"); // 1 kW= 103 W = 103 J/s = 10^3 * (1 kg*1 m^2)/1 s^3 // = (10^3 * (1/0.4536) lb x (1/0.3048)^2 ft^2)/1 s^3 lfs=(10^3*(1/0.4536)*(1/.3048)^2); //lfs->lb ft^2/s^3 printf("\n 1 kW = %.0f lb ft^2/s^3",lfs); sfs=lfs/32.2; //sfs->slug ft^2/s^3 printf("\n 1 kW = %.0f slug f...
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clear // //case a total torque //rotor phase voltage at standstill=400/2.25*3**0.5 =102.64v ns=1500 //calculated using formula as above e2=102.64 r2=0.1 s=0.04 x2=1.2 //t=(3*60*(e2**2)*(r2/s))/(2*3.14*1500*((0.1/0.04)**2)+(1.2)**2) t=65.41 printf("\n t=65.41Nm") //case b N=1440 //calculated using same formula as above ...
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clc //initialisation of variables t= 8 //in t1= 1 //in k= 0.50 //Btu/hr ft F k1= 0.02 //Btu/hr ft F A= 1 //ft^2 T= 60 //F T1= -20 //F //CALCULATIONS Rc= (t/12)/(k*A) Rf= (t1/12)/(k1*A) R= Rc+Rf q= (T-T1)/R T2= (T+(Rc/Rf)*T1)/(1+(Rc/Rf)) //RESULTS printf ('Rate of heat flow= %.1f Btu/hr',q) printf (' \n...
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-- Fuzzy Logix, LLC: Functional Testing Script for DB Lytix functions on Netezza -- -- Copyright (c): 2014 Fuzzy Logix, LLC -- -- NOTICE: All information contained herein is, and remains the property of Fuzzy Logix, LLC. -- The intellectual and technical concepts contained herein are proprietary to Fuzzy Logix, LLC. -...
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// Data Reconciliation Benchmark Problems From Lietrature Review // Author: Edson Cordeiro do Valle // Contact - edsoncv@{gmail.com}{vrtech.com.br} // Skype: edson.cv //Rao, R Ramesh, and Shankar Narasimhan. 1996. //“Comparison of Techniques for Data Reconciliation of Multicomponent Processes.” //Industrial & Enginee...
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//ques-35.17 //Calculating frequency for a given transition in CO clc r=112.81;//bond length (in pm) r_m=(12*16/1000)/((12+16)*6.23*10^23);//reduced mass (in kg) B=(6.625*10^-34)/(8*%pi^2*r_m*(r*10^-12)^2*3*10^10); printf("The frequency for the given transition in CO is %.2f /cm.",6*B);
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for i=1:2:15 // ถ้า i < 7 แล้วให้ i มีค่าเป็นสมาชิกตัวถัดไป // มิฉะนั้น ให้แสดงค่าของ i^2 ทางจอภาพ if i<7 then continue; else disp(i^2); end end j = 1; while j <= 10 disp(j); if j == 5 then continue; else j = j + 1; end end
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function result = mdaqFileData(filename, filetype, rows, cols) result = []; if (argn(2) > 4 | argn(2) < 2) | (filetype == 2 & argn(2) <> 4) then mprintf("Description:\n"); mprintf("\tReads data from file created with MicroDAQ ''To File'' block\n"); mprintf("Usage:\n"); mprintf("...
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ModuleName="time_since_epoch"; Version="0.01"; DateModified="07-May-2015"; DateOfCreation="07-May-2015"; Author="Rob Eccleston"; Description=""; mprintf("Loading " + ModuleName + " V" + Version + ", Last Modified: " + DateModified + "\n"); function num_seconds=time_since_epoch(year,month,day,hour,minute,sec...
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// Exa 1.17 clc; clear; close; // Given data R1=10;// in kohm R2=150;// in kohm R3=10;// in kohm R4=300;// in kohm V1= 1;// in V V2= 2;// in V Vo= [(1+R4/R2)*(R3*V1/(R1+R3))-(R4/R2)*V2]; disp(Vo,"Output voltage in volts is : ")
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//Kunii D., Levenspiel O., 1991. Fluidization Engineering(II Edition). Butterworth-Heinemann, MA, pp 491 //Chapter-18, Example 2, Page 457 //Title: Kinetics of Carbon Burning //========================================================================================================== clear clc //INPUT xA=0....
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clear; clc; // Example: 3.2 // Page: 89 printf("Example: 3.2 - Page: 89\n\n"); // Solution //*****Data*****// V1 = 8;// [cubic m] P1 = 300;// [kPa] V2 = 2;// [cubic m] //**************// // Apptying the ideal gas Eqn. & since the Temperature remains constant: P2 = P1*V1/V2;// [kPa] printf("The p...
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# start Dutch.X11 16*m + m^2 - 21 # start Dutch.X11 16*m - m^2 + 21 # start Dutch.X11 - 4*m + 2*m^2 + 42 # start Dutch.X11 4*m + 2*m^2 + 42 Dutch.X11 [0] 0 16*M + M^2 - 21 Dutch.X11 [0] 1 16*M - M^2 + 21 Dutch.X11 [0] 2 - 4*M + 2*M^2 + 42 Dutch.X11 [0] 3 4*M + 2*M^2 + 42 Dutch.X11 [1] 0 18*M + M^2 - 4 ...
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//variable declaration r=0.123 //Atomic radius n=4 A=55.8 //Atomic wt a=2*sqrt(2) N=6.02*10**26 //Avagadro number //Calculations rho=(n*A)/((a*r*10**-9)**3*N) //Result printf('Density of iron =%0.3fkg/m**-3",rho)
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//Given that Iwh = 1.2 //in kg.m/s^2 Wwh = 3.9*2*%pi //in rad/s Ib = 6.8 //in kg.m/s^2 //Sample Problem 12-7 printf("**Sample Problem 12-7**\n") //angular momentum conservation along the axis of rotation of the system //Ib*Wb - Iwh*Wwh = Iwh*Wwh Wb = 2*Iwh*Wwh/Ib printf("The angular speed of the composit...
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clear; clc; printf("\nEx1.18\n"); //page no.-32 //given n=2;...........//no. of atoms per unit cell M=55.85;........//atomic wt. of Ge N=6.02*10^26;....//avagadro no. rho=7860;........//density in Kg/m^3 a=((n*M)/(rho*N))^(1/3)........//lattice constant in angstrom printf("\nlattice constant is 0.286 angs...
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//--------------------------------------------------// // main program // // author Claire Dune // date 24/01/2010 // ;exec('testAsserVisuTous.sce'); //--------------------------------------------------// //clear //------- Load the functions // ------ Describe the problem [cInitMo_m,cFinalMo_m,LFunction_m,target_m,...
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Example0_15.sce
//clear// //Example 1.5:To express sum of two complex exponentials //as a single sinusoid clear; clc; close; t =0:1/100:2*%pi; x1 = exp(sqrt(-1)*2*t); x2 = exp(sqrt(-1)*3*t); x = x1+x2; for i = 1:length(x) X(i) = sqrt((real(x(i)).^2)+(imag(x(i)).^2)); end plot(t,X); xtitle('Full wave rectified sinusoid'...
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// Chapter3 // Page.No-86, Figure.No-3.8 // Example_3_4 // Output voltage of voltage-shunt feedback amplifier // Given clear;clc; R1=470;Rf=4.7*10^3; A=200000; // Open-loop voltage gain vin=1; // Input voltage in volts K=Rf/(R1+Rf); // Voltage attenuation factor B=R1/(R1+Rf); // Gain of the feedback circuit ...
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clear //Given V=90 //V d=2.0*10**-2 e=1.8*10**11 x=5*10**-2 v=10**7 //Calculation E=V/d a=e*E t=x/v y=0.5*a*t**2 //Result printf("\n Transverse deflection produced by electric field is %0.1f cm",y*10**2)
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example_5_11.sce
//Chapter 5 //Example 5.11 //page 172 //To determine sending-end voltage.maximum power delivered clear;clc; A=0.93*(cosd(1.5)+%i*sind(1.5)); B=115*(cosd(77)+%i*sind(77)); Vr=275; Ce=abs(A/B)*Vr^2; printf('Centre of the receiving end circle is = %0.1f MVA\n\n',Ce); CrP=850;Vs=CrP*abs(B)/Vr; printf('(a) From the diagram...
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a = 0.5,b = 0.001,c = 0.5, d = 0.001; //a = 1, b = 1, c = 1, d = 1; function dx=fun1(t,x) dx=zeros(2,1); dx(1)=a*x(1)-b*x(1)*x(2); dx(2)=c*x(2)-d*x(1)*x(2); endfunction function dx=fun2(t,x) dx=zeros(2,1); dx(1)=a*x(1)-b*x(1)*x(2); dx(2)=c*x(1)*x(2)-d*x(2); endfunction //Реше...
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//clear// clear; clc; //Example 26.4 //Given F = 10; //[gal/day-ft^3] Do = 300*10^-6; //[m] Di = 200*10^-6; //[m] vi = 0.5; //[cm/s] rho = 1; //[g/cm^3] mu = 0.01; //[g/cm-s], assumed f = 0.97; //Solution //For 10 gal/day-ft^2 Jw = F*231*16.3871/(24*3600*929); //[cm/s] Nre = Do*100*vi*rho/mu; Ds = 1...
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clc clear printf("Example 10.9 | Page number 355 \n\n"); //Find thermodynamic properties //Given data t = 250 //°C h = 2855.8 //kJ/kg //From superheated property table p = 3e6 //Pa v = 0.07058 //m^3/kg s = 6.2871 //kJ/kgK u = h - p*v*.001 //kJ/kg printf("Pressure = %.1f MPa\n",p*1e-6) printf("Volume per k...
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clear //Given Cab=10 //micro F C1=8.0 //micro F C2=8.0 C3=8 C4=8 C5=12 V=400 //Calculation Cbc=((C1*C2)/(C1+C2))+C3+C4 Cac=Cab*Cbc/(Cab+Cbc) Ccd=C1+C5 Cad=Cac*Ccd/(Cac+Ccd) q=Cad*V Vcd=q/Ccd q1=C5*Vcd //Result printf("\n (i) The equivalent capacitance between A and D ...
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//Variable Declaration u=3.986*(10**14) //Earth's Gravitational constant(m^3/sec^2) //Calculation n=(2*3.14)/(24*60*60) //Mean Motion(rad/sec) a=((u/n**2)**(0.33333))/1000 //Radius of the orbit by kepler's 3rd law(km) //Result printf("The Radius of the circular orbit with 1 day period is : %d km",a) ...
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clc,clear function [y,p]=testexp(n) y=[] //counter=0 c1=0 i=0 while i<=n z=grand(1,1,'exp',1) //counter=counter+1 i=i+1 if z>=0.5 then z=z-0.5 y=[y',z']' end end p=(n-length(y))/n endfunction clf [y,p]=testexp(50000); printf('Th...
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ex4_3.sce
clc; q1=2*10^-7; //charge in C q2=3*10^-7; //charge in C r=30*10^-2; //r in m F=(9*10^9)*((q1*q2)/r^2); //calculating F disp(F,"Force in Newton = "); //displaying result
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clc; clear; RL=3 //load resistor in ohm hie=1*10^3 //in ohm hre=2*10^-4 //in mho hfe=25 //in mho hoe=15*10^-6 //in mho //Calculation gm=hfe/hie Ave=-gm*RL*10^3 mprintf("Transconductannce= %0.3f mho\n",gm) mprintf("Voltage gain= %0.2i",Ave)
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//Example 3.14 //calculate the optimum thickness. //Given Ti=172 //C, saturation temp. To=20 //C, ambient temp. Cs=700 //per ton, cost of steam Lv=487 //kcal/kg, latent heat of steam ho=10.32 //kcal/h m^2 C, outer heat transfer coefficient kc=0.031 //W/m...
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exec(INTER_SYS_DIR+'/bin/gl_draw_phy.sci'); exec(INTER_SYS_DIR+'/bin/gl_retrieve_skeleton.sci');
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clc; //page 224 //problem 5.4 // Repeat example 5.3 with m(t) expanded by a factor of 2 i.e. if the period of m(t) is 4*10^-4 // The values of constsnts Kf and Kp are given as Kf= 2*pi*10^5 and Kp=5*pi . // we know that time expansion by a factor 2 reduces the signal spectrum width by a factor 2 // Therefore band...
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@relation led7digit @attribute Led1 real[0.0,1.0] @attribute Led2 real[0.0,1.0] @attribute Led3 real[0.0,1.0] @attribute Led4 real[0.0,1.0] @attribute Led5 real[0.0,1.0] @attribute Led6 real[0.0,1.0] @attribute Led7 real[0.0,1.0] @attribute number{0,1,2,3,4,5,6,7,8,9} @inputs Led1,Led2,Led3,Led4,Led5,Led6,Led7 @output...
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function [r]=%lnc(l1,l2) //%lnc(l1,l2) : l1==l2 //! r=%t
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//Chapter-4, Example 4.15, Page 144 //============================================================================= clc clear //given voltage applied is e=340*sin(314*t) //given current applied is i=42.5*sin(314*t) //CALCULATIONS R=340/42.5;//resisitance in ohms E=(340)/sqrt(2);//average value of voltage in vol...
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// A => B k1 // B => C k2 // // How to find reaction time when concentration of B reaches max.? // kinetic model function dy = model(t, y) A = y(1) B = y(2) C = y(3) dAdt = -k1*A dBdt = k1*A - k2*B dCdt = k2*B dy=[dAdt, dBdt, dCdt] // order endfunction // parameters & initial conditi...
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h1=2//ft h2=1//ft h3=4//ft S1=0.80 S2=0.65 S3=1
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clc;clear; //Example 15.11 //given values Tsurr=298;//in K //contansts used Ru=8.314;//in kJ/kmol K //calculations //part - a // CH4 + 3(O2 + 3.76N2) = CO2 + 2H2O + O2 + 11.28N2 //The amount of water vapor that remains in the products is determined as in Example 15–3 Nv=0.43;//moles of water vapour ...
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clear; clc; // Stoichiometry // Chapter 5 // Energy Balances // Example 5.25 // Page 257 printf("Example 5.25, Page 257 \n \n"); // solution // basis 100 kmol/h of benzene feed rate Cl2 = .4*100 HClp = 40 Benzenecon = 37 MCBp = 100*.37*.9189 DCBp = Benzenecon-MCBp unreactBenzene = 100-Benzeneco...
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//find.. clc //soltuion //given b=0.100//m t=0.01//m v=16.67//m/s //T1-T2=1.8 *T2 f=1.6//N/mm^2 rho=1000//kg/m^3 //let T1 and T2 be tneion on tight and slag side T=f*b*t*10^6//N//max tension m=0.1*0.01*1000//kg/m Tc=m*v^2//N T1=T-Tc//N T2=T1/2.8//N P=(T1-T2)*v printf("the power transmitted is,%f W\n",...
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clc(); clear; // To calculate the thermal resistance b1 = 0.5/12; // Thickness of iron wall in ft b2 = 0.0005/12; // Thickness of air gap in ft b3 = 1/12; // Thickness of aluminium wall in ft k1 = 30; // The...
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//Example 6_10 clc(); clear; //To find the average speed of the nitrogen molecule in air ap=1.01*10^5 //units in Newton/meter^2 nofmol=2.69*10^25 //Number of molecules nitmass=4.65*10^-26 //units in Kg v=sqrt((ap*3)/(nofmol*nitmass)) //units in meters/sec printf("The average speed of the nitrogen molecu...
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clc clear //INPUT p=100*746/4.2;//power developed in cal/sec t1=300;//temperature of the sink in K t2=500;//temperature of the source in K //CALCULATIONS n=1-(t1/t2);//efficiency of the engine q1=p/n;//heat supplied in cal/sec q2=q1*(1-n);//heat rejected to the sink in cal/sec //OUTPUT mprintf('the eff...
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## Test of strip command set echo read <simple.fi strip --blobs write -
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errcatch(-1,"stop");mode(2);//Example 1.11.1: peak reverse recovery current ; ; //given data : itt=10;// time in micro seconds qtt=150;//charge in micro colums prrc=((2*qtt)/itt);//peak reverse recovery current in amperes disp(prrc,"peak reverse recovery current in amperes") exit();
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// **** Purpose **** // This function generates the lattice vectors to construct a conventional // cell. // **** Variables **** // [a_vec]: 3x3, real // <= lattice row vectors // [new_b_red]: 3x3, real // <= new reciprocal row vectors in reduced coordinate // [new_a_red]: 3x3, real // => new lattice row vectors in te...
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// exa 9.6 Pg 267 clc;clear;close; // Given Data W=100;// kN lift=400;// mm sigma_ts=100;// MPa sigma_cs=100;// MPa tau_s=60;// MPa tau_tn=50;// MPa sigma_cn=45;// MPa tau_n=40;// MPa pb=15;// MPa mu=0.2;// coefficient of thread friction mu_c=0.15;// coefficient of collar friction //sigma_cs=4*W/(%pi*dc**2) dc=sqrt(...
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//ques5 //The Simple Ideal Brayton Cycle clear clc //Process 1-2 (isentropic compression of an ideal gas) T1=300;//initial temp in K //from table h1=300.19;//enthalpy of heat at state 1 in kJ/kg Pr1=1.386;//reduced pressure at state 1 r=8;//constant ratio Pr2=r*Pr1;//reduced pressure at state 2, r=P2/P1 //u...
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polys[0]=0 polys[1]=1 polys[2]=1 polys[3]=-1 order=2 initialize: mN=-1, mRElen=3, mNPlen=1, mOrder=2, mLinit=2 0 1 1 10 2 60 3 264 4 930 5 2766 6 7205 7 16880 8 36279 9 72610 10 136906 11 245400 12 421200 13 696294 14 1113915 15 1731296
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//pagenumber 338 example 3 clear w=1*10^-4;//centimetre em1cur=2*10^-3;//ampere q=47; voltag=26*10^-3;//volt cde=(em1cur*w^2)/(voltag*2*q); fq1=(em1cur)/(2*3.14*cde*voltag); disp("cde = "+string((cde))+"farad"); disp("frequency = "+string((fq1))+"hertz");
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// Example 7.3 page no-403 clear clc //(a) dA=100 A=1000 dAf=0.1 Af=100 B=(((dA/A)*(Af/dAf))-1)/A printf("(a)\nBeta=%.3f",B) //(b) Aff=A/(1+B*A) printf("\n\n(b)\nAf=%d",Aff)
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//Declare tchar function for torque characteristic computation //x = d/D function [T] = tchar(x) T = x * (1 - (x^2)) endfunction
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// Lowering the viscosity of a polymer clc T1 = 453 // First temperature in K T2 = 423 // Second temperature in K k = 2.2 // ratio of obtained result to desired output printf("\n Example 10.2") del_t = T1-T2 // temperature difference in Kelvin neeta1 = 10^(12-(17.5*del_t/(52+del_t))) // First viscosity neeta2...
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// MATRIZ DE RIGIDEZ E DE MASSA LOCAIS // O scilab não trabalha com variáveis simbólicas como o matlab // Para resolver esse problema fez-se uso de funções que utilizam polinomios // Também se fez uso de uma função que integra os polinomios numa matriz function MatrizN=MN(L) // Variável do polinômio x...
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clc clear //Initialization of variables P=200 //psia T=500 //F //calculations disp("From mollier chart,") hi=1269 //Btu/lb hf=1063 //Btu/lb dh=hi-hf y1=91 //results printf("Quality = %.1f percent",y1) printf("\n Change in enthalpy = %d Btu/lb",dh)