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//Example No. 6.2.3 clc; clear; close; format('v',5); //E=cos(fi)+sin(fi)<si; //En=cos(%pi/4+%pi*cosd(fi)) as 2*E0=1 fi=[0 30 60 90 120 150 180 210 240 270 300 330];//degree(Angle) si=%pi/2*(cosd(fi)+1);//(Phase) En=cos(%pi/4+%pi*cosd(fi));//Normalized field disp("Different values of fi : "); disp(string(fi)...
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clear; clc; printf("\t\t\tProblem Number 6.35\n\n\n"); // Chapter 6: The Ideal Gas // Problem 6.35 (page no. 285) // Solution //In this problem,the air expands from 5 atm absolute to 1 atm absolute from an initial temperature of 1000R, pr=12.298; //relative pressure //unit:atm h=240.98; //Btu/lbm //enthalpy...
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function x=GaussSeidel(A,b,es,maxit) if nargin < 4 then maxit=50; end if nargin < 3 then es=0.00001; end [m,n] = size(A); if m~=n then error('Matrix A doit etre caree'); end C=A; for i=1:n C(i,i)=0; x(i)=0; end x=x'; for i=1:n C(i,1:n) = C(i...
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clc,clear printf('Example 3.18\n\n') V=200,I_L=40, R_sh=200,R_a=0.2 //shunt field winding and armature resistance //case(a) : As a generator P_out_g=V*I_L //output poewr as generator I_sh=V/R_sh I_a = I_L + I_sh E = V + I_a*R_a P_a_g=E*I_a //power developed in armature P_cu_g= R_a*I_a^2 + R_sh*I_sh^2 //co...
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clc; s = %s; G = syslin('c',((s-3)*(s-5))/((s+1)*(s+2))); disp(G); evans(G,100);xgrid(); printf("For all the points on the root locus K.G(s).H(s) = -1"); K = -G^(-1); disp(K); Kdot = derivat(K);disp(Kdot,"dK/ds ="); root = roots(numer(Kdot)); disp(root(2),"Break away point at ",root(1),"Break in point at"); ...
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clc clear //Initialization of variables w=0.3448 R=8.3143 Tc=647.3 //calculations disp("From charts of entropy") h0=0.57 h1=0.05 h2=h0+w*h1 h3=h2*R*Tc dh=-h3 //results printf("Enthalpy departure = %d kJ/kmol",dh) disp("The answer is a bit different due to rounding off error in the textbook")
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// Scilab Code Ex13.9: Page-502(2014) clc; clear; k = 1.38e-023; // Boltzmann constant, J/K r = 3e-015; // Distance at whcih the nuclear force becomes effective, m e = 1.6e-019; // Charge on an electron, C K = 9e+009; // Coulomb's constant, N-Sq.m/C^2 V = K*e^2/r; // Coulomb potential energy, J // A...
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clear //Given R=20.0 //K ohm R2=1 //K ohm //Calculation Vr=(R*R2)/(R+R2) //Result printf("\n (i) Voltmeter resistance is %0.3f K ohm", R) printf("\n (ii) Voltmeter resistance is %0.3f K ohm",R2) printf("\n (iii) Voltmeter resistance is %0.2f K ohm",Vr)
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EXAMPLE6_3.SCE
//ANALOG AND DIGITAL COMMUNICATION //BY Dr.SANJAY SHARMA //CHAPTER 6 //NOISE clear all; clc; printf("EXAMPLE 6.3(PAGENO 282)"); //given R_1 = 20*10^3//resistance one R_2 = 50*10^3//resistance two T = 273+15//temperature in kelvin B = 100*10^3//bandwidth k = 1.38*10^-23//boltzman's constant //calculat...
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function y = moc_conv (a, b, shape ) // Convolve two vectors. // Calling Sequence // y = nan_conv (a,b) // y = nan_conv (a, b) returns a vector of length equal to length (a) + length (b) - 1 // Description // If a and b are polynomial coefficient vectors, conv // returns the coefficients of the product polynomial. // E...
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//Problem 2.09: //initializing the variables: D = 5/12; // in ft p = 50; // in lb/ft3 v = 10; // in fps u = 0.65*6.720E-4 ; //in lb/ft.sec //calculation: Re = D*p*v/u if (Re>2100) then s = 'turbulent'; else s = 'laminar'; end printf("\n\nResult\n\n") printf("\n Reynolds number for a fluid flo...
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//no i/p args are passed to the function clc; clear; exec('/home/debdeep/Desktop/TEST NOW!!/rooteig/rooteig.sci'); y=rooteig(); //output // !--error 77 //rooteig //at line 73 of function rooteig called by : //y=rooteig();
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// Exciting current calculation needed to setup reqd flux clc; U_o=4*%pi*10^-7; A1=800*10^-6; A2=600*10^-6; l1=1*10^-3; //air gap length l2=160*10^-3; //length of central limb l3=400*10^-3; //length of side limb phi=.8*10^-3; N=500; function [B]=fd(A) B=phi/A; endfunction ...
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// Scilab code Exa 3.6.1 : To determine the mass of daughter nucleus for given reaction : Page no. 138 : (2011) M_C = 14.007685; // Mass of C-14 nucleus, amu E_e = 0.156/931.47; // Kinetic energy of emitted electron, amu M_N = M_C-E_e; // Mass of N-14 nucleus, amu printf("\n Mass of N-14 nucleus : %9.6f amu", M_N) /...
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//3.9 clc; AH=5*1/2; printf("AH passed in 30 minuties=%.1f percent",AH) V_assumed=0.51*1000/AH; V_actual=200; Error=V_actual-V_assumed; Correction=-Error; Cor=Correction*100/V_actual; printf("\nCorrection required=%.1f percent",Cor)
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Expanding for base=2, level=4, reasons+features=base Refined variables= ReasonFactory: base, code="base" BaseReason.consider( "0", "4a²-4b+1") = failure constant=1, vgcd=4
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// Code to solve Gomme, Rogerson, Rupert and Wright, "Home Production in // a Life-cycle Model", NBER Macroeconomics Annual 2004, pp. 415-461 // // Coding by Paul Gomme, Concordia University // // Code written in Scilab: http://www.scilab.org // clear; clearglobal; //cd ("~/Work/scilab"); rand('seed'); rand('normal');...
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function [fval] = myf (x) fval = exp(x) / (cos(x)^3+sin(x)^3) endfunction
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<?xml version="1.0" encoding="UTF-8"?> <Project Name="map1106" Width="13" Height="9" CellSize="40" BackgroundSize="1" Background="7plus.png"> <Cell Name="丛林图腾1" X="1" Y="1" /> <Cell Name="丛林图腾2" X="3" Y="1" /> <Cell Name="丛林图腾2" X="4" Y="1" /> <Cell Name="丛林图腾2" X="5" Y="1" /> <Cell Name="丛林图腾2" X="6" Y="1" ...
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// Example 5.26:fh,fl and bandwidth clc; clear; close; fln=25;//in hertz fhn=16;//in kelo hertz n=3;// x=sqrt(2^(1/n)-1);// fl=x*fln;//lower cut off frequency in hertz fh=fhn/x;//upper cut off frequency in hertz BW=fh-fl*10^-3;//bandwidth disp(fl,"lower cut off frequency in hertz") disp(fh,"upper cut off fr...
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//ElGamal Key Encryption r = 4 pt = 7 e1 = 2 e2 = modulo(e1^d,p) c1 = modulo(e1^r,p) c2 = modulo(pt*e2^r,p) disp("Cipher text") printf("(%d,%d)",c1,c2)
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//<h>=%rvs(h1,h2) // %rvs(h1,h2) calcule (I+h1*h2)\h1. h1: matrice de fractions rationnelles // h2 matrice de scalaires //! [m1,n1]=size(h1(2)) [m2,n2]=size(h2) if abs(n1-m2)+abs(m1-n2)<>0 then error('inconsistent dimensions'),end h=(eye(m1,m1)+h1*h2)\h1 //end
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clc; b=0.228; a=1-b; c=[1+(2*0.455)-b-2*a]/2 n2=a+b+c+1.709; p1=8.28; T2=555; n1=1+0.455+1.709; T1=2968; p2=p1*(n2/n1)*(T1/T2); p=1; K=a/b*[n2*p/(c*p2)]^0.5; disp(log(K),"log(K) is:"); disp("2968","from tables it is proved that temperatur is:")
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clc C=2.5*10^-6; //Assigning values to parameters R=15; L=260*10^-3; temp=(1/(L*C))-(R^2/L^2); fr=(1/20*%pi)*sqrt(temp); Q=(2*%pi*fr*L)/R; Zr=L/(C*R); disp("Hertz",fr,"Resonant frequeny"); disp(Q,"Quality factor"); disp("Ohms",Zr,"Dynamic Impedance");
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//// //Variable Declaration n = 3.0 //Number of moles of CO2 Ti = 300 //Initial and final state Temeperatures of CO2, K Tf = 600 pi = 1.00 //Initial and final state pressure of CO2, K pf = 3.00 cpm = 27.98 //Specific heat of mercury, J/(mol.K) M = 200.59 //Molecualr...
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clear // // //Given //Variable declaration d=1.2 //Diameter in m p=1.5 //Internal pressure in MN/sq.m sigmat_star=200 //Yield stress in MN/sq.m Sf=3 //Factor of safety //Calculation sigmat=sigmat_star/Sf //Permissible stress in simple tension in MN/sq.m //case(i):Thic...
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//Chapter 24 clc //Example 1 //given L=1.2 // Seperation between screen and double-slit in meter d=3*10^-5 //distance between the two slits m=2 //second order bright fringe Y=4.5*10^-2 //distance of second order bright fringe from centerline //wavelength of light lambda=(Y*d)/(m*L) disp(lambda,"(A) wavelengt...
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//EX3_11 PG-3.38 clc Rf=0.1; Idc=10; Rs=0; Es=30;//rms value of input voltage Esm=sqrt(2)*Es;//peak value of the input voltage Im=Idc*%pi/2;//DC output current disp("We know that Im=Esm/(2Rf+Rs+Rl) for fullwave rectifier") Rl=Esm/Im-2*Rf-0; printf("\n Therefore load resistance is %.1f ohm \n",Rl) Pdc=Idc^2*R...
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// Exa 13.2 // To determine secret encrypting key K using DH key exchange algorithm. clc; clear all; p=23; //prime number that both parties agreed upon g=5;// g is primitive mod p a=6; //party A choosen number b=15; //party B choosen number //solution printf('Party A sends to party B as (g^a mod p) = %...
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clear; clc; // Illustration 2.8 // Page: 120 printf('Illustration 2.8 - Page: 120\n\n'); // solution //*****Data*****// // a-liquid benzene b-nitrogen T = 300; // [K] l = 3; // [length of vertical plate, m] b = 1.5; // [width of vertical plate, m] P = 101.3; // [kPa] v = 5; // [velocity across ...
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// 08.08.12 // 08.10.28 function CL=Projpers(varargin) Nargs=length(varargin); Flg=0; if Nargs==1 & Mixtype(varargin(1))==1 Flg=1; end; CL=[]; for N=1:Nargs Crv=varargin(N); if Mixtype(Crv)==1 Tmp=CameraCurve(Crv); CL=Mixadd(CL,Tmp); else if Mixtype(Crv)==3 ObjL=[]...
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exec('readpbm.sci') exec('display_gray.sci') img = readpbm('Europa_surface.pbm'); //gray = display_gray(img); max_gray=max(img); disp(max_gray); //216 colonne=512; ligne=384; //si point le plus blanc if img(j,i) > 200 //si point le plus noir if img(j,i) < 50 for i=1:ligne for j=1:colonne if img(...
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clear// //Caption:Program to Caculate Electric Field E at P due to 4 identical charges //Example2.2 //page 33 clc; P = [1,1,1]; P1 = [1,1,0]; P2 = [-1,1,0]; P3 = [-1,-1,0]; P4 = [1,-1,0]; R1 = norm(P-P1); aR1 = (P-P1)/R1; R2 = norm(P-P2); aR2 = (P-P2)/R2; R3 = norm(P-P3); aR3 = (P-P3)/R3; R4 = norm(P-P4); aR4 = (P-P...
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//Example 3.2 clc clear A = [1 1 1; 3 3 4; 2 1 3]; //Coefficient Matrix B = [7; 24; 16]; //Constant Matrix n = length(B); Aug = [A,B]; // Forward Elimination for j = 1:n-1 // Partial Pivoting [dummy,t] = max(abs(Aug(j:n,j))); lrow = t(1)+j-1; Aug([j,lrow],:) = Aug([lrow,j],:); ...
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function [p, s, mu] = moc_polyfit (x, y, n) // Return the coefficients of a polynomial // Calling Sequence // p= polyfit (x, y, n) // [p, s] = polyfit (x, y, n) // [p, s, mu] = polyfit (x, y, n) // Parameters // n: degree (scalar) or logical vector // p: The polynomial coefficients are returned in a row vector. // s...
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clear all; clc; disp("Scilab Code Ex 14.11 : ") //Given: A = 400*10^-6; //m^2 E = 200*10^6; //kN/m^2 P = 100; //kN //Virtual Work Equation: n = [0 0 -1.414 1]; N = [-100 141.4 -141.4 200]; L = [4 2.828 2.828 2]; del_cv = 0; for i=1:4 del_cv = del_cv + (n(i)*N(i)*L(i))/(A*E); end del_cv = d...
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clc //initialisation of variables d= 4 //ft d1= 5/4 //ft g= 32.2 //ft/sec^2 h= 3 //ft K= 1 //CALCULATIONS C= (%pi/4)*d^2*sqrt(2*g)/(sqrt((d^2/d1^2)^2-1)) Q= K*sqrt(h)*C V= Q/(%pi*d1^2/4) //RESULTS printf ('Velocity at the throat= %.2f ft/sec ',V)
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function [y]=f(x) /*Dados de Entrada x0: 4 tolerancia: 0.00001 */ y = (x^4 + 2 * (x^3) - 13 * (x^2) -14 * x + 24) endfunction function [y]=df(x) y = (4 * (x^3) + 6 * (x^2) - 26 * x - 14) endfunction tic(); t=100; for i=1:1:t xZero=4; tolerancia=0.00001; Fx=f(xZero); DFx = df(xZero); ...
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//Example 4.3 clear; clc; fc=1*10^(3); fs=1.3*10^(3); AmaxdB=0.1; Amax=10^(AmaxdB/20); AmindB=40; Amin=10^(AmindB/20); f01=648.8; fz1=4130.2; Q1=0.625; f02=916.5; fz2=1664.3; Q2=1.789; f03=1041.3; fz3=1329; Q3=7.880; C1=2.2*10^(-9); R1=1/(2*%pi*f01*C1); w01=2*...
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//Example 3.44:balance current and bridge sensivity clc; clear; close; P=100;//ohms Q=1000;//ohms S=857;//ohms X=((P/Q)*S);//ohms E=1.5;//volts dx=1/X;// rg=50;//ohms a1=((rg+(X*(Q+S))/(X+S)));//ohms dig=((E*S*X*dx)/((X+S)^2*a1));// D=100;//M-ohm sb=((dig*D*10^6)/dx);// disp(dig*10^6,"balance current is ,(micro-A)=") d...
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clear //Given f=50 //Hz L=2 Ev=12 //V L1=6 //Calculation // Xl=2*%pi*f*L Iv=Ev/Xl Xl1=2*%pi*f*L1 Iv1=Ev/Xl1 //Result printf("\n Current flows when the inductance is changed to 6 H %0.4f A",Iv1)
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clc,clear //Example 6.4 //To solve the given equation //Given equation is cos_theta = tan_theta //simplyfying given equation, we get //(sin_theta)^2 + sin_theta - 1 = 0 //Solve for sin_theta as follows p=[1 1 -1] sin_theta= roots(p) printf('Values of sin(theta) after simplifying and solving = %f and %f\n',si...
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// simple test : bar in traction-compression FEnode=[1 0 0 0 0 0 0 2 0 0 0 50 0 0]; FEel0=[%inf abs('bar1')]; FEel0(2,:)=[1 2 1 1 1]; pl=[1 1 2.1e10 0 2500 0]; il=[1 1 0 0 0 1]; femesh(';divide500'); model=struct('Node',FEnode,'Elt',FEel0,'pl',pl,'il',il); data=struct('DOF',2.01,'def',1e6)...
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clear clc //Example 6.6 FORCES ACTING ON A PIPE BEND p=75*10^3 //[Pa] r=0.5; //[m] A=%pi*r^2 //area[m^2] S=0.94; rho=S*1000 //drnsity[kg/m^3] Gamma=S*9.81 //specific weight of oil[kN/m^3] V=1.2; //volume of oil[m^3] Q=2; //[m^3/s] m=rho*Q //mass flow rate[kg/s] v=2.55; //[m/s] theta=30; //degrees //Reacti...
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\set time slow \rele print CROUTPUT: \DISK EXTEND 100 \LIST 1 REAL 7.232 9.927 10.643 83.58 82.04 73.98 \LIST 5 OVERALL SCALE=.6415809 READ NATOM=1 ATOM C 1 1 .05 1 1 1 END \LIST 13 DIFF GEOM=KAPPA COND .71073 6.05 90 MATRIX -0.032117 0.056039 0.076280 CONT 0.023782 -0.088931 0.056803 CONT 0.139157 -0.000812 -0.0...
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//Chapter 29 Ex3 clc; clear; close; facevalue=100; //since the stock is calculated over 100 discount=4; brokerage=1/4; //value is in percentage purchaseAmt=2400; cashfacevalue=facevalue-discount-brokerage; //cash required to purchase Rs.100 stock cashpurchaseAmt= cashfacevalue*purchaseAmt/facevalue; mprintf...
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[[-2,2,0,-4],[-6,-2,-2,-4],[-5,-4,-5,-2],[1,-2,4,1]],det=156 [89,-17,-40,-86], chain 2 => [132,-76,-5,-123] => [76,-138,-85,141] ?? [-992,-574,315,153] [[2,5,0,0],[2,-5,2,2],[0,-6,-1,2],[0,0,-2,2]],det=56 [89,-17,-40,-86], chain 2 => [93,11,-30,-92] => [241,-113,-220,-124] ?? [-83,359,650,192] [[5,-2,-4,6],[-4,3,4,-6...
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rand("seed", fscanfMat("seed.txt")); R1 = rand(3,3); R2 = R1 + eye(3,3)*0.01; [U,S,V]=svd(R2); H = eye(3,3); H(3,3)=det(U)*det(V); R = U*H*V'; t=rand(3,1)*0.2; fprintfMat("RT.txt", [R'; (-R'*t)']); P=fscanfMat("P101.txt"); P(:,4)=[] Q=R * P' + t * ones(1, 101); Q=Q'; fprintfMat("Qnew101.txt", Q); P=fscanfMat("P504...
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function [w, c, s ]= rbfn(X, t, k, h) p = length(X(:, 1)) //calculate the centroids //centroids = neural_gas(1, k, X, 0.1, 10, 5, 50) centroids = fs_learning(2, k, X, 0.1, 10) //determine length of kernel Gaussian sigmas //distance from points to their centroid dists = zeros(k,1) //...
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clc // initialization of variables clear Do=22 //mm Di=18 //mm Dm=20 //mm tD=0.1 // t/D //part (a) tau=70 //MPa G=77.5 //GPa //calculations Do=Do*10^-3 Di=Di*10^-3 Dm=Dm*10^-3 tau=tau*10^6 G=G*10^9 A=%pi*Dm^2/4 t=Dm*tD T1=2*A*tau*t th1=tau*%pi*Dm/(2*G*A) J=%pi/32*(Do^4-Di^4) r=Dm/2 T2=tau*J/r th2...
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// chapter 11 // example 11.3 // Determine control range of firing angle, maximum value of rms load current, maximum power and power factor, maximum values of average and rms thyristor current, maximum possible of di/dt and the conduction angle for alpha=0 and alpha=120 // page-721-722 clear; clc; // given R=4; // in o...
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// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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clc; v=24; //velocity in m/sec a=8; //acc. in m/sec square t=v/a; //using t=v/a disp(t,"Time in sec = "); //displaying result s=(1/2)*(a*t*t); //kinematical equation disp(s,"Distance in metre = "); //displaying result
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clc //initialisation of variables clear n=7 w= 62.4 //lbf/ft^3 v= 6 //ft/sec d= 2 //in u= 2.34*10^-5 //lbf/ft^3 f= 0.0178 g= 32.2 //ft/sec^2 R= 1.224 R1= 8 //ft/sec //CALCULATIONS r= (n+1)*(2*n+1)/(2*n^2) Red= w*v*(d/12)/(u*g) C= (d/Red)^(1/7)*R*(R1/f)^(4/7) V = v*sqrt(f/8) //RESULTS printf ('Vmax/V =...
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// THIS PROVIDES A SOLUTION FOR A BOUNDARY-VALUE PROBLEM FOR A // FIRST-ORDER ODE WITH ONE UNKNOWN PARAMETER TO BE DETERMINED. // THE ODE IS OF THE FORM Dy/Dx = f(x,Q) WHERE Q IS THE // UNKNOWN PARAMETER. THE BOUNDARY CONDITIONS ARE y = Ya FOR // x = a AND y = Yb FOR X = b. // THE FUNCTION f(x,Q) IS PRO...
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// Grob's Basic Electronics 11e // Chapter No. 05 // Example No. 5_1 clc; clear; // Solve for branch currents I1 and I2. R1 = 1*10^3; // Resistor 1=1*10^3 Ohms R2 = 600; // Resistor 2=600 Ohms Va = 15; // Applied Voltage=15 Volts I1 = Va/R1; disp (I1,'The Current Resistor R1 in Amps') disp...
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k=[0.2 0.3 0.4 1]; x=[-1 -2 -3 -4 -5 -6 -7]; [f,g] = latcfilt(k,x); disp(f); disp(g); //output // !--error 10000 //dimension mis-match between k and v //at line 46 of function latcfilt called by : //[f,g] = latcfilt(k,x); //matlab //Columns 1 through 6 // // -1.0000 -2.7800 -5.3680 -8.7360 -13.1040 ...
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//To find the greatest permissible angle clc //Given: N=500 //rpm //Solution: //Calculating the angular velocity of the driving shaft omega=2*%pi*N/60 //rad/s //Calculating the total fluctuation of speed of the driven shaft q=12/100*omega //rad/s //Calculating the greatest permissible angle between the centre ...
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clc;funcprot(0);//EXAMPLE 4.7 // Initialisation of Variables r=15;......................//Compression ratio C=43000;..................//Calorific value of fuel used in kJ/kg afr=27;...................//Air fuel ratio t2=870;....................//Temperature of the charge at the end of the stroke in Kelvin cv=0.71...
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clear // // // //Variable declaration m=9.11*10**-31 //mass(kg) e=1.602*10**-19 //charge(c) E=5.5 //fermi energy(V/m) tow=3.97*10**-14 //relaxation time(s) //Calculation Vf=sqrt(2*E*e/m) //fermi velocity(m/s) lamda=Vf*tow //mean free path(m) //Result printf("\n fermi velocity...
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//exapple 2.13 clc; funcprot(0); // Initialization of Variable l=20/100;//length of photograph w=20/100;//breadth of photograph Pl=0.6;//longitudinal lap Pw=0.3;//side lap s=100*20; L=(1-Pl)*s; W=(1-Pw)*s; Ar=L*W/1000/1000; N=100/Ar; A=round(N); if N-A<0 then disp(A,"no. of photographs to be taken...
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clc; clear; Q=9;//gal/min l=5;//ft b=2;//ft H=1.5;//ft //continuity equation to water: integral of m= d*((h*b*l)+(H-h)*A); where A is cross-sectional area of faucet //m=d*(b*l-A)*dh/dt, where dh/dt= hrate //m=d*Q //since A<<l*b, it can be neglected fn=poly([0 (1.94*l*b)],"h","c"); x=derivat(fn);//x=m/(dh/dt)...
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function [b, c] = prog7(A) n = 5; j = 1; for i = 1:n if A(i) > 0 then b(j) = A(i); c(j) = i; j = j + 1; end; end endfunction
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clc(); clear; //Given : Q = 4 ;// in MeV Ex = 2; // in MeV Ey = 5 ; // in MeV mx = 4; // in u my = 1 ; // in u My =13; // in u theta = acosd(( (Ey*(1 + (my/My))) - (Ex*(1 - (mx/My))) - Q )/((2/My)*sqrt(mx*Ex*my*Ey))); // angle of ejection in degrees printf("Angle of ejection is %.0f degrees",theta);
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clc clear //Input data x=0.03//Length stretched by the spring in m m=0.25//Mass of the body in kg //Calculations k=(m*9.8)/x//Force constant of the spring in N/m //Output printf('Force constant of the spring is %3.2f N/m',k)
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// EXA 3.8 clc; clear; close; // Given data R1 = 5;// in k ohm R_F = 500;// in k ohm V_in = 0.1;// in V A_F = -(R_F/R1); disp(A_F,"Voltage gain is"); R_i = R1;// in k ohm disp(R_i,"The Input resistance in kΩ is"); R_o = 0;// in ohm disp(R_o,"Output resistance in Ω is"); V_out = A_F*V_in;// in V disp(V_...
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//(Friction Clutches) Example 11.7 //Refer Fig. 11.9 in the book //Torque transmitting capacity of the multi-disk clutch Mt (N-m) Mt = 10 //Coefficient of friction for cork sheet-steel plate in wet condition mu mu = 0.2 //Permissible pressure on cork sheet Pa (MPa) Pa = 0.1 //Inner diameter of the friction li...
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//5.4 clc; Vin=120; Vm=2^0.5*Vin; alph=90; R=10; VL=Vm*(1/(2*%pi)*(%pi-90*%pi/180+sind(180)/2))^0.5; printf("\nRMS output voltage =%.2f V", VL) Po=VL^2/R; IL=VL/R; VA_input=IL*Vin; pf_input=Po/VA_input; printf(" \nInput Power factor =%.3f lagging", pf_input) Iavg_thy=Vm*(1+cosd(alph))/(2*%pi*R); pri...
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// Calculate the range of readings specified interms of f.s.d. and true value clc; disp('Range when specified interms of f.s.d.') Error_fsd=1*1000/100' Range_lower_value=100-Error_fsd; disp(Range_lower_value,'Lower value of range (kN/m2)') Range_upper_value=100+Error_fsd; disp(Range_upper_value,'Upper value of r...
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//chapter-12,Example12_2,pg 383 fc=10^6//carrier frequency m=0.4//modulation index fs=100//signal frequency V=2//(+/-)2V range delfc1=m*fc//frequency deviation for FS(full scale) //(+/-) 2V corresponds to delfc Hz deviation assuming linear shift, for (+/-)1V delfc2=delfc1/V//frequency deviation for...
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function strHex=hrtTypeDate2Hex(strDate) auxVet = strtod(tokens(strDate,'/')); strHex = msprintf("%02s %02s %02s",dec2hex(auxVet(1)),dec2hex(auxVet(2)),dec2hex(auxVet(3)-1900)); endfunction
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w=10 R=2 L=0.3 Ir=10*(cos(%pi/4)+%i*sin(%pi/4)) Vr=Ir*R Vc=20*(cos(%pi/4)-%i*sin(%pi/4)) V=Vr+Vc Ic=Ir C=Ic/(w*Vc*%i) disp(real(C)) ///////Wrong in book
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clc clear //Initialization of variables V61=10.8 //ft/s V81=6.05 //ft/s r0=3 //in e=0.00015 d1=6 //in rho=1.94 //slugs/ft^3 mu=2.34e-5 //ft-lb/s^2 //calculations roe=r0/(12*e) Nr1=V61*(d1/12)*rho/mu f6=0.0165 V6=11.6 //ft/s V8=6.52 //ft/s Q=V6*%pi/4 *(d1/12)^2 //results printf("Discharge = %.2f ft^3/s...
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function matriceImage = chargerImage(path, isRGB) if isRGB == 0 then matriceImage = double(imread(path)); else matriceImage = double(rgb2gray(imread(path))); end endfunction
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//exercicio de iteração com ponto fixo function [raiz,n] = simples(func,x0,es) //n é o numero de interações //x0 é a condição inicial //es é o criterio de parada //func = sen(sqrt(x)) //inicialização ea= 100; x=x0; i=0; if argn(2)<3 then es=0.0001; end //inincia o ...
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clear;lines(0); //flag=list('st',dim_cont_subs,dim_stab_subs,dim_stab0) //dim_cont_subs<=dim_stab_subs<=dim_stab0 //pair (A,B) U-similar to: // [*,*,*,*; [*; // [0,s,*,*; [0; //A= [0,0,i,*; B=[0; // [0,0,0,u] [0] // // (A11,B1) controllable s=stable matrix i=neutral matrix u=unstab...
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// Exa 2.c clc; clear; close; // Given data V_GS= 3;// in V Vth= 1;// in V unCox= 25;// in mA/V^2 unCox= unCox*10^-3;// in A/V^2 W=3;// in µm L=1;// in µm r_DS= 1/(unCox*W/L*(V_GS-Vth));// in Ω disp(r_DS,"The value of r_DS in Ω is : ")
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//applying KVL we have Vi(t) = R*i(t) + 1/C * int(i(t)) dt // Vo(t) = 1/C * int(i(t)) dt syms s R C I Vi= R*I + I/(s*C) Vo = I/(C*s) disp(Vo/Vi,"transfer function=")
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clc// // // //Variable declaration V=344; //voltage(V) n=1; theta=60*%pi/180; //angle(radian) //Calculation lamda=(12.26/sqrt(V)); //de broglie wavelength(angstrom) d=n*lamda/(2*sin(theta)); //spacing of crystal(angstrom) //Result printf("\n spacing of crystal is %0.4f angstrom",d)
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function [x]=stp(orbit,NbrIti,Dim,Delai, ResTemps, EtapTemp, EtapFarc) // Initialisation Commandline=''; NbrComp=size(orbit,2); if ~isdef('DoEstim','local')... then DoEstim=%F, end; if isdef('NbrIti','local')... then Commandline=Commandline+' -l'+string(NbrIti), end; if isdef('EtapTemp','local')... then C...
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clear; clc; funcprot(0); //given data T01 = 293;//in K pi = 5;//pressure ratio R = 0.5;//stage reaction Um = 275;//in m/s phi = 0.5;//flow coefficient psi = 0.3;//stage loading factor eff_stage = 0.888;//stage efficiency Cp = 1005;//J/(kgC) gamma = 1.4; //Calculations beta1 = (180/%pi)*atan((R + 0.5*p...
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+---a---b---c---d---e---f---g---h---+ | | 8 . . . . . . . . 8 | | 7 . . . . . . . . 7 | | 6 . . . . . . . . 6 | | 5 . . . ...
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// Exa 1.17 clc; clear; close; format('v',7) // Given data Je = 360;// in A/cm^2 T = 300;// in K d = 1.5;// in mm d = d * 10^-1;// in cm e = 1.6*10^-19;// in C del = 2*10^18-5*10^17;// assumed dnBYdx = del/d; De = Je/(e*dnBYdx);// in cm^2/s V_T = T/11600; miu_e = De/V_T;// in cm^2/V-s disp(miu_e,"The mo...
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N=100 c=4 MNw=N*c TNw=MNw/2//no. of wireless links disp(TNw,'total no. of wireless links in the network')
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//Example 17// Ch 3 clc; clear; close; // given data E = 5; //electric field in V/m n_o = 10^11; //ion density in ions/m3 T = 293; // in kelvin z = 0.02; //distance in meters e = 1.6*10^-19; //in couloumb k = 1.38*10^-23; // in m2 kg s-2 K-1 n1 = n_o*exp((-e*E*z)/(k*T));//ion density 0.02m away n2 = n_o*exp...
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// properties of a graphite epoxy reinforce plastic clc x = 0.15 Ef = 250 // elastic modulus of fiber in GPa Em = 80 // elastic modulus of resin in GPa sigma_f = 2000 // strength of fiber in MPa sigma_m = 100 // strength of resin in MPa Fc = 1 // let printf("\n Example 10.4") Ec = x*Ef+(1-x)*Em F_ratio = x*Ef...
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${ // Enable extension methods by adding using Typewriter.Extensions.* using Typewriter.Extensions.Types; string typeInit(Property prop) { if (prop.Type.IsPrimitive || prop.Type=="any"){ return prop.Type; } else { if(prop.Type.IsEnumerable) { return prop.Type +" = []"...
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//Section-1,Example-6,Page no.-AC.36 //To find M_wbar for PP given its degree of polymerisation as 10,000. clc; DP_wbar= 10000 //Degree of polymerisation(given) M_o=(12*3)+(6*1) //Molecular weight of repeat unit of PP M_wbar= (10000*42) disp (M_wbar,'weight averge molecular mass...
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//Example 1-4, Page No - 15 clear clc wavelength_inches=8 wavelength_meter= 8/39.37 c=300000000 frequency= c/wavelength_meter printf('\nThe signal freuency is %.3f Megahertz',frequency/1000000) printf('\nThe signnalfrequency is %.3f Gegahertz',frequency/1000000000)
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//To Calculate the Magnetic Field at the Centre of Coil //Example 35.4 clear; clc; i=1.5;//Current Carried by the Circular Coil in Amperes n=25;//Number of turns in the coil a=1.5*10^-2;//Radius of the Circular coil in metres u0=4*%pi*10^-7;//Permeability of Vaccum B=u0*i*n/(2*a);//formula for ...
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// Example 6.2, page no-144 clear clc lam=6715*10^-10//m h=6.626*10^-34 c=3*10^8//m/s e=1.6*10^-19//C Eg=h*c/lam Eg=Eg/e printf("The band gap of the given GaAsP is %.2f eV",Eg)
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//Example 3.1(a) clc; Rm=100; //Internal resistance Im=1*10^-3; //Full Scale deflection current I=100*10^-3; //Total current Rsh=Im*Rm/(I-Im); //Shunt resistance printf('\nValue of Shunt resistance = %.2f ohm\n',Rsh)
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clc; //Example 5.2 //page no. 42 printf("Example 5.2 page no 42\n\n"); //To calculate the force to maintain movement of left plate //velocity of moving plate is equal to the velocity of the plate and velocity of the gas at the surface of the stationary plate is zero k=1.66//kinamatic viscosity of gas rho=0.08//...
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clc // Fundamental of Electric Circuit // Charles K. Alexander and Matthew N.O Sadiku // Mc Graw Hill of New York // 5th Edition // Part 1 : DC Circuits // Chapter 2: Basic Laws // Example 2 - 13 clear; clc; close; // // Given data I = 30.00/1000; R6 = 6.00*1000; R12 = 12.00*100...
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clc clear //Page number 481 //Input data T=300;//The temperature of the metallic copper disc in K Cp=24.5;//The specific heat at constant pressure in J/mol K a=50.4*10^-6;//The coefficient of thermal expansion in K^-1 K=7.78*10^-12;//Isothermal compressibility in N/m^2 V=7.06*10^-6;//The specific volume in...
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//valores Linealizados analiticamente caso del 1er lab // Load the parameters exec('pendulojParametersLab1.sce', -1); Aa=[0 0 1 0;... 0 0 0 1;... 0 ((alpha^2*g)/(bet)) -((THETA*b)/(bet)) 0;... 0 ((alpha*M*g)/(bet)) -((alpha*b)/(bet)) 0]; Ba=[0;... 0;... THETA/bet;... alpha/bet]...
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//Example No.6.5. //Page No.187. clc;clear; a = 0.42;//Lattice constant -[nm]. //(h1,k1,l1) are the miller indices of the plane (101). h1 = 1; k1 = 0; l1 = 1; d1 = (a/sqrt(h1^(2)+k1^(2)+l1^(2)));//interplanar and interatomic distance of plane (101) printf("\nFor (101) plane, the interplanar and interatomic d...