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//Caption:Calculate lowest operating frequency for circuit //Ex5.5 clc; clear; close; V=4//Peak to peak amplitude of output waveform(in volts) Vi=10//Input voltage(in volts) Vs=15//Supply voltage(in volts) Ib=500//Maximum Base current(in nA) f=250//Frequency of input waveform(in hz) I=1//Circuit current(in mA...
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clear // //Initilization of Variables F=30*10**3 //N //Shear Force //Channel Section d=400 //mm //Depth of web t=10 //mm //THickness of web t2=15 //mm //Thickness of flange b=100 //mm //Width of flange //Rectangular Welded section b2=80 //mm //Width d2=60 //mm //Depth //Calculations //Distance of Centroid From T...
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//Author: Parthasarathi Panda //parthasarathipanda314@gmail.com function typ=firtype(b) if (type(b)~=1) then error('check input type'); end v=size(b); if length(v)>2 then error('check input dimension'); end if v(1)~=1 & v(2)~=1 then error('check input dimension'); els...
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clc; // function [y]=delta(t) if t==0 y=1 else y=0 end endfunction
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//Example No. 3_02 //hexadecimal to decimal //Pg No. 46 clear ; close ; clc ; h = '12AF' ; u = str2code(h) u = abs(u) n = length(u) d = 0 for i = 1:n d = d*16 + u(i) end disp(d,'Decimal value = ') //Using Scilab Function d = hex2dec(h) disp(d,'Using scilab function Decimal value = ')
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clear ; clc; // Example 3.10 printf('Example 3.10\n\n'); printf('Page No. 71\n\n'); // given C = 2500;// Cost of the project P = 1000;// Cash in flow r_r = 0.12;// Rate of return S = 0;// Zero salvage value n = 4;//years for j= 1:1:4 // as for four years d_(j) = P*(1/(1+r_r)^j); end P_v =...
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clc //initialisation of variables v=15//ft^3 m=20 //lbm M=24 //lbm/lb T=540//R //CALCULATIONS R=1545/M //ft-lbf/lbm R P=(m*R*T)/(144*v) //lbf/in^2 //RESULTS printf('the presure=%f lbf/in^2',P)
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//Variáveis de saída: //x: solução do sistema Ax=b (assumimos que tal solução existe). //C: Seja A=LU a decomposição LU de A. //Então C(i,j)=L(i,j) para i>j e C(i,j)=U(i,j) para j>=i. function[x, C]=Gaussian_Elimination_2(A, b) C=[A,b]; [n]=size(C,1); for j=1:(n-1) //O pivô está na posição (j,j) ...
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// force is necessary to hold the defelector inplace in 32kg/s //ex 2.13 pgno.51 clc m=32 // MASS FLOW RATE p=1000 // PRESURE l=0.02//length b=0.04//width v1=m/(p*l*b)//velocity mprintf('The velocity V1 = %d m/s',v1) v2=40 Fx=m*(v1-v2*cosd(30))//fource mprintf('\n Fx= %d N',Fx) Fy=m*(v1-v2*sind(30)) mprint...
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//Transport Processes and Seperation Process Principles //Chapter 7 //Example 7.6-1 //Principles of Unsteady state and convective mass transfer //given data rb=6/(10^9);//pore radius Ma=2.016;//mol wt of hydrogen T=373;//temp in K Dka=97*rb*sqrt(T/Ma); mprintf("the knudsen diffusivity is %f m2/s",Dka) //end
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@relation @attribute f1 real[0.19,16.0] @attribute f2 real[0.0,12.0] @attribute class{red,green} @inputs f1,f2 @outputs class @data green green green green red red red red green green green green green green green green red green red green red green green green green green green green green green green green green gr...
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//========================================== // Exercise 3: Short Surface Gravity Waves //========================================== // Animation of equivalent vertical displacements of pressure surfaces //Author: Jochen Kaempf, 2015 (update) f = gcf(); scf(0); f.figure_size = [700,400]; f.children.font_size = 3...
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clc; clear; //Example 2.39 //Given h=11.36 //W/sq m.K k=43.3 //w/(m.K) r=25.4 //radius in mm r=r/1000 // radius in m A=4*%pi*r^2 //Area of sphere [sq m] V=A*r/3 //Volume in [cubic m] rho=7849 //kg/cubic m Cp=0.4606*10^3 //J/kg.K t=1 //hour t=t*3600 //seconds T_inf=394.3 //[K] T0=700 ...
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rand("seed", 9504); T = rand(10,10) + rand(10,10); A = floor((1.0-0.02-4*0.005-0.25)*T); disp(A); for i=1:10 for j=1:10 if(A(i,j)==1 && A(j,i)~=1) then A(j,i)=1; end end end disp(A); clf; plot2d([0,100], [0,100],0); function circle(x, y, r) xarc(x-r, y+r, 2*r, 2*r, ...
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// Example 10_6 clc;clear; //Given data // Assume (vdot/L)_1=V1,(vdot/L)_2=V2; V1=2.00;// m^2/s V2=-1.00;// m^2/s gamma1=1.50;// m^2/s x_1=0; y_1=1; x_2=1; y_2=-1; x=1.0; y=0;// where all spatial coordinates are in meters. //Calculation //From fig.10-53,The vortex is located 1 m above the point (1, 0) a...
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errcatch(-1,"stop");mode(2);//Ex:2.5 ; ; r=27*(10^3); printf("Resistor value = %d ohm",r); printf("\nTolerance = 5 %%"); exit();
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// Test #5 :For 1 output argument exec('./allpassrateup.sci',-1); [n]=allpassrateup(8); disp(n); // //Scilab Output //n= 0. 0. 0. 0. 0. 0. 0. 0. 1. // //Matlab Output //n= 0 0 0 0 0 0 0 0 1
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// **** Purpose **** // This function add a '/' to the directary path // **** Variables **** // [dir_path]: 1x1, str // <= original path // => path with '/' ending // **** Version **** // Apr 22, 2016: 1st version // **** Comment **** function dir_path=PIL_dir_path(dir_path) if dir_path==[] then dir_pa...
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clear close clc s = poly(0,'s'); G = 10/(s*(s+2)*(s+4)); K = 2; G_cl = K*G/(1+K*G); disp(G_cl,' The transfer function of the closed loop system is ')
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# ATWM1 MEG Experiment scenario = "ATWM1_Working_Memory_MEG_salient_cued_run2"; #scenario_type = fMRI; # Fuer Scanner #scenario_type = fMRI_emulation; # Zum Testen scenario_type = trials; # for MEG #scan_period = 2000; # TR #pulses_per_scan = 1; #pulse_code = 1; pulse_width=6; default_monito...
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function path=mfile_path(nam) // Copyright INRIA fil=nam+'.m';nf=length(fil) path=[]; for k=1:size(mfiles,'*') pk=mfiles(k); kk=strindex(pk,'/'); if fil==part(pk,kk($)+1:length(pk)) then path=pk; break end end
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//Exa 3.10 clc; clear; close; //Given Data : format('v',4); //Applying KCL we get I1+i1=I2+ix and I2+i2=I3+iy //On solving we get : 1*2*E1=1*1*E2+0*1*E3 and 0*2*E1=-1*2*E2+1*3*E3 E1byE=1/(1+(154/155)+(166/155));//assumed E2byE=(154/155)*E1byE;//assumed E3byE=(166/155)*E1byE;//assumed Eff=1/((3*(166/155)*E1b...
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clear //find the brake thermal efficency of an engine //given w=16.2 t=20. p=126. q=19300. //during 20 minutes period of the test 126 bhp for a period 1/3 hour 126*(1/3.) btu=42.*2544. hi=16.2*19300. bth=(btu/hi)*100. printf("\n \n brake thermal efficency %.2f percent",bth)
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//Example 32.2 a1=2.014102;//Atomic mass of deuterium (u), See Appendix A a2=3.016050;//Atomic mass of tritium (u), See Appendix A a=a1+a2;//Total atomic mass per reaction (u) m=a;//Mass per mole of reactants (g/mol) mol_of_reactants=1000/m;//Mol of reactants in 1kg N=mol_of_reactants*6.02*10^23;//Number of react...
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//water and its treatment// //example 2.18.29// clc Purity_Lime=0.85 Purity_soda=0.95 W1=3.5;//amount of CaCO3 in ppm// W2=6.8;//amount of CaSO4 in ppm// W3=8.4;//amount of MgCO3 in ppm// W4=5.7;//amount of MgCl2 in ppm// W5=6.0;//amount of MgSO4 in ppm// W6=3.0;//amount of SiO2 in ppm// W7=11.7;//amount...
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// Chip teste para função px load px.hdl, output-file px.out, compare-to px.cmp, output-list in%B3.5.3 out%B3.1.3; set in %B00000, eval, output; set in %B00001, eval, output; set in %B00010, eval, output; set in %B00011, eval, output;
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<?xml version="1.0" encoding="UTF-8"?> <Project Name="map1209" Width="13" Height="11" CellSize="40" BackgroundSize="1" Background="11plus.png"> <Cell Name="出生点" X="2" Y="1" /> <Cell Name="瘟疫花" X="4" Y="1" /> <Cell Name="蝙蝠-0(怪)" X="7" Y="1" arg0="8" /> <Cell Name="枯骨" X="11" Y="1" /> <Cell Name="墙1" X="2" Y=...
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//developed in windows XP operating system 32bit //platform Scilab 5.4.1 clc;clear; //example 12.6w //calculation of the maximum speed of the block and the speed when the spring is stretched //given data nu=10//frequency(in s^-1) of oscillation l=.20*10^-2//stretch(in m) of the spring g=%pi^2//gravitational ...
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clear all; clc; disp("Scilab Code Ex 10.3 : ") //Given: ep_x = -350;//(*10^-6) Normal Strain ep_y = 200; //*(10^-6) Normal Strain gamma_xy = 80; //*(10^-6) Shear Strain //Orientation of the element: tan_thetap = -(ep_x - ep_y)/(gamma_xy); thetap1 = (0.5)*(atan(tan_thetap)); //Maximum in-plane shear str...
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EXAMPLE5_47.SCE
//ANALOG AND DIGITAL COMMUNICATION //BY Dr.SANJAY SHARMA //CHAPTER 5 //ANGLE MODULATION clear all; clc; printf("EXAMPLE 5.47(PAGENO 264)"); //given f_m = 2*10^3//modulating frequency for first case delta_f1 = 5*10^3//frequency deviation for first case f_m1 = 1*10^3//modulating frequency for second case //...
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load Memory.hdl, output-file Memory.out, compare-to Memory.cmp, output-list in%D1.6.1 load%B2.1.2 address%B1.16.1 out%D1.16.1; echo "Before you run this script, select the 'Screen' option from the 'View' menu"; set in -1, // Set RAM[0] = -1 set load 1, set address 0, tick, output; tock, output; set in 9999, /...
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clc; funcprot(0); //Example 13.1 //Initializing the variables rho0 = 1.8; R = 287; T = 75+273; // Temperature in kelvin gma = 1.4; Ma = 0.7; //Calculations P0 = rho0*R*T; c = sqrt(gma*R*T); V0 = Ma*c; Pt = (P0^((gma-1)/gma) + rho0*((gma-1)/gma)*(V0^2/(2*P0^(1/gma))))^(gma/(gma-1)); rhoT = rho0*(Pt/P0...
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//Value of P //Refer fig.5.8 //consider equilibrium mu=0.2 //750N block N1=750*cosd(60) //N F1=mu*N1 //N T=F1+750*sind(60) //N //500N block //N2=500-0.5P //Law of friction //F2=0.2*N2 P=(724.52+100)/(cosd(30)+0.1) //N printf("\nP=%0.2f N",P)
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//Book Name:Fundamentals of Electrical Engineering //Author:Rajendra Prasad //Publisher: PHI Learning Private Limited //Edition:Third ,2014 //Ex12_10.sce clc; clear; Z_R=complex(8,6); Z_Y=complex(8,-6); Z_B=complex(5,0); Z_N=complex(0.5,1); Y_R=1/Z_R; Y_Y=1/Z_Y; Y_B=1/Z_B; Y_N=1/Z_N; E_R=220; E_Y=22...
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//Example 1.8 Conversion from decimal number to binary number. clc; x = dec2bin(105); // binary equivalent of decimal number disp('The binary number is = '); disp(x) // answer in binary form
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// Exa 2.15 format('v',6);clc;clear;close; // Given data V = 80;// in V I = 15;// in mA I = I * 10^-3;// in A R_T = V/I;// in ohm R_T = R_T * 10^-3;//apparent resistance in k ohm Rapp = R_T;// in k ohm disp(Rapp,"The apparent resistance in kΩ is"); sensitivity = 1.5;// in k ohm f_s_reading = 150;//full scale...
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clc // Given that n = 20000 // flux lines entering in given volume in Vm n_ = 45000 // flux lines entering out from given volume in Vm e0 = 8.85e-12 // permittivity of space // Sample Problem 16 on page no. 10.42 printf("\n # PROBLEM 16 # \n") fi = n_ - n q = e0 * fi printf("Standard formula used \n fi= q/e_. \n") pri...
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// Scilab code Ex4.30 : Pg:180 (2008) clc;clear; Lambda = 6000e-08; // Wavelength of light, cm d = 0.005; // Diameter of wire, mm x = 15; // Distance between the glass plates, cm theta = d/x; // Angle of the wedge, degree omega = Lambda/(2*theta); // Fringe width in air wedge for normal incidence, ...
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//Drain supply Vdd, Drain resistance Rd, source resistance Rs, Gate resistance Rg close(); clear; clc; Idss = 8/1000;//A Vpo = 4;//V Vdd = 15;//V Rd = 5000;//ohm Rs = 2000; Rg = 10^6; Idq1 = 1.22*10^(-3);//A Vdsq1 = 0; Vgsq1 = -Idq1*Rs; Vgsq2 = Vgsq1; Vdsq2 = Vdd - Vdsq1- Idq1*(Rs+Rd); mprintf('Vgsq1 = %...
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//Exa 10.9 clc; clear; close; //given data : R=6370;//in Km hm=400;//in Km //Formula : d=2*R*Q=2*R*acos(R/(R+hm)) d=2*R*acos(R/(R+hm));//in Km disp(d,"Maximum Range in a single range transmission in Km : ");
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// Example 10.11 // Determine (a) Electrical losses (b) Rotational losses (c) Efficiency // Page No. 430 clc; clear; close; // Given data T=124; // Hp rating of motor Rf=32.0; // Field resistance VT=240; // Rated voltade of the machine IT=420; ...
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// The code was developed under Horizon2020 Framework Programme // Project: 748767 — SIMFREE function Out=SSSoAttenuator(In,Attenuation_dB) // Attenuator // // Calling Sequence // Out=SSSoAttenuator(In,Attenuation_dB) // // Parameters // In : Optical Input // Attenuation_dB : Requi...
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//Chapter 1,Example 1.8,Pg 1.12 clc; disp("We know that R1 = R0(1+a0t)") disp("At t1=20 degree C, R1=45 ohms") R0=45/(1+0.004*20) disp("At t2, R2=48.5 ohms") disp("Therefore, we can calculate t2 as follows") disp("45/48.5 = (1+0.004*20)/(1+0.004t2)") t2=(48.5-R0)/(0.004*R0) printf("\n Therefore t2= %.0f degree...
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function [x,y,typ]=GENERAL_f(job,arg1,arg2) x=[];y=[];typ=[]; select job case 'plot' then standard_draw(arg1) case 'getinputs' then [x,y,typ]=standard_inputs(arg1) case 'getoutputs' then [x,y,typ]=standard_outputs(arg1) case 'getorigin' then [x,y]=standard_origin(arg1) case 'set' then x=arg1; graphics=arg1(...
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write_codes = false; pulse_width = 2; #no_logfile = false; #active_buttons = 1; #button_codes = 3; #target_button_codes = 3; randomize_trials = false; default_attenuation = 0.2; default_pan = 0.0; begin; array { sound { wavefile { filename = "audio\\1_ang_ss_trimF.wav"; } s1_ang_ss_trimF;}; sound { wavefile { fil...
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clc,clear //Example 1.25 //To find sin_theta and tan_theta when cos_theta is given cos_theta = -4/5; adjacent =4 ; hypotenuse =5 ; opposite = sqrt(hypotenuse ^2 - adjacent ^2) //by pythagoras theorem //minus sign of cos_theta implies 2nd or 3rd quadrant //Possibility 1 : 2nd quadrant x= -adjacent ; y= op...
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//chapter1,Example1_1,pg 481 Ir=10*10^-3//current drawn by resistor Vr=100//voltage across resistor Rv=40*10^3//voltmeter resistance Ru=(Vr/Ir)*(1/(1-(Vr/(Ir*Rv))))//unknown resistance printf("output resistance\n") printf("\nRu=%.2f ohm",Ru)
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// Exa 2.16 clc; clear; close; // given : H=2 // ampliutude of magnetic field in A/m sigma=0 // conductivity mu_0=4*%pi*10^-7 // permeability in free space in H/m epsilon_0=8.854*10^-12 // permittivity in free space in F/m mu=mu_0 // permeability in F/m epsilon=4*epsilon_0 // permittivity in F/m Eta_0=120*%p...
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clc clear //Combined seperating and throttling calorimeter Mw=8; //in kg M=63; //in kg Ms=M-Mw; //in kg P1=81.5; //Pressure after throttling in mm P2=754; //Barometer reading in mm SD=13.6; //Specific Density of...
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clear, clc function F = f(x) F= (2*exp(x^2)*x + 1)^(-1/2); disp(F); endfunction a=0; b=1; n=2; h = (b-a)/n; x=a:h:b; soma=0; for i=2:n soma = soma + 2*f(x(i)) end intt = (h/2)*(f(x(1)) + soma + f(x($))); disp(intt);
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// Scilab ( http://www.scilab.org/ ) - This file is part of Scilab // Copyright (C) 2013 - Scilab Enterprises - Antoine ELIAS // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The...
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//example1.19 clc disp("Using the loop analysis, (fig 1.88(a) see on next page)") disp("Applying KVL to the three loops,") disp("-(I1)-(I1)-2(I1)+2(I3)+5-2(I1)=0 i.e -6(I1)+2(I3)= -5 ...(1)") disp("-2(I3)+2(I1)-2(I3)-5-2(I3)-(I3)+I2=0 i.e 2(I1)+I2-7(I3)=5 ...(2)") disp("-2(I2)-(I2)+(I3)-2(I2)+5=0 i.e ...
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//ques-18.41 //Calculating final temperature and w and q and change in internal energy for the process clc V1=6; V2=2;//volume (in L) T1=273+27;//temperature (in K) Cv=20.91;//(in J/K/mol) q=1.4; T2=T1*((V1/V2)^(q-1)); U=Cv*(T2-T1); w=-U; q=0;//adiabatic process printf("Final temperature is %.0f K, w=%.4f kJ...
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// use : // image = coordOfValue(img, value) // // image = coordUnderValue(img, value) // image = coordUnderValue(img, max(img)) // // image = coordUpperValue(img, value) // image = coordUpperValue(img, min(img)) function coord=coordOfValue(imgsrc,value) pos = 1 [width,height]=size(imgsrc) for i=1:heigh...
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clc; clear; format('e',11); f=10*10^9; epsilone_r=2; epsilone_0=8.85*10^-12; epsilone=epsilone_r*epsilone_0; loss_tangent=0.05; epsilone_c=epsilone*(1-%i*loss_tangent); w=2*%pi*f; B_0=w*sqrt((4*%pi*10^-7)*epsilone); B=B_0*(1+(loss_tangent^2)/8); alpha=B_0/2*loss_tangent; delta=1/alpha; //skin dept...
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//chapter-2,Example2_3,pg 54 //P=(dE/dt)Fe=a+b*t=1734-4.87*t //P=(dE/dt)Cu=a+b*t=136+0.95*t aFe_Pb=1734*10^-6 aFe_Cu=(1734-136)*10^-6 aCu_Pb=136*10^-6 bFe_Pb=-4.87*10^-6 bFe_Cu=(-4.87-0.95)*10^-6 bCu_Pb=0.95*10^-6 a=aFe_Cu b=bFe_Cu t=100 EFe_Cu=(a*t)+0.5*(b*(t^2)) printf("e.m.f of...
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//example 5.16 clear; clc; disp("C8H18(g)+12.5O2(g)-->8CO2(g)+9H2O(l)"); //Given: T=298;//temperature[K] S=421.5;//change in entropy[J/K] H=-5109000;//Heat of reaction[J] R=8.314;//Universal gas constant[J/K/mol] dn=8-(1+12.5);//change in no. of moles //To find the helmholts free energy and Gibbs free...
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clear; n = 6; // # of cells in a row m = 200; // # of steps cp = 1; cr = -1; con_coef = 1; pos_coef = 1; x = linspace(0,9,n);// initial values y = linspace(0,9,n);// initial values if 1==2 then for i=1:n for j=1:n p(i,j)=n-i//abs(cos(j)); r(i,j)=1//abs(sin(i)*cos(j)); end end end...
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clc Ltot=123.03; Fn=3.16;..//noise factor Gt=10;..//transmitter gain Pt=1500;..//transmitter peak power To=296.7; R=10^5; k=1.38*10^-23;..//boltzmann constant sigma=1.5; Ae=8; Bn=10^3;..//bandwidth pi=3.14; F=1; w=1.67; angle=(4*%pi/Gt)*180/%pi; Beamwidth=sqrt(angle);..//elevation beamwidth SNR=log10(Pt...
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//Harriot P.,2003,Chemical Reactor Design (I-Edition) Marcel Dekker,Inc., USA,pp 436 //Chapter-4 Ex4.1.c Pg No. 135 //Title: Effective Diffusivity of chlorine at 15 atm //============================================================================================================ clear clc //INPUT S_g=235; V_g...
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load Not16.hdl, output-file not16Output.out, output-list in%B1.16.1 out%B4.16.3; set in %B0000000000000000, eval, output; set in %B1111111111111111, eval, output; set in %B1111111111111111, eval, output; set in %B0000111111110000, eval, output;
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//chapter13 //example13.11 //page284 R1=40 // kilo ohm R2=10 // kilo ohm Re=2 // kilo ohm Vcc=10 // V Vbe=0.7 // V V2=Vcc*R2/(R1+R2) // voltage across R2 Ve=V2-Vbe // voltage across Re Ie=Ve/Re re_dash=25/Ie printf("ac emitter resistance = %.3f ohm \n",re_dash)
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// Y.V.C.Rao ,1997.Chemical Engineering Thermodynamics.Universities Press,Hyderabad,India. //Chapter-7,Example 11,Page 259 //Title: The skating problem //================================================================================================================ clear clc //INPUT m=60;//mass of the pers...
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//Function migration (image list to matrix) for: integralImage //Generated by migrate.cpp //Author: Anirudh Katoch function res = integralImage(varargin) select length(varargin) case 02 then res = raw_integralImage(varargin(01), varargin(02)) case 01 then res = raw_integralImage(varargin(01)) else error...
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avg = 0; var = 4; num = 9; X =[5 8.5 12 15 7 9 7.5 6.5 10.5]; samplemean= mean(X); lowerlim = samplemean - (1.645*sqrt(var/num)) upperlim = samplemean + (1.645*sqrt(var/num)) disp(" to infinity", lowerlim,"The 95% upper confidence interval is " ) disp(upperlim,"The 95% upper confidence interval is minus infin...
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// Yuhao Ye // 529006730 // Filename = gcd.tst load gcd.hack, output-file gcd.out, compare-to gcd.cmp, output-list RAM[0]%D2.6.2 RAM[1]%D2.6.2 RAM[2]%D2.6.2; set RAM[0] 9, set RAM[1] 6, set RAM[2] 0, repeat 400 { ticktock; } output; set PC 0, set RAM[0] 11, set RAM[1] 21, set RAM[2] 0, repeat 400{ ticktock; } outp...
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codeblock readtextfile(ScriptDir+"\_TOOLS.sci"); codeblock readtextfile(ScriptDir+"\Physics\Optics\_Optics.sci"); rootframe=T_scene_create; SetOpticFrame(rootframe); sss=T_getscene; vp=T_getviewport; vp.CameraPos=point(0,0,10); vp.CameraDir=vector(0,0,-1); vp.FocalDistance=10; vp.NearClipPlane=0.1; vp.FarClipPlane=...
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//Caption: Confidence Interval Estimation (when Sample Size is Small) //Example7.12 //Page216 clear; clc; X = 20;// mean diameter of the shafts in mm Var = 9;// variance of the safts in mm Std = sqrt(Var);//standard deviation n = 16;// number of samples alpha = 0.05;//confidence level alpha = alpha/2; talph...
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clear //Given q=16*10**-19 a=3.9*10**-12 E=10**5 //Calculation p=q*a U=-p*E //Result printf("\n (i) The electric dipole moment %e Cm", p) printf("\n (ii) Potential energy of dipole in the stable equilibrium position %e J",U)
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//Chapter1,Example1.3,Pg1.10 printf("\n Diameter of wire=d\n") printf("\n Length of wire=l\n") printf("\n Resistance of wire = 4pl/A\n") printf("\n For another wire diameter =2d\n") printf("\n length =4l\n") printf("\n Hence Resistance = 4pl/A") printf("\n Hence Resistance = R\n")
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//Example 14.2. clc format(6) Af=100 dAf=0.02 dA=0.2 disp("We have, dAf/Af = dA/A * 1/(1+A*beta)") disp(" dAf/Af = dA/A * 1/(1+A*beta)") Ab=dA/dAf disp(Ab,"Therefore, (1 + A*beta) =") disp("Also, the gain with feedback is") disp(" Af = A / (1+A*beta)") A=Af*Ab disp(A,"Therefore, A =") ...
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clear all; clc; disp("Scilab Code Ex 7.6 : ") //Given: F = 40; //N s = 9; //cm h = 5; //cm t = 0.5; //cm w = 3; //cm w_3 = w/3; //cm //Calculations: I = (w*h^3)/12 - (2*w_3*(h - 2*t)^3)/12; //Case 1: Q1 = ((h-t)/2)*(w*t); V1 =((F/s)*I)/Q1 ; //q = VQ/I //Case2: Q2 = ((h-t)/2)*(w_3*t); V2...
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function[cmpa]= add(A,B,C,n) cmpa=0; if n==1 then C= A+B; cmpa =1; return; end for i=1:n for j=1:n C(i,j) = A(i,j) + B(i,j); cmpa = cmpa+1; end end endfunction
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//example 14.7 PG-14.38 clc clear printf(" Given=> A(A+B) = AA+AB .......Distributive property\n\n") printf(" A(A+B) = A+AB ........Since A.A=A\n\n") printf(" A(A+B) = A(1+B) .......Distributive property\n\n") printf(" A(A+B) = A ........... Since A+1=1\n\n")
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// This file is part of www.nand2tetris.org // and the book "The Elements of Computing Systems" // by Nisan and Schocken, MIT Press. // File name: projects/07/MemoryAccess/PointerTest/PointerTestVME.tst load, output-file OverFlowTests.out, compare-to OverFlowTests.cmp, output-list RAM[3000]%D1.6.1 RAM[3001]%D1...
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clc //Intitalisation of variables clear e= 0.761 //volt e1= -0.34 //volt k= 0.02958 //volt //CALCULATIONS r= 10^((e-e1)/k) //RESULTS printf ('K for the reaction = %.1e ',r)
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//Example 5.20 //Newtons Forward Difference Formula //Page no. 144 clc;close;clear; printf(' x\t sin x\t\t 1st\t\t 2nd\t\t 3rd\t\t 4th\t\t 5th\n\t\t\tdifference\tdifference\tdifference\tdifference\tdifference\t') printf('\n---------------------------------------------------------------------------------...
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//Example 12.5 from 'Brakes' cannot be coded because almost all the information is obtained from the figure. //The entire solution is based on the free-body diagram and not on formulae.
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clc clear //Initialization of variables P=200 //psia T=540 //F pow=1000 //kw ms=16000 //lb/hr //calculations disp("From mollier charts,") h1=1290 //Btu/hr h2=940 //Btu/hr dh=h1-h2 hf2=83 //Btu/lb etat=(h1-h2)/(h1-hf2) act=pow*3413/(ms*(h1-hf2)) etae=act/etat //results printf("Ideal thermal efficiency =...
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//Example 7.3 F_app=120;//Applied force (N) F_fr=5;//Opposing friction force(N) d=0.800;//Distance traversed (m) F_net=F_app-F_fr;//Net force (N) W_net=F_net*d;//Net work (J) printf('a.Net work done on the package = %0.1f J',W_net) W_app=F_app*d*cosd(0);//Work done due to applied force in direction of displaceme...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Engineering Thermodynamics by Onkar Singh Chapter 3 Example 15") T1=400;//initial temperature of gas in K R=8.314;//gas constant in disp("for constant pressure heating,say state changes from 1 to 2") disp("Wa=...
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type newType = short; void sym1(newType a) { a = 1; } main() { var a : newType; a = 1 + newType; }
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//Part B Ex 1.6 clc;clear;close; format('v',5); Av=10;//voltage gain Ri=1;//kohm Ro=10;//ohm Vs=2;//V(Sensor voltage) Rs=100;//ohm(Sensor resistance) RL=50;//ohm Vi=Vs*Ri*1000/(Rs+Ri*1000);//V Vo=Av*Vi*RL/(Ro+RL);//V Po=Vo^2/RL;//W Pi=Vi^2/Ri;//mW Ap=Po*1000/Pi;//Power gain disp(Ap,"Power gain"); //Answe...
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// Norm2 of a vector // // Computed as the square root of the dot product. // // INTPUT // - v: a vector // // OUTPUT // - res: the norm2 of the vector // // USAGE // res = vect_norm(v); // // HISTORY // 28/03/2014: T. Pareaud - Creation function [res] = vect_norm(v) res = sqrt(vect_dotProd(v,v)); endfunction
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clear; clc; Na=6.02*10^23 // Avagadro Number in mol^-1 AtWt=28.09 //in g/mole Density=5*10^22 //in atoms/cm^-3 //Calculation DensityPerUnitVolume=(Density*AtWt)/(Na) mprintf("Density per unit volume= %1.2f g cm^-3",DensityPerUnitVolume)
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clear; clc; disp('Example 4.11'); // aim: To determine // the change of internal energy // Given values m = 1.5;// mass of steam,[kg] P1 = 1;// initial pressure, [MN/m^2] t = 225;// temperature, [C] P2 = .28;// final pressure, [MN/m^2] x = .9;// dryness fraction of steam at P2 // solution //...
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clc //initialisation of variables b= 10 //ft n= 2 d= 3.5 //ft i= 1/625 //CALCULATIONS A= d*(b+(d/n)) L= sqrt(d^2+(d/2)^2) P= b+2*L m= A/P v= 1.486*m^(2/3)*i^0.5/0.03 Q= A*v //RESULTS printf ('Discharge = %.1f cuses ',Q)
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function f=%s_d_r(n1,f2) // n1./f2 //! // Copyright INRIA if size(n1,'*')==0 then f=[],return,end f=rlist(n1.*f2('den'),ones(n1).*f2('num'),f2('dt'))
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// Example6.23 // to determine the output voltage of an op-amp clc; clear; close; Vin = 5 ; // V R1 = 25*10^3 ; // ohm R2 = 75*10^3 ; // ohm // in this problem op-amp A1 perform the voltage follower and op-amp A2 perform inverting amplifier and op-amp A3 perform non-inverting amplifier // the output volta...
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Example3_2.sce
//clear// //Caption: To Calculate input and output power in dBm //Example3.2 //page 91 clear; close; clc; Pin = 200e-06; //power launched into the fiber alpha = 0.4; //attenuation in dB per KM z = 30; //optical fiber length 30 KM Pin_dBm = 10*log10(Pin/1e-03); Pout_dBm = 10*log10(Pin/1e-03)-alpha*z; Pout =...
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clc; //e.g 18.16 Vbe=0.7; Vcc=10; Rc=1*10**3; beta=100; R1=10*10**3; R2=5*10**3; Re=500; Vb=Vcc*(R2/(R1+R2)); disp('V',Vb*1,"Vb="); Ve=Vb-Vbe; disp('V',Ve*1,"Ve="); Ie=Ve/Re; disp('mA',Ie*10**3,"Ie="); Ic=Ie; disp('mA',Ic*10**3,"Ic="); Vce=Vcc-(Rc+Re); disp('V',Ve*1,"Ve=");
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<?xml version="1.0" encoding="UTF-8" standalone="yes"?> <AutoTestC version="2.0.0"> <Title>Test case 1 - polarity static - 60s</Title> <Organization>Mercedes-Benz</Organization> <Standard>MBN LV 124 2013</Standard> <Item>6.15 E-15 Reverse polarity</Item> <system> <PowerSystem>3</PowerSystem>...
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clc clear disp('example 14.16') vp=132;vs=33;vt=11 //voltage at primary ,secondary ,teritiory pp=75;ps=50;pt=25 //MVA rating at prinary ,secondary,teritiory rpr=0.12;rv=132;rp=75 //reactance power of primary under rv and rp as voltage and power base poa=60;rea=50 //load real and reactive power a pva=125;sva...
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clear; clc; //Caption : Parameters of a Common Emitter Amplifier //Given Data hie=1.1;//in K hre=2.5*(10^-4); hfe=50; hoe=25*(10^-3);//in K^-1 r=200;//in K Rs=10;//in K Ri=1;//in K Rl=10;//in K rl=(r*Rs)/(r+Rs);//in K Ai = -hfe/(1+(hoe*rl));//Current Gain disp(Ai,'Ai = '); Ri = hie + (hre*Ai*rl);...
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//chapter_no.-8, page_no.-334 //Example_no.8-3-1 clc; J=20*(10^3);//current_density q=1.6*(10^-19); NA=2*(10^15);//Doping_Concentration vs=J/(q*NA); disp(vs,'avalanche-zone_velocity(in cm/s)is ='); disp('This means that the avalanch-zone velocity is much larger than the scattering-limited velocity');
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// Scilab code Ex17.9 : Pg:893 (2011) clc;clear; e = 1.6e-019; // Energy equivalent of 1 eV, J/eV N_A = 6.023e+023; // Avogadro's number E_f = 200*1e+06*e; // Energy released per fission, J E_mol = E_f*N_A; // Energy released by one mole of U235, J E = E_mol*1000/235; // Energy released by the fiss...
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exec('scilab-base-calculs-testexo5l.sce',-1) //to delete u13=[u11 u12]
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<?xml version="1.0" encoding="UTF-8"?> <Project Name="map2207" Width="13" Height="15" CellSize="40" BackgroundSize="1" Background="15plus.png"> <Cell Name="箱子1" X="3" Y="1" /> <Cell Name="墓碑" X="4" Y="1" /> <Cell Name="箱子1" X="6" Y="1" /> <Cell Name="墓碑" X="8" Y="1" /> <Cell Name="箱子1" X="10" Y="1" /> <Cel...