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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run1"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monito...
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clear // // // //Variable declaration lamda=5000*10**-8 //wavelength(cm) mew=1.5 //refractive index beta1=1 //assume S=6*beta1 //Calculation t=S*lamda/(beta1*(mew-1)) //least thickness of glass plate(cm) //Result printf("\n least thickness of glass plate is %0.0f *10**-4 cm",t*10**4)
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disp("∆Ed=13.64*(me/mo)*(1/(Єr^2)) eV"); disp("me = (0.015)*m0"); a=0.015; c=18; //say Єr=c d=13.64*(a)*(1/(c^2)); printf('the value of the ∆Ed = %f eV',d);
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//example 17.2 //design a submerged pipe clc;funcprot(0); //given q=0.04; //discharge through outlet D=100.0; //F.S.L of distributing canal wc=99.90; //F.S.L of water course dep=1.1; //full supply depth distributing canal C=0.7; //average value of coefficient of discharge ...
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//chapter11 //example11.17 //page222 del_Vbe=200 //mV del_Ib=100 // micro ampere Ri=del_Vbe/del_Ib printf("input resistance = %.3f kilo ohm \n",Ri)
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clear; clc; // Example: 6.2 // Page: 205 printf("Example: 6.2 - Page: 205\n\n"); // Solution // *****Data******// density_water = 0.998;// [g/cubic cm] density_ice = 0.9168;// [g/cubic cm] Hf = 335;// [J/g] T = 0 + 273;// [K] //*****************// V_water = 1/density_water;// [cubic cm/g] V_ice =...
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//example 4.3 clc; funcprot(0); k=0;//B/L; c2=30; Gamma=17.5; H=1.5; Df=1.2; H=1.5; B=2.0; Ks=2.5; phi=40; pi=%pi; qu=(1+0.2*k)*5.14*c2+(1+k)*Gamma*H^2*(1+2*Df/H)*Ks*tan(phi*pi/180)/B+Gamma*H; Qu=qu*B; disp(Qu,"bearing capacity in kN/m"); disp("there is slight variation due to rounding off error") //soi...
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//The flow conditions are assumed to be isentropic in nature. P1=20; //pressure of burned gas in combustion chamber in atm unit T1=3500; //temperature of the burned gas in combustion chamber in degree kelvin P2=0.5; //pressure of the gas at exit in atm y=1.15; //specific heat ratio for the gas
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clc;funcprot(0);//Example 9.24 //Initilisation of Variables A=25;...//Total surface area of furnance in m^2 V=10;...//Volume of furnance in m^3 Tw=500;....//Constant temparature in K Tg=1250;.....//Gas temparature in K Pg=2;....//Total pressure in atm Pco2=0.2*Pg;...//Carbondioxide Pressure containing in furnan...
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clc //initialisation of variables clear V1= 1800 //ft/sec a= 14 //degrees p= 0.75 //in h= 2 //in e= 0.02 //in vc= 0.89 v= 650 //ft/sec l= 9 //in P= 80 //psia T= 320 //F J= 50000 rh1= 7.6 //Btu/ per lb v1= 5.632 //cu ft per lb //CALCULATIONS VR1= sqrt((V1*cosd(a)-v)^2+(V1*sind(a))^2) VR2= vc*VR1 rh=...
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A=[8 -4 2;5 10 2;3 -1 7] b=[-22;-44;-53] D=A.*eye(A) InvD=inv(D) B=eye(A)-InvD*A g=InvD*b x=zeros(b) xOld=x x=B*x + g Er=max(abs(x-xOld))/max(abs(x)) Betas=ones(b) Bt=abs(B) Betas(1)=Bt(1,:)*Betas Betas(2)=Bt(2,:)*Betas Betas(3)=Bt(3,:)*Betas Bi=abs(spec(B))//Autovalores de B
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0 - 42*v - 32*v^2 - 8*v^3 - 16 - 21*v - 16*v^2 - 4*v^3 - 8 1 - 34*v - 32*v^2 - 8*v^3 - 17*v - 16*v^2 - 4*v^3 2 - 26*v - 32*v^2 - 8*v^3 + 24 - 13*v - 16*v^2 - 4*v^3 + 12 3 - 18*v - 32*v^2 - 8*v^3 + 56 - 9*v - 16*v^2 - 4*v^3 + 28 4 - 10*v - 32*v^2 - 8*v^3 + 96 - 5*v - 16*v^2 - 4*v^3 + 48 5 - 2*v - 32*v^2 ...
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errcatch(-1,"stop");mode(2);// Example 4.6, page no-211 c0=25 x0=0.5 x1=0.05 c1=c0*x0/(x0-x1) c2=c0*x0/(x0+x1) printf("C1=%.2f pF\nC2=%.2f pF",c1,c2) exit();
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clc clear //INPUT DATA n=2//no.of atoms in BCC structure d=7.86*10^6//density of iron of FCC structure in kg/m^3 AW=55.85//atomic weight of Fe N=6.023*10^23//Avogadro's Number per Kg mol //CALCULATION a=(((n*AW)/(d*N))^(1/3))/10^-10//The lattice constant in m r=((a*sqrt(3))/4)//The atomic radius of Fe which ...
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//Find the torque exerted on the crankshaft clc //given D=9//in stroke=24//in d=2//in l=60//in CP=l N=120 theta=40//degrees x=theta*%pi/180 P1=160//lb/in^2 P2=32//lb/in^2 OC=stroke/2 F=%pi*(D/2)^2*P1-%pi*(D/2)^2*P2+%pi*(d/2)^2*P2 //Ft*Vc=F*Vp; Where Vc and Vp are velocities of crank and pin respectively ...
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java make.Main -f make-tests/make05.mk -D make-tests/file05 C
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-- Fuzzy Logix, LLC: Functional Testing Script for DB Lytix functions on Teradata -- -- Copyright (c): 2014 Fuzzy Logix, LLC -- -- NOTICE: All information contained herein is, and remains the property of Fuzzy Logix, LLC. -- The intellectual and technical concepts contained herein are proprietary to Fuzzy Logix, LLC. ...
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clear; LK25 = fscanfMat("./pomiary/pomiar_LK_25.0%.txt"); LK50 = fscanfMat("./pomiary/pomiar_LK_50.0%.txt"); LK75 = fscanfMat("./pomiary/pomiar_LK_75.0%.txt"); LK100 = fscanfMat("./pomiary/pomiar_LK_100.0%.txt"); LS25 = fscanfMat("./pomiary/pomiar_LS_25.0%.txt"); LS50 = fscanfMat("./pomiary/pomiar_LS_50.0%.txt"); LS75...
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clc; p=0.263*10^5; //Pascal v=120; //volume in m cube t=223; //Kelvin R=8.31; //constant n=(p*v)/(R*t); //calculating n disp(n,"n = "); //displaying result m=n*4; //cal mass of He disp(m,"Mass of He = "); //displaying result
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clc clear //Input data V=25;//Volume of gasoline consumed by an engine in litres/hour cv=6*10^6;//The calorific value of gasoline in calories/litre P=35;//The output of the engine in kilowatts //Calculations h=V*cv;//Total heat produced by gasoline in one hour in calories H=h/3600;//Heat produced per se...
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//Example 4.5: Resistance clc; clear; close; //given data : l=65;// in cm V=0.1;// in V V1=5.5;// in V R=20;// in ohm E=V*l; I=V1/R; Ri=(E-V1)/I; disp(Ri,"Internal resistance,Ri(ohm) = ")
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<<<<<<< HEAD // Copyright (C) 2018 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Li...
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clear; clc; close; disp("Example 5.12") gm=1.1 M0=2.5 g1=[] z0=[0:0.1:4] i=2 for gm=1.1:0.1:1.4 gc1=1 for M=0:0.1:4 p0=(1+(gm-1)/2*(M^2))^(gm/(gm-1)) p20=.4*p0-.5*p0 M=3 p42=0.37 NPR=p20*p42 g1(gc1)=p0 gc1=gc1+1 end plot2d(z0,g1,i) xgrid title("Total-to-static pressure ratio") xlabel("Fli...
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clc //initialisation of variables T1=1100//k T3=200//k r=0.5 //CALCULATIONS T=(T1-(T3*r))/(1+r) //results printf(' \n value of T= % 1f k',T)
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//Section-9,Example-2,Page no.-E.57 //To find the transport number of copper ion. clc; L=0.420 //Loss of Cu in anode compartment{=(Y-X)} W=1.058 //Total weight of Cu deposited in voltmeter(=Z) t_no=L/W disp(t_no,'Transport no. of copper ions')
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// Chaos deterministyczny - modelowanie i prognozowanie rozkladu temperatury // Model Lorenza - wersja stabilna //Parametry sigma = 5; rho = 20; betta = 3; N0 = [1;0;0]; t = [0:0.1:10]; // Definicja modelu function Ndot = lorenz(t, N) Ndot = [sigma * (N(2) - N(1)); N(1) * (rho - N(3)) - N(2); ...
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//Example 7.3 //Page 354 disp("The maximum information rate per channel is determined as") Imax=[(6.312*288)/1176] disp('The minimum information rate per channel is determined as') Imin=[(6.312*287)/1176] disp('Since there are three possible combinations of two errors in the C bits, the probability of mis...
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pathname=get_absolute_file_path('3_24.sce') filename=pathname+filesep()+'3_24_data.sci' exec(filename) //Efficiency of Otto cycle notto=1-(1/r^(y-1)) //Heat supplied(in kJ/s) qs=P/notto //No of cycles per second Nc=N/(2*60) //Net work output per cycle per cylinder(in kJ) W=P/(k*Nc) //Mean effective pressure(...
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## Copyright (C) 2006-2017 John W. Eaton ## ## This file is part of Octave. ## ## Octave is free software; you can redistribute it and/or modify it ## under the terms of the GNU General Public License as published by ## the Free Software Foundation; either version 3 of the License, or (at ## your option) any later vers...
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errcatch(-1,"stop");mode(2);// Exa 2.6 ; ; // Given data Ad= 100; Acm= 0.01; CMRR= Ad/Acm; CMRR_desh= 20*log10(CMRR);// in dB disp(CMRR_desh,"CMRR in dB") exit();
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// Example 2.1 // Calculation of core diameter // Page no 31 clc; clear; close; // Given data n1=1.5; // Refractive index of core n2=1.48; // Refractive index of cladding N=1000; // No of modes lambda=1.3; // Light wavelength V=sqrt(2*N); // Mod...
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clear all; clc; disp("Scilab Code Ex 8.4 : ") //Given: y_c = 125/1000; //m x_c = 1.5; //m y_b = 1.5; //m x_b = 6; //m udl = 50; //kN/m l_udl = 2.5; //m l = 250/1000; //m width = 50/1000; //m //Internal Loadings: N = 16.45; //kN V = 21.93; //kN M = 32.89; //kNm //Stress Components: //Normal ...
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scenario = "frame"; scenario_type = fMRI_emulation; #scenario_type = fMRI; scan_period = 3000; response_matching = simple_matching; no_logfile = false; sequence_interrupt=false; #default active_buttons = 2; button_codes=0,1; default_font="arial"; default_font_size=30; default_text_color=255,255,255; default_background_...
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//Example 15.7, page 547
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clear //Given M=-20 R=-120 //Calculation f0=R/2.0 fe=f0/M //Result printf("\n Focal length of eyepiece is %0.3f cm", fe)
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// Example 1.3 : Overall voltage gain of cthree-stage amplifier gainloss_in=10^6/(1*10^6+100*10^3); // fraction of input signal is obtained using voltage divider rule , gainloss_in= v_i1/v_s A_v1=10*100000/(100000+1000); // A_v1 = v_i2/v_i1 is the voltage gain at first stage A_v2=100*10000/(10000+1000); // A_v2 = v_...
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// To determine all day efficiency clc; clear; p=15*(10^3); t1=12; t2=6; t3=6; pf1=0.5; pf2=0.8; pf3=0.9; x=poly([0 1],'x','c'); nm=0.98; // Max Efficiency y=(nm*(p+(2*x)))-p; x=roots(y); // To find the iron loss or copper loss at unity p.f for maximum efficiency Pil=x; // Iron loss Pc=...
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% example while loop with a break % try1 = 1; while try1 n = input( ' Enter a number: ' ) ; if n < 0.5 disp 'Too small !' elseif n > 100 disp ' Too big !' else disp ' It will do.' % break % the below line will also work for terminating the loop try1 = 0; end end
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// Example 6.10, Page No-286 clear clc fh=2500 fL=250 B=fh-fL printf('Bandwdth B= %d Hz', B) fr=sqrt(fh*fL) printf('\nResonant Frequency fr= %.2f Hz', fr) fc=(fL+fh)/2 printf('\nCenter Frequency fr= %d Hz', fc) printf('\nHence, resonant frequency is always less than center frequency')
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clc; clear; m=68.1; g=9.8; c=12.5; a=8.3; b=2.2; vmax=46; function yp=f(t,v) yp=g-c*v/m; endfunction v0=0; t=0:15; x=ode(v0,0,t,f); disp(x) plot(t,x,'.-') function yp=f1(t,v) yp=g-(c/m)*(v+a*(v/vmax)^b) endfunction x1=ode(v0,0,t,f1); plot(t,x1) xtitle("velocity vs time","t (s)","v (m/s)")...
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// Process 1-2 Q12 = 235; // in KJ/Kg W12 = 0 ; U12 = Q12-W12; // Process 2-3 Q23 = 0; U23 = -70 ; W23 = Q23-U23; // Process 3-1 Q31 = - 200; U31 = -U12-U23; W31 = Q31-U31; // W = W12 + W23 + W31; Q = Q12 + Q23 + Q31; disp("KJ/Kg",Q,"Heat trasfer in the cycle is") disp("KJ/Kg",W,"Work done during the ...
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//To Determine the necessary realy and recloser coordination //Page 542 clc; clear; //For Recloser InstT=0.03; //From Curve A //Instaneous Time TimeD=0.17; //From Curve B //Time Delay //For Relay PickU=0.42; //From Curve C //Pick Up Reset=(1/10)*60; //Assuming a 60 s reset time for the relay with number 10 ...
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//Chapter 7, Problem 15, Figure 7.6 clc; u0=4*%pi*10^-7; ur=1; B=0.80; //flux density H=750; //field intensity from B-H curve l1=25*10^-2; //length of cast steel core l2=1*10^-3; //air gap A=2*10^-4; //cross-sectional area ...
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clc; K=2*10^-7; //constant in N/A square I=8; //current in Ampere s=5*10^-2; //distance in m B=(K*I)/s; //calculating magnitude of field disp(B,"Magnitude of field in Tesla = "); //displaying result disp(2*B,"Total field in Tesla = "); //displaying result
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clear; clc; //page no. 305 Q = 90;//gpm d = 3;//in l = 3000;//ft V = Q/(60*7.48*0.25*%pi*(d/12)^2); R_h = (d/12)/4; C_hw = 140; S = (V/(1.318*140*R_h^0.63))^(1/0.54); h_L = S*l; printf('The loss of head = %.1f ft of water',h_L); //there is a minute error in the answer given in textbook
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clear; clc; close; Vee = 20; Vbe = 0.7; R1 = 5.1*(10^(3)); R2 = R1; Re = 2.2*(10^(3)); Vb = (R1/(R1+R2))*(-Vee); Ve = Vb - Vbe; Ie = (Ve-(-Vee))/Re; disp(Ie,"Constant current :");
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// example 1.7(b) // //conversion of binary to hexadecimal // clc //clears the screen // clear //clears already existing variables // x= bin2dec ('1011001110' ) // binary to decimal conversion // a= dec2hex (x) //decimal to hexadecimal conversion // disp ('conversion of given binary number to its hexadecimal ...
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//Chapter-2 example 2.6 //============================================================================= clc; clear; PW = 2*10^-6; //pulse width in sec PRF=800; //pulse repetition frequency in KHz V0=3*10^8; //velocity in m/s //Calculations Ru=V0/(2*PRF); //unambigious range in mts...
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clc; clear; //Example 3.1 mu=10^-3 //N.s/m^2 //At distance y from surface //ux=a+by+cy^2+dy^3 //At y=0,ux=0 therefore a=0 //i.e tao=0 //At edge of boundary layer,ie y=del //ux=u_inf //At y=o,c=0 //At y=del,ux=b*del+d*del^3 //Therefore, b=-3*d*del^3 //d=-u_inf/(2*del^2) //b=3*u_inf/(2*del) //Fo...
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function [out]=blur(input_image ,ksize_width,ksize_height,anchorX,anchorY) input_image1=mattolist(input_image); a=opencv_blur(input_image1, ksize_width,ksize_height,anchorX,anchorY); dimension=size(a) for i = 1:dimension out(:,:,i)=a(i); end endfunction;
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// Test # 4 : When either Input Argument #1 or #2 is of complex type exec('./allpasslp2bs.sci',-1); [n,d]=allpasslp2bs(0.3,[0.4,0.2*%i]); //!--error 10000 //Wt must be real and numeric and must contain only 2 elements //at line 43 of function allpasslp2bs called by : //[n,d]=allpasslp2bs(0.3,[0.4,0.2*%i]);
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function [c]=readc_(unit) //Syntaxes : c=readc_(unit) // c=readc_() // //readc_ reads a character string //This macro allows one to interrupt an exec file without pause; //the exec file stops until carrige return is made. //! // [lhs,rhs]=argn(0); if rhs<=0 then unit=%io(1); end; c=read(unit,1,1,'(a)');
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//Example 3.7: Unknown resistance clc; clear; close; //given data : s=0.5;//Mega ohms g=10;//killo ohms d1=41;//divisions d2=51;//divisions r=(((s*10^6)+(g*10^3))*(d1/d2))-(g*10^3);//ohms disp(r*10^-6,"unknown resistance is,(Mega-ohm)=")
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//Example 20.10 P_ave=100*10^6;//Average power (W) V_rms=200*10^3;//Rms voltage (V) I_rms=P_ave/V_rms;//Rms current (A) printf('a.Current required = %0.1f A',I_rms) R=1;//Resistance (ohm) P_ave_b=I_rms^2*R;//Power dissipated (W) printf('\nb.Power dissipated by transmission lines = %0.1f kW',P_ave_b/1000) percen...
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//check o/p for vector i/p k = [0.3090 0.9800 0.0031 0.0082 -0.0082]; r0 = 0.1; a = rc2ac(k,r0); disp(a); //output // // 0.1 // - 0.0309 // - 0.0790948 // 0.0786627 // 0.0293629 // - 0.0950000 // //
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//EX13_39 Pg-21 clc clear printf("8''s complement (346)_8 is : ") x=['346']; y=oct2dec(x);//octal to decimal conversion// z=bitcmp(y,9);//one's complement of the number// z=z+1; z2=dec2oct(z)//8's complement of the number// printf("%s",z2)
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//Chapter-2,Example 2_27,Page 2-49 clc() //Given Data: m=2 //order lam1=5.77*10^-7 //Wavelength of light lam2=5.791*10^-7 //Wavelength of light GE=1/6000*10^-2 //GE=(a+b) grating element //Calculations: //We know, (a+b)*sin(theta)=m*lam t...
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// (6.9) Air undergoes an isentropic process from p1 = 1 bar, T1=  300K to a final state where the temperature is T2=  650K.,Employing the ideal gas model, determine the final pressure p2, in atm. Solve using (a) pr data from Table A-22 (b) Interactive Thermodynamics: IT, and (c) a constant specific heat ratio k e...
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// Aim:Refer Example 14-7 for Problem Description // Given: // diamter of hydraulic cylinder: D=152; //mm // cylinder extension: L=2.54; //m // duration of cylinder extension: t=10; //s // time between crushing stroke: t_crush=5; //min // gas precharge pressure: p1=84; //bars abs // gas charge pressure when pump is tur...
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clc; figure; n=0:2:100; fs=0.002; fm=5 A=1; x=A*cos((2*%pi*fm*(n/fs))); subplot(2,2,1) plot2d3(n,x); //figure; n=0:2:100; fs=0.04; fm=45 A=1; x=A*cos((2*%pi*fm*(n/fs))); subplot(2,2,2) plot2d3(n,x); //figure n=0:2:100; fs=0.4; fm=55 A=1; x=A*cos((2*%pi*fm*(n/fs))); subplot(2,2,3) plot2d3(n,x);
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A=8.0 alpha=0.3 rho=0 mu=0.1 psi=0.05 function r=cobbdouglas(x) r=A*x^alpha; endfunction function r=ces(x) r=A*(alpha*x^(-rho)+1-alpha)^(-1/rho); endfunction eps=0.00001 function r=dcobbdouglas(x) r=(cobbdouglas(x+eps)-cobbdouglas(x))/eps; endfunction function r=dces(x) r=(ces(x+eps)-ces...
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//Example 16.2 clc syms tau s zeta w; j=%i; n=1; d=tau^2*s^2+2*zeta*tau*s+1; G=n/d s=j*w; G=1/(2*s*tau*zeta+s^2*tau^2+1) [num den]=numden(G) d=abs(den) cof_a_0=coeffs(den,'%i',0) cof_a_1=coeffs(den,'%i',1) AR=1/d theta=AR*atan(-cof_a_1/cof_a_0); disp(theta,'Phase angle=')
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clear; clc; // Illustration 1.13 // Page: 36 printf('Illustration 1.13 - Page:36 \n\n'); // Solution //*****Data***** // acetic acid-1 water-2 ethyl alcohol-3 T = 298; // [K] // The data required data for water at 298 K u_2 = 0.894; // [cP] V_c1 = 171; // [cubic cm/mole] // From equation 1.48 V_b...
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//chapter25 //example25.9 //page556 fh=1000 // Hz // case (i) :- ratio of fv to fh = 1:1 fv1=1*fh // case (ii) :- ratio = 2:1 fv2=2*fh // case (iii) :- ratio = 6:1 fv3=6*fh printf("for case1 i.e. fv/fh = 1/1, fv = %.3f Hz \n",fv1) printf("for case2 i.e. fv/fh = 2/1, fv = %.3f Hz \n",fv2) printf("f...
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clc //initialisation of variables h= 6.625*10^-27 //ergs/mole f= 2.65*10^-5 //sec^-1 c= 3*10^10 //cm/sec t= 2 N= 6*10^23 //molecules M= 382 //gms E1= 750 //ergs //CALCULATIONS E= h*c/f n1= E1/E m= n1/(t*7) G= m*M/N //RESULTS printf ('number of quanta = %.2e ',n1) printf ('\n number of quanta = %.2e mole...
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//Chapter 2,Example 2.24,Pg 2.30 clc; disp("Refer to the diagram shown in the figure") A=[4 -2 -1;-50 71 -20;-5 -4 10] B=[-24;0;180] V=A\B printf("\n Va=%.2f V\n",V(1)) printf("\n Vb=%.2f V\n",V(2)) printf("\n Vc=%.2f \n",V(3)) printf("\n Voltage across 5 ohms resistor=%.2f \n",V(3)-V(2))
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//Chapter 6, Problem 7 clc; Q=1.2*10^-6; //Charge A=4*10^-4; //Area of plates d=0.1*10^-3; //Distance between plates e0=8.85*10^-12; er=100; C=(e0*er*A)/d; //Calculating capacitance V=Q/C; //Calculating potential di...
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//Chapter 6,Example 6.5 Page 200 clc clear Ca = 50 // pF C = 190 // pF loss = 0.0085 // loss angle of electrodes Er = C/Ca tang = 0.0085 Er1 = Er*tang E0 = 8.854*10^-1 E1 = E0*Er jE1 = E0*Er1 printf (" The dielectric constant = %f \n ",Er) printf (" tan δ = %f \n ",tang) printf (" E = (%f - j %f ) * 10^-11 F/m \n ",E1,...
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//Page Number: 198 //Example 4.8 clc; //Given a=5;//cm a1=a/100;//m b=4;//cm b1=b/100;//m c=10;//cm c1=c/100;//m sig=5.8D+7; u0=4D-7*%pi; er=3; eet=377; ur=1; spl=3D+8; tandel=2.5D-4; //TE101 mode m=1; n=0; p=1; fr=(spl/(2*sqrt(er*ur)))*sqrt((m/a1)^2+(n/b1)^2+(p/c1)^2);//hz disp('Ghz',fr/10^9,...
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// Variable Declaration kv = 11.0 //Voltage rating(kV) MVA = 5.0 //MVA rating R = 10.0 //Resistance(ohm) per_a = 0.15 //Armature winding reactance per_trip = 0.3 //Relay trip for out-of-balance // Calculation Section x_p = per_a*kv**2/MVA //Winding Reactance(ohm) V = k...
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# Just adding and joining nodes but no explicit stabilize or fix # predecessor is None and successor is valid and finger table is stale add 0 add 1 add 2 add 3 join 1 0 join 2 0 join 3 0 list show 0 show 1 show 2 show 3 end
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//example2.6 clc disp("Consider a short shunt generator as shown in the fig 2.32") disp("R_a=0.04 ohm, R_sh=90 ohm, R_se=0.02 ohm") disp("V_t=225 V , I_L=75 A") disp("I_a = I_L + I_sh") disp("Now, E=(V_t)+[(I_a)*(R_a)]+[(I_L)*(R_se)]") disp("and drop across armature terminals is,") disp("E-[(I_a)*(R_...
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//Chapter-5,Example 1,Page 121 clc(); close(); //for 1st order reaction //k = (1/t)*log(a/(a-x)) a= 46.1 //time value //time intervals t=[ 5 10 20 30 50] x=[ 37.1 29.8 19.6 12.3 5.0] k = (1 ./t).*log(a./(x)) printf('value of k are ' ) disp(k) printf('since k values are fairly constan...
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//****************************************************************// // .Rutina: Permeancia Devanado Primario 127V ...// // .Autor: Marco Polo Jacome Toss ...// // .Version : 1.0 ...// // .Plataforma : Scilab (https://www.sc...
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//Ex:3.27 clc; clear; close; n1=1.47;// core refractive index n2=1.46;// cladding refractive index y=1.3;// wavelength in um dl=(n1-n2)/n1;// fractional refractive index diff NA=sqrt(n1^2-n2^2); v=2.405; a=(v*y)/(2*3.14*(sqrt(n1^2-n2^2)));// largest core radius in micrometer n_eff=n1-(NA/(2*3.14*(a/y)));// ...
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clear;lines(0); t=[0:0.3:2*%pi]'; z=sin(t)*cos(t'); [xx,yy,zz]=genfac3d(t,t,z); plot3d(xx,yy,zz)
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function M = mediana(M, v) // MEDIANA_ // M: imagem em tons de cinza // v: vizinhança do tipo v x v, 3 ou 5 // // Uso: // I = imread('figura.jpg'); // M = mediana(I, 3); // imshow(M) // [m n] = size(M); // análise do tamanho da vizinhança if (v==3) d = 1; elseif (v==5) d = 2; end // m1 = m + 2*d; ...
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/* Créateur: Jinshan GUO et Anais Debureaux */ exec(fullpath(pwd() + '\TP7.sci'),-1); a = [2;-2]; t0 = 0; T = 15; Nptmil = 100; Neul = 100; Node = 100; Nrk4 = 100; tracevdp(a, t0, T, Neul, Nptmil, Node, Nrk4); //tracevdp(a, t0, T, 1000, 1000, 1000, 1000); //===========Exo5 =========== T = 10; [TV, TE...
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load CS16B032Register8.hdl, output-file CS16B032Register8.out, compare-to CS16B032Register8.cmp, output-list time%S1.4.1 in%D1.6.1 load%B2.1.2 out%D1.6.1; set in 0, set load 0, tick, output; tock, output; set in 0, set load 1, tick, output; tock, output; set in 120, set load 0, tick, output; tock, output; set i...
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pathname=get_absolute_file_path('17_9.sce') filename=pathname+filesep()+'17_9_data.sci' exec(filename) //Brake specific energy consumption(Power remains same as in the previous problem) bsec=(mf/bp)*CV*10^-3 //Indicated specific energy consumption(mechanical efficiency remains same as in previous problem) isec=bs...
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//// read_off // Read mesh data from OFF file // //// Syntax // [face,vertex] = read_off(filename) // [face,vertex,color] = read_off(filename) // //// Description // filename : string, file to read. // // face : double array, nf x 3 array specifying the connectivity of the mesh. // vertex : double array, nv ...
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//Test the functions for the Buck //REactive elements and switching frequency L=1e-6; rl=5e-3; rc=10e-3; //Parasitic element values are needed, but not very important C=200e-6; f_switch=1e6; tctrl=400*1e-9; Po=9; Vo=1.8; Io=Po/Vo; //The model requires the output current Rl=Vo/Io; Vin=5; //Input voltage range //...
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clc; P=20000; // rated power of transformer E1=2500; // primary side voltage E2=500; // secondary side voltage r1=8; // primary resistance in ohm x1=17; // primary leakage reactance in ohm r2=0.3; // secondary resistance in ohm x2=0.7; // secondary leakage reactane in ohm k=E2/E1; // turns ratio re2=r2+r1*k^2;...
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// Clear already defined variables clear; // funcprot(0) prevents from getting a warning message about already defined/loaded functions funcprot(0); function new_graphic_window() AllCurrentFiguresId = get('figures_id'); if isempty(AllCurrentFiguresId) then NewFigureId = 0; else CurrentFigure ...
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clc // Given that lambda = 1.4 // wavelength of x-ray in angstrom x1 = 1 // coordinate on x axis of plane y1 = 1 // coordinate on y axis of plane z1 = 1 // coordinate on z axis of plane a = 5 // lattice parameter of of crystal in angstrom // Sample Problem 16 on page no. 13.30 printf("\n # PROBLEM 16 # \n") printf(" S...
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n = 405 A = eye(n,n) for j = 1:n for i = 1:n if(abs(i - j) > 1) A(i,j) = 0 else A(i,j) = 1 end end end function [L,A,C] = fatoraLU(A) n = size(A,1) L = eye(n,n) C = 0 for j = 1:n-1 for i = j+1:n L(i,j) = A(i,j)/A(j,j) ...
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5 5:0.5 6:0.11764705882352941 15:0.2222222222222222 24:1.0 34:0.3 37:0.3333333333333333 42:0.2 56:0.3333333333333333 64:0.5 73:1.0 82:0.16666666666666666 97:0.5 140:0.5 173:2.0 191:0.3333333333333333 261:0.019230769230769232 320:2.0 373:0.3333333333333333 399:1.0 488:1.0 489:2.0 583:1.0 587:1.5 671:1.0 775:2.0 908:1.0 ...
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//example-16.1 //page no- 484 //given //atomic radiii of gamma-iron having FCC lattice rFCC=1.26 //A //atomic radius of alpha-iron having BCC lattica rBCC=1.24 //A //as we know that FCC and BCC has effective no of atoms 4 and 2 resp //so aBCC=4/sqrt(3)*rBCC //A aFCC=2*sqrt(2)*rFCC //A //volume of lattice...
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clear // //find the total weight and airfuel ratio //given data O2=409.9 lb=0.231 w=409.9 W=w/lb AFR=W/120. printf("\n \n total weight %.2f ",W) printf("\n \n air fuel ratio %.2f ",AFR)
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clear clc //to find speed of ball // GIVEN: //refer to problem 9-10 //mass of disk M = 2.5//in kg //distance of fall y = 0.56//in meters //mass of block m = 1.2//in kg //acceleration due to gravity g = 9.8//in m/s^2 // SOLUTION: //applying conservation of mechanocal energy principle //speed of blo...
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//Function to standardise the given bolt-size function[v] = standard(w) v = ceil(w) rem = pmodulo(v,10) if (rem ~= 0) then v = v + (10 - rem) end endfunction //Obtain path of solution file path = get_absolute_file_path('solution7_4.sce') //Obtain path of data file datapath = path + fi...
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clc; clear; lambda=6000*10^-10 //wavelength in m myu_0=1.554 //refractive index myu_e=1.544 //refractive index //calculation d=lambda/(4*(myu_0-myu_e)) mprintf("The thickness of the quarter wave plate is = %1.1e m",d)
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// This file is adapted from part of www.nand2tetris.org // and the book "The Elements of Computag Systems" // by Nisan and Schocken, MIT Press. load ALUcore.hdl, output-file ALUcore.out, compare-to ALUcore.cmp, output-list a%B1.4.1 b%B1.4.1 carryIn%B3.1.3 sums%B3.1.3 ands%B3.1.3 xors%B3.1.3 ors%B3.1.3 out%B1.4.1 carr...
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clc; clear; close; Ceff=1;//in fF/um Cint=0.2;//in fF/um Cg=2;//in fF/um Wn=0.8;//in um Wp=0.4;//in um Lwire=20;//in um reff=12.5/2;//in kiloohm rsq=0.054;//in ohm Cfan=4*Cg*(Wn+Wp); disp(Cfan,'Fanout Capacitance(in fermifarads)='); Cself=Ceff*(Wn+Wp); disp(Cself,'Self Capacitance(in fermifarads)='); Cwi...
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clc clear //input v=14 //voltage //calculation v0=v*sqrt(2)//rms value //output printf("rms value of ac is 14 V") printf("\n the peak value of ac is %3.3f V",v0)
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-- Fuzzy Logix, LLC: Functional Testing Script for DB Lytix functions on Teradata -- -- Copyright (c): 2014 Fuzzy Logix, LLC -- -- NOTICE: All information contained herein is, and remains the property of Fuzzy Logix, LLC. -- The intellectual and technical concepts contained herein are proprietary to Fuzzy Logix, LLC. ...
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2_3.sce
clear; clc; printf("\t\t\tExample Number 2.3\n\n\n"); // heat transfer through a composite wall // illustration2.3 // solution // 1. heat transfer through studs for unit depth l = 0.0413;// [m] length of wood studs b = 1.0;// [m] unit depth A = l*b;// [square meter] area of studs for unit depth hi = 7.5;// ...