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clc //initialisation l=1//m ld1=0.7//m ld2=0.78//m d1=0 d2=30 vd1=l-(ld1*cosd(d1)) vd2=l-(ld2*cosd(d2)) //CALCULATIONS H=((ld1*vd1)-(ld2*vd2))/(vd1-vd2) //results printf(' atmospheric pressure= % 1f m',H)
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x0=0;x1=0:0.1:2*%pi; X=integrate('sin(x)','x',x0,x1); norm(cos(x1)-(1-X)) x1=-10:0.1:10; X=integrate(['if x==0 then 1,'; 'else sin(x)/x,end'],'x',0,x1)
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Turbomachinery Design and Theory,Rama S. R. Gorla and Aijaz A. Khan, Chapter 7, Example 2") disp("The specific work output in kJ/kg") etats = 0.85; Cpg = 1.147; T01 = 800 + 273; gam = 1.33; W = etats*Cpg*T01*...
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//Chapter 04:Number Theory and Cryptography clc; clear all; i=0 oct=input("Enter the octal number:") tmp=oct dec=0 while(oct~=0) dec=dec+(modulo(oct,10))*(8**(i+0)) i=i+1 oct=int(oct/10) end disp(dec,'Equivalent Decimal Value:')
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// Y.V.C.Rao ,1997.Chemical Engineering Thermodynamics.Universities Press,Hyderabad,India. //Chapter-3,Example 12,Page 72 //Title:Pressure developed using two paramter compressibility factor correlation //==============================================================================================================...
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// Example 2.38.a:S clc; clear; close; Beta=180;//Common emitter D.C. Current gain Re=1;// Collector resistance in killo ohms R1=5.76;// resistance in killo ohms R2=34.67;// resistance in killo ohms S=1+Beta; disp(S,"Stability factor in fixed bias case is")
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//Chapter 9 Ionic Equilibria and Buffer Action clc; clear; //Initialisation of Variables c= 0.050 //M Kb= 1.8*10**-5 T= 25 //C Kw= 10**-14 //CALCULATIONS C= sqrt(Kw*c/Kb) //RESULTS mprintf("Concentration of hydronium ion = %.2e mol per litre",C)
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// Initilization of variables v_t=10 // m/s // velocity of the train v_s=5 // m/s // velocity of the stone // Calculations // Let v_r be the relative velocity, which is given as, (from triangle law) v_r=sqrt(v_t^2+v_s^2) // m/s // The direction ofthe stone is, theta=atand(v_s/v_t) // degree // Results clc pri...
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errcatch(-1,"stop");mode(2); disp("example 8.1") h=100 //given height q=200 //discharge e=0.9 //efficiency p=(735.5/75)*q*h*e printf("\npower developed by hydro plant is %ekW",p) exit();
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//Example 14_3 clc(); clear; //To find the intensity of sound level=3.5 //Units in dB i2=10^-12 //Units in W/meter^2 i=10^(level+log10(i2)) //Units in W/meter^2 printf("The intensity of sound is I=") disp(i) printf("W/meter^2")
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clear a= input(' entrez nombre a:') b= input(' entrez nombre b:') c= input(' entrez nombre c:') tr=max (a,b,c) //fonction maximum disp ('le nombre le plus grand est '+string(tr))
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//DECOMPOSIÇÃO LU: //A = LU //Ax = b //a matriz L eh formada p parti dos fatores calculados com a decomposição de gauss clc a = [10 2 1; 1 5 1; 2 3 10]; b = [7; -8; 6]; //a = [5 2 1; 3 1 4; 1 1 3]; e = [0 -0.2 0.5; 0.1 0 0.4; -0.3 0.1 0]; h = [0 0 1; 1 0 0; 3 0 0]; function [L,U,d] = decom_lu(a) [l,c] = si...
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A=input("Enter elements of matrix A:") disp(A,"The coefficients of matrix A are:") B=input("Enter elements of matrix B:") disp(B,"The coefficients of matrix B are:") for l=1:3 L(l,l)=1 end for x=1:3 for y=1:3 s=0 if y>=x for k=1:i-1 s=s+L(x,k)*U(k,y) ...
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//Chapter 4 Ex 12 clc; clear; close; x=poly(0,'x'); for x=0.1:0.1:0.9 if (x/(1+1-x))==0.5 mprintf("\n The value of x is %.2f",x); break; end end
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//value// s=%s; H=syslin('c',(s+2)/((s+1)*s*(s+4))); evans(H,100)
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//========================================================================== // chapter 9 example 4 clc clear // Variable declaration Lf = 42.3; // guage length after strain mm Lo = 40; // guage length in mm // Calculations e = ((Lf - Lo)/Lo)*100 // Engineering Strain in percent ...
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//example 1 //coefficient of performance of refrigerator clear clc Th=60 //temperature at which heat is rejected from R-134a Tl=0 //temperature at which heat is absorbed into the R-134a s1=1.7262 //specific entropy at 0 Celsius s2=s1 //process of state change from 1-2 is isentropic s3=1.2857 //specific entrop...
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// Exa 1.20 format('v',7); clc; clear; close; // Given data Rf=100;// in kohm R1=20;// in kohm V1= 1.5;// in V Vo1= V1; Vo= -Rf/R1*Vo1;// in volts disp(Vo,"Output voltage in volts is : ")
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// Example 10.5 clear all; clc; // Given data fission_density = 4*10^7; // Fission density in fissions/cm^2-sec // 1 inches = 2.54 cm d = 28*2.54; // Diamaeter of plate in cm R = d/2; // Radius of plate in cm v = 2...
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clc; //page no 37 //problem 2.3 T=12.5*10^-6; //in sec f0=0; //dc f1=1/T*10^-3; //in kHz f2=f0+2*f1; f3=f0+3*f1; f4=f0+4*f1; disp('kHz',f4,f3,f2,f1,f0,'The lowest five frequencies are (in kH)');
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// returns only T function [T]=cholesky_fact(A) [m,n] = size(A) if (m~=n) then print(%io(2), "error, not a square matrix"); else T = zeros(n); T(1,1) = sqrt(A(1,1)); for j = 2:n T(j, 1) = A(1, j)/T(1, 1); end for i = 2:n T(i, i) = sqrt( A(i, i) - sum( T(i...
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a = input('a: '); b = input('b: '); h = input('h: '); y0 = input('y(a): '); absErr = 0; for x = a:h:(b - h) y0 = y0 + h * ((x + h) * cos(x + h) + y0/(x + h)); y = (x + h) * sin(x + h); absErr = max(absErr, abs(y-y0)); printf('x: %f, ny: %f, y: %f, delta: %f\n', x+h, y0, y, abs(y-y0)); end printf(...
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// Scilab code: Ex6.6 : Minimum wavelength emitted by an X-ray tube : Pg: 157 (2008) h = 6.625e-034; // Planck's constant, Js c = 3e+08; // Velocity of light, m/s e = 1.6e-019; // Charge of an electron, coulombs V = 4.5e+04; // Accelerating potential of X-ray tube, volt // Since e*V = h*c/L_min; // ...
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//Example 12_3 clc;clear;funcprot(0); // Given values m=3;//Mass flow rate in kg/s T_0=473;// T_0=T_1 in K P_0=1400;// P_0=P_1 in kPa P=1200;// kPa // Properties C_p=0.846;// kJ/(kg.K) k=1.289; R=0.1889;// kJ/(kg.K) //Calculation T=T_0*(P/P_0)^((k-1)/k);// k V=sqrt(2*C_p*(T_0-T)*1000);// m/s printf('Vel...
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clc; clear; exec("C:\Program Files\scilab-5.3.0\bin\TCP\8_12data.sci"); d=0.00238;//slugs/(ft^3) vis=3.74*(10^(-7));//lb*sec/(ft^2) x=Q/(%pi/4);//where x =V*(D^2) //energy equation with z1=z2 and V1=V2 y=l*d*(x^2)*0.5/(pd*144);//where y=(D^5)/f f=0.027;//using reynolds number, roughness and moody's chart D=(y*...
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DECLARE FUNCTION c.loadstring$ (fl1$) DECLARE SUB dma.makeready (channel%, seg1%, off1%, transfer%, initialize%, address%, mode%, length%) DECLARE SUB dma.dotask () DECLARE SUB dma.pause () DECLARE SUB dma.resume () DECLARE SUB dma.stop () Engine$ = c.loadstring$("dma.dll") DIM Status%(11) CLS dma.makeready 1, &HB80...
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// Calculating the sqrt. y = [1.2, 1, 1.9; 4, 2.6, 5; 2.3, 8, 7]; sqrtres = armaMat("sqrt",y)
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//Chapter-5,Example5_3_4,pg 5-7 E=0.025 //energy of neutron h=6.63*10^-34 //Plancks constant m=1.676*10^-27 //mass of a neutron e=1.6*10^-19 //charge on electron wavelength=h/...
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clc //initialization of variables w=1 //lbm Sw=0.3120 //B/lbm R Ss=1.7566 //B/lb R T=672 //R //calculations Q=T*(Ss-Sw) //results printf("Latent heat of water = %d B/lbm",Q)
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//example 10.8 //page 391 clc; funcprot(0); //initialisation of variable b=60;//bottom width y1=2.5;//depth g=32.2; Q=2500;//flow rate Gamma=62.4//unit weight V1=Q/b/y1;//velocity F1=V1/sqroot(g*y1); k=0.5*(sqroot(1+8*F1^2)-1);//k=y1/y2 y2=k*y1; //depth V2=Q/b/y2;//velocity L=y2*4.25; LE=y2+V2^2/2/g-y1...
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// Scilab code Ex2.1: Pg:55 (2008) clc;clear; V1 = 250; // Accelerating potential of electron in first region, volts theta1 = 50; // Angle of incidence, degrees theta2 = 30; // Angle of refraction, degrees // According to Bethe's law sind(theta1)/sind(theta2) = []V2/V1]^1/2 // On solving for V2 V2 = V1...
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x <- x <- x <- x <-; a <- b <- c <- 1 <- 2 <- 3;
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// This file is part of www.nand2tetris.org // and the book "The Elements of Computing Systems" // by Nisan and Schocken, MIT Press. // File name: projects/05/ComputerMax.tst load HackComputer.hdl, output-file p3.out, output-list time%S1.5.1 reset%B2.1.2 ARegister[]%D1.7.1 DRegister[]%D1.7.1 PC[]%D0.4.0 RAM16K[...
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//EX3_28 PG-3.61 clc Es=230;//rms voltage f=50; Il=10e-3;//load current Rf=.01;//ripple factor Esm=sqrt(2)*Es;//peak value of input voltage Edc=2*Esm/%pi;//for full wave Rl=Edc/Il; C=(4*sqrt(3)*f*Rf*Rl)^(-1);//for full wave rectifier C=C*1e6; printf("\n Therefore capacitance required is %.2f microF",C)
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// Scilab Code Ex1.8 Increase in mass of water: Pg: 23 (2008) c = 3e+08; // Speed of light, m/s T1 = 273; // Initial temperature of water, K T2 = 373; // Final temperature of water, K M = 1e+06; // Mass of water, kg C = 1e+03; // Specific heat of water, cal/kg-K J = 4.18; // Joule's mechanical e...
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//finding peak voltage// //example 7// clc //clears the command window// clear //clears// T=250*10^-12;//time constant// t=.05*10^-6; Vo=100;//peak output voltage// Vi=(Vo*t)/T;//peak voltage of generator// printf('peak voltage=%f volt',Vi) //result is displayed//
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clc T=200//temperature in degree celsius P=15.549 //pressure in bars hf=852.37 hg=2790.9 hfg=hg-hf mprintf("Saturation pressure=%f bar\n",P) mprintf("Latent heat of vaporisation=%f kJ/kg\n",hfg) vg=0.1272 //in metre-cube/kg ug=(hg*10^3)-(P*10^5*vg) mprintf("ug=%fkJ/kg",ug/1000)//ans may vary due to roundoff e...
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//Chapter 12 //page no 488 //given clc; clear all; CNR=50; //in dB Bch=4*10^6; m=0.03; RIN=m^2/2/Bch/10^(CNR/10) mprintf("\n RIN = %e ",RIN); //Miscalculated answer in the book RINdB=10*log10(RIN); printf("\nRIN in Db is %.2f",RINdB)
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function [L012,L02,L01]=iteratedinterpol (x,f,n) X=poly(0,"X"); L01=(1/(x(2)-x(1)))*det([f(1) x(1)-X;f(2) x(2)-X]); L02=(1/(x(3)-x(1)))*det([f(1) x(1)-X;f(3) x(3)-X]); L012=(1/(x(3)-x(2)))*det([L01 x(2)-X;L02 x(3)-X]); endfunction ...
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//Caption:Find the equivalent circuit parameters of the transformer reffered to LV side and also calculate the secondary voltage //Exa:3.10 clc; clear; close; V1=300;//in volts I_o=0.8;//in amperes W_o=70;//in watts pf=W_o/(V1*I_o); I_w=I_o*pf; I_m=I_o*sqrt(1-pf^2); R_O=V1/I_w; X_O=V1/I_m; a=300/600; V_sc...
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//Scilab Code for Example 8.10 of Signals and systems by //P.Ramakrishna Rao clear; clc; syms s1; s=%s; H=poly(0,'s'); H=s^3/(s^3+6*s^2++11*s+6); H1=denom(H); a=roots(H1); H2=5*(s1^3/(s1-a(1)))*(s1/(s1-a(2)))*(s1/(s1-a(3))); disp(H2,'(ii) Cascade Form: H(s)'); h1=s1^3*(s1-a(1))/((s1+1)*(s1+2)*(s1+3)); h2=s...
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//chapter1,Example1_4,pg 482 Vs=3//supply voltage Vu=2.75//voltmeter reading Rp=10*10^3//parallel resistance Ru=Rp*((Vs/Vu)-1)//unknown resistance printf("unknown resistance\n") printf("\nRu=%.2f ohm",Ru)
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//Exa2.7 clc; clear; close; format('v',11); //given data : E=100;//in V/m rho=1.5*10^-8; //in ohm-meter //since sigma=1/roh sigma=1/rho; n=6*10^28 ; //unit less e=1.601*10^-19; //in C m=9.107*10^-31;//in kg // Relaxation time toh=(sigma*m)/(n*e^2); disp("(i) Relaxation time of electrons is : "+string(toh...
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clc; clear; P_1=0.3; //P( 1 is transmitted) Pe_1=10^(-3); //P(detecting an error when 1 is transmitted) P_0=0.7;//P( 0 is transmitted) Pe_0=10^(-7); //P(detecting an error when 0 is transmitted) error_prob=P_1*Pe_1+P_0*Pe_0; disp(error_prob,"Error Probabillity of the channel");
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//Book Name:Fundamentals of Electrical Engineering //Author:Rajendra Prasad //Publisher: PHI Learning Private Limited //Edition:Third ,2014 //Ex13_7.sce clc; clear; R=10; L=0.1; t1=0.01; omega=100*%pi; phi=omega*t1; t=(asin(1)+atan((omega*L)/R))/omega; Imax=((-omega*L*exp(-R*t/L))/(R^2+(omega*L)^2))-(s...
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//ANALOG AND DIGITAL COMMUNICATION //BY Dr.SANJAY SHARMA //CHAPTER 2 //AMPLITUDE MODULATION clear all; clc; printf("EXAMPLE 2.31(PAGENO 119)"); //given //percentage modulation for first case Pm_1 = 100 //percentage modulation for second case Pm_2 = 50 m_1 = 1//modulation index for first case m_2 = .5//mo...
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// Exa 5.9.2 clc; clear; close; // Given data alpha = 0.9; I_E = 1;// mA I_C = alpha * I_E;// in mA I_B = I_E - I_C;// in mA disp(I_B,"The value of base current in mA is");
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example_10.sce
clc clear printf("example 3.10 page number 98\n\n") //to find the amount of water evaporated xf = 0.15; xl = (114.7)/(114.7+1000); xc = 1; K2Cr2O7_feed = 1000*0.15; //in kg n = 0.8; C = n*K2Cr2O7_feed; V = (K2Cr2O7_feed-120 - 880*0.103)/(-0.103); printf("amount of water evaporated = %f kg",V)
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SSSoModMZ.sci
// The code was developed under Horizon2020 Framework Programme // Project: 748767 — SIMFREE function Out=SSSoModMZ(In,V) // Mach-Zehnder Modulator // // Calling Sequence // Out=SSSoModMZ(In,V) // // Parameters // In : Optical Input // V : Modulating Signal // Out : Optical ...
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exec("swigtest.start", -1); checkequal(vararg_over1("Hello"), "Hello", "vararg_over1(""Hello"")"); checkequal(vararg_over1(2), "2", "vararg_over1(2)"); checkequal(vararg_over2("Hello"), "Hello", "vararg_over2(""Hello"")"); checkequal(vararg_over2(2, 2.2), "2 2.2", "vararg_over2(2, 2.2)") checkequal(vararg_over3("H...
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//Exa 2.2 clc; clear; close; disp("Two wire dc system : "); disp("I1=P/V & W=2*I1^2*R1=2*P^2*rho*l/V^2/a1"); disp("Therefore, Volume required, v1 is 2*a1*l=4*P^2*rho*l^2/V^2/W"); disp("Three phase four wire system : "); disp("I2=P/3/Vas Power by each phase is P/3 & W=3*I1^2*R2=P^2*rho*l/3/V^2/a2"); disp("The...
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clc clear //Inputs //The Values in the program are as follows: //Temperature in Celcius converted to Kelvin(by adding 273) //Pressure in bar converted to kPa (by multiplying 100) //Volume in m^3 //Value of R,Cp and Cv in kJ/kg K V1=0.1; V3=V1; P1=10; T1=200+273; P2=3; R=0.287; G=1.4; Cv=0.718; m=(P1...
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// Calculations W_actual=1360 //N //Load lifted P_actual=100 //N // Effort n=4 // no of pulleys // Calculations // for 1st system of pulleys having 4 movable pulleys, Velocity ratio is V.R=2^(n) // Velocity Ratio // If the machine were to be ideal(frictionless) M.A=V.R // Here, M.A= mechanical advantage // Fo...
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// Exa 1.2 clc; clear; close; format('v',7) // Given data n_i = 1.4*10^18;// in /m^3 N_D = 1.4*10^24;// in /m^3 n = N_D;// in /m^3 p = (n_i^2)/n;// in /m^3 // Ratio of electron to hole concentation, ratio = n/p; disp(ratio,"Ratio of electron to hole concentration is");
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// SAMPLE PROBLEM 5/9 clc;funcprot(0); // Given data n=1500;// rev/min theta=60;// degree r=5;// inch d_AG=10;// The distance from A to G in inch d_GB=4;// The distance from G to B in inch d_AB=14;// The distance from A to B in inch // Calculation v_B=(r/12)*((2*%pi*n)/60);// ft/sec // From the law of sine...
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// // a1=0,a2=3.0, b1=2.20,b2=5.50, c1=1.75,c2=3.0, d1=1.5,d2=0, e1=4.75,e2=5.25, f1=6.40,f2=7.30, g1=0,g2=3.0, printf("\n at station 1') sp=(e1*d2)+(f1*e2)+(d2*f2)+(c1*d2)+(b1*c2)+(a1*b2) sq=(e2*d1)+(e1*f2)+(f1*g2)+(d1*c2)+(c1*b2)+(b1*a2) area1=0.5*(sp-sq) area1=abs(area1) printf("\n sp= %0.3f,sq= %0.3f...
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 22.1w //calculation of the total radiant flux,total luminous flux and the luminous efficiency //given data E1=12//energy(in J) emitted by the source lambda1=620*10^-9//wavelength(in m) of the light1 E2=8//energy(in J...
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# Simple distilation column test units SI $thermo = VirtualMaterials.Peng-Robinson / -> $thermo thermo + PROPANE n-BUTANE ISOBUTANE n-PENTANE col = Tower.Tower() col.Stage_0 + 20 # twenty two stages` cd col.Stage_10 f = Tower.Feed() f.Port.T = 30 f.Port.P = 720 f.Port.MoleFlow = 10 f.Port.Fraction = .4 .05 .4 .15 f....
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extractpid.sci
// extarct the pid data from the given function function [Kp, Ki, Kd, Tf, Ts] = extractpid(varargin) //store the dimension of the data [lhs,rhs]=argn(0) total_dim = [] //find out the data type for ii =1:rhs if and(typeof(varargin(ii))<>[ "rational" "state-space" "constant" "hypermat"]) then ...
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var=[]; maxcong=[]; maxtrans=[]; var(1)=0.1; maxcong(1)=1139.8514851485147; maxtrans(1)=16; meancong(1)=445.82301980197997; meantrans(1)=5.986986818962758; var(2)=0.3333333333333333; maxcong(2)=1099.6287128712872; maxtrans(2)=20; meancong(2)=462.9615305280528; meantrans(2)=7.155777256114574; var(3)=1; maxcong(3)=327.97...
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//scilab 5.4.1 //Windows 7 operating system //chapter 9 Basic Voltage and Power Amplifiers clc clear //In a class B push pull circuit //Transformer winding resistances are to be ignored n=3//n=primary-to-secondary turns ratio of a transformer RL=9//RL=load resistance in ohms VCC=15//VCC=collector supply voltag...
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// ELECTRIC POWER TRANSMISSION SYSTEM ENGINEERING ANALYSIS AND DESIGN // TURAN GONEN // CRC PRESS // SECOND EDITION // CHAPTER : 3 : FUNDAMENTAL CONCEPTS // EXAMPLE : 3.3 : clear ; clc ; close ; // Clear the work space and console // GIVEN DATA // For case (c) I_normal = 1000 ; // Normal full load curren...
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clear; clc; // P101.sce // (a) CÁLCULO DEL ESTADO ESTACIONARIO // Sistema de ecuaciones algebraicas function dxdt = f(x) // Variables h = x // Balance de materia dhdt = (F1 + F2 - k*sqrt(h))/At // Derivadas dxdt = dhdt endfunction // Constantes At = 0.5; // m2 F1 = 1; // m3/h F2 = 5; // m3/h...
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clc //initialisation of variables z=40//mm q=28//m w=1*21/49//mm //CALCULATIONS P=z/q//mm //RESULTS printf('the workpicece handle the circle=% f mm',P)
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//Example 7.35 // Integral Control of a Motor Speed System xdel(winsid())//close all graphics Windows clear; clc; //------------------------------------------------------------------ //Transfer function model num=1; s=poly(0,'s'); den=(s+3); G=syslin('c',num/den); sys=tf2ss(G) // State space represen...
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clc; //Example 28.6 //page no 434 printf("Example 28.6 page no 434\n\n"); //comparison between flow in pipes and open channel flow //water is passing through a trapezodial channel l_b=20//length of bottom base,ft l_t=50//length of top base,ft h=7.5//height of channel,ft A = (l_b+ l_t)*(h/2)//cross sectional ar...
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clear; clc; //Caption:If input is high in NAND gate //Given Data //For transistor Vbesat=0.8;//in V Vy=0.5;//in V R = 5;//in K Rc = 2.2;//in K //For diode Vyd=0.6;//in V Vdrop=0.7;//in V //The logic levels are Vcesato=0.2V for 0 state Vcesato=0.2;//in V //And Vcc = 5V for 1 state. Vcc = 5; // volts Vp = Vdrop + Vdr...
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clear clc G=[ %inf %inf 1.5 1 0 %inf 2.0 .5 3.5 %inf 0 0 0 %inf 2 .8 ] ld=[ 1 2 %i*.2 2 3 %i*.1 3 4 %i*.1 1 4 %i*.2 1 3 %i*.2 ] n=4 e=5 Y=zeros(n,n) for i=1:e ynew = 1/(ld(i,3)) y0=0 n1=real(ld(i,1)) n2=real(ld(i,2)) if(n1==0) Y(n2,n2)=Y(n2,n2)+yne...
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clear; clc; X=input('Enter the values of input sequence ='); M=length(X); N=4; for n=1:N x(n)=0; for k=1:M x(n)=x(n)+(1./N).*)(X(k)*exp(%i*2*%pi*(k-1)*(n-1)/N)); end disp(x(n./N)); end magH=abs(x./N); phaH=atan(imag(x),real(x)); figure(1); subplot(211); plot2d3(magH); xtitle('Magnitude') subplot(212); ...
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function [q2] = %ZQuat_t(q1) q2 = conj(q1); endfunction
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19 35:0.1 67:0.5 84:0.25 93:0.5 94:0.5 122:0.3333333333333333 235:0.25 277:0.4 331:0.3333333333333333 398:0.07142857142857142 451:0.5 545:1.0 939:0.5 1435:0.25 2860:1.0 4826:1.0 5858:1.0 19 1:0.125 12:0.019801980198019802 20:0.07142857142857142 45:0.5 122:0.6666666666666666 197:0.09090909090909091 305:0.333333333333333...
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//Generation of Pattern //1. linSI.m // // Clear previous variables and graphics windows // clear ; //plotlibmode // // Set parameters // fc = 40; n = 480; i= 1; nphases = 3; // number of phases nangles = 3; // number of angles theta=linspace(0,%pi,nangles+1); theta=theta(1:nangles); phi=linspace(0,2*%pi,nphases+1)...
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//Chapter 14, Problem 7 clc; Vrms=240; //rms voltage Vp=Vrms/0.707; //peak voltage Vav=0.637*Vp; //average value of voltage printf("Peak voltage = %f V\n\n",Vp); printf("Mean value = %f V",Vav);
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//Example 4.15 clc; Ifsd=1*10^-3; //Full scale deflection current Rm=200; //Meter resistence Erms=10; //RMS voltage Range=0.45*Erms; //RMS to DC value //Using Sensitivity S=1/Ifsd; //Sentitivity of meter Rs=S*Range-Rm; //Multiplie...
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///withoutPrompt //function void() /// @@prerequisite ( trick here I do not want scilab to execute the f code) load batch1.cos freq_list=[.1 1 2 4]; /// \sleftarrow{\normalfont list of frequencies to consider} k=find(%cpr.sim.labels=='toto'); /// \sleftarrow{\normalfont block number} idx=%cpr.sim.rpptr(k):%cpr.sim...
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clc pathname=get_absolute_file_path('7_6_1.sce') filename=pathname+filesep()+'761.sci' exec(filename) printf(" All the values in the textbook are Approximated hence the values in this code differ from those of Textbook") deltaH=m3*H3-m1*H1-m2*H2 disp("From tables, Vdot=0.1166 m^3/kg") Vdot=0.1166 A=%pi*(ID/2)^...
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function [rowspace, dimR, colspace, dimC, nullspace, dimN] = spaceRCSN(A) [m, n] = size(A); r = rank(A); echelon = rref(A); rowspace = zeros(r, n); colspace = zeros(r, m); k = 1; for i=1:m if ~and(echelon(i, :)==0) then rowspace(k, :) = echelon(i, :); ...
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//Example No.4.14. //Page No.140. //The mass of the particle. clc;clear; E = 0.025*1.6*10^(-19);//Lowest energy. h = 6.626*10^(-34);//Planck's constant. L = 100*10^(-10);//Width of the well -[m]. m = ((h^(2))/(8*E*L^(2))); printf("\nThe mass of the particle is %3.3e kg",m);
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////given V1=.82 //volts V2=1.85 //volts lembda1=4.0*10**-7 //m lembda2=3.0*10**-7 e=1.6*10**-19 c=3.0*10**8 //m/s //Calculation lembda=(1/lembda2)-(1/lembda1...
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//EXAMPLE 5.8 //Cicular convolution clc; clear; g = [1 2 0 1]; disp(g,'g[n] = '); h = [2 2 1 1]; disp(h,'h[n] = '); G = fft(g,-1); H = fft(h,-1); Y = G.*H; yc = fft(Y,1);//IDFT of Y disp(yc,"circular convolution,yc = ") n=0:3; clf(); figure(0); a = gca(); plot2d3(n,yc,2); plot(n,yc,'r.'); a.x_location = 'origin'; a.y_l...
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//2.31 clc; Vm=400*2^0.5/3^0.5; alph=0; Vdc_max=3*3^0.5*Vm/(%pi)*cosd(alph); Vdc=0.5*Vdc_max; alph=acosd(0.5); printf("Firing Angle = %.2f degree", alph) R=10; Idc=Vdc/R; disp('For discontinious load') Vrms=(3^0.5*Vm)*(3*3^0.5/(4*%pi)*cosd(2*alph)+0.5)^0.5; printf("\nRMS value of voltage = %.2f V", Vrms) I...
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clc syms k; disp('total probability= integrate (f,x,0,6 )=') p=integrate ('k*x','x',0,2) q=integrate ('2*k','x',2,4) r=integrate ('-k*x+6*k','x',4,6)
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errcatch(-1,"stop");mode(2);//Theory problem exit();
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// Example 2.11: Calculate base current , Collector current and Collector to emitter voltage Vcc=20;// Colector voltage in volts Rb= 400;// in KILLO OHMS Beta=100;//Common emitter D.C. Current gain Rc=2;// Collector resistance in killo ohms Re=1;// Emitter resistance in killo ohms Ib= Vcc / (Rb + (Beta*Re)); Ic=...
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//Shubham Sharma //Msc PhD OR //Roll no: 18i190002 clc clear function [i,k]=JobsDoneInOneArrival(lembda,mu,x) summ=0 y=grand(1,1,"exp",1/lembda) k=y for i=0:x p= grand(1,1, "exp",1/mu) summ=summ+p if summ>=y then break end end endfunction M = 10000; X0 =...
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r=2.2*10^6; i=6*10^(-6); disp("Part a"); v=i*r; disp("the potential difference (in V) across the resistor is"); disp(v); disp("Part b"); g=10^(-6); v1=12; r1=1/g; i1=v1/r1; disp("the new current (in μA) is"); disp(i1*10^6);
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off echo,msg; on latex; (a+b)**5\(a-b)**4; x:=(a+b)**3; {x,DF(x,a),DF(x,a,2)}; {{a,x},x}; ON VERBATIM; SOLVE(a^7-13*a+5); SOLVE(a**(2*y)-3*a**y+2,y); OFF VERBATIM; DEPEND a,c; DF(x,c,2); DEFID al,NAME=alpha; DEFID be,NAME=beta; SIN al**2+COS al**2=1; SIN(al+be)=SIN al*COS be+COS al*SIN be; OFF LASIMP; DEFID u,FONT=bold...
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//Chapter 2 //Example 2.4 //Ex3inPerUnit //Page 32 clear;clc; //Given values Vll = 4.4e3; Zline = 1.4 * (cos(75 * %pi / 180) + %i * sin (75 * %pi / 180)); Zload = 20 * (cos(30 * %pi / 180) + %i * sin(30 * %pi / 180)); Vbase = Vll; Ibase = 127; Zbase = (Vbase / sqrt(3)) / Ibase ; //Displaying the given values and th...
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//example 4.2 //page 161 clc; funcprot(0); // Initialization of Variable h=2; d=2.5/100; g=9.81; pi=3.14; Cd=0.65;//coeff of discharge A=pi*d^2/4; Q=Cd*A*sqroot(2*g*h); disp(Q*1000,"flow rate(l/s)="); clear
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// to find coefficient of velocity speed ratio,jet diameter //ex 5.5 pgno119 clc cv=0.98//velocity of volume g=9.8//gravity h=130//head loss V1=cv*(sqrt(2*g*h))//velocity of jet mprintf('\n velocity of the jet = %f m/s',V1) s=0.46//specific gravity u=s*V1//velocity mprintf('\n u = %f m/s',u) N=200//Rotatio...
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//Ex 3.7 clc;clear;close; format('v',6); fo=3;//kHz Ap=4;//Band pass gain alfa=1.414;//for butterworth filter C1=0.01;//micro F(Assumed) C2=alfa^2*C1/4;//micro F R=1/(2*%pi*fo*10^3*sqrt(C1*10^-6*C2*10^-6))/1000;//kohm Rf=2*R;//kohm(Assumed) disp("Design values are :"); disp(C1,"Capacitance C1(micro F)"); di...
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//CHAPTER 2 ILLUSRTATION 1 PAGE NO 57 //TITLE:TRANSMISSION OF MOTION AND POWER BY BELTS AND PULLEYS clc clear //=========================================================================================== //INPUT DATA Na=300;//driving shaft running speed in rpm Nb=400;//driven shaft running speed in rpm Da=60;//...
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clc; //e.g 17.6 Ton=30*10**-3; Toff=10*10**-3; Vdc=200; a=Ton/(Ton+Toff); disp(a); Vl=Vdc*a; disp('V',Vl*1,"Vl=");
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//Ex:8.26 clc; clear; close; nt=0.18;// total efficiency Eg=1.43;// band gape energy eV V=2.5;// appied voltage in volt n_ex=(nt*(Eg/V))*100;// external efficiency printf("The external efficiency =%f %%", n_ex);
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codeblock readtextfile(ScriptDir+"\_TOOLS.sci"); codeblock readtextfile(ScriptDir+"\_SSYS.sci"); codeblock readtextfile(ScriptDir+"\_Movie\_PlanetariumTools.sci"); ########################################################################################################### #############################################...
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//Example 6-16// //Reduce using mapping// clc //clears the console// clear //clears all existing variables// //Mapping the expression// disp('Y=m(0,2,4,8,10,13,15,16,18,20,23,24,26,32,34,40,42,45,47,48,50,56,57,58,60,61)') disp(' B'' B ') disp(' E...
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//Book Name:Fundamentals of Electrical Engineering //Author:Rajendra Prasad //Publisher: PHI Learning Private Limited //Edition:Third ,2014 //Ex2_9.sce. clc; clear; R1=3; R2=4; R3=2; R4=1; //case (a) a1=13;b1=-6;c1=20; //these are the coefficient values of VA,VB and so...
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//Ex:3.8 clc; clear; close; I_sc=19;//in uA R=1000; R_m=968; V_out=I_sc*(R*R_m/(R+R_m)); printf("Voltage produced = %d uV",V_out);