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@relation vehicle @attribute Compactness integer[73,119] @attribute Circularity integer[33,59] @attribute Distance_circularity integer[40,112] @attribute Radius_ratio integer[104,333] @attribute Praxis_aspect_ratio integer[47,138] @attribute Max_length_aspect_ratio integer[2,55] @attribute Scatter_ratio integer[112,26...
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// Value of polynomial p(x), evaluated at x // 11.16 // finds the value of a polynomial in powers of z^{-1} // function Y = filtval(P,z) function Y = filtval(P,z) N = length(P)-1; Q = polyno(P,'x'); Y = horner(Q,z)/z^N; endfunction;
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exec("swigtest.start", -1); // TODO: add tests here exec("swigtest.quit", -1);
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clc //initialisation of variables V= 20 //L m= 0.050 //gms M= 29 //gms T1= 20 //C T2= 150 //C k= 1.4 V1= 0.05 //m^3 //CALCULATIONS p1= m*R*(273.15+T1)/(M*(V/10)) p2= m*R*(273.15+T2)/(M*(V/10)) dU= p1*V1*(((273.15+T2)/(273.15+T1))-1)*100/(k-1) dH= k*dU //RESULTS printf (' intial pressure = %.1f kPa',p1) ...
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flist =[] dlist =[] i = 1 while i<54 if sum(sizelist(i)==[180:210]) if sum(xlist(i)==[35:38]) flist = [flist 261.63*2] dlist =[dlist 1] end if sum(xlist(i)==[26:32]) flist = [flist 293.66*2] dlist =[dlist 1] end if sum(xlist(i)==[19:25]) flist = [flist 329.63*2] dlist =[dlist 1] end if sum(xlist(...
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<?php class Forms_[[NOM_TABLE_MAJ]] extends Zend_Dojo_Form { // protected $_standardElementDecorator = array( // 'ViewHelper', // array('decorator' => array('td' => 'HtmlTag'), 'options' => array('tag' => 'td')), // array('Label', array('tag' => 'td')), // array('decora...
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function [y] = dirichlet(x) m=length(x) y=zeros(x) for i=1:m do for k=1:10^4 do y(i)=y(i)+1/k^x(i) end end endfunction x=linspace(1.1,5.50) y=dirichlet(x) clf plot(x,y) xtitle("Funkcja Dirichleta",'x','D(x)') xtitle("Ivan Napolskykh")
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//Mesh Analysis A=[4,-2;998,24.5] I=inv(A)*[1/1000;0] disp(I) P1=I(2)^2*2.5*1000 P2=1/1000*I(1) P3=-10^6*I(1)*I(2) P=[P1,P2,P3] disp(P)
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clear;lines(0); x=[0:0.1:2*%pi]'; plot2d(x,sin(x)) xclea(1,1,1,1)
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(X (X (X (X (X (X a) (X Lorillard)) (X spokewoman)) (X (X said) (X ,))) (X (X ``) (X This))) (X (X is) (X (X (X an) (X (X old) (X story))) (X .)))) (X (X there) (X (X is) (X (X (X no) (X asbestos)) (X (X in) (X (X (X (X our) (X products)) (X now)) (X (X .) (X ''))))))) (X (X (X it) (X (X has) (X (X no) (X bearing)))) (...
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// Scilab Code Ex5.23: Page-295 (2008) clc; clear; h = 6.62e-034; // Planck's constant, Js m = 9.1e-031; // Mass of the electron, kg v = 1e+003; // Velocity of the electron, m/s delta_v = v*0.05/100; // Minimum uncertainty in the velocity of the electron, m/s delta_x = h/(m*delta_v); // Minimum unc...
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clear dia = 50 //mm - diameter of aluminium p = 100 // KN - instant force applied dia_c = 0.01215 //mm- change in diameter l_c = 0.219 //mm - change in length l = 300 //mm - length strain_dia = -dia_c/dia // lateral strain strain_l = -l_c/l //longitudinal strain po = strain_dia/strain_l // Poisson ratio area = 3.14*dia...
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clc; clear; close; //pagec no 107 //Figure 4.13 Ri=20*10^3; //In Ohm Vin=0.4; //In Volt Rl=1*103;//In ohm gm=1/Ri; //unit-micro*Siemens Iload=gm*Vin; disp("A",Iload,"Load current is"); //maximum current is 20microAmp in Op Amp Vout=(Ri+Rl)*Iload; disp("V",Vout,"V max ");
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-> solution [5,3],NONTRIVIAL -> solution [5,3],NONTRIVIAL -> solution [5,3],NONTRIVIAL -> solution [5,3],NONTRIVIAL -> solution [5,3],NONTRIVIAL
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//Chapter 7 Ex12 clc; close; //let ten's digit be x, thus unit's digit is 9-x //number=10x+9-x=9x+9 //number obtained by reversing digits=10(9-x)+x=90-9x //polynomial is: 18x-144=0 mycoeff=[-144 18]; p=poly(mycoeff,"x","coeff"); ans=9*roots(p)+9; //since given number as calculated in line 6 printf("The numb...
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clc clear mprintf('Mechanical vibrations by G.K.Grover\n Example 4.11.3\n') //given data J=0.049//moment of inertia in kg-m^2 Kt=0.98//stiffness in N-m/rad Ct=0.11//damping coefficient in N-m_sec/rad N=15//R.P.M thetaRD=2//relative amplitude between ring and shaft in degrees //calculations W=N*2*%pi/60 //freq...
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//CHAPTER 5 ILLUSRTATION 4 PAGE NO 162 //TITLE:Inertia Force Analysis in Machines clc clear pi=3.141 D=.10// Diameter of petrol engine in m L=.12// Stroke length in m l=.25// length of connecting in m r=L/2 mR=1.2// mass of piston in kg N=1800// speed in rpm...
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//Find relative permeability and Intensity of magnetisation //Ex:14.1 clc; clear; close; x=1500;//susceptibility h=2400;//mafnetic field in A/m u_r=1+x; disp(u_r,"relative permeability = "); m=x*h;//in A/m disp(m,"Intensity of magnetisation (in A/m)"); u_0=4*3.14*10^-7; b=u_0*u_r*h;//in T disp(b,"Remanance...
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//Ductility clear; clc; printf("\tExample 6.4\n"); di=12.8; //Initial dia in mm df=10.7; //Final dia in mm printf("\n\tPart A"); //Ductility in terms of Reduction Area RA = ((di^2-df^2)/di^2)*100; printf("\npercent reduction in area is %d %%\n",RA); //End
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clc;clear; //Example 2.3 //given values d=6*10^-3;//distance between plates in m V=900;//potential difference in V B=0.5;//uniform magnetic field in Wb/m^2 Q=1.6*10^-19;//the charge on electron in C R=10.6*10^-2;//circular track radius in m //calculation v=V/(B*d); m=R*Q*B/v; disp(m,'The mass(in kg) of p...
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//Program to show usage of subplot function //subplot function produces a figure as a matrix x=linspace(-2*%pi,2*%pi,1000); //1st figure of a 2X2 figure matrix subplot(221) plot(x,sin(x),'r*') title('Plot for sin(x)') xlabel('x') ylabel('sin(x)') //2nd figure of a 2X2 figure matrix subplot(222) plot(x,s...
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//To calculate the Hall coefficient Vy = 37; //voltage, micro-V Vy = Vy*10^-6; //voltage, V t = 1; //thickness, mm t = t*10^-3; //thickness, m Bz = 0.5; //flux density, Wb/m^2 Ix = 20; //current, mA Ix = Ix*10^-3; //current, A RH = Vy*t/(Ix*Bz); //Hall coefficient, C-1 m^3 pri...
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//example 12.3 //page 450 clc; funcprot(0); //initialisation of variable Q1=82;//flow rate Q2=100;//flow rate H1=17.5;//head of water H2=20;//head of water d1=36;//diameter N1=1500;//rpm k1=Q2/Q1*N1*d1^3;//k1=N2*d2^3; k2=H2/H1*N1^2*d1^2//k2=N2^2*d2^2; d2=(k1^2/k2)^(1/4); disp(d2,"diameter (cm)"); N2=k1/...
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function output = soustractionPBM(pbm1, pbm2) endfunction
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function see_possibility(S) // S= sudoku with 9 rows and 9 columns S_pos=[] for i=1:9 row=[] for j=1:9 if S(i,j)==0 then P=possibility(i,j,S) else P=S(i,j) end row=[row strcat(string(P),',')] end S_pos=[S_pos;row] end ...
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//chapter27 //example27.3 //page578 h11=10 h12=1 h21=-1 h22=0.2 rL=5 // ohm Zin=h11-(h12*h21/(h22+1/rL)) Av=-h21/(Zin*(h22+1/rL)) printf("input impedence = %.3f ohm \n",Zin) printf("voltage gain of circuit = %.3f \n",Av)
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//exapple 1.12 clc; funcprot(0); // Initialization of Variable pi=3.14159; alpha=22+36/60;//altitude of star A=42//azimuth angle delta=40;//latitude of observer //in triangle ZPM(figure in book) PZ=(90-delta)*pi/180; A=A*pi/180; ZM=(90-alpha)*pi/180; PM=acos((cos(PZ)*cos(ZM)+sin(ZM)*sin(PZ)*cos(A))); t...
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// Scilab Code Ex1.21 Fractional speed of electron: Pg:29 (2008) m0 = 9.1e-031; // Rest mass of an electron, kg c = 3e+08; // Speed of light, m/s E = 0.5*1e+06*1.6e-019; // Kinetic energy of electron, J // As E = (m - m0)*c^2, solving for m m = E/c^2+m0; // Mass of moving electron, kg // As m = m0/sqr...
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// Aim:To convert given pressure into absolute pressure // Given: // Gage Pressure: Pg=-5; //psi
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// A => B, k(T) function dy = model(t, y, T) A = y(1) B = y(2) k0 = 1e11 // L/(mol*s) R = 8.314e-3 // kJ/(mol*K) Ea = 78 // kJ k = k0*exp(-Ea/(R*T)) dAdt = -k*A dBdt = k*A dy=[dAdt, dBdt] endfunction // A0 = 2 B0 = 0 y0 = [A0; B0] // order t0 = 0 t = linspace(0,300) y = ode(y0, t0, t, list(model, ...
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// Scilab Code Ex5.5 : Phase retardation for quartz : Page-114 (2010) lambda = 500e-09; // Wavelength of incident light, m mu_e = 1.5508; // Refractive index of extraordinary ray mu_o = 1.5418; // Refractive index of ordinary ray t = 0.032e-03; // Thickness of quartz plate, m dx = (mu_e - mu_o)*t; /...
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//Example 2.8 //Derive equtations for temprature distribution. //calculate the maximum temp. in the assembly //Given ka=24 //W/mC thermal conductivitiy of material A tA=0.1 //m, thickness of A material kB=230 //W/mC thermal conductivity of metl B kC=200 //W/mC thermal conductivity of...
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clear; clc; printf("\n Example 14.1"); //Assuming that the steam is dry and saturated at 205 kN/m2, then from the Steam Tables in the Appendix, the steam temperature = 394 K at which the total enthalpy = 2530 kJ/kg. //At 13.5 kN/m2, water boils at 325 K and, in the absence of data on the boiling point elevation,t...
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; @Harness: simulator ; @Format: atmel ; @Arch: avr ; @Purpose: "Test the ASR (arithmetic shift right) instruction" ; @Result: "r16 = -64, flags.c = 1, flags.s = 1, flags.n = 1" start: ldi r16, 0b10000001 asr r16 end: break
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// A Texbook on POWER SYSTEM ENGINEERING // A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar // DHANPAT RAI & Co. // SECOND EDITION // PART II : TRANSMISSION AND DISTRIBUTION // CHAPTER 18: POWER DISTRIBUTION SYSTEMS // EXAMPLE : 18.4 : // Page number 439 clear ; clc ; close ; // Clear the work space and ...
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clear //Given e=8.854*10**-12 h=6.62*10**-34 m=9*10**-31 e1=1.6*10**-19 //Calculation // r1=((e*h**2)/(%pi*m*e1**2))*10**10 v1=e1**2/(2*e*h) n=2*r1 //Result printf("\n Radius of first orbit is %0.2f A",r1) printf("\n Velocity of electron is %0.1f *10**6 m/s",v1*10**-6) printf("\n Size of hydrogen atom is %0.2f A",...
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clear; clc; printf("Example 1.12"); //[BIG "oh"]f(n)=O(g(n)). (big oh notation). printf("\n \n 3n+2=O(n) as 3n+2<=4n for all n>=2."); printf("\n \n 3n+3=O(n) as 3n+3<=4n for all n>=3.");............// O(n) is called linear. printf("\n \n 3n+2=O(n) as 100n+6<=101n for all n>=10."); printf("\n \n 10n^2+4n+2=O(n^2)...
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clf xo=1; xmax=5; N=100; h=(xmax-x0)/(N-1); y1=zeros(1,N); y1(1)=2; y=2*exp(atan(x)-%pi/4) for i=1:N-1 y1(i+1)=y1(i)+h*((y1(i)/(1+x(i)*x(i)))); end y2=zeros(1,N); y2(1)=2; for i=1:N-1 y22=y2(i)+h*((y2(i)/(1+x(i)*x(i)))); y2(i+1)=y2(i)+(h/2)*((y2(i)/(1+x(i)*x(i)))+(y22/(1+x(i+1)*x(i+1)))); e(i+1)=abs(...
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//ex2.14 find the power delivered to the load and the peak voltage at the load-end of the line ZL=50; Z0=50+%i*50; Tl=(ZL-Z0)/(ZL+Z0); VSWR=(1+abs(Tl))/(1-abs(Tl)); disp('VSWR = '+string(VSWR)); vmax=50; PL=0.5*vmax^2/(VSWR*real(Z0)); RL=50; VL=sqrt(PL*RL*2); disp('Peak voltage at the load = '+string(VL)+' V','Power ...
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// Electric Machinery and Transformers // Irving L kosow // Prentice Hall of India // 2nd editiom // Chapter 8: AC DYNAMO TORQUE RELATIONS - SYNCHRONOUS MOTORS // Example 8-8 clear; clc; close; // Clear the work space and console. // Given data from Ex.8-3a // 3- phase Y-connected synchronous motor P = ...
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// Calculating possible phase angles clc; Y1=1.25; Y2=2.5; PA=asind(Y1/Y2); disp(PA,'phase angle (degree)') disp('possible angle are 30 degree and 330 degree')
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<?xml version="1.0" encoding="utf-8"?> <test> <description>NS, Couette flow, mixed bcs, WeakDG advection and IP diffusion, Implicit</description> <executable>CompressibleFlowSolver</executable> <parameters>Couette_WeakDG_IP_MODIFIED_IM_PRECON.xml</parameters> <files> <file description="Session F...
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clc(); clear; //To determine the distance between centres of central maximum and the fourth dark fringe n=4; lambda=589.6*10^-9; //wavelength D=0.95; //distance of the screen from the slit w=0.28*10^-3; //width of the slit d=((n*lambda*D)/w)*10...
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//============================================================================== // chapter 1 example 16 clc; clear; //input data m = 9.1*10^-31; // mass of electron in kilograms e = 1.6*10^-19; //charge of electron in coulombs n = 1; //bragg's reflection h1 ...
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clear close clc s = poly(0,'s'); G = s^5 + 3*s^4 + 5*s^3 + 4*s^2 + s +3; disp(routh_t(G));
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NWChem topology file for caa_em Generated by the NWChem prepare module 4.60000008/26/10 23:01:31 amber 1 26 17...
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//Example 3.20 //Complex logical Expression funcprot(0); printf("\nEnter error value and count value:"); printf("\nEnter Error: ") error=scanf("%f"); printf("\n Enter Count: ") count=scanf("%f"); ans=error >.0001 & count <100; disp(ans,"error >.0001 & count <100"); ans=error >.0001 | coun...
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// Example 2_6 clc;funcprot(0); // Given data // T(z)=15-0.00651°C z_0=0;// m P=101;// m z_1=3000;// m // Calculation // Using the given equation for T(z) we have // dP=P/(29.3)*(288-0.00651 z) // By solving this equation,we get P=101*exp(-0.368);// kPa printf("\nThe pressure at an elevation of 3000 m,P=%...
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// Example 24_31 clc;funcprot(0); //Given data T_1=288;// K p_1=1;// bar R_c=2.5;// Pressure ratio of each compressor stage R_c1=R_c; R_c2=R_c; T_3=300// K T_5=1000;// K W_2=100;// kW/kg of air p_l1=0.2;// Pressure loss in air side of H.P and main combustion chamber in bar p_l2=0.1;// Pressure loss in rehe...
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//Problem 36.04: A complex voltage is represented by // v = 10sinwt + 3sin(3wt) + 2sin(5wt) Volts //Determine for the voltage, (a) the rms value, (b) the mean value and (c) the form factor. //initializing the variables: A1 = 10; // in volts A3 = 3; // in volts A5 = 2; // in volts //calculation: //the rms va...
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// Grob's Basic Electronics 11e // Chapter No. 20 // Example No. 20_5 clc; clear; // Calculate L of the coil when the frequency is 1000 Hz. // Given data Xl = 6280; // Inductive reactance=6280 Ohms f = 1000; // Frequency=1000 Hz pi = 3.14; L = Xl/(2*pi*f); disp (L,'The value of Inductor in He...
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// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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R=1.987;//universal gas constant// T=556;//temperature in kelvin// E=44;//Energy in Kcal// dS=-10;//entropy change in cal per deg// k=(exp(2)*exp(dS/R)*exp(-E/(R*T))*10^13.07);//rate constant for the reaction// printf('Rate constant for the reaction=k=3.47*10^-7litre per mol per sec');
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function [stk,txt,top]=sci_echo() // Copyright INRIA RHS=[] for k=1:rhs RHS=[RHS stk(top-rhs+k)(1)] end txt=['//! echo '+strcat(RHS,' ')+' ignored' '// echo '+strcat(RHS,' ')] write(logfile,'echo '+strcat(RHS,' ')+' ignored at line '+string(lcount)) stk=list(' ','-2','0','0','1')
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//Chapter 3 //Example 3_31 //Page 64 clear;clc; max_l=60000; min_l=20000; peak_l=50000; lf=1; n_steam=0.6; s=poly(0,"s"); p=333*s^2+24000*s-338000; r=roots(p); x=r(1); y=40000*round(x)/24; steam_capacity=max_l-y; printf("x=%d \n", x); printf("y=%d kW \n", y); printf("Capacity of steam plant = %d kW \n", steam_capac...
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//Example 15.31 //time domain specifications of second order system clear;clc; xdel(winsid()); mode(0); //converting the given differential equation in "s" domain //since x and y are constants //therefoere considering "x=y=1" s=%s; g=s^2+5*s+7; x=coeff(g) //comparing with the standard equation...
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//problem 9-17 data //matrices size n*n n=60; //floating point multiplier pipeline segments = 4 //floating point adder pipeline segments = 4
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// Chapter7 // Page.No-287 // Example_7_15 // Design of squarewave oscillator // Given clear;clc; fo=1*10^3;; // Frequency of oscillation R1=10*10^3; // Assumption C=0.05*10^-6; // Assumption R2=1.16*R1; printf("\n Resistance R2 is = %.1f ohm \n",R2) // Result R=1/(2*fo*C); printf("\n Resistance R is = %.1f...
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// clear previous calculations close; clc; clear; close; // Independent Parameters gamma_a = 1.4; gamma_e = 1.33; R = 287; T_a = 223.252; P_a = 16500; h_c = 43000000; FA_st = 0.06; T_max = 2600; cp_a = (gamma_a/(gamma_a-1)*R); cp_e = (gamma_e/(gamma_e-1)*R); M = [1:0.25:6]; //setting up empty matrices To_4 ...
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//to determine in F2,peak rotor AT, max torque, ele i/p at max torque(motoring mode),open ckt voltage(generating mode) clc; disp('motoring mode'); K_w=.976; N_pole=746; p=4; I_f=20; F2=(4/%pi)*K_w*(N_pole/p)*I_f; disp(F2,'F2(AT)'); B_r=1.6; D=.29; l=.35; T_max=(p/2)*(%pi*D*l/2)*F2*B_r; disp(T_max,'T_max'...
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//Ex3_9 clc V = 4.5*10^-3//applied dc voltage r = 100// given resistance I = V/r//flow of current disp("DC voltage = "+string(V)+"V") disp("The current in 100 ohm = "+string(I)+"A")
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g=9.8; b_a = 0.1; m=1; b=30; k=100000; // x(t) > 0 A=[0, 1 ; 0 , - b_a / m]; Ap= A + [0.001, 0; 0, 0]; B = [0; -g]; u = 1; x0 = [10; 0]; t1 = [0:0.0001:1.47]; x1 = ltisol(Ap,B,u,x0, t1); //plot(t1,x1); // x(t) <= 0 p1 = 14643 A=[0, 1 ; -k/m , - b / m]; x0 = [0; x1(2,p1)]; t2 = [t1(p1):0.00001:1.50]; x2 = ltisol...
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//Ex 5.5 clc;clear;close; Vo=0.7;//V Vsat=12;//V R1=10;//kohm R2=60;//kohm Vth=R1/(R1+R2)*Vo;//V iDmax=(Vsat-Vo)/R1-Vo/(R1+R2);//mA disp(iDmax,"Maximum current(mA) : ");
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// Grob's Basic Electronics 11e // Chapter No. 14 // Example No. 14_3 clc; clear; // A coil with 400 turns must provide 800 A t of magnetizing force. How much current is necessary? // Given data mmf = 800; // Magnetizing Force=800 A.t N = 400; // No. of Turns=400 I = mmf/N; disp (I,'The Current ...
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exec VideoReader.sci exec has_frame.sci exec readframe.sci myVideo = VideoReader('vid2.mp4'); disp(myVideo) while hasFrame() stacksize('max') F = readFrame(); length_out = size(F); for i = 1 : length_out N(:, :, i) = F(i); end J_list = detecting(N); imshow(J_list); end close()
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//signals and systems //time domain analysis of discreet time systems //energy of a signal clear; close; clc; n=0:1:5 figure a=gca(); plot2d(n,n); energy=sum(n^2) power=(1/6)*sum(n^2) disp(energy) disp(power)
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//Exa 6.5 clc; clear; close; // given : f=20 //ferquency in MHz f=20*10^6 //frequency in Hz c=3*10^8 //speed of light in m/s K=0.74 // constant lambda=c/f //wavelength in meter Delta=20 // angle of elevation in Degrees H=lambda/(4*sind(Delta)) // Rhombic height in m phi=90-Delta // tilt angle in Degrees l=...
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solution1_4.sce
//Obtain path of solution file path = get_absolute_file_path('solution1_4.sce') //Obtain path of data file datapath = path + filesep() + 'data1_4.sci' //Clear all clc //Execute the data file exec(datapath) //Calculate ratio factor Fi Fi = (b/a)^(1/n) //Use R10 series //Initialise c c = a //Use 'for' loop...
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Ex11_4.sce
clear // //Initialisation v1=5 //constant 5V r=10 //resistance in Ohm vrms=5 //sine wave of 5 V r.m.s vp=5 //5 V peak //Calculation p=(v1**2)*r**-1 //Power in watts p2=(vrms**...
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17_09.sce
//Problem 17.09: The winding of an electromagnet has an inductance of 3 H and a resistance of 15 ohm. When it is connected to a 120 V, d.c. supply, calculate: (a) the steady state value of current flowing in the winding, (b) the time constant of the circuit, (c) the value of the induced e.m.f. after 0.1 s, (d) the tim...
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clc //initialisation of variables t1=120//F t2=82//F s1=2800//ft p=14.7//ft p1=1.3//ft pv=0.5410//psia s2=0.622//ft s=0.02372//lb per lb dry air //CALCULATIONS P=pv-((p-pv)*(t1-t2)/(s1-p1*(t2)))//psia H1=s2*(P/(p-P))//lb per lb dry air H2=s2*(pv/(p-pv))//lb per lb dry air M=H2-H1//lb per lb dry air S=s-H...
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// Chapter7 // Page.No-264 // Example_7_6_b // Frequency response of second order highpass filter // Given clear;clc; Af=1.586; // Passband gain of the filter fl=1000; // Cut-off frequency f1=100; // Input freq in Hz av1=Af/sqrt(1+(fl/f1)^4); printf("\n Gain magnitude av1 at f1 is = %.5f \n",av1) // Result f...
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//clear// clc clear //this code is only for Part C exec("9.2data.sci"); t = 55:1:121; function w=f(t,Y) w =zeros(2,1); k=.00017*exp(11273/(1.987)*(1/461-1/Y(1))) Qr=UA*(Y(1) -298) Theata=Nbo/Nao ra=-k*(Nao**2)*(1-Y(2))*(Theata-2*Y(2))/(U**2) rate=-ra Qg=ra*U*(dH) w(1)=(Qg-Qr)/NCp w(2)=(-ra)*U/...
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clc //initialisation of variables d=10//hr p=50000//in a=7.5//mgd w=0.75//mg s=5.03//mg //CALCULATIONS S=s/w//mg P=S-s//mg //RESULTS printf('a steady gravity supply equal to maximum daily=% f mg',P)
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//example 1 //chapter 45 //clc() m=1 lambda=4000//in A d=31700//in A theta=asind((m*lambda)/d) disp(theta,"The first order diffraction pattern in degree=")
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loadSrcImg.sce
function[] = loadSrcImg() // Load source image for the Main Window's source viewport // GUI-related variables global viewportSrcImg; global listboxSrcImg; global srcImg; // Load the pixel data from the filename specified by the // listbox containing source image filenames. srcImg = loadpg...
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4_11.sce
clc //initialisation of variables T1= 1000 //K T2= 300 //K k1= 6.0954 //cal deg^-1 mole^-1 k2= 3.2533*10^-3 //cal deg^-2 mole^-1 k3= -1.071*10^-6 //cal deg^-3 mole^-1 //CALCULATIONS dH= k1*(T1-T2)+(k2*(T1^2-T2^2)/2)+(k3*(T1^3-T2^3)/3) //RESULTS printf ('dH= %.f cal mole^-1',dH)
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clc; clear; //clears the console and all previously stored variables function V_0 = CRR_AmPut(S_0, r, sigma, T, M, K) delta_t = T/M; //calculation of delta_t Beta = (exp(-r*delta_t)+exp((r+sigma^2)*delta_t))/2; //calculation of beta for CRR u=Beta+sqrt((Beta^2)-1); //so u>d is true d=u^-1; //be...
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projet AxePrinc.sce
function [] = AxePrinc (composantes,lambda) for i=1:2 normeCarComposante = norm(composantes(:,i)) ^2; if(max(abs(C(i)-sqrt(n*lambda(i))))==0) then disp("C ok"); end end endfunction function M = composante(BON, Z) // fonction permettant de récuperer tout...
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// Example 3_9 clc;funcprot(0); // Given data T=100;// °F p=95.0;// psia // Calculation // From Table C.7a,C.8a of Thermodynamic Tables to accompany Modern Engineering Thermodynamics, v_1=0.5751;// ft^3/lbm (100°F,90.0 psia) v_2=0.5086;// ft^3/lbm (100°F,100.0 psia) p_i1=100;// psia (Pressure used for interp...
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2MetodoHeun.sce
clc() clear all clf() function result = solucionAnalitica(t) result = (4/1.3)*(exp(0.8*t)-exp(-0.5*t))+2*exp(-0.5*t) endfunction function result= eqdiff(y,t) result = 4*exp(0.8*t)-0.5*y endfunction function [result,points]=metodoHeun(stepsize,y0, t0, tf, eqf) points = t0:stepsize:tf result = (length...
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ex5_19.sce
//Chapter-5, Example 5.19, Page 178 //============================================================================= clc clear //v=350*cos(3000*t-20) //i=15*cos(3000*t-60) //INPUT DATA L=0.5;//inductance in Henry phi=-40;//phase difference between applied voltage and current //Xl>Xc(P.f is lagging) w=3000;//fr...
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Ex4_63.sce
clc; v1=6; // hoist speed i=60; // series current v=600; // supply voltage r=0.5; // net resistance g=9.81; // acceleration due to gravity v2=4; // reduced hoist speed Ea1=v-i*r; // counter EMf corresponding to v1 rx=((v-((v2/v1)*Ea1))/i)-r; printf('External resistance to be added is %f ohms',rx);
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kon.tst
tomba V;FUT soka V;PST puluka V;NFIN sangana V;FUT suama V;NFIN simba V;PST tanda V;FUT vova V;PRS tsuba V;PRS toma V;PST tsubula V;FUT sakumuna V;NFIN tanga V;PST suama V;FUT tatuka V;FUT pasuka V;NFIN semba V;PST sadisa V;NFIN tombola V;PRS sungika V;PRS tuta V;FUT suba V;NFIN tola V;FUT tumbula V;FUT tensika V;FUT...
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ex11_2.sce
clc //Example 11.2 //Calculate the average power printf("Given") disp('v=4*cos(%pi/6*t), V=4(0 deg), Z=2(60 deg)') Vamp=4;Vang=0;Zamp=2;Zang=60; //Let I be the phasor current Iamp=Vamp/Zamp Iang=Vang-Zang P=0.5*Vamp*Zamp*cos((Zang*%pi)/180) printf("P=%d W \n",P); t=-1:1:15 t1=-3:1:12 v=Vamp*cos(%pi/6*t) ...
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Ex4_2_2.sce
clc //initialization of variables d = 10 //cm s = 3 // km v = 500 //cm/sec nu = 0.15 // cm^2/sec //Calculations E = 0.5*d*v // cm^2/sec c1 = 1000 // m/km c2 = 1/100 // m/cm z = sqrt(4*E*c1*c2*s/v) percent = z*100/(s*c1) //Results printf(" The percent of pipe containing mixed gases is %.1f percent",percent...
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EX_2_18.sce
//Example 2.18//series equivalent of unknown impedence clc; clear; w=3000;//in rad/s R1=1.8;//in killo ohms C1=0.9;//capacitance in micro farads R2=9;//in killo ohms R3=0.9;// in kilo ohms Rx= ((w^2*(C1*10^-6)^2*R1*10^3*R2*10^3*R3*10^3)/(1+w^2*(R1*10^3)^2*(C1*10^-6)^2));// Lx=((R2*10^3*R3*10^3*C1*10^-6)/(1+w^2*(R1*10^...
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EX1_39.sce
//EXAMPLE 1-39 PG NO-32-33 V=440; //voltage V1=5; //voltage R=40; //resistance V2=220; V3=100; Rv=(V3*R)/[V2-V3]; //insulation resistance disp('i)Resistance (Rv) = ' + string (Rv)+' Kohm') Ri=[Rv*(V-V1)]/V1; //insulation resis...
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CPM Aerowalk combo kills.sce
Name=CPM Aerowalk combo kills PlayerCharacters=CPMer BotCharacters=All Strafes.bot IsChallenge=true Timelimit=90.0 PlayerProfile=CPMer AddedBots=All Strafes.bot PlayerMaxLives=0 BotMaxLives=0 PlayerTeam=1 BotTeams=2 MapName=aero_at.map MapScale=3.8125 BlockProjectilePredictors=true BlockCheats=true InvinciblePlayer=tru...
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start.sce
getd ../../../common_files/ exec ../../../common_files/loader.sce exec ser_init.sce exec pid_bda_tuned.sci xcos pid_tuned_setpoint.xcos
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induced_velocity_5.sce
clear; function [G,b,s,ds] = circulation(n,rho,u,L,ar,cl_avg,cla,A1,A2,A3,A4,B1,B2,B3) q = 0.5 * rho * u * u; area = L / (q * cl_avg); b = sqrt(ar*area); chord0 = area / (%pi/4 * b); s = ([0:1:n] + 0.5) * b / (n+1) - b/2; ds = b / (n+1); chord = chord0 * sqrt( 1 - (2*s/b).^2 ...
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ex4_82.sce
//AC Circuits : example 4.82 :(pg 4.66) V=230; f0=50; I0=2; Vco=500; R=V/I0; Xco=Vco/I0; C=(1/(2*%pi*f0*Xco)); L=(Xco/(2*%pi*f0)); printf("\nV = 230 V \nf0 = 50 Hz \nI0 = 2A \nVco = 500 V"); printf("\nR=V/I0 =%.f Ohm",R); printf("\nXco=Vco/I0 =%.f Ohm",Xco); printf("\nXco=1/2.pi.f0.C \nC= %.e F",C);//capaci...
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tst-scheddownasup-nested.tst
description = count scheduled downtime as uptime, nested sqlfile = test_nested_downtimes.sql global_vars { start_time = 1202684400 end_time = 1202770800 includesoftstates = 1 } down_dtstart_dtstart_dtend_dtend: normal { host_name { down_dtstart_dtstart_dtend_dtend } scheduleddowntimeasuptime = 0 correct { ...
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//Example 2.7:Convolution Integral clear; close; clc; t =-6:1/100:6; for i=1:length(t) if modulo(t(i),3)==0 then h(i)=1; else h(i)=0; end if t(i)<-1 then x(i)=0; elseif t(i)<0 x(i)=1+t(i); elseif t(i)<1 x(i)=1-t(i); else x(i...
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Ex6_2.sce
// Exa 6.2 clc; clear; // Given data /// Referring Fig. 6.5- Adjustable regulator Vo= 7.5; // Volts // Solution printf(' From the data sheeet of 7805, IQ=4.2 mA. Say, we choose IR1 = 25 mA.\n '); IQ = 0.0042; // Amperes IR1 = 0.025; //Amperes printf(' The voltage across load for 7805 is 5 Volts.\n '...
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example_10_2.sce
Mp=0.12 //given from table zeta=0.5594 Tp=0.2 omegaN=%pi/(Tp*sqrt(1-zeta^2)); disp(omegaN,"omegaN = ") Mr=1/(2*zeta*sqrt(1-zeta^2)) disp(Mr,"Mr = ") omegaR=omegaN*(sqrt(1-2*(zeta)^2)) disp(omegaR," omegaR= ")
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webpack.gulpfile.tst
import { mixin } from '@radic/build-tools' import { gulp, Gulpclass, GulpEnvMixin, GulpInteractiveMixin, Task } from '@radic/build-tools-gulp' import { build, GulpWebpackMixin, serve } from '@radic/build-tools-webpack' export interface Gulpfile extends GulpEnvMixin, GulpInteractiveMixin, GulpWebpackMixin {} @Gulpclas...